M4maths Previous Puzzles

09 Sep 2015 Mixture

Kantilal mixes 80 kg of sugar worth of Rs. 6.75 per kg with 120 kg worth of Rs. 8 per kg. At what rate shall he sell the mixture to gain 20%.

OPtion

1) Rs. 7.50
2) Rs. 7.75
3) Rs. 7
4) Rs. 6.50
5) Rs. 8.50
6) Rs. 9.50
7) Rs. 9
8) Rs. 8.20
9) Rs. 8.85
10)None of these

Solution

Total C.P. of Rs. 200 kg of mixture
= Rs. (80*6.75 + 120*8) = Rs. 1500
Average rate = 120% of Rs. 7.50 = Rs. 9 per kg

Option 7)

Correct Option: 7 Best Solution (115)

Ajeet Kumar   9 years AGO

Total CP= (80*6.75)+(120*8) =1500
Gain = 20%
So, SP= 1500 +300 =1800
SP/Kg= 1800/(120+80) = 9

Like? Yes (21) | No (6)  

kriti kankariya   9 years AGO

total amt paid by him for 200kg(80+120)=80*6.75 + 120*8
=1500rs
so amt for 1 kg mix= 1500/200 = 7.5rs
to gain 20%
(20/100)*7.5 = 1.5
amt per kg should be = 7.5 + 1.5
= 9rs

Like? Yes (5) | No (1)  

Arvind kumar   9 years AGO

let avg price=x
(8-x)/(x-6.75)=80/120
i.e. x=7.5
for gain of 20%
selling price of mixture=7.5+7.5*20/100
i.e. rs. 9

Like? Yes (5) | No (1)  

Sukanya   9 years AGO

80 kg for 6.75/kg=540 rs
120 kg for 8/kg=960 rs
totally 1500 for 200 kg
20% profit= 300
1500+300=1800 is his S.P.
1800/200=9 rs /kg

Like? Yes (6) | No (3)  

sudiptaa   9 years AGO

Avg price = 80*6.75+120*8/(80+120)=Rs. 15/2
SP at 20% gain = 120/100*15/2 = Rs 9

Like? Yes (3) | No   

Sandip Shaw   9 years AGO

total mixture=120+80=200
total cost of mixture=6.75*80+120*8=1500
cp per kg of mixture=1500/200=7.5
gain=20% of cp/kg=7.5*20/100=1.5
therefore sp=cp/kg+gain
=7.5+1.5=9

Like? Yes (4) | No (1)  

Satadru Dutta   9 years AGO

total c.p= (80*6.75)+(120*8)=1500
s.p=1500+(1500*20/100)=1800
rate at which he must sell=1800/200=9

Like? Yes (3) | No   

lakshmi priya   9 years AGO

cost prices of 200 kg s 1500, 20 percentage of is 1800 ,1800/200 gives 9

Like? Yes (4) | No (1)  

Shashank Gupta   9 years AGO

x = (80*6.75+120*8)/(80+120)
x=7.5
on this profit of 20% means 7.5*20/100=1.5
so he sell the mixture at 7.5+1.5=9

Like? Yes (4) | No (1)  

Kalpana   9 years AGO

cost price=(80*6.75)+(120*8)=Rs.7.5
gain%=gain/cp*100=20%
gain=Rs.1.5
selling price=gain+cost price=Rs.9

Like? Yes (4) | No (1)  

Aman Gaurav   9 years AGO

total quantity of sugar is 80+120 = 200kg
total cost of sugar is 540+960 = 1500 kg
so to gain profit of 20 % he should earn Rs 1800

hence, at 9 rs/kg he should earn Rs 1800 i.e 20% gain

so Rs. 9 is answer

Like? Yes (3) | No   

Venkatesh Matta   9 years AGO

80:120=2:3 so, 2*6.75+3*8=5*(cost price of kg mix) i.e. c.p of 1kg mix =7.5
so selling price of kg mix =1.2 * 7.5= 9

Like? Yes (4) | No (2)  

Shyamnks    9 years AGO

80Kg * 6.75rs= 540 rs
120kg * 8rs = 960 rs
540+960=1500 * 20% =300
1500+300=1800
To get 1800 rs. We have 200Kg so we have to sell it at Rs.9

Like? Yes (3) | No (1)  

Joy cindrella   9 years AGO

cost price of 80 kg= 80*6.75 => 540 and cost price of 120 kg = 120*8=>960 so totally (120+80=200 kg's) cost price is 540+960=1500. To find selling price , use the formula, SP= (100+20)/100 *1500 =>1800 i.e., cost price of 200 kg of rice = 1800. For per kg, divide 1800/200 which gives you 9 per kg.

Like? Yes (3) | No (1)  

Sandeep Kumar   9 years AGO

80*6.75= 540
120*8= 960

total weight = 120+80=200
total amount= 540+960 = 1500

20% profit on total amount = 300
now amount = 1500+300= 1800
now, mixture rate per kg = 1800/200 = Rs. 9

Like? Yes (2) | No (1)  

vaibhavi lodhiya   9 years AGO

total=200kg,
sp=((100+20)/100)*cp,
cp=540+960=1500 Rs.
therefore :sp=9 Rs/kg

Like? Yes (2) | No (1)  

adarsh   9 years AGO

because we want to get profit of 300 so we have to earn total of 1800

Like? Yes (1) | No   

Shalu   9 years AGO

total c.p of mixture is 80*6.75+120*8=1500 & gain=20%.
s.p=(1500*120)/100=1800
thus s.p of mix. per kg= 1800/200=rs.9

Like? Yes (1) | No   

Pranjali Wankhede   9 years AGO

80 kg- 6.75*80= 540
120 kg- 8*120= 1500
540+960=1500=Cost Price

Profit %=20%
Profit%= (c.p-s.p)/cp
sp= 1800
1800/(120+80)kg= 1800/200= Rs. 9

Like? Yes (2) | No (1)  

ajay kulkarni   9 years AGO

80 Kg Sugar= Rs. 540 and 120 Kg Sugar= Rs. 960
Hence 200 Kg Sugar = Rs. 1500
20% profit on 1500= 300
Hence 200 Kg Sugar = Rs. 1800
Therefore 1 kg worth 9 Rs per kg.

Like? Yes (1) | No   

ritu yadav   9 years AGO

Cost of 80 kg sugar will be =80*6.75=Rs 540
Total cost of 120 kg sugar will be= 120*8= Rs,960
Now total C.P.= 540+960=1500
Total S.P to get 20% profit will be= 1500*120100= Rs 1800
Rate per kg of mixture of sugar will be = 1800200= Rs 9 per kg

Like? Yes (2) | No (1)  

chaitali chanda   9 years AGO

total cost price of 200 kg of mixture = ?(80*6.75+120*8)= 1500
so, cp of 1 kg of mixture= 1500/200=7.5
Rate for 20% profit = 7.5*120/100= ? 9.

Like? Yes (1) | No   

Aman   9 years AGO

total quantity of sugar is 80+120 = 200kg
total cost of sugar is 540+960 = 1500 kg
so to gain profit of 20 % he should earn Rs 1800

hence, at 9 rs/kg he should earn Rs 1800 i.e 20% gain

so Rs. 9 is answer

Like? Yes (1) | No   

Subhasri Pal   9 years AGO

total cp= 6.75*80+120*8=540+960=1500
gain=20%
therefore, sp=1800
now, 1800 for 200 kgs
so, rate of 1 kg=1800/200=9 rs/kg.

Like? Yes (3) | No (2)  

AARTI OJHA   9 years AGO

total CP= Rs 1500
20% profit on CP will result in a SP of Rs 1800
Thus, cost of each kg of sugar is 1800/200= 9

Like? Yes (2) | No (1)  

TAUSEEF AMEEN   9 years AGO

1.20*cp...
now cp=80*6.75+120*8=1500
sp=1.20*1500=1800
rs 1800 is for 200 kg..
hence for 1 kg it is 9 rs

Like? Yes (2) | No (2)  

RagunathKC   9 years AGO

(80 kg*6.75) +(120 kg *8 )=1500 rs 200 kg..

20 % profit 300rs (1500 *.2)
1800 rs 200 kg..1kg 9rs

Like? Yes (1) | No (1)  

poojasaisri   9 years AGO

cp=(80*6.75)+(12*8)=1500
sp=(120/100)*1500=1800
sp per kg=1800/200=9

Like? Yes (1) | No (1)  

Homenath   9 years AGO

80kg=540
120kg=960
total=1500
20%=30
gain with total=1800
so to make ...... sell in rupees 9 per kg... we get for 200kg=1800

Like? Yes (1) | No (1)  

Rahul kumar   9 years AGO

total cp=80*6.75+120*8=1500
gain%=20=(gain/cp)*100
gain=300
sp=1500+300=1800
sp for 1 kg=1800/200=Rs9

Like? Yes (1) | No (1)  

shashank   9 years AGO

total weight = 200
total price = 1500
20%of 1500 = 300
so he had to sell it at 1800 to gain a profit of 20%
so 1800/200 kg = Rs 9 per kg

Like? Yes (1) | No (1)  

Ankit   9 years AGO

6.75*80=540, 8*120=960, on adding both 1500, i.e . CP=1500, Profit%=20% therefore SP=1800 for 200 kg so for 1kg it is 9RS

Like? Yes (1) | No (1)  

MRITUNJAY   9 years AGO

total cp of mixture=80*6.75+120*8=1500
1500/100*120=1800
price of mixture=1800/200=9
option 7

Like? Yes (1) | No (1)  

Dorfy Rao   9 years AGO

CP= (80*6.75 ) + (120*8) = 1500
SP = 120*1500/100 = 1800
RATE PER KG= 1800/200=9

Like? Yes (1) | No (1)  

PIYUSH AGRAWAL   9 years AGO

HERE
80*6.75=540
120*8=960
540+960=1500
20%Of 1500=300
1500+300=1800
1800/(120+80)=9

Like? Yes (1) | No (1)  

Shubham Raj   9 years AGO

cp=1500 rs
sp= ?
gain=20%
sp=(120/100) *1500
=1800
rate=1800/200
=9

Like? Yes (1) | No (1)  

Lakhi kant Roy   9 years AGO

Total C.P=80*6.75+120*8=1500
%g=20,
so,S.P=[(100+%g)/100]*C.P
=[(100+20)/100]*1500
=1800
so,Required Rate=1800/200
=9.

Like? Yes (1) | No (1)  

Vishal Kumar   9 years AGO

80kg at the prize of 6.75/kg rate that will come 540 rupess
And 120 kg at the prize of 8/kg that will come 960 rupess total invwstment on cost prize of 200 kg then he wants to gain 20% profit on 1500 investment on 200 kg that the selling price of 200 kg is 1800 on 20% profit
So that 1800/200=9/kg

Like? Yes (1) | No (1)  

Deepak Kumar   9 years AGO

CP of 200kg = 80*6.75+120*8= 1500
CP per kg = 7.5
SP @20%gain= 7.5*1.2= 9

Like? Yes (1) | No (1)  

Akshay Agarwal   9 years AGO

total sugar=200kg
total sugar purchase=(80x6.75)+(120x8)=1500
thn he sell mix and gain 20%=1500x20%=300 profit
thn he earn the total amount =1500+300=1800
find th rate of per kg = 1800/200=9 per kg

Like? Yes (1) | No (1)  

Keshav Kishlay   9 years AGO

80kg at the rate of Rs.6.75 so total=Rs.540
and 120kg at the rate of Rs.8 so total=Rs.960
so total cost of the total sugar = Rs.1500 for 200kg
so rate of 1kg sugar = Rs.7.5
so now for 20% gain the rate will be Rs.9

Like? Yes (1) | No (1)  

praveendas   9 years AGO

total amount spend for both varieties is1500.
in order to gain 20 percent .we should get 1800 for total.
cost per kg is 1800/200=9

Like? Yes (1) | No (1)  

Dinesh Kumar   9 years AGO

n1+n2 corresponds to A2-A1
so, 2+3 corresponds to 1.25
i.e 5 corresponds to 1.25

n2=(A2-A1)*n2/(n1+n2)
n2=0.75
Aw-A1=0.75
Aw=0.75+6.75
=7.50/kg

20 % is..
i.e 9/kg

Like? Yes (1) | No (1)  

AAKASH MANIYA   9 years AGO

Average cost price after mixing will be 7.5 Rs/- and after adding 20% ((7.5*0.2)=1.5)Profit it will be 9 Rs/-.

Like? Yes (1) | No (1)  

J E Tejeswar Gowd   9 years AGO

Average weighted method=(120×8+80×6.75)÷(120+80)
=7.5
But he must get the profit of 20% so, 20% of 7.5 is 1.5
Total price that he need to sell for profit of 20% is 9

Like? Yes (1) | No (1)  

Sonu kumar   9 years AGO

cost of type 1 sugar = 80*6.75=540
cost of type 2 sugar=120*8=960
total 200 k.g sugar cost is 1500.
now 20% gain on total amount(1500)=1500+1500*(20/100)=>1800.

now 1k.g rate =1800/200=9.

kantilal want to gain 20% then he has to sell sugar Rs. 9 per k.g.

