M4maths Previous Puzzles

24 Feb 2016 Possible value

A number when divided by 48 gives 47 as remainder and x as quotient, the same number when divided by 49 gives 8 as remainder and y as quotient. Minimum possible value of x will be

OPtion

1) 19
2) 24
3) 29
4) 35
5) 39
6) 45
7) 88
8) 94
9) 137
10)186

Solution

According to given condition
48x + 47 = z
49y + 8 = z
48x + 47 = 49y + 8
49y = 48x + 39
y = 48(x-y) + 39
y = 48k + 39
Minimum possible value of k = 0
y = 39
and k = 0
x = y
x = 39
Option 5)

Correct Option: 5 Best Solution (3)

Shagun Chaudhary   8 years AGO

n=48x+47
n=49x+8
on solving we get
x=39
39 being the smallest is the answer

Like? Yes (6) | No   

Maneesh Gupta   8 years AGO

let the no. be n,
n=48x+47
n=49x+8
solving the above eqn. we get
x=39
39 is the smallest ans => option 5

Like? Yes (3) | No   

Devendra Marghade   8 years AGO

If 'a' is a number , then
48x+47 =a and
49y+8 =a
Comparing both equations 48x+47 =49y+8 or
x=(49y-39)/48
We get a 'x' as a whole number for y=39 and x=39, which is minimum value of 'x'
Option 5)

Like? Yes (2) | No (1)  

23 Feb 2016 Percentage

If Bablu's income is 25% more than Chetan's and Chetan's income is 20% more than Deepak's by what percent is Bablu's income more than Deepak's?

OPtion

1) 15%
2) 20%
3) 30%
4) 25%
5) 35%
6) 45%
7) 33.5%
8) 40%
9) 43.5%
10)50%

Solution

Let Deepak's income = 100. Then Chetan's income = 120
And Bablu's income = 125% of 120 = 150
Therefore
Bablu's income 50% more than Deepak's
Option 10)

Correct Option: 10 Best Solution (40)

Shagun Chaudhary   8 years AGO

Let the income of Bablu, Chetan and Deepak be x,y,z.
x=1.25y
y=1.2z
=>x=1.25×1.2×z
=>x=1.5z
Thus Bablu's income is 50% more than that of Deepak.

Like? Yes (2) | No (1)  

satish ojha   8 years AGO

babalu. chetan. Deepak
125. 100
120. 100

make equal

125*120. 12000. 10000
=15000



15000-10000)*100/10000=50%

Like? Yes (1) | No   

pooja   8 years AGO

let x,y,z be income of chetan, deepak, bablu respectively
then x=y+20y/100 similarly z= x+25x/100 then solve the equations we get z= 150y/100= y+50y/100 hence 50%
so option 10 is correct ans

Like? Yes (2) | No (1)  

dhiraj prasad   8 years AGO

let deepak income= 100
chetan = 100×120% =120
bablu = 120×125% =150
% incr = (50×100)/100 = 50

Like? Yes (1) | No   

MAMTA KUMARI   8 years AGO

LET CHETAN SAL=100RS THEN BABLU SAL=125RS THEN DEEPAK SAL =X RS THEN X+X*20/100=120X/100=100
X=250/3
THEN BABLU'S SAL =[(125-250/3)*3/250*100]
=125/3*3/250*100
=50%

Like? Yes (1) | No   

Ranjan kumar   8 years AGO

b = c/4
c= 6d/5
b = 6d/4

Like? Yes (2) | No (1)  

K.NagaSugunaManasa   8 years AGO

let 100 be deepak's income
then 20% more than Chethan's income is=120
then Balu's income=25% more than chthan i.e 150
so Balu's income is 50% more than of Deepak's Income
so answer is 50%

Like? Yes (1) | No   

paushali karmakar   8 years AGO

let d=100
c=120
25% of 120 is b's income so 25/100=(1/4)*120=30
120+30=150.
150-100=50...

Like? Yes (1) | No   

Mathi Vanan P   8 years AGO

if bablu have an income =x
then the chetan's income=y
then the Deepak's income=z
x=(25/100)y
y=(20/100)z
x=y/4
y=z/5
x=z/20
% of x=(z/20)*100
x=50% more than z
bablue is 50% more than deepak

Like? Yes (1) | No   

AMAR KUMAR REDDY   8 years AGO

well let us assume chettan's income be 100
babu's income is 25% more than chettan
so 25% of chettans income would be rs 25(25 percent 100)
then babu's income would be rs (100+25)=125rs
chettans income is 20% more than deepk that meant deepks income is 20% less than chettans .so 20% of chettan will be rs=20(20%100)
so deepks income will be(100-20=80)
so yhe answer woild be ((125-80)/80)*100=50%

Like? Yes (1) | No   

ABHINAV PUSHPAM   8 years AGO

bablu. : chetan. : deepak.
125. : 100
120. : 100.
------------------------------------------
600. : 480. : 400

so, more income of bablu is (200/400)*100 =50%
option 10)

Like? Yes (1) | No (1)  

Arun Maharana   8 years AGO

let deepak's income is x

Given chetan's income is 20% more than deepak's income
chetan's income =x+(1/5)x=6x/5

Given bablu's income is 25% more than chetan
bablu's income=(6x/5)+25% of (6x/5)=3x/2=x+50% of x

ans:-10. 50%

Like? Yes (1) | No (1)  

Sagar Jinachandran   8 years AGO

Let B be Bablu's income, C be Chetan's Income, D be Deepak's income
According to question
B=1.25 C (1)
C=1.2 D (2)
Then putting (2) in (1)
B=1.25 (1.2 D)
B=1.5 D
So that means Bablu's income is 50% more than Deepak's
Option 10

Like? Yes (1) | No (1)  

Maneesh Gupta   8 years AGO

Let the income of Bablu, Chetan and Deepak be x,y,z.
x=1.25y
y=1.2z
=>x=1.25×1.2×z
=>x=1.5z
Bablu's income is 50% more than that Deepak.
Option 10

Like? Yes (1) | No (1)  

Amit   8 years AGO

chetan=6d/5
babul=3d/2=1.5d=50% more than d
where d=deepak's income
or
let deepak's income=100
then chetan's income=120
then babul's income=150=50 more than deepak i.e. 50% more than deepak

Like? Yes (1) | No (1)  

mcamanjeet   8 years AGO

let x be deepak income
20% more is chetan income = x+x*20%
=6x/5
25% more from chetan income= 6x/5+6x/5*25%
=3x/2
% increment of bablu from deepak is
=(3x/2-x)*100/x
=50%

Like? Yes (2) | No (2)  

GOURANGA SUNDAR MANDAL   8 years AGO

let depak's income =x,then chetan incomeis x*120/100=6x/5..
and bablu'sincome =6x/5*125/100=15x/10..
so 50% more than depak's income..
option 10 is correct answer

Like? Yes (1) | No (1)  

Vaibhav Khedkar   8 years AGO

B=C+C/4
C=D+D/5
4B/5=6D/5
B=D+D/2=50%

Like? Yes (1) | No (1)  

alka verma   8 years AGO

let deepak income=100 then chetan income =120 then bablu income=150
then( (150-100)/100)*100=50

Like? Yes (1) | No (1)  

Jamil Ahmed   8 years AGO

If Deepak's income is 100, the Bablu's income is (120/100)*(125/100)*100% = 150% of Deepak's income.
Therefore, Bablu's is 50% more than Deepak's income.

Like? Yes (1) | No (1)  

Isha Saxena   8 years AGO

let Deepak's income=Rs.100
thus chetan's income=Rs. 120
and bablu's income=Rs. 150
now, let bablu's income be x% more than deepak's
thus,
100 + {(100*x)/100} = 150
solving this, x=50% Answer

Like? Yes (1) | No (1)  

sachin sawant   8 years AGO

Let Deepaks income be Rs 100
Then Chetans income is 20% more is Rs 120
Bablus income is 25% more than chetans
Thus Bablus income =Rs 150
Hence Bablus income will be 100*50/100=50%more than Depaks income
And option10

Like? Yes (1) | No (1)  

Ram Kumar Prajapati   8 years AGO

Let Deepak=100
then Chetan= 120
further Bablu= 150
increase in % = {(150-100)/100]*100
= 50%

Like? Yes (1) | No (1)  

Deepesh Malviya   8 years AGO

Let bablu's income is 100
Then chetan's income Will be 120
And deepak's income will be
120*125/100=150
Hence answer is 50

Like? Yes (1) | No (1)  

Jebas Gnana Prakash E   8 years AGO

Bablu income=x
chetan income=y
Deepak income=z
x=y(25/100)
x=y/4
y=z/5
y=z/5
x=z/5*4
x=z/20
%of x= (z/20)*100
x=z50%

Like? Yes (1) | No (1)  

Manish Kumar   8 years AGO

Let Deepak=100
then a/q chetan =120
now again a/q =150
hence %=50*100/100
=50%

Like? Yes (1) | No (1)  

Richa Jain   8 years AGO

Let deepak's income is 100
Then chetan's income=120
Bablu's income= 25% more than chetan's = 120*125/100= 150
Which is 50% more than deepak's income

Like? Yes (1) | No (1)  

mohit mittal   8 years AGO

Assume deepak's income 100
Then chetan income= 120
Bablu income = 150
So, 150-100 = 50

Like? Yes (1) | No (1)  

Saurabh Bajaj   8 years AGO

Deepak's income = x
Chetan's income = 1.2x
Bablu's income = 1.5x
So, bablu's income is 50% more than that of Deepak's income.

