The compound interest on Rs.5000 for 3 years at 8% for first year, 10% for Second year and 12% for third year, will be

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24 Jul 2014 Compound Interest The compound interest on Rs.5000 for 3 years at 8% for first year, 10% for Second year and 12% for third year, will be: OPtion
1) 1560.40
2) 1565.60
3) 1652.80
4) 1500.50
5) 1675.50
6) 1686.40
7) 1658.50
8) 1564.50
9) 1574.40
10)None of these; Correct Option: 3 Best Solution (117)

shabih abbas 10 years AGO

principle=5000
so compound interest for 1st year =5000*8*1/100=400
so new principle=5000+400=5400
C.I. for 2nd year=5400*10*1/100=540
so principle=5400+540=5940
C.I. for 3rd year=5490*12*1/100=712.8
so total compound interest in 3 years = 400+540+712.8=1652.8

Like? Yes (26) | No (18)

Swarnali Deb 10 years AGO

Amount=P(1+R1/100)(1+R2/100)(1+R3/100)
Compound Interest=Amount-p

Like? Yes (4) | No

aswinipriya 10 years AGO

for 1st year
interest= (5000*8*1)/100=540
p=interest+amt=5000+400=5400
for 2nd year
interest=(5400*10*1)/100=540
p=5400+540=5940
for3rd year
interest=(5940*12*1)/100=712.8
p=5940+712.8=6652.8
compound interest=6652.8-5000=1652.8

Like? Yes (3) | No (1)

TUSHAR 10 years AGO

1652.8

Like? Yes (4) | No (2)

Hanish 10 years AGO

5000*8/100=400
5000+400=5400
5400*10/100=540
5400+540=5940
5940*12/100=712.8
5940+712.8=6652.8
therefore, 6652.8-5000=1652.8
i.e. option 3)

Like? Yes (3) | No (2)

Alok Pandey 10 years AGO

interest of previous years will be added to the capital amount.

Like? Yes (2) | No (1)

Sagar Dey 10 years AGO

after 3 years amount will be =5000*(1+8/100)*(1+10/100)*(1+12/100)=6652.80
so compound interest=6652.80-5000=1652.80

Like? Yes (3) | No (2)

HARDIP BHALANI 10 years AGO

5000(1+(8/100))(1+(10/100))(1+(12/100))=6652.8
Interest =6652.8-5000=1652.80

Like? Yes (3) | No (3)

vishal 10 years AGO

5000 *1.12*1.1*1.08=6652.8

6652.8-5000=1562.8

Like? Yes (2) | No (2)

deepak kumar 10 years AGO

by simple compound interst formula

Like? Yes (2) | No (2)

NAMBURU L V S MOUNIKA 10 years AGO

ci=p(1+r/100)^n or i=ptr/100 and for 2nd year p=p of 1st year+i

Like? Yes (2) | No (2)

sai 10 years AGO

5000*8/100=5400*10/100=5940*12/100=6652.8
6652.8-5000=1652.80

Like? Yes (1) | No (1)

Yamuna Muthusamy 10 years AGO

amount=P(1+R1/100)(1+R2/100)(1+R3/100)
=5000(1+8/100)(1+10/100)(1+12/100)
=6652.80
compound interest =amount-Principal
=6652.80-5000
=1652.80
ans: Rs 1652.80

Like? Yes (2) | No (2)

AMIT KUMAR SHAW 10 years AGO

1st yr
p=5000,
r=8
si=5000*8/100=400
2nd yr
p=5400
r=10
si=5400*10/100=540
3rd yr
p=5940
r=12
si=5940*12/100=712.8
Compound interest will be=400+500+712.8=1652.8...option(3)

Like? Yes (2) | No (2)

ANKIT SRIVASTAVA 10 years AGO

its correct :)

Like? Yes (2) | No (2)

