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muhammad razique to m.sharmila 11 years ago

have any body here which sent me cognizant latest paper pattern for fresher @@
raziqansari480@gmail.com

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muhammad razique to m.sharmila 11 years ago

can any body gives my syntel latest paper pattern for fresher @@ raziqansari480@gmail.com

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muhammad razique 12 years ago

What least number must be added to 1056, so that the sum is completely divisible by 23 ?

A.2 B.3
C.18 D.21

Reply Like? Yes | No

Manohar Kumar 12 years ago

ans will be 2..........

Like? Yes | No

sai sindhu 12 years ago

1056+2=1058 which is exactly divisible by 23

Like? Yes (1) | No

Sruthi karuturi 12 years ago

1056/23 leaves a remainder of 2 so,2 has to be added

Like? Yes (1) | No

Parveen Soni 12 years ago

2 should be added since remainder is 2 So on adding 2 to 1056 it will become 1058 which is completely divisible by 23

Like? Yes (2) | No

pritam kundu 12 years ago

take the remainder... 1056%23... and the ans will be 23-(1056%23)

Like? Yes | No

RenukaMurugan 12 years ago

1056+2=1058 and 1058/23=46

Like? Yes | No

muhammad razique 12 years ago

the sum of ages of a son and father is 56yrs.after fours ,the age of the father will be three times of that sons thier age recpectively are:
A. 12 yrs,44yrs
B. 16 yrs,40yrs
C. 16 yrs,48yrs
D. 18 yrs,42yrs ASKED IN TCS..

Reply Like? Yes (3) | No

Nandaja Singh 12 years ago

A. 12YRS,44YRS
x+y=56
x+4=3(y+4)
solve dese

Like? Yes (1) | No

vijay davidbilla 12 years ago

solution:ans:option A
s+f=56
f+4=3(s+4)
f+4=3s+12
f=3s+8

s+3s+8=56
4s=48

s=12
f=44

Like? Yes | No

muhammad razique 12 years ago

X+4=3(56-X+4)
X+4=168-3X+12
4X=168+12-4=176 THEN X = 176/4=44YRS THEN 56-44=12YS A.12yrs,44yrs

Like? Yes | No

satypal varma 12 years ago

x+y=56
x+4=3(y+4)
x-3y=8
x=44,y=12

Like? Yes (1) | No

Arpit Varshney 12 years ago

x+y=44,y-3x=8
after solving x=12 and y=44

Like? Yes (1) | No

Ashwini Patil 12 years ago

qption a.12 yrs,44yrs is the ans

Like? Yes | No

parminder maan 12 years ago

let sons age=x
then fathers age=56-x
den after 4 yrs=3(x+4)=56-x+4)
solving w get x=11
dat z sons age n fathrs age=56-11=44

Like? Yes (2) | No

Arjun 12 years ago

You can assume through the option that if you add 4 in both 12 and 44 than we get 16 and 48 which satisfied the condition

Like? Yes | No

Rupinder Baidwan 12 years ago

option a 12 n 44

Like? Yes (1) | No

Ananthi 12 years ago

ans :a) 12 yrs, 44 yrs
father's age=x
son's age=y
x+y=56 ->equation 1
after 4 years (x+4)=3(y+4) ->equation 2
from equation 1 we will get y=56-x
substitute y value in equation 2
x+4=3((56-x)+4)
x+4=168-3x+12
x+3x=180-4
4x=176
x=176/4
x=44 -> Father's age
then substitute y value to equation 1
44+y=56
so we get y=56-44
son's age y=12

Like? Yes (2) | No

sindhura kantipudi 12 years ago

it is 12yrs n 44yrs

Like? Yes | No

RenukaMurugan 12 years ago

after 4 years the sons age is 16 and fathers age is 48

Like? Yes | No

muhammad razique to Deepthi Vasupalli 12 years ago

The wages of 10 workers for a six day week is Rs.1200.what are one day
's wages of 4 workers?
A. RS.40
B. RS.32
C. RS.80
D. RS.24 ASKED IN TCS

Reply Like? Yes (7) | No

Ankeeta Sinha 12 years ago

80
since 10 workers wages for 6 days is 1200
therefore, 10 workers wages for 1 day is 1200/6=200
then, 1 worker wage for 1 day is 200/10 = 20
then 4 workers wages for 1 day is 20*4=80(ans)

Like? Yes (4) | No

SAMBASIVAN 12 years ago

Ans. c) six days wages for 10 people 1200. One day wage for 10 workers 200. Wage for one Rs.20 and for four 20*4 = 80

Like? Yes (2) | No

kamal behl 12 years ago

10 workers for 6 days=1200
1 worker for 6 days=1200/10=120
1 worker for 1 day=120/60=20
so 20*4=80ans

Like? Yes (3) | No (1)

xyz 12 years ago

ans is 80
10 workers wag for 6 day=1200
1 workers wag for 1 day=1200/(6*10)=20
4 workers wag for 1 day=20*4=80

Like? Yes (1) | No

anjali 12 years ago

80since 10 workers wages for 6 days is 1200
therefore, 10 workers wages for 1 day is 1200/6=200
then, 1 worker wage for 1 day is 200/10 = 20
then 4 workers wages for 1 day is 20*4=80(ans)

Like? Yes (1) | No

muhammad razique 12 years ago

4 10
1 6 : 1200::x then 4*1*1200=10*6*x=80

Like? Yes | No

NARAYANA SWAMY DAMMALA 12 years ago

80
each worker get 20 per day...so 20*4=80

Like? Yes | No

sriram kumar mannava 12 years ago

10w -> 16d -> 1200

10w -> 1d -> 1200/6=200

1w -> 1d -> 200/10 = 20

Now 4w -> 1d -> 20*4 =80

Like? Yes (1) | No

Ashwini Patil 12 years ago

80 becoz 1worker wages is 20 so 4*20=80

Like? Yes | No

pala suphala 12 years ago

80
10*6=60
1200/60=20
20*4=80

Like? Yes (2) | No

Ananthi 12 years ago

Ans: C) 80
10 worker's work in 6 day will give salry times = 10*6=60
then 1 day salary = total 10 worker's 6 day salary/60
=1200/60=20
then 4 worker's salary = 20*4=80

Like? Yes | No

muhammad razique 12 years ago

A Watch,which gains uniformaly ,is 2 mint slow at noon on monday,and is 4 mints,48 sec fast at 2pm on the following monday ,At what time it was correct?

Reply Like? Yes (2) | No

Gowtham 12 years ago

Wednesday 8.27p.m

Like? Yes | No (1)

Reshmi Kar 12 years ago

Could u plz explain this ans?

Like? Yes | No

Anchal 12 years ago

Wednesday 2:00 p.m.

Like? Yes (1) | No

muhammad razique 12 years ago

time from monday noon(12pm ) to 2 pm the following mondays= 7 days 2 hrs =170hrs
now watch gains (2+4*4/5)mints from monday( 12 pm to 2pm) on the follwong monday then or in othr wrds watch gains 34/5 mnts in 170 hrs there fre it will gains 2 mints(170*5*12/34)hrs =50hrs means 2 days 2 hrs....then 2 pm on wednesday

Like? Yes (3) | No

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