M4maths Previous Puzzles

13 Jul 2016 Time and work

If 4 examiners can examine a certain number of answer books in 8 days by working 5 hours a day, for how many hours a day would 2 examiners have to work in order to examine twice the number of answer books in 20 days.

OPtion

1) 6 hours
2) 7 hours
3) 15/2 hours
4) 10/3 hours
5) 9 hours
6) 16/3 hours
7) 20/3 hours
8) 8 hours
9) 12 hours
10)None of these

Solution

Less examiners, more hours per day (Indirect)
More days, less hours per day (Indirect)
More answer books, more hours per day (Direct)

Examiners 2:4
Days 20:8 --------- :: 5:x
Answer books 1:2

=> x = 4*8*2*5/2*20*1 = 8 hours per day
Option 8)

Correct Option: 8 Best Solution (47)

Jaikumar Bhatia   8 years AGO

(M1*D1*H1)/W1=(M2*D2*H2)/W2
IF
M1=4
D1=8
H1=5
W1=1
&
M2=2
D2=20
H1=x
W2=2
THEN
(4*8*5)/1=(2*20*x)/2
x=8
Answer is x=8 hours
Option is (8)

Like? Yes (31) | No (5)  

Mridula Shaw   8 years AGO

4 examiner working for 8 days(5 hours a day)
thus,
1 examiner=8*5=40 hrs/person
Now,
2 examiner working for 20 days(x hrs a day) to have twice the work.
thus,2*x hrs spent each day
We need 160 hrs.Working 2 hrs the duration will be:
160/2*x=20
=>x=4 hrs
Twice work is done,thus,time=4*2=8 hrs.

Like? Yes (15) | No (1)  

Lakshmipathi   8 years AGO

m1d1h1/w1 = m2d2h2/w2
assume w=100;
4*8*5/100=2*20*h/200
h=8 hrs

Like? Yes (11) | No (3)  

Jay parmar   8 years AGO

If 4 examiners takes 40 hrs to complete a work then for same work 2 examiners take 80 hrs to complete
And if the work is doubled they will take 160 hrs
That means. 20 days ,8 hrs a day

Like? Yes (11) | No (3)  

Soumyaranjan Dalai   8 years AGO

(men1*time1*hours1*)/work1=(men2*time2*hours2)/work2
4men*8days*5hours/1work=2men*20days*hours2/2work
hours2=8

Like? Yes (4) | No (1)  

sachin sawant   8 years AGO

4 ex take-8 days-5hrs-to do 1 work
2 ex take 16 days-5 hrs to do 1 work
2ex take 20 days 4 hrs to do 1work
2 ex take 20 days 8 hrs to do 2 work

Ans- 8 hrs

Like? Yes (3) | No (1)  

satya   8 years AGO

In first case one examiner 1 day work is 1/32

whereas in 2nd case one examiner work is 1/40

difference is 8 days

Like? Yes (3) | No (2)  

Divyansh Jain   8 years AGO

4*8*5/x=1 => x=160

2*20*y/160=2 => y=8hrs ans.

Like? Yes (2) | No (1)  

Vipul Puranik   8 years AGO

m1*r1*t1/w1 = m2*r2*t2/w2
4*5*8/w = 2*r2*20/2w
r2 = 8 hrs

Like? Yes (1) | No (1)  

Sagar Wadjikar   8 years AGO

2 examiners twice pages 1hr = 160 days
so 10 hr = 16 days
for 20 days 8 hrs will be required

Like? Yes | No   

rishi   8 years AGO

1 teacher checks x book within 1 day in=(5*4*8)/xhrs
2 teacher checks 2x books in 20 days in=(5*4*8*2x)/(x*2*20)=8hrs

Like? Yes | No   

Santhosh Kumar   8 years AGO

The first certain no of papers can be examined by a single person in (8*5*4)=160 hrs

Hence a person need (160*2) hrs for completing twice the work

If it is to be shared b/w 2 persons time required for each person =(160*2)/(2)=160

No of hours to be worked for 20 days is (160/20)=8 hrs/day

Like? Yes | No   

G.S.Kantharao   8 years AGO

4 examiners - Let x papers - by working 5 hours per day for - 8days.
It means 2 examiners - x papers - by working 5 hours per day - in 16 days
If there are 2x papers the same 2 examiners can do by working 5 hours per day in 32 days.
If there are 20 days for the same 2 examiners for 2x papers they have to work = 5 x32/20 =8 hours per day. Hence right choice is 8.

Like? Yes | No   

sairam   8 years AGO

let us assume that 4 examiners can examine 40 papers in 8days working 5hours a day. each can examine 10 papers in 40 hours. so it will take 4hours for each examiner to examine one paper. now our question is in howmany hours 2 examiners can examine 80 papers working for 20 days.each examiner have to examine 40 papers. so for 40 papers it will take 40*4=160 hours. so they have to work 8hours per day to complete the work

Like? Yes | No   

Akhila Dumpala   8 years AGO

using the formula (Men *Days)/Work.
let us assume 4 examiners examined x answer books in 8 days for 5 hours a day. then 2 examiners should examine 2x answer books in 20 days in y hours per day.
(4*5*8)/x = (2*20*y)/(2*x)
will give us 8 as the answer.

Like? Yes | No   

T.uma maheswari   8 years AGO

let no.of books being examined be s
s=(no. of examiners)*(no.of days)*(no.of hours per day)
s=8*4*5=160
now for 2 examiners
hours of work per day H
2 s=2*20 H
H=2*4*8*5/40
H=8

Like? Yes | No   

JENSI KARUNYA.S   8 years AGO

let x=no of answer books
4*8*5=x--->(1)
2*20*h=2x---->(2)
simplify the two above equations (1) & (2)
h=8
so they work 20 days for 8 hrs per day
option 8) 8 hrs is the correct answer

Like? Yes | No   

Durgesh Pal   8 years AGO

Let there are x answer sheets.
Examiners= E
Total hours (days * hours/day) = H

4 Examiners can examine x sheets.
i.e x is directly proportional to Examiners.

x sheets can be examined in 40 hours ( 8days * 5hours/day)
i.e x is directly proportional to Total Hours.

Hence,
(E1 * H1)/x1 = (E2 * H2)/x2

(4 * 40)/x = (2 * 20*H)/2x

H= 8 Hours

Like? Yes | No   

M Narasimhulu   8 years AGO

4 mem 40 hours a work
2 mem 80hours a work
twice work for 2 mem 160
20*x=160
x=8

Like? Yes (1) | No (1)  

Abhinav Kumar   8 years AGO

Formula :
(M1*D1*H1/W1*R1)=(M2*D2*H2/W2*R2)

Where M = No. of persons ; D = No. of days ; H = No. of hours ; W = Work ; R = Wage/Money

Putting respective values in above formula, we get required time as 8 hrs.
( Note that here wage i.e. R is not given so we will not consider R in the formula .)

Like? Yes | No   

Rohit Saha   8 years AGO

total work = 320hrs which is to be completed in 20 days. so per day work is 16 hours

Like? Yes | No   

Amit Gurbani   8 years AGO

M1*D1*T1*W2 = M2*D2*T2*W1
4*8*5*2 = 2*20*T2*1
T2 = 8

Like? Yes | No   

G.Mounika   8 years AGO

As we know
M1D1H1/W1 = M2D2 H2/W2 let us take x as number of books
so we have
4*5*8/x = 2*20*y/2x
Y =8

Like? Yes | No   

KUMUD UPADHYAY   8 years AGO

man*hours*days must equate.
as in case two work in twenty days is double the actual work so for the actual work the examiners would have to work only for 10 days(20/2).
Let's take h as no of hours per day in case 2.
Now 4*8*5=2*10*h, and on solving we get 8 hours per day as the answer

Like? Yes | No   

gayathri   8 years AGO

4 examiners corrected a x papers in 5hrs per day
Per 8 days=40hrs
One person=40 hrs
For 4 =160 hrs
So, 2x papers will be corrected by 2 examiners in 20 days is
160hrs-x papers
2x papers-320 hrs
So,320/20=16 hrs for 2 members
For 1 member 8 hrs per day

Like? Yes | No   

Riya Prakash Ratnaker   8 years AGO

Let the no.of books be x
x=(no.of examiners)*(no of days)*(no of hours a day)
x=4*8*5
x=160

now the no of books doubled and examiner becomes 2,also days are 20

2x=2*20*H
2*160=40*H
320=40*H
H=8

hence 8 hours is the answer.Option (8)

Like? Yes | No   

vikas   8 years AGO

4*8*5=160
double work means..320
so, 320/(20*2)=8

Like? Yes | No (1)  

Lenin   8 years AGO

no. of examiners -4, working hours a day = 5, no. of days =8
so, work done = n = 4 * 8 * 5 = 160 units.
so, for 2n=320 units, no.of examiners=2, no. of days =20

required working hours per day = 320/(2*20) = 8 hours.
option 8.

