M4maths Previous Puzzles

18 Jun 2015 Average

Out of three given numbers, the first one is twice the second and three times the third. If the average of these numbers is 88, then the difference between first and third is.

OPtion

1) 48
2) 82
3) 64
4) 72
5) 96
6) 32
7) 36
8) 44
9) 76
10)94

Solution

Let first = x, Then, second = x/2 and third x/3
x + x/2 + x/3 = 3*88
11x/6 = 264
x = 144
First - Third
144 - 1/3*144 = 96

Option 5)

Correct Option: 5 Best Solution (70)

Supriya Mondal   9 years AGO

Sum of three number is=88*3=264
Let three numbers are a, b,c and a is the highest and c is the lowest
Then,
2b=a so b=a/2 and 3c=a so c=a/3
we can write,
a+b+c=264
a+a/2+a/3=264
11a/6=264
a=144
So, c=144/3=48
So there difference is=144-48
=96
So, option 5)96 is the right answer

Like? Yes (14) | No (5)  

varsha   9 years AGO

x1=2.x2=3.x3
(x1+x2+x3)/3=88
x1=144
x3=48
x1-x3=96

Like? Yes (8) | No (2)  

sai   9 years AGO

sum=274
first =144
third =48
difference 96

Like? Yes (7) | No (4)  

SANTOSH   9 years AGO

let numbers be 6x,3x,2x
average 11x/3=88
then x=24
Numbers 144,72,48
difference 144-48=96

Like? Yes (4) | No (2)  

MRITUNJAY   9 years AGO

x y z
6 3 2
difference between x and z be 4.
so 88*3/11*4=96

Like? Yes (5) | No (3)  

neha gupta   9 years AGO

Let a ,b and c be three numbers
then acc to ques a=2b=3c
therefore b=a/2
and c=a/3

a+b+c=88*3=264
a+(a/2)+(a/3)=264
11a=264*6
a=144
c=144/3=48

a-c=144-48=96

Like? Yes (3) | No (1)  

Chandrima Goswami   9 years AGO

Let 1st= 6a, 2nd= 3a and 3rd no= 2a
Average, 11a/3=88 => a=24
Therefore 1st no=144 and 3rd no=48
Difference between 1st and 3rd is 96

Like? Yes (2) | No   

vignesh   9 years AGO

since the first number be x and second be x/2 and third be x/3 by given avg is 88 so (x+x/2+x/3)/3=88 on solving we get x as 144 then the second number is 72 and the third is 48 now the difference is 96

Like? Yes (2) | No   

Rhul Sharma   9 years AGO

Let the numbers be
X
X/2
X/3
(X X/2 X/3)/3. =88
6X 3X 2X = 1584
X= 144
144. - 48 = 96

Like? Yes (1) | No   

Mehul D Parmar   9 years AGO

(x+x/2+x/3)/3=88

11x/18=88
x=144

thn x/3=144/3
x/3=48

thn 144-48=96

Like? Yes (1) | No   

Surendhar Ramanujam   9 years AGO

let x be the third number
Then the three numbers are 3x, 1.5x and x
since the average is 88 we get x=48
Thereby the difference between 1st and 3rd number is
3x-x=2x
2x=2*48=96

Like? Yes (1) | No   

Urvashi Jain   9 years AGO

according to the question a=2b,a=3c
a+b+c/3=88
a+b+c=264.....(i)
b=a/2,c=a/3
put in equation (i)
a+a/2+a/3=264
6a+3a+2a=6*264
11a=6*264
a=6*24
a=144
c=a/3,144/3=48
a-c=144-48=96

Like? Yes (1) | No   

Divyansh jaiswal   9 years AGO

(6x+3x+2x)/3=88

x=24

first no=48
third=144
diff.=96

Like? Yes (1) | No   

Hemalatha   9 years AGO

On calculating, the first no is 144, the next is 96, and the third is 72. The average of the three nos results to 88 as per the question.

Like? Yes (1) | No   

anuj kumar singh   9 years AGO

let the first no. be n
then 2nd no. be n/2
third no. be n/3

thn,
(n+n/1+n/3)/3=88
calculate it...and you'll get the answer

Like? Yes (1) | No   

Deepak   9 years AGO

let three numbers be x,y,z
second number y=x/2,
third number, z = x/3
average, x + x/2 + x/3 = 88, x = 144 and z = 48
thus difference is x-z = 96

Like? Yes (1) | No   

swetha   9 years AGO

x,x/2,x/3
(x+x/2+x/3)/3=88
x=144
x-x/2=72

Like? Yes (1) | No   

RAVAL   9 years AGO

according to given data,
x=2y=3z
& (x+y+z)/3=88
by solving the above equation,
x=144
y=72
z=48
difference x-z=96

Like? Yes (1) | No   

Debraj Ghosh   9 years AGO

numbers are 6x,3x,2x
so (6x+3x+2x)=(88*3)
=>11x=(88*3)
=>x=24
so difference between first and third is 4x=96

Like? Yes (1) | No   

Jyothi C Allapur   9 years AGO

let the three numbers be a,b,c
given :
a = 2b and a = 3c
i.e., b = a/2 and c = a /3
and average is 88
( a+ b + c ) / 3 = 88
substituting b and c in above eqn, we get a = 144
and b = 72 and c = 48
and difference between a and c is 144 - 48 = 96

Like? Yes (1) | No   

Shiva Sharma   9 years AGO

2A,A,B
2A = 3B
3A+B = 3*88
11B/2 = 3*88
B=8*3*2=48
A=3*48/2=72
first Number = 2*A=2*72=144
last number = 48
difference(2A-B)=144-48=96

Like? Yes (1) | No   

Parvathi.R   9 years AGO

Lets take the no.s as x, x/2, x/3
Now
(X+(x/2)+(x/3))/3= 88
On solving , we get x=144
1st no s 144
2nd no s 72
3rd no s 48
Diff bw 1 & 3 is 96

Like? Yes (1) | No   

ravi singh   9 years AGO

let, no. are X1, X2, X3
then, X1=2*X2=3*X3 ......eq(1)

and (X1+X2+X3)/3 = 88 .......eq(2)

from eq(1) and eq(2)

X1 = 144 and X3 = 48

hence difference us 96

Like? Yes (1) | No   

kush nigam   9 years AGO

x=2y, x=3z, x+y+z= 88*3=264, => 3z+3/2z + z= 11/2z =264 => z= 48=> difference x n z= 3z-z = 2z

= 96

Like? Yes (1) | No   

KARAN SHARMA   9 years AGO

a=2b , a=3c
(a+b+c)/3=88
solve dis we get a=144 and c= 3*144
required ans. is a-c = 96

Like? Yes (1) | No   

Divya Obilishetti   9 years AGO

let numbers are a,b ,c
a=2b and a=3c
i.e b=a/2 and c=a/3
average of a+b+c is 88
(a+a/2+a/3)/3=88
you will get the vcalues

Like? Yes (1) | No   

RAKESH ARYA   9 years AGO

if 1st no = x
then , (x + x/2 + x/3 ) / 3= 88
=> 11x/6 = 88*3
=> x= 144

then x - x/3 = 144 - 48
=96

Like? Yes (1) | No   

Pranesh S   9 years AGO

let the second number be x.
then the first number will be 2x.
if let the third number be y
then first number will be 3y.
therefore 2x=3y and y =(2/3)x
given (2x +x+(2/3)x)/3=88.
solving this ,we get x=72.
therefore the 2x-(2/3)x=2(72)-2/3(72)=96

Like? Yes (1) | No   

MUKESH   9 years AGO

let x be the 1st value,y be the 2nd value,z be the 3rd value
from given x=2y=3z
(i.e) (x+x/2+x/3)/3=88
on solving this we get x=144,y=72,z=48
difference of 1st and 3rd is 96

Like? Yes (1) | No   

K.M.AYESHA SHARMIL JAHAN   9 years AGO

let the 3 no. be x,y,z
x=2y
x=3z
x+y+z/3=88
by solving,
x =144
z =48
x-z=96

Like? Yes (1) | No   

Priyanka Kumari   9 years AGO

a=2b=3c
(a+b+c)/3=88
by solving we get
a=144
b=72
c=48

Like? Yes (1) | No   

santhosh   9 years AGO

X+1/2x+1/3X=88
X(1+1/2+1/3)=88
(11/6 )X=88
X=144
(1/3)X=48
144-48=96

Like? Yes (1) | No   

chanchal kumar choudhary   9 years AGO

let 1st no=x,2nd=x/2,3rd=x/3,
(x+x/2+x/3)/3=88
x=144;
1st=144;
3 rd=48;
diff=144-48=96

Like? Yes (1) | No   

naveen v   9 years AGO

take series as 2a, a, 2a/3 then u will get 144,72,48 ..
144-48= 96

Like? Yes (1) | No   

Kamlesh Kumar   9 years AGO

6x+3x+2x=3*88
11x=264
x=264/11
x=24
6*24-2*24
=> 96

Like? Yes (1) | No   

Vinith Mahendran   9 years AGO

The values are 3y,3y/2,y
Therefore 11y/2/3=88
11y/6=88
Y=48
Then 48(3-1)=96

Like? Yes (1) | No   

Lavanya Rajendran   9 years AGO

X=2y,
x=3z,
(x+y+z)/3=88
(x+x/2+x/3)/3=88
on solving x=144
144/3=48
144-48=96

Like? Yes (1) | No   

ENABOTHULA MOUNIKA   9 years AGO

Let x,y,z are 3 numbers
Given x=2y, x=3z and x +y +z/3=88
(X+x/2+x/3)/3=88
11x/18 =88
X=144 ==> y=72 and z=48
X-Z = 144 - 48 =96

Like? Yes (1) | No   

SHEELA S   9 years AGO

x+y+z/3=88
x+x/2+x/3=264
11x=1584
x=144 so y=72,z=48
x-z=96

Like? Yes (1) | No   

vimal tiwari   9 years AGO

let no be x y z
y=x/2
z=X/3

avg=(x+y+z)/3
88=(x+x/2 + x/3)/3
x=144
y=72
z=48

x-z =144-48=96

Like? Yes (1) | No   

bipro biswas   9 years AGO

x=2y=3z
(x+y+z)/3=88
solving:x=144
thereforex-z=x-(x/3)=2/3*x=96

Like? Yes (1) | No   

v v shyam kumar   9 years AGO

let the three no.s be :
x,x/2,x/3.
average of these is given as 88.
(x+x/2+x/3)/3=88,
therefore x=144.
The difference between first and third no.is = 144-48=96.

Like? Yes (1) | No   

UDIT   9 years AGO

x=2y=3z and x+y+z=264 so solving, x=144 z=48 x-z=96 (option 5)

Like? Yes (1) | No   

TUSHAR CHHABRA   9 years AGO

let second be x, first=2x, third=y,but y=2x3

Like? Yes (1) | No   

Subashini Nagarajan   9 years AGO

x,y,z are three nos....then x=2y; x=3z; so ...x+y+z / 3 = 88
so.... (x+(x/2)+(x/3))= 88*3 ........ x = 144 and z = 48 then x- z = 96

Like? Yes (1) | No   

Gadupudi Ramakrisna   9 years AGO

a=2b
a=3c
((a+b+c)/3)=88
(a+(a/2)+(a/3))/3=88
11a=88*6*3
a=144
b=77
c=48
a-c=96

Like? Yes (1) | No   

pratap kumar sahoo   9 years AGO

x=2y=3z;
(x+y+z)/3=88;
putting,
x=3Z,y=(3Z)/2;
z=48;
x-z=z*(3-1)=48*2=96

Like? Yes (1) | No   

GADUPUDI RAMAKRISHNA   9 years AGO

Let me take the three numbers are a,b,c
then
a=2b
a=3b
average of the numbers=(a+b+c)=88*3
(a+(a/2)+(a/3))=88*3
6a+3a+2a=88*3*6
11a=88*3*6
a=144
b=a/2=72
c=a/3=48
so a-b=144-48=96

Like? Yes (1) | No   

ADERU CHENCHU NITHISH   9 years AGO

let the numbers be x,x/2,x/3
(x+x/2+x/3)/3=88
(11x/(3*6))=88
x=8*18
x-x/3=x(1-1/3)=2x/3=2*8*18/3=96

Like? Yes (1) | No (1)  

Devendra Marghade   9 years AGO

If three numbers are x,y & z, then
x=2y=3z, so y=x/2 and z=x/3
As the average of these three numbers is 88,
(x+y+z)/3= 88 or [x+(x/2)+(x/3)]/3=88, so x=144 & z=48
So difference between x & z=144-48=96
Answer is option (5)

Like? Yes (1) | No (1)  

aman aditya   9 years AGO

6x+3x+2x=11x
average of three no is 88 so total is=88*3=264
264/11x
so x=24
so numbers are: 144,72,48

Like? Yes (1) | No (1)  

ABHINAV PUSHPAM   9 years AGO

Let 1st no. be x, 2nd = x/2, 3rd= x/3

=> x+x/2+x/3 = 3*88

=> 11x/6=264

so, x= 144

Hence difference = 144 - 1/3*144 = 96
option 5)

Like? Yes (1) | No (1)  

Swetha   9 years AGO

(3x+(3x/2)+x)/3=88
(6x+3x+2x)/2=264
11x=528
X=48

So, difference btw 1st n 3rd no.'s is (48*3)-48=96

So the ans is option 5 i.e., 96

Like? Yes (1) | No (1)  

Math Lovers   9 years AGO

let numbers are x,y,z
=> x=2y=3z
now,
(x+y+z)/3 =88
=> x+y+z = 88*3

now, z=x/3, y=x/2
=> x + x/2 + x/3 = 88*3
=> x = 88*3*6/11 = 8*3*6
now x-z = x - x/3 = 2x/3 = 96

Like? Yes (1) | No (1)  

virendra tiwari   9 years AGO

(a+a/2+a/3)/3=88
a=144
c=48
difference=96

Like? Yes (1) | No (1)  

shivaprabhu   9 years AGO

Let X be the number

Given three numbers in the ratio X:X/2:X/3

and also (X+X/2+X/3)/3=88

solving X=144

Hence difference between 1st and 3rd number is

X-X/3=144-144/3
=144-48
=96

Ans:-96

Like? Yes (1) | No (1)  

kishor Mali   9 years AGO

let the no be 6x,3x,2x
so avg is 11x/3=88
now x=24
so diiference is 6*24-2*24=96

Like? Yes (1) | No (1)  

mohita verma   9 years AGO

let 3 no be x,y,z
As per question,
y=x/2 and z=x/3
(x+x/2+x/3)/3=88
x=144
so, y=72
z=48
x-z=144-48=96

Like? Yes (1) | No (1)  

lokesh   9 years AGO

let the numbers be x , x/2 ,x/3

so (x + x/2 + x/3)3 = 88
=> x= 144

now , 144 - 144/3 = 96

Like? Yes (1) | No (1)  

POOJA YADAV   9 years AGO

Let 2nd no =x 3rd no=y
1st no = 2x = 3y
x=3y/2
(3y+3y/2+y)/3=88
y=48
x= 72
2x=144
so, 144-48=96 ans

Like? Yes (1) | No (1)  

asim   9 years AGO

let 3 given numbers be a , b , c
=> a = 2b ...........................(i)
and a = 3c ........................(ii)

given avg = 88
=> a + b + c = 88 * 3
=> a + (a/2) + (a+3) = 88 * 3 ................(from eq i and eq ii )
=> a(11/6) = 88 * 3
=> a = 48 * 3
=> c = a / 3 = 48*3 / 3 = 48

i.e. a - c = 48 * 3 - 48
= 48 ( 3 - 1 ) = 48 * 2 = 96 ans

Like? Yes (1) | No (1)  

ISHITA UPADHYAY   9 years AGO

Let the numbers be : 3x, 3x/2, x resp.
(3x+3x/2+x)/3 = 88
x=48
Difference = 144 - 48 = 96 Ans

Like? Yes (1) | No (1)  

Ayan Patra   9 years AGO

Let the 3 numbers be a, b and c.
Now, a = 2b = 3c.
So their average can be expressed as:
(2b + b + c) / 3 = 88.
or, 3b + c = 264.
We know that 2b - 3c = 0, from the given condition.
Solving the equations we get b = 72.
So, a = 2b = 144 and c = a / 3 = 48.
Therefore, a - c = 144 - 48 = 96.