Like? Yes | No (1)  

Saleel Kulkarni   8 years AGO

Let Deepak's income be 100, then Chetan's income will be 100*1.2=120 and Bablu's income will be 120*1.25=150.
So Bablu's income is 50 more than Deepak's income=(50/100)*100=50%
Option 10

Like? Yes | No (1)  

Devendra Marghade   8 years AGO

Babu's Income=1.25*1.2*Deepak's income
=1.5*Deepak's Income
So Babu's Income=50% more than Deepak's Income
Option 10)

Like? Yes (1) | No (2)  

PRABHAT KUMAR   8 years AGO

Let Deepak income is 100
Then Chetan income is 100+20=120
Bablu income is 120+30=150
% more Income Bablu =((150-100)*100)/100=50%
Option 10

Like? Yes | No (1)  

MRITUNJAY   8 years AGO

bablu chetan Deepak

600. 480. 400
200/400*100=50%
option10

Like? Yes | No (1)  

Akshat Sood   8 years AGO

Taking Deepak income as rupees 500
we get income of chetan as 600 rupees and income of bablu as 750 rupees
percent by which bablu income is more than Deepak is 750-500/500*100
50percent

Like? Yes | No (1)  

Mukund Manohar   8 years AGO

Let the income of Deepak be Rs 100
then the income of Chetan is Rs 120 (20% more)
and the income of Bablu is Rs 150 (25% more than Chetan's income)
So, Bablu's income is 50% more than Deepak's income

Like? Yes | No (1)  

Nikunj Agarwal   8 years AGO

let income of Deepak be Rs 100, then chetan's income is 100*1.2= 120, and for babloo income is 120*1.25=150, thus b's income with that if D's is of 50%

Like? Yes | No (1)  

Bablu patel   8 years AGO

LET DEEPAK SAL IS 100RS THEN CHETAN SAL IS 120,THEN BABLU'S SAL WILL BE 120*25/100=30+120 =150-100=50
50*100/100=50%

Like? Yes | No (1)  

Amit pandey   8 years AGO

let deepak's income be 100.
chetan'n income=120% of 100=120
bablu's income=125% of 120 =150
so 50% more than deepak.

Like? Yes | No (1)  

Akshat Mokashi   8 years AGO

let deepaks income is 100.
so chetan income is 120 (20% more).
Now bablu income is 120+1/4(120)=120+30=150.
So bablus income is more by 50%

Like? Yes | No (1)  

Neetin Kumar   8 years AGO

Let Deepak income=100
chetan income is 20% more than deepak
i.e.chetan income=120
Bablu income is 25% more than Chetan
Bablu income =150

So Bablu income is 50% more than Deepak

Like? Yes | No (1)  

22 Feb 2016 Solve Linear Equation

[40/(x+y)] + [2/(x-y)] = 5
[25/(x+y)] - [3/(x-y)] = 1

OPtion

1) x=6 and y=8
2) x=10 and y=6
3) x=3 and y=4
4) x=8 and y=4
5) x=2 and y=6
6) x=4 and y=2
7) x=6 and y=4
8) x=4 and y=8
9) x=2 and y=4
10)x=4 and y=6

Solution

Putting 1/x+y = u and 1/x-y = v
and solve
x = 6 and y = 4
Option 7)

Correct Option: 7 Best Solution (38)

Mukund Manohar   8 years AGO

Let 1/x+y = P and 1/x-y = Q
40P+2Q=5 -----I
25P-3Q=1 -----II
MULTIPLYING I BY 3 AND II BY 2 AND ADDING IT
P=1/10
SUBSITUTING THE VALUE OF P IN I,WE GET Q = 1/2
NOW,
1/x+y = 1/10 and 1/x-y = 1/2
x+y=10 and x-y=2
ON SOLVING,
x=6 and y=4

Like? Yes (8) | No (2)  

Neetin Kumar   8 years AGO

[40/(x+y)]+[2/(x-y)]=5.........(i)
[25/(x+y)]-[3/(x-y)]=1..........(ii)

equation (i)*3+(ii)*2

[120/(x+y)]+[6/(x-y)]=15.......(iv)
[50/(x+y)]-[6/(x-y)]=2............(v)

Add (iv)+(v)

[170/(x+y)]=17
x+y=10.....(vi)

put (x+y) in (i)

[40/(x+y)]+[2/(x-y)]=5

40/10+2/(x-y)=5
x-y=2........(vii)

from vi and vii

x=6 and y=4

Like? Yes (10) | No (5)  

Shagun Chaudhary   8 years AGO

put (1/(x+y))=u and (1/(x-y))=v
40u+2v=5
25u-3v=1
u=0.1,v=0.5
=>x+y=10
=>x-y=2
On solving,
=>x=6,y=4

Like? Yes (6) | No (2)  

MRITUNJAY   8 years AGO

40/x+y+2/x-y=5
25/x+y-3/x-y=1
after solving the equation we get
x+y=10
from equation 1
x-y=2
then x=6,y=4
option 7

Like? Yes (3) | No   

Sanjay Karmakar   8 years AGO

let x+y=p and x-y=q
then the given equations become
(40/p)+(2/q)=5
(25/p)-(3/q)=1
now, equating these two equations we have p=10 and q=2.
Now, equating x+y=10 & x-y=2, we have x=6 and y=4.

Like? Yes (3) | No   

A Dinesh Kumar Reddy   8 years AGO

A=1/x+y B=1/x-y
40 A+2 B=5---------1
25 A-3 B=1----------2
multiply eq 1 by 3 and eq 2 by 2 and add them
120 A+6 B+50 A-6 B=15+2
170 A=17
A=1/10
So then
40/10+2 B=5
4+2 B=5
2 B=1
B=1/2
So
1/x+y=1/10
x+y=10------------3
1/x-y=1/2
x-y=2--------------4
Add eq 3 and eq 4
x+y+x-y=10+2
2x=12
x=6
Then
6+y=10
y=4

Like? Yes (3) | No   

yedukondalu .t   8 years AGO

substitute
or
simlify

Like? Yes (3) | No   

Siva   8 years AGO

40A+2B=5,25A-3B=1 by solving these equattions we get A=1/10&B=1/2; this means x+y=10,x-y=2 by solving these two equations we will get x=6,y=4.

Like? Yes (2) | No   

Testing Account   8 years AGO

by simplify x/y=102/68
=>x/y=3/2
=>x=6;y=4

Like? Yes (2) | No   

Ankita   8 years AGO

Using the method of substitution put 1/(x+y)=A and 1/(x-y)=B
Then on solving simultaneous equation answer we get as 1/(x+y)=1/10 and 1/(x-y)=1/2
on solving these equation we get x=6 and y=4

Like? Yes (2) | No   

Ranvir Singh   8 years AGO

We need x2 - y2 = positive number
So x>y and difference between x&y a small number

Like? Yes (2) | No   

sandhya kumari   8 years AGO

(21*x-19*y)/(11*x-14*y)=5 gives x=1.5*y
put in one of given equations to get x=6 and y=4

Like? Yes (2) | No   

mangobind kumar kishan   8 years AGO

6+4=10
40/10=4
6-4=2
2/2=1
4+1=5

Like? Yes (2) | No   

Akshat Mokashi   8 years AGO

consider x+y=a and x-y=b and their product (x+y)(x-y)=ab and solve the equation. you will get y:x=4:6. Therefore y=4 and x=6.

Like? Yes (2) | No   

Maneesh Gupta   8 years AGO

assume (1/(x+y))=u and
(1/(x-y))=v
40u+2v=5
25u-3v=1
u=0.1
v=0.5
=x+y=10
=x-y=2
further On solving,
=>x=6,y=4

Like? Yes (3) | No (2)  

Siddharth Jain   8 years AGO

Let 1/(x+y) = a
and 1/(x+y) = b
so 40a + 2b = 5 ---(1)
and 25a - 3b =1----(2)
solving (1) and (2)
a = 1/(x+y) = 1/10 ------(3)
b = 1/ (x-y) = 1/2 ------(4)

so, solving eq. (3) and (4)
we get
x =6, y = 4 ANSWER

Like? Yes (1) | No   

K.NagaSugunaManasa   8 years AGO

substitute x=6 and y=4 in equation 1 and 2 then we get for 1st equation 5 and for second 1 so option is 7

Like? Yes (1) | No   

Surabhi Yadav   8 years AGO

By using the given options in the place of x & y
x=6,y=4

Like? Yes (1) | No   

Amit ambastha   8 years AGO

assume 1/x+y=p and 1/x-y= q then the equation will be 40p+2q=5 and 25p-3q =1 solve the equation then we get p=1/10 and q=1/2 then put the value of p and q in 1/x+y and 1/x-y respectively and we get by solving x=6 and y=4

Like? Yes (1) | No   

vikash kumar das   8 years AGO

put 1/x+y=u and 1/x-y=v..then the eqn becomes
40u+2v=5 and 25u-3v=1 and we get u=1/10 v=1/2
then x+y=10 and x-y=2 and after solving these two eqns we get x=6 and y=4

Like? Yes (1) | No   

dev   8 years AGO

40/(x+y) + 2/(x-y) = 5 ---------(1)
25/(x+y) - 3/(x-y) = 1 ----------(2)

(1) * 3 --> > 120/(x+y) + 6/(x-y) = 15 ---------(3)
(2) * 2 --> > 50/(x+y) - 6/(x-y) = 2 ---------(4)

adding eq(3) + eq(4) ,,,we get ----
120 / (x+y) + 50 / (x+y) = 15+2
=> 170 / (x+y) = 17
=> x+y =10 ---------(5)

putting value of (x+y) in eq (1) ,,,we get
4+2 / (x-y) = 5
=>2 / (x-y) = 1
=> x - y = 2 -------------(6)

adding eq (5) and (6) ,,we will get
x + y + x - y = 10+2
=> 2x = 12
=> x = 6
by putting value of x in eq(6) ,,,,we will get
6 - y = 2
=> y = 6 - 2 = 4

so option is (7)............

