M4maths Previous Puzzles

15 Aug 2013 rank

what will be the rank of word OPTION in the dictionary of words formed by letters of the word OPTION

OPtion

1) 176
2) 182
3) 185
4) 197
5) 201
6) 206
7) 212
8) 226
9) 248
10) none of these

Solution

OPTION
total no. of words formed = 6*5*4*3*2*1/2*1 = 360
arranged order I,N,O,O,P,T

RANK: (360/6)*2+(60*2/5)*3+(24/4)*3+(6/3)*0+(2/2)*1+1 = 212

Correct Option: 7 Best Solution (7)

siddhartha   11 years AGO

there are 5 letters in total I N O P T where O is can be used twice..

so in dictionary words start in alphabetical order

words starting with I are 5!/2=60
words starting with N are 5!/2=60
then words with O starts
words starting with OI are 4!=24
words starting with ON are 4!=24
words starting with OO are 4!=24
words staring with OPI OPN OPO are 3!+3!+3!=18
next are OPTINO and OPTION which are 2

so rank = 60 + 60 + 24 + 24 + 24 + 18 + 2
= 212

Like? Yes (12) | No (2)  

ritesh kumar pandey   11 years AGO

before option the words will be from i and n and all words starting from oi, on, oo and all words from op
when all are calculated and added the sum will be 212.

Like? Yes (3) | No   

~Sandeep~   11 years AGO

Arranging alphabetically INOOPT
Counting words starting with various letter which comes before OPTION in dictionar ranking
[I/N](OOPT) -2*5*4*3 = 120
O[I/N](OPT) - 2*4*3*2 = 48
OO(INPT) - 4*3*2 = 24
OP-[I/N/O](T) - 3*3*2 = 18
OPTINO = 1
OPTION =1

Sum= 212

Like? Yes (3) | No   

mohini gupta   11 years AGO

first of all,I will be the first alphabet.after that arrangement of other five letters is 5! since O is twice hence it will be 5!/2=60.
again N will be the first letter similarly arrangement of other letters is 5!/2=60.
now O will be the first letter. then at second position firstly I will be placed and arrangement of other 4 is 4!.then N will be at second position.hence again 4!.then O will be at third hence again 4!. then T will be at third.now arrangement of other three is 3!.it will also happen thrice.then for last two O will come first then N will come.
hence, 5!/2+5!/2+4!+4!+4!+3!+3!+3!+1+1=212

Like? Yes (3) | No   

Chandni Maurya   11 years AGO

ans=(7) 212
arranging in alphabetic order (I,N,O,O,P,T)
starting with I = 5!/2
starting with N = 5!/2
starting with OI = 4!
starting with ON = 4!
starting with OO = 4!
starting with OPI = 3!
starting with OPN = 3!
starting with OPO = 3!
starting with OPTI= (N,O & O,N)=2
adding all of them =212

Like? Yes (3) | No   

Bingumalla Abinay   11 years AGO

OPTION

words that start with O= 2*5!/2!=120
2! to remove repetition's

120+72+18+1+1=212

Like? Yes (2) | No   

LOGAN WOLVERINE   11 years AGO

OPTION .
arrange the letters in alphabet order=INOOPT
I is the first letter we want. no.
I=5!/2!=60
N=5!/21=60
O is the letter we need. fix O.
again repeat the process.
[O]I=4!=24
[O]N=4!=24
[O]O=4!=24
[O]P is the letter we need. so fix [OP]
again repeat the process
[OP]I=3!=6
[OP]N=3!=6
[OP]O=3!=6
[OP]T is the letter we need . fix [OPT]
again proceed the same process
[OPT]I is the letter we need . fix [OPTI]
again do same process
[OPTI]N=1!=1
[OPTI]O is the letter we need. fix [OPTIO]
[OPTIO]N is the letter we need.
SO [OPTION]=1
sum all the values=60+60+24+24+24+6+6+6+1+1=212

so the answer is choice 7. 212

Like? Yes (1) | No   

14 Aug 2013 Age

Mr. Ashok was born 1809 A.D. In year x^2 A.D.. he was x-3 years old. Find the value of x.

OPtion

1) 38
2) 40
3) 42
4) 43
5) 46
6) 48
7) 49
8) 50
9) 51
10) None of these

Solution

According the question
age of Ashok is x-3 in the year x^2 A.D.
As he was born in 1809 A.D., and his present age is x-3
1809+x-3=x^2
solve
x=-42 and x=43 (neglect the value of -42)
x=43
option 4.

Correct Option: 4 Best Solution (30)

FRANKLIN VIJAY   11 years AGO

x2 - 1809 = x - 3
x2 - x - 1806 = 0
x = 43 or -42
So the X is 43

Like? Yes (9) | No (2)  

Bingumalla Abinay   11 years AGO

x=43

x^2=1849

His age is 43-3=40 which is true as 1849-1809=40

Like? Yes (3) | No (1)  

Chandni Maurya   11 years AGO

ans=(4) 43
according to question,
x^2-1809=x-3
=> x^2-x-1806=0
=> x=43,-42 (-42 cannot be possible)
=> x=43

Like? Yes (3) | No (1)  

Vinay Sipani    11 years AGO

x^2 - 1809 = x - 3
=> x = 43

Like? Yes (2) | No (1)  

krishnapriya   11 years AGO

x^2-1809=x-3
x^2-x-1806=0
(x+42)(x-43)=0
x=43 (or) x=-42
therefore, x=43

Like? Yes (2) | No (1)  

Sahil   11 years AGO

answer is 43
the best way to do these questions is by using options.

here we have to add some no. to 1809 nd have to make it perfect square to find value of 'x' on LHS.

so 1849 is perfect square near 1809. so we add 40 to this 1809. and after that
A.T.Q
x^2=x-3
so after x years... we will get the value 1809+x
so
43^2=[(1809+43)-3]

hence LHS=RHS 43 is value of x (:

Like? Yes (2) | No (1)  

Raunak   11 years AGO

born in 1809, let presently be x^2 AD. then age of ashok at present is x^2-1809 but it is given that he was x-3 year old when it was X^2 AD. therefor eqn comes
x^2 - 1809 = x-3
by solving this we get X=43

Like? Yes (2) | No (1)  

Md Intshamuddin   11 years AGO

x^2=1809,hence x=43

Like? Yes (3) | No (3)  

NITISH KUMAR   11 years AGO

according to question,
x^2-1809=x-3;
x^2-x-1806=0;
(x-43)(x-42)=0;
x=43or x=-42
x=-42 is not possible
x=43

Like? Yes (2) | No (2)  

Devendra Marghade   11 years AGO

43^2=1849
So his age=1849-1809 =40 = 43-3

Like? Yes (1) | No (1)  

ABHISHEK KUMAR MISHRA   11 years AGO

x^2 - 1809 = x - 3
x^2 - x - 1806 = 0
x^2 -43x + 42x - 1806 = 0
x(x - 43) +42(x - 43) = 0
so x=43, -42
but here x=43 is the answer

Like? Yes (2) | No (2)  

Jasmine Khan   11 years AGO

Given that Mr ashok born in 1809.
here we simply find the perfect square between 1809 to 2013 and it is 1849 i.e 43^2=1849
therfore his age will be 43-3=40 yrs

Like? Yes (1) | No (1)  

Tapesh mishra   11 years AGO

Because 1849 is the root of 43 then age will be
1849-1809=40
So
(43)^2=43-3.
x^2=x-3
then x=43

Like? Yes (1) | No (1)  

Anil Kumar Bharti   11 years AGO

Exp:
In year x^2 is :
43^2=1849
He was x-3 years old :
43-3=40
Ashok's dob & age is :
1809+40=1849

Like? Yes (1) | No (1)  

manoj chauhan   11 years AGO

according to question
x^2-1809=x-3 =>x^2-x=1806
by solving this equation we will get x=43
43^2-1809=43-3
1849-1809=40
40=40

Like? Yes (1) | No (1)  

Pankaj   11 years AGO

43^2=1849
43-3=40yrs old
from options
x=43 ANS.

