M4maths Previous Puzzles

04 Nov 2015 Profit

A seller purchases the green colour of HOLI from two dealers, 5 kg. from a dealer at a rate of 60 rupee per kg. and 7 kg. from other dealer at a rate of 80 rupee per kg. If he sells the colour after mixing, then its selling rate for getting a profit of 20 % will be

OPtion

1) 84
2) 85
3) 87
4) 88
5) 90
6) 92
7) 86
8) 89
9) 91
10)93

Solution

Cost of 5 kg. green colour of HOLI is 60*5 = 300
Cost of 7 kg. green colour of HOLI is 80*7 = 560
Total cost of 12 kg. green colour of HOLI is 300 + 560 = 860
For getting 20 % profit, seller has to receive 860 * 1.2 = 1032 rupee
Hence cost of the colour is 1032/12 = 86

Correct Option: 7 Best Solution (35)

MURUGESAN.P   9 years AGO

c.p=5*60+7*80=860
c.p of 1 kg mix=860/12=71.66
s.p of mix=120% of c.p (ie)120% 71.66=86
therefore s.p=86

Like? Yes (3) | No   

Nishchi   9 years AGO

cp of 12 kg is 5*60+7*80=860
sp of 12 kg is 120/100*860=1032
sp per kg is 1032/12=86

Like? Yes (2) | No   

MRITUNJAY   9 years AGO

total cost=300+560=860

sp=860*1.2=1032

cost per kg=1032÷12=86
option 7

Like? Yes (1) | No   

Abhisheak Kumar Missu   9 years AGO

total cost price= 50*6+80*7=860
cp of one kg=860/12
so on 20%=860/12+(860/12*20/100)=258/3=86
hence sp= rs 86/kg

Like? Yes (1) | No   

RAHUL KUMAR   9 years AGO

Total C.P. = (5*60+7*80)= 860. Rs.
S.P. = (120*860)/100 = 1032 Rs.
Total Price of Green colour of HOLI = 1032 Rs.
Total weight of colour is 12 KG
so the price of per Kg is 1032/12 = 86 RS per Kg.
option (7) is correct answer.

Like? Yes (1) | No   

Kethineni Vinodh   9 years AGO

n1/n2=(A2-Aw)/(Aw-A1)
5/7=80-Aw/Aw-60
Aw=71.66
20% of 71.66=14.33
Then S.P=71.66+14.33=86

Like? Yes (1) | No   

PRAGATHI G   9 years AGO

cost price of 5kg rice is 300 rupees
cost price of 7 kg rice is 560 rupees
total cost price of 12kg Is 860
selling price = cost price + 20% of cost price
selling price=1032 rupees for 12kg
hence 86 rupees per kg

Like? Yes (1) | No   

L.Saral Martina   9 years AGO

5*60-300
7*80-560
20%300 is60
20% of 560 is 112
60+112 is 172
172/2 will be 86

Like? Yes (1) | No   

harshavi   9 years AGO

the answer would be 86 because the ccolurs are mixed in the ratio 5:7
thus we get (80-x)/(x-60)=5:7
then by solving we get x the mixture price as 215/3
thus for to get 20% profit (215/3)*(120/100)=86

Like? Yes (1) | No   

DHAYYALA SREEKANTH REDDY   9 years AGO

20%=((selling price-860)/860)*100
then selling price=1032
rate per kg=1032/12=86

Like? Yes (1) | No   

ramakrishnateja   9 years AGO

profit%=((s.p-c.p)/c.p)*100
total 12kgs c.p= 5*60+7*80=860/-.
hence ((s.p-860)/860)*100=20. s.p=1032. for 1kg=1032/12=86.

Like? Yes (1) | No   

Shubham Raj   9 years AGO

option 7 is correct ans
gain%=(gain/cost price)*100
we get gain=1032
rate (per kg)=1032/12=86

Like? Yes (1) | No   

Akshay   9 years AGO

he bought total 12kg in total of ru.860 ., so total 20 % profit then the total amt. will be 1032..
after that 1032/12 ans =86

Like? Yes (1) | No   

Anubhav jain   9 years AGO

5*60=300
7*80=560
Total cost=860
profit=selling price-cost price
860*20/100=profit
profit=172
selling rate=860+172=1032/12=86

Like? Yes (1) | No   

CHANDAN KUMAR   9 years AGO

from 1st dealer
amount spent for buying 5 kg colour at the rate of 60 =60×5
=Rs300

similarly from 2nd dealer
amount spent for buying 7 kg colour at the rate of 80 =80×7 = Rs 560

total amount spent for buying 12 kg of colours =Rs(300+560)=Rs860

so , according to the question,
20 percent of Rs 860=
( 20×860)/100 = Rs 172

new total amount spent for buying 12 kg colour =Rs (172+860) =Rs 1032

so , for selling price of1 kg colour=Rs 1032/12 =Rs 86

hence , correct option is 7 ) 86

Like? Yes (1) | No   

vinay agarwal   9 years AGO

5kg at the rate of 60 Rs per kg... so 300/-
7kg at the rate of 80 rs per kg....so 560/-

total:- 860/-

Now 100% of 860 is 860/-
10% will be,, divided by 10:- 86/-
20% will be ...multiplied by 2:- 172/-

total amount after selling of mixture of Green color:- 860+172=1032/-

12kg= 1032/-
1kg= 1032/12=86/- Rs per kg .................Ans

Like? Yes (1) | No   

dolly   9 years AGO

rs. 860 for 12 kg
if we cal. 20% of 860 its 172
adding we get rs. 1032
to cal. selling rate per kg cost needs
so,1032/12
gives 86

Like? Yes (1) | No   

Shadab Shaikh   9 years AGO

5Kg+7Kg=12Kg
(5X60)+(7X80)=860
860+20%=1032
1032/12=86

Like? Yes (1) | No   

Ankit Sharma   9 years AGO

from first dealer 300rs worth colors and from second 560rs worth.
for 20% profit (860/12)*1.2 = 86rs

Like? Yes (1) | No   

Vaithiyanaathan   9 years AGO

The amount spent by him on 12kg of green holi powder is 860. In order to gain a profit of 20 % , he has to get 1032 rupees on selling the 12kg.
1032/12 gives the price of 1kg
Hence 86

Like? Yes (1) | No   

vanitha thummala   9 years AGO

p%=(p/cp)*100
20=(sp-860/860)*100
sp=2*86+860
sp per kg=1032/12
sp=86

Like? Yes (1) | No   

SURAN PRASAD PENKE   9 years AGO

buy price =(5*60)+(7*80)=860
(20/100)860=172 is profit
selling=860+172=1032
per kg price=(1032/12)=86

Like? Yes (1) | No   

YASODA SURENDRA   9 years AGO

(5*60)+(7*80)=860
20% profit=860+172
Total=1032
(1032/12)=86

Like? Yes (1) | No   

Devendra Marghade   9 years AGO

SP/Kg @20% profit=120% of CP/Total weight
=(120/100)*(5*60 + 7*80)/(5+7)
=86
Option 7)

Like? Yes (1) | No   

chetan   9 years AGO

Total cost of color from two dealers=5*60+7*80=860.
20% of profit =860*0.2=172.
Total selling price of color=860+172=1032.
1kg color price=1032/12=86.
So option 7 is correct.

Like? Yes (1) | No   

Nandkishor jaiswal   9 years AGO

total cost of 5 kg rate 60 rpkg=300rs
total cost of 7 kg rate 80 rpkg=560rs
total cost of 12 kg mixed rice is =300+560=860
gain percent is 860+172=1032rs
so cost price of one kg mixed rice is =1032/12=86rpkg--option 7)

Like? Yes (1) | No   

rahul shaw   9 years AGO

total price of 12kg is 860
so 1 kg costs 71.6
after 20% profit the cost will be 86

Like? Yes (1) | No   

Venkateswarlu   9 years AGO

total price=60*5+7*80=860;
20% profit =172
total=1032;
price per kg=1032/12=86

Like? Yes (1) | No   

Jaikumar Bhatia   9 years AGO

Cost Price(C.P.)=(5*60+7*80)
=860..................(for 12kg)

Profit%=P%=20%

Selling price (S.P.) ={(100+P%)/100xC.P.
={(100+20)/100x860
=1032..........................(for12kg)

therefore for 1kg=1032/12
=86

ans is selling rate rupees 86 per kg
ie option (7)

Like? Yes (1) | No   

Sudipa Chakraborty   9 years AGO

Cost price of 5kg=5*60=rs 300
cost price of 7kg= 7*80=rs 560
total cp=860
he makes a profit of 20%
so selling price of (5+7)12kg=120*860/100=1032
so SP of 1kg=1032/12=86(ans)

Like? Yes (1) | No   

Manikandan.L   9 years AGO

5kg=300rs
7kg=560rs
total 12kg=860rs...
20% profit of 860rs is 1032rs...
hence 1032/12=86....
1kg=86rs