Like? Yes (1) | No   

Akshat Sood   8 years AGO

Both the equations equate to (x+y)(x-y)
so we can find value of x which comes out to be 3/2y
put it in eq and we get x=6 and y=4

Like? Yes (1) | No   

sachin sawant   8 years AGO

Let x+y=a &x-y=b
40/a+2/b=5 ---(1)
25/a-3/b=1 ---(2)
Solving we geta=a=10& b= =2
Putting value of a & b in x+y & x-y we get
x=6& y=4
Option7

Like? Yes (1) | No   

Elamaruthu   8 years AGO

[40/(6+4)]+[2/(6-4)]=5
[25/(6+4)]-[3/(6-4)]=1

Like? Yes (1) | No   

S.MANJULA   8 years AGO

40(x-y)+2(x+y)=5((x^2)-(y^2)) --------(1)
25(x-y)-3(x+y)=((x^2)-(y^2)) ---------------(2)
(1)*3==> 120(x-y)+6(x+y)=15((x^2)-(y^2))
(2)*2==> 50(x-y)-6(x+y)=2((x^2)-(y^2))
(1)+(2)==> x+y=10------(3)
similarly (1)-(2)==> x-y=2 -----(4)
solving for (3) and (4) we get,
x=6 and y=4

Like? Yes (1) | No   

mcamanjeet   8 years AGO

let 1/x+y=p,1/x-y=q and solve equation
you will get p=1/10,q=1/2
now x+y=10,x-y=2
hence final solution is x=6,y=4

Like? Yes (1) | No   

CHANDAN KUMAR   8 years AGO

by solving the equations
we get x=6
and y=4.

Like? Yes (1) | No   

shubhrika   8 years AGO

Let 1/(x+y)=w and 1/(x-y)=z , 40w+2z=5;25w-3z=1
w=1/10 z=1/2
x+y=10
x-y=2
x=6 y=4

Like? Yes (1) | No   

gunjan   8 years AGO

If we put x =6 and y =4 in both equation,it satisfy the condition.

Like? Yes (1) | No   

Saleel Kulkarni   8 years AGO

Method 1:
Solve the two equations simultaneously and yield answer.
Method 2:
Trial and error method:
Each time it is not feasible to do complete calculations in short span of time.
For the first equation [40/(x/y)]+[2/(x-y)]=5
we can predict that 4+1=5
so to get 4 the x+y must be equal to 10
So the options are now 7 and 10
but for x-y we require 2 so x must be 6 and y must be 4
Apply the x and y values for equation 2 for cross checking
Hence Option 7

Like? Yes (1) | No (1)  

Jamil Ahmed   8 years AGO

[40/(x+y)] + [2/(x-y)] = 5
or, [120/(x+y)] + [6/(x-y)] = 15 -------- (eqn. 1)

[25/(x+y)] - [3/(x-y)] = 1
or, [50/(x+y)] - [6/(x-y)] = 2 ------- (eqn.2)

Adding eqns. 1 & 2, we get,
[120/(x+y)] + [50/(x+y)] = 15+2
or, x+y = 10 ---------------- eqn.(a)

Again, [40/(x+y)] + [2/(x-y)] = 5
or, [200/(x+y)] + [10/(x-y)] = 25 ------------- eqn.3

[25/(x+y)] - [3/(x-y)] = 1
or, [200/(x+y)] - [24/(x-y)] = 8 -------------- eqn.4

Subtracting eqn.4 from eqn.3, we get,
[10/(x-y)] + [24/(x-y)] = 25-8
or, x-y = 2 -------------- eqn. (b)

From eqns. (a) & (b), x = 6 & y = 4

Like? Yes | No (1)  

Nikunj Agarwal   8 years AGO

if x=6 & y=4 then, (40/(x+y)=4) & 2/(x-y)= 1, which gives rhs values, & satisfies both equation

Like? Yes | No (1)  

VEMULA HIMAVARSHA   8 years AGO

(40/x+y)+(2/(x-y))=5=>40x-40y+2x+2y=>42x-38y=5x^2-5y^2---->eq1
(25/x+y)-(3/x-y)=1=>25x-25y-3x-3y=>22x-28y=x^2-y^2-------->eq2
multiply eq2 to with 5
110x-140y=5x^2-5y^2---->eq3
subtract eq1 from eq3then
-68x+102y=0=>68x=102y
divided by 34 on both sides
2x=3y=>by substituting x=6 and y=4 we will get equal values i.e
2*6=3*4=>12=12
so option 7

Like? Yes | No (1)  

Mathi Vanan P   8 years AGO

assume X-Y=A and X+Y=B
(40/B)+(2/A)=5
assume the above eqn 1
(25/B)-(3/A)=1
assume the above eqn 2
multiply 3 with eqn 1
eqn 1 becomes,
(120/B)+(6/A)=15
multiply 2 with eqn 2
eqn 2 becomes
(50/B)-(6/A)=2
add the above two eqns
(170/B)=17
B=10
put B=10 in eqn 1
4+(2/A)=5
2/A=1
A=2
X-Y=2
X+y=10
the answer is X=6,Y=4

Like? Yes (1) | No (2)  

Jebas Gnana Prakash E   8 years AGO

put x=6 and y=4

in eqn 1weget
40/10 + 2/2
=4+1
=5

in eqn 2

(25/10) - (3/2)
=5/2 -3/2
5-3=2
2=2

Like? Yes | No (1)  

sanjeet kumar   8 years AGO

Solving these two equation, we get
2x^2 - 10x =2y^2 - 5y.
By trail we find x=6 and y=4

Like? Yes | No (1)  

Amit Kumar   8 years AGO

to get the ans 5 in 1st we need to look that 40 is getting divided by such a number that sum of x and y must be multiple of 5 or 10 or 8.this left us with only two option forhit n trial

Like? Yes | No (1)  

pooja   8 years AGO

multiply the both equation by (x^2-y^2) and eliminate x+y in both equations we get x+y=10 similarly for x-y hence we get x=6 and x=4

Like? Yes | No (2)  

19 Feb 2016 Find the ratio

Find the ratio between the total surface area and the curved surface area of the solid generated by rotating a right angled triangle with base 7 cm and height 24 cm about the height.

OPtion

1) 7:25
2) 7:10
3) 32:25
4) 33:18
5) 7:32
6) 3:7
7) 7:36
8) 23:25
9) 18:7
10)32:27

Solution

Ratio = surface area/ curved surface area
= Pi r^2 + Pi r l / Pi r l
= 1 + r/l
= 1 + 7/25 = 32:25

Option 3)

Correct Option: 3 Best Solution (28)

MRITUNJAY   8 years AGO

rotating along height means it is cone
l=25cm
r=7cm
ratio=Pi*r(r+l)/pi*RL
=25+7/25=32:25
option 3

Like? Yes (6) | No (2)  

mcamanjeet   8 years AGO

it makes cone
total s .a=pie*r*l+pie*r*r
cur s .a =pie*r*l
ratio=l+r/l
ans=25+7/25=32/25

Like? Yes (4) | No (1)  

Aakash Beniwal   8 years AGO

slant height(l)=25,
ratio=
pi * r *(l+r) : pi * r *l

Like? Yes (2) | No   

RAHUL KUMAR   8 years AGO

rotating along height means it is cone
l=25cm
r=7cm
ratio=Pi*r(r+l)/pi*RL
=25+7/25=32:25
option 3

Like? Yes (2) | No   

ABHINAV PUSHPAM   8 years AGO

rotating along height means it is cone
l=25cm
r=7cm
ratio=Pi*r(r+l)/pi*RL
=25+7/25=32:25
option 3

Like? Yes (2) | No (1)  

Saleel Kulkarni   8 years AGO

The solid formed is a cone. The surface area = pi*r*l
r=7 l=sqrt(7^2+24^2)=25
the total surface area of the cone = pi*r*l + pi*r^2
So the ratio will be = 1 + (r/l)
=1+(7/25)
=32/25

Like? Yes (1) | No   

Akshat Sood   8 years AGO

After rotation it is found that we get a cone
hence
?r(l+r):?rl
32:25(r=7)

Like? Yes (1) | No   

Bablu patel   8 years AGO

it is given r=7 and h=24
slant hight =(7^2+24^2)^1/2
=25;
total surface area=pi*r^2+pi*r*l
curvwed surface area=pi*r*l
ratio=(r+l)/l
=(7+25)/25
32/25

Like? Yes (1) | No   

Mukund Manohar   8 years AGO

Solid formed is Cone with radius =7 cm and height=24 cm
Slant height of Cone= sq.root(24^2 + 7^2)=sq.root(625)=25 cm
Total Surface Area=22/7 * 7(25 + 7) = 22 * 32 cm
Curved Surafec Area= 22/7 * 7 *25 = 22 * 25 cm
Req.Ratio =32:25

Like? Yes (1) | No   

anupam   8 years AGO

tsa/csa = pi*r(l+r)/(pi*r*l)
so ratio is. ( l+r)/l

here l is slant height.......find it is 25
so ratio is 32/25

Like? Yes (2) | No (1)  

Peeyush Agarawal   8 years AGO

It makes cone So,.
total surface area=pie*r*r+pie*r*l,
curved surface area=pie*r*l,
totalsurface area/curved surface area=r+l/l=25+7/25=32:25

