M4maths Previous Puzzles

10 Feb 2016 Number X is

The cost of apple and grapes are between Rs 20 and 30 per kg. If total cost of 5 Kg apple and 7 Kg grapes is a number X having unit's and hundred's place equal and sum of cost of 1 Kg apple and 1 Kg
grapes is Rs 50. Then the number X is

OPtion

1) 313
2) 282
3) 272
4) 333
5) 252
6) 303
7) 262
8) 323
9) 292
10)343

Solution

There are 9 possibilities
No. --- Cost of apple/Kg. ----- Cost of grapes/Kg.
1 ----- 21 -------------------- 29
2 ----- 22 -------------------- 28
3 ----- 23 -------------------- 27
4 ----- 24 -------------------- 26
5 ----- 25 -------------------- 25
6 ----- 26 -------------------- 24
7 ----- 27 -------------------- 23
8 ----- 28 -------------------- 22
9 ----- 29 -------------------- 21
Check the following cases.

Correct Option: 9 Best Solution (18)

Prakash Panda   8 years AGO

must between 290 n 310
as cost of 1kg of apple n 1 kg of grapes is 50
if we take 5 kg each den the total is 250
rest 2 kg of grapes at max 60 n at min 40..

considering the condition units place n hundreds place is same ...option 9 is the best suitable ans i.e 292... (option 9)

Like? Yes (2) | No   

MRITUNJAY   8 years AGO

cost of grapes be 21
and apple is 29
so total cost is 21*7+29*5=292
option9

Like? Yes (1) | No   

Neetin Kumar   8 years AGO

cost of 1kg apple + 1 kg grapes=50
Let cost of apple=29/kg and grapes=21/kg

Cost of 5kg apple + 7 kg grapes=x
145+147=292
x=292(unit and hundred place are same)

Like? Yes (1) | No   

Saleel Kulkarni   8 years AGO

Consider the combinations of 21+29 or 22+28 or 23+27 or 24+26 or 25+25 or29+21 or 28+22 or 27+23 or 26+24 for apples and grapes respectively as 1kg of apple+grapes=rs.50
For Rs.29/kg apple and Rs.21/kg of grapes, if 5kg apples and 7kg grapes are purchased then the total price will be 292
Option 9

Like? Yes (1) | No   

satish ojha   8 years AGO

ans only b/w .. follow in 350-2x where x =21 to 29
at 29 value give 292 .

Like? Yes (1) | No   

Akshat Sood   8 years AGO

taking values as 29 for apples and 21 for grapes(in rupees)
we get x=292

Like? Yes (1) | No   

vineesha p   8 years AGO

1kg Apple + 1 kg Grape =50
5kg A + 5 kg G = 5*50 =250
The cost 1kg grape lies between 20-30
We need 2 more kg grapes =so the cost lies between 42-58
On adding 42 to 250 the first and last digits same.
Hence the answer 250+42=292

Like? Yes (1) | No   

sanjeet kumar   8 years AGO

The possible combination of Apple's and Grapes price are (20,30),(21,29)...(30,20).
Since cost of 1kg apple and 1kg grapes is 50 . So cost of 5kg apple and 5kg grapes is 250 . Now for the cost of 5kg apple and 7 kg grapes we have to add only cost of 2 kg of grapes into it. Therefor 250+40

Like? Yes (1) | No   

Sejal Harsoda   8 years AGO

we make 2 equation from given information and check for values in which both values between 20 and 30

Like? Yes (1) | No   

anand raj   8 years AGO

5x+7y=X
x+y=50
5x+5y=250
hence
20

Like? Yes (1) | No   

rammohan reddy   8 years AGO

5Kg apples and 5kg grapes costs 250 and the remaining 2kg grapes cost satisfies only option9(292).

Like? Yes (1) | No   

tejaswini dixit   8 years AGO

sum of cost of 1kg apple and 1kg grapes is 50.(given)
so, by this.. sum of cost of 5kg apple and 5 kg grapes is = 50*5=250 rs.
we have to calculate sum of cost of 5kg apple and 7 kg grapes which is = number X
5kg apple cost + 5 kg grapes cost =250 rs.
we have to calculate 2 kg grapes cost too.
cost of 1kg grapes is between 20 and 30.(given)
lets check that cost of 1 kg grapes is 21rs.
then cost of 2kg grapes=21*2=42rs.
sum of cost of 5kg apple+7 kg grapes= 250+42=292rs.
by this , number X=292 , in which unit digit equal too hundreds digit. it satisfies the condition .
hence it is correct.

Like? Yes (1) | No   

TARUN CHAUHAN   8 years AGO

let cost of apple and grapes be x & y rs/kg
given x+y=50
5(x+y)=250

now we need to add cost of 2 kg of grapes too in 250
minimum price can be 40 (20 each)

and we need to keep unit and hundred digit same
so
cost of 2 kg of grapes will be 42 hence
total cost of 5 kg apple and 7 kg grapes will be 250+42=292 rs
and cost of apple and grapes will be 29 &21 rs/kg.

Like? Yes (1) | No   

Mukund Manohar   8 years AGO

Using trial and error method,
1 kg apple= 29
1 kg grapes = 21
29 + 21 = 50
and
29*5 + 21*7 = 145 + 147 = 292

Like? Yes (1) | No   

Vipin Lakhera   8 years AGO

Cost of 1kg apple is 29rs And cost of 1 kg apple is 21 rs so X=292

Like? Yes (1) | No   

Yallapu Uday tarun kumar   8 years AGO

apple 1kg cost is 29rs
grapes 1kg cost is 21rs

Like? Yes (1) | No (1)  

Devendra Marghade   8 years AGO

Cost/kg of Apples=29 & Grapes=21
So, 5*29 +7*21 =292= X, which satisfies the condition of same digits at unit place hundred place.
Option 9)

Like? Yes | No (1)  

Bablu patel   8 years AGO

let price of 1 kg apple is x and 1 kg grapes is y
then x+y=50;
5x+7y=X;
if we put values of x from options then y=(X-250)/2
y>20 and y

Like? Yes | No (1)  

09 Feb 2016 Integer

If y = (6+x)^2/(6-x)^2 is not a perfect square integer and x is less than 6 and greater than 0, then the value of y is

OPtion

1) 100/9
2) 16/3
3) 81/8
4) 49/25
5) 20
6) 1/2
7) 121
8) 25
9) 25/16
10) 24

Solution

On taking x = 1, 2, 3, 4, 5 respectively, we get
y = 49/25, 4, 9, 25, 121
Only 49/25 is not a perfect square integer, hence is the solution.

Option 4)

Correct Option: 4 Best Solution (16)

karnatakam.Jaswanth kumar   8 years AGO

Given that the y is not a perfect square integer
Then (6+x)÷(6-x) must not the integer
From values in the interval x
x=1 gives the non integer value
So by substituting the x value we will get y=49/25

Like? Yes (3) | No   

Garrepally Gopikrishna   8 years AGO

As x varies from 0 to 6 (i.e.1,2,3,4,5)
so substitute 1,2,3,4,5
if you substitute 2,3,4,5 gets intezer
but if you substitute 1 you get 49/25 which is not an intezer
so option 4

Like? Yes (3) | No   

RAHUL KUMAR   8 years AGO

Y= (6+x)^2/(6-x)^2
At X = 2,3,4,5 it is a perfect sq number
But At X= 1
the value of Y = 49/25
option (4) is correct.

Like? Yes (2) | No   

Mukund Manohar   8 years AGO

Calculating the value of y by taking x=1,2,3,4 & 5 (because 0

Like? Yes (1) | No   

SHUBHAM   8 years AGO

Solution

On taking x = 1, 2, 3, 4, 5 respectively, we get 
y = 49/25, 4, 9, 25, 121
Only 49/25 is not a perfect square integer, hence is the solution

Option (4)

Like? Yes (1) | No   

vineesha p   8 years AGO

[(6+1)/(6-1)0^2=49/25.
The rest are all perfect squares

Like? Yes (1) | No   

harsh dhir   8 years AGO

on taking x=1,2,3,4,5 we get y=49/25,4,9,25,121.
only 49/25 is not a perfect square integer.
y=49/25

Like? Yes (1) | No   

Yashi Das   8 years AGO

when x= 1 y=49/25
x=2 y=4
x=3 y=9
x=4 y=25
x=5 y=121
Therefore option 4) 49/25

Like? Yes (1) | No   

Akshat Sood   8 years AGO

substituting value of x as 1
we get value of y comes out to be 49/25 that is not perfect square

Like? Yes (1) | No   

satish ojha   8 years AGO

x is putting 1 then give = 49/25

other is give perfect square no so not possible

Like? Yes (1) | No   

Jaikumar Bhatia   8 years AGO

By putting the value of x in the equation
x=1,y=49/25
x=2,y=4
x=3,y=9
and so on....
49/25 is not a perfect square integer
ans is 49/25
option is (4)

Like? Yes (1) | No   

aneesh s s   8 years AGO

(6+1)^2/(6-1)^2
7^2/5^2
49/25.

