Users Discussion Board

Animesh Mogha 4 years ago

University of Vikram has enrolled nine Phd candidates.Babu Chitra,Dheeraj , Eesha,Farooq,Gowri , Hameed,Iqbal,Jacob.
-Farooq and Iqbal were enrolled on the same day as each other, and no one else was enrolled that day.
-Chitra and gowri were enrolled on the same day as each other, and no one else was enrolled that day.
-On each of the other days of hiring , exactly one candidate was enrolled.
-Eesha was enrolled before Babu.
-Hameed was enrolled before Dheeraj
-Dheeraj was enrolled after Iqbal but before Eesha
- Gowri was enrolled after both Jacob and Babu
-Babu was enrolled before Jacob
Who were the last two candidates to be enrolled?

Reply Like? Yes (1) | No

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Deekshitha 4 years ago

New Public School has a circular layout. The school has teachers specializing in various subjects. All

classrooms of the school are equally spaced apart and located along its perimeter. Each teacher needs

to take 4 classes in a day. There is a strange rule. The first and last class has to be in the same class

roun. The other two classes have to be at two other distinct class rooms.

Ram is a math teacher. He never teaches two successive classes at two adjacent classrooms. How many distinct trips to class rooms are possible for Ram if there are 9 class rooms in the school?

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Varun 4 years ago

In a day
First & last room should be same
Let's choose it arbitrarily, next class can be chosen in 6 ways
Because same room cannot be chosen & neighboring rooms are also not allowed
Round represntations of class: 1 2 3 4 5 6 7 8 9. 1....

Let first one be 1
Then second can be 3 4 5 6 7 8
For 3, third class can be any of 5 6 7 8
For 4, third class can be any of 2 6 7 8 9
For 5, third class can be any of 2 3 7 8 9
For 6, third class can be any of 2 3 4 8 9
For 7, third class can be any of 2 3 4 5 9
For 8, third class can be any of 2 3 4 5 6
For 9, third class can be any of 2 3 4 5 6 7
And fourth class will be again 1

So total possible classes keeping first class constant is: (4)+(5*5)+(6) = 35

Similarly first class can be changed in 9 ways => Total possible trips per day = 9*35 = 315

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yarram poorna sahiti to SHIVENDRA PRATAP SINGH 4 years ago

sir please guide me how to solve

Reply Like? Yes | No (1)

Pargat Pal Singh 4 years ago

Please check puzzle dated 14.06.2021

If the capacity of a cylindrical tank is 4004 m^3 and the diameter of its base is 14 m, then find the depth of the tank?

Solution given is
Let the depth of the tank be h meter
πr²h = 4004
h = 4004/ πr²
h = (4004 x 7/22 x 1/14)
h = 91 m.

I think admin has considered 2r =14 only in place of r^2 ( 7^2).

It should be

Let the depth of the tank be h meter
πr²h = 4004
h = 4004/ πr²
h = (4004 x 7/22 x 1/49)
h = 26 m.

Please check and do justice to maths.

Reply Like? Yes (1) | No (2)

Deepna D.P 4 years ago

Identify which security threat can occur because of typing error on the network site

Reply Like? Yes (1) | No

~Sandeep~ 4 years ago

Typosquatting attack

Like? Yes (1) | No

Sunny Mannepalli 4 years ago

Amansells12candiesforRs.12&losesRs.2.40.Ifhesells12candiesforRs.16,howmuch
doeshegainorlose?
a.GainsRs.4
b.LosesRs.6
c.GainsRs.6.40
d.LosesRs.1.60
e.GainsRs.1.60

Reply Like? Yes | No

Devendra Marghade 4 years ago

For 12 candies, when SP=Rs 12, Loss is Rs 2.4 , So CP=12+2.4=Rs 14.4
Hence Gain, when he sells 12 candies for Rs 16 = SP - CP = 16 - 14.4 =Rs 1.6
Option e)

Like? Yes (1) | No

saran 4 years ago

f I sell two articles, one at 20% profit for Rs.100 and the other at 20% loss for Rs.100, what is my net profit/loss?

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Pargat Pal Singh 4 years ago

CP = 83.33+125 = Rs. 208.33
Loss = Rs. 8.33

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Pargat Pal Singh 4 years ago

Dear Admin,
Is there any chance of fair evaluation of scores or results are pre-decided to give prizes to a few privileged members ?

