M4maths Previous Puzzles

19 Nov 2014 Profit and Loss

Rahim got 12 & 1/4 dozen T-shirts in 12 % discount to printed price and he sold two third of these T-shirts in 19 % profit to printed price, then he sold other T-shirts in printed price. If his overall profit is 3626 rupee then printed price of the T-shirt is

OPtion

1) 95
2) 108
3) 94
4) 125
5) 136
6) 101
7) 100
8) 98
9) 84
10) 75

Solution

Let the printed price of the T-shirt is x, then according to given condition
1.19 x * 2/3 (147) + x * 1/3 (147) - 0.88 x *(147) = 3626
On solving this equation, we get x= 100
Correct Option: 7

Correct Option: 7 Best Solution (37)

Kushagra Tiwari   10 years AGO

if marked price mp=x
total cp = 147 * 0.88x = 129.36x
total sp = (98 * 1.19x) + (49 * x) = 165.62x
profit = sp - cp = 165.62x - 129.36x = 3626
=> 36.26x = 3626
=> x = 100
which is in option 7

Like? Yes (17) | No (4)  

Shreya Tiwari   10 years AGO

if marked price mp=x
total cp = 147 * 0.88x = 129.36x
total sp = (98 * 1.19x) + (49 * x) = 165.62x
profit = sp - cp = 165.62x - 129.36x = 3626
=> 36.26x = 3626
=> x = 100

Like? Yes (9) | No (1)  

akshay rathi   10 years AGO

Rahim got 12 & 1/4 dozen T-shirts i.e. = (12*12) + (1/4 * 12)= 147 tshirts

Assuming cost of Each Tshirt printed price 100 rs., we get
total price of 147 Tshirts = 14700 rs

On 12% disc. he get tshirts = 12936 rs

Printed price of 2/3rd Tshirts = 9800 rs i.e. (2/3*147*100)

19% profit on 98 Tshirts= 11662 rs

and as he sell remaining 49 tshirts @ printed price = 4900

Then total 147 Tshirts sold at = 11662+ 4900 = 16562 rs.

so by, S.P. - C.P. = profit
i.e. 16562 - 12936 = 3626
i.e. profit = 3626
Hence Proved

Like? Yes (5) | No (2)  

santosh kumar patel   10 years AGO

Let the printed price of the T-shirt is x, then according to given condition
1.19 x * 2/3 (147) + x * 1/3 (147) � 0.88 x *(147) = 3626
On solving this we get x= 100

Like? Yes (2) | No   

Narasapu Hari prasad   10 years AGO

Ans is option 7
12&1/4 means 147 t shirts
let x be the printed price
(147*12*x/100)+(98*19*x/100)=3626
solve for x u will get x=100

Like? Yes (2) | No   

NAVEEN KUMAR   10 years AGO

if in question net profit is rs. 3.626 rupees then printed price = Rs. 100 is possible

Like? Yes (1) | No   

PAWAN KUMAR   10 years AGO

Total no of T-shirts bought = 12*12 + 3 = 147
Let the printed price of one T-shirt be Rs t.
Then, cost price = 0.88t*147 = 129.36t
Also, selling price = (1.19t*98 + t*49) = 116.62t + 49t = 165.62t
Therefore, profit = (165.62 - 129.36)t = 36.26t
36.26t = 3626 => t = 100 Ans.

Like? Yes (1) | No   

Anand   10 years AGO

Let the printed price of the T-shirt is x, then according to given condition
1.19 x * 2/3 (147) + x * 1/3 (147) � 0.88 x *(147) = 3626
On solving this equation, we get x= 100

Like? Yes (1) | No   

anuj gupta   10 years AGO

100

Like? Yes (1) | No   

CHANDAN KUMAR   10 years AGO

printed price=x
cp=147*88x/100=129.36x
sp=119*98x/100+49x=165.62x
profit=36,26x=3626
x=100

Like? Yes (1) | No   

sravani   10 years AGO

let the printed price be X
12 1/4 =49/4dozens i.,e 49/4 * 12 =49* 3=147
he got 12% discont so, cost of each is 88X/100
cost 147 T-shirts is 147 *(88X/100)=12936X/100
2/3(147)=98
98 were sold for 19% profit i.,e 98 * (119X/100)
remaing(147-98=)49 for x i.,e 49X
total selling price= 49X+ 98 * (119X/100)=16562X/100
profit=s.p-c.p=3626X/100
given profit is 3626
so,3626X/100=3626
Therefore=X=100.

Like? Yes (1) | No   

prem kumar chaudhary   10 years AGO

147*2/3*x*31/100+147/3*x*12/100=3626
x=100

Like? Yes (1) | No   

Md.Sultan Khichi   10 years AGO

12&14 dozen =(12+1/4)*12=147
Let the printed prize is x.
So total cp=147*88/100=12936/100
2/3*147=98 t shirts.
Sp of 98 t-shirts =119*98x/100
Sp of 47 t-shirts =49x
Total sp=16562x/100
Profit=sp-cp
16562x/100-12936x/100=3626
After solving x=100
Ans 100

Like? Yes (1) | No   

ranjithreddy   10 years AGO

147*.12x+98*.19x=3626
x=100.

Like? Yes (1) | No   

Abhishek Porwal   10 years AGO

Let the printed price is 100
12&1/4 dozens that means 147 t-shirts he got in 12% discount i.e. Rs 88 => 88*147 =12936
i.e sold 2/3rd of 147 i.e. 98 t-shirts in 19% profit i.e. Rs 119
and the remaining 49 t-shirts in Rs 100 itself.
Now, 98*119+49*100=16562
and given t-shirts = 147*88=12936
=> 16562-12936 = 3626 i.e. our given profit .
Therefore , the printed price must have been Rs 100

Like? Yes (1) | No   

MRITUNJAY   10 years AGO

let printed price is 100.
total t-shirt cost=147*88=12936
sp of 2/3 t-shirt=2/3*147*119=11662
sp of remaing t-shirt=49*100=4900
total sp=16562
gain=16562-12936=3626
so printed price of t-shirt is 100.
that is option 7.

Like? Yes (1) | No   

khushboo goenka   10 years AGO

total shirt=144+3=147
and cp of 147 t shirt= 147x
and on discount shirt price bcm=129.36x of 98 tshirt
and 49x of 49 tshirt
and total profit= 36.26x

Like? Yes (1) | No   

Deepak prajapati   10 years AGO

total = 147 t-shirts , 2/3 rd = 98, rest=49

if x be printed price then
( 98 * 119x/100 + 49x ) - 147 * 88x/100 = 3626
238x + 100x - 264x = 74*100
74x = 74*100
x = 100
So option 7 will be ans.

Like? Yes (1) | No   

abhishek narayan   10 years AGO

Let the printed price of each T-shirt be x.
No. of T-shirt=12+3=
Given, c.p of 15 T-shirts= 147*{x-(12/100)*x}
=147*(22/25)*x
=(3234/25)*x
s.p of 15-T-shirts=98*{x+(19/100)*x} + 49*x
=(16562/100)*x
profit= s.p - c.p = 165.62x-129.36x=36.26x
so, x= 3626/36.26=100.

Like? Yes (1) | No   

ARJUN PRASAD   10 years AGO

x=100

Like? Yes (1) | No   

VIVEK KUMAR BARANWAL   10 years AGO

let marked price=x
total no. of t-shirts=(12+1/4)*12=147
c.p=147*x*88%
s.p=(2/3*147*x*119%)+(1/3*147*x)
by problem
s.p - c.p =3626
by solving we get x=100

Like? Yes (1) | No   

swasthika   10 years AGO

let printed price be x,
given profit is 3626 which is,

147*(12x/100) + 98 * (19x/100) =3626

(since 147 tshirts are sold for 12% profit + 98 (two-third of 147) are sold for 19% profit)

on solving x=100

Like? Yes (1) | No   

Anoop Tiwari   10 years AGO

Let the printed price of the T-shirt is x, then according to given condition
1.19 x * 2/3 (147) + x * 1/3 (147) +0.88 x *(147) = 3626
On solving this equation, we get x= 100

Like? Yes (1) | No   

mayank   10 years AGO

cp= 147*(p- 0.12p)
sp= 98*(p+ 0.19p)+49p
profit= {98*(p+ 0.19p)+49p} - 147*(p- 0.12p) =3626
thus, p= 100

Like? Yes (1) | No   

Swagatam Kumar Das   10 years AGO

CP of 147 shirt is 88x*147/100
SP of shirts is (119x*98/100)+(4900x)
So {(119x*98/100)+(4900x)}- (88x*147/100)=3626
So x is 100

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sanjeev kumar   10 years AGO

ans is 100

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pravin   10 years AGO

let the printed price is x rs.
total cost price is=(147*x*88)/100=12936/100
total selling price=((147)*x*2/3*119)/100+49*x
=(16562*x)/100
profit

(16562*x)/100-(12936*x)/100=3626
so x=100

Like? Yes (1) | No   

Ayushi Gupta   10 years AGO

12 1/4 dozen t-shirts = 147
2/3(147) = 98
1/3(147) = 49
so, equation will be =
98*1.19x + 49*x - 147*0.88x = 3626
36.26x = 3626
x = 100

where x = printed price of each t-shirt taken
so 12% discount = 0.88x (cost price)
19% profit = 1.19 x (selling price)

Like? Yes (1) | No   

Chirag Ranjan Lahiri   10 years AGO

If marked price mp=x
total CP = 147 * 0.88x = 129.36x
total SP = (98 * 1.19x) + (49 * x) = 165.62x
Profit = SP - CP = 165.62x - 129.36x = 3626
=> 36.26x = 3626
=> x = 100

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Anand Dwivedi   10 years AGO

Answer is 100

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Sanu Panji   10 years AGO

Say printed pize is 100/-
12 and 1/4 dozon =147

His cost = 147*(100-12)= 12936/-

2/3 of 147 is 98

98 T-shirt sold in 98*(100+19)= 11662/-

Rest 49 sold in 49*100=4900/-

Total sold 11662+4900= 16562/-

Profit 16562-12936= 3626/-

so printed pize is 100


Correct option is (7)

Like? Yes (1) | No   

vaitesh mudaliar   10 years AGO

let the printed price be x,
rahim brought 12*12+1/4 *12 =147 t-shirts
C.P. 12% discount = 0.88x *147 =129.36x
sold 2/3 rd of t-shirts at 19% profit = 2/3 * 1.19x * 147 =116.62x
remaining 1/3 rd at printed price =1/3*147*x =49x
net profit =116.26x + 49x - 129.36x = rs. 3626
x= 100 rs.

Like? Yes (1) | No   

prem   10 years AGO

12&1/4 dozen=147 t-shirts.
147 t-shirt got with 12% discount means if printed price =100x then he purchase in 88x
now 2/3rd means 98 t-shirt in 119x and
remaining 49 t-shirts in 100x
if total profit=3626
3626=98*119x+49*100x-147*88x
3626x=3626
x=1
hence printed price=100

Like? Yes (1) | No   

tirupathi reddy   10 years AGO

total = 147 2/3 = 98, 1/3=49
S.p -c.p = profit

(98*1.19x+49*0.88x)- 147(0.88x)= 3626
x= 100

Like? Yes (1) | No   

BHASKAR MANDAL   10 years AGO

let the marked price be ---> x
total no. of goods = 49 / 4 * 12 = 149
C.P = 147*0.88 x = 129.36 x
s.p = 98 * 1.19 *x + 49 * x = 165.62 x
profit = 3626
=> s.p - c.p = 3626
165.62 x - 129.36 x = 3626
=> 36.26 x = 3626
=> x = 100
so the option is 7

Like? Yes (2) | No (2)  

Abhishek Vishwakarma   10 years AGO

If x is printed price,

1.19*x*98 + 49*x - 0.88*x*147 = 3626

x= 100

Like? Yes (1) | No (1)  

RAKESH   10 years AGO

total = 147 t-shirts , 2/3 rd = 98, rest=49

if x be printed price then
( 98 * 119x/100 + 49x ) - 147 * 88x/100 = 3626
=> 238x + 100x - 264x = 74*100
=> 74x = 74*100
=> x = 100

Like? Yes (1) | No (2)  

18 Nov 2014 Probability

A bag contains 6 black and 8 red balls. A ball is drawn at random from the bag. If the ball drawn is black, a coin is tossed twice otherwise no coin is tossed. What is the probability to get two heads respectively on the coins.