Like? Yes (1) | No   

sumit kumar   9 years AGO

12 kg color has cp is 5*60+80*7=860
profit percent is 20%
so selling price is 860*120/100=1032
so selling price for unit kg is 1032/12=86
option 7

Like? Yes (1) | No   

Gaurab Kumar Jha   9 years AGO

cp = (5*60)+(7*80)=860
sp = 860+(20/100*860)=1032
sp of i item=1032/12
=86 (option 7)

Like? Yes (1) | No   

Zahid Ali   9 years AGO

5*60+7*80=860
20% of 860=172
860+172=1032
1032/12=86

Like? Yes (1) | No   

Raghul Krishnan   9 years AGO

The mixture of the color powder after mixing weighs 12 KG.
That 12 KG mixture has
5:7 ratio.
So,
5x + 7x = 100 (%)
12x = 100
x = 100/12
x = 8.33
then,
5 * 8.33 = 41.67(% of 100%)
7 * 8.33 = 58.33(% of 100%)
If one kg
costs Rs.60 then 41.67% of that one kg costs Rs. 25
If one kg
costs Rs. 80 then 58.33% of that one kg costs Rs. 46.66
Then the 1KG of the mixed color costs
25 + 46.66 = Rs. 71.66
To get 20% profit,
For that, let 'r' be the selling price with 20% profit.
120/100 = r/71.66
r = (120 * 71.66)/100
r = 8599.2/100
r = 85.992
For prices up to two decimal place is enough.
So, r = 85.99
Which is approximately
r = 86

Like? Yes (1) | No (2)  

03 Nov 2015 Age Problem

The average age of 11 players of a cricket team is decreased by 2 months when two of them aged 17 years and 20 years are replaced by two reserves. The average age of the reserves

OPtion

1) 17 years 1 months
2) 17 years 10 months
3) 17 years 7 months
4) 18 years 8 months
5) 18 years 2 months
6) 17 years 11 months
7) 18 years 9 months
8) 17 years 6 months
9) 18 years 3 months
10)None of these

Solution

Decrease in total age = (11*2) months = 1 years 10 months
Total age of reserves = 17+20 years - 1 years 10 momnths
= 35 years 2 months
Therefore Average age of reserves = 17 years 7 months

Option 3)

Correct Option: 3 Best Solution (25)

Sushmita Ghanty   9 years AGO

total age decreased =11*2=22 months
total age of previous 2 players= 20+17=37
total age of new players= 37yr-22 months = 35 yrs 2 months
average age= 17 yrs 7 months

Like? Yes (21) | No (4)  

Kethineni Vinodh   9 years AGO

11*2=22 months
17+20=37 years
37 yrs- 22 months=35 yrs 2 months
avg= 34 yrs 14 months/2= 17 yrs 7 months

Like? Yes (20) | No (8)  

ABHINAV PUSHPAM   9 years AGO

Let x be the average age of 11 players, and y be the average of the reserve players

(11x + 2y - 17 - 20)/11 = x - 2/12 or y = 211/12
So, 17 years 7 months
Option 3)

Like? Yes (12) | No (1)  

vamsi krishna   9 years AGO

the average age of new player = 17 yrs 7 months.
If initial average age of 11 players was x and average age of 2 new players is y, then
11x-11*(x-2/12) = 17+20-2y
y = 17 7/12 yrs = 17 yrs 7 months

Like? Yes (7) | No (2)  

PRAGATHI G   9 years AGO

let sum of ages be s
s/11=x
where x is average
after replacement.. (s-17yrs-20yrs+a)=(x-2months)
where a is the average of reserves
now substitute x=s/11
and solve..
we get avg as 17 and 7 momths

Like? Yes (5) | No   

RANJAN FADIA   9 years AGO

total decrease in age= 11* 2= 22 month
age of reserves = (17+ 20)year - (22 month)
= 37 year - 1 year 10 month
= 35 year 2 month

=> average age of reserve = 35 yr 2 month / 2
= 17 year 7 month

Like? Yes (8) | No (4)  

RAHUL KUMAR   9 years AGO

the average age of new player = 17 yrs 7
months.
If initial average age of 11 players was x
and average age of 2 new players is y, then
11x-11*(x-2/12) = 17+20-2y
y = 17 7/12 yrs = 17 yrs 7 months
Option (3) is correct answer.

Like? Yes (3) | No   

Dinni   9 years AGO

the average age of new player = 17 yrs 7 months.
If initial average age of 11 players was x and average age of 2 new players is y, then
11x-11*(x-2/12) = 17+20-2y
2y= 37-11/6= 211/6 yrs
y=211/12 yrs = 17 7/12 yrs = 17 yrs 7 months

Like? Yes (3) | No   

premlata   9 years AGO

Decrease = (11 * 2) months = 1 year 10 months

Total age of reserves
(17 + 20) years - (1 year 10 months) = 35 years 2 months

Avg. age of the reserves
(1/2) 35 years 2 months = 17 years 7 months

Like? Yes (3) | No   

Raghul Krishnan   9 years AGO

let x be the sum of 9 members out of that 11.
When 2 members of age, 17 and 20 are replaced, then the change in the sum of the ages of 9 members will be unchanged.
But, according to the given condition the initial average age decreases by two months after the replacement.
Hence, Considering a loss of 2 months in the age of each members will give
11 * 2 = 22(months)
22 months = 1 year 10 months
This ' 1 year 10 months ' will be the age reduced from the sum of those two members 17 & 20.
So, When " 1 year 10 months "
is subtracted from the 37 years (17+20),
then it will be
35 years 2 months
then the average of 35 years is ' 17 years 6 months '
and the average of 2 months is ' 1 month '
Then the total average age of 2 reserves is
'17 years 6 months ' + ' 1 month ' = ' 17 years 7 months '

Like? Yes (4) | No (1)  

chetan   9 years AGO

Decreased age=11*2=1year and 10 months
Total age of reserves is (17+20)-(1year 10 months)=35years 2 months
avg of reserves =0.5*35 yrs 10 months=17 years 7 months.
So option 3 is correct.

Like? Yes (1) | No   

M Sreekanth Yadav   9 years AGO

the average age of new player = 17 yrs 7 months.
If initial average age of 11 players was x and average age of 2 new players is y, then
11x-11*(x-2/12) = 17+20-2y
y = 17 7/12 yrs = 17 yrs 7 months

Like? Yes (1) | No   

harshavi   9 years AGO

if avg is considered p then the sum of all ages of sum=11p---(1)
then the new avg is sum-17-20+(x+y)=11q----(2)
then (1)-(2) we get
37-(x+y)=22
and (x+y)=422 months
and thus avg of reserves would be 211 months which means 17 years 7 months

Like? Yes (1) | No   

Dr.Dipin Singh   9 years AGO

If x is initial average age and R is average age of two reserves, then
11(x-2/12)= 11x-37+2R
R= 17 yrs 7 months

Like? Yes (1) | No   

chinu singla   9 years AGO

the average age of new player = 17 yrs 7 months.
If initial average age of 11 players was x and average age of 2 new players is y, then
11x-11*(x-2/12) = 17+20-2y
y = 17 7/12 yrs = 17 yrs 7 months

Like? Yes (1) | No   

Abhishek Jaiswal   9 years AGO

37 is equal to sum of reserves plus total decrement in age , 22 months

Like? Yes (1) | No   

MADHUBABU   9 years AGO

Let x be the average age of 11 players, and y be the average of the reserve players

(11x + 2y - 17 - 20)/11 = x - 2/12 or y = 211/12

So, 17 years 7 months

Like? Yes (1) | No   

tarun   9 years AGO

total decrease in sum= 11*2=22 months
so sum of reserve players age= 37years-22months=35 years 2 months
so average of reserves=35years 2 months/2=17years 7 months

Like? Yes (2) | No (1)  

ROHIT   9 years AGO

because the total age of two players is 37
from this age subtract 2*11=22 months
after that the age of two reserves is 35 years 2 months divided by 2= 17 years 7 months

Like? Yes (1) | No   

Venkateswarlu   9 years AGO

avg of 17 and 20 years players=18 years 6 moths
by replacing reserves avg decreased by 2 months.
18 years 6 months-11 months=17years 7 months

Like? Yes (1) | No   

Vaithiyanaathan   9 years AGO

Let the age of 9 players be a1 to a9.
(a1+a2+a3+a4+a5+a6+a7+a8+a9+17+20)/11=x
Therefore a1+a2+a3+a4+a5+a6+a7+a8+a9=11x-37
Now they are replaced by two reserves.
Let the age of reserves be a10 and a11.
(a1+a2+a3+a4+a5+a6+a7+ a8+a9+a10+a11)/11= x-(2/12).
substituting for sum of a1 to a9 we get
(11x-37 +a10+a11)/11 = x-0.166
simplifying
a10+a11= 35.174
divide by 2
a10+a11=17.587

0.5 of year is 6 months.
0.587 is 7.2 months.
rounding it
we get 17 years 7 months

Like? Yes (2) | No (2)  

Jaikumar Bhatia   9 years AGO

Sum of age of original 11 players=S
av age of original 11 players =S/11=x

S/11=x.............................(i)
sum of two reserve players =y

By subtracting two original players age of 17yrs(204months)&20yrs(240months)
and adding two reserve players age
the av. age becomes=x-2

formula for this would be
(S-204-240+y)=x-2.....................(ii)

By substituting value of S from (i) into (ii)
and simply (ii)

Y=422 months..sum of ages of two reseves

therefore av =y/2
=422/2
=211months
=17years and 7 months
option (3)

Like? Yes (3) | No (3)  

Priya Verma   9 years AGO

1year 10 months is to be subtracted from (20+17) years & to find average of two reserves divide the obtained result I.e. 35 years 2months so answer is 17 years 7 months...

