Total number of different letters = 5 ( H, O, T, S, P )
Number of Words having all the letters different = 5*4*3*2 = 120
Total number of repeated letters = 2 ( O, T )
If one letter is repeated then number of words = 2*(4*3/2)*(4*3*2*1/2)
= 144
If two repeated letters are used then number of words = 6
Total number of words = 120 + 144 + 6 = 270
Position of all the letters of the word MONKEY are 13 15 14 11 05 25
& position of 6 successive letters starting from M are 13 14 15 16 17 18
(Here M is the first letter of word MONKEY)
Modulus of differences of these numbers are 00 01 01 05 12 07
Sum of these differences = 26 hence the code
Similarly for others
In "HEROHONDA" position of all odd placed letters in English alphabet are 8, 18, 8, 14, 1
and sum of all these numbers is 49, similarly position of all even placed letters in English alphabet
are 5, 15, 15, 4 and sum is 39
Difference of these two numbers is 49 - 39 = 10
Similarly for others
If x2 + y2 + z2 - xy - yz - zx < 0 then which one statement is correct.
OPtion
1) x = y = z
2) x > y > z
3) x < y < z
4) x ≠ y = z
5) x = y ≠ z
6) x ≠ y ≠ z
7) x, y, z have negative values
8) any one of x, y, z is negative
9) any two of x, y, z are negative
10) Not possible
Solution
x2 + y2 + z2 – xy - yz – zx < 0
=> 2x2 + 2y2 + 2z2 – 2xy - 2yz – 2zx < 0
=> x2 + y2 - 2xy + y2 + z2 - 2yz + z2 + x2 - 2zx < 0
=> (x – y)2 + (y – z)2 + (z – x)2 < 0
(x – y)2 + (y – z)2 + (z – x)2 ,
This expression is the sum of three perfect square numbers and it is not possible to make this expression less than 0.
8 men and 10 boys do a work in the same days as 4 men and 16 boys do. 1 man
and 3 boys start a work to finish it in 40 days. After eighteen days, 9/20th part of the work had been finished.
How many boys should be increased to make the work complete in exact time.
In 18 days, (9/20)th part of work is finished
Thus in 1 day, {9/(20*18)}th = 1/40th part of work is finished
Hence in 40 days, work will be complete.
No additional boys are required.