Like? Yes (1) | No (1)  

utkarsh singh   11 years AGO

in x yr he was 3 yr old so 1809+3=1812 and 43^2 =1849 so nearly options

Like? Yes (1) | No (1)  

Varun Upadhyay   11 years AGO

x^2-1809=x-3
on solving we get values of x as -42 and 43
taking the positive value of x=43 which satisfies the condition we get answer =43

Like? Yes (1) | No (1)  

richa ahuja   11 years AGO

go through options
sqaures of 38,40,42,51,50,49,48 cant be the possible years
now
let x=43
43^2=1849
nw frm 1809 to 1849
age=40
x-3=40
therefore,x=43
only 43 satisfies this relation

Like? Yes (1) | No (1)  

paramesh   11 years AGO

Ashok was born in 1809
IN x^2 Year he was x-3 yrs old.. means X^2 value greater than 1809, and x value greater than 40.
so eliminate first option..
let us assume that x value is 43..
then x^2=1849
x-3=40.

to confirm the answer we sholud take the difference of two years.
so now look at the difference of two years
1849-1809=40...hence it is satisfied..answer is 43.

Like? Yes (1) | No (1)  

Rajat jain   11 years AGO

as the ques say he was born in 1809..and we have to find its age when he was in x^2.and his present age is given x-3.so...

x^2-1809=x-3

by this we can find the age of ashok

Like? Yes (1) | No (1)  

Monisha   11 years AGO

In the year x2 AD he was x-3 years old. when he was x-3 years old, year was, 1809 +x-3= 1806+x and it is x2

Therefore, x2 =1806+x

x2 -x -1806=0 =>x2-43x +42 x -1806=0 => x(x-43) +42 (x-43 )=0

(x+42) (x-43) =0

x=-42 (not possible as age cannot be negative)

hence x=43 answer

Like? Yes (1) | No (1)  

Girjesh Chandravanshi   11 years AGO

43^2=1849;
43-3=40;
1849-1809=40;

Like? Yes (1) | No (1)  

Abhishek misra   11 years AGO

43^2=1849
he was 40 yrs old in 1849

Like? Yes (1) | No (1)  

shamily.k   11 years AGO

In the year x2 AD he was x-3 years old. when he was x-3 years old, year was, 1809 +x-3= 1806+x and it is x2
x2 =1806+x

x2 -x -1806=0
=>x2-43x +42 x -1806=0
=> x(x-43) +42 (x-43 )=0
=> (x+42) (x-43) =0
=> x=-42 (not possible)
or x=43 answer

Like? Yes (1) | No (1)  

Mohit Kumawat   11 years AGO

x^2-1809=x-3
x^2-x-1806=0
x=43

Like? Yes (1) | No (1)  

ritesh kumar pandey   11 years AGO

x^2 - 1809 = (x-3);
on solving it we get x = 43, -42
since x != -42
so x = 43;

Like? Yes (1) | No (1)  

ShAg   11 years AGO

our eqn is: x^2 = 1809 + (x-3)
=> x^2 - x - 1806 = 0
=> x = 43

Like? Yes (1) | No (1)  

Balakrishnan M   11 years AGO

43^2 = 1849
In year 1849 A.D he has 40 years old.
ie., In year (43)^2 A.D.. he was 43-3 years old.

Like? Yes (1) | No (1)  

Rats   11 years AGO

x^2-(x-3)=1809
x^2-x-1806=0
on solving x=43

Like? Yes (1) | No (2)  

13 Aug 2013 Farmer

A farmer sold a calf and cow for Rs.760, there by, making a profit 25% on the calf and 10% on the cow. By selling them for Rs. 767.50, he would have realized a profit of 10% on the calf and 25% on the cow. Find the cost of cow.

OPtion

1) 250
2) 270
3) 310
4) 350
5) 360
6) 390
7) 420
8) 450
9) 500
10)None of these

Solution

Let C.P. of a calf be Rs.x and C.P. of a cow be Rs.y
By the given condition
(125x/100)+(110y/100)=760 (i)
(110x/100)+(125y/100)=767.50 (ii)
Solve
The cost of calf = Rs. 300
The cost of Cow = Rs.350
option 4

Correct Option: 4 Best Solution (48)

Jigyasa Kumar   11 years AGO

Let C.P. of a calf be Rs 'x' and C.P. of a cow be Rs 'y'.
Now according to the question;
125x/100 + 110y/100 = 760 ..............(1)

110x/100 + 125y/100 = 767.50 ..............(2)

Now by solving (1) and (2), we get,
x = 300 and y = 350
therefore,
the cost of calf is Rs 300.
the cost of cow is Rs 350.

Like? Yes (24) | No (5)  

Aarush Singh   11 years AGO

Let C.P. of a calf be Rs 'x' and C.P. of a cow be Rs 'y'.
Now according to the question;
125x/100 + 110y/100 = 760 ..............(1)

110x/100 + 125y/100 = 767.50 ..............(2)

Now by solving (1) and (2), we get,
x = 300 and y = 350
therefore,
the cost of calf is Rs 300.
the cost of cow is Rs 350.

Like? Yes (13) | No (6)  

siddhartha   11 years AGO

so accoring to first statement
125% of calf + 110% of cow = 760
110% of calf + 125% of cow = 767.50
so writing eq's

125*calf + 110*cow = 76000
110*calf + 125*cow = 76750

by solving we get calf = 300rs cow = 350rs

Like? Yes (9) | No (2)  

Ankit Raj   11 years AGO

Let C.P. of a calf be Rs 'x' and C.P. of a cow be Rs 'y'.
Now according to the question;
125x/100 + 110y/100 = 760 ..............(1)

110x/100 + 125y/100 = 767.50 ..............(2)

Now by solving (1) and (2), we get,
x = 300 and y = 350
therefore,
the cost of calf is Rs 300.
the cost of cow is Rs 350.

Like? Yes (7) | No (2)  

NIDHI   11 years AGO

1.25x+1.10y=760;

110x-1.25y=767.50;

so, x=350. cost of cow =350.

Like? Yes (9) | No (4)  

Sahil   11 years AGO

answer is 350

let cost of calf is x, cost of cow is y
so according to the question there vl b 2 equations

(x+25% of x) + (y +10% of y)=760
(x+10% of x) + (y +25% of y)=767.50

so
125x+110y=76000
110x+125y=76750

after solving we will get x=300, y=350

Like? Yes (8) | No (3)  

MUKESH KUMAR   11 years AGO

1.25x+1.10y=760;

110x-1.25y=767.50;

so, x=350.

Like? Yes (6) | No (3)  

Vinay Sipani    11 years AGO

calf -> x , cow -> y

(x + x/4) + (y + y/10) = 760
=> 25x + 22y = 15200

(x + x/10) + (y + y/4) = 767.5
=> 22x + 25y = 15350

=> x = 300,y = 350

Like? Yes (3) | No   

ravi singh   11 years AGO

let cost of calf and cow is X and Y

then,
125*X/100 + 110*Y/100 = 760

and

110*X/100 + 125*Y/100 = 767.50

by solving these two equation we get,

X=300 and Y=350

hence answer 350

Like? Yes (3) | No   

mandeep   11 years AGO

let x be the price of calf and y be the price of cow.
when he sells calf for 25% profit,it means he sells it for (x+x/4).
and by selling the cow at profit of 10%,he sells it for (y+y/10)
he sells both of them at the price of 760.
so adding above eqtns.
(x+x/4)+(y+y/10)=760
similarly in second case
we get the eqtn.
(x+x/10)+(y+y/4)=767.50
on solving these two equtions,'x'=350 is obtained.

Like? Yes (2) | No   

ASHA.S   11 years AGO

let the cost price fo calf be x and cost price be y.
so 25percent profit means selling price 1.25x
so the total selling price 1.25x+1.10y 760.0 and 1.10x+1.25y 767.50
sovving we get y equal to 450

Like? Yes (2) | No   

Chandni Maurya   11 years AGO

ans=350 Rs
Let cost of calf and cow are x and y resp.
according to ques,
(x+x*25/100)+(y+y*10/100)=760
=> 5x/4+11y/10=760
=> 25x+22y=15200 ---(1)
and
(x+x*10/100)+(y+y*25/100)=767.50
=> 11x/10+5y/4=767.50
=> 22x+25y=15350 ---(2)
solving equ. (1) & (2).
x=300 (cost of calf)
y=350 (cost of cow)

Like? Yes (2) | No   

sridevi   11 years AGO

C.P of calf =x
C.P of cow = y

125x/100 + 110y/100 = 760
110x/100 + 125y/100 = 767.50

solving this we will get

x = 300 and y = 350
The cost of cow is Rs 350.

Like? Yes (2) | No   

Anuja Subramanian   11 years AGO

let cp of cow be a and calf be b.
framing eqns,
Eqn 1, 10a+25b=760..
Eqn 2, 25a+10b=767.50..
solving eqns 1 and 2
a=350,b=300..

