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Balajikrishnan GS 5 years ago

where should i start to prepare for aptitude?

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Anindya Adhikary 5 years ago

if y = log x(1+x), then x = ?

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Sujon Ahmed 5 years ago

The price of sugar increases by 20%, by what % should a housewife reduce the consumption of sugar so that expenditure on sugar can be same as before?

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Devendra Marghade 5 years ago

16.66%

Let initial consumption=100 & price=100, then expenditure=100*100=10000
If new consumption=x & price=120, then for same expenditure, 120x=10000
=> x=83.33
So, % reduction=100-83.33=16.66

Like? Yes (1) | No (1)

Ronak to Devendra Marghade 5 years ago

the students of a class appeared for an exam which had 200 questions. Each correct answer was awarded 2 Marks and for each wrong answer one-third of a mark was deducted. two student answered all the question in it. the first student got the maximum possible marks and the second student got 175 marks less than him. find the number of questions correctly answered by the second student. 1)115 2)125 3)135 4)145 ) none of.
Please solve

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Devendra Marghade 5 years ago

2) 125

Maximum possible marks, 1st student got = 2*200 = 400
.'. Marks of 2nd student = 400 - 175 = 225
Let for 2nd student, correct answers=x and wrong answers=y
Then, x + y = 200 ---(i) and 2x - y/3 = 225 ---(ii)
Solving equation (i) & (ii), we get x=125, y=75
Hence, 2nd student solved 125 correct answers.

Like? Yes (3) | No

Sahithi Bhimavarapu 5 years ago

In a game of 80 points, A can give B 5 points and C 15 points. then how many points B can give C in a game of 60?
Devendra can you give brief Sol for this

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Ronak to Devendra Marghade 5 years ago

Two cars starts from point A and B to B and A respectively. They cross each other in 1.2 hour and the first car reaches A at 1 hour before the second car reaches B. If the distance between A and B is 50 km, what is the speed of the slower car? 1)20km/hr 2) 10km/hr 3)15km/hr 4)25km/hr........ Which is correct questions in both of. Please solve if any is correct please 🙏😊

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Devendra Marghade 5 years ago

Speed of the slower car=16.66 km/hr

Let the speed of the car starting from point A and B be a and b km/hr.
Given, car starting from B reaches A, 1 hour early => Car starting from A is slower, so we have to find 'a'
As car cross each other in 1.2 hrs => 50/(a+b) = 1.2 => a+b = 125/3 ---(i)
Time difference of cars reaching B and A = 50/a - 50/b = 1 ---(ii)
Now substituting, b=125/3 - a from eqn. (i) into (ii), we get 3a² - 425a + 6250 = 0 ---(iii)
(3a-50) (a-125) = 0
a=50/3, a=125, (Ignoring a=125 as with this speed two cars cann't cross each other in 1.2 hrs)
Therefore, speed of slower car=50/3=16.66 km/hr and faster car=25 km/hr.

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Ronak to Devendra Marghade 5 years ago

Two cars starts from point A and B to B and A respectively. They cross each other in 1 hour and the first car reaches A at 5/6 hour before the second car reaches B. If the distance between A and B is 50 km, what is the speed of the slower car? 1)20km/hr 2) 10km/hr 3)15km/hr 4)25km/hr

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Ronak to Devendra Marghade 5 years ago

Sheela, Sandhya and jyotsna can type a page in in 10, 15 and 18 minutes respectively. they decided to work together for equal time to type a document which contains 980 pages. how many pages are typed by jyotsna ? 1)280 2)275 3)245 4)350 5)none

Reply Like? Yes | No

Devendra Marghade 5 years ago

3) 245

In 1 min, individually Sheela, Sandhya and Jyotsna can type 1/10, 1/15, 1/18 pages respectively.
Together in 1 min they can type 1/10 + 1/15 + 1/18 = 2/9 page.
For 980 pages time required = 980/(2/9) = 4410 min.
So, pages typed by Jyotsna in 4410 min = (1/18)*4410 = 245

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Ronak to Devendra Marghade 5 years ago

vimal alone can do a piece of work in 36 days. the time taken by vimal in completing 1/6th of the work equals the time taken by Gopi to complete 2/5th of the same work. in how many days can they both complete the work if they work together?