Like? Yes (3) | No (3)  

anju sukumaran   9 years AGO

the average age of new player = 17 yrs 7 months.
If initial average age of 11 players was x and average age of 2 new players is y, then
11x-11*(x-2/12) = 17+20-2y
2y= 37-11/6= 211/6 yrs
y=211/12 yrs = 17 7/12 yrs = 17 yrs 7 months

Like? Yes (1) | No (1)  

JENSI KARUNYA.S   9 years AGO

correct answer is option 3) 17 years and 7months

Like? Yes (1) | No (2)  

02 Nov 2015 X and Y?

What are X and Y?
7 8 6 9 5 10 X Y 3 12

OPtion

1) 4 and 6
2) 3 and 11
3) 2 and 12
4) 9 and 10
5) 3 and 9
6) 4 and 11
7) 5 and 11
8) 5 and 10
9) 7 and 13
10)None of these

Solution

X is 4; Y is 11
Two alternate series
Starting with the first number: 7 6 5 4 3
Starting with the second number: 8 9 10 11 12

Option 6)

Correct Option: 6 Best Solution (76)

Chandrajeet Yadav   9 years AGO

Alternatively two A.P. Series starting from first term 7 & 8 with common difference 1 in decreasing and increasing nature respectively.

7, 8, (7-1), (8+1), (7-2), (8+2), (7-3), (8+3), (7-4), (8+4)

X= 4, Y= 11

Like? Yes (5) | No   

Testing Account   9 years AGO

7-1=6 (3rd number),
8 1 =9 (4th number ),
like wise
5-x=1
10 y=1
x is 4 , y is 11

Like? Yes (1) | No   

Devendra Marghade   9 years AGO

Alternate series: 7,6,5,4,3 and 8,9,10,11,12
So X=4, Y=11
Option 6)

Like? Yes (2) | No (1)  

samita mandal   9 years AGO

its combination of two sequences
1st - 7 6 5 4 3 in decresing order
2nd- 8 9 10 11 12 in increasing order
x is 4 nd y is 11
option 6

Like? Yes (1) | No   

harshavi   9 years AGO

the first series is as 7,6,5,4,3
and the second series is as 8,,9,10,11,12
and thus x and y are 4 and 11

Like? Yes (1) | No   

Abhisheak Kumar Missu   9 years AGO

series1--7,6,5,4,3
series2--8,9,10,11,12
series will be--7,8,6,9,5,10,4,11,3,12
missing no X=4,Y=11

Like? Yes (2) | No (1)  

SHUBHAM   9 years AGO

7+1,8-2,6+3,9-4,5+5 ....and so on,,solving,we get 4&11

Like? Yes (1) | No   

RENU KUMARI   9 years AGO

the series is divided into two parts the first one is 7, 6, 5, 4, 3, 2 and the second one is 8,9,10,11 so x=4 and y=11

Like? Yes (1) | No   

Lakshmipathi   9 years AGO

Consider alternate numbers as set, then in first set numbers are decreasing by 1 and in second set numbers are increasing by 1

Like? Yes (1) | No   

Badarala Pavani   9 years AGO

two series
one is decreasing 7 6 5 so x=4
second series is increasing 8 9 10 so y=11

Like? Yes (1) | No   

Yekollu Muneeswar   9 years AGO

alternate terms- 7 ,6, 5, 4, 3

8 9 10 11 12

Like? Yes (2) | No (1)  

ARVIND KHATIK   9 years AGO

Number at odd position is decreasing and even position increasing.

Like? Yes (1) | No   

RUPNARAYAN RANA   9 years AGO

7-1=6
6-1=5
5-1=4
4-1=3
so one number (X)= 4
8+1=9
9+1=10
10+1=11
11+1=12
another number (Y)=11
Hence option 6) is correct.

Like? Yes (1) | No   

SURAN PRASAD PENKE   9 years AGO

each time adding and subtracting is taking place to previous number
and +1 -2 +3 -4 +5 -6 +7 -8 +9
7+1=8
8-2=6
6+3=9
9-4=5
5+5=10
10-6=4
4+7=11
11-8=3
3+9=12

Like? Yes (1) | No   

Jagadeesh   9 years AGO

7+1 =8
8-2 =6
6+3 =9
9-4 =5
5+5 =10
10-6 =4
4+7 =11
11-8 =3

Like? Yes (1) | No   

shaikshabeena   9 years AGO

divide in two series u get
7 6 5 4
8 9 10 11

Like? Yes (1) | No   

deepak   9 years AGO

7 6 5 4 3
and other series
8 9 10 11 12
so ans is 4 and 11

Like? Yes (2) | No (1)  

phani mamidi   9 years AGO

difference of first two numbers is summed to first number then we get the second number

Like? Yes (1) | No   

RAHUL KUMAR   9 years AGO

A/c to series
7 8 6 9 5 10 X Y 3 12
take series as 7 6 5 X 3 ....... (I) and
8 9 10 Y 12 ....... (ii)
in series (1) next term is decreses by 1 and in series (2) next term is increases by 1
So X = 4 and Y = 11
option (6) is correct answer.

Like? Yes (1) | No (1)  

susmit   9 years AGO

+1 -2
+3 -4
+5 -6 +7 so
10-6 and 4+7
4 and 11

Like? Yes (1) | No (1)  

pooja   9 years AGO

odd terms are decresed by 1 even terms are increased by 1 and hence 5-1=4 , 10+1=11

Like? Yes (1) | No (1)  

RANJAN FADIA   9 years AGO

first digit is decreasing.. n second is increasing
so x=4
& y=11

Like? Yes (1) | No (1)  

MRITUNJAY   9 years AGO

one series is increasing and second one is decreasing so that 4 and 11 is answer.

Like? Yes (1) | No (1)  

rahul shaw   9 years AGO

there r 2 series one incremented and other series is decremented ...so 4 and 11

Like? Yes (1) | No (1)  

Arifa   9 years AGO

7 8 6 9 5 10 X Y 3 12
7+1=8
8-2=6
6+3=9
9-4=5
5+5=10
10-6=4=X
4+7=11=Y
11-8=3
3+9=12
ANS OPTION 6)4 AND 11

Like? Yes (1) | No (1)  

CHANDAN KUMAR   9 years AGO

from left to right
odd place decreases from 7
(7 ,6,5,(4),3 )
so x = 4

similarly,
from left to right
even places increases from 8
(8,9,10, (11),12 )

so y=11

hence,

correct option is 6) 4 and 11

Like? Yes (1) | No (1)  

MD JAVED SALIM   9 years AGO

There are 2 series in this expression
1. 1st series is decreasing by 1
7 6 5 4(X) 3 . . .
2. 2nd series in increasing by 1
8 9 10 11(Y) 12 . . .
So , the actual series will be
7 8 6 9 5 10 4 11 3 12 . . .

Like? Yes (1) | No (1)  

sai   9 years AGO

7 6 5 X 3 all are in decrement order so the missing term is 4
8 9 10 Y 12 all are in increment order so the missing term is 11

Like? Yes (1) | No (1)  

Anuj Tiwari   9 years AGO

7, 8, 6, 9, 5, 10, X, Y, 3, 12

In this 7-1=6
and 8+1=9

Again 6-1=5
9+1=10

Again 5-1=4 (Value Of X)
10+1=11(Value Of Y) ANS

Again 4-1=3
11+1=12

Like? Yes (1) | No (1)  

s.h.h.praveen   9 years AGO

there are two a.p number series 1st=7,6,5,4,3...
2nd=8,9,10,11,12...

