M4maths Previous Puzzles

22 Oct 2014 Time and Work

A can do a piece of work in 12 days. B is 60 % more efficient to do the same work. If both of them work together then the number of days required to do the same work is

OPtion

1) 5/2
2) 24/5
3) 11/3
4) 9/2
5) 7/2
6) 60/13
7) 4
8) 13/8
9) 2
10)3

Solution

60 % more efficient, therefore total number of days required by him to do the complete work can be
obtained by the formula
12 *1 = 1.6 * x
=> x = 12 / 1.6 = 7.5
When both of them work together, the work of 1 day is (1/12) + (1/7.5) = 13/60
Hence total number of days required are 60/13

Option 6)

Correct Option: 6 Best Solution (48)

Ashish Kumar   10 years AGO

work done by A in 1 day = 1/12
B being 60% efficient
work done by B in 1 day = 1/12+(60%of 1/12) = 1/12+1/20 = 2/15
work done by A and B in 1 day = 1/12+2/15 =13/60
time taken to complete the work = 60/13 days

Like? Yes (11) | No (4)  

Kushagra Tiwari   10 years AGO

Ratio of times taken by A and B = 160 : 100 = 8 : 5.

Suppose B alone takes x days to do the job.

Then, 8 : 5 :: 12 : x = 8x = 5 x 12 => x => 15/2 or 7 1/2 days.

so they together finish the work in 1/12 + 1/(15/2)
that is 1/12 + 2/15
=10+16/120 => 26/120
=13/60


so ans is a+b = 60/13

which is in option no 6

Like? Yes (17) | No (10)  

NAVEEN KUMAR   10 years AGO

Ratio of time taken by A&B=160:100 =8:5
Suppose B alone takes x days to do the job.
Then, 8:5::12:x
=> 8x=5*12
=> x=15/2 days.
If both of them work together
by fraction method,
(1/12)+(2/15)=13/60
hence,
If both of them work together then the number of days required to do the same work is 60/13 days
option(6)

Like? Yes (15) | No (9)  

ananya das   10 years AGO

1 day's work for A=1/12
1 day's work for B=(1/12)*(6/10)=1/20
1 day's work of A and B=(1/6)+(1/20)=13/60
then they will complete the work in 60/13 days

Like? Yes (6) | No   

Rashmi bharti   10 years AGO

B's work in one day=2/15
so days required to do the work by both of them =1/(1/12 + 2/15)=60/13.

Like? Yes (5) | No (1)  

Anand   10 years AGO

time taken ratio = 160: 100
=8:5
8:5::12 :x ( let no of day taken by B complete)
so x= 15/2
to complete work by A and B by = 1/12 + 2/15
= 13/60
so they complete work in 60/13 days

Like? Yes (4) | No   

aman   10 years AGO

Let A efficiency be 1 , Then B efficiency is 1.6
A do in 12 days so B do it in 12/1.6 = 7.5days
Than A do in 12 days
B do in 7.5 days
Together they do in 60/13 days

Like? Yes (3) | No   

Abhishek Vishwakarma   10 years AGO

Ratio of times taken by A and B = 160 : 100 = 8 : 5.

Suppose B alone takes x days to do the job.

Then, 8 : 5 :: 12 : x = 8x = 5 x 12 => x => 15/2 or 7 1/2 days.

so they together finish the work in 1/12 + 1/(15/2)
that is 1/12 + 2/15
=10+16/120 => 26/120
=13/60


so ans is a+b = 60/13

Like? Yes (3) | No   

abhinav singh   10 years AGO

Answer: Option 6

Explanation:

Ratio of times taken by A and B = 160 : 100 = 8 : 5.

Suppose B takes x days to do the work.

Then, 8 : 5 :: 12 : x => x = (12*5)/8 => x =15/2.

A's 1 day's work = 1/12 ;

B's 1 day's work = 2/15;

(A + B)'s 1 day's work = (1/12+2/15)=13/60.
Therefore, A and B together can complete the work in 60/13 days.

Like? Yes (4) | No (1)  

ROHIT KUMAR   10 years AGO

A's 1 day work = 1/12
since B is 60% eff. than B it is written as 160% or 160/100 of A hence

B's 1 day work = (1/12)*(16/10) = 2/15
(A+B) 's one day work = 1/12+2/15 = 13/60, hence

no. of daYS required to finish the work is 60/13 ans

Like? Yes (4) | No (1)  

santosh kumar patel   10 years AGO

ratio of time taken by A and B = 160:100=8:5
suppose B alone takes X days to do a job
then 8:5 :: 12:X
8X=5*12= 15/2
both together do the job= 1/12+2/15
39/180=13/60
so taken time=60/13
ans: 60/13

Like? Yes (3) | No   

Shreya Tiwari   10 years AGO

Ratio of times taken by A and B = 160 : 100 = 8 : 5.

Suppose B alone takes x days to do the job.

Then, 8 : 5 :: 12 : x = 8x = 5 x 12 => x => 15/2 or 7 1/2 days.

so they together finish the work in 1/12 + 1/(15/2)
that is 1/12 + 2/15
=10+16/120 => 26/120
=13/60


so ans is a+b = 60/13

Like? Yes (2) | No   

manodhar   10 years AGO

Ratio of times taken by A and B = 160 : 100 = 8:5.

Suppose B takes x days to do the work.

8 : 5 :: 12 : x x = 15/2

x = 15/2 days.

Hence, B takes 15/2 days to complete the work.
Together they complete the work in d days:
1/12 + 2/15 =1/d
13/60 = 1/d
d = 60/13

Like? Yes (3) | No (1)  

Rashi Bansal   10 years AGO

A's Efficiency = 1/12
B's efficiency = 1/12 + 60% of 1/12
= 2/15
efficiency if hey work together= 1/12 + 2/15
= 13/60
time required = 60/13 which is option (6)

Like? Yes (2) | No   

Sundar Kumar   10 years AGO

Ratio of time taken by A & B = 160:100 = 8:5
Suppose B alone takes x days to do the job.
Then, 8:5::12:x =
> 8x = 5*12 = > x
= 15/2 days.
A+B=((1/12)+(2/15))=13/60
Therefore , If both of them work together then the number of days required to do the same work is = 60/13
Answer: Option: 6) 60/13

Like? Yes (2) | No   

ranjithreddy   10 years AGO

wild guess

Like? Yes (2) | No   

nishu kumar   10 years AGO

A DO THE WORK 8 DAYS,THEN B DO IT IN 5 DAYS,
THEN IF A DO IT IN 12 DAYS,B DO IT IN 15/2 DAYS
IF BOTH OF THEM WORK TOGETHER THEN NO.OF DAYS REQUIRED TO FINISH THE WORK =1/12+2/15=60/13 DAYS

Like? Yes (2) | No   

Swagatam Kumar Das   10 years AGO

A:B=160:100
=8:5
So, 8:5 :: 12: x
x=15/2
A can do in 1 day 1/12
B can do in 1 day 2/15
So A+B do the job 1/(1/12+2/15) in days
=60/13 days.

