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Ravi Kiran 10 years ago

Please send recent amcat papers to mr.ravikiranrkulkarni@gmail.com

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Saikiran to karthikeyank 10 years ago

hello sir, plz mail me previous TCS papers to saikiranchepuri35@gmail.com....Thanks in Advance..Sai

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Pradeep Saw to RAKESH 10 years ago

A sphere is cut into 4 identical pieces after it was painted. What is the ratio of the painted area to the unpainted area?

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sharathbabu 10 years ago

A container contains a mixture of two liquids P and Q in the ratio 7 : 5. When 9 litres of mixture are drawn off and the container is filled with Q, the ratio of P and Q becomes 7 : 9. How many litres of liquid P was contained in the container initially?

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Aftab Alam 10 years ago

the series
2,44,4,41,6,38,8,?

Reply Like? Yes (1) | No

Saravanan NK 10 years ago

2,4,6,8
so,
44-3,41-3,38-3=35

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ravi prakash 10 years ago

answer is 35
44-3,41-3,38-3=35

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Aftab Alam to RAKESH 10 years ago

[jayapriya]
complete the series
2,44,4,41,6,38,8,?

Reply Like? Yes (2) | No

Farzand Bawa 10 years ago

This is a combination of 2 series.
1-2,4,6,8..
2-44,41,38..
So after 8 the number would be 35.

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Ram 10 years ago

2*1, 44, 2*2, 44-3, 2*3, 41-3, 2*4, 38-3, 2*5
so answer is 35

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Sreenivasan 10 years ago

wat is the remainder wen 29^31^301 divided by 9

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Saravanan NK 10 years ago

(2^5)^31)^301
(2^105)^301
2^46655/6
2^7775/9
2^5=5

so remainder is 5

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miraj ansari 10 years ago

Finally i placed in TCS...that all because of M4maths....thank u soooooo much for helping me guys....

Reply Like? Yes (3) | No

Soushikta 10 years ago

can you please tell me which topics I should practice and can you please mail me the questions you remember?

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Pankhuri Kansal 10 years ago

Plzzz send me some questions of TCS paper on kansalpankhuri@gmail.com

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Ravi Kiran 10 years ago

Congrats bro! How did u crack it???
Please share

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Subrata Patra 10 years ago

hiii
hiiiii
hiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii

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Shiksha Tiwari 10 years ago

chutiye galat answer diya to #include

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Pradeep Saw 10 years ago

A sphere is cut into 4 identical pieces after it was painted. What is the ratio of the painted area to the unpainted area?

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Abhrajyoti Sarkar 10 years ago

if you think just for one piece the ratio should be painted : unpainted = ( 4*pi*r^2)/4: ((pi*r^2)/2+(pi*r^2)/2)=1:1 and else if for all the 4 pieces then ( 4*pi*r^2): (pi*r^2+pi*r^2) ie 2:1

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Pradeep Saw 10 years ago

A sphere is cut into 4 identical pieces after it was painted. What is the ratio of the painted area to the unpainted area?

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parimala to karthikeyank 10 years ago

Sir, TCS is visiting my college on 17th of this month. Kindly send me recent aptitude questions on parimala.jillella@gmail.com

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VIVEK KUMAR GAUTAM 10 years ago

vivekgautam91@gmail.com....plzz send me!!

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keerthana 10 years ago

visit campus gate website it will be useful

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gomathi 10 years ago

Eesha bought 18 shapeners for Rs.100.she paid 1 rupees more for each white shaperners than for each brown sharperners.what is the price of a white sharperner and how many white sharpener did she buy?

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lakshmi nalluri 10 years ago

w+b=18,let r be cost of brown sharpener,then white will of (r+1) cost
100=(r+1)w+r(18-w)=rw+w+18r-rw=w+18r
let r be 5 then w be 10,so b will be 8
cost of white =10*6=60,num of white=10,each white costs6/-

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jayapriya 10 years ago

complete the series
2,44,4,41,6,38,8,?

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CHINNI SIVA NAGARAJU 10 years ago

35,10
2,4,6,8,10
44-3=41
41-3=38
38-3=35

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thiyagu 10 years ago

the answer is 35

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Himanshu Gupta 10 years ago

35..2 series going on
2,4,6,8 and 44,41,38,35

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swapnil saxena 10 years ago

it consist of 2 series the one (2,4,6,8) increasing by 2 and other (44,41,38) decreasing by 3 hence the next will be 35,10 n so on?

