M4maths Previous Puzzles

01 Jul 2015 Probability

Ticket numbered from 1 to 20 are mixed up and a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 7.

OPtion

1) 1/15
2) 1/2
3) 2/5
4) 1/17
5) 2/7
6) 1/7
7) 1/8
8) 7/20
9) 3/5
10)3/20

Solution

Clearly n(S) = 20 And E = {3,6,9,12,15,18,7,14)
Therefore P(E) = n(E)/n(S) = 8/20 = 2/5

Option 3)

Correct Option: 3 Best Solution (83)

Abhishek   9 years AGO

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 7 = {3, 6 , 9, 12, 15, 18, 7,14}.

P(E) = n(E)/n(S) = 8/20

P(E) = 2/5.

Like? Yes (27) | No (1)  

mohita verma   9 years AGO

total outcome=20
favorable outcome={3,6,9,12,15,18,7,14}
i.e 8
therefore,
probability=8/20=2/5

Like? Yes (19) | No (3)  

darladiwakar   9 years AGO

3 or 7=3,6,9,12,15,18, 7,14
total=20
probability=8/20=2/5

Like? Yes (5) | No (1)  

Ravi shankar   9 years AGO

multiples of 3 are 3,6,9,12,15,18.
multiples of 7 are 7 ,14
total prob=6/20+2/20=2/5

Like? Yes (4) | No (1)  

Deepthi   9 years AGO

between 1 to 20 multiples of 3:
3,6,9,12,15,18----------------6
multiples of 7:
7,14-------2
total 8 numbers
probability :8/20=2/5

Like? Yes (3) | No   

chandrika.k   9 years AGO

there are 8 possibilities such that the number is either multiple of 3 or 7...out of 20 possibilities...so ans is 8/20 i.e 2/5

Like? Yes (3) | No   

asim   9 years AGO

from number 1 to 20 ,
multiples of 3 are : 3,6,9,12,15,18
& multiples of 7 are : 7,14
i.e. given total numbers = 20
and total number of possible outcomes = number of multiples of 3 + number of multiples of 7
=> = 6 + 2
=> = 8

therefore , probability of 1 card drawn at random = no of possible outcomes / total number
= 8 / 20 = 2 / 5 i.e option 3

Like? Yes (3) | No   

Billal Hossain   9 years AGO

Here, S = {1, 2, 3, 4, 5,6,7,8,9,10,11,12,13,14,15,16,17,18,19, 20}.
Let E = event of getting a multiple of 3 or 7 = {3, 6 ,7, 9, 12, 14,15, 18}.
P(E) =n(E)/n(S)=8/20=2/5(ans)

Like? Yes (3) | No   

Veerraj Chauhan   9 years AGO

total multiples of 3 in between 1-20 = 6
total multiples of 7 in between 1-20 = 2
probability = (6+2)/20= 8/20= 2/5

Like? Yes (3) | No (1)  

Pranati Kundu   9 years AGO

3,6,9,12,15,18,7,14
so total is 8 events and sample space is 20
so 8/20
2/5

Like? Yes (2) | No   

RAJAT KHANDELWAL   9 years AGO

A be that no of cards that are multiple of 3=6
B be that no of cards that are multiple of 7 =2
total no of cards =20
Probability that cards drawn is either multiple of 3 or multiple of 7 = P(A) u P(B)
=P(A) + P(B) +P(A^B)
= 6/20 + 2/20 +0=8/20=2/5

Like? Yes (4) | No (2)  

lokesh   9 years AGO

multiples of 3 or 7 are 3,6,9,12,14,15,18

probability = favourable outcome / total outcome
= 8/20
= 2/5

Like? Yes (2) | No (1)  

DEEPAK RAJ   9 years AGO

Multiple of 3 = 3,6,9,12,15,18
So, P(Multiple of 3) = 6/20

Multiple of 7 = 7, 14
So, P(Multiple of 7) = 2/20

Total Probablity = 6/20+2/20 = 2/5 Ans

Like? Yes (1) | No   

Ramdas Singathiya   9 years AGO

3,6,7,9,12,14,15,18 => 8/20= 2/5

Like? Yes (1) | No   

Vivek   9 years AGO

Total number of tickets=20
Number of ticket with multiple of 3=6
Number of ticket with multiple of 7=2
Number of ticket with multiple of 2 or 7=8
Probability has number which is multiple of 3 or 7=8/20
=2/5
Therefore the option is 3)

Like? Yes (3) | No (2)  

Shiva Sharma   9 years AGO

total tickets = 20
ticket which are multiple of 3 or 7 are 3,6,7,9,12,14,15,18
total is 8
so probability = 8/20
=>2/5

Like? Yes (2) | No (1)  

SAGAR BAGCHI   9 years AGO

total possible outcomes are from 1 to 20 i.e 20.
favourable outcomes are:-(3,6,7,9,12,14,15,18)=8
so,probability=8/20=2/5 -option (3).

Like? Yes (1) | No   

ABHINAV PUSHPAM   9 years AGO

The numbers divisible by 3 or 7 are - 3,6,7,9,12,14,15 & 18. i.e total 8.
so, probability = 8/20. = 2/5
option 3)

Like? Yes (2) | No (1)  

vamsi krishna   9 years AGO

numbers mulitiples of 3 or 7 is 8
sample space is 20
ans 8/20=2/5

Like? Yes (1) | No   

BADRI LAL JAT   9 years AGO

multiple of 3=6 and 7=2 so total is 8 number. so probablility is 8/20=2/5. ok.

Like? Yes (1) | No   

sravani   9 years AGO

there are 8 numbers in 1 - 20 which are multiples of 3,7
3,6,9,12,15,18,7,14,,,
so probability is 8/20=2/5

Like? Yes (1) | No   

Urvil shah   9 years AGO

The probability of getting 3 is 6/20 .and getting 7 is 7/20.so 6/20+2/20=2/5

Like? Yes (2) | No (1)  

Nikhil chavan   9 years AGO

3,6,9,12,15,18 and 7, 14
8/20=2/5

Like? Yes (1) | No   

Archie   9 years AGO

Here,
S={1,2,3,4......20}
Let
Event= multiple of 3 or 7
={3,6,9,12,15,18,7,14}
P(E)=(n(E)/S(E))
=8/20=2/5
Hence option 3 is correct :)

Like? Yes (1) | No   

Chandrima Goswami   9 years AGO

Here, S = {1, 2, 3, 4, ...., 19, 20}
Let E = event of getting a multiple of 3 or 7 = {3, 6 , 9, 12, 15, 18, 7,14}
P(E) = n(E) / n(S) = 8/20 = 2/5
So ans is option 3)

Like? Yes (1) | No   

RAHUL KUMAR   9 years AGO

n(s)= 20
n(E)= {3,6,7,9,12,14,15,18}
n(E) = 8
P = 8/20= 2/5

Like? Yes (1) | No   

kanithi.shanmukharao   9 years AGO

multiples of 3 are =3,6,9,12,15,18 =>6.
multiples of 7 are =7,14 =>2.
so 6+2=8,there is no common multiple..
probability=8/20 =2/5..

Like? Yes (1) | No   

SOMA NARESH   9 years AGO

multiples of 3 and 7 from 1 to 20 are 3 6 7 9 12 14 15 18
Total number of multiples of 3 or 7 = 8
Probability = 8/20 = 2/5

Like? Yes (1) | No   

Rajanikanta Pradhan   9 years AGO

Multiple of 3 in 20 is 3,6,9,12,15,18
Multiple of 7 in 20 is 7,14
Probability of multiple of 3= 6/20
Probability of multiple of 7=2/20
6/20+ 2/20 = 8/20
= 2/5

Like? Yes (1) | No   

JYOTI CHHABRA   9 years AGO

Multiple of 3 is 3,6,9,12,15, 18 and multiple of 7 is 7,14 till 20 so probability is 8/20 i. e. 2/5

Like? Yes (1) | No   

Rohit Kumawat   9 years AGO

Answer is : 2/5
Explanation: Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 7, 14}.

P(E) = n(E)/n(S) = 8/20 = 2/5

Like? Yes (1) | No   

Pranjal   9 years AGO

calculate the multiples of 3 and 7 less then 20 they are 3,6,7,9,12,14,15,18 total number are 8
so probability is 8/20
so 2/5

Like? Yes (1) | No   

prabhat gupta   9 years AGO

multiple of 3 : 3,6,9,12,15,18
multiple of 7 : 7,14

so prob = multi(3)+multi(7) / total = 8/20 = 2/5

Like? Yes (1) | No   

Dinesh Kumar Kumawat   9 years AGO

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 7, 9, 12, 14, 15, 18}.

P(E) = n(E)/n(S) = 8/20 = 2/5

Like? Yes (1) | No   

MD IRSHAD ALAM KAMAR   9 years AGO

Here,ticket numbered from 1-20
multiple of 3 : 3,6,9,12,15.18
multiple of 7: 7,14
hence,p=(6+2)/20

Like? Yes (1) | No   

praveendas   9 years AGO

total of cases=20
no of favourable cases =8
8/20=2/5

Like? Yes (1) | No   

BASWARAJ K PATIL   9 years AGO

S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 7 = {3, 6 , 9, 12, 15, 18, 7, 14,}.

p(E) = n (E)/ n(s) = 8/20= 2/5

Like? Yes (1) | No   

SANTOSH   9 years AGO

multiples of 3,7 are 3,6,7,9,12,14,15,18

probability 8/20
=> 2/5

Like? Yes (1) | No   

A M ANKIT KALLURAYA   9 years AGO

the ticket can be 3,6,9,12,15,18,7,14=8
total no of tickets=20
P=8/20=2/5

Like? Yes (1) | No   

NIRAVKUMAR PRAVINBHAI PATEL   9 years AGO

Probability of getting 3 is 6/20
and
probability of getting 7 is 2/20
so answer is =6/20+2/20=2/5

Like? Yes (1) | No   

Piyush Telang   9 years AGO

P(multiple of 3) or P(3x) = 6/20
P(multiple of 7) or P(7x) = 2/20
P(Total) = P(3x) + P(7x) = 2/5

Like? Yes (1) | No   

Soma Naresh   9 years AGO

multiples of 3 or 7 are {3,6,9,12,15,18}{7,14}= 8
total numbers = 20
probability=8/20 =2/5

Like? Yes (1) | No   

vivek   9 years AGO

Toal favorable numbers are- 3,6,7,9,12,14,15,18=8
So required probability is 8/20=2/5

Like? Yes (1) | No   

POOJA SINGH   9 years AGO

S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 7 = {3, 6 , 9, 12, 15, 18, 7,14}.

P(E) = n(E) /n(s)=8/20=2/5 .

Like? Yes (1) | No   

Suganya   9 years AGO

n(s)=20
P(a)=6/20
P(b)=2/20
P(a)+P(b)=2/5

Like? Yes (1) | No   

sreelakshmi   9 years AGO

Multiples of 3 - 6/20
Multiples of 7 - 2/20
total=6/20+2/20=2/5

Like? Yes (1) | No   

K.M.AYESHA SHARMIL JAHAN   9 years AGO

n(s)=20
multiples of 3=20/3
=6
multiples of 7=20/7
=2
n(p)=2+6
=8
p=8/20
p=2/5

Like? Yes (1) | No   

Lavanya Rajendran   9 years AGO

no of multiples of 3 between 1 to 20 is 6 and for 7 is 2 so probability is 6/20 + 2/20 = 2/5

Like? Yes (1) | No   

santosh kumar patel   9 years AGO

ticket no 1 to 20 = 1 , 2 , 3 , 4 , 5 , 6 ,7,8,9,10,11,12,13,14,15,16,17,18,19,20

multiple of 3 = 3,6,9,12,15,18
multiple of 7 = 7,14
total = 8
probability= 8/20= 2/5

Like? Yes (1) | No   

DINESHKUMAR   9 years AGO

possibility of 3 is 3,6,9,12,15,18 and possibility of 7 is 7,14
so 8/20=2/5

Like? Yes (1) | No   

vijay shankar   9 years AGO

for 3, possible outcome...3,6,9,12,15,18
so probability =6/20
for 7....7,14
so probabality 2/20
so total prob. due to (or)=6/20+2/20=2/5

Like? Yes (1) | No   

Dinni   9 years AGO

3, 6, 9, 12, 15, 18 are multiples of 3
7, 14 are multiples of 7
Total=8
Probability=8/20=2/5.

Like? Yes (1) | No   

sai krishna koppaku   9 years AGO

Mutiples of 3 or 7-3,6,9,12,15,18,7,14
Total probability -8/20
. -2/5

Like? Yes (1) | No   

jalaj   9 years AGO

possible outcomes for multiple of 3 is 3,6,9....18=6 for multiple of 7=7,14 =2
6+2=8 for multiple of 3 or 7
total outcomes=20
Therefore,P=8/20=2/5

Like? Yes (1) | No   

Gaurav Sikka   9 years AGO

no. of multiples of 3 between 1 and 20 are 6
no. of multiples of 7 between 1 and 20 are 2
therefore, total no. of elements in sample space is 8
probability is 8/20 i.e. 2/5

Like? Yes (1) | No   

suraj nath prasad   9 years AGO

multiple of 3 b/w 1-20=3,6,9,12,15,18
multiple of 7=7,14
so probability=8/20=2/5

Like? Yes (1) | No   

Anubhav jain   9 years AGO

possible events are =7(3*1,3*2,3*3,3*4,3*5,3*6,7*1,7*2)
totalevents are=20
then prob. is =8/20=2/5

Like? Yes (1) | No   

Dheeraj Bhatia   9 years AGO

there are 6 multiple of 3 between 1 to 20 and 2 multiple of 7. and there is an or condition which means either it shoulb be the multiple of 3 or the multiple of 7 so we will add 6+2=8/20=2/5

Like? Yes (1) | No   

Sambit Pal   9 years AGO

the probability is an 'or' case of selecting 1 card among 6 of 3's multiple or 2 of 7's multiple.... i.e 8/20=2/5

Like? Yes (1) | No   

Dhanraj Wanjare   9 years AGO

3 or 7
total number of cases = 20 tickits
and favrbl number of cases
(20/3=6 and 20/7=2 and 21 is more than 20 so leave it)
probability = f/t
p= 6/20+2/20;
p=8/20
p=2/5
so option 3 is satisfied

Like? Yes (1) | No   

Hardeep Sidhu   9 years AGO

multiples of 3 are 6 + multiples of 7 are 2=8
8/20= 2/5

Like? Yes (1) | No   

venki vemuri   9 years AGO

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 7 = {3, 6 , 7,9, 12, 14,15, 18}.