Maneesh Aucharla 10 years AGO

Compound Interest
8% of 5000 = 400
At the end of 1st year amount= 5000+400 = 5400
now, 10% for 5400 = 540
At the end of 2nd year amount = 5400
450 = 5940
12% of 5940 = 712.8
total amount = 5940 + 712.8 = 6652.8
Required = 6652.8 - 5000 = 1652.8

Like? Yes (2) | No (2)

nishant kumar 10 years AGO

5000(1+8/100)(1+10/100)(1+12/100)

Like? Yes (3) | No (3)

Dark Knight 10 years AGO

5000(1-8/100)=5400
5400(1-10/100)=5940
5940(1-12/100)=6652.8
6652.8-5000=1652.8

Like? Yes (2) | No (2)

shree 10 years AGO

5000(1-8/100)=5400
5400(1-10/100)=5940
5940(1-12/100)=6652.8
6652.8-5000=1652.8

Like? Yes (2) | No (2)

Sundar Kumar 10 years AGO

Principal for the first year =$5000.

Interest for the first year = $ (5000 × 8 × 1)/100 = $400.

Amount at the end of the first year $(5000 + 400) = $5400.

Principal for the second year = $5400.

Interest for the second year = $(5400 × 10 × 1)/100 = $540.

Amount at the end of the second year = $(5400 + 540) = $5940.

Principal for the third year = $5940.

Interest for the third year = $(5940 × 12× 1)/100 = $712.8

Amount at the end of the third year = $(5940 + 712.8) = $6652.8

Therefore, compound interest = $(6652.8 - 5000) = $1652.80

Answer: option 3)1652.8

Like? Yes (4) | No (4)

sonu sahoo 10 years AGO

amount =p*(1+R1/100)(1+R2/100)(1+R3/100)
so , A=5000*1.08*1.1*1.12=6652.8
now CI=A-P=6652.8-5000=1652.8 is the ans.

Like? Yes (2) | No (2)

Niraj Ojha 10 years AGO

First year interest=5000*8/100=400
Now compound principal =5000+400=5400
2nd yr interest=5400*10/100=540
C.p=5940
3rd yr interest =5940*12/100=712.80
Total interest=712.80+540+400=1652.8

Like? Yes (1) | No (1)

kumari manisha 10 years AGO

5000(1+8/100)(1+10/100)(1+12/100)
=6652.8
6652.8-5000=1652.8

Like? Yes (2) | No (2)

Tripti Komal 10 years AGO

5000*0.08=400
5400*0.1=540
5940*0.12=712.8
total interest=400+540+712.8=1652.8

Like? Yes (2) | No (2)

Amrita priyadarshi 10 years AGO

when the compound interest for consecutive periods are r1,r2 and r3 then total amount will be given by:
p(1+r1/100)(1+r2/100)(1+r3/100)
hence here total amount will be
5000(1+8/100)(1+10/100)(1+12/100)=6652.80

thus interest after 3 years will be 6652.80-5000= Rs 1652.80
hence answer will be 3.

Like? Yes (3) | No (3)

Devendra Marghade 10 years AGO

Compounded amount after 3 years
=5000*(108/100)*(110/100)*(112/100) =6652.8
So interest=6652.8-5000=1652.8

Like? Yes (2) | No (3)

Varunraj Reddy 10 years AGO

P=5000, R1=8%,R2=10%,R3=12%

Amount=P[1+(R1/100)][1+(R2/100)][1+(R3/100)]
By solving we get,
Amount=6652.80
Then,
Interest=6652.80-5000=1652.80

Option 3)

Like? Yes (1) | No (2)

Yogesh 10 years AGO

Amount=Principle (1+r/100)^t
according to this amount for 1st = 5000(1+8/100)^1
= 5400
use this amount as the principle for the calculation of the Compond interest for 2nd year.

similarly amount at the end of 2nd year=5940
Similarly amount ath the end of 3rd year=6652.80

so the compoud interest=6652.80-5000=1652.80

Like? Yes (1) | No (2)

