3 men and 4 women do a work in 10 days as 2 men and 6 women do. 4 men and 8 women starts the same work and after 2 days only women remains in the work for completing it. How many days are required to complete the work.
3 men + 4 women = 2 men + 6 women
1 men = 2 women
Now 4 men + 8 women = 16 women
according to given condition
3 men + 4 women = 10 women do the work in 10 days
So 1 day work of 1 women = 1/100 part
In 2 days work completed = 2*16* 1/100
= 32/100 part
Remaining work = 68/100 part
and Remaining women for work = 8
So number of days required = (68/100)/(8/100) = 68/8 = 17/2
= 8.5
Option 4)
Every alphabet has a numbering from start. Convert this alphabet into a new alphabet from end.
For example
S is 19th from first so will be converted to H which is 19th from last.
Circumference of girth of roller = 440 cm
2*Pi*R = 440 = R (220*7/22) = 70 cm
Outer radius = 70 cm & inner radius = 70-4 cm = 66 cm
Therefore Volume or iron = Pi [(70^2 - 60^2)]*63
= 58752 cm^3
x, y, z and k are four non zero positive integers satisfying 1/x + y/2 = z/3 + 4/k, minimum integral value of k for integral value of x, y and z will be
For getting minima in one subject, he should get maxima in other subjects.
Let us suppose he got 100 in all other subjects
then
(n-1)100 + 64 = n*88
100n - 36 = 88n
n = 3
Since 7 multiple of the number is a perfect square so no will have a factor 7 and other factor will be definitely be a perfect square possibilities for the other factor are 1, 4, 9, 16 ....
7*1 = 7 digit
7*4 = 28 digit
7*9 = 63 digit
7*16 = 112 digit
So sum = 63 + 28 = 91
A man runs with speed 54 km/hr in a straight path starting from A at 8 AM for 35 minute. What should be his speed for rest of the motion, completing 100 kms from A to B upto 9 AM.