Like? Yes (1) | No (1)  

Chirag Jindal   9 years AGO

x=2y=3z
and x+y+z/3=88
substituting from above relations we get
x=144
y=72
z=48
therefore x-z=96

Like? Yes (1) | No (1)  

Thanakkumar T   9 years AGO

Three No's be a b and c...if b=a/2,then c=a/3...if a+b+c=88*3....then a=144,c=48 then a-c=96

Like? Yes (1) | No (1)  

poojasaisri   9 years AGO

x=2y=3z
(x+y+z)/3=88
2y+y+(2/3)y=264
y=72
x=144
z=48
x-z=96

Like? Yes (2) | No (2)  

Yathiraj   9 years AGO

(x+(x/2)+(x/3)) / 3 = 88
Hence, x=144
x/3 = 48
x - (x/3) = 96

Like? Yes (2) | No (2)  

viswambher   9 years AGO

let the three numbers be a,b,c
and a=2b=3c
and average of three numbers is 88 therefore a+b+c= 264
solving the equations we get c= 48 and since a=3c difference b/w those two is 2c = 96

Like? Yes (2) | No (2)  

Mahesh   9 years AGO

Let X be the first number
Then
(X+X/2+X/3)/3 = 88
11X/6 = 88*3
11X = 88*3*6
X = 1584/11
X = 144

Then Second number is 144/3 = 48
So 144 - 48 = 96

Like? Yes (1) | No (1)  

Prayani Singh   9 years AGO

Let a,b,c be two number
a=2b and a=3c
and (a+b+c)/3=88
=> (a+a/2+a/3)/3=88
(11a/6)/3=88
a=(3*6*88)/11=144
hence, a=144 and c=a/3=144/3=48
difference is a-c=144-48=96

Like? Yes (1) | No (3)  

16 Jun 2015 Age Problem,

Ten years ago A was half of B in age. If the ratio of their present ages is 3:4 what is the sum of their present ages?

OPtion

1) 8 years
2) 20 years
3) 35 years
4) 45 years
5) 25 years
6) 15 years
7) 38 years
8) 30 years
9) 48 years
10)50 years

Solution

Let their present ages be 3x and 4x, Then
2(3x-10) = 4x - 10
2x = 10
x = 5
Sum of their present ages = 7x = 35

Option 3)

Correct Option: 3 Best Solution (78)

Surit Datta   9 years AGO

Let A's age 10 years ago = x years.
Then, B's age 10 years ago = 2x years.
(x + 10) / (2x+ lO) = 3/4
=> x = 5.
So, the total of their present ages =(x + 10 + 2x + 10)
= (3x + 20) = 35 years.

Like? Yes (13) | No (6)  

Vijendra singh   9 years AGO

ratio of present age is 3:4
so age let it 3x and 4x
10 years ago age was- (3x-10)=(4x-10)/2;
so x=5
so current age is 3x and 4x
3*5 =15 and 4*5=20
then sum is 35 .
option is 3

Like? Yes (8) | No (1)  

Supriya Mondal   9 years AGO

10 years ago age of A=5 and B=10
Now, age of A=15 and age of B=20
So,sum of their age is =15+20=35
So, option 3)35 is the right answer

Like? Yes (15) | No (8)  

Balakumaran N.A   9 years AGO

Let the present age of P and Q be 3x and 4x respectively.

Ten years ago, P was half of Q in age

=> (3x – 10) = ½ (4x – 10)

=> 6x – 20 = 4x – 10

=> 2x = 10

=> x = 5

total of their present ages = 3x + 4x = 7x = 7 × 5 = 35

Like? Yes (9) | No (2)  

neelabh   9 years AGO

Let there present age be 3x & 4x.
Than
2(3x-10)=(4x-10)
2x=10
x=5.
There fore A present age =15 & B present age= 20
15+20=35

Like? Yes (3) | No   

Debraj Ghosh   9 years AGO

suppose today there age is 3x,4x respectively
so 10 years ago their age was (3x-10),(4x-10) respectively
Now, according to the question
(3x-10)=(4x-10)/2
=>6x-20=4x-10
=>2x=10
=>x=5
so today their present age=(3*5+4*5)=35

Like? Yes (3) | No   

Srinivas   9 years AGO

it is the answer a:b = 1:2 before
present a:b = 3:4
change is 2 parts..so 1 part = 5 yrs
Present 3+4 = 7 parts = 7*5=35

Like? Yes (2) | No   

Mehul D Parmar   9 years AGO

age of A and B 10 years ago be x and 2x years respectively

so,
x+10/2x+10=3/4

4(x+10)=3(2x+10)

4x+40=6x+30

10=2x

x=5


then sum of their ages=(5+10)+(2*5+10)=35

so ans is 3 option are 35

Like? Yes (3) | No (1)  

santhosh   9 years AGO

3x,4x are the present ages of a&b,
ten years ago so, 3x-10=1/2(4x-10)
3x=10+2x-5
x=5
3x+4x=35years

Like? Yes (3) | No (1)  

ADERU CHENCHU NITHISH   9 years AGO

Let the present age of P and Q be 3x and 4x

Ten years ago, P was half of Q in age
=> (3x – 10) = ½ (4x – 10)
=> 6x – 20 = 4x – 10
=> 2x = 10
=> x = 5
so total of their present ages = 3x + 4x = 7x = 7 × 5 = 35

Like? Yes (2) | No (1)  

ABHINAV PUSHPAM   9 years AGO

Let the present age of P and Q be 3x and 4x respectively.



Ten years ago, P was half of Q in age

=> (3x – 10) = ½ (4x – 10)

=> 6x – 20 = 4x – 10

=> 2x = 10

=> x = 5



total of their present ages = 3x + 4x = 7x = 7 × 5 = 35

Like? Yes (3) | No (2)  

K.M.AYESHA SHARMIL JAHAN   9 years AGO

from the question,
A-10=(B-10)/2
A:B=3:4
by soiving,we get B=20 & A=15
A+B=35

Like? Yes (1) | No   

k sureshbabu   9 years AGO

change in ratio is 2 parts i,e
after 10 years 1:2 changes to 3:4
so 2 parts is equal to 10 years 1p=5 years
3p+4p=7p so 7*5=35years

Like? Yes (3) | No (2)  

Yathiraj   9 years AGO

from the given data,
A-10 = (B-10)/2
which can be written as 2A-B=10
Also, their present age ratio i.e. A:B=3:4 => B = (4A)/3 -> Substitute this in above equation to derive A
2A - (4A/3) = 10
A=15
B=4A/3 = 20
So, the sum of their current age will be 15+20=35.

Option 3.

Like? Yes (2) | No (1)  

MRITUNJAY   9 years AGO

10 years ago age of A is x and B be 2x
present age be x+10
and 2x+10
x+10/2x+10=3/4
x=5
present age be 15 1nd 20
so total age is 20+15=35

Like? Yes (1) | No   

RAHUL KUMAR   9 years AGO

Let the ages of A and B 10 years ago be x and 2x years.
then, (x+10)/(2x+10) =3/4
so, x=5
sum of their present ages = (x+10) + (2x+10) =35 years.

Like? Yes (1) | No   

kiruthika   9 years AGO

let age of A be x and b becomes 2x and ratio given is 3:4 by adding A and B to 10 for present ages
the equation becomes
x+10/2x+10=3/4
by solving x is 5
now a and b is 15+20=35

Like? Yes (1) | No   

RAVAL   9 years AGO

their age ratio is 3:4
so before 10 years, a=b/2
ans .35 yrs
present age is 15 & 20 yrs

Like? Yes (1) | No   

sompon temtheerakij   9 years AGO

A and B are present ares
2(A-10) = B-10....1
3/4 = A/B......2
by solve these two equations
A = 15 , B = 20
A+B = 15+20 = 35

Like? Yes (1) | No   

Gaurav Singla   9 years AGO

3X-10/4X-10=1/2 A/B=3/4
6X-4X=10
X=2

Like? Yes (1) | No   

sainath   9 years AGO

(3x-10)=(1/2)*(4x-10)
x=5

3x+5x=15+20=35

Like? Yes (1) | No   

Srinutha Dasaroju   9 years AGO

10 years ago ages are A,2A.
present (A+10) : ((B=2A)+10)=3:4
(A+10) / (2A+10)=3/4
2A=10
A=5 thus B=10.
Present their ages will be 15 and 20. Sum= 35

Like? Yes (1) | No   

pratap kumar sahoo   9 years AGO

A-10=(1/2)(B-10);---------------------------(1)
A:B=3;4;
A=(3/4)B
putting in eq(1),
B=20;
A=15;
A+B=35

Like? Yes (1) | No   

Ayan Patra   9 years AGO

Let current age of A be 3x and that of B be 4x.
10 years ago A was half the age of B.
So, 3x - 10 = (4x - 10)/2
or, x = 5
Therefore the sum of their current age is 3x + 4x = 3*5 + 4*5 = 35.

Like? Yes (1) | No   

Muhammad Nadeem Haider Naseem   9 years AGO

Let the present age of A and B be 3x and 4x respectively.



Ten years ago, A was half of B in age

=> (3x – 10) = ½ (4x – 10)

=> 6x – 20 = 4x – 10

=> 2x = 10

=> x = 5



total of their present ages = 3x + 4x = 7x = 7 × 5 = 35

Like? Yes (1) | No   

Dharshana   9 years AGO

Ten years before :
(A-10)=(B-10)/2 ; so rearranging the equation 2A-B=10
Present ratio:
A:B = 3:4
rearranging the equation 4A-3B=0; sloving both B= 20 and A= 15 . so sum of their present age is 35.

Like? Yes (1) | No   

B.venkata suresh   9 years AGO

3x,4x
x=5
sum=3*5+4*5=15+20=35

Like? Yes (1) | No   

M,MATHIVANI   9 years AGO

10 years before, A's age is 5 and B's age is 10. presently A and B's ages are 15 and 20 respectively,Hence their present ratio is 3:4. therefore the answer is 35

Like? Yes (1) | No   

saket kumar   9 years AGO

because let present age of A is 3x and b is 4x,
10 years ago.... 3x-10=(4x-10)/2
therefore x=5
hence 3x+4x= 35

Like? Yes (1) | No   

Atishay jain   9 years AGO

we have to choose that sum of ages that is satisfaction for this question....
if we choose 35 then we have sufficient answer.. becoz this question says ten years ago.. so there are two person A and B . so we have to subtract 20 .. then see the remaining answer which is in ratio of 1:2.. then add 10 yrs per candidate .. then saw the ratio of 3:4 between A and B....
so 35 is accurate.......

Like? Yes (1) | No   

SURESH   9 years AGO

A-10=(1/2)(B-10) ----- (1)
A/B=3/4----------(2)

2A-20=B-10---FROM(1)
4A=3B-----FROM(2)

FROM(1) * 2

4A-40=2B-20
3B-40=2B-20....USING RESULT FROM(2)

B=20
A=15
TOTAL=35

Like? Yes (1) | No   

kshitij   9 years AGO

distribution 15+20
10 years back
a =5 , b=10
ratio of current = 3:4

Like? Yes (1) | No   

varsha   9 years AGO

1. (A-10)=.5×(B-10)
2. 4A=3B
by solving 1&2
A=15 B=20
A+B=35

Like? Yes (1) | No   

Kamlesh Kumar   9 years AGO

let age is x in present
10 year ago (x-10)=(2x-10)
ratio is 3:4
(x-10)/(2x-10)=3/4
4x-40=6x-30
2x=10
x=5
=>5*3+5*4
35

Like? Yes (1) | No   

Srinivas Rao   9 years AGO

A-10 = 1/2(B-10)
2A-20 = B- 10
2A-B=10--------- (1)

A/B= 3/4
4A=3B
4A-3B = 0 --------(2)
SOLVING EQUATIONS 1 AND 2 U WILL GET
A=15 years
SO B=20 YEARS (AS RATIO GIVEN, MULTIPLY BY 5)
SO SUM = 35 YEARS

Like? Yes (1) | No   

Aakash   9 years AGO

let present ages be 3x and 4x.
so, (3x-10) = (4x-10)/2
we get x =5;
hence sum of present ages is 7x = 35

Like? Yes (1) | No   

Sara Banova   9 years AGO

A was x years old
B was 2x years old
x+10/2x+10=3/4
x=5
=> A is 15
B is 20
A+B= 35

Like? Yes (1) | No   

Surendhar Ramanujam   9 years AGO

let A's present age be x and B's present age be y
Then before 10 years' {(x-10)=(y-10)/2}
Also x:y=3:4 Therefore by substituting x=(3y/4) in the above equation we get y=20 and subtituting y value we get x=15
Therefore sum of the ages is x+y=20+15=35

Like? Yes (1) | No   

vishal chandrola   9 years AGO

x is age age A
y is age of B
x:y=3:4
x-10=(y-10)/2
evaluating
x=15
y=20

Like? Yes (1) | No   

kinchit trivedi   9 years AGO

let a=x and b=y; then from question we form two equations. 4x=3y and 2x-y=10; so x=15 and y=20

Like? Yes (1) | No   

aman aditya   9 years AGO

10 year ago:
a=5
b=10
so now,
a=15
b=20
a+b=35

Like? Yes (1) | No   

kishor Mali   9 years AGO

let present age be 3x and 4x...
10 year ago...(3x-10)=(4x-10)/2
x=5
a is 15 year and b is 20 year sum is 15+20=35

Like? Yes (1) | No   

Shiva Sharma   9 years AGO

A-10 = (B-10)/2
2A-20 = B-10
multiply by 2
4A-40 = 2B-20 ...........1
A/B = 3/4
4A = 3B
put in first eq.1
3B-40 = 2B-20
B = 20
A = 15
A+B = 35

Like? Yes (1) | No   

Divyansh jaiswal   9 years AGO

suppose ages 10 yrs ago a=x then b=2x

current (x+10)/(2x+10)=3/4 x=5 current ages a=15 yrs b=20yrs sum is 35

Like? Yes (1) | No   

Thanakkumar T   9 years AGO

We have 3x and 4x ages now 7x is their sum so exactly 35 is divisible by 7 so 35 is the answer.

