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Hari Nani 10 years ago

A rectangular tank has dimensions 5 m x 3 m x 2 m. There are three inlet pipes P. Q. R, which have filling rates of 2 m3/hr. 3 m3/hr and 5 m3 /hr respectively. At 9:00 am. when the tank was empty,P was opened. Q was opened at 9 30 a.m. and R was opened at 10:30 am. The time at which the tank would be full is

Reply Like? Yes (12) | No (4)

neha gupta 10 years ago

As initially only P was opened therefore in half an hour it will fill 1m3
From 9:30 to 10:30 both p and q are opened therefore another 5m3 is filled
Remaining capacity=30-6=24m3
P+Q+R can fill 10m3 in 1 hour,
Thus no of hours after 10:30 =24/10=2.4 hours=2 hrs 24 mins
So at 12:54 am tank will be completely filled.

Like? Yes (10) | No (3)

Niladri Shekhar Dey 10 years ago

we here can get the volume of the tank as (5*3*2) m^3= 30 m^3
now if p is alone opened for 30 minute i.e half an hour ,till 9.30 1 m^3 will be filled up. then P+Q is filling it for next 1 hr so now at 10.30 1+2+3=6m^3 is filled up.
30--6=24 m^3 still left .so now the part to filled up by p is (24*(2/(2+3+5)))=4.8m^3
similerly for Q it is 7.2m^3 and for R it is 12 m^3.
They all need 2.4 hr(from calculation) i.e 2 hr 24 minutes more ... adding that to 10.30 we have 12.54 when the tank will be completely full..

Like? Yes (2) | No

Lavanya Rajendran 10 years ago

ans is 4.5 hr
in 1st 1/2 hr 1m3 is filled
thn in next 1 hr 5m3 is filled
in next 2 hr 20 m3 is filled
thn in nxt 1 hr totally in 4.5 hr all 30 m3 i.e 5*3*2=30m3 of volume is filled

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MANISH KUMAR 10 years ago

By 12:54pm the tank will be full. Hence taking 3hrs 54 mins.
The Answer : 12:54 pm

Like? Yes | No

Kashish Bhasin 10 years ago

12.54 p.m As > The the Three altogether can fill 10m3 in 1 Hour. So After 10.30 p.m., 24 m3 of Liquid is to be filled by all three of the Pipes together.

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Hari Nani 10 years ago

A group of 50 salesmen plan to achieve their target for the next 30 days by working 12 hours a day. Due to various reasons they put in only 10 hours a day for the first 15 days. Now, if 10 men leave and the rest continue working for only 10 hours a day, how many days more than the initially estimated time will they require to meet their target?

Reply Like? Yes (21) | No (2)

Devendra Marghade 10 years ago

11 1/4

Total planned man hour=50*30*12=18000
With 50 mem, 10 hrs. daily for 15 days, total man hours completed=50*10*15=7500
Remaining man hour =18000 - 7500=10500 , which is to be completed by 40 men working 10 hrs. daily, So days required to complete the remaining work=10500/(40*10)=26.25
As total time taken to complete the work=15+26.25=41.25, which is 11.25 days more than the estimated time of 30 days

Like? Yes (19) | No (5)

MANISH KUMAR 10 years ago

the answer is 11.25 days more. hence a total of 41.25 days.

Like? Yes (2) | No (1)

Puja Dhar 10 years ago

Total estimated unit of work= 50*30*12= 18000
for first 15days unit of work will be= 50*10*15=7500
for the nest case it would be=40*10*x=400x(where x is the required no of days)
then, 400x+7500=18000
or, x=26.25
total number of days will be=(15+26.25)= 41.25
that is the answer would be= (41.25-30)=11.25

Like? Yes (2) | No

Hari Nani 10 years ago

A group of men are building a wall. After half the wall has been built, double the number of men joined the original group. The wall gets completed in 6 days earlier than the scheduled. What is the total no. of days the initial group of men would have taken to complete the wall?

Reply Like? Yes (30) | No (11)

neha gupta 10 years ago

This question is of inverse variation ,It can be solved as follows:
Men Days
x y
3x y-6
So equation is:
xy=3x(y-6)
on solving we get y=9
Therefore number of days=9

Like? Yes | No (34)

Hari Nani 10 years ago

A number of crabs are kept in a jar of height 40 cm. One crab climbs up by 3 cm in a minute and in the subsequent minute it is pulled down by the other crabs by 1 cm. If this cycle of alternate up and down movements of the crab repeats until it reaches the top, then in how many minutes will the crab reach the tip of the jar?

Reply Like? Yes (19) | No (2)

neha gupta 10 years ago

In 1min it climbs 3cm and in another 1min it falls down by 1cm which implies in 2min it climbs 2cm .Therefore it will climb 40cm in 40min.
ans-40min

Like? Yes (14) | No (12)

padam singh ahlawat 10 years ago

39 minutes it take to reach the height of 40cm because crab reaches a height of38 cm in 38 minutes and it climb 3 cm in 1 minutes therefore 38 +1 =39 minutes.

Like? Yes (9) | No (8)

kishore 10 years ago

38 min

In 1 min it climbs up 3 cm and in the subsequent minute it is pulled down by 1cm
so In 2 min it will climb up by 2 cm
In 37 min it will climb 37cm
in the Next minute it will reach tip of the jar as it goes 3 cm up
so 38 min

Like? Yes (5) | No (3)

Hari Nani 10 years ago

Vivek, Rameshwar and Bhuvan divide a work amongst themselves in the ratio of 2:3:5. Their rates of work are in the ratio 1:2:3. It takes Vivek 12 days to complete his part. What is the amount of work completed by them in 8 days from the start?

Reply Like? Yes (91) | No (6)

Richi 7 years ago

4/5 yes is the answer

Like? Yes (12) | No (1)

Hari Nani 10 years ago

x+y+z=0 ; x >= 5 ; y >= -5 ; z >= -5 . how many integral solutions ??

Reply Like? Yes (2) | No

ankit 10 years ago

As per given conditions assume x=m+5 , y=n-5 , z=o-5 , where m,n,o>=0
so now equation becomes m+n+p=5
values satisfy (1,1,3) => 3 integral solution [i.e. (1,1,3),(1,3,1),(3,1,1)]
(1,2,2)=> 3 integral solution
(4,1,0)=> 3 integral solution
(3,2,0)=> 3 integral solution
so total 12 integral sol

Like? Yes (1) | No (1)

Pankaj 10 years ago

let x=a+5 y=b-5 z=c-5
put in given equation
a+b+c=5
apply combination
5C3
as we have to divide 5 into 3 parts
this can be done in 5C3 ways=10 ways

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ER. Hari
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Hari nani (M)

Total Points 295
Join 11 years ago

M4 Score

Score from best 50 Questions

Attempted 21
Date Points

23 Jul 14 15
25 Jul 14 15
28 Jul 14 15
29 Jul 14 15
31 Jul 14 15
04 Aug 14 15
05 Aug 14 15
07 Aug 14 15
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05 May 15 15

Total 315
M4 Score315 / 10 = 31

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Hari nani (M)

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