Like? Yes (1) | No (2)  

Shreeprasad Bhat   8 years AGO

total of 4*5*8=160 hrs of work
twice the work is 160*2=320 hrs
and for 20 days 320/20=16 hrs per day
with 2 examiners 16/2=8 hrs per day

Like? Yes | No (1)  

Gokul Krishnan   8 years AGO

(M1*D1*H1)/W1=(M2*D2*H2)/W2
GIVEN: W2=2W1
(4*8*5)/W1=(2*20*H2)/2W1
H2=8 hours

Like? Yes (1) | No (2)  

alka patel   8 years AGO

from above ques
4*8*5*2=2*20*x
x=8
here 4*8*5 is total men hours and it will be equal to the new equation when it is twice

Like? Yes | No (1)  

ANUJ KUMAR   8 years AGO

(e×d×h)/x=constant
e=no of examiners
d=no of days
h=no of hrs
x=no of sheets

Like? Yes | No (1)  

Dinesh kumar sah   8 years AGO

It is clear from question that more examiners than less time will be required,ie inversely proportion is happening here.
Let the x hours they have to work.
then 4:2 :: 20x:80
if we solve then we get x=8 hours Ans
hence option (8) is the correct answer.

Like? Yes | No (1)  

Sandip Das   8 years AGO

let say 4 examiner answer 100 question
4 examiner ans 100 qus 40 hr
2 examiner ans 200 qus (40*4*200)/(2*100)
=160 hours
20 days work 160 hr
1 days work 160/20
=8 hr

Like? Yes | No (1)  

Shashank Rai   8 years AGO

x number of copies require 40 hrs to complete the examining process by 4 people. for 2 people, 2x no. of copies will be completed in:- 2*2*40/20= 8 hrs a day.

Like? Yes | No (1)  

Kiran   8 years AGO

If p1 persons can do certain work w1 in d1 days by working t1 hours a day and p2 persons can do certain work w2 in d2 days by working t2 hours a day, then the formula is p1d1t1w2=p2d2t2w1 therefore, p1=4, w1=w1 , d1=8, t1=5hrs and p2=2, w2=2(w1) coz, twice the no: of answer books of w1, d2=20, and t2=? hence, 4*8*5*2 w1=2*20*t2*w1 w1 cancels both sides, and then t2=320/40 therefore, t2=8hrs a day. option 8) is correct

Like? Yes | No (1)  

Siva Raman R   8 years AGO

Let total work be x
in first case each guy doing x/4 of work.
for 1 person to complete x/4 of work it takes 40 hours.
in second case each guy is doing x of work ==> 4*40 = 160 hours. in second case they have to work for 160 hours,given that in twenty days,therefore working 8 hours per day
ans : 8

Like? Yes | No (1)  

mini atreya   8 years AGO

M*D*H/W

4*8*5/X = 2*20*H/2X
H = 4*8*5*2X/2*20*X
H=8 HOURS

Like? Yes | No (1)  

Nikita Singhal   8 years AGO

4 examiners can examine in 40 hrs
2 examiners can examine in 80 hrs
2 examiners can examine double answer books in 160 hours
to complete in 20 days, number of hours per day = 8 [total no. of hours (160)/no. of days (20)]

Like? Yes | No (1)  

RISHABH   8 years AGO

Let the no. of answer books be x
So, x = 4*5*8
Also, 2x = 2*20*h
So, h = 2*4*5*8/2*20 = 8
So, 8 hours is required

Like? Yes | No (1)  

Nishtha shree   8 years AGO

examiners time days work(answer books)
4 5 hr 8 1
2 x hr 20 2
.
. . 4*5*8 1
----------= ---
2*x*20 2
=>x=8 hr

Like? Yes | No (1)  

Pritam warule   8 years AGO

4(examinar)*8(day)*5(hr)*2x=2(examinar)*20(days)*hr*x

x=no.of ans book hr=hours
hr=8
ans=8)

Like? Yes | No (1)  

Prateek khanna   8 years AGO

Let answer books to be checked equals to x. X=4*8*5=160. Now, 2x=2*h*20. After solving we get h=8 hrs

Like? Yes | No (1)  

lalitha valeti   8 years AGO

work done by 4 = 8x5
let work done by two per day is a, then for 20 days it is = 20a
so total work done by 4 = 4x8x5
total work done by 2 = 20xax2
as work done by 2 is twice that of 4
a=8x5x4x2/20x2 = 8 hours

Like? Yes (1) | No (2)  

Nishant   8 years AGO

let no. of books being examined be x
x=(No. of examiners)*(No. of days)*(hour of work per day)
x=4*8*5=160
now
for 2 examiners
hour of work per day be H

2x=2*20*H
x=20H
H=160/20
H=8 Ans.

Like? Yes | No (1)  

MRITUNJAY   8 years AGO

Let the no of hours be x.

4*8*5/1=2*x*20/2

Solve x=8 hours
Option 8

Like? Yes | No (2)  

Mukund Manohar   8 years AGO

M1 = 4, M2 = 2
D1 = 8, D2 = 20
H1 = 5, H2 = x
W1 = 1, W2 = 2
(M1*D1*H1)/W1 = (M2*D2*H2)/W2
=> (4*8*5)/1 = (2*20*x)/2
=> x = 320/40
x = 8
Answer is 8 hours

Like? Yes | No (2)  

12 Jul 2016 Perimeter of Triangle

The area of a circle inscribed in an equilateral triangle is 346.5 cm^2. Find the perimeter of the triangle. (Use Pi = 22/7 and Sqrt3 = 1.73).

OPtion

1) 102.45 cm
2) 104.33 cm
3) 89.54 cm
4) 108.99 cm
5) 94.35 cm
6) 72.66 cm
7) 112.33 cm
8) 110.5 cm
9) 86.5 cm
10)None of these

Solution

By using figure
The incentre of the triangle is coincident with centroid (as it is an equilateral triangle)
Also I divided AD in the ratio 2:1 (I is centroid)
We have, area of circle = 346.5 cm^2
=> Pi r^2 = 346.5
r^2 = 346.5*7/22 = 110.25
r = 10.5
In triangle ABC
We have ID = AI = 1:2
ID = r = 1/3 AD
Also as triangle ABC is equilateral
AD = (Sqrt3/2)*a (From pythagoras theorem is Triangle ADB)
r = Sqrt3*a/2 * 1/3 = a/2*Sqrt3
a = 2*Sqrt3*r
Perimeter = 3a
= 3*2*Sqrt3*r = 108.99 cm.

