A two digit number is obtained by either multiplying the sum of the digits by 8 and adding 1 or by m

NAVEEN KUMAR   10 years AGO

let number=xy
a/q:-
8(x+y)+1=10x+y---------------(eq 1)
and
(x-y)13+2=10x+y----------------(eq2)
by eq 1 and eq 2
x=4 & y=1 , so req. no=41 (option 9)

Like? Yes (62) | No (19)  

Deepak Reegan A   10 years AGO

xy be the numbers , x is two digit number and y is one digit,
8(x +y)+ 1 = 10x + y ;
13(x -y) + 2 = 10 x + y
we get, 8x + 8y + 1 = 10x + y, we get the value as 2x - 7y =1
13x - 13y + 2 = 10x + y, we get the value as 3x - 14y = -2
through elimination we get, x = 4 , y = 1, the number is 41

Like? Yes (29) | No (9)  

Suganya   10 years AGO

let tens digit be x and ones digit be y
8(x+y) + 1= 10x + y -------------------1
simplified equ of 1
2x - 7y = 1 ------------------------2
13(x-y) + 2 = 10x + y-------------------3
simplified equ of 3
-3x + 14y = 2 -------------------4
by solving 2 and 4
we get x=4 and y=1
answer is 41

Like? Yes (25) | No (7)  

Mrityunjay   10 years AGO

let the digit at ten's and one's place be x and y respectively.

so, 8(x+y)+1=10x+y
and
13(x-y)+2=10x+y

solving these two equations we get
x=4, y=1
so the required number is 41
correct option=9

Like? Yes (20) | No (12)  

vartika    10 years AGO

let the two digit number be 10x+y.,
then, according to question,
10x+y= (x+y)8+1 => 2x-7y=1 ..... (1)
also, 10x+y= (x-y)13+2 => -3x+14y=2 ...... (2)
Multiplying equation (1) by 2 and adding euation (2), we get
(4x-14y)+(-3x+14y)=2+2
=> x=4
substituting this value of x in equation (1),we get
40+4=32+8y+1
=> y=1
hence the number is 41

Like? Yes (8) | No (2)  

Vikram   10 years AGO

Let xy be the unknown number. x = tens digit, and y = ones digit.
Then 8(x+y) + 1= 10x + y, 13(x-y) + 2 = 10x + y
2x - 7y = 1 and -3x + 14y = 2
we get x = 4 and y = 1
hence answer is 41

Like? Yes (6) | No   

gautam gaurav   10 years AGO

we get two eqn as
(x+y)8+1=xy
and (x-y)13+2=xy
solving these eqn we get
5x-21y+1=0
putting x=4 and y=1 we get the no
so ans is 41

Like? Yes (5) | No (1)  

Avula Suresh Babu   10 years AGO

8*5+1=41
and
4-1=3
3*13+2=41

Like? Yes (5) | No (1)  

vikas   10 years AGO

8(x+y) +1= 10x+y
2x-7y=1
similarly
13x-13y +2=10x+y
3x-14y=-2

solving thz two
we get x=4 and y as 1

Like? Yes (7) | No (4)  

Ajinkya Kulkarni   10 years AGO

10x+y= 8(x+y)+1=(x-y)*13+2

Solved these eq and get the answer
As x =4 and y =1

Like? Yes (6) | No (3)  

Venkateswarlu   10 years AGO

8*(4+1)+1=41
13*(4-1)+2=41

Like? Yes (4) | No (1)  

kalpana kumari   10 years AGO

(x+y)8+1=(x-y)13+2=10x+y
then x=4
y=1
that is ans 41

Like? Yes (4) | No (1)  

lalit   10 years AGO

(a+b)*8 + 1 = 13(a-b) +2 = 10a = b
from here we get a=4b possible(a,b)=(4,1),(8,2)
answer 41and82

Like? Yes (3) | No   

teja srinivas   10 years AGO

8(x+y)+1=10x+y
13(x-Y)+2=10x+y
by solving
x=4 y=1
therefore xy=41

Like? Yes (2) | No   

srishti talreja   10 years AGO

satisfied ans through options 41, 4+1=5*8=40+1=41
4-1=3*13=39+2=41

Like? Yes (2) | No   

gouthamdaneti   10 years AGO

(4+1)*8+1

Like? Yes (2) | No   

shreyansh   10 years AGO

on solving cosidering ab to be the no. eqn comes out to be 21b=1+5a and 41 satisfies to it. or it can also b explained as sum of digits 5 multipying 8 gives 40 n adding 1 gives 41 and similarly difference of digits 3 mutiplying 13 gives 39 adding two gives 41

Like? Yes (2) | No   

prashanth kumar us   10 years AGO

Let "ab" is a 2 digit number.
1st condition:
(a+b)*8=10a+b;

=>2*a-7*b=1;
2nd condition
(a-b)*13+2=10a+b;

=>-3*a+14*b=2;

solving a=4 and b=1

number is ab=41.

Like? Yes (2) | No   

sainath reddy    10 years AGO

first condition and second condition satisfies by 41 in trail and error method

Like? Yes (2) | No   

veeranjaneyulu   10 years AGO

8(4+1)+1=41
13(4-1)+2=41

Like? Yes (2) | No   

nagineni sukumar   10 years AGO

simply checking the options
(x+y)8+1
(x-y)13+2
41 is satisfy above conditions

Like? Yes (2) | No   

sandesh   10 years AGO

((1+4)*8)+1=41
((4-1)*13)+2=41

Like? Yes (2) | No   

shree   10 years AGO

41=41;...