Sneha Goel 10 years AGO

A=5000*(1+8/100)*(1+10/100)*(1+12/100)
C.I= A-P=1652.80

Like? Yes (4) | No (5)

azharshahid01@gmail.com 10 years AGO

S= p(1+r/100)^n
for 1st year p=5000, r=8, n=1
on solving, S= 5400
for 2nd year p=5400, r=10, n=1
on solving S=5940
for 3rd year p= 5940, r=12, n=1
on solving, s=6652.80
so, compound interest=6652.80-5000= 1652.80
so, option 3 is correct.

Like? Yes (8) | No (9)

naina 10 years AGO

If the interest rates for the successive fixed periods are r1%, r2%, r3% ..., then A (amount) is given by
A=P(1+r1/100)(1+r2/100)(1+r3/100)
A=5000(1+8/100)(1+10/100)(1+12/100)=6652.8
compound interest=6652.8-5000=1652.8

Like? Yes (2) | No (3)

nageshwarnk 10 years AGO

1652.8

Like? Yes (1) | No (2)

Ravi Bhalani 10 years AGO

5000(1+(8/100))(1+(10/100))(1+(12/100))=6652.8
Interest =6652.8-5000=1652.80

Like? Yes (2) | No (3)

Dinesh kumar 10 years AGO

For 1st year,P(1+r /100)^n
5000(1+(8/100)) = 5400
For 2nd year p will be 5400...
5400(1+(10/100)) = 5940
Similarly for 3rd year,
5940(1+(12/100)) = 6652.8..
Hence the C.I for,
1st year = 5400-5000= 400
2nd year = 5940-5400 = 540
3rd year = 6652.8-5940 = 712.8..
C.I for 3 years = 400+540+712.8 = 1652.8

Like? Yes (1) | No (2)

Harshad 10 years AGO

5000(1+(8/100))(1+(10/100))(1+(12/100))=6652.8
Interest =6652.8-5000=1652.80

Like? Yes (1) | No (2)

BISWAJIT NATH 10 years AGO

[5000(1+(8/100))(1+(10/100))(1+(12/100))]-5000=1652.80

Like? Yes (1) | No (2)

Asha Praveena 10 years AGO

Compound interest annually= P(1+R/100)^n
For the first year=5000(1+8/100)
=5400

For the second year=5400(1+10/100)
=5940

For the third year=5940(1+12/100)
=6642.8

Compound interest for 3 years=6642.80-5000
=1642.80

Like? Yes (1) | No (2)

Anish Mathur 10 years AGO

according to formula
x(1+r1/100)(1+r2/100)(1+r3/100)-x
5000(1+8/100)(1+10/100)(1+12/100)-5000
6652.8-5000=1652.80

Like? Yes (1) | No (2)

Saraswathy 10 years AGO

Amount = 5000*(108/100)*(110/100)*(112/100)
Amount = 6652.80
CI = Amount - P => 6652.80 - 5000 = 1652.8

Ans : 1652.80 (Option 3)

Like? Yes (1) | No (2)

Sourojit Dhua 10 years AGO

At the end of 1st year: amt=5400
at the end of 2nd year: 5940
interest on it at the end of 3rd year = 712.80
Therefore;
total interest= 940+712.80 = 1652.80

Like? Yes (2) | No (3)

kulasekhar reddy 10 years AGO

1 st year intrest =400
2nd year intrest=540
3 rd year intrest= 712.8

total=1651

Like? Yes (2) | No (3)

Debashis Dey 10 years AGO

amount=principal*(1+R1/100)*(1+R2/100)*(1+R3/100)
A=5000*(1+0.08)*(1+0.10)*(1+0.12)=Rs. 6652.80
therefore C.I.=Amount - Principal=6652.80-5000=Rs.1652.80
hence option (3) is the option

Like? Yes (5) | No (6)

