The position of letters of word SAURAV in English alphabet are 19, 1, 21, 18, 1, 22 respectively.
On writing the word SAURAV in a running sequence we get
SAURAVSAURAVSAURAVSAURAV.......
19th, 1st, 21st, 18th, 1st and 22nd letters in this sequence are S, S, S, U, V, S, R
Similarly for others
A mixture contains milk and water in the ratio 4:3. If 7 litres of water is added to it, the ratio of milk and water becomes 3:4. Find the quantity of milk in mixture.
Out of a group of ducks, 7/2 times the square root of the number are swimming in water while two remaining are playing on the shore. The total number of ducks is
Let the number of ducks be x.
Then, 7/2 sqrt(x) + 2 = x
=> 2x - 7 sqrt(x) - 4 = 0
=> (2y+1)(y-4) = 0
=> y = -1/2 or y = 4
=> sqrt(x) = -1/2 or sqrt(x) = 4
=> x = 1/4 or x = 16
Therefore
x=16 (Number of ducks can not be a fraction)
Option 8)
5% of income of Swati is equal to 15% income of Raju and 10% income of Raju is equal to 20% income of Mohan. If income of Mohan is Rs.2000, then total income of Swati, Raju and Mohan (in rupees) is
5/100 S = 15/100 R
and 10/100 R = 20/100 M
Therefore
S = (15/100 * 100/5)R = 3R
R = (20/100 * 100/10)M = 2M
Now M = 2000
R = 2*2000 = 4000
S = 3*4000 = 12000
12000+4000+2000 = 18000
Option 9)
A dinner party is to be fixed for a group consisting of 100 persons. In this party, 50 person do not prefer Veg, 60 prefer Non-veg and 10 do not prefer either Non-veg or Veg. The number of persons who prefer both Veg and Non-veg is
Let A be the set of persons who prefer Veg and B be the set of persons who prefer Non-veg.
Solve by using set theory
n(A U B) = 100 - 10 = 90
n(A) = 100 - 50 = 50
and n(B) = 60
Therefore
n(A Inter B) = n(A) + n(B) - n(A U B)
= 50+60 - 90) = 20
Ans - 20
Option 1)
Ramesh invests some money partly in 3% stock at 96 and partly in 4% stock at 120. To get equal dividends from both, he must invest the
money in the ratio.
For an income of Rs.1 in 3% stock, investment
= Rs.(96/3) = Rs.32
For an income of Rs.1 in 4% stock investment
= Rs.(120/4) = 30
Ratio of investment = 32:30 = 16:15
Option 2)
Ramesh and Mohan solved a quadratic equation. In solving it, Ramesh made a mistake in the constant term and obtained the roots as 5,-3 while Mohan made a mistake in the coefficient of x and obtained the root as 1,-3. The correct root of the equation are
A and B are two linear equation in two variable x and y. (0,1) is a solution of both A and B, (2,-1) is a solution of A only and (-2,-1) is a solution of B only. A and B are.
Let A and B be the equations given by ax+by=c and lx+my=n
Since (0,1) satisfies these equations, we have b=c and m=n
Since (2-1) satisfies ax+by=c, we have 2a-b=c
Therefore
2a-b=b or a=b (c=b)
Again
(-2,-1) satisfies lx+my=n we have -2l-m=d
or -2l-m=m or l=-m
Thus a=b=c and l=-m=-n
So the equation are
x+y=1 and x-y=-1
option 5)