A person has a certain number of coins. If he distributes a certain sum to each of nine persons, he has five coins left. If he distributes the same sum of six persons he has twenty coins left. What amount did he give to each persons?
Let x be the number of coins given to each person.
After giving x number of coins to each of the 9 persons, he has 5 coin left with him.
This means initially he has 9x+5 coins. (i)
When he distributes x coins each to 6 person he has left with 20 coins with him.
According to this he should have 6x+20 coin initially (ii)
From (i) and (ii), we get
9x+5=6x+20
3x=15
x=5
He gave 5 coins to each person
option 4
Total number of possible outcomes = 36 (solve)
Let E be the event "Sum of the numbers on the two dice is atleast 7
therefore
E = (1,6)(2,5)(3,4)(4,3)(5,2)(6,1)(2,6)(3,5)(4,4)(5,3)(6,2)(3,6)(4,5)(5,4)(6,3)(4,6)(5,5)(6,4)(5,6)(6,5)(6,6)
n(E)=21, n (not E) = 36-21=15
P(E)=21/36 and P(not E) = 15/36
Odd is favour of the event E = P(E):p(not E)
(21/36):(15/36) = 7:5
7/5
option 3
The rhombus here is a square. As the rhombus is cyclic, cum of opposite angles is 180 degree, which are equal. So, each angle is 90 degree and the rhombus is a square.
Area of circle = 2826 cm^2
pi*r^2=2826 (let the radius of circle be r)
r=30 cm
Each diagonal = 2r
Area of square = 1/2 (D)^2
solve
ans 1800 cm^2
option 5
90%(A) and 97%(B) pure acid solutions are mixed to obtain 21.0 litre of 95% pure acid solution, find the amount of (B) to be mixed to form the mixture.