M4maths Previous Puzzles

13 Sep 2012 biscuit

The cost of 100 gm. packet of biscuit is 15 rupee and that of 500 gm. packet is 55 rupee. If we compare cost of equal amount then % loss in purchasing a biscuit packet of 100 gm. in comparison to 500 gm. will be

OPtion

1) 40
2) 36.36
3) 36
4) 34.33
5) 39.67
6) 45.67
7) 32.67
8) 43.63
9) 34.63
10) none of these

Solution

The cost of 100 gm. in 100 gm. packet of biscuit is 15 rupee and
The cost of 100 gm. in 500 gm. packet of biscuit is 55/5 = 11 rupee
so comparative loss = 4 rupee
so % loss in comparison to 500 gm packet = [4/11]*100 = 400/11 = 36.36

Correct Option: 2 Best Solution (0)

12 Sep 2012 distance

Distance between A and B is 250 km. A train starts from station A with speed 25 m/s towards station B and other train starts from station B with speed 60 km/hrs towards station A. After how many minutes will the trains meet?

OPtion

1) 100 min.
2) 90 min.
3) 120 min.
4) 150 min.
5) 180 min.
6) 80 min.
7) 40 min.
8) 60 min.
9) 200 min.
10) none of these

Solution

speed of first train = 25 m/s = 25*18/5 = 90 km/hrs
speed of second train = 60 km/hrs
total distance = 250 km.
so time taken = 250/(90+60) = 250/150 hrs = 5/3 * 60 min = 100 min

Correct Option: 1 Best Solution (0)

11 Sep 2012 solve

x + x^2 + y + y^3 = 16
and x = y
then no. of possible real values of x are

OPtion

1) 0
2) 1
3) 2
4) 3
5) 4
6) 5
7) 6
8) 7
9) 8
10) none of these

Solution

on putting x = y in other given equation
x + x^2 + y + y^3 = 16, we get
x + x^2 + x + x^3 = 16
or 2x + x^2 + x^3 = 16
x=2 is a root of this equation and other 2 roots are imaginary

Correct Option: 2 Best Solution (0)

10 Sep 2012 sequence

sum of 2 missing numbers of the sequence
6, ?, 20, 15, ?, 1
will be

OPtion

1) 15
2) 17
3) 19
4) 20
5) 21
6) 23
7) 25
8) 27
9) 30
10) none of these

Solution

sequence is 6C1, 6C2, 6C3, 6C4, 6C5, 6C6

6/1
6*5/2*1
6*5*4/3*2*1
6*5*4*3/4*3*2*1
6*5*4*3*2/5*4*3*2*1
6*5*4*3*2*1/6*5*4*3*2*1

Correct Option: 5 Best Solution (7)

Ajay Kashyap   12 years AGO

patten is : 6,13,20,15,8,1
as difference is as
6+7 = 13
13+7 = 20
15-7 = 8
8-7 = 1

Like? Yes (11) | No (2)  

Jason   12 years AGO

21
because in
6, ?, 20, 15, ?, 1

Sum of first and 4th term = 6+15=21
Sum of third and sixth term = 20+1=21
so sum of 2nd and 5th term should also be 21.

Like? Yes (4) | No (2)  

Pranaya   12 years AGO

6,a,20,15,b,1
if a=13 and b=8 then
13-6=7 and 20-13=7 similarly
15-8=7 and 8-1=7
a+b=13+8=21

Like? Yes (3) | No (3)  

Ganga Prasad Bhusal   12 years AGO

series will be...6,13,20,15,8,1 difference between the terms will be.7,7,5,7,7..so sum=13+8=21

Like? Yes (1) | No (3)  

ArunKumar   12 years AGO

6+ 15 = 21
20 + 1 =21
Answer 12

Like? Yes (2) | No (4)  

Narender Bhardwaj   12 years AGO

Given series is
6, ?, 20, 15, ?, 1,
=6,(6+7),(13+7),15,(15-7),(8-7),....
=6,13,20,15,8,1.....
Hence sum of missing numbers is=13+8=21 ans

Like? Yes (1) | No (3)  

sagar arora   12 years AGO

the sum of 2 nos in a series separated in a series by 2 nos is the avg of these and their extreme nos

Like? Yes (1) | No (5)  

07 Sep 2012 probability

There are 2 boxes. First contains 6 red, 5 green and 9 white balls whereas second contains 10 red, 4 green and 6 white balls. If 1 ball is selected at random from one of the boxes, then probability of getting green ball will be