OPtion

1) 1/8
2) 1/4
3) 3/7
4) 1/7
5) 3/14
6) 3/28
7) 2/7
8) 1/2
9) 1/3
10) 1/48

Solution

Probability of drawing a black ball is 6/14 = 3/7
After then the probability of getting two successive heads is 1/2 * 1/2 = 1/4
Net probability = 3/7 * 1/4 = 3/28

Option 6)

Correct Option: 6 Best Solution (60)

Jayanta Dutta   10 years AGO

1 black ball from 6 black balls can be selected as 6C1 so the prob is- 6C1/14C1

now 2 heads can be obtained 1 ways i.e. {hh,ht,th,tt}
so prob is -1/4;

so the prob of getting two heads while drawing a black ball is-

6/14*1/4
i.e-3/28 option.(6)

Like? Yes (6) | No (2)  

Deepak prajapati   10 years AGO

(6/14)*(1/4)=3/28

Like? Yes (3) | No (2)  

ARJUN PRASAD   10 years AGO

6/14*1/2*1/2

Like? Yes (2) | No (1)  

SOHOME DAS   10 years AGO

probability of black ball = 6/14
probability of two consecutive head = (1/2)* (1/2) = 1/4
all along final ans will be = 6/14 * 1/4 = 3 / 28 (Ans)

Like? Yes (1) | No   

prem kumar chaudhary   10 years AGO

(3/7)*(1/4)=3/28

Like? Yes (2) | No (1)  

Rahul   10 years AGO

probability of getting the black ball = 6C1/14C1 = 3/7

probability of getting both the coins head = 1/4

combined probality = (3/7) * (1/4) = 3/28

Like? Yes (2) | No (1)  

Aman Gupta   10 years AGO

6/14x1/4=3/28

Like? Yes (1) | No   

santosh kumar patel   10 years AGO

to get head , we must choose the black ball
that's why
probability of black ball and two twice head is
6/14*1/2*1/2=3/28

Like? Yes (1) | No   

Mani Shankar   10 years AGO

chance of drawn ball is black : 6/14
chance of getting to heads in two toss are : 1/2*1/2
so chance of whole event will be : 6/14*1/2*1/2 = 3/28

Like? Yes (1) | No   

Divesh Ranjan   10 years AGO

probability of 1 black ball drawn = 6/14
and getting heads after tossing twice= 1/2*1/2=1/4
hence (6/14)*1/4=3/28

Like? Yes (1) | No   

veeranjaneyulu   10 years AGO

6/14x1/4

Like? Yes (1) | No   

MAHARAJAN.G   10 years AGO

total number of balls=14
probability of getting black=6c1/14c1=6/14
coin is tossed twice so n=4
{ (h,h) , (h,t), (t,h) , (t,t) }
probability of getting two heads is=1/4
total probability of getting two heads =6/14*1/4=3/28

Like? Yes (1) | No   

mradul kumar   10 years AGO

for first we find probability for getting a black ball :
6c1/14c1=6/14
now we calculate prob of getting two heads if drawn ball in black:
6/14*1/2*1/2=3/28
so option 6 is correct..

Like? Yes (1) | No   

Swagatam Kumar Das   10 years AGO

Problty to slct one black ball is 6/14
And prblty of 2 head is 1/4
So ans is (6/14) *(1/4) =3 /28

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shubham   10 years AGO

because probability of black is 6/14 and for one hed is 1/2 for first head and for second head 1/2 that makes it 3/28

Like? Yes (1) | No   

Shreya Tiwari   10 years AGO

Probability of drawing a black ball is 6/14 = 3/7
After then the probability of getting two successive heads is 1/2 * 1/2 = 1/4
Net probability = 3/7 * 1/4 = 3/28

Like? Yes (1) | No   

Kushagra Tiwari   10 years AGO

Probability of drawing a black ball is 6/14 = 3/7
After then the probability of getting two successive heads is 1/2 * 1/2 = 1/4
Net probability = 3/7 * 1/4 = 3/28

Like? Yes (1) | No   

Abhishek Vishwakarma   10 years AGO

Probability of drawing a black ball is 6/14 = 3/7
After then the probability of getting two successive heads is 1/2 * 1/2 = 1/4
Net probability = 3/7 * 1/4 = 3/28

Like? Yes (1) | No   

Maniratnam   10 years AGO

6/14*1/2*1/2 = 3/28

Like? Yes (1) | No   

ranjithreddy   10 years AGO

Probabilty of getting Black is=6/14.
After that if a coin is tossed twice,the probabilty of getting head two times is 1/4.
Therefore the final probability is=(6/14)*(1/4)=3/28

Like? Yes (1) | No   

Supriya Mondal   10 years AGO

probability of getting black ball from the bag is=6/14
and probability of getting one HEAD from the coin is=1/2
so answer will be=(6/14)*(1/2)*(1/2)=3/28

Like? Yes (1) | No   

Anshul Shrivastava   10 years AGO

(6/14)*(1/4)
=3/28

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Chirag Ranjan Lahiri   10 years AGO

Probability for black ball = 6/14

Probability for getting two heads respectively = 1/4

so total = (6/14)*(1/4) = 3/28

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Devendra Kumar   10 years AGO

6/14*1/4=3/28

Like? Yes (1) | No   

Parag Wagh   10 years AGO

6/14*1/2*1/2=3/28

Like? Yes (1) | No   

Rahul Dasharath Vayale   10 years AGO

3/7*1/4=3/28

Like? Yes (1) | No   

RAMAKRISHNA   10 years AGO

p(bLack ball)*p(heads)=3/28

Like? Yes (1) | No   

ADARSH GAURAV   10 years AGO

3/28 is the answer.

Like? Yes (1) | No   

Sanu Panji   10 years AGO

P = (6/14)*(1/2)*(1/2)
=3/28

Like? Yes (1) | No   

zafar   10 years AGO

probability of selecting black ball is 3/7, Probability of 2 heads is 1/4. 3/7*1/4=3/28

Like? Yes (1) | No   

khushboo goenka   10 years AGO

(6c1*1/4)/14c1

Like? Yes (1) | No   

surya   10 years AGO

probability of getting black ball out of 6 black and 8 red balls
is 3/7
if then a coin is tossed twice in the first case getting head is 1/2 and second case is also 1/2
then final probability is 3/7*1/2*1/2=3/28

Like? Yes (1) | No   

alok meher   10 years AGO

probability of getting a black=6/(6+8)=6/14
probability of getting two heads respectively = (1/2)*(1/2)=1/4

so,probability of getting two head after the ball drawn=
(6/14)*(1/4)=3/28

Like? Yes (1) | No   

Hemadri   10 years AGO

Total balls=14
probability of taking black ball=6/14=3/7
probability of getting heads on the coin=1/4
Probability=(3/7)*(1/4)=3/28

Like? Yes (1) | No   

Jigyasa Kumar   10 years AGO

Answer is .1071

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Siddharth   10 years AGO

the probability of getting a black ball is 6/14 multiplied by the probability of getting two heads i.e. 1/4 which results in 3/28!!

Like? Yes (1) | No   

abhilasha   10 years AGO

The answer os 3/28.

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abhishek narayan   10 years AGO

6/14*1/2*1/2

Like? Yes (2) | No (2)  

swati kunj   10 years AGO

probability of getting black ball=6c1/14c1=3/7
no of event of coin is tossed twice={hh,ht,th,tt}
so probability of getting 2head=1/4
probabitlity of getting black ball and 2head=3*1/7*4=3/28

Like? Yes (1) | No (1)  

Himanshu Mittal   10 years AGO

Probability of taking black ball = 6/14
Probability of coming two heads consecutively= 1/4
So, total probability will be (6/14)*(1/4)=3/28

Like? Yes (1) | No (1)  

Anirudh   10 years AGO

6/14 probability for the ball to be taken out
now 1/2 for head for first time
1/2 head for second time
and the event will be completed when all three hapeen and soit will be multiplied
6/14*2*2
=1/8

Like? Yes (1) | No (1)  

PAWAN KUMAR   10 years AGO

Probability of getting black ball = 6/14
Probability of getting two heads = 1/2 * 1/2 = 1/4
Since coin is tossed after getting black ball,so,
Probability of getting two heads = 6/14 * 1/4 = 3/28 Ans.

Like? Yes (1) | No (1)  

SUBHASH TULSYAN   10 years AGO

6/14*1/2*1/2

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kamal   10 years AGO

way of choosing a black ball from bag= 6/14=3/7
now black ball drwan so we have to toss now
getting head probability in first time=1/2
and in seond time=1/2
so probability of getting head=3/7*1/2*1/2=3/28

Like? Yes (1) | No (1)  

Akash Verma   10 years AGO

probability of getting one black ball is 6c1/14c1=3/7
now probability of getting two head=1/4
so ultimate probability=3/7*1/4=3/28(Ans)

Like? Yes (1) | No (1)  

k srinivas   10 years AGO

3/28 is answer
p(getting black)*p(two heads)
6/14 *(1/2*1/2)
3/28

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Arijit Das   10 years AGO

probability = 6/14*1/2*1/2
=3/28

Like? Yes (2) | No (2)  

pravin   10 years AGO

((6c1)*1/2*1/2)/14c1

(6*1)/(14*4)

3/28

Like? Yes (2) | No (2)  

Md Ehsanul Hoda Ansari   10 years AGO

probability of getting black ball=(6C1 / 14C1)
probability of getting 2heads=1/4

(6C1 / 14C1)*1/4=3/28

Like? Yes (1) | No (1)  

Anoop Tiwari   10 years AGO

required probability=6c1/14*1/2*1/2
=3/28
option 6) is correct.

Like? Yes (1) | No (1)  

Tarun Jain   10 years AGO

No. of favorable event = 6c1/ 14c1
and p(2 heads)= 1/4
Ans - 6/14 * 1/4 = 3/28

Like? Yes (1) | No (1)  

VIVEK KUMAR BARANWAL   10 years AGO

(6c1/14C1)*1/2*/1/2=3/28

Like? Yes (1) | No (1)  

APPIKONDA SANTOSH NAIDU   10 years AGO

(6/14)(1/2*1/2)

Like? Yes (1) | No (1)  

Y V S Chandrakanth   10 years AGO

((6c1)*(1/4))/14c1=3/28

Like? Yes (1) | No (1)  

Emanuel Abhishek Murmu   10 years AGO

probability for getting black ball= 6/14= 3/7

probability of getting two heads on getting black ball= (3/7)*(1/2)*(1/2) = 3/28

Like? Yes (3) | No (4)  

Md.Sultan Khichi   10 years AGO

(6C1/14C1)*1/4=3/28

Like? Yes (1) | No (2)  

ANIL KUMAR   10 years AGO

No of way of selecting 1 ball=14C1=14
No of selection of 1 black ball= 6C1=6
P(Black)=6/14
P(two head)=1/4

Total Probability=(6/14)*(1/4)

Like? Yes (1) | No (2)  

BHASKAR MANDAL   10 years AGO

6/14 * 1/4 = 3/28 ....option 6

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Sourabh Prasad   10 years AGO

6/14 * 1/2 * 1/2
=3/28

Like? Yes (1) | No (2)  

RAKESH   10 years AGO

p = p(black) * p( both head) = 6/14 * (1/2)^2


p = 6/14 * 1/4 = 3/28

Like? Yes (2) | No (4)  

17 Nov 2014 Sequence

What is the next number of the following sequence
81, 0, 21, 44, 69,.....

OPtion

1) 25
2) 89
3) 24
4) 96
5) 64
6) 72
7) 61
8) 76
9) 88
10)None of these

Solution

9^2 = 81 = 81 (Take last two digit)
10^2 = 100 = 0 (Take last two digit)
11^2 = 121 = 21
12^2 = 144 = 44
13^2 = 169 = 69
Similarly
14^2 = 196 = 96

Option 4) 96

Correct Option: 4 Best Solution (99)

CHANDAN KUMAR   10 years AGO

0+21=21
21+23=44
44+25=69
69+27=96

Like? Yes (5) | No   

Chandra chur anand   10 years AGO

9^2%100=81
10^2%100=0
11^2%100=21
.......
14^2%100=96 is the ans...

Like? Yes (9) | No (4)  

Alok singh   10 years AGO

81+19=100-100=0 if result is equal or more than 100
0+21=21
21+23=44
44+25=69
69+27=96

Like? Yes (3) | No   

Anubhav jain   10 years AGO

21 INC . 23 25 27
ANS 96

Like? Yes (2) | No   

NEHA KUMARI   10 years AGO

0+21=21
21+23=44
44+25=69
69+27=96

Like? Yes (2) | No   

Akshay   10 years AGO

9*9=081
10*10=100
11*11=121
12*12=144
13*13=169
14*14=196
Remove the most significant bot from all the right hand side number.
hence 96.

Like? Yes (6) | No (5)  

priyanka    10 years AGO

21*1=21
22*2=44
23*3=69
24*4=96...................

Like? Yes (1) | No   

kumar   10 years AGO

81-0=81
81-21=60
81-44=37
81-69=12
now,

diff of 81-60 =21
diff of 60-37=23 and
diff of 37-12=25
So,
12-x=27
therefore, x=-15
so,
81-(-15)=96
is the next number

Like? Yes (1) | No   

ranjithreddy   10 years AGO

Removing the digit in 100s place
9*9=81.........81
10*10=100......0
11*11=121.........21
12**12=144........44
and so on....
14*14=196......96 is the answer

Like? Yes (2) | No (1)  

prem kumar chaudhary   10 years AGO

9*9=81
10*10=100
11*11=121
12*12=144
13*13=169
14*14=196
ans=96

Like? Yes (3) | No (2)  

P Niranjan   10 years AGO

19*9 = 171 =1+7 1 = 81

20*0 = 0
21*1 = 1
22*2 = 44
23*3 = 69
24*4 = 96

Like? Yes (2) | No (1)  

Bhanoj   10 years AGO

These are the last two digits of the squares of the numbers starting from 9
9*9=081 last two digits 81
10*10=100 last two digits 00
11*11=121 last two digits 21
12*12=144 last two digits 44
13*13=169 last two digits 69
14*14=196 last two digits 96
so 96 is the one which coming next in the series.

Like? Yes (2) | No (1)  

nayan jain   10 years AGO

becoz after 0 , series is increment in order to add 21,23,25....... to the previous no.