P(E) = n(E) = 8/20=2/5 .
n(S) 20

Like? Yes (1) | No   

syed kashif ullah   9 years AGO

3,6,9,12,15,18--->6
7,14---> 2
fav/ total= 6+2/20
=8/20=2/5
hence optiin 3

Like? Yes (1) | No   

RAKESH ARYA   9 years AGO

mul. of 3 in 20 = 6
mul of 7 in 20 = 2
mul of (3*7) in 20= 0

hence , total possible cases = 8

probability = 8/20
= 2/5

Like? Yes (1) | No   

sravani podipireddy   9 years AGO

No. of multiples of 3 & 7 from 1 to 20 are
3,6,7,9,12,14,15,18

So , probability = 8/20 = 2/5

Like? Yes (1) | No   

MUKESH   9 years AGO

total number,n(s)=20
let A be multiple of 3 =3,6,9,12,15,18
let B be multiple of 7 =7,14
n(A)=6
n(B)=2
p(A or B)=(P(A)+p(B))/20
therefore answer is 2/5

Like? Yes (1) | No   

Cp Choudhary   9 years AGO

8/20

Like? Yes (1) | No   

Rajeshkumar   9 years AGO

n(s)=20
P(a)=6/20
P(b)=2/20
P(a intersect b)=0
Therefore,
P(a+b)=(6/20)+(2/20)-0
=8/20
=2/5

Like? Yes (1) | No   

akshay ishwarkar   9 years AGO

total event=t
no. of getting multiple of 3 & 7=n={3,6,7,9,12,15,14,18}
probability=n/t
=8/20=2/5

Like? Yes (1) | No   

Shantanu Udapure   9 years AGO

probability for multiple of 3= 6/20
probability for multiple of 7=2/20
probability = (6/20) + (2/20) = 2/5

Like? Yes (1) | No   

RUPALI DADHE   9 years AGO

S={1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20}
Let E= events of getting a multiple of 3 or 7
= {3, 6, 9, 12, 15, 18, 7, 14}
P(E)=n(E)/n(S)
=8/20
=2/5

Like? Yes (2) | No (1)  

Akshay Bhandakkar   9 years AGO

probability for multiple of 3= 6/20
probability for multiple of 7=2/20
probability = (6/20) + (2/20) = 2/5

Like? Yes (1) | No   

PAVAN HATWAR   9 years AGO

probability for multiple of 3= 6/20
probability for multiple of 7=2/20
probability = (6/20) + (2/20) = 8/20=2/5
the probability for multiple of 3 or 7 = 2/5

Like? Yes (1) | No   

ajit kumar sharma   9 years AGO

S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 7, 14}.

probability P(E)=n(E)/s(E)=8/20=2/5

Like? Yes (1) | No   

jyothsna   9 years AGO

3,6,9,12,15,18,7,14 are multiples of 3 or 7.hence 8/20 i.e.,2/5 is the answer

Like? Yes (1) | No   

ezhilane   9 years AGO

since ply.of multiple of 3=6/20 and ply.of multiple of 7 is 2/20
and both are added so ans is 2/5

Like? Yes (1) | No   

Gaurav Singh   9 years AGO

Multiples of 3 --> 3,6,9,12,15,18
Multiples of 7--> 7,14

favourable events -->8
Total events--> 20

probability of 3 or 7 = 8/20 = 2/5

Like? Yes (1) | No   

shashi   9 years AGO

multiple of 3 nd 7 are n(e)= 3,6,9,12,15,18,7,14
n(s)=20
p(s)=8/20
=2/5

Like? Yes (1) | No   

nitin   9 years AGO

There are total 8 favourable outcomes i.e. 3,6,9,12,15,18,7,14 out of 20 possible outcomes So, 8/20 i.e 2/5.

Like? Yes (1) | No   

shyamala   9 years AGO

multiples of 3: 6
multiples of 7: 2
6+2=8
total cards 20
probability= 8/20
ans:2/5

Like? Yes (1) | No   

arti kumari   9 years AGO

total probablity = 20
require = 3,6,7,9,12,14,15,18(8)
it means = 8/20=2/5

Like? Yes (1) | No   

harman kaur   9 years AGO

6 numbers divisible by 3 nd 2 by 7..
i.e
(6+2)/20=2/5

Like? Yes (1) | No   

Aravinth kumar   9 years AGO

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 7 = {3, 6 , 9, 12, 15, 18, 7,14}.

n(E) = 8 .
n(S) = 20
p(E)=8/20
=> 2/5

Like? Yes (2) | No (2)  

30 Jun 2015 Area

A wheel makes 1000 revolutions in covering a distance of 88 km. The diameter of the wheel is

OPtion

1) 24 m
2) 34 m
3) 40 m
4) 28 m
5) 14 m
6) 30 m
7) 22 m
8) 25 m
9) 20 m
10)15 m

Solution

Distance covered in 1 revolution = 88*1000/ 1000 = 88 m
Therefore circumference = 88 m
So Pi*D = 88
D = 28 m

Option 4)

Correct Option: 4 Best Solution (79)

Snigdh Mayank   9 years AGO

No. of revolutions = 1000
Now
Distance travelled in 1 revolution = 2 * 22/7 * R
Distance travelled in 1000 revolutions = 2 * 22/7 * R * 1000
1000 * 2 * 22/7 * R = 88000
R = 88000 * 7/1000 * 2 * 22
= 14
Thus , radius of wheel = 14 m
and , diameter of wheel = 2 * R
= 2 * 14
= 28 m

Like? Yes (26) | No (5)  

lokesh   9 years AGO

1000 revolution = 88 km
=> 1 revolution = 88 m
=> 2?r = 88
=> r = 14
=> d = 28

Like? Yes (27) | No (8)  

shree   9 years AGO

perimeter of the wheel = 88000/1000
=88
therefore, 2*pi*r = 88
r=14
therefore, diameter=2*r= 28m

Like? Yes (13) | No (4)  

sourav pal   9 years AGO

No. of revolutions = 1000
Now
Distance travelled in 1 revolution = 2 * 22/7 * R
=> Distance travelled in 1000 revolutions = 2 * 22/7 * R * 1000
=> 1000 * 2 * 22/7 * R = 88000
=> R = 88000 * 7/1000 * 2 * 22
=> = 14
Thus , radius of wheel = 14 m
and , diameter of wheel = 2 * R
= 2 * 14
= 28 m

Like? Yes (7) | No (1)  

Vivek   9 years AGO

Circumference of the wheel=22/7*d
where d is the diameter
Now Total distance covered=88km=88*1000
Which is also equal to circumference * No of revolution
i.e 22/7*d*1000
Equating both
88*1000=22/7*d*1000
Therefore d=4*7=28 m
Therefore the answer is 4)

Like? Yes (8) | No (3)  

ABHINAV PUSHPAM   9 years AGO

No. of revolutions = 1000
Now
Distance travelled in 1 revolution = 2 * 22/7 * R
=> Distance travelled in 1000 revolutions = 2 * 22/7 * R * 1000
=> 1000 * 2 * 22/7 * R = 88000
=> R = 88000 * 7/1000 * 2 * 22
=> = 14
Thus , radius of wheel = 14 m
and , diameter of wheel = 2 * R
= 2 * 14
= 28 m

option 4)

Like? Yes (4) | No   

Supriya Mondal   9 years AGO

2*pi*r=88000/1000=88m
so, 2*r=28 m
So, option 4)28 m is the right answer

Like? Yes (6) | No (3)  

neha gupta   9 years AGO

let the radius of wheel be r m
then its diameter is 2r m
its circumference=2*pie*r
It covers a distance equal to its circumference in one revolution.
therefore distance covered in 1000 revolutions is= 2*pie*r*1000
According to question it is equal to 88km
2*pie*r*1000=88*1000
2r=(88*7)/22
2r=28
so diameter of wheel=28m

Like? Yes (4) | No (2)  

RAJAT KHANDELWAL   9 years AGO

distance covered in one revolution = 2*pi*r
distance covered in 1000 revolutions=1000*2*pi*r
therefore 1000*2*pi*r=88*1000
so diameter(2r)=88/pi
i.e =
28 m

Like? Yes (5) | No (3)  

SURAJ KUMAR   9 years AGO

for thousand revolution it covers 88 km
for one revolution it cover 88000/1000 = 88m
circumference of circle =2 x pie x radius
2 x pie x radius = 88
radius = 14
diameter = 2x 14 = 28m.

Like? Yes (8) | No (6)  

Soma Naresh   9 years AGO

1 revolution = 2 pi ×r
1000 revolutions = 2000pi ×r
88 km = 2000 pi×r
88000 = 2000×22×r/7
r = 88000×7/44000
r= 14
diameter = 2×radius= 28

Like? Yes (2) | No   

BABYMATHS   9 years AGO

In 1 rotation the wheel covers a distance equal to its circumfence of wheel, which inturn is circle
So 2* 22/7*(d/2) * 1000= 88 * 1000 ( in meters) , on solving we get d as 28 m

Like? Yes (2) | No   

nirmal kumar saini   9 years AGO

1000 revolutions for 88000 meters
so for 1 revolution=88 meter
means πd=88
and d=88/Ï€
and d=28 meter

Like? Yes (2) | No   

RAMPALA JYOTHI   9 years AGO

for 1000 revolutions wheel makes 2000*3.14*r=88*1000 m
2*3.14*r=88
r=14m
diameter=28m.

Like? Yes (2) | No   

yashwant verma   9 years AGO

circumference = (88*1000)/1000=88
2*(22/7)*r=88
therefore r=14
diameter = 2r=28

Like? Yes (2) | No   

sumit bansode   9 years AGO

1000×pi×D=88000
D=88×7÷22
D=28m

Like? Yes (1) | No   

SAGNIK DATTA   9 years AGO

2 pi r = 88
r=14
dia = 28

Like? Yes (1) | No   

Ravi shankar   9 years AGO

using formula :
no of rev *pi*dia= tot dist
option 4.

Like? Yes (1) | No   

vamsi krishna   9 years AGO

2*pi*r*1000=88000
diameter 2*r=88000/(1000*pi)
diameter = 28

Like? Yes (1) | No   

viswambher   9 years AGO

a wheel covers 2pi(radius) distance per revolution
in 1000 revolutions it covers 1000*2pi(radius).
radius = 88*10^3/2 *pi
radius =14
diameter = 2*radius
ans = 28

Like? Yes (1) | No   

Abhishek   9 years AGO

Circumference of circle = 2*(pi)*r = 88000/1000
2*r*(22/7)=88
2*r=28
Diameter =28

Like? Yes (2) | No (1)  

mohita verma   9 years AGO

circumference of circle is 2*pi*radius
88000=1000(2*22/7*radius)
radius=14m
diameter=2*radius=28 m

Like? Yes (2) | No (1)  

sudiptaa   9 years AGO

88km=88000m

2*pi*r*1000=88000
=>2*r=(88000*7)/(1000*22)
=>2*r=28 m

Like? Yes (1) | No   

anand vijay   9 years AGO

distance covered by wheel in 1000 revolution=88 km
=88000m
in 1 revolution =88000/1000=88 m
circumference of wheel = 88
2 * pi * r =88/22 * 7
2r= 28 m

hence , diameter of the wheel = 28 m
option (4) is the right answer.

Like? Yes (1) | No   

Subha Natarajan   9 years AGO

The wheel revolves 1000 times to cover 88000m.. so it revolves once for every 88 m.. now find the circumference of the wheel.. it will give us the radius which is 14.. therefore the diameter is 28

Like? Yes (1) | No   

SOMA NARESH   9 years AGO

1 revolution = 2*pi*r = 2*22*r/7 where r is radius
1000 revolutions = 1000*2*22*r/7 = 44000*r/7
given 1000 revolutions = 88 km = 88000
44000*r/7 = 88000
r = (88000*7)/44000
r = 14
Diameter = 2*r = 2*14 = 28 m

Like? Yes (1) | No   

Archie   9 years AGO

We know for circular objects,
No. of revolutions=(Distance covered /Circumference)
----->1000=(88km/2*pi*r)
------>Diametre(2r)=(88000m/(1000*(22/7)))
Solving ,
We get..
Diametre=28m
Hence option 4 is correct

Like? Yes (1) | No   

TUSHAR CHHABRA   9 years AGO

1000 rev =88 km
1 rev =88/1000=.088 =88 m
2*3.14*r=88
r=14

Like? Yes (1) | No   

PAWAN KUMAR   9 years AGO

r = 88000/(1000*2*pi) = 14m.
So, D = 2r = 28m.

Like? Yes (2) | No (1)  

Aravinth kumar   9 years AGO

The total distance traveled is 88 km = 88000 m
No. of revolutions = 1000
Now
Distance traveled in 1 revolution = 2 * 22/7 * R
=> Distance traveled in 1000 revolutions = 2 * 22/7 * R * 1000
=> 1000 * 2 * 22/7 * R = 88000
=> R = 88000 * 7/1000 * 2 * 22
=> = 14
Thus , radius of wheel = 14 m
and , diameter of wheel = 2 * R
= 2 * 14
= 28 m

Like? Yes (1) | No   

Hemavathy Nangan   9 years AGO

1 revolution=(88*1000)/1000
= 88 m
circumference(2*pi*r)=88m
r = 14 m
d=28 m

Like? Yes (1) | No   

santosh kumar patel   9 years AGO

distance covered in one revolution = (88*1000)/1000=88m
so, 2*22/7*r = 88
so r=(88*7)44 = 14 m
hence diameter = 2r = 2* 14 = 28 m

Like? Yes (1) | No   

vivek   9 years AGO

In 1 revolution it covers 88000/1000=88m
so 2*pi*r= 88
Or, pi*d= 88
d= (88/22)*7=28 m

Like? Yes (1) | No   

Shaswata Chowdhury   9 years AGO

1000 revolutions=88km
1revolution=88m
2x3.14xr=88
2r or diameter=28m

Like? Yes (1) | No   

Billal Hossain   9 years AGO

We know that, Circumference=2*pi*r
if radius is r, then diameter=2r
According to query,
so,2*pi*r*1000=88*1000
or, 2r=88/pi
or, 2r=88/3.1416
or, 2r=28m
Therefore, The diameter of the wheel is 28m(ans)

Like? Yes (1) | No   

POOJA SINGH   9 years AGO

No. of revolutions = 1000
Now
Distance travelled in 1 revolution = 2 * 22/7 * R
=> Distance travelled in 1000 revolutions = 2 * 22/7 * R * 1000
=> 1000 * 2 * 22/7 * R = 88000
=> R = 88000 * 7/1000 * 2 * 22
=> = 14
Thus , radius of wheel = 14 m
and , diameter of wheel = 2 * R
= 2 * 14
= 28 m

Like? Yes (1) | No   

Ayon Roy   9 years AGO

the wheel covers 88km /88*1000=88000 min 1000 revolution

so in 1 revolution it covers 88 m.
the perimeter of the circle = 2*pi*r
2*pi(22/7)*r=88
2*r=28

Like? Yes (1) | No   

Devendra Marghade   9 years AGO

If radius(in m.)=r, then
1000*(2*Pi*r)=80000, r=14
So diameter=2*14=28 m.

Like? Yes (1) | No   

Sourabh Gupta   9 years AGO

total distance =88*1000 m=88000m
distance covered in one revolution = 88000/1000=88m
circumference of wheel = distance in one revolution
(22/7)d=88
d=28

Like? Yes (2) | No (1)  

alpesh kurhade   9 years AGO

1000 rev = 88000 met
so,
1 rev = ?
solving ,1 rev = 88 met
i.e. circum = 88 met
2*pi*r=88
2r=28

Like? Yes (1) | No   

shreyanka patil   9 years AGO

2(pi)R=88;
2(22/7)R=88;
2*7=R;
R=14;
D=2R;
D=2*14;
D=28.