Tark Patel 10 years AGO

1)1st year 5000 * .08*1 =400 ->5000+400=5400
2)2nd year 5400*.10*1=540 ->5400+540=5940
3)3rd year 5940*.12*1=712.8

so compound interest = 400+540+712.80=1652.80

Like? Yes (2) | No (3)

priyanka 10 years AGO

amount=p*(1+r1/100)(1+r2/100)(1+r3/100)
5000(108/100)(110/100)(112/100)=6652.80
compound interst 6652.80-5000=1652.80
answer 3) 1652.80

Like? Yes (3) | No (4)

Liti 10 years AGO

400+540+712.8=1652.8

Like? Yes (2) | No (3)

ravi sharma 10 years AGO

for 1st year (5000*1*8)/100 = 400
for 2nd year (5400*1*10)/100 = 540
for 3rd year (5940*1*12)/100 = 712.8
total interest (400+540+712.8) = 1652

Like? Yes (4) | No (5)

sompon temtheerakij 10 years AGO

5000 x 8% = 400
(5000+400) x 10% = 540
(5400+540) x 12% = 712.80
400 + 540 + 712.80 = 1652.80 Rs.

Like? Yes (1) | No (2)

Nagar Bansri 10 years AGO

amount=p(1+R1/100)(1+R2/100)(1+R3/100)
=5000(1+8/100)(1+10/100)(1+12/100)
=6652.8
so ,compound interest=6652.8-5000
=1652.8

Like? Yes (1) | No (2)

natuva aditya 10 years AGO

for 1st year 8% interest for Rs. 5000 is 400.
for 2nd year 10% compound interest for (5000+400) is 540.
for 3rd year 12% compound interest for (5000+400+540) is 712.80
Compound interest on Rs. 5000 for 3 years is
400+540+712.8=1652.80

Like? Yes (2) | No (3)

Kaustubh karekar 10 years AGO

compound interest has variable principal amount every year

for first year principal 5000, no of years 1, rate 8%
so interest = 5000*1*8/100
we get interest 400---------(1)

principal becomes 5400, no of years 1, rate 10%
so interest = 5400*1*10/100
we get interest 540---------(2)

principal becomes 5940, no of years 1, rate 12%
so interest = 5940*1*12/100
we get interest 712.8---------(3)

adding all interest from 1,2,3 we get 1652.80

Like? Yes (2) | No (3)

Pankaj Yogi 10 years AGO

Initial principle amount is p = 5000
after first yr. the interest will be = 5000*8% = 400
hence principle amount for second yr is = 5000+400 = 5400
after second yr, the interest will be = 5400*10% = 540
hence principle maount for third yr bcome = 5400+540=5940
last yr interest = 5940*12% = 712.80
total cmpd interest = 400+540+712.8 =1652.8

Like? Yes (2) | No (3)

Kushagra Tiwari 10 years AGO

By Formula

A=P(1+r1/100)(1+r2/100)(1+r3/100)

where r1= 8%, r2=10% , r3= 12% and p=5000

we calculate the Amount that comes 6652.8

And we know that for CI
CI = Amount-Principle

i .e
CI = 6652.8-5000
Ci= 1652.8

which is in 3rd option

Like? Yes (2) | No (3)

Bishwajeet kumar 10 years AGO

given principal (p)=5000
as we know, amount (A)=p*[1+(r/100)]^n
so for 1st yr, given rate of interest(roi)=8%;
so, A=5000*[1+(8/100)]^1=5400 ;
now p=5400,
given roi for 2nd yr=10%
so, A=5400*[1+(10/100)]^1=5940 ;
now p=5940,
given roi for 3rd yr=12%
so, A=5940*[1+(12/100)]^1=6652.80 ;
now CI= A-P=6652.80-5000=1652.80

Like? Yes (2) | No (3)

abhishek kumar 10 years AGO

for 1st yr= 8 / 100 * 5000= 400.
for 2nd yr= 10 / 100 * 5400= 540.
for 3rd yr= 12 / 100 * 5940= 712.8
total interest=400+540+712.80=1652.80.