Like? Yes (1) | No (1)  

supreeta diwan   9 years AGO

7+8= 15.
6+9=15.
5+10=15.
4+11=15.
3+12=15.
so option is (6)

Like? Yes (1) | No (1)  

ARUN YADAV    9 years AGO

alternate series
first series is decreasing
and second series is increasing

Like? Yes (1) | No (1)  

Debanjan Maity   9 years AGO

1st number minus 1 will be the 3rd digit and 2nd number plus 1 will be the 4th digit

Like? Yes (1) | No (1)  

RAKESH   9 years AGO

7,6,5,4.......is series
9,10,11,12,,,is a series
so answer is 4,11

Like? Yes (1) | No (1)  

YASHWANT SAHU   9 years AGO

because 4 and 11 are the missing term in given series

Like? Yes (1) | No (1)  

Ashish Jaiswal   9 years AGO

7 8 6 9 5 10 X Y 3 12
there are two series
Ist series =7,6,5,4,3
IInd series=8,9,10,11,12
Then the value X=4
Y=11

Like? Yes (1) | No (1)  

karthiga   9 years AGO

In that Series, the alternate numbers 7, 6, 5, X, 3
It is in the form of Decreasing Consecutive Number So the X value is 2;
The next alternate numbers 8, 9,10, Y, 12
It is in the Form of Increasing Consecutive Number So the Y Value is 11;

Like? Yes (1) | No (1)  

Mahalakshmi   9 years AGO

it is a sequence
7 8
6 9
5 10
4 11 x and y
3 12

Like? Yes (1) | No (1)  

prasanthi   9 years AGO

every time the digit increment by +1,-2,+3,-4,+5,-6,+7,-8,+9

Like? Yes (1) | No (1)  

padmavati rai   9 years AGO

the series is formed by alternatively adding and subtracting the natural nos from the previous one

Like? Yes (1) | No (1)  

Shubham Raj   9 years AGO

first series decrease by 1,so-4
and second increase by 1 ,so-11

Like? Yes (1) | No (1)  

PRITI MISHRA   9 years AGO

8-7=1
8-6=2
9-6=3
9-5=4
10-5=5
10-x=6
x-y=7
hence x=4 and y=11

Like? Yes (1) | No (1)  

vimal tiwari   9 years AGO

odd position starts with 7 and decreases by 1

even position strts with 8 increases by 1

Like? Yes (1) | No (1)  

Vaithiyanaathan   9 years AGO

Odd numbers are added and even numbers are subtracted.
7+1=8
8-2=6
6+3=9
9-4=5
and so on.

Like? Yes (1) | No (1)  

Sushant Kumar   9 years AGO

7 8 6 9 10 4 11 3 12
firstly decreasing order then increasing order

Like? Yes (1) | No (1)  

Abhineet Singh   9 years AGO

add and subtract +1 and -1 ,you get value of X and Y as:
7-1=6,8+1=9,6-1=5,9+1=10,5-1=4(X),10+1=11(Y),4-1=3,11+1=12

Like? Yes (1) | No (1)  

ambar Vishwakarma   9 years AGO

every alternate number is a series of continuous integers.
7_6_5_X_3
8_9_10_Y_12

Like? Yes (1) | No (1)  

Hareesh   9 years AGO

7 +1 =8
7-1=6

7+2=9
7-2=5

7+3=10
7-3=4

7+4=11
7-4=3

and so on..

Like? Yes (1) | No (1)  

Dinesh thatti   9 years AGO

differences between them are as +1,-2,+3,-4,+5,-6,+7,-8,+9

Like? Yes (1) | No (1)  

Narasimha Swamy   9 years AGO

alternative numbers are in order which means odd position values are in decreasing order and even position values are in increasing order.

Like? Yes (1) | No (1)  

Navneet Goyal   9 years AGO

7 _ 6 _ 5 _ 4 _ 3 _decreasing by one
_ 8 _ 9 _ 10_ 11 _ 12

Like? Yes (1) | No (1)  

Aswini   9 years AGO

Numbers in odd places gradually decreased by 1 where as in even places increased by 1

Like? Yes (1) | No (1)  

prasenjit roy   9 years AGO

7 8 6 9 5 10 X Y 3 12
odd position numbers are7,6,5,4(x),3
Even position numbers are 8,9,11(y),12

Like? Yes (1) | No (1)  

Manoj   9 years AGO

first digit is in decrements of 1 and second digit in increment of 1

Like? Yes (1) | No (1)  

Tripti Garg   9 years AGO

The sequence can be split in 2 sequences:
7,6,5,X,3 and 8,9,10,Y,12
Clearly, the next term in 1st sequence is previous term-1, and in 2nd sequence is previous term+1.
Hence, X= 5-1=4, Y=10+1=11.

Like? Yes (1) | No (1)  

Rahul Mishra   9 years AGO

because in that digits first digit is decreasing and second one is increasing

Like? Yes (1) | No (1)  

tushar singh   9 years AGO

7,6,5,X,3 are in descending order, 4 will fit at position of X
8,9,10,Y,12 are in ascending order, 11 will fit at position of Y

Like? Yes (1) | No (1)  

SANKALP DUA   9 years AGO

8,9,10,11.12
7,6,5,4,3
these two series are mixed

Like? Yes (1) | No (1)  

oman jangir   9 years AGO

even place digit is incremented by 1 and odd place digit is decremented by 1

Like? Yes (1) | No (1)  

Somya Suravi Panda   9 years AGO

the series goes like..
+1, -2, +3, -4,....
so 10-6=4=x
4+7=11=y

Like? Yes (1) | No (1)  

Shubham Saxena   9 years AGO

7=G, 8=H
6=F, 9=I
5=E, 10=J
4=D, 11=k
3=C, 12=L

one time it is from left side thn from right side

Like? Yes (1) | No (1)  

Nandkishor jaiswal   9 years AGO

Each odd place is decreased by 1 and each even place is increased by 1
so, x=4 and y= 11

Like? Yes (1) | No (1)  

divya   9 years AGO

7 8 6 9 5 10 X Y 3 12
7-1=6
8+1=9
6-1=5
9+1=10
5-1=4
10+1=11
4-1=3
11+1=12

Like? Yes (1) | No (1)  

Udit Gopalka   9 years AGO

addition and subtraction signs go on alternatively with the numbers increasing as 1,2 and so on

Like? Yes (1) | No (1)  

Surabhi Yadav   9 years AGO

7 8 6 9 5 10 X Y 3 12
difference such as= +1,-2,+3,-4,+5,-6,+7,-8,+9
therefore
X=4 Y=11

Like? Yes (1) | No (1)  

pathrudu   9 years AGO

first series decreasing with 1 and second increasing with 1

Like? Yes (1) | No (1)  

jayachandra   9 years AGO

7+1=8
8-2=6
6+3=9
9-4=5
5+5=10
10-6=4*
4+7=11*
11-8=3
3+9=12

Like? Yes (1) | No (1)  

JENSI KARUNYA.S   9 years AGO

alternate num like 1st num 7 3rd num 6 likewise 7th num x is 4 and 8th num y is 11

Like? Yes (1) | No (1)  

Chandra chur anand   9 years AGO

one is decreasing by alternate and other one is incresing by alternate .

so x=4 and y=11

Like? Yes (1) | No (1)  

veerpal kaur   9 years AGO

acc. to pattern x=4 and y=11,bcoz in this pattern two successive no. have another no b/w them

Like? Yes (1) | No (1)  

swetha rekha   9 years AGO

it is following the sequence of +1 -2 +3 -4 and so on.so after subtracting -6 from 10 we get 4 and after adding +7 to 4 we get 11.hence,the answer is 4 and 11

Like? Yes (1) | No (1)  

YASODA SURENDRA   9 years AGO

7+1=8
8-2=6
6+3=9
9-4=5
5+5=10
10-6=4
4+7=11
11-8=3
3+9=12

Like? Yes (1) | No (1)  

mohan ranga rao   9 years AGO

odd place numbers=7,6,5,4,3,1
even place numbers =8,9,10,11,12
so x=4
y=11

Like? Yes (1) | No (1)  

Sushmita Ghanty   9 years AGO

the series is divided into two parts
7 6 5 X 3
&
8 9 10 Y 12
so we can easily solve X & Y 4 & 11 respectively

Like? Yes (1) | No (1)  

Divyani gupta   9 years AGO

it is combination of two series and two Adjacent number has sum 15
7 8 6 9 5 10 4 11 3 12

Like? Yes (1) | No (1)  

kundan roy   9 years AGO

in this series first +1 then -2 and then +3,-4,+5...
likewise added with numbers

Like? Yes (1) | No (1)  

30 Oct 2015 Area

Three non-concentric circles of equal radii are drawn such that each circle touches the other two externally. The centres are joined to form a triangle whose area is 17320.5 cm^2. Find the area of the triangle not included in the circles.