Like? Yes (1) | No   

thendral   9 years AGO

x , 2x are ages of A and B 10years ago.
So, x+ 10/2x+10 = 3/4
2x= 10 x=5
Sum of present ages (5+10)+(10+10)
= 35 years

Like? Yes (2) | No (1)  

geeta   9 years AGO

let suppose the present age of A and B be x and y respectively
... 10 yrs before, A's age is (x-10) and is 1/2 that of B's age i.e (y-10)... and present age's ratio i.e x/y = 3/4 . solving 2 equations we get x=15 and y=20 ... sum of their ages = 15+20=35

Like? Yes (1) | No   

Deepak kushwaha   9 years AGO

in present their ages in ratio 3:4
let A's age be 3x
and B's age be 4x
10 years ago
their ages A=3x-10 & B=4x-10
and we know 10 years ago A=B/2------(1)
put these value of A & B in eqn (1)
we get x=5
A=15 & B=20
total is 35

Like? Yes (1) | No   

Chetan Arya   9 years AGO

two equations
2(A-10)=(B-10)
and A=(3/4)A
after solving them
A=15 and B=20
So Answer is 35

Like? Yes (1) | No   

kishor anap   9 years AGO

go back 10 yrs...consider ages as a=x, b=2x
after 10 yrs :
(a+10) /(b+10) = 3/4
i.e. (x+10) /(2x+10) = 3/4
solving gives x=5,

so now a= 5+10 = 15, b=20
sum = 35

Like? Yes (1) | No   

Urvashi Jain   9 years AGO

A was half of B x, 2x
10 years ago
x+10/2x+10=3/4
x=5
so A IS 5 and B is 10
sum of present age is 5+10+10+10=35

Like? Yes (1) | No   

hemant jain   9 years AGO

let the ratios be x.
then present age of a=3x and b=4x
ten years ago ages of a=2*age of b
=> 3x-10=2*(4x-10)
on solving we get x=5
that means present age of a=3x=15 years
and that of b=4x=20 years
therefore the sum of ages will be(present)=15+20=35 years

Like? Yes (1) | No   

mohita verma   9 years AGO

let 3x and 4x be the present age of A and B respectively
10 years ago,
3x-10=(1/2)(4x-10)
x=5
sum of present age=3x5+4x5=35 years

Like? Yes (1) | No   

bipro biswas   9 years AGO

x/y=3/4
x-10=(y-10)/2
solving x=15
y=20
x+y=35

Like? Yes (1) | No   

AMMU TESSA JOSEPH   9 years AGO

let the ages of A and B 10 years ago be x and 2x respectively
then, x+10/ 2x+10 =3/4
=> 2x=10
x=5
then sum of their present ages=(x+10)+(2x+10)=35
thus the ans is 35 years

Like? Yes (1) | No   

Mounis Swaleh   9 years AGO

present age of A:B = 3x:4x
after 10 years
3x-10 = (4x-10)/2
x=5
A=15, B=20
A+B=35

Like? Yes (1) | No   

Vishnu Varthan A   9 years AGO

A-10=1/2(B-10)=>2A-B=10
given present ages in ratio 3:4
total age be x
A=3x/7, B=4x/7 on substituting in first line, we get x=35

Like? Yes (1) | No   

Shreya Maiwal   9 years AGO

Let present age of A=x
and that of B =y
Given x/y=3/4
10 yrs ago, age of A would have been x-10
and that of B=y-10
Given 10 yrs ago age of A is 1/2 of B hence
x-10=1/2(y-10)
after solving we get y=20 i.e. age of A
and x=15 i.e. age of B hence x+y=35

Like? Yes (1) | No   

ammar   9 years AGO

Let the present ages of A and B be 3x and 4x respectively.
According to given conditions,we have
2(3x-10) = 4x-10
2x = 10
x = 5
Therefore,
A's present age = 3x5 = 15
B's present age = 4x5 = 20
Sum of their ages = 15 + 20 = 35

Like? Yes (1) | No   

Karthick Raja   9 years AGO

10 years ago age ratio of A & B is
A=(B/2)

present age A+10:B+10 = 3:4
A+10/B+10 = 3/4
4A+40=3B+30
B=2A
4A-6A=30-40
-2A=10
A=5
B=10
Present ages of A 15
Present age of B 20
Sum of present ages 35

Like? Yes (1) | No   

Akash Dinkar   9 years AGO

10 years ago, Let B's age=x years
According to Question, A's will be of age=x/2 years
for present ages:
x/2+10/(x+10)=3/4
On solving,
x=10
So, Ans=10+5=15 years

Like? Yes (1) | No   

sourav pal   9 years AGO

Let A's age 10 years ago = x years.
Then, B's age 10 years ago = 2x years.
(x + 10) / (2x+ lO) = 3/4
=> x = 5.
So, the total of their present ages =(x + 10 + 2x + 10)
= (3x + 20) = 35 years.

Like? Yes (1) | No   

Gaurab Kumar Jha   9 years AGO

let the age ten year ago be x and 2x
(x+10)/(2x+10)=3/4
x=5
therefore the present age will be 15 and 20 and the sum will be 35

Like? Yes (1) | No   

Kajal Gupta   9 years AGO

present ages be 3x and 4x
and 10 yrs ago ,so eq will be
((3x-10)/(4x-10))=1/2
by solving this we get present age as 15 and 20 yrs and sum is 35 yrs

Like? Yes (1) | No   

Ramdas Singathiya   9 years AGO

a-10=(b-10)/2 .........................(1)
a= 3b/4 ...................................(2)

solving equation (1) and (2)
a=15 , b=20 so a+b= 35

Like? Yes (2) | No (2)  

RAKESH   9 years AGO

2*(3x-10) =(4x-10)
or, x = 5
sum of present ages = 7x = 7*5 = 35

Like? Yes (1) | No (1)  

Devendra Marghade   9 years AGO

A-10=(B-10)/2 or 2A-B=10 ---(i) and
A/B=3/4 or 4A=3B ---(ii)
Solving (i) & (ii), A=15, B=20
So A+B=15+20=35
Answer is option (3)

Like? Yes (1) | No (1)  

Ayush Gupta   9 years AGO

Let present ages be A and B
Ten years before
2(A-10)= B-10
at present 4A=3B
solve this and get A and B

Like? Yes (2) | No (2)  

Venkatesh kadali   9 years AGO

10 years ago A age is half of b age i.e
A : B=1:2
present ages of A and B is A:B=3:4
difference of ratios is 2
2----->10
1------->5
sum of their present ages is=(3+4)*5
= 7*5
=35

Like? Yes (1) | No (1)  

SANTOSH   9 years AGO

Let their ages Ayrs,Byrs
10yrs ago, their ages (A-10)yrs, (B-10)yrs
Conditions,
(A-10) = (B-10)/2
and A/B = 3/4

By solving we get A=15, B=20

A+B=5

Like? Yes (1) | No (1)  

Math Lovers   9 years AGO

(A-10)/ 2 = (B-10)
=> 2A - B = 10 -------------------- (1)

now, A/B = 3/4
=> B = 4A/3

putting the value in eqn (1)

=> 2A/3 = 10
=> A =15
=> B = 4A/3 = 20
A+B = 35 years

Like? Yes (1) | No (1)  

Chirag Jindal   9 years AGO

A-10=(B-10)/2 where A and B are present ages.
Also,A:B=3:4

solving above 2 relations give A=15 and B=20
therefore,
A+B=35

Like? Yes (1) | No (1)  

viswambher   9 years AGO

let the ages of A and B 10 years ago be a,b respectively where
a=b/2 and ten years the ages will be a+10 and b+10 which are in the ratio 3:4.
so 4(a+10) = 3(b+10) and a=b/2 .
on solving the two equations we get b=10.
hence the present age of B=20 whereas present age of A=15 , therefore the sum of their ages is 35

Like? Yes (1) | No (1)  

Lavanya Rajendran   9 years AGO

(A-10)=1/2(B-10) , A/B = 3/4 , A /2A-10= 3/4 , A= 15 , 5=1/2(B-10),B=20 , 20+15=35

Like? Yes (1) | No (1)  

shivaprabhu   9 years AGO

A-10=(B-10)/2

A/B=3/4

A=(3/4)B

solving
we get A=15 B=20 so A+B=35

Like? Yes (1) | No (1)  

sravani   9 years AGO

from given question
A will be 20
B will be 15
A+B=35 Years

Like? Yes (1) | No (1)  

asim   9 years AGO

Let present age be A and B respectively ,
10 years ago (A-10) = (B-10)/2 ..............................(i)
present ratio is A : B :: 3 : 4
=> 4A = 3B .....................................................................(ii)

on solving eq (i) and (ii) ,
we get
B = 20 => A = 15

A + B = 15 +20 = 35 i.e. option 3

Like? Yes (1) | No (1)  

Rakesh Kumar Thakur   9 years AGO

Let present age of A & B be 3x & 4x respectively.
10 yrs ago, according to given condition

(3x-10)=(4x-10)/2;
solving the above equation , we get x=5;
Therefore present age of A & B is 15yrs & 20yrs..
sum=15+20=35yrs

Like? Yes (1) | No (1)  

15 Jun 2015 Sequence

What is the next number of the following sequence.
17, 27, 44, 64, 108, 138, .....

OPtion

1) 238
2) 240
3) 242
4) 256
5) 258
6) 276
7) 266
8) 269
9) 246
10)208

Solution

17
17+10 = 27

17+27 = 44
44+20 = 64

44+64 = 108
108+30 = 138

108+138 = 246

Option 9)

Correct Option: 9 Best Solution (57)

Supriya Mondal   9 years AGO

There are two series. They are-
17,44,108,? and 27,64,138
We have to find ? mark so that we find the 7th term of the series
For first series
2nd term=17*2+10=44
3rd term=44*2+20=108
so, 4th term=108*2+30=246
For second series
2nd term= 27*2+10=64
3rd term=64*2+10=138
So, option 9)246 is the right answer

Like? Yes (3) | No   

pradeep sarathe   9 years AGO

here increase second number by 10
you will get 17+10=27
17+27=44
44+20=64
44+64=108
108+30=138
108+138=246
so next term is 246

Like? Yes (2) | No (1)  

sravani   9 years AGO

17+27=44
44+20=64
64+44=108
108+30=138
108+138=246

Like? Yes (1) | No   

kiruthika   9 years AGO

the first two has difference of 10 and next no is first no multiplied by 2 and add the difference

Like? Yes (1) | No   

M,MATHIVANI   9 years AGO

the second no is +10 of the previous, the third is scond+first no,fourth is +20 of the previous, fifth is fourth +third, and it goes on, so the right one is 138+108=246

Like? Yes (1) | No   

Pradeep   9 years AGO

246
17+27=44
44+20=64
44+64=108
108+30=138
108+138=246

Like? Yes (1) | No   

ROHIT JAIN   9 years AGO

17*2+10=44
27*2+10=64
44*2+20=108
64*2+10=138
108*2+30=246

Like? Yes (1) | No   

kishor Mali   9 years AGO

gaps are 10,17,20,44,30....so next is 108...and no is 138+108=246
alternative squence are there....

Like? Yes (1) | No   

SANTOSH   9 years AGO

17 * 2 = 34 +10 =44
44 * 2 = 88 +20 =108
108 * 2 =216 +30 =246

Like? Yes (1) | No   

neelabh   9 years AGO

Add 10 to the first number & than add the number itself to the result to get the next number. Than add 20 to get the next number & again add the number itself to get the another number . Than 30 and so on

Like? Yes (1) | No   

Bholanath    9 years AGO

17 + 10 = 27
27 + 17 = 44
44 + 20 = 64
64 + 44 = 108
108 + 30 = 138
so,
138 + 108 = 246 Ans.

Like? Yes (1) | No   

Chirag Jindal   9 years AGO

27-17=10
44-27=17
64-44=20
108-64=44
138-108=30

17 ,44 ,108
therefore
138+108=246

Like? Yes (1) | No   

sompon temtheerakij   9 years AGO

17
27 = 17+10
44 = 17+27
64 = 44+20
108 = 44+64
138 = 108+30
246 = 108+238

Like? Yes (1) | No   

UDIT   9 years AGO

17+10=27
27+17=44
44+10+10=64
64+44(previous term)=108
108+10+10+10=138
138+108(previous term)=246(ANS.)
OPTION 9 IS ANS.

Like? Yes (1) | No   

k sureshbabu   9 years AGO

17+27=44
,ten gap between 17&27
44+64=108
,twenty gap bet ween 44&64
108+138=246
thirty gap bet ween 18&138

Like? Yes (1) | No   

Ramdas Singathiya   9 years AGO

17 +10=27,
44+20=64,
108+30=138..... make pairs of two nos and the difference between them is 10,20,30..
now add no. in each pair will provide next pair's first no...so here 108+138=246

Like? Yes (1) | No   

Jotshnesh Patel   9 years AGO

Answer is 246

17+27=44
44+64=108
108+138=246

so Next number is 246.

