Find the income derived from 44 shares of Rs.25 each at 5 premium (brokerage 1/4 per share), the rate of dividend being 5%. Mainly find the rate of interest on the investment.
Cost of 1 share = Rs.(25 + 5 + 3/4)
= Rs. 171/4
Cost of 44 shares = Rs. (121/4 *44) = Rs. 1331
Therefore investment made = Rs. 1331
Now face value of 1 share = Rs. 25
Face value of 44 shares = Rs. 44*25 = Rs. 1100
Now, dividend on Rs. 100 = 11/2
Dividend on Rs. 1100 = Rs.(11/2*100 * 1100) = Rs. 60.50
Also income on investment of Rs. 1331 = Rs. 60.50
Income on investment of Rs. 100 = Rs. 60.50/1331 * 100
= 4.55 %
Option 2)
Let S be the sample space and E be the event of drawing 2 white balls.
Then, n(S) = Number of ways of drawing 2 balls out of 13
= 13 C 2 = 13*12/2 = 78
n(E) Number of ways of drawing 2 balls out of 5
5 C 2 = 5*4/2 = 10
Therefore
P(E) = n(E)/n(S) = 10/78 = 5/39
Option 7)
A man lends Rs.10000 in four parts. If he gets 8% on Rs.2000, 7.5% on Rs.4000 and 8.5% part on Rs.1400, what percent must he get for the remainder, if the average interest is 8.13%
Let required rate be x%
Then
2000*8*1/100 + 4000*15*1/2*100 + 1400*17*1/2*100 + 2600*x*1/100
= 10000*8.13*1/100
or 160+300+119+26x = 813
x = 9
Option 3)
Face value of the bill = Rs.5656
Date on which the bill was drawn = July, 14th at 5 months
Nominally due date = December, 14th
Legally due date = December, 17th
Date on which the bill was discounted October, 5th
Period for which the bill has yet to run
Oct, Nov, Dec.
26+30+17 days or 1/5 years
Note----------------
BD (Banker Discount) = SI on Rs.5656 for 1/5 years at 5%
= Rs.(5656*1*5 / 100*5) = Rs.56.56
TD(True Discount) = Rs.(5656*5*(1/5) / 100+(5*1/5) = Rs.56
BG(Banker Gain) = BD - TD = 56 Paise
-----------------
Money received by the holder of the bill
Rs.(5656-56.56) = Rs.5599.44
Option 6)
Shweta and Sandhya solved a quadratic equation. In solving it, Shweta made a mistake in the constant term and got the roots as 6 and 2, while Sandhya made a mistake in the coefficient of x only and obtained the roots as -7 and -1. The correct root of the equation are.
When there is no mistake in a and b, the sum of roots must be correct. When there is no mistake in a and c, product of the roots must be correct.
Therefore sum of roots = 6+2 = 8 and product of roots -7*-1 = 7
So the correct equation is x^2-8x+7
(x-7) (x-1)
The roots are 7, 1
A cylindrical pencil of 2 cm diameter is sharpened so as to produce a perfect hemispherical portion at one end and a perfect conical portion of length 2 cm at the other end. Find the volume of shavings.
For each portion
Volume of shavings = Volume of original cylindrical portion - Volume of final portion (Conical and Hemispherical)
and r = 1 cm
Volume of hemispherical portion = 2/3 Pi 1^3 = 2*Pi/3
Volume of conical portion = 1/3*Pi*1^2*2 = 2*Pi / 3
Total volume of cylindrical portion of both ends =
Pi(1)^2*1 + Pi(1)^2*2 = 3 Pi
Volume of shavings = Total volume of cylindrical portion - Volume of conical portion - Volume of hemispherical portion
3 Pi - 2Pi/2 - 2Pi/3 = 3Pi - 4Pi/3 = 5Pi/3
Using Pi = 22/7
5*22 / 21
5.238 cm^3
Option 9)
A man wishes to invest Rs.2490. He invests Rs.900 in 7/2% stock at 75, Rs.850 in 3% at 68 and the remainder in 6% stock. If the total yield from his investment is 5%, at what price does he buy the 6% stock?
Income from 7/2% stock at 75 = Rs. 7/2*75 * 900 = Rs.42
Income from 3% stock at 68 = Rs. 3/68 * 850 = Rs. 37.50
Total income from these two stocks = Rs 79.50
But total income from the three stocks Rs. 5/100 * 2490 = Rs.124.50
Therefore Income from the third stock Rs. (124.50 - 79.50) = Rs.45
Investment in this case = Rs.2490 - (900+850) = Rs.740
If income is Rs.45, investment = Rs.740
If income is Rs.6, investment = Rs. 740/45 * 6 = 296/3
So he buys 6% stock at 296/3
Option 9)
Students attend our lectures, not because the mathematics we teach ‘makes lots of fun’ for us, but because they believe they can learn some essential knowledge from us. And each of our young students has only one life to live. We should therefore be a