Like? Yes (2) | No   

Gitanjali K   10 years AGO

8(4+1)+1=41 or 13(4-1)+2=41
so option (9) is the answer

Like? Yes (2) | No   

chakshu   10 years AGO

4+1=5
5*8=40
40+1=40
4-1=3
3*13=39
39+2=41

Like? Yes (2) | No   

yagnik pandya   10 years AGO

We got equation like,
5x-21y=-1
Let x=4 and y=1
Answer is the 41

Like? Yes (2) | No   

T.Aravinth kumar   10 years AGO

((4+1)*8)+1=41=((4-1)*13)+2

Like? Yes (2) | No   

Amit Toor   10 years AGO

41
(4+1)*8+1=(4-1)*13+2
41=41

Like? Yes (2) | No   

Ranjit Singh   10 years AGO

solving simple equations

Like? Yes (2) | No   

sachin verma   10 years AGO

given conditions are true only for 41 i.e.
41=8(4+1)+1
or
41=13(4-1)+2

Like? Yes (2) | No   

Parag Wagh   10 years AGO

[(x+y)*8]+1=[(x-y)*13]+2

Like? Yes (2) | No   

Ankur Gupta   10 years AGO

(10x+y)8+1=(10x-y)13+2
after solving this equation
x=4
y=1

Like? Yes (2) | No   

pankaj   10 years AGO

8(a+b)+1=13(a-b)+1
21b=5a+1

ans could be
b=1
a=5

Like? Yes (2) | No   

D.HARINATH REDDY   10 years AGO

let take number as 10*X+Y
(X+Y)*8+1=10*X+Y (X-Y)*13+2=10*X+Y
2X-7Y=1 3X-14Y=-2
solve above two equations we get
X=4,Y=1
so number is 41

Like? Yes (1) | No   

sumit   10 years AGO

By hit & trial option (9)
41=(4+1)*8+1
41=(4-1)*13+2

Like? Yes (7) | No (6)  

AMIT JHA   10 years AGO

41=(4+1)*10+1
41=(4-1)*13+2

Like? Yes (2) | No (1)  

S.SHAFI   10 years AGO

Let xy be the unknown number. ==> x = tens digit, and y = ones digit.
Then from the given, 8(x+y) + 1= 10x + y, and 13(x-y) + 2 = 10x + y.

2x - 7y = 1 and -3x + 14y = 2
Proceeding with the method of elimination, we get x = 4 and y = 1.
Therefore the number is 41.

Like? Yes (3) | No (2)  

manish kumar singh   10 years AGO

Let xy be the unknown number.
x = tens digit, and y = ones digit.
Then from the given question,
8(x+y) + 1= 10x + y, and 13(x-y) + 2 = 10x + y.
2x - 7y = 1 and -3x + 14y = 2
by using elimination method, we get x = 4 and y = 1.
Therefore the number is 41

Like? Yes (3) | No (2)  

Devendra Marghade   10 years AGO

If two-digit number= 10x+y
1st case: 10x+y=(x+y)8+1 or 2x-7y=1 ---(i) &
2nd case:10x+y=(x-y)13+2 or 3x-14y=-2 ---(ii)
On solving, x=4 ,y=1
So the number=41

Like? Yes (2) | No (1)  

Tania Chatterjee   10 years AGO

Let xy be the unknown number. ==> x = tens digit, and y = ones digit.
Then from the given, 8(x+y) + 1= 10x + y, and 13(x-y) + 2 = 10x + y.
=> 2x - 7y = 1 and -3x + 14y = 2
Proceeding with the method of elimination, we get x = 4 and y = 1. (Check these solution against the original system!)
Therefore the number is 41.

Like? Yes (3) | No (2)  

pramita raha   10 years AGO

4+1=5
5*8=40+1=41
4-1=3
3*13=39+2=41

Like? Yes (2) | No (1)  

priyanka    10 years AGO

xy is digit
then (x+y)*8+1=xy
means (4+1)*8+1=41

Like? Yes (4) | No (3)  

RAKESH   10 years AGO

8(x+y)+1 = 13(x-y)+2 = 10x+y
solving
no. is 41

Like? Yes (3) | No (2)  

ANKITA prasad   10 years AGO

let units digit be y and tens digit be x
8(x+y)+1=10x+y
13(x-y)+2=10x+y
solving we get y=1, x=4

Like? Yes (3) | No (2)  

BHANU KUMAR   10 years AGO

8(x+y)+1=10x+y
13(x-y)+2=10x+y

on solving we get
x=4
y=1
4*10+1=41

Like? Yes (2) | No (1)  

Rahul shaw   10 years AGO

ans. is 41

Like? Yes (3) | No (2)  

vishnuvardhan   10 years AGO

41=(4+1)*8+1=40+1=41
41=(4-1)*13+2=39+2=41

Like? Yes (2) | No (1)  

krishna kanth   10 years AGO

suppose number be xy
from given conditions 8*(x+y)+1=13*(x-y)+2=10*x+y
by solving we are going to get

21*y=5*x+1
2*x=7*y+1
form this we are getting values as x=4
and y=1
therefore number is 41

Like? Yes (1) | No (1)  

anand vijay   10 years AGO

Let x and y be their two digit
then, (x+y)8+1=(x-y)*13+2
on checking through option 41 is the right answer
option(9)

Like? Yes (1) | No (1)  

Aakash Jain   10 years AGO

if we put options in the given conditions so we got the answer 41

Like? Yes (2) | No (2)  

Gourab Dutta   10 years AGO

(4+1)*8+1=41
(4-1)*13+2=41

Like? Yes (1) | No (1)  

Ramandeep Singh   10 years AGO

4+1=5
(5*8)+1=41
and
4-1=3
(3*13)+2=41

Like? Yes (1) | No (1)  

ANAND KUMAR   10 years AGO

let digits are x and y
so 8(x+y)+1=10x+y or 2x-7y=1
& 13(x-y)+2=10x+y or 3x-14y=-2
by solving both eqn we get
x=4 & y=1
hence number is 41

Like? Yes (4) | No (4)  

Samrat Adhikari   10 years AGO

let, the no. is 10x+y (x>y)
1st condition, 8(x+y)+1 = 10x+y
2nd condition, 13(x-y) = 10x+y
solving these 2 equation, we get x=4, y=1
hence, the no. is 41.