Like? Yes (1) | No (1)  

Rituparna Chakraborty   9 years AGO

total price of 80 kg of sugar=80*6.75=540,and total price of 120 sugar=120*8=960
total price of 200 kg sugar is 1500 Rs.
to get a profit of 20 all over he have to shell it 120/100*1500=1800 Rs.
so sugar per kg =1800/200=9

Like? Yes (1) | No (1)  

gaurav singh   9 years AGO

80*6.75=540
120*8=960
total=1500
profit=1500*20/100=300
selling price of (80+120)kg=1800
selling price per kg =1800/200=rs 9

Like? Yes (1) | No (1)  

Devendra Marghade   9 years AGO

Cost price=80*6.75 + 120*8=1500
Price at 20% gain=1500*(120/100)=1800
So per Kg. rate he must sell=1800/(80+120)=9 Rs.
Option 7)

Like? Yes (1) | No (1)  

Rameez Raja   9 years AGO

total cost price is 1500..to earn 20% profit he should sell at 1800..total quantity of mix sugar is 200 kg..therefore selling price = 1800/200=9

Like? Yes (1) | No (1)  

puja kumari   9 years AGO

total amout=200 and total price 1500.for 1 kg price is=7.5
to gain 20% profit price will be 9

Like? Yes (1) | No (1)  

RAKESH ARYA   9 years AGO

Rs 9

Like? Yes (1) | No (1)  

Kethineni Vinodh   9 years AGO

Aw=7
20%Aw+Aw=9

Like? Yes (1) | No (1)  

Rahul Khatavkar   9 years AGO

6.75*80+8*120=1500
20*1500/100 =300+1500=1800 1800/200=9

Like? Yes (1) | No (1)  

Rakshith Bellare   9 years AGO

total cost price of the mixture : (80 * 6.75 ) + (120 * 8)
therefore total cost price = 1500

to earn 20% profit the mixture must be sold at 1500+150+150 = 1800

therefore the rate at which the mixture must be sold to earn a profit of 20% is 1800/(80+120) = 9

Like? Yes (1) | No (1)  

karthigalakshmi   9 years AGO

80kg*6.75=540rs
120kg*8=960rs
so cost prize=540+960=1500
we know that ((S.P-C.P)/C.P)*100=GAIN
THEREFORE ((S.P-1500)/1500)*100=20(GIVEN gain=20%)
we get s.p=1800
total KG of sugar is 200kgs
so 1800/200=9
so ans is RS.9

Like? Yes (1) | No (1)  

CHANDAN KUMAR   9 years AGO

(80×6.75 ) + (120×8) = 1500

mixture cost = Rs 1500

20 percent of cost of mixture =300

total cost of mixture at 20 percent gain = Rs 1800

mixture 1=80 kg
mixture 2 =120 kg

total weight of mixture = 200

200×9 = 1800

if he sell the mixture at Rs 9 per kg
then only he will gain
20 percent.

so, the right answer must be Rs.9

Like? Yes (1) | No (1)  

prabhu   9 years AGO

80kg-->6.75 therefore total amount=80*6.75=540.
120kg-->8 therefore total amount=120*8=960.

total kg=200kg total amount= 1500. 1500*(20/100)=300

if he want to sell 20% gain he have to sell the total 200kg to 1800rs., therefore 200*9=1800.

ans=9

Like? Yes (1) | No (1)  

Indranil Bhattacharya   9 years AGO

( 120*8 + 80*6.5 )/( 120 + 80 ) = 7.5

Now 7.5's 120% = 9.

Like? Yes (1) | No (1)  

rajkumar   9 years AGO

because the total cost price is 6.75*80 + 120*8=1500
so inorder to get 20% profit the selling price should be
(20/100)*1500=300(profit 20%)
300+1500=1800
for 1kg 1800/200=rs9

Like? Yes (1) | No (1)  

Dhanraj Wanjare   9 years AGO

80*6.75 = Rs. --> 540;
+ 120*8 = Rs --> 960;
..................................................
200 kg = R ---> 1500;
...................................................

=> 1500*120/100=1800;
=> 1800/200;
==> 9 Rs / Kg;
option 7 satisfied

Like? Yes (1) | No (1)  

Soumya Ghosh   9 years AGO

lets say his CP for mixture be x. now by alligation rule the ratio of mixing is (8-x):(x-6.75) which would be equal to 80:120.equating these two we get x=7.50 at selling price would be at 20%profit meaning 1.2*x=9.00 :)

Like? Yes (1) | No (1)  

Vinay kumar rai   9 years AGO

6.75*80+120*8=1500;
1500/200=7.5
7.5*20%=1.5
7.5+1.5=9

Like? Yes (1) | No (1)  

priyanka burnwal   9 years AGO

weight of 80 kg of sugar is 540
weight of 120 kg of sugar is 960
540+960=1500
cp of 200kg of sugar =1500
putting the formula gain%=((sp-cp)/cp)*100
20=((sp-1500)/1500)*100
sp=1800
sp of 1 kg of sugar =1800/200=9..

Like? Yes (1) | No (1)  

sanchit soni   9 years AGO

80 kg at 6.75=540
120kg at 8 = 960
tptal = 1500 for 200 kg,so 7.5/kg
c.p. = 7.5/kg and gain = 20%
.s.p. = [(100+20)/100]*7.5=9

Like? Yes (1) | No (1)  

neeraj   9 years AGO

7.5/- per kg is mixture cost and 20% of profits makes total cost 9

Like? Yes (1) | No (1)  

Pronab Paul   9 years AGO

80×6.75=540
120×8=960
Cp=1500
Sp=(120×1500)/100=1800
1800/200=Rs.9 per kg

Like? Yes (1) | No (1)  

Ashutosh Kumar Mantoo   9 years AGO

total cost=80*6.75+120*8=540+960=1500
now to gain 20% profit , calculate the selling price that is
1500+1500*20/100=1800
now there is total of 200 kg the calculate the selling price of one Kg=1800/200=9

Like? Yes (1) | No (1)  

suresh sahu   9 years AGO

Total CP= 80 *6.75 + 120*8
= 1500
gain is 20% so
SP will be=1500+300
=1800
and Total quantity of sugar is 200 kg
so rate per kg = 1800/200
Rs 9/Kg
ans is option 7

Like? Yes (1) | No (1)  

DHANALAKSHMI PRAKASAM   9 years AGO

et c1 and c2 be the cost of two types of sugar and q1 & q2 be their quantities.
c1=6.75 , q1=80 ,c2=8 ,q2=120
cost of the mixture=c=(c1q1+c2q2)/q1+q2
c=7.5
to have a gain of 20% the cost of the mixed sugar will become
7.5+1.5=9
therefore kantilal will sell the mixed sugar @ Rs.9/kg to gain 20%.

Like? Yes (1) | No (1)  

Sivaprakash.J   9 years AGO

6.75*80+8*120=1500 per 200 kg
Then the cost price is 7.5 per kg
Gain is 20rs so
20% of 7.5 is 1.5
Selling price equal to 1.5+7.5=9 Rs.

Like? Yes (1) | No (1)  

Sunil Kumar Yadav   9 years AGO

80×6.75+120×8=1500
80+120=200
20% of 1500 is 300
Total = 1800
1800/200= 9 ans

Like? Yes (2) | No (2)  

sivakumar   9 years AGO

80*6.75+120*8=1500
1500*20/100=300
1500+300=1800
1800/200=9

Like? Yes (1) | No (1)  

Subhendu Pradhan   9 years AGO

80*6.75 + 120*8=1500(cp)
sp=1500*120/100=1800
rate=1800/(80+120)=9

Like? Yes (1) | No (1)  

rahul sharma   9 years AGO

because total cost of mixture is 150. if 20% profit than cost will be 180 of mixture than per unit rate 1800/200 =9

Like? Yes (1) | No (1)  

sumitha saseendran   9 years AGO

total cost of sugar1 = 540
totat cost of sugar2 = 960
total cost price = 1500
gain = 1500x20%
=300
so selling price = 1800 for 200kg
1800/total kg = Rs.1800/200kg = Rs. 9

Like? Yes (1) | No (1)  

Vijay   9 years AGO

total price of 80 kg sugar = 80*6.75= 540
total price of 120 kf sugar = 120*6=960
total mixture = 200kg
total price = Rs.1500
price per Kg of mixture = Rs 7.5

to gain 20% he save to sail this at 120% of per Kg price that is = Rs 9

Like? Yes (1) | No (1)  

gourav   9 years AGO

first use alligation to find the avg price when he mixes both by using the equation (8-x)/(x-6.75)=80/120 and x will come out to be 7.5 and 20 percent profit on 7.5 will be 1.5 and selling price 7.5+1.5=9. thus 9 will be selling price

Like? Yes (1) | No (1)  

N.Vennela Rani   9 years AGO

80*6.75=540,
120*8=960,
total putting amount=540+960=1500,
gain 20% means Rs 300,then total become Rs 1800,
total mixture weight=200kg,
1800/200=Rs 9

Like? Yes (1) | No (1)  

PRABIR    9 years AGO

total C.P= 6.75*80+8*120=1500
S.P=1800
SP/kg=1800/200=9

Like? Yes (1) | No (1)  

Rajat   9 years AGO

6.75 * 80 = 540
8*120 =960
540+960=1500
20% of 1500 =300
1500+300=1800
1800/200=9

Like? Yes (1) | No (1)  

jaganathan   9 years AGO

total cost price= 80kg*6.75rs + 120kg*8rs
C.P=1500rs for 200kg
C.P for 1 kg = 1500÷200
=7.5rs
since he has to sell for 20 percentage profit the selling price is
= 7.5+7.5*.2
=9 Rs

Like? Yes (1) | No (1)  

sukriti singh   9 years AGO

total sugar=120+80=200kg
c.p of 200 kg= 80*6.75+120*8=1500.
s.p= (120/100)*1500=1800
sp per kg= 1800/200=9
rs.9/kg

Like? Yes (1) | No (1)  

m.lokeswari   9 years AGO

Total amount=80×67.5+120×8=1500
20% gain=1500×120/100
=1800
Cost/kg=1800/200

Like? Yes (1) | No (1)  

nithin   9 years AGO

cp=80*6.75+120*8
20% profit=1800=sp
for 1 kg =1800/(80+120)

Like? Yes (1) | No (1)  

rahul shaw   9 years AGO

total cost price= 6.75*80+8*120=1500
CP of 1kg= 1500/200= 7.5
gain of 20%=7.5*1.2=9
option 7

Like? Yes (1) | No (1)  

Deepanshu Chaturvedi   9 years AGO

80*6.75 = rs. 540---------cost of 1st type of sugar
120*8 = rs. 960-----------cost of 2nd type of sugar
total cost = 540 +960 = rs. 1500
to make profit of 20 % i.e. selling price = rs. 1800
therefore cost of 1 unit of mixture = rs. 1800 / 200 = rs. 9/kg

Like? Yes (1) | No (1)  

Ashok Raj   9 years AGO

Average price of the product is 7.5 and the selling price must be ₹9

Like? Yes (1) | No (1)  

pavan   9 years AGO

total cost of 200 kg=1500
to have gain of 20%it should be sold st 1800
200 kg=1800
1kg=9 RS

Like? Yes (1) | No (1)  

Amit chaturvedi   9 years AGO

80*6.75+120*8=1500,
i.e total cost of 200 kg sugar is 1500 RS
now, 1500*20/100=300
So he have to sell sugar at 1800 to gain 20% gain .
so 1800/200=9 which should be the rate of per kg sugar.

Like? Yes (1) | No (1)  

shailendra   9 years AGO

total sugar=80+120=200kg
rs for 200kg = (80*6.75)+(120*8)= 1500
20% of 1500 = (1500*20)/100 = 300
the selling price of mixtur = 1500+300 =1800
to gain Rs = 1800/200 = 9 Rs/kg

Like? Yes (1) | No (1)  

Nick Jain   9 years AGO

80*6.75=540
120*8=960
total 200kg =1500 rs
for 20% profit 300 i.e. 1800
so 1800/200=9rs/kg

Like? Yes (1) | No (1)  

Abhishek singh   9 years AGO

As 80*6.75=540
and 120*8=960
total cost=1500
so she have to sold it at 1800 to get 20% gain
i.e Rs 9

Like? Yes (1) | No (1)  

vishal varma   9 years AGO

for 80 kg it costs 6.75*80=540
for next 120 kg cost is =120*8=960
total cost uis equal to 540+960=1500
now v have given gain % i.e., 20%
20=(g*100)/7.5
from this g=1.5
gain= s.p-c.p
1.5=s.p-7.5
s.p=9

Like? Yes (1) | No (1)  

ADITYA KUMAR   9 years AGO

total price=80*6.75+120*8=1500
price of per kg now=1500/(80+120)=15/2
selling price per kg to get 20% profit=(15/2)(1+20/100)=9

Like? Yes (1) | No (1)  

himanshu jaiswal   9 years AGO

Total weight of sugar -200 kg
Total price of sugar (80*6.75)+(120*8)=1500
20% of 1500=(1500*20)/100=300
Total price after selling sugar=1500+300=1800
So the selling price to get 20% profit=1800/200= 9

Like? Yes (1) | No (1)  

Srikanthreddy    9 years AGO

total cost of sugar:80*6.75+120*8=1500
to gain 20%,the s.p:1500+20%1500=1800
the s.p=1800/200=9/kg

Like? Yes (1) | No (1)  

Deepak Kumar   9 years AGO

total suger=80+120=200.
80 kg suger prize=80*6.75=540.
120kg suger prize=120*8=960
total 200 suger prize=960+540=1500.
20% gain
1500*20/100=300
selling prize of 200 kg suger is 1800
1kg suger prise is 1800/200=9

Like? Yes (1) | No (1)  

saurabh kumar   9 years AGO

price of 80 kg=540
price of 120 kg=960
total c1500
20% gain sp=1800
per kg sp =1800/200=9

Like? Yes (1) | No (1)  

krishna kumar   9 years AGO

gain%={(sp-cp)/cp}x100
here cp= 80kg x rs6.75/kg + 120kg X rs8/kg =rs1500
from the formula given above we get, sp= rs1800 (as gain% = 20%) for 200kg of sugar
hence,selling price is rs9/kg

Like? Yes (1) | No (1)  

Samir Malakar   9 years AGO

Price of 80Kg Suger of Rs. 6.75 per Kg=Rs. 540.00
Price of 120Kg Super of Rs. 8 per Kg= 960.00
Total price of (80+120)Kg= 200Kg Mixed Suger= Rs. 1500.00
20% gain i.e., Selling Price= (1.20*1500.00)= Rs. 1800.00
Cost/Kg of Suger= Rs. 1800.00/200=Rs. 9.00/Kg

Like? Yes (1) | No (1)  

Rupkatha Banerjee   9 years AGO

80*6.75=540
120*8=960
540+960=1500
120+80=200
1500/200=7.5
7.5*120/100=9

Like? Yes (1) | No (1)  

ankit ardeshana   9 years AGO

(6.75*80)+(8*120)=1500
1500/(80+120)=7.5
7.5*120/100=9

Like? Yes (1) | No (1)  

umang agarwal   9 years AGO

total cp=rs(6.75*80+ 8*120)=rs1500.
total weight=(80+120)kg=200kg
s.p=1500+20%0f1500
=1500+300
=rs1800.
s.p per kg=1800/20=rs9/kg ans....

