M4maths Previous Puzzles

14 Jan 2015 X will be

[Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)] ........... infinite = x
Then x will be

OPtion

1) Sqrt(2)
2) [Sqrt(2)]^[Sqrt(2)]
3) [Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)]
4) 1.91
5) 3
6) 4
7) 5
8) 8
9) 16
10)2

Solution

[Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)] ........... infinite = x
[Sqrt(2)]^x = x
Sqrt(2) = x^(1/x)
Now 2 and 4 satisfies this equation but for any value of n
[Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)] .......... n terms < 2
So only 2 will be the solution

Option 10)

Correct Option: 10 Best Solution (26)

Vinay Sipani    10 years AGO

Two solutions are possible i.e. 2 and 4
I claim whoever has answered as 4,they must also be right.

It can be written as

(Sqrt 2 )^x = x
=> 2^(x/2) = x
=> x = 2 or 4

so both 2 and 4 are right

Like? Yes (8) | No (2)  

Shreeom Singh   10 years AGO

=> [Sqrt(2)]^x=x
=>Sqrt(2)=(x)^(1/x); //powering both side with (1/x)
=>x=2;//2^(1/2)=Sqrt(2).

Like? Yes (3) | No   

Supriya Mondal   10 years AGO

Given,
[Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)] ........... infinite = x
then we can write,
[Sqrt(2)]^x=x
so, x=2
so option 10)2 is the right answer

Like? Yes (2) | No   

RAKESH   10 years AGO

[Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)] ........... infinite = x

or [Sqrt(2)]^x = x

or [Sqrt(2)] = 2^(1/2) = x^(1/x)

so, x = 2

Like? Yes (1) | No   

Sravanthi   10 years AGO

The square root of 2 is the only real number other than 1 whose infinite is equal to its square.

Like? Yes (1) | No   

Sanu Panji   10 years AGO

sqrt=1/2
so 2 and 1/2 will cancellwd out last is 2^1=2

Like? Yes (1) | No   

Abhik Das   10 years AGO

x=[sqrt(2)]^[sqrt(2)]........infinite
or, x=[sqrt(2)]^x
or, x=(2)^(x/2)
taking LOG on both side we get
or, log(x)=(x/2)*log(2)
or, 2*log(x)=x*log(2)
or, x^2=2^x
By using option we get x=2
But Here x=4 also satisfies the equation

Like? Yes (1) | No   

Jaspalsingh Parmar   10 years AGO

option 10 is correct by solving

Like? Yes (1) | No   

Surit Datta   10 years AGO

according to the sequence
x = sqrt(2)^x
so
x^(2/x) = 2
so
x = 2
so option 10
That's it.

Like? Yes (1) | No   

Anjali   10 years AGO

sqrt(2)^x=x
x^2=2^x
=> x=2

Like? Yes (1) | No   

ranjithreddy   10 years AGO

2^x/2=x
x=2

Like? Yes (1) | No   

sandeep kumar   10 years AGO

By "infinite tetration", I'm going to assume you mean the limit of the sequence
A to the base 0 = 1
An + 1 = sqrt(2)^an
The following is meant to be a proof sketch:

1. An is an increasing sequence as long as
a < 2 this is true because
f(x) = sqrt(2)^x > x
for the interval
0 < x < 2

2. The sequence is bounded above namely if then
An < 2 then
An+1 = sqrt(2)^infinite < sqrt(2)^2 = 2
By induction, this is always true; moreover it also means that the sequence is always increasing.

3.The limitof L the sequence must satisfy,
limt An+1 = limt 2^an/2
i.e.
L = 2^L/2
(by continuity of exponentiation). Only
L = 2 and L = 4
andwork here - it's easy to verify that these are solutions, and writing
g(x) = 2^x/2 - x
and differentiating we find that (g) decreases on (0, 3.05) and increases on
(3.05 , infinite)

(note - it's not exactly 3.05) - thus we can have at most two zeros ofg(x) , which means only two possible values for L
(since our equation for
L is equivalent to)

g(L) = 0
Putting it all together:
An is bounded above by 2 and strictly increasing, and thus must converge (namely, to the least upper bound of the sequence). The only values it can converge to are 2 and 4; since we know every term in the sequence is less than 2 , it must converge to 2.

Like? Yes (3) | No (2)  

arush gupta   10 years AGO

[[Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)] ........... infinite = x
xlog[Sqrt(2)=logx
log[Sqrt(2)=1/xlogx
1/2log2=1/xlogx
x=2 ans

Like? Yes (1) | No   

rajan jha   10 years AGO

[Sqrt(2)]^x=x;
[Sqrt(2)]=(x)^(1/x);
=2

Like? Yes (1) | No   

sabir ahmd   10 years AGO

[Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)] ........... infinite = x

or x=[Sqrt(2)]^x
or x^1/x=2^1/2
from above equation we can say that x=2

Like? Yes (1) | No   

Meenakshi   10 years AGO

sqrt(2)^sqrt(2)^sqrt(2).....infinite=x
let sqrt(2)^(sqrt(2)^sqrt(2)^sqrt(2)....)=x
sqrt(2)^x=x
multiplying 1/x on both powers,
sqrt(2)=x^1/x
=>x=2
ans is 2.

Like? Yes (1) | No   

NUPUR JHA   10 years AGO

[sqrt 2] ^ [sqrt 2] ^ [sqrt 2] ........ infinity =x
hence, [sqrt 2] ^ x =x
[2] ^ (x/2) = x
2= x ^ (2/x)
on solving we get x= 2

Like? Yes (1) | No   

Saurabh Kumar Gupta   10 years AGO

[Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)] ........... infinite = x

[Sqrt(2)]^x = x

By hit and trial, x=2 and x=4 satisfy

Like? Yes (1) | No   

Ankit Sirohi   10 years AGO

[Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)] ........... infinite = x

or [Sqrt(2)]^x = x

or [Sqrt(2)] = 2^(1/2) = x^(1/x)

so, x = 2..........option 10 is the answer

Like? Yes (1) | No   

A M ANKIT KALLURAYA   10 years AGO

by elimination of invariant
2^x=x
=>x=2

Like? Yes (1) | No   

guru   10 years AGO

sqrt(2) is roughly equal to 1.414.
So, our problem simplifies to 1.414^1.414...........
If we take finite steps say 2,3,4 etc we see that the value converges to 2.
So, x=2

Like? Yes (1) | No   

MRITUNJAY   10 years AGO

this the answer.
2^1/2*x=x
by squaring both side
2^1/2=x^1/x
so x=2.

Like? Yes (1) | No   

ABHINAV PUSHPAM   10 years AGO

Answer is 10

Like? Yes (1) | No   

ash pandey   10 years AGO

Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)] ........... infinite = x
THUS, sqrt(2)^x=x
2^(x/2)=2,
which is possible at x=2
which is option 10

Like? Yes (1) | No   

Chandra chur anand   10 years AGO

a/c to Q sqrt(2)^x=x
or x=2 satisfy this...

Like? Yes (1) | No   

b.subbarao   10 years AGO

[Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)]^[Sqrt(2)] ........... infinite = x then sqrt2=x ...(i) squiring both sides we get x=2

Like? Yes (1) | No (1)  

13 Jan 2015 Two Numbers

Two numbers are known as first number and second number. 20% of the first number is 9 more than 30% of second number. The difference of two numbers is x more than the half of second number. x will be

OPtion

1) 25
2) 30
3) 35
4) 40
5) 45
6) 50
7) 55
8) 60
9) 65
10)70

Solution

Let first number A and second number B then
according to given condition
20A/100 = 9 + (308/100)
2A = 90 + 3B
2(A-B) = 90 + B
A - B = 45 + B/2
So x = 45

Option 5)

Correct Option: 5 Best Solution (61)

Supriya Mondal   10 years AGO

let 1st number is y and 2nd number is z
then according to question we can write
(1/5)*y=9+(3/10)*z............................(i)
Again, from the question we can write
y-z=x+(z/2)
y=x+(3/2)*z
then we put value of y in equation (i) and get
(1/5)*x+(3/10)*z=9+(3/10)*z
so, x=45
So, option 5)45 is the right answer

Like? Yes (4) | No   

Surit Datta   10 years AGO

Let the 1st number be a
2nd number be b
so,
(a/5-3b/10) = 9
from the above equation we get
2a-3b = 90
which implies
(a-b) = b/2 + 45
so according to the question x is 45
That's it.
Option 5.

Like? Yes (2) | No   

Sravanthi   10 years AGO

20% of a=9+30% of b
a-b=x+0.5b
x=45

Like? Yes (2) | No   

sai sindhu   10 years AGO

let a,b be he numbers
given (20/100)*a=9+(30/100)*b
i.e;a-(3/2)b=45------->1
also given a-b=x+b/2
i.e;a-(3/2)b=x------>2
on comparing, 1&2
x=45

Like? Yes (2) | No   

Jaspalsingh Parmar   10 years AGO

Let 1 st and 2nd no. be p and q
1st condition
0.2p=0.3q+9----------(1)

2nd condition
p-s=x+(s/2)
p-(3/2s)=x

2p-3s=2x----------(2)

2x=90
x=45

Like? Yes (2) | No   

Vinay Sipani    10 years AGO

Let the numbers be a and b

Given:
20a/100 = 9 + 30b/100
=> 2a - 3b = 90

Also,
a - b = x + b/2
=> 2a - 3b = 2x

Equating both, we have 2x = 90
=> x = 45

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MRITUNJAY KUMAR   10 years AGO

Option)5

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SREENIVASA RAO PALLAPU   10 years AGO

Let y is first number and z is second number
Given that
0.2y = 0.3z + 9 => 2y - 3z = 90
y - z = x + (z/2) => 2y - 3z = 2x
=>2x = 90 => x =45

Like? Yes (1) | No   

Tark Patel   10 years AGO

In first condition,
Let two numbers are a and b
then 20 % of a = 30 % of b + 9

-> 2*a - 3*b = 90 ............(i)

In second condition,

a - b = (b/2) + x
-> 2*a - 3*b = 2*x .............(ii)

comparing (i) & (ii)
we get 2*x = 90 so x = 45

Like? Yes (1) | No   

Abhishek Porwal   10 years AGO

20% of a=9+30% of b
a-b=x+0.5b
On solving both equations we get,
y=0 &
x=45

Like? Yes (1) | No   

Md.Sultan Khichi   10 years AGO

Let the first num is a and 2nd num is b .
So according to the sum
20%*a-30%*b=9
2a-3b=90
Agn
a-b=x+b/2
2a-3b=2x
Comparing both equations we get
x=45
Ans ob 5

Like? Yes (1) | No   

Sanu Panji   10 years AGO

say, a = 1st number and b = 2nd number
so
1st condition:
( 20a/100) - (30b/100) = 9
or, 2a - 3b = 90 --------------(1)
2nd condition:
a - b = (b/2) + x
or, 2a - 2b = b + 2x
or, 2a - 3b = 2x ---------------(2)
from (1) and (2) we get
2x = 90
or, x = 45
so option (5) is correct

Like? Yes (1) | No   

RAKESH   10 years AGO

u/5 = 9 + 3v/10

or u - v = 45 + v/2

Like? Yes (1) | No   

K SRILEKHA   10 years AGO

let the 2 no's be a,b
0.2a = 9+ 0.3b --------> 1
and a-b = x+0.5b ----------> 2
let us assume a=100
then b=36.667
put these values in 2 eqn then
x=45

Like? Yes (1) | No   

ABHINAV PUSHPAM   10 years AGO

let number be p and q.
20*p/100-30*q/100=9
2p-3q=90........(1)

p-q=x+q/2
2p-3q=2x.........(2)
from 1 and 2 we get
2x=90
x=45.
option (5)

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Ajinkya Kulkarni   10 years AGO

45

Like? Yes (1) | No   

sravani   10 years AGO

let the numbers be a,b
Given 20/100 a =30/100 b + 9
a=3/2 b + 45
and
a - b = x + b/2
a - 3/2 b =x
3/2 b + 45 - 3/2 b = x
x=45.