Like? Yes (1) | No   

K.M.AYESHA SHARMIL JAHAN   9 years AGO

given sequence: 17,27,44,64,108,138,.......................
27-17 =10
44-27 =17
64-44 =20
108-64 =44
138-108=30
therefore,next number should be 138+108=246

Like? Yes (1) | No   

Ayan Patra   9 years AGO

17 + (10 x 1) = 27
27 + 17 = 44
44 + (10 x 2) = 64
64 + 44 = 108
108 + (10 x 3) = 138
138 + 108 = 246

Every odd term i in the sequence is the sum of the (i-1)th and the (i-2)th term.

Like? Yes (1) | No   

virendra tiwari   9 years AGO

17=10=27
27+17=44
44+20=64
64+44=108
108+30=138
138+108=246 answer

Like? Yes (1) | No   

Divyabala R   9 years AGO

The sequences can be calculated as 17+1(10)= 27
27+(17)(previous sum)= 44
44+2(10)=64
64+44(previous sum)=108
108+3(10)=138
138+108(previous sum)=246

answer is 9

Like? Yes (1) | No   

Math Lovers   9 years AGO

17, 27, 44, 64, 108, 138, .....


numbers at even place
64 = 27 +37 = 27 +(27+10)
138 = 64 +74 = 64 + (64+10)
numbers at odd place
44 = 17 + 27
108 = 44 + 64

hence ,
last term = 108 +138 = 246

Like? Yes (1) | No   

ganesh babu   9 years AGO

17,
17+10=27,
27+17=44,
44+20=64,
64+44=108,
108+30=138,
138+108=246

Like? Yes (1) | No   

Arish M R   9 years AGO

17+10=27
27+17(the previous number)=44
44-20=64
64+44(the previous number)=108
108+30=138
138+108(the previous number)=246

Like? Yes (1) | No   

Aakash   9 years AGO

17 +10 = 27
17+ 27 =44
44 +20 = 64
44+ 64 = 108
108 + 30= 138
108 + 138 =246

Like? Yes (1) | No   

Emanuel Abhishek Murmu   9 years AGO

17,27,44,64,108,138,___

In the above series,
27-17=10
44-27=17
64-44=20
108-64=44
138-108=30
so, according to the above patter the next term will be as follows:
138+108= 246

Like? Yes (1) | No   

swetha   9 years AGO

27-17=10
44-27=17
64-44=20
108-64=44
138-108=30
246-138=108

Like? Yes (1) | No   

Apurv   9 years AGO

17+10=27
17+27=44
44+20=64
44+64=108
108+30=138
108+138=246, Ans

Like? Yes (1) | No   

R.AMARAVATI   9 years AGO

27-17=10
,44-27=17,
64-44=20,
108-64=44,
138-108=30,
246-138=108. the diff is incresing by 10 alternately and alternately v r gettng previous no.

Like? Yes (1) | No   

RAVAL   9 years AGO

ans.246
because,,,
17 27 44 64 108 138 246
10 17 20 44 30 108

Like? Yes (1) | No   

Ketaki Dhanorkar    9 years AGO

17*2+10=44
44*2+20=108
so,
108*2+30=246

Like? Yes (1) | No   

Divyansh jaiswal   9 years AGO

17+10=27->27+17=44->44+20=64->64+44=108->108+30=138
so 138+108=246

Like? Yes (1) | No   

Vinithalakshmi   9 years AGO

17+10=27 then that 17 is added with 27 to get 44.44+20=64 then 44 is added to get 108.then 108+30=130,then that 108 is to be added to get 138+108=246

Like? Yes (1) | No   

Parvathi.R   9 years AGO

17+27=44
44+64=108
similarly
108+138=246

Like? Yes (1) | No   

himanshu   9 years AGO

27-17=10
27+17=44

64-44= 20
64+44=108

138-108= 30
138+108=246

Like? Yes (1) | No   

Mehul D Parmar   9 years AGO

17+10=27 27+17=44
44+20=64 64+44=108
108+30=138 138+108= 246

Like? Yes (1) | No   

Deepak   9 years AGO

44 - 27 = 17
108 - 64 = 44
x - 138 = 108, thus unknown number, x = 138+108 = 246

Like? Yes (1) | No   

anmol jain   9 years AGO

add 2 elements
17+27,
44+64
108+138

Like? Yes (1) | No   

anamika sahu   9 years AGO

every time 10 is added then next is the sum of the previous number
17+10=27+17=44+20=64+44=108+30=138+108=246

Like? Yes (1) | No   

Debraj Ghosh   9 years AGO

17+10=27
17+27=44

44+20=64
44+64=108

108+30=138
108+138=246

Like? Yes (1) | No   

aashish kumar   9 years AGO

17+10=27
27+17=44
44+20=64
64+44=108
108+30=138
138+108=246

Like? Yes (1) | No   

asim   9 years AGO

if we give index number to each of the given number , we get our series as :

index no - given no
1 - 17
2 - 27
3 - 44
4 - 64
5 - 108
6 - 138
now , through inspection we can say that difference between number with odd index with even index is multiple of 10 i.e. 27-17 = 10 , 64-44 = 20 , 138-108 = 30
&
difference between number of even index with odd index is previous number stored at odd index i.e.
44-27 = 17 (located at index 1) , 108-64 = 44 (located at index 3) .
hence , next number will be 138 + 108 = 246

Like? Yes (1) | No   

pragya   9 years AGO

you add 10 to 1st no. to get 2nd no. then add 1st two no. to get 3rd. now add 20 to 3rd to get 4th no. n add 3n 4th no. to get 5th no. now add 30 to 5th no. to get 6th no. n add 5th n 6th to get 7th which is option 9

Like? Yes (1) | No   

Priyal Walmiky   9 years AGO

The differences between the 1st and 2nd number, the 3rd and the number and the 5th and 6th number is in the multiples of 10 respectively
i.e., 27-17=10
64-44=20
and 138-108=30
Now, the first two numbers are added to get the 3rd number i.e.,
17+27=44
Similarly
44+64=108
So the next number in the sequence would be
108+138=246

Like? Yes (1) | No   

VISHAL KUMAR   9 years AGO

17+10=27
17+27=44
44+20=64
44+64=108
108+30=138
108+138=246

Like? Yes (1) | No   

v v shyam kumar   9 years AGO

the given series is in the form
17 44 108 x;
then
17*2+10 gives the next no. which is 44
simlarly 44*2+20 which gives 108.
so,the required no. is
108*2+30 which is 246.

Like? Yes (1) | No   

pradeep   9 years AGO

difference between 27-17 =10
44-27 =17
64-44 = 20
108-64 =44
138-108=30
x-138=108
x=246

Like? Yes (1) | No   

Kalpesh   9 years AGO

17+10=27
then 27+17=44
then 44+20=64
44+64=108
then 108+30=138
then 138+108=246

Like? Yes (1) | No   

suresh unnam   9 years AGO

17+10=27
27+17=44
44+20=64
64+44=108
108+30=138
138+108=246

Like? Yes (1) | No   

Usha Nandhini   9 years AGO

if we give index number to each of the given number , our series will be :
index no - given no
1 - 17
2 - 27
3 - 44
4 - 64
5 - 108
6 - 138
now , through inspection we can say that difference between number with odd index with even index is multiple of 10 i.e. 27-17 = 10 , 64-44 = 20 , 138-108 = 30
&
difference between number of even index with odd index is previous number stored at odd index i.e.
44-27 = 17 (located at index 1) , 108-64 = 44 (located at index 3) .
hence , next number will be 138 + 108 = 246

Like? Yes (1) | No   

Priyadarshni Somasundaram   9 years AGO

first number is added by 10 to get the second number and first two numbers are added to get the third number.similarly third number is added with 20 to get fourth and third and fourth numbers are added to get the fifth number.similarly the it goes on....

Like? Yes (1) | No   

Karthick Raja   9 years AGO

increase second number by 10
you will get 17+10=27
17+27=44
44+20=64
44+64=108
108+30=138
108+138=246
Next term is 246

Like? Yes (1) | No   

aman aditya   9 years AGO

add 1st and 2nd term they become 3rd term
4th term add 10 then 20... so on

Like? Yes (1) | No   

ABHISHEK   9 years AGO

DIVIDE SERIES IN TWO PARTS
17*2+10= 44 27*2+10=64
44*2+20= 108 64*2+10= 138
108*2+30= 246

Like? Yes (1) | No   

RAKESH   9 years AGO

17+27=44
44+64=108
108+138=246

Like? Yes (1) | No   

Atishay jain   9 years AGO

sum of two elements with their adjacent elements is equal to next number..
17+27=44
44+64=108
108+138= 246
so option 9 (246) is correct....

Like? Yes (1) | No   

santhosh   9 years AGO

17+17=34+10=44
44+44=88+20=108
108+108=216+30=246

Like? Yes (1) | No   

12 Jun 2015 Time, distance and speed

Two trains starting at the same time from two stations 200 km apart and going in opposite directions cross each other at a distance of 110 km from one of them. The ratio of their speeds is

OPtion

1) 11:20
2) 11:21
3) 9:20
4) 8:9
5) 11:9
6) 11:10
7) 7:8
8) 11:7
9) 5:6
10)11:12

Solution

Let their speeds be x km/hr and y km/hr. Then, time taken by 1st to cover 110 km = time taken by other to cover 90 km
x/110 = y/90
x/y = 11/9
11:9

Option 5)

Correct Option: 5 Best Solution (60)

Ayan Patra   9 years AGO

When the two trains cross each other then one of the train has travelled 110 km and another has travelled 200-110 = 90 km.
If time taken to cross is t then the speeds of the trains are 110/t and 90/t.
Therefore the ratio of their speed is 110/t : 90/t = 11: 9.

Like? Yes (15) | No (3)  

Supriya Mondal   9 years AGO

Let, first train distance covered 110 km and at the same time second train distance covered (200-110)=90 km
So,ratio of there speed is=110:90
=11:9
So, option 5)11:9 is the right answer

Like? Yes (6) | No   

pradeep sarathe   9 years AGO

as both the trains start at same time and take equal time for covering respectively 110 km and 90 km.

so the ratio of the speed is proportional to their respective distances covered.

let train a covers 90 km and b covers 110 km then ratio = a:b=110/90=11:9

Like? Yes (3) | No   

shankar jha   9 years AGO

lets the speed o the trains s1 and s2 . then from the given condition,
110/s1=90/s2;
so, s1/s2=11/9

Like? Yes (2) | No   

W J Krishna Teja   9 years AGO

they are 200km apart
let the two trains be A and B
They met at 110 km frm one of the trains so tym taken to travel 110 km for one train and remaining 90 km fr another train is same. let the speed of A be x and speed of B be y
then 110/x=90/y
=>x/y=110/90=11/9
required ratio is 11:9

Like? Yes (1) | No   

shivaprabhu   9 years AGO

Let 'A' and 'B' are two stations located 200km apart

Let 'Ta' be the train departing from Station 'A'
Let 'Tb' be the train departing from Station 'B'
Let 'X' be the time taken to meet each other

Let the trains will meet at 110km from station 'A'

Hence speed of train Ta is Va=110/X

Therefore the distance covered by Train Tb in time X is 200km-110km=90km

Therefore speed of Train Tb is Vb=90/X

Therefore speed ratio is Va/Vb=110/90

Hence Va:Vb=11:9

Like? Yes (1) | No   

Karthick Raja   9 years AGO

speed(s)= distance(d)/time(t)
so for train1
s1=(d1)/(t1)
for train2
s2=(d2)/(t2)
we can assume train1 is travels110km at a time t1
and train 2 travels 90km at time t2
two trains are started at same time so the time for crossing each other is same
so t1=t2
we can find speed ratio
s1:s2
(d1/t1):(d2/t2)
t1=t2
so
d1:d2
110:90
11:9
the ratio of speed is 11:9

Like? Yes (1) | No   

Pranati Kundu   9 years AGO

110:90=11:9

Like? Yes (1) | No   

vishal chandrola   9 years AGO

We know total distance is 200 Km
If both trains crossed each other at a distance of 110 km then one train covered 110 km and other 90 km [110+90=200km]
So ratio of their speed = 110:90 = 11:9

Like? Yes (1) | No   

Rahul Bajaj   9 years AGO

S1/S2 => D1/T1 = D2/T2 => D1/D2 => 11/9 or 9/11

Like? Yes (1) | No   

SAYAN CHATTERJEE   9 years AGO

velocity ratio
=(110/t : 90/t)
=11:9 (5).

Like? Yes (1) | No   

Dinni   9 years AGO

We know total distance is 200 Km
If both trains crossed each other at a distance of 110 km then one train covered 110 km and other 90 km [110+90=200km]
So ratio of their speed = 110:90 = 11:9

Like? Yes (1) | No   

kishor Mali   9 years AGO

the ratio of their distance is 110:90 ie 11:9
so the speed dirctly prop so also 11:9 time is same...bcoz they cover distance in same time..

Like? Yes (1) | No   

sai   9 years AGO

speed directly propotional to disatance so 110:90= 11:9

Like? Yes (1) | No   

vini   9 years AGO

Distance between the station is 200 km
Two trains starting at same time. Equate to train
Let 'x' be the speed of Train 1 and 'y' be the speed of the Train 2.
Train 1 Time = 110/x
Train 2 Time = 90/y
So, 110/x = 90/y
x:y = 11:9

Like? Yes (1) | No   

Debraj Ghosh   9 years AGO

if one train goes 110km/hr,other goes 90km/hr.....after one hour 1st train will meet with 2nd train at a point

Like? Yes (1) | No   

k sureshbabu   9 years AGO

same time so
one is @110
another @90 so 11:9

Like? Yes (1) | No   

sravani   9 years AGO

Same time (given) let it be t.
Let the Speed of one be x and the other be y...
distances travelled by them are 110 and 90 so xt/yt = 110/90
so the ratio of speeds is 11:9

Like? Yes (1) | No   

kranthi kanchanapally   9 years AGO

If the train cross each other at a distance 110km from one of the stations,at same time they cover 110km and 90km respectively
sp ratio of their speed is =110:90
11:9is the correct answer

Like? Yes (1) | No   

Srinivas Rao   9 years AGO

TOTAL 200 KM
TRAIN A COVERED 110 KM IN AN HOUR ASSUME
TRAIN B COVERED 90 KM IN SAME HOUR
RATION BETWEEN THEM IS 11:9

Like? Yes (1) | No   

neha gupta   9 years AGO

Both will cover different distances in equal interval of time at the point where they meet. Let they meet in time x hours.
then for A speed=110/x
and for B speed=90/x
Dividing both we get 11:9

Like? Yes (1) | No   

Shweta   9 years AGO

speed1=distance1/time for 2nd train speed2=distance1/time
time will be same for both train and one train cover distance 110 so 2nd train will cover 90 km distance so
s1=110/t s2=90/t
so comparing both we will gate s1/s2=11/9
i.e. 11:9

Like? Yes (1) | No   

Sravanthi Aasa   9 years AGO

Total distance=200km and they crossed each other at a distance of 110km from one of them so...
Let distance traveled by train1=110km
Let distance travelled by train2=90km
we have speed=distance/time.i.e.,s=(d/t)
so s1:s2=(d1/t1):(d2/t2)
time taken by 2 trains is same
so s1:s2=(110/T):(90/T)--->s1:s2=11:9

Like? Yes (1) | No   

BODAGALA VENKATA SIVA PRAKASH   9 years AGO

because first train traveled distance is 110km, second train traveled distance is 90kms.

