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sujitha 12 years ago

guys do u knw wen will be tcs offcampus in chennai ??

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priyanka jain 12 years ago

plz guide me tcs will came tomarrow in my college so help me same qustion guide and send me paper currently hire in tcs

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sujitha 12 years ago

find the sum of 3+5/(1+22)+7/(1+22+32)+........? how should we need to solve dis problem

Reply Like? Yes (3) | No (1)

sujitha 12 years ago

out of 55 eggs 5 are defective.what is the % of defective eggs?

Reply Like? Yes (2) | No (1)

Anish Anto 12 years ago

(5/55)*100=9.09%

Like? Yes (5) | No (1)

venkatesh 12 years ago

the % of defective 0.00000000........01%

Like? Yes | No (1)

sathyapriya 12 years ago

the defective is 9.090%

Like? Yes (2) | No

Rahul Shalot 12 years ago

Total No of eggs = 55
no of defective eggs = 5
Percentage of defective eggs
= (5/55)*100 = 100/11 = 9.09

Like? Yes (1) | No

HARJINDER SINGH 12 years ago

(5*100)/55
answer is 9.090909091

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anisha 12 years ago

percent of defective eggs=(5/55)*100=9.09%

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ganesh chowdary 12 years ago

guys.. the question is defective % ..
so answer is 0.01

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sujitha 12 years ago

How much percent must be added to the cost price of goods so that a profit of 20% must be made after giving a discount of 10% from the market price?

Reply Like? Yes (1) | No

vasanthapriyan 12 years ago

33.33% percent must be added to the cost price of goods so that a profit of 20% must be made after giving a discount of 10% from the market price

Like? Yes (2) | No (1)

sujitha 12 years ago

can u explain clearly i can get u ..

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vasanthapriyan 12 years ago

let the cost price is rs.100
increase 33.33% => 133.33
now reduce discount 10% => 119.997 => 120
so the profit is 20% on cost price

Like? Yes (1) | No

Sandeep R 12 years ago

Let cost price be 100
let it be increased by x%
then new price = 100+x/100*100=100+x
now on reducing it by 10% we will get 20% profit i.e. 20% on Rs. 100. So new amount =120
therefore:

(100+x)-10(100+x)/100=120
(100+x)-(100+x)/10=120
=>9(100+x)=1200
=>3(100+x)=400
=>100+x=400/3=133.33
=>x=33.33

Like? Yes (2) | No

sujitha 12 years ago

In a class of boys and girls vikas's rank is 9th and tanvi's Rank is 17th . Vikas's Rank among the boysin that class is 4th from the top and 18th from the bottom and tanvi's rank among the girls is 8th fromtop and 21st from bottom. In the order of rank, how many girls are there between tanci and vikas ?

Reply Like? Yes (1) | No

raviteja 12 years ago

two girls b/w vikas and tanvi

Like? Yes (1) | No

vasanthapriyan 12 years ago

2 girls are there between tanci and vikas

Like? Yes | No

Shubham Anand 12 years ago

2 girls bcoz 5 girls above vikas and 7 girls above tanvi so simple subtraction

Like? Yes | No

Prakash Singh 12 years ago

2 girls as tanvi is the 8th and out of 7, 5 girls are above vikas

Like? Yes (1) | No

sujitha 12 years ago

Two men together start a journey in the same direction. They Travel 9km/hr and 15km/hr respectively. After travelling for 6 hours the man travelling at 9km/hr doubles his speed and both of them finish the distance in the same time. How many hours will they take to reach their destination?

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vasanthapriyan 12 years ago

18 hours will they take to reach their destination

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chiatanya 12 years ago

18 hrs is the answer

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Shobhit Varshney 12 years ago

19 hrs
equation will be 9*6+18*x=15(6+x)
from here we wil get x and total time will be x+6

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Shobhit Varshney 12 years ago

18hrs
equation will be 9*6+18*x=15(6+x)
from here we wil get x and total time will be x+6

Like? Yes (1) | No

priya bajaj 12 years ago

18 hours they will take..

Like? Yes | No

Sandeep R 12 years ago

Solve it mentally:

distance traveled by both in 6hrs is 54km and 90 km respectively.
so gap after 6 hrs is 36km.
new speed = 18 km/h and 15 km/h which means the person who started with 9km/hr will close the gap by 3km per hour. so he will take another 12 hours to close the gap of 36km.

hence total time taken = 6+12=18 hours.

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sujitha 12 years ago

At what time between 9 and 10 will the hands of a watch be together?

Reply Like? Yes | No

manikanta 12 years ago

49 1/11 min past 9

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vasanthapriyan 12 years ago

49 1/11 mins past 9

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Manju 12 years ago

0=(11/2)m-(30*9)
m=49 1/11
so ans is 49 1/11 mins past 9

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kwatra 12 years ago

12h>>>>360 degree
12+x/60>>>>360/12*(12+x/60)

60min>>>360 x min>>>360/60*x
subtract 1 and 2 to get angle equals 0..

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kwatra 12 years ago

so ans 49 1/11.