Reply Like? Yes (3) | No (2)

Karan 4 years ago

No chance. I think Admin team is working from home. :)

Like? Yes (3) | No

Pargat Pal Singh 4 years ago

In today's puzzle dated 5-5-21, I have answered option 5 as answer which is shown as 5 in my home page of m4maths. But marks given are -1 .
Please check.

Reply Like? Yes (4) | No (2)

Harsha 4 years ago

With 4/5 Full Tank

Reply Like? Yes | No

Pargat Pal Singh 4 years ago

In today's puzzle dated 5-5-21, I have answered option 5 as answer which is shown as 5 in my home page of m4maths. But marks given are -1 .
Please check.

Reply Like? Yes (3) | No (1)

Pargat Pal Singh 4 years ago

If admin is not ready to check and take corrective action for yesterday puzzle , it is better to stay away from today's puzzle as a mark of protest.

Like? Yes (1) | No (3)

Sunil 4 years ago

20 people going to one temple,they want rs 20.for men rs 3,women rs 2,children 50 paisa,how much money spent for men,women,children?

Reply Like? Yes | No

G.S.Kantharao 4 years ago

Let men,Women are =x,y respectively
Then children are =(20-x-y)
Then amount=
3x+2y+(20-x-y)/2=20
6x+4y-x-y=20
5x+3y=20
For the Natural Numbers N (x,y)=(1,5)
So men =1
Women =5
Children =14
Expenditure=1*3+5*2+14*0.5=20

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Ishfaq Ahmad to Devendra Marghade 4 years ago

A train passes a standing man 11.3 seconds and passes a bridge of length 396m in 18 seconds .the speed of the train is

Reply Like? Yes (1) | No

Devendra Marghade 4 years ago

Let the speed of the train be x m/sec and length of the train be y m, then y/x=11.3 or y - 11.3x = 0 --(i)
Also, (y + Length of platform)/x=18
(y+396)/x=18 => 18x-y=396 ---(ii)
Solving (i) & (ii), we get, x=59.10 and y=667.88
Hence speed of the train is 59.10 m/s

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Ishfaq Ahmad 4 years ago

When you keep believing, keep trying and keep doing... Someday, you will succeed.

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Shubhashish Sinha 4 years ago

Find the elements in the relation "have the same remainder when divided by 8" if the
relation is defined on {1, 2, 3 .... 24, 25}. Also, find the distinct equivalence classes
of this equivalence relation.

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Sai laxmi Nomula 4 years ago

the average number of people visitedredfort on every day is 2240.but 2200 on every saturday, 3000 on sunday and on wednesday it is 1500people visited . what is the average number of people visited on remaining days in the ,month of december when there are 4 thursdays abd 4 mondays in the month?

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G.S.Kantharao 4 years ago

Average Visited in December = 2240
Then total visitors = 2240*31 = 69440
As there are 4 Thursdays and 4 Mondays the other 3 are Sunday,Friday and Saturday. It means 5 Sundays 5 Fridays and 5 Saturdays
It means 5*2240+5*2200+5*3000=11200+11000+15000=37200
Remaining=69440-37200=32240
Average of remaining=32240/16=2015
So Average =2015

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allam vishwaja 4 years ago

help me for placements

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rohit ranjan 4 years ago

please give more details ?

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"> 4 years ago

hero
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"> 4 years ago

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

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karthik 4 years ago

Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?

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naveen 4 years ago

Long ago a princess wanted

Reply Like? Yes | No (2)

nandy ram 4 years ago

during a period of decline in a stock market prices a stock sold at ₹50/share on the first day,₹40/share on the second day and ₹25 on the third day.If a invester bought 100,120&180 shares on the respective 3 days the average price paid per share will be?.

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Devendra Marghade 4 years ago

Avg. Price = (100*50 + 120*40 + 180*25) / (100+120+180) = 35.75

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Karakavalasa sai manohar 4 years ago

Help me to get score in tcs nqt 2021

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TAVVA PAVAN KUMAR 4 years ago

On Feb 18 I have TCS NQT can some one help me friends

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Meghavath Madhu Naik 4 years ago

A man sets out by cycle from Delhi to Rohtak, and at the same time another man starts from Rohtak by cycle to Delhi. After passing each other they complete their journeys in 3 1/3and 4 4/5 hours respectively. At what rates does the second
man cycle if the first cycles at 8 km per hour?

