M4maths Previous Puzzles

22 Apr 2015 Number of Sunday

If 1st Jan is Tuesday in a year then number of Sunday between 4th March to 20 September of the same year are

OPtion

1) 18
2) 20
3) 22
4) 24
5) 25
6) 27
7) 28
8) 30
9) 32
10)33

Solution

Total number of days between 4th March to 20th September = 199
(Where 3rd March and 22nd September are Sunday)
So number of weeks = 199/7 = 28.4
so 28 Sunday

Option 7)

Correct Option: 7 Best Solution (12)

Supriya Mondal   9 years AGO

Number of Sundays(between 4th March to 20th September) in
March-4
April-4
May-4
June-5
July-4
August-4
September-3
So, total number of Sundays is=4+4+4+5+4+4+3=28
So, option 7)28 is the right answer

Like? Yes (10) | No (4)  

Abhishek Ranjan   9 years AGO

count total no of Sundays. .. its 28

Like? Yes (2) | No   

SAGNIK DATTA   9 years AGO

plotting the week of day 1 and counting number of sundays

Like? Yes (2) | No   

SUSHANT KUMAR   9 years AGO

mar-4
apr-4
may-4
june-5
july-4
aug-4
sep-3
so total 28

Like? Yes (1) | No   

Neha Shahi   9 years AGO

No of days b/w 1st jan and 4th march =30+28+4 = 62 days = 8 weeks and 6 days ( since, 62/7 = 8 weeks and 6 days)
so, 4th march is Monday.
now, no of days between 4th march and 20th September = 27 +30 + 31 + 30 + 31 + 31 + 20 = 200 days = 28 weeks and 4 days
so, 2oth September is Friday....
in 28 weeks we have 28 sundays...
ans = option: 7 i.e 28 sundays

Like? Yes (6) | No (5)  

sompon temtheerakij   9 years AGO

1st Jan is Tuesday
4th March is Monday
10th March is Sunday
days from 4th March to 20 Sept
= 22+30+31+30+31+31+20 = 195 days
no. of Sunday = 195/7 = 27+1 =28

Like? Yes (1) | No   

vibhu raj gupta   9 years AGO

from ques.. we get 3rd march is sunday, not count it and add 7 in it till 20 sep. we get 28 sundays.....

Like? Yes (1) | No   

Vaibhav Srivastava   9 years AGO

10,17,24,31,7,14,21,28,5,12,19,26,2,9,16,23,30,7,14,21,28,4,11,18,25,1,8,15

Like? Yes (1) | No   

santosh kumar patel   9 years AGO

every month 4 sunday
total month=7
so total sunday b/w month= 7*4=28

Like? Yes (3) | No (3)  

Stoycho   9 years AGO

from 4 March to 20 Sep are 201 days
201/7=28.714
=> 28 weeks and 5days

Like? Yes (2) | No (2)  

kishore   9 years AGO

I've considered the year as non-leap year.so if we calculate 4th march is tuesday and then b/w 4th march and sept 2o we have 200 days divide it by 7 then we get 28 and remainder as 4.that means we have 28 weeks and 4 days.so 28 sundays + in that remain 4 days we don't have sunday as our week start with tuesday

Like? Yes (1) | No (2)  

ABHINAV PUSHPAM   9 years AGO

counted in year 2019.. in this year 1st Jan is Tuesday..

Like? Yes (1) | No (5)  

21 Apr 2015 Percentage

16% of 16% of 16% of ............... < 1
Minimum number of 16, which can be used in the following inequality, are

OPtion

1) 2
2) 3
3) 4
4) 5
5) 6
6) 7
7) 8
8) 9
9) 10
10)11

Solution

16% of 16 = 2.56
16% of 2.56 = 0.4096
So 3 are sufficient
16% of 16% of 16 = 0.4096

Option 2)

Correct Option: 2 Best Solution (10)

Supriya Mondal   9 years AGO

Here 3 16 are needed.
16% of 16=2.56
16% of 2.56=0.4096
So, minimum 3 16 are needed to fulfill the above condition
So, option 2)3 is the right answer

Like? Yes (7) | No (3)  

Keshav Kishlay   9 years AGO

16*16/100*16/100=0.4096

Like? Yes (1) | No   

Madhumoy Gope   9 years AGO

16% of 16% of 16~=0.4

Like? Yes (1) | No   

sreenivasa reddy   9 years AGO

16%16=2.56then anther 16% becomes lessthan 1

Like? Yes (1) | No   

shareef   9 years AGO

16*.16*.16 = .4096 < 1 so 3

Like? Yes (1) | No   

shaweta   9 years AGO

.16*.16*.16*2=0.008192

Like? Yes (1) | No   

ved   9 years AGO

16%of 16 =2.56 and 16 % of this 2.56 = 0.4 which is

Like? Yes (1) | No (2)  

moumita   9 years AGO

((16% of 16)% of 16)% of 100 = 0.4096

Like? Yes (1) | No (2)  

NITHYA   9 years AGO

=16/100*16/100
=0.32

Like? Yes (1) | No (2)  

POOJA SINGH   9 years AGO

16%of16%of16=0.4096
so minimum no. of 16 reqd is 3

Like? Yes (1) | No (2)  

20 Apr 2015 Suitable word

Which of the following number is most suitable for the word "CLIMATE"

OPtion

1) 48
2) 51
3) 52
4) 55
5) 58
6) 60
7) 63
8) 65
9) 67
10)72

Solution

CLIMATE
3+12+9+13+1+20+5 = 63

Option 7)

Correct Option: 7 Best Solution (61)

MD SOHAIL AKHTER   9 years AGO

A=1..........Z=26
similarly
climate =63

Like? Yes (1) | No   

kranthi kanchanapally   9 years AGO

c--->3
L--->12
I--->9
M--->13
A--->1
T--->20
E--->5
3+12+9+13+1+20+5=63
option 7 is correct