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Devendra Marghade 5 years ago

10 (10/17) days

Days required by Vimal=36. So Vimal can complete 1/6 of the work in (1/6)*36=6 days.
If Gopi takes 'x' days for same work, then days required for 2/5 of work=2x/5=6
=> x=15
Thus 1 day's work of Vimal & Gopi = 1/36 + 1/15 = 17/180
Hence, required days = 180/17 = 10 10/17

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Ronak to Devendra Marghade 5 years ago

, Q, R and S are four friends and they are working independently on a work. R can do the work in M days, whereas S can do the same work in 2M days. R started the work and worked for only 144/7 days. then, he was replaced with S, who completed the remaining work in the same time as P and Q working together would finish the entire work. the efficiency ratio of P and Q is 4:3. if P and Q are working on alternate days, with P being first, the work will finished in 41 days.

1)in how many days can R individually complete the total work?

Reply Like? Yes | No

Ronak 5 years ago

P, Q, R and S are four friends and they are working independently on a work. R can do the work in M days, whereas S can do the same work in 2M days. R started the work and worked for only 144/7 days. then, he was replaced with S, who completed the remaining work in the same time as P and Q working together would finish the entire work. the efficiency ratio of P and Q is 4:3. if P and Q are working on alternate days, with P being first, the work will finished in 41 days.
1)in how many days can R individually complete the total work?

Reply Like? Yes | No

Devendra Marghade 5 years ago

216/7 days

Given R takes M days, so 1 day's work of R = 1/M
Similarly S takes 2M days, so 1 day's work of S = 1/(2M)
Work completed by R in 144/7 days = (1/M)*(144/7) = 144/(7M) and remaining work = 1 - 144/(7M)

Given, efficiency ratio of P and Q is 4:3.
Days required is inversely proportional to efficiency. Let P & Q can complete the work in x/4 & x/3 days respectively.
Given, P and Q are working on alternate days, with P being first, the work will finished in 41 days.
=> P works for 21 days whereas Q works for 20 days to complete the work.
=> 21*P's 1 day work + 20*Q's 1 day work = 1
21*4/x + 20*3/x = 1
=> x=144
Thus, P takes 144/4=36 days and Q takes 144/3=48 days to complete the work individually.
Now (P+Q)'s 1 day work = 1/36 + 1/48 = 7/144
.'. Together P & Q require 144/7 days = Days required by S to complete remaining work
=> (144/7)*1/(2M) = 1 - 144/(7M)
72/(7M) = (7M - 144)/7M
7M = 216
M = 216/7 = Days required by R individually to complete the work.

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Ronak to Devendra Marghade 5 years ago

If 36 persons are engaged on a piece of work, the work can be completed in 40 days. After 32 days, only 3/4 th of the work was completed. How many more persons are required to complete the work on time?
A)10
B)8
C)9
D)12

Reply Like? Yes (2) | No

Devendra Marghade 5 years ago

D)12

Work completed by 36 persons in 32 days=3/4
1 person's 1 days work = (3/4)/(32*36) = 1/1536
Now remaining work=1/4 and remaining days=40-32=8
So, required work in 1 day = (1/4)/8 = 1/32
Total persons required = (1/32)/(1/1536) = 48
Hence, additional persons = 48 - 36 = 12

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Ronak 5 years ago

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Ronak 5 years ago

The ratio of difference between Compound interest and simple interest at 2 year and 2.5 year is 9:17 then rate of compound interest? 1)22.22% 2)11.11% 3)18.18% 4)22.5%

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Ronak to Devendra Marghade 5 years ago

The ratio of difference between Compound interest and simple interest at 2 year and 2.5 year is 9:17 then rate of compound interest? 1)22.22% 2)11.11% 3)18.18% 4)22.5%

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Ronak to Devendra Marghade 5 years ago

A man borrows a sum of rs 96,000 at 5% p.a. interest compounded annually. At the end of one year, he repays a certain amount and he repays the balance amount of rs 70,980 at the end of the second year. What amount does he repays at the end of the first year?