Like? Yes (1) | No   

Anshul Shrivastava   10 years AGO

81+(19+0)=100=00
100+(19+2)=121=21
121+(19+4)=144=44
144+(19+6)=169=69
169+(19+8)=196=96

Like? Yes (2) | No (2)  

vamsi priyanka   10 years AGO

the diff between the 21,44 is 23
and diff between the 44 ,69 is 25
nd diff between the 69,96 may be 27

Like? Yes (2) | No (2)  

chanchal   10 years AGO

21*1=21, 22*2=44,23*3=69,24*4=96

Like? Yes (2) | No (2)  

Sonam   10 years AGO

choose last two digits of square of a no.
9*9=81
10*10=100
11*11=121
12*12=144
13*13=169
14*14=196

81,0,21,44,69,96

Like? Yes (2) | No (2)  

KRISHAN MURARI   10 years AGO

9^2=81
10^2=100~0 (last two number)
11^2=121~21 (last two number)
12^2=144~44 (last two number)
13^2=169~69 (last two number)
14^2=196~96 (last two number)

Like? Yes (1) | No (1)  

Hemadri   10 years AGO

(9)2=81
(10)2=100
(11)2=121
(12)2=144
(13)2=169
(14)2=196

Like? Yes (1) | No (1)  

LOKESH KUMAR   10 years AGO

21-0=21
44-21=23
69-44=25
96-69=27
So series of increasing order of 2

Like? Yes (1) | No (1)  

sachin verma   10 years AGO

81=9^2
00=last two digits of(10^2)
21=last two digits of(11^2)
44=last two digits of(12^2)
69=last two digits of(13^2)
So, next is
last two digits of(14^2)=96

Like? Yes (1) | No (1)  

Siddharth   10 years AGO

The series is made of the last two terms of squares of 9,10,11,12,13,14 respectively
so
81,0,21,44,69,96

Like? Yes (1) | No (1)  

Harshal R Satapute   10 years AGO

guess

Like? Yes (1) | No (1)  

Rohit Sharma   10 years AGO

Looking at the last 3 number and their combination this looks like to be the next number.

Like? Yes (1) | No (1)  

Parag Wagh   10 years AGO

last 2 digits are there:
13^2=169 so 69
14^2=196 so 96
option 4) 96

Like? Yes (1) | No (1)  

MINTU KUMAR GUPTA   10 years AGO

last two digit of square of 9,10,11,12,13,14,15.....
81 100 121 144 169 196
ans is 96

Like? Yes (1) | No (1)  

Rahul Rathod   10 years AGO

9^2=81 mod 100=81
10^2=100 mod 100=0
11^2=121 mod 100=21
12^2=144 mod 100=44
13^2=169 mod 100=69
similarly
14^2=196 mod 100=96

Like? Yes (2) | No (3)  

Kushagra Tiwari   10 years AGO

Here a(n) = n^2 reduced mod 100.
AS
9^2 = 081 => 81
write square of no and then take last two digits of its starting from 9
similarly
10^2 = 100 => 00
11^2 = 121 => 21
12^2 = 144 => 44
13^2 = 169 => 69

so the next term is
14^2 = 196 => 96

which is in option no 4

Like? Yes (6) | No (7)  

Saranjit Singh   10 years AGO

taking last two digits of perfect squares starting frm 81.

Like? Yes (2) | No (3)  

Udhaya kumar   10 years AGO

n^2 mod 100.....
where n = 9,10,11,12,13,14...respectively....
14^2 mod 100 = 96.......

Like? Yes (2) | No (3)  

Rahul   10 years AGO

81 (-81) = 0,
0 (+21) = 21,
21 (+23) = 44,
44 (+25) = 69,
69 (+27) = 96

Like? Yes (2) | No (3)  

priya saha   10 years AGO

taking last two digit of squares of no. greater than and equal to 9

9^2=81 81
10^2=100 0
11^2=121 21
12^2=144 44
13^2=169 69
14^2=196 96 (ansr)

Like? Yes (2) | No (3)  

Anand Dwivedi   10 years AGO

96 Will be Correct Answer
.
a(n) = n^2 reduced mod 100.

Like? Yes (2) | No (3)  

SUCHETA BISWAS   10 years AGO

14*14=196
ignore 1

Like? Yes (2) | No (3)  

RAKESH   10 years AGO

9^2, 10^2, 11^2, 12^2, 13^2, 14^2

take last two digit of the series
14^2 --------------> 96

Like? Yes (1) | No (3)  

Abhishek Vishwakarma   10 years AGO

Here a(n) = n^2 reduced mod 100.
AS
9^2 = 081 => 81

similarly
10^2 = 100 => 00
11^2 = 121 => 21
12^2 = 144 => 44
13^2 = 169 => 69

so the next term is
14^2 = 196 => 96

Like? Yes (1) | No (3)  

Dr.Dipin Singh   10 years AGO

taking last two digits of 81,100,121,14,169 (13^2) and then 196(14^2).
hence 96 is next number.

Like? Yes (2) | No (4)  

Surit Datta   10 years AGO

1, 4, 9, 16, 25, 36, 49, 64, 81, 0, 21, 44, 69, 96, 25, 56
it is the series where after square of 10
the numbers are written as
11 square = 121 we write it as 21
12 square = 144 we write it as 44
13 square = 169 we write it as 69
14 square = 196 we write it as 96
That's it..

Like? Yes (1) | No (3)  

Abhishek mani   10 years AGO

81+19=100(last two digit)=0
0+21=21
21+23=44
44+25=69
69+27=96so answer is (4)

Like? Yes (2) | No (4)  

anuj gupta   10 years AGO

N^2 MOD 100.
9^2 MOD 100=81.
10^2 MOD 100=0.
11^2 MOD 100=21.
12^2 MOD 100=44.
13^2 MOD 100=69.
14^2 MOD 100=96.

SO ANS IS 96.

Like? Yes (1) | No (3)  

lakshmi   10 years AGO

If an integer is congruent to 0 mod 10, then x^2 = 0^2 = 0 mod 10

i.e., if x = 0 mod 10 then the last digit of x^2 is 0.
a(n) = n^2 reduced mod 100.

Like? Yes (1) | No (3)  

Sandeep Kumar   10 years AGO

81= 9*9;
0= 10*10;
21= 11*11;
44= 12*12;
69=13*13;
96=14*14;
so 96 will be the answer.

Like? Yes (1) | No (3)  

purushothama   10 years AGO

If an integer is congruent to 0 mod 10, then x^2 = 0^2 = 0 mod 10

i.e., if x = 0 mod 10 then the last digit of x^2 is 0.
a(n) = n^2 reduced mod 100.

Like? Yes (1) | No (3)  

jayalakshmi   10 years AGO

If an integer is congruent to 0 mod 10, then x^2 = 0^2 = 0 mod 10

i.e., if x = 0 mod 10 then the last digit of x^2 is 0.
a(n) = n^2 reduced mod 100.

Like? Yes (1) | No (3)  

bhagya   10 years AGO

If an integer is congruent to 0 mod 10, then x^2 = 0^2 = 0 mod 10

i.e., if x = 0 mod 10 then the last digit of x^2 is 0.
a(n) = n^2 reduced mod 100.

Like? Yes (1) | No (3)  

CHANDA VIJAYALAKSHMI   10 years AGO

If an integer is congruent to 0 mod 10, then x^2 = 0^2 = 0 mod 10

i.e., if x = 0 mod 10 then the last digit of x^2 is 0.
a(n) = n^2 reduced mod 100.

Like? Yes (1) | No (3)  

NAVEEN KUMAR   10 years AGO

9*9=81.............81
10*10=100............00
11*11=121..............21
12*12=144............44
13*13=169.............69
14*14=196..............96 only consider unit & tenth place
hence,option (4) is correct

Like? Yes (1) | No (3)  

MANISH KUMAR SINGH   10 years AGO

The pattern is square of a number mod by 100.
like 9^2%100=81
10^2%100=0
11^2%100=21
12^2%100=44
13^2%100=69
14^2^100=196

Like? Yes (1) | No (3)  

Mani kandan   10 years AGO

ans is option 4)96

Periodic with period 50: (0, 1, 4, 9, 16, 25, 36, 49, 64, 81, 0, 21, 44, 69, 96, 25, 56, 89, 24, 61, 0, 41, 84, 29, 76, 25, 76, 29, 84, 41, 0, 61, 24, 89, 56, 25, 96, 69, 44, 21, 0, 81, 64, 49, 36, 25, 16, 9, 4, 1) and next term is 0. The period is symmetrical about the "midpoint" 25.
add the odd digit with the number and it reach 100, then take 100 as a zero.then continue add the odd digit with the number

Like? Yes (1) | No (3)  

Supriya Mondal   10 years AGO

Here we took last 2 digit of a square number
9^2=081(here last two digit is 81)
10^2=100(here last two digit is 00)
11^2=121(here last two digit is 21)
12^2=144(here last two digit is 44)
13^2=169(here last two digit is 69)
14^2=196(here last two digit is 96)
So the answer is 96

Like? Yes (1) | No (3)  

Tark Patel   10 years AGO

first number is 81 which is square of 9 so
starting from 9 onwards do the sqquare of numbers in sequence and divide by it with 100 then write the remainders,

9^2 = 81 / 100 = 81 (remainder)

10^2 = 100 / 100 = 0 (remainder)

11^2 = 121 / 100 = 21 (remainder)

12^2 = 144 / 100 = 44 (remainder)

13^2 = 169 / 100 = 69 (remainder)

answer is

14^2 = 196 / 100 = 96 (remainder)

Like? Yes (1) | No (3)  

Sanu Panji   10 years AGO

answer is 96

coz:-


(9^2)mod100=81
(10^2)mod100=0
(11^2)mod100=21
(12^2)mod100=44
(13^2)mod100=69
(14^2)mod100=96

so correct is option (4)

Like? Yes (1) | No (3)  

Anoop Tiwari   10 years AGO

9^2+0,0,1^2+20,2^2+40,3^2+60 so next term will be.......
4^2+80=96
hence option 4) is correct

Like? Yes (1) | No (3)  

Mathan Raj   10 years AGO

Its adding 21, 23, 25 sequentially

Like? Yes (1) | No (3)  

Narasapu Hari prasad   10 years AGO

Ans is 96 option 4
the series is like this
9*9,10*10,11*11,12*12,13*13,14*14
81,100,121,144,169,196
take last two digits of every number
81,0,21,44,69,96

Like? Yes (1) | No (3)  

sandineni kiran   10 years AGO

if we neglect the first number, the series is increased with 21,23,25,27
69+27=96

Like? Yes (1) | No (3)  

santosh kumar patel   10 years AGO

ans: 96

Like? Yes (2) | No (4)  

satyam sharma   10 years AGO

9^2=081
10^2=100
11^2=121
12^2=144
13^2=169
14^2=196
last two digit of each number is the required series
so answer is 96
correct option is 4

Like? Yes (1) | No (3)  

sayantani jana   10 years AGO

the diff between 0 and 21 is 21 ,21and 44 is 23 ,69 and 44 is 25so the difference b/w the differences is 2 i.e(23-21=2,25-23=2). so the next term will be [69+(25+2)]=(69+27)=96.

Like? Yes (1) | No (3)  

sravani   10 years AGO

2*1*10 + 1*1=21

2*2*10 + 2*2=44
2*3*10 + 3*3=69
2*4*10 + 4*4=96

Like? Yes (1) | No (3)  

balu   10 years AGO

0-21=21 diff,
21-44=23 diff,
44-69=25 diff,
69-96=27 diff...

Like? Yes (1) | No (3)  

K.ARun   10 years AGO

9^2=81 -----> 81
10^2=100 ----->0
11^2=121 ----->21
12^2=144 ----->44
13^2=169 ----->69
14^2=196 ----->96

so.. 96 :) :)

Like? Yes (1) | No (3)  

raviteja   10 years AGO

last two digits of no's are given in the series.so the next no is 14 square last two digits are 9&6 so answer is 96

Like? Yes (1) | No (3)  

Shivan kumar jha   10 years AGO

9*9=81
10*10=100
11*11=121
12*12=144
13*13=169
14*14=196
take last 2 digit so
ans =96

Like? Yes (1) | No (3)  

Nikita Kumari   10 years AGO

9*9=81
10*10=100
11*11=121
12*12=144
13*13=169
we have considered only 2 digits from left side
in the same way next number of the series will be: 96

since 14*14= 196
and 2 digits from left will be '96'.

Like? Yes (1) | No (3)  

Jigyasa Kumar   10 years AGO

the difference between consecutive nos. from 0 is following order 21, 23, 25 so the next no. will be 96

Like? Yes (1) | No (3)  

SUBHASH TULSYAN   10 years AGO

19*9=171=>(1+7)1=81
20*0=000=>(0+0)0= 0
21*1=021=>(0+2)1=21
22*2=044=>(0+4)4=44
23*3=069=>(0+6)9=69
24*4=096=>(0+9)6=96.........(Answer)

Like? Yes (1) | No (3)  

~Sandeep~   10 years AGO

Series is based on following formula : n^2 mod 100
n starts from 9

Like? Yes (2) | No (4)  

kamal   10 years AGO

last digit of squares 1,4,9,16,25,36,49,64,81,0,21,44,69,96,25,56,.....and so on

Like? Yes (1) | No (3)  

VIVEK KUMAR BARANWAL   10 years AGO

14*14=196
so answer is 96.