Like? Yes (1) | No (2)  

Venkatesh kadali   9 years AGO

8o kg of sugar worth 6.75 per kg
total=540
120 kg sugar worth 8 per kg
total=960
--->960+540
--->1500
its gain 20%
i.e 1500*20/100
=300
s0 mixture=1500+300=1800

so 1800/(80+120)

= 1800/200

= 9
so answer is 7

Like? Yes (1) | No (2)  

pankaj   9 years AGO

total cost of mixture=Rs7.5
to have gain of 20% he must sell at Rs9

Like? Yes (1) | No (2)  

Rohit Agrawal   9 years AGO

he purchases 200 kgs for rs 1500
thus 1kg for rs 7.5
hance selling at 9 per kg gices him 20% gain

Like? Yes (1) | No (2)  

RAVAL   9 years AGO

total rs. 6.75*80 + 8*120
= 1500
so 20% of 1500 is = 1800rs.
1500/200kg=7.5 kg/rs
according to it 1800/200 = 9 kg/rs

Like? Yes (1) | No (2)  

MATLOOB HUSAIN   9 years AGO

80x6.75=540
120x8=960
total c.p.=1500
1500X20%=300
so s.p.=1800
200 kg=1800
So 1 kg=Rs.9

Like? Yes (1) | No (2)  

pavandeep singh ubbi   9 years AGO

total coat of two type of sugar is 1500
now after 20% it's cost will be 1800 so
1800/200=9 .. I thing it's right

Like? Yes (1) | No (2)  

Sruthi Sreejan   9 years AGO

quantity of cheaper C.P of dearer - mean price
______________________ = _____________________________
quantity of dearer mean price - C.P of dearer

=> 80 8 - mean price
____ = __________________
120 mean price - 6.75

=> mean price = 7.5 = CP of 1kg of mixture
gain%=20
SP of 1kg mixture= [(100 + gain%)/100]* CP
= (120/100)*7.5
= Rs 9.

Like? Yes (1) | No (2)  

payal   9 years AGO

Price of 80 KG Sugar=80*6.75=540rs
Price of 120 KG Sugar=120*8=960rs
total sugar after mixing=200kg
(after mixing sugar we cannot take it as mixture of 2 unidentical things because it is sugar only)
total cost=1500 rs
20% of 1500=300
selling price of 200kg sugar=1500+300=1800rs
cost of 1 kg sugar=1800/200=9rs

Like? Yes (1) | No (2)  

anita kumari   9 years AGO

because the price of 80 kg sugar is 6.75 per kg. So the total amount for 80 kg sugar of 6.75 rs is 540.
Similarly 120 kg sugar of 8 rs per kg is mixed and amount id 960.
so total amount is => 540+960=1500
20% of the amount is =(1500*20)/100=300
overall amount will be=1500+300=1800 rs
the 200 kg sugar's price is=1800/200=9.so 9 is the answer

Like? Yes (1) | No (2)  

Inderjeet Singh   9 years AGO

6.75*80=540 and 120*8=960 so total comes to be 1500 i.e c.p is 1500.
to gain 20% profit =20*1500/100=300 .so S.P must be 1800.
total sugar is 200kg .Therefore 1800/200=9

Like? Yes (1) | No (2)  

sai siddardha   9 years AGO

we have 80kgs of sugar worth 6.75 rps so 6.75*80=540
we have 120 kgs ofsugar worth 8rps so 8*120=960
total we have sugar worth 1500 rps.
we require 20 percentage of profit .
x/1500*100=20.
therefore x=300.
so we need a profit of 300 rps.
we have total of 200 kgs of sugar.
from the options 200*9=1800.
we had the sugar worth 1500 rps and we are selling at 1800rps .
1800-1500=300.
therefore we need to sell sugar at a price of 9 per kg to get 20% profit.

Like? Yes (1) | No (3)  

08 Sep 2015 Probability

Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn bears a number which is a multiple of 3.

OPtion

1) 3/20
2) 3/10
3) 2/5
4) 1/2
5) 1/3
6) 2/3
7) 3/5
8) 1/10
9) 3/4
10)None of these

Solution

S = {1,2,3,....20) and E = {3,6,9,12,15,18)
P(E) = n(E) / n(S)
6/20 = 3/10

Option 2)

Correct Option: 2 Best Solution (64)

Venkatesh kadali   9 years AGO

multiples of 3 are upto 20 are :3
6
9
12
15
18
total number of favoirable choices are :6
total number of choices are: 20
so probability is=6/20
=3/10
so answer is 2

Like? Yes (7) | No (1)  

sudesna mukherjee   9 years AGO

multiple of =3,6,9,12,15,18.
so 6/20
=3/10

Like? Yes (4) | No (1)  

MRITUNJAY   9 years AGO

n(e)=3 6 9 12 15 18=6
n(s)=20
p=6/20
=3/10

Like? Yes (3) | No (1)  

Ankita Sharma   9 years AGO

Total no. of tickets=20
Tickets having numbers multiple of 3=6
Reqd Probability=6/20=3/10

Like? Yes (2) | No   

Shashank Gupta   9 years AGO

Total=20
Multiple of 3 b/w 1 to 20 = 6 {3,6,9,12,15,18}
probablity=6/20 = 3/10(ans)

Like? Yes (2) | No   

priyanka burnwal   9 years AGO

no. divisible by 3 is 3,6,9,12,15,18=6
probability =6/20=3/10..

Like? Yes (2) | No   

vanitha thummala   9 years AGO

multiples of 3 are 6....
so p=6/20
=3/10

Like? Yes (2) | No   

Shyamnks    9 years AGO

Total number of possible outcomes while rolling a die = 20
possible outcomes are multiples of 3 = 3,6,9,12,15,18=6
So the probability of getting a multiple of 3
= No. of desirable outcomes (multiple of 3)/No of possible outcomes
= 6/20
=3/10

Like? Yes (2) | No   

sanchit soni   9 years AGO

multiple of 3 = 3 6 9 12 15 18 = 6 = fav. outcomes
total poss. outcomes = 20
prob. = 6/20 = 3/10 ans.

Like? Yes (2) | No   

SAGNIK DATTA   9 years AGO

there are 6 multiples of 3 less than 20
so 6/20=3/10

Like? Yes (1) | No   

suresh sahu   9 years AGO

total possible no-3,6,9,12,15,18
and total out come 20
so p=6/20=3/10

Like? Yes (2) | No (1)  

PRAGATHI G   9 years AGO

multiples of 3 are 3,6,9,12,15,18.. so out of 20 tickets. . any of des 6 may come. hence prob is 6/20. which is 3/10

Like? Yes (1) | No   

vikas kulshrestha   9 years AGO

p(E)=6
P(S)=20
P=P(E)/P(S)
=6/20
3/10

Like? Yes (2) | No (1)  

sudhir kumar maurya   9 years AGO

multiples of 3 =(3,6,9,12,15,18) = 6
total sample space=20
p=6/20=3/10

Like? Yes (1) | No   

Sonu kumar   9 years AGO

total case=20
no.of events=3,6,9,12,15,18=6

probability= 6/20=3/10.

Like? Yes (1) | No   

Akash Kumar   9 years AGO

total numbers=20
and favourable numbers are 3,6,9,12,15,18
so favourable case=6
therefore probability is=6/20=3/10.

Like? Yes (1) | No   

Lakhi kant Roy   9 years AGO

from 1 to 20 there are 6 multiples of 3 i.e is--3,6,9,12,15,18,
and sample space=20
so,Required Probability=6/20
=3/10

Like? Yes (1) | No   

Shubham Raj   9 years AGO

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18 }.
n(E) = 6
n(S) 20
P(E) =6/20
=3/10

Like? Yes (1) | No   

sudiptaa   9 years AGO

multiples of 3= 3,6,9,12,15,18
n=6
p= 6/20 = 3/10

Like? Yes (1) | No   

Testing Account   9 years AGO

number which is multiple of 3 are.....3,6,9,12,15,18
total number which is multiple of 3 is 6
so probability of getting multiple of 3 is......3/10

Like? Yes (1) | No   

ramya   9 years AGO

Here, S = { 1,2,....20}.

Let E = event of getting a multiple of 3 = {3, 6 , 9, 12, 15, 18,}.
P(E)=n(E)/n(S)=6/20
=3/10

Like? Yes (1) | No   

Appasaheb Sole   9 years AGO

possibilites:-3,6,9,12,15,18
total fav cases=6
prob:-fav.cases/total cases
p=6/20=3/10

Like? Yes (1) | No   

sravani   9 years AGO

there are 6 multiples of 3 in 1 to 20...so
6/20 is the probability.=3/10...

Like? Yes (1) | No   

Neelaksh Mishra   9 years AGO

multiples of 3 are 3,6,9,12,15,18 therefore number of multipls 6
then total outcomes are 20
therefore 6/20=3/10

Like? Yes (1) | No   

Kunal nemu   9 years AGO

Here S ={1,2,3,...........,19,20}
Let E = event of getting a multiple of 3 ={3,6,9,12,15,18}
So P(E) = n(E) / n(S) = 6 / 20 = 3 / 10

Like? Yes (1) | No   

NAIKWADE SURAJ LAXMAN   9 years AGO

among 1 to 20 numbers , 6 numbers are multiples of 3, 6/20=3/10

Like? Yes (1) | No   

RAVAL   9 years AGO

multiple of 3 in 1 to 20 are 3,6,9,12,15,18
so, total no is 6 out of 20
ans.=6/20 = 3/10

Like? Yes (1) | No   

Indranil Bhattacharya   9 years AGO

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18}.

P(E) = n(E) = 6 .
n(S) = 20

Answer: 3/10

Like? Yes (1) | No   

adi   9 years AGO

Total possible outcomes=6
Total outcomes=20
Probabilities=6/20=3/10

Like? Yes (1) | No   

ABHIJIT GURUDATTA PATIL   9 years AGO

no.s wich are multiple of 3=3,6,9,12,15,18
total multiples no.s=6
total no.s=20
prob.=6/20=3/10

Like? Yes (1) | No   

Deepanshu Chaturvedi   9 years AGO

3,6,9,12,15,18----------------6 outtcomes
20--------------------------------total otcomes
probability = 6/20 = 3/10

Like? Yes (1) | No   

Praveenkumar J   9 years AGO

3,6,9,12,15,18...multiples of 3=6
Total numbers=20
Probability=6/20=3/10

Like? Yes (1) | No   

harman kaur   9 years AGO

because number of multiples of 3 are 6 and probability=6/20=3/10

Like? Yes (1) | No   

ayushi   9 years AGO

multiples of 3 are : 3,6,9,12,15,18
hence probability=6/20=3/10

Like? Yes (1) | No   

pranay kumar   9 years AGO

its answer is 3/10 because there are 6 numbers which are multiple of 3 between the numbers from 1 to 20. multiples are 3,6,9,12,15 and 18 .so total 6 of them..so,

probability = possible outcome / total given outcome
= 6/20 = 3/ 10 (answer )..so option 2 is correct..

Like? Yes (1) | No   

lakshmi priya   9 years AGO

6 numbers which r multiples of 3 so 6/20

Like? Yes (1) | No   

praveen   9 years AGO

There are 20 papers.....multiples of 3 upto 20 are 3,6,9,12,15,18..
Therefoe probability is 6/20 i.e, 3/10

Like? Yes (1) | No   

pratibha   9 years AGO

3,6,9,12,15,18 are the multiple of 3
so, total no. of digits is 20
6/20=3/10

Like? Yes (1) | No   

mounika   9 years AGO

probability of an event=probability of occuring/total number of events

Like? Yes (1) | No   

Moumita Choudhury   9 years AGO

Total numbers multiple of 3 = 6
Total numbers 20
Probability = 6/20 = 3/10

Like? Yes (1) | No   

asim   9 years AGO

between 1 to 20 there is 6 numbers which is multiple of 3 so probable outcome by total outcome gives 3/10.

Like? Yes (1) | No   

lavanya lahari   9 years AGO

multiples of 3 between 1 and 20 are 3,6,9,12,15,18....so probablity=6/20=3/10

Like? Yes (1) | No   

Arvind kumar   9 years AGO

nos. divisible by 3 between 1 to 20 are 3,6,9,12,15 and 18 i.e. there are six nos.
so,probability of taking a ticket is 6c1/20c1
i.e. 6/20 i.e 3/10

Like? Yes (1) | No   

Mahalakshmi   9 years AGO

possible ways to get multiples of 3 = 6 (3,6,9,12,15 and 18)
Total possibility =20
So 6/20 = 3/10

Like? Yes (1) | No   

Surya.v   9 years AGO

multiples of 3 from 1 to 20: 3,6,9,12,15,18.
n(a) = 6
n(s) = 20
p(a) = n(a)/n(s)
= 6/20
= 3/10.

Like? Yes (1) | No   

gvsmaneesha   9 years AGO

no.ways to select a ticket from 20 is 20 ways and there are 6 cards..(3,6,9,12,15,18) multiple of 3.. so 6/20 is the answer on simpilfying it we get.. 3/5

Like? Yes (1) | No   

sukriti singh   9 years AGO

chances of getting multiple of 3 is 3,6,9,12,15,18
nd total cards are. 20 so,
6/20=3/10

Like? Yes (1) | No   

Sandeep Kumar   9 years AGO

No of probability which is multiple of 3 = 6
No of total number = 20

P(n) = 6/20 = 3/10

Like? Yes (1) | No   

adarsh   9 years AGO

6 tickets are the multiple of 3 probability =6/20=3/10

Like? Yes (1) | No   

Sasidhar   9 years AGO

There are 6 multiples of 3 from 1-20
And can be selected in 6 ways
The total no of selections is 20
ie n(p)=n(e)/n(s)
=6/20
=3/10

Like? Yes (1) | No   

riya srivastava   9 years AGO

no. of outcomes =6
total no. of outcomes=20
probability=6/20=3/10

Like? Yes (1) | No   

J E Tejeswar Gowd   9 years AGO

multiples of 3 with in first 20 natural numbers is 6 i.e.,(3,6,9,12,15,18)
prob=6/20
=3/10

Like? Yes (1) | No   

Deepak kumar singh   9 years AGO

only 6 no's 3,6,9,12,15,18 can be taken from the given series.
so the prob will be 6/20=3/10

Like? Yes (1) | No   

nithin gb   9 years AGO

multiples of 3=3,6,9,12,15,18=6
20 tickets are their
6/20=3/10

Like? Yes (1) | No   

Ajay Kumar Gupta   9 years AGO

probability of getting multiple of 3 i.e {3,6,9,12,15,18} are=6/20=3/10.

Like? Yes (1) | No   

atul vishwakarma   9 years AGO

becoz no of favourable outcome=6
total no of outcome=20

Like? Yes (1) | No   

saurabh kumar   9 years AGO

there are 6 numbers between 1 and 20 which is multiple of 3.so probability=>6c1/20c1,6/20=3/10.