Like? Yes (1) | No   

Kamlesh Kumar   9 years AGO

if train cross each other 110
total distance is 200Km
so 200-110=90
110:90
11:9

Like? Yes (1) | No   

swetha kanduri   9 years AGO

one train travels 110 kms and other train travels 90kms at their meeting point. the time is constant so speed ratio is directly proportional to distance ratio

Like? Yes (1) | No   

B.venkata suresh   9 years AGO

in the same time ,they cover 90 & 110 km respectively
the ratio of the speeds is 110:90=11:9

Like? Yes (1) | No   

aastha sharma   9 years AGO

since they cross each other when one train is 110km apart from one station so it means it has travelled a distance of 110km so distance travelled by the other train is (200-110)Km which is 90Km. Therefore ratio of their speeds is 11:9

Like? Yes (1) | No   

swetha   9 years AGO

speed is directly proportional to distance
the distance covered by one train is 110 km and the remaining is 90 km
therefore the ratio is 11:9

Like? Yes (1) | No   

ravi singh   9 years AGO

answer is 11:9
since one cover 110 km therefore other cover 90 km

since time is same hence,
(v1/v2)= 11:9

Like? Yes (1) | No   

Y M ANIEF   9 years AGO

at constant duration of journey there speeds are directly proportional to distance.

Like? Yes (1) | No   

Shashirekha   9 years AGO

both train started at same time and time taken by one train to travel 110km is same as time taken by other train to travel 90km( 200-110 as given in the problem)
so ratio of speed is same as ratio of distance covered
hence s1/s2 = d1/d2 = 110/90 = 11/9
i.e., 11:9 hence option 5)

Like? Yes (1) | No   

keerthi   9 years AGO

its a guess work answer i dont know whether it is correct or wrong please clearly explain the answer

Like? Yes (1) | No   

Deepak   9 years AGO

Speed is proportional to distance covered.
ratio of distances covered is 110 : 90
speed ratio = 110 : 90 = 11 : 9

Like? Yes (1) | No   

ammar   9 years AGO

Since time taken by both train is same, therefore ratio of their speeds is same as ratio of distance travelled by them.
Hence the required ratio = 110:90 = 11:9

Like? Yes (1) | No   

RAVAL   9 years AGO

total distance between two station is 200 km.
now consider two station A & B.
dAB=200km
so at 110km between station A & B , both train cross each other.
therefore any one train cover distance 110km & other cover 90km from their source with same time
ans.=== 11:9

Like? Yes (1) | No   

krishna soni   9 years AGO

let two train be A and B travelling in opposite dirction.
speed=distance/time
taking ratio of speed of two train=distance travelled by train A/distance travelled by train B

Like? Yes (1) | No   

anmol jain   9 years AGO

in same time distance covered by them is 110km and 90 km
so ratio =110/90

Like? Yes (1) | No   

Mehul D Parmar   9 years AGO

here time is same..
one train cut other train at 110 thn other train distance of his position is 90
then

t1=t2
and
d1/s1=d2/s2

put d1 and d2 then

ans is
11:9

Like? Yes (1) | No   

SANTOSH   9 years AGO

speed of 1st train is 110/t
speed of 2nd train is 90/t

ratio 11/9

Like? Yes (1) | No   

sompon temtheerakij   9 years AGO

time of train A = time of train B
distance A/speed A = distance B/speed Bspeed A/speed B = 110/90 = 11/9

Like? Yes (1) | No   

Ipshita   9 years AGO

distance from train 1 = 110 Km .....(dist1)
therefore, distance from train 2 = 200-110= 90 Km .....(dist2)
speed= distance/time

time of meeting for both the trains is same, so
speed of train1/speed of train 2 = dist1/dist2 = 110/90= 11:9

Like? Yes (1) | No   

Anjan kumar   9 years AGO

one train at 110km...and other at 90km....speed = distance covered by trains...so 110:90 = 11:9

Like? Yes (1) | No   

pratap kumar sahoo   9 years AGO

let train A cross 110km in time T
so,B will cross 90 km at time T
s1:s2=11/9

Like? Yes (1) | No   

Mamtha   9 years AGO

First train covers 110 km and second time 90 km in the same time.
Equating the time,
110/s1=90/s2
-> s1/s2=11/9

Like? Yes (1) | No   

Deepak kushwaha   9 years AGO

Let us name the speed of the Train reaching v(110), and the slower one which reached 90 km we name v(90).
Both Trains have used the same time t when they meet.
t*v(110)/tv(90)=110/90.
so the answer is 11:9

Like? Yes (1) | No   

Shiva Sharma   9 years AGO

they meet at distance 110 km from one
and 90 km from second and let time is t
speed of one = 110/t
speed of second = 90/t
ratio of their speed = (110/t)/(90/t)
=> 11/9

Like? Yes (1) | No   

K.M.AYESHA SHARMIL JAHAN   9 years AGO

two trains cross each other at a distance of 110m.time taken by the two trains to cross each other is same,so by appling direct formula we can get the answer
t is constant speed=distance/time
for first train(t1) ,s1=110/t (s1=speed of t1)
for second train(t2),s2=90/t (s2=speed of t2)
s1:s2=11:9

Like? Yes (1) | No   

SOHINI GHOSH   9 years AGO

The answer is 11:9 because one train has travelled 110km and the other 90km in the same time.So the ratio of their speeds is 110:90=11:9. The 90km comes from subtracting 110 from 200 as the total distance between both the trains is 200.

Like? Yes (1) | No   

KARTHIKA.N   9 years AGO

s=d/t;
s1=110/t;
s2=90/t;
s1:s2=11:9

Like? Yes (1) | No   

RAKESH ARYA   9 years AGO

ratio = 110/(speed of 1st train ) : 90/ (speed of 2nd train)
or, 90/ (speed of 1st train) : 110/(speed of 1st train )

= 11:9 or 9:11

Like? Yes (1) | No   

Swetha   9 years AGO

Let us assume that one train has reached 110km in 1hr n the other train reached 90km in 1hr. So,
110:90=11:9

Like? Yes (1) | No   

junaid   9 years AGO

Distance covered is in ratio 110:90. simplified form will be 11:9

Like? Yes (1) | No   

KRISHNA BANDLA   9 years AGO

let consider,one train reach 110km in hour and another train reach 90km in one hour.so,the answer is 11:9

Like? Yes (1) | No   

LETAN MALLICK   9 years AGO

Two train has travelled d1=110 km & d2=90 km respectively in time say t.
now , t=distance/speed=d/s

as time is same so
t1=t2
d1/s1=d2/s2
110/s1=90/s2
110/90=s1/s2

therefore
s1/s2=11:9

Like? Yes (1) | No   

mohita verma   9 years AGO

let d1 and d2 be the distance of train1 and train2
ratio of speed of train1(s1) to train2(s2) is
s1/s2=d1/d2 (since time taken by them is same)
s1/s2=110/90 (d2=200-d1)
i.e. 11:9

Like? Yes (1) | No   

Kethineni Vinodh   9 years AGO

distance=110:90 or 90:110
then speed= 11:9 or 9:11

Like? Yes (1) | No   

RAHUL KUMAR   9 years AGO

In the same time they cover 110 Km and 90 Km respectively.
So the ratio of their speeds = 110:90 = 11:9

Like? Yes (1) | No   

ROHIT JAIN   9 years AGO

In same time, they cover 110km & 90 km respectively.
For the same time speed and distance is inversely proportional.
so ratio of their speed =110:90= 11: 9

Like? Yes (1) | No (1)  

viswambher   9 years AGO

since both trains take equal time to reach other, one of the trains cover 110km and the other covers 90km, which means that the ratio of their seeds is 11:9

Like? Yes (1) | No (1)  

11 Jun 2015 4 digit number

A 4 digit number having all distinct digits is such that the product of all digits is 8 less than the sum of all digits. How many such 4 digit number are possible.

OPtion

1) 21
2) 18
3) 9
4) 72
5) 45
6) 54
7) 63
8) 36
9) 51
10)27

Solution

Since sum of all distinct digits is more than their product so definitely one of the digits will be zero. Since sum is 8
only two cases arise
0,1,2,5 and 0,1,3,4
No of numbers having
0,1,2,5 are 3*3*2*1 = 18
Similarly for other
Total 36

Option 8)

Correct Option: 8 Best Solution (9)

Ayan Patra   9 years AGO

Since product of all digits is 8 less than the sum of all digits, it is only possible if one of the four digit is 0.
Now if one digit is 0 the possible combination of digits that satisfies the above mentioned condition are 0, 1, 2, 5 and 0, 1, 3, 4.
Now digits starting with 0 are not considered as 4 digit numbers so the number of valid 4 digit numbers that can be formed from each set of numbers are = 4! - 3! = 18.
For 2 sets = 18 x 2 = 36 numbers containing 4 digits can be formed.

Like? Yes (10) | No   

Supriya Mondal   9 years AGO

Two numbers are satisfy the above condition.
They are- 1250 and 1340
we can write 1250 in 3*3*2*1=18 ways
similarly we can write 1340 in 18 ways too
So, total 18+18=36 such 4 digits numbers are possible
So, option 8)36 is the right answer

Like? Yes (4) | No   

Ashwin Dinesh   9 years AGO

1,0,2,5 ---> 18
1,0,3,4 ---> 18
18+18=36
which is option 8

Like? Yes (2) | No   

Math Lovers   9 years AGO

Suppose number is abcd
then a*b*c*d + 8= a+b+c+d
where a!=b!=c!=d
its only possible when either of a, b, c or d is 0
hence,
8 = sum of 3 single digit number = a+b+c

=> (a,b,c) = (4,3,1) or (5,2,1)
now (4,3,1,0) can be arranged in 18 different ways to make 4 digit number.
in similar way,
now (5,2,1,0) can be arranged in 18 different ways to make 4 digit number.

so total 4 digit number = 36

Like? Yes (1) | No   

pratap kumar sahoo   9 years AGO

no possible=4301
4_ _ _ =6
3_ _ _ =6
1_ _ _ =6
5201
5 _ _ _=6
2 _ _ _=6
1_ _ _=6
so ans=36

Like? Yes (1) | No   

shivaprabhu   9 years AGO

the only two numbers we have that satisfies the the condition is ith numbers 0125 and 0143


therefore total combinations using 4 digits is 4! i.e 24
but the number cannot start with 0 therefore total number of combinations for one number is =4!-3! i.e 18

i.e number of combinations using both numbers is=36

Like? Yes (1) | No   

kishor Mali   9 years AGO

posssible comb are 0,1,3,4 and 0,1,2,5

1) 0,1,3,4 the 4 digit no for this is 18
2) 0,1,2,5 the 4 digit no for this is 18
so total 36

Like? Yes (1) | No   

vini   9 years AGO

The digit are 0, 1, 2 , 3 ,4 ,5 ,6 ,7,8, 9
Let the product of four number is 'A'
and sum of four number be 'B'
B - A = 8 (Given)
So the possible number are
Case 1
0 1 3 4
3*3*2*1 = 18 ways
Case 2
0 5 2 1
3*3*2*1 = 18 ways
So, total possible four digit numbers are ( 18+18)= 36

Like? Yes (1) | No   

Dinni   9 years AGO

4,3,1,0 in 18 ways &
5,2,1,0 in 18 ways.
Total 36 4-digit no.s will get.

Like? Yes (1) | No   

10 Jun 2015 Ration and Proportion

A and B are two alloys of gold and copper prepared by mixing metals in the ratio 7:2 and 7:11 respectively. If equal quantities of alloys are melted to form a third alloy C, find the ratio of gold and copper in C.

OPtion

1) 1:3
2) 3:7
3) 5:9
4) 7:5
5) 2:9
6) 11:18
7) 7:6
8) 5:6
9) 2:5
10)2:3

Solution

Let 1 kg of each one of A and B be taken to form 2 kg of C.
Gold in 1 kg of A = 7/9, copper in 1 kg of A = 2/9
Gold in 1 kg of B = 7/18, copper in 1 kg of B = 11/18
Gold in 2 kg of C = (7/9 + 7/18) = 21/18 = 7/6
Copper in 2 kg of C = (2/9 + 11/18) = 15/18 = 5/6
Ratio of gold and copper in C = 7/6 : 5/6 = 7:5

Option 4)

Correct Option: 4 Best Solution (46)

Supriya Mondal   9 years AGO

Ratio of gold and copper in C will be=(7/9+7/18):(2/9+11/18)
=(21/18):(15/18)
=7:5
So, option 4)7:5 is the right answer

Like? Yes (41) | No (9)  

Ayan Patra   9 years AGO

In alloy A per (7+2) 9 unit, gold is 7 and copper is 2.
In alloy B per (7+11) 18 unit, gold is 7 and copper is 11.
So to mix A and B in equal quantity we need 2 x A for each B.
So 2 x A means - gold:copper = 14:4
Now alloy C = A + B = 14:4 + 7:11 = 21:15 = 7:5.
Therefore new alloy has gold:copper at 7:5 ratio.

Like? Yes (38) | No (7)  

Dinni   9 years AGO

Ratios and proportions
Gold in c =7/9+7/18=21/18.
Copper in c =2/9+11/18=15/18.
Gold & cu ratio =(21/18)/(15/18) = 21/15 = 7/5.