Like? Yes (1) | No   

Supriya Mondal   9 years AGO

A is the 1st number, B is the 2nd number, C is the 3rd number,......., Z is the 26th number
So, here
C=3
L=12
I=9
M=13
A=1
T=20
E=5
So, sum of this is=3+12+9+13+1+20+5=63
So, option 7)63 is the right answer

Like? Yes (4) | No (3)  

Vaibhav Srivastava   9 years AGO

C-> 3
L -> 12
I -> 9
M -> 13
A -> 1
T -> 20
E -> 5

Like? Yes (2) | No (1)  

moumita   9 years AGO

If we consider A=1, B=2, C=3,........ and so on..
Then, C=3
L=12
I=9
M=13
A=1
T=20
E=5
sum of "CLIMATE" i.e, 3+12+9+13+1+20+5 =63
Ans (7)

Like? Yes (2) | No (1)  

sompon temtheerakij   9 years AGO

c=3
l=12
i=9
m=13
a=1
t=20
e=5

Like? Yes (1) | No   

PASPULETI SAHITHI REDDY   9 years AGO

c+l+i+m+a+t+e=3+12+9+13+1+20+5

Like? Yes (1) | No   

vibhu raj gupta   9 years AGO

sum of the corresonding position in albhabet.

Like? Yes (1) | No   

suraj kumar   9 years AGO

c=3,l=12,i=9,m=13,a=1,t=20,e=5, 3+12+9+13+1+20+5=63

Like? Yes (1) | No   

ramesh   9 years AGO

the value of each word holds the total of 63.

Like? Yes (1) | No   

sailaja   9 years AGO

sum of letters numbers of the word

Like? Yes (1) | No   

sandeep kumar dash   9 years AGO

as per the alphabate serial num
C=3
L=12
I=9
M=13
A=1
T=20
E=5
IF WE ADD ALL THESE THEN WE GET
C+L+I+M+A+T+E=
3+12+9+13+1+20+5=63

Like? Yes (1) | No   

SUSHANT KUMAR   9 years AGO

C=3
L=12
I=9
M=13
A=1
T=20
E=5
TOTAL=63

Like? Yes (1) | No   

vivek   9 years AGO

climate= 3+12+9+13+1+20+5=63

Like? Yes (1) | No   

pulkit   9 years AGO

just add up all the alphabets as c=3 L=12.....

Like? Yes (1) | No   

SAMRIDHI GIRI   9 years AGO

3+12+9+13+1+20+5=63

Like? Yes (1) | No   

Subrata Sadhukhan   9 years AGO

c-3, l-12, i-9, m-13, a-1, t-20,e-5
3+12+9+13+1+20+5=63

Like? Yes (1) | No   

sai   9 years AGO

sum of all character

Like? Yes (1) | No   

MRITUNJAY   9 years AGO

c=3,l=12,i=9,m=13,a=1,t=20,e=5
add together we get
63

Like? Yes (1) | No   

sudhakar   9 years AGO

answer 63

Like? Yes (1) | No   

nitish sahoo   9 years AGO

add the position of the letters in the alphabate

Like? Yes (1) | No   

M.Nivetha    9 years AGO

summing up the corresponding alphabet's numerical position will gve 63 i.e,3+12+9+13+1+20+5=63

Like? Yes (1) | No   

konanki keerthi   9 years AGO

it is number of words and all numbers are added

Like? Yes (1) | No   

anwesha oraon   9 years AGO

c=3
l=12
i=9
m=13
a=1
t=20
e=5
so 3+12+9+13+1+20+5=63

Like? Yes (1) | No   

RAKESH   9 years AGO

CLIMATE = 3+12+9+13+1+20+5 = 63

Like? Yes (1) | No (1)  

susmit   9 years AGO

taking A= 1 B= 2 ETC
WE GET THE TOTAL 63

Like? Yes (1) | No (1)  

ABHINAV PUSHPAM   9 years AGO

3+12+9+13+1+20+5=63
Option 7)

Like? Yes (2) | No (2)  

Neha Shahi   9 years AGO

C+L+I+M+A+T+E=3+12+9+13+1+20+5=63

Like? Yes (3) | No (3)  

shareef   9 years AGO

c+l+i+m+a+t+e = 3+12+9+13+1+20+5 = 63

Like? Yes (2) | No (2)  

Meenakshi   9 years AGO

Give numbers to alphabets like A=1,B=2,C=3...and so on
The most suitable number for the word climate is
-> 3+12+9+13+1+20+5
->63

Like? Yes (1) | No (1)  

shabana banu shaik   9 years AGO

give numbering for alphabets from 1 to 26......for climate the numbers are 3,12,9,13,1,20,5 and the sum of numbers is 3+12+9+13+1+20+5=63

Like? Yes (1) | No (1)  

mukund   9 years AGO

3+12+9+13+20+6=63

Like? Yes (1) | No (1)  

umesh   9 years AGO

CLIMATE=3+12+9+13+1+20+5
63 ans.

Like? Yes (1) | No (1)  

Devendra Marghade   9 years AGO

Taking the sum of the digits corresponding to letters of the word,
C+L+I+M+A+T+E=3+12+9+13+1+20+5=63

Like? Yes (1) | No (1)  

aman aditya   9 years AGO

3+12+9+13+1+20+5=63

Like? Yes (1) | No (1)  

Sundar Kumar   9 years AGO

A (1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25), Z(26).
C L I M A T E = 3 | 12 | 9 |13 |1|20 |5
Add all the Values = 3+12+9+13+1+20+5
=63
Answer: Option 7) 63

Like? Yes (2) | No (2)  

NITHYA   9 years AGO

sum of their positions in english alphabet

Like? Yes (1) | No (1)  

Samyak   9 years AGO

The sum of the no respected to letters like a-1, b-2.. so on. Thats the sum will be 63.

Like? Yes (2) | No (2)  

Yathiraj   9 years AGO

Take A=1, B=2, C=3... Z=26
Sum up all the numbers for letters CLIMATE
3+12+9+13+1+20+5 = 63

Option 7.