Like? Yes (1) | No (1)  

Jigyasa Kumar   10 years AGO

4+1 = 5; 5*8+1 = 41
so ans is 41

Like? Yes (1) | No (1)  

Dinesh thatti   10 years AGO

by following the clues given in the question we get the answer 41

Like? Yes (1) | No (1)  

MUKESH YADAV   10 years AGO

let 10x+y is the two digits of number then
(x+y)*8+1=10x+y and
|x-y|*13+2=10x+y
taking x=4 and y=1 then the no will be 10*4+1=41.
and condition
(4+1)*8+1=41

(4-1)*13+2=41
are full filled..
hence 41 is d ans..

Like? Yes (2) | No (2)  

ANSHIKA JAIN   10 years AGO

let the tens digit be x and units digit be y ,so the no. is (10x+y)
acc. to ques
8(x+y)+1=10x+y and 13(x-y)+2=10x+y
the two equations are :-
3x-14y=-2 and 2x-7y=1

on solving both we get x=4 y=1
hence the two digit no. is 41

Like? Yes (1) | No (1)  

sanjeev kumar   10 years AGO

And 41

Like? Yes (1) | No (1)  

Pranoy Bej   10 years AGO

(4+1)*8+1=41
(4-1)*13+2=41

Like? Yes (3) | No (3)  

Kushagra Tiwari   10 years AGO

Let xy be the unknown number. ==> x = tens digit, and y = ones digit.
Then from the given, 8(x+y) + 1= 10x + y, and 13(x-y) + 2 = 10x + y.

2x - 7y = 1 and -3x + 14y = 2
Proceeding with the method of elimination, we get x = 4 and y = 1. (Check these solution against the original system!)
Therefore the number is 41.

Like? Yes (1) | No (1)  

Abhishek Vishwakarma   10 years AGO

Let xy be the unknown number. ==>
x = tens digit,
and y = ones digit.
Then from the given,
8(x+y) + 1= 10x + y, and
13(x-y) + 2 = 10x + y.

2x - 7y = 1 and -3x + 14y = 2
Proceeding with the method of elimination, we get x = 4 and y = 1.
Therefore the number is 41.

Like? Yes (1) | No (1)  

karthik sundaresan.S   10 years AGO

sum is 5 so (5*8+1=41)
difference is 3 so (3*13+2=41)......

Like? Yes (2) | No (2)  

Pranay Mukhopadhyay   10 years AGO

By trial and error method,
((4+1)*8)+1=41
((4-1)*13)+2=41

Like? Yes (1) | No (1)  

amit   10 years AGO

8(1+4) + 1 =41

Like? Yes (2) | No (2)  

virendra tiwari   10 years AGO

go by option
(1+4)*8+1=41
(4-1)*13+2=41

Like? Yes (1) | No (1)  

ADARSH GAURAV   10 years AGO

41 is the answer.

Like? Yes (2) | No (2)  

ganesh babu   10 years AGO

8(x+y)+1=10x+y ---->2x-7y=1
13(x-y)+2=10x+y----->3x-14y=-2
x=4, y=1---->10 x+y=41

Like? Yes (1) | No (1)  

Nomendra Sinha   10 years AGO

8(x+y)+1=13(x-y)+2
so 5x-21y+1=0
x=4, y=1 means 41 ans.

Like? Yes (1) | No (1)  

Prashant Rupnur   10 years AGO

by option

Like? Yes (5) | No (5)  

Upasana Bhattacharjee   10 years AGO

2x-7y=1

14y-3x=2

Like? Yes (2) | No (2)  

Satyaki Bhattacharjee   10 years AGO

x and y be the digits
(x+y)*8+1
(x-y)*13+2
So cheking by options,putting values of x and y..

Like? Yes (2) | No (2)  

Enukonda Ramakrishna   10 years AGO

by option verification
41=(4+1)*8+1
41=(4-1)*13+2

Like? Yes (6) | No (6)  

anandhakumar   10 years AGO

let us try from option
the answer is 41
option 9

Like? Yes (2) | No (2)  

sudhakar   10 years AGO

answer option 9)41

Like? Yes (2) | No (2)  

selvakumar   10 years AGO

answer option 9)41

Like? Yes (2) | No (2)  

ATUL SHUKLA   10 years AGO

on solving eqn got the result

Like? Yes (1) | No (1)  

Ujjwal Mishra   10 years AGO

4+1=5
5*8=40
40+1=41

Like? Yes (2) | No (2)  

sharathbabu   10 years AGO

let the two digit number be 10x + y.
Two digit number is obtained by multiplying sum of the digits by 8 and adding 1
⇒ 10x + y = 8(x + y) + 1
⇒ 2x - 7y = 1 ---------------- (1)
Two digit number is obtained by multiplying the difference of the digits by 13 and adding 2
⇒10x + y = 13(x - y) + 2
⇒ 3x - 14y = -2 ----------- (2)
Solving equations 1 and 2, we get x = 4 and y = 1.

Therefore, the two digit number is 41.