Correct Option: 4 Best Solution (31)

Jaikumar Bhatia   8 years AGO

i) Area of inscribed circle=346.5 cm^2=Pi*r^2
=> r=10.5 cm
ii) In equilateral Triangle let h=altitude
Three altitudes bisects each other at centre of circle
& whose point of intersection divides the medians in the ratio of 2:1
r=h/3
h=3r=3*10.5=31.5 cm
iii) Let each side of Triangle be a
then,
h=root3a/2
a=2h/root3
a=2*31.5/root3
a=63/root3
a=21root3
a=36.33 cm
iv) Perimeter of equilateral triangle=3a
=>3*36.33
=>108.99 cm
Ans is 108.99 cm
option is (4)

Like? Yes | No   

Gokul Krishnan   8 years AGO

22/7*r^2=346.6cm^2
r=10.5cm
Perimeter of a triangle=3a (a=(2*h)/1.73)
where h=3r
hence ans=108.99cm

Like? Yes | No   

Razen Yadav   8 years AGO

pi*r^2=346.5
r=10.5
for equilateral triangle r=h/3(h=height)
h=31.5
again for equilateral triangle
a=2h/sqrt3 (a=side of triangle)
Perimeter of an equilateral triangle is =3a
3a=sqrt3*2*h
=108.99

Like? Yes | No   

Lakshmipathi   8 years AGO

pi r^2=346.5
r=10.5
1/rt 3=onside/another side
oneside=10.5*rt 3 (1.73)
'''''''''
108.99 cm

Like? Yes | No   

Sagar   8 years AGO

Let side be a cm of eq. Traingle
Radius of circle is a/2sqrt(3)
Area of circle = a*a*22/(7*12)

Like? Yes | No   

venkata gowtham   8 years AGO

equilateral traingle have 60degree between to sides ad you can know radius of circle and find the side length using tan formula

Like? Yes | No   

Sandip Das   8 years AGO

circle area 346.5 cm^2
pi*r^2=346.5 cm^2
r=21/2 cm
equilateral triangle height ratio is 2:1
so 2*(21/2)
height=(21/2)+21
=63/2 cm
equilateral triangle each angle is 60 degree
so tan60=(63/2)/base
base=(63/2*sqrt3)
so side=(63/2*sqrt3)+(63/2*sqrt3)
=63/sqrt3
so now perimeter is 3*side
=3*(63/sqrt3)
=sqrt3*63
=1.73*63
=108.99 cm

Like? Yes | No   

madanpal vishwakarma    8 years AGO

Given area of the circle =346.5 cm^2

So Radius 346.5 =(22/7) r^2
r=10.5
Intersection divide median in the ratio of 2:1

so height of triangle is 3r

or r=(h/3)
h=10.5 *3=31.5
Now side of triangle is a = (2*h)/sqrt3
a= (2*31.5)/sqrt3
a = 63/sqrt 3
Now perimeter of an equilateral triangle is = 3 a
= 3 *(63/sqrt 3)
= 108.99 cm
So option 4 is correct....

Like? Yes | No   

suthanth   8 years AGO

Radius of incircle of equilateral triangle of side a is a/2*sqrt(3)
So side a =36.33
Perimeter is 3a=108.99

Like? Yes | No   

NANDAN KUMAR SINGH   8 years AGO

area of circle=pi*r^2=346.5
so, r=10.5 cm
we know that in equilateral triangle each angle is 60 degree.
so,from question we can say that radius of circle is perpendicular to each side of equilateral triangle .
also radius bisect each angle .
we consider a rignt triangle OBD
in OBD
tan30=(OD/BD)
where OD=radius=10.5
BD=half distance of side BC
after calculation BD=10.5*root(3)=18.165 cm
so, BC=2*BD=2*18.165=36.33 cm

so ,perimeter of triangle=3*side length=3*BC=108.99 cm

Like? Yes | No   

Nikita Singhal   8 years AGO

area of circle = 346.5
radius of circle = 10.5 (area = pi*r^2)
altitude of equilateral triangle = 31.5 (3*radius)
side of equilateral triangle = 36.33 (2*altitude/sqrt3)
perimeter = 108.99 (3*side of triangle)

Like? Yes | No   

Ankit Kumar   8 years AGO

Area of circle=(pi)*(square of radius r) =346.5 cm sq
so,r=10.5 cm
we know that height of an equilateral triangle is divided in the ratio of 2:1 by the centre of the circle inscribed in that triangle.
Also the length of the 1st part of height(altitude) of triangle=2r and that of the 2nd part is r.
So by pythagoras theorem, length of triangle =x=2*r*(root 3)
so perimeter=3*x=108.99 cm...

Like? Yes | No   

Akshat Sood   8 years AGO

Now 22/7*r^2=3465mm

r=105mm

Now as triangle is equilateral radius is perpendicular to the side of triangle.

We know centroid divides median in ratio 2:1

BO:OE=2:1

BO=210mm

Now apply Pythagoras theorem in triangle BOF x=210?3mm or 21?3cm

As we have to find perimeter,

3x=63?3cm=108.99 cm

Option(4)

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KOTHA VINOD KUMAR   8 years AGO

First we need find out radius of the circle from given area of the circle. Then height of the circle h=3r relation and using pygthagoars theorem u will get answer

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Nishtha shree   8 years AGO

area of circle=346.5 cm^2
Pi*r^2=346.5=> r=10.5 cm(line from center of circle and perpendicular bisector to one side of triangle)
A line from center of circle to corner of triangle will bisect the angle
so,tan(30)=p/b=r/b=10.5 cm/b
b=18.165 cm
side of equilateral triangle=2*b
perimeter of triangle=3*(2*b)=108.99 cm

Like? Yes | No   

G.S.Kantharao   8 years AGO

Pi r^2 = 346.5cm^2
r^2= 346.5 x 7/22
= 693/2 x 7/22
= 63 x 7/4
r = 21/2
Median = 3r
Median = root 3 a/2
Root 3a = 63
Perimeter = 63 x root3
= 63 x 1.73 = 108.99

root 3 =

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guntupalli thirumaladevi   8 years AGO

pi*r^2=346.5
r=10.5
side of the triangle(s)=2*sqrt3*r=36.33
perimeter=3s=108.99

Like? Yes | No   

milan   8 years AGO

r=10.5
tan30=r/b
one side of a triangle=2b
perimeter=3*side of a triangle

Like? Yes | No   

T.uma maheswari   8 years AGO

radius of circle=a/3.46
area of circle=(22/7)*a*a/(12)cm^2
a=36.3
perimeter of the triangle=3*a=3*36.3=108.9cm

Like? Yes | No   

nainsi gupta   8 years AGO

the inradius of equilateral triangle is=a/2root3
area of circle=pi r^2=346.5, then r=10.50
10.50=a/2root 3,then a=36.33
hence,perimeter of triangle is=3*36.33=108.99cm

Like? Yes | No   

Anish Prasad   8 years AGO

ratio of area of inscribed circle to the area of triangle is pi/3Sqrt3 so with this we can find area of the tringle which is 562.1975 cm^2
now equating this with the formula of area of an equilateral triangle ie: Sqrt3 *(side)^2/4
we would get side=21sqrt3 so perimeter will be thrice of side ie: 108.99

Like? Yes | No   

Riya Prakash Ratnaker   8 years AGO

area of circle=346.5cm^2
pi*r^2=346.5

i.e. r=10.5

In an inscribed triangle,altitude h=3*r
h=3*10.5
h=31.5

also, altitude=(root(3)/2)*side
31.5=(root(3)/2)*side

side=63/root(3)

perimeter of equilateral triangle=3*63/root(3)
=108.99cm

so answer is (4)

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Shreeprasad Bhat   8 years AGO

since equilateral,
side = 2 * ?3 * radius
radius = ?(346.5 * 7 / 22)
side = 2 * ?3 * ?(346.5 * 7 / 22)
side = 36.33
perimeter = 3 * side
perimeter = 3 * 36.33
perimeter = 108.99

Like? Yes | No   

KUMUD UPADHYAY   8 years AGO

as in an equi triangle angle bisectors , medians and altitudes all are same so first we calculate r from pi*r^2=346.5 and we get r=10.5 cms.
Now one angle bisector makes a triangle with the centre of inscribed circle with radius as the height.
tan30°=r/x where x : half the side length of the triangle.
we get x=18.165 cms
now there 6 such x for perimeter.
perimeter=18.165*6=108.99 cms

Like? Yes | No   

arjun pandey   8 years AGO

area of triangle =22/7*r^2
r= 346.5*7/22
h=3r
h= 3*346.5*7/22
a= 2h/square root of 3
perimeter =3a
hence correct option is 4

Like? Yes | No   

sanjeet kumar   8 years AGO

Since area of circle = 346.5 cm^2.
So, Pi* r^2 = 346.5
r = 10. 5 cm
Now, tan30 = 10.5 * (side/2)
So, perimeter = 3* side = 108.99 cm

