Users Discussion Board

SUPRIYA 9 years ago

8. A boat went down the river for a distance of 10 km. it then turned back and returned to its starting point . Having travelled a total of 3.5 hours. On its return at a distance of 6km from the starting point it encountered a block of wood, which had passed the starting point at the moment at which the boat had started downstream. What was the downstream speed of the boat?

Reply Like? Yes (1) | No

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Ayantika Rakshit 9 years ago

If Pn denotes the product of the binomial coefficients in the expansions of (1 + x)n, the Pn+1/Pn=?
a)n+!/n! b)n^n/n! c)(n+1)^n+1/n! d)(n+1)^n+1/(n+1)!

Reply Like? Yes (19) | No (7)

Onlinepsa.in 9 years ago

You can take n=2 and observe that P2 =1*1*2=2.
Also P3 = 1*1*3*3=9
P3/P2= 9/2

Using the value of n and n+1 in every option, (d) seems to be correct!

Thanks,
onlinepsa.in

Like? Yes (3) | No (10)

rajveer singh 7 years ago

alert("asdasd");

Like? Yes | No

Syed asbah 7 years ago

Answer is.......503156

Like? Yes (1) | No

kishor 9 years ago

what is the largest number that divides all three numbers 23400,272304,205248 without leaving a remainder?
a. 48 b. 24 c. 96 d.72

Reply Like? Yes | No

Onlinepsa.in 9 years ago

Kishore, check if the first number 23400 is correct or not!
In any case, if a,b,c are three such numbers than you can find out the HCF of (b-a), (c-a) and (c-b) to find out which number it is!

Thanks,
onlinepsa.in

Like? Yes | No

ashish kumar sahoo 9 years ago

(#M40153095) CAPGEMINI QUESTION KEEP AN EYE
IMAGE: HTTP://WWW.M4MATHS.COM/IMAGES/EYE_CLOSE.PNG

Keep an eye puzzle
Mr. Sohan works for Azania Company. The company grants 1000
shares to Mr. Sohan in 2008. At that point each share is worth Rs. 100. In
2010, he decides to sell his entire stake and at that point, the value is Rs.
120 per share. The government declares that the tax to be paid is 10% of
the entire profit. Due to the inflation, the value of a rupee in 2010 is
equivalent to 0.8 of a rupee in 2008. In this situation, which of the following
model indicates the actual tax to be paid by the investor?
A. 120 Rs at 2008 value " 100 Rs at 2010 value * (1 Re at 2008 value / 0.9
Re at 2010 value)

Read more at http://www.m4maths.com/placement-puzzles.php?SOURCE=capgemini#y7lTJJMuqmRvJKsR.99

Reply Like? Yes | No

priyanka 9 years ago

Length, Breadth and Height of a 3D figure is in the ratio 3:2:1. If the length is doubled and Breadth & Height are halved, then what is the % decrease in the volume of the solid?

Reply Like? Yes (31) | No (3)

Devendra Marghade 9 years ago

50% decrease

If original length, breadth & height are 3x, 2x and x respectively, then volume=3x*2x*x=6x^3
With length doubled, breadth & height halved, new dimensions are 6x, x and x/2 respectively and volume=6x*x*x/2=3x^3
So % decrease in volume=100*(6x^3-3x^3)/6x^3=50

Like? Yes (16) | No (4)

Deepak kumar 9 years ago

old volume=3*2*1=6
new volume=6*2*1=12
Change in volume=12-6=6
New volume is 100% more than old volume
so, old volume is ( (100*100)/(100+100)) % =50% less than new volume

Like? Yes (8) | No (3)

kadimetla parusaramudu 9 years ago

assume elements length,breadth ,height are 300,200,100 then volume is 300*100*200=6000000
new elements are 600,100,50 then volume is 600*100*50=300000
so volume is decreased by 50%

Like? Yes (6) | No (2)

Revanth 9 years ago

3*2*1=6
after modifications 6*2*0.5=3
3/6%=50%

Like? Yes (5) | No (4)

AVIDHANSHU VAIDYA 9 years ago

decrease 50% ................................................................