Like? Yes (1) | No   

Sagar Jinachandran   8 years AGO

y=((36+12x+x^2)/(36-12x+x^2))
substituting values of x from 1-5 we get
x=1, y= 49/25
x=2, y=4
x=3, y=9
x=4, y=25
x=5, y=121
rest all are perfect squares
so we get
49/25
option 4

Like? Yes (1) | No   

aruj chatterjee   8 years AGO

Y is not a perfect square integer then 25 nd 121 are excluded from the option ...so 8 options are left
since 0

Like? Yes (1) | No   

SHAIK JANI BASHA   8 years AGO

(6+x)^2/(6-x)^2..if x=1 then y=49/25 its not a perfect square..if x=2,3,4,5 we get perfect squares

Like? Yes (1) | No   

Jaspalsingh Parmar   8 years AGO

option 4 is correct

Like? Yes (1) | No (1)  

08 Feb 2016 Sequence

What is the next number of the following sequence.
48, 132, 363, 726, 1353, ......

OPtion

1) 5648
2) 5448
3) 4984
4) 4888
5) 4884
6) 5488
7) 4896
8) 4958
9) 5484
10)4484

Solution

48,
48 + 84 = 132
132 + 231 = 363
363 + 363 = 726
726 + 627 = 1353
Similarly
1353 + 3531 = 4884
Option 5)

Correct Option: 5 Best Solution (49)

santosh kumar patel   8 years AGO

48 = 48
48+84=132
132+231=363
363+363=726
726+627=1353
1353+3531=4884
ans: 4884

Like? Yes (2) | No   

Shagun Chaudhary   8 years AGO

48
adding the reverse,
48+84=132
132+231=363 similarly
ans=4884

Like? Yes (1) | No   

Garrepally Gopikrishna   8 years AGO

Sum of digits of numbers are 3,6,3,6,3
So next number should have sum of digits should be 6 so 4884 equals to 4+8+8+4 gives 24
Again sum 2+4 gives 6

Like? Yes (1) | No   

Maneesh Gupta   8 years AGO

48+84=132
132+231=363
.
.
.
1353+3531=4884

Like? Yes (1) | No   

Ramgopal   8 years AGO

48
48+84=132
132+231=363
363+363=726
726+627=1353
1353+3531=4884

Like? Yes (1) | No   

Rahul Khatavkar   8 years AGO

48+84=132
132+231=363
.......................
1353+3531=4884

Like? Yes (1) | No   

Vibhay Thakur   8 years AGO

48+84=132
132+231=363
363+363=726
726+627=1353
1353+3531=4884

Like? Yes (1) | No   

Testing Account   8 years AGO

5)..... Because
48 84=132
132 231=363
363 363=726
726 627=135
......so inversely
1353 +3531=4884

Like? Yes (1) | No   

Prakash Panda   8 years AGO

48+84=132
132+231=363
363+363=726
726+627=1353
1353+3531=4884

Like? Yes (1) | No   

farhat jahan   8 years AGO

1353=3+1=4
5+3=8
3+5=8
1+3=4
now reverse=4884

Like? Yes (1) | No   

A Dinesh Kumar Reddy   8 years AGO

48+84=132 132+231=363 363+363=726 726+627=1353 1353+3531=4884

Like? Yes (1) | No   

satish ojha   8 years AGO

48+84=132
132+321=363
363+363=726
726+627=1353
1353+3531=4884

Like? Yes (1) | No   

Sagar Jinachandran   8 years AGO

Adding the mirror images of the numbers to itself we have
48+84=132
132+231=363
363+363=726
726+627=1353
So
1353+3531=4884
Option 5

Like? Yes (1) | No   

harsh dhir   8 years AGO

48=48
The reverse of 48 is 84.So reverse sum=48+84=132
132+231=363
363+363=726
726+627=1353
1353+3531=4884

Like? Yes (1) | No   

jagannathan   8 years AGO

Adding up the reversed form of no. With itself to get next number

Like? Yes (1) | No   

Subha Poddar   8 years AGO

48+84=132
132+231=363
363+363=726
726+726=1353
1353+3531=4884
ans is 5

Like? Yes (1) | No   

RISHABH   8 years AGO

Reverse of 48 is 84
So, 48+84=132
132+231=363 and so on...
1353+3531=4884

Like? Yes (1) | No   

EMANDI KETHAN KUMAR   8 years AGO

48+84=132
132+231=363
363+363=726
726+627=1353
1353+3531=4884
ans 5

Like? Yes (1) | No   

T SIVAPRAKASH   8 years AGO

132-48=84
363-132=231
762-363=363
1353-762=627
4884-1353=3531....ans is 4884

Like? Yes (1) | No   

sayam aparanji   8 years AGO

48 is added to reverse ofo84 then it is 132.
132 is added to reverse of231 then it becomes 363 same like that 1353 reverse 3531 then added it becomes 4884

Like? Yes (1) | No   

GOURANGA SUNDAR MANDAL   8 years AGO

the logic is ..previous no +reverse of the number
so..the next number is 1353+3531=4884
so option 5 is correct answer

Like? Yes (1) | No   

swasthika   8 years AGO

number + reverse of the same number = next number
48+84=132
132+231=363
like wise, 1353 + 3531 = 4884

Like? Yes (1) | No   

Venkateswarlu   8 years AGO

48+84 =132;
132+321=363;
similarly,
1353+3531 =4884

Like? Yes (1) | No   

aditya kataria   8 years AGO

series is define as
48+84=132
132+231=363
..
..
1353+3531=4884

Like? Yes (1) | No   

Karthick Raja   8 years AGO

48+84=132
132+231=363
363+363=726
726+627=1353
1353+3531=4884

Like? Yes (1) | No   

Gajera karankumar mahendrabhai   8 years AGO

48+84=132

132+231=363

363+363=726

726+627=1353

so1353+3531=4884.

Like? Yes (1) | No   

ayushi   8 years AGO

48+84=132
132+231=363
.....
..
1353+3531=4884

Like? Yes (1) | No   

Neetin Kumar   8 years AGO

48+84=132
132+231=363
363+363=726
726+627=1353
1353+3531=4884

Like? Yes (2) | No (1)  

Swetha Gottimukkula   8 years AGO

add first no+ reverse of first no gives the second no in the series
ex:
48+84=132
132+231=363
363+363=726
726+627=1353
1353+3531=4884

Like? Yes (1) | No   

G BHARATH REDDY   8 years AGO

48+84=132
132+231=363
363+363=726
726+627=1353
1353+3531=4884

Like? Yes (1) | No   

kousika   8 years AGO

since 132-48 gives the reversal of 48 ie 84. and so on.... hence 4884 -1353 gives 3531.hence 5 option is correct

Like? Yes (1) | No   

Saleel Kulkarni   8 years AGO

The difference between the two nos is sum of the number and inverse of it.
48+84=132
132+231=363
363+363=726
726+627=1353
1353+3531=4884
Option 5

Like? Yes (1) | No   

JENSI KARUNYA.S   8 years AGO

4+8=12=>1+2=(3)
1+3+2=>(6)
3+6+3=12=>1+2=(3)
7+2+6=15=>1+5=(6)
1+3+5+3=12=>1+2=(3)
so the answer is 4884
i.e. 4+8+8+4=24=>2+4=(6)
so the correct answer is option 5) 4884

Like? Yes (1) | No   

suryakant singh   8 years AGO

answer:5) 4884
48+84 = 132
132+231 = 363
363+363 = 726
726+627 =1353
1353+3531 =4884
all numbers added with their reverse then get result

Like? Yes (1) | No   

vamsi krishna   8 years AGO

48+84= 132
132+231 = 363
363+363 = 726
726+627 =1353
1353+3531 = 4884

Like? Yes (1) | No   

Jamil Ahmed   8 years AGO

Reversing the digits of the number and adding it to the number itself, we get the next number. So,
48 + 84 = 132
132 + 231 = 363
363 + 363 = 726
726 + 627 = 1353
1353 + 3531 = 4884

Like? Yes (1) | No   

Surendra Naraga   8 years AGO

By adding the reverse numbers... we can get the answers..
48+84=132
132+231=363
363+363=726
726+627=1353
1353+3531=4884.

Like? Yes (1) | No   

kriti chaudhary   8 years AGO

48+84=132
132+231=363
363+363=726
726+627=1353
1353+3531=4884

Like? Yes (1) | No   

RITESH KUMAR JHA   8 years AGO

sum of all digits come in 3 6 3 6.... in that manner so, that sum of 4884 is 6.

Like? Yes (1) | No   

S.Tejasri   8 years AGO

We are adding the give number and the reverse of that number

Like? Yes (1) | No   

Surabhi Yadav   8 years AGO

48+84=132
132+231=363
363+363=726
726+627=1353
1353+3531=4884

Like? Yes (1) | No   

divys malik   8 years AGO

first take out difference between consecutive numbers
132-48=84
84 is reverse of 48....similarly calculate for all
you will observe the pattern.....
now reverse of last no is 3531
add this to 1353 to get answer
3531+1353=4884

Like? Yes (1) | No   

JANARTHANAN RAM   8 years AGO

No+(Reverse Of No)=Next No.
1353+3531=4884;

Like? Yes (1) | No (1)  

RAHUL KUMAR   8 years AGO

48+84 = 132
132 +231 = 363
363 +363 = 726
726 +627 = 1353
Similarly
1353 +3531 = 4884
option 5).

