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Balajikrishnan GS 5 years ago

where should i start to prepare for aptitude?

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Anindya Adhikary 5 years ago

if y = log x(1+x), then x = ?

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Sujon Ahmed 5 years ago

The price of sugar increases by 20%, by what % should a housewife reduce the consumption of sugar so that expenditure on sugar can be same as before?

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Devendra Marghade 5 years ago

16.66%

Let initial consumption=100 & price=100, then expenditure=100*100=10000
If new consumption=x & price=120, then for same expenditure, 120x=10000
=> x=83.33
So, % reduction=100-83.33=16.66

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Ronak to Devendra Marghade 5 years ago

the students of a class appeared for an exam which had 200 questions. Each correct answer was awarded 2 Marks and for each wrong answer one-third of a mark was deducted. two student answered all the question in it. the first student got the maximum possible marks and the second student got 175 marks less than him. find the number of questions correctly answered by the second student. 1)115 2)125 3)135 4)145 ) none of.
Please solve

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Devendra Marghade 5 years ago

2) 125

Maximum possible marks, 1st student got = 2*200 = 400
.'. Marks of 2nd student = 400 - 175 = 225
Let for 2nd student, correct answers=x and wrong answers=y
Then, x + y = 200 ---(i) and 2x - y/3 = 225 ---(ii)
Solving equation (i) & (ii), we get x=125, y=75
Hence, 2nd student solved 125 correct answers.

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Sahithi Bhimavarapu 5 years ago

In a game of 80 points, A can give B 5 points and C 15 points. then how many points B can give C in a game of 60?
Devendra can you give brief Sol for this

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Ronak to Devendra Marghade 5 years ago

Two cars starts from point A and B to B and A respectively. They cross each other in 1.2 hour and the first car reaches A at 1 hour before the second car reaches B. If the distance between A and B is 50 km, what is the speed of the slower car? 1)20km/hr 2) 10km/hr 3)15km/hr 4)25km/hr........ Which is correct questions in both of. Please solve if any is correct please 🙏😊

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Devendra Marghade 5 years ago

Speed of the slower car=16.66 km/hr

Let the speed of the car starting from point A and B be a and b km/hr.
Given, car starting from B reaches A, 1 hour early => Car starting from A is slower, so we have to find 'a'
As car cross each other in 1.2 hrs => 50/(a+b) = 1.2 => a+b = 125/3 ---(i)
Time difference of cars reaching B and A = 50/a - 50/b = 1 ---(ii)
Now substituting, b=125/3 - a from eqn. (i) into (ii), we get 3a² - 425a + 6250 = 0 ---(iii)
(3a-50) (a-125) = 0
a=50/3, a=125, (Ignoring a=125 as with this speed two cars cann't cross each other in 1.2 hrs)
Therefore, speed of slower car=50/3=16.66 km/hr and faster car=25 km/hr.

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Ronak to Devendra Marghade 5 years ago

Two cars starts from point A and B to B and A respectively. They cross each other in 1 hour and the first car reaches A at 5/6 hour before the second car reaches B. If the distance between A and B is 50 km, what is the speed of the slower car? 1)20km/hr 2) 10km/hr 3)15km/hr 4)25km/hr

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Ronak to Devendra Marghade 5 years ago

Sheela, Sandhya and jyotsna can type a page in in 10, 15 and 18 minutes respectively. they decided to work together for equal time to type a document which contains 980 pages. how many pages are typed by jyotsna ? 1)280 2)275 3)245 4)350 5)none

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Devendra Marghade 5 years ago

3) 245

In 1 min, individually Sheela, Sandhya and Jyotsna can type 1/10, 1/15, 1/18 pages respectively.
Together in 1 min they can type 1/10 + 1/15 + 1/18 = 2/9 page.
For 980 pages time required = 980/(2/9) = 4410 min.
So, pages typed by Jyotsna in 4410 min = (1/18)*4410 = 245

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Ronak to Devendra Marghade 5 years ago

vimal alone can do a piece of work in 36 days. the time taken by vimal in completing 1/6th of the work equals the time taken by Gopi to complete 2/5th of the same work. in how many days can they both complete the work if they work together?