Like? Yes | No   

Rahul Das   8 years AGO

R=10.5
H=3*10.5=31.5
Side of triangle =(2*h) /sqrt3=36.41
Perimeter=3*36.41=109.1

Like? Yes | No   

Tirthankar Kundu   8 years AGO

area=346.5
pi*r^2=346.5
r=10.5
now equilateral triangle has each angle 60 degrees.
so tan 30=p/b where p=r=10.5
so we get b=10.5 * sqrt 3
each side of traingle is 2*b=21 sqrt 3 = 36.33
perimeter=3*a=3*36.33=108.99 cm

Like? Yes | No   

anil k    8 years AGO

side of trian=2sqrt3r
perimeter =3a=6sqrt3r =10.18r=10.38x10.5=108.99 cm
now r=sqrt 346.5/22x7=10.5

Like? Yes | No   

MRITUNJAY   8 years AGO

radius of circle =(346.25*7/22)^1/2
r=10.5cm

radius of incircle r= a/2*1.73
then a=r*2*1.73
a=10.5*2*1.73=36.33 cm

so perimeter of equilateral traingle =3*a=108.99 cm
option 4

Like? Yes | No (1)  

Mukund Manohar   8 years AGO

Let the radius of the circle and the side of an equilateral triangle be r and a respectively.
r = Sqrt(346.5 * 7/22)
= Sqrt(110.25)
= 10.5 cm
Now, Radius of the circle inscribed in an equilateral triangle = a/(2*Sqrt3)
=> 10.5 = a/(2*1.73)
=> a = 10.5 * 2 * 1.73
=> a = 36.33 cm
Perimeter of the triangle = 3a
= 3 * 36.33
= 108.99 cm

Like? Yes | No (1)  

11 Jul 2016 Sequence

What is the next number of the following sequence
36, 117, 166, 335, 360, 441, ..........

OPtion

1) 522
2) 581
3) 542
4) 576
5) 457
6) 442
7) 466
8) 505
9) 445
10)None of these

Solution

36
36 + (3+6)^2 = 36+9^2 = 36+81 = 117 [Number+(Sum of digit)^2]
117 + 7^2 = 117+49 = 166 [Number+(last digit)^2]
166 + (1+6+6)^2 = 166+13^2 = 166+169 = 335 [Number+(Sum of digit)^2]
335 + 5^2 = 335+25 = 360 [Number+last digit)^2]
360 + (3+6+0)^2 = 360+9^2 = 360+81 = 441 [Number+(Sum of digit)^2]
Similarly
441 + 1^2 = 441+1 = 442 [Number+last digit)^2]

Option 6)

Correct Option: 6 Best Solution (20)

bhaskar   8 years AGO

36+(9*9)
117+(7*7)
166+(13*13)
335+(5*5)
360+(9*9)
441+(1*1)

Like? Yes (3) | No (1)  

ABHINAV PUSHPAM   8 years AGO

36+(3+6)^2=36+81=117
117+7^2=166
166+(6+6+1)^2=335
335+5^2=360
360+(4+4+1)^2=360+81=441
441+1^2=442
Option 6)

Like? Yes | No   

MRITUNJAY   8 years AGO

36+(3+6)^2=36+81=117
117+7^2=166
166+(6+6+1)^2=335
335+5^2=360
360+(4+4+1)^2=360+81=441
441+1^2=442
option 6

Like? Yes (2) | No (2)  

Mukund Manohar   8 years AGO

Starting from 36,the square of the sum of digits and the square of the last digit is added to the number alternately.
36 = 36 + (3+6)^2 = 36 + 81 = 117
117 = 117 + 7^2 = 117 + 49 = 166
166 = 166 + (1+6+6)^2 = 166 + 169 = 335
335 = 335 + 5^2 = 335 + 25 = 360
360 = 360 + (3+6+0)^2 = 360 + 81 = 441
441 = 441 + 1^2 = 441 + 1 = 442

Like? Yes | No   

RAHUL KUMAR   8 years AGO

36+(3+6)^2=36+81=117
117+7^2=166
166+(6+6+1)^2=335
335+5^2=360
360+(4+4+1)^2=360+81=441
441+1^2=442

option 6

Like? Yes (1) | No (1)  

Anchal jain   8 years AGO

36 117 166 335 360 441....442
81 49 169 25 81......1
square of
9 7 13 5 9.......-1
-2 +6 -8 +4 ... -10
441 + (-1)^2=442

Like? Yes (1) | No (1)  

Ankit Kumar   8 years AGO

36
36+square of((0+3)+6)=117
117+ square of(7)=166
166+ square of(7+6)=335
335+ square of(5)=360
360+ square of((3+6)+0)=441
so
441+ square of(1)=442

Like? Yes (1) | No (1)  

Avdhesh Singh Rana   8 years AGO

difference b/w numbers are 81,49,169,25,81
3+6=9^2=81
36+81=117
last digit of 117=7^2=49
117+49=166
sum of digits of 1+6+6=13^2=169
166+169=335
similar way last number 441 then its last digit is 1=1^2=1
441+1=442

Like? Yes | No   

Siva   8 years AGO

36
117=36+(3+6)^2
166=117+7^2
335=166+(1+6+6)^2
360=335+5^2
441=360+(3+6+0)^2
442=441+1^2.

Like? Yes | No   

madanpal vishwakarma    8 years AGO

given series

36,117,166,335,360,441...

we relate the term as describe below..

36,(6+3)^2 +36=117,(7)^2+117=166,(1+6+6)^2+166=335,(5)^2+335=360,(3+6+0)^2+360=441

so next term is (1)^2+441=442

So option 6 is correct

Like? Yes | No   

RISHABH   8 years AGO

36=3+6=9^2=81
117=7^2=49
And, so on taking alternately taking the first no. and sum up all the digits of a number and squaring it & adding the no. obtained to get the second number.Secondly taking the last digit and squaring it and adding to the no. to get the next no.
So, in 441 taking the last digit i.e 1 and squaring it and adding it to 441 to get the next no. as (441+1)=442

Like? Yes | No   

Akshat Sood   8 years AGO

117=(3+6)^2+36
166=(1+7-1)^2+117
335=(6+6+1)^2+166
.
.
442=(1+4-4)^2+441

OPTION(6)

Like? Yes | No   

Shreeprasad Bhat   8 years AGO

The differences between yhe numbers are perfect squares.
Also there is alternative odd and even numbers.
To find the number to be squared
1) For even, add the digits and square and it to the number in the sequence to get next number in the sequence.
2) For odd, square the last digit and add it to the number in the sequence to get the next number in the sequence

Like? Yes | No   

Lakshmipathi   8 years AGO

36>>3+6=9==>9^2=81; 36+81=117
117>>last digit square 7^2 +117=166
''''''''
441+1^2==442

Like? Yes | No   

Jaikumar Bhatia   8 years AGO

36=>36+(3+6)^2=117
117=>117+(7)^2=166
166=>166+(1+6+6)^2=335
335=>335+(5)^2=360
360=>360+(3+6+0)^2=441
441=>441+(1)^2=442
Number+(add digits) ^2..(i)
Number+(last digit) ^2....(ii)
(i) and (ii) alternatively
Ans is 442
Option is (6)

Like? Yes | No   

Anup Sahay   8 years AGO

the numbers at odd place add the square of sum of digits of their digits to themselves to get the next number on even place
, while numbers on even place add the square of last digit to them to get the the next number on next odd place, i.e.
36: is at 1st position i.e. at odd place
so,
(3+6)*(3+6)=9*9=81
36+81=117
117: is at 2nd position i.e at even position ,
so,
117+(7*7)=117+49=166
similarly series goes so
441+(1*1)=441+1=442
since 441 is on even position
and we get next number on odd position as 442

Like? Yes | No   

Nishtha shree   8 years AGO

the difference between 36 and 117 is 81 which is square of (3+6) similarly 117 and 166 is 49 which square of the last digit 7 again from 166 and 335 the difference is 169 square of(1+6+6)=13 in this fashion square of last digit of 441 that is 1^2 will be added to 441 so result will be 441+1=442

Like? Yes | No   

T.uma maheswari   8 years AGO

36(3+6=9) so 36+(9*9)=117.
117,(1+1+7=9)....so 117+(7*7)=166
166,(1+6+6)=13 so 166(13*13)=335
335,(3+3+5)=11 so 335(5*5)=360
360,(3+6+0)=9 so 360+(9*9)=441
441,(4+4+1)=9 so 441+(1*1)=442 alternatively once we have to square it and once with last digit

Like? Yes | No   

N.Sowjanya   8 years AGO

36+9^2=117
166+13^2=335
335+9^2=441
117+7^2 silillarly 441+162=442

Like? Yes | No   

RAVAL   8 years AGO

even digit is a (odd no.s digit summation)^2
odd digit is (even no.s unit digit's square)
e.g
36 = 9^2 = 81 = 81 + 36 = 117
117 = 7^2 = 49 = 49 + 117 = 166
same....
441 = 1^2 = 1 = 1+441 = 442

Like? Yes | No   

08 Jul 2016 Simple Interest Opest

The simple interest on Rs.1920 from October 9, 1994 to December 21, 1994 at 15/2 % will be.