Like? Yes (1) | No   

Purbasha   8 years AGO

as the solid is rotating by a right angled triangle,so it will make a cone
the base is r=7cm
height is h=24cm
and s=25 cm
so,total surface of a cone is=pi*r*s
curved surface of a cone is=pi*r*(s+r)
ratio=3.14*7*(25+7)/3.14*7*25
=32:25

Like? Yes (1) | No   

yedukondalu .t   8 years AGO

total surface area=3.14*r*l + 3.14*sqr(r)
lateral surface area=3.14*r*l
r=radius
l=height

Like? Yes (1) | No   

Rakesh   8 years AGO

a/q to formula total surface area is =area of base +curved surface area ,where curved surface area is =pi*r*l where l is slant height. area of base is =pi*r*r

Like? Yes (1) | No   

sachin sawant   8 years AGO

Slant height =√(24^2+7^2)
=25
Curved surface area = pi*r*l
= 22*25
Total surface area = pi*r( l+r)
=22*32

Ratio= 22*32/22*25
= 32:25

Like? Yes (1) | No   

Jamil Ahmed   8 years AGO

TSA : CSA = sqrt(7^2+24^2) + 7 : sqrt(7^2+24^2)
=32:25

Like? Yes (1) | No   

dev   8 years AGO

TOtal surface area= 2 * pi * r * ( r + h ) =1364
curved surface area= 2 * pi * r * h = 1056
ratio of TSA : CSA = 32/25

Like? Yes (2) | No (1)  

sumit kumar   8 years AGO

if we rotate a right angle we will find a right angled cone.
desire ratio
?r(l+r)/?rl=l+r/l...........(1)
now l=sqart(7^2+24^2)
=25
from equation 1
25+7/25=32/25

Like? Yes (1) | No   

Amit Bera   8 years AGO

slant height, L=sqrt(7^2+24^2)=25
ratio=(L+R)/L=(25+7)/25=32:25

Like? Yes (1) | No   

saiprakash   8 years AGO

total surface area of cylinder=(3.14*base*hypotenuse)+(3.14*base*base)=175+49=224
curved surface area=3.14*base*hypotenuse=175
ratio=224/175=32:25

Like? Yes (1) | No   

sanjeet kumar   8 years AGO

T.S.A = pi* r * l +pi*r^2
C.S.A =pi*r*l
Since after rotating it will form cone

Like? Yes (1) | No   

Amit   8 years AGO

Curved surface area,C=pi*r*l
here l=25
total surface area,T=pi*r*l+pi*r*r
so T/C=32/25

Like? Yes (1) | No   

Yashi Das   8 years AGO

r=7 cm and h=24 cm
l=sqrt(r^2 +h^2)
l=25 cm
Curved surface area=pi*r*l =550 cm^2
total surface area =pi*r*l+pi*(r^2)
=704 cm^2


Therefore, total surface area /curved surface area =704:550 =32:25

Like? Yes (1) | No (1)  

UMANG RASTOGI   8 years AGO

total S.A= PAI* radi^2+PAI radi*slant
and Curvd S.A=PAI radi*slant

now TSA/CSA=radi*slant/slant

Like? Yes (1) | No (1)  

Vivek Ratan   8 years AGO

TSA(cone)/CSA(cone)=pi*r(l+r)/pi*r*l
=(l+r)/l
l=sqrt(24^2+7^2)
=25
r=7
hence using above formula we get the ratio= (25+7)/25
=32/25

Like? Yes | No (1)  

Siddharth Jain   8 years AGO

Cone will be formed after rotating triangle
radius of cone r = 7
height of cone h = 24
let slant height be l
l^2 = r^2+ h^2
so l = 25
Curved surface area of cone = pi*r*l
= 550
Total surface area of cone = pi*r(l+r)
= 704

Ratio will be = 704:550 = 32:25 ANSWER

Like? Yes | No (1)  

Harleen   8 years AGO

a cone will be generated with radius 7 and height 24 . then from total SA= pi *r*l+pi *r*r and curved sa=pi*r*l we can calculate ratio

Like? Yes | No (1)  

Maneesh Gupta   8 years AGO

TSA/CSA of cone={(Ï€r(r+l))/Ï€rl}
r=7,l=25
The ratio will be (32/25).

Like? Yes | No (1)  

18 Feb 2016 Profit and loss

Chocolate are purchased at the rate of 11 for Rs.10 and sold at 10 for Rs.11. The profit percent is

OPtion

1) 10%
2) 9%
3) 21%
4) 8%
5) 11%
6) 1%
7) 18%
8) 15%
9) 12%
10)5%

Solution

Gain 21%

Suppose he bought (11*10) = 110 chocolate
CP = 10/11 * 110 = Rs. 100
SP = 11/10 * 100 = Rs. 121
Gain 21%
Option 3)

Correct Option: 3 Best Solution (36)

Siddharth Jain   8 years AGO

C.P of 1 chocolate = 10/11
S.P of 1 chocolate = 11/10
Profit = S.P - C.P
= 21/110
Profit% = (Profit/C.P)*100
= 21 % ANSWER

Like? Yes (42) | No (10)  

kondapuram tirumalreddy   8 years AGO

lcm of no. of choclolates 11,10 =110
cp of chocolate = 10/11*110 =100
sp of chocolate =11/10 *110 =121
gain =121-100 =21
profit percentage = gain/cp *100 =21/100 *100 =21%

Like? Yes (23) | No (2)  

Pankaj   8 years AGO

CP 11 for Rs.10 =>110 for Rs.100
SP 10 for Rs. 11 =>110 for Rs. 121

Profit=(SP-CP)/CP x 100
=(121-100)/100 x 100
=21%

Like? Yes (19) | No (6)  

Priya jhunjhunwala   8 years AGO

cp of 1 chocolate=10/11
sp of 1 chocolate=11/10
p=sp-cp=21/110
p%=(p/cp) * 100 =21%

Like? Yes (10) | No   

Mukund Manohar   8 years AGO

CP of 11 chocolates=Rs 10
CP of 110 chocolates=Rs (10/11 * 110)=Rs 100
SP of 110 chocolates=Rs(11/10 * 110)=Rs 121
Profit%=21%

Like? Yes (10) | No (1)  

Jamil Ahmed   8 years AGO

CP of one chocolate = Rs.10/11
SP of one chocolate = Rs.11/10
Profit percentage = (11/10 - 10/11)*100*11/10 = 21%

Like? Yes (8) | No   

Divyani gupta   8 years AGO

take the LCM of 11 and 10 is 110
total no of chocolate purchased =110+110=220
c.p of 110 chocolate at rate of 11 for rs 10
110/11*10= rs 100
c.p of 110 chocolate at rate of 10 for rs 11
110/10*11=rs121
c.p of chocolates = rs 100+rs 121= rs.221
profit = s.p- c.p= 21
profit % = profit/c.p*100= 21

Like? Yes (8) | No (3)  

Maneesh Gupta   8 years AGO

c.p. of 1 chocolate=(10/11)
s.p. of 1 chocolate=(11/10)
Profit=s.p.-c.p.=21/110
profit %=(profit/c.p.)×100
=21%

Like? Yes (7) | No (3)  

Shagun Chaudhary   8 years AGO

c.p. of 1chocolate=10/11
c.p. of 10 chocolates=100/11

s.p. of 10 chocolates=11
profit=11-(100/11)
=21/11
profit%=profit/C.p.*100
=((21/11)/100/11)*100
=21%
option 3

Like? Yes (10) | No (6)  

GOURANGA SUNDAR MANDAL   8 years AGO

10 pcs chocolate's buying cost is 10/11*10=100/11 rs.
and selling cost is 11 rs
so the profit percent is 11/(100/11)*100-100=21%
so option 3 is correct answer

Like? Yes (4) | No   

karthiga   8 years AGO

C.P of 1 Chocolate = 10/11;
S.P of 1 Chocolate = 11/10;
P% = (11/10 - 10/11)100/10/11;
= 21%.

Like? Yes (4) | No   

rajani   8 years AGO

As the 11 chocolates c.p is 10 R's. And s.p of 10 chocolates is 11 R's. So s.p of 11 chocolates is 11×11÷10 I.e., 12.1 . profit percent is (12.1-10)/10×100 that is 21%

Like? Yes (4) | No   

Abhineet kumar   8 years AGO

cp of one is 10/11
so of one is 11/10
profit is 21/100
so profit % is 21%

Like? Yes (7) | No (3)  

dev   8 years AGO

total c.p=10
s.p of 10 chocolate=11
s.p of 1 chocolate=11/10=1.1
s.p of 11 chocolate= 1.1 *11 = 12.1

total profit= s.p - c.p = 12.1 - 10 = 2.1
profit % = (total profit / c.p) * 100 = (2.1 /10) * 100 = 21 %

Like? Yes (4) | No   

Prakash Panda   8 years AGO

cost price of 11 chocolate= Rs. 10
cost price of 110 chocolate= 10*10=Rs. 100
selling price of 10 chocolate=Rs 11
selling price of 110 chocolate=11*11=Rs.121

110 chocolates are purchased at 100 and sold at 121

so clearly profit % is 21% [option 3]

Like? Yes (3) | No   

Dheeraj kumar prajapati   8 years AGO

total cost = 10;
and sale cost =11*(11/10)
so = 121/10
profit % = (|total sale - total cost|*100)/total cost
= (121/10-10)*100/10
=21
so option 21% is correct .
if not than please provide full question description.