OPtion

1) 1/2
2) 3/8
3) 9/20
4) 9/40
5) 11/40
6) 1/4
7) 3/20
8) 2/5
9) 1/3
10) none of these

Solution

probability of selecting box = 1/2
probability of selecting green ball from first box = 5/20
probability of selecting green ball from second box = 4/20
so net probability = 1/2(5/20) + 1/2(4/20) = 9/40

Correct Option: 4 Best Solution (0)

06 Sep 2012 cost

The cost of 1 book and 1 pen is 60 rupee. If all the costs are multiple of 5, then possible no. of outcomes for the non zero cost of 1 book and 1 pen will be

OPtion

1) 5
2) 6
3) 7
4) 8
5) 9
6) 10
7) 11
8) 12
9) 13
10) 14

Solution

possible outcomes are
5,55
10,50
15,45
20,40
25,35
30,30
35,25
40,20
45,15
50,10
55,5

Correct Option: 7 Best Solution (16)

subratverma   12 years AGO

the total cost of 1 pen and 1 book=60
let the cost of one book and one pen x and y rupess respectively..so
x+y=60
but it is given that the cost of both items in the multiple of 5..
so we will consider only values of x and y which are the multiple of 5..
so te possible outcomes are given below.
x=5,y=55
x=10,y=50

x=15,y=45

x=20,y=40

x=25,y=35

x=30,y=30

x=35,y=25

x=40,y=20

x=45,y=15

x=50,y=10

x=55,y=5
so the possible outcomes are 11..
so option 7 is correct...thanku..:)

Like? Yes (5) | No (1)  

Ajay Kashyap   12 years AGO

As 1B+1P=60
so possible outcome with non zero cost and multiple of 5 are = 11
and are
5+55 =60
10+50 =60
15+45 =60
20+40 =60
25+35 =60
30+30 =60
35+25 =60
40+20 =60
45+15 =60
50+10 =60
55+5 =60

Like? Yes (6) | No (3)  

P M Anoop Sabir   12 years AGO

min and max values of each cost are 5 and 55
no of possible outcomes=11

Like? Yes (2) | No   

B.Senthil Kumar   12 years AGO

Range is 5 to 55 so we have eleven possiblities

Like? Yes (3) | No (2)  

ranjeet kumar pal   12 years AGO

55 5,50 10,45 15,40 10,35 25,30 30,25 35,20 40,15 45,10 50,5 55

Like? Yes (1) | No   

Preetha Maniyalath   12 years AGO

Book 5,10,15,20,25,30,35,40,45,50,55
Pen 55,50,45,40,35,30,25,20,15,10,5

Like? Yes (2) | No (1)  

sainath   12 years AGO

let x and y be two positive integers...
5x+5y=60
the possible values for each x and y are (5,55),(10,50),(15,45),(20,40),(25,35),(30,30),(35,25),(40,20),(45,15),(50,10),(55,5)...
those are 11...
so option 7

Like? Yes (3) | No (3)  

Shrikant Shete   12 years AGO

All possible combinations are
(5,55), (10,50), (15,45), (20,40), (25,35), (30,30), (35,25), (40,20), (45,15), (50,10), (55,5)

Like? Yes (2) | No (2)  

ArunKumar   12 years AGO

the possible cost of one book and one pen are,
(5+55) or (10+50) or (15+45) or (20+40) or (25+35) or (25+45) or (30+50) or (35+45) or (40+20) or (45+25) or (55+5).
Therefore Total no. of outcomes are 11

Like? Yes (2) | No (2)  

Devendra Marghade   12 years AGO

1 book and 1 pen for Rs 60 can have total 11 non zero cost in multiple of 5 combinations as
Cost(book,pen)=(5,55)(10,50)(15,45)(20,40)(25,35)(30,30)(35,25)(40,20)(45,15)(50,10)(55,5)

Like? Yes (2) | No (2)  

Balakrishnan M   12 years AGO

Possible cost of Pen ={5,10,15,20,25,30,35,40,45,50,55}
Possible cost of Book = {5,10,15,20,25,30,35,40,45,50,55}
Then possible no. of outcomes for the non zero cost of 1 book and 1 pen will be = 11

Like? Yes (2) | No (2)  