OPtion

1) Rs.22.50
2) Rs.24.50
3) Rs.32
4) Rs.21.90
5) Rs.27.30
6) Rs.36
7) Rs.28.80
8) Rs.31.40
9) Rs.29
10)None of these

Solution

Note that the day on which money is deposited is not counted and the day on which it is withdrawn is included.
Oct. Nov. Dec.
Time: 22+30+31 = 73 days
=> 73/365 days = 1/5 years
Therefore
SI = Rs. 1920*15/2*1/5*1/100 = Rs.28.80

Option 7)

Correct Option: 7 Best Solution (1)

Anchal jain   8 years AGO

s.i= p*r*t/100
p=1920
r=15/2%
t= 2 months 12 days
t=1/5 yr
put this in formula we get s.i =28.80

Like? Yes (23) | No (7)  

07 Jul 2016 Coded Language

If in coded language
BbyCDw = YybXWd
AxyBzC = ZcbYaX
Then
xvYBUz = ?

OPtion

1) acBYFe
2) ecBYFa
3) ceBYFa
4) ebCYFa
5) yeBCFa
6) ecBYDf
7) cfBYEa
8) caYBFe
9) eaFBYc
10)aeDYBc

Solution

Rules for making these codes are
1. Capital letter should be capital.
2. Small letter should be small.
3. Letters are changed according to the sequence given below
a b c d e f g h i j k l m n o p q r s t u v w x y z
z y x w v u t s r q p o n m l k j i h g f e d c b a
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
Z Y X W V U T S R Q P O N M L K J I H G F E D C B A

Option 7)

Correct Option: 3 Best Solution (26)

Anchal jain   8 years AGO

a repalced by z
A = Z
b=y
and so on
so xvYBUz =ceBYFa

Like? Yes (1) | No (1)  

ABHISHEK KUMAR   8 years AGO

logic is lyk position of alphabets is such that if in question 1st letter is 'a' (1st character of alphabet) then in answer it would be 1st character from reverse side ie 'z'
so corresponding answer is 3.

Like? Yes (1) | No (1)  

Pradeep   8 years AGO

taking reverse alphabets
z=a
y=b
x=c ....
answer will be option 3

Like? Yes | No   

Subham Pathak   8 years AGO

z=a, y=b and so on, A=Z, B=Y and so on, then it is very clear to find xvYBUz. Ans is optn 3.

Like? Yes | No   

Abhishek Kumar Sharma   8 years AGO

In the given question , The place of the alphabet is equal to the same place from the last(either in capital letter or in small letter).
i.e. A=Z. a=z
B=Y. b=y
C=X. c=x
........ ......
and so on.
Therefore,
xvYBUz = ceBYFa

Like? Yes | No   

GOVIND VARSHNEY   8 years AGO

All alphabet are equal to reverse of it that's why option 3 is correct

Like? Yes | No   

vandana   8 years AGO

z=a,y=b,........a=z,similarly for capital letters for xvYBUz=ceBYFa

Like? Yes | No   

Aakash Beniwal   8 years AGO

reverse order alphabet i.e 'z' for 'a'
'y' for 'b' etc.... answer is 3rd

Like? Yes | No (1)  

Mukesh Kumar Gandhi   8 years AGO

position of English alphabet relates such as A relates with Z and B relates with Y.And for capital A we use capital Z and for small a we use small Z.

Like? Yes | No (1)  

ashutosh kumar ojha   8 years AGO

A corresponds to Z, B corresponds to Y, C corresponds to X and so on and vice versa....
similarly a corresponds to z, b corresponds to y, c corresponds to x and so on and vice versa...
thus, xvYBUz = ceBYFa

Like? Yes | No (1)  

Gokul Krishnan   8 years AGO

answer is the place substitution of forward and reversal place of the letter(ie)xvYBUz=ceBYFa

Like? Yes | No (1)  

Akshat Sood   8 years AGO

letter are alternatively placed

for a its z

for b it's y

for c it's x....so on

answer option(3)

Like? Yes | No (1)  

keerthana   8 years AGO

A=Z;B=Y;C=X;D=W;V=E;F=U;
az;b=y;c=x;d=w;v=e;f=u;
so,xvYBUz=ceBYFa

Like? Yes | No (1)  

Yishu   8 years AGO

Alphabets are swap with their reverse in the alphabet series. like A-Z, B-Y

Like? Yes | No (1)  

Tushar Baweja   8 years AGO

Alphabat order in the sense that if A is there in left there is Z corresponding to that.

Like? Yes | No (1)  

Dev Dhalla   8 years AGO

as in question the alphabet Z is equivalent to A, so that the alphabet z is equivalent to a

Like? Yes | No (1)  

Razen Yadav   8 years AGO

In programming style...
A=Z && a=z
for(i=1;i

Like? Yes | No (1)  

G.S.Kantharao   8 years AGO

CODE:A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
DECODE: Z Y X W V U T S R Q P O N M L K J I H G F E D C B A
For smaller case letters smaller ones
From the above
xvYBUz=ceBYFa

Like? Yes | No (1)  

ABHISHEK KUMAR SINGH   8 years AGO

Small letter for small letter ,Big letter for big letter, just change the order form front to back

Like? Yes | No (1)  

Siddharth   8 years AGO

THERE IS A PTTERN GOING ON. THE POSITION OF THE ALPHABETS ON THE LEFT HAND SIDE (FROM BEGINING I.E A B C....) IS EQIVALENT TO THE POSITION OF ALPHABETS ON RIGHT HAND SIDE (FROM LAST I.E Z Y X ...)

Like? Yes | No (1)  

Anusha Reddy   8 years AGO

see the opposite letters of each alphabet such as
BbyCDw-YybXWd
Note:if the letter is in capital then the opposite letter should also be in the capital letter

Like? Yes | No (1)  

kondapuram tirumalreddy   8 years AGO

as per the given question
series should be such that
a=z, b=y c=x and so on
if the letter is capital (like A) then the corresponding letter should be capital( like Z) in the corresponding sequence

Like? Yes | No (1)  

Ovidha Das   8 years AGO

A=Z B=Y C=X and so on..
Similarly a=z b=y c=x and so on
hence option 3

Like? Yes | No (1)  

Mukund Manohar   8 years AGO

Rules for making these codes are
1. Capital letter should be capital
2. Small letter should be small
3. Letters are changed according to the sequence given below
a b c d e f g h i j k l m n o p q r s t u v w x y z
z y x w v u t s r q p o n m l k j i h g f e d c b a
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
Z Y X W V U T S R Q P O N M L K J I H G F E D C B A

So, xvYBUz = ceBYFa

Like? Yes | No (2)  

RAHUL KUMAR   8 years AGO

the code language is in the reverse alphabetical order of English
i.e. 'a' is replaced by 'Z'
'b' is replaced by 'y'
'c' is replaced by 'x'
.
.
.
.'x' is replaced by 'c'
'y' is replaced by 'b'
'z' is replaced by 'a'.
so the answer for
xvYBUz=ceBYFa

option (3)

Like? Yes | No (2)  