Like? Yes (3) | No (1)

Prabhakar Panda 9 years ago

volume decreased by 50%

Like? Yes (5) | No

oshin jain 9 years ago

volume decrease by 50%

Like? Yes (3) | No

prem naik 9 years ago

by comparing volumes,we get new volume is exactly half (50%)than first

Like? Yes (1) | No (2)

bavya 8 years ago

100*(old volume-new volume)/old volume=% decrease in vol

Like? Yes (4) | No

sharmistha 8 years ago

50℅ reduction in volume

Like? Yes | No

Deepak Kolte 9 years ago

What is the number of ways of expressing 3600 as a product of three ordered positive integers (abc, bca etc. are counted as distinct). For example, the number 12 can be expressed as a product of three ordered positive integers in 18 different ways.
a. 441

b. 540
c. 84

d. 2100

Reply Like? Yes (33) | No (1)

RATNADIP MONDAL 9 years ago

since 12 cn b represented in 18 ways..then 3600 cn b represented in 3p3+3p3+..............=2100

Like? Yes (4) | No (9)

kriti kankariya 9 years ago

plz explain 12 in 18 ways

Like? Yes (4) | No (2)

arunkumar 9 years ago

12 is expressed in 15 ways as in 12*1*1 only 3 ways are obtained: 12*1*1,1*12*1,1*1*12=3 ways,
3*4*1 for 3! ways and 6*2*1 for 3! ways. total=3!+3!+3=15 ways
not 18 ways. is repetitionis allowed are not.

Like? Yes (2) | No (2)

jyotshna bhardwaj 9 years ago

Ans should be (b) 540

Like? Yes (5) | No (2)

Shanmuga priya 8 years ago

could u plzz explain 12 in 18 ways

Like? Yes | No (2)

Kunal sisodia 8 years ago

12 in 18 ways

see we can have three cases as 12 have factors 3x4,2x6,12x1...
so case 1 - (3,4,1) Six ways as repetition can be there..
eg - (3,4,1),(3,1,4),(1,3,4),(1,4,3),(4,1,3),(4,3,1) so total Six ways..
case 2 (2,6,1) Again 6 ways
case 3 (12,1,,) again 6 ways
finally = 6+6+6 = 18
i hope it helped....

Like? Yes (5) | No (2)

Kunal sisodia 8 years ago

@RATNADIP MONDAL can u explain in detail plz...

Like? Yes | No (1)

Kunal sisodia 8 years ago

3600 = 2^4 × 3^2 × 5^2

so let, for three ordered numbers abc
a * b * c = 2^4 × 3^2 × 5^2
OR
b * c * a = 2^4 × 3^2 × 5^2
OR
c * a * b = 2^4 × 3^2 × 5^2
OR .............

so we can see that we 3 options, i.e. a,b,c , for each numbers 2^4 , 3^2 , 5^2

now according to permutation and combination formula , to distribute n things among r the formula is
n + r - 1Cr - 1

to distribute 2^4 => Four 2s among 3 places => (4+3−1)C(3−1)=6C2 = 15 ways
to distribute 3^2 => two 3s among 3 places => (2+3−1)C(3−1)=4C2 = 6 ways
to distribute 5^2 => two 5s among 3 places => (2+3−1)C(3−1)=4C2 = 6 ways

Total ways = 15 × 6 × 6 = 540

Like? Yes (13) | No (1)

Esthar 8 years ago

3600 = 2^4 * 3^2 * 5^2
n+r-1Cr-1
->6c2*4c2*4c2
->540

Like? Yes (1) | No

Harjeet Kaur to ABHINAV PUSHPAM 9 years ago

4,8,12,48,?
A.950
B.850
C.760
D.960

please provide the solution..

Reply Like? Yes (2) | No

king 9 years ago

the petrol price after two successive price hike of 20% and 30% is Rs 78 per litre what is the price of petrol before these hikes
a: Rs 56
b: Rs 50
c: Rs 42
d: Rs 64

Reply Like? Yes (5) | No

chitranshu shrivastava 9 years ago

consider x as an initial price...........then accordingly...........x*(120/100)*(130/100)=78 on solving for x we will get the answer 50 that means option "b" is correct.

Like? Yes (3) | No

PIYUSH AGRAWAL 9 years ago

50 because by supposing from option and apply this
50+ 20% of 50 =60
60+ 30 %of 60= 78.

Like? Yes (2) | No (2)

king 9 years ago

A,b,c, are three consecutive odd numbers in ascending order such that the value of three times A is 3 less than two times c find the value of c

a: 7
b: 9
c: 11
d: 5

Reply Like? Yes (5) | No (3)

Chinkesh Kumar 9 years ago

let numbers x, x+2 , x+4 be three consecutive odd numbers.
3x=2(x+4)-3
x=5
so, c=5+4=9.