Like? Yes (4) | No (4)  

Ravi Kumar   10 years AGO

The equation formed are 1+8x+8y=10x+y and 2=13x-13y=10x+y
On solving we get the answer as 41

Like? Yes (3) | No (3)  

siddharth prakash singh   10 years AGO

let tens digit=x and ones digit=y; no=10x+y;
(x+y)8+1=10x+y
2x-7y=1 ......(1)
(x-y)13+2=10x+y
3x-14y=-2 ......(2)
solving both we get x=4 and y=1..
thus giving req no 10*4+1=41

Like? Yes (2) | No (2)  

Chinmoy Samanta   10 years AGO

((4+1)*8)+1=41
((4-1)*13)+2=41

Like? Yes (2) | No (2)  

Ramesh Sriram   10 years AGO

let number=xy=10X+y
10X+y=(x+y)*8+1------------(1)
10x+y=(x-y)*13+2-----------(2)
solving above two equations
x=4 and y=1
xy=41

Like? Yes (1) | No (1)  

Sandeep Kumar   10 years AGO

Let, number is xy.
so, ATQ
(x+y)*8+1=(x-y)*13+2
solving this equation we get x=4, & y=1
so number is xy=41

Like? Yes (1) | No (1)  

vikash kumar   10 years AGO

let the digit be xy;
a/c to the question 8(x+y)+1=13(x-y)+2;
solving this we can find 21y-5x=1
by applying heat and trial method we will get 41

Like? Yes (2) | No (2)  

siva   10 years AGO

tial and error

Like? Yes (1) | No (1)  

Supriya Sinha   10 years AGO

5*8=40 +1=41 and 3*13=39+2=41

Like? Yes (1) | No (1)  

Paridhi Agarwal   10 years AGO

If the no. is taken as 10x+y
Then acc. to given conditions two equations will be formed
2x-7y=1 and 3x-14y=-2
Solving them vl get as 41

Like? Yes (2) | No (2)  

ISHWARYA VASU   10 years AGO

((4+1)*8)+1=((4-1)*13)+2=41

Like? Yes (2) | No (2)  

veera swamy vanguri   10 years AGO

8*(x+y)+1=xy
13*(x-y)+2=xy

Like? Yes (3) | No (3)  

Srikanth   10 years AGO

let number be xy,
8(x+y)+1=10*x+y; 2x-7y=1
13(x-y)+2=10*x+y; 3x-14y=-2
by solving we get x=4 y=1

Like? Yes (1) | No (1)  

MANTENA AJAY VARMA   10 years AGO

its better to verify the options rather than thinking of a formula

Like? Yes (1) | No (1)  

krishnapriya   10 years AGO

4+1=5 5*8=40+1=41
4-1=3 3*13=39+2=41

Like? Yes (1) | No (1)  

naresh potturi   10 years AGO

i).multiplying sum of the digits by 8 is
(4+1)*8=40;
then Adding \'1\' to it is 40+1=41;
ii).multiplying the difference of digits by 13 is
(4-1)*13=39;
then adding \'2\' is 39+2=41

Like? Yes (1) | No (1)  

Anshul   10 years AGO

41
4+1 = 5
5*8=40+1=41
same way for subtraction process

Like? Yes (1) | No (1)  

swarup kumar prusti   10 years AGO

satisfy the equation (X+y)*8+1

Like? Yes (1) | No (1)  

chaitanya anand   10 years AGO

sum of no =(10x+y)*8+1=xy
diffrance of no=(10x-y)*13=xy onsolving xy=41

Like? Yes (1) | No (1)  

Govind raj   10 years AGO

8(x+y)+1=(x-y)13+2.........satisfy only 41

Like? Yes (1) | No (1)  

Nagar Bansri   10 years AGO

let the unit digit will be x and tenth digit will be y
so as per equation ,
8(x+y)+1=10y+x;
7x-2y+1=0........................(1)
now 2nd eduation is,
13(x-y)+2=10y+x;
-3x+14y+2=0...............(2)

so solvimg both the equation we got x=1 and y=4 so num is 41

Like? Yes (1) | No (1)  

Parshant garg   10 years AGO

Let number is xy
(x+y)*8+1=10*x+y
(x-y)*13+2=10*x+y
solve
x=4 y=1
41

Like? Yes (2) | No (2)  

HARSH AGRAWAL   10 years AGO

let the digits be x and y
so, 8(x+y)+1 ->eq(1)
13(x-y)+2 - >eq(2)
the option which satisfies the two to give the same number is option(9)
41 is ans

Like? Yes (1) | No (1)  

Kethineni Vinodh   10 years AGO

by Verification
41=(4+1)*8+1
41=(4-1)*13+2

Like? Yes (1) | No (1)  

Urvashi Jain   10 years AGO

let the number be xy
according to the ques
xy=8(x+y)+1.....(1)
xy=13(x-y)+2....(2)
see option 9 x=4 and y=1
put in equation the option satisfied
option(9)

Like? Yes (1) | No (1)  

ranjithreddy   10 years AGO

The number is a multiple of 8 and 13 ,if we add 1 and 2 the digits simultaneously.
8*5+1=41
and
13*3+2=41

Like? Yes (1) | No (1)  

ramakrishnateja   10 years AGO

let the digits be x and y.according to the question the equations can be framed as 8(x+y)+1 and the another equation is 13(x-y)+2. but the both equations give rise to the same number hence equating them 8(x+y)+1=13(x-y)+2. which gives rise to 5x-21y=-1. then the 9th option is correct.

Like? Yes (1) | No (1)  

keerthiga   10 years AGO

take 2 digit no. must be equal with the result

condition no. must equal to sum of the 2 digit *8 +1

41 is the answer

sum = 4+1=5

5*8+1=41

and second condition is difference of 2 digit *13+2

difference =4-1=3

3*13+2=41

both are equal.