MRITUNJAY   8 years AGO

opposite of each letter .we get this by subtracting from 27.for example
b=2 then opposite of b is 27-2=25 i.e y
similarly for all letter.
BbycDw =YybxWd

similarly for xvYBUz=ceBYFa
option 3

Like? Yes | No (2)  

06 Jul 2016 Percentage

After spending 40% on machinery, 25% on building, 15% on raw material and 5% on furniture, a small scale industry owner had a balance of Rs.130500. Total money with him (in rupees) was

OPtion

1) 650000
2) 725000
3) 490000
4) 722500
5) 570000
6) 870000
7) 275500
8) 340000
9) 139000
10)None of these

Solution

[100-(40+25+15+5)] % of x = 130500
15% of x = 130500
or x = 130500 * 100/15 = 870000

Option 6)

Correct Option: 6 Best Solution (44)

Lakshmipathi   8 years AGO

total spends are 85% ;
remaining is 15%=130500;
1%=130500/15;
8700
100%=870000

Like? Yes (20) | No   

Mukund Manohar   8 years AGO

Let the total money with industry owner was Rs x
[100-(40+25+15+5)]% of x = 130500
15% of x = 130500
x = (13050000/15)
x = 870000
The total money with industry owner was Rs 870000

Like? Yes (11) | No (3)  

khushbu shrimal   8 years AGO

percentage of amount he had as balance= (100-(40+25+15+5))
=15% of total amount
& balance = 130500
=> (15/100)×total amount= 130500
=> total amount= (130500×100)/15
= 870000

Like? Yes (4) | No   

Anchal jain   8 years AGO

suppose x is money initial
x-130500=x(.4+.25+.5+.15)
x=870000

Like? Yes (4) | No (1)  

Razen Yadav   8 years AGO

let the total money is x.
spent money %=40+25+15+5=85%
now remaining money is x-x*85%=130500
x=870000

Like? Yes (3) | No   

ashwini shakya   8 years AGO

40% on machinery, 25% on building, 15% on raw material, and 5% on furniture

40+25+15+5 = 85%
rem = 100- 85= 15%

15% of x = 130500
x= 130500 X 100/15
x= 870000

Like? Yes (4) | No (2)  

swarupa malakala   8 years AGO

He spent 85% of his money. So he left with 15% of money which is equal to 130500
15% of x=130500
0.15* x= 130500
x = 870000

Like? Yes (3) | No (1)  

ashutosh kumar ojha   8 years AGO

15% corresponds to 130500 rs.
therefore, 100% corresponds to...
130500*100/15
= 870000 rs.

Like? Yes (2) | No   

Monalisa Mondal   8 years AGO

15% of total amount =130550
hence the total amount is(130500/15)*100=870000

Like? Yes (2) | No   

GAURAV D   8 years AGO

15% = 130500
100%=X
X= (130500×100)/15
X=870000

Like? Yes (2) | No   

Prateek khanna   8 years AGO

Let total balance be x according to question , x-= ( 2*x/5)+(x/4)+(3*x/20)+(x/20)+130500 X-130500=(17*x/20). So, x=870000

Like? Yes (2) | No   

SAKSHI SUMAN   8 years AGO

85% has been spent with 15% left.et total amount he had be x.
therefore,
15% of x =130500
therefore, x= 870000

Like? Yes (2) | No   

Sravanthi   8 years AGO

total money = y
(40y+25y+15y+5y)/100+(130500) = y;
y = 870000

Like? Yes (2) | No   

Vipul kumar   8 years AGO

assume initially he had x rupees in hand
now he spend (40+25+15+5)=85% of X

so the remaining with him is 15%of X
which is given as 130500

so (15*x)/100=130500
x=13050000/15
x=870000

Like? Yes (2) | No   

Akshat Sood   8 years AGO

Let the total price be x

then x-85x/100=130500

solve for x

x=870000

Like? Yes (2) | No   

Vaibhav Diwan   8 years AGO

40+25+15+5 =85
100-85= 15%
15% of x =130500
Therefore x= 130500*100/15 = 870000

Like? Yes (2) | No   

Gokul Krishnan   8 years AGO

100-(40+25+15+5)% of x=130500
x=870000

Like? Yes (1) | No   

Akshay Bhandakkar   8 years AGO

amount with him is 130500 which is the remaining 15% of total amount..
let total be x.
so,15% of x=130500.
solving,we get
x=870000
so option 6.

Like? Yes (1) | No   

jenishiya   8 years AGO

x-(85÷100)x=130500
100x-85x=13050000
15x=13050000
x=870000

Like? Yes (1) | No   

Gowtham   8 years AGO

Remaining 15% of the total money is given.Hence (15/100)*total money =130500.thereby total money is found.

Like? Yes (1) | No   

Dipanjan Mukherjee   8 years AGO

Let the total money be rs'x'
then
x-(40% of x+25% of x+15% of x+5% of x)=130500
on solving the value will be
x= rs 870000

Like? Yes (1) | No   

ramya   8 years AGO

40x+25x+15×+5x+(130500×100)=x*100
then x=870000
x is the total amount

Like? Yes (1) | No   

Ajith M   8 years AGO

for 100 rs he saves 15 and only for 87000 he could save the given amount

Like? Yes (1) | No   

ramarahavendar   8 years AGO

x is assumed as total money
so
0.4x+0.25x+0.15x+0.5x+130500=x
substituting and equating
x=870000

Like? Yes (1) | No   

Ashvini Shukla   8 years AGO

Remaining amount =15%
Balance sheet = Total amount*15%
=870000

Like? Yes (1) | No   

gayathri   8 years AGO

Total=spending+remaining
Total=x
X= (40x/100)+(25x/100)+(15x/100)+(5x/100)+130500
Then x=870000

Like? Yes (1) | No   

TANIYA ROY   8 years AGO

Let total money be x
40/100x+25/100x+15/100x+5/100x+130500=x
17x=20x-2610000
x=870000

Like? Yes (1) | No   

N.Sowjanya   8 years AGO

combining all the percentages he has left with 15% and given that he has left with the 130500 i.e.,
15%of x=130500
x=130500(10015)
x=870000
(assumed 'x' is the total sum he has)

Like? Yes (1) | No   

Amit kumar   8 years AGO

let us say he has Rs 100 then the remaining money will be rs 15 but the remaining money is Rs 130500,so 130500/15=8700
Therefore 100*8700=870000

Like? Yes (1) | No   

RAVAL   8 years AGO

if 15% is about 130500
then 100% is = ( 130500 * 100 ) / 15
answer = ? 87000

Like? Yes (1) | No   

Mudunuri rakesh   8 years AGO

total expenses are 85%
so remain 15%=130500
then 100%=8700

Like? Yes (1) | No (1)  

Rahul   8 years AGO

Let total money be 'x'.
then, (40x/100)+(25x/100)+(15x/100)+(5x/100)+130500=x
by solving above equation we get x=870000
option (6) is the answer.

Like? Yes | No   

Vipul Puranik   8 years AGO

total % spent = 85%
therefore 15% of x = 130500
x = 130500*100/15
x = 870000

Like? Yes | No   

abhishek joshi   8 years AGO

total money=x,
x-(40x/100+25x/100+15x/100+5x/100=130500
15x/100=130500
x=870000

Like? Yes | No   

keerthana   8 years AGO

(40+25+15+5)% of x +(130500)=x
85x+13050000=100x
x=870000

Like? Yes | No   

Lenin   8 years AGO

15% of total money is = 130500
then, the Total money is = (130500 * 100 /15) = 870000
Option 6.

Like? Yes | No (1)  

Jaikumar Bhatia   8 years AGO

Total Money Spending in %
=40+25+15+5=85%
Money Balance in %=15%
Money Balance in Rupees=130500
so,
Total Money in Rupees=130500/0.15=870000
Ans is 870000
Option is (6)

Like? Yes | No (1)  

Srikanthreddy    8 years AGO

let us say total money=x
spend money=>(40x/100)+(25x/100)+(15x/100)+(5x/100)
=(2x/5)+(1x/4)+(3x/20)+(1x/20)
=17x/20
remaining money=> x-(17x/20)=130500
=>3x/20=130500
total money with him(x)=>x=8,70,000

Like? Yes | No (1)  

balaji ram   8 years AGO

lets take initial amount = x
then after spending,
x - sum of spending amount(0.4x+ 0.25x +0.15x + 0.05x) = 130500
x - 0.85x = 130500
x = 130500/ 0.15
x = 870000 that is the ans.