Like? Yes (2) | No   

shamily.k   11 years AGO

Let the cost price of calf and cow be X and Y
Now frame the eqn,
25X+10Y=760
10X+25Y=767.50
Solve the above eqn we get
X=300 Y=350

Like? Yes (2) | No   

richa upadhyay   11 years AGO

n(1+25/100)+m(1+10%100)=760
n(1+10%100)+m(1+25%100)=767.50
calculating we get, n=300
m=350

Like? Yes (2) | No   

Ashutosh Anshu   11 years AGO

Let C.P. of a calf be Rs 'x' and C.P. of a cow be Rs 'y'.
Now according to the question;
125x/100 + 110y/100 = 760 ..............(1)

110x/100 + 125y/100 = 767.50 ..............(2)

Now by solving (1) and (2), we get,
x = 300 and y = 350
therefore,
the cost of calf is Rs 300.
the cost of cow is Rs 350.

Like? Yes (2) | No   

FRANKLIN VIJAY   11 years AGO

125x/100 + 110y/100 = 760
110x/100 + 125y/100 = 767.50
By solving we get
x = 300 and y = 350
Cow cost is 350

Like? Yes (1) | No   

Kalidindi Mounika   11 years AGO

Let C.P. of a calf be Rs 'x' and C.P. of a cow be Rs 'y'.
Now according to the question;
125x/100 + 110y/100 = 760 ..............(1)
110x/100 + 125y/100 = 767.50 ..............(2) Now by solving (1) and (2), we get,
x = 300 and y = 350

Like? Yes (1) | No   

Bingumalla Abinay   11 years AGO

x be calf and y be cow
1.25x+1.1y=760
1.1x+1.25y=767.5

solving both equations we get y(cow) value =350

Like? Yes (1) | No   

kiruthika   11 years AGO

let us suppose that the cost of cow is x and the cost of calf is y.
cost price of cow = selling price+profit
= x+0.25x
= 1.25x
cost price of calf= selling price +profit
= y+0.10y
= 1.10y
so the equations becomes
1.25x+1.10y=760........(1)
1.10x+1.25y=767.50........(2)
solving these we get
x=350,y=300
so x is the cost of cow.then the ans is 350

Like? Yes (1) | No   

ritesh kumar pandey   11 years AGO

let cost of calf is x, that of cow is y.
then 1.25x + 1.1y = 760
1.1x +1.25y = 767.5
on solving we get y = 350..
that is the answer
cost of cow is 350

Like? Yes (1) | No   

Jasmine Khan   11 years AGO

let x be the the actual cost of the calf and y be the cost of the cow
125% of x+ 110% of y=760
125x=110y=76000.........(1)
again by the second condition
110% of x+ 125% of y=767.5
110x+125y=76750........(2)
now solve 1 and 2 we get
y=350
cost of the cow

Like? Yes (1) | No   

Rats   11 years AGO

let cost of calf=x, cost of cow=y
1.25x+1.1y=760.....(1)
1.1x+1.25y=767.50..(2)
on solving (1)&(2)
y(cow)=350

Like? Yes (1) | No   

Devendra Marghade   11 years AGO

If cost of calf=x and cow=y
1.25x+1.1y=760 ---(i) &
1.1x+1.25y=767.5 ---(ii)
Solving x=300, y=350

Like? Yes (1) | No   

Ch Kumaraswamy   11 years AGO

first time sp=760=(125/100)*(cp of calf)+(110/100)*(cp of cow)
second time sp=765.50=(110/100)*(cp of calf)+(125/100)*(cp of cow)
by taking calf=x1,cow=x2..and solving
x1=x2-50,by sub in first equation we get x2=350..
ie cow cost=350.

Like? Yes (1) | No   

SANJEET KUMAR JHA   11 years AGO

Considering the costs of calf and cow 'x '& 'y' respectively and calculating the selling prices by taking 25% & 10% profits,we get one equation in x & y.Again we have second equation from the second condition.Solving both the equation,we get the final answer.

Like? Yes (1) | No   

Mayuresh Srivastava   11 years AGO

Let cost price of calf and cow are f and w.
Their first time selling price are f1,w1 and second time f2,w2.
Now f1=f+(f/4) and w1=w+(w/10)
f2=f+(f/10) and w2=w+(w/4)
and also f1+w1=760----1st and f2+w2=767.50----2nd
Put values of f1,f2,w1 and w2 in equation 1st and 2nd and solve.It will give w=350.

Like? Yes (1) | No   

Uthra PV   11 years AGO

By solving,
1.25 calf + 1.1 cow = 760
and
1.1 calf +1.25 cow = 767.50

Like? Yes (1) | No   

malarvezhi.m   11 years AGO

Let C.P. of aalf be Rs 'x' and C.P. of a cow be Rs 'y'.
Now according to the question;
125x/100 + 110y/100 = 760 ..............(1)

110x/100 + 125y/100 = 767.50 ..............(2)

Now by solving (1) and (2), we get,
x = 300 and y = 350
therefore,
the cost of calf is Rs 300.
the cost of cow is Rs 350.

Like? Yes (1) | No   

Balakumaran N.A   11 years AGO

Solution:
Let C.P. of a calf be Rs 'x' and C.P. of a cow be Rs 'y'.
Now according to the question;
125x/100 + 110y/100 = 760 ..............(1)

110x/100 + 125y/100 = 767.50 ..............(2)

Now by solving (1) and (2), we get,
x = 300 and y = 350
therefore,
the cost of calf is Rs 300.
the cost of cow is Rs 350.

Like? Yes (1) | No   

Banumathy   11 years AGO

form equations using the statements :
let x -> c.p of calf ; y -> c.p of cow
from 1st statement :
(25/100*x)+x + (10/100*y)+y = 760 ----> eqn.1
from 2nd statement :
(10/100*x)+x + (25/100*y)+y =767.50 ----> eqn.2
simplifying and solving eqn 1 nd 2 we get,
x= 300 and y= 350
hence ans is 4)350.

Like? Yes (1) | No   

Tapesh mishra   11 years AGO

Let cost of calf is x and cow is y.
1.25X+1.10Y=760
1.10X+1.25Y=767.5
BY Solving it
Y is 350.

Like? Yes (1) | No   

pravallika nathi   11 years AGO

1.25x+1.1y=760
1.1x+1.25y=767.50
solve y for cost of cow

Like? Yes (1) | No   

Sanampreet Singh   11 years AGO

Let x and y are the cost of calf and cow repectively.
From first statement it is clear that (x+x*0.25)+(y+y*0.10)=760 i.e. 25x+22y=15200
ANd from second statement it is clear that
(x+x*0.10)+(y+y*0.25)=767.50 i.e. 22x+25y=15350
After solving both equations we will get y=350.

Like? Yes (1) | No   

Anil Kumar Bharti   11 years AGO

Exp:
Let C.P. of a calf be Rs 'x' &
C.P. of a cow be Rs 'y'.
Now according to the question;
125x/100 + 110y/100 = 760 ..............(1)

110x/100 + 125y/100 = 767.50 ..............(2)

Now by solving (1) and (2), we get,
x = 300 and y = 350
Hence
the cost of calf is Rs 300.
the cost of cow is Rs 350. Ans

Like? Yes (1) | No   

Grishma Shah   11 years AGO

let the cost price of calf be 'x' and that of cow be 'y'.
Eq1 formed: 125x/100 + 110y/100=760
i.e. 125x + 110y = 76000
Eq2 formed: 110x + 125y =76750

solving the 2 equation its will give
x= 300 and y= 350

Like? Yes (1) | No   

Balakrishnan M   11 years AGO

CP of Calf = x
CP of Cow= y
x+(25/100)x+y+(10/100)y=760
==> 50x+44y=30400
x+(10/100)x+y+(25/100)y=767.5
44x+50y=30700
solve this eqn,
we get Cost of cow = 350
Cost of calf =300

Like? Yes (1) | No   

ShAg   11 years AGO

let original cost of calf = x, and that of cow = y; so our equations are:
25x + 22y = 15200
22x + 25y = 15350

Like? Yes (1) | No   

ch n m chaitanya   11 years AGO

760=125calf+110cow
767.5=110calf+125cow

by solving cow=3.5
100*cow=350;

Like? Yes (1) | No   

JAGYANDUTTA CHOUDHURY   11 years AGO

Ans:4) 350
1.25calf + 1.1cow = 760--------- i)
1.10calf + 1.25cow= 767.50------ii)

By solving eqn i) and ii) cow = Rs.350

Like? Yes (1) | No   

Pargat Pal Singh   11 years AGO

If x is cost of cow and y is cost of calf, then
1.1x+1.25y=760
1.25x+1.1y=767.50

solving these eqns, we get
x=350 Rs

Like? Yes (1) | No   

Udhaya kumar   11 years AGO

let x as calf and y as cow
FROM GIVEN DATA
X+(25X/100)+Y+(10Y/100)=760
X+(10X/100)+Y+(25Y/100)=767.5
BY SOLVING THESE
WE GET X=300,Y=350.................
SO ANSWER IS 350.......

