Rate list of some liquids purchased by Subham is
Item Rate per litre Amount required in litres
Milk 20/- 5
Oil 80/- 1
Cream 120/- 0.5
A shopkeeper offers a discount of 10%, 20% and 30% in the rate of following items. These discounts
are given according to the demand of customer. For getting maximum profit, Subham will
use 30% discount in ...... Item and he will pay ....... rupee to the shopkeeper.
In the problem, Subham has to invest 100 rupee in 5 litre milk, 80 rupee in 1 litre oil and 60 rupee
in 0.5 litre cream, therefore for getting maximum profit he will use 30% discount in milk of maximum price then 20% in oil
and 10% in cream of minimum price.
A man earns Rs. 10000 per month. His salary increases by 1% in every month. What will be his salary
after 6 months. Give your solution in integers only.
: First sequence is
JAN, FEB, MAR, APR, MAY JUN
On arranging these words in increasing alphabetic sequence, we get
AJN, BEF, AMR, APR, AMY, JNU
On arranging these words in dictionary order we get
AJN, AMR, AMY, APR, BEF, JNU
Taking the words in their original words we get
JAN, MAR, MAY APR, FEB, JUN as changed sequence
On taking similar steps for finding the solution we get
SUN, MON, TUE, WED, THU, FRI, SAT
NSU, MNO, ETU, DEW, HTU, FIR, AST (increasing alphabetic sequence)
AST, DEW, ETU, FIR, HTU, MNO, NSU (dictionary order)
SAT, WED, TUE, FRI, THU, MON, SUN (answer)
This sequence contains 1 digit extra in every next number.
1 | 74 | 894 | 9688 | 88997 | 897999
=> 1 | 7 + 4 |8 + 9 + 4| 9 + 6 + 8 + 8| 8 + 8 + 9 + 9 +7|8 + 9 + 7 + 9 + 9 + 9 |
=> 1| 11| 21 | 31 | 41 | 51| ….
In ninth term sum of all digit of the number will be 81.
After that it should be 91 in tenth term which is not possible because the greatest
number of ten digit is 9999999999, the sum of its all digits = 9 × 10 = 90