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akhila 9 years ago

The net selling price of a dozen pens is Rs.256.50. If successive discounts of 10% and 5% were allowed, Find the marked price.

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Narendra Dhaker 9 years ago

Method 1:
Net price of pen is 256.50
after adding a discount of 10% new cost will be : 256.50 - 10% of 256.50
=> 230.85
Again adding an 5 % discount Final rate : 230.85 -5% of 230.85
=> 219.307

OR
Method 2:
if a object have successive discount of 10% and 5% then
lets assume its value is 100
and after these 2 discount value will be : 100- 10% of 100 = 90 and 90- (5% of 90 )=> 85.5
Than
100 rs value after 2 successive discount is : 85.5
1 rs .................................................................:85.5/100
256.5 rs .................................................................: 85.5/100*256.5= 219.3075

Choose your method :P

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Mallikarjuna Reddy 9 years ago

((95/100)*(90/100))*m=256.50
=>m=(256.50*10000)/(95*90)=>300
so marked price is 300

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vijay 9 years ago

Out of 17 applicants 8 boys and 9 girls. Two persons are to be selected for the job. Find the probability that at least one of the selected persons will be a girl.
ans

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NEHA BHARTI 9 years ago

no.of ways of selecting two persons out of 17 applicant; n(S)= 17C2 *2! = (17*16)/2 *2=272
At least one girl means 1 or more girl and they can be selected in two possible ways i.e.
(1 girl + 1 boy) or (2 girls)
no. of ways of selecting at least one girl ;n(E) = (9C1*8C1) +(9C1*8C1) = 9*8 +9*8 = 144
P(E)=n(E)/n(s) =144/272 =0.53

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MADHUBABU 9 years ago

The events of selection of two person is redefined as (i) first is a girl AND second is a boy OR (ii) first is boy AND second is a girl OR (iii) first is a girl and second is a girl.

So the required probability:
(9/17 * 8/16) +(8/17 * 9/16) + (9/17 * 8/16)
= (9/34)+(9/34)+(9/34)
=27/34

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Mallikarjuna Reddy 9 years ago

n(s)=17C2
n(e)=17C2-8C2
i.e., if we subtract selection of two boys from all possibilities remaining possibilities shall have atleast
one girl included

probability=(17C2-8C2)/17C2

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vijay 9 years ago

ans is 0.74 or 27/34

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vijay 9 years ago

A person starting with 64 rupees and making 6 bets, wins three times and loses three times, the wins and loses occurring in random order. The chance for a win is equal to the chance for a loss. If each wager is for half the money remaining at the time of the bet, then the final result is
ans . ?

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MADHUBABU 9 years ago

As the win leads to multiplying the amount by 1.5 and loss leads to multiplying the amount by 0.5, we will multiply initial amount by 1.5 thrice and by 0.5 thrice (in any order).

The overall resultant will remain same.
So final amount with the person will be (in all cases):
=64(1.5)(1.5)(1.5)(0.5)(0.5)(0.5)= Rs 27
Hence the final result is:
64−27=37: A loss of Rs 37

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zeeshan 9 years ago

1. The appropriate atmospheric conditions made it feasible for the astronomers to see the stars and they could even distinguish the sizes. Select the correct alternative for Bolded Words
a. And even distinguish the sizes
b. And they were even distinguishing the sizes
c. And he could even distinguishing the sizes
d. And even distinguishing the sizes

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swati krishna 9 years ago

we hav got alot of question here bt no correct answer .plz send me the answer of these question of amcat

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kavya rastogi 9 years ago

please tell me if any 1 know about the syllabubs of radisys aptitude and send the me placement papers also on this mail id
kavyarastogibca@gmail.com

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M.Parvathi to Sruthi karuturi 9 years ago

Probability of one of the power plants over heating is 0.15 per day and the probability of failure of the backup cooling system is 0.11. if these events are independent, what is the probability of ‘big trouble’ (i.e., both evnets taking place)?

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Narendra Dhaker 9 years ago

Answer is : 0.0165
Probability of power plant over heating is : 0.15.
Probability of failure of backup cooling system is : 0.11.

Probability of Big Problem is : Backup cooling system fails as well as power plant over heating
: (0.15) *(0.11)
: 0.0165

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shelly jain 9 years ago

A permutation is often represented by the cycles it has. For example, if we permute the numbers in the natural order to 2 3 1 5 4, this is represented as (1 3 2) (5 4). In this the (132) says that the first number has gone to the position 3, the third number has gone to the position 2, and the second number has gone to position 1, and (5 4) means that the fifth number has gone to position 4 and the fourth number has gone to position 5. The numbers with brackets are to be read cyclically. If a number has not changed position, it is kept as a single cycle. Thus 5 2 1 3 4 is represented as (1345)(2). We may apply permutations on itself If we apply the permutation (132)(54) once, we get 2 3 1 5 4. If we apply it again, we get 3 1 2 4 5 , or (1 2 3)(4) (5) If we consider the permutation of 7 numbers (1457)(263), what is its order (how many
times must it be applied before the numbers appear in their original order)?