Reply Like? Yes | No (2)

Devendra Marghade 5 years ago

Rs. 33200

Amount after 1 year = 96000*(1 + 5/100) = 100800
Let he repays Rs. x after 1 year, then amount to be paid after 2nd year=(100800 - x)*(1 + 5/100) = 70980
100800 - x = 67600
=> x=33200

Like? Yes (2) | No

Sushma 5 years ago

For Today's puzzle, options 3 and 5 are same as 246.
Please check.

Reply Like? Yes (1) | No

Kousalya Ravichandran 5 years ago

Anyone plz send me the model papers of amcat.. mail id kousalya97r@gmail.com

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Himanshu Sharma 5 years ago

Plz send me the model papers of amcat...

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Nyeff Feey 5 years ago

How many ports will be allocated to a new emulator?

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Aarti Galar 5 years ago

H17, B11, P79, G16, L48, ?

Reply Like? Yes (45) | No (5)

ALLURI VENKATRAMA AKHIL VARMA 5 years ago

problem statement:

you are given an array a[],and you need to find out the combination of array element which has same different.print the count of combinations

SAMPLE INPUT: SAMPLE OUTPUT:
5
4
27
37
47
57
EXPLANATION:

the possible comnibation are with 10 difference(27,37),(37,47),(47,57) -3 with 20 difference (27,47),(37,57)-2 total 3+2=5

E

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Kousalya Ravichandran 5 years ago

Anyone tell me the pattern of Amcat

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Ronak to MAN 5 years ago

In a election between two parties P and Q, Q is loser. If Q get 25% more votes then he win by the thrice the majority then that of P. If the total number of votes are 4250. How many vote did P get? 1)2250 2)1125 3)2000 4) 1525.. please give solution

Reply Like? Yes (4) | No

Devendra Marghade 5 years ago

3) 2250

Total votes = P + Q = 4250 ---(i)
When Q is loser, majority of P = (P - Q)
When Q gets 25% more votes, then votes of Q = Q + 0.25Q = 1.25Q and votes of P = (P - 0.25Q)
According to given condition, 1.25Q - (P - 0.25Q) = 3*(P - Q)
=> 4P - 4.5Q = 0 ---(ii)
On solving equations (i) & (ii), Q=2000, P=2250

Like? Yes (4) | No

Karan 5 years ago

As per given ststement, Q is the looser.
From given options, only 2250 votes for P satisfies this condition.
No need to waste time to solve in detail while appearing for multiple choice questions test in limited time.

Like? Yes (1) | No

Ronak to Devendra Marghade 5 years ago

In a local election, 2400 people were to vote for Party A or Party B. Party A was bound to win the election. However, on Election Day, 33% of the voters of Party A were kidnapped. Party B was also able to influence the remaining Party A voters and thus double the strength of its voters. In this way, Party A lost by a majority which was half of that by which it would have won had the elections been fair. How many people finally voted for Party A and Party B?

Reply Like? Yes | No

Devendra Marghade 5 years ago

Final voters of party A=1029, B=1371

In fair election, party A voters=1542, party B voters=858, majority of A=684
After 33% and some voters of A shifted to B, Party A voters=1029, party B voters=1371, majority of B=342

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Ronak 5 years ago

Reply Like? Yes | No

Ronak 5 years ago

Reply Like? Yes | No (1)

Karan 5 years ago

As per given statement, Q is the loser.
From given options, only 2250 votes for P satisfies this condition.
No need to waste time to solve in detail while appearing for multiple choice questions test in limited time.

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S. Singh 5 years ago

Pls check on site.
May answer is 5 which is correct as per site only .
But marks .. -1.
Any reason ?

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S. Singh 5 years ago

Regarding 'Today's puzzle'dated 30.01.2020, it is to inform you that result displayed at site is incomplete.
I have submitted same answer ( option) in first 10 minutes, but same is not displayed here.
Please check.