Like? Yes (1) | No   

Amit chaturvedi   9 years AGO

favourable chance= 3,6,9,12,15,18

6/20=3/10

Like? Yes (1) | No   

SHAHARBAN O   9 years AGO

p(event)=n(event)/n(total)
p(event)=n(number of multiples of 3 less than 20)/20
p(event)=6/20 ie, 3/10

Like? Yes (1) | No   

Akhil   9 years AGO

Because we have 6 possible outcomes nd 20 total no of outcomes so 6/20 =3/10

Like? Yes (1) | No   

suresh   9 years AGO

out 20 cards 6 cards are divisible by 3. So the probability is 6/20 which is 3/10

Like? Yes (1) | No   

pragya khanna   9 years AGO

multiples of 3 b/w 1-20 are 6 3,6,9,12,15,18 hence 6/20 = 3/10

Like? Yes (1) | No   

sunil p rao   9 years AGO

multiples of 3 are 3,6,9,12,15,18. total numbers available are 20. so 6/20 = 3/10.

Like? Yes (1) | No   

akshay   9 years AGO

The multiples of 3 within 20 are 3,6,9,12,15,18. That's a total of 6. The probability is 6/20 which is equal to 3/10.

Like? Yes (1) | No   

07 Sep 2015 Sequence

What is the next number of the following sequence
17, 77, 605, 1331, 5324, 95249, .....

OPtion

1) 1805498
2) 1794678
3) 1146579
4) 1089458
5) 1045896
6) 1056879
7) 1867499
8) 1084589
9) 1048967
10)None of these

Solution

17
17*2 = 34 + 43 = 77
77*2 = 154 + 451 = 605
605*2 = 1210 + 0121 = 1331
1331*2 = 2662 + 2662 = 5324
5324*2 = 10648 + 84601 = 95249
Similarly
95249*2 = 190498 + 894091 = 1084589

Option 8)

Correct Option: 8 Best Solution (8)

RAKESH   9 years AGO

17*2 ------ 34+43 = 77
77*2 ------- 154+451 = 605


95249 *2 -----

Like? Yes (14) | No   

Ajeet Kumar   9 years AGO

77, 605, 1331, 5324, 95249 all are the multiple of 11
and in option only 8 is the multiple of 11

Like? Yes (5) | No (1)  

Shyamnks    9 years AGO

The difference between all the two nos or divisible by 11.

Like? Yes (3) | No   

Indranil Bhattacharya   9 years AGO

17*2 = 34, 34 + 43 = 77
77*2 = 154 154 + 451 = 605
605*2 = 1210 1210 + 0121 = 1331
1331*2 = 2662 2662 + 2662 = 5324
5324*2 = 10648 10648 + 84601 = 95249
95249*2 = 190498 190498 + 894091 = 1084589


Hence the answer is 8) 1084589

Like? Yes (3) | No   

pavandeep singh ubbi   9 years AGO

I have just divided all the... options by 11 and 8one was perfectly divisible by 11

Like? Yes (2) | No   

sudesna mukherjee   9 years AGO

7*11=77
55*11=605
121*11=1331
484*11=5324
8659*11=95249
9859*11=1084589

Like? Yes (1) | No   

Priya   9 years AGO

Except 17, all are completely divisible by 11 in the given series. So the only option that is completely divisible by 11 is 1084589

Like? Yes (2) | No (1)  

adarsh   9 years AGO

all no. except 17 in the sequence is the multiple of 11 so next no. is also multiple of 11

Like? Yes (1) | No   

04 Sep 2015 Probability

A 3 digit number is such that 2 digits of the number are 1 and 2. What is the probability that we would get success in our one trail to guess the number.

OPtion

1) 1/54
2) 1/6
3) 1/9
4) 1/10
5) 1/48
6) 1/50
7) 1/52
8) 1/900
9) 1/450
10)None of these

Solution

Number of method to select 3rd digit = 10
If is 0 then total 3 digit number = 2*2*1 = 4
If it is 1 then total 3 digit number = 3!/2! = 3
Similarly if number is 2
possible number = 3
If selected number is 3 then 3 digit number = 3! = 6
Similar for 4, 5, 6, 7, 8, 9
So total 3 digit number
= 4 + 2*3 + 7*6
= 4+6+42
52
So required probability = 1/52

Correct Option: 7 Best Solution (2)

bhaskar   9 years AGO

12_ ->8
21_ ->8
_12 ->7
_12 ->7
1_2 ->8
2_1 ->8
121
122
211
212
112
221
46+6=52
total 52 possibilities

Like? Yes (21) | No (5)  

amit   9 years AGO

total no. possible without using 0 are 9*3! =48.
3! because arrangements can be possible

in addition to this 4 more no. are possible when we use third no as 0 with having other no. as 1 and 2 respectively

Like? Yes (18) | No (4)  

03 Sep 2015 Ratio and Proportion

If (a+b):(a-b) = 1:5, then (a^2 - b^2):(a^2 + b^2) equals

OPtion

1) 2:3
2) 4:5
3) 3:2
4) 3:5
5) 5:13
6) 11:13
7) 13:5
8) 1:5
9) 4:13
10)None of these

Solution

a+b / a-b = 1/5
a+b+a-b / a+b-a+b = 1+5 / 1-5
a/b = - 3/2

a^2 / b^2 = 9/4
a^2 - b^2 / a^2 + b^2 = 9-4 / 9+4 = 5/13

Correct Option: 5 Best Solution (105)

Anup Sahay   9 years AGO

given a+b/a-b=1/5
so apply componendo and dividendo method here
so (a+b+a-b)/(a+b-a+b)=1+5/1-5
so a/b=6/-4
put a=6 and b=-4 in (a^2-b^2):(a^2+b^2)
which on calculations comes to be 20:52
i.e. option 5) 5:13

Like? Yes (15) | No (3)  

Ajeet Kumar   9 years AGO

let a=3, b=-2
then a^2-b^2/a^2+b^2=5/13

Like? Yes (12) | No (2)  

Sruthi Sreejan   9 years AGO

(a+b):(a-b) = 1:5
=>a/b= -3/2
so
(a^2 - b^2):(a^2 + b^2)
dividing numerator and denomenator with b^2,we get
(a/b)^2 - 1 : (a/b)^2 +1
substituting value for a/b, we get
5/13

Like? Yes (8) | No (2)  

praveendas   9 years AGO

by solving given equations we get a=3,b=-2.
ans is 5:13

Like? Yes (4) | No   

kriti kankariya   9 years AGO

applying componendo dividendo
a/b = -3/2
i.e. a=-3b/2
putting in required eq.
((-3b/2)^2 - b^2 ) / ((-3b/2)^2 + b^2 )
= 5/13

Like? Yes (4) | No   

anvitha   9 years AGO

By Solving two eqns a+b=1 & a-b=5 we get a=3 &b= -2
by substituting in the gvn qtn we get 5:13

Like? Yes (4) | No (1)  

shivam dubey   9 years AGO

A+b = 1
A-b = 5


A = 3
B = -2

So
(9-4)/(9+4)

5/13

Like? Yes (3) | No   

Sivaprakash.J   9 years AGO

a+b:a-b=1:5
a+b/a-b=1/5
From this,
a=-6b/4
So (a^2-b^2):(a^2+b^2)
Can be written as (a^2-b^2)/(a^2+b^2)=((-6b/4)^2-b^2)/((-6b/4)^2+b^2)
=20b^2/52b^2
=5/13
So the answer is 5:13

Like? Yes (3) | No   

meghana   9 years AGO

(a+b):(a-b)=1:5

[1+(b:a)]:[1-(b:a)] =1:5

[1+(b:a)]*5 = [1-(b:a)]

b:a= (-2:3)

(b:a)^2 = 4:9

(a^2-b^2):(a^2+b^2) = [1-(b:a)^2]:[1+(b:a)^2]


= [1-(4:9)]:[1+(4:9)]

= 5:13

Like? Yes (3) | No   

SAGNIK DATTA   9 years AGO

5(a+b)=a-b
a=(6/4)b
now let b=4 so a=6
now solving ans=5:13

Like? Yes (6) | No (4)  

Aniket choudhary   9 years AGO

on solving a=-3/2*b,after that putting the value in original equation we will get the value i.e option 5

Like? Yes (2) | No   

bharath   9 years AGO

a+b=1
a-b=5
then a=3, b=-2
then a^2-b^2:a^2+B^2=5:13

Like? Yes (2) | No   

umang agarwal   9 years AGO

5(a+b)=a-b;
=>a=-3/2*b;
(9/4*b^2-b^2)/(9/4*b^2+b2)=5/13 ans...

Like? Yes (2) | No   

santosh kumar patel   9 years AGO

(a+b):(a-b)=1:5
so a+b/a-b=1/5
after solving, we get
a/b=-3/2
hence a= -3 and b= 2
so solve the next condition i found
5:13

Like? Yes (2) | No   

Chitra.S   9 years AGO

a+b:a-b=1:5
5a+5b=a-b
2a=-3b
a:b=-3:2.
Therefore,a2-b2/a2+b2=5:13

Like? Yes (3) | No (1)  

shameer guptha   9 years AGO

just take a+b=1 and a-b=5
by solving we get a=3,b=-2
so ans is 5:13 by solving

Like? Yes (2) | No   

sireesha.yammanuru   9 years AGO

a/b = (-3)/2
a^2/b^2 = 9/4
by componendo & dividendo it will be 5:13

Like? Yes (2) | No   

shibanti sanyal   9 years AGO

Solving, 5a+5b=a-b.

Therefore, a=(-3/2)b

Putting this value in given ratio, answer obtained is 5:13.

Like? Yes (2) | No   

Koushik Modak   9 years AGO

a:b= -3/2
so a^2/b^2=9/4
then a^2-b^2/a^2-b^2= 5/13

Like? Yes (2) | No   

SUMAN KUMAR   9 years AGO

(a+b)(a+b)/(a-b)(a+b)=1/5
((a^2+b^2)/(a^2-b^2))-+(2ab/(a^2-b^2))=1/5
(a^2-b^2)/(a^2+b^2)=5/13

Like? Yes (2) | No   

Asha Verma   9 years AGO

From given a =-(3/2)b
On putting we get 5/13

Like? Yes (2) | No   

DHAYYALA SREEKANTH REDDY   9 years AGO

5(a+b)=a-b
by solving this we got a=(-6/4)b
substitute this in a^2-b^2/a^2+b^2
then we this ratio as 5:13

Like? Yes (2) | No   

H. Sreekanth   9 years AGO

If we solve we get a=-6b/4;
substitute a in (a^2 - b^2):(a^2 + b^2) we get 5:13

Like? Yes (2) | No   

pavan   9 years AGO

by solving a:b=-3;2 then ((a/b)^2-1):((a/b)^2+1)=9-4:9+4=5;13

Like? Yes (2) | No   

kiran   9 years AGO

a^2-b^2=(a+b)(a-b)
a^2+b^2=(a+b)^2-[(a+b)^2-(a-b)^2]/2
substituting a+b=1 and a-b=5 we get 5:13

Like? Yes (2) | No   

ADUSUMALLI VAMSI KRISHNA   9 years AGO

a+b = 1 and a-b = 5 then a= 3 , b=-2 so a^2-b^2 : a^2+b^2= 5:13

Like? Yes (2) | No   

Anubrindha   9 years AGO

(a^2-b^2)= (a-b)(a+b)
(a^2+b^2)=(a^2+b^2)-2ab

(a-b)(a+b)/((a^2+b^2)-2ab) =(1*5)/(1-2ab)

By solving (a^2+b^2)/(a^2-b^2)=1/5
a/b= (-3/2) Therefore a= -3 and b= 2
5/(1-2ab)= (5/1+12)
5/13 = 5 :13

Like? Yes (2) | No   

REVATHIVENKATESAN   9 years AGO

a+b/a-b=1/5;
so a+b=1 and a-b=5;
(a^2-b^2)/(a^2+b^2)=2*(a^2-b^2)/(a^2+b^2)*2;
=(2*(a+b)*(a-b))/((a+b)^2+(a-b)^2)
=(2*1*5)/(1^2)+5^2
=10/26
=5/13
so answer is 5:13

Like? Yes (2) | No   

kalyan ram   9 years AGO

a^2+b^2=((a+b)^2+(a-b)^2)/2 & a^2-b^2=(a+b)(a-b)
now ((a+b)(a-b))/((a+b)^2+(a-b)^2)/2=2/(1/5)+5=5/13

Like? Yes (2) | No   

shilpa hs   9 years AGO

if we take a=3,b=-2 we will get (a+b):(a-b)=1:5
and (a^2-b^2):(a^2+b^2)=5:13

Like? Yes (2) | No   

VADLA CHANDRA SHEKHAR   9 years AGO

a^2-b^2=(a+b)x(a-b)=1*5=5
(a+b)^2+(a-b)^2=2(a^2+b^2)=26
(a^2+b^2)=13
resultant=5/13

Like? Yes (2) | No   

lavanya   9 years AGO

a^2-b^2=(a+b)*(a-b)
so 5*1=5
a^2+b^2=(a+b)^2-(a-b)^2
so 1^2+5^2=26
then answer is 5:26

Like? Yes (2) | No   

Gunavathy.R   9 years AGO

a^2-b^2=(a+b)(a-b);
a+b=1,a-b =5;
so 1*5=5;

Like? Yes (2) | No   

Danda Sindhura   9 years AGO

Let a+b=1x
a-b=5x
On solving we get a=3x
b=-2x
by substituting these values in a^2-b^2:a^2+b^2 we get 5:13

Like? Yes (2) | No   

vishal varma   9 years AGO

(a+b)/(a-b) =1/5
5a+5b=a-b
2a=-3b
(9/4*b^2-b^2)/(9/4*b^2+b^2) =5:13

Like? Yes (2) | No   

velmala gangadhar   9 years AGO

a^2+b^2=1/2[(a+b)^2+(a-b)^2]
from given equn...(a-b)^2=25(a+b)^2...
5(a+b)^2:1/2[(a+b)^2+(a-b)^2]...
...5:13...

