What is the next number of the following sequence 1,17,17,34,33,51,49,.......

Ann Theressa   10 years AGO

16,17 18... is added to alternating numbers subtracting o,1,2... inbetween.

1+16=17

17-0=17

17+17=34

34-1=33

33+18=51

51-2=49

49+19=68

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ashish kumar   10 years AGO

look at the series it is the multiple of 17 and the next no is 17n-(n-1).
17*1=17
17-0=17
17*2=34
34-(2-1)=33
17*3=51
51-(3-1)=49
17*4=68

Like? Yes (9) | No (4)  

azharshahid01@gmail.com   10 years AGO

There is alternate addition and subtraction in the series.
1,17,17,34,33,51,49...

1+16 = 17
17-0 = 17
17+17= 34
34-1 = 33
33+18= 51
51-2 = 49
49+19= 68
Thus answer is option 3)68

Like? Yes (4) | No (1)  

Varunraj Reddy   10 years AGO

Given sequence
1,17,17,34,33,51,49,.....
Difference between 2nd and 1st number=17-1=16
4th and 3rd number=34-17=17
6th and 5th number=51-33=18
similarly
8th and 7th number=x-49=19 (+1 increase)
x=19+49=68

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Saraswathy   10 years AGO

Divide the series like below

(1, 17, 33, 49 ) (17, 34, 51, x)

In the first group of numbers, difference between each number is 16

In the second group, Multiply by "17" with 1, 2, 3, 4

1 * 17 = 17
2 * 14 = 34
3 * 17 = 51
4 * 17 = x ==> 68

So option is (3)

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RAKESH   10 years AGO

1,17,17,34,33,51,49,..
(1,17),(17,34),(33,51),(49,x)
1+16=17
17+17=34
33+18=51
49+19=68

Like? Yes (4) | No (2)  

Krsihna Prasad   10 years AGO

1
17*1=17
1+16=17
17*2=34
17+16=33
17*3=51
33+16=49
17*4=68
Ans=68

Like? Yes (3) | No (1)  

Pulkit Dureja   10 years AGO

Seq..17*0-(0-1),17*1,17*1-(1-1),17*2,17*2-(2-1)...

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PINKY   10 years AGO

1 (17) 17 (34) 33 (51) 49 .... (68)
two sequence are working here
First->1, (1+16=17), (17+16=33),(33+16)..
Second-> multiple of 17

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Arnab Majumder   10 years AGO

1,17,17,34,33,51,49
next-
1,1*17,(1*17-0),(2*17),(2*17-1),(3*17),(3*17-2)
so next no. = 4*17=68

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VEERENDRA KUMAR K G   10 years AGO

alternate numbers addition is 16 even places .
then even number places addition is 17. hence
1+16=17
17+16=33
33+16=49

next series is
17+17=34
34+17=51
last is
51+17=68

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shamma mohammad   10 years AGO

17*1=17
17-0=17
17*2=34
34-1=33
17*3=51
51-2=49
17*4=68

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basha shaik   10 years AGO

17*1=17
17-0=17
17*2=34
34-1=33
17*3=51
51-2=49
17*4=68

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haritha   10 years AGO

check the difference between the numbers

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Soham Dalwadi   10 years AGO

In Following sequence 1,17,17,34,33,51,49,.......

The no. in odd place is incremented with +16
1+16=17, 17+16=33, 33+16=49

The no. in even place is incremented with +17
17+17=34, 34+17=51, 51+17=68

hence answer is 68

Like? Yes (3) | No (1)  

subramani   10 years AGO

1
17
(1*17)-0=17
2*17=34
(2*17)-1=33
3*17=51
(3*17)-2=49
4*17=68

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Mahalakshmi   10 years AGO

Take alternate series of 1,17,17,34,33,51,49,?
if we take alternate series we will get two sequence
1,17,33,49(addition of 16)
17,34,51,?(addition of 17 or multiples of 17)
1 * 17 =17
2 * 17 =34
3 * 17 =51
4 * 17 =68
so ans is 3)68

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Sunku Mounika   10 years AGO

A/c to the series the second number is 17. and the multiples of 17 are repeating in the respective even places.
So the ans is 68.

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Snehasis   10 years AGO

Just write the multiplication table of 17 with the numbers repeating two times where the repeated number is decremented by 1 every time a new number appears.
17*1=17
17*1=17

17*2=34
17*2=34-1=33

17*3=51
17*3=51-2=49

17*4=68................this is the required no.
17*4=68-3=65

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ADVAITA BASAK   10 years AGO

68

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arun prakash singh   10 years AGO

17*4=68 is

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ASHISH MITTAL   10 years AGO

1 17*1
17 17*2
33 17*3
49 17*4
so answer will be 68 option no (3)

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J.DHANDAPANI   10 years AGO

2nd,4th,6th,8th...terms are multiples of 17.so,ans:17x4=68

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B karthik   10 years AGO

1 to 17 =increment is 16
17 to 17=decrement is 0
17 to 34=increment is 17
34 to 33=decrement is 1
33 to 51=increment is 18
15 to 49=decrement is 2
49 to 68=increment is 19..
like this series will continue...
1,17,17,34,33,51,49,68,65....
Ans=68

