R76 = 76/18 (18 is the position of R in English alphabet)
On solving this division problem we get 4 as quotient (D is the fourth letter of English alphabet) and 4 as reminder hence code is D4
Similarly for others.
In a coded language
If "WHAT IS YOUR NAME" - ABH
"HOW ARE YOU" - BG
"WHAT ARE YOUR SUBJECTS" - CHD
Then "WHO IS YOUR FRIEND" is coded as
OPtion
1) DD
2) BDA
3) AD
4) ADD
5) CDH
6) GHA
7) IDH
8) ADB
9) DAD
10) AEC
Solution
In this coded language
WHAT IS YOUR NAME
= 4244 (according to the number of letters used in the corresponding word)
On multiplying these numbers we get 4*2*4*4 = 128
In alphabetic order these are equivalent to A, B, H
Similarly for others
Position of all the letters used in ABHISHEK are
ONE TWO EIGHT NINE NINETEEN EIGHT FIVE ELEVEN
Total letters used in this expression are 38
In AKSHAY position of all the letters used are
ONE ELEVEN NINETEEN EIGHT ONE TWENTY-FIVE
Total letters used in this expression are 35
In ARJUN position of all the letters used are
ONE EIGHTEEN TEN TWENTY-ONE FOURTEEN
Total letters used in this expression are 31
similarly for AMITABH position of all the letters used are
ONE THIRTEEN NINE TWENTY ONE TWO EIGHT
Total letters used in this expression are 32, hence the code
(16, 8, 36), (28, 11, 48), (12, 7 ,32) are 3 set of integers according to some mathematical operations,
a similar set based on the similar operations are
All 26 letters A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
in English alphabet are divided into 2 category
If one of the category contains A H M V Z ......etc
And other contains C G J O U ..........
Then which one of the following set contains all the letters of the same category
OPtion
1) E F G T
2) B C I Y
3) C G L T
4) D H M R
5) A K R X
6) A E I N
7) O P U Y
8) I L N R
9) B K W X
10) C F L Y
Solution
In this distribution all the letters having any curved part in it are taken in a category whereas letters
having no curved part are taken in other category
First category contains B C D G J O P Q R S U
Second category contains A E F H I K L M N T V W X Y Z
Let marks of Amit is x
Then according to given condition marks of Suraj is 1.1x
Difference of marks is 1.1x – x = 0.1x
Hence marks of Amit are (0.1x/1.1x)*100 = 100/11 = 9.09 % less than marks of Suraj.
Here (32+57+48) is solved in the following manner
First divide 57 by 32, we get 1 and 25 as reminder then divide 48 by reminder we obtain 1 and 23 as
reminder hence the result code is 11/23. Similarly in second case (27+62+51), first divide 62 by 27
we get 2 and 8 as reminder then divide 51 by reminder we obtain 6 and 3 as reminder hence the result code is 26/3, similarly for others.
In a coded language some words and their coded sets are given below
Word Coded set
RAM {A,C,H}
KRISHNA {A,D,H,I}
SHIV {D,H,I}
Then coded set for HANUMAN is
Positional value of letters of word RAM are 18, 1, 13 respectively
Coded values are 1*8, 1, 1*3
= 8, 1, 3
Letter of these positions are H, A, C, hence the coded set
Similarly Positional value of letters of word KRISHNA are 11, 18, 9, 19, 8, 14, 1 respectively
Coded values are 1*1, 1*8, 9, 1*9, 8, 1*4, 1
=1, 8, 9, 9, 8, 4, 1
Letter of these positions are A, H, I, I, H, D, A,
Hence coded set is {A, D, H, I}
similarly for others.
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