The present age of a brother is 7 years more than three times the age of his sister. Nine years hence, brother’s age will be 6 years more than twice the age of the sister. Find the present age of the brother.
Let the sister’s present age be ‘n’ years.
=> brother’s present age = (3n + 7) years
So, according to the question
(3n + 7 + 9) = 2 (n + 9) + 6
=> 3n + 16 = 3n + 24
=> n = 8
Hence, brother’s present age = (3n + 7) = 31 years
A man goes down stream with a boat to some destination and returns upstream to his original place in 8 hours. If the speed of the boat in still water and downstream are 12km/hr and 15km/hr respectively, the distance of the destination from the starting place in KMs is
Divide Rs. 21411 into 3 parts so that their amount after 2,3 and 4 years respectively may be equal, the rate of interest being 5% per annum at simple interest. The second part is
Let the parts be x, y and z
x + (x * 2 * 5/100) = y + (y * 3 * 5/100) = z + (z * 4 * 5/100)
11x/10 = 23y/20 = 6z/5 = k
x = 10k/11, y = 20k/23, z = 5k/6
But x + y + z = 21411
10k/11 + 20k/23 + 5k/6 = 21411
k = 8197.2
y= (20/23)*8197.2 = 7128
Option 4)
When A covers 500m B Covers 420m
When A Covers 500m C covers 480m
A : B = 500 : 420
A : C = 500 : 480
C/B = (C/A*A/B) = (480/470) = 480:420
When C covers 480 m, B covers 420 m.
When C covers 700 m, B covers (420/480)*1200)m = 612.5
Therefore, C beats B by (700 - 612.5) m = 87.5 m.
Jallaluddin went to buy 5 chocolates worth Rs. x. He gave Rs.200 rupee note to the shopkeeper to buy the chocolates then shopkeeper gave rest of the money in the denominations of 50 paise, 2 rupee, and 10 rupees. If the ratio of the number of coins is 18:13:9 respectively. Then what is the price of two chocolate?
Let a = the age of the younger brother now
a+6 = the age of the older brother now
given:
In 6 years:
a+6 = the age of the younger brother
a+6+6 = the age of the older brother