In Mac Donald following taxes are added on the price of purchased items.
1) Vat 12.5% of purchased items.
2) Service tax 4% of purchased items.
3) Edu. cess 2% of service tax.
4) Add. Ed. Cess 1% of service tax.
Diana went to Mac Donald with his daughter and they purchased some burger, Mc pizza & Coffee. Diana paid 932.96 rupee as bill. The cost of items without all taxes was
The sum of x% of y and y% of z is z% of x. x and z are integers such that 1 =< x =< 9, 1 =< z =< 9. If y is a perfect square number then how many ordered pair (x, z) are possible satisfying the given condition.
OPtion
1) 1
2) 2
3) 3
4) 4
5) 5
6) 6
7) 7
8) 7
9) 9
10)0
Solution
xy/100 + yz/100 = zx/100
y = xz/(x+z)
If either x or z is one then no possible case because n/(n+1) will never a perfect square.
For x=2 and z=2, y=1 (Perfect square)
Similarly for x=8 and z=8, y=4 (Perfect square)
For x=3 and z=9, sum=12
so y = 3*9/12 = 9/4 (Perfect square)
so (3,9) and (9,3) are possible pair
So total possible pairs are (2,2), (8,8), (3,9) and (2,3)
Option 4)
A six digit number has the maximum number of possibilities of perfect square as given below
1) First digit is a perfect square
2) Second digit is a perfect square
3) Third digit is a perfect square
4) Number formed by first and second digit in order is perfect square.
5) Number formed by third and fourth digit in order is a perfect square.
6) Number formed by fifth and sixth digit in order is a perfect square.
7) Number formed by last 3 digit in order is a perfect square.
Here sixth digit means the units place.
All the digits in the number are different and non-zero.
The product of all the six digit will be
Perfect square single digits are 1, 4, 9
Two digit no by using 1, 4, 9 is only 49
So first three no will be 491 now third and fourth digit number is perfect square so it will be 16 and last two digit set will only be 25 because no integer can be revised so no is 491625
A business man invested 45% of the sum in dry fruit business, 35% of the sum in gift item business and 20% of the sum in fruit business. In a year he received a profit of 1 million rupee in dry fruit business and fruit business both. In gift item business he got a percentage profit equal to the sum of profit percentage in dry fruit and fruit businesses. His profit in gift item business (in million rupee) was
Let total investment = A (million rupee)
investment in dry fruit business = .45 A
so % profit = 1(100)/(.45*A)
similarly in fruit business
% profit = 1*(100)/ (0.20A)
Net % profit = 100/(0.45A) + 100/(0.20A)
So profit in gift item business
= [100/(0.45A) + 100/(.020A)]*(.35A/100)
= .35(1/.45 + 1/.20)
= (.35*.65)/(.45*.20)
= 35*65/45*20 = 2.53
Option 6)
A man travels 10 meter towards east from point A to point B, then he turns left for 10 m from point B to point C. From point C it starts to move in a semicircle CXD. CD is perpendicular to BC and D is towards east relative to C. If his distance at D from initial point
A is 50 m, then radius of semicircle path will be
According to given condition
Net distance of man along east = 10 + 2R
Net distance of man along north = 10
So
10^2 + (10+2R)^2 = 50^2
10 + 2R = Sqrt(2400)
2R = 10*Sqrt(24) - 10
R = 5*Sqrt(24) - 5
R = 10*Sqrt(6) - 5
A man purchase 180 shares of a company @ 2492.50 per share and sell these @ 2675.00 per share. If brokarage is 40 paisa per 100 rupee with 20% addition tax on brokarage both time (at the time of purchase and also at the time of sell) then his profit will be