Like? Yes (2) | No   

p.supriya   9 years AGO

by sustituting the value of a =-3/2b
in the equation we get 5:13

Like? Yes (2) | No   

Sowjanya Surisetty   9 years AGO

clearly given that (a+b):(a-b)=1:5
then by cross multiplication& equating we get 2a+3b=0
them b=-2a/3
substitute this in given question
then we get (a^2-(4a^2/9))/(a^2+(4a^2/9))
now we get the answer as 5:13

Like? Yes (2) | No   

MADDALI HEMA NARAYANA   9 years AGO

from the given relation we can get relation between a and b as a=(-3/2)b
just we have to substitute this value in the asked question then we can get 5:13

Like? Yes (2) | No   

Lakhi kant Roy   9 years AGO

(a+b)/(a-b)=1/5, by solving we get,
a=(-3b/2)^2, put this value in (a^2-b^2)/(a^2+b^2),
we get,
{(-3b/2)^2-b^2} / {(-3b/2)^2+b^2},
by solving this we will get, 5/13
so required ratio=5:13

Like? Yes (2) | No   

Ayush Singhal   9 years AGO

(a+b)/(a-b)=1/5
5a+5b=a-b
2a=-3b
a/b=-3/2
(a^2-b^2)/(a^2+b^2)=((a^2/b^2)-1)/((a^2/b^2)+1)
put the value of a/b & then calculate
ans is 5/13

Like? Yes (2) | No   

AARTI OJHA   9 years AGO

a/b=-3/2
thus, a^2/b^2=9/4
further,a^2-b^2/a^2+b^2=5/13

Like? Yes (2) | No   

Sakshi Agarwal   9 years AGO

A+B/A-B=1/5
By components dividendo.
A/b=3/(-2)
A^2 / B^2 =. 9/4
Applying componendo dividendo..
A^2+b^2/ a^2-B^2 = 13/5

Ans. 5/13

Like? Yes (2) | No   

Pallavi Reddy   9 years AGO

formulae for a^2-b^2 is (a+b)(a-b) and the formulae for
a^2+b^2 is (a+b)^2+(a-b)^2/2
we have values for both (a+b) and (a-b)
so we can solve it easily

Like? Yes (2) | No   

pavandeep singh ubbi   9 years AGO

by taking a common in both tha eq.... and finding the value of b/a and putting it on other eq

Like? Yes (2) | No   

AMIT KUMAR   9 years AGO

(a+b) /(a-b) =1/5
So,a/b=-3/2
(a2-b2)/(a2+b2)={(a2/b2)-1}/{(a2/b2)+1}
={(9/4)-1}/{(9/4)+1}
=5/13

Like? Yes (2) | No   

shivom pandey   9 years AGO

get value of (a/b) from equation 1 & then get the a/b =(-3/2) .



put in second equ and get 5/13

Like? Yes (2) | No   

Udita Maitra   9 years AGO

a+b/a-b=1:5
by componendo dividendo,
a/b=-3/2
a^2/b^2=9/4
(a^2-b^2):(a^2+b^2)=5:13

Like? Yes (2) | No   

MATLOOB HUSAIN   9 years AGO

2a=-3b
and then value a put in second expression and get 5:13,

Like? Yes (2) | No   

aman aditya   9 years AGO

a=3
b=-2
so
5:13

Like? Yes (3) | No (2)  

ajay kulkarni   9 years AGO

from 1st equation we get value of a=(-3/2).
put this value in second equation we get
ans=5/13

Like? Yes (1) | No   

sudiptaa   9 years AGO

(a+b)/(a-b)=1/5
a=-3/2b
(a^2 - b^2)/(a^2 + b^2)= 5/13

Like? Yes (1) | No   

Kunal nemu   9 years AGO

Let (a - b)=5k,,and (a + b)=k
So we get a=3k,and b= -2k
ab= -6 k^2
(a^2-b^2)=(a-b)*(a+b) =5k * k =5 k^2
(a^2+b^2)=(a+b)^2 -2*a*b=k^2 - 2*3k* -2k=k^2+12k^2=13k^2
therefore (a^2 - b^2) : (a^2+b^2)=5:13

Like? Yes (1) | No   

Deepak kumar kumawat   9 years AGO

5a-5b=a+b
a/b=3/2
a^2/b^2=9/4
(a^2-b^2)/(a^2+b^2)=5/13
hence option 5

Like? Yes (1) | No   

vikas kulshrestha   9 years AGO

a+b/a-b= 1
by componendo and dividendo method,
a/b=-3/2
a=-3b/2
a^2-b^2/a^2+b^2= 5/13

Like? Yes (1) | No   

Monika Nemiwal   9 years AGO

(a+b):(a-b)=1:5,means
(a+b)=x
(a_b)=5x
on solving, we get :a=3x
b=-2x
thus,(a^2-b^2):(a^2+b^2)=(9-4)x^2:(9+4)x^2
=5:13

Like? Yes (1) | No   

ishan chourishi   9 years AGO

a=3 and b=(-2) is satisfying the first condition.
putting values on right side we get ratios 5:13

Like? Yes (1) | No   

Akash Kumar   9 years AGO

(a+b)/(a-b)=1/5 is given
by Componendo and dividendo rule
{if a/b=c/d then (a+b)/(a-b)=(c+d)/(c-d)}
a/b=-(3/2)
(a^2-b^2)/(a^2+b^2)
=[(a/b)^2-1]/[(a/b)^2+1]
=[(9/4)-1]/[(9/4)+1]
=(5/4)/(13/4)
=5/13 => 5:13
Therefore option 5 is true.

Like? Yes (1) | No   

ramya   9 years AGO

From the given question: we get a=3 and b= -2
So the answer is 5:13 for (a^2-b^2):(a^2+b^2)

Like? Yes (1) | No   

RAVAL   9 years AGO

a+b+a-b : a+b-a+b = 6 : -4
so,
a : b = 3 : -2
a^2+b^2 : a^2-b^2 = (9-4) : (9+4)
= 5 : 13

Like? Yes (1) | No   

Pronab Paul   9 years AGO

a+b/a-b=1/5
a=-3b/2
((-3b/2)^2-b^2)/((-3b/2)^2+b^2)=5b^2/13b^2=5:13

Like? Yes (1) | No   

rashmi r m   9 years AGO

Select a=6,b=-4. So that it satisfy the given equation..
Then appling a and b values to (a^2-b^2):(a^2+b^2)=5÷13

Like? Yes (1) | No   

Shubham Raj   9 years AGO

from question-
(a+b) / (a-b) = 1/5
so, 5a+5b = a-b
=> 4a+6b =0
=> 2a = -3b
=> a = (-3b) / 2
now, (a+b)(a-b) / (a+b)^2 -2ab
=>( ( -3b/2 +b)(-3b/2 -b) ) / (((-3b + b)/2)^2 - 2* -3b/2 *b)
=> (5b^2/4 ) / (13b^2 / 4)
=>5 : 13
therfore
(a^2 - b^2):(a^2 + b^2) equals 5:13

Like? Yes (1) | No   

md shabbir ahmad   9 years AGO

from given cond ,
a+b/a-b=1/5
b(a/b+1)/b(a/b -1)=1/5
then a/b=-3/2
we can write a^2-b^2/a^2+b^2 as
b^2[a^2/b^2-1]/b^2[a^2/b^2+1]
then we can put the value of a/b
then we get
5/13

Like? Yes (1) | No   

vivek   9 years AGO

By solving eq we get a=3 and b=-2,
So , required result is 5:13

Like? Yes (1) | No   

vinod   9 years AGO

a is 3 and b is -2...so a+b is 1 and a-b will be 5


same way square of a is 9 and square of b is 4...substitute in the required and u l get the answer as 9-4:9+4=5:13

Like? Yes (1) | No   

chindam laxman   9 years AGO

(a^2-b^2)/(a^2+b^2)=(a+b)(a-b)/0.5[(a+b)^2+(a-b)^2]
if we simlify
we know a+b=(a-b)/5
so we get finaaly
5/13 is our Ans. i.we 5:13

Like? Yes (2) | No (1)  

VISHAL.MORI   9 years AGO

There are two equations are given, By solving this we gate A=3 & B=-2.
now sqare and get ans.5:13

Like? Yes (1) | No   

PIYUSH AGRAWAL   9 years AGO

there are two variable A and b so by supposing value of a=3
b=-2 and butting this value we find this solution

Like? Yes (1) | No   

SHOWMIA DAISY RAJENDRAN   9 years AGO

a^2- b^2= (a+b)(a-b)
a^2+b^2= 1/2{[(a+b)^2]+[(a-b)^2]}
by calculating the values as given,
a+b=1 and a-b=5
we will be getting the final value as 5/13.

Like? Yes (1) | No   

Vishu   9 years AGO

(a+b)/(a-b) = 1/5
a = -(3/2)b
Put in second u will get the ratio as 5:13

Like? Yes (1) | No   

tamilmani   9 years AGO

assume a=3
b=-2
a+b=1
a-b=5
a^2-b^2=9-4=5
a^2+b^2=9+4=13
ans: option 5
(5:13)

Like? Yes (1) | No   

siddhi datri   9 years AGO

as a+b/a-b=1/5
=>a/b=-3/2
=>a=-3b/2
therefore, (a^2 - b^2):(a^2 + b^2)=(9/4-1)/(9/4+1)=5/13

Like? Yes (1) | No   

Suraj   9 years AGO

5a+5b=a-b
4a+6b=0
a/b=-6/4
ans=5/13

Like? Yes (1) | No   

Belal Ahmed   9 years AGO

by usual method we get a=-3b/2
by substitution we get ans as 5:13

Like? Yes (1) | No   

Rituparna Chakraborty   9 years AGO

(a+b)/(a-b)=1/5=>a=-3b/2
Now (a^2-b^2)/(a^2+b^2)
putting the value that a=-3b/2
we get the value of given expression 5/13.
so required ratio=5:13

Like? Yes (1) | No   

Dwaipayan Goswami   9 years AGO

by solving first equation we get a =-3/2b. Now in second equation replace each a by -3/2b. You'll get 5/13

Like? Yes (1) | No   

Santhosh R   9 years AGO

then
(a^2-b^2)/(a^2+b^2)
=(2(a+b)(a-b))/((a-b)^2+(a+b)^2)
=(2*(1/5)*(a-b)^2)/((a-b)^2+(1/25)(a-b)^2)
=(2/5)*(25/26)
=5/13=Ans

Like? Yes (1) | No   

nitin rawat   9 years AGO

(a/b+1)/(a/b-1)=1/5;
so a/b=-3/2;
Putting value of a/b in 2nd eqn.
((a/b)^2-1)/((a/b)^2+1)=5/13

Like? Yes (1) | No   

Ajay Kumar Gupta   9 years AGO

from given ratio we found => b=(-2/3)*a
so (a^2-b^2)/(a^2+b^2)=(5/9)a^2/(13/9)a^2
so ratio is 5:13.

Like? Yes (1) | No   

Arpan Datta   9 years AGO

a+b/a-b = 1/5
so, a= -3b/2
puttin the valu of a,
the ans is 5/13

Like? Yes (1) | No   

pratik avinash   9 years AGO

a+b= 1 ----- eq. 1
a-b= 5 -----eq. 2
solving both we will get
a= 3, b= -1
so,
(a^2 - b^2):(a^2 + b^2) = 5/13

Like? Yes (1) | No   

gidda reddy   9 years AGO

Suppose a=3,b=-2
Substitute in
(a+b) :(a-b) =1:5
So Substitute in a& b values
(a^2-b^2) :(a^2+b^2) =5:13

Like? Yes (1) | No   

Lakhan H. Jadhav   9 years AGO

a+b=1,
a-b=5
After solving a=3, b=-2,
so put this values in given equation

Like? Yes (1) | No   

Ankit   9 years AGO

(a+b)/(a-b)=1/5, Applying componendo and dividendo, we get a/b=-(3/2). therefore answer will be 5:13

Like? Yes (1) | No   

tarun kumar rajak   9 years AGO

5(a+b)=a-b
=> a= -3b/2

put value in eq

Like? Yes (1) | No   

Deepanshu Chaturvedi   9 years AGO

(a+b)/(a-b)=1/5
so, a= (-3/2)b
(a^2 - b^2):(a^2 + b^2)=5/13

Like? Yes (1) | No   

Sanjeev Tiwari   9 years AGO

use componendo and dividendo for the first ratio. which will give a/b=3/-2. Substitute in 2nd ratio to get the answer.

Like? Yes (1) | No   

Nilesh Dattatraya Veer   9 years AGO

a+b=1
a-b=5
solve these equation
we get a=3 b=-2
put thivalues

Like? Yes (1) | No   

neha gupta   9 years AGO

(a+b):(a-b) = 1:5
Using componendo and dividendo in above equation, we get
a:b = -3:2
squaring both sides:
a^2 : b^2 = 9:4
againg using componendo and dividendo
(a^2 + b^2):(a^2 - b^2) = 13:5
thus (a^2 - b^2):(a^2 + b^2) = 5:13

Like? Yes (1) | No   

Manikanta   9 years AGO

let a+b=x
a-b=5x
by solving the Above equations a=3x; b=2x
then a^2-b^2=5x^2
a^2+b^2=13x^2
so the ratio=5/13

Like? Yes (1) | No   

IMRAN UL HAQUE   9 years AGO

a+b/a-b=1/5
using coponando and dividando formulaa and putting value we get
a=3/2b
put this value in requier equatio
we get
answer 5:13

Like? Yes (1) | No   

Abhishek Anand   9 years AGO

a+b = 1 .......................eqn 1
a -b = 5 .......................eqn 2
Adding the above two eqn,we got
a=3 and b= -2
Now,Calculating (a^2-b^2)/(a^2+b^2) we get 5/13 Ans.

Like? Yes (1) | No   

Gousulu K   9 years AGO

a+b/a-b=1/5
a+b=1
a-b=5
solving we get
a=3,b=-2
(a^2-b^2)/(a^2+b^2)=5/13

Like? Yes (1) | No   

Surendra Naraga   9 years AGO

a+b=1
a-b=5
so a=3 and b=-2
a^2-b^2/a^2+b^2=
5/13
5:13

Like? Yes (1) | No   

venkatesh   9 years AGO

Here,
a+b=5,
a-b=1;
then, a=3,b=-2...
Hence (a^2 - b^2):(a^2 + b^2)=5:13.