Like? Yes (5) | No (2)

Tridip Das 9 years ago

Nos are a,b=a+2,c=a+4
3a=2c-3=> 3a+3=2a+8=> a=5
So b=7,c=9

Like? Yes (1) | No (1)

DEEPAK KR. 9 years ago

Let 2n-1,2n+1,2n+3 are the consecutive odd numbers
3(2n-1)=2(2n+3)-3
2n=6
so, n=3
so C=2n+3 = 9

Like? Yes (2) | No

rekha 9 years ago

Find the sum of prime numbers from 1 to 100 which when divided by 4 and 5 leaves the remainder 1 and 4 respectively.

Reply Like? Yes (36) | No (7)

kalaiyarasi.v 9 years ago

prime numbers 2,3,5,7,........97
sum 2+3+5+7+..............+97=929
929/4=Rem(1) and 929/5=Rem(4)
Ans:929

Like? Yes (5) | No (16)

velmala gangadhar 9 years ago

the nos.should be 29,49,69,89..
in that 29 and 89 are prime no.rs
so sum is 118

Like? Yes (7) | No (2)

kadimetla parusaramudu 9 years ago

between 1 to100 prime numbers the required numbers are 29,69.
29+89=118

Like? Yes (3) | No (2)

rohit raj 9 years ago

118..?
no should be end by 9
because if some no will be divided by 5 and we add 4 in that it will end with 4 or 9. no which will end with cannot be prime
now all the which is multiple of 5 end with 8 and on adding 1 we get 9(b/w 1 to 100) are---
9,29,69,89
29 and 89 are prime so sum=118

Like? Yes (3) | No (2)

Siva 9 years ago

among all prime numbers between 1 to 100 there are only two numbers are available as per the requirement which is leaves reminders 1 and 4 when divided with 4 and 5 respectively, so the sum of two numbers is 29+89=118

Like? Yes (3) | No (2)

thamizmani 9 years ago

2 and 7
2+7=9
94=1
95=4

Like? Yes (2) | No (2)

sugayathri 9 years ago

29+89=118 [(29/4=1,29/5=4)+(29/5=4,89/5=4)]

Like? Yes (2) | No (1)

sugayathri 9 years ago

29+89=118 [(29/4=1,29/5=4)+(89/4=1,89/5=4)]

Like? Yes (2) | No (2)

brahmaiah 7 years ago

Find the sum of prime numbers from 1 to 100 which when divided by 4 and 5 leaves the remainder 1 and 4 respectively

Like? Yes (3) | No (1)

sai yasaswini 7 years ago

Answer is 245 not 929 or 118

Like? Yes (10) | No

bittubharti to yagnii 9 years ago

yagnii that was the question of c "sharmili want to""""""that program will work properly or not

Reply Like? Yes | No

Ramakrishna Siluveru 9 years ago

Apples cost L rupees per kilogram for the first 30 kilograms and Q rupees per kilogram for each additional kilogram. If the price paid for 33 kilograms of apples is Rs. 1167 and for 36 kilograms of apples is Rs. 1284, thenn the cost of the first 10 kgs of apples is:

Reply Like? Yes (22) | No (9)

Devendra Marghade 9 years ago

350 Rs.

30L+3Q=1167 ----(i)
30L+6Q=1284 ----(ii)
Solving (i) & (ii),Q=39, L=35
So cost of first 10 kg.=10*L=10*35=350

Like? Yes (16) | No (3)

rajat gupta 9 years ago

350 right answer

Like? Yes (3) | No (2)

Siva 9 years ago

350 is the correct answer

Like? Yes (2) | No (1)

sandesh chavan 9 years ago

cost of the first 10 kg=350

Like? Yes (1) | No

oshin jain 9 years ago

350 Rs. as each apple cost for Rs.. 35

Like? Yes (1) | No

Shreya 6 years ago

30L+3Q=1167
30L+6Q=1284
Solving above two equations we get
L=35 Q= 39
therefore 10 kg of apples will be 350

Like? Yes | No

duggisetty greeshma 6 years ago

By framing equations we get
30L+3Q=11.67
30L+6Q=12.48
Eliminate Q by multiplying the first equation by 2 and subtracting second equation from the first
Then we get L = 0.362
Cost of 10 kgs of apples = 0.362 x 10 = 3.62

