Ram and Rahim agree to meet at a place between 4 P.M. to 6 P.M. The first one to come waits for 24 minutes and then leaves. If the time of their arrival are independent and at random then what is the probability of a meeting between Ram and Rahim.
Total interval = 120 minutes
There are two persons hence total areal time interval = 120*120
Meeting interval = 24 minutes
Interval in which meeting is not possible = 96 minutes
There are two persons hence the total areal time interval for cancellation of meeting = 96*96
Total areal time interval for meeting = 120*120 96*96
Probability = (120*120 96*96)/ 120*120
= 9/25
A train P leaves Bareilly at 5 am and reaches Dehradun at 9 am. Another train Q leaves Dehradun at 7 am and reaches Bareilly at 10.30 am. At what time do the two trains cross one another.
OPtion
1) 8.26 am
2) 7.10 am
3) 8 am
4) 8.10 am
5) 7.36 am
6) 8.40 am
7) 7.56 am
8) 7.30 am
9) 8.56 am
10)None of these
Solution
Let the distance between Bareilly and Dehradun be x km and let the train meet y hours after 7 am
Clearly, P covers x km in 4 hours and Q covers x km in 7/2 hrs
Speed of P = x/4 kmph and Speed of Q = 2x/7 kmph
Distance covered by P in (y+2) hrs + Distance covered by Q in y hrs = x
x(y+2) / 4 + 2xy/7 = x
y+2 / 4 + 2y/7 = 1
y = 14/15 hrs = 14/15 * 60 min = 56 min
So the train meet at 7.56 am
Option 7)
Since half (1/2) filled car engine holds 15 ltrs of petrol
we can write it as
15 liters is contained in 1/2 as fraction
so 1 liter will be contained in 1/30 as fraction
hence 18 liters will be contained in 18/30 . i.e 3/5 as a fraction .
Rohan and Suraj can do a piece of work in 12 days; Suraj and Mahesh in 15 days; Mahesh and Rohan in 20 days. In how many days will they finish it together.
(R+S)'s day's work = 1/12;
(S+M)'s 1 day's work = 1/15
(M+R)'s 1 days's work = 1/20
Adding : 2(R+S+M)'s 1 day's work = (1/12 + 1/15 + 1/20)
= 12/60 = 1/5
=> (R+S+M)'s 1 day's work = 1/10
So, they together can finish the work in 10 days.
Option 2)