Like? Yes (2) | No (3)

Aravinth kumar 10 years AGO

5000*8/100=400
5400*10/100=540
5940*12/100=712.8
400+540+712.8=1652.80

Like? Yes (1) | No (2)

Aravinthkumar 10 years AGO

5000*8/100=400
5400*10/100=540
5940*12/100=712.8
400+540+712.8=1652.80

Like? Yes (1) | No (2)

Ashwin Dinesh 10 years AGO

8% of 5000 = 400
10% of 5400 = 540
12% of 5940 = 712.8
So total = 400+540+712.8 = 1652.80 = option 3)

Like? Yes (1) | No (2)

RAJIB BANERJEE 10 years AGO

When Rates are different for different years, say R1%, R2%, R3% for 1st, 2nd, and 3rd year
respectively,
Then, Amount = P*(1 + R1/100)*(1 + R2/100)*(1 + R3/100)
So,from the problem we got,
Amount=5000*(1+8/100)*(1+10/100)*(1+12/100)
=6652.80
Now,Compound interest = 6652.80-5000
=1652.80

Like? Yes (1) | No (2)

Gokul Krishnan 10 years AGO

a=p(1+8/100)(1+10/100)(1+12/100)
a=6652.8
CI=6652.8-5000
=rs.1652.80

Like? Yes (2) | No (3)

Vikram Saini 10 years AGO

Amount=P((1+R1/100)(1+R2/100)(1+R3/100))
and
Compound Interest=Amount-Principal
SO,c.i.=6652.80-5000=1652.80
Correct Answer option 3
thats it

Like? Yes (3) | No (4)

Ramesh Sriram 10 years AGO

A=5000*(108/100)*(110/100)*(112/100)
C.I=A-P=6652.8-5000
=1652.80

Like? Yes (3) | No (4)

Vinay Choudhary 10 years AGO

C.I. for 1st year=400
C.I. for 2nd year=540
C.I. for 3rd year=712.8
So C.I. for 3 years=400+540+712.8=1652.80

Like? Yes (2) | No (3)

Ravi Kumar Kodari 10 years AGO

5000*(108/100)*(110/100)*(112/100)
=6652.80
C.I=A-P
C.I=6652.80-5000
=1652.80 ans

Like? Yes (2) | No (3)

vinusha reddy 10 years AGO

amount=5000*(1+8/100)*(1+10/100)(1+12/100)
=6652.80
compound interest=6652.80-5000=1652.80

Like? Yes (2) | No (3)

poojasaisri 10 years AGO

1st year interest=(8/100)*5000=400
2nd year interest=((10/100)*5400)+400=940
3rd year interest=((12/100)*5940)+940=1652.8

Like? Yes (2) | No (3)

Udhaya kumar 10 years AGO

5000(1+8/100)(1+10/100)(1+12/100) = 6652.8.....
6652.8-5000 = 1652.8..............

Like? Yes (4) | No (5)

Rajamohan Raju 10 years AGO

for the first year the CI at 8% is 5000[1+(8/100)] = 5400.
for the second year CI at 10% is 5400[1+(10/100)] = 5940.
For the third year CI at 12% is 5940[1+(12/100)] = 6652.80.
So the final CI is 6652.80-5000 = 1652.80

Like? Yes (1) | No (2)

Palash Malani 10 years AGO

5000+8%=5400
5400+10%=5940
5940+12%=6652.8

Interest= 6652.8-5000
=1652.8 (Option 3)

Like? Yes (1) | No (3)

Basavasagar 10 years AGO

5000(1+.08)=5400
5400(1+.1)=5940
5940(1+.12)=6652.8
therefore 6652.8-5000=1652.8

Like? Yes (1) | No (3)

swarupa nuggu 10 years AGO

400+540+712.8=1652.8

Like? Yes (1) | No (3)