Narender Bhardwaj   12 years AGO

Given cost of 1 book+1 pen=60 /-
Specify that all the values are multiple of 5 therefore possible outputs are,
5+55=60,
10+50=60,
15+45=60,
20+40=60,
25+35=60,
30+30=60,
35+25=60,
40+20=60,
45+15=60,
50+10=60,
55+5=60,Hence total number of possible outcomes are=10 ans

Like? Yes (2) | No (2)  

Gulshan Kumar   12 years AGO

Given cost of 1 book+1 pen=60
Specify that all the values are multiple of 5 therefore possible combinations are,
1)5+55=60
2)10+50=60
3)15+45=60
4)20+40=60
5)25+35=60
6)30+30=60
7)35+25=60
8)40+20=60
9)45+15=60
10)50+10=60
11)55+5=60
Hence total number of possible outcomes are=11
Hence option 7 is correct

Like? Yes (2) | No (2)  

jomon v j   12 years AGO

let 5x be price of pen and 5y be cost of pen then

5x+5y =60

x+y =12 then possible combination are

1+11 =12
2+10=12
3+9 =12
4+8 =12
5+7 =12
6+6 =12
7+5 =12
8+4=12
9+3=12
10+2=12
11+1=12

total 11 possibilties are there

Like? Yes (2) | No (2)  

Bhabatosh Das   12 years AGO

there can be such combinations (5,55),(10,50),(15,45),(20,40),(25,35),(30,30)except(30,30)others will be repeated for 2 times because first will be hold either by book or pen.so total(5*2)+1=11

Like? Yes (1) | No (1)  

sagar arora   12 years AGO

cost of 1 book and 1 pen in the multiple of 5 out of 60 can be 12
so making pairs for 1 book and 1 pen are as follows:-
5,55
10,50
15,45
20,40
25,35
30,30
35,25
40,20
45,15
50,10
55,5

Like? Yes (2) | No (3)  

05 Sep 2012 bill

Calculate bill for the following table.

Articles Cost per piece (rupee) Quantity Discount percentage
A 12.50 8 4
B 20.00 10 8
C 25.00 16 2
D 30.00 6 6

OPtion

1) 841.20
2) 823.40
3) 801.30
4) 794.90
5) 788.50
6) 730.40
7) 690.50
8) 570.40
9) 470.80
10) none of these

Solution

total bill

A 12.50*8*96/100 = 96
B 20.00*10*92/100 = 184
C 25.00*16*98/100 = 392
D 30.00*6*94/100 = 169.20

on adding these, total cost = 841.20

Correct Option: 1 Best Solution (25)

sainath   12 years AGO

A 12.5*8=100 after 4% discount 96.00 rs.
B 20*10=200 after 8% discount 200*92/100=184.00 rs.
C 25*16=400 after 2% discount 400*98/100=392.00 rs.
D 30*6=180 after 6% discount 180*94/100=169.20 rs.
so total bill is 96+184+392+169.2=841.20 rs.

Like? Yes (6) | No (4)  

P M Anoop Sabir   12 years AGO

bill amount for x%discount=cost*(100-x)/100
therefore total amount=
12.5*8*.96+20*10*.92+25*16*.98+30*6*.94=841.2

Like? Yes (1) | No   

SHUBHAM KARODIYA   12 years AGO

12.50*8=100
45 of 100=4
A cost 100-4=96
20*10=200
8% of 200
B cost 200-16=184
25*16=400
2% of 400=8
C cost 400-8=392
30*6=180
6% of 180=10.80
D cost=179.20
total cost=96+184+392+179.20=841.20

Like? Yes (1) | No   

rajendrasinh parmar   12 years AGO

for A the prize after 4 % discount(100-4 = 96) is 12.50*8*96/100 = 96
for B the prize after 8 % discount(100-8 = 92) is 20.00*10*92/100 = 184
for C the prize after 2 % discount(100-2 = 98) is 25.00*16*98/100 = 392
for D the prize after 6 % discount(100-6 = 94) is 30.00*6*94/100 = 169.2

total of all this A+B+C+D = 96 + 184 + 392 + 169.2 = 841.20

Like? Yes (1) | No   

MADHUKAR   12 years AGO

96% of 100=96
92% of 200=184
98% of 400=392
94% of 180=169.20
total= 841.20

Like? Yes (1) | No   

Md Zahid Akhtar Molla   12 years AGO

12.5*8=100
100-4=96

20*10=200
200-16=184

25*16=400
400-8=392

30*6=180
180-1.8*6=169.2

So answer will be
96+184+392+169.2=841.20

Like? Yes (1) | No (1)  