Like? Yes (2) | No (2)  

deepak   10 years AGO

(4+1)*8+1

Like? Yes (1) | No (1)  

Bhagyashree Bhatt   10 years AGO

Let xy be the unknown number. ==> x = tens digit, and y = ones digit.

Then from the given, 8(x+y) + 1= 10x + y, and 13(x-y) + 2 = 10x + y.
2x - 7y = 1 and -3x + 14y = 2
Proceeding with the method of elimination, we get x = 4 and y = 1.

Therefore the number is 41.

Like? Yes (1) | No (1)  

sujit   10 years AGO

4-1=3
3x13=39
39+2=41

Like? Yes (1) | No (1)  

shashank   10 years AGO

8*(x+y)+1=13*(x-y)+2
5x-21y+1=0
20-21+1=0
so 41

Like? Yes (1) | No (1)  

ashok   10 years AGO

by options
4+1=5
5*8=40
40+1=41
4-1=3
3*13=39
39+2=41

Like? Yes (2) | No (2)  

Aravinth kumar   10 years AGO

Let the two digit number be 10x + y.
Two digit number is obtained by multiplying sum of the digits by 8 and adding 1
⇒ 10x + y = 8(x + y) + 1
⇒ 2x - 7y = 1 ---------------- (1)
Two digit number is obtained by multiplying the difference of the digits by 13 and adding 2
⇒10x + y = 13(x - y) + 2
⇒ 3x - 14y = -2 ----------- (2)
Solving equations 1 and 2, we get x = 4 and y = 1.

Therefore, the two digit number is 41.

Like? Yes (1) | No (1)  

ravindra   10 years AGO

41 satifies all the conditions

Like? Yes (1) | No (1)  

K Sudharshan reddy   10 years AGO

8(x+y)+1=10x+y
13(x-y)+2=10x+y
on solving we get x=4 and y=1
so the number is 41

Like? Yes (1) | No (1)  

Nischay Jain   10 years AGO

checking the options it can solved

Like? Yes (1) | No (1)  

Rajat sadhu   10 years AGO

let the no be xy then,10x+y=8(x+y)+1=13(x-y)+2
we get x=4 and y=1
so the no. is=41

Like? Yes (1) | No (1)  

ESHA   10 years AGO

8(x+y) + 1= 10x + y, and 13(x-y) + 2 = 10x + y. and on solving these equations we get 41

Like? Yes (1) | No (1)  

shubham singh   10 years AGO

the right answer will be 41..
4+1=5
5*8=40
40+1=41
and
4-1=3
3*13=39
39+2=41
both sides is equal

Like? Yes (1) | No (1)  

Mansi Maheshwari   10 years AGO

final eqn : 5x-21y=-1

Like? Yes (1) | No (1)  

juhi   10 years AGO

8(x+y)+1=10x+y; this is the first statement
13(x-y)+2=10x+y ;this is the second statement
by solving these equations the value of x and y will be 4 and 1 then answer will 41

Like? Yes (1) | No (1)  

Jyothi P   10 years AGO

41-1=40 is divisible by 8
41-2=39 is divisible by 13 so only 41 satisfies 2 conditions,hence ans 41.

Like? Yes (1) | No (1)  

shashikanth   10 years AGO

8(x+y)+1=13(x-y)+2
on solving this we get
21y-1=5x
and
8(x+y)+1=10x+y
we get 7y+1=2x
On solving these two eqns
we get
x=4, y=1

Like? Yes (1) | No (1)  

kly   10 years AGO

8(4+1)+1=41
13(4-1)+2=41

Like? Yes (1) | No (1)  

srishti khurana   10 years AGO

bcoz 8(4+1)+1=13(4-1)+2

Like? Yes (1) | No (1)  

Jyoti Bajpai   10 years AGO

4+1=5, 5*8=40+1=41
4-1=3*13=39+2=41

Like? Yes (1) | No (1)  

ashvini kumar   10 years AGO

10y+x=8(x+y)+1>>2y-7x=1.............eq1
10y+x=13(y-x)+2>>14x-3y=2...............eq2
y=4,x=1
ans=41
correct option (9)

Like? Yes (1) | No (1)  

hemny   10 years AGO

lets number is : 10*x + y
then
8(x+y)+1 = 10*x+y //eqn1
13(x-y)+2 = 10*x+y //eqn2

here, x > y by eqn 1
by solving both eqn we will get answer as : x = 4 & y = 1

Like? Yes (1) | No (1)  

ankit sharma   10 years AGO

as per the options ..
9 suits the best

Like? Yes (1) | No (1)  

SUGAM   10 years AGO

8(a+b)+1=10a+b
13(a-b)+2=10a+b
by solving these two equations we can get the values of a & b

Like? Yes (1) | No (1)  

sundeep gullapudi   10 years AGO

by sovling we get 41 as ans :P

Like? Yes (1) | No (1)  

Vanika   10 years AGO

let the no. be 10x + y
then 8 (x+y) + 1 = 10x+ y
Solving this we get
2x - 7y=1 .....eq (1)
now by given conditon
13(x-y) +2 = 10x+y
Solving this
3x - 14y = -2 ........eq (2)
Solving eq (1) and (2)
we get x= 4
y= 1
So, no. is 41

Like? Yes (1) | No (1)  

pranoti patil   10 years AGO

41
4+1=5*8+1 or 4-1=3*13+2

Like? Yes (1) | No (1)  

MRITUNJAY KUMAR   10 years AGO

option 9

Like? Yes (1) | No (1)  

Nitish kumar   10 years AGO

(4+1)*8+1=41 and (4-1)*13+2=41

Like? Yes (1) | No (1)  

Udhayanidhi N   10 years AGO

multiplying the sum of the digits by 8 and adding 1:8(x+y)+1
multiplying the difference of the digits by 13 and adding by 2:13(x-y)+2
so.....the ans is 41.