Like? Yes (1) | No   

Akhil Malhotra   10 years AGO

Let first number=a
Let second number =b
According to condition:
20% of a=30% of b+9
Solving it we get
2a-3b=90
2(a-b)-b=90

According to second condition
a-b=x+b/2

Putting in first condition
2x+b-b=90
2x=90
So x =45

Like? Yes (1) | No   

MRITUNJAY   10 years AGO

let number be p and q.
20*p/100-30*q/100=9
2p-3q=90........(1)

p-q=x+q/2
2p-3q=2x.........(2)
from 1 and 2 we get
2x=90
x=45.
option (5)

Like? Yes (1) | No   

Anjali   10 years AGO

0.2y-0.3=9
y-z=x+(1/2)z
on solving we get
2y-3z=2x
=> x=45

Like? Yes (1) | No   

Jay parmar   10 years AGO

Let 1 st and 2nd no. be p and q
1st condition
0.2p=0.3q+9----------(1)

2nd condition
p-s=x+(s/2)
p-(3/2s)=x

2p-3s=2x----------(2)

2x=90
x=45

Like? Yes (1) | No   

Arnic Roy Chowdhury   10 years AGO

3A/10 - X/5 =9
X=90
DIFF=90/2=45

Like? Yes (1) | No   

ranjithreddy   10 years AGO

1st condition:
.2a-.3b=9
2nd condition:
a-b=x+b/2
on equating 1 and 2
we get 2x=90
x=45

Like? Yes (1) | No   

guru   10 years AGO

Let the numbers be A and B.
20A/100 = 30B/100 +9
This yields A= 45+3/2 B
Now, A is greater than B.
So, A-B= B/2 +x
A- 3B/2 =x
45+3B/2 -3B/2 =x
x=45

Like? Yes (1) | No   

Shreeom Singh   10 years AGO

a/5+9=3b/10.......eqn(1)
a-b+x=b/2........eqn(2)
on solving both enq.s we get,
2x=90
=> x=45
hence, x=45

Like? Yes (3) | No (2)  

himanshu   10 years AGO

GT 20% of a= 30% of b + 9
=> a/5 - 3b/10 = 9 ---eqn 1
also a - b = b/2 + x
=> a - 3b/2 = x ---eqn2
balancing the factors of bothe eqns
x/5 = 9
=> x = 45

Like? Yes (1) | No   

kvsnlr   10 years AGO

let first no be F and second number be S
given 0.2F-0.3S=9
then 0.2F-0.2S-0.1S=9
0.2(F-S)-0.1S=9
(F-S)-0.1/0.2S=0.9/0.2
(F-S)=45+0.5S

Like? Yes (1) | No   

Gitanjali K   10 years AGO

0.2F.N-0.3S.N=9.....(1)
2F.N-3S,N=2x..........(2)

solving eq (1) & (2) we get x=45

Like? Yes (1) | No   

ayush bagga   10 years AGO

Two no.s are F & S
20/100F=9+30/100S (1)
F-S=X+1/2S (2)
Solving Eqn 2-
F=45+3/2S (3)
By 2 & 3
we get X=45

Like? Yes (1) | No   

Ankit Sharma   10 years AGO

2a-3b=90
2a-3b=-2x
Solve them

Like? Yes (1) | No   

DurgaPrasad   10 years AGO

Let's just assume the 1st no: and 2nd no: is A and B
so from the ques :
1/5A=9+3/10B---------(1)
From the second part
A-B=X+1/2B
SO A-3/2B=X--------------(2)
Solve the 2 equations
ans is 45

Like? Yes (1) | No   

sandeep kumar   10 years AGO

20% of a=9+30% of b
a-b=x+0.5b
x=45

Like? Yes (1) | No   

Anusha   10 years AGO

Given 20% of f=9+30% of s
20f/100=9+(30s/100)
2f=90+3s
2f-3s=90.
Given f-s=x+(s/2)
f-s-(s/2)=x
2f-3s=2x
comparing 2f-3s=90 and 2f-3s=2x the x=90/2=45
so answer 45.

Like? Yes (1) | No   

Meenakshi   10 years AGO

Let the first and second number be f and s
1st condition:
20%of f = 9+30%of s
=>f/5 = 3s/10+9
=>f/5-3s/10=9----->(1)
2nd condition:
f-s = x+1/2*s
=>f-3s/2=x----->(2)
Solve equ (1) and (2)
=>x=45
so,answer is 45
option 5)

Like? Yes (1) | No   

arush gupta   10 years AGO

let the no. be a and b then (20a/100) - (30b/100)=9
20a -30b=900-------(1)
a-b=x +b/2
a- 3b/2=x------------(2)
multiplyng eq(2) by 20 we will get
20a-30b=20x---------(3)
from eq(1) comparing it is clear that
20x=900
x=45.ans

Like? Yes (1) | No   

Arman Khan   10 years AGO

a/5=3b/10+9
and a-b=x+b/2
after solving x=45

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Devendra Marghade   10 years AGO

If two numbers are 'a' & 'b', then
a*(20/100) =9+ b*(30/100) or 0.2a-0.3b=9 ---(i) &
a- b= x + (b/2) or 2a - 3b=2x ---(ii)
On solving (i) & (ii), x=45

Like? Yes (1) | No   

gourav shukla   10 years AGO

2a/10=9+3b/10
2a-3b=90.........
a-b=x+b/2
a-b-b/2=x
(2a-3b)/2=x
90/2=x
45

Like? Yes (1) | No   

khushboo goenka   10 years AGO

diff bw 1 and 2 nno is 0.5a-45=x
=0.5a

Like? Yes (1) | No   

Ankit Sirohi   10 years AGO

let first number be f, and second be s,
so x=f-3s/2;
taking basic case of f=90 and s=30 we get x=90-90/2
x=45...option 5...is the answer....

Like? Yes (1) | No   

Ankit Pandey   10 years AGO

Let Numbers are a & b
20% of a = 30% of b+ 9
on solving;
2a - 3b=90
from 2nd condition
a - b= X+b/2
on solving; 2a-3b= 2X
so 2X = 90
hence X=45

Like? Yes (1) | No   

Ashu Tomar   10 years AGO

Let 20% of first number is 27
So first number is 135
And 30% of second number is 18
So second number is 60
The difference between them is 75 which is 45 more than half of second number (60)

Like? Yes (1) | No   

NITHYA   10 years AGO

20%F=30%S+9

F/5=3S/10+9
2F-3S=90------->I


F-S=S/2+X
2F-3S=2X----------->2

FROM I&II,

2X=90

X=45

Like? Yes (1) | No   

Mukul Abhijit Bhate   10 years AGO

let a & b be two no.s
0.2a+ 9=0.3b
a-b=x+0.5b
compare both equation
x=45

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PRAJJWAL AGARWAL   10 years AGO

After solving both equations, I got x = 45.

Like? Yes (1) | No   

sneha sri   10 years AGO

20m=900+30n
m-n=x+50n/100
x=45

Like? Yes (1) | No   

Abhik Das   10 years AGO

Let A,B the two numbers
Simple according to the 1st condition the equation is-
(2*A-3*B)=90
And by using 2nd condition the equation is-
(2*A-3*B)=2*x
Equating right hand side we get
x=45

Like? Yes (1) | No   

Anuj Rana   10 years AGO

Let first no. Be a and second no. Be b
Then,(20/100)*a=(9+(30/100)*b)
And (b/2)+x=a-b
Therefore, a=((3*b)/2)+x
Putting the value of a in (1)
((3*b)/10)+(x/5)=(90+(3*b))/10
=x=45

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Pramod Gaikwad   10 years AGO

20% of a=9+30% of b
2a-3b=90..........1

a-b=x+b/2........2
from 1 and 2
2x=90
x=45
so option is 5)45

Like? Yes (1) | No   

Abhinav   10 years AGO

let numbers be x and y
equation 1: 20% of x=30% of y+9
20x=30y+900
2x-3y=90
equation 2: x-y=x+y/2
y/2+y=0
y=0
solving both equation we get x=45

Like? Yes (1) | No   

A M ANKIT KALLURAYA   10 years AGO

20% of a=9+30% of b
a-b=x+0.5b
x=45.
hence the answer

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Mithun Kumar Kesari   10 years AGO

opp. 5 (x=45)
let two numbers are m and n.
given,
20/100*m - 30/100*n= 9 =>2m- 3n =90 -----------(1)

and m-n= x+ n/2 => m-3/2*n= x => 2m- 3n = 2x ------(2)

from equations 1 and 2, 2*x=90 => x=45 ans.

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sabir ahmd   10 years AGO

let
the first no=a and
the second no=b,
20% of a=9+ 30% of b
or 2a-3b=90

again a-b=x+b/2
or 2x=2a-3b
or x = 45

Like? Yes (1) | No   

Paras Jain   10 years AGO

x = 45 Ans.

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Ankan Biswas   10 years AGO

Let first and second numbers be k and y respectively.
so, k/5 = 3y/10 + 9 ==>2k - 3y = 90
==>2k - 2y =90 + y ==> k-y= 45+y/2 .... (i)
Again, k-y = y/2+x ....(ii)
From (i) and (ii), x=45

Like? Yes (1) | No   

Chandra chur anand   10 years AGO

=>20% *x=30% *y+9
=>x/5=3y/10+9
=>2x-y=90------- eqn 1
now x - y = x + y/2
or 2x+y=2x-2y----------eqn 2
frm eq1 and eq2
x+y=45 or y=45-x---- eq3
put eq3 into eq1
2x-(45-x)=90
3x=135
or x=45 ans...!!!!!

Like? Yes (1) | No   

priya saha   10 years AGO

option 5 : 45

let frst no. be a
secnd no. be b
then by the conditions given above if we apply substitution method we get the ansr as 45

Like? Yes (1) | No   

venkatesh v   10 years AGO

Let two numbers are A,B.
20% 0f A = 30% of B + 9
i.e 2A = 90+3B;----(1)
->difference A-B = x+B/2
i.e 2A = 2x+3B;-----(2)
Now let equation (1) and (2) similar, so
2x+3B = 90+3B
so x = 45.

Like? Yes (1) | No   

Rohit Raj Sonha   10 years AGO

we take the first number 100, then 20 pecent 20

Like? Yes (1) | No   

Anurag Dwivedi   10 years AGO

.2p=.3q+9
2p-3q=90
p-1.5q=45 (eq 1)
now from equation 2
p-q=45+.5q

Like? Yes (1) | No   

NUPUR JHA   10 years AGO

Let the two numbers be a and b
a(0.2)= b(0.3) +9
i.e. 2a- 3b=90

Now,
a- b= x + (b/2)
i.e. 2a-3b = 2x

hence 2x= 90
x=45

Like? Yes (1) | No   

12 Jan 2015 Sequence

What is the next number of the following sequence
1/2, 5/4, 25/12, 71/24, 463/120, .....

OPtion

1) 515/120
2) 517/120
3) 521/120
4) 527/120
5) 539/120
6) 547/120
7) 559/120
8) 573/120
9) 593/120
10)601/120

Solution

5/4 - 1/2 = 3/4
25/12 - 5/4 = (25-15)/12 = 5/6
71/24 - 25/12 = (71-50)/24 = 21/24 = 7/8
463/120 - 71/24 = (463-355)/120 = 108/120 = 9/10
Similarly
573/120 - 463/120 = (573-463)/120 = 110/120 = 11/12

Option 8)

Correct Option: 8 Best Solution (29)

Supriya Mondal   10 years AGO

Difference between 1st and 2nd number is=3/4
Difference between 2nd and 3rd number is=5/6
Difference between 3rd and 4th number is=7/8
Difference between 4th and 5th number is=9/10
So, like that difference between 5th and 6th number will be=11/12
So, answer will be=(463/120)+(11/12)=573/120
So, option 8)573/120 is the right answer

Like? Yes (4) | No (1)  

Surit Datta   10 years AGO

Here the difference between the 1st & 2nd numbers are 3/4
the difference between the 2nd & 3rd numbers are 5/6
the difference between the 3rd & 4th numbers are 7/8
the difference between the 4th & 5th numbers are 9/10
So the difference between the 5th & 6th numbers will be 11/12
so the number fraction will be 573/120
That's it.
Option 8.

Like? Yes (2) | No (1)  

Dr.Dipin Singh   10 years AGO

463/120 +11/12= 573/120 ... option 8

Like? Yes (2) | No (1)  

Mukul Abhijit Bhate   10 years AGO

1/2+3/4=5/4
5/4+5/6=25/12
25/12+7/8=71/24
71/24+9/10=463/120
463/120+11/12=573/120

Like? Yes (1) | No   

sneha sri   10 years AGO

1/2+3/4=5/4
5/4+5/6=25/12
25/12+7/8=71/24
71/24+9/10=463/120
463/120+11/12=573/120

Like? Yes (1) | No   

saikat das   10 years AGO

diff is 3/4,5/6,7/8,9/10 so next should be 11/20 .
so let's take the ratio is x/y.. then x/y-463/120=11/12 . After solving it we get 573/120....

Like? Yes (1) | No   

Sajir   10 years AGO

Series goes on like this
1/2
1/2+3/4=5/4
5/4+5/6=25/12
25/12+7/8=71/24
71/24+9/10=463/120
463/120+11/12=573/120
Hence option 8

Like? Yes (1) | No   

Abhishek Porwal   10 years AGO

1/2+3/4=5/4
5/4+5/6=25/12
Similarly
463/120+11/12=573/120

Like? Yes (1) | No   

RAKESH   10 years AGO

differences are

3/4 , 5/6 , 7/8 , 9/10 , 11/12

Like? Yes (1) | No   

A M ANKIT KALLURAYA   10 years AGO

guessed

Like? Yes (1) | No   

santosh kumar patel   10 years AGO

573/120

Like? Yes (1) | No   

Shreeom Singh   10 years AGO

(463/120)+(11/12)=573/120

Like? Yes (1) | No   

Paras Jain   10 years AGO

Convert all in the form of (x/120) then pattern can be esaily identified. Thus, 573/120 Ans.