Like? Yes (1) | No (2)  

Dinesh kumar sah   8 years AGO

Let the total money with him was X Rupees.
Then According to the question,
X-{(40X/100)+(25X/100)+(15X/100)+(5X/100)}=130500
or,15 X=13050000
Hence X=870000 Rupees Ans
so option(6 ) is the right answer.

Like? Yes | No (1)  

surya teja   8 years AGO

since all items consumed a total of 85% from 100%..Hence The remaining 15% is the amount 130500=15% of 870000

Like? Yes | No (1)  

shekhar kumar   8 years AGO

100-[40+25+15+5]% of x=130500
15% of x=130500
15/100*x=130500
x=130500*100/15
x=870000

Like? Yes | No (1)  

sapna gupta   8 years AGO

40%+25%+15%+5%=85% the owner spend
it means he has only 15% of the total balance left
so
15% of total amt= 130500
total amt= 130500*100/15
total amt= 870000

Like? Yes | No (1)  

sweety agarwal   8 years AGO

the remaining saving of man for 100%=100-40-25-15-5 =15
by the unity method
if prsn hv 5 in saving then total money=100
person have 130500 then total money was=130500*100/15=870000

Like? Yes | No (1)  

05 Jul 2016 Radius of fountain

A park is in the form of a rectangle. At the centre of the park there is a circular fountain. The area of the park excluding the fountain is 2086 m^2. The dimension of the park are 70m*65m. Find the radius of the fountain.

(Note - There was an error in the question; thus preventing you from getting the correct answer. As recompense, to all those who attempted the question before 11:37, we would provide with 20 points. The question has been edited, the new users can now attempt the question and gain points according to the previous guidelines.)

Users provided the answer before 11:37 please don't update your answer.

OPtion

1) 24 m
2) 7 m
3) 14 m
4) 18 m
5) 22 m
6) 26 m
7) 36 m
8) 39 m
9) 28 m
10) None of these

Solution

area of circular fountain = area of rectangle - remaining area
= 70*65 - 2086 m^2
4550 - 2086 = 2465 m^2
=> 22/7 r^2 = 2464
=> r^2 = 784 m^2
=> r = 28 m
Option 9)

Correct Option: 9 Best Solution (33)

swarupa malakala   8 years AGO

Area of park=70*65=4550m2
The area of park excluding fountain = area of park- area of fountain
2086=4550-Ï€r2
r=√(4550-2086)/π
r=28

Like? Yes (1) | No   

Jaspalsingh Parmar   8 years AGO

Area of rectangle = 70*65 = 4550
Area of fountain = 4550 - 2086 = 2464
So (22/7)* R^2 = 2464

So R = 28 m

Like? Yes (1) | No   

Vipul Puranik   8 years AGO

Total area of park = 70*65 = 4550 m^2
Area excluding fountain = 2086 m^2
Hence, remaining area of fountain = 4550 - 2086 = 2464 m^2
22/7*r*r = 2464 m^2
r*r = 784 m^2
r = 28m

Like? Yes (1) | No   

SURAJ PANDEY   8 years AGO

area of rectangle - area of fountain = 2086
70*65 - area of fountain = 2086
solving we get
area of fountain = 2464
as fountain is of circular area we can find its radius by formula
radius = 28m

Like? Yes (1) | No   

kavya   8 years AGO

area except fountain = 2080m^2
area of rectangle=70*65m^2
area of fountain=area of rectangle-area except fountain
AF=4550-2080
AF=2470
pi r^2=2470
r=sqrt(2470/3.14)
AF=28.6m

Like? Yes | No   

b sarath chandra   8 years AGO

PI*r*r+2086=70*65
PI*r*r=4550-2086
PI*r*r=2464
r*r=2464/PI
[PI=22/7]
r= sqrt(784)
r=28m

Like? Yes | No   

Param   8 years AGO

Area of park=70*65=4550
Area of fountain = 4550-2086 = 2464

As fountain is circular,
Area of fountain = pi*r*r = 2464

r*r = 784

r = 28m

Like? Yes | No   

sanjeet kumar   8 years AGO

70*65 - pi * r ^2 = 2086
On solving we get,
r = 28 m

Like? Yes | No   

anugna mythri   8 years AGO

Area of rectangle is 70*65.= 4550m^2 and given radius 2086 m^2 so deduct 2086 from 4550.to get area of circle it is 2464 finding r from pi*r^2= 2464 we get r=28

Like? Yes | No   

Ankit   8 years AGO

Total area of the rectangle is = 4550 m^2
Area of circular fountain is = (area of rectangle - area of remaining area)
4550-2086 = 2464

now, pi x r^2 = 2464
r = 28m

Like? Yes | No   

Vijayalakshmi Kandhan   8 years AGO

A park is rectangular which area is 70m*65m=4550(m^2). and the area of park excluding fountain is 2086 m^2. hence the area of circular fountain is 4550-2086=2464 m^2. area of circle is 22/7*r*r=2464m^2. r^2= 2464*7/22. radius r=28m.

Like? Yes | No   

A.KARTHIKA   8 years AGO

Area of the rectangle park is,
=70*65=4550
Area of the rectangle park excluding foundation,
=2086 m^2
diff between areas= 4550-2086 = 2464
Area=22/7*r^2
r^2= area*7/22
r^2=2464*7/22 = 784
r^2=784
r=28 m
ANS:28 m

Like? Yes | No   

Srikanthreddy    8 years AGO

=>total area of rectangle=70*65 = 4550 m^2.
=>So,area of circular fountain=> 4550-2086 = 2464 m^2.
=>Radius of fountain=>Pi*r^2 = 2464
=>r^2 = (2464*7)/22=784
=>r(radius) = 28 m.

Like? Yes | No   

Pranay   8 years AGO

area of the rectanglular park - area of park excluding mountain gives circular fountain area. then using circle area formula we can find radius.

Like? Yes | No   

Namrta shahapurkar   8 years AGO

Area of park-4550
Area of fountai-2464

Area of circle=22/7*r*r
r=28

Like? Yes | No   

Hemant Kanyal   8 years AGO

Area of rectange - area of circle = 2086
Area of rectangle = 4550
So, radius^2 = 7*2464/22
So, radius = 28

Like? Yes | No   

sweety agarwal   8 years AGO

the total area of the park is =70*65=4550
and the area excluding fountain is 2086
so the area of the fountain circle is 4550 - 2086 =2464
2464= PI r^2
r=28

Like? Yes | No   

Jayanth.V   8 years AGO

area of fountain =area of rectangle - area excluding fountain
so= 4550-2086
than solve for,area of circle..
so r=28m

Like? Yes | No   

kiran   8 years AGO

rectangle area - circle excluded rectangle = circle area

Like? Yes | No   

Raushan   8 years AGO

becoz we can find rectangle area by using dimension,and then subtract to given area to calculate fountain area and then area=22/7*r*r
simple r=28 m

Like? Yes | No   

Surendra Naraga   8 years AGO

Actual area of the park= 70*65 = 4550m^2
Area of the park excluding fountain=2086m^2
Area of the circular fountain = 4550-2086=2464 m^2
Area of the circle= pi.r^2
r^2=2464/pi
r^2=784.32
r=sqrt(784.32)
r=28.00
So the radius of the fountain is 28m.