Like? Yes (2) | No (2)  

Satya B   9 years AGO

CLIMATE = 3+12+9+13+1+20+5 =63

Like? Yes (1) | No (1)  

sangrambadi sahoo   9 years AGO

climate=3+12+9+13+1+20+5

Like? Yes (1) | No (1)  

sindhura   9 years AGO

climate=3+12+9+13+1+20+5=63

Like? Yes (1) | No (1)  

jalaj   9 years AGO

by numbering each letter and adding it we get 63
C(3)+L(12)+....etc=63

Like? Yes (1) | No (1)  

ADARSH GAURAV   9 years AGO

63 is the answer

Like? Yes (1) | No (1)  

GUDDETI ANUPAMA   9 years AGO

in a alphabets 1 to 26 numbers each alphabet has one number
so CLIMATE=3+12+9+13+1+20+5=63

Like? Yes (1) | No (1)  

shaik sharina   9 years AGO

1 to 26 no are alloted to a to z and sum them all get the ans 63

Like? Yes (1) | No (1)  

Stoycho   9 years AGO

1-a; 2-b; 3-c; 4-d; 5-e; 6-f; 7-g; 8-h; 9-i; 10-j; 11-k; 12-l; 13-m; 14-n; 15-o; 16-p; 17-q; 18-r; 19-s; 20-t; 21-u; 22-v; 23-w; 24-x; 25-y; 26-z.
=> climate = 3+12+9+13+1+20+5 = 63

Like? Yes (1) | No (1)  

Santhosh S   9 years AGO

c=3, l=12, i=9,...... so the ans is 63

Like? Yes (1) | No (1)  

Meena V   9 years AGO

CLIMATE= 3+12+9+13+1+20+5
(3,12,9,13,1,20,5)- these are the number of the alphabets.

Like? Yes (1) | No (1)  

Math Lovers   9 years AGO

Take
A=1
B=2
.
.
.
Z=26
so,
CLIMATE = 3+12+9+13+1+20+5 =63

Like? Yes (1) | No (1)  

LOKESH KUMAR   9 years AGO

C=3;L=12;I=9;M=13;A=1;T=20;E=5;
C+L+I+M+A+T+E=3+12+9+13+1+20+5=63

Like? Yes (1) | No (1)  

Chandu Priya Nelakuduru   9 years AGO

the sum of these letters is 63

Like? Yes (1) | No (1)  

himanshu   9 years AGO

CLIMATE = 3+12+9+13+1+20+5= 63

Like? Yes (1) | No (1)  

prabhat kumar   9 years AGO

c+l+i +m+a+t+e
3 +12 +9+ 13 +1+ 20 +5=63

Like? Yes (1) | No (1)  

K.Narthana   9 years AGO

c is 3,L is 12,I is 9...................

Like? Yes (1) | No (1)  

Meghna Ramesh   9 years AGO

3+12+9+13+1+20+5=63

Like? Yes (1) | No (1)  

Harsh jain   9 years AGO

every alphabet has a corresponding numeric value add these values and we get the final answer

Like? Yes (1) | No (1)  

Sushree Manisha Sahoo   9 years AGO

3+12+9+13+1+20+5 = 63

Like? Yes (1) | No (1)  

siddharth prakash singh   9 years AGO

most suitable number for climate would be the sum of all individual nos corresponding to each alphabet's position.
so for CLIMATE we have=3+12+9+13+1+20+5=63

Like? Yes (1) | No (1)  

Mohanraj K   9 years AGO

Take A=1 and for same make for 26 alphabets

C+L+I+M+A+T+E=3+12+9+13+1+20+5=63 so option is 7

Like? Yes (1) | No (1)  

Surit Datta   9 years AGO

A is the 1st number
B is the second number
.......
Z is the 26 th number
So according to this calculate the total number
and get the answer 63
so option 7
that's it.

Like? Yes (3) | No (4)  

17 Apr 2015 Probability

12 identical balls are put on 3 identical boxes. Probability that one of the box has exactly 3 balls.

OPtion

1) 5/12
2) 4/12
3) 5/17
4) 4/17
5) 5/19
6) 4/19
7) 5/21
8) 4/21
9) 4/11
10)5/11

Solution

Possible cases are
0,0,12 ----- 1,1,10 ----- 2,2,8 ----- 3,3,6 ----- 4,4,4
0,1,11 ----- 1,2,9 ------ 2,3,7 ----- 3,4,5
0,2,10 ----- 1,3,8 ------ 2,4,6 -----
0,3,9 ------ 1,4,7 ------ 2,5,5 -----
0,4,8 ------ 1,5,6 ------
0,5,7 ------
0,6,6 ------

Option 5)

Correct Option: 5 Best Solution (5)

Sundar Kumar   9 years AGO

Probability that one of the box has exactly 3 balls:::
3 0 9 3 1 8 3 2 7 3 3 6 3 4 5
Therefore, one of the box has exactly 3 balls =5

Total probability for 12 balls = 19
0 0 12 1 1 10 2 2 8 3 3 6 4 4 4
0 1 11 1 2 9 2 3 7 3 4 5
0 2 10 1 3 8 2 4 6
0 3 9 1 4 7 2 5 5
0 4 8 1 5 6
0 5 7
0 6 6
Therefore Answer: Option 5) 5/19

Like? Yes (8) | No (3)  

PASPULETI SAHITHI REDDY   9 years AGO

if we put 3 in to one boxthen remaining 9 we must put in 2 boxes so
3 0 9
3 1 8
3 27
3 3 6
3 4 5 remaining 3 5 4 ....is not possible because boxes are identical
and without condition 12 balls in 3 boxes can be put in 19 ways i.e 0 0 12 1 1 10 2 2 8 3 3 6 4 4 4
0 1 11 1 2 9 2 3 7 3 4 5
0 2 10 1 3 8 2 4 6
0 3 9 1 4 7 2 5 5
0 4 8 1 5 6
0 5 7
0 6 6 therfore ans is 5/19