Like? Yes (2) | No   

shekhar suman   10 years AGO

Rate of A,Ra=1/12
Rate of B,Rb=1/12+1/12*60/100=2/15
Rate of A+B,Ra+Rb=1/12+2/15=13/60
So, Total no days required=60/13

Like? Yes (2) | No   

shreyansh jain   10 years AGO

Like? Yes (1) | No   

Devendra Marghade   10 years AGO

(A+B)'s 1 day work=(1/12)+[(160/100)(1/12)]
=(1/12)+(2/15)=13/60
So number of days required to complete the same work=60/13

Like? Yes (1) | No   

Biswajit Saha   10 years AGO

Ratio of time taken by A & B= 160:100 = 8:5
Let B takes x days to do the work.
then, 8:5::12:x
x=15/2
Hence A's 1 day work=1/12; B's 1 day work=2/15
(A+B)'s 1 day work=(1/12 + 2/15) = 13/60
Hence A & B together can complete the job in 60/13 days.

Like? Yes (3) | No (2)  

vibhor   10 years AGO

Ratio of times taken by B and A = 160 : 100 = 8 : 5.

Suppose B takes x days to do the work.

8: 5 :: 12 : x
x = (5 x 12)/8
x = 7/2 days.

B will take 7.5 days to complete same work

now,work done by A in one day= 100/12, => 8.33%

work done bt B in one day= 100/7.5,=> 13.33%

work done by A and B in one day= 8.33% + 13.33% => 21.66 %

so total nubmer days required to finish the work= 100/21.66 ,=> 4.61

4.61= 60/13

Ans= 60/13

Like? Yes (3) | No (3)  

rosemary   10 years AGO

A can do work in 12
b is 60% more than A
if A is 100
B is 160
100:160=5:8
to find the time taken by B

5:8:12=12*5/8=60/8=8/60=2/15
total days=1/12+2/15=13/60=60/13.

Like? Yes (2) | No (2)  

Ajinkya Kulkarni   10 years AGO

60/13

Like? Yes (1) | No (1)  

KAMMILI.BALA NAGA BHARGAVI   10 years AGO

A one days work= 1/12
B is 60% more efficient than A
B's one day work = 1/12+(0.6)*1/12=2/15
together can do in= 1/12+2/15=13/60
they complete work in 60/13

Like? Yes (1) | No (1)  

Divyank Dubey   10 years AGO

B is 60 % more efficient than A
so, A=(8/5)B
And, work done in one day by A=1/12
work done in one day by B=2/15
so,1/12+2/15=13/60
total no. of days to complete work=60/13

Like? Yes (2) | No (2)  

Bhanoj   10 years AGO

In a day A can complete 1/12 th part of work, B can complete 1.6/12 th part. Then A+B can do 2.6/12 th of work per day.
So they will take 12/2.6 days to complete. Which is 60/13.

Like? Yes (3) | No (3)  

Jagruti   10 years AGO

Ratio of times taken by A and B = 160 :100 = 8:5
suppose B alone takes x days to do the job.
then, 8:5 =:: 12:x
8x =5*12
x = 7 1/2 days
A and B together can do the work in 1/12 + 2/15 = 13/60
i.e., 60/13 days

Like? Yes (1) | No (2)  

surya   10 years AGO

A work rate = 1/12
B is 60% more efficient than A so B work rate = 1.6/12
total work rate =1/12+1.6/12=2.6/12
time taken for complete the work=12/2.6=60/13

Like? Yes (2) | No (3)  

Abhishek Porwal   10 years AGO

A alone takes 12 days , Now if we calculate the efficiency of B the it will be 12+60% of 12 =19.2
So B alone can do the work in 19.2-12=7.2
Therefore a does the work in 12 days and B does the same work in 7.2 days
So on applying the formula
(a*b)/(a+b) we get 7.6 that is approx 60/13
So the answer is 60/13.

Let me know if this is helpful ?

Like? Yes (1) | No (2)  

Jabez David   10 years AGO

Ratio of time, taken by A and B = 160 : 100 = 8 : 5

If A takes 8 days, B takes 5 days.

If A takes 12 days, B takes = [5/8×12]=15/2 days

Working Together: A+B= 1/12+2/15= 13/60

So, Number days when working together is 60/13 option 6

Like? Yes (1) | No (2)  

Gajula Devendra Babu   10 years AGO

Ratio of times taken by A and B= 160:100=8:5
A can do the same work in 12 days;
then, 8:5=12:x;
x=7+1/2 B can do the same work in 7 and 1/2 days.
Both A and B can do 1 days work=1/12 + 7+1/2=13/60
so, Both A and B can work in 60/13 days.

Like? Yes (1) | No (2)  

ravi prakash   10 years AGO

ratio of theire work=A/B
=160/100
=8/5
now through ration and proporation
8/5=12/x
x=15/2
so work down by B in single day=2/15
and BY A=1/12
NOw work down by both together=1/A +1/B
=13/60
so

=60/13 days to take complete the work

Like? Yes (1) | No (2)  

ANKITA Burbure   10 years AGO

Let A do 100 units work in 1 day.As B is 60% more efficient than A then B can do 160 units in 1 day.A takes 12 days to complete the total units = 12×100=1200. Now the work done by A and B is 100+160=260. Thus no. of days required to complete 1200 units is 1200/260=60/13

Like? Yes (2) | No (3)  

Rishiraj Sengupta   10 years AGO

let a's capacity be 100 then b's capacity is 160
therefore ratio is 160/100 i.e 8/5
now using proportion
8:5::12:x
8x=60
so, x=15/2
combined work 1/12+2/15=60/13

Like? Yes (1) | No (2)  

Sanchit Kapoor   10 years AGO

A's 1 day work = 1/12
Since B is 60% more efficient than A .
So B's 1 day work= 1/12+60% of 1/12 = 8/60
So A and B 's together 1 day work= 1/12+8/60=13/60
Thus number of days=60/13

Like? Yes (2) | No (3)  

SURYA    10 years AGO

since B is 60% more efficient
if A can do a work in 160 days then B can do in 100
then A can do a work in 12 days then B can do=(100/160)*12
=15/2
then the work done when both work togather
=1/(1/12+2/15)=60/13.