Like? Yes (1) | No (1)  

Yashi Das   8 years AGO

48+84=132
132+231=363
363+363=726
726+627=1353
1353+3531=4884

Like? Yes (1) | No (1)  

ABHINAV PUSHPAM   8 years AGO

48+84=132
132+231=363
363+363=726
726+627=1353 so similarly
1353+ 3531= 4884
option 5)

Like? Yes (1) | No (1)  

MRITUNJAY   8 years AGO

second.number =number + reverse
48+84=132
132+231=363
363+363=726
726+627=1353
1353+3531=4884
option 5

Like? Yes (1) | No (1)  

Mukund Manohar   8 years AGO

Reverse the digits and add to it.
48+84=132
132+231=363
363+363=726
726+627+1353
1353+3531=4884

Like? Yes (1) | No (1)  

karnatakam.Jaswanth kumar   8 years AGO

Make the sum of all digits in each number of the given series
Then we will get the series of single digit as 3,6,3,6,3...
And check the answers by same method to get the single digit as 6
Hence 5th option is correct

Like? Yes (1) | No (1)  

05 Feb 2016 Profit and loss

Saurav bought a Washing Machine with 20% discount on the labelled price. Had he bought it with 25% discount, he would have saved Rs.500. At what price did he buy the Washing Machine.

OPtion

1) Rs.18000
2) Rs.15000
3) Rs.8000
4) Rs.16000
5) Rs.6000
6) Rs.12000
7) Rs.15500
8) Rs.10000
9) Rs.19000
10)Rs.5000

Solution

Let the labelled price be Rs.100
S.P. in 1st case = Rs.80,
S.P in 2nd case = Rs.75
5:100 :: 500 : x
So x = 100*500 / 5 = 10000
Option 8)

Correct Option: 8 Best Solution (16)

garima kadam   8 years AGO

Differce in discount = 25-20=5%
Difference in amount=rs.500
So, 5%=500
1%=100
So 100%= rs 10000

Like? Yes (12) | No (5)  

Suryakant Dwivedi   8 years AGO

10000 labelled price. he bought it on 20 % discount. so he bought it in 8000. if he bought it 25% discount he gain 500. so the ans is 10000.

Like? Yes (1) | No   

Jivanjot singh   8 years AGO

let the labeleed price be 100
so 1st s.p. is 80 and
2nd s.p. is 75

so he saved rs 5

so labelled price is
(100/5)*500
------>>>10000 rs

Like? Yes (1) | No   

RAM NATH KASHYAP   8 years AGO

Let 100 as base price & then calculate if 5 rs. is being saved on 100 then 500 rs will be saved for 10000.

Like? Yes (5) | No (4)  

Anitha Kumar   8 years AGO

let the amount be X;
(x-(x*20%))-(x-(x*25%))=500;
by solving the eq we get x=10000

Like? Yes (2) | No (1)  

Saleel Kulkarni   8 years AGO

Let the labelled price be x.
According to the given information he bought the washing machine at 0.8x but if purchased at 0.75x then he would have saved Rs.500
0.75x=0.8x-500
x=10000
Option 8

Like? Yes (2) | No (1)  

Akanksha Kansara   8 years AGO

Let C.P. be Rs. x, then for 20% discount the M.P. = Rs. x+(20x/100) and for 25% discount New M.P. = Rs. x+(25x/100).
Given the difference is Rs. 500.
Therefore New M.P. - Old M.P. = 500
(x+(25x/100)) - (x+(20x/100)) = 500
Therefore Cost Price = x= Rs. 10000

Like? Yes (2) | No (2)  

sheshank vaidya   8 years AGO

let the price of the washing machibe be x.Now sourav bought the machine with 20% discount,his price on the machine was x/5.If he would buy the same machine for 25% discount then he would have paid x/5 on the machine.Now we substitute each value of the option in x and check for the difference of ((x/4)-(x/5)),if the result is 500 then that is the right option.Here if we substitute 10000 we get difference of 500,so it is the correct option.

Like? Yes (1) | No (1)  

suraj prakash   8 years AGO

difference between the 20 % discount and 25 % discount is 500

Like? Yes (1) | No (1)  

Swetha Gottimukkula   8 years AGO

20% of 10000 is 2000 and 25% of 10000 is 2500 so he got 500 profit

Like? Yes (1) | No (1)  

Patan Asim Basha   8 years AGO

he asked 25% discount on cost price and saved 500 amount ; probably 10^4

Like? Yes (1) | No (1)  

Akshat Sood   8 years AGO

let original price be x
x=80x/100
x-500=75x/100
substitute value of x in eq 2
x=10000

Like? Yes (1) | No (2)  

Gajera karankumar mahendrabhai   8 years AGO

if labbled price=100

in 1st case=80rs
in 2nd case=75rs

so 5rs saved on labbled price.

so,frac{100}{5}time500}=10000

Like? Yes (1) | No (2)  

Garrepally Gopikrishna   8 years AGO

Let the original cost is x
Let the cost he bought the product is y
Initially at 20â„… discount
y=x-(x*20/100)
Next at the 25â„… discount there will be 500 rs save
It means that
x- (x*25/100)=y-500
By substituting the y value and by solving we get
X=10,000....

Like? Yes (2) | No (5)  

karnatakam.Jaswanth kumar   8 years AGO

Let the original cost is x
Let the cost he bought the product is y
Initially at 20â„… discount
y=x-(x*20/100)
Next at the 25â„… discount there will be 500 rs save
It means that
x- (x*25/100)=y-500
By substituting the y value and by solving we get
X=10,000....

Like? Yes (1) | No (4)  

sugayathri   8 years AGO

let us assume that,

cost price of wm=100x
sp of wm=when 20%profit
sp = 120x
sp=when 25%profit
sp=125x
125x-120x=500

x=100
cp = 100*100

=10000

Like? Yes (2) | No (6)  

04 Feb 2016 Time and work

Amit and Bharat can do a piece of work in 45 and 40 days respectively. They began the work together but Amit leaves after some days and Bharat finished the remaining work in 23 days. After how many days did Amit leave?

OPtion

1) After 9 days
2) After 16 days
3) After 13 days
4) After 10 days
5) After 6 days
6) After 8 days
7) After 7 days
8) After 15 days
9) After 11 days
10)After 12 days

Solution

Bharat's 23 days work = 23*1/40 = 23/40.
Remaining work = 1 - 23/40 = 17/40
(Amit + Bharat) 's 1 day's work = 1/45 + 1/40 = 17/360
17/360 work is done by Amit and Bharat in 1 days
Therefore 17/40 work is done by them in 360/17 * 17/40 = 9 days
Hence Amit left after 9 days
Option 1)

Correct Option: 1 Best Solution (39)

neeraja   8 years AGO

A---> 45days
B---> 40days

total work ==> 360 units
one day work
A---> 8 units
B--->9 units
A+B ---> 17 units

B does rem work for 23 days i.e B alone does 23*9=207 units of work alone

360-207=153 units A&B did
together
153/17=9

thus A left after 9 days

Like? Yes (5) | No   

Shagun Chaudhary   8 years AGO

Let x be the no. of days they work together.
x({1/45}+{1/40})+{23/40}=1
===>x=9
So Amit left after 9 days

Like? Yes (4) | No   

Mukund Manohar   8 years AGO

Amit's 1 day's work is 1/45
Bharat's 1 day's work is 1/40
Let Amit left the work after x days.
So,
x/45 + (x+23)/40 = 1
=> (8x + 9x + 207)/360 = 1
=> 17x = 153
=> x = 9
Amit left the work after 9 days

Like? Yes (4) | No   

GOURANGA SUNDAR MANDAL   8 years AGO

bharat can do finish 1/40 *23 portion work
so the remaining work is (1-23/40)=17/40.
amit and bharat can do piece of work in ond day(1/40 +1/45)=17/360 portion
so they work toghter (17/40)/917/360)=9
so amit leave after 9 days..
so option 1 is correct answer

Like? Yes (2) | No   

rakesh   8 years AGO

Bharath-- 1/40
bharath alone--23/40
Both had done work--17/40
17x/360=17/40
x=9
After 9 days amit left

Like? Yes (2) | No   

muneeskumar12@gmail.com   8 years AGO

total=360
remaining work=207

360-207=153

153÷17=9

amit and bhart 1 day work=8+9=17

Like? Yes (2) | No   

KARNI PRAVEEN KUMAR   8 years AGO

work here we have to take as chocolates
amith will eat 8 chocolates per day
bharat will eat 9 chocalates per day
bharat work 23*9=207
they both can do 153 w0rk in 9 days
bharath and amith work=9*9+9*8=153

Like? Yes (2) | No   

MRITUNJAY   8 years AGO

bharat work in last 23 days is 23/40
remaining work=17/40
work done by both is 1/45+1/40=85/45*40
number of days after amit leave is 17/40/85/45*40=9 days
option 1

Like? Yes (1) | No   

satish ojha   8 years AGO

amit do left work =360-207=153
amit + bharat do = 153/17=9 days

Like? Yes (1) | No   

Abhishek   8 years AGO

Amit & Bharat's 1 day's work = 1/45 + 1/40 = 17/360

Work done by Bharat in 23 days = 23/40

Remaining work = 1 - 23/40 = 17/40

Now, 17/360 work was done by Amit & Bharat in 1 day.

So, 17/40 work was done by Amit & Bharat in
360/17 *17/40 = 9 days

Hence, Amit left after the work after 9 days.