Like? Yes (1) | No (1)  

Rahul Rathod   10 years AGO

By formulating,We get
10x+y=8*(x+y)+1.i.e. 13*(x-y)+2
by solving we get x=4,y=1;
so number =41

Like? Yes (1) | No (1)  

SAYAN CHATTERJEE   10 years AGO

10x+y = (x+y)*8+1
10x+y = (x-y)*13+1
solving we get,
x=4,y=1
so,the no. is 41. (9)

Like? Yes (1) | No (1)  

saira fatma   10 years AGO

41 as (4+1)*8+1=41
and
4-1=3*13+2=41

Like? Yes (1) | No (1)  

Ayesha khatoon   10 years AGO

it is only solved by putting the values on it....
only 41 satisfies both conditions

Like? Yes (1) | No (1)  

CHENNADI HARIKA   10 years AGO

1.(a+b)8+1=10a+b from 1st condition,
from second condtion (a-b)13+2=10a+b
by solving these equations we get 41.

Like? Yes (1) | No (1)  

Ranodeep Ghosh   10 years AGO

From The Question We Deduce That...
If Number Is Obtained by Multiplying By 8 And Adding1... The lst digit has to be either of 9,7,5,3,2,1
And If its by Multiplying By 13 And Adding 2... The last digit has to be either of 5,8,1. So, the the common numbers being 1 and 5, Sear the option for the number which ends with either 5 or 1. And then by a quick trial method we see the answer is 41

Like? Yes (1) | No (1)  

Udhaya kumar   10 years AGO

8(4+1)+1=13(4-1)+2
41=41

Like? Yes (1) | No (1)  

Avinash   10 years AGO

only 41 satisfy both condition

Like? Yes (1) | No (1)  

AMIT SINGH   10 years AGO

hit and trial...

Like? Yes (1) | No (1)  

kaushal kishor   10 years AGO

hit and trial

Like? Yes (1) | No (1)  

Soham Chakraborty   10 years AGO

by selecting the no as x.

Like? Yes (1) | No (1)  

suman kumar   10 years AGO

10x+y=(x+y)*8+1.
10x+y=13*mod(x-y)+2.
let x>y
x=4,y=1;

Like? Yes (1) | No (2)  

prince kumar   10 years AGO

8(4+1) + 1=41

13(4-1) + 2= 41

8(x + y ) + 1 = 10*x + y .......eq 1
13(x-y) +2 = 10*x + y .......eq 2

Solving the equation we get 10x+y=41

Like? Yes (1) | No (2)  

Mogilipuri.Harish   10 years AGO

8(x+y)+1=10x+y ==> 2x-7y=1

13(x-y)+2=10x+y ==> -3x+14y=2

x=4 y=1

Like? Yes (1) | No (2)  

Md.Sultan Khichi   10 years AGO

Using obtion..
41=4+1=5
5*8+1=41
Agn 41=4-1=3
3*13+2=41
Ans 41..

Like? Yes (1) | No (2)  

rakesh yadav   10 years AGO

no=(x+y)8+1=(x-y)13+2
so x=4,y=1;

Like? Yes (1) | No (2)  

Dr.Dipin Singh   10 years AGO

only one option 41 satisfies the condition
8x+1 with x=4 and checking that number with 13y+2 with y=3,.
so 41 is the desired number.

Like? Yes (1) | No (2)  

Navpreet Singh   10 years AGO

41

Like? Yes (1) | No (2)  

Tharun   10 years AGO

8x+8y-xy+1=0; 13x-13y+2-xy=0
Soving this 2 eqns
Answer is 41

Like? Yes (1) | No (2)  

sandeep yendamuri   10 years AGO

i wont tell u :P

Like? Yes (1) | No (2)  

palasiva   10 years AGO

(x+y)*8+1=(x-y)13+2
5x-21y+1=0
x=4,y=1
41

Like? Yes (1) | No (2)  

G.Mahesh   10 years AGO

(x+y)*8+1=(x-y)13+2
5x-21y+1=0
x=4,y=1
41

Like? Yes (1) | No (2)  

posirajesh   10 years AGO

41{ 4+1}5+1=41
{4-1}13+2=41

Like? Yes (1) | No (2)  

kundan khatore   10 years AGO

4+1=5 then 5*8=40 then adding 1 40+1=41

4-1=3 then 3*13=39 then adding 2 39+2=41
41=41
so ans is 41

Like? Yes (1) | No (2)  

yunus   10 years AGO

let the degit be a and b.there fore the number is ab
8(a+b)+1=13(a-b)+2
8a+8b=13a-13b+1
21b=5a+1
substitutng a=4 ,b=1
ie:21=21
hence the number is 41

Like? Yes (3) | No (4)  

M Sandeep Reddy   10 years AGO

Let xy be the number x = 10's digit, and y = 1's digit.
Then from the given, 8(x+y) + 1= 10x + y, and 13(x-y) + 2 = 10x + y.
2x - 7y = 1 and -3x + 14y = 2 by solving two equations we get 41

Like? Yes (1) | No (2)  

swarupa nuggu   10 years AGO

41

Like? Yes (1) | No (2)  

Nitish Kumar   10 years AGO

using heat and trail method....it\'s easy then solving equations,becoz here all the no. are easly calculative.
.8(4+1)+1=41 and 13(4-1)+2=41.