Like? Yes (2) | No (4)  

vaitesh mudaliar   10 years AGO

A can do 1/12 work in one day ,while B can do 1/12 + 60% of 1/12 in one day.
let both take x days to finish the work,
if both work together then (work done by A + work done by B ) x = 1
x= 60/13

Like? Yes (2) | No (4)  

Bhavna   10 years AGO

b can do work in 1 day= a's work +60% of a's work=16/120
both can do work in one day=1/12+16/120=26/120
both can do worh in=120/26 days=60/13

Like? Yes (1) | No (3)  

swarupa nuggu   10 years AGO

60/13

Like? Yes (1) | No (3)  

v pavan   10 years AGO

work done by a in 1day(Wa)=(1/12)
work done by b in 1 day(Wb)=(1.6/12)
workdone by both in 1 day= 2.6/12
tota days required= 12/2.6=60/13

Like? Yes (1) | No (3)  

BHASKAR MANDAL   10 years AGO

A one day work = 1/12
B is 60% more efficient than B
=> B one day work = (1/12 + 1/12 * 6/10)
total A+B = 1/12 (2 + 3/5) = 13/60
so the time taken to complete the work = 60/13
so the option is 6

Like? Yes (5) | No (7)  

shubham sethiya   10 years AGO

B can do work in 7.5 days
both can do work in 60/13 days

Like? Yes (1) | No (3)  

lakshmi nalluri   10 years AGO

B=1.6A WHERE A=1/12
B=2/15
A+B=2/15+1/12=13/60 SO,A+B compkete in 60/13 days

Like? Yes (1) | No (3)  

saisudha sarva   10 years AGO

300/65=60/13

Like? Yes (1) | No (3)  

gouthamdaneti   10 years AGO

A capacity =1/12
B capacity=1/12+(60% of 1/12 )
let X=A capacity + B capacity
no.of days = 1/X

Like? Yes (1) | No (3)  

RAKESH   10 years AGO

A = 12 , B = 15/2

1/12 + 2/15 = 13/60 => 60/13 days

Like? Yes (1) | No (4)  

21 Oct 2014 Discount

A man buys a watch for Rs. 195 in cash and sells it for Rs.220 at a credit of 1 year. If the rate of interest is 10%, the man:

OPtion

1) Gains Rs.15
2) Gains Rs.3
3) Gains Rs.5
4) Gains Rs.10
5) Loses Rs.15
6) Loses Rs.3
7) Loses Rs.5
8) Gains Rs.12
9) Loses Rs.10
10)None of these

Solution

P.W. of Rs. 220 due 1 year hence
= Rs. (100*220/ (100+10) = Rs.200
Therefore Gains Rs.5

Option 3)

Correct Option: 3 Best Solution (27)

Kushagra Tiwari   10 years AGO

P.W of Rs 220 due 1 year hence = {(100*220)/(100+10)}
that is = 200
Cp was 195
so 200-195 = 5

hence the man gain rs 5
which is in option 3

Like? Yes (16) | No   

BHASKAR MANDAL   10 years AGO

amount that he sells = 220 after 1year
if he sells now
220 = p+prt/100
= p(1+rt/100) = p(1+1/10) = 11p/10
p = 200
so the selling price now = 200
selling price - cost price = 200-195 = 5
so A will gain a credit of rs 5
option 3 is the correct answer

Like? Yes (7) | No   

RAKESH   10 years AGO

220*100/(100+10*1) - 195 = rs 5 gain

Like? Yes (3) | No   

prem kumar   10 years AGO

c.p =195
here sp= rs.x
after 1 year it become 220
so we dont know sp
rate of interest=10%
x+10%x=220
x+0.1x=220
x=200
so gain=200-195=rs.5

Like? Yes (4) | No (1)  

v pavan   10 years AGO

total amount he get after 1 year(A)= 220
Let P be the price at which he sold before 1 year
A=P+(P*R*T)/100
Given T=1 year, R=10%
Solving we get P= 200
gain =Rs.5

Like? Yes (2) | No   

Ravi Kumar   10 years AGO

sp=(220*100)/(100+10)
=200
sp>cp =>gain
gain=sp-cp = 200-195=5
ans) gains rs. 5

Like? Yes (2) | No   

Sanchit Kapoor   10 years AGO

S.P. = P.W. of Rs. 220 due 1 year hence
= Rs. (220 x 100)/
(100 + (10 x 1))
= Rs. 200
Gain = Rs. (200 - 195) = Rs. 5.

Like? Yes (3) | No (1)  

Shreya Tiwari   10 years AGO

P.W of Rs 220 due 1 year hence = {(100*220)/(100+10)}
that is = 200
Cp was 195
so 200-195 = 5

hence the man gain rs 5

Like? Yes (1) | No   

Abhishek Vishwakarma   10 years AGO

P.W of Rs 220 due 1 year hence = {(100*220)/(100+10)}
that is = 200
Cp was 195
so 200-195 = 5

hence the man gain rs 5

Like? Yes (1) | No   

ragini   10 years AGO

(220*100)/(100+(10*1)) =200

gain=200-195=5

Like? Yes (1) | No   

Sukanya   10 years AGO

S.P. = P.W. of Rs. 220 due 1 year hence
= 220 x 100/100 + (10 x 1)
= Rs. 200.
Gain = Rs. (200 - 195) = Rs. 5.

Like? Yes (1) | No   

D SATHIBABU   10 years AGO

S.P. = P.W. of Rs. 220 due 1 year hence
= Rs. [220 x 100 ]/(100 + (10 x 1))
= Rs. 200.
Gain = Rs. (200 - 195) = Rs. 5.
P.W. - Present Worth
S.P - Selling Price

Like? Yes (1) | No   

vaitesh mudaliar   10 years AGO

since the present value of outflow is Rs.195 as on 0 date but the inflow after 1 year will be Rs.220 so the present value of inflow is Rs 200. i.e [1/(1+10%)*220] therefore the gain will be Rs 5

Like? Yes (1) | No   

aman   10 years AGO

@10% so we sell @200₹ at start
So C.P = 195 , S.P = 200
200-195 = 5₹ gain

Like? Yes (1) | No   

Jabez David   10 years AGO

S.P. = P.W. {Present Worth} of Rs. 220 due 1 year hence
= {(220*100)/[100+ (10*1)]}
= Rs 200
Gain= (S.P.) - (C.P.)
= 200-195
= 5
Option 3: Gains Rs.5

Like? Yes (1) | No   

rosemary   10 years AGO

S.P. = P.W. of Rs. 220 due 1 year hence
= Rs. 220 x 100 /100 + (10 x 1)

= Rs. 200.


Gain = Rs. (200 - 195) = Rs. 5.

Like? Yes (1) | No   

Anand   10 years AGO

If he sells it for Rs220 at a credit of 1yr then the
present worth of that amount is
Presentworth = (Amount*100) /(100+(R*T))
=(220*100)/(100+10*1)
=200-
So he gains 200-195=Rs.5

Like? Yes (1) | No   

sanchit soni   10 years AGO

c.p.=195 rs
s.p. =220 rs..
now at credit of 10% rate for 1 yr,it means
interest = p*r*t/100=195*10*1/100=19.5 rs
total c.p. =195+19.5=214.5 rs
so, gain =220-214.5=5.5 rs

Like? Yes (1) | No   

Shivom Sharma   10 years AGO

i am sure

Like? Yes (1) | No   

Kumar Gaurav   10 years AGO

rate of interest is 10%, means presently he's getting 200, that's become 220 after a year.
means profit=5.