Like? Yes (1) | No   

sompon temtheerakij   9 years AGO

All possible arrangements are
0 0 12 , 0 1 11 , 0 2 10 , 0 3 9 , 0 4 8 , 0 5 7 , 0 6 6
1 1 10 , 1 2 9 , 1 3 8 , 1 4 7 , 1 5 6 ,
2 2 8 , 2 3 7 , 2 4 6 , 2 5 5 ,
3 3 6 , 3 4 5 ,
4 4 4
= 5 /19

Like? Yes (1) | No   

Math Lovers   9 years AGO

All Possible arrangements are - 19
which are below
0 0 12
0 1 11
0 2 10
0 3 09
0 4 08
0 5 07
0 6 06
1 1 10
1 2 09
1 3 08
1 4 07
1 5 06
2 2 08
2 3 07
2 4 06
2 5 05
3 3 06
3 4 05
4 4 04
out of these 19 possibility, in only 5 possibility at least one bad contains exactly 3 balls.

0 3 09

1 3 08

2 3 07

3 3 06

3 4 05


so probab. = 5/19

Like? Yes (3) | No (3)  

Srinivas   9 years AGO

total out comes = 19
box having 3 balls = 5

0 3 9
1 3 8
2 3 7
3 3 6
4 3 5

Like? Yes (2) | No (3)  

16 Apr 2015 Number of bricks

The outer dimensions of a cubical room are 8m*6m*4m and inner dimension are 7.8m*5.8m*4m (roof is not included in the dimension). If the size of brick used (including cement) are 20cm*10cm*8cm, then number of bricks used to construct wall will be

OPtion

1) 7100
2) 6800
3) 6900
4) 6400
5) 6700
6) 5700
7) 6200
8) 6500
9) 7300
10)7500

Solution

Total volume = 8*6*4 = 192 m^3
Total inner volume = 7.8*5.8*4 = 180.96 m^3
So volume of bricks = 192-180.96 m^3
= 11.04 m^3
Number of bricks
11.04 / .2*.1*.08
= 110400/16 = 6900
Option 3)

Correct Option: 3 Best Solution (14)

SAURABH KUMAR SINHA   9 years AGO

Empty Volume=800*600*400-780*580*400=11040000

no of bricks=11040000÷(20*10*8)=6900 ANS..

Like? Yes (7) | No (3)  

Supriya Mondal   9 years AGO

Volume of the room respect to outer dimension is=8*6*4=192 m^3
And volume of the room respect to inner dimension is=7.8*5.8*4=180.96 m^3
So, difference between two volumes=192-180.96=11.04 m^3
Volume of each brick is=0.2*0.1*0.08=1.6*10^-3 m^3
So, numbers of bricks needed=(11.04/1.6)*10^3=6900
So, option 3)6900 is the right answer

Like? Yes (3) | No   

MRITUNJAY   9 years AGO

volume of cubical room=External -internal
=8*6*4-7.8*5.8*4=11.04m^3=11040000cm^3
volume of 1 brick=20*10*8=1600 cm^3
number of bricks=11040000/1600=6900

Like? Yes (2) | No   

Yathiraj   9 years AGO

Height of the Brick = 8cm
Height of the walls = 4m => 400cm
Hence, no. of lines of bricks required in all the 4 walls = 400/8 => 50 lines

If the inner dimension between the walls is less by 0.2m then brick thickness on each wall will be 0.1m => 10cm
Hence, the bricks will be layed down along 20cm for each wall.

2 walls of 6m => 600cm
No. of bricks per line => 600/20 => 30
Hence, no. of bricks on one wall = 30x50 => 1500. For 2 such walls => 1500*2 => 3000 ---- 1

2 other walls 7.8m (less brick on either sides) => 780m
no. of bricks per line => 780/20 => 39
Hence, no. of bricks on one wall = 39x50 => 1950. For 2 such walls => 1950*2 => 3900 ----- 2

1 + 2 => 3000 + 3900 => 6900

Option 3)

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sompon temtheerakij   9 years AGO

2*(40+29)*50 = 6900

Like? Yes (1) | No   

syed kashif ullah   9 years AGO

volume of outer - volume of inner= volume of bricks
volume of bricks = 8*6*4- 7.8*5.8*4
number of brucks = volume of bricks/volume of one brick=6900...0option 3.)

Like? Yes (1) | No   

Nandha kumar   9 years AGO

The volume of outer dimension is 192000000.
The volume of inner dimension is 180960000.
The difference between them is 11040000.
The volume of brick is 1600.
Dividing 11040000 by 1600 the ans is 6900.
Thus the no.of bricks used to construct the wall is 6900.
The answer is option 3)6900.

Like? Yes (1) | No   

Mohanraj K   9 years AGO

outer volume of cube=8*6*4=192 cum
inner volume of cube =7.8*5.8*4=180.96 cum

The volume of cube occupied by brick=192-180.96=11.04 cum
volume of single brick=0.2*0.1*0.08=0.0016 cum
So,number of bricks =0.0016*X=11.04cum
so X=6900(option 3)

Like? Yes (1) | No   

kranthi kanchanapally   9 years AGO

The outer volume is=8*6*4=192m^3
inner volume is=7.8*5.8*4=180.96m^3
then the volume is=11.04m^3
the size of the bricks is=20*10*8=1600
THen the total number of bricks used in a wall is=
volume of the room/volume of the brick
11040000/1600=6900

Like? Yes (1) | No   

Paresh   9 years AGO

Volume of outer dimensions=800*600*400
Volume of inner dimensions=780*580*400
net volume=outer-inner
no of bricks=(800*600*400)-(780*580*400)/20*10*8=6900

Like? Yes (1) | No   

vivek   9 years AGO

(outer volume- inner volume)/ volume of brick= 11040000/1600=6900

Like? Yes (1) | No   

sanjeet   9 years AGO

Total volume of WAll (in cm)=(800*600*400) - (780*580*400)
=11040000 cm^3
total volume of bricks= 20*10*8=1600 cm^3
so total number of bricks require for building=11040000/1600=6900