Like? Yes (2) | No (1)  

Devendra Marghade   8 years AGO

1 day work of Amit & Bharat=(1/45)+(1/40)=17/360
If working together for 'x' days, Amit leaves, then remaining work=1-(17x/360)=(360-17x)/360
As Bharat finished remaining work in 23 days,so
[(360-17x)/360]/(1/40) =23
On solving x=9
Option 1)

Like? Yes (1) | No   

Yashi Das   8 years AGO

( Amit + Bharat)'s one day work=( (1/45)+(1/40))
work done by Bharat in 23 days= 1*(23/40) =23/40
Remaining work =1- (23/40) =17/40
Now,
(17/360) work was done by (Amit +Bharat) in 1 day.
(17/40) work was done by (Amit+ Bharat) in 1*((360/17)*(17/40)) =9 days
Therefore, Amit left after 9 days.

Like? Yes (1) | No   

Prakash Panda   8 years AGO

1/40+1/45=17/360

cmbine work 1-23/40=17/40

solving dis we get 9 dys of cmbine work

Like? Yes (1) | No   

harsh dhir   8 years AGO

time taken by A+B to complete the work=(45*40)/(45+40)=360/17
work done by B in 23 days=23/40
remaining work=1-23/40=17/40
17/360 work was done by A+B in 1 day
17/40 work will be done in 17/360*40/17=9 days
So A left after 9 days.

Like? Yes (1) | No   

pramit   8 years AGO

A+B s 1 day work=17/360
Work done by B in 23 days=23/40
Rem work=17/40
17/360 work in 1 day
17/40 work in 9 days

Like? Yes (1) | No   

suryakant singh   8 years AGO

Answer: 9 days
In 1 day admit do 1/45 and Bharat 1/40 then both together do 17/360

A/q, Bharat do remaining work in 23 days means 23*(1/40) work=23/40 then 1-23/40 work they do together =17/40
Then amit leave the work after (17/40)/(17/360)=9 days.

Like? Yes (1) | No   

karnatakam.Jaswanth kumar   8 years AGO

A can do the work in 45 days therefore his one day work is 1/45
B can do the work in 40days therefore his one day work is 1/40
A and B together work per day will be (1/45+1/40)
Let they have done the work for x days and after that A left
The work done for the x days will be x(1/45+1/40)
The remaining work will be 1-x(1/40+1/45)
This work is done by B in 23 days then
23*(1÷[1-x(1/45+1/40)]=40
By solving we get x=9
Therefore A left the work after 9 days

Like? Yes (1) | No   

Garrepally Gopikrishna   8 years AGO

A's 1 day work is 1/45
lly B's 1/40
So 23/(1-x(1/45+1/40)) equals to 40
So x is 9
Xis work done by A

Like? Yes (1) | No   

Gajera karankumar mahendrabhai   8 years AGO

amit work in 45 days.

effi.=1/45

bharat work in 40 day.

eff. = 1/40


amit leave some day.

and bharat finish remaining work in 23 day.

bharat did work = 23*1/40*2=11.5/40

so amit and bharat works are=11.5/40/11.5/360=9 day of bharat leave.

Like? Yes (1) | No   

karthiga   8 years AGO

A - 45
B - 40
the LCM of 45,40 is 360.
A finished 360/45 =8 parts in one day;
B finished 360/40 = 9 parts in one day;
Both are finished 17 parts in one day;
23 days B only worked,
Total parts of the work is 360,
So, 23*9 + 17x = 360;
17x = 153
x = 9;
A leave after the 9th day.

Like? Yes (1) | No   

Jaikumar Bhatia   8 years AGO

Let's Amit=A & Bharat=B
(A+B)'s 1 day's work=[1/45+1/40]=17/360
=> workdone by B in 23 days=1*23/40=23/40
=>Remaining work=1-23/40=14/40
=>now, 17/360 work was done by (A+B) in 1 day
=>17/40 work was done by (A+B) in 1*360/17*17/40=9 days
Therefore A left after 9 days.
Option is (1)

Like? Yes (1) | No   

sachin sawant   8 years AGO

Completes 1/40th work in 1 day
Thus in 23 days B will complete 23/40 thi work
Now remaining work is 1-23/40=17/40 is done by both A&B
Together A&B can complete(1/40+1/45=17/360)th work in 1 day
Thus to complete 17/40th work they will need
17/40*1*360/17=9days
Thus A leaves after 9 days

Like? Yes (1) | No   

THUMMALA VINEESHA   8 years AGO

bharat work for 23 days=23/40
remaining work=17/40
this work done by both in
x(1/45+1/40)=17/40
x=9 days

Like? Yes (1) | No   

kondapuram tirumalreddy   8 years AGO

Amit and bharat's 1 day work = (1/45 + 1/40) = 17/360
Bharath's 23 days work =23/40
Remaining work 1- 23/40 = 17 /40
So 17/360 work was done Amit and bharath in 1 day .
Then 17/40 work was done by Amit& bharath in ( 1*360/17*17/40)= 9 days
Amit left after 9 days

Like? Yes (1) | No   

Jivanjot singh   8 years AGO

amit 1/45=2.22 %
bharat 1/40=2.5%

bharat did the work in 23 days = 23*1/40=23/40=0.575

rest work was done by together and also leave the work ny amit
==[23/40]/[23/360]=9
9days


so amit leaves work after 9 days ,,,

Like? Yes (1) | No   

Neelima Kongathi   8 years AGO

Remaining work which is left after bharath had done
1-23/40=17/40
one day of work done by both amith and bharat
1/40 + 1/45 = 17/360
17/360 x = 17/40
x = 9
after 9 days

Like? Yes (1) | No   

Gaurab Kumar Jha   8 years AGO

a/q 23/40 is work done by bharat in 23 days
remaining work = 1-23/40=17/40
let the work done by both in x days is 17/40
and 17 / 40 = (1/40+1/45 ) * x
x=9 i,e option 1

Like? Yes (1) | No   

Jamil Ahmed   8 years AGO

Since Bharat completed the remaining work in 23 days, the part of work done by Amit & Bharat together = (40-23)/40 = 17/40.
Part of the work done by both of them together in 1 day = 1/45 + 1/40 = 17/360.
No. of days after which Amit left = 360/17 * 17/40 = 9

Like? Yes (1) | No   

Bicky kumar   8 years AGO

one day work =1/40 + 1/45 =17/360
let amit leaves in x days then
total work done by both in x days=17x/360
remaining work=(360-17x)/360 ,done by bharat in 23 days.
bharat completes one work in 40 days hence
(360-17x)/360 will be done in (360-17x)/9 which is equal to 23.
that will my x equals to 9.

Like? Yes (1) | No   

sahil arora   8 years AGO

amit can do 1/45 part of work in 1 day
bharat can do 1/40 part of the work in 1 day
both together can do 1/45+1/40=17/360 work in 1 day

let amit nd bharat work together for x days and after it amit leaves the work
so in x days both together complete 17*X/360 part of work

remaing work is 1- (17x/360)

bharat can do 1/40 of the work in 1 day
as given in question he completes its work in 23 days so the work completed in 23 days is 23/40

hence 1-(17x/360)=23/40

on calculating we get x=9 days

Like? Yes (1) | No   

balla lakshmi sameeramani   8 years AGO

1 day amit can do a piece of work = 1/45th
1 day bharat can do a piece of work = 1/40th

both can do a piece of work in 1 day = (1/45 + 1/40)
= 17/360

bharat worked for 23 days = (1/40)*23
= 23/40

both completed work = 1-(23/40)
= 17/40

they worked together

= (completed work)/(1 day work both can complete)

=(17/40)*(360/17)

= (360/40)

= 9 days

they worked together for 9 days

Like? Yes (1) | No   

RASHMI BALWANI   8 years AGO

As work rate of B is 9 and he is doing a work for 23 days.. So work done by B alone is 207 from total work of 360.
so remaining work I.e. 153 will be done at 17 rate for 9 Days..

Like? Yes (1) | No   

Richa Jain   8 years AGO

Together amit and bharat 's complete work= 1/45 + 1/40 = 17/360
So total time=360/17 days
Now, bharat's 23 days work= 23*1/40=23/40
Remaining work = 1-23/40= 17/40
So,( A+B)'s 1 day work = 17/360
(A+B)'s 17/40 work will be complete in = 360/17 * 17/40 = 9 days
So Amit left after 9 days

Like? Yes (1) | No   

keerthana   8 years AGO

amit and bharat done the starting work. so when i calculate using work done formulae i got the answer as 9 days

Like? Yes (1) | No   

divya sree   8 years AGO

amit can complete the work in 45 days
1 day work=1/45------>(1)
bharat can complete the work in 40 days
1 day work=1/40--------->(2)
add (1)+(2), we get
1/45+1/40=17/360---------->(3)
bharat will complete the remaining work after amit had left in 23 days then bharat will complete 23*9=207
bharat's one day part ratio is 9

remaining 153 parts will be copleted by both amit and bharat in 9 days

so, answer is 9 days

Like? Yes (1) | No   

Saleel Kulkarni   8 years AGO

Amit completes 1/45 unit of work in 1 day and Bharat completes 1/40 unit of work in 1 day.
Bharat alone completed the remaining work in 23 days i.e. he did 23/40 unit of work so 17/40 unit of work was completed by Amit and Bharat both.
Amit and Bharat together completes 17/(40*9) unit of work in 1 day, so to complete 17/40 they require 9 days.
Hence Amit worked for 9 days.
Option 1

Like? Yes (1) | No   

divya   8 years AGO

x(1/45+1/40)+23*1/40=1
solving this we get
x=1/9
x=9days

Like? Yes (1) | No   

sumit kumar   8 years AGO

1 day work by both=1/40+1/45=17/360
let both work for x days
so total work by both in x days
=17x/360
rest work which has done by bharat
=1-17x/360
since bharat does 1 work in 40 days
so (1-17x/360 ) work in (1-17x/360)*40 days
a/c to question
(1-17x/360)*40=23
40-17x/9=23
17=17x/9
x=9 days
so option 1

Like? Yes (1) | No   

RITESH KUMAR JHA   8 years AGO

amit work= x
x/45 + x+23/40=1
and from here we get 9.