Like? Yes (6) | No (1)

king 9 years ago

a trader purchases oranges at Rs 600 per hundred He spends 15% on storage . What should be the selling price per hundred to earn a profit of 20%

a: Rs 812
b: Rs 828
c: Rs 720
d: Rs 764

Reply Like? Yes (9) | No (2)

rajat gupta 9 years ago

828 is the right answer

Like? Yes (7) | No (1)

Devendra Marghade 9 years ago

b: Rs 828

Selling Price to earn 20% profit= (120/100)*(Cost Price+Storage cost)
=(120/100)*[600 + 600*(15/100)]
=828

Like? Yes (6) | No (2)

kadimetla parusaramudu 9 years ago

total cost is 600_+15%of 600=690.
to get a profit of 20% i.e ( 20% of 690)+690=690+138=828

Like? Yes (5) | No (1)

Siva 9 years ago

total cost price=600+90=690, selling price=690+(690*.02)=828

Like? Yes (3) | No

oshin jain 9 years ago

15*600/100=90
so cost price=600+90=690
now profit=120*690/100=828 is the ans

Like? Yes (2) | No (1)

vamshi krishna 9 years ago

828 is the right ans

Like? Yes (2) | No (1)

Pruthvi Soni 7 years ago

828 will be the right answer

Like? Yes (2) | No

Nishi Gangrade 6 years ago

828 will be the answer
CP=600
And 15% for storage it means overall CP=600+15% of 600
690
SP=120/100+×690
828 will be the answer

Like? Yes (1) | No

king 9 years ago

The feul indicator in a car shows 1/9 of the tank is full when 25 liters of petrol is added the indicator shows two third of the tank is full what is the capacity of fuel tank

a: 40 litres
b: 36 litres
c: 50 litres
d: 45 litres

Reply Like? Yes (1) | No (1)

rajat gupta 9 years ago

45 is the right answer

Like? Yes (1) | No

Devendra Marghade 9 years ago

d: 45 liters

If capacity of fuel tank=x liters, then (x/9) + 25= 2x/3, x=45

Like? Yes (1) | No

king 9 years ago

N individuals were testedfor two infection . If 1/3 rd of the tested had infection A and those with infection A,1/5 th also had infection B how many individual donot have the infection A and B

a: none of these
b: 4N/5
c: N/5
d: 14N/5

Reply Like? Yes (1) | No

king 9 years ago

A 200 meter train crosses another train travelling oppsite in direction 15 sec the length of the train is 300 meter and speed of both the trains are equal find the speed of the train

a: 50 kmph
b: 36 kmph
c: 64 kmph
d: 60 kmph

Reply Like? Yes (5) | No (2)

rakesh sharma 9 years ago

2V=500/15
V=50/3m/s
v=(50/3)x(18/5)=60

d.60

Like? Yes (6) | No (1)

Siva 9 years ago

Let the speed of the train be S
as the two trains having same speed 2 S=[(200+300)/15]=50/3 m/s=60 Kmph

Like? Yes (4) | No

Siva 9 years ago

60, s=[(200+300)/(2*15)]*(18/5)=60

Like? Yes (1) | No

simran shanti 9 years ago

200/s-300/s=15
100/s=15
s=15/100m/s
15/100*18/5kmph
=60kmph

Like? Yes (1) | No

simran shanti 9 years ago

2s=500/15*18/5
=120/2=60kmph

Like? Yes (1) | No

Sachin saurav 9 years ago

ans=opt(d) ; 500/1000=(2x)*(15/(60*60))=60 Kmph (considering the speed of both the train be x Kmph)

Like? Yes (1) | No

pudu pravalika 5 years ago

speed=distance/time
time=distance/speed
time=300+200/s1+s2(opposite)
s1+s2=120
s1+s1=120
s1=60 and s2=60