OPtion

1) 1740.5 cm^2
2) 1650.5 cm^2
3) 1540.5 cm^2
4) 1690.5 cm^2
5) 1475.5 cm^2
6) 1620.5 cm^2
7) 1680.5 cm^2
8) 1850.5 cm^2
9) 1720.5 cm^2
10)None of these

Solution

Note that the triangle is equilateral and side length is twice radius of circle. Also from area of triangle we can obtain side length of the triangle and consequently, the radius of the circle, and its area.
solve it by using figure
Area of triangle not included in the circle
= Area of triangle - Area of sectors
= 1620.5 cm^2
Option 6)

Correct Option: 6 Best Solution (9)

Deepak kumar singh   9 years AGO

1.74/4*(2r)^2=17320.5 => r=100
area of circle inside triangle=3*(60/360*3.14*(100)^2=15700
Required area=17320.5-15700=1620.5 ans

Like? Yes (5) | No   

Abhisheak Kumar Missu   9 years AGO

diameter of circle=200cm
radius of circle=100cm
area of circle enscribed by triangle=1/2*22/7*100*100=15714cm2
Area of triangle not circle=1620.5

Like? Yes (1) | No   

RANJAN FADIA   9 years AGO

area of equilateral triangle = (root 3* side ^2 )/4
=> 17320.5 = (root 3 * 4*r^2)/4 { since side =2r , r is radius }

=> r^2 = 17320.5 /(root 3)

now, required area = (area of equilateral triangle) - 3*(area of arc made in circle)

=> area = 17320.5 - {3* (pi * r^2)/6}
[since area of arc = (angle * pi *r^2) 360 degree angle ]

=> area = 17320.5 - (pi*17320.5)/2* root 3 )
= 1620.04 cm^2...................... ans.

[take pi =3.14 ]

Like? Yes (2) | No (1)  

Robert Yogenson   9 years AGO

not included circle area ==area of triangle -3(pie*R^2)*1/6
17320.5- 1/2(pie *17320.5/root3) =1620.5

Like? Yes (1) | No   

Amit kumar yadav   9 years AGO

using area of equilateral triangle (sqrt(3)*a*a)/4 we find side=200 using sector formula
given area -(60/360)*pie*a*a*3 =1620.5

Like? Yes (1) | No   

VICKY JAISWAL   9 years AGO

area of triangl is ?3*r^2
so r=100
area of sector is (angle/360)*?r^2
and total 3 sector so tatal area is15700
remaining area is 17320.5-15700=1620.5cm^2

Like? Yes (1) | No   

Nandkishor jaiswal   9 years AGO

given that area of triangle is 17320.5 cm^2
sqrt(3)/4*a^2=17320.5
so, a=200 cm
now r=200/2=100 cm
now area of circle that are lie into the triangle is
3*60/360*3.14*100*100=15700 cm^2
so area of triangle that are lie into the circle is=
17320.5-15700=1620.5 cm^2

Like? Yes (1) | No   

Sushant Kumar   9 years AGO

Let each side of the triangle be a cm. Then,
Area = 17320.5cm2
⇒ 3√4a2=17320.5 [sinceArea=3√4(side)2]
⇒ a2=17320.5×43√=17320.5×41.73205=40000
⇒ a = 200
Thus, radius of each circle is 100 cm.
Now, required area
= Area of Δ ABC – 3 ×(Area of a sector of angle 60º in a circle of 100 cm)
=[17320.5−3(60360×3.14×100×100)]cm2
=(17320.5−15700)cm2=1620.5cm2

Like? Yes (1) | No   

sumit kumar   9 years AGO

according to question an equilateral triangle will form.
so area of equilateral triangle is (?3/4)*side^3=17320.5 cm^2
after solving it we get a=200 cm(approx).
so radius of circle will be r=a/2=100 cm
now area of 3 sector of circle is s2= 3*(angle/360)*?r^2=15700 cm^2
our design answer is =17320.5-s2
i.e 1620.5 cm^2.
option 6

Like? Yes (2) | No (1)  

29 Oct 2015 Probability

A non negative number having all distinct digits is such that the product of all digits of the number is 504. Probability that the number has sum of all its digits 25 will be

OPtion

1) 1/6
2) 2/3
3) 1/4
4) 1/72
5) 1/3
6) 1/36
7) 1/2
8) 1/12
9) 1/8
10)1/24

Solution

Product is 504
The number can have digits 1, 2, 3, 4, 6, 7, 8 & 9
Possibilities are (1,7,8,9); (2,4,7,9); (3,4,6,7)
Total numbers possible = 3(4!) = 72
Favourate numbers = 24
So probability = 24/72 = 1/3
Option 5)

Correct Option: 5 Best Solution (1)

Amit kumar yadav   9 years AGO

finding prime factor we get 2*2*3*2*3*7.so number are 4,6,21 so possibilities are total outcome are (21,4),(6,21),(4,6) hence probability is 1/3

Like? Yes (7) | No (9)  

28 Oct 2015 Time and distance

A train running at 25 kmph takes 18 second to pass a platform. Next, it takes 27/2 second to pass a man walking at the rate of 5 kmph in the same direction. Find the length of the train and that of the platform.

OPtion

1) 65m and 50m
2) 75m and 65m
3) 75m and 50m
4) 85m and 55m
5) 95m and 75m
6) 95m and 50m
7) 55m and 80m
8) 75m and 85m
9) 75m and 70m
10)None of these

Solution

Speed of the train relative to man
= 25-5 kmph = 20 kmph = 20*5/18 m/sec = 50/9 m/sec
In passing a man, the train covers it own distance with relative speed.
Therefore length of train = relative speed * time = 50/9 * 27/2 m
= 75 m
Also, the distance traveled in 18 second at 25 kmph or 25*5/18 m/sec. is the sum of lengths of the train and the platform
Therefore Length of train+Length of platrom = 25* 5/18 * 18 m
= 125
Hence, the length of platfrom = 125-75 = 50 metre
Option 3) 75m and 50 m

Correct Option: 3 Best Solution (19)

RANJAN FADIA   9 years AGO

lenght of train = 75 m
combine length of train & platform = 125m
so length of platform =50 m

Like? Yes (4) | No   

JEGATHA.H   9 years AGO

train length=x;platform len =y;
speed of train relative to man = (25-5)=20kmph
=(20*5/18)m/sec
= 50/9 m/sec
leng of train =speed*time=50/9*27/2=75m
speed of train = 25*5/18=125/18m/sec
18(x+y)/125=18
x+y=125
y=125-75=50m

Like? Yes (2) | No   

Anubhav jain   9 years AGO

D=s*t
25*5/18*18=125 meter
option 3

Like? Yes (2) | No   

bhaskar   9 years AGO

13.5*(25-5)*1000/3600=75
(25*18*1000/3600)-75=50

Like? Yes (2) | No (1)  

SAGNIK DATTA   9 years AGO

train length = t platform =p
t+p = 25*18/3600
t = 27*20/7200
solving t=75
p=50

Like? Yes (2) | No (1)  

MRITUNJAY   9 years AGO

let train length be x m and platform length is y m

x/20*5/18=27/2

x=75 m

75+y/25*5/18=18

y= 50 m

option 3.

Like? Yes (1) | No   

Robert Yogenson   9 years AGO

length of train =(25-5)X5/18X27/2=75 m
and total length =25X5=125
platform =125-75=50 m

Like? Yes (1) | No   

jalaj   9 years AGO

I Calculated the length of the train first by using concept of relative velocity of the train and man.Since both are moving in same direction.So,speed=20 * 5/18m/s=
Time (given as)=27/2 sec From this we get Distance =75m
Now I use the equation. 75+Length of platform/18=25*5/18(I used the equation Distance/Time=Speed.From this,I get the Ans length of the platform as 50m

Like? Yes (1) | No   

Ruby kaushik   9 years AGO

suppose length of train is - L
length of bridge is - B
So L+B = time* speed
L+B = 18*(75/18) [change speed in m/sec - 25*5/18]
L+B = 125 -------- (1)

now the relative speed of train and man is 20 km (25-5) = 20*5/18 = 100/18 m/sec

So L = 100/18* 27/ 2 = 75 ------- (2)

from equation 1 and 2
L = 75m and B = 50m

Answer is 3

Like? Yes (1) | No   

Priya Verma   9 years AGO

(length of train + length of platform)=25*5/18*18=125m
length of train = 20*5/18*27/2=75m
and hence length of platform = (125-75)=50m

Like? Yes (1) | No   

Arifa   9 years AGO

speed of train=25 km/ph=(25*5/18)=125/18 m/s
speed of train relative to man=25-5=20 km/ph
=(20*5/18)=100/18 m/s
length of train=(27/2)*(100/18)=75 m
total distance =length of platform+length of train
total distance=18*125/18=125 m
length of platform =125-75=50 m
ans option 3) 75 m & 50 m

Like? Yes (1) | No   

Abhisheak Kumar Missu   9 years AGO

Length of platform+train= 25*5/18*18=125m
Relative speed of train=25-5=20km/h
Length of train=20*5/18*27/2=75m
so Length of platform=125-75=50m

Like? Yes (1) | No   

sanjeev kumar   9 years AGO

by changing 25 kmph to m/s multiply it by 5/18 = 125/18m/s
and in 18 sec it covers 125m.
and 25kmph-5kmph= 20 kmph = 20*5/18=100/18m/s
in 13.5 sec it will cover = 75m (which will be the length of the train as man will have a negligible length w.r.t train).
therfore, if train lenght =75m then 125-75= 50m will be platform length.