Like? Yes (1) | No (2)  

vivek   10 years AGO

10x+y =(x+y)*8+1
10x+y=(x-y)*13+2
by solving these equation we get, the no. is 41

Like? Yes (1) | No (2)  

lakshmi nalluri   10 years AGO

10x+y=8(x+y)+1.............>2x-7y=1...............(1)
13(x-y)+2=10x+y...................>3x-14y=-2.............(2)
on solving(1)&(2),x=4 and y=1 then number is10x+y=10*4+1=41

Like? Yes (2) | No (3)  

mamta garkoti   10 years AGO

let the number be 10x+y,
according to ques,
8(x+y)+1=10x+y and
13(x-y)+2=10x+y on simplifying, we have
2x-7y=1 and 3x-14y=-2 solving these two equations,
x=4 and y=1 hence the number=41

Like? Yes (1) | No (2)  

Jaya Velankar   10 years AGO

((4+1)*8)+1=41
((4-1)*13)+2=41

Like? Yes (1) | No (2)  

Promit Saha   10 years AGO

10x +y=8(x+y)+1
10x+y=13(x-y)+2
solving we get x=4
and y=1
so answer is 10*4+1
=41

Like? Yes (1) | No (2)  

jaya chandra   10 years AGO

ans is 41
4+1=5 => 5*8+1=41
4-1=3 ==> 3*13+2=41

Like? Yes (1) | No (2)  

G.Jaya Krishna   10 years AGO

10x + y = 8(x + y) + 1
⇒ 2x - 7y = 1
Two digit number is obtained by multiplying the difference of the digits by 13 and adding 2
⇒10x + y = 13(x - y) + 2
⇒ 3x - 14y = -2
10x + y = 8(x + y) + 1
⇒ 2x - 7y = 1
Two digit number is obtained by multiplying the difference of the digits by 13 and adding 2
⇒10x + y = 13(x - y) + 2
⇒ 3x - 14y = -2
solve we get 41

Like? Yes (2) | No (3)  

Vikas   10 years AGO

Let xy be the unknown number. ==> x = tens digit, and y = ones digit.
Then from the given, 8(x+y) + 1= 10x + y, and 13(x-y) + 2 = 10x + y.


2x - 7y = 1 and -3x + 14y = 2
Proceeding with the method of elimination, we get x = 4 and y = 1.
Therefore the number is 41.

Like? Yes (1) | No (2)  

RAVI RANJAN   10 years AGO

(4+1)*8+1=41
(4-1)*13+2=41

Like? Yes (1) | No (2)  

deepak kumar   10 years AGO

let no be xy.
then (x+y)8 +1 =xy
(x-y)13 +2 =xy
after solving xy =41

Like? Yes (1) | No (2)  

Gokul Krishnan   10 years AGO

2x - 7y = 1
3x - 14y = -2
ans=41

Like? Yes (1) | No (2)  

avishek jana   10 years AGO

by option checking 41 is the ans

Like? Yes (1) | No (2)  

jitendra varshney   10 years AGO

Let xy be the unknown number. ==> x = tens digit, and y = ones digit.
Then from the given, 8(x+y) + 1= 10x + y, and 13(x-y) + 2 = 10x + y.


2x - 7y = 1 and -3x + 14y = 2
Proceeding with the method of elimination, we get x = 4 and y = 1
Therefore the number is 41.

Like? Yes (5) | No (6)  

mounika kadudhuri   10 years AGO

Let the number be 10x+y
10x+y=(x+y) 8+1
And
10x+y=(x-y) 13+2
Solving these two equations we get
x=4 y=1
The number is 41

Like? Yes (1) | No (2)  

saurabh gupta   10 years AGO

equating:- 8(x+y)+1=13(x-y)+2


-->5x-21y+1=0

hit and try

u\\\'ll get 41

Like? Yes (1) | No (2)  

abhinaw kumar   10 years AGO

by option checking
41
(4+1)*8+1=41
(4-1)*13+2=41 ans

Like? Yes (1) | No (2)  

shikha panwar   10 years AGO

Let xy be the number.
x = tens digit, and y = ones digit.
Then from the given, 8(x+y) + 1= 10x + y, and 13(x-y) + 2 = 10x + y.
2x - 7y = 1 and -3x + 14y = 2
Proceeding with the method of elimination, we get x = 4 and y = 1.

Like? Yes (1) | No (2)  

Ankit Raj   10 years AGO

let xy be the unknown number. ==> x = tens digit, and y = ones digit.
Then from the given, 8(x+y) + 1= 10x + y, and 13(x-y) + 2 = 10x + y.

2x - 7y = 1 and -3x + 14y = 2
Proceeding with the method of elimination, we get x = 4 and y = 1.

Therefore the number is 41.

Like? Yes (1) | No (2)  

Ajay Kumar Gupta   10 years AGO

41 because (4+1)*8+1=41
or (4-1)*13+2=41

Like? Yes (1) | No (2)  

vijayalakshmi   10 years AGO

`SUM OF 41:- 4+1
5*8=40
40+1=41;

Like? Yes (1) | No (2)  

Shashi nath jha   10 years AGO

Ans

Like? Yes (1) | No (2)  

ANKUR ANAND   10 years AGO

simply looking at the options u get this answer 9) i.e. 41

Like? Yes (1) | No (2)  

Pradeep Saw   10 years AGO

Let xy be the unknown number. ==> x = tens digit, and y = ones digit.
Then from the given, 8(x+y) + 1= 10x + y,
and 13(x-y) + 2 = 10x + y.


2x - 7y = 1 and -3x + 14y = 2
Proceeding with the method of elimination, we get x = 4 and y = 1.
Therefore the number is 41.