Like? Yes (1) | No   

03 Feb 2016 Age

Ramesh says to his son Girish, "My age was two years more than 7 times of your's age before 30 and 1/2 a year and after 2 and 1/2 a year, my age will be twice of yours age of 1/2 a year before". What will be the age of Girish after 12 and 1/2 a year.

OPtion

1) 36 and 1/2
2) 46 and 1/2
3) 42
4) 52 and 1/2
5) 40
6) 48
7) 38
8) 50
9) 41 and 1/2
10) 39 and 1/2

Solution

Let the present ages of father and son are "x" and "y" respectively.
According to the first condition given
(x - 30.5) = 7 ( y - 30.5 ) + 2 (i)
According to the second condition given
(x + 2.5) = 2 ( y – 0.5) (ii)
On solving these equations we get the solution.

Option 6)

Correct Option: 6 Best Solution (17)

Maneesh Gupta   8 years AGO

Let's present age of Girish is x years
and present age of Ramesh is y years.
30.5 years ago,
7(x-30.5)+2=y-30.5................(i)
After 2.5 years,
(y+2.5)=2(x-0.5).....................(ii)
simplify (ii), we get
y=2x-3.5.................................(iii)
Now put value of Y from (iii) in to (i)
7(x-30.5)+2=(2x-3.5)-30.5
7x-213.5+2=2x-34
5x=177.5
x=35.5
present age of girish is 35 & 1/2 years
35.5+12.5=48 years
after 12.5 years girish age will be 48 years

Like? Yes (5) | No   

Shagun Chaudhary   8 years AGO

Let's present age of Girish is x years
and present age of Ramesh is y years.
30.5 years ago,
7(x-30.5)+2=y-30.5................(i)
After 2.5 years,
(y+2.5)=2(x-0.5).....................(ii)
simplify (ii), we get
y=2x-3.5.................................(iii)
Now put value of Y from (iii) in to (i)
7(x-30.5)+2=(2x-3.5)-30.5
7x-213.5+2=2x-34
5x=177.5
x=35.5
present age of girish is 35 & 1/2 years
35.5+12.5=48 years
after 12.5 years girish age will be 48 years

Like? Yes (5) | No   

Rishu   8 years AGO

let present age of father and son be x & y years respectively
then,
30.5 yrs ago
fathers age=x-30.5 yrs
sons age=y-30.5 yrs

x-30.5=7(y-30.5)+2
on simplification
7y-x=181.....(1)

after 2.5 yrs
fathers age=x+2.5 yrs

before 0.5 yrs
sons age=y-0.5 yrs

therefore x+2.5=2(y-0.5)
on simplification
2y-x=3.5.....(2)

solving equation (1)&(2),
x=67.5 & y=35.5

hence Girish's after 12.5 yrs=(35.5+12.5)=48 years

Like? Yes (4) | No   

Neelima Kongathi   8 years AGO

girish ramesh
before 30+ 1/2 yrs x 7x+2
before 1/2 yr x+30
after 2 + 1/2 yrs x+33 2(x+30)

x+30+(1/2)+2+(1/2) : 7x+2+30+(1/2)+2+(1/2) = x+33 : 2(x+30)
by solving this , x =5
girish age after 12 n 1/2 yrs = 5+30+(1/2)+12+(1/2)
= 48 yrs :-)

Like? Yes (2) | No   

arundhati ubhad   8 years AGO

let present age of Girish is x years
and present age of Ramesh is y years
30.5 years ago
7(x-30.5)+2=y-30.5-------------------------------------(1)
after 2.5 years
y+2.5=2(x-0.5)------------------------------------------(2)
simplyfinf (2) we get
y=2x-3.5-----------(3)
now substituting value of y in equation (1)
7(x-30.5)+2=(2x-3.5)-30.5
7x-213.5+2=2x-34
5x=177.5
x=35.5
present age ofGirish is 35 and 1/2 year
35.5+12.5=48 years
After 12.5 years Girish age will be 48 years

Like? Yes (2) | No   

RAKESH   8 years AGO

r-30.5 = 2+7(g-30.5)
=> 7g-r = 181

r+2.5 = 2(g- .5)
=> 2g-r = 3.5

1-2 => 5g = 177.5 => g=35.5

35.5+12.5 = 48

Like? Yes (1) | No   

Mukund Manohar   8 years AGO

Let the present age of Ramesh & Girish be x & y respectively
(x-30.5)-2=7(y-30.5)
=> x-32.5=7y-213.5
=>x-7y=-181 ------------>(i)
Now,
x+2.5=2(y-0.5)
=>x+2.5=2y-1
=> x-2y=-3.5 -------------->(ii)
on solving (i) & (ii),
y=35.5
So,the age of Girish after 12 and 1/2 a year=(35.5+12.5)years
=48 years

Like? Yes (1) | No   

suryakant singh   8 years AGO

Answer : 48 years


before 30 and 1/2 year,
R - 61/2 = 7*(G-61/2)+2
after 2 and 1/2 year,
R+ 5/2 = 2*(G-1/2)

if we equate r from both equation then
G =71/2
after 12 and 1/2 year it will be 48 years

Like? Yes (1) | No   

RANJAN FADIA   8 years AGO

Let ramesh current age of ramesh=x & girish =y

then x-30.5=7(y-30.5)+2 eqn (1)

i.e. x= 7y-181

eqn (2) will x+2.5=2(y-0.5)
=> x+2.5 =2y-1
=> x= 2y-3.5

from both eqn-
7y-181=2y-3.5
=>5y=177.5 or y = 35.5 (current age of girish)

35.5 +12.5 =48 is ans....option 6

Like? Yes (1) | No   

harsh dhir   8 years AGO

Let Ramesh age=x years,Girish age=y years
By given information :-
x-7y=-181 ----- (1)
2x-4y=-7 ------(2)
On solving,we get y=35.5
After 12.5 years,35.5+12.5=48 years

Like? Yes (1) | No   

GOURANGA SUNDAR MANDAL   8 years AGO

let the present age of ramesh is x years and girish age is y years
the 1st equ is (x-61/2)=7(y-61/2)+2...equ(1)
2nd equ is (x+5/2)=2(y-1/2)....equ(2)
calculating this two equ we get y=35 years and 1/2 of a years..
so after 12 years and 1/2 of a years , girish age will be 48 years
so option 6 is correct answer

Like? Yes (1) | No   

Siva   8 years AGO

Let 30 (1/2)yrs before r=7g+2,
So present ages are r+30(1/2), g+30(1/2).
After 2(1/2) yrs Ramesh age will be r+33, before 1/2 year age of girish be g+30
Now we get r+33=2(g+30),
r=2g+27, from the two eq obtain that are r=7g+2, r=2g+27 we get g=5, so present age of girish is35(1/2) yrs, after 12 (1/2) yrs he will be at 48.

Like? Yes (1) | No   

Venkateswarlu   8 years AGO

Let Present ages of Ramesh and Girish are y & x respectively.
Now,
y-30.5=7(x-30.5)+2 ===>> y=7x-181
y+2.5=2(x-0.5) ===>> y=2x-3.5
from 1 and 2
7x-181=2x-3.5 ===>> 5x =177.5 ===>> x=35.5
after 12.5 years Girish age will be 48.

Like? Yes (1) | No   

Saleel Kulkarni   8 years AGO

Let Girish's age be x and Ramesh's age be y.
According to 1st condition,
(y-30.5)=7(x-30.5)+2
=> y=7x-181___________equation 1
According to 2nd condition,
y+2.5=2(x-0.5)
=> y=2x-3.5_____________equation 2
So solving equation 1 and 2 simultaneously we get,
7x-181=2x-3.5
=> x=35.5
After 12.5 years = 35.5+12.5=48
Option 6

Like? Yes (1) | No   

amarjeet singh   8 years AGO

g- x years
R- y years 30.5 years ago.

7(x-30.5)+2=y-30.5

after 2.5 years

y+2.5 = 2(x-.5)

then y= 2x-3.5

putting vof y :

7(x-30.5)+2=(2x-3.5)-30.5
5x=177.5
x=35.35

So Girish : 35.5+12.5 =48

Like? Yes (1) | No   

MRITUNJAY   8 years AGO

let the age of grisih is x and ramesh be y
age of grisih 61/2 year before=x-61/2
father age=7(x-61/2)+2
y-61/2=7(x-61/2)+2..... (.1)
from 2nd part
x+5/2=2(y-1/2)......(2)
after solving we get x=71/2 age after 25/2 is 71+25/2=48

option 6

Like? Yes (1) | No   

Yashi Das   8 years AGO

Assume,
Present age of Girish be a yrs and that of Ramesh be b yrs.
30 and 1/2 yrs ago,
7(a-30.5)+ 2=b-30.5
After 2 and 1/2 yrs,
b+2.5= 2(a-0.5)
on solving,
x=35.5
Therefore present age of girish is 35 yrs and 1/2 yrs
35.5+12.5=48 yrs
and after 12.5 years girish will be 48 yrs old.