ArunKumar   12 years AGO

(12.5*8)= 100
100 - 100*4/100 = 96
(20*10) = 200
200 - 200 *8/100 =184
25*16 = 400
400- 400 * 2/100 = 392
30*6 = 180
180- 180*6/100 =169.2
Total = 841.2

Like? Yes (2) | No (2)  

Muhammad Ahmed   12 years AGO

(12.50*8-4%)+(20.00*10-8%)+(25.00*16-2%)+(30*6-6%)=841.20

Like? Yes (1) | No (1)  

phani   12 years AGO

100*96/100+200*92/100+400*98/100+180*94/100=841.2

Like? Yes (1) | No (2)  

PALASH   12 years AGO

12.50*8=100
4%of 100 is 96
20*10=200
8%of 200 is 184
25*16=400
2%of 400 is 392
30*6=180
6% of 180 is169.2
now 96
+
169.2
+184
+392=841.20

Like? Yes (1) | No (2)  

birenparekh   12 years AGO

1.12.50x8=100 dis=4 so bill1=96
2.20x10=200 dis=8 per 100 so bill2=184
3.25x16=400 dis=2 per 100 so bill3=392
4.30x6=180 dis=6 per 100 so 10.8 at 180 so bill4=169.2
So total bill=bill(1+2+3+4)=841.2

Like? Yes (1) | No (2)  

ajitha   12 years AGO

ans:841.20
12.50*8=100 then 4% percent discount --96
20.00*10=200----8% discount---184
25.00*16=400----2% discount---392
30.00*6=180----6% discount---169.20
--------
841.20

Like? Yes (1) | No (2)  

Vivek Tiwari   12 years AGO

first calculate the total cost
12.5*8=100.0
20*10=200
25*16=400
30*6=180
total=880
calculate the percentage discount on first
100*4/100=4
200*8/100=16
400*2/100=8
180*6/100=10.8
total discount=4+16+8+10.8=38.8
total paid bill=880-38.8
=841.2 hence 1 is correcrt

Like? Yes (1) | No (2)  

SDeep Bhattacharya   12 years AGO

Expenditure for article A=(12.50*8)(1-.04)=96
Expenditure for article B=(20.00*10)(1-.08)=184
Expenditure for article C=(25.00*16)(1-.02)=392
Expenditure for article D=(30.00*6)(1-.06)=169.2

So, the bill payable = 96+184+392+169.2 =841.20

Hence ,the required answer will be = 841.20

So, the correct OPTION is : 1) 841.20

Like? Yes (1) | No (2)  

Devendra Marghade   12 years AGO

Total cost after discount for A,B,C & D
A->(12.5*8)=100-4=96
B->(20*10)=200-16=184
C->(25*16)=400-8=392
D->(30*6)=180-10.8=169.2
Therefore total bill=96+184+392+169.2=841.2

Like? Yes (1) | No (2)  

Gulshan Kumar   12 years AGO

Costs for the following
A 12.50*8=100
B 20.00*10=200
C 25.00*16=400
D 30.00*6=180

Total Cost =100+200+400+180
=880

Discount
For A =4%100 =4
For B =8%200=16
For C =2%400=8
For D =6%180=10.8

Total Discount =38.8

Bill = Total Cost- Total Discount
= 880-38.8
= 841.20

Like? Yes (1) | No (2)  

Narender Bhardwaj   12 years AGO

A cost=12.50*8=100 /-
B cost=20*10=200/-
C cost=25*16=400/-
D cost=30*6=180/-
Total cost=A cost+B cost+C cost+D cost=880/-..(1)
Discount of A=4/-
Discount of B=16/-
Discount of C=8/-
Discount Of D=10.8/-
Hence Total Discount=Discount of A+Discount of B+Discount of C+Discount of D=38.8/-.....(2)
Hence Bill=Total cost-Total Discount=880-38.8=841.20/- ans

Like? Yes (1) | No (2)  

