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Animesh Mogha 4 years ago

University of Vikram has enrolled nine Phd candidates.Babu Chitra,Dheeraj , Eesha,Farooq,Gowri , Hameed,Iqbal,Jacob.
-Farooq and Iqbal were enrolled on the same day as each other, and no one else was enrolled that day.
-Chitra and gowri were enrolled on the same day as each other, and no one else was enrolled that day.
-On each of the other days of hiring , exactly one candidate was enrolled.
-Eesha was enrolled before Babu.
-Hameed was enrolled before Dheeraj
-Dheeraj was enrolled after Iqbal but before Eesha
- Gowri was enrolled after both Jacob and Babu
-Babu was enrolled before Jacob
Who were the last two candidates to be enrolled?

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Deekshitha 4 years ago

New Public School has a circular layout. The school has teachers specializing in various subjects. All

classrooms of the school are equally spaced apart and located along its perimeter. Each teacher needs

to take 4 classes in a day. There is a strange rule. The first and last class has to be in the same class

roun. The other two classes have to be at two other distinct class rooms.

Ram is a math teacher. He never teaches two successive classes at two adjacent classrooms. How many distinct trips to class rooms are possible for Ram if there are 9 class rooms in the school?

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Varun 4 years ago

In a day
First & last room should be same
Let's choose it arbitrarily, next class can be chosen in 6 ways
Because same room cannot be chosen & neighboring rooms are also not allowed
Round represntations of class: 1 2 3 4 5 6 7 8 9. 1....

Let first one be 1
Then second can be 3 4 5 6 7 8
For 3, third class can be any of 5 6 7 8
For 4, third class can be any of 2 6 7 8 9
For 5, third class can be any of 2 3 7 8 9
For 6, third class can be any of 2 3 4 8 9
For 7, third class can be any of 2 3 4 5 9
For 8, third class can be any of 2 3 4 5 6
For 9, third class can be any of 2 3 4 5 6 7
And fourth class will be again 1

So total possible classes keeping first class constant is: (4)+(5*5)+(6) = 35

Similarly first class can be changed in 9 ways => Total possible trips per day = 9*35 = 315

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yarram poorna sahiti to SHIVENDRA PRATAP SINGH 4 years ago

sir please guide me how to solve

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Pargat Pal Singh 4 years ago

Please check puzzle dated 14.06.2021

If the capacity of a cylindrical tank is 4004 m^3 and the diameter of its base is 14 m, then find the depth of the tank?

Solution given is
Let the depth of the tank be h meter
πr²h = 4004
h = 4004/ πr²
h = (4004 x 7/22 x 1/14)
h = 91 m.

I think admin has considered 2r =14 only in place of r^2 ( 7^2).

It should be

Let the depth of the tank be h meter
πr²h = 4004
h = 4004/ πr²
h = (4004 x 7/22 x 1/49)
h = 26 m.

Please check and do justice to maths.

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Deepna D.P 4 years ago

Identify which security threat can occur because of typing error on the network site

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~Sandeep~ 4 years ago

Typosquatting attack

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Sunny Mannepalli 4 years ago

Amansells12candiesforRs.12&losesRs.2.40.Ifhesells12candiesforRs.16,howmuch
doeshegainorlose?
a.GainsRs.4
b.LosesRs.6
c.GainsRs.6.40
d.LosesRs.1.60
e.GainsRs.1.60

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Devendra Marghade 4 years ago

For 12 candies, when SP=Rs 12, Loss is Rs 2.4 , So CP=12+2.4=Rs 14.4
Hence Gain, when he sells 12 candies for Rs 16 = SP - CP = 16 - 14.4 =Rs 1.6
Option e)

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saran 4 years ago

f I sell two articles, one at 20% profit for Rs.100 and the other at 20% loss for Rs.100, what is my net profit/loss?

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Pargat Pal Singh 4 years ago

CP = 83.33+125 = Rs. 208.33
Loss = Rs. 8.33

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Pargat Pal Singh 4 years ago

Dear Admin,
Is there any chance of fair evaluation of scores or results are pre-decided to give prizes to a few privileged members ?

Reply Like? Yes (3) | No (2)

Karan 4 years ago

No chance. I think Admin team is working from home. :)

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Pargat Pal Singh 4 years ago

In today's puzzle dated 5-5-21, I have answered option 5 as answer which is shown as 5 in my home page of m4maths. But marks given are -1 .
Please check.

Reply Like? Yes (4) | No (2)

Harsha 4 years ago

With 4/5 Full Tank

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Pargat Pal Singh 4 years ago

In today's puzzle dated 5-5-21, I have answered option 5 as answer which is shown as 5 in my home page of m4maths. But marks given are -1 .
Please check.

Reply Like? Yes (3) | No (1)

Pargat Pal Singh 4 years ago

If admin is not ready to check and take corrective action for yesterday puzzle , it is better to stay away from today's puzzle as a mark of protest.

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Sunil 4 years ago

20 people going to one temple,they want rs 20.for men rs 3,women rs 2,children 50 paisa,how much money spent for men,women,children?

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G.S.Kantharao 4 years ago

Let men,Women are =x,y respectively
Then children are =(20-x-y)
Then amount=
3x+2y+(20-x-y)/2=20
6x+4y-x-y=20
5x+3y=20
For the Natural Numbers N (x,y)=(1,5)
So men =1
Women =5
Children =14
Expenditure=1*3+5*2+14*0.5=20

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Ishfaq Ahmad to Devendra Marghade 4 years ago

A train passes a standing man 11.3 seconds and passes a bridge of length 396m in 18 seconds .the speed of the train is

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Devendra Marghade 4 years ago

Let the speed of the train be x m/sec and length of the train be y m, then y/x=11.3 or y - 11.3x = 0 --(i)
Also, (y + Length of platform)/x=18
(y+396)/x=18 => 18x-y=396 ---(ii)
Solving (i) & (ii), we get, x=59.10 and y=667.88
Hence speed of the train is 59.10 m/s

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Ishfaq Ahmad 4 years ago

When you keep believing, keep trying and keep doing... Someday, you will succeed.

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Shubhashish Sinha 4 years ago

Find the elements in the relation "have the same remainder when divided by 8" if the
relation is defined on {1, 2, 3 .... 24, 25}. Also, find the distinct equivalence classes
of this equivalence relation.

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Sai laxmi Nomula 4 years ago

the average number of people visitedredfort on every day is 2240.but 2200 on every saturday, 3000 on sunday and on wednesday it is 1500people visited . what is the average number of people visited on remaining days in the ,month of december when there are 4 thursdays abd 4 mondays in the month?

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G.S.Kantharao 4 years ago

Average Visited in December = 2240
Then total visitors = 2240*31 = 69440
As there are 4 Thursdays and 4 Mondays the other 3 are Sunday,Friday and Saturday. It means 5 Sundays 5 Fridays and 5 Saturdays
It means 5*2240+5*2200+5*3000=11200+11000+15000=37200
Remaining=69440-37200=32240
Average of remaining=32240/16=2015
So Average =2015

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