Like? Yes (2) | No (2)  

aman aditya   9 years AGO

11040000/(20*10*8)= 6900

Like? Yes (1) | No (1)  

sangrambadi sahoo   9 years AGO

800*600*400)-780*580*400)/1600=6900

Like? Yes (1) | No (1)  

15 Apr 2015 Rank of word

Rank of word RIDER in the dictionary of words formed by letter of the word RIDER taken all 5 letter at a time

OPtion

1) 36
2) 38
3) 42
4) 44
5) 46
6) 49
7) 50
8) 51
9) 53
10)54

Solution

=Total possible words = 5*4*3*2*1/2*1 = 60
Arranged order of letters is
D E I R R
So rank of RIDER
= 60/5 *3 + 12*2/4 *2 + 6/3*0 + 2/2*0 + 1
= 36 + 12 + 0 + 0 + 1
= 49
Option 6)

Correct Option: 6 Best Solution (23)

ABHINAV PUSHPAM   9 years AGO

By the theory of permutation, arranging the letter in alphabetical order, total no. of letters made from D =4!/2!=12,same for E &I,total no. of words made from D,E,I=12*3=36.
Now fixing R in the first place,no. of letters having RD and RE=3!*2=12.
Total no. of words before RIDER=36+12=48,
.'.RIDER will be at 49th place.
Hence, option 6) is the right answer.

Like? Yes (10) | No (1)  

Supriya Mondal   9 years AGO

Word starting with D has 4!/2!=12 combinations
Word starting with E has 4!/2!=12 combinations
Word starting with I has 4!/2!=12 combinations
Word starting with RD has 3!=6 combinations
Word starting with RE has 3!=6 combinations
Then the word comes RIDER
So, it's rank will be=12+12+12+6+6+1=49
So, option 6)49 is the right answer

Like? Yes (9) | No   

Amit Bansal   9 years AGO

D_ _ _ _ it will be starting from D.Now we have to fill up 4 positions after D.so it would be (!4/!2).I'm dividing factorial 2 because R is given two times.
So D_ _ _ _=!4/!2=>12.
Same thing goes for E_ _ _ _=>12.
Same thing goes for I _ _ _ _=>12.
Now when it comes on R _ _ _ _. for the 2nd position it would be like this.R D E I R(for the first word starting from R).R D _ _ _.now for remaining three condition !3=6
When R E _ _ _. then remaining condition will be !3=6.
after this next word will be R I D E R according to alphabet.
Total=12+12+12+6+6+1=>49
So the rank is 49.

Like? Yes (3) | No   

Jay parmar   9 years AGO

3/2!*4! + 2*3! + 0*2! + 0*1! + 0*1 + 1 = 49

Like? Yes (2) | No   

MRITUNJAY   9 years AGO

R I D E R
4 3 1 2 4

3/2! 2 0 0 0
4! 3! 2! 1! 0!

rank of the word rider is 3*2!*4!+2*3!+1=36+12+1=49

Like? Yes (2) | No   

Jaspalsingh Parmar   9 years AGO

option 6 is correct

Like? Yes (1) | No   

MR. X   9 years AGO

d---- 12
e---- 12
i ---- 12
rd--- 6
re--- 6
rider +1
49

Like? Yes (2) | No (1)  

Neha Shahi   9 years AGO

FOR D=4!/2!=12
FOR E=4!/2!=12
FOR I=4!/2!=12
NOW R D _ _ _ =3!=6
THEN R E _ _ _ =3!=6
AND R I D E R=1
TOTAL=12+12+12+6+6+1=49

Like? Yes (1) | No   

syed kashif ullah   9 years AGO

STARTING WITH DICTIONARY ALPHABETS
DE*** ----1 TO 3 WORD (SINCE R IS IDENTICAL HERE THTS WHY ONLY 3 PERMUTATIONS POSSIBLE)
DI***--- 4 TO 6TH END WORD
DR***--- 7 TO 12TH WORD
SIMILARLY ER***---- 13 TO 24TH WORD
IR***---25TH TO 36TH WORD
RD***---37 TO 42ND WORD
RE***---43 TO 48TH WORD
RIDER----49TH WORD
HENCE OPTION 6.)

Like? Yes (1) | No   

shaik sharina   9 years AGO

3*(4!/2)+(2*3!)+1

Like? Yes (1) | No   

Ambica Mehrotra    9 years AGO

Words will be in alphabetical order....
Words starting with d = 4!/2=12
Words starting with e=12
Words starting with I=12
Words starting with rd=3!
Words with re=3!=6
Then acc to alphabetical order rider comes...
So rank of word rider =12+12+12+6+6+1=49

Like? Yes (1) | No   

PAWAN KUMAR   9 years AGO

Rank = 3* 4!/2! + 2*3! + 1 = 36+12+1 = 49. Ans.

Like? Yes (1) | No   

Gourav Rajdhar   9 years AGO

Words starting from d are 12
Words from e 12
Words from i 12
Words from RD are 6
Words from RE are 6
And the last 49th word is RIDER

Like? Yes (1) | No   

sangrambadi sahoo   9 years AGO

the letter starting with d is 4!/2!---12
similarly starting with e is 12
for i also 12
and for starting with rd....6
and for re -----------6
then rider comes...
so total =36+12+1=49

Like? Yes (1) | No   

kranthi kanchanapally   9 years AGO

D E I R R
before R we have 3 letters so 3*4!/2!=36
befor I we have 2 letters so 2*3!=12
then before D and E we dnt have any letters so
36+12+1=49

Like? Yes (1) | No   

Sandeep Kumar   9 years AGO

Acc to alphabetical order......
D,E,I,R,R
(4*3*2*3/2) + (3*2) + 1 = 49

Like? Yes (1) | No   

sanjeet   9 years AGO

arrage in alphabatic order
D E I R R
now
D=>4!/2!=12
E=>4!/2!=12
I=>4!/2!=12
RD=>3!=6
RE=>3!=6
RIDER=1
total=12+12+12+6+6+1=49 ans .

