A student got 425 marks out of 500 in an examination. Subject were Hindi, English, Physics, Chemistry and Mathematics. His marks in Hindi and English were ranging from 80 to 85. (80 and 85 are also included). Marks in Chemistry, Physics and Mathematics were ranging from 75 to 80, 85 to 90 and 90 to 95 (including the given number) respectively. His marks in Hindi And Chemistry were same, whereas marks in English were same as marks in Physics. His marks in Mathematics were
OPtion
1) 90
2) 91
3) 92
4) 93
5) 94
6) 95
7) Data in insufficient
8) Given data is wrong
Solution
Subject ----------- Range of marks
Hindi ------------- 80-85
English ----------- 80-85
Physics ----------- 85-90
Chemistry --------- 75-80
Maths ------------- 90-95
Since marks in Hindi and Chemistry are same
so definitely marks will be 80.
Similarly in Physics and English marks will be 85
So in Maths marks = 425-*85+85+80+80)
= 95
Option 6)
Three integers x, y, z such that 1 =< x, y, z =< 9 and x not= y not= z are choosen. The sum of products of numbers taken in pair is 73 and their sum is 16. If any of the three number is a perfect square, then their product will be
Below given are two formulae for long summation.
1) 1 + 2 + 3 + 4 + ................ + n = n(n+1)/2
2) 1^2 + 2^2 + 3^2 + 4^2 + ........ + n^2 = 1/6 n(n+1)(2n+1)
The value of
(1% of 2 + 2% of 3 + 3% of 4 + ........ + 99% of 100) will be
3 men and 8 women complete a task in same time as 6 men and 2 women do. How much fraction of work will be finished in same time if 4 men and 5 women will do that task.
In this year 2015, Holi will be enjoyed at 6th March 9 AM and Deepawali will be celebrated at 11th November 8 PM. The total time interval (in hours) between the two will be
From 6th March 12:00 night to 11th November 12:00 night; Total days = 365 - (31+28+5+19+31)
= 251
So hours = 25*24 = 6024
Now for 6th March deduct 9 hours and for 11th November deduct 4 hours so
net hours between events = 6024 - 13
= 6011 hours
Option 7)
A five digit number is choosen in such a way that ten's place is one less than units's place, hundred's place is one less than ten's place and similarly the other digits. Sum of all the digits of a number obtained by adding that choosen number and the number formed by reversing its digit is 40. Product of all the digit of the choosen number will be
Let the number
10000(x-4) + 1000(x-3) + 100(x-2) + 10(x-1) + x
Reversed number will be
10000 x + 1000(x-1) + 100(x-2) + 10(x-3) + (x-4)
Sum = 10000(2x-4) + 1000(2x-4) + 100(2x-4) + 10(2x-4) + (2x-4)
So
5(2x-4) = 40
2x - 4 = 8
2x = 12
x = 6
So number is 23456
Product 720
Option 3)
Mr. Brown tells to his son David that his age was 11 times that of David's 15 year before. After two year his age would be x more than the sum of ages of his sons, here x is the present age of David. If brother of David is 8 years younger than David, then age of Mr Brown is
Let the age of Mr Brown, David and brother B, D and P
According to given condition
B - 15 = 11(D - 15) (i)
B + 2 = D + 2 + P + 2 + D (ii)
and P = D - 8 (iii)
Put B from (i) and P from (iii) ini (ii) we get
11D - 150 + 2 = 2D + 4 + D - 8
8D = 144
D = 18
B = 48
Option 6)