There are 4 numbers in a sequence in such a way that first 3 numbers have a common difference and
last 3 have a common ratio. If middle 2 numbers are 5 and 10 then product of first and last number is
A man earns 40 % profit in his investment of 1000000 rupee, after then he invests all the money in a second business,
in which he losses 30 % of the investment. What % of the initial investment he losses.
After first business total amount received = 1000000 * 140 /100 = 1400000
After second business total amount received = 1400000 * 70 /100
= 980000
Loss = 20000
% loss = 20000 *100 / 1000000
= 2
There are six friends. The sum of the ages of all the friends is 126. If the sum of the ages of
elder 3 friends is 5/4 times that of the younger 3, then sum of the ages of younger 3 is
Answer: Let the sum of the ages of younger 3 friends is x and that of elder 3 friends is 5/4x.
According to given condition
(5/4) x + x = 126
(9/4) x = 126
x = 126 *4 /9 = 56