Like? Yes (1) | No   

SREENIVASA RAO PALLAPU   10 years AGO

Given sequence is 1/2, 5/4, 25/12, 71/24, 463/120,...
5/4 - 1/2 = 3/4
25/12 - 5/4 = 5/6
71/24 - 25/12 = 7/8
463/120 - 71/24 = 9/10
=> next ratio will be =463/120 + 11/12 = 573/120

Like? Yes (1) | No (1)  

Md.Sultan Khichi   10 years AGO

The series is like this
5/4-1/2=3/4
25/12-5/4=5/6
71/24-25/12=7/8
463/120-71/12=9/10
So the next num is..
463/120+11/12=573/120
Ans ob 8

Like? Yes (1) | No (1)  

ABHINAV PUSHPAM   10 years AGO

Answer is 8

Like? Yes (1) | No (1)  

MRITUNJAY   10 years AGO

difference between two number in series in the ratio of increasing ratio.5/4-1/2=3/4
25/12-5/4=5/6
71/24-25/12=7/8
463/120-71/24=9/10
573/120-463/120=11/12
so answer is option 8.

Like? Yes (1) | No (1)  

Gitanjali K   10 years AGO

5/4-1/2=3/4
25/12-5/4=5/6
71/24-24/12=7/8
.
.
573/120-463/120=11/12
so option 8 is the answer

Like? Yes (3) | No (3)  

Rahul Rathod   10 years AGO

1/2 + 3/4 = 5/4
5/4 + 5/6 = 25/12
25/12 + 7/8 = 71/24
71/24 + 9/10 = 463/120
463/120 + 11/12 = 573/120
answer is option 8) 573/120

Like? Yes (1) | No (1)  

Sanu Panji   10 years AGO

60, 150, 250, 355, 463, 573

Like? Yes (1) | No (1)  

Meenakshi   10 years AGO

the difference between
5/4-1/2=3/4
25/12-5/4=5/6
71/24-25/12=7/8
463/120-71/24=9/10
To find x:
x-463/120=11/12
->11/12+463/120
->573/120
So,answer is 573/120.

Like? Yes (1) | No (1)  

guru   10 years AGO

1/2+3/4=5/4
5/4+5/6=25/12
25/12+7/8=71/24
71/24+9/10=463/120
So, 463/120 + 11/12= 573/120

Like? Yes (1) | No (1)  

Jaspalsingh Parmar   10 years AGO

1/2*(3/4)=5/4

5/4*(5/6)=25/12

25/12*(7/8)=71/24

71/24*(9/10)=463/120
so,
463/120*(11/12)=573/120

so option 8 is correct

Like? Yes (1) | No (1)  

Jay parmar   10 years AGO

573/120

1/2*(3/4)=5/4

5/4*(5/6)=25/12

25/12*(7/8)=71/24

71/24*(9/10)=463/120
so,
463/120*(11/12)=573/120

so option 8 is correct

Like? Yes (1) | No (1)  

amit   10 years AGO

no..

Like? Yes (1) | No (1)  

Ankit   10 years AGO

5/4-1/2=3/4
25/12-5/4=5/6
71/24-25/12=7/8
463/120-71/24=9/10
There fore, 463/120+11/12=573/120

Like? Yes (1) | No (1)  

NITHYA   10 years AGO

guess

Like? Yes (1) | No (1)  

Aritra Ghosh   10 years AGO

Difference is in terms will fetch u the answer. Use ur logic..

Like? Yes (1) | No (1)  

arpita   10 years AGO

1/2+3/4=5/4, 5/4+5/6=25/12.........463/120+11/12=573/120

Like? Yes (1) | No (1)  

09 Jan 2015 Sum of numbers

A number is formed by using the integers 2, 3, 4 and 9. According to the condition given below.
1) Number is even
2) Thousand's digit of the number is odd
3) Ten's digit is smaller then hundred digit
What will be the sum of all such numbers.

OPtion

1) 24678
2) 26622
3) 55834
4) 64768
5) 92676
6) 52766
7) 18612
8) 70680
9) 78750
10)62728

Solution

Total numbers = 4*3*2*1 = 24
Condition one - Number is even so possibilities = 3*2*1*2 = 12
Condition two - Thousand digit of the number is odd so possibilities = 2*2*1*2 = 8
Condition three - Ten's digit is smaller then hundred digit so possibilities = 2*2*1*2/2 = 4
These are
3 9 4 2
9 4 3 2
3 9 2 4
9 3 2 4
--------
2 6 6 2 2

Option 2)

Correct Option: 2 Best Solution (46)

Supriya Mondal   10 years AGO

Given integers are 2,3,4,9
there are 4 numbers that satisfy the above three conditions. They are-
3942
3924
9432
9324
Sum of these numbers is=26622
So option 2)26622 is the right answer

Like? Yes (9) | No   

Ashwin Dinesh   10 years AGO

3924 + 3942 + 9324 + 9432 = 26622

Like? Yes (2) | No   

Surit Datta   10 years AGO

The possible numbers are
3924
3942
9432
9324
Whose summation is 26622
So option 2
That's it.

Like? Yes (2) | No   

Yekollu Muneeswar   10 years AGO

option 2) 26622
according to given conditions,
Four possibilities are there,
3 9 4 2
3 9 2 4
9 4 3 2
9 3 2 4
sum=26622

Like? Yes (2) | No   

ayush bagga   10 years AGO

There will be 4 such no.s which satisfy the above 3 conditions-
3 9 4 2
3 9 2 4
9 4 3 2
9 3 2 4
the total sum becomes=26622

Like? Yes (2) | No   

b.subbarao   10 years AGO

9432+3942+9324+3924=26622

Like? Yes (2) | No   

rishabh goyal   10 years AGO

all the no.s from these combinations are:-
9324
3942
3924
9432

Like? Yes (2) | No   

Vinay Sipani    10 years AGO

The numbers are
9432
3942
3924
9324
=> Sum = 26622

Like? Yes (1) | No   

Sanu Panji   10 years AGO

there are such 4 numbers
3942
3924
9432
9324

so sum is 26622

Like? Yes (1) | No   

Rakshit Shetty   10 years AGO

3942+9432+3924+9324=2662
that is option 2

Like? Yes (1) | No   

Gitanjali K   10 years AGO

possible numbers are..
9432,3942,9324,3924 and sum is 26622

Like? Yes (1) | No   

MRITUNJAY KUMAR   10 years AGO

Option)2

Like? Yes (1) | No   

ramesh   10 years AGO

unit value may be 2 or 4only
3942
3924
9324
9432
sum is 26622

Like? Yes (1) | No   

Jaspalsingh Parmar   10 years AGO

Forming all 4 digit no. using 2,3,4,9
By sorting according to condition we get,
3924
3942
9324
9432

so 3924+3942+9324+9432=26622

Like? Yes (1) | No   

Jay parmar   10 years AGO

Forming all 4 digit no. using 2,3,4,9
By sorting according to condition we get,
3924
3942
9324
9432

so 3924+3942+9324+9432=26622

Like? Yes (1) | No   

keerthana chennamsetty   10 years AGO

9432
3942
3924
9324
total 26622

Like? Yes (1) | No   

venkatakoteswararaolingisetty   10 years AGO

3942+3924+9432+9324=26622

Like? Yes (1) | No   

Satya B   10 years AGO

3942
3924
9324
9432
are the only numbers which follow the above condition and their sum is 26622

Like? Yes (1) | No   

Biswajit Saha   10 years AGO

3942+3924+9324+9432=26622

Like? Yes (1) | No   

PAWAN KUMAR   10 years AGO

There are 4 possible combinations:
9324
9432
3942
3924
Sum:26622. Ans.

Like? Yes (1) | No   

pappu kumar priye   10 years AGO

3942+3924+9432+9324=26622

Like? Yes (1) | No   

Ankit Pandey   10 years AGO

9432+9324+3942+3924=26622

Like? Yes (1) | No   

A M ANKIT KALLURAYA   10 years AGO

3924+9432+3942+9324

Like? Yes (1) | No   

guru   10 years AGO

The numbers according to the given conditions are 3942, 3924, 9432 and 9324 and their sum is 26622

Like? Yes (1) | No   

NITHYA   10 years AGO

3942+
3924+
9432+
9324= 26622

Like? Yes (1) | No   

sibasish   10 years AGO

3942
3924
9432
9324
are the nos....by adding these we got 26622

Like? Yes (1) | No   

KILUGU NARASINGA RAO   10 years AGO

3942+3924+9324+9432=26622

Like? Yes (1) | No   

swarupa nuggu   10 years AGO

Chfbn

Like? Yes (1) | No   

ABHINAV PUSHPAM   10 years AGO

Asnwer is 2

Like? Yes (1) | No   

MRITUNJAY   10 years AGO

numbers are 3942,3924,9324,9432
sum is 26622
option 2

Like? Yes (1) | No   

Mithun Kumar Kesari   10 years AGO

possible numbers are
9432
3942
9324
3924
and sum = 26622

Like? Yes (1) | No   

baby posamma   10 years AGO

3942+3924+9324+9432

Like? Yes (1) | No   

Shreeom Singh   10 years AGO

sum of (9432+9324+3942+3924)

Like? Yes (1) | No   

thasleema   10 years AGO

3924+3942+9432+9324=26622

Like? Yes (1) | No   

Paras Jain   10 years AGO

3942 + 3924 + 9432 + 9324 = 26622 Ans.

Like? Yes (1) | No   

jahnavi raja   10 years AGO

3942,+3924+9432+9324=26622

Like? Yes (1) | No   

Sourabh Gupta   10 years AGO

since the number is even the unit digit should either be 4 or 2
taking 2 as unit digit we have to either write 3 or 9 at the thousand's place
with 2 at unit place we have 2 numbers required by the condition
3942 and 9432
and with 4 at unit place we have 2 numbers
3924 and 9324 adding all four we get 26622

Like? Yes (1) | No   

susanta   10 years AGO

9324+3924+3942+9432=26622

Like? Yes (1) | No   

ramakrishnateja   10 years AGO

the numbers that are formed from using the above conditions are the below four numbers.
they are
9432
3942
9324
3924
hence the sum of these numbers is 9432+3942+9324+3924=26622

Like? Yes (1) | No   

Arman Khan   10 years AGO

3924+3942+9324+9432=26,622

Like? Yes (1) | No   

g lokesh   10 years AGO

the numbers possible foe given conditions are
3942
3924
9432
9324
sum=26622

Like? Yes (1) | No   

Aditya Anup   10 years AGO

According to given conditions, there are following numbers are possible using integers 2 ,3,4,9

3924 + 3942 + 9432 + 9324 = 26622

Like? Yes (1) | No   

Chandra chur anand   10 years AGO

a/c to conditions nos. are
3942+9432+3924+9324=26622 ans...

Like? Yes (1) | No   

Ankit Sirohi   10 years AGO

the numbers are 3942 3924 9324 9432 thus the sum is= 26622

Like? Yes (1) | No   

Mukund Ranjan Singh   10 years AGO

9432+9324+3924+3942

Like? Yes (1) | No   

~Sandeep~   10 years AGO

9432
9324
3942
3924

Like? Yes (1) | No   

08 Jan 2015 Sum of all the number

Sum of all the numbers formed by using the integers of the number 1977 will be

OPtion

1) 113322
2) 159984
3) 108678
4) 98638
5) 42568
6) 72664
7) 58768
8) 79992
9) 41978
10)40998

Solution

Total no = 12
Every place units ten's hundred's and thousands contain every integers thrice, if any no will be revised (like 7), it will come thrice twice so six times
so in very place
sum of integers = 3(7+7+9+1)
= 72
So sum = 72000+7200+720+72 = 79992

Option 8)

Correct Option: 8 Best Solution (19)

Supriya Mondal   10 years AGO

12 numbers are possible using 1977
they are-
1977
1797
1779
9177
9717
9771
7197
7719
7791
7179
7971
7917
so total of these numbers is=79992
so option 8)79992 is the correct answer

Like? Yes (10) | No (2)  

Sanu Panji   10 years AGO

sum of all integer : 1+7+7+9=24
each integer comes 3 times in a column
so each colomn sum = 24*3=72
there are 4 column
total sum=1111*72=79992

Like? Yes (4) | No (2)  

MRITUNJAY KUMAR   10 years AGO

Option)8

Like? Yes (1) | No   

sompon temtheerakij   10 years AGO

=1797+1779+1977+7197+7179+7791+7719+7917+7971+9177+9717+9771 = 79992

Like? Yes (1) | No   

Sravanthi   10 years AGO

numbers formed by 1977 like 1977+1797+1779 .......