Like? Yes (1) | No   

nikhil kumar   9 years AGO

relative speed=25-4=20 km/hr=100/18m/s
length of train(x)=time taken to cross pltfrm x speed=27/2 x 100/18=75m
now total length of train and platfrom =x+y
then x+y=speed of train in m/s x time to pass platform=50m
so option 3 is correct

Like? Yes (1) | No   

ABHIJEET ANAND   9 years AGO

let lenth of train =x;
lenth of plateform=y;
now,
from question,
x/(20*5/18)=27/2;
x=75m;
again,
(y+75)/(25*5/18);
y=50

Like? Yes (1) | No   

Anuj Tiwari   9 years AGO

Realtive Speed=25-5 KMPH

Now, Let length of train be x meters.
S=D/T

20*(5/18) m/s =(x) /(27/2)

Therefore, x=75 meters (Length of train)

now let length of platform be y meters

25*(5/18)=(75+y)/18

y=50 meters (length of platform)

Like? Yes (1) | No   

ritu raj anand   9 years AGO

time taken to cross the platform= (Length of train + length of platform)/ speed of train
L of train+ L of platform= 125
again,
time taken to cross the man= L of train/ relative speed of train and man
therefore, L of train =75
hence, L of platform= 125-75 = 50.

Like? Yes (1) | No   

akash gupta   9 years AGO

let l train length and p platform length
25*5/18=(l+p)/18
l+p=125
check the option 75+50
s0 3 option is right

Like? Yes (1) | No   

vikash ranjan   9 years AGO

25*5/18 *18=125
(25-5)*5/18 * (27/2)=75
125-75=50

Like? Yes (1) | No (1)  

27 Oct 2015 Area

The cost of carpeting a room 15 metres long with a carpet 75 cm wide at 30 paisa per metre is Rs. 36. The breadth of the room is

OPtion

1) 3 metres
2) 6 metres
3) 8 metres
4) 9 metres
5) 10 metres
6) 11 metres
7) 12 metres
8) 14 metres
9) 16 metres
10)None of these

Solution

Length of the carpet = Total cost / Rate = 3600/30 = 120 m
Let breadth of the room be x metres
Then 120*75/100 = 15*x or x = 6 metre

optoin 2)

Correct Option: 2 Best Solution (26)

RANJAN FADIA   9 years AGO

total lengths of carpet in room = 36/.30 =120 mtr .

so how much carpet used = 120 * 0.75 = 90 mtr sq
that is breadth of room = 90 / 15 =6 mtr ans

Like? Yes (8) | No (1)  

SAGNIK DATTA   9 years AGO

let breadth=x
so 15x/.75=3600/30
x=6

Like? Yes (8) | No (2)  

Yashi Das   9 years AGO

Length of the carpet= total cost/(rate/m) = 3600/30= 120m
Area of the carpet =(120*(75/100))=90m^2
Therefore,Breadth = Area/ length =90/15 =6 m

Like? Yes (8) | No (2)  

ramakrishnateja   9 years AGO

here the area of carpet= area of room. ,area of room=l*0.75m^2
area of room=15*bm^2. let breadth=bm.
length of carpet=totalcost of carpenting/cost per meter
hence length of carpet=3600/30=120m.
hence 15*b=120*0.75.b=6m.

Like? Yes (8) | No (3)  

vamsi krishna   9 years AGO

Length of the carpet= Total cost/ rate/m= 3600/30=120m

Area of the carpet= 120*75/100= 90m2

Breadth of the room = (Area/ length)= 90/15= 6m

Like? Yes (8) | No (4)  

ABHINAV PUSHPAM   9 years AGO

Length of the carpet= Total cost/ rate/m= 3600/30=120m
Area of the carpet= 120*75/100= 90m
Breadth of the room = (Area/ length)= 90/15= 6m

Like? Yes (9) | No (5)  

RAHUL KUMAR   9 years AGO

Length of the carpet= Total cost/ rate/m= 3600/30=120m
Area of the carpet= 120*75/100= 90m
Breadth of the room = (Area/ length)= 90/15= 6m

Like? Yes (5) | No (2)  

Shubham Raj   9 years AGO

The breadth of the room is Area of room = length * bredth Total length of carpet : 36/.3 = 120 meters
Total area of carpet used :=.75 * 120= 90 sqmeters.
Thus width of the room = 90/15= 6 meters
width = 6 meters

Like? Yes (4) | No (1)  

Meenakshi yadav   9 years AGO

Length of tha carpet= 3600/30=120m
Area of the carpet=120*75/100= 90 m^2
Breadth of the room=90/15=6 m.

Like? Yes (4) | No (1)  

Rashmi Chandra   9 years AGO

Total cost (36)={length of room(15)*width of room (6)*cost per meter(.30)}/width of carpet (.75)

Like? Yes (3) | No (1)  

Jaikumar Bhatia   9 years AGO

Breadth =6.0meters
carpet strip width=0.75 meter
No of strips:6.0/0.75=8nos
Total cost =LxNo of stripxrate per strip
=15x8xo.30
=36
hence proved

Like? Yes (3) | No (1)  

SHUBHAM   9 years AGO

((15*X)/(75cm))*(0.3)=36
on solving for X,we got 6

Like? Yes (3) | No (1)  

SOMA NARESH   9 years AGO

Length of carpet = 3600/30=120m
Area of carpet=120*75/100=90 m2
Breadth of carpet= Area / length = 90/15=6m

Like? Yes (3) | No (1)  

Robert Yogenson   9 years AGO

30 paisa per minute=36 and change into rupees 36/30=1.2x100=120 (is called length of carpet)
Area of carpet=.75mX120=90
then breadth of room=90/15=6 m(because both area will be equal )

Like? Yes (3) | No (2)  

Swathi   9 years AGO

Length of the carpet= Total cost/ rate/m= 3600/45=120m

Area of the carpet= 120*75/100= 90m^2

Breadth of the room = (Area/ length)= 90/15= 6m

Like? Yes (4) | No (3)  

Ruby kaushik   9 years AGO

length of carpet = total cost/(cost/m) = 3600 / 30 = 120 m
area of carpet = 120*75/100 = 90 m
breadth of room = area/length = 90/15 = 6m
so answer is option 2

Like? Yes (3) | No (2)  

MRITUNJAY   9 years AGO

length of the carpet=3600/30=120m

area of the carpet=120*75/100=90 m^2

breadth of room=90/15=6m

Like? Yes (3) | No (2)  

Sushant Kumar   9 years AGO

length of the carper=120
Area of the room =90
Breadth=Area/Length
=6m

Like? Yes (3) | No (2)  

sumit kumar   9 years AGO

.30 rupess for 1 meter carpet
so in 36 rupees carpet length is (1/.30)*120=120m
according to question
area of room=area of carpet
15*x=120*.75
x=6m

Like? Yes (3) | No (2)  

S.Hemanth kumar   9 years AGO

R.S is 36 per meter is 3600 per 30 paisa so 3600/30=120m
Area= 120*75*10^-2=90
breadth of the room = 90/15=6m
so Ans) 2

Like? Yes (1) | No (1)  

Chandrajeet Yadav   9 years AGO

let length of carpet and breadth of room is x and y meter respectively.
then, 30 * x = 36*100
so, x = 120

Now, 15 * y = 120 * 0.75 * 100
so, y = 6

So breadth of the room = y = 6 meter

option (2

Like? Yes (4) | No (4)  

rakesh sharma   9 years AGO

30/100 rupess ....1meter
1 rupess................100/30
then 36rupesss.......(100/30)*36=120 meter carpet used
so 0.75*8=6 only one option is setisfy this situation
so answer option (2) is correct

Like? Yes (3) | No (3)  

Deepanshu Chaturvedi   9 years AGO

area of room = length * bredth
total length of carpet = 36/.3 = 120 meters
total area of carpet used = .75 * 120 = 90 sqmeters
thus width of the room = 90/15 = 6 meters
option 2)

Like? Yes (2) | No (3)  

premlata   9 years AGO

Length of carpet = 3600/30 = 120 m
Area of Carpet = 120 * 75 / 100 = 90 m^2
Breadth of room = Area/length = 90/15 = 6 m.