Like? Yes (1) | No (2)  

Abhishek Tiwari   10 years AGO

let the two digit number be 10x+y
according to question :
10x+y=8(x+y)+1.............eq(1)
10x+y=13(x-y)+2...........eq(2)
solving both the equations we get :
2x-7y=1.............eq(3)
3x-14y=-2..........eq(4)
multiplying eq(3) with 2 and solving both we get :
x=4 and y=20
so the number is (10*4)+1=41
hence option (9) is correct

Like? Yes (1) | No (2)  

T.VIGNESWARA REDDY   10 years AGO

5*4+1 =3*13+2

Like? Yes (1) | No (2)  

Neel Patel   10 years AGO

suppose the number is xy=10x+y
from the question we can make
equetions: 8(x+y) +1=10x+y
—>7y+1=2x.
and 13(x-y)+2=10x+y
—> 3x+2=14y
solving 2 equetions we get x=4
and y=1
so ans is 41

Like? Yes (1) | No (2)  

Surit Datta   10 years AGO

let us assume the number is xy
so according to the question
8(x+y)+1=10x+y
13(x-y)+2=10x+y
simplifying the above to equation we get
x=4
y=1
so the two digit number is 41
thats it..

Like? Yes (1) | No (2)  

PAWAN KUMAR   10 years AGO

By putting the different nos we could see that only 41 satisfies the above criteria.

Like? Yes (1) | No (2)  

Ravi Bhalani   10 years AGO

Check by options.

Like? Yes (1) | No (2)  

HARDIP BHALANI   10 years AGO

check by options

Like? Yes (1) | No (2)  

Rajesh   10 years AGO

The equations are
Suppose, number is 10*x+y
As given, 10*x+y=(x+y)*8+1------------eq(1) (or)
10*x+y=(x-y)*13+2---------------eq(2)
on solving these eqations or substitute values from the options

Like? Yes (2) | No (3)  

Harshad    10 years AGO

check by options

Like? Yes (1) | No (2)  

Parthi Smith   10 years AGO

((a+b)*8)+1 = ((a-b)*13)+2
5a = 21b-1
therefore,
if we take 41,
5*4 = (21*1)-1
20 = 20

Like? Yes (1) | No (2)  

Vignesh   10 years AGO

4+1 = 5 ==> (5*8)+1 = 41

4-1 = 3 ==> (3*13)+2 = 41

option 9)

Like? Yes (1) | No (2)  

Anand Dwivedi   10 years AGO

10x + y.
Two digit multiplying sum of the digits by 8 and adding 1
10x + y = 8(x + y) + 1
2x - 7y = 1 ---------------- (1)
Two digit number is obtained by multiplying the difference of the digits by 13 and adding 2
10x + y = 13(x - y) + 2
3x - 14y = -2 ----------- (2)
Solving equations 1 and 2, we get x = 4 and y = 1.

Therefore, the two digit number is 41.

Like? Yes (1) | No (2)  

Arijit Acharyya   10 years AGO

if two digits is x & y
{(x+y)*8}+1={(x-y)*13}+2=xy
by observing options if x4 and y=1 then the condition satisfies
so , the number is 41

Like? Yes (1) | No (2)  

sandeep singh   10 years AGO

since 4+1=5*8+1=41
and 4-1=3*13+2=41
so number is 41

Like? Yes (1) | No (2)  

SAM   10 years AGO

(4+1)*8 +1 = 41
(4-1)*13+2 =41

Like? Yes (1) | No (2)  

gopinath   10 years AGO

if the sum of the two didits is 6 means
as it says 6*8+1=41
from the second model from 41-2(added value)=39
39 is divisible by 13
so 39/13=3(the diff of two value)
none of the answer is suitable for solve this condition so the answer is 41...

Like? Yes (1) | No (2)  

Hemadri   10 years AGO

sum of digits=4+1=5
sum of digits is multiplied by 8=5*8=40
40+1=41.
difference between numbers=4-1=3
3*13=39
39+2=41.
so ans is 41.

Like? Yes (1) | No (2)  

sayan pal   10 years AGO

The number is =10*x+y
Hence, 8*(x+y)+1=10*x+y
Or, 2*x-7*y=1 ...............eq. 1
Similarly, 13*(x-y)+2=10*x+y
Or, 3*x-14*y=-2 ...............eq. 2
Solving eq.1 & eq.2 we get;
X=4;
Y=1;
Hence , the number is 41. (ans)

Like? Yes (1) | No (2)  

Sneha   10 years AGO

4+1=5*8=40+1=41 or
4-1=3*13=39+2=41
So option 9

Like? Yes (1) | No (3)  

Nilanjan Mondal   10 years AGO

4+1=5*8=40+1=41

4-1=3*13=39+2=41

Like? Yes (1) | No (3)  

Inline Geek   10 years AGO

let x be ten's digit and y be one's of that 2 digit number
as per question

( x + y ) * 8 + 1 = ( x - y ) * 13 + 2 = number
=>
21x - 5y = 1

now apply this expression on options only 41 satisfies it.

Like? Yes (1) | No (3)  

BITU KUMAR NIRALA   10 years AGO

Let ((10*x)+y) is a number.
according to question ,
(10*x +y) = (x+y)*8 +1
and
(10*x +y) = (x-y)*13 +2
After solving x and y we get
x=4 and y=1
so number=4*10 + 1=41
Answer:-41(option:- 9)

Like? Yes (1) | No (3)  

abhilasha   10 years AGO

4+1 = 5; 5*8+1 = 41
so ans is 41

Like? Yes (1) | No (3)  

prathibha   10 years AGO

(x+y)*8+1=(x-y)*13+2

21y=5x+1

Like? Yes (1) | No (3)