Like? Yes (1) | No

king 9 years ago

sri is as older than vimal as he is younger then karthi . If some of the age of vimal and karthi is 58 years then what is the age of sri

a: 25 years
b: 30 years
c: 45years
d: 29 years

Reply Like? Yes (4) | No

king 9 years ago

an iron ore of 80 tonnes yielded 40 tonnes of metal which had 12 % of impurity what is the % of impurity in ore

a: 10%
b: 6%
c: 20%
d: 16%

Reply Like? Yes (1) | No

Devendra Marghade 9 years ago

b: 6%

100*[40*12/100]/80=6

Like? Yes (1) | No (1)

king 9 years ago

In a class 48% students failed in maths 32% failed in chemistry 20% failed in both subjects if the number of students who passed the both was 840 how many students were there in the class

a: 1800
b: 2100
c: 2000
d: 2200

Reply Like? Yes (2) | No

neha gupta 9 years ago

Let x be the total number of students
Using Venn diagram we can find out that (28+20+12)% = 60% is the percentage of students who are failed in at least one subject so 40% are the students who passed in both subjects
so 40% of x = 840
on solving it we get , x = 2100

Like? Yes (1) | No (1)

rajat gupta 9 years ago

2100 i s the right ans

Like? Yes (1) | No

king 9 years ago

find out the minimum fracion when added to 11/16+12/20 will give a complete number

a: none of these
b: 57/80
c: 15/20
d: 23/20
Read more at http://www.m4maths.com/placement-puzzles.php?UID=377184#4iTDOwPXs2iElaOt.99

Reply Like? Yes (1) | No

neha gupta 9 years ago

minimum fraction to be added is 57/80

Like? Yes (1) | No

Devendra Marghade 9 years ago

b: 57/80

(11/16) + (12/20)=(55+48)/80=103/80
If numerator becomes 160 the fraction will give a complete number, so (160-103)/80=57/80 is a minimum fraction to be added.

Like? Yes (1) | No

rishav raj 9 years ago

If B occurs which must occur

(a) D
(b) D and G
(c) G and H
(d) F and G
(e) J

Reply Like? Yes | No

anubhav kumar 9 years ago

A and B can complete the work in 12 days .B and C can complete the same work in 20 days .If A B and C started to work together and after 4 days C left the work .Then the remaining work can be completed by A and B in how many days.

Reply Like? Yes (12) | No (3)

Shivani 9 years ago

a+b=1/12 ...(1)
b+c=1/20.....(2)
(1)+(2) => a+2b+c=4/30...(3)
(1)-(2)=> a-c=1/30...(4)
(3)+(4)=> c-b=1/60...(5)
(2)+(5)=> c=1/30..(6)
now a+b+c=7/60*4=7/15
remaining work=>1-7/15=8/15
now a and b do work in 8/15*12=6.4 then 6 days

Like? Yes (5) | No (9)

praveendas 9 years ago

the ans will be 7.6==7 and half day.
given that b will be common in both cases,so take the common factor which suits best for the given conditions.it will be 24 which b alone can do the work.then
1/a+1/24=1/12 -->1/a=1/24,so that a and b alone do the work in same no of days.
let find c: 1/24+1/c=1/20 -->1/c=1/120,which is c one day work,
:for 4 days the completed work is 1/a+1/b+1/c=4*(11/120).
remaining work left is 76/120,,which should be completed by a and b together,
(a and b) one day work 1-->1/12
in order to complete 76/120 no of days required is (76/120)*12=7.6

Like? Yes (3) | No (1)

kadimetla parusaramudu 9 years ago

A+2B+C=1/12+1/20=6/20--------->1
(1)-(a+C)=2B=5/20
B=1/8.
4(A+B+C)=4(1/20+1/12+1/8)=31/120
REMAINING WORK=1-31/120=89/120
DAYS REQUIRED TO COMPLETE THE WORK ARE =89/120*12=8.9DAYS

Like? Yes (2) | No

V manikandan 5 years ago

Accurately 6 days... read carefully..
let a+b=1/12 ...(1)
b+c=1/20 ...(2)
(1)-(2)--->a-c=1/10---(3)
as b+c=1/20
(1/2)(a-c)=(b+c)---*****(a correlation between the equations)..(4)
a=3c+2b---(5) applying the given equations with b as common variable
1/12-b=3(1/20-b)+2b
by solving we get b=1/120
by solving for a and b we get a=9/120 and c=5/120
then by the condition
4(a+b+c)+t(a+b)=1----(6)
applying a,b,c values in (6)
..we get answer as t=6
thus the remaining work will be completed by a and b by 6 days...just work out

Like? Yes (1) | No (1)

Shivani 9 years ago

A,B and started a new business. If difference bw investment of A and B is 2387 and difference bw investment of B and C is 4561 then what was total investment?