Like? Yes (5) | No (2)  

mcamanjeet   8 years AGO

c.p for 11 cho=10 rs
s.p fro 11 cho=12.1 rs
profit %=(12.1-10)/10*100
=2.1/10*100
=21%

Like? Yes (3) | No   

rohit yadav   8 years AGO

c.p for 1=10/11
s.p for 1=11/10
therefore,s.p/cp=1.21
profit %=21%

Like? Yes (3) | No   

SAURAV DAS   8 years AGO

C.P of 1 chocolate=10/11
S.P of 1 chocolate=11/10
Profit=11/10-10/11=21/110
%profit=(21/110)÷(10/11)×100=21%

Like? Yes (3) | No   

sanjeet kumar   8 years AGO

profit % = (sp of 1 choclate - cp of 1 choclate)/cp of 1 choclate *100

Like? Yes (2) | No   

aditya   8 years AGO

11---rs10
10---rs11
rs10/11 cp for 1 chocolate
rs11/10 sp for 1 chocolate
profit =((sp-cp)/cp)*100
21% answer

Like? Yes (1) | No   

anupam   8 years AGO

cp of 1 chocolate is 10/11
sp of 1 chocolate is 11/10
so profit is sp-cp
i.e 11/10-10/11
so per. profit is
profit/cp *100
ie
(11/10-10/11)/(10/11)*100=21

Like? Yes (1) | No   

kavya   8 years AGO

C.p of chocolate is 10/11
S.p of chocolate is 11/10
By using gain formula as gain=s.p-c.p=21/100
Gain%=(gain/c.p)×100=21%

Like? Yes (1) | No   

PODETI SRINIVAS GOUD   8 years AGO

consier as below way
chacolates rs
cost price 11 10 =100
selling price 10 11 =121
do cross muliplicaion above 11*11=121 as sp and 10*10=100 as cp
profit=sp-cp=121-100=21
profit%=21/100*100=21%

Like? Yes (1) | No   

Dr.Dipin Singh   8 years AGO

Suppose 110 chocolates are purchased for Rs 100 and sold for Rs 121.
So profit on CP of Rs 100 is Rs 21.
so profit is 21%.

Like? Yes (1) | No   

anju sukumaran   8 years AGO

gain %= (gainX100)/cost of price
gain = 11/10 - 10/11
cost of price = 10/11
profit % = 21%

Like? Yes (1) | No   

sachin sawant   8 years AGO

CP= Rs. 10/11
SP= Rs 11/10
P= SP- CP
= 11/10- 10/11
= 21/110
P% = 21/110*100/10/11
= 21%

Ans: option 3

Like? Yes (1) | No   

saurav kumar   8 years AGO

cost of 11 chocolate of rs 10
selling price of 11 is 12.1
profit%=((s.p-c.p)*100)/c.p
=(2.1*100)/10
=21%

Like? Yes (1) | No   

Bablu patel   8 years AGO

if in Rs m,n objects and in Rs n,mobjets
profit %=
(n^2-m^2)/m^2*100
=121-100=21
=21*100/100
=21

Like? Yes (1) | No (1)  

Akshat Sood   8 years AGO

11/10-10/11/10/11*100
21%
CP of 1 chocolate =11/10
SP of 1 chocolate =10/11

Like? Yes (1) | No (1)  

karre deepak   8 years AGO

11 chocolates cost 10 rupees so one chocolate cost 10/11 rupees,same way while selling 10 chocolates cost 11 rupees so one chocolate cost 11/10 rupees ,cp = 10/11,sp = 11/10 by formula (sp - cp)/cp *100 we will get gain percentage.

Like? Yes (1) | No (1)  

Devendra Marghade   8 years AGO

% profit=100*[(11/10) -(10/11)]/(10/11)
=100*(21/110)/(10/11)
=(100*21*11)/(110*10)
=21

Like? Yes | No (1)  

UMANG RASTOGI   8 years AGO

11 for 10rp
than 1 for 10/11
so 10 for 10*10/11=9.09
total profit=11-9.09=1.91
so total %profit=1.91*100/9.09=21.01%

Like? Yes (1) | No (2)  

Saleel Kulkarni   8 years AGO

The cost price is 10/11 and the selling price = 11/10
% Profit = ((SP-CP)/CP) * 100
=(((11/10)-(10/11))/(10/11))*100
=21
Option 3

Like? Yes (1) | No (2)  

Vaishnavi Rewatkar   8 years AGO

C.P of an article = 10/11, S.P =11/10, Profit= 11/10 -10/11= 121-100/110=21/110 So profit %=21/110*100/10/11= 2100/110*11/10= 21%

Like? Yes (1) | No (3)  

kolimi neelufar   8 years AGO

Given C.P of 11 chocolates =Rs.10
for 10 chocolates (10/11)*10=Rs.9.09
and also given S.P of 10 chocolates =Rs.11
Profit =11-9.09=1.91
Profit percentage=(1.91/9.09)*100=20.7~21%

Like? Yes | No (3)  

17 Feb 2016 Find the height and volume

A right pyramid stands on a rectangular base whose sides are 24 cm and 18 cm and each of the slant edge is 17 cm. Find the height and the volume of the pyramid.

OPtion

1) 12 cm and 1252 cm^3
2) 12 cm and 1164 cm^3
3) 10 cm and 1164 cm^3
4) 10 cm and 1254 cm^3
5) 6 cm and 1450 cm^3
6) 6 cm and 1152 cm^3
7) 6 cm and 1120 cm^3
8) 8 cm and 1152 cm^3
9) 8 cm and 1164 cm^3
10)8 cm and 1252 cm^3

Solution

By using figure
AB = 25 cm (base one side)
AD = 18 cm (base other side)
AS = 17 cm (slant edge)
Now
AO = Sqrt (AP^2 + OP^2) = Sqrt (9^2 + 12^2) = 15 cm (O is base centre and P is AD centre)
AS^2 = AO^2 + OS^2 (S is top point of pyramid)
then OS = Sqrt 64 = 8
height = 8
Volume = 1/3*18*24*8 = 1152 cm^2
Option 8)

Correct Option: 8 Best Solution (24)

Shagun Chaudhary   8 years AGO

base=1/2{18^2+24^2)^(1/2)
=15 cm
height=(17^2-15^2)
=8 cm
volume=(1/2)×18×24×8
=1152 cm^3

Like? Yes (2) | No   

Devendra Marghade   8 years AGO

Using Pythagoras theorem at base :
Given Base length=24, breadth=18, If Base diagonal=x
Then x^2=24^2 + 18^2, x^2=900, x=30
Considering 2nd right angled triangle with sides x/2, height(h) and slant edge=17
So 17^2 =15^2 + h^2, h^2=64 or h=8
Volume of the pyramid=Base length*Base breadth*height/3= (24*18*8)/3 =1152
Option 8) height=8 cm ,Volume=1152 cm^3

Like? Yes (1) | No   

MRITUNJAY   8 years AGO

height is 8 cm
volume of pyramid is (b*h)/3
=(24*18*8)/3=1152 cm^3
option 8

Like? Yes (1) | No   

Ravi   8 years AGO

height 8 by pythagoras
volume= 1/3(length*width*height)

Like? Yes (1) | No   

Ankita   8 years AGO

using hypotenous theorem we calculate height and volume has a simple formula 1/3area*height

Like? Yes (1) | No   

Maneesh Gupta   8 years AGO

b=1/2{18^2+24^2)^(1/2)
=15 cm
h=(17^2-15^2)
=8 cm
v=(1/2)×18×24×8
=1152 cm^3

Like? Yes (1) | No   

sanjeet kumar   8 years AGO

Since, height is given by root under (17^2 - 15^2) =8cm
And volume =l*w*h/3

Like? Yes (2) | No (1)  

Bablu patel   8 years AGO

first find diagonal of rectangle 18^2+24^2=900^1/2=30
hight will be measure from half of diagonal=15
hight=17^2-15^2=68^1/2=8
volume =l*h*w/3
=24*18*8/3
=1152

Like? Yes (1) | No   

GOURANGA SUNDAR MANDAL   8 years AGO

diagonal of the base rectangle is sqr root of(24^2 +18^2)=30
so the height of the pyramid is sqr root of (17^2-15^2)=8
so height of the pyramid is 8 cm..
the volume of the pyramid is (24*18*8)/3=1152 cm^3
so option 8 is correct answer

Like? Yes (1) | No   

UMANG RASTOGI   8 years AGO

sqrt.18^2+24^2=30
30/2=15
sqrt.17^2-15^2=8
hight=8;

volume=1/3*8*18*24=1152

Like? Yes (1) | No   

Gaurab Kumar Jha   8 years AGO

by applying pythagorus theorum
height of pyramid = 8
voume = l*b*h/3

Like? Yes (1) | No   

Juned Akhtar   8 years AGO

from pythagorois theorem & volume of pyramid formula = LBH/3

Like? Yes (1) | No   

sachin sawant   8 years AGO

diagonal of react=18^2+24^2=30cm
Height of pyramid=17^2-15^2=8cm
Volume=1/3area of base*h
=1/3*24*18*8
=1152cm^3
And option8

Like? Yes (1) | No   

ayushi   8 years AGO

volume of pyramid =1/3*area of base*height
height =8
area=24*18
volume =1/3*24*18*8=1152

Like? Yes (1) | No   

Priya jhunjhunwala   8 years AGO

we have to draw the fig carefully then by applying pythagorus teorem we will get the value of height i.e, h=8cm and volume will be (1/3) *area * height