Like? Yes (1) | No   

YASWANTH REDDY   9 years AGO

(a+b):(a-b) = 1:5
by componendo and dividendo, we get a=3 and b=-2
therefore (a^2 - b^2) : (a^2 + b^2) = 5:13

Like? Yes (1) | No   

UDIT   9 years AGO

(a+b)/(a-b)=1/5
solving we get a=(-3b/2)
putting value of 'a' in (a^2-b^2)/a^2+b^2)
solving we get ratio=5:13(option 5)

Like? Yes (1) | No   

Sandip Shaw   9 years AGO

(a+b)/(a-b)=1/5
a/b=(-3/2)
a^2/b^2=9/4
(a^2-b^2)/(a^2+b^2)=(9-4)/(9+4)=5/13

Like? Yes (1) | No   

M.V.S sai sunidhi   9 years AGO

(a+b)/(a-b)=1/5,from this either calculate a or b value
5(a+b)=a-b
5a-a=-b-5b
a=-(3b/2)
keep this a value in the equation(a^2-b^2)/(a^2+b^2)
((-3b/2)^2-b^2)/((-3b/2)^2+b^2)=5/13

Like? Yes (1) | No   

Wenveil lius   9 years AGO

A+b=¹
A-b=5
On solving a=3,b=-2

Like? Yes (1) | No   

shiva   9 years AGO

ans:5 option
(a+b)/(a-b)=1/5
then 5a+5b=a-b
a/b=-3/2 so a=-3 and b=2 then ans is 5:13

Like? Yes (1) | No   

Sarika A S   9 years AGO

a+b=1/6,a-b=5/6
a^2-b^2=(a+b)(a-b)
a^2+b^2=[(a+b)^2-(a-b)^2]/2
so ans is 5/13

Like? Yes (1) | No   

Sushmita Ghanty   9 years AGO

a+b/a-b=1:5
a/b=-3/2
so, (a^2-b^2)/(a^2+b^2)=5/13

Like? Yes (1) | No   

rituraj   9 years AGO

i solved it

(2*(a+b)(a-b))/(a+b)^2+(a-b)^2

Like? Yes (2) | No (1)  

02 Sep 2015 Volume

If a sphere is placed inside a right circular cylinder so as to touch the top, base and the lateral surface of the cylinder. If the radius of the sphere is R, the volume of the cylinder is

OPtion

1) 4 Pi R^3
2) 6 Pi R^3
3) 5/2 Pi R^3
4) 8/3 Pi R^3
5) 12 Pi R^3
6) 2 Pi R^3
7) 7/3 Pi R^3
8) 8 Pi R^3
9) 10 Pi R^3
10)None of these

Solution

Clearly, Radius of cylinder = Radius of sphere = R
And, height of the cylinder = 2R
Therefore
Volume of the cylinder = Pi R^2 * 2R = 2 Pi R^3

Option 6)

Correct Option: 6 Best Solution (73)

ABHINAV PUSHPAM   9 years AGO

Answer is - 2pi r^3
Explanation
H=2R
Volume of cylinder = pi * R^2* H
Put h=2r
so volume will be pi*r^2 * 2r = 2 * pi *r^3

Like? Yes (12) | No   

Abhijeet   9 years AGO

radius of cyl = rad of sphere
height of cylinder=diameter of sphere

Like? Yes (4) | No   

Ravi Yadav   9 years AGO

from given information
radius of cylinder base=R=r
Height of cylinder=2R=h
volume of cylinder = pi*r^2*h
ANS= 2*pi*R^3.

Like? Yes (2) | No   

pravin kumar   9 years AGO

height of cylinder = 2r
therefore volume of cylinder= pi*r*r*h= pi*r*r*2r=2*pi*r*r*r

Like? Yes (2) | No   

Anusha Kota   9 years AGO

volume of the right circular cylinder=pi*r*r*h
here h=2*r as per the given conditions.
so volume of cylinder= pi*r*r*2*r
=2*pi*r*r*r

Like? Yes (1) | No   

sudiptaa   9 years AGO

Height of cylinder = 2R
Volume of cylinder = Pi * R ^2 * H
= 2*Pi * R^3

Like? Yes (1) | No   

ramya   9 years AGO

The volume of the cylinder must be 2Pi r^3 using the volume of sphere and cylinder

Like? Yes (1) | No   

Rahul kumar   9 years AGO

VOL OF CYLINDER=PI*R^2*H
here H=2R
so, vol=2PIr^3

Like? Yes (1) | No   

Prathyusha    9 years AGO

Radius of Cylinder = R,
Height of Cylinder = 2R,
then, Volume of Cylinder = Pi*R^2*H,
= Pi*R^2*2R
= 2 Pi R^3

Like? Yes (1) | No   

siddhi datri   9 years AGO

let the heights be h and radius be r
h=2r
volume=pi r^2h= 2 Pi r^3

Like? Yes (1) | No   

surendra   9 years AGO

bcz sphere touches uper lower and lateral surfaces . so height of cylinder is 2r hence volume is pi*r*r*2r=2pir3

Like? Yes (1) | No   

ANIK KUMAR HALDER   9 years AGO

as the sphere touches the top and bottom and curved surface area of the cylinder .
so radius of the cylinder =radius of the sphere=R
height of the cylinder=R+R=2R
area of the cylinder =pi*r^2h=pi*R^2*(2R)=2piR^3

Like? Yes (1) | No   

tamilmani   9 years AGO

volume=pi r^2 h
r=r
h=2r
volume=pi(r^2)*(2r)
=pi*2(r^3)

Like? Yes (1) | No   

Nitheesh Aithu   9 years AGO

let r=radius of base and top of cylinder and h=height of cylinder
According to the problem given,
r=R,h=R+R=2R
where R=Radius of inner placed sphere
Volume of R.C.C=pi*r^2*h=pi*R^2*2R
=2*pi*R^3

Like? Yes (1) | No   

praveendas   9 years AGO

volume of the cylinder is pi*r^2*h
h is 2R.
therefore volume is 2*(pi)*R^3

Like? Yes (1) | No   

umang agarwal   9 years AGO

here sphere touches both upper nd base of cylinder.
so, diameter of sphere=height of cylinder.=2r.
so the area of cyinder=pi*r^2*h=pi*r^2*2r=2pi*r^3

Like? Yes (1) | No   

Prabhat Burnwal   9 years AGO

radius of the cylinder=R
height of the cylinder=2R
volume=2 PI R^3

Like? Yes (1) | No   

Sahana Jayasimha   9 years AGO

Given:
a. The radius of the sphere is R
b. The sphere is touching the top,bottom and lateral surfaces of the cylinder .
Therefore from this we can infer that the height of cylinder is equal to the diameter of the sphere , h=2R
and the radius of the cylinder is equal to the radius of the sphere.
volume of cylinder is =PI* (R^2) *h
= PI * (R^2) * 2R
= 2 PI R^3

Like? Yes (1) | No   

Monika Nemiwal   9 years AGO

volume of cylinder=Pi*r^2*h
Pi(R^2)(2R)
2Pi(R^3)

Like? Yes (1) | No   

Sushant Kumar   9 years AGO

r=R
h=2R
VOLUME OF CYLINDER= PIr^2h
= piR^2*2R
= 2piR^3

Like? Yes (1) | No   

RAVAL   9 years AGO

sphere is placed in cylinder
so, height (h) = 2R
volume of cylinder = pi* R^2 * 2R
= 2*pi*R^3

Like? Yes (1) | No   

SHIVUMUNI SHASTRIMATH   9 years AGO

volume of sphere=4/3 pi r^3
volume of cylinder=pi r^2 h
substitute sphere volume in cylinder i.e.
pi r^2 h, h=2r so answer is 2 pi r^3

Like? Yes (1) | No   

vikas kulshrestha   9 years AGO

the radius of the cylinder = R
height of the cylinder = 2R
volume of cylinder =Pi R^2 (h)
=Pi R^2 (2R)
=2 Pi R^3

Like? Yes (1) | No   

Amiya Ranjan   9 years AGO

radius of the sphere is R , so the radius of the bottom circle of the cylinder will be R as well. The height of the cylinder will be equal to the diameter of the sphere so H=2R.

Vol=pi*r^2*h=pi*r^2*2r=2*pi*r^3

Like? Yes (1) | No   

Zulekha Parveen   9 years AGO

sphere covers cylinder.
radius of base of cylinder=R
height of cylinder=diameter of sphere=2R
so, vol of cylinder=pi*r^2*h
=pi*R^2*2R
=pi*2R^3

Like? Yes (1) | No   

Devendra Marghade   9 years AGO

Cylinder's Radius=R and Height=2R
So Volume of Cylinder=Pi*(Radius)^2*Height
=Pi*R^2*2R=2*Pi*R^3
Option 6)

Like? Yes (1) | No   

gaurav   9 years AGO

height=2r
radius=r
apply formula for volume of cylinder

Like? Yes (1) | No   

gaurav singh   9 years AGO

radius of sphere=R
height of cylinder=2R
volume of cylinder = pi r^2 h
=> pi R^2 (2R)
=> 2 Pi R^3

Like? Yes (1) | No   

PAWAN KUMAR   9 years AGO

RADIUS OF CYLINDER = R , HEIGHT = 2R
SO, VOLUME = 2*PI*R^3.

Like? Yes (1) | No   

PIYUSH AGRAWAL   9 years AGO

volume of cylinder is 2 pi r^2 h
but here h = r so

Like? Yes (2) | No (1)  

Rishab Kumar   9 years AGO

h=2R
r=R
volume of cylinder=pi*r*r*h
=2*pi*R^3

Like? Yes (1) | No   

Goutham Venkatesh K   9 years AGO

radius of cylinder = r
height of cylinder = 2r
volume = pi r^2 h = pi * r * r * 2r = 2 Pi r^3

Like? Yes (1) | No   

milan gupta   9 years AGO

r of cylinder =r of sphere
h of cyl.=2xr of sphere

Like? Yes (1) | No   

nikhil bansal   9 years AGO

volume of cylinder = pi r^2 h
here r=R
h=2R
so
volume = pi R^2 2R = 2pi R^3

Like? Yes (1) | No   

ajay kulkarni   9 years AGO

If R is the radius of the sphere and sphere touches the cylinder internally then
length of cylinder is 2R and radius of cylinder is R
then volume of cylinder is
=pi*R^2*(2R)=2*pi*R^3.

Like? Yes (1) | No   

kriti kankariya   9 years AGO

volume of cyl = pi * r^2 *h
here r of cyl=R of sphere
and h of cyl = 2R of sphere
therefore,vol of cyl = pi* R^2 *2R
= 2*pi* R^3

Like? Yes (1) | No   

YASWANTH REDDY   9 years AGO

as per the given information, the height of the cylinder is equal to 2 times of radius of the sphere and therefore,
Volume of cylinder = pi R^2 H = pi R^2 * (2R) = 2 pi R^3

Like? Yes (1) | No   

Deepanshu Chaturvedi   9 years AGO

Radius of sphere = Radius of cylinder
Height of cylinder = 2 * Radius of sphere
so, volume of cylinder = Pi * (R)^2 * H
= Pi * R^2 * 2 * R
= 2 Pi R^3

Like? Yes (1) | No   

Gayathri   9 years AGO

Given radius of the sphere= r
as it touches the base, top and lateral surface, height of the cylinder,h=r+r=2h
volume of the cylinder = pi*r^2*h
replace h with 2r
therefore, volume of the cylinder=pi*r^2*2r
= pi*r^3

Like? Yes (1) | No   

Archie   9 years AGO

Volume of cylinder=pi*R^2*h
h=dia. of sphere = 2R
Vol. of cylinder =pi*R^2*(2R)
=2 Pi R^3

Like? Yes (1) | No   

vishal varma   9 years AGO

volume of cyinder=pir^2H
PI*R^2*2R=2PIR^3
ssince ht of cylinder= diameter of circle=2r

Like? Yes (1) | No   

Dipanjan Bhattacharjee   9 years AGO

The diameter of the circle is 2R which is actually the height of the cylinder

Like? Yes (1) | No   

Rishav Kumar   9 years AGO

since, the sphere is touching top ,base and lateral surfaces of the cylinder
hence, height of cylinder=2* radius of sphere
&& radius of cylinder,s base= radius of sphere
v=pi* R^2 * h=pi* R^2 * 2*R =2*pi*R^3

Like? Yes (1) | No   

anant rathi   9 years AGO

Radius of cylinder = radius of sphere
Height of cynlinder = 2* R

Like? Yes (1) | No   

diksha   9 years AGO

radius of cylinder= r
height = 2r
volume=pi*r^2*h
=pi*r^2*(2r)
=2pir^3

Like? Yes (1) | No   

Vertika Srivastava   9 years AGO

radius of sphere=r=radius of cylinder
so, diameter of sphere=2r=height of cylinder
volume of cylindder= pie r^2*h

Like? Yes (1) | No   

Rashmi Verma   9 years AGO

volume of cylinder= ?r^2h
h=2r
vol=2?r^3

Like? Yes (1) | No   

Pronab Paul   9 years AGO

Vol of cylinder=pi*r^2*h
Here radius of cylinder=radius of sphere=R
And height of cylinder= diameter of sphere=2R
So, vol= pi*R^2*2R=2pi*R^3

Like? Yes (1) | No   

raj sekhar   9 years AGO

height of cylinder: 2R
radius of cylinder: R
bol of cylinder: circle area * height
=pi* (R)² * (2R)

Like? Yes (1) | No   

rahul raj sharma   9 years AGO

volume of cylinder=pi*r*r*h
and radius of circle is R which is also the radius of cylinder and also height of cylinder is 2R because it is equal to diameter of circle

Like? Yes (1) | No   

ishan chourishi   9 years AGO

volume of cylinder is pi *r^2*h
here h=2R (as cylinder is touching all sides so 2*radius =h)
r=R
so pi*r^2*h= pi *R^2* 2R => 2 pi R^3

Like? Yes (1) | No   

M.V.S sai sunidhi   9 years AGO

as the sphere is connected to top ,bottom and lateral surfaces ,the height of cylinder is,h=2*r
so as volume of cylinder is ,v=pi*r^2*h=pi*r^2*2*r
=2*pi*r^3

Like? Yes (1) | No   

Sivaprakash.J   9 years AGO

Height of sphere is 2R
Then,
Volume of cylindet=Ï€R^2h
Now volume is 2Ï€R^3

Like? Yes (1) | No   

Ravi kumar   9 years AGO

Here the radius of sphere will be equal to radius of cylinder and height of the cylinder will be = to diameter of sphere .

Like? Yes (1) | No   

suhail anjum   9 years AGO

curved surface area of the sphere placed inside the right circular cylinder is same as cylinder.so base radius of cylinder is same as radius of sphere and hence height is two times of radius of sphere .