Like? Yes (19) | No (1)  

RAKESH   9 years AGO

(7/9 + 7/18 ) : (2/9 +11/18)

= 21:15 = 7:5

Like? Yes (24) | No (7)  

Pranati Kundu   9 years AGO

IN A Alloy-multiply 7:2 by 2, u get 14:4 now total parts are 18 in A alloy and total parts in B alloy are also 18 that is 7:11.now u can add directly gold with gold and copper with copper bcz total parts are equal.7+14:4+11.u get 21:15 which is equal to 7:5

Like? Yes (9) | No   

Karthick Raja   9 years AGO

in alloy A the ratio of gold and copper is 7:2
in alloy B the ratio of gold and copper is 7:11

in c alloy equal quantities of alloy A and Alloy B mixed
so we didn't considered quality

amount of gold in alloy A 7/9
Amount of gold in alloy B 7/18

total amount of gold in alloy c = (7/9)+(7/18)=21/18. for 1 quantity of Alloy A and Alloy B

total amount of copper in alloy A = (2/9)
total amount of copper in alloy B = (11/18)
total amount of copper in alloy C =(2/9)+(11/18)=(15/18) for one quantity mixture of alloy A and alloy B.

In Alloy C the ratio of Gold and Copper is (21/18):(15/18)

21*18:15*18
21:15
7:5
so the ratio of gold and copper ratio in alloy C is 7:5

Like? Yes (8) | No   

sompon temtheerakij   9 years AGO

equal quantities , so
A ; gold : copper = 14 : 4
B : gold : copper = 7 : 11
C : gold : copper = 21 : 15 = 7 : 5

Like? Yes (4) | No   

SAYAN CHATTERJEE   9 years AGO

in the new alloy -- gold:coppper
=(7x/9+7x/18):(2x/9+11x/18)
= 7:5 (4).

Like? Yes (4) | No   

anubhav verma   9 years AGO

for b in 18 we have 7g and 11c. therefore for 9 we get 3.5g and 5.5g . now quantity of a and b are same hence 7+3.5=10.5g and 2+5.5=7.5c...
ratio105:75=7:5

Like? Yes (3) | No   

ravi singh   9 years AGO

answer is 7:5

since quantity is same hence,
in alloy A gold is 14 and copper is 4
and in alloy B gold is 7 and copper is 11
hence in alloy C gold is 21 and copper is 15
hence ratio is 21:15=7:5

Like? Yes (4) | No (1)  

shivaprabhu   9 years AGO

gold in alloy Ag =7/9 and copper is Ac=2/9

similarly gold in alloy B is Bg=7/18 and copper Bc=11/18
since equal quantities are melted to for alloy c
therefore gold in alloy C is Cg=(Ag+Bg)/2
i.e Cg=(7/9 +7/18)/2
= 7/12
similarly
Cc=(2/9 +11/18)/2
=5/12

Therefore ratio of C is C=Cg/Cc
=(7/12)/(5/12)

Ans C=7:5

Like? Yes (3) | No   

Math Lovers   9 years AGO

for metal A-
gold = 7x kg
copper = 2x kg

for metal B
gold = 7y kg
copper = 11y kg

now for same quatities -

7x + 2x = 7y+11y
=> x = 2y

so in metal C

ratio = total gold/total copper = (7x+7y)/(2x+11y)
put x=2y and solve

so ratio = 21/15 = 7/5

Like? Yes (3) | No   

Maria   9 years AGO

Total gold=7x/(7+2)+7x/(7+11)=21x/18
Total copper=2x-21x/18=15x/18
so ratio of gold and copper to make alloy c is 21x:15x=7:5

Like? Yes (2) | No   

Venkatesh kadali   9 years AGO

g : c
a: 7:2 *2 -->a: 14:4
b: 7:11 -->b: 7:11 differences are equal
c: a+b:a+b=14+7:4+11
=21:15
c=7:5

Like? Yes (4) | No (2)  

viswambher   9 years AGO

in alloy A let there be 7kgs of gold and 2kgs of copper and in alloy B let there be 7kgs gold and 11kgs copper
so if 18 kgs of alloy A and 18 kgs of alloy B are mixed to form alloy C then in the alloy C there is 21 kgs of gold and 15kgs copper therefore it is in the ratio 7:5

Like? Yes (4) | No (2)  

prabhat kumar   9 years AGO

g=7/9+7/18=21/18
c=2/9+11/18=15/18
so new ratio will be 7/5

Like? Yes (2) | No   

P.ARUNA   9 years AGO

alloy 1=7:2
alloy 2=7:11
alloy 3=>gold=(7/9+7/18) : copper=(2/9+11/18)
=21:15
=7:5

Like? Yes (2) | No   

padam   9 years AGO

gold in alloy A=7/9 and copper is 2/9
gold in alloy B=7/18 and silver is 11/18
now in alloy c gold is 21/18 and silver is 15/18
ratio is 7:5

Like? Yes (4) | No (2)  

RAVAL   9 years AGO

here,
* B=2A
* 2A+B=C
so,C= 21:15= 7:5

Like? Yes (2) | No   

Ramdas Singathiya   9 years AGO

let assume first alloy=9kg and second alloy =18 kg
now mix 9 kg of each so in new alloy gold=10.5 kg and copper=7.5 kg so ratio=7:5

Like? Yes (1) | No   

vini   9 years AGO

Make the ratio to equal parts because equal quantities are taken to C
In A 7:2
In B 7:11
B has 18 parts, making A to 18 parts so the ratio becomes 14:4( proportion wont change)
Mixing A and B into C
so the ratio of gold and copper in C is
21:15
ie., 7:5

Like? Yes (1) | No   

mohita verma   9 years AGO

the reason is very simple...
gold is {(7/(7+2))+(7/(7+11))}=21/18
silver is {(2/(7+2))+(11/(7+11))}=15/18
gold to silver ration is=21/15 i.e. 7:5

Like? Yes (1) | No   

Rohit Gurjar   9 years AGO

7/9+7/18= 2/9+11/18
21:18 =15:18
21:15
7:5

Like? Yes (1) | No   

Mani Sachdev   9 years AGO

gold in C=(7/9+7/18)=7/6
Copper in C=(2/9+11/18)=5/6
gold:Copper=7/6:5/6=7/5
7/5 Ans

Like? Yes (1) | No   

neha gupta   9 years AGO

Let 1kg of both alloys are taken
then in alloy A:
gold content=7/9
copper content=2/9
and in alloy B :
gold content=7/18
copper content=11/18
If they are mixed together then :gold content=7/9 + 7/18 = 21/18
copper content=2/9+ 11/18 = 15/18
Dividing both we get 21:15 = 7:5

Like? Yes (1) | No   

W J Krishna Teja   9 years AGO

In A gold and copper is in the ratio 7:2
let the copper and gold be in the amounts 14g and 4 g respectively.
In B copper and gold are in the ratio 7:11
let the amount of copper and gold be 7g and 11g respectively.
so, Now wt of A is 18 g(14g copper+4g gold)
and B is 18 g(7g copper+11g gold)
these equal amounts of A and B are mixed and melted to form C which contains (14+7)g copper and (4+11)g gold
therefore ratio of copper and gold in C is (14+7):(4+11)
= 21:15
= 7:5

Like? Yes (2) | No (1)  

B.venkata suresh   9 years AGO

gold in 2 kg C = 7/9 + 7/18

= 7/6 kg

And Quantity of copper in 2 kg C = 2 – 7/6

= 5/6 kg

∴ Required ratio = 7/6 : 5/6 = 7 : 5

Like? Yes (1) | No   

swetha   9 years AGO

Quantity of gold in A = 7/9* wt. of A

Quantity of gold in B = 7/18* wt. of B

If 1 kg of each A and B are mixed to form third alloys C.

Then quantity of gold in 2 kg C = 7/9 + 7/18

= 7/6 kg

And Quantity of copper in 2 kg C = 2 – 7/6

= 5/6 kg

∴ Required ratio = 7/6 : 5/6 = 7 : 5

Like? Yes (1) | No   

ammar   9 years AGO

First of all convert ratios to equal no. of parts.
Composition of alloy A = 2(7:2) = 14:4
Composition of alloy B = 7:11
After mixing,
No. of parts of gold in mixture = 14 + 7 = 21
No. of parts of copper in mixture = 4 + 11 = 15
Therefore, gold:copper = 21:15 = 7:5

Like? Yes (1) | No   

NESAB JAFAR   9 years AGO

7/9+7/18=21/18
2/9+11/18=15/18
mixture=21:18
7:5

Like? Yes (1) | No   

ROHIT JAIN   9 years AGO

we will add 7:2 which will become (7+2) 9 &
(7:11) 18.
LCM of 9 and 18 are 18.

so we will convert ratio into accordingly
now ratio became 7:2 to 14:4
& 7:11 will remain same.

now add respectively
New ratio = 21 : 15
= 7 : 5

Like? Yes (1) | No   

sai   9 years AGO

a gold=7/9 copper 7/18
b gold=7/18 copper 11/18
1:1 ratio
ixture 7:5

Like? Yes (1) | No   

saibabu   9 years AGO

gold in (7/9)+(7/18) units = 7/6 units
copper in (2/9)+(11/18) units = 5/6 units
c=gold=(7/6) : (5/6) = 7 : 5.

Like? Yes (1) | No   

HARMEET KAUR   9 years AGO

A and B are two alloys of gold and copper prepared by mixing metals in the ratio 7:2 and 7:11 respectively. If equal quantities (18 gms) of alloys are melted to form a third alloy C, then quantity of Gold and copper in C are (14+7=21gms) & (4+11=15 gms) respectively and hence ratio of gold to copper is 21:15 or 7:5.

Like? Yes (1) | No   

ADERU CHENCHU NITHISH   9 years AGO

gold=(7/9)+(7/18)=7/6
copper=(2/9)+(11/18)=5/6
so C alloy ratio=7:5

Like? Yes (1) | No   

Yashi Das   9 years AGO

Let 1kg of A and B be taken to form 2kg of C
Therefore,Gold in 1kg of A=7/9 ,copper in 1kg of A=2/9
Gold in 1 kg of B=7/18,copper in 1kg of B=11/18
Gold in 2 kg of C=(7/9+7/18)=7/6
Copper in 2 kg of C=(2/9+11/18)=5/6
Ratio of Gold to copper in C=(7/6):(5/6)=7:5

Like? Yes (1) | No   

veeramanikandan   9 years AGO

C={7/9+7/18} =7/6.
C={2/9+11/18}= 5/6
G:copper= 7/6:5/6=7:5

Like? Yes (1) | No   

udaya   9 years AGO

Gold ratio=7/9+7/18=21/18
copper ratio=2/9+11/18=15/18

gold ratio:copper ratio
21/18:15/18=7:5

Like? Yes (1) | No   

Thilaka Elangovan   9 years AGO

gold ratio=7/9+7/18 =7/6
copper ratio=2/9+11/18 =5/6
c's ratio = 7:5

Like? Yes (1) | No   

pratap kumar sahoo   9 years AGO

A:gold=7/9
copper=2/9

B:gold=7/18
copper=11/18

when A and B are mixed equally then,
gold=(7/9)+(7/18)=21/18
copper=(2/9)+(11/18)=15/18

so, G: C=7:5

Like? Yes (1) | No   

Rahul Raj Barnwal   9 years AGO

in alloy c for equal quantity of alloy 1 and alloy 2 there is
(7*2 + 7)/(2*2 + 11) = 21/15 = 7/5

Like? Yes (1) | No   

upama ghosh   9 years AGO

equal quantity lets say x kg of both the metals are mixd.so total quantity of gold is 7x/6 and copper is 5x/6.so ratio of two metals is 7:5

Like? Yes (1) | No   

RAKESH ARYA   9 years AGO

G:C= (7/9*1/2 + 7/18*1/2) / (2/9 * 1/2 + 11/18 *1/2 )
= 21/ 15
=7 /5
=7 :5

Like? Yes (1) | No   

manju   9 years AGO

9kg of A contains 7G, 2C
18Kg of B contains 7G, 11C
Take 18kg of A and 18kg of B
We get 21G, 15C
7: 5

Like? Yes (1) | No (1)  

Surit Datta   9 years AGO

After solving we get that the ratio of Gold and Copper is 7 : 5
so option 4
that's it.

Like? Yes (1) | No (1)  

vishal chandrola   9 years AGO

gold in alloy c=(7/9+7/18)=21/18=7/6 units
copper in alloy=(2/9+11/18)=15/18=5/6 units
ratio of gold:copper is

7/6:5/6= 7:5

Like? Yes (1) | No (1)  

09 Jun 2015 Time and Distance

A thief steals a car at 1.30 p.m. and drives it at 40 kmph. The theft is discovered at 2 p.m. and the owner sets off in another car at 50 kmph. he will overtake the thief at

OPtion

1) 3.30 p.m.
2) 4 p.m.
3) 4.30 p.m.
4) 5 p.m.
5) 5.30 p.m.
6) 6 p.m.
7) 6.30 p.m.
8) 6.45 p.m.
9) 7 p.m.
10)7.30 p.m.

Solution

Distance covered by the thief in 1/2 hour = 20 km
Now, 10 km is compensated in 1 hour
Therefore 20 km will be compensated in 2 hours
so, he overtakes the thief at 4 p.m.

Option 2)

Correct Option: 2 Best Solution (58)

Ayan Patra   9 years AGO

At 2 p.m. when the theft was discovered the thief has already travelled 20 km. [40 kmph * 1/2 hr = 20 km].
Let the owner overtake the thief after x hrs from 2 p.m.
By x hrs later from 2 p.m. the thief has travelled 40x + 20 km and the owner has travelled 50x km.
Now the distance covered by both should be equal so:
40x + 20 = 50x
or, x = 20 / (50 - 40).
So, x = 2 hrs.
Therefore the owner will overtake the thief at 2 p.m. + 2 hrs = 4 p.m.

Like? Yes (24) | No (5)  

Karthick Raja   9 years AGO

thief steals a car at 1.30 pm and drive at 40 kmph
Theft was discovered at 2pm and owner drives another car at 50kmph
at 2pm thief cross 20 km & owner at 0km

at 3 pm thief cross 60 km & owner cross 50 km

at 4pm thief cross 100 km & owner cross 100 km

so the owner overtake the thief at 4 pm

Like? Yes (20) | No (2)  

ROHIT JAIN   9 years AGO

20 km will cover in 30min.
and they are going in same direction .

20/10 = 2hr.