Like? Yes (2) | No (1)  

Paras Jain   10 years AGO

1779+1797+1977+7179+7197+7719+7791+7917+7971+9177+9717+9771 = 79992

Like? Yes (1) | No   

Rakshit Shetty   10 years AGO

1779+1797+1977+7179+7197+7719+7791+7917+7971+9177+9717+9771=79992
option 8

Like? Yes (1) | No   

ramakrishnateja   10 years AGO

numbers formed with the integers of the number is 3!/2!. the 2!in the denominator is because of repetition of 2 7's . then in order to find the sum of the numbers first form the number that starts with 1 in units place=3!/2!.
similarly with the remaining numbers we can form like this. then the sum of the value of the numbers in units place is given by 3!/2!(1+9+7+7).and similarly with the numbers in the tens place it is 3!/2!(10+90+70+70). and it goes like this 3!/2!(100+900+700+700),3!/2!(1000+9000+7000+7000).which gives the total as 79992

Like? Yes (1) | No   

b.subbarao   10 years AGO

6*7(1111)+3*9(1111)+3*1(1111)=79992

Like? Yes (1) | No   

Sourabh Prasad   10 years AGO

1779+1797+1977+7179+7197+7719+7791+7917+7971+9177+9717+9771=79992

Like? Yes (1) | No   

jahnavi raja   10 years AGO

1779+1797+1977+7179+7197+7719+7791+7917+7971+9177+9717+9771=79992

Like? Yes (1) | No   

Prasanth G   10 years AGO

1779+1797+1977+7179+7197+7719+7791+7917+7971+9177+9717+9771=79992

Like? Yes (1) | No   

MERUGU SANTHU   10 years AGO

We have 3 different numbers i.e., 1,9,7. By fixing 1 in the first place we can form 3 numbers(1977,1797,1779). By fixing 9 in first place we can form 3 numbers(9177,9717,9771). By fixing 7 in first place we can form 6 numbers(7197,7917,7719,7791,7179,7971).. Sum of all these numbers gives result as 79992

Like? Yes (1) | No   

Chandra chur anand   10 years AGO

1977+1797+1779+7197+7917+7971+7719+7791+7179+9177+9717+9771=79992

Like? Yes (1) | No   

susanta   10 years AGO

1977+1797+1779+9177+9717+9771+7197+7917+7971+7791+7719+7179= 79992

Like? Yes (1) | No (1)  

Ankit Pandey   10 years AGO

1977+1797+1779+9177+9771+9717+7917+7971+7197+7179+7719+7791=79992

Like? Yes (1) | No (1)  

Surit Datta   10 years AGO

the possible numbers are
1797
1977
1779
7791
7719
7917
7971
7197
7179
9177
9771
9717
whose summation is 79992
so option 8
that's it.

Like? Yes (1) | No (1)  

Ashwin Dinesh   10 years AGO

guessed :P

Like? Yes (1) | No (1)  

Rahul Rathod   10 years AGO

1779+1797+1977+
7179+7197+7719+7791+7917+7971+
9177+9717+9771
=79992
answer is option 8)79992

Like? Yes (1) | No (2)  

07 Jan 2015 Rank of word

What will be the rank of word "WEDNESDAY" in the dictionary of words formed by letters of the word "WEDNESDAY" (using all the letter in every word)

OPtion

1) 75028
2) 75065
3) 75096
4) 75101
5) 75109
6) 75113
7) 75116
8) 75132
9) 75123
10)75149

Solution

Total no of words = (9*8*7*6*5*4*3*2*1)/(2*1*2*1) = 90720
In denominator 2*1 and 2*1 used due to revision of D & E twice
90720*7/9 + 10080*3/8 + 1260*2*1/7 + 360*2*3/6 + 120*2/5 + 24*2/4 + 6*1/3 + 2*0/2 + 1
= 70560 + 3780 + 360 + 360 + 48 + 12 + 2 + 0 + 1 = 75123

Option 9)

Correct Option: 9 Best Solution (14)

Supriya Mondal   10 years AGO

Number of words starting with a=(8!/2!*2!)=10080
Number of words starting with d=(8!/2!)=20160
Number of words starting with e=(8!/2!)=20160
Number of words starting with n=(8!/2!*2!)=10080
Number of words starting with s=(8!/2!*2!)=10080
Number of words starting with wa=(7!/2!*2!)=1260
Number of words starting with wd=(7!/2!)=2520
Number of words starting with wea=(6!/2!)=360
Number of words starting with weda=5!=120
Number of words starting with wedd=5!=120
Number of words starting with wede=5!=120
Number of words starting with wedna=4!=24
Number of words starting with wednd=4!=24
Number of words starting with wednea=3!=6
Number of words starting with wedned=3!=6
Number of words starting with wednesa=2!=2
Number of words starting with wednesda=1!=1
So rank=10080+20160+20160+10080+10080+1260+2520+360+120+120+120+24+24+6+6+2+1=75123
So option 9)75123 is the right answer

Like? Yes (8) | No   

VIKRAM KUMAR MAHTO   10 years AGO

The alphabets in the word "WEDNESDAY" in numbers are A=1,D=2,E=2,N=1,S=1,W=1,Y=1 . There are 7 alphabets in which 2 are repeated 2 times.
To get the rank of "WEDNESDAY" we need to check the number of words that can be formed before "WEDNESDAY".
From A 8!/(2!2!) words can be formed.
From D 8!/2! words can be formed.
From E 8!/2! words can be formed.
From N 8!/(2!2!) words can be formed.
From S 8!/(2!2!) words can be formed.
Now starting with W number of words that can be formed before "WEDNESDAY" are
WA = 7!/(2!2!)
WD = 7!/2!
WEA = 6!/2!
WEDA = 5!
WEDD = 5!
WEDE = 5!
WEDNA = 4!
WEDND = 4!
WEDNEA = 3!
WEDNED = 3!
WEDNEN = 3!
WEDNESA = 2!
WEDNESDAY

Like? Yes (5) | No (2)  

Ashwin Dinesh   10 years AGO

guessed

Like? Yes (3) | No (1)  

SWETHA BAPANAH K S   10 years AGO

6 3 2 4 3 5 2 1 7
W E D N E S D A Y
(7/(2!*2!))(8!)+(3/(2!*2!))(7!)+(1/2!)(6!)+(3/1!)(5!)+(2/1!)(4!)+(2/1!)(3!)+(1/1!)(2!)+(0/1!)(1!)+(0/1!)(0!)+1
70560+3780+360+360+48+12+2+1
Ans:75123

Like? Yes (2) | No (1)  

Paras Jain   10 years AGO

its 75123...

Like? Yes (1) | No   

ABHINAV PUSHPAM   10 years AGO

6 3 2 4 3 5 2 1 7
W E D N E S D A Y
7/2!*2! 3/2!*2! 1/2! 3/1! 2/1! 2/1! 1/1! 0/1! 0/1!

8! 7! 6! 5! 4! 3! 2! 1! 0!

Now rank of WEDNESDAY= (7/2!*2!) *8! + (3/2!*2!) *7! + (1/2!)*6! + (3/1!)*5! + (2/1!)*4! + (2/1!)*3! + (1/1!)*2! + (0/1!)*1! + ( 0/1!)0! + "1" =75123

i.e. Option 9)

Like? Yes (1) | No   

MRITUNJAY   10 years AGO

6 3 2 4 3 5 2 1 7
W E D N E S D A Y
7/2!*2! 3/2!*2! 1/2! 3/1! 2/1! 2/1! 1/1! 0/1! 0/1!

8! 7! 6! 5! 4! 3! 2! 1! 0!

Now rank of WEDNESDAY= (7/2!*2!) *8! + (3/2!*2!) *7! + (1/2!)*6! + (3/1!)*5! + (2/1!)*4! + (2/1!)*3! + (1/1!)*2! + (0/1!)*1! + ( 0/1!)0! + "1" =75123

i.e. Option 9)

Like? Yes (1) | No   

Meenakshi   10 years AGO

answer is 75,123

Like? Yes (1) | No   

b.subbarao   10 years AGO

arrange the letters ascending order in the given word: ADDEENSWY,thencalculating of the rank words stating with A=8!/2!2!=10080,like wise after calculation wednesday is 75123

Like? Yes (1) | No   

Sanu Panji   10 years AGO

8!/4 + 8!/2 + 8!/2 + 7!/4 + 7!/2 + 6!/2 + 5! + 5! + 5! + 4! + 4! + 3! +3! + 2! + 1
=75123

Like? Yes (1) | No   

arush gupta   10 years AGO

the rank will be 9

Like? Yes (1) | No   

Akhil Malhotra   10 years AGO

Letters are : A D D E E N S W Y
words starting with A= 8!/2!2!= 10080
Similarly words starting with D= 20160
With E= 20160
With N= 10080
With S= 10080
The total is 70560
Now the words with WA= 7!/2!2!= 1260
With WD= 2520
similarly by applying permutations, the total number of words before Wednesday are 75122
Hence rank of WEDNESDAY is 75123

Like? Yes (1) | No (1)  

Rakshit Shetty   10 years AGO

since words are repeated we use the following calculation:
rank of wednesday=(7*8!/(2!*2!))+(3*7!/(2!*2!))+(1*6!/2!)+(3*5!/1!)+(2*4!/1!)+(2*3!/1!)+(1*2!/1!)+(0*1!/1!)+(0*0!/1!)+1

rank of wefnesday=70560+3780+360+360+48+12+2+0+0+1

ranks of wednesday=75123

option 9

Like? Yes (1) | No (1)  

MRITUNJAY KUMAR   10 years AGO

Option)9

Like? Yes (1) | No (2)  

06 Jan 2015 Find the average

The rate of auto meters in delhi are given below
Distance(Km) --- Rate(Rupee)
First 2 Km ----- 25/- Fixed
Every next Km -- 8/- Per Km
Total length of journey, for which average is 10 Rupees per km will be

OPtion

1) 3.4 Km
2) 3.8 Km
3) 4 Km
4) 4.2 Km
5) 4.5 Km
6) 4.9 Km
7) 5 Km
8) 5.2 Km
9) 5.4 Km
10)5.5 Km

Solution

Let the length of Journey is x km then according to given condition
25 + (x-2)8 = x 10
25 - 16 = 2x
9x = 2
x = 4.5

Optio 5)

Correct Option: 5 Best Solution (57)

Supriya Mondal   10 years AGO

let total length of journey is x km
so,
10*x=25+(x-2)*8 (As, for first 2km 25 rupees is fixed)
then,2x=9
so,x=4.5
so option 5)4.5km is the right answer

Like? Yes (10) | No (3)  

Surit Datta   10 years AGO

First 2 Km = 25 rupees
then 8 rupees/km
so 2.5 km @ 8 rupees will be 2.5*8 rupees
which is 20 rupees
so total (2+2.5) = 4.5 km distance
and total rupees are (20+25) = 45 rupees
so the average is 10 rupees per km.
So option 5
That's it.

Like? Yes (5) | No (3)  

Rahul   10 years AGO

suppose the total distance of journey is n km
then the average rupee is given 10
so 10 = (total charge)/n
total charge = 10n
now if we subtract 25 from this total charge then the average will become 8rs per km
so,
total charge - 25/(n-2)=8
let total charge = 10n
so 10n - 25 = 8(n-2)
10n - 25 = 8n - 16
n= 4.5 km

Like? Yes (3) | No (1)  

ABHINAV PUSHPAM   10 years AGO

Answer is 5

Like? Yes (2) | No   

Yekollu Muneeswar   10 years AGO

Given for 2 km --25 rs then for each km --8 rs
let suppose it travels for 2+x km then
(25+8x)/2+x=10
x=2.5
there fore 4.5 km ds=istance travelled
option5)4.5KM

Like? Yes (2) | No (1)  

Rakshit Shetty   10 years AGO

let dist be x
and avg price is 10rs
so the cost for travelling is 10x Rs
as per the statement:
25+8(x-2)=10x
25+8x-16=10x
9=2x
x=4.5
therefore ans =4.5km option 5

Like? Yes (2) | No (1)  

khushboo goenka   10 years AGO

4.5 km=45 rs
so, 45-25=20rs
mns he travels 2+2.5=4.5km

Like? Yes (1) | No   

sompon temtheerakij   10 years AGO

Let A = Total length of journey
25+8(A-2) = 10A
2A = 9
A = 4.5

Like? Yes (1) | No   

CHANDAN KUMAR   10 years AGO

(2+x)*10=(25+8x)
20+10x=25+8x
x=5/2=2.5
total distance=2+2.5=4.5

Like? Yes (1) | No   

Dolly   10 years AGO

If x kms is required distance, then
10x= 25+8*(x-2)
2x=9
x=4.5 kms

Like? Yes (1) | No   

jitendra   10 years AGO

(25+8*x)/(2+x)=10
x=2.5
means x km he is going after 2 km so tptal distance is
=x+2
=2.5+2
=4.5

Like? Yes (1) | No   

Gitanjali K   10 years AGO

45/4.5=10 rs

Like? Yes (1) | No   

pallavi kumbhar   10 years AGO

let length of journey=x

so, 10x=25+8(x-2)
by solving this equ. we get x=4.5

Like? Yes (1) | No   

hirenwaghela    10 years AGO

First 2 km➡ 25
Next 2.5 km➡ (8*2.5)➡ 20

Total distance equal to 4.5 &
Total amount equal to 45 ₹.
Average is 10₹.

Like? Yes (1) | No   

Aparna Bhattacharya   10 years AGO

Let the total length of journey is x km/hr.
From the above problem we get,
[25+(x-2)*8]/10=x
25+8x-16=10x
-2x=-9
X=4.5
Total length of journey will be 4.5 km/hr
Option : 5

Like? Yes (1) | No   

A M ANKIT KALLURAYA   10 years AGO

(25+8x)/(2+x)=10
=>x=2.5
total distance travelled =2+x=4.5

Like? Yes (1) | No   

alamuri vijaya sekhar reddy   10 years AGO

(10x - 25)/8 = x-2 --> x= 4.5

Like? Yes (1) | No   

v pavan   10 years AGO

25+16+4
=45/4.5=10 per km

Like? Yes (1) | No   

b.subbarao   10 years AGO

let the total journey distance in the auto be = x km.,first 2 km. fare= Rs.25, for every another 1 km.journey fare= Rs.8,so total journey fare= Rs.{25+(x-2)8} ,average fare rate per 1 km.=.{25+(x-2)8}/x=10, 25+ 8 x -16= 10x,2x=25-16=9; x=9/2 = 4.5, The total journey= 4.5 km.