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Devendra Marghade 5 years ago

10 (10/17) days

Days required by Vimal=36. So Vimal can complete 1/6 of the work in (1/6)*36=6 days.
If Gopi takes 'x' days for same work, then days required for 2/5 of work=2x/5=6
=> x=15
Thus 1 day's work of Vimal & Gopi = 1/36 + 1/15 = 17/180
Hence, required days = 180/17 = 10 10/17

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Ronak to Devendra Marghade 5 years ago

, Q, R and S are four friends and they are working independently on a work. R can do the work in M days, whereas S can do the same work in 2M days. R started the work and worked for only 144/7 days. then, he was replaced with S, who completed the remaining work in the same time as P and Q working together would finish the entire work. the efficiency ratio of P and Q is 4:3. if P and Q are working on alternate days, with P being first, the work will finished in 41 days.

1)in how many days can R individually complete the total work?

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Ronak 5 years ago

P, Q, R and S are four friends and they are working independently on a work. R can do the work in M days, whereas S can do the same work in 2M days. R started the work and worked for only 144/7 days. then, he was replaced with S, who completed the remaining work in the same time as P and Q working together would finish the entire work. the efficiency ratio of P and Q is 4:3. if P and Q are working on alternate days, with P being first, the work will finished in 41 days.
1)in how many days can R individually complete the total work?

Reply Like? Yes | No

Devendra Marghade 5 years ago

216/7 days

Given R takes M days, so 1 day's work of R = 1/M
Similarly S takes 2M days, so 1 day's work of S = 1/(2M)
Work completed by R in 144/7 days = (1/M)*(144/7) = 144/(7M) and remaining work = 1 - 144/(7M)

Given, efficiency ratio of P and Q is 4:3.
Days required is inversely proportional to efficiency. Let P & Q can complete the work in x/4 & x/3 days respectively.
Given, P and Q are working on alternate days, with P being first, the work will finished in 41 days.
=> P works for 21 days whereas Q works for 20 days to complete the work.
=> 21*P's 1 day work + 20*Q's 1 day work = 1
21*4/x + 20*3/x = 1
=> x=144
Thus, P takes 144/4=36 days and Q takes 144/3=48 days to complete the work individually.
Now (P+Q)'s 1 day work = 1/36 + 1/48 = 7/144
.'. Together P & Q require 144/7 days = Days required by S to complete remaining work
=> (144/7)*1/(2M) = 1 - 144/(7M)
72/(7M) = (7M - 144)/7M
7M = 216
M = 216/7 = Days required by R individually to complete the work.

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Ronak to Devendra Marghade 5 years ago

If 36 persons are engaged on a piece of work, the work can be completed in 40 days. After 32 days, only 3/4 th of the work was completed. How many more persons are required to complete the work on time?
A)10
B)8
C)9
D)12

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Devendra Marghade 5 years ago

D)12

Work completed by 36 persons in 32 days=3/4
1 person's 1 days work = (3/4)/(32*36) = 1/1536
Now remaining work=1/4 and remaining days=40-32=8
So, required work in 1 day = (1/4)/8 = 1/32
Total persons required = (1/32)/(1/1536) = 48
Hence, additional persons = 48 - 36 = 12

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Ronak 5 years ago

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Ronak 5 years ago

The ratio of difference between Compound interest and simple interest at 2 year and 2.5 year is 9:17 then rate of compound interest? 1)22.22% 2)11.11% 3)18.18% 4)22.5%

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Ronak to Devendra Marghade 5 years ago

The ratio of difference between Compound interest and simple interest at 2 year and 2.5 year is 9:17 then rate of compound interest? 1)22.22% 2)11.11% 3)18.18% 4)22.5%

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Ronak to Devendra Marghade 5 years ago

A man borrows a sum of rs 96,000 at 5% p.a. interest compounded annually. At the end of one year, he repays a certain amount and he repays the balance amount of rs 70,980 at the end of the second year. What amount does he repays at the end of the first year?

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Devendra Marghade 5 years ago

Rs. 33200

Amount after 1 year = 96000*(1 + 5/100) = 100800
Let he repays Rs. x after 1 year, then amount to be paid after 2nd year=(100800 - x)*(1 + 5/100) = 70980
100800 - x = 67600
=> x=33200

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Sushma 5 years ago

For Today's puzzle, options 3 and 5 are same as 246.
Please check.

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