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lakshmi nalluri 10 years ago

35
44-3,41-3,38-3,35-3............=44,41,38,35
2,4,6,8,10,...............=2,4,6,8,10

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Udaybhan Viswkarma 10 years ago

2,4,6,8 and 44,41,38 then 35

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yuvaraj 10 years ago

find the remainder (32^31^301)/9

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thiyagu 10 years ago

32^9331/9 we get the remainder 5

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abhineel to karthikeyank 10 years ago

Sir, TCS is visiting my college on 22nd of this month. Kindly send me aptitude questions on abhineelrai007@gmail.com

Reply Like? Yes (1) | No

Naveen 10 years ago

submit this exam detail at http://www.m4maths.com/all-job-exam.html then you can discuss with the user who are going to attend this exam.

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Deepak Naresh C 10 years ago

which college u r from

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ramjianand 10 years ago

A man goes upstream for a distance of 10 km in 5 hours. Another man goes the same distance downstream in 3 hours.What is the difference of the two speeds of the men if the river speed is 0.5kmph ? ( round to nearest decimals)

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B.Akhilesh 10 years ago

A circle has 29 points arranged in a clockwise manner numbered from 0 to 28, as shown in the figure below. A bug moves clockwise around the circle according to the following rule. If it is at a point i on the circle, it moves clockwise in 1 second by ( 1 + r ) places, where r is the reminder ( possibly 0 ) when i is divided by 11. Thus if it is at position 5, it moves clockwise in one second by ( 1 + 5 ) places to point 11. Similarly if it is at position 28 it moves ( 1 + 6 ) or 7 places to point 6 in one second. If it starts at point 23, at what point will it be after 2012 seconds?

1) 1
2) 7
3) 15
4) 20

Reply Like? Yes (4) | No

RAMYA MURUGAN 10 years ago

using the HCF OF 2012 AND 23,THEN WE GET A MAXIMUM POSITION ,SO THE MAXIMUM POSITION IS 1.

Like? Yes (1) | No

anu mishra 10 years ago

We can see a pattern emerging in the point positions from the 3rd second
onwards…1, 3, 7, 15, 20 and then the cycle keeps repeating. After 5 s, 10 s, 15 s,
the bug’s position is 7. So after 2010s, the position should be 7. The position
after 2011s is 15, and after 2012s it is 20.

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ramesh 10 years ago

here you r using table

time in sec position reminder (1 + r ) new position
1 sec 23 1 1+1=2 23+2=25
2 sec 25 3 1+3=4 25+4=29=0
3 sec 0 0 1+0 0+1=1
4 sec 1 1 1+1=2 1+2=3
5 sec 3 3 1+3=4 3+4=7
6 sec 7 7 1+7=8 7+8=15
7 sec 15 4 1+4=5 15+5=20
8 sec 20 9 1+9=10 20+10=30=1
9 sec 1 1 1+1=2 1+2=3
10 sec 3 3 1+3=4 3+4=7
and so on this process continue up to end
so 3 sec, 8 sec, 13 sec, 18 sec, and so on ............2008 sec later the position is 1 position,
2009 sec the position is 3,
2010 sec the position is 7,
2011 sec the position is 15
2012 sec the position is 20

so the position is 20th position.

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Naveen 10 years ago

this is my first comment testing

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Akanksha Mishra to RAKESH 10 years ago

integration of
(2x^12 + 5x^9)/(x^5 + x^3 +1)

Reply Like? Yes (2) | No

RAKESH 10 years ago

divide (2x^12 + 5x^9) by (x^5 + x^3 +1) & then use partial fraction

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nandita shrivastava to Niveditha Ravichandran 10 years ago

hi niveditha ..how did it go..did u crack?

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ch.jyothsna to karthikeyank 10 years ago

sir pls mail me tcs latest papers to chilukurijyothsna99@gmail.com sep 6th i had drive sir plss

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ch.jyothsna to Varsha 10 years ago

pls mail me tcs questions to chilukurijyothsna99@gmail.com

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lakshmi 10 years ago

If u get tcs question papers pls mail me . my mail id is kalailakshmii21@gmail.com

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Bavana Sekhar 10 years ago

if u have recent tcs questions pls mail to kalpana.bornleader@gmail.com

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divya 10 years ago

Guys dose who have attended for tcs written test today, please post the questions or mail me to kuchipudidivyachowdary123@gmail.com.Plzz its urgent we r having written test on saturday i.e. on 6th. So please help me

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apeksha 10 years ago

yaar plz,thn after 6th mail me the questions of tcs at apekshag2@gmail.com..all the best..