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Rahul Kesharwani   10 years AGO

Even places are multiple of 17, so next digit would be 68 only

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Keshav Kishlay   10 years AGO

17*1=17,17*2=34,17*3=51,17*4=68

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AMIT KUMAR   10 years AGO

1 17 17 34 33 51 49 .. ..
here there are two series
1st is......1 17 33 49 here each term added 16..so next will be 65 which is not require
............................................
2nd is......17 34 51 which is find to add 17 in each term......next will be 68
explain.......
17 17+17 =34 34+17 = 51 51+17 = 68ans>>>>>68

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muni   10 years AGO

the sequence is
1,17,17,34,33,51,49
it is fallowing like
16,0,17,1,18,2,19

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Leelanand Kumar Yalla   10 years AGO

Here Alternate digits are added with 16 and 17...
1+16= 17;
17+17=34;
17+16=33;
34+17=51;
33+16=49;
51+17=68; this is the answer.......

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Dinesh thatti   10 years AGO

take alternative series
we get 1,17,33,49
17,34,51, ?
from 1st series 17*1-0=17
17*2-1=33
17*3-2=49

from 2nd series 17*2=34
17*3=51
17*4=68

so answer is 68 which is 3rd option

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Pallekonda Rajesh   10 years AGO

1,17,17,34,33,51,49,.....
1 +16=17 then 17-0=17
17+17=34 then 34-1=33
33+18=51 then 51-2=49
similarly
49+19=68 so ans:68

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TRIMURTULU   10 years AGO

differenc
1,17=16
17,17=0
17,34=17
34,33=1
33,51=18
51,49=2
x-49=19
x=68

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SHEREENA NISHAD   10 years AGO

1,17,17,34,33,51,49....
17-0=17
34-1=33
51-2=49
second, fourth , sixth etc terms are
17,34,51,....
34=17+17
51=34+17
So next term is
51+17=68

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Dishant   10 years AGO

1ST SEQUENCE TABLE OF 17...17,34,51,68
2ND SEQUENCE 1,1+16,1+16+16,1+16+16+16

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NAGENDRA P   10 years AGO

1+16=17..
17-0=17..
17+17=34..
34-1=33..
33+18=51..
51-2=49..
49+19=68..
SO OPTION (3)..

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Vikram Saini   10 years AGO

1 17 17 34 33 51 49 68
16 0 17 1 18 2 19
so ans is 68

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Hemalatha   10 years AGO

17*4=68

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mafidul   10 years AGO

17*1-0, 17 17
17*2-1, 34 33
17*3-2, 51 49
17*4-3, 68

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Manikumar R   10 years AGO

series is like this
1
17*1=17,17-0=17
17*2=34,34-1=33
17*3=51,51-2=49
17*4=68

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gomathi baskar   10 years AGO

17*1=17
17*2=34
17*3=51
17*4=68

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tejaswini g   10 years AGO

1,17,17,34,33,51,49,...

alternate series:1,17,33,49...
17,34,51,....

1,17,33,49..
1x16=16+1=17
2x16=32+1=33
3x16=48+1=49
4x16=64+1=65..........

17,34,51...
17x2=34
17x3=51
17x4=68

so answer is 68

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KEERTHIPALLE SUDHEERKUMAR   10 years AGO

1*17=17,17-0=17
2*17=34,34-1=33
3*17=51,51-2=49
4*17=68,68-3=65

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PRAGATHI G   10 years AGO

Odd places numbers have 16 as difference.. And even place numbers have 17 as difference
1+16= 17
17+16=33
33+16=49
Similarly in even place,
17+17=34
34+17=51
51+17=68

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Rajat Goyal   10 years AGO

Add 17

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MAHESH CV   10 years AGO

alternate number is added by 17 and another is added 17,16

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Sudipta Mukherjee   10 years AGO

17,34,51,68

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meghana   10 years AGO

Given series is 1,17,17,34,33,51,49,__
This series contain two series.
1: 1,17,33,49
2: 17,34,51,__
the next number we want to find will follow second series.
2: 17*1=17
17*2=34
17*3=51
17*4=68
so,the answer is 68.

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salma   10 years AGO

to solve this series we need to divide series into 2 parts like below
1,17,33,49,....=difference is 16 so next number in the series is 65
1,17,34,51,......=here series is increasing by multiple of 17 so next num is 68

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hanamant k   10 years AGO

there are two siries
17,34,51,...
1,17,33,49,...

in first siries 17*1=17
17*2=34
17*3=51
17*4=68...

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kedasu suresh   10 years AGO

from sequence

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nazar   10 years AGO

1
17
17-0=17
17+17=34
34-1=33
34+17=51
51-2=49
51+17=68
so ans is 3)68

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Gourab Dutta   10 years AGO

1,17,33,49...17-1=33-17=49-33=16
17,34,51,68..17+17=34..34+17=51..51+17=68..