Like? Yes (1) | No (3)  

Emanuel Abhishek Murmu   10 years AGO

21-0= 21
44-21= 23
69-44= 25

so, 69+27= 96
next term in series is 96.

Like? Yes (1) | No (3)  

Rajat Jain   10 years AGO

21*1,22*2,23*3,24*4

Like? Yes (1) | No (3)  

Mani Shankar   10 years AGO

9*9 = 81
10*10 = 100
11*11 = 121
12*12 = 144
13*13=169
14*14= 196
so ans is 96

Like? Yes (1) | No (3)  

P.Nikhil Reddy   10 years AGO

By adding consecutive odd numbers from 19,21...

Like? Yes (1) | No (3)  

Ashish Kumar chhabra   10 years AGO

Last Two Digits Of Squares of numbers But Except 10

Like? Yes (1) | No (3)  

abhishek narayan   10 years AGO

14*14=196 neglecting 1st term so ans is 96

Like? Yes (1) | No (3)  

bikash tiwari   10 years AGO

9*9=81
10*10=100
11*11=121
12*12=144
13*13=169
14*14=196
after crossing two digit no. ignore first digit of 3digit no
so and becomes 96 ,ignore 1

Like? Yes (2) | No (4)  

sanjeev kumar   10 years AGO

ans 96

Like? Yes (1) | No (3)  

abhishek agrawal   10 years AGO

0+21=21
21+23=44
44+25=69
69+27=96

Like? Yes (1) | No (3)  

Pushkar lal dangi   10 years AGO

81+19=100
0+21=21
21+23=44
44+25=69
69+27=96

Like? Yes (1) | No (3)  

Shreya Tiwari   10 years AGO

Here a(n) = n^2 reduced mod 100.
AS
9^2 = 081 => 81

similarly
10^2 = 100 => 00
11^2 = 121 => 21
12^2 = 144 => 44
13^2 = 169 => 69

so the next term is
14^2 = 196 => 96

Like? Yes (1) | No (4)  

Md.Sultan Khichi   10 years AGO

9^2=81
10^2=100=00
11^2=121=21
12^2=144=44
13^2=169=69
14^2=196=96
Ans. 96

Like? Yes (1) | No (4)  

dhanaseelan   10 years AGO

0+21=21
21+23=44
44+25=69
69+27=96
so option 4

Like? Yes (1) | No (4)  

P.Pandeeswari   10 years AGO

the series will be
(0+0)%100=0
(0+1)%100=1
(1+3)%100=4
(4+5)%100=9
(9+7)%100=16 .........
(64+17)%100=81
(81+19)%100=0
(0+21)%100=21
(21+23)%100=44
(44+25)%100=69
(69+27)%100=96

so the ans is option 4)

Like? Yes (3) | No (6)  

abhilasha   10 years AGO

the difference between consecutive nos. from 0 is following order 21, 23, 25 so the next no. will be 96

Like? Yes (1) | No (4)  

Aparna Bhattacharya   10 years AGO

Periodic with period 50: (0, 1, 4, 9, 16, 25, 36, 49, 64, 81, 0, 21, 44, 69, 96, 25, 56, 89, 24, 61, 0, 41, 84, 29, 76, 25, 76, 29, 84, 41, 0, 61, 24, 89, 56, 25, 96, 69, 44, 21, 0, 81, 64, 49, 36, 25, 16, 9, 4, 1) and next term is 0.
Option: 4

Like? Yes (1) | No (4)  

dara naga anjani prasad   10 years AGO

between 0 & 21, 21& 44, 44& 69 and the diff is 21 , 23, 25, next number 27 if we added 69+27=96.

Like? Yes (1) | No (4)  

swaroopfrancis   10 years AGO

81,100,121,144,169,196...squares

Like? Yes (1) | No (4)  

AMREEN   10 years AGO

9^2=81
10^2=100
but take only last two digits.
11^2=121 take,21
12^2=144 take 44
13^2=169 take only 69
now next is 14^2=196
then take only 96 answer

Like? Yes (1) | No (4)  

Male priyanka   10 years AGO

21-0=21
44-21=23
69-44=25
96-69=27
In the answer the difference is only 2.

Like? Yes (1) | No (4)  

Dipali Badade   10 years AGO

0+21=21
21+23=44
44+25=69
69+27=96

Like? Yes (1) | No (4)  

Jitendra Prasad   10 years AGO

9^2=81
10^2=100
11^2=121
12^2=144
13^2=169
14^2=196
then
14^2=96
Then seen two digit in square of the no.
ans=96

Like? Yes (1) | No (4)  

Deepak prajapati   10 years AGO

9*9=81
10*10=100=00
11*11=121=21
12*12=144=44
13*13=169=69
14*14=196=96

Like? Yes (2) | No (5)  

Devendra Kumar   10 years AGO

As the last digit of the series is of square of the number so the ans is 96

Like? Yes (1) | No (4)  

ARJUN PRASAD   10 years AGO

take only two digit 9^2=81,10^2=100 take only last two digit,13^2=169 ie69 and so on... so 14^2=196 ie 96

Like? Yes (2) | No (5)  

Sanchit Kapoor   10 years AGO

Each consecutive number is the last two digits of the square of natural number starting from 9
9^2 =81
10^2=100=0
11^2=121=21
12^2=144=44
13^2=169=69
So 14^2=196=96
Hence option 4 is correct.

Like? Yes (3) | No (7)  

BHASKAR MANDAL   10 years AGO

these are the remainder when a perfect square is divided by 100
9^2 = 81 = 100 *0 +81 , r = 81
10^2 = 100/100 = 1*100 +0 , r = 0
11^2 = 121 /100 = 1*100 +21 , r = 21
.......
14^2 = 196 /100 = 1*100 + 96 , r = 96
so option 4 is the correct answer.

Like? Yes (1) | No (5)  

APPIKONDA SANTOSH NAIDU   10 years AGO

21-0=21
44-21=23
69-44=25
96-69=27
so ans is=96

Like? Yes (1) | No (5)  

Santosh Kumar Behera   10 years AGO

9*9=81 last two digit 81
10*10=100 last two digit 00 so 0
11*11=121 last two digit 21
12*12=144 last two digit 44
13*13=169 last two digit 69
14*14=196 last two digit 96 so ans is 4

Like? Yes (1) | No (5)  

14 Nov 2014 Probability

Two cards are drawn at random from a pack of 52 cards. What is the probability that the drawn cards are both aces ?

OPtion

1) 2/13
2) 1/52
3) 1/112
4) 3/56
5) 1/13
6) 1/26
7) 1/222
8) 1/221
9) 2/26
10)None of these

Solution

n(S) = Number of ways of drawing 2 cards out of 52 cards
= (52)C(2) = 52*51/ 2*1 = 1326
n(E) = Number of ways of drawing 2 cards out of 4
= (4)C(2) = 4*3/ 2 = 6
Therefore
P(E) = 6/1326 = 1/221

Option 8)

Correct Option: 8 Best Solution (111)

P.Pandeeswari   10 years AGO

probability that the both cards are same=4P2/52P2=4*3/52*51=1/221
option 8)1/221

Like? Yes (27) | No (4)  

Udhaya kumar   10 years AGO

4C2 / 52C2 = 1 / 221........

Like? Yes (14) | No (4)  

santosh kumar patel   10 years AGO

n(S) = 52C2 = 1326
n(E) = 4c2 = 6
P(E) =n(E)/n(S) = 1/221

Like? Yes (11) | No (2)  

Sravanthi   10 years AGO

(4/52)*(3/51)=1/221

Like? Yes (8) | No (1)  

rosemary   10 years AGO

There are 4 aces in a 52-card deck. Suppose without replacement, the probability is
P(2 aces)= (4/52) * (3/51) = (1/13) * (1/17) = 1/221

Like? Yes (7) | No   

Anoop Tiwari   10 years AGO

for first card drawn probability of ace=4/52=1/13
for second card drawn probability of ace=3/51
so total probability=1/13* 3/51=1/221
hence option 8) is correct

Like? Yes (5) | No   

padmaja   10 years AGO

4c2/52c2
=1/221

Like? Yes (4) | No   

Ramesh Sriram   10 years AGO

4c2/52c2

Like? Yes (6) | No (2)  

Swagatam Kumar Das   10 years AGO

Probability of getting two aces is 4c2
So ans is 4c2/52c2=1/221.

Like? Yes (4) | No   

Manasa Dullur   10 years AGO

4C2/52C2 = 1/221

Like? Yes (3) | No   

Parag Wagh   10 years AGO

4c2/52c2=1/221

Like? Yes (3) | No   

swarupa nuggu   10 years AGO

1/221

Like? Yes (3) | No   

Aparna Chakraborty   10 years AGO

4/52 *3/51 =1/221

Like? Yes (3) | No   

Himanshu Srivastava   10 years AGO

4c2/52c2

Like? Yes (2) | No   

aman   10 years AGO

There r 4 aces
So 4c2
Total card 52
52c2
Prob 4c2/52c2 = 1/221

Like? Yes (2) | No   

vinit   10 years AGO

probabilities: 4/52*3/51=1/221

Like? Yes (2) | No   

A SIRISHA    10 years AGO

the way to draw 2 cards out of a possible 4 aces = 4P2
the way to draw 2 cards from a deck of 52 cards= 52P2
4P2/52P2=1/221

Like? Yes (2) | No   

Jayanta Dutta   10 years AGO

4 aces can be selected as 4C2 And from 52 we can select as 52C2 so prob is-4C2/52C2
=1/221

Like? Yes (3) | No (1)  

Anubhav jain   10 years AGO

4/52*3/51
1/17*1/13
=1/221

Like? Yes (2) | No   

G.Praveen Kumar   10 years AGO

there are 4 aces so while drawing 1 card pfobility is 4/52 and while drawing 2nd 3/51
taking both (4/52)*(3/51)=1/221

Like? Yes (2) | No   

Jabez David   10 years AGO

There are 4 aces in a 52-card deck.

Suppose without replacement, the probability is

P(2 aces)= (4/52) * (3/51) = (1/13) * (1/17) = 1/221

Like? Yes (2) | No   

Anshul Shrivastava   10 years AGO

(4/52)*(3/51)=(1/221)

Like? Yes (2) | No   

Surit Datta   10 years AGO

probability = 4C2/52C2 = 1/221
That's it..

Like? Yes (2) | No   

swati kunj   10 years AGO

probability of getting aces=4c2/52c2 =1/221

Like? Yes (2) | No   

SUCHETA BISWAS   10 years AGO

4c2/52c4=1/221

Like? Yes (3) | No (2)  

laxmi kumari   10 years AGO

Let S be the sample space . Then
n(S)=1326
Let E be the event of getting 2 aces out of 4. Then
n(E)=6
so,n(P)=1/221

Like? Yes (3) | No (2)  

Supriya Mondal   10 years AGO

We know that there is 4 ace card in a deck of playing card..
so probability is=4c2/52c2=1/221

Like? Yes (1) | No   

ravi prakash   10 years AGO

4c2/52c2= 1/221

Like? Yes (1) | No   

saikumar.chejerla   10 years AGO

4c2/52c2

Like? Yes (1) | No   

Karthick Raja   10 years AGO

4 aces in a deck of cards
first ace=4/52
second ace=3/52
p(two aces)=4/52*3/51
=12/2652
=1/221

Like? Yes (1) | No   

Vivek Raj   10 years AGO

4/52*3/51=1/221

Like? Yes (1) | No   

kancharla kavya   10 years AGO

Since there are only 4 ace cards in a pack of 52 cards ....Then the probability that both are aces is 4c2/52c2=1/221....

Like? Yes (1) | No   

Chirag Ranjan Lahiri   10 years AGO

Clearly, there are 52 cards, out of which there are 4 aces.

P (getting both aces) = 4c2/52c2 = 12/2562 = 1/221 answer.......