Like? Yes (1) | No   

Piu Rit   9 years AGO

1000*2*(22/7)*r = 88*1000
or, (44/7)* r = 88
or. r = 14
so, d= 2r = 28 m

Like? Yes (1) | No   

Sanjoy   9 years AGO

Distance covered in one revolution =((88 X 1000)/1000)= 88m.
2*pi*R = 88 ;2 x (22/7) x R = 88 ; R = 88 x (7/44) = 14 m.
Hence, Diameter=2*R=2*14=28

Like? Yes (1) | No   

shweta baheti   9 years AGO

distance covered in one revolution =((88 X 1000)/1000)= 88m.
2{color{Blue}prod }R = 88 ;2 x (22/7) x R = 88 ; R = 88 x (7/44) = 14 m.
diameter is 2x14= 28

Like? Yes (2) | No (1)  

Prashant Malvaniya   9 years AGO

The Total distance = (revolution * perimeter of the wheel); 88km=1000*2*pi*Radius 88000 (in meter)=2000*22/7*Radius Radius=88000*7/(44000) =14 m diameter=28 m

Like? Yes (1) | No   

Lavanya Rajendran   9 years AGO

2*pi*r*1000=88000
r=(88000)/(2*pi*1000)
r=14m
d=28m

Like? Yes (1) | No   

Biren Patel   9 years AGO

1000 revolution= 1000*Circumference of a circle
=1000*Ï€d
=1000*(22/7)d m
distance =1000*(22/7)d m
88km =1000*(22/7)d m
88000 m=1000*(22/7)d m
d=88*7/22
=4*7
=28m

answer is 4).

Like? Yes (3) | No (2)  

Jawahar   9 years AGO

The Total distance = (revolution * perimeter of the wheel); 88km=1000*2*pi*Radius 88000 (in meter)=2000*22/7*Radius Radius=88000*7/(44000) =14 m diameter=28 m

Like? Yes (1) | No   

Thupakula vasu   9 years AGO

he total distance travelled is 88 km = 88000 m
No. of revolutions = 1000
Distance travelled in 1 revolution = 2 * 22/7 * R
=> Distance travelled in 1000 revolutions = 2 * 22/7 * RUK * 1000
=> 1000 * 2 * 22/7 * R = 88000
=> R = 88000 * 7/1000 * 2 * 22
=> = 14

diameter of wheel = 2 * R
= 2 * 14
= 28 m

Like? Yes (1) | No   

krishan kant soni   9 years AGO

1 resolution=2*22/7*r; where r=radius
1000*2*22/7*r=88*1000
r=14
and diameter=2r=2*14=28

Like? Yes (1) | No   

BASWARAJ K PATIL   9 years AGO

1) Convert 88km to m by multiplying by 1000. You'll get 88km=88000m.
2) Let the diameter = x. Circumference of the wheel is (Ï€)*(diameter) = (Ï€)*(x).
3) Given that after 100 revolutions the wheel covers a distance of 88000m, the following equation is true:

(1000)*(Ï€)*(x) = (88000)

4) Solving for x, you should get diameter = 28.01m

Like? Yes (1) | No   

shahbaz Alam Ansari   9 years AGO

1000 rev = 88 km
1 rev = 88/1000
2*(22/7)*r = 0.088 km
r = 14 m
diameter d = 28 m

Like? Yes (1) | No   

Rohit Kumawat   9 years AGO

Answer: 28 m.
Explanation:
Distance covered in 1 revolution is 88/1000 = .088 km = 88 m.
since circumference = 2Ï€r = 88 m.
So diameter is 2r= 88/Ï€ =28 m.

Like? Yes (2) | No (1)  

Gomathi P   9 years AGO

1 revolution=88m
2*3.14*r=88
r=14.0127
d=28m

Like? Yes (1) | No   

Dinesh Kumar Kumawat   9 years AGO

Answer: 28 meter
Explanation:
Distance covered in 1 revolution is 88/1000 = .088 km = 88 meter
since circumference = 2Ï€r = 88 meter
So diameter is 2r= 88/Ï€ =28 meter

Like? Yes (1) | No   

naina shukla    9 years AGO

The Total distance = (revolution * perimeter of the wheel); 88km=1000*2*pi*Radius
88000 (in meter)=2000*22/7*Radius
Radius=88000*7/(44000) =14 m
diameter=28 m.

Like? Yes (1) | No   

Akshay Bhandakkar   9 years AGO

Wheel makes 1000 revolutions for distance of 88 km.
So for 1 revolution,
distance=88000/1000=88 m.
1 revolution of wheel=Circumference of wheel
therefore,diameter of wheel=88/3.14=28 m.

Like? Yes (1) | No   

akshay ishwarkar   9 years AGO

distance=n(3.14)diameter
88000=3.14*1000*d
d=28

Like? Yes (1) | No   

Shantanu Udapure   9 years AGO

distance covered in one revolution=(88*1000)/1000=88m
distance=2*3.14*r=88
2*22/7*r=88
R=88*(7/44)
=14m
d=2r
d=2*14
d=28

Like? Yes (1) | No   

shivam singh   9 years AGO

1 revolution=2*22/7*r
1000 revolution=2*22/7*r=85km(given)
then dia=2r=28m

Like? Yes (1) | No   

fatima saeed   9 years AGO

no. Of revolutions=total distance covered.
1 revolution=88m
2pir=88
d=28m

Like? Yes (1) | No   

KAVITHA   9 years AGO

Distance covered in one revolution =((88 X 1000)/1000)= 88m.
2*pi*R = 88 ;2 x (22/7) x R = 88 ; R = 88 x (7/44) = 14 m
d=2*14=28

Like? Yes (1) | No   

MUKESH   9 years AGO

distance traveled is 88 km=88000
revolution = 1000
distance traveled in 1 rev = 2*3.14*r
88000 = 2*3.14*r
r=14
therefore d= 2 r
=28m

Like? Yes (1) | No   

Indumathi   9 years AGO

1 revolution=88m
2*3.14*r=88m
r=14.0127
d=28m

Like? Yes (1) | No   

v v shyam kumar   9 years AGO

The total distance travelled is 88 km = 88000 m
No. of revolutions = 1000
Now
Distance travelled in 1 revolution = 2 * 22/7 * R
=> Distance travelled in 1000 revolutions = 2 * 22/7 * R * 1000
=> 1000 * 2 * 22/7 * R = 88000
=> R = 88000 * 7/1000 * 2 * 22
=> = 14
Thus , radius of wheel = 14 m
and , diameter of wheel = 2 * R
= 2 * 14
= 28 m

Like? Yes (2) | No (1)  

Aparajitha   9 years AGO

1000*2*pi*r=88000m
=> r=88000/(1000*2*pi)
=> r=14m
=> diameter=2*r=28m

Like? Yes (2) | No (1)  

Shiva Sharma   9 years AGO

2*pi*r*1000 = 88000
we want 2r
here value of pi = 22/7
so 2r = 28 m

Like? Yes (1) | No   

Chirantan Guin   9 years AGO

Let d be the diameter.
(22/7)*d*1000=88000
d=(88000*7)/(22*1000)
= 4*7
=28m

Like? Yes (1) | No   

Shanmukh   9 years AGO

it takes 88000m for 1000 revolutions so for 1 revolution it takes 88m ...and the distance covered by wheel in 1 revolution is 2*pi*r and that is equal to 88m .. so we can find r= 14 from that equation and diameter is 28

Like? Yes (1) | No   

jatin   9 years AGO

2*(22/7)*r*1000=88*1000
r=14
d=r*2=14*2=28m

Like? Yes (1) | No   

Rajanikanta Pradhan   9 years AGO

1000*2Pi*r= 88000
1000 * 22/7 * r = 88000
44r= 88 * 7
r=14
2r= 28

Like? Yes (1) | No   

suraj nath prasad   9 years AGO

1 rev =pi*d,& 1000 rev=88 km
so d=(88*1000)/1000*pi

Like? Yes (1) | No   

RAJ KUMAR   9 years AGO

Distance travelled is equal to the circumference of the wheel multiplied with number of revolution...so
88000=2*3.14*r*1000(88km=88000m)
r=14.01m
d=28.02m

Like? Yes (1) | No   

Thanakkumar T   9 years AGO

Circumference=3.14d
88/3.14=28km
28*1000/1000=28

Like? Yes (1) | No   

ramojirao narayanasetti   9 years AGO

The total distance travelled is 88 km = 88000 m
No. of revolutions = 1000
Now
Distance travelled in 1 revolution = 2 * 22/7 * R
=> Distance travelled in 1000 revolutions = 2 * 22/7 * R * 1000
=> 1000 * 2 * 22/7 * R = 88000
=> R = 88000 * 7/1000 * 2 * 22
=> = 14
Thus , radius of wheel = 14 m
and , diameter of wheel = 2 * R
= 2 * 14
= 28 m

Like? Yes (1) | No   

Patel Himaja   9 years AGO

By using the formula.
PI*D*1000=88
Sol: 3.1415*D*1000=88
D=88/3.1415
D=28.011

Like? Yes (1) | No   

Thilaka Elangovan   9 years AGO

1rev=88/1000
2pi r = 0.088
r=14
d=28

Like? Yes (2) | No (1)  

ajit kumar sharma   9 years AGO

1 revolution=88000m/1000=88m

which is equal to circumference(pie*d) of the wheel
therefore
(22/7)*d=88m
d=(88/22)*7

Like? Yes (1) | No   

sudeendra   9 years AGO

No. of  revolutions = 1000

Now

Distance travelled in 1 revolution = 2 * 22/7 * R

=> Distance travelled in 1000 revolutions = 2 * 22/7 * R * 1000

=>    1000 * 2 * 22/7 * R = 88000

=>                           R         = 88000 * 7/1000 * 2 * 22

=>                                      =  14

         Thus , radius of wheel = 14 m

          and  , diameter of wheel = 2 * R

                                               =  2 * 14

                                               =  28 m

Like? Yes (1) | No (1)  

29 Jun 2015 Sequence

What is the the next number of the following sequence
37, 63, 36, 64, 46, 54, 45, 55, .......

OPtion

1) 45
2) 46
3) 64
4) 43
5) 42
6) 55
7) 50
8) 52
9) 54
10)56

Solution

37 + 63 = 100
on interchanging the digits of 63 we get 36
36 + 64 = 100
on interchanging the digits of 64 we get 46
46 + 54 = 100
on interchanging the digits of 54 we get 45
45 + 55 = 100
on interchanging the digits of 55 we get 55
Next one is 55,
option 6)

Correct Option: 6 Best Solution (64)

ajit kumar sharma   9 years AGO

37 got decremented by 1 and is placed as the 3rd number as 36. To that 10 is added and placed as 5th number 46.
subtracing 1 gives 7th number (45).
now the 9th number,add 10 to it. So 9th number = 45 +10 == 55

Like? Yes (2) | No   

nirmal kumar saini   9 years AGO

every no is reciprocal of previous no.
like
63:-36
64:-46
54:-45

at same pattern
55:-55

Like? Yes (1) | No   

Vivek   9 years AGO

In this sequence ,37 to 63 is formed by decreasing 1 from units place i.e 6 and interchanging tenths and units place i.e63
next number is formed by just interchanging the position i.e36
next number is formed by now increasing the tenths place by 1,i.e 4 and interchanging the position i.e 64
next number by interchanging the numbers again 46
the sequence continues like this
The last number to be found is obtained just by interchanging the position..which is nevertheless the same number 55
So ,the answer is option 6)

Like? Yes (1) | No   

Snigdh Mayank   9 years AGO

37,..36,..46,..,45,..,55

we subtract 1 to get next term then add 10 to get the next term

Like? Yes (1) | No   

viswambher   9 years AGO

The first number(37) is decremented by one and is placed as 3rd number (36).
To that 10 is added and placed as 5th number (46)
Same sequence of subtracting one gives 7th number(45).
To get 9th number add 10 to the 7th number
45+10= 55

ans: 55

Like? Yes (1) | No   

RAKESH   9 years AGO

two series, or
37, (63,...> 36),( 64,...> 46), (54,...> 45), (55, ....> 55).

Like? Yes (1) | No   

Venkatesh kadali   9 years AGO

37,63,36,64,46,54,45,55--------

in the above series first term is leave it

and 2nd term is 63 .second term reverse is 36 that is 3rd number.

so 63 ,36

4th term is 64 .4th term reverse is 46 that is 5th term.

so 64 ,46

6th term is 54.6th term reverse is 45 that is 7th term.

so that's way

8th term is 55.8th term reverse is 55 that is answer .

so answer is 55.

37,63,36,64,46,54,45,55, 55.

Like? Yes (1) | No   

UDIT   9 years AGO

37(first no.), its reverse=73-10=63(second no.), its reverse 36(third no.), its reverse=63+1=64(fourth no.), its reverse 46(fifth no.), its reverse=64-10=54+1=55(sixth no.), now its reverse is answer i.e. 55(answer (option 6))

Like? Yes (1) | No   

Chandrima Goswami   9 years AGO

37-1=36
63+1=64
36+10=46
64-10=54
again 46-1=45
54+1=55
45+10=55
so ans is 6) 55

Like? Yes (1) | No   

Subha Natarajan   9 years AGO

consider the pair of values.. the total sum is 100. the sequence goes like this.. in case of even pairs, reduce 1 from the first number in the previous pair.. in case of odd pairs add 10 to the first number of the previous pair

Like? Yes (1) | No   

Mehul D Parmar   9 years AGO

100-37=63 100-46=54 100-55 then next term is 55 and
100-36=64 100-45=55 aftr that next is 45 after 54 ,46...

Like? Yes (1) | No   

Veerraj Chauhan   9 years AGO

37 is reduced by 10 to 36 and then 36 is increased by 10 to 46 and then it is reduced by 10 again to 45.
following the same pattern first we increase 45 by 10 to 55...
and hence 55 is obtained.

Like? Yes (1) | No   

Shiva Sharma   9 years AGO

look alternate number in the series
if we subtract from first number to find third one then we add same number as -1, +10 to +1 , -10
so we find next number in the series is 55.

Like? Yes (1) | No   

poojasaisri   9 years AGO

taking the alternative numbers in the series
37,36,46,45,___
this is in the sequence of -1,+10,-1,+10
37-1=36 36+10=46 46-1=45 45+10=55
55 is the required number

Like? Yes (1) | No   

SANTOSH   9 years AGO

37-1=36
36+10=46
46-1=45
45+10=55

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kanithi.shanmukharao   9 years AGO

for odd position in the sequence
37-1=36
36+10=46
46-1=45
so ans is 55....
45+10=55
even position in the sequence
63+1=64
64-10=54
54+1=55
55-10=45..sequence is repeated.

Like? Yes (1) | No   

Nikhil chavan   9 years AGO

37-36=1
36-46=-10
46-45=1
and 63-64=-1
64-54=10
54-55=-1
so as per trend..45+10=55

Like? Yes (1) | No   

RAJAT KHANDELWAL   9 years AGO

37
interchanging the digits, we get 73
now subtracting 1 from tens place
we get 63
again interchanging the digits we get 36
now again interchanging the digits we get 63
now adding 1 to the ones place
we get 64

Similarly we get 46,54,45,55
and the next no in the sequence is 55

Like? Yes (1) | No   

SURAJ KUMAR   9 years AGO

37-1= 36
36+10=46
46-1=45
45+10=55
so 55 is the next no.

