Find the income derived from 44 shares of Rs.25 each at 5 premium (brokerage 1/4 per share), the rate of dividend being 5%. Mainly find the rate of interest on the investment.
Cost of 1 share = Rs.(25 + 5 + 3/4)
= Rs. 171/4
Cost of 44 shares = Rs. (121/4 *44) = Rs. 1331
Therefore investment made = Rs. 1331
Now face value of 1 share = Rs. 25
Face value of 44 shares = Rs. 44*25 = Rs. 1100
Now, dividend on Rs. 100 = 11/2
Dividend on Rs. 1100 = Rs.(11/2*100 * 1100) = Rs. 60.50
Also income on investment of Rs. 1331 = Rs. 60.50
Income on investment of Rs. 100 = Rs. 60.50/1331 * 100
= 4.55 %
Option 2)
Let S be the sample space and E be the event of drawing 2 white balls.
Then, n(S) = Number of ways of drawing 2 balls out of 13
= 13 C 2 = 13*12/2 = 78
n(E) Number of ways of drawing 2 balls out of 5
5 C 2 = 5*4/2 = 10
Therefore
P(E) = n(E)/n(S) = 10/78 = 5/39
Option 7)
A man lends Rs.10000 in four parts. If he gets 8% on Rs.2000, 7.5% on Rs.4000 and 8.5% part on Rs.1400, what percent must he get for the remainder, if the average interest is 8.13%
Let required rate be x%
Then
2000*8*1/100 + 4000*15*1/2*100 + 1400*17*1/2*100 + 2600*x*1/100
= 10000*8.13*1/100
or 160+300+119+26x = 813
x = 9
Option 3)
Face value of the bill = Rs.5656
Date on which the bill was drawn = July, 14th at 5 months
Nominally due date = December, 14th
Legally due date = December, 17th
Date on which the bill was discounted October, 5th
Period for which the bill has yet to run
Oct, Nov, Dec.
26+30+17 days or 1/5 years
Note----------------
BD (Banker Discount) = SI on Rs.5656 for 1/5 years at 5%
= Rs.(5656*1*5 / 100*5) = Rs.56.56
TD(True Discount) = Rs.(5656*5*(1/5) / 100+(5*1/5) = Rs.56
BG(Banker Gain) = BD - TD = 56 Paise
-----------------
Money received by the holder of the bill
Rs.(5656-56.56) = Rs.5599.44
Option 6)
Shweta and Sandhya solved a quadratic equation. In solving it, Shweta made a mistake in the constant term and got the roots as 6 and 2, while Sandhya made a mistake in the coefficient of x only and obtained the roots as -7 and -1. The correct root of the equation are.
When there is no mistake in a and b, the sum of roots must be correct. When there is no mistake in a and c, product of the roots must be correct.
Therefore sum of roots = 6+2 = 8 and product of roots -7*-1 = 7
So the correct equation is x^2-8x+7
(x-7) (x-1)
The roots are 7, 1
A cylindrical pencil of 2 cm diameter is sharpened so as to produce a perfect hemispherical portion at one end and a perfect conical portion of length 2 cm at the other end. Find the volume of shavings.
For each portion
Volume of shavings = Volume of original cylindrical portion - Volume of final portion (Conical and Hemispherical)
and r = 1 cm
Volume of hemispherical portion = 2/3 Pi 1^3 = 2*Pi/3
Volume of conical portion = 1/3*Pi*1^2*2 = 2*Pi / 3
Total volume of cylindrical portion of both ends =
Pi(1)^2*1 + Pi(1)^2*2 = 3 Pi
Volume of shavings = Total volume of cylindrical portion - Volume of conical portion - Volume of hemispherical portion
3 Pi - 2Pi/2 - 2Pi/3 = 3Pi - 4Pi/3 = 5Pi/3
Using Pi = 22/7
5*22 / 21
5.238 cm^3
Option 9)
A man wishes to invest Rs.2490. He invests Rs.900 in 7/2% stock at 75, Rs.850 in 3% at 68 and the remainder in 6% stock. If the total yield from his investment is 5%, at what price does he buy the 6% stock?
Income from 7/2% stock at 75 = Rs. 7/2*75 * 900 = Rs.42
Income from 3% stock at 68 = Rs. 3/68 * 850 = Rs. 37.50
Total income from these two stocks = Rs 79.50
But total income from the three stocks Rs. 5/100 * 2490 = Rs.124.50
Therefore Income from the third stock Rs. (124.50 - 79.50) = Rs.45
Investment in this case = Rs.2490 - (900+850) = Rs.740
If income is Rs.45, investment = Rs.740
If income is Rs.6, investment = Rs. 740/45 * 6 = 296/3
So he buys 6% stock at 296/3
Option 9)