Like? Yes (2) | No (1)  

Md.Sultan Khichi   10 years AGO

4C2/52C2=1/221

Like? Yes (1) | No   

SUNITEE GARIMA   10 years AGO

P=4C2/52C2=1/221

Like? Yes (1) | No   

Aparna Bhattacharya   10 years AGO

Let S be the sample space and E be the the event of getting 2 aces out of 4. Then,
n(S)=52C2=1326
n(E)=4C2=6
P(E)=n(E)/n(S)=6/1326=1/221
Option: 8

Like? Yes (2) | No (1)  

m.lokeswari   10 years AGO

there are four aces in the pack we select two out of four so the answer is 1/221

Like? Yes (1) | No   

MRITUNJAY   10 years AGO

proability of aces=4c2/52c2
=1/221

Like? Yes (1) | No   

dhanaseelan   10 years AGO

4C2/52C2=1/221

Like? Yes (1) | No   

Arkja tiwari   10 years AGO

4c2/52c2

Like? Yes (1) | No   

MAHARAJAN.G   10 years AGO

p(e)=n(e)/n(s)
there are four aces
n(e)=4p2
total cards is 52 drawn card is 2
n(s)=52p2
4p2/52p2=4*3/52*51=12/2652=1/221

Like? Yes (2) | No (1)  

Zaheen Shekh   10 years AGO

total card for aces is 4 so the first case is 4/52. this is first selection then sencond is 3/51. now both multiplied 4/52*3/51=1/221

Like? Yes (1) | No   

CHANDAN KUMAR   10 years AGO

4c2/52c2=1/221

Like? Yes (1) | No   

Gaurav Sharan   10 years AGO

p(E)= 4C2/52C2
i.e. (4*3/2*1)/(52*51/2*1)=1/13*17= 1/221

Like? Yes (1) | No   

niraj   10 years AGO

6/1326=1/221

Like? Yes (1) | No   

khushboo goenka   10 years AGO

4C2/52C2

Like? Yes (1) | No   

rakesh   10 years AGO

4/52*3*51=1/221

Like? Yes (1) | No   

ayushi   10 years AGO

probability of drawing 2 aces is= 4C2/52C2=1/221

Like? Yes (1) | No   

vaitesh mudaliar   10 years AGO

total no. of outcomes is 52C2.
no. of ways through which we can take out exactly 2 aces from 4 ace cards is 4C2. probability = 4C2/52C2 =1/221

Like? Yes (1) | No   

Shivan kumar jha   10 years AGO

4c2/52c2'
4c2=6
52c2=1326
6/1326=1/221
opction==8

Like? Yes (1) | No   

Riyaz   10 years AGO

probability of getting an ace is 4/52 and getting an other ace is 3/51. so probability of getting 2 aces is 4/52*3/51=1/221

Like? Yes (1) | No   

MD SHAMIM MONDAL   10 years AGO

4C2/(52C2)
there are 4 aces out of which 2 are taken so 4C2
there are 52 card a whole out of which 2 are taken

Like? Yes (1) | No   

RAMAKRISHNA   10 years AGO

p(ace 1)=4/52
p(ace 2)=3/51
p(both are ace)=(4/52)*(3/51)=1/221

Like? Yes (1) | No   

Akash Verma   10 years AGO

4c2/52c2
since first selecting 2 cards of ace from total of 4 aces and as we are selecting 2 cards of total 52 cards
so,, 4c2/52c2=1/221 is the answer

Like? Yes (1) | No   

Chandra chur anand   10 years AGO

probability= (4c2) / 52c2= 1/221

Like? Yes (1) | No   

bhavyasri nunna   10 years AGO

2 ace cards are selected from 4 ace cards so p(ace/total) is 4c2/52c2

Like? Yes (1) | No   

A M ANKIT KALLURAYA   10 years AGO

PROBABILITY=NO OF FAVOURABLE CASES/TOTAL NO OF CASES
=(4/52)(3/21)=1/221

Like? Yes (1) | No   

sachin verma   10 years AGO

selection of 2 aces from 4 aces=4c2
and selection of 2 cards from 52 cards=52c2
so P(E)=4c2/52c2=1/221

Like? Yes (1) | No   

Arijit Acharyya   10 years AGO

(4/52)*(3/51) = 1/221

Like? Yes (1) | No   

Amit Karmakar   10 years AGO

probability = (4*3)/(52*51)
= 1/221

Like? Yes (1) | No   

anjali s   10 years AGO

4 aces,selceting 2 =4C2 /52c2(2 from 52 cards)

Like? Yes (1) | No   

LOKESH KUMAR   10 years AGO

I'm assuming that you are NOT replacing the first card and then drawing the second. For the first card drawn , probability of ace is 4/52. Then for the second card, after the first ace is drawn, there are only 3 aces left out of 51 cards, so probability is 3/51. The probability of performing two independent activities such as this is actually the product of the probabilities:

Like? Yes (1) | No   

Akshay   10 years AGO

(4/52)*(3/51)=1/221

Like? Yes (1) | No   

Deeksha Sharma   10 years AGO

4C252C2=6/1326=1/221

Like? Yes (1) | No   

Santosh Kumar Behera   10 years AGO

Let S sample space then n(S)= 52C2 =(52*51)/2*1=1326

Let E is the getting of Aces 2 out of 4
n(E)=4C2=6
P(E)=n(E)/n(S)=6/1326=1/221

Like? Yes (1) | No   

JILCY J ABRAHAM   10 years AGO

Answer:option 8
If we are not replacing the first card and then drawing the second, the solution is given below.
There are 4 aces out of 52 cards in the packet.
When the first card drawn, the probability of ace is 4/52.then we take the second card ,the probability of getting an ace is 3/51.
The probability of performing two independent activities such as this is actually the product of the probabilities
I.e. (4/52)*(3/51) = (1/13) (1/17)
=1/221

Like? Yes (1) | No   

Sourabh Prasad   10 years AGO

(4C2)/(52C2)

Like? Yes (1) | No   

Naga Divya Peddi   10 years AGO

n(E):aces are 4 from out of 52 cards..so only 2 are drawn
so 4C2
now n(S)=52C2 n now P(E)=n(E)/n(S)
i.e 4c2/52c2=6/1326=1/221
so option is 8

Like? Yes (1) | No   

Hemadri   10 years AGO

n(s)=52C2=1326
n(E)=4c2=6
P(E)=n(s)/n(E)=6/1326=1/221

Like? Yes (1) | No   

Sandeep Kumar   10 years AGO

4/52 * 3/51 = 1/221

Like? Yes (1) | No   

BHASKAR MANDAL   10 years AGO

4c2 / 52c2 = 1/221...option 8

Like? Yes (2) | No (2)  

abhishek narayan   10 years AGO

4c2/52c2=1/221

Like? Yes (2) | No (2)  

bhagya   10 years AGO

probability of ace = 4/52
Then for the second card=3/51
(4/52)*(3/51)
=(1/13)*(1/17)
=1/221

Like? Yes (1) | No (1)  

P.ARUNA   10 years AGO

4c2/52c2
=6/26x51
1/221

Like? Yes (1) | No (1)  

Chandra Bhushan Kumar Dubey   10 years AGO

4C2/52C2=1/221

Like? Yes (2) | No (2)  

ARJUN PRASAD   10 years AGO

4c2/52c2

Like? Yes (2) | No (2)  

Deepak prajapati   10 years AGO

4c2/52c2=1/221

Like? Yes (2) | No (2)  

v pavan   10 years AGO

probability of drawing 1st ace= (4/52)
probability of drawing 2nd ace= (3/51)
total probability= (4/52)*(3/51)

Like? Yes (1) | No (1)  

Abhishek mani   10 years AGO

4c2/52c2
=1/221

Like? Yes (2) | No (2)  

MINTU KUMAR GUPTA   10 years AGO

(4C2)/(52C2)
=1/221

Like? Yes (2) | No (2)  

Biswajit Saha   10 years AGO

(4/c2)/(52c2)=1/121

Like? Yes (1) | No (1)  

prem kumar chaudhary   10 years AGO

4c2/52c2=1/221

Like? Yes (2) | No (2)  

Tark Patel   10 years AGO

( 4 P 2 ) / ( 52 P 2) = ( 4 * 3 ) / ( 52 * 51 ) = 1 / 221

Like? Yes (1) | No (1)  

Rishikesh Ranjan   10 years AGO

4c2/52c2= 1/221

Like? Yes (1) | No (1)  

Arijit Das   10 years AGO

ToTAL NO. OF CARDS= 52
NO. OF ACES= 4

PROBABILTY OF DRAWING 2 ACES= 4C2/52C2 = 1/221

Like? Yes (1) | No (1)  

lakshmi   10 years AGO

probability of ace = 4/52
Then for the second card=3/51
(4/52)*(3/51)
=(1/13)*(1/17)
=1/221

Like? Yes (1) | No (1)  

purushothama   10 years AGO

probability of ace = 4/52
Then for the second card=3/51
(4/52)*(3/51)
=(1/13)*(1/17)
=1/221

Like? Yes (1) | No (1)  

Narasapu Hari prasad   10 years AGO

option 8 is correct
no.of ways of selecting two aces are=4c2=6
no.of ways of selecting 2 cards from 52 cards=52c2=1326
so required probability=6/1326=1/221

Like? Yes (1) | No (1)  

jayalakshmi   10 years AGO

probability of ace = 4/52
Then for the second card=3/51
(4/52)*(3/51)
=(1/13)*(1/17)
=1/221

Like? Yes (1) | No (1)  

bikash tiwari   10 years AGO

4c2/52c2

Like? Yes (2) | No (2)  

APPIKONDA SANTOSH NAIDU   10 years AGO

4c2/52c2

Like? Yes (2) | No (2)  

sanjeev kumar   10 years AGO

And is 8

Like? Yes (1) | No (1)  

CHANDA VIJAYALAKSHMI   10 years AGO

probability of ace = 4/52
Then for the second card=3/51
(4/52)*(3/51)
=(1/13)*(1/17)
=1/221

Like? Yes (1) | No (1)  

nikhil pogale   10 years AGO

probablity=4*3/52*51
= 12/2652
= 1/221

Like? Yes (1) | No (1)  

K.ARun   10 years AGO

4/52 * 3/51

Like? Yes (1) | No (1)  

Ramrup Chatterjee   10 years AGO

(4c2)/(52c2)
=1/221

Like? Yes (2) | No (2)  

SUBHASH TULSYAN   10 years AGO

4c2/52c2=1/221

Like? Yes (1) | No (1)  

RAJEEV RANJAN   10 years AGO

4c2/52c2=1/221

Like? Yes (2) | No (2)  

M CHIRANJIBI   10 years AGO

this is the answer

Like? Yes (1) | No (1)  

poojasaisri   10 years AGO

there are 4 ace cards in pack of 52 cards
probability of taking 2 ace cards =
4c2/52c2=(4*3/2*1)/(52*51/2*1)=1/(13*17)=1*221

Like? Yes (1) | No (1)  

Zameer Khan   10 years AGO

4/52*3/51
=1/221

Like? Yes (1) | No (1)  

Pravallika   10 years AGO

4c2/52c2=3/663=1/221

Like? Yes (1) | No (1)  

himaja   10 years AGO

there are 4 aces
so probability of picking 2 aces = 4/52 + 3/51 = 1/13+1/17 = 1/221

Like? Yes (1) | No (1)  

swarna   10 years AGO

4/52 * 3/51

Like? Yes (1) | No (1)  

Sanu Panji   10 years AGO

For the first card drawn , probability of ace is 4/52.
Then for the second card probability is 3/51.
Total probability = (4/52)*(3/51)= 1/221

So option 8)

Like? Yes (1) | No (1)  

Mani Shankar   10 years AGO

chance of first card being ace is: 4/52,
and chance of being second card ace is: (4-1)/(52-1)
so, 4/52 * 3/ 51 = 1/ 221

Like? Yes (1) | No (1)  

sravani rachakonda   10 years AGO

4c2/52c2=1/221

Like? Yes (1) | No (1)  

Y V S Chandrakanth   10 years AGO

4c2 / 52c2=1/221

Like? Yes (1) | No (1)  

shubham sethiya   10 years AGO

4C2/52C2= 1/221

Like? Yes (1) | No (1)  

Anand Dwivedi   10 years AGO

= 4·3 = 12 = 1
52·51 2652 221

Like? Yes (1) | No (2)  

RAKESH   10 years AGO

P = 4C2 / 52C2 = 1/221

Like? Yes (1) | No (3)  

13 Nov 2014 Area

A circular disc of area 0.49*Pi square metres rolls down a length of 1.76 Km. The number of revolutions it makes is

OPtion

1) 300
2) 200
3) 400
4) 500
5) 600
6) 1600
7) 3000
8) 4000
9) 1400
10)None of these

Solution

Pi*R^2 = .49*Pi
R = 7/10 m.
Circumference = (2* 22/7 * 7/10)m
= 44/10 m
Number of revolution = 1.76*1000* 10/44
= 400

Option 4)

Correct Option: 3 Best Solution (88)

MAHARAJAN.G   10 years AGO

area=pi*r^2=0.49*pi => r^2=0.49 => r=0.7
radius=r=0.7 diameter=r*2=0.7*2=1.4
in here if a disc rotates it moves certain distance that distance is measured as length of disc rotates so
length of disc is=pi*d=distance moved by disc (one revolution)=pi*d=3.14*1.4=4.396
total distance=1.76km=1760m
total revolution=total length crossed/length of one revolution
total revolution=1760/4.396=400

Like? Yes (4) | No (1)  

LOKESH KUMAR   10 years AGO

Area=.49*pi
= radius(r)=.7
=circumference(c)=2*pi*.7
=Total length(l)=1.76*1000=1760
=Number of revolutions=l/c
=(1760)/(2*pi*.7)
=400

Like? Yes (3) | No   

Anand   10 years AGO

pi *r^2=0.49 pi

r=7/10
circumfrence= 2*pi*7/10
=44/10
no of revolution= 1.76*1000*10/40

Like? Yes (3) | No (1)  

Deepak prajapati   10 years AGO

n*(2*pi*r)=1760
by given area we can calculate radius =.7
so n=400

Like? Yes (2) | No   

prem kumar chaudhary   10 years AGO

2*pi*r*n=1.76*1000
r=0.7
n=400

Like? Yes (2) | No   

bikash tiwari   10 years AGO

1.76*10^3/4.396=400.363

Like? Yes (2) | No   

Sravanthi   10 years AGO

Radius=7/10
circumference=2*(22/7)*(7/10)=44/10
number of revolutions=1.76*1000*(10/44)=400

Like? Yes (3) | No (1)  

Gaurav Sharan   10 years AGO

r= 0.7
1.76*1000=(n)*2*(22/7)*0.7
gives n = 400

Like? Yes (2) | No   

pravin   10 years AGO

pi*r^2=0.49pi
r=0.7m
circumference=2*pi*r=440m
no. of revolution=(1.76*1000)/440=400

Like? Yes (2) | No   

Chirag Ranjan Lahiri   10 years AGO

2*pi*r = 2*3.14*0.7 = 4.398m

so, ans will be 1760/4.398 = 400 answer......