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tanya bhatia   10 years AGO

ans is 68 bcz The odd terms go up by 16:
1 .. 17 .. 33 .. 49

The even terms go up by 17:
.. 17 .. 34 .. 51

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khazi mohammad azharuddin   10 years AGO

two series give
first series:1,17,33,49
second series:17,34,51
first series add 16 to previous number.
second series multiples of 17..
so answer is 17*4=68

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vipin kumar   10 years AGO

1+16=17
17-17=0
17+17=34
34-1=33
33+18=51
51-2=49
49+19=68

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AVIJIT   10 years AGO

here two seres 1,17,33,49--> difference 16
and another is 17,34,51,68 ---> difference is 17
so ans is 68.

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K.Bhagyasri   10 years AGO

17*4=68

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Satish Zod   10 years AGO

49 + 19 = 68
i.e. Answer (3)

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rana chowdhury   10 years AGO

1*17=17
17-0=17
2*17=34
34-1=33
3*17=51
51-2=49
4*17=68

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Sohar Lal Singh   10 years AGO

1...17...17..34..33...51..49..
16 0 17 1 18 2 hence there will be
49+19=68

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usharani   10 years AGO

differencce is 17

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Komala.G   10 years AGO

Option (3)
this is a jumble sequence
1 1st no in sequence
add 16
1+16 = 17 3rd
17+16 = 33 5th
33+16 = 49 7th
add 17
17 2nd
17+17 = 34 4th
34+17 = 51 6th
51+17 = 68 8th

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swarnalatha   10 years AGO

1 17 33 49 as one series
17 34 51 as other series are multiples of 17
so next term is 17*4=68

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VIMALRAJ V   10 years AGO

difference between 34 & 17 is 17.Then 17 is added to 51 it gives 68.
17+17=34.
34+17=51.
51+17=68.
Answer is 68.

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SIBNATH HALDER   10 years AGO

1,17,17,34,33,51,49,..
you divided the series into 2 section
1st one odd place value
1,17,33,49,..
that addition of 16 the series go on
2nd one for even place value
17,34,51,..
that's multiplication of 17
so next value is
17*4=68;
the series may be
1,17,17,34,33,51,49,68,65,85...
the ans is option 3=>68

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R.RAVIKUMAR   10 years AGO

1,17,17,34,33,51,49,?
let's consider given series as combination of two series alternatively...

1st series: 1,17,33,49.. here increment is 16..
2nd series: 17,34,51,? here increment is 17.. so, next number in the series is 51+17 = 68..

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Gotlooru Venkata Kartheek Kumar   10 years AGO

Dividing in to two halves as odd and even numbers
and then

Adding 16 to the 1st number and adding 17 to the 2nd number


1+16=17
17+17=34
17+16=33
34+17=51
33+16=49
51+17=68

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chinni gayatri   10 years AGO

51+17=68

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gyan ranjan panigrahi   10 years AGO

every even place is sum of 17

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Rahul Verma   10 years AGO

Difference Between Alternative Sequence is 16 and 17

ex
49-33=16
33-17=16
17-1=16

same as

68-51=17
51-34=17
34-17=17

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saisudha sarva   10 years AGO

divide ito 2 series :

so.. 2nd series 17+17=34
34+17=51
51+17=68

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Sandeep Jadala   10 years AGO

17*1=17
17*2=34
17*2=34-1=33
17*3=51
17*3=51-2=49
17*4=68

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jhinuk sikder   10 years AGO

There is a sequence of 1+16=17, 17-0=17,17+16+1=34,34-1=33,33+18=51,51-2=49,49+19=68
so 68 is the answer

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geet kalani   10 years AGO

double series is going on table of 17.

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Vivek Jain   10 years AGO

Two series 1,17,33,49 with common difference 16 and
17,34,51,? with common difference of 17 so next number will be 51+17=68
Hence option 3) 68 is the answer

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Rajasekhar Reddy   10 years AGO

1,17,33,49 means adding 16 to previous number
17,34,51,68 multiples of 17
so ans is 68

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Gopal Tamrkar   10 years AGO

here two series like this

1, 17,17, 34,33, 51,49.....

in first
1, 17, 34, 51, so that next is 68

and also
n second series dependent on first like

1, 17=17-0, 34=34-1, 51=51-2 so here next is

68=68-3 like that

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Khushboo Kumari   10 years AGO

there r 2 series.....
1).1,17,33,49...
2).17,34,51,...
In first series there is a difference of 16
and in the 2nd one there is a difference of 17...

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eswariteja   10 years AGO

1,17,17,34,33,51,49 diff is:
17-1=16
17-17=0
34-17=17
34-33=1
51-33=18
51-49=2
68-49=19

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Devendra Marghade   10 years AGO

Alternate series
1,17,33,49,65,.. &
17,34,51,68,..

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anubhav verma   10 years AGO

A PAIR OF TWO
1+16=17
17+17=34
33+18=51
49+19=68
HENCE ANSWER=68

Like? Yes (1) | No (1)