SUMIT 10 years AGO

(5000*1.08*1.1*1.12)-5000=1652.80

Like? Yes (2) | No (4)

BHANU KUMAR 10 years AGO

amt after 1st yr= 5000+8% of 5000=5400
amt after 2nd yr=5400+10% of 5400=5940
amt after 3rd yr=5940+12% of 5940=6652.80
Hence the compound interest =6652.80-5000=1652.80 [option 3]

Like? Yes (1) | No (3)

RAHUL RANJAN 10 years AGO

principal amt=5000;
so for 1st year intrest=5000*(8/100)=
400;
now for 2nd year principal amt=5400
so intrest=5400*(10/100);
now for 3rd year principal amt=5940
so intrest=5940*(12/100)=712.8
so total intrest=400=540+712.8=1652.8 ans

Like? Yes (1) | No (3)

RAVI RANJAN 10 years AGO

in 1 st year interest =400
in 2nd year interest= 540
in 3rd year interest =712.8
total=1652.8

Like? Yes (1) | No (3)

DIPAK TIWARI 10 years AGO

5000(1+.08)(1+.1)(1+.12)-5000
=6652.8-5000
=1652.8

Like? Yes (1) | No (3)

prem kumar sr 10 years AGO

A=p(1+R1/100)(1+R2/100)(1+R3/100) will give you the total amount , where R1,R2, R3.. will be the rate of interest for successive fixed period...
therfore A=6652.8 ;
ci=A-P=6652.8-5000=1652.80 will be the ans

Like? Yes (1) | No (3)

SAHIL DIWAN 10 years AGO

amt of ist year=5000+(5000*.08)=5400
amt of 2nd year=5400+(5400*.1)=5940
amt of 3rd year=5940+(5940*.12)=6652.8
compound intrest =6652.8-5000=1652.8

Like? Yes (2) | No (4)

LOKESH SAMANT 10 years AGO

c.i=5000(1+8/100)(1+10/100)(1+12/100) - 5000
=1652.8

Like? Yes (1) | No (3)

madanpal vishwakarma 10 years AGO

first year interest =400
now p=5400
so second year interest =540
now p=5940
so interest =712.80
after adding all 3 ears interest =400+540+712.80=1652.80
so option 3 is correct.

Like? Yes (2) | No (4)

Vivek Jain 10 years AGO

712.8+540+400 interest for 3 years respectively

Like? Yes (1) | No (3)

chauhan dhara vinayakkumar 10 years AGO

first compound interest of first yr
then of second and then third.
ans=1652.80

Like? Yes (1) | No (3)

sanghavi 10 years AGO

c.i for 1st year is 400
c.i for 2nd year is 540
and for 3rd year c.i is 712.8

Like? Yes (1) | No (3)

dheeraj 10 years AGO

5000(1+8/100)=5400
5400(1+10/100)=5940
5940(1+12/100)=6652.8

CI=6652.8-5000=1652.8

Like? Yes (1) | No (3)

Amit kumar 10 years AGO

5000+5000*8%=5400
5400+5400*10%=5940
5940+5940*12%=6652.8
so required ans will be 6652.8-5000=1652.8

Like? Yes (1) | No (3)

Inderjeet Singh 10 years AGO

principal = 5000
interest on 5000 for first year at rate 8% = 400
amount now = 5400
interest on 5400 for second year at rate 10% = 540
amount now= 5940
interest on 5940 for third year ar rate 12% = 712.80

total interest = 400 + 540 + 712.80 = 1652.80

Like? Yes (1) | No (3)

Tanbir Yusuf Ahmed 10 years AGO

400(1st year)+540(2nd year)+712.8(3rd year)=1652.8

Like? Yes (1) | No (3)