Like? Yes (2) | No   

Udhaya kumar   10 years AGO

pi * r^2 = 0.49 pi
r = 0.7
2 * pi * r = 4.4
1760 / 4.4 = 400.....

Like? Yes (2) | No (1)  

ravi prakash   10 years AGO

17600/44

Like? Yes (1) | No   

Arijit Das   10 years AGO

Area of the circular disc= pi*r2= 0.49*pi
therefore, r= 0.7 m
Perimeter of the circular disc = 2*pi*r =2*pi*0.7
=4.39823 m
No. of revolutions it will make= DISTANCE/PEREMETER
=(1.76*1000)/4.39823
=400

Like? Yes (2) | No (1)  

ranjithreddy   10 years AGO

r=0.7meters.
circumfernce+=2*pi*0.7=4.4metres.
no Of revolutions=1.76*1000/4.4=400

Like? Yes (1) | No   

MINTU KUMAR GUPTA   10 years AGO

pi*r^2=0.49*pi
r=0.7m
no of revolution=1.76*1000/(2*pi*0.7)
=400

Like? Yes (2) | No (1)  

Ajinkya Kulkarni   10 years AGO

No of revolution equals to distance divided by perimeter...
1760/(2π*0.7)=400

Like? Yes (1) | No   

Divyank Dubey   10 years AGO

area of circular disc = pi*R^2=.49*pi (given)
so, R=0.7
And distance traveled by disc in 1 revolution=2*pi*R
so if n revolution takes to travel distance=1.76KM
== 1.76*1000=(2*pi*0.7)*n
== n=400

Like? Yes (1) | No   

Rishikesh Ranjan   10 years AGO

r=0.7
no of revolsn=1.76*1000/2pi*.7= 400

Like? Yes (1) | No   

aman   10 years AGO

0.49pi=pi r^2
r=7/10
Circumference =2 pi*r
44/10

Revolution = length in meter/circumference
(1.76*1000)/(44/10) =400

Like? Yes (1) | No   

ARJUN PRASAD   10 years AGO

pi*r^2=pi*0.49
r=0.7
circumference=2*pi*r=1.4*pi
no. of revolution=(1.76*1000)/1.4*pi=400 approx.

Like? Yes (2) | No (1)  

Jabez David   10 years AGO

circular disc of area 0.49*Pi

Pi*R^2=0.49*Pi
R=7/10 m

Circumference= 2*pi*R
=44/10 m

number of revolutions = 1.76*1000*44/10
= 400

Option 3

Like? Yes (1) | No   

Ramrup Chatterjee   10 years AGO

n*2*3.14*.7=1760
so n=400

Like? Yes (2) | No (1)  

abhishek narayan   10 years AGO

area=pi*r^2=0.49*pi
r=0.7
circumference=2*pi*0.7=1.4*pi
no. of turns= (1.76*1000)/(1.4*pi)=400

Like? Yes (1) | No   

Dinesh thatti   10 years AGO

pi r^2=0.49pi = > 49pi/100 * 1/pi = > r =7/10 m
Circumference= 2pir => 2* 22/7* 7/10 =44/10 m

no of revolutions= 1.76*1000*44/10=400

Like? Yes (1) | No   

kamal   10 years AGO

pi*R^2=.49*pi
R^2=.49
R=.7
so circumference = 2* pi * .7=4.4
no of revolution= 1.76* 1000 * 1/4.4=400.

Like? Yes (1) | No   

vikash kumar   10 years AGO

1.76*1000/(3.14*1.4)=400.36=400

Like? Yes (1) | No   

Arijit Acharyya   10 years AGO

pi*r^2 = 0.49*pi
r=0.7
2*pi*r = 2*(22/7)*0.7 = 4.4 m
1.76 km = 1,760 m
the number of revolution it makes = 1,760/4.4 =400 revolutions

Like? Yes (1) | No   

SHIVAM KASHYAP   10 years AGO

radius =7/10,1 revolution=(2*22*7)/7000

Like? Yes (1) | No   

pawan kumar   10 years AGO

radius= 0.7 m
so, perimeter = 22/5 m

hence,
No. of revolution= (1760*22) / 5
= 400

Like? Yes (1) | No   

jagan   10 years AGO

area of disc=.49*pi so r=.7mtr
perimeter of circle=2*pi*r=2(22/7)*.7=4.4mtr
required distance=1.76km=1760mtr
so revolutions=1760/(4.4)=400

Like? Yes (1) | No   

anuj gupta   10 years AGO

400

Like? Yes (1) | No   

gouthamdaneti   10 years AGO

let n be the number of revolutions
1.76 = n*2*.7*Pi/(1000)

Like? Yes (1) | No   

RAMAKRISHNA   10 years AGO

pi*r^2 =0.49 *pi r=0.7 m
circumference=2*Pi*r
n0. of revolutions =1.76*1000*10/44=400

Like? Yes (1) | No   

rahul ranjan   10 years AGO

pi*r2= .49pi
r=.7
circumference=2pi*r=4.4m
no of rool = 1.76km/4.4m= 400

Like? Yes (1) | No   

Chandra chur anand   10 years AGO

pi*r^2=0.49pi
so r=7/10m
now circumference= 2*pi*7/10=2*22/7*7/10
=44/10m
so no. of revolution=1.76*1000*10/44 revolution
=400 revolution...ans

Like? Yes (1) | No   

T.Aravinth kumar   10 years AGO

r=0.7
1.76*10^3/2pi*r=400

Like? Yes (1) | No   

AMREEN   10 years AGO

Area =0.49*Pi
pi*r*r=0.49*pi
r*r=0.49
r=0.7m
let no. of revolution=n
perimeter*n=1.76*1000 m
2*pi*r*n=1.76*1000m
n=400

Like? Yes (1) | No   

aman   10 years AGO

find r, then find circumference then divide it by 1760

Like? Yes (1) | No   

Manjesh   10 years AGO

area = pi *r*r which is equal to .49pi sq. mts
therefore, r=.7
circumfrence =2*pi*r
no of rev= (total length covered /circumfrence)
i.e
17600/(2*pi*.7)=400

Like? Yes (1) | No   

Shivan kumar jha   10 years AGO

3.14*049=3014*0.7*0.7'
r=0.7
so,2*3.14*0.7=(22/5 m area will cover in one round)
1.76*1000(convrt into metre)=1760*5/22=400
option:3(400)

Like? Yes (1) | No   

Manoj Chouhan   10 years AGO

Area πr2 = 0.49*π
r2 =0.49
r = 0.7

One circle of disc will be equal to the circumference.

now, circumference C = 2πr
C = 2*3.14*0.7
C = 4.398 or 4.40

if it has to complete 1.76 km, than divide it ...
1 circle = 1.76 km/4.40
1 circle = 176000 meter/440
= 400 ans (3)

Like? Yes (1) | No   

satyam sharma   10 years AGO

1760/(2*pi*0.7)=400
so correct option is 3

Like? Yes (1) | No   

Vandana Sahu   10 years AGO

1.76*1000/2*.7*pi

Like? Yes (1) | No   

himasnhu joshi   10 years AGO

area =.49*pie
pie*r^2=.49*pie
r=.7
circumference=2*pie*r=2*3.14*.7=4.38m
1 revolution=4.38m
400=1.76km
ans =400
i.e 3)400

Like? Yes (1) | No   

Neha Pandey   10 years AGO

no. of revolutions= total distance/ perimeter of the disc.
perimeter = 2*pi*r
area= pi*r*r
r= 0.7
so, perimeter = 4.4 m

Like? Yes (1) | No   

Manav singh   10 years AGO

r=7/10. then circumference=22/5. now no. rolls= 1760*5/22 gives 400

Like? Yes (1) | No   

A M ANKIT KALLURAYA   10 years AGO

N=1.76/(pi*.49)

Like? Yes (1) | No   

Mani Shankar   10 years AGO

0.49*pi = 2*pi*r^2
so, r = 0.7
thus 2*pi*r * x = 1.76 km = 1760 m
so x = 400

Like? Yes (1) | No   

RAJEEV RANJAN   10 years AGO

(1.76*10^3)/(2*pi*.7)=
=400

Like? Yes (1) | No   

RAKESH   10 years AGO

A = 0.49*Pi m^2 => r = .7m

C = 2*pi* .7 = 4.4m

no. of revo = 1760m / 4.4 = 400 ..........

Like? Yes (1) | No (1)  

Anand Dwivedi   10 years AGO

49/100*pi*1/*= 7/10
2*pi*7/10=44/10
no of revolution = 1.76*1000*10/44=400

Like? Yes (1) | No (1)  

padmaja   10 years AGO

Area=PI*R^2
0.49*Pi =Pi*R^2
R=0.7m or 7/10 m
Circumference=2*Pi*R
=2*(22/7)*(7/10)
=4.4m or 44/10 m
Number of revolutions=1.76*1000*(10/44)
=400

Like? Yes (1) | No (1)  

v pavan   10 years AGO

area=pi*r^2=0.49*pi
solving we get r=0.7
1revolution=2*pi*r
no. of revolutions= 1760/(2*pi*0.7)=400

Like? Yes (1) | No (1)  

Maniratnam   10 years AGO

pi*r^2 = 0.49*pi from this r = 0.7 m, 1 Rev = 4.4 m then 1.76 km = 1760/4.4 there fore 400 revs

Like? Yes (1) | No (1)  

swarupa nuggu   10 years AGO

3

Like? Yes (1) | No (1)  

Manasa Dullur   10 years AGO

Pi * r^2 = .49 Pi = > r = .7,
2Pi* .7*k = 1.76 * 1000, k = 400

Like? Yes (1) | No (1)  

kancharla kavya   10 years AGO

Given area of circular disc is 0.49*pi Sqmts....
so.., pi*r^2 =0.49*pi ;
r^2=0.49;
r=0.7 mts;
Circumference of a circle which makes n revolutions=length it has roll down;
so...2*pi*r*n=l;
Given l=1.76 km;
=1.76/1000
=1760 mts;
Now n= l/(2*pi*r)
=1760/(2*(22/7)*0.7)
=1760/(22/5)
=(1760*5)/22
=400
so number of revolutions is 400....

Like? Yes (1) | No (1)  

SUBHASH TULSYAN   10 years AGO

pie*r*r=0.49*pie
so r=0.7 m
no. of revolution=(1.76*1000)/(2*pie*0.7)
=400.16
=400 (approx)

Like? Yes (1) | No (1)  

Akshay   10 years AGO

pi*r*r=0.49*pi
r=0.7
circumference=2*pi*r=4.4meter
number of revolution=1760/4.4=400

Like? Yes (1) | No (1)  

Md.Sultan Khichi   10 years AGO

Area of circle=.49π
πr^2=.49π
r=.7m
Circumference=2*22/7*.7=4.4m
Revolution=1.76*1000/4.4=400
Ans. On 3

Like? Yes (1) | No (1)  

Parag Wagh   10 years AGO

r=0.7
2*pi*r=4.39
1760/4.39=400

Like? Yes (1) | No (1)  

Abhishek mani   10 years AGO

pi*radius^2=0.49pi*pi sq metre
so,r=0.7
so.circummference=2*pi*r
(1760/2*pi*0.7)
=400

Like? Yes (1) | No (1)  

vaitesh mudaliar   10 years AGO

area = pi*r^2 = 0.49pi so,r= 0.7 m. circumference =2*pi*r ,
length traveled =1760 m.
no. of revolutions = 1760/2*pi*r = 400 revolutions

Like? Yes (1) | No (1)  

subhadeep santra   10 years AGO

pi*r^2=.49*pi=>r=.7;Let n be the no. of revolution .
n*2*pi*r=1.76*1000=>n=400.