Like? Yes | No   

bharath   8 years AGO

28m
70*65=4550
4550-2086=2464
r2=2464/3.141
r=28.00

Like? Yes | No   

nadeem zaya   8 years AGO

area of fountain is equal to the difference of area of whole reactangle park and area of park excluding fountain

Like? Yes | No   

sahil   8 years AGO

total area of rectangular -area of park excluding circle= area of circle

Like? Yes | No   

Gokul Krishnan   8 years AGO

tot area=350+2086=2436
22/7*R^2=2436
R=28

Like? Yes | No (1)  

Mrs.Thangaraj   8 years AGO

null

Like? Yes | No (1)  

balaji ram   8 years AGO

the whole are of the park is found from the dimension and it is subtracted with area excluding fountain. frm we got the area of fountain and using the pi/4* d^2 equals area we get the answer

Like? Yes | No (1)  

Shruti Mathur   8 years AGO

given area is of rectangle fountain area is not included.
Take the total of rectangle minus area of fountain is equal to 2086 m*2

Like? Yes | No (1)  

Akshat Sood   8 years AGO

Area of park excluding fountain=2086m^2

Area of park=60*75=4550m^2

Area of fountain=4550-2086=2464m^2

Now pi*r^2=2464

r=28 m [option 9]

Like? Yes | No (1)  

Jaikumar Bhatia   8 years AGO

Area of Park=70*65=4550m^2.........................(a)
Area of Park excluding fountain=2086m^2.....(b)
Area of Fountain=(a)-(b)=4550-2086=2464m^2
(Pi/4)d^2=2464
d=56m
r=28m
Ans is 28m
Option is (9)

Like? Yes | No (2)  

Rahul Sinha   8 years AGO

Area of the park = 4550
area excluded fountain = 2086
area of fountain = 2464
R^2 = 2464 * 7/ 22
R = 28 m

Like? Yes | No (2)  

Mridula Shaw   8 years AGO

Area of Park=70*65=4550 m^2
Area of fountain=4550-2086=2464 m^2
Thus,
Pi*r^2=2464
r^2=2464/pi
=>r=28 m

Like? Yes | No (2)  

Devendra Marghade   8 years AGO

Let radius of circular fountain be 'r' m. then
Area of the fountain=Pi*r^2=(70*65) - 2086=2464
r^2=2464/(22/7)=784
r=28
Option 9)

Like? Yes | No (2)  

04 Jul 2016 Sequence

What is the next number of the following sequence
2^4, 7, 4^4, 61, 6^4, 109, 8^4, .....

OPtion

1) 245
2) 9
3) 82
4) 42
5) 24
6) 118
7) 1
8) 48
9) 96
10)None of these

Solution

2^4 = 16
16 => 1*6+1 = 7

(4^4) = 256
256 => 2*5*6+1 = (61)

(6^4) = 1296
1296 => 1*2*9*6+1 = (109)

(8^4) = 4096
4096 => 4*0*9*6+1 = (1)
Option 7)

Correct Option: 7 Best Solution (3)

ashutosh kumar ojha   8 years AGO

the given series is...
2^4,7,4^4,61,6^4,109,8^4
i.e., 16,7,256,61,1296,109,4096
now..
1*6+1=7
2*5*6 +1=61
1*2*9*6+1=109
4*0*9*6+1=1
therefore the next term is 1

Like? Yes (6) | No (2)  

Jaikumar Bhatia   8 years AGO

2^4=16>1*6=6+1=7
4^4=256>2*5*6=60+1=61
6^4=1296>1*2*9*6=108+1=109
8^4=4096>4*0*9*6=0+1=1
Ans is 1
Option is (7)

Like? Yes (2) | No (2)  

madanpal vishwakarma    8 years AGO

given series (expended)
2^4,7,4^4,61,6^4,109,8^4.....

16 , 7 , 256 , 61 , 1296 , 109 , 4096 ,....

16, ((1*6)+1)=7 , 256, ((2*5*6) +1)=61 , 1296 , ((1*2*9*6)+1)=109 , 4096 , ((4*0*9*6)+1)=1....

So option 7 ) 1 is correct

Like? Yes (2) | No (2)  

01 Jul 2016 The sum of the bill

A bill was drawn on March 8, at 7 months date and was discounted on May 18, at 5%. If the banker's gain is Rs.3, find the sum of the bill.

OPtion

1) 6250
2) 8450
3) 6950
4) 7450
5) 8150
6) 6850
7) 7400
8) 7650
9) 7950
10)None of these

Solution

Date on which the bill was drawn = March 8th, at 7 months.
Nominally due date = Oct., 8th
Legally due date = Oct., 11th
Date on which the bill was discounted = May, 18th
Time for which the bill has yet to run
May June July Aug. Sep. Oct.
13+30+31+31+30+11 = 146 days = 2/5 years
Now (i) Banker's gain = S.I. of T.D.
i.e., Rs.3 is S.I. on T.D. for 2/5 years at 5%
=> T.D. = Rs. 100*3 / 5*(2/5) = Rs.150.
B.D. = T.D.+S.I. on T.D.
= Rs.150 + S.I. of Rs.150 for 2/5 years at 5%
= Rs.150 + Rs.150 * 2/5 * 5/100 = Rs.153
Therefor the sum of the bill
Sum = B.D.*T.D. / B.D.-T.D.
= Rs. 153*150 / 153-150 = Rs.7650
Option 8)

Correct Option: 8 Best Solution (1)

T.Bhargav saikumar Reddy   8 years AGO

B.D.*T.D.
sum= ------------------=153*150/153-150=7650
B.D.-T.D

Like? Yes (1) | No (3)  

30 Jun 2016 How many litre of water

The vertical cross-section of a trench is a trapezium, measuring 5 m. across the top, 3 m across the bottom, depth of trench uniform 2.5 m; length of trench 20 m. Find the roughly how many litres of water the trench with hold. (1 litre = 1000 cc)

OPtion

1) 2*10^8 L
2) 2*10^6 L
3) 4*5^5 L
4) 2*10^5 L
5) 2*10^9 L
6) 4*5^8 L
7) 4*10^4 L
8) 4*10^5 L
9) 2*10^4 L
10)None of these

Solution

Area of trapezium = 1/2 * (3+5)*2.5 = 10 m^2
Volume of trench = 10*20 = 200 m^3 = 200*10^8 cm^3
= 2*10^8 cm^3
= 2*10^8 / 1000 = L
= 2*10^5 L

Option 4)

Correct Option: 4 Best Solution (8)

Aakash Beniwal   8 years AGO

Area of trapezium * length of trench
(a+b) * 1/2* height * 20 m^3
(5+3) * 1/2 * 2.5 * 20 = 200 m^3 = 2*10^5 L

Like? Yes (1) | No   

ABHINAV PUSHPAM   8 years AGO

Area of the trench = 1/2*(a+b)*h
=1/2*(3+5)*2.5=10
volume= area* length=10*20=200 metre^3
= 2*10^2 meter^3
1 metre^3= 1000 litre= 10^3 litre
thus volume= 2*20^2*10^3 litre
= 2*10^5 litre

Like? Yes | No   

RAVAL   8 years AGO

Area of trapezium = 0.5 * (a +b) * h
= 0.5 * (5 + 3) * 2.5
= 10 cm^2
volume = area * length of trench
= 10 * 20
= 200 mc = 200 * 1000 cc
= 2*10^5 L
so, 2,00,000 litre of the water trench with hold.

Like? Yes | No   

Gokul Krishnan   8 years AGO

Volume of Trapezium=area of Trapezium*length
=[1/2(sum of 2 Parallel sides)*depth]*length
=[1/2(5+3)*2.5]*20
=200m^3 (1m^3=1000 L)
=2*10^5 L

Like? Yes | No   

Jayanth.V   8 years AGO

area of trapezium is 10 m^3 and volume is 200 m^3.
converting to litres the total litre is 200,000,000cc=200,000L
which is 2x10^5

Like? Yes | No   

Akshat Sood   8 years AGO

L*H*(A+B)/2

=200 m^3=2*10^8cm^3

now 1L=10^3cm3

2*10^8cm^3=2*10^5L

Like? Yes | No   

Lenin   8 years AGO

area = (5+3)*2.5/2=10 m^2.
volume= 10*20 = 200 m^3.
so, it is 200000 L.
option 4.

Like? Yes | No (2)  

Mukund Manohar   8 years AGO

Volume of Water = 1/2[(5+ 3) * 20] * 2.5 m^3
= 4*20*2.5 m^3
= 200 m^3
Capacity of water the trench with hold = 200 * 1000 litres
= 2 * 10^5 litres

Like? Yes | No (2)