Like? Yes | No

sagar 12 years ago

Angle=30h-11/2m put angle=0 h=9 gives m=49.09 it means at 9.49 apx

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sujitha 12 years ago

A train covers a distance between stations A and B in 45 Minutes. If the speed is reduced by 5km/hour. It will cover the same distance in 48 Minutes, What is the distance between station A & B in

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vasanthapriyan 12 years ago

distance between station A & B is 60 kms

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Shobhit Varshney 12 years ago

80kms is the answer

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Manju 12 years ago

let d speed of d train be xkm/hr
and distance be dkm
(45/60)x = d
(48/60)(x-5) = d
by solving we get, x = 80km/hr and d= 60km
hence distance b/w A & B station is 60km.

Like? Yes (1) | No

Shubham Anand 12 years ago

answer is
60 kmph

Like? Yes (1) | No

sujitha 12 years ago

A Train running at 40 kms/hr passes a person riding parallel to the railway line in the same direction at 25 kms/hr in 48 seconds. Find the length of the train

Reply Like? Yes | No

aman kumar jaiswal 12 years ago

15km.
relative speed=(40-25)=15,so length=15*(48/3600)=1/5=.2km

Like? Yes (3) | No (1)

Anuradha 12 years ago

relative velocity
(40-25)km/hr=15km/hr
15*1000/3600=25/6 m/s
distance=25*48/6
d=200m

Like? Yes (1) | No

Kripendra Ahirwar 12 years ago

200m.....15km*5/18*48=200m length of train

Like? Yes (1) | No

Shobhit Varshney 12 years ago

200 mtrs is the length of the train

Like? Yes | No

vasanthapriyan 12 years ago

length of the train is 200m

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sujitha 12 years ago

the average set of numbers is 46, if 4 numbers whose average is 52 are subtracted from this set , the average becomes 44.5...find the original number of numbers in the set ?..

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sujitha 12 years ago

i gt d ans its 20 ..

Like? Yes (4) | No

udhayaqm 12 years ago

how? can u explain tat?

Like? Yes (1) | No

Md Shahnawaz Shahab 12 years ago

let the number of no.s be x
therefore, 46x-52*4=44.5(x-4)
1.5x = 208-178
x = 20

Like? Yes (1) | No

Anuradha 12 years ago

plz explain it....

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vasanthapriyan 12 years ago

let the original number of numbers in the set be x,
x*46 = 46x
4*52 = 208
46x-208 = 44.5(x-4)
=>x=20

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priya bajaj 12 years ago

original number of numbers is 20...

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sujitha 12 years ago

raja and rakesh started a bussiness and invested rs 20,000 and rs 25,000 respectively.after 4 months rakesh left and mukesh joined by investing rs 15,000. at the end of the year there was a profit of rs 4600.what is the share of mukesh?

Reply Like? Yes | No

balaraju 12 years ago

At the end of year their shares are in the ratio of 12:5:6. Then mukesh share is 4600*(6/23)=1200.

Like? Yes (1) | No (1)

sujitha 12 years ago

can u give me clear nd brief explaination ?

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sujitha 12 years ago

s i understood thank u

Like? Yes (1) | No

udhayaqm 12 years ago

can u give some brief expl?

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udhayaqm 12 years ago

can u explain briefly?

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saradapolnati 12 years ago

raja:rakesh:mukesh
for 1st 4 months=4:5:0
next 8 months=4:0:3
final share=48:20:24
=>12:5:6
share of mukesh=(6/23)*4600=1200

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monikashri 12 years ago

final share 4:15:6
4x+15x+6x=4600
x=184
mukesh's share =6*184 = 1104

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sujitha 12 years ago

16 men can complete a work in 24 days , while 48 children can do it in 16 days.12 men started the work , aftr 14 dats 12 children joined the.in how many days will all of them do the remaining work ?16 men can complete a work in 24 days , while 48 children can do it in 16 days.12 men started the work , aftr 14 dats 12 children joined the.in how many days will all of them do the remaining work ? pls som 1 solve dis

Reply Like? Yes (1) | No

Nirmalaw 12 years ago

ans : 12
M1*D1=M2*D2=> 1 man=2 children then we have to find total work.
16M*24=16*2*24=768
12 men started work so 12m*14=12*2*14=336

768-336=432
then 12M+12C=12*2c+12C=36
remaing work/36
=432/36
=12

Like? Yes (1) | No (1)

Radhey 12 years ago

2
M1*D1=M2*D2=> 1 man=2 children then we have to find total work.
16M*24=16*2*24=768
12 men started work so 12m*14=12*2*14=336

768-336=432
then 12M+12C=12*2c+12C=36
remaing work/36
=432/36
=12

Like? Yes (1) | No

chaitu chowdary 12 years ago

assume 1man completes 1 unit of work....therfore 16man in 24days completes =16*24=384units...
48 children do the same work in 16days...
if x unit is d wrk done by one child then total work done is 48*x*16=384
x=0.5 units
12 men started d work n performs 14 days so work completed=12*14=168units
work left=384-168=216units
12children joins dem work done by them in one day is 12*0.5=6 units
total work done by 12 men and 12 children in one day is 12+6=18 units
therfore days needed=216/18=12days

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