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Narendra Dhaker 9 years ago

shelly your question is not clear .
please make it clear so that it could be understandable

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Krishnpriya Sinha 9 years ago

A box contains 20 balls. In how many ways can 8 balls be selected if each ball can be repeated any number of times?

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ramana kottapalli 9 years ago

answer is 20c8 * 8!

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girija anbu 9 years ago

send me recent AMCAT placement question papers to my mail id girijaanbu14@gmail.com

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saran 9 years ago

8,8,6,2,_ what is next number

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ABHIRUCHI SHARMA 9 years ago

Pipe A can fill a tank in 4 hours.There is a hole at the bottom due to which it takes double time to fill the tank.After filling the tank full,the Pipe A is closed.How long does it take to empty the tank by itself due to leakage?

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Mallikarjuna Reddy 9 years ago

let x hrs be the time taken to empty the tank

from given data we can write

(1/4)-(1/x)=(1/8)
=>1/x=1/8

so it takes 8hrs

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kriti kankariya 9 years ago

(1/4)-(1/x)=(1/8)
=>1/x=1/8
=>x=8hrs to empty the tank

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ABHIRUCHI SHARMA 9 years ago

The answer for this question is :2hr 40 min

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chandan kumar mania 9 years ago

When the numerator of a fraction is decreased by 20% and its denominator is decreased by 50%, the new fraction obtained is 4/3 . Find the original fraction?
A) 4/7 B) 5/7 C) 5/6 D) 6/7 E) None of these

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Deepanshu Gupta 9 years ago

its option c.. 5/6

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Narendra Dhaker 9 years ago

its C) 5/6

take X/Y as original fraction

new fraction will be 0.8* X/0.5*Y
which is equal to 4/3
on solving this we will get
ans 5/6

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AntoHelen 9 years ago

the salary received by officer A is 5% more than that received by officer B but 12 1/2 % less than that received by officer C. if the officer C received x% more than what is received by officer B, then the value of x will be

Reply Like? Yes (17) | No (2)

Deepanshu Gupta 9 years ago

the value of x will be 20

Like? Yes (5) | No (1)

AntoHelen 9 years ago

Will you plz..explain, how the x= 20

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Mythri 9 years ago

A car travels a certain distance taking 7 hrs in forward journey,during return journey increase speed 12km/hr takes time 5hrs.what is distance travelled

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Deepanshu Gupta 9 years ago

distance travelled is 210 km

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pawan kumar to suman kumari 9 years ago

Visit here daily, make a habit of it.

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AntoHelen 9 years ago

A house wife spends of an article is 80% of the price at which it is marked for sale . How much % does the tradesman gain after allowing a discount of 12%

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AntoHelen 9 years ago

If the ratio of the cost price and the selling price is 5:6, the gain percent is

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Devendra Marghade 9 years ago

20

If Cost Price=5x & Selling Price=6x, then Gain%=100*(6x-5x)/5x=20

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saragadam indira to MAKKE MANEESHA 9 years ago

hi maneesha wt r u doing?

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Vulchi.navya 9 years ago

A,B,C are three friends the average age of any two of them exceeds one third the age of third by 10 years.find the age of A.

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aditya to premlata 9 years ago

hiiiiiiiiii how r u

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premlata 9 years ago

hiii ... i am gud

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A.karthigeyini 9 years ago

and it raises the questions of weather a pieceful ___________of diputes between the ttwo is possible,despite intensive_________ by the us
a) outcome,compelling b)resolution,cajoling c) result,filtering d)answer,persuasion
i need answer for this

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Deeksha 9 years ago

There is a set of 32 distinct points on a plane with the following characteristic:
There is a subset A consisting of ten collinear points.
Any subset of three or more collinears point from 32 are a sub set of A.
how many distinct triangles with positive area can be formed with each of its vertices being one of the 32 points?(Two triangles are said to be distinct if at least one of the vertices is differently)
a) 4190 b)3850 c)4840 d)1540

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karun chaudhary to kriti kankariya 9 years ago

hi lets be frnd on fb if u r intersted

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kriti kankariya 9 years ago

ya sure.........

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AntoHelen 9 years ago

5+3+2=151012
9+2+4=183662
8+6+3=482466
5+4+5=202504
7+2+5=?