Like? Yes (1) | No   

Anilkumar   11 years AGO

let cost of calf=x
cost of cow =y
(125/100)*x+(110/100)*y=760--(1)
(110/100)*x+(125/100)*y=767.50--(2)
solving 1 and 2 we get
x=300
y=350

Like? Yes (1) | No   

Prem Kumar   11 years AGO

Let C.P. of a calf be Rs 'x' and C.P. of a cow be Rs 'y'.
Now according to the question;
125x/100 + 110y/100 = 760 ..............(1)

110x/100 + 125y/100 = 767.50 ..............(2)

Now by solving (1) and (2), we get,
x = 300 and y = 350
therefore,
the cost of calf is Rs 300.
the cost of cow is Rs 350.

Like? Yes (1) | No   

KARTHIGA DEVI.J   11 years AGO

Let cost of calf be x and cow be y.
x+25x/100 + y + 10y/100 =760
==> 125x+110y=76000...........(1)
x+10x/100 + y+ 25y/100 =767.50
==>110x+125y=76750.............(2)
solving 1 and 2,
x=300 and y=350
Hence cost of cow is Rs.350.

Like? Yes (1) | No   

KUNAL CHATTOPADHYAY   11 years AGO

solve the equations
(5/4)x+(11/10)y=760
(11/10)x+(5/6)y=767.50
find and solve y
y=350

Like? Yes (1) | No   

yogesh   11 years AGO

calf cost x
cow cost y
x(125/100) + y(110/100)= 760.... (1)
1.25x + 1.1y=760

now
x(110/100) + y(125/100)= 767.50
1.1x + 1.25y= 767.50 ........ (2)

(1.25*1.25 - 1.1*1.1)Y= 767.50 * 1.25 - 760 * 1.1
.3525Y = 123.375
y= 123.375/.3525
Y= 350
cost of cow = 350

Like? Yes (2) | No (1)  

12 Aug 2013 Sequence

What is the next number of the following sequence.
7,14,23,34,....

OPtion

1) 41
2) 47
3) 49
4) 53
5) 57
6) 61
7) 65
8) 69
9) 72
10) None of these

Solution

1+2*3 = 7
2+3*4 = 14
3+4*5 = 23
4+5*6 = 34
5+6*7 = 47

Correct Option: 2 Best Solution (65)

Hasina Abdulhakkim   11 years AGO

7,14,23,34,.... =>7,(7+7),(14+9),(23+11)...so next term will be 34+13=47

Like? Yes (19) | No (6)  

Sahil   11 years AGO

answer is 47

14-7=7
23-14=9
34-23=11

so in this in the difference is increasing by 2, so next difference must be 13

hence 34+13=47

Like? Yes (7) | No   

Md Intshamuddin   11 years AGO

7,14,23,34,.... can be written as
3^2-2,4^2-2,5^2-2,6^2-2,7^2-2...hence next term will be 7^2-2=47

Like? Yes (9) | No (3)  

ravi singh   11 years AGO

2^2 + 3 = 7

3^2 + 5 = 14

4^2 + 7 = 23

5^2 + 9 = 34

6^2 + 11 = 47

Like? Yes (7) | No (1)  

ABHISHEK KUMAR MISHRA   11 years AGO

14-7=7
23-14=9
34-23=11
according to above trend next term is 34+13=47
so required answer is 2) 47

Like? Yes (6) | No (2)  

Mayuresh Srivastava   11 years AGO

7,14,23,34...
Difference b/w consecutive terms 7,9,11
so next differences must be 13,15 and so on
hence next term is 34+13=47.
Series will be 7,14,23,34,47,62...

Like? Yes (3) | No   

Balakrishnan M   11 years AGO

7
7+7=14
14+9=23
23+11=34
34+13=47

Like? Yes (3) | No   

Pradyumna K S   11 years AGO

07+00=07
07+07=14
14+09=23
23+11=34
34+13=47
hence answer is 47

Like? Yes (3) | No   

mohan lal garg   11 years AGO

in this series
nth number is n²+4n+2
1st number=1+4+2=7
2nd number=4+8+2=14
3rd number=9+12+2=23
4th number=16+16+2=34
5th number =25+20+2=47.....

Like? Yes (3) | No (1)  

mandeep   11 years AGO

diff. b/w 7 and 14 is 7
b/w 23 and 14 is 9
b/w 34 and 23 is 11
i.e. it forms an A.P. 7,9,11,...
so the diff b/w 34 and next term is 13 which gives 47 as the next number

Like? Yes (2) | No   

Sachin Singh Gusain   11 years AGO

7
7+7=14
14+9=23
23+11=34
34+13=47

Like? Yes (2) | No   

Niraj kumar   11 years AGO

respectively 7,9,11,are added to the so d last nmbr to add is 13 and rslt 47

Like? Yes (2) | No   

SUMIT   11 years AGO

the sequence is the (squares of the number-2)starting from 3 that is (9-2),(16-2),(25-2),(36-2)
therefore next term is (49-2)=47

Like? Yes (2) | No   

Pradeep sahu   11 years AGO

because difference between each digit is increasing by 2 then we have 47 as answer

Like? Yes (2) | No   

FAISAL RIZWAN   11 years AGO

7+7=14
14+9=23
23+11=34
34+13=47
so all no. are increasing by 2

Like? Yes (3) | No (1)  

Pankaj   11 years AGO

14-7=7
23-14=9
34-23=11
next term-34=13
=> next term=47

Like? Yes (2) | No   

Kalidindi Mounika   11 years AGO

square of a no - 2
3^2=9-2=7
4^2=16-2=14
5^2=25-2=23
6^2=36-2=34
7^2=49-2=47

Like? Yes (1) | No   

Bingumalla Abinay   11 years AGO

Given 7,14,23,34

take differences between the two numbers we get
14-7=7
23-14=9
34-23=11
so in the series the next difference should be 13
x-34=13
therefore x=34+13=47

Like? Yes (1) | No   

Chandni Maurya   11 years AGO

ans=(2). 47
7+7=14
14+9=23
23+11=34
34+13=47

Like? Yes (1) | No   

sandeep pandey   11 years AGO

7+7=14
14+9=23
23+11=34
34+13=47

Like? Yes (1) | No   

Deepak Sharma   11 years AGO

3^2-2=7
4^2-2=14
5^2-2=23
6^2-2=34
7^2-2=47
so option 2 is correct.

Like? Yes (1) | No   

vishnu vardhan   11 years AGO

7+7=14
14+9=23
23+11=34
34+13=47

Like? Yes (1) | No   

Balakumaran N.A   11 years AGO

Sequence increasing by 7,9,11,13....
34+13=47.

Like? Yes (1) | No   

ASHA.S   11 years AGO

7 +7 14
14+11 23
23 +9 34
34 +13 47
7,9,11,13 are odd nos starting from 7

Like? Yes (1) | No   

kiruthika   11 years AGO

the ans is 47
2^2+3=7
3^2+5=14
4^2+7=23
5^2+9=34
6^2+11=47

Like? Yes (1) | No   

Ankit Raj   11 years AGO

7,14,23,34,47,62,79,98,119,142,167,194,...

We notice that if we add 2 to each of those we get this
familiar sequence of squares:

9,16,25,36,49,64,81,100,121,144,169,196,...

which equals

3²,4²,5²,6²,7²,8²,9²,10²,11²,12²,13²,14²,...

Connecting it with the sequence 1,2,3,...

(1+2)²,(2+2)²,(3+2)²,(4+2)²,(5+2)²,(6+2)²,(7+2)²,(8+2)²,(9+2)²,(10+2)²,(11+2)²,(12+2)²,
which has nth term (n+2)².

The original sequence has terms which are 2 less than the terms of this
sequence, so the nth term of the original sequence is (n+2)²-2 = n²+4n+4-2 or
n²+4n+2

So the nth number is n²+4n+2.