Like? Yes (1) | No (1)  

Swagatam Kumar Das   10 years AGO

22/7*R^2=.49*pi
so R is .7
So no of revolutin is1.76*1000/2*pi*.7 =400

Like? Yes (1) | No (1)  

Deb Das   10 years AGO

17600/(2*22/7*7)=400

Like? Yes (1) | No (1)  

Souvik Adhikary   10 years AGO

Pi*r^2=0.49*Pi
r=0.7
2*Pi*r=4.4
no. of revolution =1760/4.4=400

Like? Yes (1) | No (1)  

Jayanta Dutta   10 years AGO

Pi*R^2=.49*Pi
or,R=7/10;


Circumference =2*22/7*7/10;

=44/10;

so revolutions= 1.76*100*10/44

=ans(3) 400

Like? Yes (1) | No (1)  

A SIRISHA    10 years AGO

AREA OF CIRCULAR DISC = Pi*r^2 = Pi*0.49
=Pi*(0.7)^2
so, radius r = 0.7
Distance covered in 1 revolution=circumference =2*Pi*r
= 2*(22/7)*0.7
=4.4m
so no.of revolutions= (1.76*1000)/4.4
=400

Like? Yes (1) | No (1)  

Payal Namdeo   10 years AGO

In 1 revolution=2πr=2*π*0.7=22/5m
No. Of revolution =1760*5/22=400

Like? Yes (1) | No (1)  

sanjeev kumar   10 years AGO

ans 400

Like? Yes (1) | No (1)  

niraj   10 years AGO

1760/4.396=400.02

Like? Yes (1) | No (1)  

Ramesh Sriram   10 years AGO

PI*r2=0.49PI
Number of rolls=(1.76*10000*7)/(2*22*0.7)
=400

Like? Yes (1) | No (1)  

suparna senapati   10 years AGO

pi*r(square)=0.49*pi
r=7/10
circumference=2*pi*r=44/10m
number of revolution=1,76*1000*10/44=400

Like? Yes (1) | No (1)  

NAVEEN KUMAR   10 years AGO

perimeter of circular disc=2*pi*0.7=4.4m

The number of revolutions=1760/4.4=400 option(3)

Like? Yes (1) | No (1)  

Aparna Chakraborty   10 years AGO

pi*r^2 = .49m^2
r= 0.7 m
2pi*r= 4.4m = .0044km
revolutions= 1.76/.0044
=400

Like? Yes (2) | No (2)  

madanpal vishwakarma    10 years AGO

given area of disk= 0.49*pi
so radius of disk =0.7
so circumference of disk= 2*pi*0.7= 4.396(approx)

so to cover 1.7km= 1760m the disk have to revolve =1760/4.396= 400 round

so option 3 is correct

Like? Yes (1) | No (1)  

Shashi nath jha   10 years AGO

ans-400

Like? Yes (1) | No (1)  

pritam banerjee   10 years AGO

pir^2=.49pi so r=.7 so rev=1760/2*pi*.7

Like? Yes (1) | No (1)  

BHASKAR MANDAL   10 years AGO

answer is 400

Like? Yes (1) | No (1)  

kiran chillerge   10 years AGO

w.k.t area=pi*r*r
hence r=0.7
now circumference=2*pi*r
therefore total revolutions=distance covered/circumference
=1.76*1000(in metres)/(2*.7*3.142)
=400(approx)

Like? Yes (1) | No (1)  

Aparna Bhattacharya   10 years AGO

pi*R^2=0.49*pi
R^2=(49*pi/100)*(1/pi)
R=7/10 m
Circumference=(2 * 22/7 * 7/10)m=44/10 m
Number of revolutions=1.76 * 1000 * 10/44=400
Option: 3

Like? Yes (1) | No (1)  

Tark Patel   10 years AGO

Circular disk area = 0.49*pi then

radius = 0.7

2*pi*radius = 1 revolutions

then for 1.76 km total number of
revolutions are = (1.76 * 1000) / (2*pi*0.7) = 400

Like? Yes (1) | No (1)  

CHANDAN KUMAR   10 years AGO

pi*r^2=0.49pi
r=0.7
c=1.4*pi
rev=1760/1.4*pi=400

Like? Yes (1) | No (1)  

Bimal Behera   10 years AGO

circular disc area=pi*r^2
so r=root of 0.49=0.7
then perimeter=28pi*r=2*3.14*0.7=4.4meter
total revolution=(1.76*1000)/(4.4)=400

Like? Yes (1) | No (1)  

ayushi   10 years AGO

since area =0.49 * pi sq m
=> 0.49*pi=pi*r*r;
=> r=0.7
=> perimeter=2*pi*r;
=> =4.396 m;
=> no of revolutions=1.736*1000 m/4.396m;
=> =394.90=400(appro)

Like? Yes (1) | No (1)  

Surit Datta   10 years AGO

according to the problem
π*R*R = 0.49 *π
so R = 7/10 m
so circumference = 2* π*R = 44/10 m
so no of revolutions = (1.76*1000*10)/44 = 400
That's it.

Like? Yes (1) | No (2)  

Anoop Tiwari   10 years AGO

pi*R*R=0.49Pi
R*R=(49pi/100)*(1/pi)
R=7/10
circuumference=2*pi*R=2*22/7**7/10=44/10
no. of revolutions=L/2pi*R=1.76*1000/44/10=1.76*1000*10/44
=400
hence option 3) is correct

Like? Yes (1) | No (2)  

12 Nov 2014 Profit and Loss

If the selling price of 12 article is equal to the cost price of 15 articles, the gain per cent is:

OPtion

1) 25 %
2) 15 %
3) 20 %
4) 30 %
5) 20/3 %
6) 35 %
7) 75 %
8) 40 %
9) 25/3 %
10)None of these

Solution

Let CP of each article be Rs. 1
CP of 12 article = Rs.12, SP of 12 article = Rs.15

Gain = (3/12 *100)% = 25 %

Option 1)

Correct Option: 1 Best Solution (106)

Arijit Das   10 years AGO

Let CP OF 1 ARTICLE= RS.1
THEN CP OF 12 ARTICLES= 12
AND SP OF 12 ARTICLES= 15
GAIN= SP-CP= 15-12=3
GAIN%= (GAIN/CP)*100 %
=(3/12)*100
=25%

Like? Yes (81) | No (23)  

A SIRISHA    10 years AGO

GIVEN THAT
C.P OF 15 ARTICLES = S.P OF 12 ARTICLES
ASSUME
C.P OF 1 ARTICLES =100
C.P OF 15 ARTICLES =1500
SUBSTITUTE IN GIVEN CONDITION
1500 = S.P OF 12 ARTICLES
SO. S.P OF 1 ARTICLE = 125
GAIN % = (G)
= ((S.P - C.P)/C.P)*100
=25
SO, GAIN =25%

Like? Yes (27) | No (9)  

kowsalya devi   10 years AGO

12 S P = 15 C P

S P = 5/4 C P

= 125% C P

profit % = 25 %

Like? Yes (28) | No (14)  

SUBHASH TULSYAN   10 years AGO

12*sp=15*cp
sp/cp=5/4

Gain %=(sp-cp)/cp*100
=(sp/cp-1)*100
=25%

Like? Yes (16) | No (6)  

Gagandeep Singh Chhabra   10 years AGO

Given: 12*(SP)=15*(CP)
12*(CP+P)=15*(CP)
12P=3*CP
P=CP/4
GAIN%=P*100/CP
=CP*100/(CP*4)
=25% Ans

Like? Yes (15) | No (7)  

MINTU KUMAR GUPTA   10 years AGO

12a+ b=15a
b=3a
gain %= 3a/12a*100
=25%

Like? Yes (11) | No (6)  

pravin   10 years AGO

s.p of one article=1/12
c.p of one article=1/15
profit=1/60
profit(%)=25

Like? Yes (8) | No (3)  

rahul singh   10 years AGO

c.p of 15 article=x
c.p of 1 article=x/15
s.p of 12 article=x
s.p of 1 article=x/12
gain=x/12-x/15=x/60
gain(%)={(x/60)/(x/15)}*100=25%

Like? Yes (4) | No   

abhishek narayan   10 years AGO

s.p of 12 article = c.p of 15 article
s.p of 1 article = c.p of 5/4 article.
gain= (s.p - c.p)/c.p
= (5/4)c.p-c.p/c.p
= 1/4.
gain %=25%

Like? Yes (4) | No (1)  

Akshay   10 years AGO

sp of 12 article=cp of 15 article
sp of 1 article =15/12(c)
profit=0.25c
profit=25%

Like? Yes (6) | No (3)  

kuldeep singh   10 years AGO

profit % = (goods left/goods sold)*100

= (3/12)*100

= 25 %

Like? Yes (3) | No   

shree   10 years AGO

15-12=3
12/4=3
25%

Like? Yes (4) | No (1)  

Narasapu Hari prasad   10 years AGO

ans is option 1
let cost price of 15 articals is 150 then cost price of 1 artical is 150/15=10
selling price of 12 articals is 150 then selling price of one artical is 150/12=12.5
selling price of 15 articals is 15*12.5=187.5
profit percentage is 187.5*100/150-100=25%

Like? Yes (5) | No (3)  

Arijit Acharyya   10 years AGO

12*s.p = 15* c.p
s.p/c.p = 15/12
s.p/c.p-1 = 15/12-1
(s.p-c.p)/c.p = 3/12 = 1/4
(s.p-c.p)/c.p *100% = 1/4*100 = 25%

Like? Yes (4) | No (2)  

ARJUN PRASAD   10 years AGO

(15-12)/12*100

Like? Yes (7) | No (5)  

Deepak prajapati   10 years AGO

(((5/4)-1)/1)*100=25%
so option 1 is correct

Like? Yes (6) | No (5)  

Manasa Dullur   10 years AGO

12 s.p = 15 c.p , s.p = (15/12) c.p , gain % =( s.p - c.p ) ×100 / c.p = ( (15/12) -1) ×100 = 25%

Like? Yes (1) | No   

swarupa nuggu   10 years AGO

25%

Like? Yes (2) | No (1)  

Abhishek mani   10 years AGO

(3/12)*100
=25%

Like? Yes (3) | No (2)  

Gaurav Sharan   10 years AGO

gain %= left*100/sold

Like? Yes (2) | No (1)  

bikash tiwari   10 years AGO

actual gain is 3 articles so
3/12*100=25%

Like? Yes (6) | No (5)  

gouthamdaneti   10 years AGO

(15-12/12)*100

Like? Yes (1) | No   

ganesh babu   10 years AGO

gain%= gain/c.p X 100
= 3/12 x 100 (c.p= 12 article, gain= 15 -12 = 3)
=25%

Like? Yes (1) | No   

Mani Shankar   10 years AGO

let cost of one item is 100
so cost of 15 item = 1500 = selling price of 12 item
then selling price of one item is 1500/12 = 125
so gain per is 125 - 100 = 25%

Like? Yes (1) | No   

Amit Neogi   10 years AGO

selling price- cost price=profit
let x be the c.p
x/12-x/15=x/60
for x/15 profit is x/60
100 profit is 25
so, 25%

Like? Yes (1) | No   

Vishal Chugh   10 years AGO

3*100/12==25%

Like? Yes (2) | No (1)  

Satyanarayana   10 years AGO

gain % = (gain/cost)*100;

let 1 artical cost = Rs. 1
12 artical cost= Rs 12
gain % =[ (15-12)/12]*100

= 3*100/12=25%

Like? Yes (1) | No   

Arkja tiwari   10 years AGO

12sp=15cp
profit =sp -cp/ cp%i

Like? Yes (1) | No   

Sravanthi   10 years AGO

Let us assume cost price of 1 article=1rs
cp of 12 =12rs
sp of 12=cp of 15=15
gain=15-12=3
gain %=(3/12)*100=25

Like? Yes (2) | No (1)  

Aparna Bhattacharya   10 years AGO

Let the cost price of 1 article is Rs 1
Cost of 12 articles = Rs 12
Selling price of 12 articles = 15
Gain = 15 - 12 = 3

Gain%=(Gain/Cost∗100)%=(3/12∗100)%=25%
Option: 1

Like? Yes (1) | No   

Anshul Shrivastava   10 years AGO

If C.P. of 1 article is 100
12x100=1200
Now
S.P. of 12 articles = C.P. of 15 article =15x100=1500
1500/12=125
so the answer will be 25%

Like? Yes (1) | No   

K UGESH YADAV   10 years AGO

kjl

Like? Yes (1) | No   

kamal   10 years AGO

12* SP = 15 * CP so that SP/CP=15/12=5/4.
now use formulae 1 + Gain %/100= SP/CP
an you will get % gain= 25 %

Like? Yes (1) | No   

koni   10 years AGO

c.p=1/15,s.p=1/12 then gain=((s.p-c.p)/c.p)*100=25%

Like? Yes (2) | No (1)  

maths hater   10 years AGO

(15-12)*100/12=25

Like? Yes (1) | No   

Prachi Jain    10 years AGO

sp of 1 articles =1/12
cp of 1 articles =1/15
by formula;
gain%=(sp-cp/cp)*100
gain%=( (1/12 - 1/15)/1/15)*100 =25%

Like? Yes (1) | No   

Neha Ashok Jain   10 years AGO

3/12*100

Like? Yes (1) | No   

CHANDAN KUMAR   10 years AGO

let cp 0f 15 article=15
sp of 12 article=12y=15
y=5/4
gain=5/4-1=1/4
gain%=1/4*100=25%

Like? Yes (1) | No   

Shivan kumar jha   10 years AGO

lets
cp of 1 article=100
than cp f 15 article=1500
so
sp of 12article=1500
than 1article=1500/12
than sp of 3article=1500/12*3=375

375/1500*100=25%profit

Like? Yes (1) | No   

AMREEN   10 years AGO

let selling prce of 12 articles and cost prce of 15 article = x rs.
SP of 1 article=x/12
CP of 1 article=x/15
gain % =(SP-CP/CP)/100
gain %=(x/12-x/15)/(x/15)*100
gain %=25%

Like? Yes (1) | No   

Udhaya kumar   10 years AGO

Gain%=(Gain/Cost∗100)%
let gain % = 3/12 * 100 = 25%

Like? Yes (1) | No   

Adithya s   10 years AGO

12 article sp = 15 article cp
so, 15/12 =0.25 , so for 1 article = 0.25 extra for each article , hence 25%

Like? Yes (1) | No   

MANISH KUMAR SINGH   10 years AGO

s.p of 12=c.p of 15
s.p of 1 article=15/12
s.p of 3 article=(15/12)*3=15/4
gain %=(15/4*100)/15
(15*25)/15=25%

Like? Yes (1) | No   

Joyabrata Saha   10 years AGO

Let, x be the cost price of 15 articles & y be the selling price of 12 articles.
Then, the general equation will be,
15*x=12*y
or, 5*x=4*y
or, y=(5*x)/4
So, percentage of profit will be=((((5*x)/4)-x)*100)/x=25%

Like? Yes (1) | No   

harika challagolla   10 years AGO

let cp of 1 article=1
cp of 15 articles=15
cp of 12 articles =12
sp of 12 articles = cp of 15 articles=15
gain percent=(15-12)/12*100

Like? Yes (1) | No   

anupriya sinha   10 years AGO

let c p of one article =1 re
s p of 1 article =15/12 =1.25
profit =s p -c p =1.25 -1 =.25
profit % =profit/c p= .25/1*100
=25%

Like? Yes (1) | No   

aman   10 years AGO

let c.p. of one item be 1rupee.
that means we spend 15 rupees for 15 items.
Also, we get 15 rupees for 12 items, which gives 18.75 rupees for fifteen items.
After simple calculation 25% is answer.