Ajay Kashyap   12 years AGO

A cost=12.50*8=100 /-
B cost=20*10=200/-
C cost=25*16=400/-
D cost=30*6=180/-
Total cost=A cost+B cost+C cost+D cost=880/-..(1)
Discount of A=4/-
Discount of B=16/-
Discount of C=8/-
Discount Of D=10.8/-
Hence Total Discount=Discount of A+Discount of B+Discount of C+Discount of D=38.8/-.....(2)
Hence Bill=Total cost-Total Discount=880-38.8=841.20/- ans

Like? Yes (1) | No (2)  

B.Senthil Kumar   12 years AGO

Total cost = 880
Discount = 38.8
880-38.8 = 841.2
So answer is option 1

Like? Yes (1) | No (2)  

deepika goyal    12 years AGO

find discount and subtract from cost price thn price for one article thn get price of all article sum all thm

Like? Yes (1) | No (2)  

Abhijit    12 years AGO

12.5*8*96/100+20*10*92/100+25*16*98/100+30*6*94/100=841.20

Like? Yes (1) | No (2)  

Balakrishnan M   12 years AGO

(8*12.50)-((8*12.50)*4%)=96
(10*20)-((10*20)*8%)=184
(16*25)-((16*25)*2%)=392
(6*30)-((6*30)*6%)=169.20
Total Amount=96+184+392+169.20=841.20

Like? Yes (1) | No (2)  

Jamil Ahmed   12 years AGO

Cost of A = (96% of 12.50)*8 = 96
Cost of B = (92% of 20.00)*10 = 184
Cost of C = (98% of 25.00)*16 = 392
Cost of D = (94% of 30.00)*6 = 169.2
Total = 96+184+392+169.2 = 841.20

Like? Yes (1) | No (2)  

vignesh waran A   12 years AGO

(Product *Quantity)* disc/100 For Each row
Then Finally Add them all

Like? Yes (1) | No (2)  

karthikvarma   12 years AGO

96+180.4+392+169.2=841.2

Like? Yes (1) | No (3)  

04 Sep 2012 perfect square

x % of x^2 % of x^3 % of an unknown integer = perfect square integer.
unknown integer will be
(x is any integer)

OPtion

1) 5
2) 9
3) 12
4) 19
5) 25
6) 32
7) 49
8) 2 options are possible
9) 3 options are possible
10) none of these

Solution

according to the given conditions
(x/100)*(x^2/100)*(x^3/100)*y = perfect square
or (x^6/10^6)*y = perfect square integer
so y should be a perfect square integer
and 3 options are perfect square

Correct Option: 9 Best Solution (0)

03 Sep 2012 sequence

1, 3, 7, 13, 21, 31, ?
? will be

OPtion

1) 33
2) 36
3) 39
4) 40
5) 41
6) 42
7) 43
8) 49
9) 53
10) none of these

Solution

1, 3, 7, 13, 21, 31, ?
successive difference = 2, 4, 6, 8, 10, so next difference will be 12
so next number = 31+12 = 43

Correct Option: 7 Best Solution (48)

Dr.Dipin Singh   12 years AGO

nth term is given by
1+n*(n-1)
when n=1, term =1+0=1
T2= 1+2*1=3
T3= 1+3*2= 7
..
..
T7 = 1+7*6=1+42=43

Like? Yes (18) | No (8)  

Sukh   12 years AGO

1, 3, 7, 13, 21, 31, ?
1+2=3
3+4=7
7+6=13
..
..
31+12=43

Like? Yes (14) | No (7)  

parul mishra   12 years AGO

option(7)
the sequence is following as.
1^2-0=1
2^2-1=3
3^2-2=7
4^2-3=13
5^2-4=21
6^2-5=31
now 7^2-6=43

Like? Yes (4) | No (2)  

ritesh dhawale   12 years AGO

the diff. between each no. is in the form of 2 4 6 8 10 12 so 31+12=43

Like? Yes (2) | No   

pallavi sahu   12 years AGO

boz the no of diffrence is 6,8,10,12.........

Like? Yes (2) | No   

mahesh   12 years AGO

each number to add +2,+4,+6,+8,+10
then last no. to add +12
then our ans is 43

Like? Yes (3) | No (1)  

A J V   12 years AGO

The difference of the sequence is the multiplication of 2.

Like? Yes (5) | No (5)  

SHUBHAM KARODIYA   12 years AGO

3-1=2
7-3=4
13-7=6
21-13=8
31-21=10
hence next term is 43 as 43-31=12
the diffrence of succesive term form the table of 2.