Like? Yes (1) | No   

arya   9 years AGO

option 6

Like? Yes (1) | No   

Srinivas   9 years AGO

it is ans
(3/2!)*4! =2*3! +1=49

Like? Yes (1) | No   

Math Lovers   9 years AGO

Number of words which starts from D = 12
Number of words which starts from E = 12
Number of words which starts from I = 12
Number of words which starts from RD = 12
After RD, words starts from RI and first word is RIDER
so position= 12+12+12+12+1 = 49

Like? Yes (1) | No   

SAURABH KUMAR SINHA   9 years AGO

The answer is 49.
No. of words starting from D=4!/2!
No. of words starting from E=4!/2!
No. of words starting from I=4!/2!
No. of words starting from RD=3!
No. of words starting from RE=3!
The next word will be RIDER.
Thus Rank of RIDERh in the dictionary will be=3*(4!/2!)+2*3!+1=49. ANS.

Like? Yes (1) | No   

aman aditya   9 years AGO

36+6+6+1=49

Like? Yes (1) | No   

anshuman   9 years AGO

ANSWER SHOULD BE : 49


// CODE TO PROVE IT

#include
#include

long fact(int n)
{
long f = 1;
while (n > 0)
{
f *= n;
n--;
}
return f;
}

int find_rank(char s[], int len)
{
long rank = 1;
int i, j, k, l, fr[26], f; //fr is frequency
char sorted[100], cur, t, pre;

for (i = 0; i < len -1 ; ++i)
{
cur = s[i];
strcpy(sorted, s + i);
l = len - i;
memset(fr, 0, sizeof(fr));
fr[sorted[0] - 'a']++;
for (j = 1; j < l; ++j)
{
t = sorted[j];
fr[t-'a']++;
for (k = j-1; k >=0 && sorted[k] > t; --k)
sorted[k+1] = sorted[k];
sorted[k+1] = t;
}
pre = 1;
for (k = 0; sorted[k] != cur ;++k)
{
if (sorted[k] == pre)
continue;
pre = sorted[k];

f = fact(l - 1);
fr[pre - 'a']--;
for (j = 0; j < 26; ++j)
if (fr[j])
f /= fact(fr[j]);
rank += f;
fr[pre - 'a']++;
}
}
return rank;
}

int main()
{
char s[100];

scanf("%s", s);
printf("%d", find_rank(s, strlen(s)));
return 0;
}

Like? Yes (1) | No (1)  

14 Apr 2015 The average age of students

The average age of 20 students is 16. 2 students of ages 17 and 13 leave the group and 2 new of ages 10 and 11 join the group. New average will be.

OPtion

1) 14.25
2) 14.45
3) 14.95
4) 15
5) 15.25
6) 15.55
7) 15.75
8) 15.95
9) 16
10)None of these

Solution

20*16 = 320
Sum of the ages of leaving students = 17+13 = 30
Sum of the ages of joining students = 10+11 = 21
So new sum = 320-30+21 = 311
New avg = 311/20 = 15.55

Option 6)

Correct Option: 6 Best Solution (7)

Supriya Mondal   9 years AGO

Average age of the 20 students is 16
So, total age of the 20 students is=20*16=320
2 students of ages 17 and 13 leaves so total age of 18 students will be=320-17-13=290
Then 2 new students of ages 10 and 11 joins so new total age of 20 students will be=290+10+11=311
So, new average will be=311/20=15.55
So, option 6)15.55 is the right answer

Like? Yes (2) | No   

aman aditya   9 years AGO

16*20=320
320-17-13+10+11=311
311/20=15.55

Like? Yes (1) | No   

kranthi kanchanapally   9 years AGO

sum of age of 20 students id 20*16=320
Two people left the group of ages 17,13 and two are added with ages 10 and 11
So new age is 311
now the avg age is 311/20=15.55

Like? Yes (1) | No   

Samyak   9 years AGO

the average of 20 people is 16 . So total is 320 now substarct 17& 13 & add 10 & 11. So its 311 and divide it by 20. So ans will be 15.55

Like? Yes (1) | No   

MRITUNJAY   9 years AGO

Difference in age of replaced person=30-21=9 years
reduced average=16-9/20=15.55

Like? Yes (1) | No   

prem kishor   9 years AGO

sum of ages of 20 student =320.
after leaving two student from the group remaining sum of 18 students= 290.
after joining of two student the sum of 20 students become = 311.
then,the new average is 311/20 = 15.55

Like? Yes (1) | No   

Josepheena Joseph   9 years AGO

Sum of ages of 20 students = 20*16 = 320
Sum after leaving of 2 students and joining of 2 students
= 320 - (17+13) + (10+11) = 311
Average = 311/20 = 15.55

Like? Yes (1) | No   

13 Apr 2015 Sequence

What is the next number of the following sequence
5/3, 11/4, 19/5, 29/6, 41/7, ?

OPtion

1) 43/8
2) 45/8
3) 47/8
4) 49/8
5) 51/8
6) 53/8
7) 55/8
8) 57/8
9) 59/8
10)61/8

Solution

5/3 = 1 (2/3)
11/4 = 2 (3/4)
19/5 = 3 (4/5)
29/6 = 4 (5/6)
41/7 = 5 (6/7)
Similarly
6 (7/8) = 55/8
Option 7)

Correct Option: 7 Best Solution (11)

Supriya Mondal   9 years AGO

Difference between numerator increasing by 2+difference between previous two numerator.
And difference between two denominator is 1
So, next term will be 55/8
So, option 7)55/8 will be the right answer

Like? Yes (2) | No   

RAKESH   9 years AGO

5,11,19,29,41,55
+6,+8,+10,+12,+14

(41 + 14) / (7 +1) = 55/8

Like? Yes (1) | No   

sourav pal   9 years AGO

Numerator 5, 11, 19, 29, 41, .... so next is 55
Similarly denominator 3, 4, 5, 6,7 ... so next is 8

Like? Yes (1) | No   

Daras rani   9 years AGO

Numerator:
5+6=11
11+8=19
19+10=29
29+12=41
41+14=55
And the denominator gets increased by one..

