ER. A SIRISHA Profile Page

ER. A SIRISHA Profile page View Public Wall My Profile Page

A SIRISHA 10 years ago

A is thrice as efficient as B and hence completes a work in 40 days less than the number of days taken by B.
What will be the number of days taken by both of them when working together ?

Reply Like? Yes (9) | No

ashutosh shukla 10 years ago

(ET)a =(ET)b i.e 3(t-40)=1*t;

Like? Yes | No

A SIRISHA 10 years ago

IF M% OF M + N% OF N = 2% OF (M*N) ,THEN WHAT PERCENTAGE OF M IS N ? WITH EXPLANATION

OPTION
A) 50%
B) 75%
C) 100%
D) CANNOT BE DETERMINED DUE TO INSUFFICIENT DATA

Reply Like? Yes (3) | No

ashutosh shukla 10 years ago

m*m + n*n=2mn; i.e m=n. 50% ans

Like? Yes | No (1)

Sneha Singh 10 years ago

50% is the correct & verified ans.

Like? Yes | No (2)

Ramakrishna 10 years ago

Q: In a 200m race A beat B by 10m or 2 seconds. What is A"s time over the race? I NEED COPLETE SOLUTION

a) 38sec b) 40 c) 42 d) none

Reply Like? Yes (19) | No

abhishek narayan 10 years ago

let the speed and time taken by B be x m/s and t sec respectively.
t*x=190
(t+2)*x=200
t=38 sec

Like? Yes (11) | No (1)

A SIRISHA 10 years ago

If 1 1 1 1= R
2 2 2 2= T
3 3 3 3= E
4 4 4 4= N
Then
5 5 5 5= ?
????????????????????

Reply Like? Yes (7) | No (3)

Sravanthi 10 years ago

1+1+1+1=Fou(r)=R
2+2+2+2=Eigh(t)=T
3+3+3+3=Twelv(e)=E
4+4+4+4=Sixtee(n)=N
5+5+5+5=Twent(y)=Y

Like? Yes (14) | No (3)

Amar Poonia 10 years ago

Y (last charachter of addtion of all digits). e.g. 5+5+5+5=20 Twent Y

Like? Yes (2) | No

balu 10 years ago

Your super sravanthi....ur right ans

Like? Yes (2) | No

A SIRISHA to RAKESH 10 years ago

Q. In an election between two candidates , a candidate who gets 40% of total votes is defeated by 15000 votes. The number of votes polled by the winning candidate is ? WITH EXPLANATION

Reply Like? Yes (149) | No (35)

abhishek narayan 10 years ago

let the no. of votes polled= x.
given, 3x/5-2x/5=15000.
x=75000.
no. of votes polled for winning candidate is = 3x/5 =45000

Like? Yes (51) | No (22)

Deepak prajapati 10 years ago

let total no of vote=x
according to the question candidate who got 40% vote,defeated by 15000 votes
that means(no of votes of winner-no of votes for losser=15000)
((60*x)/100)-(40*x)/100)=15000
after solving we got x=75000
no of vote polled by winning candidate=((3*75000)/5)=45000

Like? Yes (78) | No (19)

Akash Verma 10 years ago

let total no. of votes be x.
then (x*40/100)+15000=x*60/100
total no votes =x=75000
So votes polled by winning candidate = 3*x/5=3*75000/5=45000 Ans

Like? Yes (31) | No (14)

Nishant Chaudhary 10 years ago

We know in the election only two candidate participates .
A candidate who found 40% vote is defeated by 15000 votes
it show that that that the condidate defeated by 20% vote
20% votes =15000
thus the winning candidate polled 15000×3=45000 votes
Ans-45000 votes

Like? Yes (29) | No (14)

llamar 10 years ago

defeated candidate got 40% votes , winning candidate get 60%
difference b/w them is 20%=15000
so winning candidate get (60%)=3*15000=45000

Like? Yes (62) | No (10)

Vaishali mittal 10 years ago

winning candidate got
45000

Like? Yes (7) | No (12)

selvam 9 years ago

let take two candidate as A and B
if A takes 40% then B takes 60%.difference is 20% which is nothing but 15000 votes.
20%=15000
60%=? (here i have taken 60% because it is asked to find the winning cand votes)
?=(15000*60)/20=45000

Like? Yes (38) | No (4)

Abdul Majid 8 years ago

in an election between two candidates, a candidate who obtained 7650 votes lost by a margin of 10% of total votes . Find the total votes? Please answer this question.