Like? Yes (1) | No   

Sandeep Kumar   10 years AGO

25+8 * 2.5 = 45 i.e 45/4.5 = 10.

Like? Yes (1) | No   

amit kumar   10 years AGO

25+8x= 20+10x
X=2.5
Total distance = 2.5+2
Which is 4.5

Like? Yes (1) | No   

Ankit Pandey   10 years AGO

rate for 4.5 kms. = 25+8+8+0.5*8 = 41+4 = 45 Rs.
Which will give the average of 10 Rs for each Km.

Like? Yes (1) | No   

PAWAN KUMAR   10 years AGO

For 4.5 km, fare will be:
for first 2km--> Rs.25
for next 2.5 km --> 2.5*8 --> Rs.20
Therefore average fare = (20+25)/4.5 = Rs 10/km. Ans.

Like? Yes (1) | No   

Paras Jain   10 years AGO

(25+8x)/(2+x) = 10
=> x=2.5
thus, total journey = 2 + 2.5 = 4.5 km Ans.

Like? Yes (1) | No   

karthik hariharan   10 years AGO

option 5 is probability

Like? Yes (1) | No   

SHAIK.KARIMULLA   10 years AGO

first 2 kms=25
next 2 kms=16
next 0.5 km=4
total=45/4.5=10

Like? Yes (1) | No   

JUHI RAI   10 years AGO

suppse total length=x+2
10=x*8+25/x+2
x=2.5
x+2=4.5

Like? Yes (1) | No   

guru   10 years AGO

let the additional distance traveled be x km
Total distance traveled=(2+x)km
Total fare= (25+8x)Rs.
The average fare is 10Rs.
So (25+8x) / (2+x)=10
25+8x=20+10
x=2.5
So the total distance traveled=2+x=4.5 km

Like? Yes (1) | No   

swarupa nuggu   10 years AGO

Fhjn

Like? Yes (1) | No   

jyotsna kumari   10 years AGO

N=total number of km;

(25+8(N-2))/N=10
BY SOLVING THE EQUATION N=4.5

Like? Yes (1) | No   

Devendra Marghade   10 years AGO

If 'x+2' is total km or length of journey.
(25+ 8x)/(2+x) =10
x=2.5
So length of journey=2+2.5=4.5

Like? Yes (1) | No   

Pradyumna K S   10 years AGO

Let x+2 km be the distance travelled in auto.For first two km.rate is 25 and for next rate is 8. Therefore the amount paid per kilometer is given by,
(25+8x)/(2+x)=10
x+2=4.5km
And hence the correct option is(5)4.5km

Like? Yes (1) | No   

venkatakoteswararaolingisetty   10 years AGO

Reason:for 2kms - 25/-
after for 1km = 8/-
for 100mts=0.80
for 4.5km=25+16+4=45

Like? Yes (1) | No   

SWETHA BAPANAH K S   10 years AGO

First 2km-->Rs.25/-
let the Distance travelled after this 2km be xkm
Given:Avg=10==>
(25+8x)/(2+x)=10;
Solving This we get, x=2.5km
Therefore,Total distance for which avg is 10 is 2+x=2+2.5=4.5km
Ans:4.5km

Like? Yes (1) | No   

vignesh   10 years AGO

4 km = 41 rupees
next 0.5 km = 4rs
total 45 rs and 4.5 . avg becomes 10 rs

Like? Yes (1) | No   

Shreeom Singh   10 years AGO

avg wouid be 10.
thus
10=(25+8x)/(2+x)
x=2.5
hence total length=2+2.5=4.5

Like? Yes (1) | No   

arush gupta   10 years AGO

(25 +8x)/(2+x) = 10 solvng this we will get x=2.5 therefore total distance travel = 2+2.5=4.5 Ans.

Like? Yes (1) | No   

Sanu Panji   10 years AGO

10x=25+(x-2)*8
or, x= 4.5 km

Like? Yes (2) | No (2)  

Akhil Malhotra   10 years AGO

Let the distance which the avg fare is 10rs/km be x
Actual fare will be: 25+8(x-2)
This must be equal to 10x
Equating terms
10x=25+8(x-2)
2x=9
x=4.5
Hence the distance is 4.5 km

Like? Yes (1) | No (1)  

Sravanthi   10 years AGO

(25+8(x-2))/x=10
x=4.5
where x is total length of journey

Like? Yes (2) | No (2)  

Abhik Das   10 years AGO

using option,we for 1st 2 km 25/- fixed and for next 2.5 km the fare required=(2.5*8)=20/-,so the total fare is=(25+20)=45 & the total journey is=(2+2.5)=4.5 km so the average is=(45/4.5)=10/-

Like? Yes (2) | No (2)  

priti sagar   10 years AGO

(25+8*x)/x+2=10
=25+8x=10x+20
=5/2=x
total distance=2+2.5
=4.5km

Like? Yes (2) | No (2)  

Tark Patel   10 years AGO

answer is 4.5 km

Finding average for 4.5 km

( 25 + 20 ) / 4.5 = 45 / 4.5 = 10Rs.

so answer is 4.5 km

Like? Yes (1) | No (1)  

Anjali   10 years AGO

25+(x-2)8=10x
x=4.5 Ans

Like? Yes (1) | No (1)  

Ashwin Dinesh   10 years AGO

[25+8+8+4]/4.5 = 10

Like? Yes (1) | No (1)  

anuj gupta   10 years AGO

2km+1km+1km+.5km=4.5Km
-------------------------------
25rs+8rs + 8rs + 4rs=45rs

So Avg=45/4.5=10

Total Length is 4.4km.

Like? Yes (1) | No (1)  

Anubhav jain   10 years AGO

4.5

Like? Yes (1) | No (1)  

gaurav garg   10 years AGO

4.5*10=45 rs
First 2 km=25 rs
Next 2.5 km=2.5*8=20 rs
So total = 45 rs

Like? Yes (1) | No (1)  

Ajinkya Kulkarni   10 years AGO

25+8(x-2)=10x

X=4.5

Like? Yes (1) | No (1)  

Saravanakumar   10 years AGO

let the total distance = x.
therefore,
25+(x-2)*8=10x
2x=9
ans : x=4.5

Like? Yes (1) | No (1)  

pappu kumar priye   10 years AGO

4.5-2=2.5
2.5*8=20
(20+25)/4.5=10

Like? Yes (1) | No (1)  

Daivashala   10 years AGO

no

Like? Yes (1) | No (1)  

Ishan Pushkarna   10 years AGO

Ans is 5) 4.5 KM
Taking option 5
First 2Km will COst = Rs 25
Then after that another 2KM will cost Rs 16
Rest remains 0.5KM so if 1KM costs Rs 8 then 0.5km will cost Rs 4
So by adding up total Cost becomes 45 (25+16+4=45).
the distance travelled is 4.5km
Therefore Average Cost of 1km becomes 45/4.5= Rs 10

Like? Yes (1) | No (1)  

Mithun Kumar Kesari   10 years AGO

(25+8*x)/(2+x)=10
x=2.5
so total distance= 2+ 2.5= 4.5 km

Like? Yes (1) | No (1)  

Vinay Sipani    10 years AGO

Let total distance travelled = x
Total cost = 25 + 8(x - 2)
(x - 2) because the first 2 kms are not considered for Rs 25

=> Average cost = [ 25 + 8(x - 2) ] / x

=> [ 8x + 9 ] / x = 10
=> x = 4.5 km

Like? Yes (1) | No (2)  

MRITUNJAY   10 years AGO

first 2 km =25
remaining 2.5=2.5*8=20
total fair=45
total distance=4.5
average 10
so distance covered is 4.5
5 is the answer

Like? Yes (1) | No (2)  

niraj   10 years AGO

25+16+4/4.5=4.5

Like? Yes (1) | No (2)  

05 Jan 2015 Sequence

What is the next number of the following sequence
3, 2, 5, 6, 7, 12, 9, ..... ?

OPtion

1) 15
2) 12
3) 20
4) 11
5) 30
6) 13
7) 42
8) 25
9) 30
10) 24

Solution

1+2 = 3
1*2 = 2
2+3 = 5
2*3 = 6
3+4 = 7
3*4 = 12
4+5 = 9
Similarly
4*5 = 20

Option 3)

Correct Option: 3 Best Solution (79)

Anand Dwivedi   10 years AGO

Series like :
3,4,7,9 : Diff between number is 2

next series 2,6,12 : in first two number diff is 4 another last two no diff is 6 means . so next term should be 8

So 12+8=20

Like? Yes (7) | No (2)  

Jaspalsingh Parmar   10 years AGO

The even digits are increasing by difference of 4,6,8.......
i.e. 2,6,12,......
so 12+8=20
so option 3 is correct simple

Like? Yes (3) | No (1)  

Supriya Mondal   10 years AGO

Difference between 1st number and 3rd number=2
Difference between 3rd number and 5th number=2
Difference between 5th number and 7th number=2

Difference between 2nd and 4th number is=4
Difference between 4th and 6th number is=(4+2)=6
so,difference between 6th and 8th number will be=(6+2)=8
so, answer will be (12+8)=20
so, option 3)20 is the right answer

Like? Yes (4) | No (2)  

SAYAN CHATTERJEE   10 years AGO

two series: 3,5,7,9
& 2, (2+4=6), (6+6=12)
so next will be 12+8= 20 (3)

Like? Yes (1) | No   

Sravanthi   10 years AGO

2 6 12
6-2=4
12-6=6
x-12=8
ans is 20

Like? Yes (3) | No (2)  

Surit Datta   10 years AGO

we divide the series into 2 parts
1st part:- 3,5,7,9....
2nd part "- 2,6,12,..
so the number after 9 will the next number of the 2nd series.
whose difference is like 4 then 6 then 8 ....
so the next number is 12+8 = 20
So option 3
That's it.

Like? Yes (3) | No (2)  

Pradyumna K S   10 years AGO

3,2, 5, 6, 7, 12, 9, ...
3,1(1+1),3+2,2(2+1),5+2,3(3+1),7+2,4(4+1)
Therefore required Term is 20

Like? Yes (3) | No (2)  

sunita chanda   10 years AGO

3,5,7,9 are odd nos.
2+4=6
6+6=12
12+8=20

Like? Yes (1) | No   

Rajkumar Singh   10 years AGO

2+4=6
6+6=12
12+8=20

Like? Yes (1) | No   

Nupur   10 years AGO

Two different series are running parallel

3,5,7,9....
2,6,12,20....

Like? Yes (1) | No   

souraj sadhukhan   10 years AGO

odd positions are increasing with the odd numbers.even positions are incresng 4,6,8,.. like ths.

Like? Yes (1) | No   

asha   10 years AGO

3,2,5,6,7,12,9

take sequence from first number i.e., 3 and leave one number so that it will be in odd numbers
3,_,5,_,7,_9
now take second number sequence from 2
they are in the form of even number difference
2-6=4
6-12=6
12-x=8
so x=12+8
x=20

Like? Yes (1) | No   

Sachin   10 years AGO

First Alter net numbers are on mean difference of 2 ,,and second alternet numbers have a mean difference of 4+n where n=(0,1......n)

Like? Yes (1) | No   

kaladhar   10 years AGO

in order leaving number of count

Like? Yes (1) | No   

murugan   10 years AGO

add 4,6,8 so get 20

Like? Yes (1) | No   

APPIKONDA SANTOSH NAIDU   10 years AGO

20

Like? Yes (1) | No   

saurabh kumar ojha   10 years AGO

odd numbers=3,5,7,9
even numbers=2,6,12,?
we can see that
3+2=5+1=6
6+5=11+1=12
so,
12+7=19+1=20
so the answer is 20

Like? Yes (1) | No   

JUHI RAI   10 years AGO

alternate odd no n diffrcne is 2 andd alternate even no n in incrasing order +4.+6+8

Like? Yes (1) | No   

anupriya sinha   10 years AGO

answer 20

Like? Yes (1) | No   

Abhishek Singh   10 years AGO

diff is 8

Like? Yes (1) | No   

guru   10 years AGO

3,5,7,9.. are the consecutive odd numbers.
2+4=6
6+6=12
So, 12+8=20
Therefore the next number in 3,2,5,6,7,12,9, is 20.

Like? Yes (1) | No   

swarupa nuggu   10 years AGO

Fhh

Like? Yes (1) | No   

sureshbhalaji   10 years AGO

difference between 1 and 3 rd term is 2..then 2nd 4 th term is 4 ..3 nd 5th term is 2 ..4 th and 6 th term is 6 ...so my answer is 12+8=20

Like? Yes (1) | No   

A M ANKIT KALLURAYA   10 years AGO

2+4=6
6+6=12
12+8=20

Like? Yes (1) | No   

Neha Agarwal   10 years AGO

2+4=6,6+6=12,12+8=20

Like? Yes (1) | No   

pallavi kumbhar   10 years AGO

3+2=5
5+2=7
7+2=9 this series is for odd position
now for even position.....
2+4=6
6+6=12
12+8=20

Like? Yes (1) | No   

annad   10 years AGO

12+8

Like? Yes (1) | No   

Arijit Poddar   10 years AGO

6-2=4
12-6=6
So the next difference will be 8.
the next number is (12+8) = 20.

