M4maths Previous Puzzles

29 Oct 2009 plot a graph

A man moves 4 m. towards east then 3 m. towards left after then 8 m. towards right then 6 m.towards right
then 16 m. towards right. Finally he moves 4m towards north followed by 4 m. towards right.
What is his distance from the starting point.

OPtion

1) 1 m.
2) 2 m.
3) 3 m.
4) 4 m.
5) 5 m.
6) 6 m.
7) 7 m.
8) 8 m.
9) 9 m.
10) 10 m.

Solution

a graph to obtain the result.

Correct Option: 1 Best Solution (8)

28 Oct 2009 change the HAT

If CAT is changed to XAT
RAT is changed to NAT
BAT is changed to PAT
FAT is changed to VAT
Then HAT is changed to

OPtion

1) YAT
2) MAT
3) SAT
4) ZAT
5) LAT
6) OAT
7) DAT
8) EAT
9) GAT
100 UAT

Solution

Here C is changed to X. The position of C in English alphabet is 3. 8 multiple of 3 is 24 and 24th letter
in English alphabet is X.Similarly R is changed to N. The position of R in English alphabet is 18.
8 multiple of 18 is 144 and 144th letter in English alphabet on taking running sequence as
ABCDEFGHIJKLMNOPQRSTUVWXYZABCDEFGHIJKLMNOPQRSTUVWXYZABCDEFGHIJKLMNOPQRSTUVWXYZ............... is N
Similarly for others

Correct Option: 5 Best Solution (11)

27 Oct 2009 fine the number

After increasing a number by 1, its square and cube are added in it. If this expression is 5220,
then the number is

OPtion

1) 14
2) 19
3) 20
4) 17
5) 16
6) 15
7) 18
8) 13
9) 21
10) 22

Solution

According to given condition (x+1)+ x^2+ x^3 = 5220
On solving we get x = 17

Correct Option: 4 Best Solution (2)

26 Oct 2009 code for loye

XMAT = 2/2
GCAR = 3/1
SIJM = 2/2
HPSX = 1/3
Then LOYE =

OPtion

1) 1/3
2) 2/2
3) 3/1
4) 4/0
5) 0/4
6) 1/4
7) 4/1

Solution

Answer: Positions of X, M, A & T in English alphabet are 24, 13, 1 & 20.
Two numbers are not cancelled by any of the integer and two numbers are cancelled by any integer, hence code is 2/2, similarly for others
Similarly positions of L, O, Y & E in English alphabet are 12, 15, 25, 5
One number is not cancelled by any integer and three are cancelled by any integer, hence code is 1/3.

Correct Option: 1 Best Solution (7)

23 Oct 2009 code for Rakshit

If SAURAV = SSUVSR
KRITIKA = TTRKRTK
ROHINI = IHOHOH
Then RAKSHIT =

OPtion

1) RHRSSAI
2) SRHSAAI
3) RHKSITH
4) RRKHIST
5) ASTRRHI
6) KSRHITT
7) ARKSITH
8) SRSHRAI
9) ITRHAAR
10) RAISRSH

Solution

The position of letters of word SAURAV in English alphabet are 19, 1, 21, 18, 1, 22 respectively.
On writing the word SAURAV in a running sequence we get
SAURAVSAURAVSAURAVSAURAV.......
19th, 1st, 21st, 18th, 1st and 22nd letters in this sequence are S, S, U, V, S, R
Similarly for others

Correct Option: 8 Best Solution (1)

22 Oct 2009 Code for Break

If WATCH = 4/5
MOUSE = 3/5
DOLL = 1/4
MASTER = 3/6
then BREAK =

OPtion

1) 4/5
2) 2/5
3) 3/5
4) 1/5
5) 5/5
6) 0/5

Solution

In WATCH 4 letters W, A, T & H out of 5 letters have suprimeposable mirror images, hence code is 4/5
Similarly in BREAK only A out of 5 letters has suprimeposable mirror image, hence code is 1/5

Correct Option: 4 Best Solution (7)

21 Oct 2009 find the value

169524 = 80/1
426538 = 1440/7
398254 = 8640/31
413526 = 240/7
Then 245231 =

OPtion

1) 232/17
2) 236/13
3) 358/11
4) 465/19
5) 240/17
6) 197/7
7) 289/5
8) 477/43
9) 321/8
10) 260/9

Solution

169524 =(1*6*9*5*2*4)/(1+6+9+5+2+4)
=2160/27 = 80/1
Similarly 245231=(2*4*5*2*3*1)/(2+4+5+2+3+1)
=240/17

Correct Option: 5 Best Solution (4)

20 Oct 2009 find the code for 1649

If 4216 = 3
9164 = 5
1211 = 4
Then 1649 =

OPtion

1) 7
2) 6
3) 8
4) 9
5) 1
6) 2
7) 3
8) 4
9) 5
10) 0

Solution

Here 4216 contains 4, 1 & 16 (Total 3 numbers). All these numbers are perfect squares hence code is 3
Similarly in 1649, there are 6 perfect square numbers. These are 1, 4, 9, 16, 64, 49

Correct Option: 2 Best Solution (2)

19 Oct 2009 2401 written as

If 512 = 9
729 = 6
3125 = 5
then 2401 =

OPtion

1) 9
2) 5
3) 6
4) 7
5) 8
6) 4
7) 1
8) 2
9) 3
10) 10

Solution

512 = 29 (here 2 is a prime number), hence 512 = 9
Similarly other numbers can also be written as powers of prime numbers

Correct Option: 6 Best Solution (0)

16 Oct 2009 History Puzzle (Its Friday)

If Ashok, Bindusar, Chandragupta is coded as CBA
Then Akber, Baber, Humaun, Shahjahan is coded as

OPtion

1) BAHS
2) HASB
3) BSAH
4) BHAS
5) HABS
6) HSBA
7) BASH
8) SABH
9) ABSH
10) ABHS

Solution

Chandragupta is father of Bindusar and Bindusar is father of Ashok
Hence order is CBA
Similarly Baber is father of Humaun, Humaun is father of Akber, Akber is father of Jahangir, Jahangir is father of Shahjahan hence order is BHAS.

Correct Option: 4 Best Solution (0)