Like? Yes (34) | No (8)

A SIRISHA to RAKESH 10 years ago

Q. if the price of wheat be raised by 30% , find by how much percent a house holder must reduce his consumption so as not number increase his expenditure ? WITH EXPLANATION

Reply Like? Yes (45) | No (16)

abhishek narayan 10 years ago

let x and y be the cost of the wheat and household consumption respectively.
expenditure= x*y.
new cost of wheat= 1.3x. Let new household consumption be a.
in order to not let the expenditure increase, x*y=1.3x*a
a=10y/13.
thus, consumption should decrease by = (3/13)*100%=23.07%

Like? Yes (24) | No (19)

Akash Verma 10 years ago

direct formula= (R/(R+100))*100,
then, (30/130)*100=23.07%

Like? Yes (23) | No (5)

Gaurav Sharan 10 years ago

Let old price be 100
Then new price = 130
Consumption needs to be decreased by 30 which is in percentage (30/130)*100 = 23.07%

Like? Yes (64) | No (9)

llamar 10 years ago

assume
initially wheat 1kg=100/-
price increased by 30% means 1kg=130
how much wheat he is getting for 100 is x=(100*1000)/130=769.23 grams
consumption should decrease by 1000-769.23=230.7=23.07% of kg

Like? Yes (14) | No (6)

balaji singh 6 years ago

(r/r+100)*100
(30/30+100)*100
=23.07

Like? Yes (1) | No (3)

A SIRISHA to RAKESH 10 years ago

Q. If the radius of a circle is decreased by 50%, its area is reduced by ...? WITH EXPLANATION

Reply Like? Yes | No

abhishek narayan 10 years ago

Let the radius be R.
new area = pi*(0.5R)^2
= 0.25*pi*(R^2).
% reduced = {(1-0.25)/1}*100 = 75%

Like? Yes (2) | No

P.ARUNA 10 years ago

for any 2 dimensional geometry figure the change in its area can be found bye (2x+(x)^2/100)
given area decreased ny 50% so (2(-50)+(-50)^2/100)
= -100+25
= -75%
the area reduced by 75%

Like? Yes | No

A SIRISHA to RAKESH 10 years ago

Q. By mixing water a man gains the profit of ((100/9) %). Find the quantity of water mixed by him.
WITH EXPLANATION

Reply Like? Yes (16) | No

Gaurav Sharan 10 years ago

Let cp of milk =c and of water is 0.
sp of mixed milk = c
cp of mixed milk = 0.9c
let qty of water and milk be n1 and n2 respectively.
By rule of allegation,
n1/n2=(c-0.9c)/(0.9c-0)
i.e. n1/n2= 1/9
So, ratio of milk to water is 9:1

Like? Yes (1) | No (5)

yash 10 years ago

Assume the quantity of milk is n1 @ rate of Rs x /unit
and quanity of water is n2
before mixing water the cost price of milk is n1 *x
after mixing water the cost price will be (n1+n2) *x
the profit will be
(n1+n2)*x- n1*x which will be equal to (100/9)%* n1 *x
so n2*X= (1100/9)*1/100*(n1*x)
n2*x=(1/9) n1*x
n2/n1=1/9
so the ratio of water and millk is 1 ratio 9

Like? Yes (6) | No (2)

A SIRISHA to RAKESH 10 years ago

Q.I mixed some water in pure milk and the mixture is sold at the cost price of the milk. If I gained 16 ⅔% ,in what ratio did I mix water in the milk ? WITH EXPLANATION

Reply Like? Yes (68) | No (17)

A SIRISHA to RAKESH 10 years ago

Q . In a certain camp , 20% of the boys are from Maharashtra state and30% of those are from Bombay city. If there are 49 boys in the camp who are from Maharashtra state but not from Bombay city, what is the total number of boys in the camp ? WITH EXPLANATION

Reply Like? Yes (10) | No (2)

abhishek narayan 10 years ago

Let the no. of total boys in the camp be x.
Given, x/5 are from maharashtra.
and 0.3*x/5 are from Bombay city.
Also, x/5-{(0.3x)/5}= 49
7x=49*50
x=350. ans

Like? Yes (14) | No (4)

Gaurav Sharan 10 years ago

Let total boys be x.
Boys from Maharashta : 0.2x
Boys from Maharashtra but not Bombay : (0.7)0.2x = 49
so, x = 350

Like? Yes (5) | No (2)

A SIRISHA to RAKESH 10 years ago

Q. A rise of 600m is required to get a rail road over a mountain the grade can be kept down by lengthening the track and curving it around the mountain peak. The additional length of the track required to reduce the grade from 2% to 3% is approx ? WITH EXPLANATION

Reply Like? Yes (28) | No (3)

sundar 10 years ago

600/3%-600/2%= 10000

Like? Yes (2) | No (6)

ravi teja ravi teja 9 years ago

why should we take 600/3% ?