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Sindhu G 9 years ago

ans:143542 (7*2,7*5,rev((7+5)*2))

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kamlesh 9 years ago

it is a best question ever

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Yashi Das 9 years ago

7x2=14
7x5=35
7+5=12, 12x2=24 reverse it 42
Añs is 143542.

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Deepanshu Gupta 9 years ago

answer will be 143542

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Devake Rukmaji Annarao 9 years ago

How to solve probability question?

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amrita.ece09@yahoo.in 9 years ago

Y=x/(x-y), where k is a constant and x s a real number...
1.y increases with x.
2.y first increases then decreases with x.
3.y decreases and then increases with x.
4.y remains constant.

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amrita.ece09@yahoo.in 9 years ago

amrita.ece09@yahoo.in ( Few seconds ago) "Other"
image: http://www.m4maths.com/discussion-board.php

Y=x/(x-y), where k is a constant and xX s a real number...
1.y increases with x.
2.y first increases then decreases with x.
3.y decreases and then increases with x.
4.y remains constant.

Reply Like? Yes | No

amrita.ece09@yahoo.in 9 years ago

Y=x/(x-y), where k is a constant and xX s a real number...
1.y increases with xX.
2.y first increases then decreases with xX.
3.y decreases and then increases with xX.
4.y remains constant.

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Venkatesh to MOUNIKA P 9 years ago

FRIENDS ............

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Mallikarjuna Reddy 9 years ago

how many different ways th word MINIMUM can be arranged so that M,s neve rcome together

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MADHUBABU 9 years ago

I think (7!)/(3!*2!) = 420 ways

Like? Yes | No (1)

Narendra Dhaker 9 years ago

there will be 2 combination such as :
place M at Even position OR place M at odd postion
=> 4C3 *4!/2! + 3C3 * 4!/2!
=>48+ 12
=> 60

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sumit kumar 9 years ago

a man can dig a pit in 20 days if a man works half as much as a boy,then 4 men and 9 boys dig a similar pit in
a.10 days
b.12 days
c.15 days
d.16 days
Answer with explanation

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kriti kankariya 9 years ago

options are wrong as 1 man can dig in 20 days then 4 men can do it in 5 days and 4men & 9 boys together will require even lesser time

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Laxman 9 years ago

16 days if 8 man...

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Devendra Marghade 9 years ago

10/11 days

A boy with twice the efficiency can dig a pit in 20/2=10 days,
4 men and 9 boys 1 day work=(4/20)+(9/10)=22/20
So days require to dig similar pit=20/22=10/11

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RITESH DIXIT 9 years ago

from where the test will start

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chandan kumar mania 9 years ago

One fifth of a number is equal to 5/8 of other number. If 35 is added to first number, it becomes four times of the second number. The second number is
A) 25 B) 40 C) 70 D) 125

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kriti kankariya 9 years ago

its b 40
1/5 *x =5/8 *y
x+35 = 4y
solving y=40

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Narendra Dhaker 9 years ago

Ans is (B) 40
by 1st relation x*(1/5) = y* (5/8)
and
by 2nd relation x+35 = 4*y
solve them by puting value of x from 1st equation to 2nd.
Y will be 40

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ramana kottapalli to Aashu 9 years ago

hi bro first of all congratulate to be a part of this event

Reply Like? Yes (1) | No

swagat 9 years ago

Sixteen men can complete a work in twelve days. Twenty-four children can complete the same work in eighteen days. Twelve men and eight children started working and after eight days three more children joined them. How many days will they now take to complete the remaining work ?

A) a. 2days
B) b. 4days
C) c. 6days
D) d. 8 day

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Shruti Singhwal 9 years ago

Two numbers are such that the square of one number is 224 less than 8 times the square of the other. If the numbers be in ratio of 3:4, their values are?

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Yashi Das 9 years ago

(x^2+224)=8(y^2)
3x=4y
x=4y/3
((4y/3)^2)+224)=8(y^2)
(16/9y^2)+224=8(y^2)
(16/9y^2)+224=72/9(y^2)
(56/9)y^2=224
56y^2=2016
y^2=36
y=6
3x=4y
3x=24
x=8

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Shruti Singhwal 9 years ago

thanks yashi.. :)

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MADHUBABU 9 years ago

lets numbers be 3x and 4x, then
16x^2 = (8*9x^2)-224
16x^2 = 72 x^2 - 224
56x^2 = 224
x^2 =4 => x=2
therfore two numbers are 6,8

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chandan kumar mania 9 years ago

Suppose a big circle radius " r= 14 m" is the diameter for the small circle. Find the area of small circle in square meters?
a) 124 b)134 c)224 d)154