Reply Like? Yes | No

G.S.Kantharao 4 years ago

Let A and B are the persons.
A travelled x km,B travelled y km before they meet.
Time taken for A and B to reach their destinations are 10/3h,24/5h
Speeds are y/(10/3),x/(24/5)
At the time they meet they travelled same time => x/(3y/10)=y/5x/24)
10x/3y = 24y/5x=>50x^2=72y^2
=>x^2/y^2=72/50
x/y=√(1.44)=1.2
=>x=1.2y
Total distance =(x+y)=(x+x/1.2)=2.2x/1.2=11x/6
Now time taken for B=(11x/6)/(5x/24)
=11*24/6*5=44/5=8h 48m

Like? Yes (4) | No

JACK KISSER 4 years ago

ORDER RESEARCH CHEMICALS FROM https://www.highgradeschemicals.com/

Reply Like? Yes (1) | No (1)

Amanjot kaur Saroa 4 years ago

If the sum of the first 43 terms of an arithmetic progression is 2967, then find the sum of the 11th and the 33rd terms of the same series.

Reply Like? Yes | No

Varun 4 years ago

First term = a, Number of terms=n, Difference = d
nth term = a+(n-1)d
11th term = a+10d, 33rd term = a+32d
Sum of 11th & 33rd= 2a+42d = 2(a+21d)=2(22nd term)

Middle term = Total sum/n
43/2 th term = 22nd term = 2967/43 = 69

=>Sum of 11th & 33rd = 2(69) = 138

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G.S.Kantharao 4 years ago

Sum of first 43 terms in A.P=43(2a+42d)/2=2967
11th term +33rd terms =(a+10d)+(a+32d)=(2a+42d)
43(2a+42d)/2=2967=>(2a+42d)=2967*2/43=138

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Amar Kumar Yadav 4 years ago

solution of quastion

Reply Like? Yes | No (1)

Renu 4 years ago

Keshav runs a factory of 210 employes in each 3 shift 80 emp are required no one is allowed to work more than 16 hrsin a day how many emp are required to work 16 hrs in a day

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Varun 4 years ago

80*3 = 240 employees needed
We have 210
So 240-210 = 30 employees need to work double shift
Cross check: 180*8+30*16=1920 hours
240*8 = 1920 hours
So 30 is the answer

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naurah 4 years ago

We know that the vertices of a quadrilateralare 2, 3, 5, and 6 cm, respectively,from a point P. What is the largest possible area of this quadrilateral?

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Varun 4 years ago

Lets divide the area into 4 triangles
Area of triangle = 1/2 * base * height
So total area for right angle triangles are:
0.5*(2*3+3*5+5*6+6*2) = 31.5cm^2
If we diminish or expand any of the portions we eventually fall into same bucket I guess, so I think 31.5cm^2 should be the answer, all suggestions are welcome. Thanks.

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PRATIBHA PRAKASH GAVANALE 4 years ago

give me apportunity

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Varun 4 years ago

What exactly apportunity means? Can you be more specific?

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DIVYADEEP 4 years ago

Twenty five sets of problems on Data Interpretation– one each for the DI sections of 25
CATALYST tests were prepared by the AMS research team. The DI section of each CATALYST
contained 50 questions of which exactly 35 questions were unique, i.e. they had not been used in
the DI section of any of the other 24 CATALYSTs. What could be the maximum possible number
of questions prepared for the DI sections of all the 25 CATALYSTs put together?
(Can anyone help by explaining the solution to this question)

Reply Like? Yes | No

Varun 4 years ago

Let me try to understand the question:
25 set of papers
50 in each with 35 distinct questions
Did I understand the question correctly?

If yes, the answer is: 35*25 = 875 questions.