Like? Yes (1) | No   

Ravi shankar   9 years AGO

odd position follows the sequence -1 and +10 while even position nos follows the sequence +1,-10. so next nos in seq is 55

Like? Yes (1) | No   

vamsi krishna   9 years AGO

sum adjecent number follow alternatively 99,110 between two hundereds.

Like? Yes (1) | No   

Pankaj Kumar Tiwari   9 years AGO

if u will see alternate numbers you will see that 37 reduced ones to 36 then plus 10 then again minus one and get 45 ...now it will again add 10 which will yield 55...

Like? Yes (1) | No   

praveendas   9 years AGO

reverse the digits ..we can get it..
observe those are mirror images of next number

Like? Yes (1) | No   

Kethineni Vinodh   9 years AGO

37,36,46,45,55,54
63,64,54,55,45,46
37,63,36,64,46,54,45,55,55,45,54,46

Like? Yes (1) | No   

saket kumar   9 years AGO

37-36=1
46-36=10
46-45=1
55-45=10
therefore 55 is next no.

Like? Yes (1) | No   

neha gupta   9 years AGO

37,63,36,64,46,54,45,55,
This series consists of two sequences:

37,36,46,45,
37-1=36
36+10=46
46-1=45
so next term is
45+10=55

and
63,64,54,55
63+1=64
64-10=54
54+1=55
55-10=45
so the above series can be written as:
37,63,36,64,46,54,45,55,55,45
so answer is 55

Like? Yes (1) | No   

V SARATH KUMAR   9 years AGO

Every number succeeding another is a reverse of its previous.
37,63,36,64,46,54,45,55,55. So 55 is the answer

Like? Yes (1) | No   

vikaskumar jaisal   9 years AGO

the sequence like this
37,63,36,64,46,54,45,55,55,45

Like? Yes (1) | No   

Geetharani   9 years AGO

if you see in the sequence given before,36 is reversed as (63+1=64),again reversed as 46. Similarly if we do it in the 45 as (54+1=55) and reversed to get 55 as answer.

Like? Yes (1) | No   

BASWARAJ K PATIL   9 years AGO

becaz sequence is like ths 37-1= 36
36+10 = 46
46-1 = 45
there fore 45+10 = 55

Like? Yes (1) | No   

santosh kumar patel   9 years AGO

in the term of 1 , 3 , 5 , 7 ..........odd term
in odd term of odd term added each digt=10
in odd term of even term added ech digit=9
then increase by 10
in the term of 2 , 4 , 6 , 8 ..........even term
in even term of odd term added each digt=9
in odd term of even term added ech digit=10
then decrease by 10
so i got next term is according to 1 case
hence , ans= 55 so option is 6

Like? Yes (1) | No   

saranya.s   9 years AGO

The sequence are
37 =63 ( the before of 7 is 6 , and the remaining digit, so 63)
63=36( interchange the values)
36=64
64=46
46=54
54=45
45=55
55=55

Like? Yes (1) | No   

Billal Hossain   9 years AGO

There are two series here,
one is 37, (37-1)36,(36+10)46,(46-1)45,(45+1)55, (55-1)54......

and, another is 63,(63+1)64,(64-10)54,(54+1)55, (55-10)45......

Like? Yes (1) | No   

m.lokeswari   9 years AGO

it is a combination of two series
1 st series -1,+10
second series +1,-10

Like? Yes (1) | No   

Gomathi P   9 years AGO

reverse of 63 is 36
reverse of 64 is 46
reverse of 54 is 45
reverse of 55 is 55
Ans:55

Like? Yes (1) | No   

RUPALI DADHE   9 years AGO

37, 63 ~ 36;
36, 64 ~ 46;
46, 54 ~ 45;
45, 55 ~ 55.
so ans is 55.

Like? Yes (1) | No   

PAVAN HATWAR   9 years AGO

37 36
63 64
46 45
54 55
55 54

Like? Yes (1) | No   

aman   9 years AGO

55 will be next
See alternate number. 37,36,46,45 so next will be 55,54
Similarly 63,64,54,55 so next will be 45,46 combination of both
Alternatively 37,63,36,64,46,54,45,55,55,45,54,46

Like? Yes (1) | No   

krishan kant soni   9 years AGO

because this is following a sequence alternatively.increasing first place no and decreasing second place no.

Like? Yes (1) | No   

RAKESH ARYA   9 years AGO

since (63-36)=27
(64-46)=18
(54-45)=9
(55-55)=0

so, the next term = 55

Like? Yes (1) | No   

Ayon Roy   9 years AGO

37(reverse-10)->63(reverse)->36(reverse+1)->64(reverse)->46(reverse-10)->54(reverse)->45(reverse+1)->55(reverse)->55

so by following the sequence i.e

r-10,r,r+1,r,r-10,r,r+1,?= we have to 'reverse' the last digit 55 witch is 55

so answer is '55'

Like? Yes (1) | No   

E.Yamuna   9 years AGO

37+9=46 which is number 5 in the series
46+9=55 should be the 7th number in the series

Like? Yes (1) | No   

Pravin   9 years AGO

1st 3rd element difference -1 and 3rd and 5th element difference +10 and so on

Like? Yes (1) | No   

PANKAJ   9 years AGO

The number in 1s (37)t got decremented by 1 and is placed as the 3rd number (36). To that 10 is added and placed as 5th number(46).
Same sequence of subtracing 1 gives 7th number (45).
To get the 9th number, you should add 10 to it. So 9th number = 45 +10 == 55

Like? Yes (1) | No   

pavan kumar   9 years AGO

(37,36)(63,64)(46,45)(54,55)(55,56)
63-9=54
37+9=46,46+9=55

Like? Yes (1) | No   

sandeepreddy   9 years AGO

odd number sequence follows -1 and +10 sequence. Here 37-1 and 36+10 likewise follow the sequence.

Like? Yes (1) | No   

KAVITHA   9 years AGO

The number in 1s (37)t got decremented by 1 and is placed as the 3rd number (36). To that 10 is added and placed as 5th number(46).
Same sequence of subtracing 1 gives 7th number (45).
To get the 9th number, you should add 10 to it. So 9th number = 45 +10=55

Like? Yes (1) | No   

shyamala   9 years AGO

starting with 37,alternatively 37-1=36.then in 40's 36+10=46..46-1=45..in that way in 50's 45+10 ans is 55

Like? Yes (1) | No   

Piyush Telang   9 years AGO

This is the actual series => 37,63,36,64,46,54,45,55,(55,45) ....
Divided into 2 series
Difference between odd placed numbers is shown below.
37 (-1) 36 (+10) 46 (-1) 45 (+10) 55
^ ^ ^ ^
| | | |
63 (+1) 64 (-10) 54 (+1) 55 (-10) 45
Difference between even placed numbers is shown above.

Like? Yes (1) | No   

ujjwal   9 years AGO

37 36
36 46
46 45
45 55

Like? Yes (1) | No   

Thupakula vasu   9 years AGO

37,63,36,64 and 46,54,45,55
Difference between the first term in first sequence and second sequence is 9.
As same the next first term in the sequence wiil be of value 46+9=55

Like? Yes (1) | No   

Rohit Kumawat   9 years AGO

Given Sequence: 37, 63, 36, 64, 46, 54, 45, 55,...
Answer: 55
Explaination: we separate it as:
37, 36, now add 10 thn it become 46, 45
and second sequence is: 63, 64, and now substract 10 thn it become 54, 55

now next is again add 10 in sequence 46, 45
so 45+10=55
So 55 is answer.

Like? Yes (1) | No   

vinod   9 years AGO

37-1=36
36+10=46
46-1=45
45+10=55

Like? Yes (1) | No   

saikrishnagoud   9 years AGO

there are two sub series in given series
first series is 37 36 46 45
37-1=36
36+10=46
46-1=45
45+10=55
second series is 63 64 54 55
so answer is 55 because he is asking next number in first series

Like? Yes (1) | No   

shubham shukla   9 years AGO

alternate number from 37 are in sequence:
37-1=36
36+10=46
46-1=45
now,required number is: 45+10=55
also alternate number from 63 are the reverse of the digits of next term like,
36=63, 46=64, 45=54, 55=55

Like? Yes (1) | No   

Medi Lethesh   9 years AGO

Its in the increment of the number 54 situated before number 45 and 45 and 54 are mirror images.

Like? Yes (1) | No   

shivani singh   9 years AGO

37,63,36,64 and 46,54,45,55
Difference between the first term in first sequence and second sequence is 9.
As same the next first term in the sequence wiil be of value 46+9=55

Like? Yes (1) | No   

kamatchi   9 years AGO

37 reverse and subtract 63
again 36 .....
so 55

Like? Yes (1) | No   

Monika Kashyap   9 years AGO

there are two series...
first is 37,36,....
and second is 63,64,....

in first series-first subtract 1,then add 10,then again subtract 1and again add 10 and so on...

in second series-just opposite of the first series
first add1 ,then subtract 10 and so on..

Like? Yes (1) | No   

jatin   9 years AGO

37-1=36
63+1=64
next value will be interchange of 64 i'e 46 and same above process will repeat

Like? Yes (1) | No   

asha   9 years AGO

each pair is changing its position in next location

Like? Yes (1) | No   

tejaswini   9 years AGO

first two alternate numbers are decreasing by 1 then the next alternate number is increased by 10 and it goes on

Like? Yes (1) | No   

Biren Patel   9 years AGO

63-37=26
63-36=27
64-36=28
64-46=18(28-10)
54-46=8
54-45=9
55-45=10(next is 10-10)
observing above next is 55-0=55.

Like? Yes (1) | No   

Sheenu Arora   9 years AGO

firstly 63-37=26
then 63-36=27
then 64-36=28
then 64-46=18
then 54-46=8
then goes increasing 54-45=9
then 55-45=10
then 56-55=1

Like? Yes (1) | No   

26 Jun 2015 Area

A parallelogram has sides 60 m and 40 m and one of its diagonals is 80 m long. Then its area is

OPtion

1) 480 Sqrt(15) m^2
2) 450 m^2
3) 450 Sqrt(15) m^2
4) 600 m^2
5) 650 m^2
6) 600 Sqrt(15) m^2
7) 550 Sqrt(15) m^2
8) 350 Sqrt(15) m^2
9) 680
10)300 Sqrt(15) m^2

Solution

Using diagram
ABCD
s = 1/2(60+40+80) = 90 m
and use
triangle area = Sqrt{s(s-a)(s-b)(s-c)}
*2
solve
Option 6)

Correct Option: 6 Best Solution (34)

mohita verma   9 years AGO

by herons formula,
s=(1/2)(a+b+c)
s=(40+60+80)/2
s=90
area of //gm =2Xsqrt(90(90-60)(90-40)(80-80))
=2X300 sqrt(15)
=600 sqrt(15) m^2

Like? Yes (32) | No (5)  

Vivek   9 years AGO

Considering parallelogram as two symmetrical triangles with sides 40,60,80 metres
we have
Area of triange= Sqrt(s(s-40)(s-60)(s-80))
s=(40+60+80)/2=90
So area= Sqrt(90*(90-40)*(90-60)*(90-80))
=Sqrt(90*50*30*10)
=300*Sqrt(15)
Since there are two such triangle
Total area of parallelogram =2*300*Sqrt(15)
=600*Sqrt(15) m^2
Therefore the answer is 6)

Like? Yes (33) | No (9)  

Rakesh Kumar   9 years AGO

my answer is correct ,because first of all i find height and then calculate its area

Like? Yes (13) | No (3)  

viswambher   9 years AGO

let the parallelogram be divided into 2 similar triangles of side lengths a,b,c which are 40,60,80 respectively

area of 1 triangle = sqrt[s(s-a)(s-b)(s-c)]
where s= (a+b+c)/2
and area of the parallelogram is twice the area of the triangle which comes out to be 600sqrt(15)m^2

Like? Yes (13) | No (3)  

POOJA SINGH   9 years AGO

Let ABC be a triangle such that a=60m b=40m c=80m so s=(a+b+c)/2=90m
Then area of triangle=?s(s-a)(s-b)(s-c)=300?15m^2
So area of parallelogram=2*300?15=600?15m^2

Like? Yes (14) | No (6)  

anand vijay   9 years AGO

Let ABCD be a parallelogram where AB is parallel to CD
Let AC be one of its diagonal
then, ABC becomes triangle
where
AB = 60m, BC=40m and AC = 80m
s=1/2(60+40+80)m=90m
where s is the semi perimeter of the triangle
(s-a) = 30m, (s-b) = 50m and (s-c)=10m
calculating area of triangle when all the three sides are given using Heron's formula
Area of triangle ABC = Sqrt( s(s−a)(s−b)(s-c)) m^2
= Sqrt(90 * 30 * 50 * 10) m^2
= 300 Sqrt(15) m^2
Hence, area of ABCD =2* area of ABC
=600 Sqrt(15) m^2
option (6) is the right answer

Like? Yes (15) | No (9)  

manju   9 years AGO

Explanation:
AB = 60m, BC=40m or AC = 80m
s=1/2(60+40+80)m=90m
(s-a) = 30m, (s-b) = 50m and (s-c)=10m
Area of ΔABC = √s(s−a)(s−b)(s−c)
=√90×30×50×10m^2=300√15−−m^2
Area of //gm ABCD = 600√15m^2

Like? Yes (7) | No (1)  

sudiptaa   9 years AGO

s=(1/2)*(40+60+80)=90
area of ||gm=2*(sqrt(90*10*50*30))=600sqrt(15)

Like? Yes (7) | No (3)  

RAJESH   9 years AGO

s=1/2(60+40+80)=90cm
s=1/2(s(s-a)(s-b)(s-c))
abc=300sq root 15 m^2
abcd=600sqroot15m^2

Like? Yes (6) | No (2)  

kanithi.shanmukharao   9 years AGO

ab=40m,bc=60m,ac=80m..
s=1/2(40+60+80)=90m
triangle ABC area=sqrt(s(s-a)(s-b)(s-c)=300sqrt15 m^2.
area of ||gm ABCD=600sqrt15 m^2

Like? Yes (5) | No (2)  

vamsi krishna   9 years AGO

sum of the areas of two triangles formed in parallelogram is
= 2*sqrt(s(s-a)(s-b)(s-c))
s=a+b+c/2

Like? Yes (4) | No (1)  

Chandrima Goswami   9 years AGO

angle A = arccos( (p2 - a2 - b2) / (-2ab) )=104.47 degree
other diagonal, q = √( a2 + b2 + 2ab cos(A) )=63.24 m
area K = ab sin(A)=2323.79 m^2= 600( sqrt15) m^2

Like? Yes (5) | No (2)  

Soma Naresh   9 years AGO

two sides 40, 60 with diagonal 80 of parallelogram makes two triangles of three sides 40, 60, 80
area of parallelogram becomes twice of the area of triangle
area of triangle with sides a, b and c is
sqrt (s (s-a)(s-b)(s-c))
s =(a+b+c)/2 =(40+60+80)/2=90
area= sqrt (90×50×30×10)
=sqrt (1350000)
=sqrt (90000×15)
=300sqrt(15)
area of parallelogram= 2×300 sqrt (15)
=600sqrt (15) m^2

Like? Yes (4) | No (1)  

Math Lovers   9 years AGO

AB=60 m =c, BC= 40 m=a, and AC=80m=b

now,

s= 0.5 *(40+60+80) = 90
Area of triangle ABC = sqrt {(s-a)(s-b)(s-c)}
=> A = 300 sqrt(15)
Area of Parallelogram = 2*300sqrt(15) = 600sqrt(15)

Like? Yes (3) | No   

SURAJ KUMAR   9 years AGO

diagonal^2= 40^2+60^2+2cosx
cosx=1/4
sinx=sqrt(15)/4
area=60*40*sqrt(15)/4
area=600sqrt(15)m^2

Like? Yes (6) | No (3)  

Ravi shankar   9 years AGO

considering half parallelogram a triangle is formed 3 side are given 40 ,60, 80.
applying herons formula for half triangle A=sqrt(p*(p-40)*(p-60)*(p-80)). where p=(40+60+80)/2=90.
ans==2*a= 600*sqrt(15)

Like? Yes (3) | No   

shubham shukla   9 years AGO

since, diagonal divides parallelogram into 45 degree angles.
so, area of parallelogram=(sum of area of two similar triangles)+(area of rectangle)
now,for triangles:
base=80cos45-40
from Pythagoras,height=square root{(60^2)-(base^2)}
now,for rectangle:
length=40-base of triangle
breadth=height of triangles
now, Area of parallelogram=2*{(1/2)*(16.568)*(57.66)}+{57.66*23.432}=23015.6m^2
so option(6)=600sqrt(15)=2315.6(approx.)