Like? Yes (1) | No   

Vatan Chaudhary   9 years AGO

volume of cylinder=pie *(R)sq*H
here H= 2R
therefore volume of cylinder=pie*(R)cube

Like? Yes (1) | No   

shyam sundar satpathy   9 years AGO

Here radius of cylinder is equal to the radius of sphere i.e. 'R' and height is the diameter of the sphere i.e. '2R' so
volumn of cylinder is =PI * R*2R=2 PI R^3

Like? Yes (1) | No   

NAGENDRA P   9 years AGO

volume of a cylinder= pi*r*r*h=pi*R^2*2R=2pi*R^3
so option (6)

Like? Yes (1) | No   

Surabhi Yadav   9 years AGO

volume of cylinder=pi r^2 h
sphere touching cylinder= 2R^3 pi
hence option (6)

Like? Yes (1) | No   

Ashish Kumar Karan   9 years AGO

height=2*R
volume=(pi*R^2)*(2*R)
=2*pi*R^3

Like? Yes (1) | No   

Prateek sanganeria   9 years AGO

as volume of a cyliner = pi*r^2*h
here h=2r
therefore, V=2*pi*R^3

Like? Yes (1) | No   

Kishan Kumar   9 years AGO

Height =2R, Radius = R then put iy into volume of cylinder formula

Like? Yes (1) | No   

sidd   9 years AGO

height = 2R
radius = R
volume = pi * R^2 * H = 2 * pi * R^3

Like? Yes (1) | No   

KAVITHA   9 years AGO

Volume of the cylinder is
Pi*R^2*H
here is is 2R as diameter of the circle which is the height of the cylinder so
Volume is 2*Pi*R^3

Like? Yes (1) | No   

Aman Gaurav   9 years AGO

Volume of the cylender is
Pi*R^2*H
here is is 2R as diameter of the circle which is the height of the cylinder so
Volume is 2*Pi*R^3

Like? Yes (1) | No   

Aman   9 years AGO

Volume of the cylinder is
Pi*R^2*H
here is is 2 R as diameter of the circle which is the height of the cylinder so
Volume is 2*Pi*R^3

Like? Yes (1) | No   

Shubhendu Shrivastava   9 years AGO

volume of regular cylinder= pi*r*r*h
here, the sphere touches the top, base and the lateral surface thence, the cylinder has the diameter of base equal to the height. therefore, h=2R
So, vol= pi*R*R*2R
=2*pi*R^3

Like? Yes (1) | No   

Khushboo Pasari   9 years AGO

Volume of a Cylinder= Pi R^2 H
Sphere is in the Right Circular Cylinder with the condition that it touches the top, base and the lateral surface.
Hence, Height of the Cylinder, H= 2 R
Volume of the Cylinder= Pi R^2 2 R
Therefore, Answer= 2 Pi R^3

Like? Yes (1) | No   

Harsh Poddar   9 years AGO

Radius of cylinder is equal to radius of sphere and height of cylinder is the diameter of sphere so volume=pi R^2h=2piR^3

Like? Yes (1) | No (1)  

vivek   9 years AGO

radius of cylinder will be r and hight will be 2r.
volume will be pi*r*r*h= pi*r*r*2r=2*pi*r*r*r.

Like? Yes (3) | No (3)  

Akash Kumar   9 years AGO

As sphere touches all the dimensions of the cylinder so radius and height of the of the cylinder are following..
r=R; h=2R,
so volume of cylinder is=pi*r^2*h=pi*(R)^2*(2R)=2 pi R^3
that's why answer is option 6

Like? Yes (1) | No (1)  

Ajeet Kumar   9 years AGO

as it touches the top and bottom of the cylinder, so
h= 2r
volume= pi(r*r)h
=2pir^2h

Like? Yes (1) | No (1)  

TINKU MITTAL   9 years AGO

as the sphere touches the base and top as well as side walls, so the radius of cylinder= radius of sphere= R
and height of cylinder= dia of sphere= 2R
so volume of cylinder= pi*R^2 *(2R)
= 2 pi R^3

Like? Yes (1) | No (1)  

01 Sep 2015 Stocks and shares

Find the market value of a 21/4 % stock, in which an income of Rs.756 is derived by investing Rs.14976, brokerage being 1/4 %.

OPtion

1) Rs. 105.55
2) Rs. 106.25
3) Rs. 101.35
4) Rs. 104.75
5) Rs. 103.75
6) Rs. 110.25
7) Rs. 109.50
8) Rs. 108.75
9) Rs. 115.75
10)Rs. 100.75

Solution

For an income of Rs.756, investment = Rs.14976
For an income of Rs. 21/4, investment = Rs. (14976/756 * 21/4)= Rs.104
Therefore For a Rs. 100 stock, investment = Rs.104
Hence market value = Rs.(104 - 1/4) = Rs. 103.75

Option 5)

Correct Option: 5 Best Solution (15)

ABHINAV PUSHPAM   9 years AGO

Answer : Option 5

Explanation :

Assume that face value = Rs.100

Dividend per share = Rs.21/4 (as it is 5.25% stock)

By investing Rs.14976, earnings = Rs.756

To get an earning of Rs. 5.25, investment required = (14976×5.25)/756 = Rs.104

ie,market value of Rs. 100 stock = Rs.(104 - 1/4) = Rs.103.75

Like? Yes (3) | No (1)  

jayaram   9 years AGO

For an income of Rs. 756, investment = Rs. 14976;
For an income of Rs. 21 , investment = Rs.9000 x(21/4) = Rs. 104.
=104-(1/4)=415/3=103.75

Like? Yes (1) | No   

Venkatesh kadali   9 years AGO

For an income of Rs. 756, investment = Rs. 14976

For an income of Rs. 21/4 ,
investment = (14976/756)x (21/4)
=104
For a Rs. 100 stock, investment = Rs. 104.

Market value of Rs. 100 stock = 104 -(1/4)
=405/4
=103.75
so answer is 5

Like? Yes (2) | No (1)  

Kunal nemu   9 years AGO

For an income of Rs.756,investment = Rs.14976
For an income of Rs.21/4 investment = Rs.((14976/756) * (21/4)) =Rs.104
For a Rs.100 stock,investment =Rs.104
Market value of Rs.100 stock =Rs.(104 - 1/4) =Rs.103.75

Like? Yes (2) | No (1)  

sowjanya kasam   9 years AGO

Assume that face value = Rs.100

Dividend per share = 21/4=5.25

By investing Rs.14976, earnings = Rs.756

To get an earning of Rs.5.25, investment required = (14976*5.25)/756=104

ie,market value of Rs. 100 stock = Rs.(104- 1/4) = Rs.103.75

Like? Yes (1) | No   

THUMMALA VINEESHA   9 years AGO

(14976/756)*(21/4)=104
Including brokerage 104-(1/4)=103.75

Like? Yes (1) | No   

Lakhi kant Roy   9 years AGO

Let face value = Rs.100

Dividend per share = 21/4 %

By investing Rs. 14976, earnings = Rs.756

To get an earning of Rs.21/4,
investment required = (14976×21)/(4 * 756) = Rs.104

ie,market value of Rs. 100 stock = Rs.(104- 1/4) = Rs.103.75

Like? Yes (1) | No   

Monika Nemiwal   9 years AGO

investment to make income of 756=14976
thus,investment to make income of 21/4=14976/756*(21/4)
=104
brokerage being 1/4,market value=104-(1/4)
=103.75

Like? Yes (1) | No   

Prathyusha    9 years AGO

For an income of Rs. 756, investment = Rs. 14976

For an income of Rs. 21/4 ,
investment = Rs.((14976/756)*(21/4)) = Rs. 104.
For a Rs. 100 stock, investment = Rs. 104.

Market value of Rs. 100 stock = Rs.(104 -(1/4))= Rs. 103.75

Like? Yes (1) | No   

Deepanshu Chaturvedi   9 years AGO

for income of Rs. 756, investment = 14976
for an income of Rs. 21/4, investment = Rs. (14976/756)*(21*4) = Rs. 104
therefore, for a Rs. 100 stock, investment = Rs. 104
Market value of Rs. 100 stock = Rs. (104-1/4) = Rs.103.75

Like? Yes (1) | No   

vikas kulshrestha   9 years AGO

Assume that face value = Rs.100

Dividend per share = Rs.21/4 (as it is 21/4% stock)

By investing Rs.14976, earnings = Rs.756

To get an earning of Rs.21/4, investment required = 14976*21/4*756 = Rs.104

ie,market value of Rs. 100 stock = Rs.(104- 1/4) = Rs.103.75

Like? Yes (1) | No   

Anusha Kota   9 years AGO

For Rs 756 income, investment=14976;
For Rs (21/4) income, investment=?
=(21*14976)/(4*756)=104 Rs
For 100 stock, investment=104;
but for 1/4 brokerage, market value ==104-(1/4)=103.75 rs

Like? Yes (1) | No   

Joy cindrella   9 years AGO

For an income of Rs.756, investment=Rs.14976
For an income of 21/4,investment= (14976/756)*(21/4) which gives you Rs.104. i.e., For Rs.100 stock investment=Rs.104
Due to the brokerage, market value is reduced. i.e.,
104- (1/4%)= 104-0.25 which gives 103.75

Like? Yes (1) | No   

Ajay Kumar Gupta   9 years AGO

income=756,investment=14976
for an income of 21/4
invest=(14976/756)*(21/4)=104
for a 100 rs stock invest=104
so market value of 100 stock=104-1/4=103.75

Like? Yes (1) | No (1)  

Shubham Raj   9 years AGO

Assume that face value = Rs.100

Dividend per share = 21/4 %

By investing Rs. 14976, earnings = Rs.756

To get an earning of Rs.21/4, investment required = (14976×21)/(4 * 756) = Rs.104

ie,market value of Rs. 100 stock = Rs.(104- 1/4) = Rs.103.75

Like? Yes (1) | No (1)  

31 Aug 2015 Sequence

What is the next number of the following sequence
27, 54, 81, 135, 189,........

OPtion

1) 108
2) 243
3) 405
4) 216
5) 378
6) 486
7) 297
8) 459
9) 351
10)None of these

Solution

27*1 = 27
27*2 = 54
27*3 = 81
27*5 = 135
27*7 = 180
Similarly
27*11 297
(Multiplication of prime numbers)

Correct Option: 7 Best Solution (95)

Deepanshu Chaturvedi   9 years AGO

3*3*3=27
3*3*3*2=54
3*3*3*3=81
3*3*3*5=135
3*3*3*7=189
similarly,
3*3*3*11=297

Like? Yes (4) | No   

Moumita Choudhury   9 years AGO

54-27 = 27
81-54 = 27
135 - 81 = 54
189-135 = 54 so 189 + (54*2) = 189+108 = 297.

Like? Yes (4) | No (2)  

Chandrajeet Yadav   9 years AGO

1st Method:
-----------------
27, 54, 81, 135, 189, .......
(3)^3, (3)^3*2 , (3)^3*3, (3)^3*5, (3)^3*7.....
By multiplying 1st prime Number in (3)^3 we get 2nd term and multiplying 2nd prime number in (3)^3, we get 3rd term and so on...

So that by multiplying 11 (5th prime number) in (3)^3 we get required number (6th number of the given sequence) is (3)^3*11=297
================================================

2nd Method:
------------------
27, 54, 81, 135, 189, .......
27, 54, (27+54), (54+81), {(27+54)+2*54},....
27, 54, (27+54), (54+81), {(27+54)+2*54}, {(54+81)+2*81},....
27, 54, 81, 135, 189, 297,.....

Like? Yes (2) | No   

Danda Sindhura   9 years AGO

27=3*9
54=3*2*9
81=3*3*9
135=3*5*9
189=3*7*9
next prime number which has to be multiply with 3 and 9 is 11..........so
3*11*9=297

Like? Yes (2) | No   

pravin kumar   9 years AGO

27*1,27*2,27*3,27*5,27*7,27*11
multiplication with prime numbers

Like? Yes (2) | No   

vikas kulshrestha   9 years AGO

27*1=27
27*2=54
27*3=81
27*5=135
27*7=189
27*11=297
the series is multiplication of prime numbers.

Like? Yes (2) | No   

SAGNIK DATTA   9 years AGO

27*3,27*5,27*7,27*11

Like? Yes (1) | No   

Shubham Raj   9 years AGO

ans- option - 7) 297
27 * 2 (first prime no) =54
27 * 3(second prime) =81
27 * 5(third prime) =135
27 * 7(fourth prime) = 189
27 * 11 (fifth prime) =297

Like? Yes (1) | No   

BONAM SRINIVAS   9 years AGO

first two times 27 difference next two times 54 and next 108,so 189+108=297

Like? Yes (1) | No   

Lakhi kant Roy   9 years AGO

The series is incrementing like this--------->
27*1=27
27*2=54
27*3=81
27*5=135
27*7=189
so,
27*11=297 (Ans)

Like? Yes (1) | No   

sravani   9 years AGO

It is 297...
If the series is
27*1, 27*2,27*3,27*5,27*7,27*11=297

Like? Yes (1) | No   

vivek raj   9 years AGO

27 is multiplied by prime nos
27*2=54
27*3=81
27*5=135
27*7=189
27*11=297

Like? Yes (1) | No   

sudiptaa   9 years AGO

27
54=27*2
81=27*3
135=27*5
189=27*7
27*11=297
All prime numbers

Like? Yes (1) | No   

velmala gangadhar   9 years AGO

27+27=54
54+27=81
81+54=135
135+54=189
189+108=297.....ans is 297 option 7

Like? Yes (1) | No   

Dhirendra Gautam   9 years AGO

54-27=27
81-54=27
now difference gets double
135-81=54
189-135=54
now again differnce get double
so,
?-189=108
so?=!97

Like? Yes (1) | No   

ramya   9 years AGO

All the numbers are prime multiples of 27
that is:
27 *1, 27 *2, 27 *3, 27*5, 27 *7, so the next one must be 27 *11= 297

Like? Yes (1) | No   

himanshu shekhar   9 years AGO

54-27=27
81-54=27
135-81=54
I.e the sum of above 2 diffrences
and 189-135=54
I.e. 54+54 is the next value I.e 108 , add this to 189 to get 297 as answer

Like? Yes (1) | No   

sum gup   9 years AGO

27*2=54
27*3=81
27*5=135
27*7=189
27*11=297

Like? Yes (1) | No   

darladiwakar   9 years AGO

9*3
9*3*2
9*3*3
9*3*5
9*3*7
9*3*11=297

Like? Yes (1) | No   

Sneha Chakraborty   9 years AGO

27*1 = 27
27*2 = 54
27*3 = 81
27*5 = 135
27*7 = 189

as we can see 2,3,5,7 is prime no., so next is 11 and therefore
27*11 = 297...........so ans is (7)

Like? Yes (1) | No   

mithilesh izardar   9 years AGO

9*(3*1) , 9*(3*2) , 9*(3*3) , 9*(3*5), 9*(3*7) , 9*(3*11)

9*3*next prime number

Like? Yes (1) | No   

Priyank   9 years AGO

In each and Every Term 27 Is Multiplied By Prime numbers

i.e 1,3,5,7
such that
27*2 =54
27*3 =81
27*5=135
27*7=189
after 7 -- 11 Is the Prime number ( Number which is divisible by 1 And thatself Only)
i.e. We multiplied by 11
i.e.27*11 =297

Like? Yes (1) | No   

ANUSHKA   9 years AGO

3*9=27
6*9=54 (3+3=6)
9*9=81 (6+3=9)
15*9=135 (9+6=15)
21*9=189 (15+6=21)
33*9=297 (21+12=33)

Like? Yes (1) | No   

Saiteja Turlapati   9 years AGO

each element in the series is multiplied with prime numbers starting from 1.
27*1, 27*2, 27*3, 27*5, 27*7
so next in the series is 27*11 =297

Like? Yes (1) | No   

Akash Kumar   9 years AGO

starting from 27
next terms are achieved by multiplying subsequent prime number to 27.As following
27
27*2=54
27*3=81
27*5=135
27*7=189
and so
next prime is 11 therefore
27*11=297
therefore 297 is right answer.