Like? Yes (1) | No   

Swagatam Kumar Das   10 years AGO

pw of Rs. 220 is 220/(1+.1) =200.
CP is 195
now SP is 200.
So gains (200-195)=5

Like? Yes (1) | No   

shekhar suman   10 years AGO

gain=220-(195+195*10/100)=5.5

Like? Yes (1) | No   

yaman kumar gunturi   10 years AGO

Gains 5

Like? Yes (1) | No   

ravi prakash   10 years AGO

25-19.5=5.5

Like? Yes (1) | No   

PRAVIN PRAJAPATI   10 years AGO

195*10%=19.5
195+19.5=214.5
then gain of 5.5 rupees

Like? Yes (1) | No   

T.Aravinth kumar   10 years AGO

200-195=5

Like? Yes (2) | No (2)  

Gaurav Sharan   10 years AGO

present value = 220*(10/11)

Like? Yes (1) | No (1)  

20 Oct 2014 Sequence

What is the next number of the following sequence
142, 251, 381, 463, .....?

OPtion

1) 527
2) 558
3) 421
4) 466
5) 574
6) 585
7) 454
8) 572
9) 432
10)None of these

Solution

Add the digit and its multiplication
142 = 1*4*2+(1+4+2) = 15 reverse is 51
first digit in increase by 1 251
251 = 2*5*1+(2+5+1) = 18 reverse the number 81
first digit in increase by 1 381
381 = 3*8*1+(3+8+1) = 36 reverse is 63
first digit in increase by 1 463
463 = 4*6*3+(4+6+3) = 85 reverse is 58
first digit in increase by 1 558
558

Option: 2

Correct Option: 2 Best Solution (1)

santosh kumar patel   10 years AGO

1*4*2+(1+4+2)=15 reverse=51
first digit increased by 1 so 1+1=2
similarly,
4*6*3+(4+6+3)=85 reverse = 58
first digit increased by 1=4+1=5
hence 558

Like? Yes (21) | No (5)  

17 Oct 2014 Stock and Shares

Find the cash required to purchase Rs. 1600, 17/2 % stock at 105. (Brokerage 1/2%)

OPtion

1) Rs. 1698
2) Rs. 1978
3) Rs. 1588
4) Rs. 1658
5) Rs. 1768
6) Rs. 1762
7) Rs. 1800
8) Rs. 1688
9) Rs. 1600
10)None of these

Solution

Cash required for purchasing Rs.100 stock
= Rs. (105 + 1/2) = Rs. (211/2)
Cash required for purchasing Rs. 1600 stock
= Rs. (211*1600 / 2*100) = Rs. 1688

Option 8)

Correct Option: 8 Best Solution (28)

Kushagra Tiwari   10 years AGO

For Rs. 100 it will be (105 + 1/2)
i.e Rs. 211/2
then for Rs. 1600 it will be
(211*1600)/(2*100) = Rs. 1688

Like? Yes (7) | No   

BHASKAR MANDAL   10 years AGO

for purchasing 100 stock we need = 105+1/2 = 211/2
purchase of 1600 = (1600*211)/(2*100) = 1688
option 8 is the correct answer

Like? Yes (10) | No (6)  

santosh kumar patel   10 years AGO

cash required to purchase rs. 100 stock= 105+1/2=211/2
cash required to purchase rs. 1600 stock= (211/2)*(1/100)*1600 = 1688

Like? Yes (3) | No (2)  

khushboo goenka   10 years AGO

cash req to purchase 100 rs stock=105+1/2
so for 1600 rs required=1600*1/100*211/2

Like? Yes (1) | No   

CHANDAN KUMAR   10 years AGO

cash required=211*1*1600/200=1688

Like? Yes (1) | No   

Chirag Ranjan Lahiri   10 years AGO

For Rs. 100 it will be (105 + 1/2)
i.e Rs. 211/2
then for Rs. 1600 it will be (211*1600)/(2*100) = Rs. 1688 (answer)

Like? Yes (2) | No (1)  

Shreya Tiwari   10 years AGO

For Rs. 100 it will be (105 + 1/2)
i.e Rs. 211/2
then for Rs. 1600 it will be
(211*1600)/(2*100) = Rs. 1688

Like? Yes (1) | No   

Abhishek Vishwakarma   10 years AGO

For Rs. 100 it will be (105 + 1/2)
i.e Rs. 211/2
then for Rs. 1600 it will be
(211*1600)/(2*100) = Rs. 1688

Like? Yes (1) | No   

NAGENDRA P   10 years AGO

For Rs. 100 it will be (105 + 1/2)
i.e Rs. 211/2
then for Rs. 1600 it will be (211*1600)/(2*100) = Rs. 1688 (answer)

Like? Yes (1) | No   

Chandra chur anand   10 years AGO

105+1/2=211/2
so, cash=211*1600/2*100
=1688 rs ans...

Like? Yes (1) | No   

Sagar Kumar Subudhi   10 years AGO

cash required to purchase rs 100 stock=105+0.5=105.5
cash required to purchase rs 1600 stock=(105.5*1600)/100=1688

Like? Yes (1) | No (1)  

Anand   10 years AGO

cash required to purchase 100 stock =105+1/2
=211/2
cash required to purchase 100 stock=211/2 *1/100*1600
=1688

Like? Yes (1) | No (1)  

Sanchit Kapoor   10 years AGO

Cash required to purchase Rs 100 stock=Rs 107+1/2= Rs 211/2
So cash required to purchase Rs 1600 stock= Rs [211/2*1/100*1600]=Rs 1688
So option 8 is correct

Like? Yes (2) | No (2)  

MRITUNJAY   10 years AGO

cash required to purchase rs 100 stock=(105+1/2)=211/2
cash required to purchase rs 1600 stock =(211/2*1/100*1600)=1688

Like? Yes (1) | No (1)  

Ashish Kumar   10 years AGO

cash req. to purchase rs.100 stock=rs.(105+1/2)
cash req. to purchase rs 1600 stock = 211/2*1/100*1600=rs 1688

Like? Yes (1) | No (1)  

Akshay   10 years AGO

cost of purchase=amount of stock*(m.v.+brokerage/100)
=1600*(105+0.5)/100=1688

Like? Yes (2) | No (2)  

v pavan   10 years AGO

market value of rs.100 stock =rs.105
market value of 1600 stock= rs.1680
brokerage=1/2% of 1600= rs.8
cost to purchase =1680+8
Rs.1688

Like? Yes (2) | No (2)  

vartika    10 years AGO

cash reqd to purchase rs. 100 stock= (105+1/2)= rs 211/2
cash reqd to purchase rs.1600 stock= (211/2*1/100*1600)
= rs1688

Like? Yes (2) | No (2)  

lakshmi nalluri   10 years AGO

cash for 100 stock=105+1/2=211/2
cash for 1600 stock=211/2*1/100*1600=1688

Like? Yes (2) | No (2)  

AbhinayRapolu   10 years AGO

cash required to purchase Rs.100 stock=(105+1/2)=211/2
cash required to purchase Rs.3200 stock=(211/2*1/100*1600)=1688

Like? Yes (1) | No (1)  

DIPAK TIWARI   10 years AGO

Cash required to purchase ₹100 stock=₹(105 + 1/2)=₹211/2
Cash required to purchase
₹1600 stocks=₹(211/2)*(1/100)*1600=>₹1688
Option 8

Like? Yes (2) | No (2)  

Jeenesh Suryavanshi   10 years AGO

Cash Required to purchase Rs. 100 stock = Rs.(105+1/2)=Rs.211/2.
Cash Required to purchase Rs. 1600 stock = Rs.(211/2*1/100*1600)=Rs.1688.