Like? Yes (3) | No   

prithwiraj banerjee   9 years AGO

drawing the diagram we get two equal triangle with sides of length 60m,40m,80m.
finding the area of each triangle and doubling it we get the area of the parallelogram.

Like? Yes (4) | No (1)  

syed kashif ullah   9 years AGO

s=(a+b+c)/2
s=90
apply herons formula
are of triangle=sqrt s(s-a)(s-b)(s-c)
=sqrt 90*30*50*10
=sqrt 1350000
=300 sqrt 15
area of parallelogram=2*300 sqrt 15
=600sqrt 15 square meter

Like? Yes (4) | No (1)  

aditi goyal   9 years AGO

we can solve it using herons formula..
and calculate area of triangle i.e 300 sqrt (15) and doubling it we get option 6

Like? Yes (3) | No   

Shiva Sharma   9 years AGO

we find height and base*height is answer
now we find cosA
6400 = 3600+1600+2*40*60*cosA
cosA = 1/4
sinA=sqrt(15)/4
so sinA = height/hypotenuse
sqrt(15)/4 = height/40
height = 10*sqrt(15) m
area = 60*10*sqrt(15)m^2
=>600sqrt(15) m^2

Like? Yes (4) | No (1)  

KAVITHA   9 years AGO

We can relate lenth f sides of triangle as s=1/2(40*80*60)=90
from diagonal its a triangle thus area of triangle is sqrt of(90*(90-40)*(90-80)*(90-60))=300sqrt15 metr sqr.
For a paralellogram 2*300sqrt 15 metr sqr=600*sqrt 15 metr sqr.

Like? Yes (3) | No   

vivek   9 years AGO

s=(40+60+80)/2=90
so required area is = 2*[90*30*50*10]^1/2=600 sqrt(15)m^2

Like? Yes (5) | No (2)  

shiva gurram   9 years AGO

area of abcd=2area of abc
a=60,b=40,c=80
s=(a+b+c)/2
area of abc=sqrt(s(s-a)(s-b)(s-c))=3oosqrt(15)
area of parelleo(abcd)=600sqrt(15)

Like? Yes (3) | No   

m.lokeswari   9 years AGO

s=(a+b+d)/2
=(60+40+80)/2
=90
Area=2sqrt(s(s-a)(s-b)(s-c))
=2sqrt(90×30*50*10)
=600sqrt(15)

Like? Yes (3) | No   

SANTOSH   9 years AGO

by Hercules formula area of triangle one triangle is (area)^2=s(s-a)(s-b)(s-c) where s=(a+b+c)/2
==> area=300sqrt(15)
==> area of parallelogram is 600 sqrt(15)

Like? Yes (3) | No (1)  

Subha Natarajan   9 years AGO

Let ABCD be a parallelogram.. the area of the triangles separated by a diagonal will be equal.. the area of one triagle is 300sqrt(15) m^2..
therefore the area of the entire parallelogram is 2*300sqrt(15) which is equal to 600sqrt(15) m^2.

Like? Yes (2) | No   

SOMA NARESH   9 years AGO

the parallelogram with given two sides and diagonal is equal to two triangles of sides 40, 60, 80
So Area of parallelogram = twice that of area of triangle
area of triangle with sides a,b,c = Sqrt(s(s-a)(s-b)(s-c))
where s=(a+b+c)/2 = (40+60+80)/2 = 90
area of triangle = Sqrt(90*50*30*10)
=Sqrt(900*100*15)
= 30*10*Sqrt(15)
=300Sqrt(15)
Area of parallelogram = 2*300Sqrt(15)
=600Sqrt(15) m^2

Like? Yes (2) | No   

akshay kumar   9 years AGO

using hero's formula

Like? Yes (4) | No (2)  

v v shyam kumar   9 years AGO

Here we will be calculating the area of two triangles,by adding those becomes the area of parallelogram.
Area of triangle is =Sqrt(s*s-a*s-b*s-c);
S=a+b+c/2;
a,b,c are sides of a triangle;
So s=80+40+60/2=90;
Area=Sqrt(90*10*50*30)=>300Sqrt(15);
Area of parallelogram =2times area of triangle.
2*300Sqrt(15)m^2;
Area =600Sqrt(15)m^2.

Like? Yes (3) | No (1)  

Snigdh Mayank   9 years AGO

let the height of parallelogram be h
let the foot of perpendicular be at a position x on the base.
then
h^2=40^2-x^2
h^2=80^2-(60-x)^2
solving we get h
so area is 60*h

Like? Yes (3) | No (2)  

Piyush Telang   9 years AGO

Height of the Parallelogram = sqrt(1500) = 10 x sqrt(15)
Base of the Parallelogram = 60
Area of Parallelogram = Base x Height = 600 x sqrt(15)

Like? Yes (3) | No (2)  

Kumar Ankur   9 years AGO

since two triangle are formed with same area i.e sides are 80m, 60m, 40m
Area of triangle is calculated with the help of heron's formula:-
s=80+40+60/2=90m
Area of triangle= sqrt s(s-a)s(s-b)(s-c)
on calculation we get s=300 sqrt (15)
hence, area of parallelogram=2* area of triangle=600 sqrt(15) m^2

Like? Yes (1) | No (1)  

RAVAL   9 years AGO

area of paralleleogram abcd=2* area of triangle abc
=2* sqrt(s*(s-a)*(s-b)*(s-c))
=2* 1161.89 (s=half periphery of abc)
= 2323.079 m^2
=600 sqrt m^2

Like? Yes (2) | No (2)  

25 Jun 2015 Two digit number

2 two digit numbers chosen in such a way that all 4 digits used are distinct, are such that their sum is 90. How many such pairs are possible if in both numbers units place is 1 more than tens place.

OPtion

1) 1
2) 2
3) 3
4) 4
5) 5
6) 6
7) 7
8) 8
9) 9
10)0

Solution

Let given number are
10x + (x+1) and 10y + (y+1)
then as given
10x + (x + 1) + 10y + (y + 1) = 90
11x + 11y = 88
x + y = 8
So 12 & 78, 23 & 67, 34 & 56.

Option 3)

Correct Option: 3 Best Solution (27)

SURAJ KUMAR   9 years AGO

12 +78,23+ 67, 34+56 these are the the 3 pairs

Like? Yes (3) | No (1)  

viswambher   9 years AGO

let the numbers be(x x+1) and ( y y+1)
and the sum is 90 there fore
x+y+2 = 10
I.e x+y = 8
therefore the pairs are
(12,78) (23,67) , (34,56)

Like? Yes (2) | No (1)  

Chandrima Goswami   9 years AGO

12+78=90
23+67=90
34+56=90
So ans is 3

Like? Yes (1) | No   

RAJAT KHANDELWAL   9 years AGO

the nos are
12+78=90
23+67=90
34+56=90

Like? Yes (2) | No (1)  

Surendhar Ramanujam   9 years AGO

the three possibilities such as:
12+78,
23+67 and
34+56 are the only possibilities for the given conditions that are as follows
1. units place should be 1 more than tens place
2. sum of the numbers should be equal to 90
3. the numbers used should be distinct

Like? Yes (1) | No   

SANTOSH   9 years AGO

34 56
23 67
12 78

Like? Yes (1) | No   

darladiwakar   9 years AGO

a b
c d
-----
b+d sum must equal to 10 ;; so total sum=90 gives
so it seems a+c=8. then check by the given condition there three such kind of pairs.
12+78
23+67
34+56

Like? Yes (1) | No   

vamsi krishna   9 years AGO

let two digit numbers
first number = ab
second number =cd
require answer is = 90
so b+d=10;
s0 we need digits for a,b, positions such that a+b=8
so pairs are (1,7)(2,6)(3,5) bcz digits are distinct
ans=3 pairs are possible

Like? Yes (1) | No   

Deepthi   9 years AGO

12+78=90
23+67=90
34+56=90

Like? Yes (1) | No   

Harihara Panigrahy   9 years AGO

the range of the smaller number is 12 - 45 as 45*2=90 but 45 isn't an option cause 4 digits wont be distinct so range is reduced to 12 to 34 and so only 3 pairs possible 12 78,23 67 and 34 56

Like? Yes (1) | No   

Ramdas Singathiya   9 years AGO

12,78 23,67 56,34

Like? Yes (1) | No   

RAVAL   9 years AGO

as per given condition,
ans. is 3
there pairs are....
1) 1278
2) 2367
3) 3456

Like? Yes (1) | No   

Dhanraj Wanjare   9 years AGO

12 + 78 = 90;
23 + 67 = 90;
34 + 56 = 90; that's why option 3 pairs

Like? Yes (1) | No   

vivek kr. chatterjee   9 years AGO

four possible cases possible
1> 01 and 89
2> 23 and 67
3> 34 and 56

Like? Yes (1) | No   

p.supriya   9 years AGO

12+78=90
23+67=90
34+56=90
these series continue in reverse order so only 3 paires

Like? Yes (1) | No   

shree   9 years AGO

suppose two numbers 10's place are x and y
therefore 10x+ x+1+10y+y+1=90
11x+11y+2=90
x+y=8
therefore 3 pairs are available that are(1, 7), (2, 5)
(3, 5)

Like? Yes (1) | No   

Math Lovers   9 years AGO

Let ten digit place numbers are x and y
then,
numberes are 10x+(x+1) and 10y+(y+1) where x!=y
sum = 11 (x+y)+2 =90
=> x+y = 8
possible value of (x,y) are (1,7), (2,6), (3,5)
hence possible pair of numbers are 3

Like? Yes (1) | No   

Purnima Paliwal   9 years AGO

pairs are formed by :
12
23
34
56
67
78
89
in which 45 and 89 are not fulfilled the condition of the question so 12&78, 23&67,34&56 are the only three pairs.

Like? Yes (1) | No   

ajit kumar sharma   9 years AGO

12+78=90(1st pair)
23+67=90(2nd pair)
34+56=90(3rd pair)

Like? Yes (1) | No   

akshay ishwarkar   9 years AGO

12+78,
23+67,
34+56,

Like? Yes (1) | No   

RUPALI DADHE   9 years AGO

12+78=90;
23+67=90;
34+56=90.

Like? Yes (1) | No   

veeramanikandan   9 years AGO

12+78 = 90
23+67= 90
34+56=90

Like? Yes (1) | No   

Payal meshram   9 years AGO

23+67
12+78
34+56

Like? Yes (1) | No   

selva kumar R R   9 years AGO

12+78=90
23+67=90
34+56=90

Like? Yes (1) | No   

swetha   9 years AGO

01+89=90
12+78=90
23+67=90
34+56=90

Like? Yes (1) | No   

shabana banu shaik   9 years AGO

the numbers which satisfy above conditions are (56,34),(78,12),(23,67)......so three is the answer

Like? Yes (1) | No   

Mohammad Husain   9 years AGO

(12,78),(23,67),(34,56) not (45,45) they r not distinct

Like? Yes (1) | No   

24 Jun 2015 Partnership

A, B, C enter into partnership. A invests some money at the beginning. B invests double the amount after 6 month and C invests thrice the amount after 8 months. If the annual profit be Rs. 9000, then C's share is

OPtion

1) 2875
2) 3150
3) 3750
4) 3000
5) 3600
6) 3675
7) 3250
8) 3800
9) 3775
10)3850

Solution

Let A's investment Rs. x for 12 month.
Then B's investment Rs. 2x for 6 month
And, C's investment Rs. 3x for 4 month
Therefor A : B : C = (x*12 : 2x*6 : 3x*4 = 1:1:1)
C's share = 9000/3 = 3000
Option 4)

Correct Option: 4 Best Solution (59)

SAURABH SINGH   9 years AGO

for time and amount invested their total amount invested for the year will be same.
sotheir profit will be equal

Like? Yes (6) | No   

SURAJ KUMAR   9 years AGO

A:B:C is written as
12x +12x +12x=9000
X=250
So c's share is =12 X 250=3000

Like? Yes (5) | No   

viswambher   9 years AGO

A invests 'x' amount of money and 1year time
B invests '2x' amount of money and 6months time
C invests '3x' amount of money and 4 months time so each of them is going to get equal share of the profit which is 3000

Like? Yes (2) | No   

Nikhil chavan   9 years AGO

A contributes x for 12 months so A=12x
B contibutes for 6 months so B=12x
C contributes for 4 months so C=12x
total 36x=9000 gives x=250
so C share is 12x=12x250=3000

Like? Yes (2) | No   

k sureshbabu   9 years AGO

even though B&C late join they have equal share
B-join after 6 months with double amount means half of year with double amount
C-join after 8 months with thrice amount at 1/3 of the year with thrice amount
so finally they have equal in profit

Like? Yes (2) | No   

Vivek   9 years AGO

let amount invested by A be x
Then the amount invested by B is 2x and that by C is 3x
Now we know that for annual profit
profit shares= A:B:C=12*x:(12-6)*2x:(12-8)*3x
=12:12:12=1:1:1
Therefore the share of C =1/3*9000=3000
So the answer is 4)

Like? Yes (3) | No (1)  

Veerraj Chauhan   9 years AGO

A:B:C=x*12:2x*6:3x*4 = 12x:12x:12x = 1:1:1

C's share= 9000 * (13) = 3000

Like? Yes (2) | No   

anand vijay   9 years AGO

Let's A's investment be Rs. x
then Ratio of capitals =(x*12) : (2x*6) : (3x*4)
= 12x : 12x :12x
= 1 : 1 : 1
Hence , C's share=Rs 9000 * 1/3
= Rs 3000
option 4) is the right answer.

