A merchant has 550 kg of sugar, part of which he sells at 4% loss and the rest at 6% profit. He gains 2% on the whole. What is the difference between the quantities of sugar sold at 6% profit and that sold at 4% loss?
(Quantity of Cheaper)/(Quantity of Dearer) = (Price of Dearer - Mean Price)/(Mean Price - Price of Cheaper)
(Quantity of Cheaper)/(Quantity of Dearer) = (106 - 102)/(102-96) = 4/6 = 2/3
Total Quantity = 550 KG
The quantity sold at 4% loss is = (2/5) * 550 = 220 Kgs
The quantity sold at 6% profit is = (3/5) * 550 = 330 Kgs
Difference between Quantity = 330-220 = 110 Kgs
Total number of prime numbers less than 60 = 17 => 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59
Number of positive outcomes i.e. number where at least one of its digit is 2 = 3
In 2017, A is 9 years older than B who is five times as old as C. The total of the ages of A, B and C is 97 years. What would be the average of A and C ages in the year 2024 ?
OPtion
1) 31 years
2) 30 years
3) 33 years
4) 34.5 years
5) 36.5 years
6) 35.5 years
7) 29 years
8) 24 years
9) 35 years
10)None of these
Solution
Let’s assume Age of B be B years
Age of A = B+9
Age of C = B/5
Total age = B + 9 + B + B/5 = 97
Solving 11B/5 = 88
B = 40
A = B+9 = 40+9 = 49
C = 40/5 = 8
Age of A in 2024 = 49+7 = 56
Age of C in 2024 = 8+7 = 15
P can do a work in 46.5 days. Q can do the same work in 31 days and R can do the same in 77.5 days. Q and R start the work and leave after 15 days. P finishes the remaining work in X days. What is the value of X?
OPtion
1) 20.0 days
2) 16 days
3) 17 days
4) 12 days
5) 13 days
6) 15 days
7) 14 days
8) 11 days
9) 18 days
10) None of these
Solution
Amount of work done by Q and R in 15 days = 15*(1/31 + 1/77.5) = 15((2.5+1)/77.5) = 52.5/77.5 = 21/31
Amount of work remaining after 15 days = 10/31
Amount of work done by P in 1 day = 1/46.5
So for 1/46.5 work P takes 1 day
Hence for 10/31 work P would take (1/(1/46.5))*10/31 = 15 days
In 2017, A is 6 years older than B who is seven times as old as C. The total of the ages of A, B and C is 126 years. What would be the average of A and B ages in the year 2029 ?
OPtion
1) 44 years
2) 47 years
3) 71 years
4) 69 years
5) 42 years
6) 40 years
7) 73 years
8) 72 years
9) 75 years
10)None of these
Solution
Let’s assume Age of B be B years
Age of A = B+6
Age of C = B/7
Total age = B + 6 + B + B/7 = 126
Solving 15B/7 = 120
B = 56
A = B+6 = 62
C = 56/7 = 8
Age of A in 2029 = 62+12 = 74
Age of B in 2029 = 56+12 = 68
Sum of the ages of a boy and his father is 49 years. Before 11 years Father's age was 8 times the age of the boy. What was the age of father (in years) at the time of birth of the child?