4 PM

Like? Yes (16) | No (2)  

RAJKUMAR P   9 years AGO

Relative speed =50-40=10kmph
Relative distance =20km
Relative time =20/10=2hr
Total time=2+2hr=4p.m

Like? Yes (13) | No (2)  

Supriya Mondal   9 years AGO

Let, x hours needed to overtake the thief after theft discover.
Then we can write,
x*50=40*(x+0.5)
so, x=2 hr
So,owner will overtake the thief at (2+2)=4 p.m.
So, option 2)4 p.m is the right answer

Like? Yes (11) | No (4)  

RAKESH   9 years AGO

50t = 20 + 40t
=> t = 2 hr
at 4:00 pm

Like? Yes (10) | No (4)  

viswambher   9 years AGO

since the thief is going at 40kmph ,in half an hour he will be 20km ahead of the owner at 2pm. now the owner is driving at 10kmph relatively with the thief so it takes the owner 2hrs to overtake the thief , therefore he overtakes the thief by 4pm

Like? Yes (5) | No (1)  

RAKESH ARYA   9 years AGO

till 4 pm
thief covers 100 km
and the owner also cover 100 km

Like? Yes (4) | No   

Math Lovers   9 years AGO

A thief steals a car at 1.30 p.m. and drives it at 40 kmph and the theft is discovered at 2 p.m.

so thief has traveled 40 8 0.5 = 20 km

now diff in speed = 50-40 =10 km/h
so time to catch thief = 20/10 = 2 hr

so time = 2pm +2 = 4pm

Like? Yes (3) | No   

k sureshbabu   9 years AGO

caluculate for every half an hour their distances in bet ween 3:30 to 4p.m. he reach the thief

Like? Yes (5) | No (2)  

vibhu raj gupta   9 years AGO

distance cover by thief till 2 pm is =40kmph*1/2h=20km
owner catch the thief at=20/(50-40)=2 hrs
at 4.00 pm

Like? Yes (3) | No   

padam   9 years AGO

distance covered by thief in half hour=20km
10 km will be travelled in 1 hour so 20 km will be travelled in 2 hours
hence at 4pm overtakes the thief

Like? Yes (2) | No   

SAYAN CHATTERJEE   9 years AGO

the thief is 30 mins or 20 km ahead the owner when discovered, so let after 2 pm, the owner had to travel t hrs to overtake the thief
so, 50t=40t+20
=>t=2 hrs
so, owner will overtake at 4 pm.

Like? Yes (2) | No   

Yathiraj   9 years AGO

By the time the theft discovered, the thief has moved 20KMs (30 minutes @40KMPH).
The owner drives @10KMPH faster than the thief and hence he needs 2 hours to cover the difference of 20KMs.
2Hrs from 2pm is 4 p.m.

Option 2.

Like? Yes (2) | No   

aman aditya   9 years AGO

In half hour thief travels 20 km
Now the car cover (50-40)= 10km in an hr.
Total distance to cover is 20 km, so time =2hr
So it will overtake at 4:00

Like? Yes (2) | No   

brijesh mavani   9 years AGO

At 2pm thief ran away 20km.
At 2pm owner started to follow the driver.
So relative speed is 10kmph and distance is 20km.
Hence,owner wilo overtake the thief after 2hrs. By formula, T=D/S where d=20km and s=10kmph.

Like? Yes (2) | No   

SANTOSH   9 years AGO

Thief traveled during 30min with speed of 40kmph is 20km.
let x be the distance, where they met each other after t mins.

for thief,
x/t = 2/3 (40 km/hr = 40km/60min)
for owener,
(20+x)/t = 5/6 (50 km/hr = 50km/60min)
by solving
we get t=120mins

so owner reach at 2pm+120min = 4pm

Like? Yes (2) | No   

Yogesh Kumawat   9 years AGO

theif travel..1/2hour..with speed of 40 kmph and covers..20 km..then police start discovering him @ 50 kmph..
20+40*x = 50*x.....where x is time taken by police to catch d theif..,,x = 2 hours ..hence at 4 p.m....police will overtake theif :)

Like? Yes (2) | No   

Pavithra    9 years AGO

If the thief sets of at 1.30 pm,then at 2 pm
Distance covered by thief= 20 km
Distance covered by owner= 0 km

If we see after 2 hours Thief= (40 x 2 + 20)
Owner= 50 x 2

Both are equidistant at 100 km,so they will meet at 4:00 pm.

Like? Yes (2) | No   

p.sree divya keerthi   9 years AGO

at 2.30 the thief travelled 40 km and the police would have travelled 25 km . at 3.30 the thief by 80 km and police by 75 km.at 4.00 thief by 100 km and the police also 100 km

Like? Yes (2) | No   

manju   9 years AGO

Thief sets of at 1:30 at a speed of 40 km/h

After 30 mins has travelled 20 km

Owner sets off at 2 pm at 50 km/h
May now assume thief car at rest and owner travelling at 10km/h
ie relative speed = 10 km / h

t = 20 / 10 h
t = 2 h
so they will meet at 4 pm

Like? Yes (1) | No   

sompon temtheerakij   9 years AGO

1.30 p.m. the thief drives = 20 km.
let X = the distance from 2 p,m, to overtake the thief
(X+20)/50 = X/40
solve the equation ; X = 40 km.
the thief drives 40 km. in 2 hours
so the owner overtake the thief at 4 p.m.

Like? Yes (1) | No   

vishal chandrola   9 years AGO

in half hour thief is 20 km ahead. car owner's speed is 10km/h faster then thief therefore it will required 2 hour overtake thief. hence 2+2=4 p.m

Like? Yes (1) | No   

Kamlesh Kumar   9 years AGO

thief start at 1:30 and discovered at 2:00pm
so distance covered in half hour=40*1/2=20 km
distance covered by thief in 3:00 pm 60 km

now owner start at 2:00 pm .so he covers 100 km at 4:00 pm and thief covers another 40 km in 1 hour

therefore, at 4 pm both thief and owner both cover 100 km.
so Ans is 4 p.m

Like? Yes (1) | No   

W J Krishna Teja   9 years AGO

since thief is travelling with 40kmph , theft was discovered after half an hour so thief had already travelled 40*0.5=20km
now owner starts with 50kmph
let the owner overtakes after travelling 'x' distance then thief will travell 'x-20' distance
so the times are equal
(x-20)/40=x/50
on solving we get x=100
so the time taken by owner =x/50=100/50=2 hrs
so owner will overtake the thief at 2:00+2 hrs =4:00 pm

Like? Yes (1) | No   

krishna chandrika   9 years AGO

by 4 pm both will reach 100km so the owner can overtake the theif

Like? Yes (1) | No   

vini   9 years AGO

The time difference between them is half an hour.
Thief have traveled 20 km ( coz thief speed is 40 kmph)
When owner started to chase thief the distance between them is 20 km
Distance between them = Distance traveled by owner - Distance traveled by thief
Let 't' be the time taken by owner to over take thief
20 = (50*t) - (40*t) [Distance=Speed*time]
20=10t
t=2 hrs
After two hours ie., at 4 pm owner will over takes thief

Like? Yes (1) | No   

pratap kumar sahoo   9 years AGO

for thief,he has already cover (40*(1/2))=20km at 2p.m

so,owner has to cover 20+x distance at a speed of 50kmph
so tw=(20+x)/50

for thief,he has to cover x distance at a speed of 40kmph
so, tt=x/40

and tw=tt

x=80km

and time required=2h to overtake.
ans:4p.m

Like? Yes (1) | No   

Mani Sachdev   9 years AGO

The thief will be overtaken x hrs after 1:30 pm
and, the distance covered by theif is x hrs == Distance covered by owner in (x-1/2) hrs
40x=50(x-1/2)
x=2:30 min
So, finally the theif is overtaken at 4:00 pm

Like? Yes (1) | No   

NESAB JAFAR   9 years AGO

thief run in the 30 min =20km
relative speed =50-40=10kmph
this 20 km is covered by 10kmph
so time =20/10=2h
so he will overtake the thief =2+2=4pm

Like? Yes (2) | No (1)  

ravi singh   9 years AGO

answer is 4 pm

let, owner over take in X hr
then,
X*40 + 20 = 50*X
then, X=2

2 pm + 2 hr = 4 pm

Like? Yes (1) | No   

aastha sharma   9 years AGO

as the owner dicovers the theft at 2 pm so by that time the theif would have travelled 20 km as only half hour has passed.
now applying the relative velocity concept the relative vel. of owner is 10 km/hr. now the owner has to cover 20 km with speed of 10 km/hr. so it will take 2 hours for owner to travel 20 km.
thus starting at 2 pm he will catch the theif at 4 pm

Like? Yes (1) | No   

PATHIPATI LOKESH   9 years AGO

theif will reach 100kms by 4:00pm and there by the owner who starts at 2:00 with 50kmph also reaches 100km by 4:00.so owner will overtake theif at 4:00pm.

Like? Yes (1) | No   

Tinku   9 years AGO

Distance covered by the thief in 1/2 hour is 20minutes.
10kms is Compensated in 1 Hour.
20kms will be compensated in 2 hours.
Hence, he will overtake the thief at 4 p.m.

Like? Yes (1) | No   

KAVITHA   9 years AGO

Let the thief is overtaken x hrs after 1.30pm
distance covered by the thief in x hrs = distance covered by
the owner in x-1/2 hr
40x = 50 ( x- ½)
x= 2.5 hr
thief is overtaken at 1.30 pm + 2 ½ hr = 4 pm

Like? Yes (1) | No   

santhosh   9 years AGO

suppose the thief overtaken after x hrs..after 1.30pm
distance travelled by the thief in x hrs = dist.travelled by the owner in (x-1/2)hrs..
40×x= (x-1/2)50
we get x=5/2 hrs..
so..it is 4pm

Like? Yes (1) | No   

ANANTHI.P   9 years AGO

40*x=50*(x-1/2)=2.5hrs
so after 2.5hrs from 1.30pm4.00pm

Like? Yes (1) | No   

poojasaisri   9 years AGO

thief speed=40km/hr
owner speed=50 km/hr
difference of speeds =10 km/hr
they two will meet after 2 1/2 hours i.e at 4 pm

Like? Yes (2) | No (1)  

Champ Lucifer   9 years AGO

Considering relative velocity ......
initial displacement is the displacement of the thief in 30 hrs. i.e. 40*(5/18)*30 .....(5/18 is the conversion of velocity kms/hr to mtr/s
Now relative velocity is (50-40)*(5/18)......i.e. 2.77mtr/s.
Now using the formula displacement= velocity*time ............ therefore time = 333.33/2.77 which results in 120 min i.e 2 hrs after 2 pm

Like? Yes (1) | No   

Dark Knight   9 years AGO

The thief after 1 hrs ie 2:30 -->40kmph (t)thief
2:30 -->25kmph(o)owner
3:00 -->60kmph(t)
3:00 -->50kmph(o)
3:30 -->80kmph(t)
3:30 -->75kmph(0)
4:00 -->100kmph(t)
4:00 -->100kmph(o)

Hence 4pm

Like? Yes (1) | No   

Praval Sharma   9 years AGO

thief's speed was 40 km/h so he reaches 100 km in 150 min i.e. at 4:00 pm. While owner's was 20 km/h so he reaches 100 km in 120 min. As owner starts 30 min late so he will reach at 4:00 km

Like? Yes (1) | No   

neha gupta   9 years AGO

Let the owner and thief meet each other when both have travelled distance x.
then for thief time=x/40
and for owner time=x/50
According to question
(x/40) - (x/50)=1/2
0n solving above equation we get:
x=100
time=100/50=2 hrs(for owner)
Therefore owner overtakes thief at 4:00 pm

Like? Yes (1) | No   

Omprakash Pachkawade   9 years AGO

thief covers 40km in 1hr and owner covers 50km in 1hr
at 2pm thief covers 20km and owner start at 2pm
at 3pm thief covers 60km and owner covers 50km
at 4pm thief covers 100km and owner covers 100km
so ans is 4pm

Like? Yes (1) | No   

Mamtha   9 years AGO

(x+0.5)*40=x*50
4x+2=5x
x=2
2hrs from 2.00 pm

Like? Yes (1) | No   

syed kashif ullah   9 years AGO

at 4 pm both thief and owner are at 100 km away from the steal point

Like? Yes (1) | No   

Vernika   9 years AGO

they collide at 4 pm bacuse it takes the second car two hours to nullify the 20 km distance which the first car had already covered

Like? Yes (1) | No   

sharmi saha   9 years AGO

in 30mins the thief goes 20k.m
now the owner makes up 10 k.m in 1hr. so he will make up 20k.min 2 hrs.

Like? Yes (1) | No   

asdf   9 years AGO

in 1st 30min thief achieved a 20 km lead.
the owner will catch him in 20/(50-40)=2hrs
past 2pm

Like? Yes (1) | No   

Yashi Das   9 years AGO

let the thief is overtaken x hrs after 1:30p.m.
therefore,
40x=50(x-1/2)
on solving,
x=5/2 hr
the thief is overtaken at 1:30p.m. +5/2 hr=4p.m.

Like? Yes (1) | No   

Deepak kushwaha   9 years AGO

thief steal car at 1.30 p.m. and distance travelled by thief till 2 p.m. is 20km
now at 2p.m. the owner get informed and start chasing and the distance travelled by owner in 1hr(3p.m.) is 50 km and distance travelled by owner till 4p.m. is 50+50=100km
speed of thief is 40 kmph so distance travelled by thief till 3p.m. is 60km and distance travelled by thief till 4p.m is 60+40=100km
so the answer is 4p.m.

Like? Yes (1) | No   

sabban rushikesh kailas   9 years AGO

after discovering the thief he will travel 80 km so..it will take 2 more hrs after 2 pm

Like? Yes (1) | No   

Rahul Raj Barnwal   9 years AGO

at 4 thief cover (20+40+40)km = 100km
and owner covers (50+50)km = 100km
so owner catch thief at 4p.m.

Like? Yes (1) | No   

Kumari Riya   9 years AGO

for thief distance covered from time 1:30-4:00 pm at speed 40kmph=100km and for owner distance covered from time 2:00pm-4:00pm at speed 50kmph=100km.so both will intersect at 4:00pm

Like? Yes (1) | No   

Prateek Garg   9 years AGO

at 3:30 the owner will travel 75 km and the thief wud have travelled only

Like? Yes (1) | No   

Surit Datta   9 years AGO

Distances covered by the thief in 1/2 hour is 20 km
10 km is compensated in 1 hour
20 km is compensated in 2 hour
so ,
he would overtake the thief at 4 p.m
so,
option 2
that's it.