Reply Like? Yes | No (1)

kriti kankariya 9 years ago

134
r of smaller circle = 14/2 = 7
ar. of smaller circle = pi*7*7
=134 sq. meters

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chandan kumar mania 9 years ago

Sorry kriti, right answer is
( 22/7 )*7*7 = 154

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MADHUBABU 9 years ago

small circle daimeter = 14 m
therfore area =(22*14*14)/(7*4) = 154

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Narendra Dhaker 9 years ago

ans is (D) 154
Radius of smaller circle = 14/2 = 7
so Area will be = (22/7)*7*7
=154 sq. meters

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Akshat Mokashi 9 years ago

equilateral triangle and regular hexagon has same perimeter. find the ratio of their areas?

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MANISH 9 years ago

ratio of their areas will be 2:3

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kriti kankariya 9 years ago

2:3
hexagone consists of 6 equilateral triangles
so ratio of their ares = x^2 : 6 y^2
and we know,3x=6y ==> x=2y
putting it, ratio will come out to be 2:3

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Akshat Mokashi 9 years ago

In a circle the length of the chords are 6 and 8 respectively and the distance between them is 1 unit. What is the diameter of the circle?

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MANISH 9 years ago

diametre of circle=10 units

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Akshat Mokashi 9 years ago

@manish please provide explanation and if u know any shortcut tricks please do share

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MANISH 9 years ago

Akshat send your email id so that i can send snapshot of solution.

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Akshat Mokashi 9 years ago

my email id is mokashi.akshat17@gmail.com

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Akshat Mokashi 9 years ago

A can do piece of work in 10 days.B can do it in 15 days. C in 20 days. After 2 days A left and B left before 3 days of completion of the work. So the work is completed in how many days ?
asked in tcs

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MANISH 9 years ago

let work is completed in d days.
b work for (d-3) days
c work for d days.
so,work done by a in 2 day+work done by b in (d-3) day+work done by c in d day=1.
calculating d we get d=60/7 day

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Akshat Mokashi 9 years ago

100 students appeared for test. 60 passed in first ,40 in second and 30 in both. What is the probability that a student selected at random is failed in both.

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kriti kankariya 9 years ago

prob of selecting student failed in both = 3/10 = .3

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Bandaru Krishna Chaitanya 9 years ago

Rs. 49 were divided among 150 children. Each girl got 50 paisa and a boy 25 paisa. How many boys were there?

OPTION 1) 100
2) 102
3) 104
4) 105
5) 106
6) 109
7) 110
8) 112
9) 114
10)None of these

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SANJIL GARG 9 years ago

3) 104 is the correct answer

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dee hack kr to Bushra 9 years ago

u want the correct answer,

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mohit 9 years ago

In a right angled triangle, two sides are consecutive whole number in which one side is hypotenuse. what could be the possible length of third side?

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rajesh dharamdasani 9 years ago

49/15--x = 0.25
=> x = 46
now No. of boys will 150-46 = 104

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SORNA KAMALAM S 9 years ago

Let the length of hypotenuse side be x
Hence, the length of second side =x-1
Let the length of third side be y
Using pythagaros theorem,
x^2=(x-1)^2+y^2
x^2=x^2-2x+1+y^2
0=-2x+1+y^2
y^2=2x-1
y=√(2x-1)
example:
x=5
x-1=4
y=√(2*5-1)= √(9)=3

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kriti kankariya 9 years ago

all the odd no.s can be the third side

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DIVYA MURUGESH 9 years ago

A container contains milk and water in the ratio 4:1 How much mixture should be taken out and replaced with water so that the container contains milk and water in the ratio of 3:2?

Explain pls

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SORNA KAMALAM S 9 years ago

Ans:25%

Let the initial mixture content be 100 litres
Ratio 4:1
4x+1x=100
5x=100
X=20
mixture Ratio Litres(100)
milk 4 80
water 1 20

Let R litre of the mixture be replaced with water
Now, let us first consider the mixture content
Ratio 4:1
4x+1x= (100-R)
5x= (100-R)
X= ((100-R)/5)

mixture Ratio Litres(100-R)
milk 4 4*((100-R)/5)
water 1 1*((100-R)/5)

Now, let us consider the new mixture content
(100-R)+R=100
where,
(100-R)-->Original solution
R-->Replaced water

Given: ratio 3:2
3x+2x=100
5x=100
X=20

mixture Ratio Litres(100-R)+R=100
milk 3 60= 4*((100-R)/5)
water 2 40= 1*((100-R)/5)+R

60=4*((100-R)/5)
15= ((100-R)/5)
75=100-R
R=25

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