Like? Yes (1) | No   

Mani Sachdev   9 years AGO

A=x
B=2x
C=3x
A invest for 12 months
B invest for 6 months
C invests for 4 months
A :B :C=x*12 : 2x*6 : 3x*4=3x : 3x : 3x
C=3x=9000
x=3000 -----> Option 4

Like? Yes (1) | No   

Chandrima Goswami   9 years AGO

A's share 12x, B's share 12x and C's share also 12x
so, 36x=9000 => x=250
so C's share = 12*250 = 3000

Like? Yes (1) | No   

Math Lovers   9 years AGO

Let A invested x rupee then,
B invested 2x and C invested 3x rupees

Now A's investment is for 12 months
B's investment is for 6 months and
C's investment is for 3 months

so, ratio should be 12X:12X:12x = 1:1:1
so each one should get 3000

Like? Yes (1) | No   

Kumar Ankur   9 years AGO

Let A investment be Rs x
Ratio of Capital=(x*12):(2x*6):(3x*4)=12x:12x:12x=1:1:1
C's share=9000*(1/3)=3000

Like? Yes (1) | No   

Mehul D Parmar   9 years AGO

let A invest x
ratio
x*12:2x*6:3x*4=1:1:1

c share=9000*1/3
=3000

Like? Yes (1) | No   

sravani   9 years AGO

share is directly proportional to time period *amount..
so,c's share is 3000/-

Like? Yes (1) | No   

sompon temtheerakij   9 years AGO

A 1 part x 12 months = B 2 parts x 6 months = C 3 parts 3 months
C's share = 9000/3 - 3000

Like? Yes (1) | No   

shree   9 years AGO

suppose a's share is x
b's share is 2x and c's share is 3x
therefore x*12 : 2x *6 : 3x*4=1:1:1
therefore the share of c is (1/3)*9000=3000Rs.

Like? Yes (1) | No   

poojasaisri   9 years AGO

let the amount A invested be x
x*12:2x*6:3x*4
x:x:x
share of c is
(x/(3*x))*9000
3000

Like? Yes (1) | No   

moumita   9 years AGO

let A's investment be Rs. x
Then, according to the question ratio of capitals =
(x*12 : 2x*6 : 3x*4) = 12x:12x:12x = 1:1:1
therefore, C's share = Rs.(1/3 * 9000) = Rs.3000
An (4)3000

Like? Yes (1) | No   

Shiva Sharma   9 years AGO

x,2x and 3x are money which invested
so let say profit with rate of y% per annum
profit
in one year = x*y/100
in half year = 2x*y/2*100
in one third year = 3x*y/3*100
so all three are equal
now break 9000 in 3 parts = 3000

Like? Yes (1) | No   

Snigdh Mayank   9 years AGO

let the money invested by A be x,then for B is 2x and C is 3x
Therefore the ratio of their profits will be
x*12:2x*6:3x*4=1:1:1

So all will get equal amount,i.e,3000
Therefore,C's share is Rs 3000

Like? Yes (1) | No   

Lavanya Rajendran   9 years AGO

A invests x amt for 12 months ,
B invests 2x amt for 6months,
C invests 3x amt for 4 months ,
however the amt invested by all the 3 are same for 12 months so annul profit should be equally divided
9000/3=3000 is tha ans.

Like? Yes (1) | No   

krishna chandrika   9 years AGO

let the initial amount of A,B,C be x,2x,3x
ratio of their investments =(x*12) : (2x*6) : (3x*4)
= 1 : 1 : 1

c's share=1/3*9000 = 3000

Like? Yes (1) | No   

neha gupta   9 years AGO

Let ratio of money invested by A,B and C be 1:2:3
Ratio of time period for which the money is invested 1:(6/12):(4/12) = 12:6:4=6:3:2
The compounded ratio of both
6:6:6=1:1:1
Therefore each wil get equal share after a year and the amount of share is
9000/3=3000
Thus C's share is 3000.

Like? Yes (1) | No   

Anuj Rai   9 years AGO

Let A invest x amount then investment by A in 12 month will be 12x.
B invest twice of A investment for 6 months=2x*6=12x
C invested thrice of A for 4 months= 3x*4=12x
this they have equal share in profit=9000/3=3000 Answer

Like? Yes (1) | No   

pankaj daripa   9 years AGO

let A invested RS x. so B invested Rs.2x and C invested Rs. 3x.
a's amount works for 12 month. b's amount works for 6 month.c's amount works for 4 month.
so the ration of profit is 12*x : 6 *2x :4*3x=1:1:1
so every one will get same amount .the amount is Rs.3000

Like? Yes (1) | No   

syed kashif ullah   9 years AGO

let amount of A for investment =x
therefore for 12 months=12x
similarly according to the condition B=C=12x during one year
total profit in that year=9000
therefore c's share=12x/36x *9000=3000

Like? Yes (1) | No   

Surendhar Ramanujam   9 years AGO

Let x be A's investment then B's investment will be 2x and C's investment will be 3x
Since B invested 6 months later and C invested 8 months later then
ratio of their investment is = (x*12):(2x*6):(3x*4)
=12x:12x:12
since their ratios being equal the profit is divided equally among them so 9000/3=3000
so each of them get equal share in the profit of Rs.3000
Thereby C's share is Rs. 3000/-

Like? Yes (2) | No (1)  

nidhi   9 years AGO

Let A invest Rs. x then B 2x and C 3x for 12 months, 6 months and 4 months respectively.
(x*12):(2x*6):(3x*4)=1:1:1
The profit of c would be 9000*1/3=3000.

Like? Yes (1) | No   

Dinni   9 years AGO

(X.12):(2x.6):(3x.4)
12x:12x:12x
1:1:1
Equal shares
So c's share is 3000

Like? Yes (1) | No   

vishwanath   9 years AGO

LET THE INITIAL INVESTMENT IS ' X ' THEN
ACCORDING TO GIVEN IN QUESTION
X * 12 : 2X * 6 : 3X * 4
then 1:1:1
(1/3)*9000=3000

Like? Yes (1) | No   

Divyansh jaiswal   9 years AGO

x*12+2x*6+3x*4=9000

x=250
c=250*12=3000

Like? Yes (1) | No   

priyanka tripathi   9 years AGO

Let A invest x Rs, then B= 2x abd C=3x
Time taken by money for A 12 months, for B 6 months and for C 4 months.
12x+2x.6+3x.4=9000
X=250
Share of C=12x=12×250=3000

Like? Yes (1) | No   

Kamlesh Kumar   9 years AGO

A invest =x
B invest =2x
C invest=3x

x 2x 3x
| | |
12 6 4
=12x 12x 12x
ratio =1:1:1:
so
c share =1*(9000/3)
3000

Like? Yes (1) | No   

vishva shikha   9 years AGO

Let A invests x amount for 12 months, B invests 2x amount for 6 months and C invests 3x amount for 4 months.
So, ratio of their capitals= (x*12):(2x*6):(3x*4)
= 12x : 12x : 12x
= 1 :1 : 1
So, C's share= RS. (9000*(1/3))
=Rs. 3000

Like? Yes (1) | No   

karthiga   9 years AGO

Share Ratio of A : B : C is x*12 : 2x*6 : 3x*4 = 1:1:1
c' share is 9000/3 = 3000;

Like? Yes (1) | No   

jahnavi   9 years AGO

let X be the amount invested by A for 12 months, then B invests 2X for 6months, and C invests 3X for 4 Months
ratios of their profits are equal.
therefore 9000/3=3000
so C's share is 3000

Like? Yes (1) | No   

vivek kr. chatterjee   9 years AGO

in a year.. a's money (say x) worked for for 12 months, so =x*12= 12x
b"s money (2x)worked for 12-6 = 6 months ,so = 2x*6 = 12x
c's money (3x) worked gor 12-8 = 4 months. so =3X*4 = 12


hence money will be divided between them as 12x:12x:12x
so c's share 9000/3 = 3000 ans

Like? Yes (1) | No   

anuanwesh   9 years AGO

a=12months,b=6months,c=4months, given a=2b=3c so the 9000 annual profit is divided among them equally so c's share=3000 option 4

Like? Yes (1) | No   

ajit kumar sharma   9 years AGO

let capital of A is x therefore capital of B and C will be 2x and 3x respectively.
now total capital of A=x*12 months=12x
total capital of B=2x*6 months=12x
and total capital of C=3x*4 months=12x
therefore capital ratio among three=1:1:1
total amount =9000
there share of C=3000..

Like? Yes (1) | No   

darladiwakar   9 years AGO

time*investment gives share
so share for a =12*inv
for b=6m*2*inv
c=4*3*inv
so the share is same for all investers.

Like? Yes (1) | No   

Shiv Raj Sharma   9 years AGO

If A invests amount = a for 12 months, then B invests amount = 2a for 6 months and C invests amount = 3a for 4 months.
Hence ratio of share of profit A : B : C = ax12 : 2ax6 : 3ax4 = 1:1:1. Hence each of A,B,C get equal share = 9000/3 = 3000

Like? Yes (1) | No   

vamsi krishna   9 years AGO

share goes like on basis of investment for per period of time.A and B and C invested let assume x,2x,3x.period they invested 12,6,4 respectively so the share for all is same.so C share is 9000/3. Ans is 3000

Like? Yes (1) | No   

veeramanikandan   9 years AGO

A:B:C
12x: 6b : 4c
12x:12x:12x
1:1:1
So c share is 3000

Like? Yes (1) | No   

paavai   9 years AGO

If A invests 'x' amt of money,
thus 'B'=2x,'c'=3x,
then ratio=(x*12):(2x*6):(3x*4)=12:12:12=1:1:1
then C's share is 9000*(1/3) ie equal to 3000

Like? Yes (1) | No   

Nagarjun   9 years AGO

take A investement be X
now ratio of A,B,C investements is A:B:C=X:2X:3X
=1:2:3
now profit ratio will be =1*12:2*6:3*4
= 1:1:1
total profit =9000
hence C share will be 9000/3=3000

Like? Yes (1) | No   

Mithun   9 years AGO

investment ratio 12: 12:12 => 1:1:1
hence, c's share= (9000/3)*1 =3000

Like? Yes (1) | No   

shabana banu shaik   9 years AGO

amount=investment*time,12x:2x*6:3x*4.........so all invested the same amount so profit must be equally distributed....9000/3=3000

Like? Yes (1) | No   

saipriya adavala   9 years AGO

let A invests money x,then
x*12: 2x*6 :3x*4
then for c
(4/12)*9000=3000

Like? Yes (1) | No   

souvik dey   9 years AGO

let a give amount of x,b amount of 2x,c amount of 3x
a's money works for whole year =12 months
b's money works for 6 months
c's money works for 4 months
so,12*x : 6*2x : 4*3x
=1:1:1
so, c's amount is=9000*(1/3) =3000

Like? Yes (1) | No   

Aashish Jacob   9 years AGO

all three invested same amount at the end of the year so money is divided equally among the trio.

Like? Yes (1) | No   

Vinith Mahendran   9 years AGO

Consider A as amount
Then A*12:2A*6:3A*4
=1:1:1
Hence c's share is (1/3)*9000
=3000

Like? Yes (1) | No   

mohita verma   9 years AGO

let x be the amount invested by A
then ratio between A,B,C is
12x:12x:12=1:1:1
so c's share is 9000X(1/3)=3000

Like? Yes (1) | No   

ravi singh   9 years AGO

all will invested equal amount
hence, c share is 9000/3 =3000

Like? Yes (1) | No   

shiva gurram   9 years AGO

let the investment of A is Rs. X
Ratio of investment of A, B, and C
= (12xX) : (6x2X) : (4x3X) = 1:1:1
C's share = Rs. 9,000 x
1/3
=Rs. 3,000

Like? Yes (1) | No   

Kethineni Vinodh   9 years AGO

P=IT
then
a:b:c=12x:(6*(2x)):(4*(3x))=>12x:12x:12x
then c=(12x/36x)*9000=3000

Like? Yes (1) | No   

Piyush Telang   9 years AGO

Let X be the initial amount invested at the beginning by A.
The duration for which A invested is for 12 months.
B's investment becomes 2X and duration is for 6 months &
C's investment becomes 3X and duration is for 4 months.
A:B:C = X x (12) : 2X x (6) : 3X x (4) = 1 : 1 : 1
So C's share = 1/3 x 9000 = 3000

Like? Yes (1) | No   

lakshmi nalluri   9 years AGO

x(12):2x(6):3x(4)=1:1:1
so,c's profit will be 3ooo

Like? Yes (1) | No   

Ravi shankar   9 years AGO

Suppose the investment of A is Rs. X
Ratio of investment of A, B, and C
= (12x X) : (6x 2X) : (4x 3X) = 1:1:1
C's share = Rs. 9,000 x(1/3)=3000

Like? Yes (1) | No (1)  

Devendra Marghade   9 years AGO

If A's investment=x Rs., then
Ratio of A,B and C's investment are x*12, 2x*6 and 3x*4= 12x, 12x and 12x
So 12x+12x+12x=9000, x=250
C's share=12*250=3000
Answer is option (4)

Like? Yes (1) | No (1)  

23 Jun 2015 Ratio and proportion

Divide 581 among A, B, C so that 4A = 5B = 7C

OPtion

1) A = 286, B = 126, C = 169
2) A = 244, B = 192, C = 145
3) A = 236, B = 156, C = 189
4) A = 272, B = 196, C = 113
5) A = 286, B = 176, C = 119
6) A = 248, B = 192, C = 141
7) A = 224, B = 192, C = 165
8) A = 208, B = 106, C = 267
9) A = 210, B = 190, C = 181
10)A = 245, B = 196, C = 140

Solution

Let 4A = 5B = 7C = k. Then A = k/4, B = k/5 and C = k/7
Therefore
A : B : C = k/4 : k/5 : k/7 = 35:28:20
Solve by using ratio proportion
A;s Share = 581*35/83 = 245
Similarly for others
Option 10)

Correct Option: 10 Best Solution (70)

asim   9 years AGO

here , we have to divide 581 in A,B,C such that
A + B + C = 581 ...................................(i)
let 4A = 5B = 7C = x
=> A = x / 4
=> B = x / 5
=> C = x / 7
on placing values of A,B,C in eq(i)
we get
(x/4) + (x/5) + (x/7) = 581
=> x * ( (1/4) + (1/5) + (1/7) ) = 581
=> x * ( (35+28+20) / 140 ) = 581 .................LCM (4,5,7) = 140
=> x * (83 / 140) = 581
=> x = 581 * 140 / 83
=> x = 140 * 7 ......................................(ii)

now , from eq(ii)
we get
A = x / 4 = 140 * 7 / 4 = 35 * 7 = 245
B = x / 5 = 140 * 7 / 5 = 28 * 7 = 196
C = x / 7 = 140 * 7 / 7 = 140 i.e. option 10) ANS

Like? Yes (20) | No (3)  

kanithi.shanmukharao   9 years AGO

In above problem gives 4timesof A=5times of B=7 times of C.
so their ratios are being:4:5:7
find out L.C.M of 4,5,7 is 140.
Therefore the ratio of A:B:C is 140/4:140/5:140/7=>35:28:20.
=>A:B:C=35:28:20.
Now sum of total ratio is 35x+28x+20x=581=>x=7...
so 35A=35*7=245:
28B=28*7=196:
20C=20*7=140:
So finally the answer is A=245,B=196,C=140