Reply Like? Yes (17) | No (1)

Shivani 9 years ago

if price of product is increased by 25% and no of product is decreased by 22 then what will be change in selling price??

Reply Like? Yes | No (1)

Devendra Marghade 9 years ago

2.5 % decrease

If original price=100 and number of product=100, then selling price=100*100=10000
With 25% increase new price=100*125/100=125, Number of product=100-22=78,then new selling price=125*78=9750
So % change in selling price=(10000-9750)/100=2.5

Like? Yes | No (1)

A 9 years ago

10a)
If log10 7 = a, then log10(1/70) is equal to:

Reply Like? Yes | No

umesh 9 years ago

within hw many days we wil get amcat result???????

Reply Like? Yes | No

kannya 9 years ago

Length, Breadth and Height of a 3D figure is in the ratio 3:2:1. If the length is doubled and Breadth & Height are halved, then what is the % decrease in the volume of the solid?
A) decreased by 50%
B) decreased by 15%
C) decreased by 18%
D) decreased by 30%

Reply Like? Yes | No

praveendas 9 years ago

it decreased by 50%.
given length,br,hght are in the ratio is 3x:2x:x.
volume =6x^3.
then after length is doubled breadth and height are halved:6x:x:0.5x
volume =3x^3
change in per=(3x^3/6x^3)*100=50%

Like? Yes (1) | No

Mithilesh kumar 9 years ago

There is a right angle Triangle inside a circle of diameter 18cm.Inside this triangle ,there is another circle of diameter 6 cm. Find the perimeter of the triangle.
OPTIONS:
A.)24cm B.)36*2^1/2cm C.)36cm D)54cm

Reply Like? Yes | No

neela 9 years ago

A sealed envelope contains a card with a single digit written on it. Three of the following statements are true and one is false.I. The digit is 1.II. The digit is not 2.III. The digit is not 9.IV. The digit is 8.Which one of the following must necessarily be correct?II is falseIII is trueIV is falseThe digit is even.I is true

Reply Like? Yes | No

Sunil sharma to arya 9 years ago

What you want to share with Arya?A sum of Rs. 12,000 deposited at compound interest becomes double after 5 years. After 20 years, it will become

Reply Like? Yes | No

Devendra Marghade 9 years ago

192000 Rs.

With compound interest=r, 12000[1+(r/100)]^5=24000, [1+(r/100)]^5=2
As [1+(r/100)]^20=[1+(r/100)]^5*4=2^4=16
So 12000[1+(r/100)]^20=12000*16=192000

Like? Yes | No

Sunil sharma to kriti kankariya 9 years ago

Please provide me shortcut method.

Reply Like? Yes (1) | No

Sunil sharma to kriti kankariya 9 years ago

A sum of Rs. 12,000 deposited at compound interest becomes double after 5 years. After 20 years, it will become?

Reply Like? Yes | No

kriti kankariya 9 years ago

p=12000
t=5
c.i. =2p
p(1+r/100)^t = 2p
(1+r/100)^5 = 2
for 20 yr,
p(1+r/100)^20 =p((1+r/100)^5)^4 = p* 2^4 = p*16 = 12000*16 = 192000

Like? Yes | No

karthick 9 years ago

In an examination 10 questions are to be answered choosing at least 4 from each of part A and part B. If there are 6 questions in part A and 7 in part B, in how many ways can 10 questions be answered ? Op 1: 212 Op 2: 266 Op 3: 272 Op 4: 312 Op 5: Correct Op

Reply Like? Yes | No

anandhi 9 years ago

Combination can be 4-6 or 5-5 or 6-4
therefore
(6C4*7C6)+(6C5*7C5)+(6C6*7C4)=105+126+35= 266..

Like? Yes (2) | No

DIPANKAR SAHA 9 years ago

If A & B work together, they will complete the job in 7.5 days. If A works alone and completes half the job and then B takes over and completes the remaining half alone, they will be able to complete the job in 20 days. How long B alone will take to do the job, if A is more efficient than B ?
(A) 20 days
(B) 30 days
(C) 40 days

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Sujan Chhetri 9 years ago

since A is more efficient than B therefore no.of days taken by B to complete the job alone will be 30 days

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Devendra Marghade 9 years ago