Like? Yes (1) | No   

Pronab Paul   9 years AGO

27
27*2=54
27*3=81
27*5=135
27*7=189
27*11=297

Like? Yes (1) | No   

KALA BHANU PRAKASH   9 years AGO

27+27=54
54+27=81
81+54=135
135+54=189
189+108=297.....ans is 297 option 7

Like? Yes (1) | No   

Ankit Singh   9 years AGO

27 multiplied by prime numbers 2, 3, 5, 7 then it is 11, so 27*11=297

Like? Yes (1) | No   

Rishikesh Ranjan   9 years AGO

27*2
27*3
27*5
27*7
27*11=297
(27*prime numbers)

Like? Yes (1) | No   

RAVAL   9 years AGO

there is a multiplication of 27 with prime no.s
27;
27*2=54
27*3=81
27*5=135
27*7=189
so,27*11=297

Like? Yes (1) | No   

vivek   9 years AGO

as here 27*2=54
27*3=81
27*5=135
27*7=189
27*11=297
2,3,5,7,11 are prime numbers

Like? Yes (1) | No   

Krishns   9 years AGO

27*2
27*3
27*5
27*7
27*11

Like? Yes (1) | No   

Dharmraj Sharma   9 years AGO

27*1=27
27*2=54
27*3=81
27*5=135
27*7=189
27*11=297

Like? Yes (1) | No   

sanjay singh meena   9 years AGO

differenece between first two(27-54,81-54) no is 27,next two(135-81,189-135)is 54 so next no will have differenc 108
so next no is 189+108=297

Like? Yes (1) | No   

Ravi Yadav   9 years AGO

54-27=27
81-54=27
27 two times, now 27 gets doubled
135-81=54
189-135=54
54 two times, now 54 gets doubled
189+108=297

Like? Yes (1) | No   

kayenaat   9 years AGO

27=9x3x1
54=9x3x2
81=9x3x3
135=9x3x5
189=9x3x7
9x3x11= 297

Like? Yes (1) | No   

Math Lovers   9 years AGO

numbers are prime multiples (2, 3, 5, 7) of 27

so next number will be 11 multiples of 27 =297

Like? Yes (1) | No   

ANURAG DADWAL   9 years AGO

the difference of the first four terms is 27 and 54 that is
54-27=27
81-54=27
135-81=54
189-135=54
x-189=(should be multiple of 54 i.e 2x54=108)
now add 108+189=297

Like? Yes (1) | No   

vishal varma   9 years AGO

series in format of
3*1*9,3*2*9,3*3*9,3*5*9,3*7*9,________
i.e, 3*11*9=297

Like? Yes (1) | No   

mithilesh kumar   9 years AGO

multiply 27 by consecutive prime no.
27×2=54
27×3=81
27×5=135
27×7=189
so next prime no. is 11
27×11=297

Like? Yes (1) | No   

Mrinalini Singh   9 years AGO

27*1, 27*2, 27*3, 27*5, 27*7, 27*11=297
consecutive prime numbers

Like? Yes (1) | No   

nisha   9 years AGO

first 27 +27 = 54,
54+27 =81
81 + 54= 135
135 +54= 189
189 +(54+ 54) = 297 ans

Like? Yes (1) | No   

Amit Niranjan   9 years AGO

it is series of multiple of 27 with consecutive prime numbers.

Like? Yes (1) | No   

Kunal nemu   9 years AGO

27 * 1=27
27 * 2=54
27 * 3=81
27 * 5=135
27 * 7=189
here 1,2,3,5,7 are prime number ...
so next prime number is 11
so the answer is 27 * 11=297

Like? Yes (1) | No   

A.neeli swarna   9 years AGO

3 multiplcation
starting 3*9=27
3*(9+9)=54
3*(18+9)=81
3*(27+18)=135
3*(45+18)=189
3*(63+36)=297
3*(99+36)=405

Like? Yes (1) | No   

tarun kumar rajak   9 years AGO

the series is in the form of = 27 (1,2,3,5,7,11......)
multiplication of prime number

Like? Yes (1) | No   

Surendra Naraga   9 years AGO

54-27=27
81-54=27
135-81=54
189-135=54
so next the difference will be 108
189+108=297

Like? Yes (1) | No   

Kumar Gaurav   9 years AGO

all the numbers are prime multiple of 27. 1,2,3,5,7,11,13..... like this

Like? Yes (1) | No   

DHAYYALA SREEKANTH REDDY   9 years AGO

9*3=27
9*6=54
9*9=81
9*15=135
9*21=189
9*33=297

Like? Yes (1) | No   

venkatesh   9 years AGO

MULTIPLES OF 27 WITH PRIME NUMBERS=
27*2,27*3,27*5,27*7,27*11=297

Like? Yes (1) | No   

H. Sreekanth   9 years AGO

2*27=54;
54+27=81;
81+54=135;
135+54=189;
189+108=297;

Like? Yes (1) | No   

sudhir   9 years AGO

the difference between number is increase by
27,27,(2*27=54),(2*27=54),so next will be(54*2=108)
so next term is 189+108=297

Like? Yes (1) | No   

ezhilane   9 years AGO

since
27*1=27
27*2=54
27*3=81
27*5=135
27*7=189 then next prime no. is 11
27*11=297.
so 27 54 81 135 189 297

Like? Yes (1) | No   

JAHAGIRDAR RUPALI MANOJ    9 years AGO

in this sequence
the numbers are multiple of 27 ,but he multipliers are only prime numbers.
the last multipliers is 7 i.e. 27*7=189
series is:-
27*1=27
27*2=54
27*3=81
27*5=135
27*7=189
and the next no is
27*11=297
option 7)

Like? Yes (1) | No   

REVATHIVENKATESAN   9 years AGO

The difference between first two number=27
next 2 no difference=27
next 2 no difference=54
next 2 no difference=54
So the next 2 no difference must be 108.
189+108=297.
So the answer is 297.

Like? Yes (1) | No   

Gousulu K   9 years AGO

54-27=27
81-54=27
135-81=54
189-135=54
so next the difference will be 108
189+108=297

Like? Yes (1) | No   

chindam laxman   9 years AGO

27=9*3=9*3*1
54=9*6=9*3*2
81=9*9=9*3*3
135=9*15=9*3*5
189=9*21=9*3*7
there fore 297=9*33=9*3*11

Like? Yes (1) | No   

PALAK AGRAWAL   9 years AGO

27×2=54
27×3=81
27×5=135
27×7=189
27×11=297
I.e :27×prime no.

Like? Yes (1) | No   

Alina Roy   9 years AGO

9*3=27
9*3*2=54
9*3*3=81
9*3*5=135
9*3*7=189
9*3*11=297

Like? Yes (1) | No   

ajit   9 years AGO

series is - 3x9, 6x9, 9x9, 15x9, 21x9, 33x9
3 3 6 6 12
3x2 3x2 6x2

Like? Yes (1) | No   

Rupkatha Banerjee   9 years AGO

54-27=27
81-54=27
195-81=54
189-135=54
189+108=297

Like? Yes (1) | No   

indira   9 years AGO

27/3,54/3,81/3,135/3,189/3 we get 9,18,27,45,63 when divided by 9 we get 1,2,3,5,7 which are prime numbers.then next prime num is 11..hence multiplied by 9, then we get 99..again multiplied by 3 we get 297 as ans.

Like? Yes (1) | No   

Dileep Kumar   9 years AGO

because in 1st two pairs 27 is difference and gain in next two pairs difference is 54 then again for next two pairs difference should be 108

Like? Yes (1) | No   

santosh kumar patel   9 years AGO

27*2=54
27*3=81
27*5=135
27*7=189
27*11=297

27*prime number

Like? Yes (1) | No   

Tharun   9 years AGO

multiplying 27 with prime numbers that is in the series next with 11

Like? Yes (1) | No   

sireesha.yammanuru   9 years AGO

27+27=54
54+27=81
81+54=135
135+54=189
189+108=297

Like? Yes (1) | No   

UDIT   9 years AGO

54-27=27
81-54=27
double 27
135-81=54
189-135=54
so now double 54
189+108=297

Like? Yes (1) | No   

Anusha Kota   9 years AGO

Reason is 27* consecutive prime numbers
27
27*2=54
27*3=81
27*5=135
27*7=189
27*11=297

Like? Yes (1) | No   

Biswajit Bora   9 years AGO

54-27=27
81-54=27

Now, 27*2=54

135-81=54
189-135=54

Now, 54*2=108

297-189=108

So, the next number is 297 :)

Like? Yes (1) | No   

Vishal Kumar   9 years AGO

27*1=27,27*2=54,27*3=81,27*5=135,27*7=189...
1,2,3,5,7 is a prime number series that why the next number is 27*11=297

Like? Yes (1) | No   

Amrita Kumari   9 years AGO

27*2,27*3,27*3,27*5,27*7,27*11...
prime nos..2,3,5,7,11....
27 multiplied by prime nos.

Like? Yes (1) | No   

THUMMALA VINEESHA   9 years AGO

Series follows 3*9*1=27
3*9*2=54
3*9*3=81
3*9*5=135
3*9*7=189
3*9*11=297

Like? Yes (1) | No   

Koumudhi Bonagiri   9 years AGO

series follow the below logic...
27x1, 27x2, 27x3, 27x5, ...27x the next prime number i.e; 7
27x7 = 297

Like? Yes (1) | No   

Goutham   9 years AGO

27
54=27*2
81=27*3
135=27*5
189=27*7
NEXT NUMBER IS
27*11=297

Like? Yes (1) | No   

shameer guptha   9 years AGO

9*3,9*6,9*9,9*15,9*21.. Why i choose 3,6,9,15,21 as a pattern because they are all productive prime nos.So,3*1,3*2,3*3,3*5,3*7

So the next pattern will be 3*11=33

Hence,the next number is 9*33=297.

Like? Yes (1) | No   

shivam dubey   9 years AGO

series is become by multiplying prime numbers
27*2 = 54
27*3 = 81
27*5 = 135
27*7 = 189
27* 11 = 297

Like? Yes (1) | No   

Mugesh sivagnanam Krishnapillai   9 years AGO

The sequence os formed by the multiples of 27 with prime
numbers 2,3,5,7,11.....
Therefore the sequence is 27,54,81,135,189,297.....

Like? Yes (1) | No   

madhav gang   9 years AGO

27*1=27
27*2=54
27*3=54
27*5=135
27*7=189
27*11=297
it follows the series 1,2,3,5,7,11

Like? Yes (1) | No   

R.NIVEDITA   9 years AGO

All the numbers are multiples of 27.
The first number can be given as (27*1)
The second number can be given as (27*2)
Third number:(27*3)
Fourth number:(27*5) and so on..
Note that only prime numbers are being multiplied with the number 27.
The last number is 189 = 27*7
The next number in the sequence is:
27*11=297

Like? Yes (1) | No   

NAVEEN KUMAR   9 years AGO

9*3--(3*1)
9*6--(3*2)
9*9--(3*3)
9*15--(3*5)
9*21---(3*7)..
hence next prime no 11 so,11*3
9*33=297

Like? Yes (1) | No   

Shashank Sourabh Singh   9 years AGO

9*3,9*6,9*9,9*15,9*21.. We choose 3,6,9,15,21 as a pattern because they are all productive prime numbers.So,3*1,3*2,3*3,3*5,3*7

Hence,the next number is 9*33=297.

Like? Yes (1) | No   

mukul   9 years AGO

54-27=81-54=27
135-81=189-135=54(27*2)
therefore next term will be 108+189=297
{54*2=108}

Like? Yes (1) | No   

Suraj Raju   9 years AGO

27*1,27*2,27*3,27*5,27*7,..(27*prime numbers)
So 27*11=297

Like? Yes (1) | No   

M Narasimhulu   9 years AGO

given 27,54,81,135,189 which are mulitiples of 27*consecutive prime numbers i.e.,
27*1,27*2=54,27*3=81,27*5=135,27*7=189,then 27*11=297

Like? Yes (1) | No   

PRIYADHARSINI.P   9 years AGO

the 1st 2 difference between the numbers in the series is 27, whereas next 2 difference is 54 (27*2) and so on.

Like? Yes (1) | No   

YASWANTH REDDY   9 years AGO

27 = 27*1
54 = 27*2
81 = 27*3
135 = 27*5
189 = 27*7
these numbers are obtained by multiplying the number 27 with prime numbers starting from 1...if we continue like that, the next number we get will be
27*11 = 297

Like? Yes (1) | No   

deepa singh   9 years AGO

54-27=27
81-54=27
135-81=54(27+27)
189-135=54
189+(54+54)=297

Like? Yes (1) | No   

Ankita Mishra   9 years AGO

first two digits have the difference of 27
and next two have difference of 54
so at next it will be of difference 108
hence the answer is 297

Like? Yes (1) | No   

Ravi Kumar   9 years AGO

9*3*1,9*3*2,9*3*3,9*3*5,9*3*7, so next no is 9*3*11 as 9*3 is constant the other multiplied no are prime numbers

Like? Yes (1) | No   

ishan chourishi   9 years AGO

the series consists of the number we get by multiplying 27 * prime numbers.
27*1=27
27*2=54
27*3=81
27*5=135
27*7=189
next prime number is 11, so
27*11=297
hence 297 is answer.

Like? Yes (1) | No   

bharath   9 years AGO

27+27=54
54+27=81
81+54=135
135+54=189
189+108=297

Like? Yes (1) | No   

ayushi dhanak   9 years AGO

Because 27 are divided by prime numbers 2*27=54,3*27=81,5*27=135,7*27=189,then next prime no is 11 therefore 11*27=297

Like? Yes (1) | No   

Mayank Kumar   9 years AGO

57-27=27
81-54=27
135-81=54
189-135=54
(since, 27x2=54; and 54x2=108)
thus,
189+108=297

Like? Yes (1) | No   

yadlapati venkat   9 years AGO

prime numbers sequence 1,2,3,5,7,11,13,17,....

Like? Yes (1) | No   

LAVANYA P   9 years AGO

Multiply 27 with the prime numbers such as 2,3,5,7,11......
so the next answer will be 27*11=297

Like? Yes (1) | No