Like? Yes (1) | No   

KUHELI ROY   10 years AGO

2+4=6,6+6=12.Therefore,the next number is 12+8=20.

Like? Yes (1) | No   

ganesh babu   10 years AGO

3, 3+2,5+2,7+2,..
2,2+4,6+6,12+8,...

3, 5, 7, 9
2, 6, 12, 20,30

Like? Yes (1) | No   

Meera R   10 years AGO

3,___,5,___,7,___9,___ (odd numbers)
other given numbers are 2,6,12
6=(5-1)+2 where 5 and 2 are given
12=(7-1)+6
so (9-1)+12=20

Like? Yes (1) | No   

RAVI KUMAR   10 years AGO

odd terms 3+2=5
5+2=7,7+2=9
even
2+4=6,6+6=12
12+8=20
ans==20

Like? Yes (1) | No   

ANAND.K   10 years AGO

In the sequence, odd numbers are In order and even numbers are arranged in some order like ,2 omitting next number 4,then 6 then omitting in between two even numbers,hence when we omit three ewn numbers after 12,it will be 20

Like? Yes (1) | No   

Sanu Panji   10 years AGO

12+8

Like? Yes (1) | No   

Yuvaraju D   10 years AGO

from the series
3,5,7,9...
2,6,12,20......

Like? Yes (1) | No   

SWETHA BAPANAH K S   10 years AGO

3,2,5,6,7,12,9,?
Divide the series into parts as follows.
a. 3,5,7,9
b. 2,6,12,?
In the First series +2 is added successively.
In the Second Second series==>
2+4=6;
6+6=12;
12+8=20;
Here add the successive even numbers.

Like? Yes (1) | No   

Nikita Mulchandani   10 years AGO

Since,2+4=6
and 6+6=12
Therefore,12+8=20

Like? Yes (1) | No   

CHANDAN KUMAR   10 years AGO

3+2=5
5+2=7
7+2=9
2+4=6
6+6=12
12+8=20

Like? Yes (1) | No   

ramakrishnateja   10 years AGO

the given series is 3,2,5,6,7,12,9.....
the next number is 20. As alternately in the series 2+4=6,6+6=12,12+8=20.

Like? Yes (1) | No   

Chandra chur anand   10 years AGO

alternate it increase by
2 then 2+4=6 then 6+6=12 then 12+8=20 ans..

Like? Yes (1) | No   

khushboo goenka   10 years AGO

3 thn 5 thn 7
and 2nd series is 2 , 2+4,6+6,12+8

Like? Yes (1) | No   

sonu   10 years AGO

3, 2, 5, 6, 7, 12, 9, 20

it is the combination of two alternate series

series 1 : 3,5,7,9,11----> number added by 2
series 2 : 2,6,12,20 ----->number added are even no. series starting from 4 onwards

Like? Yes (1) | No   

pappu kumar priye   10 years AGO

2+4=6
6+6=12
12+8=20

Like? Yes (1) | No   

vignesh   10 years AGO

The alternate numbers are increasing in increasing multiple of two

Like? Yes (1) | No   

susanta   10 years AGO

2,6,12,20

Like? Yes (1) | No   

jayashree   10 years AGO

3+2=5,5+2=7,7+2=9
like wise take the alternate
2+4=6,6+6=12,12+8=20.

Like? Yes (1) | No   

shubham   10 years AGO

dedd

Like? Yes (1) | No   

Sandeep Kumar   10 years AGO

it is an order of +2 in alternate place (even places)

Like? Yes (1) | No   

Jamil Ahmed   10 years AGO

There are two alternate series. First 3, 5, 7, 9, ............ and the second 2, 6, 12, 20, 30. Hence 20 will be the next term.

Like? Yes (1) | No   

MRITUNJAY   10 years AGO

3,5,7,9....this is increasing with 2 each time
2,6,12....in this +4,+6,+8..
so the next number is 12+8=20.
3,2,5,6,7,12,9,20.that is 3rd is the answer

Like? Yes (1) | No (1)  

ABHINAV PUSHPAM   10 years AGO

Alternate odd number is increased by 2 and even by 4,6 then 8. So 20 is answer

Like? Yes (1) | No (1)  

Jay parmar   10 years AGO

odd digits are increasing with difference of 2
3,5,7,9....
even digit are increasing with difference of 4,6,8......
so 12+8=20
so option 3 is correct

Like? Yes (1) | No (1)  

Yekollu Muneeswar   10 years AGO

This is a combination of two series
odd position series: 3,5,7,9,...adding 2 to the previous term
even position series: 2,6,12,20,30,...adding 4 then increment with 2 to each term.

Like? Yes (2) | No (2)  

Tark Patel   10 years AGO

Two series are there...
3, 2, 5, 6, 7, 12, 9, .....
1st is -> 3 , ... , 5 , ... , 7 , ... , 9 , ...
2nd is -> ... , 2 , ... , 6 , ... , 12 , ... , ? (we have to find)

so in 2nd series pattern is n^2 + n
... , (1^2+1) , ... , (2^2+2) , ... , (3^2+3) , ... , (4^2+4) ,
so answer is 20.

Like? Yes (1) | No (1)  

satyam sharma   10 years AGO

3+2=5
5+2=7
7+2=9
2+4=6,
6+6=12
12+8=20
so correct option is 3

Like? Yes (1) | No (1)  

Meenakshi   10 years AGO

The following sequence consists of two series
3,_,5,_,7,_,9,_,11...(increase by 2)
2,_,6,_12,_,20(increase by even terms +4,+6,+8...)

The answer is:20

Like? Yes (1) | No (1)  

amit kumar   10 years AGO

2+4=6
6+6=12
12+8=20

Like? Yes (1) | No (1)  

BHASKAR MANDAL   10 years AGO

12+8 = 20

Like? Yes (1) | No (1)  

Md.Sultan Khichi   10 years AGO

The series is like this
3,5,7,9 and 2,(2+4)=6,(6+6)=12,(12+8)=20.
So series become 3,2,5,6,7,12,9,20
Ans 20

Like? Yes (1) | No (1)  

Satya B   10 years AGO

3,2,5,6,7,12,9, ?

it is an alternate series
3,5,7,9 is one series is formed by adding 2 to previous digits in the series and the second series is 2,6,12,... is formed by adding multiples of 2 from 4 to previous numbers in the series
2,2+4=6, 6+6=12,12+8=20

Like? Yes (1) | No (1)  

Anubhav jain   10 years AGO

ODD PLACE ARE ADD2
EVEN PLACE ARE ADD INC. 2
3+2 =5 5+2= 7
2+4= 6 6+6 =12

Like? Yes (1) | No (1)  

priti sagar   10 years AGO

there is 2 series here:
1st 3,5,7,9 where difference is 2.
2nd 2*1,2*3,2*6,2*10.where difference between multiplier is 2,3,4.....
so correct ans is 20 i.e c)20

Like? Yes (2) | No (2)  

RAKESH   10 years AGO

(1+2), 1*2 , (2+3), 2*3, ..................., (4+5), 4*5

Like? Yes (1) | No (1)  

Rishikesh Ranjan   10 years AGO

20

Like? Yes (1) | No (1)  

PAWAN KUMAR   10 years AGO

The above series is two A.Ps.
In the first one,there is addition of 2.
In the second one, there is addition of AP.
i.e, 2+4 = 6
6+6 = 12
12+8 = 20. Ans.

Like? Yes (1) | No (1)  

Ajinkya Kulkarni   10 years AGO

Ans 20
Stop giving such faltu problems

Like? Yes (1) | No (1)  

varun Galar   10 years AGO

There are two series
3 5 7 9

6-2=4
12-6=6
20-12=8

above three has common diff. of 2

so the missing no is 20

Like? Yes (1) | No (1)  

kiran   10 years AGO

1st ,3rd,5th and 7 th numbers are general odd numbers...for even place numbers2,6,12...2 next even 4 missed then 6. 6's next even 8,10 missed...12....12's next 3 even numbers 14,16,18 missed...so answer is 20

Like? Yes (1) | No (1)  

Anjali   10 years AGO

two series
series 1: 3,5,7,9,...
series 2: 0+2=2
2+4=6
6+6=12
12+8=20 Ans

Like? Yes (1) | No (1)  

S.SHAFI   10 years AGO

given series 3, 2, 5, 6, 7, 12, 9..

Series at odd places: 3, 5, 7, 9
Series at evenplaces: 2, 6, 12, ?

2 + 4 --> 6

6 + 6 --> 12

12 + 8 --> 20

Like? Yes (1) | No (1)  

ayush bagga   10 years AGO

Here we have 2 series 1-3,5,7,9 & 2 series-2,6,12
Now we can see that the next no. will be from 2nd series bcoz the no.s are alternate as first from 1st sreies then 2nd series.
in the second series the gap between first 2 no.s is 4 and next 2 no.s is 6 so this is also forming an AP so the next gap should be 8 and the no. beccomes 20 and after that from the first series the no. become 11.

Like? Yes (1) | No (1)  

abhishek   10 years AGO

3,5,7,9,11,13,.....
2,6,12,20,30,42,...

Like? Yes (1) | No (1)  

Jayanta Dutta   10 years AGO

2+4=6
6+6=12
12+8=20

Like? Yes (1) | No (1)  

Mithun Kumar Kesari   10 years AGO

20

Like? Yes (1) | No (1)  

shree   10 years AGO

2+4=6, 6+6=12, 12+8=20

Like? Yes (1) | No (1)  

MRITUNJAY KUMAR   10 years AGO

Option)3

Like? Yes (1) | No (1)  

GUDDETI ANUPAMA   10 years AGO

2+4=6,6+6=12,12+8=20

Like? Yes (1) | No (1)  

Vinay Sipani    10 years AGO

There is alternate sequence here

Consider odd terms i.e.1st, 3rd , 5th, ... terms
=> (3 , 5 , 7 , 9 ,...) which is a sequence with common difference 2

Consider the even terms i.e. 2nd , 4th , 6th ... terms
=> 2 , 6 , 12 ...
This is a sequence of sum of even numbers
2 , 2 + 4 , 2 + 4 + 6

So next term = 2 + 4 + 6 + 8 = 20

Like? Yes (1) | No (2)  

Ashwin Dinesh   10 years AGO

guessed

Like? Yes (1) | No (2)  

02 Jan 2015 Time and Distance

A man riding a cycle at 12 km/hr can reach a village in 9/2 hours. If he is delayed by 3/2 hours at the start, then in order to reach his destination in time, he should ride with a speed of

OPtion

1) 15 km/hr
2) 16 km/hr
3) 17 km/hr
4) 18 km/hr
5) 19 km/hr
6) 20 km/hr
7) 21 km/hr
8) 22 km/hr
9) 24 km/hr
10)None of these

Solution

Distance = (Speed*Time)
= (12* 9/2) km = 54 km
Now, distance = 54 km and time taken = 3 hrs
Speed = Distance/Time
54/3 km/hr
18 km/hr

Option 4)

Correct Option: 4 Best Solution (79)

Supriya Mondal   10 years AGO

Speed of the man is 12km/hr and he takes 9/2 hr i.e 4.5 hr.
So total distance is=12*4.5=54km
Due to delay he looses 3/2hr i.e 1.5 hr.
So time in hand is=(4.5-1.5)=3 hr to reach the destination.
So speed needed to reach the destination in time=(54/3)=18km/hr.
So option 4)18 hr is the right answer

Like? Yes (9) | No (5)  

P.Pandeeswari   10 years AGO

distance=12*9/2 =54,
speed=54/(9/2-3/2) == 18 km/hr

Like? Yes (8) | No (4)  

Saranjit Singh   10 years AGO

Distance = 12*9/2= 54 kms
speed for reaching destination in (9/2-3/2=3 hrs) = 54/3= 18 kmph

Like? Yes (2) | No   

SAYAN CHATTERJEE   10 years AGO

distance = s= v*t= 12*9/2=54 km
now delaying by 3/2 hours he has (9/2-3/2)=3 hours time
so. v= s/t'
= 54/3
= 18 km/hr (4)

Like? Yes (1) | No   

Surit Datta   10 years AGO

According to the question
A man riding a cycle at 12 km/hr can reach a village in 9/2 hours
So the total distance covered is (12*9)/2
which is 54 km
If he is delayed by 3/2 hours at the start
so distance covered by (9/2-3/2) = 3 hour is 54 km
So in order to reach his destination in time
he should ride with a speed 54/3 = 18 km/hr
So option 4
That's it.