Like? Yes (1) | No   

02 Feb 2016 Number

Sohini was asked to multiply a certain number by 25. She multiplied it by 52 and got her answer more than the correct one by 324. The number to be multiplied was

OPtion

1) 14
2) 52
3) 28
4) 15
5) 36
6) 25
7) 18
8) 26
9) 46
10)None of these

Solution

Let the required number be x. Then
52x - 25x = 324
x = 12
Option 10)

Correct Option: 10 Best Solution (44)

PIYUSH KUMAR   8 years AGO

x * 52 = (x * 25) + 324
x*52-x*25 =324
x(52-25) = 324
x(27) = 324
x = 324//27
x = 12

Like? Yes (2) | No   

Garrepally Gopikrishna   8 years AGO

25x=y,
52x=y+324,
by solving above equations we get x=12

Like? Yes (2) | No   

Maneesh Gupta   8 years AGO

let the number to be multiplied with b x
then
52x=25x+324
27x=324
x=12
hence the answer is not given in option will choose the near most option available to the answer
12~14

Like? Yes (2) | No   

Shikhar Awasthi   8 years AGO

Let x is the number.
So,
X*25+324=x*52
27*x=324
X=12
So option is none of these

Like? Yes (2) | No   

sumit kumar   8 years AGO

let the no is x
a/c to question
52x-25x=324
27x=324
x=12
option is 10

Like? Yes (1) | No   

Devendra Marghade   8 years AGO

If the number was 'x' then 25x+324=52x or 27x=324,x=12
Option 10)None of these

Like? Yes (1) | No   

Abhineet kumar   8 years AGO

let the number is x
52*X-25*X=324
27 X = 324
x=12
so ans is 12

Like? Yes (1) | No   

RANJAN FADIA   8 years AGO

x*25=y
x*52=y+324

tthen..52x=25x+324
=> 27x=324
=> x = 12 n it is answer.

Like? Yes (1) | No   

Mukund Manohar   8 years AGO

Let the number be x
52x=25x+324
x=324/27
x=12

Like? Yes (1) | No   

priya sunupu   8 years AGO

let the number be x.
acc to given question 25*x+324=52*x
27x=324
x=12

Like? Yes (1) | No   

suprita hadimani   8 years AGO

consider x in number to be multiplied
x*25=y
when multiplied by 52
x*52=y+324
by solving simultaneous equations
x=12

Like? Yes (1) | No   

divya sree   8 years AGO

25x+324=52x

x=12, it satisfies the condition

so, answer is 12

Like? Yes (1) | No   

Arun Maharana   8 years AGO

as per question
25x=52x-324
=>27x=324
=>x=12
12 is ans but not in the list so ans is 10.none of these

Like? Yes (1) | No   

karnatakam.Jaswanth kumar   8 years AGO

Let x be the multiplied number
And y be the correct answer
Then52*x=25*x+324
Where y=25*x

Like? Yes (1) | No   

suryakant singh   8 years AGO

Answer : none of these
Let the number is x
52x=25x +324
27x=324
X=12

Like? Yes (1) | No   

THUMMALA VINEESHA   8 years AGO

25x=y
52x=y+324
27x=324
x=12

Like? Yes (1) | No   

rohit yadav   8 years AGO

52*x-25*x=324

after solving,
x=12

Like? Yes (1) | No   

GOURANGA SUNDAR MANDAL   8 years AGO

let the number is x..
then 52x-25x=324
so x=12
so option 10 is correct answer

Like? Yes (1) | No   

Rajanikanta Pradhan   8 years AGO

From question we can written as 25x+324=52x then calculating x=12

Like? Yes (1) | No   

Atul kumar singh   8 years AGO

let x be tht no.
thn 52x-25x=27x
and also 52x-25x=342
so 27x=324
and x =12

Like? Yes (1) | No   

Deepak   8 years AGO

Let the number be x and product y.
x * 25 = y...(1)
x * 52 = y + 324....(2)
solving for x we get x = 12

Like? Yes (1) | No   

shivangi bahuguna   8 years AGO

52x-25x=324
which gives x=12
hence, answer is none of these.

Like? Yes (1) | No   

Anand Kishore   8 years AGO

x*25=(x*52)-324
after solving,we get
x=12
which is not given as optn

Like? Yes (1) | No   

Gaurab Kumar Jha   8 years AGO

let tho no. be x
25 X + 324 = 52 X
324 = 27 X
X = 324 / 27
X= 12 i,e None of these

Like? Yes (1) | No   

Amit Kumar Pal   8 years AGO

25*x = y
but 52*x = y+324

put value of y in the form of x nd find x.
x = 12

Like? Yes (1) | No   

RAM NATH KASHYAP   8 years AGO

Answer is 12.
x*52=x*25+324
27x=324
x=12

Like? Yes (1) | No   

sunita kumawat   8 years AGO

suppose that number is =x
after the multiplication ans is =y
when it multiply by 25----->25x=y
when it multiply by 52---->52x=y+324

put the y value into last equation--->
52x-25x=324
27x=324
x=12

Like? Yes (1) | No   

SUBHASH TULSYAN   8 years AGO

Let the no. be k
A/Q
25k=r--->1 where r=actual result
52k=r+324------->2

after Solving
k=12

Like? Yes (1) | No   

kavi   8 years AGO

x*25=52*x-324
52*x-25*x=324
27x=324
x=12

Like? Yes (1) | No   

SHIVAM RAJ SINGH   8 years AGO

let the number b x
25*x=Y
52*x=Y+324
solving both x=12

Like? Yes (1) | No   

Akshat Sood   8 years AGO

52x=y+324
25x=y
52x=25x+324
solve
x=12
which is not in options
ans is option (10)

Like? Yes (1) | No   

HARMEET KAUR   8 years AGO

if x is the number, then
52x-25x=27x= 324; x=12 ... none of these

Like? Yes (1) | No   

harsh chaurasia   8 years AGO

x*25=y
x*52=y+324
- -
27x=324
x=324/27 = 12
Answer is 12
which is not present

Like? Yes (1) | No   

Rishu   8 years AGO

let the number be x
then,
52x-25x=324
27x=324
x=12

Like? Yes (1) | No   

Meenakshi   8 years AGO

Let x be the number which was asked to multiply with 25
then x * 25
x*52=(x*25)+324
52x-25x=324
27x=324
x=12
Answer is 12
option 10)

Like? Yes (1) | No   

mukesh kumar mishra   8 years AGO

let no = x;

required no = 25x;
wrong no= 52x;

52x = 25x+324;

27x= 324;
x=12;

as 25 *12 = 300;
52 *12 = 624;

Like? Yes (1) | No   

Aamir Beriwala   8 years AGO

Correct answer is=12
52x=25x + 324
27x = 324
so, x=12

Like? Yes (1) | No   

JENSI KARUNYA.S   8 years AGO

let the number to be multiplied is x
let the correct answer be y
25x=y
52x=y+324
52x=25x+324
27x=324
x=12
therefore the number to be multiplied is 12
the answer is option10) none of these

Like? Yes (1) | No   

PRASHANT TAYAL   8 years AGO

The number is=12
Let the number be=x
Let 25*x=y
Given 52*x=y+324
on solving we get x=12

Like? Yes (1) | No   

Behara Avinash   8 years AGO

let the variable be X and it can have difference of correct one subtract of original one then result as 324 then find X value as 12.

Like? Yes (1) | No   

kuna moulika   8 years AGO

let the number be 'x'
given that she multiplied the number by 52 and get 324 more than the correct one.so,we can write it as 52x=25x+324
27x=324
x=12

Like? Yes (1) | No   

Saleel Kulkarni   8 years AGO

Let the no to be multiplied be x.So the answer supposed to get is 25x. But she got 334 on multiplying x by 52, so
52x=25x+324
27x=324
x=12
None of the option mentioned
Option 10

Like? Yes (1) | No   

Manisha   8 years AGO

x*25=y
x*52=y+324
27x=324
x=12

Like? Yes (1) | No   

vikram jeet singh   8 years AGO

let no. is x
if she multiplied x with 25 , then product will be 25x
but she multiplied it with 52,then product is 52x
so 52x-25x=324
then we get x=12
so ans is none of these

Like? Yes (1) | No   

01 Feb 2016 CalculationI

If (Sqrt3)^5 * (9^2) = (3^x)*(3*Sqrt3)
Then x equals :

OPtion

1) 4
2) 3
3) 2
4) 5
5) 6
6) 7
7) 9
8) 8
9) 1
10)None of these

Solution

(sqrt3)^5 * 9^2 = 3^x * 3.sqrt3
3^5/2 * 3^4 = 3^x * 3^(3/2)
solve
we get x = 5
Option 4)

Correct Option: 4 Best Solution (38)

Arun Maharana   8 years AGO

sqrt3^5 *9^2=(3^x)*(3*sqrt3)
=>3^(5/2)*3^4=(3^x) * 3^(3/2)
=>3^((5/2)+4)=3^(x+3/2)
=>x+(3/2)=13/2
=>x=10/2
=>x=5

Like? Yes (2) | No   

Shagun Chaudhary   8 years AGO

equating the power of 3 and sqrt 3, we get x+1=6
x=5

Like? Yes (1) | No   

MRITUNJAY   8 years AGO

sqrt3^4*sqrt3*3^4=3^x*3*sqrt3
3^2*3^4*sqrt3=3^x*sqrt3
after solving we get x=5
option 4