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Fatima Rahim 4 years ago

Why 0!=1 ?
Please help me

Reply Like? Yes | No

Devendra Marghade 4 years ago

n! = n*(n-1)!
1! = 1*(1-1)!
1! = 1*0!
As 1! = 1, hence 0! = 1

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Billal Hossain 4 years ago

We know that n! = n(n-1)(n-2)(n-3).....3(2)(1) which means that
n! = n(n-1)!
Dividing both sides of the equation by n, we have
(n - 1)! = n!/n
Using this fact, we can check the following pattern.
4! = 5!/5 = {(5)(4)(3)(2)(1)}/5 = 24
3! = 4!/4 = {(4)(3)(2)(1)}/4 = 6
2! = 3!/3 = {(3)(2)(1)}/3 = 2
1! = 2!/2 = {(2)(1)}/2=1

Now, we go to 0!
0! = 1!/1 = 1

Like? Yes (1) | No

Asif iqbal Chaudhry 4 years ago

Like and subscribe my Youtube channel
Asif Iqbal
Maths class 10th and 9th Lectures
https://youtu.be/s7qPmsPs5bA

Reply Like? Yes (1) | No

Neha PARMAR 4 years ago

Ten years ago,the average of family of four members was 24 years.Three children having been born,the average age of family is same today.What are the present ages of children if two children are identically twins and differ by two years from the younger one?

Reply Like? Yes | No

AMIT GARG 4 years ago

24×4 =96 + 4×10 = 136
current age = 24×7 = 168
hence children age = 32
2A + A - 2 = 32
A = 34/3 = 11.33 not possible
data is wrong as child can not be older than 10 years

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ritik rathore 4 years ago

hi ,my self Ritik Rathore want to place in a core organisation of civil engineering and groom my self .

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alister james 4 years ago

Hi, my name is Alister james lives in Delhi and doing my education in creativethinksmedia want to become an engineer.

Reply Like? Yes (1) | No

vuresakuntala 4 years ago

hello my name in vuresakunthala iam teacher in private school now free because corona holidays now i need job at home any on help me thq

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Lisha 4 years ago

here are 20 balls which are red, blue or green. If 7 balls are green and the sum of red balls and green balls is less than 13, at most how many red balls are there?

Reply Like? Yes | No

AMIT GARG 4 years ago

7 balls are green
sum of red balls and green balls is less than 13
7 + R < 13
=> R < 6
Hence at most 5 red balls are there

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priyanshu mandil 4 years ago

if the tank is half fulled and set X and set Y are closed how many minutes will it take for set Z to empty the tank if alternate taps of set Z are closed

Reply Like? Yes | No

AMIT GARG 4 years ago

X, Y & Z details missing

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Bargavi 4 years ago

The number of 5-digit numbers that can be formed from 4,2,0,7 and 3

Reply Like? Yes | No

kishor 4 years ago

5! is the answer

Like? Yes | No (2)

tej 4 years ago

4*5*5*5*5 bcoz 0 cant be at first place

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AMIT GARG 4 years ago

Assuming repetition allowed - 1st Digit can be in 4 ways - Rest 4 can be in ways Hence 4*5*5*5*5 = 2500
Assuming repetition mot allowed = 4*4! = 4 * 24 = 96

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YUVANSANKAR 4 years ago

What is the referral code

Reply Like? Yes | No

ansh 5 years ago

please help me in tcs nqt 2021

Reply Like? Yes (2) | No

ragavan 5 years ago

got placed in infosys

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lakshmi 5 years ago

Three marketers distribute their products in a colony for pilot testing. Marketer A distributes
150 Items to the people equally and then was left with a few items. Marketer B distributes 270
Items to the people equally and then was left with the same number of Items as the number left
with Marketer A. Marketer C distributes 320 items to the people and is left with the same
number of items as the number left with Marketer A. What is the maximum possible number of
people in the colony?

Reply Like? Yes (1) | No

G.S.Kantharao 5 years ago

Let q are the no of people
150=aq+r----(1)
270=bq+r----(2)
320=cq+r-----(3)
Eqn. 2 -1=q(b-a)=120
Eqn.3-2=q(c-b)=50
Eqn.3-1=q(c-a)=170
H.c.f of all these is 10
Hence the members are 10.

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meenakshi 5 years ago

A ball is dropped from a height of 144 m and it rebounds to two thirds of the height from which it falls. if it continues to rebound, what distance will the ball have travelled before coming to rest?

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Vipul Chavan 5 years ago

Thanks m4 maths for helping to get placed in several companies.
I must recommend this website for placement preparations.

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