Deepak Yadav 10 years AGO

5000*(1+8/100)*(1+10/100)*(1+12/100)
1652.80

Like? Yes (1) | No (3)

RANJAN KUMAR PANDIT 10 years AGO

5000*108% * 110% * 112% = 6652.8
so total c.i = 6652.8-5000=1652.8

Like? Yes (2) | No (4)

MRITUNJAY KUMAR 10 years AGO

for 8% C.I will be=5000*1*8/100=400.
for 10% C.I will be=5400*1*10/100=540.
for 12% C.I will be=5940*1*12/100=712.8
totlal C.I will be=400+540+712.8=1652.8
Ans-option 3)

Like? Yes (1) | No (3)

Madan 10 years AGO

CI=P(1+r1/100)(1+r2/100)(1+r3/100) - P
CI=5000(1+8/100)(1+10/100)(1+12/100)-5000
CI=1652.80

Like? Yes (1) | No (3)

krishna kanth 10 years AGO

5000*(1+8/100)*(1+10/100)*(1+12/100)
5000*1.08*1.1*1.12=6652.80
6652.80-5000=1652.8

Like? Yes (1) | No (3)

Navpreet Singh 10 years AGO

p=5000
A=5000*1.08*1.1*1.12=6652.8
C.I=A-P
C.I=6652.8-5000=1652.8

Like? Yes (1) | No (3)

Priya Verma 10 years AGO

for first year amount=(5000*108)/100=5400 and interest=400
for second year amount=(5400*110)/100=5940 and interest=540
for third year amount=(5940*112)/100=6652.80 and interest=712.80
total interest=400+540+712.80=1652.80

Like? Yes (1) | No (3)

neeraj 10 years AGO

CI= A-P
A= P(1+r1/100)(1+r2/100)(1+r3/100)
here
P=5000
r1=8
r2=10
r3=12
this gives A=6652.80
thus CI=1652.80

Like? Yes (1) | No (3)

ananthavalli 10 years AGO

5000*(1+8/100)(1+10/100)(1+12/100)=6652.80
compound Interset=6652.80-5000=1652.80
so option 3) is correct

Like? Yes (1) | No (3)

souharda 10 years AGO

1st yr int= 400
2nd year principal=5400
2nd year int= 540
3rd year int=5940
3rd year int=712.8
total ci= 5940+712.8- 5000= 1652.8

Like? Yes (1) | No (3)

Mohit Aggarwal 10 years AGO

(5000*1.08*1.10*1.12) - 5000 = 1652.80

Like? Yes (1) | No (3)

piyush ranjan behera 10 years AGO

1st yr interest (5000*1*8)/100= 400
2nd yr interest (5400*1*10)/100=540
3rd yr interest (5940*1*12)/100=712.80

total principal amt is 5940+712.80= 6652.80

then total interest= 6652.80-1000= 1652.80

Like? Yes (1) | No (3)

SANJEET 10 years AGO

5000*8/100=400 intrest in first month
5000+400=5400
5400*10\\100=540 intrest in second month
5400+540=5940
5940*12\\100=712.80intrest in third month
total compound intrest= 400+540+712.80=1652.80

Like? Yes (1) | No (3)

ANUP KUMAR 10 years AGO

In first year, intrest = 5000*8/100=400;
Now total ammount = 5000+400=5400;
In 2nd year, intrest = 5400*10/100=540;
Now total ammount = 5400+540=5940;
In 3rd year,intrest =5940*12/100=712.8;
So, compound Intrest on 5000 for 3 years=400+540+712.8=1652.80
option(3) ans

Like? Yes (3) | No (5)

Chandra Bhushan Kumar Dubey 10 years AGO

ans=(5000*(108/100)*(110/100)*(112/100)) -5000
=1652.80

Like? Yes (1) | No (3)

AMIT SINGH 10 years AGO

p(1+r1/100)(1+r2/100)(1+r3/100)
=5000(1+8/100)(1+10/100)(1+12/100)
=6652.80
required CI=6652.80-5000
=1652.80.