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Siva 5 years ago

i want questions on TCS nqt

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prakasha Jency 5 years ago

a student asked to get the combined sum of three individual series but due to his laziness he wrote all three 1 series in the combined form as 3+2+4+8+3+a+27+ . then he realizes that some of the terms merged and converted to new term. what will be the exact sum if he suppose to find the sum of first 36 terms a)6812 b)9812 c)6914 d)6912

Reply Like? Yes (23) | No (4)

Sujeet kumar 5 years ago

No. Of zero?
1/2(6+10).

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Ronak 5 years ago

The ratio of A and B’s income last year was 4:3 the ratio of their own incomes of last year and this year individually, it’s 3:4 and 5:6 respectively. If the total sum of their present income is ₹8.04 lakh, then what is the last year income of b? Please give solution

Reply Like? Yes (2) | No

Devendra Marghade 5 years ago

2.7 lakh

Let the income of A & B last year was 4x and 3x.
Given ratio of their last year to this year income individually are 3:4 and 5:6 respectively.
Then income this year of A = 4x*(4/3) = 16x/3 and income of B = 3x*(6/5) = 18x/5
Sum of the incomes this year = 16x/3 + 18x/5 = 804000
=> x = 90000
Therefore, last year income of B = 3x = 3*90000 = 270000 = 2.7 lakh

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v.kusuma 5 years ago

How to learn python

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nicky thomas 5 years ago

consulting firms nj

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rohini jadhav 5 years ago

I have aptitude question solution

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ravitejafe 5 years ago

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ravitejafe 5 years ago

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RAMANA PAVAN KUMAR to Rajaboina Radhika 5 years ago

hiiii can u plz share infosys papers madam

Reply Like? Yes (1) | No

SK JOLL 5 years ago

Mumbai¤¤Pune¤¤,91–8426924404 Black magic to kill enemy

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veni 5 years ago

Ibm written papers

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janakapriya 5 years ago

near by a yard which is 225 meters long 26 papaya tree are planted at equal distance one tree being at each end of the yard what is the distance between two consecutive trees?

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Karan 5 years ago

9 meters
225/(26-1)= 225/25= 9 meters

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Edward lucky 5 years ago

in december 12 2007 mohammed bought 300 units of afrococo cooperation shares @$55 per shares december 10th 2008 mohammed sold all his shares for $60 dollars per share what is mohammed realised gain?

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Edward lucky to Himanshu Kesharwani 5 years ago

in december 12 2007 mohammed bought 300 units of afrococo cooperation shares @$55 per shares december 10th 2008 mohammed sold all his shares for $60 dollars per share what is mohammed realised gain?

Reply Like? Yes | No

Adi 5 years ago

The main temperature from 9th to 16th of march both days inclusive 11.6 degree Celsius and from 10th to 17th market was 12.2 degree Celsius if the temperature on month of march was 10.8 degree then on 17th march it was

Reply Like? Yes | No (1)

Sriramulu 5 years ago

How to prepare m4 maths

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Keval 5 years ago

Two fill pipes A and B can fill a tank in 30 and 20 hours respectively. Pipe B alone
is kept open for half the time and both pipes are kept open for the remaining time.
In how many hours, will the tank be completely full?

Reply Like? Yes (1) | No

Devendra Marghade 5 years ago

15 hrs

Let the total time taken be 'x' hrs.
Then, for x/2 hrs pipe B fills at 1/20 per hr and for remaining x/2 hrs both pipes A & B fills at (1/30 + 1/20) per hr.
(x/2)*(1/20) + (x/2)*(1/30 + 1/20) = 1
(x/2)*(8/60) = 1
=> x=15

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Keval 5 years ago

Thanks DEVENDRA.

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Placed User Comments

M4Math helped me a lot.

Vipul Chavan 5 years ago

Thanks m4 maths for helping to get placed in several companies.
I must recommend this website for placement preparations.

yash mittal 5 years ago