Like? Yes (5) | No (4)  

Sagar Jadhav   10 years AGO

speed=12kph
time=4.5hr
so, dist=12*4.5 = 54km
and delay is 1.5 hr
means he has to reach in 3 hrs
so new speed is 54/3 = 18kph

Like? Yes (1) | No   

Abhishek Porwal   10 years AGO

Distance=12*9/2 = 54,
speed=54/(9/2-3/2) = 18 km/hr

Like? Yes (1) | No   

alamuri vijaya sekhar reddy   10 years AGO

his journey distance = 12*9/2 = 54 km

new journey time after time reduction = 9/2 - 3/2 = 3 hours

his new speed = 54/3 = 18 km/hr

Like? Yes (1) | No   

K.NagaSugunaManasa   10 years AGO

distance=speed*time
distance=x;
time=9/2;
speed=12km/hr
so x=12*(9/2)=54
now x=second speed*second time
now 54=s*(9/2-3/2)
s=18km/hr
so option is 4

Like? Yes (1) | No   

Lakhan Nagrale    10 years AGO

12 *9/2=54
in 4.5 hrs he goes 54 km
after 3/2 i.e 1.5 hr delay he has to cover same distance in
4.5-1.5=3 hours
thus 54/3=18 km/hr

Like? Yes (1) | No   

Mithun Kumar Kesari   10 years AGO

18 km/hr

Like? Yes (1) | No   

Yuvaraj   10 years AGO

Total distance to be traveled at 9/2 hours = 12*(9/2)
= 54 kms

9/2 = 4.5 hours.. 3/2 = 1.5 hours.
Time need to travel same distance is 4.5-1.5 = 3 hrs.

Distance to travel for 3 hours for time = 54/3
= 18km/hr

Like? Yes (1) | No   

kiran nekkanti   10 years AGO

Total distance to be travelled is 54 km
he is delayed by 1.5 hours
so,he has to travel to destination in 3hours
speed=distance/time=54/3=18

Like? Yes (1) | No   

Sahil Thakral   10 years AGO

from speed = 12km/hr and time = 4.5hr, distance = sp*t = 54km
Now dis=54 km/hr, time = 9/2-3/2hr = 6/2hr = 3hr ,
so speed = dis/time = 54/3 = 18km/hr

Like? Yes (1) | No   

APPIKONDA SANTOSH NAIDU   10 years AGO

18km/hr

Like? Yes (1) | No   

guru   10 years AGO

Total distance traveled= 12x9/2= 54 km
If he is delayed by 3/2 hours at the start, then he has to cover the distance in 9/2-3/2=6/2=3 hours.
So the speed he needs to travel at = 54/3=18 km/hr

Like? Yes (1) | No   

A.Vignesh Guru   10 years AGO

distance=12* 9/2 =54Km
actual speed= 54 / ( (9/2)-(3/2) ) =18 km/hr

Like? Yes (1) | No   

Abhishek Singh   10 years AGO

becuase distance to cover is 54 km and he need to cover it in 3 hr then speed should be 18 km/hr

Like? Yes (1) | No   

jatin arora   10 years AGO

12*9/2*1/3

Like? Yes (1) | No   

JUHI RAI   10 years AGO

D=12*9/2=54km
new speed=54/3=18km/hr

Like? Yes (1) | No   

Sravanthi   10 years AGO

d=s*t

Like? Yes (1) | No   

khushboo goenka   10 years AGO

distance is 12*9/2= 54 km'
so new speed = 9/2-3/2=3
so speed will become 54/3

Like? Yes (1) | No   

pallavi kumbhar   10 years AGO

Total distance he have to travel=12*4.5=54km
speed to reach within 3 hour=54/3=18km/hr

Like? Yes (1) | No   

niraj   10 years AGO

3*18=12*9/2

Like? Yes (1) | No   

komal kumar bandi   10 years AGO

9/2*12=54
9/2-3/2*18=54

Like? Yes (1) | No   

b.subbarao   10 years AGO

cycle speed=12 km/hr, time taken for reach the destination=9/2 hrs,destination distance=9/2*12=54 km. after delaying 3/2 hrs, the remaining time is 3 hrs. so the speed of the cycle=d/t=54/3=18 km/hr

Like? Yes (1) | No   

siddharth prakash singh   10 years AGO

distance=speed*time
so, D=12*(9/2)=54km
delayed by 3/2 hr means remaining time = 3 hr.
required speed= 54/3= 18kmph

Like? Yes (1) | No   

THUMMALA VINEESHA   10 years AGO

dis=sp*time=12*(9/2)=54 km
time=tot-delay=(9/2)-(3/2)=3 hrs
sp=d/t=54/3=18 km/hr

Like? Yes (1) | No   

jitendra kumar   10 years AGO

distance=speed*time
distance is constant here
s1*t1=s2*t2
s1=12 t1=9/2 t2=9/2-3/2=3
s2=18km/hr

Like? Yes (1) | No   

Asim Dinda   10 years AGO

(12*9/2)/(9/2-3/2)=18

Like? Yes (1) | No   

Rishabh   10 years AGO

12 km/h* 9/2 hr is total distance which is 54 km.now divided by remaining time which is 3 hr so 54/3=18km/hr ans.

Like? Yes (1) | No   

susanta   10 years AGO

s=v*t
=12*9/2
=54
t=9/2-3/2
=3
now, 54=v*3
v=18 km/hr

Like? Yes (1) | No   

Gaurav Sharan   10 years AGO

dist = 12*(9/2)= 54
or, 54= v*(4.5-1.5)
v= 18

Like? Yes (1) | No   

Harshabh Srivastava   10 years AGO

this is answer

Like? Yes (1) | No   

VISHNU   10 years AGO

Distance = speed x time
here,
speed = 12km/hr and time = 9/2hrs

so D = 12 x 9/2
= 54
delay of 3/2 which means new time is 9/2 - 3/2 = 3

54 = speed x 3
speed = 54/3
= 18 km/hr

Like? Yes (1) | No   

abhishek   10 years AGO

dist=12*9/2
=54
now time=9/2-3/2
=6/2=3Hrs
speed=54/3
=18Km/hr.

Like? Yes (1) | No   

ABHAS TIWARI   10 years AGO

the distance to be covered = 12 * 9/2 = 54 km
time available = 9/2 - 3/2 = 3 hrs
therefore the required speed should be = 54/3 = 18kmph

Like? Yes (1) | No   

T.Aravinth kumar   10 years AGO

d=4.5*12=54km
speed=54/(4.5-1.5)=18km/hrs

Like? Yes (1) | No   

Pankaj Kumar Mishra   10 years AGO

A/Q, Speed = 12 km/hr
Time = 9/2 hrs
So, Distance = Speed * Time
=> Distance = 12 * 9/2 = 54 km

Again,
Since he is 3/2 hrs delayed,
So he has 9/2 - 3/2 hrs = 3 hrs to reach destination.

So, Required Speed = Distance / Time
= 54 / 3 km/hr
= 18 km/hr
= Option (4) Answer

Like? Yes (1) | No   

Chandra chur anand   10 years AGO

time delayed =9/2-3/2=3hr
he has to complete 54 km in 3 hr.
so his speed will be s*3=54
s=18km/hr
ans...

Like? Yes (1) | No   

Nagesh   10 years AGO

12 km/hr = D/(9/2).
D = 54 km

new Speed = 54/(9/2-3/2) = 18km/hr

Like? Yes (1) | No   

Abdul kadir khan   10 years AGO

18 km/hr

Like? Yes (1) | No   

lavanya   10 years AGO

distance=12*9/2 =54, speed=54/(9/2-3/2) == 18 km/hr

Like? Yes (1) | No   

aman   10 years AGO

from- dis = time*speed

dis = 12*9/2 = 54km
then
time req = 9/2-3/2 = 3hr
speed = 54/3 = 18km/hr

Like? Yes (1) | No   

Vinay Sipani    10 years AGO

Speed = 12 kmph in 9/2 = 4.5 hrs
=> distance = 4.5 * 12 = 54 km

He delays 1.5 hrs
Remaining time = 3 hrs
=> Required speed = 54 / 3 = 18 kmph

Like? Yes (2) | No (2)  

Md.Sultan Khichi   10 years AGO

D=12*9/2=54 km
Time remaining =9/2-3/2=3 hr
Speed =d/t=54/3=18
Ans ob 4.

Like? Yes (1) | No (1)  

Akhil Malhotra   10 years AGO

Speed of man=12kmph
Time taken=9/2 hrs=4.5 hrs
Distance=12*4.5=54km

Time delay=3/2 hrs=1.5 hrs
Time left=4.5-1.5=3 hrs
Distance =54km
So new speed= 54/3= 18kmph

Like? Yes (6) | No (6)  

Ashwin Dinesh   10 years AGO

using v = d/t
d=54, t=3 then v = 18
which is option 4)

Like? Yes (1) | No (1)  

A M ANKIT KALLURAYA   10 years AGO

s=12kmph
t=9/2hr d=st=12*9/2=54km
d=s(t-3/2)
54=s(9/2-3/2)
=>s=18kmph

Like? Yes (1) | No (1)  

MRITUNJAY KUMAR   10 years AGO

Option)4

Like? Yes (1) | No (1)  

RAKESH   10 years AGO

d = 12* 9/2 = 54 km

s = 54 / (9/2 -3/2) = 18 km/h

Like? Yes (1) | No (1)  

Pradyumna K S   10 years AGO

Let d km be the distance to be covered. Given that d km is covered within 9/2hr in the speed of 12 km. Then d=12*9/2km=54km. If he by delayed by 3/2hthen to reach by the time he should reach within 3hr.therefore required speed is 54/3kmph=18kmph 4th option

Like? Yes (4) | No (4)  

Aarti Galar   10 years AGO

Ans. is 18 km/hr
as we know that Speed = Distance/Time
=> Distance = Speed x Time Distance is same in both the cases therefore,
12 x 9/2 = s x 6/2
54 = s x 3
s = 18 km/hr

Like? Yes (1) | No (1)  

Sanu Panji   10 years AGO

distance = 12*9/2 =54 km
time = 9/2- 3/2 = 3 hr
speed = 54/3 = 18 km/hr

Like? Yes (2) | No (2)  

priti sagar   10 years AGO

total distance=12km/hr * 9/2hr
=54km
3/2 hr is passed so remaining time required to complete 54 km is 9/2hr-3/2hr=3hr
so,speed =54km/3hr
=18km/hr

Like? Yes (3) | No (3)  

NITHYA   10 years AGO

speed=dist/time

=12/9/2=54 km

he is delayed by 3/2. so he should take the time of (9/2-3/2=6/2)

actual speed= 54/6/2=18 km

Like? Yes (1) | No (1)  

ABHINAV PUSHPAM   10 years AGO

Distance= 9/2*12= 54 KM
So, time after 3/2 hrs of late tart wii be= 9/2- 3/2= 6/2= 3 hrs. i.e in 3hrs He has to travel 54 KM. So, now required time would be= 54/3= 18 km/hr. Hence option 4 is right

Like? Yes (1) | No (1)  

MRITUNJAY   10 years AGO

distance=12*9/2=54 km
time to cover distance after delay is 4.5-1.5=3 hr
speed to cover distance in 3 hrs=54/3=18km/hr
that is option 4.

Like? Yes (1) | No (1)  

Yekollu Muneeswar   10 years AGO

given, 12 km/hr*9/2hr= 54km

he delayed 3/2 hrs means he having 9/2hr-3/2hr=3hr time

54km in 3 hr means=> 54km/3hr=18km/hr

so option 4) 18km/hr

Like? Yes (2) | No (2)  

Ajinkya Kulkarni   10 years AGO

54km
Time req 3hr
So speed 54/3=18

Like? Yes (2) | No (2)  

Faisal JAffry   10 years AGO

Total distance= 12*9/2;
= 54 Km;
Time Delayed=3/2;
Therfore total time= 9/2-3/2=3 hrs;
Hence Speed = 54/3==> 18 km/hr;

Like? Yes (1) | No (1)  

viveka subraya bhatta M.S   10 years AGO

distance =12*9/2 =54 km
due to delay, time left =9/2-3/2 = 3 hours
required speed = 54/3 =18 km/hours

Like? Yes (1) | No (1)  

PAWAN KUMAR   10 years AGO

Distance = 12*9/2 = 54km.
Time of travel = 3 hours
Therefore, speed = 54/3 = 18 kmph. Ans.

Like? Yes (1) | No (1)  

pappu kumar priye   10 years AGO

total distance=(12*9)/2=54 km
remaining time after delay=9/2-3/2=3hrs
so speed =54/3=18km/hr

Like? Yes (1) | No (1)  

RAVI KUMAR   10 years AGO

total distance = 9/2*12=54
time remaining = 9/2-3/2= 3
req speed = 54/3
= 18 km/hr

Like? Yes (1) | No (1)  

Sheetal Ghutukade   10 years AGO

the distance is 54km. so if we are starting 3/2 hrs late then we have only 3hrs in hand so speed will be 54/3=18km/hr

Like? Yes (2) | No (2)  

BHASKAR MANDAL   10 years AGO

12*4.5 = x * (4.5-1.5 )
=> x = 18

Like? Yes (1) | No (1)  

Satya B   10 years AGO

12 km/hr time to reach 9/2 hrs
distance traveled= 12*9/2= 54 km
delayed by 3/2 hrs the remaining time left to reach on time is
9/2hrs - 3/2 hrs = 6/2 hrs
seed=distance/time
speed=54/(6/2)
=54*2/6
=18km/hr ans

Like? Yes (2) | No (2)  

jassi   10 years AGO

D=s*T

D=12*(9/2)=54

T=9/2-3/2=6/2

S=54/(6/2)=18km/h

Like? Yes (1) | No (1)  

Jagdish Joshi   10 years AGO

d=4.5 * 12 = 54 km
reduced time = 9/2- 3/2 = 3 hrs
s=54/3 = 18 km /hr

Like? Yes (1) | No (1)  

Ankit   10 years AGO

Distance=speed*time=12*(9/2)=54km
late by 3/2 hr so time left is 9/2-3/2=6/2=3 hrs
tehrefore, new speed will be distance/time=54/3=18km/hr

Like? Yes (1) | No (1)  

swarupa nuggu   10 years AGO

18

Like? Yes (1) | No (1)  

Dibakar Mandal   10 years AGO

D = 54km
s=54/3=18km/hr

Like? Yes (1) | No (1)  

ASHISH MITTAL   10 years AGO

distance=speed*time
distance= 12*9/2 =54km
now new time=(9/2) - (3/2) =3 hours
so new speed = 54/3 = 18 km/hr

Like? Yes (2) | No (2)  

vikram   10 years AGO

dist= speed *time
d=12*9/2=54kms
as his start was delayed by 3/2 hrs, then the remaining time to reach the destination in right time is 9/2-3/2= 6/2 hrs
now speed = distance /time
S=54/6/2=18Kmph.