Like? Yes (1) | No   

ritu yadav   8 years AGO

(sqrt3)^5*9^2= 3^x*3(sqrt3)
(sqrt3)^5*(sqrt3)^8=(sqrt3)^2x*(sqrt3)^3
equating the powers of sqrt3
we get,
5+8=2x+3
x=5

Like? Yes (1) | No   

Prakash Panda   8 years AGO

(sqrt3)^5*(9^2)=(3^x)*(3*sqrt3)
==>(3^x)=((sqrt3)^5*(9^2))/(3*sqrt3)

we know that (sqrt 3)^5= 9*(sqrt 3)
so that part cancled n remain 3

now (3^x)=3*(9^2)

by solving dis we get the ans as option 4 i.e 5

Like? Yes (1) | No   

Abhineet kumar   8 years AGO

(?3)^5*9^2=3^x*(3?3)
3*3?3*3^4=3^x*3?3
3^5=3^x
so
x=5

Like? Yes (1) | No   

suryakant singh   8 years AGO

answer: x=5
EXPALNATION:
(sqrt3)^5 = 3^5/2
(3*sqrt3)=3^3/2
if take log in both side then
log(3^5/2*9^2) = log(3^x*(3^3/2))
log(3^5/2)+log(9^2)=log(3^x)+log(3^3/2)
5/2log(3)+4log(3 )=xlog(3)+3/2log(3)
if we take log(3)common and cancelled then
5/2+4 = x+3/2
then x=5

Like? Yes (1) | No   

PRAGATHI G   8 years AGO

by power law..
3^((5/2)+4) = 3^(x+(3/2))
cancelling the bases and equating the powers
(5+8)/2 = (2x+3)/2
x = 5

Like? Yes (1) | No   

Sagar Jinachandran   8 years AGO

Left Hand Side
=Sqrt 3= 1.732
=(sqrt3)^5=15.58
=(sqrt(3)^5)*(9^2)=1262.665
RHS
=3^x*(3*sqrt(3))
=3^x*(3*1.732)
=3^x*5.196152
Comparing LHS and RHS and solving
we get
1262.665=(3^x*5.196152)
or 3^x=243
solving we get x=5
option 4

Like? Yes (1) | No   

Abhishek   8 years AGO

(Sqrt3)^5* 9^2 = (3^x) * (3*Sqrt3)

On simplifying:
3^(5/2) * 3^4 = 3^x * 3^(3/2)

on further simplifying:
3^(13/2) = 3^((2x+3)/2)

13/2 = (2x+3)/2
13 = 2x+3
x = 5

Like? Yes (1) | No   

Anurag Bawankar   8 years AGO

wrting each term in power of 3 we get

(3)^6.5 =(3)^x+1.5

x+1.5=6.5

x=5

Like? Yes (1) | No   

sachin sawant   8 years AGO

3^(5/2)*3^4=3^( x+3/2)
5/2+4=x+3/2
x=5

Like? Yes (1) | No   

GOURANGA SUNDAR MANDAL   8 years AGO

(sqrt3)^5*(9^2)
=(sqrt3)^13.....equ 1
(3^x)*(3*sqrt3)
=(sqrt3)^3+2x...equ 2
..calculating this two equ..we get x=5..
so option 4 is correct answer

Like? Yes (1) | No   

suprita hadimani   8 years AGO

(sqrt 3)^5*(9^2)=(3^x)*(3*sqrt3)
1.732^5 * 81= (3^x)*(5.196)
15.5861*81=(3^x)*(5.196)
1262.27/5.196=3^x
242.96=3^x
x=5

Like? Yes (1) | No   

kriti chaudhary   8 years AGO

L.H.S
(sqrt3)^5*9^2=(sqrt3)^5*9^2
=(sqrt3)^2(sqrt3)^2(sqrt3)*9^2=3*3*(sqrt3)*9^2=
9*(sqrt3)*9^2=(sqrt3)*9^3=729*(sqrt3)
R.H.S
(3^x)*(3*sqrt3)=(3^x+1)*(sqrt3)
if x=5,then 3^5=243 and x+1=6,then 3^6=729
so,3^6*(sqrt3)=729*(sqrt3)
L.H.S=R.H.S
So value of x=5.
answer.x=5

Like? Yes (1) | No   

Jamil Ahmed   8 years AGO

(sqrt3^5)*(9^2) = (3^x)*(3*sqrt3)
or, [3^(5/2)]*[(3^2)^2] = (3^x)*[3^(3/2)]
or, 3^(5/2+4) = 3^(x+3/2)
or, 5/2 + 4 = x + 3/2
or, x = 5/2 + 4 - 3/2 = 5

Like? Yes (1) | No   

SARANYA   8 years AGO

(SQRT3)^5*(9^2) = 3^X*(3*SQRT3)
(SQRT3)^5*(3^4) = 3^X*(3*SQRT3)
(SQRT3)^2*3^4 = 3^X
3*3^4 = 3^X
X=5

Like? Yes (1) | No   

Rajanikanta Pradhan   8 years AGO

As (sqrt3)^5 *(9^2)=(3^x)*(3*sqrt3)
so this can be rewritten as
fallows (sqrt3)*((sqrt3)^4) *((3^2)^2)=((3)^x)* 3*(sqrt3)
do by solving this we can get x=5

Like? Yes (1) | No   

sumit kumar   8 years AGO

(?3)^5*9^2=3^x*3?3
3^5/2*(3^2)^2=3^x*3^3/2
3^(5/2+4)=3^(3/2+x)
3^13/2=3^3/2+x
13/2=3/2+x
x=13/2-3/2=10/2=5
option 4

Like? Yes (1) | No   

Neelima Kongathi   8 years AGO

(sqrt3)^5 * (9^2) = (3^x)* 3 (sqrt3)
(sqrt3)^4 * 3^4 = 3^(x+1)
3^6 = 3^(x+1)
if bases are equal then powers are also equal
6 = x+1
x = 5

Like? Yes (1) | No   

Venkateswarlu   8 years AGO

3^(5/2)*9^2=3^(x)*3*3^(1/2);
3^(2)*3^(4)=3^(x+1);
3^(6)=3^(x+1);
x+1=6;
x=5;

Like? Yes (1) | No   

Laxmi Venkata Mownika Kurapati   8 years AGO

(sqrt3)^4*(3^4)=(3^x)*3
(3^4)*(3)=(3^x)
3^6=3^x
x=6

Like? Yes (1) | No   

Devendra Marghade   8 years AGO

(Sqrt3)^5*9^2 =(3^x)*(3*Sqrt3)
(Sqrt3)^5*(Sqrt3)^8=(Sqrt3)^2x*(Sqrt3)^3
(Sqrt3)^13 =(Sqrt3)^(2x+3)
So 13=2x+3
x=10/2=5
Option 4)

Like? Yes (1) | No   

vicky mehta   8 years AGO

3*sqrt3*9*9=3^x*3sqrt3
Then
3*3*3*3*3=3^x
Hence
X=5

Like? Yes (1) | No   

Shikhar Awasthi   8 years AGO

(√3)^5*9^2=3^x*3(√3)
(√3)^4*9^2=3^x*3
9*9*9=3^x*3
3^5=3^x
By comparing
X=5

Like? Yes (1) | No   

Vibhay Thakur   8 years AGO

--(Sqrt3)^5*(9^2)=(3^x)*(3*Sqrt3)

--(Sqrt3)*(Sqrt3)*(Sqrt3)*(Sqrt3)*(Sqrt3)*(9^2)=(3^x)*(3*Sqrt3)

--(Sqrt3)*(Sqrt3)*(Sqrt3)*(Sqrt3)*(9^2)=(3^x)*(3)

--9*(9^2)=(3^x)*(3)

--3*(81)=3^x

--3*3*3*3*3=3^x

--3^5=3^x
--x=5

Like? Yes (1) | No   

Ankur Chaurasia   8 years AGO

3^(5/2) * 3^4 = 3^x * 3^(3/2)
hence 13/2 = (2*x+3)/2
therefore 2*x+3 = 13
so x=5

Like? Yes (1) | No   

Mrs.Thangaraj   8 years AGO

(3^1/2)^5 * (3^2)^2=3^x*3^1*3^1/2
Apply the rule (a^x)^y = a^xy
3^5/2*3^4=3^x*3^1*3^1/2
Apply the rule a^x*a^y=a^(x+y)
3^(5/2+4)=3^(x+1+1/2)
5/2+4=x+1+1/2
(5+8)/2=(2x+2+1)/2
13=2x+3
2x=10
X=5

Like? Yes (1) | No   

Parag Wagh   8 years AGO

(3*sqrt3)*3*3*3*3*3=(3^x)*(3*sqrt3)
3^5 = 3^x
x = 5

Like? Yes (1) | No   

karnatakam.Jaswanth kumar   8 years AGO

Split the square roots and compare the square root terms and non sqaue root terms on both sides

Like? Yes (1) | No   

Rishu   8 years AGO

((sqrt3)^5)*(9^2)=(3^x)*3*(sqrt3)
((sqrt3)^4)*(9^2)=3^(x+1)
9*(9^2)=3^(x+1)
9^3=3^(x+1)
3^6=3^(x+1)
since bases are same
6=x+1
x=5

Like? Yes (1) | No   

monu kumar   8 years AGO

3^(5/2+4)
=3^(x+1+/2)
SO x=5

Like? Yes (1) | No   

divya   8 years AGO

by solving the given equation we get
3^6=3^x*3
so 6=x+1
x=5

Like? Yes (1) | No   

Saleel Kulkarni   8 years AGO

3^5/2*3^4=3^x*3^3/2
3^5=3^x
Taking logarithm on both sides
5log3=xlog3
i.e. x=5
Option 4

Like? Yes (1) | No   

Vijay H   8 years AGO

convert to 3 powers, and equate the powers and solve for x.
equated equation will be (5/2)+4 = x+(3/2)

Like? Yes (1) | No   

Behara Avinash   8 years AGO

All the bases should be converted into 3 and if bases all are equal power should be added then we get answer as 5.