Like? Yes (1) | No   

Saleel Kulkarni   8 years AGO

For the height of the pyramid, consider the a right angled triangle first. The hypotenuse is the slant edge = 17, the height is unknown whereas the base is half the diagonal of the rectangle. The length of the diagonal = sqrt(24^2 + 18^2)/2 = 15
So the by Pythagoras theorem, height of the pyramid = 8 cm.
Now volume of the pyramid = (length*breadth*height)/3=1152 cm^3
Option 8

Like? Yes (1) | No   

N.Vennela Rani   8 years AGO

height=8cm
volume=1152cm^3
by using formula v=(1/3)Ah

Like? Yes (1) | No   

Divyani gupta   8 years AGO

height of pyramid= sh2=h2+w2
h2=sh2-w2
volume=lwh/3

Like? Yes (1) | No   

Prakash Panda   8 years AGO

lwh/3 formula

using dis we can get h=8 n volume =1152 cm^3

Like? Yes (1) | No (1)  

Siddharth Jain   8 years AGO

l = 24
w =18
slant height s = 17
rectangular base diagonal d = 30
so,
h^2 = s^2-(d/2)^2 = 64
h = 8 cm ANSWER

Volume of Pyramid = (lwh) / 3
= 1152 cm^3 ANSWER

Like? Yes (1) | No (1)  

Mukund Manohar   8 years AGO

Diagonal (d) of rectangular base is
sq.root(d)=sq.root(24) + sq.root(18)
=576+324 =900
d=30 cm
Now,height (h) of pyramid is
sq.root(17)=sq.root(h) + sq.root(15),because diagonals of a rectangle bisect each other,so 30/2=15
289=sq.root(h) + 225
sq.root(h)=64
h=8 cm
Volume of pyramid=1/3 *24*18*8
=1152 cm^3

Like? Yes | No (1)  

sugayathri   8 years AGO

(17^2) - (900/2)^2 =8cm

volume of pyramid = 1/3ah

= 1/3*24*18*8

= 1152cm^3

Like? Yes | No (1)  

Rajeev teja   8 years AGO

Volume=a×b×h÷3
h=height
a,b= length and breadth of rectangle

Like? Yes | No (1)  

Jamil Ahmed   8 years AGO

Diagonal of the base = sqrt of (24^2 + 18^2) cm = 30 cm

So, height of the pyramid = sqrt of {17^2 + (30/2)^2} cm = 8 cm.

Therefore, volume of the pyramid = 24*18*8/3 cm^3 = 1152 cm^3.

Like? Yes | No (1)  

16 Feb 2016 Calculate the ratio

The radii of two cylinders are in the ratio 2:3 and their height are in the ratio 5:3. Calculate the ratio of their volume and the ratio of their curved surfaces.

OPtion

1) 10:9 and 3:7
2) 8:9 and 4:1
3) 20:27 and 10:9
4) 19:23 and 5:4
5) 16:21 and 2:3
6) 3:4 and 11:9
7) 15:17 and 8:7
8) 11:13 and 9:8
9) 1:3 and 12:7
10)20:23 and 5:3

Solution

Let radii be 2r and 3r respectively
and height be 5h and 3h respectively
Volume ratio = Pi*(2r)^2 5h / Pi*(3r)^2 3h = 20:27
Curved surface area ratio = 2 Pi*(2r) 5h / 2 Pi*(3r) 3h = 10:9

Option 3)

Correct Option: 3 Best Solution (53)

Richa Saini   8 years AGO

Ratio of radii r1:r2 = 2:3
ratio of heights h1:h2 = 5:3
Ratio of volume v1:v2=pi *r1^2*h1 : pi*r2^2*h2

v1/v2 = (pi*r1^2*h1 )/ (pi*r2^2*h2)
v1/v2 = (r1/r2)^2 *(h1/h2)
= (2/3)^2 * (5/3)
= 20/27

Ratio of curved surface=2*pi*r1*h1 : 2*pi*r2*h2
=(r1*h1)/(r2*h2)
=( r1/r2)* (h1/h2)
=(2/3)*(5/3)
= 10/9
Therefore option(3) is the answer.

Like? Yes (86) | No (43)  

Mukund Manohar   8 years AGO

Ratio of Volume={(22/7)*2*2*5}/{(22/7)*3*3*3}=20/27
Ratio of their Curved Surfaces
={2*(22/7)*2*5}/{2*(22/7)*3*3} = 10/9
Answers are 20:27 and 10:9

Like? Yes (43) | No (18)  

Siddharth Jain   8 years AGO

Volume of cylinder = 3.14 * r^2 * h
Ratio will be = r1^2*h1 : r2^2 * h2
= 2^2 * 5 : 3^2 * 3
= 20:27 ANS.

Curved Surface area of cylinder = 2 * 3.14 * r * h
So ratio of curved surface area will be = r1 * h1 : r2 * h2
= 2 * 5 : 3 *3
= 10 : 9 ANS.

Like? Yes (38) | No (16)  

sugayathri   8 years AGO

volume of cylinder = 22/7r^2h

22/7*2*2*5)/22/7*3*3*3 =20/27
curved surface=2*22/7rh=10/9

Like? Yes (26) | No (10)  

Shagun Chaudhary   8 years AGO

(Ï€*2*2*5):(Ï€*3*3*3)
20-27



2*Ï€*2*(5+2):2*Ï€*3*(3+3)
4*Ï€*7:6*Ï€*6
28Ï€:36Ï€
7:9

20:27 and 7:9
option 3

Like? Yes (22) | No (10)  

Jaikumar Bhatia   8 years AGO

Ratio of radii=r1:r2=2:3,
Ratio of height=h1:h2=5:3,
Then,
Ratio of Volumes
V1:V2=(r1^2*h1)/r2^2*h2)
=(2^2*5)/(3^2*3)
=20/27
=20:27.....................................(i)
Ratio of curved surface areas=
A1:A2
=(r1h1)/r2h2)
=2*5/3*3
=10/9
10:9............................................(ii)
Ans is 20:27 and 10:9
Option is (3)

Like? Yes (17) | No (8)  

ABHINAV PUSHPAM   8 years AGO

Ratio of volumes=> 4*5/9*3= 20:27
Ratio of curved surface area => 2*5/3*3= 10:9
Option 3)

Like? Yes (12) | No (7)  

abhishek kumar sahu   8 years AGO

suppose the radii of both cylindr are 2 and 3, and heights are 5 and 3 respectively. now put the values in the formula for volume(pir^2h) and for area(2pirh) thats it.

Like? Yes (12) | No (7)  

Sayantan Samaddar   8 years AGO

Let the radii of both the cylinders be 2r and 3r respectively and their heights be 3r and 3h.

Now, Ratio of their volumes = (pi*sqr(2r)*5h)/(pi*sqr(3r)*3h)=20/27 i.e., 20:27
Ratio of their ured surfa e = 2pi*2r*5h/2pi*3r*3h=10/9=10:9

Like? Yes (10) | No (7)  

Meghana Ramya   8 years AGO

Volume of a cylinder=Ï€r^2h
C.s.a of a cylinder=2Ï€rh
Sub r and h values
Ans is volume =20:27
C.s.a=10:9

Like? Yes (11) | No (9)  

Vasuthaarini   8 years AGO

let the radius of the cylinders r:R= 2x:3x and height h:H=5x:3x
volume of cylinder=pi*r*r*h
so by substituting the values in the formula we get ans volume=20:27
csa= 2*pi*r*h and by substituting the value we get csa=10:9
so option 3 is correct

Like? Yes (7) | No (5)  

jothi   8 years AGO

volume= 2*22/7*r^2*h & surface area=2*22/7*r*h
ratio of volume = (2^2*5)/(3^2*3)=20/27
ratio of curved surf=(2*5)/(3*3)=10/9

Like? Yes (5) | No (4)  

Murthy   8 years AGO

given radius of two cylinders r1 = 2, r2 = 3,
given heights of two cylinders h1 = 5, h2 = 3
so volume of cylinder is pi*r^2*h so by calculating
their volume ratio is 20:27
area is 2*pi*r*h so it 10:9...so answer is 3

Like? Yes (5) | No (4)  

sanjeet kumar   8 years AGO

Since, Volume of cylinder varies with r^2*h.
Therefore ratio of volume would be 20:27.
And since only one option is equals this so no need of calculating the surface area

Like? Yes (8) | No (7)  

Vaishnavi P Agarkathe   8 years AGO

curved surface area of cylinder=(2*3.14*2x*5Y)/(2*3.14*3x*3y)=10:9
volume of cylinder=3.14*r*r*h=20:27
hence ans =20:27 and 10:9

Like? Yes (6) | No (5)  

Arvind kumar   8 years AGO

ratio of their volume=(4/3*pi*r1^2*h1) / (4/3*pi*r2^2*h2)...a
ratio of their curved surface=(pi*r1*h1) / (pi*r2*h2).........b
by putting r1=2r and r2=3r
also by putting h1=5h and h2=3h in both eqn a and b
we get ratio of their volume=20:27
and ratio of their curved surface=10:9

Like? Yes (4) | No (3)  

REVATHI   8 years AGO

formula for cylinder volume is pi*r2*h and curved surface=2*pi*r*h.