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kotteswaran 10 years ago

Hi friend, could you please send me tcs question papers to my email (kottestom@gmail.com) ,iam having written test by next week,and i wish all the best for your written exam.

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kishan 10 years ago

if u get tcs paper then plz send me at kishanyadav1280@gmail.com ...

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Pankhuri Kansal 10 years ago

Plzzz yaar mail me too..on kansalpankhuri@gmail.com

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Bavana Sekhar 10 years ago

pls send the recent tcs questions to kalpana.bornleader@gmail.com

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dinesh 10 years ago

when we multipy certain two digit number by the sum of its digit 144 is achieved if we reverse the number and multiply it by the sum of the digits we get 252 what is the last digit of the original number

give me an answer

Reply Like? Yes (1) | No

Vijay Menaria 10 years ago

let the two digit of no. x,y
then no. will be 10x+y
given (10x+y)(x+y)=144 ........1
if no. is reversed then no. will be 10y+x
given (10y+x)(x+y)=252 ..............2
solve equ 1 and 2
x=2
y=4
no. will be 24
last digit 4

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aanchal sharma 10 years ago

(68)^5 /7 gives remainder

Reply Like? Yes (2) | No

Nomendra Sinha 10 years ago

3 ans.
(7*10-2)^5
7*10 is multiple of 7 so it won't give remainder.
(-2)^5 =(-2)^4 (-2)=16*(-2)=(7*2+2)(-2)=2*5=10
(-2 remainder or 7-2=+5 is same)
10/7=3

Like? Yes (3) | No (1)

Nomendra Sinha 10 years ago

or (-2)^5=-32
-32/7=-4 remainder or +3 remainder

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shivendra kumar 10 years ago

ans is 3 here...

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abhishek kumar 10 years ago

Using remainder theorem (68^5)/7 gives rem as 3

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prashant trivedi to Varsha 10 years ago

plz post paper or mail me tommorow there is driv at my college
prashanttrivedi39@gmail.com

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sathish kumar.s 10 years ago

Allways keep smiling......

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Nitesh Sarangi 10 years ago

In base 7, a number is written only using the digits 0,1,...6. The number 21 in base 7 is equal
to 2*7+1 =15 in base 10. Similarly the number 135 in base 7 is 1 x 7^2 + 3 x 7 + 5 = 75 in base
10. What is the sum of the base 7 numbers 1234 and 6543 in base 7?
a) 11110
b) 11011
c) 10111
d) 11101

Reply Like? Yes | No

ranjithreddy 10 years ago

1234+6543=11110.
Just a simple logic 4+3 is 7,we don't have digit 7 in base 7 format.we will write it as 10

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Prasanth to karthikeyank 10 years ago

Sir please send the latest TCS apptitude questions that you collected at j35007s@gmail.com. soon as i have got TCS drive on sep 6

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Pankhuri Kansal 10 years ago

How was ur TCS apti??? plzz mail me some qusetions if u remember...on kansalpankhuri@gmail.com

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yunus to khushboo 10 years ago

The times taken by a phone operator to complete a call are 2,9,3,1,5 minutes respectively. What is the average time per call?
a) 4 minutes
b) 7 minutes
c) 1 minutes
d) 5 minutes

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vamsi 10 years ago

a)4 min
avg of numbers is 4

Like? Yes | No (3)

keerthy reddy 8 years ago

avg is 4 minutes

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shanthisri to sahitya 10 years ago

A closed cylindrical tank contains 36 pie cubic feet of water and it’s filled to half its capacity. When the tank is placed upright on its circular base on level ground, the height of water in the tank is 4 feet. When the tank is placed on its side on level ground, what is the height, in feet, of the surface of the water above the ground?

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shivendra kumar 10 years ago

3 feet..
is the ans.

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shanthisri 10 years ago

can u explainn ur answer shivendra??

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shivendra kumar 10 years ago

36 pie is half capacity..hence 72 pie is full.
hence 1/3*pie*r*r*h=72 hence here h will be 8 unit.& then r will be 3 unit.
in side ways for half capacity radius will be required height.

Like? Yes (1) | No

priyanka to RAKESH 10 years ago

A series is given as 1,6,7,13,20,33,........and so on. Find the sum of first 52 terms.

a]19284756374
b]243768954321
c]287621088425
d]357849113670

Reply Like? Yes (4) | No

Sandeep Kumar 10 years ago

The given series is Fibonacci series and range will be high.