Like? Yes (3) | No (2)  

Jigyasa Kumar   11 years AGO

The nos. are following a pattern in which the differences between the consecutive nos. are in odd no.series.from 7,9,11.so the next no.will be at a difference of 13.
Answer : 47

Like? Yes (2) | No (1)  

Aarush Singh   11 years AGO

the nos. are following odd no. series from 7.so the next no. will be 47 i.e.13 more than 34

Like? Yes (2) | No (1)  

Sourav Maity   11 years AGO

in this series the difference between two numbers 7,9,11. so next difference is 13.so next number is 34+13=47

Like? Yes (1) | No   

Vikram Saini   11 years AGO

difference b/w 7-14=7
difference b/w 14-23=9
difference b/w 23-34=11
difference b/w 34-?=13


so ans is ?=47

Like? Yes (1) | No   

krishnapriya   11 years AGO

14-7=7
23-14=9
34-23=11
47-34=13

Like? Yes (1) | No   

kanchan   11 years AGO

first term, 7
second term, 7+7=14
third term, 14+7+2=23
fourth term, 23+7+4(2 add by 2)=34
fifth term, 34+7+6(2+2+2,4 add by 2)=47

Like? Yes (1) | No   

M Rakesh   11 years AGO

3^2-2,4^2-2,5^2-2,6^2-2, next will be 7^2-2

Like? Yes (1) | No   

IFFAT IRAM   11 years AGO

diff of the consecutive nos are 7, 9,11
so next increment should be 13
next no. in the series = 47

Like? Yes (1) | No   

Sanampreet Singh   11 years AGO

First number is 7.
then added 7 i.e 7+7=14.
then 14+9=23
then 23+11=34
So next is 34+13=47.

Like? Yes (1) | No   

Muthu Madhavan   11 years AGO

9-2=7
16-2=14
25-2=23
36-2=34
49-2=47
so ans is 47

Like? Yes (1) | No   

ritesh kumar pandey   11 years AGO

7 = 3^2 - 2
14 = 4^2 - 2
23 = 5^2 -2
34 = 6^2 - 2
47 = 7^2 - 2
so, 47 is the answer

Like? Yes (1) | No   

khuzema bohra   11 years AGO

d diff bet each number is increasing by 2

Like? Yes (1) | No   

Prakash   11 years AGO

7+7=14
14+9=23
23+11=34
34+13=47

Like? Yes (1) | No   

sc mandota   11 years AGO

Difference increases by 2

Like? Yes (1) | No   

SARASVATHI   11 years AGO

14-7=7
23-14=9
34-23=11
so
34+13=47
the difference between the two nos are in the odd series.

Like? Yes (1) | No   

MD JARJIS HOSSAIN   11 years AGO

The n-th term is f(n) = n^2 + 2n - 1. For example,
f(1) = 1^2 + 2(1) - 1 = 2,
f(2) = 2^2 + 2n - 1 = 7,
f(3) = 3^2 + 2(3) - 1 = 14, and so on.

Like? Yes (1) | No   

mohamed ismail   11 years AGO

the difference between the consequent numbers are 7,9,11,13.....

Like? Yes (1) | No   

shamily.k   11 years AGO

The difference between the above numbers are odd numbers. Eg)14-7=7, 23-14=9 and 34-23=11. so the next odd number is 13. 34+13=47.
So the ans is 47.

Like? Yes (1) | No   

rajkumar m   11 years AGO

7+7=14
14+9=23
34+11=34
34+13=47

Like? Yes (1) | No   

saravanakumar   11 years AGO

7+7=14
14+9=23
23+11=34
34+13=47

Like? Yes (1) | No   

ShAg   11 years AGO

difference increases by 2 at each stage:
14-7=7
23-14=9
34-23=11
47-34=13

Like? Yes (1) | No   

chandan kumar yadav   11 years AGO

the difference between 7 and 14 is 7.
everytime the difference increases by 2.
that is, the next difference is 9 and its between 14 and 23.
similarily the difference between 23 and 34 is 11.
hence, the next difference is 13.
therefore the answer is 47.

Like? Yes (1) | No   

shekhar pankaj   11 years AGO

......7 14 23 34 47
DIFF...7..9..11.13

Like? Yes (1) | No   

Harsh Poddar   11 years AGO

(3^2)-2=7
(4^2)-2=14
(5^2)-2=23
(6^2)-2=34
next number=(7^2)-2=47
option 2

Like? Yes (1) | No   

Uthra PV   11 years AGO

7+7=14
14+9=23
23+11=34
34+13=47

Like? Yes (1) | No   

malarvezhi.m   11 years AGO

the difference between the numbers is odd.

Like? Yes (1) | No   

Tapesh mishra   11 years AGO

14-7=7
23-14=9
34-23=11
Next difference will be 13
so 34+13=47

Like? Yes (2) | No (1)  

Monisha   11 years AGO

the difference between the numbers is odd.
14-7=7
23-14=9
34-23=11
So,47-34=13

Like? Yes (1) | No   

sridevi   11 years AGO

the difference between the numbers is odd.
14-7=7
23-14=9
34-23=11
So,47-34=13

Like? Yes (1) | No   

Anurag Kumar Singh   11 years AGO

14-7=7
23-14=9
34-23=11
=> 9-7=2
& 11-9=2
11+2=13
=> 34+13=47 Ans.

Like? Yes (1) | No   

Sanjeev R   11 years AGO

+7,+9,+11,+13
34+13 = 47

Like? Yes (1) | No   

divya ramesh   11 years AGO

diff is 2,9,11,13...
so 34+13=47

Like? Yes (1) | No   

ponprakash   11 years AGO

14+9=23
23+11=34
34+13=47
(odd numbers adding)

Like? Yes (1) | No   

mohini gupta   11 years AGO

7+7=14
14+9=23
23+11=34
34+13=47
everytime 2 is incremented in the addition

Like? Yes (1) | No   

adil nazir   11 years AGO

14-7=7
23-14=9
34-23=11
47-34=13

Like? Yes (2) | No (1)  

Rats   11 years AGO

3^2-2=7
4^2-2=14
5^2-2=23
6^2-2=34
so next term is
7^2-2=47

Like? Yes (1) | No (1)  

Nayan Agrawal   11 years AGO

since +7=14
14+9=23
23+11=34
34+13=47............answer

Like? Yes (1) | No (1)  

Vinay Sipani    11 years AGO

14 - 7 = 7
23 - 14 = 9
34 - 23 = 11

=> next term - 34 = 13
=> next term = 47

Like? Yes (1) | No (1)  

Narendra Pargain   11 years AGO

this sequence is (n+2)^2 -2
value of n sequence
1 7
2 14
3 23
4 34
5 47
:)

Like? Yes (1) | No (1)  

09 Aug 2013 Fruit-seller

A fruit-seller sells half of his fruits plus 4 oranges; again he sells half of what remains plus 4 oranges; and so again a third time. His store is now exhausted; How many did he start with?

OPtion

1) 14
2) 24
3) 28
4) 32
5) 36
6) 42
7) 56
8) 60
9) 64
10)None of these

Solution

Let he has x fruits in the beginning.
He sells half of his stock and 4 oranges.
Number of fruits sold by him in the first instance = (x/2)+4
The remaining fruits = x-[(x/2)+4]= (x/2)-4
Number of fruits sold by him in the second instance =
=(1/2)[(x/2)-4]+4 = (x/4)-2+4 = (x/4)+2
Balance of fruits after the second sale = [(x/2)-4]-[(x/4)+2]
= (x/4)-6
Similarly Number of fruits sold by him in the third instance
= (1/2)[(x/4)-6]+4 = (x/8)-3+4 = (x/8)+1
Balance of fruits after the third sale = [(x/4)-6]-[(x/8)+1]=(x/8)-7
According to the question, his store is exhausted after the third sale
so (x/8)-7 = 0
x = 56 ..... To start with, there were 56 fruits
option 7
total fruit structure after the sale
total other fruit orange
initial 56 44 12
after first sale (28+4) 24 16 8
after second sale(12+4) 8 4 4
after third sale (4+4) 0 0 0

Correct Option: 7 Best Solution (0)

08 Aug 2013 number

The sum of a number, its cube root and its reciprocal number is an integer x. x will be

OPtion

1) 1
2) 2
3) 3
4) 4
5) 5
6) 6
7) 7
8) 8
9) 9
10) none of these

Solution

the only number possible is 1 for which x will be integer so
x = 1 + (1/1) + (1)^1/3 = 3

Correct Option: 3 Best Solution (17)

jitendra sharma   11 years AGO

y+(y)1/3+1/y=x;
y=1; only 1 satisfy this condition.
then x=3 so correct option 3..