Like? Yes (16) | No (1)  

viswambher   9 years AGO

given 4A = 5B =7C
and since 581 must be divided among A,B,C
A+B+C= 581
B= 4A/ 5
C= 4A/7
(A + 4A/5 +4A/7) =581
therefore we get
A= 245
B=196
C=140

Like? Yes (11) | No   

mohita verma   9 years AGO

A/B=5/4
B/C=7/5
C/A=4/5
A:B:C=35:28:20
A's share=581x(35/(35+28+20))=245
similarly,
B's Share=581X(28/83)=196
C's share=581X(20/83)=140

Like? Yes (5) | No   

k sureshbabu   9 years AGO

as per question a&c must be divisible by 5
in the options 10 only satify that
or
go as per maths rule a=5/4b=7/4c=245
solving this we get answer

Like? Yes (3) | No   

Vivek   9 years AGO

its given that 4A=5B=7C
considering A=x
then B=4x/5
and C=4x/7
Sum of all the 3 is given as 581
Therefore A+B+C=581
i.e x+4x/5+4x/7=581
x(1+4/5+4/7)=581
x(83/35)=581
x=245 -> A=245
then B= 4*245/5=196
C=4*245/7=140
Therefore The Answer is option 10)

Like? Yes (5) | No (2)  

SANTOSH   9 years AGO

A+B+C = 581
A+4A/5+4A/7=581
then A= 245

Like? Yes (3) | No   

RAJESH   9 years AGO

4A=5B=7C
BY OPTION VERIFICATION
4*245=980
5*196=980
7*140=980

Like? Yes (3) | No   

Pranjal   9 years AGO

as 4A=5B=7C
SO A>B>C
option can be as 2,4,5,6,7,9,10
now mutiply the last digit and compares it with B's last digit on multiplying it with 5 if same check for 7C

Like? Yes (3) | No   

poojasaisri   9 years AGO

b=4/5a ,c=4/7a
a+b+c=581
a+(4/5)a+(4/7)a=581
a=245
b=196
c=140

Like? Yes (3) | No   

Math Lovers   9 years AGO

Let 4A = 5B = 7C = x

=> A = x/4
=> B = x/5
=> C = x/7

Now, A+B+C = x/4 + x/5 + x/7 = 581
=> 83x/140 = 581
=> x = 980
so, A=x/4 = 245
B = x/5 = 980/5 = 196
C = x/7 = 140

Like? Yes (3) | No (1)  

Dinni   9 years AGO

A+B+C=581
Given 4A=5B=7C
So, B=4/5A & C=4/7A
Then A+(4/5A)+(4/7A) =581
(83A/35) =581
A=245, B=196, C=140
So option 10 is correct.

Like? Yes (2) | No   

ABHINAV PUSHPAM   9 years AGO

A+4A/5+4A/7 = 581

=> 83A/35=581

SO, A= 245
And in options only in option 10, A=245 so option 10) is the answer

Like? Yes (2) | No   

RAVAL   9 years AGO

because,
4a=5b=7c
a=4/5b=4/7c
a+4/5a+4/7a=581
a=245
b=196
c=140

Like? Yes (2) | No   

Mani Sachdev   9 years AGO

a:b=5/4; b:c=7/5
a:b:c=38:28:20;
a=38/83*581=245
b=28/83*581=196
c=20/83*581=140

Like? Yes (2) | No   

Deepthi   9 years AGO

4A=5B=7C
A+B+C=581
A+4/5A+4/7A=581
83/35A=581
A=245
B=4/5*245=196
C=4/7*245=140

Like? Yes (2) | No   

shree   9 years AGO

the addiction of values a,b , c of option 10 is 581
and if we multiply with 4, 5, 7 then all the values are equal

Like? Yes (2) | No   

anand vijay   9 years AGO

4A=5B=7C
simply we can check from option that after multiplication from 5 the digit at unit place must be 0
If it is even else 5 if it is odd so,
here digit at unit place be 0 so after multiplication by 7 the unit digit must be 0
hence option (10) is correct.

Like? Yes (2) | No   

lokesh   9 years AGO

5B = 7C
which is possible when C ends in 0 or 5
so i tried the last option

Like? Yes (3) | No (2)  

Dharshana   9 years AGO

Reverse Method)
4A=4(245)=5(196)=980
5B=5(196)=980
7C=7(140)=980

Like? Yes (1) | No   

sompon temtheerakij   9 years AGO

B = 4/5A , C = 4/7A
A+4/5A+4/7A = 83/35A = 581
A = 245 ; B = 196 ; C = 140

Like? Yes (1) | No   

nidhi   9 years AGO

4A=5B=7C
4*245=5*196=7*140=980

Like? Yes (1) | No   

K Sudharshan reddy   9 years AGO

Just check the options
5b , so the result ends in or 0
4a to get the value equal to 0 the last digit in a should be 0 or 5
so check only last two options......
or we can solve the problem by writing them in equation form
a+b+c= 581 and 4a=5b=7c.....

Like? Yes (1) | No   

kush nigam   9 years AGO

a+b+c = 581 _____(1)

4a=5b=7c

so putting values in equation 1

a+ 4/5 a+ 4/7 a = 581

a( 1+ 4/5+ 4/7 ) =581

73 a = 20335

a = 245

so b = 4/5 a =196

so c = 4/7 a = 140

Like? Yes (1) | No   

Akhil   9 years AGO

245*4=196*5=140*7=980
245+196+140=581
so option 10.....

Like? Yes (1) | No   

krishna chandrika   9 years AGO

4A=5B=7C
A+B+C=581
A+(4/5)A+(4/7)A=581

83A=581*35

A=245

B=4/5A=4/5*245 = 196

C=4/7A=4/7*245 = 140

Like? Yes (1) | No   

anuanwesh   9 years AGO

4a=5b=7c a=5÷4b, b=7÷5c, so option 10 is rght ans

Like? Yes (1) | No   

Ravi shankar   9 years AGO

we have to choose a option which must be divisible by other two.
for choosing value A: must be divisible by 5 and 7 both
for choosing value B: must be divisible by 4 and 7 both
for choosing value C: must be divisible by 4 and 5 both
only option 10 is correct

Like? Yes (1) | No   

ANANTHI.P   9 years AGO

83 581
35 X =245
28 X =196
20 X =140

Like? Yes (1) | No   

Lavanya Rajendran   9 years AGO

a+b+c=581
b=4a/5
c=4a/7
on equating a=245
4a=5b
So b=196
similarly 4 c

Like? Yes (2) | No (1)  

RISHABH SINGH   9 years AGO

(A/35)=(B/28)=(C/20)=k(let)
so A=35k B=28k C =20k
we know that
A+B+C=581
putting value of A,B and C
we have k=7
So
A=245 B=196 C=140

Like? Yes (1) | No   

RAJAT KHANDELWAL   9 years AGO

A+B+C=581
4A=5B
4A=7C
5B=7C

SOLVING EQUATIONS WE GET B=196
A=245
C=140

Like? Yes (2) | No (1)  

Divyansh jaiswal   9 years AGO

a:b=5:4 b:c=7:5
a:b:c=35:28:20

83x=581
x=7
a=245 b=196 c=140

Like? Yes (1) | No   

pratik   9 years AGO

go through option
jus check digit at once place

only option 10 gives same

4*245= **0. 5*196=**0. 7*140 =**0
so its gotta be option 10

Like? Yes (1) | No   

anuj jain   9 years AGO

since there is a 5B so other answers must be multiple of 5.
And due to 4A ans. must be multiple of 10.
245*4=980
196*5=980
140*7=980
245+196+140=581

Like? Yes (1) | No   

puneet   9 years AGO

we take ratio of them like
1/4:1/5:1/7
we take lcm of them
and we gate the ratio 35:28:20
and dive the value

Like? Yes (1) | No   

Dhanraj Wanjare   9 years AGO

option 10 satisfy the condition i.e.--
4A=5B=7C
A=245 then 4A ==> 4*245= 980;
B=196 then 5B ==> 5*196= 980;
C=140 then 7C ==> 7*140= 980;

Like? Yes (1) | No   

bahul   9 years AGO

a:b=5:4 and b:c=7:5 so, a:b:c=35:28:20
now, we have to divide 581 among a, b, c so
581= 35x+28x+20x ,
x=581/83
x=7
a=7*35=245
b=7*28=196
c=7*20=140

Like? Yes (1) | No   

PRASHANT KUMAR   9 years AGO

4A=5B=7C=K;
581=A+B+C;
SO SOLVE FOR K.....K=980...
SO ANS.--->>(10)

Like? Yes (1) | No   

Jyothi C Allapur   9 years AGO

A + B +C = 581 --- eqn (1)
4A=5B=7C => A = (5/4)*B and C = (5/7)*B
substituting A andC in eqn (1), we get
(5/4)B + B + (5/7)B = 581
B = 196
A = 245 and C = 140

Like? Yes (1) | No   

Abhishek singh   9 years AGO

a/35=b/28=c/20=x
a=35x
b=28x
c=20x
a+b+c=581
x=7
so
a=245
option 10.

Like? Yes (1) | No   

sivakumar   9 years AGO

4 * 245 = 980
196 * 5 = 980
140 * 7 = 980

245+196+140 = 581

Like? Yes (1) | No   

Aravinth   9 years AGO

because all the unit digits are respective place..so that condition is easily satisfiedwhen compared to other ones

Like? Yes (1) | No   

Ganesh garg   9 years AGO

A:B=5:4
B:C=7:5
so the ratio of
A:B:C=35:28:20
now
A=(35/83)*581 = 254
B=(28/83)*581 = 196
C=(20/83)*581 = 140

Like? Yes (1) | No   

Thanakkumar T   9 years AGO

Assume if 5 is multiplied last digit should be zero...then probably last two answers would be correct if multiplied by 4....calculate last two and arrive at answer.

Like? Yes (1) | No   

soumith vooda   9 years AGO

simply option verification
in given options bx5 is always zero in last digit so choose an option while multiplying the other options such that last digit is zero
4*285=5*196=7*140=980

Like? Yes (1) | No   

SWATI   9 years AGO

A+B+C=581
B=(4/5)A
C=(7/5)A
putting values and solving
A=245..
further
B=196 and C=140

Like? Yes (1) | No   

Archie   9 years AGO

Let 4A=5B=7C=x
then A's share =x/4
B's share=x/5
C's share =x/7
-----> x/4+x/5+x/7=581
Solving, we get x=980
------> A=x/4=245
B=x/5=196
C=x/7=140
Hence, option 10 is correct .

Like? Yes (1) | No   

sonu   9 years AGO

Assume 4A=5B=7C=K

Now K/4+K/5+K/7=581 => K=980

Put the value of K.

A = 245, B = 196, C = 140

Like? Yes (1) | No   

Piyush Telang   9 years AGO

A + B + C = 581 -> Equation 1
A = 7C/4
B = 7C/5
Substituting A and B in Equation 1
C = 140
Thus A = 245 and B = 196

Like? Yes (1) | No   

ARUP GHOSH HAZRA   9 years AGO

4A= 5B=7C=x(assume)
i.e. A= x/4,
B= x/5,
C= x/7.
so, A+B+C= 581
or, (x/4+x/5+x/7)= 581
or, x=980

Like? Yes (1) | No   

chitra   9 years AGO

its like trail and error method...check from the options
which satisfies
4a=5b=7c...980
ie..,4*245,5*196,7*140
has a total of 581....a+b+c=581

Like? Yes (1) | No   

Shubham   9 years AGO

As A+B+C =581;
so 5(A+B+C)=5*581 => 9A+5C=2905;
and 4(A+B+C)=5*581 => 9B+4C=2324
and 7(A+B+C)=7*581 => 11A+7B=4067
and solving above 3 Equation we get A=245 ,B=196,C=140

Like? Yes (1) | No   

Nabin   9 years AGO

A:B:C=35:28:20
A=35/83×581=245...similarly find Band C

Like? Yes (1) | No   

ashwin   9 years AGO

jus multiply the last digit of a,b,c with 4,5,7 respectively.....doing so we find that only the 10th option gives the same answer zero...hence answer is (10)

Like? Yes (1) | No   

radhakrishna bajpai   9 years AGO

A+B+C=581
now put A=5B/4
and c=5b/7
then solve for B wr get B=196
after solving A=245 and C=140

Like? Yes (1) | No   

SURAJ KUMAR   9 years AGO

option 10 is correct coz if we multiply A by 4 ,B by 5 and C by 7 then according to option we will get same value of 980 which is possible in option 10 only.

Like? Yes (1) | No   

SAURABH SINGH   9 years AGO

A:B:C=35:28:20
hence, 35k+28k+20k=581
k=7
A=35k=35*7=245

Like? Yes (1) | No   

K.M.AYESHA SHARMIL JAHAN   9 years AGO

divide 581 among A,B,C
4A=5B=7C(given)
4(35*x)+5(28*x)=7(20*x) (by taking l.c.m)
581 is divided only by 7
so,x=7
A=35*x
=35*7
=245
B=28*7
=196
C=20*7
=140

Like? Yes (1) | No   

RAKESH   9 years AGO

a:b:c = 35:28:20
& a+b+c = 581, so,
a=245 , b=196, c=140

Like? Yes (2) | No (2)  

BADRI LAL JAT   9 years AGO

take ratio of A, B, C, AND FIND : 35:28:20 SO A HAS VALUE 245, B HAS 196 AND C HAS 140

Like? Yes (1) | No (1)  

Venkatesh kadali   9 years AGO

4A=5B=7C
4A=5B that implies a:b=5:4
5B=7C that implies b:c=7:5
then a:b:c=35:28:20
A share=810*35/83=245
B share=810*28/83=196
C share=810*20/83=140

Like? Yes (1) | No (1)  

Pradeep   9 years AGO

=>4A=5B=7C=1
=>A:B:C=1/4:1/5:1/7
=>A:B:C= 35:28:20
=>A=35/83 *581 =245
=>B=28/83*581=196
=>C=581-(245+196)=140

Like? Yes (1) | No (1)  

Rats   9 years AGO

A+B+C=581........(1)
4A=5B=7C.......(2)
On solving (1) & (A), we get,
A=245, B=196, C=140

Like? Yes (1) | No (1)  

neha gupta   9 years AGO

4A=5B=7C
from this we get,
A:B=5:4
B:C=7:5
therefore
A:B:C=35:28:20
let the ratio be x
then 35x + 28x + 20x = 581
83x = 581
x=581/83=7
A=35x=35*7=245
B=28x=28*7=196
C=20x=20*7=140

Like? Yes (1) | No (1)  

Nikhil chavan   9 years AGO

check the option to satisfy the given conditions..so answer is 10th option.

Like? Yes (2) | No (2)  

sravani   9 years AGO

B=4/5A
C=4/7A
A+B+C=581
=>A=245
B = 196,
C = 140

Like? Yes (1) | No (1)  

vimal tiwari   9 years AGO

go with the options...