Like? Yes (1) | No   

praveen kumar   9 years AGO

ans 7 is correct

Like? Yes (1) | No   

Surit Datta   9 years AGO

Here the numerator is increasing by 2,like the following way,
6,8,10,12,14......
and the denominator is increasing by 1 , like
3,4,5,6,7,8.....
so the next number will be,
41 + 14 / 7 + 1 = 55/8
So option 7
That's it.

Like? Yes (1) | No   

umesh   9 years AGO

the denominator is increasing by 1
and numerator difference is increasing by 2
so 7 is right
11-5=6,19-11=8,29-19=10,41-29=12 so 41+14=55 numertor
and denominator is 8

Like? Yes (1) | No   

Samyak   9 years AGO

5/3 ,11/4,19/5,.. So in top add 6, 8 , 10, 12 and in the bottom it add 1 like 3,4,5,6.. So the ans will be 55/8

Like? Yes (1) | No   

Jay parmar   9 years AGO

option 7 is right

Like? Yes (1) | No   

Anuj Rai   9 years AGO

As the series denominator is increasing like 2,3,4 and the numerator is increasing with a multiple of 2

Like? Yes (1) | No   

ABHINAV PUSHPAM   9 years AGO

Numerator is increased by 6,8,10,12, so now increment will be 14. I.e 41+14= 55
Denominaor is icreased by 1
So answer will be 55/8
Option 7)

Like? Yes (1) | No   

10 Apr 2015 Percentage

10% of x more than x is what % less than 20% of 2x less than 2x.

OPtion

1) 25%
2) 30%
3) 31.25%
4) 35.5%
5) 39.25%
6) 42%
7) 45%
8) 47.25%
9) 4%
10)49.5%

Solution

10% of x more than x = 1.1 x
20% of 2x less than 2x = 1.6 x
Therefore difference = 0.5 x
So % difference = 0.5x/ 1.6x * 100 = 500/16
= 31.25 %

Option 3)

Correct Option: 3 Best Solution (16)

SUNITEE GARIMA   9 years AGO

let x be 100.
A/q,
100+100*10/100=110
again,
2*100-200*20/100=160

160-110=50
50/160*100=31.25%

Like? Yes (12) | No   

MRITUNJAY   9 years AGO

let x be 100.
100+100*10/100=110
2*100-200*20/100=160

160-110=50
50/160*100=31.25%

Like? Yes (3) | No   

sai   9 years AGO

x= 100
110 is what % less than 160 = 31.25%

Like? Yes (2) | No   

neha   9 years AGO

10% of x+x= 110*x/100
and 2x-20% of 2x=80*2x/100
160x/100-110x/100=50x/100
%=(50x/100)/(160x/100)*100=5*100/16=6.25*5=31.25% less

Like? Yes (2) | No   

ANURAG KUMAR   9 years AGO

let X=100
then 110 is 31.25% less than 160

Like? Yes (2) | No   

siddharth prakash singh   9 years AGO

10% of x more than x= x+(10x/100) =11x/10
20% of 2x less than 2x =2x-(20*2x/100) =16x/10
req difference= 5x/10
req %age=(5x/10)*)100/16)*10=31.25%

Like? Yes (2) | No   

aman aditya   9 years AGO

10 % of x + x=1.1
20 % of 2x -2x= 1.6
(.5/1.6)*100= 31.25

Like? Yes (1) | No   

prabhat kumar   9 years AGO

11/10 is 68.75 percent of 5/8 so it is 31.25 percent less.

Like? Yes (1) | No   

kranthi kanchanapally   9 years AGO

clearly he has given x+10%(x) is what percent less than
2x-20%(2x)
then by solving we get
11x/10 , 16x/5
then 11x/10 is 31.25% less than 16x/5

Like? Yes (1) | No   

Josepheena Joseph   9 years AGO

2x - (2x*0.2) - (x + (x*0.1)) = 0.5x
Required Percentage =( 0.5x/2x - (2x*0.2))*100 = 31.25

Like? Yes (1) | No   

syed kashif ullah   9 years AGO

10 percent of x more than x=11x/10 and 20 percent of 2x less than 2x =8x/5...now solving u get 31.25 percent less.option 3

Like? Yes (1) | No   

vibhu raj gupta   9 years AGO

10% 0f x more x is 1.1x
20% of 2x less 2x is 1.6x
1.6x is 1.1x is 31.25% more.

Like? Yes (1) | No   

anamika   9 years AGO

let x=100
and 2x= 200
then 80% of 2x= 160
and 110 % of x= 110
then ans = 50/160 *100= 31.25%

Like? Yes (1) | No   

Rishabh Gupta   9 years AGO

x+x(10/100)=1.1x
2x-2x(20/100)=1.6x
now 1.1x is less by 0.5x than 1.6x
so 0.5x/1.6x=.3125 and so % is 31.25%.

Like? Yes (1) | No   

PAWAN KUMAR   9 years AGO

(1.6x-1.1x)/1.6x *100 = 31.25%. Ans.

Like? Yes (1) | No   

manohar kumar singh   9 years AGO

let x= 100.
10% of 100=10. more than 100= 110.
20% of 200=40. less than 200 =160.
160-110=50 is 31.25% of 160.

Like? Yes (1) | No   

09 Apr 2015 Find the volume

Volume of a conical bucket having bottom and top radii 30 cm and 60 cm and height 1 meter.

