M4maths Previous Puzzles

17 Sep 2009 Code for hanuman

In a coded language some words and their coded sets are given below
Word Coded set
RAM {A,C,H}
KRISHNA {A,D,H,I}
SHIV {D,H,I}
Then coded set for HANUMAN is

OPtion

1) {A,B,D}
2) {A,B,C,D,H}
3) {A,D,H,I}
4) {A,E,I,N}
5) {A,D,H}
6) {D,H,R}
7) {C,D,H}
8) {B,H,I,R,Z}
9) {A,B,C,D,I}
10) {B,D}

Solution

Positional value of letters of word RAM are 18, 1, 13 respectively
Coded values are 1*8, 1, 1*3
= 8, 1, 3
Letter of these positions are H, A, C, hence the coded set
Similarly Positional value of letters of word KRISHNA are 11, 18, 9, 19, 8, 14, 1 respectively
Coded values are 1*1, 1*8, 9, 1*9, 8, 1*4, 1
=1, 8, 9, 9, 8, 4, 1
Letter of these positions are A, H, I, I, H, D, A,
Hence coded set is {A, D, H, I}
similarly for others.

Correct Option: 2 Best Solution (1)

16 Sep 2009 find the original Number

33 is subtracted from one third of a number, then the obtained number is increased by 250 % .
5/7 of the number obtained is multiplied by 3/2 then its half is increased to 120 % .
when 225 is decreased from the obtained number, zero is obtained, then the number is

OPtion

1) 237
2) 6543
3) 399
4) 453
5) 465
6) 96
7) 600
8) 300
9) 666
10) 222

Solution

[{(?/3)-33}*3.5*(5/7)*(3/2)*(1/2)*1.2]-225=0 => ?=399
Note that number is increased by 250 % means the number will become 100% +250% = 350% of the
original number for this we should multiply the number to 3.5. Similarly number is
increased to 120 % means the number will become 120% of the original number for this
we should multiply the number to 1.2

Correct Option: 3 Best Solution (0)

15 Sep 2009 How to get max Profit

Rate list of some liquids purchased by Subham is
Item Rate per litre Amount required in litres
Milk 20/- 5
Oil 80/- 1
Cream 120/- 0.5

A shopkeeper offers a discount of 10%, 20% and 30% in the rate of following items.
These discounts are given according to the demand of customer. For getting maximum profit,
Subham will use 30% discount in..... Item and he will pay ...... rupee to the shopkeeper.

OPtion

1) Oil, 190
2) Cream, 194
3) Milk, 190
4) Cream, 196
5) Oil, 194
6) Milk, 180
7) Oil, 188
8) Cream, 178
9) Oil, 178
10) Milk, 188

Solution

In the problem, Subham has to invest 100 rupee in 5 litre milk, 80 rupee in 1 litre oil and
60 rupee in 0.5 litre cream, therefore for getting maximum profit he will use 30% discount in milk
of maximum price then 20% in oil and 10% in cream of minimum price.

Correct Option: 10 Best Solution (0)

14 Sep 2009 Break the code

If 15*16 = 62 & 2(18#14) = 252
Similarly 11*13 = 48 & 2(22#17) = 374
On the basis of these formulae if
10*15 = A & 2(21#12) = B
Then A & B are

OPtion

1. 50, 374
2 48, 158
3. 62, 374
4. 48, 252
5. 50, 252
6. 98, 98
7. 50, 184
8. 45, 450
9. 67, 98
10. 52, 80

Solution

Here 15*16 = 2(15+16) = 62
And 2(18#14) = 18×14 = 252
Similarly for others

Correct Option: 5 Best Solution (0)

11 Sep 2009 break the notation.

By applying some arithmetic operations, we got.
1234 = 1
2345 = 2
4567 = 19
5678 = 8
Then 6789 = ?

OPtion

1) 9
2) 4
3) 30
4) 25
5) 8
6) 10
7) 1
8) 3
9) 40
10) 7

Solution

Here
1234 = 1*2*3*4/1+2+3+4 = 24/10 = 12/5
after dividing 12 by 5 we get 2 as divisor and 2 as reminder
2/2 = 1
4567 = 4*5*6*7/4+5+6+7 = 840 /22 = 420/11
after dividing 420 by 11 we get 38 as divisor and and 2 as reminder
38/2 = 19

on applying same rule
6789
=6*7*8*9/6+7+8+9 = 3024/30 = 1512/15 = 504/5
after dividing 504 with 5 we get 100 as divisor and 4 as reminder
100/4 = 25

Correct Option: 4 Best Solution (0)

10 Sep 2009

If in a coded language four fundamental operations of arithmetic -
addition, subtraction, multiplication and division are given as follows -
Operation Code
+ it
- a
X li
/ .....
The code in blank place is-

OPtion

1) is
2) i
3) s
4) il
5) ti
6) was
7) am
8) y
9) on
10) in

Solution

Code for "+" is "it", the middle letters of word "addition". Since the word contains 8 letters totally,
therefore 2 letters are middle letters.Similarly code for "-" is "a", the middle letter of word "subtraction".
Since the word contains 11 letters hence only 1 letter is middle letter. Same for others
Division => is

Correct Option: 1 Best Solution (1)

09 Sep 2009 break the code

If in a coded language
40% of 10 = 4
60% of 30 = 216
And 80% of 50 = 32768
Then 90% of 30 = ?

OPtion

1) 19683
2) 729
3) 4578
4) 27
5) 72
6) 127863
7) 612
8) 86723
9) 2700
10) 30

Solution

In this coded language
40% of 10 = 4^1 = 4
Similarly for 60% of 30 and 80% of 50
And 90% of 30 = 9^3 = 729

Correct Option: 2 Best Solution (1)

08 Sep 2009 Surface Area

Ratio of surface area of a sphere and a hemi sphere is

OPtion

1. 3:4
2. 2:1
3. 1:1
4. 1:2
5. 4:3
6. 4:5
7. 5:4
8. 4:1
9. 1:4
10. 3:2

Solution

Area of sphere is 4ΠR2
And that of semi sphere is 2ΠR2+ΠR2 = 3ΠR2
Hence ratio is 4ΠR2 : 3ΠR2 = 4:3

Correct Option: 5 Best Solution (2)

07 Sep 2009 Plates Area

The breadth of a plate increases from one corner to other in a continuous manner.
Breadth of the plate changes from 10 cm. to 20 cm. and length of the plate is 50 cm., then area of the plate is

OPtion

1) 250
2) 860
3) 1455
4) 4800
5) 475
6) 500
7) 750
8) 625
9) 125
10) 1000

Solution

We can assume that the plate is formed of three geometries
First is a right angled triangle of two perpendicular sides 50 & 5 cm.
Second is a rectangle of dimensions 50 & 10 cm.
Third is a right angled triangle of two perpendicular sides 50 & 5 cm.
Total area of the plate is 1/2(50+5) + 50×10 + 1/2(50+5) = 750

Correct Option: 7 Best Solution (1)

04 Sep 2009 Paper sheet

A cylinder of radius and height both equal to 10 cm. made by paper is unfolded to form a plane sheet of paper.
If circumference of a circle is 2ΠR, then area of plane paper sheet is-

OPtion

1) 100Π
2) 400Π
3) 300Π
4) 200Π
5) 20Π
6) 10Π
7) 40Π
8) 2Π
9) 5Π
10) 50Π

Solution

When we unfold a cylinder, its height becomes breadth of paper and circumference becomes length of paper,
therefore area is l×2ΠR = 10×2Π×10 = 200Π

Correct Option: 4 Best Solution (0)