Like? Yes (6) | No (1)  

ABHISHEK KUMAR MISHRA   11 years AGO

according to question
n + (n)^1/3 + 1/n = x
but here for x should be integer then then n must be 1
so that x=1+1+1=3

Like? Yes (4) | No   

aniruddh shrivastava   11 years AGO

see, 1 is the only number which have its cube root and reciprocal integer.... so 1+cube root (1)+1/1=3

Like? Yes (4) | No (1)  

Jigyasa Kumar   11 years AGO

let the no. be 1 then 1 +(1^1/3)+(1/1)=3
3 is an integer.
Answer : 3

Like? Yes (3) | No   

Nayan Agrawal   11 years AGO

since 1 and its cr and its reci is only 3

Like? Yes (3) | No   

Pankaj   11 years AGO

1+cube rt.(1)+1/1=3
only 1 satisfies the conditions given.

Like? Yes (2) | No   

shailesh kumar mishra   11 years AGO

let the no is y
then y+y^1/3+1/y= should be integer
now 2,3,4,5,6,7,9 has no cube root and for 2 1/y
is 1/2 so using these we never get an integer but put y=1
then 1++^1/3+1/1= 1+1+1 =3 integer

Like? Yes (2) | No   

Vinay Sipani    11 years AGO

a + a^3 + (1/a) = x

As x is interger => (1/a) is also integer
=> a = 1

=> x = 1 + 1 + 1 = 3

Like? Yes (1) | No   

Chandni Maurya   11 years AGO

ans=(3).3
1+ cube root(1)+ 1/1
=1+1+1
=3

Like? Yes (1) | No   

rajakumar   11 years AGO

let the no be 1
cube of 1=1
reciprocal of 1 =1
sum =1+1+1======>3

Like? Yes (1) | No   

Bingumalla Abinay   11 years AGO

reciprocal of any number other than 1 will not give integer, so the unknown number is 1, 1+1^3+1/1=3

Like? Yes (1) | No   

chandan kumar yadav   11 years AGO

Let the number be 1
Cube root of 1=1
Reciprocal of 1=1
Adding all we get 3
Hence ans is 3

Like? Yes (1) | No   

Ann Mary Jolly   11 years AGO

If the no. is 1
Then the given sum = 1 + 1^(1/3) + 1/1
= 1 + 1 + 1
= 3

Like? Yes (1) | No   

Hema J   11 years AGO

x is 3.
let the number be y.
given that y+y^(1/3)+(1/y)=x
the value of 1/y is a whole number only if y=1.
so substituting y=1 ,the answer will be 3.

Like? Yes (1) | No   

JAGYANDUTTA CHOUDHURY   11 years AGO

1+cuberoot(1)+reciprocal(1)=1+1+1 is an integer x is 3

Like? Yes (1) | No   

KARTHIGA DEVI.J   11 years AGO

only perfect cube numbers can be taken,
So 1 is the applicable number from the options.
1+cube root(1)+1/1 = 3.
So 3 is the answer.

Like? Yes (1) | No   

kamlesh kumar vishwakarma   11 years AGO

1+cuberoot(1)+(1/1)=3 is an integer..
hence answer is 3

Like? Yes (1) | No   

07 Aug 2013 Solve

A and B are friend and their ages differ by 2 years. A's father D is twice as old as A and B is twice as old as his sister C. The age of D and C Differ by 40 years. Find the ages of A.

OPtion

1) 18
2) 20
3) 21
4) 23
5) 26
6) 29
7) 31
8) 32
9) 36
10) None of these

Solution

By the given condition
A-B=2 (i)
Now as D is twice of 'A'
D's age = 2A years
and B is twice of his sister C
C's age = B/2 years
So D is older than C
2A-(B/2)=40 = 4A-B=80 (ii)
solve (i) and (ii) eq.
A=26

Correct Option: 5 Best Solution (0)

06 Aug 2013 Solve

The difference of two numbers is five sixth of their sum and the greater exceeds ten times the lesser by 3. Find the greater number.

OPtion

1) 96
2) 84
3) 72
4) 68
5) 55
6) 48
7) 33
8) 28
9) 24
10) None of these

Solution

Let the number be x and y.
Now according to the given condition
x-y=(5/6)x+y = x-11y=0 (i)
and x=3+10y = x-10y=3 (ii)
Now by solving (i) and (ii)
x=33 y=3

option 7

Correct Option: 7 Best Solution (38)

jitendra sharma   11 years AGO

suppose greater no is x and second y;
x-y=5/6(x+y)
6x-6y=5x+5y
x=11y------(1)
again
x/3=10+y/3
x=y+30----(2)
from (1)and (2)
x=33,y=3
then ans is 33 option 7)

Like? Yes (6) | No   

ravi singh   11 years AGO

let the greater no. is 'a' and smaller no. is 'b'
therefore
(a-b)=(5/6)*(a+b)
=>a=11*b

and also given that
a=10*b+3

by solving both equation
we get a=33 and b=3
therefore greater no. is 33

Like? Yes (3) | No   

kiruthika   11 years AGO

the diff between their number=5/6(of their sum) (x-y)=5/6(x+y)
6(x-y)=5(x+y)
6x-6y=5x+5y
x-11y=0.........(1)
then
greater exceeds ten times the lesser by 3 which means,suppose take y is smaller then we get ,
x-10y=3.........(2)
solving (1)and (2) we get
x=33,y=3
so the greatset number is 33.

Like? Yes (2) | No   

rajakumar   11 years AGO

x-y=5/6(x+y)----1 and x-10y=3----2
from 1 6x-6y-5x-5y=0=====>x-11y=0
from 2 x-10y=3
eq1-eq2======>y=3 substitute this value in eq1
x-11*3=0======>x=33

Like? Yes (2) | No   

Rats   11 years AGO

x-y=(5/6)(x+y).......(1)
x=10y+3..............(2)
on solving (1)&(2)
y=3 & x=33
hence, greater number is 33.

Like? Yes (1) | No   

susmit   11 years AGO

Let the smaller number be x.
So, greater number is 10x + 3.
So their sum is 11x + 3 and their difference is
9x + 3.
So 9x + 3 = 5/6 (11x + 3).
So 54x + 18 = 55x + 15.
So x = 3.
So greater number is 3*10+3 = 33.
Hence option no. 7.

Like? Yes (1) | No   

Vinay Sipani    11 years AGO

(x - y) = (5/6)*(x + y)
x = 10y + 3

=> x - 11y = 0 , x - 10y = 3
=> x = 33, y = 3

Like? Yes (1) | No   

Kalidindi Mounika   11 years AGO

From the question we can get two equations :
=> x-y = 5/6 [x+y] => x-11y =0 ------ (1)
=> x-10y = 3 -------------------------(2)
By solving 1 & 2 we will get
x=33 ; y= 3

Like? Yes (1) | No   

Pankaj   11 years AGO

let x be greater no. and y smaller
x-y=5/6(x+y)___________(1)
x-10y=3________________(2)
solving the two v get:
x=33,y=3______ANS

Like? Yes (1) | No   

Deepak Sharma   11 years AGO

Let greater no. is x. and lesser no. is y.
then by first condition of question:-
x-y=5/6(x+y)
x-11y=0............equation (1)
and now by second condition of question,
x=10y+3
x-10y=3....................equation(2)
by solving equation (1) & (2)
we get, x=33 & y=3
so option 7 is correct.

Like? Yes (1) | No   

Jasmine Khan   11 years AGO

let those two numbers are x & y and the greater number be x then,
x-y=5/6(x+y)
x=11y..........(1)
and x=10y+3.......(2)
by (1) and (2)
x=33 and y=3

Like? Yes (1) | No   

Jigyasa Kumar   11 years AGO

the two equations are x-y=5/6(x+y)
and y-10x = 3
we get x = 11y
so.y = 33 satisfies the second equation.

Like? Yes (1) | No   

Aarush Singh   11 years AGO

the two equations are x-y=5/6(x+y)
and y-10x = 3
we get x = 11y
so.y = 33 satisfies the second equation.