Like? Yes (1) | No (1)  

Satyaki Bhattacharjee   10 years AGO

Cash reqd to purchase R 100 stock = (105+1/2) = 211/2
Cash reqd to purchase R 1600 stock =211/2*1/100*1600)
=R 1688

Like? Yes (1) | No (1)  

Gitanjali K   10 years AGO

(211/2)*(1/100)*1600=1688 Rs.

Like? Yes (1) | No (1)  

Daivashala   10 years AGO

cash required to purchase Rs 100 stock=105+1/2=211/2
Cash required to purchase Rs Rs 1600 stock=(211/2*1/100*1600)=1688

Like? Yes (1) | No (1)  

shekhar suman   10 years AGO

face vakue of stock=1600
its market value=1600*105/100=1680
brokerage charge=1/200*1600=8
net market value=1680+8=1688

Like? Yes (1) | No (1)  

vivek prakash   10 years AGO

cost required to purchase rs 100 stock=rs(105+1/2)
cost required to purchase rs 1600 stock=((211/2)1600)/100

Like? Yes (1) | No (1)  

TINKU MITTAL   10 years AGO

To purchase Rs.100 stock, we need 105+1/2 =211/2
Purchase of Rs.1600 stock,we need = (211/2)*(1600/100)
= 1688 rs

Like? Yes (1) | No (1)  

16 Oct 2014 Average

The average speed of a cyclist who covers first, second and third km at 20, 16 and 12 km/hr respectively (in km/hr) is

OPtion

1) 16.24
2) 18.14
3) 16.22
4) 17.24
5) 15.66
6) 18.44
7) 15.32
8) 16.56
9) 16.88
10)None of these

Solution

Total distance covered = 3 km
Total time taken = (1/20 + 1/16 + 1/12) = 47/240
Therefore Average speed = 3/(47/240) km/hr
=15.32 km/hr

Option 7)

Correct Option: 7 Best Solution (107)

Kushagra Tiwari   10 years AGO

Since we know that Avarage Speed = Total diatance/Total time taken

Here total distace is 3km

SO putting in formula we get = 3/(1/20 + 1/16 + 1/12)

on solving = (3*20*16*12)/(192+240+230)

that is 15.32 km

Which is in option no 7

Like? Yes (18) | No (5)  

Sourojit Dhua   10 years AGO

Avg. speed= Total distance covered/ Total time taken
So,
S= 3/(1/20+1/16+1/12)= 15.32 km/hr

Like? Yes (9) | No (4)  

aman   10 years AGO

1km with 20 speed so time taken = 1/20
another 1 km with 16 speed so time taken = 1/16
and last 1 kmwith 12 speed so time taken = 1/12
total time taken = 1/20 + 1/16 + 1/12 = 47/240
total distance = 3 km
total time = 47/240
so speed = distance/time = (3*240)/47 = 15.319
speed = 15.32 km/hr

Like? Yes (4) | No   

CHANDAN KUMAR   10 years AGO

avg speed=3/(1/20)+(1/16)+(1/12)=3/0.1958=15.32

Like? Yes (2) | No   

ashok   10 years AGO

3xyz/xy+yz+xz

Like? Yes (5) | No (3)  

s.veeresh kumar   10 years AGO

avg. speed=harmonic mean of given speeds

Like? Yes (2) | No   

ravi prakash   10 years AGO

total dist/total time
=720/47=15.32

Like? Yes (1) | No   

Aishwarya Chandra   10 years AGO

Let first distance be x
Second be y
N third be z
Den.,
Time taken by first km is = 1/20 hr
Time taken by second km is = 1/16 hr
Time taken by third km is = 1/ 12 hr
The avg speed= total distance / total time
Therefore,
Avg speed = 3/(1/20 + 1/16 +1/12)
= 15.32
Correct option is = 7

Like? Yes (2) | No (1)  

ADARSH GAURAV   10 years AGO

15.32 is the answer

Like? Yes (1) | No   

saket saurav sahu   10 years AGO

here d is same in all three round ,
so, avg speed =total dist./total time taken
total d= 1+1+1= 3
total t = ( 1/20 +1/16 +1/12) = 47/240
therefore,avg. speed = (3*240)/47 = 15.32

Like? Yes (1) | No   

Ajinkya Kulkarni   10 years AGO

As we know Average speed = Total Distance / Total Time

Total Distance = 3 KM
Total Time (Time is distance upon velocity ) = (1/20)+(1/16)+(1/12)=0.1958 hr

So Avg Speed = 3/0.1958=15.32Kmph

Like? Yes (1) | No   

Anurag Dwivedi   10 years AGO

3/((1/20)+(1/16)+(1/12))= 15.316

Like? Yes (2) | No (1)  

Sushil Singh   10 years AGO

let each distance= x km and avg. speed =y
then,
((12x)+(15x)+(20x))/240=x/y
by solving we get
y=15.32

Like? Yes (2) | No (1)  

ganesh babu   10 years AGO

avarge =3 (20x16x12)/(20x16)+(16x12)+(20x12)
=11520/752
=15.319
=15.32

Like? Yes (2) | No (1)  

Devendra Marghade   10 years AGO

Average Speed=Total Distance/(Total Time)
=[1+1+1]/[(1/20)+(1/16)+(1/12)]=720/47=15.32

Like? Yes (1) | No (1)  

Jabez David   10 years AGO

If a cyclist travels three equal distances at a Speed of

S1=20 km/hr
S2=16 km/hr
S3= 12 km/hr

then average speed is 3*S1*S2*S3/(S1S2+S2S3+S3S1)

Answer: 15.31915-> 15.32

Like? Yes (1) | No (1)  

AAKANCHA SRIVASTAV   10 years AGO

avg speed= 3*x*y*z/(x*y+y*z+z*x)
where x,y and z are 20,16 and 12 respectively
so,
3*20*16*12/752 =15.319 i.e 15.32(approx)

Like? Yes (1) | No (1)  

Sagar Kumar Subudhi   10 years AGO

3xyz/(xy+yz+zx)=15.32

Like? Yes (1) | No (1)  

Pradeep Kumar   10 years AGO

3(xyz) 3*20*16*12
-----------------= -------------------------------
xy+yz+xz 20*16+16*12+20*12