Like? Yes (1) | No (2)  

Preetha Maniyalath   12 years AGO

2 4 6 8 10
next difference will be 10+2
=12
number 31+12=43

Like? Yes (4) | No (5)  

Balakumaran N.A   12 years AGO

sequence increasing by 2,4,6,8,10,12...

Like? Yes (3) | No (5)  

thangamari   12 years AGO

3-1=2*1
7-3=2*2
13-7=2*3
21-13=2*4
31-21=2*5
x-31=2*6
=>x=12+31
=>x=43

Like? Yes (4) | No (6)  

susmit   12 years AGO

DIFFERENCE IN NUMBERS IS
2,4,6,8,10
SO THE NEXT DIFFERENCE IS 10+2=12
HENCE THE NEXT NUMBER IS 31+12=43.. OPTION NO.7

Like? Yes (3) | No (6)  

sagar arora   12 years AGO

every step multiple of 2 is being added

Like? Yes (2) | No (5)  

SDeep Bhattacharya   12 years AGO

Let's calculate {Tn – T(n-1) } for the given sequence.
Where Tn & T(n-1) respectively are the nth and (n-1)th terms of the given sequence.
Now, clearly calculating {Tn – T(n-1) } for the given sequence we get :
2,4,6,8,10,(T7-31)
So, definitely the next term of the above sequence will be : 12.
Therefore,(T7-31)=12
=>T7=43
So, OPTION 7)43

Like? Yes (2) | No (5)  

Ajay Kashyap   12 years AGO

difference between terms is as: 2,4,6,8,10,12
so next term will be : 31+12 =43

Like? Yes (3) | No (6)  

Narender Bhardwaj   12 years AGO

Given series 1, 3, 7, 13, 21, 31,...
=1+(2+1)+(3+4)+(7+6)+(13+8)+(21+10)+....
Hence next term=31+12=43 ans

Like? Yes (1) | No (5)  

PARAG KAMRA   12 years AGO

1+2=3
3+4=7
7+6=13
13+8=21
21+10=31
31+12=43(ans)

Like? Yes (2) | No (6)  

lala   12 years AGO

k(n) = k(n-1) +2(n-1) with k(1) =1
k(7) =k(6) +2(7-1)
k(7) =31 +2*6
k(7) =31+12
k(7) =43

Like? Yes (1) | No (5)  

jyotish r   12 years AGO

the differences of adjacent terms forms the sequence of even numbers 2 4 6 8 10
so next difference=12
so next term in the given sequence is 31+12=43

Like? Yes (2) | No (6)  

ArunKumar   12 years AGO

1
1+2 =3
3+4 =7
7+6=13
13+8= 21
21+10=31
31+12=43

Like? Yes (1) | No (5)  

vishnukarthick   12 years AGO

(7) 43
series 1, 3 ,7 ,13 ,21 ,31
k(n) = k(n-1) +2(n-1) with k(1) =1
k(7) =k(6) +2(7-1)
k(7) =31 +2*6
k(7) =31+12
k(7) =43
seventh term of series is 43

Like? Yes (1) | No (5)  

swati   12 years AGO

1+2=3
3+4=7
7+6=13
13+8=21
21+10=31
31+12=43......so..on
each number is added by multiple of 2

Like? Yes (3) | No (7)  

richa   12 years AGO

The difference between each number is of 2's table
1+2=3
3+4=7
7+6=13
so 31+12=43

Like? Yes (1) | No (5)  

Devendra Marghade   12 years AGO

The series is
1+2=3
3+4=7
7+6=13
13+8=21
21+10=31
31+12=43

Like? Yes (1) | No (5)  

ajitha   12 years AGO

ans:43
1, 3, 7, 13, 21, 31
| | | | | |
1+0^2 2+1^2 3+2^2 4+3^2 5+4^2 6+5^2 ..7+6^2=43
The series is 1,3,7,13,21,31,43...

Like? Yes (1) | No (5)  

Balakrishnan M   12 years AGO

1, 3, 7, 13, 21, 31, ?
difference of the seq is 2,4,6,8,10,..
next term is 31+12=43

Like? Yes (1) | No (5)  

kumara swamy D G   12 years AGO

even numbers(2,4,6,8,10)31+12=43 increasing

Like? Yes (1) | No (5)  

Ganga Prasad Bhusal   12 years AGO

3-1=2
7-3=4
13-7=6
21-13=8
31-21=10
so 43-31=12
hence ANS=7)43

Like? Yes (1) | No (5)  

karthikvarma   12 years AGO

sequence is adding with 2 ,+4,+6,+8
so our answer is 31+12=43

Like? Yes (1) | No (5)  

Vikas Bhutada   12 years AGO

Series increases by multiples of 2's (2, 4, 6, 8, ...)