Like? Yes (1) | No   

Narendra Pargain   11 years AGO

x-y =5/6(x+y)...1
x-10y=3...2
on solving this equation.
greater no. will be 33

Like? Yes (1) | No   

ABHISHEK KUMAR MISHRA   11 years AGO

Let the x is greater no and y is lesser no
then x-y = 5/6(x+y).......(1)
and also x-10y = 3.........(2)
now solve (1) & (2) then
x=33, y=3 so our required answer is 33

Like? Yes (1) | No   

sandeep pandey   11 years AGO

x-y=5/6(x+y)..1
solving we get
x-11y=0
also given
x-10y=3....2
solving 1 & 2 we get y=3 and x=33
greater is 33 ans

Like? Yes (1) | No   

V CHANDRA SHEKHAR   11 years AGO

Here, x-y=5/6(x+y)
6x-6y=5x+5y
x=11y
x/y=11-eqn 1
then again,x=10y+3 - eqn 2
equating both equations we get
y=3 and x=33 ans

Like? Yes (1) | No   

sudhakar   11 years AGO

LET THE GREATEST NUMBER BE X AND SMALLEST BR Y
GIVEN THAT X-Y=5/6(X+Y)---1
AND ALSO
X=10Y+3 ---2

SUBSTITUTE EQUATION 2 IN 1
WE GET Y=3 AND X=33

Like? Yes (1) | No   

Chandni Maurya   11 years AGO

ans=(7).33
condition1: a-b=5/6(a+b)
condition2: 10b+3=a => b=(a-3)/10
put b in 1
a-(a-3)/10=5/6(a+(a-3)/10)
=>54a+18=55a-15
=>a=33

Like? Yes (1) | No   

preeti sinha   11 years AGO

x-y=5/6*(x+y)----eq 1
x=10y+3------eg2
solving eq1 and eq2
y=3
x=33
thus greatest number = 33

Like? Yes (1) | No   

krishna   11 years AGO

a-b=5/6(a+b)
a=10b+3
there for b=3,a=33

Like? Yes (1) | No   

MD KONAIN UDDIN   11 years AGO

x-y =5/6 x+y

x-10y =3

solve it

and get the anaswer x =33 and y =3

Like? Yes (1) | No   

Bingumalla Abinay   11 years AGO

a-b=5/6(a+b)
a=10b+3
sloving b=3 and a=33 which is answer

Like? Yes (1) | No   

priyanka semwal   11 years AGO

x-y=5/6(x+y) eq(1)
by solving-x=11y
x-10y=3 eq(2)
putting x=11y in eq(2)
11y-10y=3
y=3
hence by eq(1)
x=33

Like? Yes (1) | No   

Sachin Singh Gusain   11 years AGO

6(x-y)=5(x+y) gives x=11y
put this in x-10y=3 we get y=3
using y=3 we can easily get x=(10y+3)=33

Like? Yes (1) | No   

RagunathKC   11 years AGO

Let 2 num x,y;
x-y=(5/6)x+y;
cros multiply
6x-6y=5x+5y;
x=11y; //eq 1
x is multiples of 11.
{Given x (greater)exceed ten times lesser by 3}
x-3=10y; // subs eq 1
11y-3=10y;
y=3;
x=33;
ans 33.

Like? Yes (1) | No   

Shyoram   11 years AGO

The simplest way is
Question said ten times + 3 means
10X + 3
it means last digit of big number will be 3 for sure
answer option 7)

Like? Yes (1) | No   

kamlesh kumar vishwakarma   11 years AGO

let x is greater..
x-y=(5/6)(x+y).......(1)
x=10*y+3.........(2)
by solving these equation we get
x=33
y=3
answer is 33

Like? Yes (1) | No   

Anil Kumar Bharti   11 years AGO

Exp:
let get no=x and lesser no=y
by ques: x-y=(x+y)*5/6
=>x-11y=0 ---------(i)
and
x-10=3 ----------(ii)
After solving eqn. i & ii


x=33 Ans

Like? Yes (1) | No   

c varun   11 years AGO

6(x+y)=5(x-y)
x=10y+3
y=3
x=33

Like? Yes (1) | No   

Trisha   11 years AGO

x1-x2=5/6(x1+x2)
and x1-10x2=3
solving we get x1=33,x2=3

Like? Yes (1) | No   

ShAg   11 years AGO

Let x is the smaller number and y be the greater number, we get;
(y-x) = (5/6)(x+y) and
(y-10x) = 3

Like? Yes (1) | No   

Sumit Chopra   11 years AGO

x-y=5/6(x+y) so x=11y
and x-10y=3 s0 11y-10y=y=3 and hence x=33 the greater no.

Like? Yes (1) | No   

preeti choudhary   11 years AGO

Y-x=5/6(x+y)
Y=10x+3
In equ. First 10x+3-x=5/6(x+y)
9x+3=(5x+5y)/6
54x+18=5x+5y
49x=5y-18
49x=50x+15-18
-x=-3
X=3 And
Y=33.

Like? Yes (1) | No   

AVNLRedddy   11 years AGO

y-x=(5/6)(x+y)
y=10x+3
when solved, leads to y=33

Like? Yes (1) | No   

SNEHA   11 years AGO

Let the bigger no. be b and smaller no. be a.
ATQ,
eqn 1 is: b-a=5/6*(a+b)
eqn 2: b-10a=3
so,b=10a+3
substituting in eqn 1
=>(10a+3)-a=5/6*(a+10a+3)
=> 9a+3=5/6*(11a+3)
=>54a+18=55a+15
=>a=3
so,b=10*a+3
= 33

Like? Yes (1) | No   

Ann Mary Jolly   11 years AGO

Let the greater no. be a.
Then as given a = 10b+3
=> 9b+3 = 5/6 *(11b+3)
=> 54b+18 = 55b+15
=> b = 3
=> a = 10b+3 = 10*3+3 = 33

Like? Yes (1) | No   

Dipak Liladhar Patil   11 years AGO

x-y = 5/6(x+y)

x-10y=3

after solving two eqn: x=33 & y=3
so greater is 33.

Like? Yes (1) | No   

05 Aug 2013 Sequence

What is the next number of the following sequence
5, 10, 17, 26,.......

OPtion

1) 31
2) 35
3) 37
4) 40
5) 42
6) 46
7) 52
8) 64
9) 72
10)None of these

Solution

1*2+3 = 5
2*3+4 = 10
3*4+5 = 17
4*5+6 = 26
5*6+7 = 37

Correct Option: 3 Best Solution (18)

jitendra sharma   11 years AGO

5+5=10;
10+7=17;
17+9=26;
26+11=37;
so 37 is correct answer.....

Like? Yes (10) | No (1)  

SATYAM SAURABH   11 years AGO

using formula A^2 +1
2^2+1=5
3^2+1=10
4^2+1=17
5^2+1=26
now 6^2+1= 37
another way..use the difference.
5----5-->10-----7--->17---9---->26----now 11---37
every time odd number is added in previous number

Like? Yes (4) | No   

Shyoram   11 years AGO

The given sequence follows rule :
5 + 5 = 10
10 + 7 = 17
17 + 9 = 26
26 + 11= 37
Hence the correct option is (3) - 37

Like? Yes (3) | No   

Jasmine Khan   11 years AGO

2^2+1=5
3^+1=10
4^2+1=17
5^2+1=26
6^2+1=37

Like? Yes (2) | No   

Pankaj   11 years AGO

therefore difference b/w consecutive terms
5, 10, 17, 26.....___________(1)
5 ,7 ,9_______________(2)
diff. b/w these terms i (2) is 2
so the next term in (2) is 11
hence next term in (1) is 37

Like? Yes (2) | No   

Abhik Kumar Dey   11 years AGO

10-5=5
17-10=7
26-17=9
therefore it is obvious that the next difference will be 11
and thus 26+11=37

Like? Yes (2) | No   

Neha Rani   11 years AGO

since 1st digit is 5,next digit increased by 5 it becomes 10,next digit increased by 7 it becomes 17,next digit increased by 9 it becomes 26 and so next digit will be increased by 11 and it will be 37

Like? Yes (2) | No   

Rats   11 years AGO

2^2+1=5
3^2+1=10
4^2+1=17
5^2+1=26
so next term is
6^2+1=37

Like? Yes (2) | No (1)  

FRANKLIN VIJAY   11 years AGO

n^2+1
2^2+1=5
3^3+1=10
4^4+1=17
5^5+1=26
6^6+1=37
Answer=37

Like? Yes (2) | No (1)  

kiruthika   11 years AGO

5,10,17,26,....
the difference between the numbers
10-5=5
17-10=7
26-17=9
so the next number will be 26+11=37
the answer is 37

Like? Yes (2) | No (1)  

Jigyasa Kumar   11 years AGO

The difference between the nos. follows odd nos. from 5,7,9 .so answer is 37,difference will be 11 because 37-26 = 11.so the answer is 37

Like? Yes (2) | No (1)  

Deepak Sharma   11 years AGO

5,10,17,26........
5
5+5=10
10+7=17
17+9=26
so next number will be 26+11=37
therfore option 3 is correct.