Like? Yes (1) | No   

rahul ranjan   10 years AGO

let cp of 1= rs10
cp of 15=150
sp of 12=150
sp of 1= 150/12
profit= sp-cp that is 150/12-10= 2.5
profit %= profit/cp * 100= 2.5/10 * 100 = 25%

Like? Yes (1) | No   

vishal kumar   10 years AGO

(100/12-100/15)/(100/15)*100=25%
so correct option is 1

Like? Yes (1) | No   

himasnhu joshi   10 years AGO

s.p of 12 article=cp of 15 article
sp of 1 article=15/12 = 5/4

we know that
sp=(gain%+100)/100*cp
5/4 *cp= (gain%+100)*cp
5/4*100=gain%+100
gain%=25%

Like? Yes (1) | No   

ajay kushwaha   10 years AGO

(15-12)/12=.25
.25*100=25%

Like? Yes (1) | No   

aman   10 years AGO

C.p of 15 arti 15x
C.p of 12 arti 12x

S.p of 12 arti equal to c.p of 15 arti
Sp of 12 arti = 15x
(15x-12x)/12x * 100 = 25%

Like? Yes (1) | No   

Olivia Dutta   10 years AGO

s.p =15
c.p=12
profit %= 3/12*100%
=25%

Like? Yes (1) | No   

sandeep kumar   10 years AGO

12 S.P= 15 C.P



GAIN %= 100(S.P/C.P-1)



%GAIN = 100*3/4 = 25%

Like? Yes (1) | No   

poojasaisri   10 years AGO

if cp of x articles=sp of y articles then
if x>y then gain percent=x-y/y% is made
here x=15 , y=12 =>x>y
therefore (15-12)/12=1/4%=25%

Like? Yes (1) | No   

rakesh kumar   10 years AGO

(m-n/n)*100
m=cp
n=sp

Like? Yes (1) | No   

Priya Patidar   10 years AGO

cp of 1 article= re 1
cp of 12 article = 12
sp of 12 article = cp of 15 article = 15
(15 *100)/12= 100+gain

Like? Yes (1) | No   

jagan   10 years AGO

if cost price of 12 articles 12rs
then s.p of 12 articles 15rs
so profit is 3 rs
so gain %=(gain*1oo)/c.p (3*100)/12=25%

Like? Yes (1) | No   

Tark Patel   10 years AGO

Let Selling Price of 12 articles = Cost Price of 15 articles = x

Selling Price of 1 article = x/12
Cost Price of 1 article = x/15

Gain per cent,

= ( ( (x/12) - (x/15) ) * 100 )/ (x/15)

Solving this we get 25%

Like? Yes (2) | No (1)  

Sanu Panji   10 years AGO

Say selling price of 12 article = cost price of 15 articles = x
so gain = x*(15-12)/12 = x/4
so, parcentage gain = {(x/4)/x}*100 = 25%

option 1 is correct

Like? Yes (2) | No (1)  

Vipul Pophale   10 years AGO

SP 12 = CP 15
since we know that gain % = (SP-CP)/CP*100 or (SP/CP-1)*100
from above relation SP/CP=15/12 so,
gain% = (15/12-1)*100 = 25

Like? Yes (1) | No   

sakshi gupta   10 years AGO

let cp of 1 article be 1/-
then cp of 15 articles=15/-
and cp of 12 articles=12/-
nw sp of 12 articlees=cp of 15 articles
=15/-
thus we have profit of 15-12=3/-
profit%=3/12*100=25%

Like? Yes (1) | No   

sahil sood   10 years AGO

let the cp of each piece be x
then the gain woud be 3x
hence gain% is 3x/12x*100=25%

Like? Yes (1) | No   

santu ghosh   10 years AGO

let,selling price of 12 article=x
so,selling price of 1 article=x/12
&cost price of 1 article =x/15
so,gain per cent=((x/12-x/15)/(x/15))*100%=25%

Like? Yes (1) | No   

pawan kumar   10 years AGO

gain%= [(X/4)*100] / X
= 25%

Like? Yes (1) | No   

karuna   10 years AGO

s/c= 5/4
s=(5/4) c
s=1.25 c
= 25%

Like? Yes (1) | No   

Sameer gupta   10 years AGO

12SP=15CP..............(1)
PROFIT%=SP-CP/SP*100
SO, TAKE CP COMMON THN CP((SP/CP)-1)/CP*100
THN ((SP/CP-1))*100................(2)
FROM 1
SP/CP=15/12.........PUT THIS IN (2)...AND GET ANSWER

Like? Yes (1) | No   

Sandeep Kumar   10 years AGO

15 - 12 = 3
so profit % = 3*100/12 = 25 %

Like? Yes (1) | No   

Anusha   10 years AGO

12s.p.=15c.p.
s.p./c.p.=15/12
=1.25
25 %gain

Like? Yes (1) | No   

Chirag Ranjan Lahiri   10 years AGO

let cp of 1 article be Re.1
cp of 12 articles=Rs.12
sp of 12 articles=cp of 15 articles=Rs.15
%p=(3/12)*100=25%
so option 1.....

Like? Yes (2) | No (1)  

kaushik Gopireddy   10 years AGO

(15x-12x)/12x = 1/4 = 25%

Like? Yes (2) | No (1)  

Ravi nishad   10 years AGO

C.P OF 12 ARTICLE = 12
S.P OF 15 ARTICLE = 15
GAIN = S.P - C.P
= 15 - 12
= 3
GAIN% = GAIN*100/C.P
= 3*100/12
= 25%

Like? Yes (2) | No (1)  

Parag Wagh   10 years AGO

(3/12)*100=25%

Like? Yes (1) | No   

RAKESH   10 years AGO

(15-12) / 12 * 100

= 3/12 * 100 = 25%

Like? Yes (2) | No (2)  

ravi prakash   10 years AGO

profit=75/4-15
profit will be 15/4
cp =15

profit%= 100/4
=25%

Like? Yes (2) | No (2)  

BHASKAR MANDAL   10 years AGO

sp : cp = 12:15 = 4:5

profit % = ((sp-cp) / cp) * 100 = (5-4)*100 / 4 = 100 / 4 = 25%
so option 1 is the correct answer

Like? Yes (3) | No (3)  

Md.Sultan Khichi   10 years AGO

Let the cp of obe article is x.
Selling price of one article =15*x/12
Profit=15x/12-x=3x/12
Profit%=(3x/12)*100/x=25
Ans on 1.

Like? Yes (2) | No (2)  

prem kumar chaudhary   10 years AGO

let cp of 15 article =15 then
sp of 12 article=15 then
gain =15/12-1=3/12
gain%=1/4*100=25

Like? Yes (4) | No (4)  

sanjeev kumar   10 years AGO

25

Like? Yes (2) | No (2)  

alok meher   10 years AGO

let c.p. of 1 article = 12 Rs
so,c.p of 15 article = 12*15=180
so, s.p of 12 article = 180
s.p of 1 article =180/12=15
here profit = s.p of 3 article
so, profit=3*15=45
now, profit % =(45/180)*100=25%

Like? Yes (5) | No (5)  

veena vyas   10 years AGO

(3*100)/4 = 25
gain is 15 - 12 =3 so % gain will be 25%

Like? Yes (3) | No (3)  

Swagatam Kumar Das   10 years AGO

the gain per cent is (15-12)/12*100 =25%

Like? Yes (2) | No (2)  

Sukanya   10 years AGO

profit %= 15-12/12*100=25%

Like? Yes (3) | No (3)  

Himanshu Srivastava   10 years AGO

let selling price is 5 rs
total selling price=60
cost price =60
so cost price of 1 item =4
gain=(5-4)/4*100=25%

Like? Yes (1) | No (1)  

neda df   10 years AGO

3/12=X/100--->X=25

Like? Yes (2) | No (2)  

kancharla kavya   10 years AGO

Given 12 S.P= 15 C.P
so gain percent = (s.p-c.p)/c.p*100;
i.e.., Gain percent for 12 articles is
( 12 S.P- 12 C.P)/12 C.P *100 =
(15 C.P- 12C .P)/12 C.P *100
=
3 C.P/12 C.P *100
=
1/4*100
=
25%
So, gain percent is 25%

Like? Yes (1) | No (1)  

PAWAN KUMAR   10 years AGO

We have, S.P. of 12 items = C.P. of 15 items
i.e., S.P. of 1 item = C.P. of 1.25 items
Let the Cost Price of 1 item be Re 1.
Then, S.P. of 12 items = 12*1.25 = Rs 15
Gain% = {(15-12)/12}*100 = 3*100/12 = 25% Ans.

Like? Yes (1) | No (1)  

Dinesh thatti   10 years AGO

let each article be 1/-
Cp of 12 articles = 12 /-
Sp of 15articles = 15 /-

Gain %= 3/12*100=25%

Like? Yes (2) | No (2)  

prasad   10 years AGO

s.p of 1 art=x/12
cp of 1 art=x/15
profit=((x/12-x/15)/(x/15))*100=25%

Like? Yes (3) | No (3)  

Ajinkya Kulkarni   10 years AGO

3/12*100=25%

Like? Yes (2) | No (2)  

tirupathi reddy   10 years AGO

Let the c.p of one article is 1/-
C.p of 12 articles is 12 /-
S.p of 12 articles is 15/-
Profit= (3/12)*100= 25%

Like? Yes (1) | No (1)  

Prakash kumar Pariari   10 years AGO

since the money spent is equall to the money earned .the percentage of profit is given by % profit=goods left/goods sold*100=3/12*100=25%

Like? Yes (2) | No (2)  

Aman   10 years AGO

If cost of one articlke is x, then CP of 12 items =12x
sp of 12 items =15 x
% age gain = 100*(15-12)/12=25%

Like? Yes (2) | No (2)  

RAMAKRISHNA   10 years AGO

Let the cost price of 1 article is Re 1
Cost of 12 articles = Rs 12
Selling price of 12 articles = Rs 15
Gain = 15-12 = 3

Gain%=(Gain/Cost∗100)%=(3/12*100)=25 %

Like? Yes (1) | No (1)  

byreddy anuradha   10 years AGO

profit=(s-c)*100/c

Like? Yes (1) | No (1)  

Jayanta Dutta   10 years AGO

12 articl gives 3
1 givs 3/12
100 givs 3*100/12

Like? Yes (2) | No (2)  

khushboo goenka   10 years AGO

let cp=y
12 sp=15y
12(y+profit)=15y
profit=y/4

Like? Yes (1) | No (1)  

NAVEEN KUMAR   10 years AGO

(3/12)*100=25%

Like? Yes (1) | No (1)  

padmaja   10 years AGO

let cost of one article is 1rs
then c.p of 15 articles=s.p of 12 articles
so sp of 12 articles=15
cp of 12 articles=12
so gain%=(gain/cp)*100
=(15-12)/12)*100
=(1/4)*100
=25%

Like? Yes (1) | No (1)  

abhishek   10 years AGO

(15-12)*100/12
=20%

Like? Yes (1) | No (1)  

Jagruti   10 years AGO

let CP of 1 article = 1
therefore, CP of 15 articles = 15
SP of 12 articles = CP of 15 articles = 15....(1)

Now CP of 12 articles = 12
And SP of 12 articles = 15....(by 1)

Hence,Profit = SP-CP = 15-12 = 3
% profit = 3/12*100 = 25%

Like? Yes (5) | No (5)  

Manish Singh   10 years AGO

Let the cost price of 1 pen is Re 1
Cost of 15 article = Rs 15
Selling price of 12 article =Rs 12
Gain = 15 - 12 = 3

Gain%=(Gain/Cost)∗100)%=(300%12)%=25%

Like? Yes (4) | No (4)  

Chandra chur anand   10 years AGO

gain %={(15-12)/12}*100%
=25%

Like? Yes (1) | No (1)  

Hemavathy Nangan   10 years AGO

((15-12)/3)*100
=25%

Like? Yes (1) | No (1)  

MRITUNJAY   10 years AGO

gain=sp-cp
=sp of 12 article-cp of 12 article
=1-12/15=3/15
gain%=gain*100/cp
=3/15*100/12/15=25%

Like? Yes (1) | No (1)  

Sahil Nagpal   10 years AGO

Gain profit=(Selling price*cost price)/cost price*100

Like? Yes (1) | No (2)