(B) 30 days

(1/A) + (1/B)= 1/7.5 or 2AB=15(A+B) ---(i)
Half of the work from A & B= (A/2) + (B/2)=20, A+B=40 ---(ii)
From (i) & (ii), AB=300 ---(iv)
Values matching for AB=300 & A+B=40, where A is more efficient than B, So A will be less than B
We have A=10, B=30

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DIPANKAR SAHA 9 years ago

Mr. Decimal enters a lucky draw that requires him to pick five different integers from 1 through 31 inclusive. He chooses his five numbers in such a way that the sum of their logarithms to base 10 is an integer. It turns out that the winning 5 numbers have the same property, i.e. the sum of their logarithms to base10 is also an integer. What is the probability that Mr. Decimal holds the winning numbers?
o 1/8
o 1/6
o 1
o 1/2
o 1/4

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DIPANKAR SAHA 9 years ago

You are given 87 matchsticks. They are arranged in rectangular manner.Find the number of triangles formed?

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DIPANKAR SAHA 9 years ago

6.A bag contains six sticks of the following lengths 1 cm, 3 cm, 7 cm, 11 cm and 13 cm. three sticks are drawn at random from the bag. What is the probability that we can form a triangle with those sticks? 1.11/20
2.1 3.1/4 4.2/5..asked in TCS

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DIPANKAR SAHA 9 years ago

In an year N, the 320th day of the year is Thursday. In the year N+1 the 206th day of the year is also Thursday. What is the 168th day of In the year N-1? 1.Friday 2.Thursday 3.Tuesday 4.Saturday

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DIPANKAR SAHA 9 years ago

In Loonyville, four people called Doctor, Engineer, Lawyer and Architect follow the professions of doctor, lawyer, engineer and architect. However, none of them follow the profession indicated by their name. Doctor plays bridge very regularly, as he thinks it as an intellectual card game. Doctor is allergic to sea food, and does not eat it at all. Architect nearly died in a car accident two years ago. The architect is very poor at card games and does not play them at all. The engineer loves fish and has it twice a week. The engineer is a good driver, and has never been involved in a car accident. Engineer does not like the Lawyer’s habit of constantly interrupting others.What is the
profession of Engineer? 1.a lawyer 2.an architect 3.a doctor 4.Cannot be determined.plz solve ia asap...

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Girish kumar to Aastha 9 years ago

Can u pls tell how tcs app test will be

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VUYYALA RAMANJANEYULU 9 years ago

80, 63, 72, 72, 64, 81, 56. Find the next number in the series?
could you please give me the conventional answer......

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shafi 9 years ago

80,63,72,72,64,81,56.
,divide into two fragments..then u will get the answer in this manner...
80,72,64,56,48
63,72,81,90....
After this make it into one series formation
80,63,72,72,64,81,56,90,48...thats it.

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meena kumari 9 years ago

Answer is 90
the complete series is divided into 2 series like
80,72,64,56
63,72,81,
the difference between the numbers in second series is 9
So the next number in the series must be 91+9=90

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VUYYALA RAMANJANEYULU 9 years ago

1) One man has hens and cows, total number of heads is 48 and total number of legs is 120. how many hens and how many cows he has?

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saragadam indira to kriti kankariya 9 years ago

hi kriti akka! this is indira from IIIT in kadapa

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kriti kankariya 9 years ago

hii..........................

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saragadam indira 9 years ago

hi...........what is your profession ?

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kriti kankariya 9 years ago

m pursuing engg.

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Neha Sharma 9 years ago

raghul can finish 1/5th of his work in 1hr,neha can finish his 3/7th of his work in 1hr 30 mins and riya can finish his 3/4th of his work in 3hr 30 mins. if all of them start their work at 12 pm and can go to play as soon as they all can finish their work . when can they start their play when they take a break at 3.30 pm for 30 mins.

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Abhishek Singh 9 years ago

Raghul takes break at 5:30 pm, Neha takes break at 3:30 pm only, Riya takes break at 5:10 pm

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vidhi 9 years ago

River is running at 2 kmph. It took a man twice as long to row up as to row down the river. The rate (in km/hr) of the man in still water is: Explanation chahy

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Sachi Rai 9 years ago

A is twice as good a workman as b and together they finish a piece of work in 18 days.
in how many days will A alone finish the work?

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neha gupta 9 years ago

Let A can finish a work in x days then B will finish it in 2x days
Thus 1/x + 1/2x = 1/18
solving it, we get x=27
so A alone can do it in 27 days.

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