Like? Yes (2) | No (1)  

Aarush Singh   11 years AGO

The difference between the nos. follows odd nos. from 5 .so answer is 37.then difference will be 11

Like? Yes (2) | No (1)  

sk   11 years AGO

5+5=10
10+7=17
17+9=26
so next wouuld be 26+11=37

Like? Yes (1) | No   

Amarjeet Kumar   11 years AGO

5+5=10
10+7=17
17+9=26
26+11=37

Like? Yes (2) | No (1)  

NITISH KUMAR   11 years AGO

5,10,17,26,......
here 10-5=5;
17-10=7;
26-17=9;
i.e difference increases by 2
so next difference is 9+2=11
so next no is 26+11=37

Like? Yes (1) | No (1)  

shailesh kumar mishra   11 years AGO

since 5,10,17,26
the differece is 5,7,9 so next should be 11
hence next no of the series is 37

Like? Yes (1) | No (1)  

ankur pratap singh   11 years AGO

5+5=10; add 5
10+7=17; add 7
17+9=26; add 9
26+11=37; add 11
answer= 37.

Like? Yes (1) | No (1)  

02 Aug 2013 Problem

Seven times a given two digit number is equal to four times the number obtained by inter changing the digits and the difference of the digits is 3. Find the numbers.

OPtion

1) 63
2) 41
3) 74
4) 36
5) 52
6) 69
7) 76
8) 96
9) 12
10) None Of these

Solution

Suppose x is digit in ten's place and y is the digit in unit's place.
So the number 10x+y
By reversing the order of the digits, the new Number is 10y+x
According to the given condition 7(10x+y)=4(10y+x)
Also x-y=3
Solve
number is 36
option 4

Correct Option: 4 Best Solution (27)

Balakrishnan M   11 years AGO

Seven times a given two digit number is equal to four times the number obtained by inter changing the digits
7(10x+y)=4(x+10y)
70x+7y=4x+40y
66x-33y=0
2x-y=0
2x=y
The difference of the digits is 3
y-x=3
2x-x=3
x=3
y=6
that number is 36.

Like? Yes (194) | No (46)  

NITISH KUMAR   11 years AGO

7(10y+x)=4(10x+y);
x-2y=0......(1)
x-y=+/-3......(2)
from 1 and 2
y=3ory=-3
y=3 is possible
so number is 10(3)+6=36
36 is the number

Like? Yes (61) | No (30)  

krishnapriya   11 years AGO

Let the unit digit and 10's digit be x an y respectively. So, the number is 10y+x and when the number is reversed, then the number is 10x+y.
Also,x-y=3-------(1) and
7(10y+x)=4(10x+y)
70y+7x=40x+4y
2y-x=0-------(2)
adding (1) and (2) we have,
y=3 and x=6
hence the number is 10y+x=10x3+6=30+6=36

Like? Yes (42) | No (23)  

sandeep pandey   11 years AGO

let the no be 10x+y
7 times is 70x+7y
no obtained by interchanging the digit is 10y+x
4 times is 40y+4x
therefore,
70x+7y=40y+4x
=>66x=33y
=>2x-y=0.......(1)
we know
either x-y=3 or y-x=3.(2)
solving we get x=-3,3
x=3 y=6
therefore no is 36

Like? Yes (27) | No (13)  

Pankaj   11 years AGO

by the given conditions 2 eqs. r formed:
7(10x+y)=4(10y+x)____________(1)
y-x=3________________(2)
x being no. at tens place
y being no. at ones place
(1) equ. becomes: 2x-y=0
putting the value of y=x+3 in above v get
2x-x-3=0
=> x=3 and y=6(by solving from above equation)

Like? Yes (24) | No (18)  

Chandni Maurya   11 years AGO

ans=36
let two digits are a&b,
=> 7*(a*10+b)=4*(b*10+a)
=> 70a + 7b = 40b + 4a
=> 66a - 33b =0
=> 2a - b =0 ---(1).
according to ques, |a-b|=3
from eq. (1). we can conclude=> b-a=3
=> b=a+3
put it in (1)
2a-a-3=0
=> a=3, =>b=a+3=3+3=6
so no. is= 36

Like? Yes (20) | No (14)  

Vinay Sipani    11 years AGO

7(10x + y) = 4(10y + x)
=> 2x = y

Also (y - x) = 3

=> x = 3 , y = 6

Like? Yes (28) | No (23)  

jitendra sharma   11 years AGO

suppose two digit no is ab,
by interchanging digits ab becomes ba;
given 7ab=4ba;
ab/ba=4/7;difference bw digit=3;
so the ans=36

Like? Yes (26) | No (22)  

Tirtha Bhattacharya   11 years AGO

Let tha digit in units\'s place be x and in ten\'s place be y
then the number is 10y+x
By the problem,
7(10y+x)=4(10x+y)
or,33x-66y=0
or,x-2y=0...........(1)
Again,x-y=3.........(2)
solving (1)and (2),
x=6 and y=3
so the number is 36

Like? Yes (17) | No (13)  

Priyanka Sharma   11 years AGO

Let the digits of the no. be x and y.
Then no. is 10x+y.
Given that 7(10x+y)=4(10y+x)
Simplify it to get y=2x
Another condition given is |x-y|=3
Using both equations, we get x=3 and y=6.
Therefore the no. is 36.

Like? Yes (11) | No (7)  

nithya   11 years AGO

ans: 36.
from option,
7(36) = 252; 4(63) =252
7(36)=4(63) =252. And difference between two digits is 3.It satisfies the given condition.

Like? Yes (14) | No (11)  

Anilkumar   11 years AGO

7(10x+y)=4(10y+x)
Solving we get 2x=y
Applying second condition answer is 36

Like? Yes (14) | No (12)  

kiruthika   11 years AGO

the answer is 36
36*7=252
by reversing the digits we get
63*4=252
then
the diff between the digits is 6-3=3
so the number is 36

Like? Yes (11) | No (10)  

SATYAM SAURABH   11 years AGO

better eliminate option than the solve whole problem
from the last condition only 1, 2, 3, 4,6,8. n use condition 1 you will your answer

Like? Yes (10) | No (9)  

Anil Kumar Bharti   11 years AGO

Exp: Using options
36*7=63*4

Like? Yes (9) | No (9)  

FRANKLIN VIJAY   11 years AGO

36*7=252
63*4=252
6-3=6
So answer is 36

Like? Yes (7) | No (7)  

rajkumar m   11 years AGO

36*7=252 63*4=252 6-3=3

Like? Yes (9) | No (9)  

Amrit Anand   11 years AGO

let the 2 digit number =10*x+y & another will be 10y+x A/c to question
go through option
7*36=4*36
* diff between digit=3
so ans:-36

Like? Yes (7) | No (7)  

Deepak Sharma   11 years AGO

Let tens digit of number is x and unit digit is y.
then the two digit number is 10x-y.
therefore by first condition,
7(10x+y)=4(10y+x)
2x-y=0..................equation 1
from second condition
x-y=3.................equation 2
by solving equation 1 & 2, we get
x=3, y=6
then that two digit no. is 36
so option 4 is correct.

Like? Yes (11) | No (11)  

gulshan kumar   11 years AGO

Y =2 x & x -y =3
By solving these two equations, we get the 36

Like? Yes (1) | No (1)  

Sachin Singh Gusain   11 years AGO

using the equations
7(10X+Y)=4(10Y+X) and Y-X = 3
we get X=3 and Y=6

Like? Yes (8) | No (8)  

mandira kundu   11 years AGO

check all d options given.
if original/interchanged=4/7 then that will b d ans.
ans-36

Like? Yes (8) | No (8)  

mohamed ismail   11 years AGO

7*36=252
4*63=252
and also it satisfies the second condition too
6-3=3.

Like? Yes (7) | No (8)  

Gaurav Sharma   11 years AGO

let us take the 4 option which is 36
36*7=252
reverse of digits is 63
63*4=252
so is the answer

Like? Yes (8) | No (9)  

sajjan kumar   11 years AGO

opposite of number should be divisible by 7.
36*7=4*63

Like? Yes (10) | No (11)  

Udhaya kumar   11 years AGO

fro given data
7(10x+y) = 4(10y+x)
then y-x=3 (because y is greater than x)
by solving this we get x=3 and y=6
so answer is 36.............

Like? Yes (12) | No (14)  

ABHISHEK KUMAR MISHRA   11 years AGO

let x is on unit place and y is on ten's place so the no is: 10y + x
when reverse the digit then no is: 10x + y
now according to question
7(10y + x)= 4(10x + y)......(1)
and difference is:
x - y = 3.....(2)
now solve (1) & (2) then
x=6 & y=3
so the no is 36

Like? Yes (10) | No (12)