Like? Yes | No

RAKESH 10 years ago

1+6 = 13-6
1+6+7 = 20-6
1+6+7+13 = 33-6
sum upto Nth term is (N+2)nd term - 6
so, sum of first 52 terms = 54th term - 6

i think 54th term should be given in paper
if nt then u can find it from options by adding only unit digits of all terms

Like? Yes (7) | No

Ram 10 years ago

Answer is Option b

Like? Yes (1) | No

Manideep to miraj ansari 10 years ago

If C leaves before 3 days,Then y will u include C's work???
Actually we need to include only B's work in those 3 days na...
Explain it now??

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miraj ansari 10 years ago

sorry it was wrongly written..

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sanjana 10 years ago

66. During a special sale, the shop assistant was supposed to reduce the marked price of each article by 15%. For a particular item, he made a mistake and increased the marked price by 15%. Consequently for that item, the customer had to pay Rs.540 more than what he would have paid if the price was correctly reduced by 15%. What was the price paid by the customer?
(1) 1800 (2) 2070 (3) 2340 (4) 2000 (5) None of these

Reply Like? Yes | No

shivendra kumar 10 years ago

2070..
is the answer.

Like? Yes (1) | No

prashant trivedi 10 years ago

(30/100)P=540 so P=1800
(1800*115)/100= 2070

Like? Yes | No

Manideep to prasad polineni 10 years ago

How 4+3=7???
If A works for 2 days,and C leaves before 3 days.

Reply Like? Yes | No

Manideep to Navdeep Singh 10 years ago

I didn't get ur answer.Will u explain it claearly??

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RISHAN KHAN 10 years ago

manideep bhai...can u tell me what ques were asked in tcs exam which u gave......plz

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gagandeep singh to Triloki Shaw 10 years ago

last two digit of 1122^1122! den in this case bro as u sai after 4!,0

Reply Like? Yes | No

shivendra kumar 10 years ago

76...
is the answer.

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NISHANDHINI CAROUNA 10 years ago

How many polynomials of degree >=1 satisfy f(x2)=[f(x)]2=f(f(x)
a) more than 2
b) 2
c) 0
d) 1

Reply Like? Yes | No

ranjithreddy 10 years ago

Answer is d.Only one polynomial will sastisfy the given condition and the polynomial is X^2.

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V Priyanka to RAKESH 10 years ago

base 7 can be formed using digits 0,1,2,3,4,5,6.135 as base 7. then 1*72+3*7+5.pls give solution ... rakesh

Reply Like? Yes | No

saikeerthana 10 years ago

A circle circumscribes three unit circles that touch each other. What is the area of the larger circle? Note that is the ratio of the circumference to the diameter of a circle ( 3.14159265). please answer this question soon if possible kindly include diagram

Reply Like? Yes | No

divya sri 10 years ago

product of the non co prime factor is 60.how many such pairs are possible?

Reply Like? Yes | No

MONA 10 years ago

If there are 30 cans out of them one is poisoned if a person tastes very little he will die
within 14 hours so if there are mice to test and 24 hours to test, what is the minimum no. of
mice’s required to find poisoned can?

Reply Like? Yes | No

shivendra kumar 10 years ago

i think one mice is answer....if 1 mice taste can with the gap of 20minute then 3 can will be tested in 1 hour.
if we have watch then note the timing & decide the can no according to his death..

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Gurkiran Kaur to dhivya 10 years ago

hey dear kindly send me tcs recent papers pls @kirankaurgkk@gmail.com ... n all the best :)

Reply Like? Yes | No

Pradeep Saw 10 years ago

No. of rectangles in a chess board????

Reply Like? Yes | No

radha 10 years ago

1296...
shud be the answer

Like? Yes | No

shivendra kumar 10 years ago

1296..
is correct..

Like? Yes | No

prashant trivedi 10 years ago

((n + 1)^2) x(( n^2) / 4) put n=8 ans = 1296

Like? Yes | No

sharvan kumar 10 years ago

may i seat in tcs campus placement if i have a backlog?

Reply Like? Yes | No

radha 10 years ago

in my university 1 backlog is allowed

Like? Yes | No

Pradeep Saw 10 years ago

its vary from campus to campus..........

Like? Yes | No

raviteja 10 years ago

yes backlog is allowed but,they allow only 1 at the time of joining you should complete that backlog

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Sowmiya 10 years ago

KarthikeyanK sir!!!!!!! Can u pls mail me the recent question papers of tcs.....................I have my tcs apti test on sept 10th............Pls do help................

Reply Like? Yes | No

radha 10 years ago

i have it on 5th!!

Like? Yes | No

Pankhuri Kansal 10 years ago

If u get plzzzz mail me too ...on kansalpankhuri@gmail.com

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