Like? Yes (1) | No (1)  

vinit   10 years AGO

3xyz/xy +yz+ xz

Like? Yes (1) | No (1)  

Chandra chur anand   10 years AGO

time to cover first km=1/20 hr
time to cover second km=1/16 hr
time to cover third km=1/12 hr
so avg time=total dist/total time=3/(1/20+1/16+1/12)
so avg time ll be 720/47=15.319~15.32 hr ans

Like? Yes (1) | No (1)  

kishore muddada   10 years AGO

total distance = 3 kms
first, second and third km at 20, 16 and 12 km/hr respectively (in km/hr)
avg velocity = total distance/total time and
time= distance/velocity
=3/[(1/20)+(1/16)+(1/12)]
=3/[47/240]
=720/47
=15.32

Like? Yes (1) | No (1)  

Pallavi Verma   10 years AGO

distance covered in 1 km @20 km/hr=1/20,similarily for other two time taken will be 1/16 and 1/12
total time taken=1/20+1/16+1/12=0.195833
total distance=1+1+1=3kms
avg speed=total distance/total time=3/0.195833=15.3191=15.32(upto 2 decimal places)

Like? Yes (1) | No (1)  

manish kumar sharma   10 years AGO

first we should have to calculate total time taken by him.
time taken in completion of first km = 1/20 hr
time taken in completion of second km = 1/16 hr
time taken in completion of third km = 1/12 hr

total time = 1/20+1/16+1/12
= 47/240 hr

average speed = total distance/ total time
= 3/(47/240)
= 15.32 km/hr

Like? Yes (1) | No (1)  

Rashi Bansal   10 years AGO

avg. speed = total distance / total time taken
total distance = 3 km
total time taken = 1/20 + 1/16 + 1/12

Like? Yes (1) | No (1)  

dhanaseelan   10 years AGO

Ans is 15.32

Like? Yes (1) | No (1)  

falguni singh   10 years AGO

average speed =(total distance travelled)/(total time taken)

=(d1+d2+d3)/((d1/s1)+(d2/s2)+(d3/s3))
=(1+1+1)/((1/20)+(1/16)+(1/12))
=15.32

Like? Yes (1) | No (1)  

Pallab Das   10 years AGO

avg speed=3.xy7/(xy+yz+xz)
x=20
y=16
z=12
Ans.-15.32

Like? Yes (1) | No (1)  

abhinav singh   10 years AGO

3xyz/xy +yz+ xz
3*20*16*12/(20*16+16*12+12*16)=15.32
ans=15.32
option 7

Like? Yes (1) | No (1)  

himanshu jaiswal   10 years AGO

avg speed = 3*(20*12*16)/(20*12+12*16+16*20)
=15.32 km/hr

Like? Yes (1) | No (1)  

Prarthana Veda Priya   10 years AGO

average speed=total distance covered/time taken
=3/(1/20+1/16+1/12)
=2520/752
15.32

Like? Yes (1) | No (1)  

shekhar suman   10 years AGO

avg speed=(1+1+1)/(1/20+1/16+1/12)=3*240/47=15.32

Like? Yes (1) | No (1)  

Biswajit Saha   10 years AGO

let the avg speed is x km/hr.
1/20 + 1/16 + 1/12 = 3/x [Since total distance is 3]
x=15.319 ~ 15.32

Like? Yes (1) | No (1)  

Pinaki Ghosh   10 years AGO

let the avg speed is x km/hr.
1/20 + 1/16 + 1/12 = 3/x [Since total distance is 3]
x=15.319 ~ 15.32

Like? Yes (1) | No (1)  

Aastha   10 years AGO

av.speed=3xyz/xy+yz+zx
=15.32km/hr

Like? Yes (2) | No (2)  

satyam sharma   10 years AGO

avg time taken to cover the distance of 3 km is
(1/20+1/16+1/12) hr=47/240 hr
avg speed=distance/avg time=3/(47/240)=(3*240)/47= 15.32 km/hr
so correct option is 7) 15.32

Like? Yes (1) | No (1)  

SOURABH   10 years AGO

time taken in covering first km=1/20 hr
for second km=1/16
for third=1/12
total time =1/20+1/16+1/12=47/240
avg speed=total dist/total time
=3/(47/240)=15.32 kmhr

Like? Yes (1) | No (1)  

MRITUNJAY   10 years AGO

Average speed=total distance travelled/total time taken

Like? Yes (1) | No (1)  

stuti priyambda   10 years AGO

time taken to cover distance=((1/12)+(1/16)+(1/20))=47/240
avg.speed=(3/(47/240))=15.32

Like? Yes (1) | No (1)  

Devesh Gupta   10 years AGO

time taken to cover first km = 1/20 hr
time taken to cover first km = 1/16 hr
time taken to cover first km = 1/12 hr

total distance covered = 3Km
total time taken=(1/20)+(1/16)+(1/12)

avg. speed=total distance covered/total time = 15.32

Like? Yes (1) | No (1)  

SOURAV MUKHERJEE   10 years AGO

avg speed=avg distance/avg time
avg distance=3/3=1
avg time=((1/20+1/16+1/12)/3)=47/(240*3)
avg speed=15.32

Like? Yes (1) | No (1)  

prem kumar   10 years AGO

3xyz/xy+ yz+ xz
15.32

Like? Yes (2) | No (2)  

Kashish Aneja   10 years AGO

1/20+1/16+1/12 will give the time
and dividing this time by total distance will give average speed
i.e 3/(47/240)=15.32

Like? Yes (1) | No (1)  

Arijit Acharyya   10 years AGO

3xyz/(xy+yz+zx)

(3*20*16*12)/((20*16)+(16*12)+(12*20))

=15.32

Like? Yes (1) | No (1)  

GAURAV KUMAR   10 years AGO

Average speed =total distance / total time
=(d1+d2+d3)/(d1/s1+d2/s2+d3/s3)
= (1+1+1) /(1/20+1/16+1/12)
=(3*240)/47
=15.3 (answer)

Like? Yes (1) | No (1)  

Sanchit Kapoor   10 years AGO

Total time=1/20+1/16+1/12 km/h
Total distance=3 km
So average speed =Total distance/Total time = 15.32 km/h
Thus option 7 is correct

Like? Yes (2) | No (2)  

raja babu   10 years AGO

Avg Speed= total distace travelled/total time taken
=> ______3_______
1/20+1/16+1/12
=> (3*20*16*12)/(16*12+ 12*20+20*16)
=>1152/192+240+320
=>11520/752
=>15.32

Like? Yes (1) | No (1)  

RABI KR. SHAW   10 years AGO

speed=distance/time
avg speed=(1+1+1)/(1/20+1/16+1/12)=15.32

Like? Yes (1) | No (1)  

Dharampal   10 years AGO

Total distance =3km
Total time taken =1/20+1/16+1/12
Avg speed=3/total time taken
=15.32