Like? Yes (4) | No (5)  

JEGATHA.H   9 years AGO

area=len*bre=15b
length of carpet=area/width=15b*4/3=20b
cost=20b*30
b=6 meters

Like? Yes (2) | No (3)  

Arnab Maity   9 years AGO

Area of room = length * breadth
Total length of carpet => 36/.3 = 120 metres
Total area of carpet used => 0.75 * 120= 90 sqmetres.
Thus breadth of the room => 90/15= 6 metres.
Answer) option 2) breadth of the room is 6 metres.

Like? Yes (2) | No (4)  

26 Oct 2015 Sequence

What is the next number of the following sequence
1, 2, 6, 24, 120, 720,......

OPtion

1) 5760
2) 4320
3) 6120
4) 3960
5) 5400
6) 6480
7) 5040
8) 5220
9) 5184
10)None of these

Solution

Multiply each number by 2, 3, 4, 5 and 6 and (finally) 7.
720*7 = 5040

Option 7)

Correct Option: 7 Best Solution (72)

MD JAVED SALIM   9 years AGO

1=1
1*2=2
1*2*3=6
1*2*3*4=24
1*2*3*4*5=120
1*2*3*4*5*6=720
1*2*3*4*5*6*7=5040

Like? Yes (8) | No   

DIPAK TIWARI   9 years AGO

5040
keeps increasing the number being multiplied.
1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
next would be:
720*7=5040

Like? Yes (3) | No   

karthiga   9 years AGO

1, 2, 6, 24, 120, 720, ...
It is in the form of
1!, 2!, 3!, 4!, 5!, 6!, 7!....
So the next number is 7! = 5040 Answer.

Like? Yes (3) | No   

Kopal Agarwal   9 years AGO

1!=1
2!=2
3!=6
4!=24
5!=120
6!=720
7!=5040

Like? Yes (3) | No   

bhaskar   9 years AGO

1*2
2*3
6*4
24*5
120*6
720*7=5040

Like? Yes (2) | No   

RUPNARAYAN RANA   9 years AGO

1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
720*7=5040

Like? Yes (2) | No   

Yashi Das   9 years AGO

1 x 2 = 2;
2 x 3 = 6;

6 x 4 = 24;

24 x 5 = 120;

120 x 6 = 720;

720 x 7 = 5040

Like? Yes (1) | No   

sheenu garg   9 years AGO

sequence is as 1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
so 720*7=5040

Like? Yes (1) | No   

Dinesh thatti   9 years AGO

1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
720*7=5040

Like? Yes (1) | No   

RANJAN FADIA   9 years AGO

when we divide next term from previous.. we get a sequence like 2...3...4...5...6....7
ans. 720*7=5040

Like? Yes (1) | No   

Meenakshi   9 years AGO

1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
720*7=5040
option 7)

Like? Yes (1) | No   

Nandkishor jaiswal   9 years AGO

This series are factorial called from 1 to 7
1*2=2,2*3=6,6*4=24,24*5=120,120*6=720,720*7=5040

Like? Yes (1) | No   

Akshay   9 years AGO

this series based on the factorial , factorial of 7 is 5040

Like? Yes (1) | No   

SOMA NARESH   9 years AGO

1*1=1
1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
720*7=5040

Like? Yes (1) | No   

AKASH RAO DESHMUKH   9 years AGO

2÷1=2
6÷2=3
24÷6=4
120÷24=5
720÷120=6
5040÷720=7

Like? Yes (1) | No   

Tanya Sachdev   9 years AGO

series of multiplication in increasing order
1*2,2*3,6*4 and so on
therefore 720*7= 5040

Like? Yes (1) | No   

Ruby kaushik   9 years AGO

relationship between numbers are
1* 2 = 2
2* 3 = 6
6*4 = 24
24*5 = 120
120*6 = 720
so
720*7 = 5040
option 7 is the answer

Like? Yes (1) | No   

saurabh kumar   9 years AGO

1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
720*7=5040

Like? Yes (1) | No   

dee hack kr   9 years AGO

1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
720*7=5040

Like? Yes (1) | No   

Jaikumar Bhatia   9 years AGO

1x2=2
2x3=6
6x4=24
24x5=120
120x6=720
720x7=5040

Like? Yes (1) | No   

ved prakash yadab   9 years AGO

1!=1
2!=2
3!=6
4!=24
5!=120
6!=720
7!=5040

Like? Yes (1) | No   

Shijan handa   9 years AGO

1×2=2
2×3=6
6×4=24
and so on
720×7=5040

Like? Yes (1) | No   

raghavendra   9 years AGO

720*7=5040
120*6=720
24*5=120
6*4=24...

Like? Yes (1) | No   

vineesha p   9 years AGO

1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
720*7=5040

Like? Yes (1) | No   

JEGATHA.H   9 years AGO

1*2=2,
2*3=6
6*4=24
24*5=120
120*6=720
720*7=5040

Like? Yes (1) | No   

Manish prajapati   9 years AGO

1*1=1.
1*2=2
2*3=6
6*4= 24
24*5=120.
120*6=720
720*7=5040

Like? Yes (1) | No   

shanmuga   9 years AGO

multiplication of the nos increases in ascending order

1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
720*7=5040

Like? Yes (1) | No   

banusundar   9 years AGO

1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
720*7=5040
ANS : 5040

Like? Yes (1) | No   

s.h.h.praveen   9 years AGO

series is 1*1+1,2*2+2,6*3+6,24*4+24,120*5+120,720*6+720=5040

Like? Yes (1) | No   

Sayyad Raeesa   9 years AGO

1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
720*7=5040

Like? Yes (1) | No   

Ann Theressa   9 years AGO

1*2 2
2*3 6
6*4 24
24*5 120
120*6 720
720*7 5040

Like? Yes (1) | No   

amrit   9 years AGO

Each number is appearing by multiplying the previous number by 1,2,3,4.... So on

Like? Yes (1) | No   

CHANDAN KUMAR   9 years AGO

1!,2!,3!,4!,5!,6!,......
next no. will be 7!
which is equal to 5040

Like? Yes (1) | No   

Rajesh Jakkula   9 years AGO

every number is multiple of sequence 1,2,3,4.. so on.720*7=5040

Like? Yes (1) | No   

Rahul kumar   9 years AGO

1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
720*7=5040

Like? Yes (1) | No   

supreeta diwan   9 years AGO

1*2=2 , 2*3=6, 6*4=24 , 24*5= 120, 120*6= 720, 720*7= 5040.
so option is 7

Like? Yes (1) | No   

Chandra Bhushan   9 years AGO

n(i) = n(i-1)*i, i=2,3.... where n(i) is the ith number in the series

Like? Yes (1) | No   

rajkumar   9 years AGO

1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
720*7=5040

Like? Yes (1) | No   

TARUN CHAUHAN   9 years AGO

It is a simple series

1, 1*2=2, 2*3=6, 6*4=24, 24*5=120, 120*6=720, 720*7=5040

Like? Yes (1) | No   

Shana Hermiya   9 years AGO

1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
720*7=5040

Like? Yes (1) | No   

AASTHA MITTAL   9 years AGO

1!=1
2!=2
3!=6
4!=24
5!=120
6!=720
7!=5040

Like? Yes (1) | No   

Tinku   9 years AGO

X*2 , *3 , *4 , *5 , *6 , *7.
1 * 2 = 2,
2 * 3 = 6,
6 * 4 = 24,
24 * 5 =120,
120 * 6 = 720,
720 * 7 = 5040.

Like? Yes (1) | No   

subbulakshmi   9 years AGO

1
1x2=2
2x3=6
6x4=24
24x5=120
120x6=720
720x7=5040

Like? Yes (1) | No   

ramakrishnateja   9 years AGO

sequence is of the form 1!,2!,3!,4!,5!,6! hence next is 7!=5040

Like? Yes (1) | No   

RENU KUMARI   9 years AGO

series is 1*2=2, 2*3=6, 6*4=24, 24*5=120, 120*6=720, 720*7=5040

Like? Yes (1) | No   

mohan ranga rao   9 years AGO

1*2
2*3
6*4
24*5
120*6
720*7=5040
option 7

Like? Yes (1) | No   

Isha Saxena   9 years AGO

the given series is nothing but 1! , 2! , 3! , 4! , 5! , 6! , 7! , ........
we are given till 6! that is=720
so next term =7! =5040
and a factorial is calculated as :
n!=n*(n-1)*(n-2)*(n-3)*.......*2*1
where n is any positive integer.