Like? Yes (5) | No (4)  

S.MANJULA   8 years AGO

radii=2:3
ht=5:3
volume=pi*r1*r1*h1:pi*r2*r2*h2
=pi*2*2*5:pi*3*3*3
=20:27
surface area=pi*r1*h1:pi*r2*h2
=2*5:3*3
=10:9

Like? Yes (5) | No (4)  

Maneesh Gupta   8 years AGO

(Ï€*2*2*5):(Ï€*3*3*3)
20:27

2*Ï€*2*(2+5):2*Ï€*3*(3+3)
7:9

option 3

Like? Yes (12) | No (12)  

Gaurab Kumar Jha   8 years AGO

let the ratios be x
so the volume ratio will be 2^2 * 5 : 3^2 * 3 = 20:27
and the ratio of curve surfaces are 2*5 : 3*3 = 10:9
i,e option 3

Like? Yes (5) | No (5)  

Richa Jain   8 years AGO

Ratio of volume=
[Pi*(r1)^2*h1] /[Pi*(r2)^2*h2] = 20/27
Ratio of curved surface =
2pi*r1*h1/2pi*r2*h2 = 10/9

Like? Yes (5) | No (5)  

Harshit Sharma   8 years AGO

volume of cylinder is pi r^2 h. so their ratio result in option 3

Like? Yes (4) | No (4)  

Saleel Kulkarni   8 years AGO

The volume of cylinder is 2*pi*r^2*h and curved surface area is 2*r*h. Then taking its ratio we get 20:27 and 10:9
Option 3

Like? Yes (4) | No (4)  

Shivling Nagnath Bhange   8 years AGO

valume of cylendre formula=pi*r*r*h

there fore ratio of theirvalume= pi*r*r*h/pi*R*R*H

=pi*2*2*5/pi*3*3

= 4*5/3*3*3

=20/27

curve surface of cyl=2*pi*r*h

= 2*pi*2*5/2*pi*3*3

=10/9

Like? Yes (5) | No (5)  

Jamil Ahmed   8 years AGO

Ratio between the volumes of the two cylinders = 2^2*5 : 3^2*3 = 20 : 27

Ratio between the curved surfaces of the two cylinders = 2*2*5 : 2*3*3 = 20 : 18 = 10 : 9

Like? Yes (4) | No (4)  

Akshat Sood   8 years AGO

let radius be x
and heights be y
?4x^25y:?9x^3y
20:27(ratio of volumes)

similarly
ratio of surface areas 10:9

Like? Yes (4) | No (4)  

sachin sawant   8 years AGO

V=pi*r^2h
Thus pi*(2r)^2*5h/pi*(3r)^2*3h=20/27
Curved surface area=2*pi*r*h
Thus,2*pi*2r*5h/2*pi*3r*3h=10/9
And option 3

Like? Yes (4) | No (4)  

Sathya   8 years AGO

vol of cylinder=pi*r2*h
and also curved surface area=2*pi*r*h
so v1/v2=4*5/9*3
= 20/27
so v1:v2=20:27
similarly c1/c2=2*5/3*3
=10/9
so c1:c2=10:9
so op 3 is correct

Like? Yes (5) | No (5)  

Ajithkumar   8 years AGO

Radii ratio r:R=2:3
Let r=2x R=3x
Heights ratio h:H=5:3
Let h=5x H=3x
CSA of 1 st Cylinder=2Ï€rh
2Ï€*2x*5x=20Ï€x^2
2 nd = 2Ï€RH
=18Ï€x^2
Ratio = 20/18=10:9
Volumes 1st = πr^2h
=Ï€20x^2
Volume 2 nd= πR^2H
=Ï€27x^2
Ratio = 20/27

Like? Yes (4) | No (4)  

Devendra Marghade   8 years AGO

If radii are 2x ,3x and heights being 5y ,3y respectively, then
Ratio of Volumes=[Pi*(2x)^2*5y]/[Pi*(3x)^2*3y]=20/27
Ratio of curved surface areas=(2*Pi*2x*5y)/(2*Pi*3x*3y)=10/9
Option 3)

Like? Yes (4) | No (5)  

ayushi   8 years AGO

cylinder's volume=pi*r^2h
v1=pi*4*5
v2=pi*9*3
v1/v2=20/27

curvd surface=2*pi*r*h
s1=2*pi*2*5
s2=2*pi*3*3
s1/s2=10/9

Like? Yes (4) | No (5)  

Rajeev teja   8 years AGO

Volume=4 ×pi× r×r×h
Curved surface area= 2×pi×r×h
Ratio of v=(r1×r1×h1)÷(r2×r2×h2)
Ratio of csa= (r1×h1)÷(r2×h2)

Like? Yes (4) | No (5)  

sivaswamy cheduluri   8 years AGO

Given data r1/r2=2/3 & h1/h2=5/3
volume of cylinder = pi r^2 h
curved surface area=2pi r h
ratio of volume=20/27
ratio of curved surface=10/9

Like? Yes (5) | No (6)  

Dinesh kumar sah   8 years AGO

simply applied formula for volume ie v=?r^2h and curved surface area in is a=2?rh and got the above answer...

Like? Yes (3) | No (4)  

dev   8 years AGO

as Volume of Cylinder = pi*r*r*h
so V1 : V2 = (3.14*2*2*5) : (3.14*3*3*3) == 20 : 27

Like? Yes (3) | No (4)  

kavya   8 years AGO

Volume of cylinder is πr1^2h1/πr2^2h2.curved surface area is2πr1h1/2πr2h2.

Like? Yes (3) | No (4)  

GS MANISHA   8 years AGO

volume of cylinder is ?r*rh
and the curved surface 2?rh.so the option will be 3.

Like? Yes (4) | No (5)  

prateekshukla   8 years AGO

1. R^2×h=R^2×h
(2X)^2×5X= (3X)^2x3X
20X^3= 27X^3
20:27

2.
RxH=R×H
2×X5×=3×X3×
10x^2=9x^2
10:9

Like? Yes (3) | No (4)  

AYAN PAUL   8 years AGO

The reason is by using the formula pi*r*r*h and pi*r*r we can get the two answers.

Like? Yes (3) | No (4)  

Aakriti sharma   8 years AGO

first i took radii in form of 2r and 3 r and then for heights in the form of h ,threafter with the formula of volume and c.s.a of cylinder

Like? Yes (3) | No (4)  

harsh dhir   8 years AGO

Volume of Cylinder=pi*r^2*h
ratio=r1^2*h1/r2^2*h2=(4*5)/(9*3)=20/27
Curved surface area of cylinder=2*pi*r*h
ratio=2*5/3*3=10/9

Like? Yes (3) | No (5)  

GOURANGA SUNDAR MANDAL   8 years AGO

the volume of the cylinder is pi*raddi^2*height
let the radii is 2x and 3x...and height is 5y and 3y..
so the ratio of volume is pi*4x^2*5y:Pi*9x^2*3y..
=20:27
and the curved surface of the cylinder is 2*pi*radii*height
so the ratio is 2*pi*2x*5y:2*pi*3y*3x
=10:9
so option 5 is correct answer

Like? Yes (2) | No (4)  

Vivek Ratan   8 years AGO

on calculating the ratio is 20:27 and 10:9 respectively for Volume and CSA.

Like? Yes (4) | No (6)  

MADHUBABU   8 years AGO

volume of cylinder = (3.14*r^(2)*h)
ratio of volume of two cylinders =(r1/r2)^2 *(h1/h2)=(4/9 * 5/3) =
20/27
curved surface area of cylinder = 2*3.14*r*l
ratio of curved surface areas of two cylinders =(r1h1/r2h2) = (2*5/3*3) = 10/9

Like? Yes (2) | No (4)  

Abhineet kumar   8 years AGO

volume of cylinder is ?r^2h
area is 2?rh
so by puting value we will get option 3 as answer

Like? Yes (3) | No (5)  

keerthy   8 years AGO

square of radius and height are directly proportional to volume

Like? Yes (3) | No (5)  

Sowjanya a v   8 years AGO

Volume of cylinder is πr^2 h.ratio of volume of the 2 cylinders is r1^2*h1÷r2^2*h2=20/27
Curved surface area of cylinder is 2*π*r*h. Ratio of the curved surface of the 2 cylinders is r1*h1÷r2*h2=10/9

Like? Yes (3) | No (5)  

Dhaneshri Maniar   8 years AGO

r1:r2=2:3 & h1:h2=5:3
let r1=2r, r2=3r, h1=5h, h2=3h
v1/v2=(pi)(r1)(r1)(h1)/(pi)(r2)(r2)(h2)=(2r)(2r)(5h)/(3r)(3r)(3h)=20/27
CSA1/CSA2=2(pi)(r1)(h1)/2(pi)(r2)(h2)=(2r)(5h)/(3r)(3h)=10/9

Like? Yes (2) | No (4)  

JENSI KARUNYA.S   8 years AGO

vol of cylinder=22/7*r*r*h
4*5:9*3
20:27

Like? Yes (2) | No (5)  

Dharika   8 years AGO

radius r in ratio 2x and 3x so r1=2x and r2=3x and heights are in ratio 5x nd 3x..h1=5x h2=3x.

Like? Yes (2) | No (5)  

Priya jhunjhunwala   8 years AGO

given, r1/r2=2/3 so r1=(2/3)r2 similarly h1=(5/3)h2
we know,vol of cylinder is given by pi*r^2*h so ratio would be
(pi*r1^2*h1)/(pi*r2^2*h2) by putting the values we can get the result
we know curved surface area is given by 2*pi*r*h
likewise we can get the result

Like? Yes (2) | No (5)  

Siva   8 years AGO

volume of cylinder v is directly proportionanl to product of square of the radius and height of the cylinder, so V1:V2=((2/3)^2)*(5/3)= 20/27, rest of the problem need not to solve 3rd option only gives this ratio. curved surface is directly proportional to product of radius and height of cylinder so A1:A2 =(2/3)*(5/3)= 10/9.