Like? Yes (1) | No (1)  

abhishek kumar   10 years AGO

total distance=3 km
total time= 47/240 hrs
so av speed= 3*240/47 = 15.319 km/hr

Like? Yes (1) | No (1)  

Ramesh Sriram   10 years AGO

total distance /total time

Like? Yes (1) | No (1)  

abhishek   10 years AGO

Average speed=total distance/total time

Like? Yes (1) | No (1)  

Chirag Ranjan Lahiri   10 years AGO

Let, x, y and z be 20, 16 and 12 respectively
So the average speed of x, y and z will be,
= 3*x*y*z/(x*y+y*z+z*x)
by, putting the values of x, y and z, the average speed becomes = 15.319 i.e = 15.32approx(answer)

Like? Yes (1) | No (1)  

SADINENI RAGHAVENDRA BABU   10 years AGO

total distance=3k.m
time taken for 1 k.m= 1/20
2 k.m=1/16
3 k.m= 1/12
total avg speed= 3/((1/20)+(1/16)+(1/12))
= 15.31914894 ~ 15.32

Like? Yes (1) | No (1)  

ANKITA Burbure   10 years AGO

The avg speed can be calculated as tot distance/tot time.Now the tot distance is 3km (1st 2nd and 3rd km).This will come in numerator.Now in denominator we represent time in the form of dist/speed.So in denominator we have (1/20 +1/16 +1/12) . On solving we get the ans as 15.319 i.e 15.32 (option 7)

Like? Yes (1) | No (1)  

Udit Pathak   10 years AGO

Avg speed= total dist./total time
Let dist be x.
Therefore avg speed= x/(x/3*20 + x/3*16 + x/3*12)
Solving x gets cancelled.
Takimg LCM in denominator we get
3/(47/240) = 15.31 hence answer.

Like? Yes (1) | No (1)  

PRIYA JAIN   10 years AGO

total distance=3km
total time=1/20+1/16+1/12=47/240hr
average speed=3/(47/240)=15.32km/hr

Like? Yes (1) | No (1)  

saket    10 years AGO

the answer would be 3/ ( 1/20 + 1/16 + 1/12) = 15.32km/hr

Like? Yes (2) | No (2)  

Simranjit Singh   10 years AGO

Avg Speed= Total Distance/total Time
=3*60/11.75
=15.32 km/hr

Like? Yes (1) | No (1)  

SIDDHARTH KUMAR   10 years AGO

3/(1/20 +1/16+1/12)=15.32

Like? Yes (1) | No (1)  

harini   10 years AGO

let X=20km/hr,Y=16km/hr,Z=12km/hr
average speed =3XYZ/XY+YZ+ZX
average speed =15.32

Like? Yes (1) | No (1)  

RANDHIR KUMAR   10 years AGO

total distance/total time taken

Like? Yes (1) | No (1)  

Jyoti kumari   10 years AGO

time taken in covering 1st km(t1)= 1/20
t2= 1/16
t3= 1/12
total time taken in covering 3 kms= (1/20)+(1/16)+(1/12)
=0.19583
average speed = 3/0.19583
=15.32

Like? Yes (1) | No (1)  

surya   10 years AGO

15.32

Like? Yes (1) | No (1)  

Abhishek birkh   10 years AGO

3xyz/(xy+yz+zx)=15.32
here x=20,y=16,z=12

Like? Yes (1) | No (1)  

Anupam Banerjee   10 years AGO

Average speed = 3/(1/20 + 1/16 + 1/12) = 15.32 km/hr

Like? Yes (1) | No (1)  

NIVEDA SIVAPRAKASAM   10 years AGO

formula : 3xyz/xy+yz+zx

Like? Yes (1) | No (1)  

vivek prakash   10 years AGO

(3x)/(x/20+x/16+x/12)=15.32

Like? Yes (1) | No (1)  

NAVEEN KUMAR   10 years AGO

avg. speed=3xyz/(xy+yz+xz)=3*20*16*12/(20*16+16*12+20*12)
=

Like? Yes (1) | No (1)  

Gauraw   10 years AGO

Total Distance Traveled = 3km
Total Time taken to cover 3km = (1/20)+(1/16)+(1/12) = 47/240 hrs
So Average speed = 3/(47/240) = 15.32 km/hrs

Like? Yes (1) | No (1)  

Bhupendra Rana   10 years AGO

TOTAL TIME=1/20+1/16+1/12
SPEED=DISTANCE/TIME
=3/TOTAL TIME
15.32

Like? Yes (1) | No (1)  

AMREEN   10 years AGO

time=distance/speed
for 1st km, speed=20km/hr
t1=1/20hr
for 2nd km
t2=1/16hr
for 3rd km,
t3=1/12hr
total time=t1+t2+t3
t=47/240hr
total distance=3km
avg speed=total distance/total time
avg speed=3*240/47
=15.32km/hr

Like? Yes (1) | No (1)  

Bhanoj   10 years AGO

time taken by the vehicle to complete each km is 3,3.75,5 min respectively.
Average velocity = (3/11.75)*60 = 15.32 kmph

Like? Yes (2) | No (2)  

RISHABH SHARMA   10 years AGO

avg speed=total distance/total time=3/(1/16+1/20+1/12)=15.32

Like? Yes (1) | No (1)  

santosh kumar patel   10 years AGO

3abc/(ab+bc+ca)

(3*20*16*12)/(20*16+16*12+12*20)=15.32

Like? Yes (1) | No (1)  

AMIT AGARWAL   10 years AGO

3xyz/xy +yz+ xz

Like? Yes (1) | No (1)  

Keerthanaa R S   10 years AGO

Total cyclist=3
Now average can be find by using,

3xyz/xy+yz+xz = 3(20)(16)(12) / ((20*16) + (16*12) + (12*20))

= 11520/752
=15.3191
Answer = 15.32(approx)

Like? Yes (1) | No (1)  

Shreya Tiwari   10 years AGO

Average Speed = Total distance/Total time taken

Here total distance is 3km

SO putting in formula we get = 3/(1/20 + 1/16 + 1/12)

on solving = (3*20*16*12)/(192+240+230)

that is 15.32 km

Like? Yes (2) | No (3)  

Abhishek Vishwakarma   10 years AGO

Average Speed = Total distance/Total time taken

Here total distance is 3km

SO putting in formula we get = 3/(1/20 + 1/16 + 1/12)
= (3*20*16*12)/(192+240+230)
15.32 km

Like? Yes (1) | No (2)  

RAKESH   10 years AGO

3*20*16*12 / (20*12+20*16 +16*12) = 15.32

Like? Yes (1) | No (2)  

Sneha   10 years AGO

Average speed=total distance covered/total time taken
=3/(1/20+1/16+1/12)
=15.32

Like? Yes (1) | No (2)  

DIPAK TIWARI   10 years AGO

(1+1+1)/(1/20 +1/16 +1/12)
=>15.319=15.32

Like? Yes (2) | No (3)  

ABHILESH PURI GOSWAMI   10 years AGO

avg speed = total distance / total time
= 3 /((1/20)+(1/16)+(1/12))
=15.32
option 7)