Like? Yes (1) | No (4)

BHUVNESH SINGH 7 years ago

The grade is actually the slope of the railroad line. So the given slopes are 0.03 and 0.02. Calculate the length required for each slope and subtract the answers to get your final answer which is the additional length of track required. Slope is the change is height over change in length.

1) For a slope of 0.03 and height of 600 m (which is same for both cases), the length required is 30000 m
2) For a slope of 0.02 and height of 600 m, the length required is 20000 m

So 30000-20000= 10000 m, which is your final answer. The answer to the question is "a" 10000 m

Like? Yes (11) | No (2)

A SIRISHA to RAKESH 10 years ago

Q An insurance collector receives 15% commissions on the premium collected .How much must he collect per week in order that his annual income may be rs.6500/- ? WITH EXPLANATION

Reply Like? Yes (2) | No

Deepak prajapati 10 years ago

suppose,
insurance collector collects x premium per day
so
commission per day will be=(x*15)/100=(3*x)/20
according to question
((3*x*365)/20)=6500
so,x=118.72 per day
for a week =7*118.72=831.04 per week
total income for a week will be 831.04

Like? Yes (3) | No (6)

Uttam guha 6 years ago

((6500/52)*100)/15=833.33...

Like? Yes (7) | No (1)

A SIRISHA to RAKESH 10 years ago

Q. a man taxed at a rate of 5 % as income tax and 10% special surcharge on the amount of income tax pays altogether Rs. 1110 . Find his gross income if he allowed a deduction of 20% . WITH EXPLANATION

Reply Like? Yes (252) | No (25)

chandra 6 years ago

a man taxed at a rate of 5% as income tax and 10% special surcharge on amount of income tax pays altogether 1110. Find his gross income if he is allowed for deduction of 20%.

Like? Yes (17) | No (8)

A SIRISHA to RAKESH 10 years ago

Q A garden has only red, green and white flowers. 60% of flowers have red colours, 30% have green colour and 50% have white colour. If no flower has all the three colours, What percentage of the flowers have only one colour ? WITH EXPLANATION

Reply Like? Yes (5) | No

abhishek narayan 10 years ago

let n(X) be the total no. of flowers in the garden = x.
n(X)= n(RUGUW)= n(R)+n(G)+n(W)-n(two color flowers) + n(three color flower)
x= 0.6x+0.3x+0.5x-n(two color flowers)+ 0
n(two color flowers)=0.4x
n(only R)+n(only G)+n(only W)= n(R) + n(G) +n(W) - 2(two color flowers) )+ 3(three color flowers).
= 0.6x + 0.3x + 0.5x -2(0.4x) + 3*0
=1.4x- 0.8x = 0.6x.
Hence, %(only one color flowers)= 60%

Like? Yes (5) | No (5)

Deepak prajapati 10 years ago

suppose total flowers in the garden=x
given that
n(r)=.6*x
n(g)=.3*x
n(w)=.5*x
n(r g w)=0 (no of flowers has all the three colors)/here space between consecutive no represents intersection
we know that
n(ruguw)=n(r)+n(g)+n(w)-n(r g)-n(g w)-n(r w)+n(r g w)
so,x=(.6+.3+.5)*x-[n(r g)-n(g w)-n(r w)]+0
so,
x[n(r g)-n(g w)-n(r w)]=1.4*x-x=.4*x
now
//formula (only A)=[n(A)-N(A B)-N(B C)+N(A B C)]

[(only r)+(only g)+(only w)]=[n(r)+n(g)+n(w)]-2*x[n(r g)-n(g w)-n(r w)]+3*n(r g w)
=(1.4*x)-2*(.4*x)+(3*0)
so,
[(only r)+(only g)+(only w)] =.6*x
% of [(only r)+(only g)+(only w)]=((.6*x)/x)*100=60% ans.