Like? Yes (1) | No   

Gaurab Kumar Jha   8 years AGO

A/Q 9*sqrt 3 * 81 = 3^x * 3 * sqrt 3
81 * 3 = 3 ^ x
3 ^ 5 = 3 ^ x
therefore x = 5 i,e option 4 .

Like? Yes (1) | No   

Pradeepta Chattopadhyay   8 years AGO

9=(sqrt3)^4
so LHS = (sqrt3)^13
RHS=(sqrt3)^(3+2x)
therefore, 3+2x=13
thus x=5...

Like? Yes (1) | No   

29 Jan 2016 Mixture

A shopkeeper buys two kinds of tea, the price of the first kind being twice that of the second. He sells the mixture at Rs.17.50 per kg, thereby making a profit of 25%. If the ratio of first and second kinds of tea in the mixture be 2:3, find the cost price of each kind of tea.

OPtion

1) Rs.30 per kg and Rs.15 per kg
2) Rs.20 per kg and Rs.20 per kg
3) Rs.25 per kg and Rs.45 per kg
4) Rs.40 per kg and Rs.15 per kg
5) Rs.60 per kg and Rs.30 per kg
6) Rs.28 per kg and Rs.14 per kg
7) Rs.50 per kg and Rs.25 per kg
8) Rs.44 per kg and Rs.22 per kg
9) Rs.20 per kg and Rs.10 per kg
10)Rs.40 per kg and Rs.20 per kg

Solution

In 1 kg of mixture
tea of 1st kind = 2/5 kg
and tea of 2nd kind = 3/5 kg
Le the price of first kind of tea be Rs.x per kg.
Then, price of second kind = Rs.(x/2) per kg
Therefore Price of 1 kg mix = Rs.(2x/5 + 3x/10) = Rs.(7x/10)
But C.P. of mix per kg = Rs.(17.50*100 / 125) = Rs.14
Therefore 7x/10=14
then find x

Option 9) Rs.20 per kg and Rs.10 per kg

Correct Option: 9 Best Solution (15)

SHUBHAM   8 years AGO

using the method of alligations.
let price of first item be 2*X and price of second item b X.also the mixture is sold at the rate of 17.5 per kg with a profit of 25%.
thus price per kg would be Rs 14.
now framing the equations,
(x-14)/(14-2*X)=(2/3).
solving for X we get, X=10,hence the prices are 20,10
option...(9).

Like? Yes (17) | No (4)  

Prakash Panda   8 years AGO

125%=17.5
100%=14

now we know the ratio is 2:3 i.e
40%:60%

now check the option which gives u the xact 14 with the sum of 40 n 60% of 2 kind of tea.

40% of 20 is 8
60% of 10 is 6

Like? Yes (3) | No (1)  

Devendra Marghade   8 years AGO

If CP of 1st kind of tea=2x & 2nd kind of tea=x,
As on selling at Rs. 17.5 per kg. he gets profit of 25%, so his CP/kg must be 17.5*100/125=14 Rs.
If he takes 2y & 3y of these two kinds of tea respectively, then [(2x*2y)+(x*3y)]/((2y+3y)= 14 or 7xy/5y=14, x=10, So 2x=20
Option 9)

Like? Yes (2) | No (1)  

Gaurab Kumar Jha   8 years AGO

cp= (100/125)*17.50 =14
and by checking it on options we will find option 9 will be correct

Like? Yes (3) | No (2)  

Ram Kumar Prajapati   8 years AGO

Let Tea1 has cp= 2x and Tea2=x
cp of mixture= 17.5/125% = 14
Using allegation:
(14-x)/(2x-14)= 2/3
we get 2x=20 and x=10

Like? Yes (1) | No (1)  

Ravi P   8 years AGO

given 125%=17.5->100%=14
let first kinb be "x" and seconb be "Y"
given ratio x:y=2:3
so total 2+3=5 parts
-> (x*2/5)+)y*3/5)=15
we know x=2y;
->4y/5+3y/5=14;
y=14*5/7
y=10;
so x=20;
option 9

Like? Yes (1) | No (1)  

Richa Jain   8 years AGO

S.P of mixture=Rs 17.50/kg
P=25%
So, C.P of mixture= Rs 14/kg
T1/T2= (T2-14)/(14-2T2)
2/3= (T2-14)/(14-2T2)
T2= Rs 10/kg
T1=2T2= Rs 20/kg

Like? Yes (1) | No (1)  

suryakant singh   8 years AGO

selling price on the profit of 25% =17.50
cost price of mixture =14
then if price of second type = x
then frst type =2x
(x-14)/(14-2x)=2/3
hence,x=10 then 2x=20
answer is 20 and 10

Like? Yes (1) | No (1)  

Nazmul Hasan   8 years AGO

S.P. @ 17.50 with 25% profit, i.e, CP=14.
now, .4*2x+.6*x=14
thus, a=10.
so CP of 1st & 2nd kind will be 20 & 10.

Like? Yes (2) | No (2)  

harsh dhir   8 years AGO

let the tea be in ratio=2x and 3x
total quantity=5 x
S.P. of one kg=Rs.17.50
Total S.P.=17.50*5=Rs.87.50
Profit=25 %
C.P.=87.50/125 *100=Rs.70
Since the cp of 1st kind of tea is twice the second,
4x+3x=70
x=10
Therefore CP of 1st tea=Rs.20
Cp of 2nd Tea=Rs.10

Like? Yes (1) | No (1)  

GOURANGA SUNDAR MANDAL   8 years AGO

lex he buys 2x kg first kind tea and 3x kg second kind of tea.
And the price of the first kind of tea is 2y RS.per kg and second kind is y RS. per kg.
so the total cost =(2x*2y +3x*y)
making cost of per kg is=(2x*2y +3x*y)/(2x+3x)
according to qus {(2x*2y +3x*y)/(2x+3x)} *125/100=17.50
calculating this equ ..we get y 10, and 2y=20...
so option 9 is correct answer

Like? Yes (1) | No (1)  

pramit   8 years AGO

let prices of A and B be 2x and x
weights be 2/5 kgs and 3/5 kgs
cp=2/5*2x+3/5*x=7x/5
profit=25%0f 7x/5
sp=17.50
7x/5+25%of7x/5=17.50
x=10
2x=20

Like? Yes (1) | No (1)  

sachin sawant   8 years AGO

SP=17.50
SP=(1+25/100)*CP
17.50=125/100*CP
CP of mixture=14
let CP of first tea be 2x&CP of second tea be x
Hence CP of mixture=2x*2+x*3/2+3
Hence 14=7x/5
x=10& 2x=20
CP of first tea=20
CP= of second tea=10

Like? Yes (1) | No (1)  

Rajani P C   8 years AGO

125% --- 17.50
100%----14
2x x
/
14
/
x-14. 14-2x

x-14. 2
------ = --- then x=10 and 2x=20
14-2x 3

Like? Yes (1) | No (1)  

Abhineet kumar   8 years AGO

let the price of second kind tea is x
so cost price of first kind is 2x
sell price is 17.50 at 25% profit
so cost price is (100/125)*17.50=14
from the rule of alligation and mixture
(2x-14/14-x)=2/3
x=10
and is 20,10

Like? Yes (4) | No (5)  

28 Jan 2016 Mixture

A container contains 80 kg. of milk. From this container, 8 kg. of milk was taken out and replaced by water. This process was further repeated two times. How much milk is now contained by the container?

OPtion

1) 56.55 kg
2) 50.50 kg
3) 46.80 kg
4) 58.34 kg
5) 62.86 kg
6) 72.4 kg
7) 64.40 kg
8) 62.24 kg
9) 54.38 kg
10)None of these

Solution

By using - Amount of liquid left after n operation, when the container originally contains x units of liquid, from which y units is taken out each time is
x ( 1 - y/x)^n units
Amount of milk left
80 (1 -1 8/80)^3 kg = 58.34 kg
Option 4)

Correct Option: 4 Best Solution (4)

Abhishek   8 years AGO

Total milk taken out in 3 such operations
80 ( 1 - 8/80 )^3 = 80 * 9 /10 * 9/10 * 9/10 = 58.32 ~ 58.34Kg

Like? Yes (17) | No (2)  

Devendra Marghade   8 years AGO

After 3 successive replacement of 8 kg or 1/10 th of mixture with replacement, out of 80 kg. milk remained=80[1-(1/10)]^3=80* (9/10)^3=80*0.9^3=80*0.729=58.32
Nearest option 4)

Like? Yes (8) | No (1)  

Bhaskar Karmakar   8 years AGO

Starting with milk 80 kg and water 0 kg
After first, 72 and 8
After second 64.8 and 15.2
After third 58.34 and 21.66

Like? Yes (18) | No (14)  

lakshman   8 years AGO

X ( 1-y/x)^n
X------total quantity
Y-------taken out quantity
N-----no.of operaions

Like? Yes (3) | No (5)