10)

245 * 4 = 196 * 5 = 7*140
980 = 980 = 980

Like? Yes (1) | No (1)  

Vaibhav kumar    9 years AGO

ratio =35:28:20
(35/83)*581=245
(28/83)*581=196
(20/83)*581=140

Like? Yes (1) | No (1)  

Chitra.S   9 years AGO

a/b=5/4..
b/c=7/5
so ..a:b::b:c..5:4::7:5...
the ratio is 35:28:20..
total is 35+28+20=83
581*35/83=245
581*28/83=196
581*20/83=140

Like? Yes (1) | No (1)  

22 Jun 2015 Sequence

What is the next number of the following sequence
42, 66, 810, 1014, 1218,

OPtion

1) 1444
2) 1424
3) 1622
4) 1532
5) 1456
6) 1222
7) 1422
8) 1488
9) 1644
10)1822

Solution

42
(4+2) (2+4) = 66
(6+2) (6+4) = 810
(8+2) (10+4) = 1014
(10+2) (14+4) = 1218
Similarly
(12+2) (18+4) = 1422

Option 7)

Correct Option: 7 Best Solution (63)

Dhanraj Wanjare   9 years AGO

Ans-1422
42, 66, 810, 1014, 1218, 1422
first add 2 in first digit of first number 42's=> 4+2=6
6 is first digit of second one's first digit now same process

4+2=6
6+2=8
8+2=10
10+2=12
12+2=14
this all are the first digits of series number
next process is same as but
second time we will take second digits and add 4 in all digit like -

2 +4=6
6 +4=10
10+4=14
14+4=18
18+4=22
so
4+2=6 2 +4= 6 ==> 66;
6+2=8 6 +4= 10 ==> 810;
8+2=10 10+4=14 ==> 1014;
10+2=12 14+4=18 ==> 1418;
12+2=14 18+4=22 ==> 1422;

Like? Yes (4) | No   

Aravinth   9 years AGO

first two digits are added on a trought with 2 as a difference
and second two digits are added with 4 as difference.

Like? Yes (2) | No   

RAKESH   9 years AGO

two series
4/2, 6/6, 8/10, 10/14, 12/18, 14/22

Like? Yes (1) | No   

Rats   9 years AGO

Addition of two series
1st:-4,6,8,10,12,...
2nd:-2,6,10,14,18,...
So the series 42,66,810,1014,1218,...
The next term is 1422.

Like? Yes (1) | No   

Aarti Galar   9 years AGO

4 2 66 810 1014 1218 1422
+ 2 + 2 +2 + 2 + 2 for tens term
+ 4 + 4 + 4 + 4 + 4 for ones term
therefore, the next number will be 1422
ans. is 7) 1422.

Like? Yes (1) | No   

k sureshbabu   9 years AGO

4-2+2-4=6-6
6-6+2-4=8-12
8-12+2-4=10-14
10-14+2-4=12-18
12-18+2-4=14-22

Like? Yes (1) | No   

ABHINAV PUSHPAM   9 years AGO

1422
4.2
6.6
8.10
10.14
12.18
14.22
There are 2 series
One as +2 and the other +4
Option 7)

Like? Yes (1) | No   

viswambher   9 years AGO

if the number is equally divided into 2 parts
the first part of the number is increased by 2
the second part is increased by 4
4 , 6 , 8 , 10 ,12 , 14
2 ,6 ,10 ,14 ,18 ,22
therefore ans is 1422

Like? Yes (1) | No   

APPIKONDA SANTOSH NAIDU   9 years AGO

1422

Like? Yes (1) | No   

Vivek   9 years AGO

In the sequence the last three number differ by same number 204,so the new number will also be an increment of previous number by 204 . i.e. 1218+204=1422

Like? Yes (1) | No   

Venkatesh kadali   9 years AGO

every number first digit difference is 2 thatis add 2 first number to get next first number,and every number second number difference is 4.
--->44 toadd first number by 2 and second number by 4
i.e 66.
----->66 to add first n umber by 2 and second number by 4 then we get 810
in this same way
12 18 to add first number by 2 and second number by 4 ie 14 22=1422
so answer is 1422

44,66,810,1014,1218,____________

Like? Yes (1) | No   

Swetha   9 years AGO

First half o every no. Is 2 to the previous no.'s first half.
Second half of every no. Is 4 to the previous no.'s second half.
So the no after 1218 is 1422 i.e., option 7.

Like? Yes (1) | No   

Deepthi   9 years AGO

adding 2 to 1st digit and 4 to next digit.apply this to all numbers.

Like? Yes (1) | No   

DAMARLA BALAJI   9 years AGO

sum of digits in the order 6,3,9,6,3,9 so sum of digits of no. must be 9, hence only option 7 satisfies

Like? Yes (1) | No   

Mehul D Parmar   9 years AGO

42= 4 and 2
66=6 and 6
810=8 and 10
same as all
ABC=(A-1)+2 and (bC-1)+4

thn 1218=1422

Like? Yes (1) | No   

N.Dayanithi   9 years AGO

First number is incremented by 2... 4,6,8,10,12,14...
Second number is incremented by 4... 2,6,10,14,18,22...
So the answer is 1422

Like? Yes (1) | No   

vimal tiwari   9 years AGO

-> 40+2, 60+6, 800+10, 1000+14, 1200+18
here +2,+6,+10,+14,+18 inc with +4 each thus next will be 18+4=22
last two digits are 22
now,
first 2 digits inc with +2
4,6,8,10,12 this next will be 14

no. will be 1422

Like? Yes (1) | No   

Nikhil chavan   9 years AGO

42, 66, 810,1014,1218.......first number increases by 2..i.e..4, 6, 8, 10,12...and second number increses by 4 increment..i..e..2 then 6 then 10 ..as per this rule next no is 1422.

Like? Yes (1) | No   

RAJAT KHANDELWAL   9 years AGO

20*2 +2 , 20*3+6 ,20*40 +10 , 20*50+14 ,20*60+18 ,
so 20*70 +22=1422

Like? Yes (1) | No   

swetha   9 years AGO

first two digits of answer=2*natural number
last two digits of answer=odd number*2
therfore the next number=(2*7)(2*11)
=1422

Like? Yes (1) | No   

Rajeev   9 years AGO

First digit is increasing by 2. Second digit is increasing by 4

Like? Yes (1) | No   

samiul islam   9 years AGO

4+2=6,6+2=8,8+2=10,10+2=12
2+4=6,6+4=10,10+4=14,14+4=18

Like? Yes (1) | No   

Devendra Marghade   9 years AGO

digits of a number are increasing by +2 and +4 of the previous number
4, 6, 8, 10, 12, 14 and
2, 6, 10, 14, 18, 22
So next number is 1422
Ans is option (7)

Like? Yes (1) | No   

Billal Hossain   9 years AGO

42,66(4+2 2+4), 810(6+2 6+4), 1014(8+2 10+4), 1218(10+2 14+4), 1422(12+2 18+4)..........

Like? Yes (1) | No   

Gowtham   9 years AGO

in all cases 1 number added by 2 and 2 num + by4 ..
42 => 4+2 2+4 = 66
66 => 6+2 6+4 = 810
so 1218 be 12+2 18+4= 1422 So Answer is 7 option =1422

Like? Yes (1) | No   

naina shukla    9 years AGO

42 for 2nd term 4+2=6 and 2+4=6 i.e. 66
for 3rd term 6+2=8 and 6+4=10
for 4th 8+2=10 and 10+4=14
for 5th 10+2=12 and 14+4=18
so ,at last 1218 i.e. 12+2=14 and 18+4=22
answer is 1422
option 7 is correct.

Like? Yes (1) | No   

B.venkata suresh   9 years AGO

from 4 2
we get 6 6 by adding 2 in the first place and 4 in the second place.
like 4+2=6,2+4=6....
similarly from 12 18 ....by adding 2in 1st place and 4 in the second place...
we get 12+2=14 and 18+4=22...
therefore answer is 1422

Like? Yes (1) | No   

anand vijay   9 years AGO

sum of digits for the series : 42,66,810,1014,1218
=> 4+2,6+6,8+1+0,1+0+1+4,1+2+1+8
=> 6,12,9,6,12,_??
if we follow the following pattern the answer would be:
1422 as 1+4+2+2=9
option : 7

Like? Yes (1) | No   

ANANTHI.P   9 years AGO

4+2=6
6+6=12
8+10=18
10+14=24
12+18=30
14+22=36

Like? Yes (1) | No   

Surendhar Ramanujam   9 years AGO

1st digits is the multiples of 2, last 2digits is the addition of 4

Like? Yes (1) | No   

NESAB JAFAR   9 years AGO

fist digit is increasing by two and second digit increasing by four

Like? Yes (1) | No   

Ravi shankar   9 years AGO

series of sum of digits is as follows:
6,12,9,6,12,
so next sum must be 9 and only option 1422 has it.

Like? Yes (1) | No   

nidhi   9 years AGO

The first digit of all the numbers are increasing by 2 like 4,6,8,10 and 12. Therefore next digit would be 14. The last digit of the numbers are 2,6,10,14 and 18. It is clear that difference between it is 4 , means when the number is subtracted from the previous number. Here from this series next no. would be 22. So, the next number in the sequence is 1422.

Like? Yes (1) | No   

K.M.AYESHA SHARMIL JAHAN   9 years AGO

given sequence 42,66,810,1014,1218
if we split the number
2*2=4 ; 2*1=2
2*3=6 : 2*3=6
2*4=8 : 2*5=10
2*5=10: 2*7=14
2*6=12 :2*9=18
therefore,
2*7=14 :2*11=22

Like? Yes (1) | No   

neha gupta   9 years AGO

Break the terms into two parts:
like 42 as 4 and 2
66 as 6 and 6
810 as 8 and 10
1014 as 10 and 14
1218 as 12 and 18
we can easily notice the pattern as first part is incremented by 2 and second part is incremented by 4
Therefore first part of next term is 12+2=14
last part of next term is 18+4=22
thus next number is -----> 1422

Like? Yes (1) | No   

aravinth   9 years AGO

keeping the 42 as constant and cross adding we get the answer

Like? Yes (1) | No   

Vivek   9 years AGO

first 2 no's in the order 4, 6, 8 , 10 , 12,14
2nd 2 digits 2,6,10,14,18,22,

Like? Yes (1) | No   

nirmal kumar saini   9 years AGO

becoz
42, 4+2 2+4 == 66
66, 6+2 6+4 == 810
and so on
.
.
.
1218 12+2 18+4 == 1422;
is the right answer

Like? Yes (1) | No   

bipro biswas   9 years AGO

42,66,810,1014,1218....
here 66=(4+2) and (2+4)
810=(6+2)and(6+4)
1014=(8+2)and(10+4)
1218=(10+2)and(14+4)
here higher term is increased by 2 and lower term is increased by 4
there fore..next term is (12+2) and (18+4)=1422

Like? Yes (1) | No   

M,MATHIVANI   9 years AGO

increase the last digit of the first no by 4 and continue
2+4=6+4=10+4=14+4=18+22
increase the first digit of the first no by 2 and continue
4+2=6+2=8+2=10+2=12+2=14
the answer is 1422

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KARTHIKA.N   9 years AGO

the first digit is increased by 2;
second digit is increased by 4;
ans:1422;

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soumith vooda   9 years AGO

1st digit is of 2 difference
2nd part is 4 difference so 12+2=14 ,18+4=22,so no is 1422

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AYUSHTIWARI   9 years AGO

since 1st part in sequence is increasing by 2 and and second part is by 4

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Lavanya Rajendran   9 years AGO

add 2 consequently with the 1st no and alternatively 2 with the 2nd digit

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kiruthika   9 years AGO

first and second number is even number starting from 4 and other two number is even alternative number from 2

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Sindhu Velliangiri   9 years AGO

1s5t digit gets increases by 2nd digit increases by 4 so 1422

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Priyadarshni Somasundaram   9 years AGO

the first number is increased by 2 and second number is increased by 4. so according to the pattern 1422 is the answer

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venkatesh harugeri   9 years AGO

first two digit adding of two and second two digit adding of four for previous number

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mohita verma   9 years AGO

42
66=(4+2)(2+4)
810=(6+2)(6+4)
1014=(8+2)(10+4)
1218=(10+2)(14+4)
so the next term is-
1422=(12+2)(18+4)

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shree   9 years AGO

4+2=6.2+4=6 then 66
6+2=8,6+4=10 then 810
8+2=10, 10+4=14 then 1014
10+2=12, 14+4=18 then 1218
therefore next no is 12+2=14,18+4=22 that is 1422

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ravi singh   9 years AGO

answer is 1422

Add 2 in first half digit and add 4 in second half digit

(4+2)(2+4)=66,

(6+2)(6+4)= 810,

(8+2)(10+4)=1014,

(10+2)(14+4)=1218,

(12+2)(18+4)=1422

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RAVAL   9 years AGO

42::::66:::::810:::::1014::::::1218
4+2 6+6 8+1 1+1+4 1+2+1+8
6 12 9 6 12
so according to option
ans= 1422~ 1+4+2+2= 9

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sowmica   9 years AGO

42->(2*2)(2*1)
66->(3*2)((2+4)*1)
810->(4*2)((2+4+4)*1)
.....
1218->(6*2)((14+4)*1)
1422->(7*2)((18+4)*1)
ANS::1422

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yanamala nagajyothi   9 years AGO

4+2=6,6+2=8,8+2=10,10+2=12,
2+4=6,6+4=10,10+4=14,14+4=18

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Piyush Telang   9 years AGO

4 x 10 .. 6 x 10 .. 8 x 100 .. 10 x 100 .. 12 x 100 .. 14 x 100
+ 2 .. + 6 .. + 10 .. + 14 .. + 18 .. + 22
|__ +4__||__ +4__||__ +4__| |__ +4__| |__ +4__|
42 66 810 1014 1218 1422
Row 1 - Initial Numbers are an AP of Difference 'd' = 2 & Multiplying those initial numbers by 10s and 100s.
Row 2 - Adding the results of multiplication with an AP with starting number 2 and difference of 4.
Row 3 - shows the difference of 4.
Row 4 - are the actual numbers.

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mohanraj   9 years AGO

42,66=2+6,4+6=810
42,810=2+8,4+10=1014
42,1014=2+10,4+14=1218
42,1218=2+12,4+18=1422

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Urvashi Jain   9 years AGO

42,66,810,1014,1218
add 2, 4+2=6,6+2=8,8+2=10,10+2=12,12+2=14
add 4, 2+4=6,6+4=10,10+4=14,14+4=18,18+4=22
combined both 1422

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Nitesh Kumar Mandhyan   9 years AGO

difference of the first digits of the consecutive no.s is in the A.P. of common diff. =2
difference of the secnd digits of the consecutive no.s is in the A.P. of common diff. =4

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Rohit Singh   9 years AGO

There are two series.
One is +2 and other is +4
4.2
6.6
8.10
10.14
12.18
14.22

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Preethi   9 years AGO

Because for 42 and 66, 4+2=6(first digit) and 2+4=6(second digit) and so 12+2=14(first two digits) and 18+4=22(last two digits).

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SANTHOSH KUMAR K   9 years AGO

First digit in a number is increases by 2 and second digit in a number increases by 4 so 42, (4+2)(2+2)=66, (6+2)(6+4)=810..... etc

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Adep Kavita Vasudev   9 years AGO

42 66 6+2=8 6+4=10 810
42 810 8+2=10 10+4=14 1014
42 1014 10+2=12 14+4=18 1218
42 1218 12+2=14 18+4=22 1422

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bahul   9 years AGO

first we have 42 then (4+2)(2+4)=66 the we have (6+2)(6+4)=810 same pattern for rest of numbers... so in end we have (12+2)(18+4)=1422

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