Like? Yes (5) | No

A SIRISHA to RAKESH 10 years ago

Q. An alloy contains tin and copper in the ratio 4:5. If tin has 20% impurity and copper has 58%, what is the average percent impurity ? WITH EXPLANATION

Reply Like? Yes (13) | No (1)

RAKESH 10 years ago

tin = 4/9 , copper = 5/9
impurity in, tin =4/9 *20% = 8/90 , copper = 5/9 *58% = 29/90
total impurity = (8/90 +29/90) = 37/90

% impurity = 37/90 *100 = 41 % approax

Like? Yes (14) | No (5)

Harsha Vardhan 8 years ago

rakesh how did u take tin as 4/9 and cu 5/9 ?? is it 4+5=9 or any other explanation

Like? Yes (6) | No

Saloni 6 years ago

Let the quantity of tin and copper in the alloy be 4x and 5x, respectively.
Then impurity of tin
= 0.2 × 4x = 0.8x.
and that of copper
= 0.58 × 5x= 2.9x
Total impurity=0.8x + 2.9x = 3.7x

Average impurity percentage
= 3.7x/9x × 100% = 41.1%

Like? Yes (2) | No (1)

A SIRISHA 10 years ago

Q. An alloy contains tin and copper in the ratio 4:5. If tin has 20% impurity and copper has 58%, what is the average percent impurity ? WITH EXPLANATION

Reply Like? Yes | No

abhishek narayan 10 years ago

Let the quantity of alloy be x.
tin impurity = (0.2*4x)/9 and copper impurity=(0.58*5x)/9.
Total % impurity= {(0.8+2.9)/9}*100%=(3.7*100)/9%=41.11%

Like? Yes | No

A SIRISHA 10 years ago

Reply Like? Yes (1) | No (1)

A SIRISHA 10 years ago

Reply Like? Yes | No (1)

A SIRISHA 10 years ago

Q An insurance collector receives 15% commissions on the premium collected .How much must he collect per week in order that his annual income may be rs.6500/- ? WITH EXPLANATION

Reply Like? Yes | No

A SIRISHA 10 years ago

Reply Like? Yes (1) | No

Pages - 4

First prev 1 2 3 4 Next Last

ER. A
login

Andhra Pradesh

A sirisha (F)

Total Points 130
Join 12 years ago

M4 Score

jntua

Today's Puzzle Report

Puzzle Attempts8
Total Puzzle Points 120

Placement Puzzle Report

Question Ask 3
Best Solution 0
Solution 1

Last Update 10 years ago

Best 5 Engineers From
jntua

Karnataka

Swarupa nuggu (F)

Total Points 1332
Join 11 years ago

M4 Score

Andhra Pradesh

G lokesh (M)

Total Points 699
Join 11 years ago

M4 Score

Andhra Pradesh

Shaik sharina (F)

Total Points 10
Join 10 years ago

M4 Score

Andhra Pradesh

Narasapu hari p (M)

Total Points 439
Join 11 years ago

M4 Score

Andhra Pradesh

Sindhura (F)

Total Points 210
Join 10 years ago

M4 Score

What is the sum (in RS) which when divided among X Y Z in the proportion 3:5:7 provides rupees 8000

visali 3 Months ago

Buy Fake USD,EUR,CAD,GBP:Call/Text/Whatsapp:+15014362415/

Whatsapp/ +1(501)436-2415 / +44 7851 026

Morgan James Globalshopcc 3 Months ago

Welcome here! Virtual Coworkers https://virtualcoworkers.com connects businesses with top-tier virtu

Kate Johnson 4 Months ago

After a long and intense volleyball match, the team takes a much-needed water break. The girls each

Samson akinjede 6 Months ago

A mute person enters the pharmacy and decides to buy a toothbrush. He imitates the movements of brus

Samson akinjede 7 Months ago

elderly care
[url=https://myassuredhomenursing.com/]elderly care[/url]
[url=https://myassuredhomenur

RahPeninsula 7 Months ago

Searching for Elderly home care Service in Belmont, CA? Right at Home offers personalized home care

RahPeninsula 7 Months ago

A field has 4 gates, in how many ways is it possible to enter the field by one gate and come out at

Sadhanaa 7 Months ago

Hey, I am a student starting to prepare for placements can someone guide me on how to start preparin

Disha Gujar 9 Months ago

Two cars with speed of 15 kmph and 30 kmph respectively are 100 km apart and face each other. The di

Nashi Informatics Solutions Private Limited 10 Months ago