Like? Yes (2) | No (7)  

Divyani gupta   8 years AGO

v1/v2
ratio of volume of both cylinder will be calculated
v=pie (r)sq h
curved surface= 2pie rl

Like? Yes (2) | No (10)  

15 Feb 2016 Sequence

What is the next number of the following sequence
89, 234, 263, 312, ....

OPtion

1) 325
2) 328
3) 356
4) 346
5) 368
6) 326
7) 364
8) 332
9) 338
10)None of these

Solution

89
89+8^2+9^2 = 89+64+81 = 234
234+2^2+3^2+4^2 = 234+4+9+16 = 263
263+2^2+6^2+3^2 = 263+4+36+9 = 312
Similarly
312+3^2+1^2+2^2 = 312+9+1+4 = 326

Option 6)

Correct Option: 6 Best Solution (20)

swasthika   8 years AGO

square each digit in the number and add the number
8*8+9*9 +89 =234
2*2 + 3*3 +4*4 +234 =263
similarly
3*3 + 1*1 + 2*2 =326

Like? Yes (3) | No (1)  

Meenakshi   8 years AGO

89,234,263,312,..
8^2+9^2=145 + 89 = 234
2^2+3^2+4^2=4+9+16=29+234=263
2^2+6^2+3^2=4+36+9=49+263=312
similarly, 3^2+1^2+2^2=9+1+4=14+312=326
option 6)

Like? Yes (3) | No (1)  

Shagun Chaudhary   8 years AGO

89+8^2+9^2=234
234+2^2+3^2+4^2=263
263+2^2+6^2+3^2=312
312+3^2+1^2+2^2=326

Like? Yes (2) | No   

Maneesh Gupta   8 years AGO

89+8^2+9^2=89+145=234
234+2^2+3^2+4^2=234+29=263
263+2^2+6^2+3^2=263+49=312
312+3^2+1^2+2^2=312+14=326
option(6)

Like? Yes (2) | No   

PRABHAT KUMAR   8 years AGO

89
89+8^2+9^2=234
234+2^2+3^2+4^2=263
263+2^2+6^2+3^2=312
312+3^2+1^2+2^2=326
Option 6

Like? Yes (1) | No   

RISHABH   8 years AGO

89= 8^2 +9^2=145
so, 89+145=234
234=2^2+3^2+4^2=29
so,234+29=263
and so on...........
312= 3^2+1^2+2^2=14
so next no. is 312+14=326

Like? Yes (1) | No   

Saipriya    8 years AGO

8^2+9^2+89=234
2^2+3^2+4^2+234=263
2^2+6^2+3^2+263=312
then,3^2+1^2+2^2+312=326

Like? Yes (1) | No   

Siddharth Jain   8 years AGO

89+ 8^2+ 9^2 = 89+64+81 = 234
234 + 2^2+ 3^2+ 4^2 = 263
263 + 2^2+ 6^2+ 3^2 = 312
312 + 3^2+ 1^2+ 2^2 = 326 Ans.

Like? Yes (1) | No   

sivaswamy cheduluri   8 years AGO

89+8^2+9^2=234
234+2^2+3^2+4^2=263
263+2^2+6^2+3^2=312
312+3^2+1^2+2^2=326

Like? Yes (1) | No   

Subha Poddar   8 years AGO

p.no+square of separate digit=next no
89+8^2+9^2=234...... so on
312+3^2+1^2+2^2=326

Like? Yes (1) | No   

MRITUNJAY   8 years AGO

89 234 263 312
145. 29. 49
81+64=145
4+9+16=29
4+36+9=49
9+1+4=14
So final number is 312+14=326
Option 6

Like? Yes (1) | No   

ayushi   8 years AGO

89=8^2+9^2=145
89+145=234
234=4+9+16=29
234+29=263
so on
.
.
.
.9+1+4=14
312+14=326

Like? Yes (1) | No   

ABHINAV PUSHPAM   8 years AGO

89 234 263 312
145. 29. 49
81+64=145
4+9+16=29
4+36+9=49
9+1+4=14
So final number is 312+14=326
Option 6

Like? Yes (1) | No   

RAHUL KUMAR   8 years AGO

89, 234, 263, 312
the diff between the these term are 145, 29, 49
81+64 = 145
4+9+16 = 29
4+36+9 = 49
9+1+4 = 14
so final number is 312+14 = 326
option (6) is correct.

Like? Yes (1) | No   

GOURANGA SUNDAR MANDAL   8 years AGO

the logic is,..every term =previoue term+sum of previous term 's digit's square.
so the last term is..312+{3^2+1^1+2^2}=326
so option 6 is correct answer

Like? Yes (1) | No (1)  

Akshat Sood   8 years AGO

8^2+9^2+89=243
2^2+4^2+3^2+243=263
similarly 326 is the ans

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Mukund Manohar   8 years AGO

89+8^2+9^2=234
234+2^2+3^2+4^2=263
263+2^2+6^2+3^2=312
312+3^2+1^2+2^2=326

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Dr.Dipin Singh   8 years AGO

next number is 312+3^2+1^2+2^2= 312+14=326

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SHUBHAM   8 years AGO

8^2+9^2=145+89=234
2^2+3^2+4^2=29+234=263
2^2+6^2+3^2=49+263=312
3^2+1^2+2^2=14+312=326
hence (6) is the answer

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Saleel Kulkarni   8 years AGO

89+(8^2)+(9^2)=234
234+(2^2)+(3^2)+(4^4)=263
263+(2^2)+(6^2)+(3^2)=312
312+(3^2)+(1^2)+(2^2)=326
Option 6

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12 Feb 2016 Solve the following

Solve the following
20 % of {100 + 200*400 / 50 of 2} / 40 % of {6*400 of 2 / 40 - 10}

OPtion

1) 20/3
2) 40/27
3) 36/7
4) 22/9
5) 13/5
6) 19/4
7) 16/9
8) 45/11
9) 29/2
10) None of these

Solution

Solve it by BODMAS rule
First solve “of ” then “divide” and then “multiply”

Correct Option: 8 Best Solution (0)

11 Feb 2016 Three Objects

Ramesh purchases three objects of consecutive prices. The number of purchased objects are 1, 2 & 3. He pays Rs 115 to shopkeeper. If all prices are taken in integers, then out of 10 choices, the price of that object, whose 3 pieces are purchased, is

OPtion

1. 18
2. 21
3. 20
4. 22
5. 24
6. 17
7. 16
8. 26
9. 12
10.28

Solution

6 cases arise
1x + 2(x + 1) + 3(x + 2) = 115 => x ≠ integers
1x + 3(x + 1) + 2(x + 2) = 115 => x = 18
2x + 1(x + 1) + 3(x + 2) = 115 => x = 18
2x + 3(x + 1) + 1(x + 2) = 115 => x ≠integer
3x + 1(x + 1) + 2(x + 2) = 115 => x ≠ integer
3x + 2(x + 1) + 1(x + 2) = 115 => x ≠ integer
Since x = 18, hence solutions are 19 & 20 according to 2nd and 3rd conditions given above,
Out of 10 choices, 20 is correct
Option 3)

Correct Option: 3 Best Solution (9)

karnatakam.Jaswanth kumar   8 years AGO

Let the prices be x,x+1,x+2
Then 1(x)+2(x+1)+3(x+2)=115
X=18(because prices are integer values )
Then price of the object,3pieces is 18+2=20

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Siddharth Jain   8 years AGO

Lets say the prices are
whose 1 quantity is purchased = a+1
whose 2 quantity is purchased = 2a
whose 3 quantity is purchased = 3(a+2) = 3a+6

Paid to Shopkeeper = 115
a+1+2a+3a+6 = 115
6a+7 = 115
a = 18

So, price of object whose 3 quantity is purchased = a + 2
= 18+2
= 20 Ans.

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Mukund Manohar   8 years AGO

If
1x+2(x+1)+3(x+2)=115,then x=107/6 which is not integer
if
1x+3(x+1)+2(x+2)=115,thenx=108/6=18
if
2x+1(x+1)+3(x+2)=115,then x=108/6=18
if
2x+3(x+1)+1(x+2)=115,then x=110/6 which is not integer
if
3x+1(x+1)+2(x+2)=115,then x=110/6 which is not integer
and if
3x+2(x+1)+1(x+2)=115,then x=111/6 which is not integer
x=18,so we get the solution as 19 & 20
Hence,from the given 10 choices,20 is the answer

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ABHINAV PUSHPAM   8 years AGO

2x+(x+1)+3(x+2)=115

X=18

3items price is 20

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MRITUNJAY   8 years AGO

2x+(x+1)+3(x+2)=115
x=18

so price of item having three piece is 20
option 3

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RAHUL KUMAR   8 years AGO

2x+(x+1)+3(x+2)=115

X=18

3items price is 20

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Prakash Panda   8 years AGO

(20*3)+(19*1)+(18*2)=115

So ans is 20 (option 3)

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Saleel Kulkarni   8 years AGO

Consider the 1st object be x then other will be x+1 and x+2.
So, x+2(x+1)+3(x+2)=115
==>x=17.83
So if we take x =18 then the other other nos will be 19 and 20 but putting in above equation gives sum as 116, so rearrange the combination,
19+2(18)+3(20)=115
Option 3

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Devendra Marghade   8 years AGO

If prices are x, x+1, x+2, then number of objects purchased can have combinations with 1,2 & 3 objects, checking for (x+1)*1 + x*2 + (x+2)*3=115
x+1+2x+3x+6=115 or x=18
So price of the object whose three pieces are purchased is x+2=18+2=20
Option 3)

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