Like? Yes (1) | No   

SK INTAJ MOHAMMAD   9 years AGO

1*2=2;
2*3=6;
6*4=24;
24*5=120;
120*6=720;
720*7=5040(ans)

Like? Yes (1) | No   

SHUBHAM   9 years AGO

1*2=2
2*3=6
6*4=25
24*5=120
120*6=720
720*7=5040

Like? Yes (1) | No   

Ashish Jaiswal   9 years AGO

it is an factorial series
1*1=1
1*2=2
1*2*3=6
1*2*3*4=24
1*2*3*4*5=120
1*2*3*4*5*6=720
1*2*3*4*5*6*7=5040

Like? Yes (1) | No   

ABHISHEK GAURAV   9 years AGO

In the sequence 1,2,6,24,120,720....
jst go on multiplying...1*2= 2 next digit of the sequence
2*3= 6(next digit)
.....keep on multiplying lyk dat
lastly 720*7=5040

the correct option is 7

Like? Yes (1) | No   

JENSI KARUNYA.S   9 years AGO

1*2=2,2*3=6,6*4=24,24*5=120,120*6=720,720*7=5040
so,the correct answer is option 7) 5040

Like? Yes (1) | No   

vimal tiwari   9 years AGO

no. * (it's position + 1 ) = next no.

720 *( 6+1)= 5040

Like? Yes (1) | No   

Nagabhairu Samrajyam   9 years AGO

1*2=2
2*3=6
...
720*7=5040

Like? Yes (1) | No   

rakesh sharma   9 years AGO

1,2,6,24,120,720,......?
1*2=2,
2*3=6,
6*4=24,
24*5=120,
120*6=720,
720*7=5040 answer

Like? Yes (1) | No   

DHAYYALA SREEKANTH REDDY   9 years AGO

1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
720*7=5040

Like? Yes (1) | No   

H. Sreekanth   9 years AGO

1*2=2;
2*3=6;
6*4=24;
24*5=120;
120*6=720;
720*7=5040;

Like? Yes (1) | No   

Arpit Sohgaura   9 years AGO

Simply..sequenced used *1
*2
*3
*4
*5
*6
*7

Like? Yes (1) | No   

Arvind kumar   9 years AGO

series of factorial
so next sequence will be factorial of seven
i.e. 5040

Like? Yes (1) | No   

Devake Rukmaji Annarao   9 years AGO

each time increase multiplication no such as 1*2=2,2*3=6,
so 720*7=5040

Like? Yes (1) | No   

Arifa   9 years AGO

1,2,6,24,120,720
1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
next term will be 720*7=5040
ans option 7

Like? Yes (1) | No   

Ankur kumar   9 years AGO

sum of two cosecutive no is mul by a no. n sum of next 2 numbers is multiplied by next number

Like? Yes (1) | No   

vamsi krishna   9 years AGO

1x2=2
2x3=6
6x4=24
24x5=120
120x6=720
720x7=5040

Like? Yes (1) | No   

anju sukumaran   9 years AGO

1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
so the answer is 720*7=5040
ans.5040

Like? Yes (1) | No   

Sushant Kumar   9 years AGO

1×1=1
2×3=6
6×4=24
24×5=120
120×6=720
720×7=5040

Like? Yes (1) | No   

veeraram   9 years AGO

1+0=1
1x1+1=2
2x2+2=6
6x3+6=24
24x4+24=120 and so
720X6+720=5040

Like? Yes (1) | No   

naveen   9 years AGO

1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
720*7=5040

Like? Yes (1) | No   

Lalit Meena   9 years AGO

1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
720*7=5040
so option 7 is correct

Like? Yes (1) | No   

RAHUL KUMAR   9 years AGO

1*2=2
2*3=6
......
......
......
720*6=5040
so option (7) is right.

Like? Yes (1) | No   

Shubham Raj   9 years AGO

1*2=2
2*3=6
6*4=24
24*5=12
120*6=720
720*7=5040

Like? Yes (1) | No   

sumit kumar   9 years AGO

1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
720*7=5040

Like? Yes (1) | No (1)  

Binay kumar   9 years AGO

1*2=2
2*3=6
6*4=24
24*5=120
120*6=720
720*7=5040

Like? Yes (1) | No (1)  

23 Oct 2015 Visible Area

A cone, placed on a table, is cut from the middle by a horizontal plane. The lower portion is placed in inverted position & upper portion is placed symmetrically on it. Calculate the total visible area (Take R = 14 cm, Pi = 22/7 and h = 48cm)

OPtion

1) 2472 cm^2
2) 2664 cm^2
3) 2642 cm^2
4) 2564 cm^2
5) 2482 cm^2
6) 2364 cm^2
7) 2662 cm^2
8) 2766 cm^2
9) 2854 cm^2
10)None of these

Solution

Total visible are = surface are of cone + surface are of frustum + area of the ring

Using figure and solve it
Area = 2662 cm^2

Correct Option: 7 Best Solution (4)

anushka bansal   9 years AGO

total surface area of cone + (area of base of the original cone - area of base of the smaller cone)
slant height s = sqrt(48^2+14^2)
= 50
total surface area = pi*r*s = 22/7*14*50 = 2200
visible area = 2200 + (pi*14*14 - pi*7*7)
2662cm^2

Like? Yes (9) | No   

ABHISHEK GAURAV   9 years AGO

As it is clearly mentioned in the question is that the cone is cut horizontally in the middle such that its height gets halved.
Area of the upper most cone is = pi*r(r+sqrt(h^2+r^2))
(as the lower portion of the cone is not visible, so we will not take the value of r in the formula)
= 22/7*7( sqrt(24^2+7^2)
=550cm^2
area of concentric circle around the cone=pi(14^2-7^2)
= 462cm^2
area of lower part of the cone=
pi*r(sqrt(14^2+48^2)) - pi* 7 (7^2+24^2)
= 1650cm^2

adding all these areas= 550+462+1650
= 2662 cm^2

Like? Yes (3) | No   

vikash ranjan   9 years AGO

22/7 *14 (48*48 +14*14)^1/2 + 22/7 (14*14 - 7*7 )= 2662

Like? Yes (1) | No   

RAKESH   9 years AGO

R=14, r=7, L=l=25

pi(R+r)L + pi*rl + pi(R^2-r^2) ===== 2662 cm^2

Like? Yes (1) | No   

22 Oct 2015 Four digit number

A four digit positive number having all non-zero distinct digits is such that the product of all the digits is least. If the difference of hundreds digit and tens digit is 1, then total number of possibilities for that number are:

OPtion

1) 2
2) 3
3) 4
4) 6
5) 8
6) 9
7) 12
8) 16
9) 18
10)24

Solution

Since product is least so number will have digits 1, 2, 3, and 4
Difference is one so possibilities for hundreds and tens digit are 2,1 and 3,2 and 4,3
So possible number are 6
4 2 1 3
3 2 1 4
1 3 2 4
4 3 2 1
1 4 3 2
2 4 3 1

Correct Option: 4 Best Solution (11)

kriti kankariya   9 years AGO

the no.s will be 1,2,3,4
so taking 2 no's in 10's and 100's place -- 12,21,23,32,34,43
i.e. 6 possiblities

Like? Yes (2) | No   

mohan ranga rao   9 years AGO

1324
4321
3214
4213
2431
1432
so total 6 possibilities
option 4

Like? Yes (2) | No   

dee hack kr   9 years AGO

4321,3421
1432,4132
2143,1243

Like? Yes (1) | No   

Robert Yogenson   9 years AGO

we require least product so .
minimum combination number is 1,2,3,4
then there are 6 possibilities comes out .

Like? Yes (1) | No   

rakesh sharma   9 years AGO

1324
1432
2431
3214
4213
4321
total 6 number is possible

Like? Yes (1) | No   

RANJAN FADIA   9 years AGO

possible no are with least product :
4213
3214

4321
1324

1432
2431

total =6

Like? Yes (1) | No   

Deepak kumar singh   9 years AGO

lest product=1*2*3*4=24
product of 100 place and 10 place should be 1= 21,32,43
no= 3214,4213,4321,1324,1432,2431

Like? Yes (1) | No   

PRABAKARAN SAMINATHAN   9 years AGO

If the product should be least then the each number must be as small as possible. The four digit number with all distinct and least product is 1234.
According to the condition that hundreds digit and tens digit difference is 1. We can arrange this in 6 ways so that the difference will be one.
Therefore the answer is 6.

Like? Yes (1) | No   

RAHUL KUMAR   9 years AGO

The four digits numbers are 1324,1432, 2431, 4321, 3214, 4213
so the option (4) is correct.

Like? Yes (1) | No   

JENSI KARUNYA.S   9 years AGO

the product of all digits should be least.so 4 digits are 1,2,3,4.
thus , the possibilities are 4321,1324,2431,1432,4213,3214.
In all these numbers, the difference of hundreds and tens digit is 1.therefore,the no. of possibilities are 6.
option : 4) is correct

Like? Yes (1) | No   

MRITUNJAY   9 years AGO

number is 1 2 3 4

1324
1432
4321
2431
3214
4213

Like? Yes (1) | No