Like? Yes (1) | No (1)  

Suganya   10 years AGO

s=12km/hr
t=4.5hrs.
d=128*4.5=54km
4.5-1.5=3
so speed =54/3=18
speed is 18km/hr

Like? Yes (1) | No (1)  

Raghwendra Sharan   10 years AGO

total distance covered in first scenrio is
12*4.5 = 54KM
if delayed by 1.5 hrs, then need to cover 54 KM in 3 hrs
so the speed should be 544/3 = 18KM/HR

Like? Yes (1) | No (1)  

LOKESH KUMAR   10 years AGO

Speed of cycle=12kmph
Time man takes=4.5hrs
Total distance man covers
=12kmph*4.5hrs
=54kms
Man is delayed by 1.5hrs.
Remaining time he has
=4.5-1.5hrs.
=3hrs.
So, Speed needed to cover the same distance in 3hrs.
Speed=54km/3hrs.
=18kmph.

Like? Yes (1) | No (1)  

sravani   10 years AGO

Giveen speed is 12 Kmph
Time taken is 9/2hr
so, dist is 12*9/2=54km
time tobe taken is 9/2-3/2=3hr
dist=54Km
speed =54/3=18Kmph

Like? Yes (1) | No (2)  

01 Jan 2015 Tank contains

A tank contains 1 litre of water. Water is falling drop wise from the tank. Radius of the drop is 2 mm. If every drop takes 1 sec. to fall from the tank, then the total time required to make the tank empty is

OPtion

1) 8h 16m 25s
2) 8h 17m 37s
3) 8h 15m 23s
4) 8h 10m 21s
5) 8h 3m 24s
6) 8h 13m 35s
7) 8h 11m 28s
8) 8h 22m 56s
9) 8h 19m 34s
10) 8h 23m 23s

Solution

Total amount of water = 1 litre = 1000000 cubic mm
Volume of 1 drop of water = 4*π*r*r*r/3 = 4*π*2*2*2/3 cubic mm and this drop takes 1 sec to fall from the tank
Hence total time taken = 1000000/(32*π/3) sec.
= 29856.688 sec.
= 29856.688/3600 hours
= 8.2935244 h
= 8h 17m 37s

Option 2)

Correct Option: 2 Best Solution (33)

Surit Datta   10 years AGO

Total amount of water = 1 litre = 1000000 cubic mm
Volume of 1 drop of water = 4*π*r*r*r/3 = 4*π*2*2*2/3 cubic mm and this drop takes 1 sec to fall from the tank
Hence total time taken = 1000000/(32*π/3) sec.
= 29856.688 sec.
= 29856.688/3600 hours
= 8.2935244 h
= 8h 17m 37s
So option 2
That's it.

Like? Yes (4) | No (3)  

Supriya Mondal   10 years AGO

Given,total amount of water in tank = 1 litre = 1000000 cubic mm
Volume of 1 drop of water = 4*π*r^3/3 = 4*π*2^3/3 cubic mm and this drop takes 1 sec to fall from the tank
Hence total time taken = 1000000/(32*π/3) sec.
= 29841.55 sec.
= 29841.55/3600 hours
= 8.2893 h
= 8h 17m 37s
So option 2)8h 17m 37s is the correct answer

Like? Yes (3) | No (2)  

Shreya Banerjee   10 years AGO

Total amount of water = 1 litre = 1000000 cubic mm
Volume of 1 drop of water = 4*π*r*r*r/3 = 4*π*2*2*2/3 cubic mm and this drop takes 1 sec to fall from the tank
Hence total time taken = 1000000/(32*π/3) sec.
= 29856.688 sec.
= 29856.688/3600 hours
= 8.2935244 h
= 8h 17m 37s

Like? Yes (1) | No   

MRITUNJAY   10 years AGO

Volume of tank/volume of drop=no of drop
1000000*21/4*22*8=29830
approx 8hr 17 min 37sec

Like? Yes (1) | No   

madhusudhanreddy   10 years AGO

Total amount of water = 1 litre = 1000000 cubic mm
Volume of 1 drop of water = 4*π*r*r*r/3
= 4*π*2*2*2/3 cubic mm
and this drop takes 1 sec to fall from the tank
Hence total time taken = 1000000/(32*π/3) sec.
= 29856.688 sec.
= 29856.688/3600 hours
= 8.2935244 h
= 8h 17m 37s

Like? Yes (1) | No   

pallavi kumbhar   10 years AGO

volume of sphere = 4/3 (pi) r^3
=0.0334933...
total time required= 1000/0.033493=29856.68=29857 second
i.e. 8h 17m 37s

Like? Yes (1) | No   

payal vyas   10 years AGO

1 litre =1000000mm
1 litre=4*22*2^3(7*3)xN mm
where N is no of drops to empty the tank

N=29842(round fig.)
1 drop takes 1 sec
so 29842 takes 29842 sec
or 497.359 min
or 8.28931 hour
so 8 hours 17 min 37 s
option (2)

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Jigyasa Kumar   10 years AGO

29841.6 sec...

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b.subbarao   10 years AGO

volume of drop=4/3*22/7*2*2*2=704/21 , 1 liter voume=1000000 cubic mm ,time taken for the empty of the tank= 1000000/704/21=29829.54 sec.=8h 17m 37sec

Like? Yes (1) | No   

sai sindhu   10 years AGO

1 litre=10,00,000 cubic mm
volume of drop=4*3.14*(r^3)/3
1sec->4*3.14*(r^3)/3
?->10,00,000
which is equal to 8h 17m37sec

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ABHINAV PUSHPAM   10 years AGO

Answer is 2

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Faisal JAffry   10 years AGO

Water in tank=1000cm3;
Radius of drop of water= .2 cm;
Vol. of 1 drop= 4/3 * 3.14 * .008 ->> = .03349 cm3;
So,
.03349 takes one second,
therfore 1000cm3 will take >>
1000/.03349 sec
29856.687 sec
THAT IS 8h 17m 37s
Option = 2

Like? Yes (1) | No   

Swagatam Kumar Das   10 years AGO

Total amount of water = 1 litre = 1000000 cubic mm
Volume of 1 drop of water = 4*π*r*r*r/3 = 4*π*2*2*2/3 cubic mm and this drop takes 1 sec to fall from the tank
Hence total time taken = 1000000/(32*π/3) sec.
= 29856.688 sec.
= 29856.688/3600 hours
= 8.2935244 h
= 8h 17m 37

Like? Yes (1) | No   

aishwarya   10 years AGO

1 litre= 1000000 cubic mm
total time required to make the tank empty is
= 1000000/(4/3*3.14*8)sec= 29857 sec= 8h 17m 37s....

Like? Yes (1) | No   

Sourabh Prasad   10 years AGO

1 litre= 1000000 cubic mm
Radius of the drop is 2 mm.and every drop takes 1 sec. to fall from the tank, then the to tal time required to make the tank empty is
= 1000000/(4/3*3.14*8)sec= 29857 sec= 8h 17m 37s....

Like? Yes (1) | No   

A M ANKIT KALLURAYA   10 years AGO

1 litre= 1000000 cubic mm
Radius of the drop is 2 mm.and every drop takes 1 sec. to fall from the tank, then the to tal time required to make the tank empty is
= 1000000/(4/3*3.14*8)sec= 29857 sec= 8h 17m 37s....

Like? Yes (1) | No   

Jaspalsingh Parmar   10 years AGO

I guess option 2

Like? Yes (1) | No   

Ajinkya Kulkarni   10 years AGO

Vol of drop=4πr^3/3=33.51*10^-9 m^3
=33.51*10^-6 lit


No of droplet in 1lit=29857

Time sec =29857 sec

Like? Yes (1) | No   

Narendra   10 years AGO

Total amount of water = 1 litre = 1000000 cubic mm
Volume of 1 drop of water = 4*π*r*r*r/3 = 4*π*2*2*2/3 cubic mm and this drop takes 1 sec to fall from the tank
Hence total time taken = 1000000/(32*π/3) sec.
= 29856.688 sec.
= 29856.688/3600 hours
= 8.2935244 h
= 8h 17m 37s

Like? Yes (1) | No   

Jay parmar   10 years AGO

option 2 is correct

Like? Yes (1) | No   

Sravanthi   10 years AGO

1 litre= 1000000 cubic mm
total time required is
1000000/(4/3* 3.14* 8)sec= 29857 sec= 8h 17m 37s

Like? Yes (3) | No (3)  

Abhishek Porwal   10 years AGO

Total amount of water = 1 litre = 1000000 cubic
mm
Volume of 1 drop of water = 4*π*r*r*r/3 =
4*π*2*2*2/3 cubic mm and this drop takes 1 sec
to fall from the tank
Hence total time taken = 1000000/(32*π/3) sec.
= 29856.688 sec.
= 29856.688/3600 hours
= 8.2935244 h
= 8h 17m 37s

Like? Yes (1) | No (1)  

Ravi Bhalani   10 years AGO

Like? Yes (1) | No (1)  

RAKESH   10 years AGO

vol of drop = 4/3 * 3.14 * (.2)^3 cm^3

reqd time = 1000 cm^3 / 4/3 * 3.14 * (.2)^3 cm^3 = 29856.688 sec

= 8h 17m 37s

Like? Yes (1) | No (1)  

Ashwin Dinesh   10 years AGO

guessed

Like? Yes (1) | No (1)  

Sanu Panji   10 years AGO

volume of one drop water
= (4/3)*pi*(2/10)^3 cc
= .033493 cc
total water = 1 litre = 1000 cc
so number of drops
= 1000/0.033493
= 29857
so time takes to make the tank empty is
= 29857 sec
= 8h 17m 37s

so option (2) is correct

Like? Yes (2) | No (2)  

P.Pandeeswari   10 years AGO

1 litre= 1000000 cubic mm
Radius of the drop is 2 mm.and every drop takes 1 sec. to fall from the tank, then the to tal time required to make the tank empty is
= 1000000/(4/3*3.14*8)sec= 29857 sec= 8h 17m 37s....Option 2)

Like? Yes (2) | No (2)  

guru   10 years AGO

The volume of the drop=4/3 pi r^3
=4/3 times 22/7 times 0.2^3 cm^3=0.03352381
Volume of the tank = 1000 cm^3
Time taken in seconds= 29830 (nearly)
Time taken in hour, minute and seconds = 8h 17m 37s

Like? Yes (1) | No (1)  

Mithun Kumar Kesari   10 years AGO

8hrs 17 min 37 sec

Like? Yes (1) | No (1)  

Sundar Kumar   10 years AGO

Solution
Total amount of water = 1 litre = 1000000 cubic mm
Volume of 1 drop of water = 4*π*r*r*r/3 = 4*π*2*2*2/3 cubic mm and this drop takes 1 sec to fall from the tank
Hence total time taken = 1000000/(32*π/3) sec.
= 29856.688 sec.
= 29856.688/3600 hours
= 8.2935244 h
= 8h 17m 37s

Like? Yes (1) | No (1)  

Tark Patel   10 years AGO

Total amount of water = 1 litre = 1000000 cubic mm
Volume of 1 drop of water = 4*π*r*r*r/3 = 4*π*2*2*2/3 cubic mm and this drop takes 1 sec to fall from the tank
Hence total time taken = 1000000/(32*π/3) sec.
= 29856.688 sec.
= 29856.688/3600 hours
= 8.2935244 h
= 8h 17m 37s

Like? Yes (1) | No (1)  

venkatesh.p   10 years AGO

Total amount of water = 1 litre = 1000000 cubic mm
Volume of 1 drop of water = 4*π*r*r*r/3 = 4*π*2*2*2/3 cubic mm and this drop takes 1 sec to fall from the tank
Hence total time taken = 1000000/(32*π/3) sec.
= 29856.688 sec.
= 29856.688/3600 hours
= 8.2935244 h
= 8h 17m 37s

Like? Yes (1) | No (2)  

Aarti Galar   10 years AGO

Total amount of water = 1 litre = 1000000 cubic mm
Volume of 1 drop of water = 4*π*r*r*r/3 = 4*π*2*2*2/3 cubic mm and this drop takes 1 sec to fall from the tank
Hence total time taken = 1000000/(32*π/3) sec.
= 29856.688 sec.
= 29856.688/3600 hours
= 8.2935244 h
= 8h 17m 37s

Like? Yes (1) | No (3)