OPtion

1) 660 litre
2) 450 litre
3) 780 litre
4) 6.6 litre
5) 4.5 litre
6) 7.8 litre
7) .66 litre
8) .45 litre
9) .78 litre
10)106 litre

Solution

Volume of bucket = [1/3*Pi*(2R)^2*2h] - (1/3*Pi*R^2 h)
where R and 2R are bottom and top radii and height 1 meter.
7/3 Pi R^2 h
= 7/3*22/7*(.3)^2*1
= 0.66 m^3
= 660 litre
Option 1)

Correct Option: 1 Best Solution (28)

Anuj Rai   9 years AGO

Using formula of volume of frustum
V=(pie*height(R^2+R*r+r^2))/3
where R=60cm and r-30 cm and height =100cm
we get 660 litres

Like? Yes (4) | No   

Samyak   9 years AGO

v =1/3*PI8(r12 +r1*r2+r22)
So its value 660 ltr

Like? Yes (2) | No   

Anuj Rai   9 years AGO

Calculate it using formula of frustum R=60cm and r=30cm and height =100cm
volume will be 660 litre

Like? Yes (2) | No   

MRITUNJAY   9 years AGO

volume of frustum of cone=Pi*h(R^2+R*r+r^2)/3
=22/21*100*(3600+60*30+900)
=22/21*630000
=22*30000
=660000
=660 litre

Like? Yes (2) | No   

siddharth prakash singh   9 years AGO

volume of conical bucket=pi/3*h*(r1^2+r1*r2+r2^2)
putting given values,
22/21*100*(900+1800+3600)
=660000 cm^3
=660 litre

Like? Yes (2) | No   

praveen kumar   9 years AGO

1 is right ans

Like? Yes (1) | No   

ABHINAV PUSHPAM   9 years AGO

Volume of frustum = πh/3(R^2+r^2+Rr)
Putting h=100cm, R=60cm, r=30cm
Volume = 660000 cm^3 = 660 litre is answer
So option 1)

Like? Yes (2) | No (1)  

prabhat kumar   9 years AGO

vol of frustum 660000
so 660 lt.

Like? Yes (1) | No   

RAKESH   9 years AGO

22/7 * 100/3 * (900+3600+1800) /1000 = 660 l

Like? Yes (1) | No   

Josepheena Joseph   9 years AGO

volume of conical bucket = 1/3*3.14*( r1^2 + r2^2 + r1*r2 )*h
=1 / *3.14*(30^2 + 60^2 +30*60)*100
=65940 cm3
=659.4L

Like? Yes (1) | No   

GIRISH TYAGI   9 years AGO

1/3 pi*h (R^2 +r^2)=V and 1cubic meter = 1000 liter

Like? Yes (1) | No   

kranthi kanchanapally   9 years AGO

the top radius a=60 and b=30 and h=1m
then volume=1/3pi*h*(b^2+a*b+a^2)
=1/3*22/7*100(900+1800+3600)
660000cm^3
converting to liter we get 660 liter
so option 1 is correct

Like? Yes (1) | No   

Meenakshi   9 years AGO

given
top radii,R=60cm
bottom radii,r=30cm
height,h=1m(100cm)

volume of conical bucket=1/3[pi*h(R^2+R*r+r^2)]
=>1/3[22/7*100(60^2+60*30+30^2)]
=>660000cm^3
=>660 litre

Like? Yes (1) | No   

sonal   9 years AGO

volume of conical bucket=3.14*100*(60*60+60*30+30*30)/3
=659734.4 cm3
=659.7 l
=660 l
so correct option is 1

Like? Yes (1) | No   

sai   9 years AGO

volume of conical bucket is = (ri^2+r2^2+r1*r2)*22*h/(7*3)
calculate we get 900+3600+1800*22*100/(3*7) =660 lit

Like? Yes (1) | No   

Pranati Kundu   9 years AGO

v=?h(r*r+R*R+R*r)
v=.66m3
=660lt

Like? Yes (1) | No   

Pragati Rode   9 years AGO

R1=0.6m R2=0.3m
by using the formula,
Volume of Frustum cone = 1/3 * πh((R1 )2 +(R2 )2 +R1 *R2 )
we get volume= 0.66m
convert it into liter using conversion 1m=1000 liter
0.66m = 660 liter
option is 1)

Like? Yes (1) | No   

moumita   9 years AGO

Volume of conical frustum = 1/3*3.14*h*(R^2+r^2+R*r)
Here, R=0.6m, r=0.3m, h=m
V = 1/3*3.14*1*((0.6)^2+(0.3)^2+(0.6*0.3)) = 0.659 =0.66 m^3
= 660litre

Like? Yes (1) | No   

shreya saklecha   9 years AGO

volume of frustum=3.14h/3(R^2+Rr+r^2)
=3.14*100/3[(60^2+60*30+30^2]
=660000cm^3(aprox)
=660 lit [1000cm^3=1lit]

Like? Yes (1) | No   

Yathiraj   9 years AGO

Volume of cone
V=(pi*h)/3(R^2 + R*r + r^2)

R=60cm
r=30cm
h=100cm

With the above values, V=660000 cm^3

1 cubic centimeter = 0.001 Liter and hence
660000 cm^3 = 660 Liter

Like? Yes (1) | No   

aman aditya   9 years AGO

volume of frustum= 653400 cm cube
so
659400/1000 =660 li

Like? Yes (1) | No   

ANUJ KUMAR   9 years AGO

Using the formula of frustum
Volume=(1/3)×pi×h×[R^2+r^2+R×r]
solving we get 6594m^3
which equals to 659 litre
or 660 litre

Like? Yes (1) | No   

chinni   9 years AGO

(pi*h*(R^2+r^2+R*r))÷3
1 litre=(cm^3)÷1000

Like? Yes (1) | No   

virendra tiwari   9 years AGO

formula=3.14*(1003)*(60^2+30^2+30*60)=660

Like? Yes (1) | No   

Jitendra Kumar   9 years AGO

V=(1/3)pi*h*(R^2+R*r+r^2)

Like? Yes (1) | No   

ADERU CHENCHU NITHISH   9 years AGO

use formula v=(22*h/3)*(r1^2+r2^2+r1*r2)

Like? Yes (1) | No   

anand kumar   9 years AGO

volume =3.14(r^2+R^2+rR)/3

Like? Yes (1) | No   

alok kumar   9 years AGO

V=pi*h*(R^2+r^2+Rr)/3
=660l

Like? Yes (1) | No