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sandeep gowd 10 years ago

A wallet contains 200 notes made up of Rs.100, Rs.50 and Rs.20 notes and their values are in the ratio 1:2:3 then find the values and notes of each type?

Reply Like? Yes (18) | No (8)

Gopal gupta 10 years ago

if values ratio of Rs.100, Rs.50 and Rs.20 notes are 1:2:3 then minimum notes require to fulfill this condition is : rs100:rs200:rs 300 = 1 note of rs.100 : 4 notes of rs.50 :15 notes of rs.20 = total 20 notes and RS.600 .

But here We have 200 notes , so (1* Rs.100 + 4 * Rs.50 + 15 * Rs.20 )*200/20 =RS.6000(Total Amount) and total RS.100 notes= 10 , Total RS.50 notes=40 ,Total RS.20 notes = 150 .

Like? Yes (10) | No (9)

nikkie gargi 10 years ago

100 rs notes- 33 =rs.3300
50 rs notes-66=rs.3300
20 rs notes-99=rs.1980

Like? Yes (8) | No (10)

ANUPMA 10 years ago

value : 100rs 50rs 20rs
ratio of no.: 1 : 2/1/2 : 3/1/5
1 : 4 : 15
so, 100 rs= 1/20 *200 = 10 notes
50 rs = 4/20*200 = 40 notes
20 rs= 15/20*200= 150 notes

Like? Yes (10) | No (1)

chinmay 10 years ago

10 notes of Rs 100 makes Rs 1000.
40 notes of Rs 50 makes Rs 2000.
150 notes of Rs 20 makes Rs 3000.

Therefore total notes=== 10+40+150=200
Total value of notes====1000+2000+3000=6000

Like? Yes (3) | No (1)

Darshit Pathak 10 years ago

suppose no.of 100 rs notes=x,50rs->y , 20rs.->z
total rs made up from 100rs=100x,simillarly for 50 and 20 i.e. 50y,20z
now compare the ratios 100x/50y=1/2 ==>y=4x
similarly 15y=4z , 15x=z

now x+y+z=200
replace the values of y,z
x+4x+15x=200
x=10
y=40
z=150

no. of 100rs notes=10
no.of 50rs notes=40
no. of 20rs. notes=150

Like? Yes (2) | No (3)

kaustubh salunke 10 years ago

100 rs=10 notes, 50 rs=40 notes, 20rs=150 notes.

Like? Yes (1) | No (1)

sandeep gowd 10 years ago

Void main( )
{
char ch = 321;
printf("%d%c",ch,ch);
}
what will be the output and how?

Reply Like? Yes | No

NAVEEN KUMAR 10 years ago

i hate pro..............

Like? Yes | No

Anand Dwivedi 10 years ago

Number 321 is beyond the range of char variable ch.

Equivalent to 321 = 321 % 128 = 65

65 is ASCII value of character ‘A’

Like? Yes (2) | No

sandeep gowd 10 years ago

In an examination 80 % students passed in Mathematics and 75 % passed in English, while 15 % of the students failed in both the subjects. Of 340 students passed, find the total number of students who appeared in the examination

Reply Like? Yes (2) | No

sandeep gowd 10 years ago

main()
{
printf( 4 + "goodbye");
}

Reply Like? Yes | No

sandeep gowd 10 years ago

main()
{
int i=5;
printf("%d%d%d%d%d%d",i++,i--,++i,--i,i);
}
What will be the output?

Reply Like? Yes (9) | No

ASTHA 10 years ago

output : 4 5 5 4 5

Like? Yes (1) | No

Santosh Kumar Behera 10 years ago

Ans: 4 5 5 4 5 3164
here we have 6 "%d" but we want here values of 5 variables...
so we will get any garbage for last "%d"

Like? Yes (1) | No (1)

sandeep gowd 10 years ago

main()
{
int i=5;
printf("%d%d%d%d%d%d",i++,i--,++i,--i,i);
}
What will be the output?

Reply Like? Yes | No

Nithiya 10 years ago

output:5 6 6 5 5

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