Like? Yes (1) | No (5)  

krutika patidar   12 years AGO

3-1=2
7-3=4
13-7= 6
21-13=8
31-21=10
so 31+12=43

Like? Yes (1) | No (5)  

Pradeep   12 years AGO

Simply find the differnce between the consequetive integers. Here it comes to be 3-1=2, 7-3=4,21-13=8,31-21=10, therefore next differnce should be of 12 Hence, 31+12=43

Like? Yes (1) | No (5)  

Rakesh Kumar Kohli   12 years AGO

The nth term of the series are
1, 1+2 , 3+4, 7+6, 13+8, 21+10, 31+12=43 ,.....

Like? Yes (1) | No (5)  

birenparekh   12 years AGO

difference between two numbers are 2,4,6,8,10..so next number will be 31+12=43...so ans is option 7

Like? Yes (1) | No (5)  

Leena Sahani   12 years AGO

1+2 = 3
3+4 = 7
7+ 6 = 13
13+ 8 = 21
21+10 = 31
31+12 = 43

Like? Yes (1) | No (5)  

Ashita Kaushik   12 years AGO

1+2=3
3+4=7
7+6=13
13+8=21
21+10=31
31+12=43
hence the answer is 43

Like? Yes (1) | No (5)  

phani   12 years AGO

differences:2,4,6,8,10,12,..................

Like? Yes (1) | No (5)  

jagannathan   12 years AGO

there is addition in series starting with +2

Like? Yes (1) | No (5)  

prem kumar.s   12 years AGO

1+2=3
3+4=7
7+6=13
13+8=21
21+10=31
31+12=43...
so ans is 43 and option 7th is correct

Like? Yes (2) | No (6)  

VIVEK SINGH   12 years AGO

1+2=3
3+4=7
7+6=13
13+8=21
21+10=31 &
31+12=43
every next digit is added by 2,4,6,8,10 so next wil be come by adding 12

Like? Yes (2) | No (6)  

kiran ks   12 years AGO

the successive nums are having differences 2,4,6,8,10 and 12

Like? Yes (1) | No (5)  

ramadevivalli   12 years AGO

the difference is in 2,4,6,8,10,.. sequence
next we have to add 12 to 31 and the answer is 43

Like? Yes (1) | No (5)  

Madhu   12 years AGO

the sequence is,
1+2,3+4,7+6,13+8,21+10,31+12
each is added with multiples of 2.

Like? Yes (1) | No (5)  

Susanta Kar   12 years AGO

as the difference between two subsequent nos are gradually increasing like 2,4,6,8,10.
so next will be 12.
so,no is = 31+12 = 43

Like? Yes (1) | No (5)  

ASWARTHA   12 years AGO

1+2=3
3+4=7
7+6=13
13+8=21
21+10=31
31+12=43

Like? Yes (1) | No (5)  

sainath   12 years AGO

the sequence follows T(n+1)=Tn+2*(n)
where Tn is nth term...
so T7=T6+2*(6)=31+12=43...

simply 1,(1+2)=3,(3+4)=7,(7+6)=13,(13+8)=21,(21+10)=31, finally (31+12)=43...

Like? Yes (2) | No (7)  

ABHINAV KUMAR SINHA   12 years AGO

1+2=3
3+4=7
7+6=13
13+8=21
similarly 31+12=43

Like? Yes (1) | No (6)  

TazimAhemad   12 years AGO

Add 2 in increasing manner
1+2=3
3+4=7
7+6=13
13+8=21
21+10=31
31+12=43
So ans is 43

Like? Yes (1) | No (6)  

31 Aug 2012 average

average of 10 numbers is 9 and average of 9 numbers is 9.3. What will be the 10th number.

OPtion

1) 9
2) 9.3
3) 6
4) 6.3
5) 5
6) 5.6
7) 3.9
8) 10.2
9) 8.9
10) none of these

Solution

average of 10 numbers is 9 so total = 90
average of 9 numbers is 9.3 so total = 83.7
so 10th number = 90-83.7 = 6.3

Correct Option: 4 Best Solution (0)