Like? Yes (1) | No (3)

loks 10 years AGO

c.i=5000(1+8/100)(1+10/100)(1+12/100) - 5000
=1652.8

Like? Yes (1) | No (3)

prince kachhela 10 years AGO

5000(1+8/100)(1+10/100)(1+12/100)=6652.8
6652.8-5000=1652.8

Like? Yes (1) | No (3)

kaushal kishor 10 years AGO

ci=a-p
a=p*{(1-r1/100)(1-r2/100)(1-r3/100)}

Like? Yes (1) | No (3)

Satishbabu 10 years AGO

A=p(1+r1/100)(1+r2/100)(1+r3/100)
=5000*(1+8/100)(1+10/100)(1+12/100)=6652.80
=>C.I=A-P=6652.80-5000=1652.8
Therefore option (3)

Like? Yes (1) | No (3)

sivaramakrishna 10 years AGO

(108/100)(110/100)(112/100)(5000)=6652.8
6652.8-5000=1652.8

Like? Yes (1) | No (3)

bharti arya 10 years AGO

amount=5000[1+8/100]*[1+10/100]*[1+12/100]
therefore amount=6652.8
compound interest=6652.8-5000
=1652.8

Like? Yes (1) | No (3)

SAURADIPTA SADHU 10 years AGO

5000*8/100=400
(5000+400)*10/100=540
(5000+400+540)*12/100=712.80
400+540+712.8=1652.80

Like? Yes (1) | No (3)

Pranay Sahith 10 years AGO

I=5000*8%+5400*10%+5940*12%=1652.8

Like? Yes (1) | No (3)

MANU 10 years AGO

for first yr ,I=400
FOR 2ND YR, I=540
FOR 3rd yr, i=712.8
CI=400+540+712.8=1652.80

Like? Yes (1) | No (3)

S.Rosyponmary 10 years AGO

first year==> 5000*8/100=400
second year (5000+400) because of compound interest
5400*10/100=540
third year ==>(5400+540)=5940
5940*12/100=712.80

so the compound interest is =400+540+712.80
=1652.80

Like? Yes (1) | No (3)

Niveytha 10 years AGO

5000(1+(8/100))(1+(10/100))(1+(12/100))=6652.8
6652.8-5000=1652.8

Like? Yes (1) | No (3)

Rammohana rao Balaga 10 years AGO

1st year total [5000+5000*8/100] = 5400
2nd year total [5400+5400*10/100] = 5940
3rd year total [5940+5940*12/100] = 6652.8

interest is = 6652.8-5000 = 1652.80

Like? Yes (1) | No (3)

GOWRABATHUNI RAJESH 10 years AGO

5000*[108/100]*[110/100]*[112/100]
=6652.8
interest=6652.8-5000=1652.8

Like? Yes (1) | No (3)

sundeep gullapudi 10 years AGO

At first year
8 % of 5000 = 400
total = 5400
second year
10% of 5400 = 540
total = 5940
third year
12% of 5940 = 712.8
total = 6652.8
compoud interest = 6652.8 - 5000 = 1652.8

Like? Yes (1) | No (3)

dushyant singh pawar 10 years AGO

Amount=5000*(1+(8/100))*(1+(10/100))*(1+(12/100))

therefore,

5000*((108/100)+(110/100)+(112/100))

or Amount=6652.8

CI=Amount-Principle Amount

CI=6652.80-5000.00=1652.80 [option 3]

Like? Yes (1) | No (4)

Dimple

India

Punjab

Time: 00:01:33

Points

Maths Quotes

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MATHEMATICS IS A "LANGUAGE OF UNIVERSE"

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The compound interest on Rs.5000 for 3 years at 8% for first year, 10% for Second year and 12% for t

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24 Jul 2014 Compound Interest