Like? Yes (2) | No (2)  

B.venkata suresh   9 years AGO

thief:
1:30-2:00-20km.
2:00-3:00-40km.
3:00-4:00-40km
total: 100km
owner:
2:00-3:00-50km
3:00-4:00-50km
total: 100km

Like? Yes (1) | No (1)  

Sagar Mate   9 years AGO

owner starts journey 30 mins late
i.e. thief goes 20 km ahead of theft place
(as thiefs speed is 40 KMPH)
according to this
in two hours theief travels 40 + 40 +20 (from abv.)=100 KM
and after 2 hours owner travels 50 +50 = 100 KM

Like? Yes (1) | No (2)  

Mehul D Parmar   9 years AGO

D=S*T
20=10*t
t=2


or simple way

when thief away from orignal potion at 2:pm =20km
and owner away from origanal position at 2;pm=0km

when thief away from orignal potion at 3:pm =20km+40km=60km
and owner away from origanal position at 2;pm=0km+50km=50km


when thief away from orignal potion at 4:pm =60km+40km=100km
and owner away from origanal position at 4;pm=50km+50km=100km

then easily to say ans is 4:pm

Like? Yes (1) | No (2)  

08 Jun 2015 Sequence

What is the next number of the following sequence
36, 324, 2916, 52488, .......

OPtion

1) 1416178
2) 1546376
3) 1435687
4) 1534265
5) 1423986
6) 1417176
7) 1423567
8) 1756463
9) 1654387
10)1423547

Solution

36
(3+6)*36 = 9*36 = 324
(3+2+4)*324 = 9*324 = 2916
(2+9+1+6)*2916 = 18*2916 = 52488
Similarly
(5+2+4+8+8)*52488 = 27*52488 = 1417176

Option 6)

Correct Option: 6 Best Solution (59)

Ayan Patra   9 years AGO

36 x (9) = 324
324 x (9) = 2916
2916 x (9+9) = 2916 x (18) = 52488
52488 x (18+9) = 52488 x (27) = 1417176

Each i th number in the sequence is a multiple of the (i - 1)th number with the sum of the (i-1)th and (i-2)th number's multiple.

Like? Yes (6) | No (1)  

Supriya Mondal   9 years AGO

Sum of digits of first number is=3+6=9
So, next digit will be=36*9=324
Sum of digits of 324=3+2+4=9
So, next digit will be=324*9=2916
Sum of digits of 2916=2+9+1+6=18
So, next digit will be=2916*18=52488
Sum of digits of 52488=5+2+4+8+8=27
So, next digit will be=52488*27=1417176
So, option 6)1417176 will be the right answer

Like? Yes (4) | No (1)  

MRITUNJAY   9 years AGO

multiply the next number with the sum of prevoius number
36*9=324
324*9=2916
2916*52488
52488*271417176
this is answer

Like? Yes (2) | No   

VISHWA UDAYKUMAR SHAH   9 years AGO

36*9=324, 324*9=2916, 2916*18=52488, 52488*27=1417176

Like? Yes (2) | No   

viswambher   9 years AGO

36*9=324
324*9*1=2916
2916*9*2=52488
52488*9*3=1417176

Like? Yes (4) | No (3)  

kranthi kanchanapally   9 years AGO

THe seq is
36*9=324
324*9=2916
2916*18=52488
52488*27=1417176
seq is 9,9,18,27

Like? Yes (1) | No   

Yathiraj   9 years AGO

36
(3+6) * 36 => 324
(3+2+4) * 324 => 2916
(2+9+1+6) * 2916 => 52488
(5+2+4+8+8) * 52488 => 1417176

Option 6.

Like? Yes (1) | No   

Niraj   9 years AGO

6 x (6 + 0) = 36
36 x (3 + 6) = 324
324 x (3 + 2 + 4)= 2916
2916 x (2 + 9 + 1 + 6) = 52488
52488x (5+ 2+ 4 + 8 + 8) = 1417176

Like? Yes (1) | No   

Divyabala R   9 years AGO

=>36 *(3+6)=36*9 = 324,
=>324 * (3+2+4) = 324 * 9 = 2916,
=>2916 * (2+9+1+6) = 2916 * 18 =52488,
=>52488 * (5+2+4+8+8) = 52488 * 27 = 1417176
:)

Like? Yes (1) | No   

Gaurav Singla   9 years AGO

36*9
324*9*1
2916*9*2
52488*9*3

Like? Yes (1) | No   

SAYAN CHATTERJEE   9 years AGO

each no. is the product of the previous no. & the sum of the digits of the previous no. So, the ans. is (52488*(5+2+4+8+8=27)=1417176 ) (6).

Like? Yes (1) | No   

W J Krishna Teja   9 years AGO

If we see the sequence 36 , 324 , 2916 , 52488
let the terms in the sequence be a ,b , c ,d
here we can see that b=a*9
c=b*9
d=c*18
here the no which is multiplied is sum of the previous two multiples.
hence the next number to be multiplied is 9+18=27
therefore next term will be d*27 i.e 52488*27=1417176

Like? Yes (1) | No   

vini   9 years AGO

324/36=9
2916/324=9
52488/2916=18( 9+9)
x/52488=27(9+18)
x=52488*27=1417176

Like? Yes (1) | No   

Gourav Rajdhar   9 years AGO

36>3+6=9
36*9=324
324>3+2+4=9
324*9=2916
2916>2+9+1+6=18
2916*18=52488
52488>5+2+4+8+8=27
52488*27=1417176

Like? Yes (1) | No   

keerthi   9 years AGO

I dont know how to solve the sequence
This is my guess work
Please explain the number series and sequence problems with good explinations

Like? Yes (1) | No   

Soham Dalwadi   9 years AGO

36=36*(3+6)=324

similarly
52488=52488*(5+2+4+8+8)=1417176

Like? Yes (1) | No   

Venkatesh kadali   9 years AGO

36*9=324
324*9=2916
2916*18=52488
52488*27=1417176

Like? Yes (1) | No   

Mehul D Parmar   9 years AGO

3=3+6=9 then 36*9=324

324=3+2+4=9 then 324*9=2916

2916=2+9+1+6=18 then 2916*18=52488

then next term is

52488=5+2+4+8+8=27 then 52488*27=1417176

then next term is 1417176

Like? Yes (1) | No   

Meenakshi   9 years AGO

36*(3+6)=324
324*(3+2+4)=2916
2916*(2+9+1+6)=52488
52488*(5+2+4+8+8)=1417176

Like? Yes (2) | No (1)  

vishal chandrola   9 years AGO

36, 36*9, 36*(9+9), 36*(18+9), 36*( previous multiplier+9)...

Like? Yes (1) | No   

Soma Naresh   9 years AGO

36*(3+6) = 36*9 = 324
324*(3+2+4) = 324*9 = 2916
2916*(2+9+1+6) = 2916 *18 = 52488
52488*(5+2+4+8+8) = 52488*27 = 1417176

Like? Yes (1) | No   

KAVITHA   9 years AGO

Next number=the previous num*(sum of all digits)
52488*(5+2+4+8+8)
52488*(270)
ANS= 1417176
option-6

Like? Yes (1) | No   

poojasaisri   9 years AGO

36*9=324
324*9=2916
2916+2916=5832*9=52488
52488+52488+52488=157464*9=1417176

Like? Yes (1) | No   

arpit sharma   9 years AGO

factorise the no. we get
2^2*3^n where 'n' varies from 2,4,6,8,10

Like? Yes (1) | No   

RAVAL   9 years AGO

in given whole series,
all no's. sum individually is 9, for example....
36=3+6=9
324=3+2+4=9
2916=2+9+1+6=18=1+8=9
52488=5+2+4+8+8=27=2+7=9
so ans,
1417176=1+4+1+7+1+7+6=27=2+7=9

Like? Yes (2) | No (1)  

Yogesh Kumawat   9 years AGO

Sum of the digits of the number is logic :)
36...3+6..= 9....36*9..=324
324...3+2+4....=9.....324*9..= 2916
2916...2+9+1+6..=18....2916*18...=52488
52488...5+2+4+8+8...=27...52488*27.....=1417176...:)

Like? Yes (1) | No   

anwar hussain   9 years AGO

36*9=324
llry for 2916
but for next no 2916*9=26244,then *2=52488.
llry for next no. 52488*9*3=1417176 because no.lies in third position

Like? Yes (1) | No   

sompon temtheerakij   9 years AGO

324x9 = 2916
2916x9x2 = 52488
52488x9x3 = 1417176

Like? Yes (1) | No   

santosh verma   9 years AGO

3+6=9, 3+2+4=9, 2+9+1+6=18, 5+2+4+8+8=27 , 1+4+1+7+1+7+6=27

Like? Yes (1) | No   

sourav pal   9 years AGO

6*6 = 36

36*(6+3) = 324

324*(3+2+4) = 2916

2916*(2+9+1+6) = 52488

52488*(5+2+4+8+8)= 1417176

Like? Yes (1) | No   

Ramesh gujjula   9 years AGO

36*(3 6)=36*9=324
324*(3 2 4)=324*9=2916
2916*(2 9 1 6)=2916*18=52488
52488*(5 2 4 8 8)=52488*27=1417176

Like? Yes (1) | No   

ravi singh   9 years AGO

answer is option 6

only option 6 is divisible by 52488

Like? Yes (1) | No   

Abhishek Kumar   9 years AGO

36*10-36=324
324*10-324=2916
[(2916*10)-2916]*2=54488
[(54488*10)-54488]*3=1417176

Like? Yes (1) | No   

Parth Sorathiya   9 years AGO

36=3+6=9 so 36*9=324
324=3+2+4=9 so 324*9=2916
2916=2+9+1+6=18 so 2916*18=52488
52488=5+2+4+8+8=27 so 52488*27=1417176

Like? Yes (1) | No   

Endraja B Dhage   9 years AGO

324/36=9
2916/324=9
52488/2916=18
hences 52488*18=1417176

Like? Yes (1) | No   

pragya   9 years AGO

in this number are multipled by multiple of 9. firstly by 9 then by 18 n then by 27
and we get answer by multiplying 52448 by 27

Like? Yes (1) | No   

anmol jain   9 years AGO

36*9=324
324*9=2916
2916*18=52488
52488*27=1417176

Like? Yes (1) | No   

Ashish singh kushwah   9 years AGO

6*6=36
36(3+6)=324
324(3+2+4)=2916
2916(2+9+1+6)=52488
52488(5+2+4+8+8)=1417176

Like? Yes (1) | No   

kajal mehta   9 years AGO

(36*9=324),(324*9=2916),(2916*18=52488),(52488*27=1417176)

Like? Yes (1) | No   

venkat   9 years AGO

36 *9 =324 '9'
324 *9 =2916 '0+9'
2916 *18 =52488 '9+9'
52488*27 =1417176 '18+9'

Like? Yes (1) | No   

MANDEEP SINGH   9 years AGO

Sum of all digits in the numbers is 9 like
36 > 3 + 6 = 9
324 > 3 + 2 + 4 = 9
2916 > 2 + 9 + 1 + 6 > 18 > 1 + 8 = 9
52488 > 5 + 2 + 4 + 8 + 8 > 27 > 2 + 7 > 9
And in the given options on 1417176 sums to 9.

Like? Yes (1) | No   

ganesh babu   9 years AGO

36, 36*(3+6)=324
324*(3+2+4)=2916
2916*(2+9+1+6)=52488
52488*(5+2+4+8+8)=52488*27
1417176

Like? Yes (1) | No   

krishna chandrika   9 years AGO

36x9=324
324x9=2916
2916x18=52488
52488x27=1417176

Like? Yes (1) | No   

Harpreet Kaur   9 years AGO

when we sums up all digit in the number it equals to 9
36 => 3+6 = 9
324 => 3+2+4 = 9
so on
1417176 => 1+4+1+7+1+7+6 => 9

Like? Yes (1) | No   

Summit    9 years AGO

multiple of nine multiplied by the successive numbers

Like? Yes (1) | No   

manikanta p   9 years AGO

it's clearly known as next number has divided by 9
and after it will doubled 9,9,18,27,........so ans is 1417176

Like? Yes (1) | No   

RAKESH ARYA   9 years AGO

36*9=324
324*(0+9)=2916
2916*(9+9)=52488
52488*(9+18)=1417176

Like? Yes (1) | No   

Koushik Dey   9 years AGO

36*9=324
324*9=2916
2916*18=52488
52488*27=1417176

Like? Yes (1) | No   

vibhu raj gupta   9 years AGO

number are multiplied by their sum of digits

Like? Yes (1) | No   

Kamlesh Kumar   9 years AGO

324/36=9
2916/324=9 9+9
52488/2916=18 18+9
1417176/52488=27

Like? Yes (1) | No   

Jotshnesh Patel   9 years AGO

Answer: option 6 is correct.

Solu.:-
36=> 3+6 = 9
36*9 = 324,
now,
3+2+4 = 9
9*324 = 2916,

2+9+1+6 = 18
18*2916 = 52488

5+2+4+8+8 = 27
27*52488 = 1417176

Like? Yes (1) | No   

Mamtha   9 years AGO

the number multiplied by the sum of its digits gives the next number. 36*(3+6)=324, 324*(3+2+4)=2916, 2916*(2+9+1+6)=52488, 52488*(5+2+4+8+8)=1417176

Like? Yes (1) | No   

Surit Datta   9 years AGO

a(n + 1) = a(n) * sum of digits of a(n)
like,
324 = 36 * (3 + 6)
similarly,
1417176 = 52488 * (5 + 2 + 4 + 8 + 8)
so option 6
that's it.

Like? Yes (1) | No (1)  

Pradyumna K S   9 years AGO

36(3+6)=36*9=324
324(3+2+4)=324*9=2916
2916(2+9+1+6)=2916*18=52488
52488(5+2+4+8+8)=52488*27=1417176
Therefore the answer is option 6) 1417176

Like? Yes (1) | No (1)  

Karthick Raja   9 years AGO

36,324,2916,52488
all 4 numbers are divided by 9
fronm options 1417176 is divided by 9 so the answer is 1417176.
other options are not divided by 9.

Like? Yes (1) | No (1)  

Palash Malani   9 years AGO

36x9
36x9x1
36x9x2
36x9x3=1417176

Like? Yes (1) | No (1)  

padam   9 years AGO

next no=term*sum of digit
324=36*9
hence 52488*27=1417176 option 6

Like? Yes (1) | No (1)  

prabhat kumar   9 years AGO

36*9=324
3+6=9
hence 52488*27=1417176
5+2+4+8+8=27

Like? Yes (1) | No (1)  

Ramdas Singathiya   9 years AGO

all numbers given in series are even and sum of all digits (in single digit) is 9.. :)

Like? Yes (1) | No (1)