Like? Yes (1) | No (2)  

pawan kumar   10 years AGO

Time for 1st km= 3min
time for 2nd km= 15/4min
time for 3rd km= 5min

Avg speed= [3/(47/4)]*60 km/h
= 15.32 km/h

Like? Yes (1) | No (2)  

BHASKAR MANDAL   10 years AGO

If a person or thing travel three equal distances at a speed of x,y and z km/hr respectively then the average speed during the whole journey is 3xyz/(xy+yz+zx) km/hr

= 3*(20*16*12)/(20*16+16*12+20*12)
= 3*5.106
=15.32
so option 7 is the answer

Like? Yes (4) | No (5)  

harshit gupta   10 years AGO

from the equation we can solve where x is avg speed
x=(3/((1/20)+(1/12)+(1/16))
x=15.321 km/hr

Like? Yes (1) | No (2)  

gouthamdaneti   10 years AGO

1km in 20km/hr and 16 km/hr and 12km/hr
1 divide by each speed we get time for each km and 3/(totaltime)

Like? Yes (1) | No (2)  

Akshay   10 years AGO

time to travel 1st km=1/20=0.05 hr
time to travel 2nd km=1/16=0.0625
time to travel 3rd km=1/12=0.08333
average speed=total distance/total time=3/0.196=15.31
so,approx average value=15.32

Like? Yes (1) | No (2)  

Anand   10 years AGO

15.32 3xyz/xy+ yz+ xz

Like? Yes (2) | No (3)  

SANU PANJI   10 years AGO

If a person travels 3 equal distance at a speed of X, Y& Z km/hr resppectively, then the avg speed during whole journey is
3*X*Y*Z/(X*Y+Y*Z+Z*X)
=3*20*16*12/(20*16+20*12+12*16)
=15.32

Like? Yes (1) | No (2)  

pritika singh   10 years AGO

Total dist.= 3 km
Total time taken = 1/20 + 1//6 + 1//2 = 47/240
Average speed = 3×240/ 47 = 15.32

Like? Yes (2) | No (3)  

Gitanjali K   10 years AGO

3xyz/(xy+yz+xz)=15.32

Like? Yes (1) | No (2)  

vatan singh   10 years AGO

av. speed is total distance / total time
each distance is 1km find time taken
i.e. 1/20, 1/16, 1/12
total distance 3km
total time is 1/20+1/16+1/12
divide both got 15.319 i.e 15.32 approx

Like? Yes (1) | No (2)  

K Sudharshan reddy   10 years AGO

The time taken to cover 1st km is 1/20
the time taken to cover 2nd km is 1/16
and the time taken to cover 3rd km is 1/12
so total time taken to cover entire distance is 1/20+1/16+1/12
=47/240
And the total distance is 3 km.
Average speed can be given by avg speed=total distance/total time taken
=3*240/47
=15.32 km/hr

Like? Yes (1) | No (2)  

TINKU MITTAL   10 years AGO

If a person or thing travel three equal distances at a speed of x,y and z km/hr respectively then the average speed during the whole journey is 3xyz/(xy+yz+zx) km/hr
so avg speed = (3*20*16*12)/(20*16+16*12+12*20)
= 15.32 km/hr

Like? Yes (1) | No (2)  

v pavan   10 years AGO

time taken for covering 1st km=(1/20)hr
time taken for covering 2nd km=(1/16)hr
time taken for covering 3rd km = (1/12)hr
total distance=3km
total time=(1/20)+(1/16)+(1/12)
average speed= total distance/total time
upon feedind data average speed comes to be 15.32km/hr

Like? Yes (1) | No (2)  

Dinesh thatti   10 years AGO

(xyz) / (xy*yz*zx)=15.32

Like? Yes (1) | No (2)  

Ashish Kumar   10 years AGO

time taken for 1st km = 1/20 hr
similarly for 2nd an 3rd km is 1/16 n 1/12 resp.
total time taken = 1/20+1/16+1/12=752/3840
avg.speed= (3*3840)/752=15.32

Like? Yes (1) | No (2)  

nandyala sandhya rani   10 years AGO

avg speed=(3xyz)/(xy+yz+zx)
= 15.32

Like? Yes (1) | No (2)  

Deepu Kumar   10 years AGO

A/Q option 7 is correct.

Like? Yes (1) | No (2)  

sanjeev kumar   10 years AGO

ans is 15.32

Like? Yes (1) | No (2)  

swarupa nuggu   10 years AGO

15.66

Like? Yes (1) | No (2)  

Tania Chatterjee   10 years AGO

avg speed is 15.32

Like? Yes (1) | No (2)  

lakshmi nalluri   10 years AGO

avg speed=total distance covered/total time taken
=3*abc/(ab+bc+ca)
=3*(20*16*12)/(20*16+16*12+12*20)
=15.32kmph

Like? Yes (1) | No (2)  

chaitanya lakshmi   10 years AGO

avg speed=total distance/total time
a.s= D+D+D/(D/20 +D/16 + D/12 )
a.s=720/47 = 15.32

Like? Yes (1) | No (2)  

PRANEETH   10 years AGO

so total distance is 3km. and total time is 1/20 + 1/16 + 1/12. then average speed is equal to total distance/ total time which is qual to 15.319 approximately 15.32

Like? Yes (1) | No (3)  

niraj   10 years AGO

let total distance be 240
240/20=12
240/16=15
240/12=20
720/47=15.32(ans)

Like? Yes (1) | No (3)  

15 Oct 2014 Number

Sum of a positive single digit number, its square & its cube is 3 more than a perfect square number. Sum of all such single digit numbers will be
Note: 0 is considered as a perfect square number

OPtion

1) 12
2) 1
3) 3
4) 11
5) 8
6) 6
7) 9
8) 4
9) 7
10)5

Solution

Solve x+x^2+x^3 = P +3
For x=1; P=0 (1)
For x=3; P=36 (2)
For x=4; P=81 (3)
Possible value 1, 3, 4
Sum = 1+3+4 = 8

Option 5)

Correct Option: 5 Best Solution (59)

Kushagra Tiwari   10 years AGO

according to question we can write
1+1^2 + 1^3 -3 = 3-3 = 0, which is a
perfect square
2+4+8 -3 = 11,
3+9+27 - 3 = 36
4+16+64- 3 =81
5+25+125 - 3 =152
6+36+216 -3 = 255
7+49+343 - 3 = 396
8+64+512 -3 = 584
9+81+729 -3 = 816
it is clear from above that only 1,3,4
gives perfect square
so the sum will be 1+3+4 = 8

Like? Yes (15) | No (3)  

BHASKAR MANDAL   10 years AGO

according to question we can write
1+1^2 + 1^3 -3 = 3-3 = 0, which is a perfect square
2+4+8 -3 = 11,
3+9+27 - 3 = 36
4+16+64- 3 =81
5+25+125 - 3 =152
6+36+216 -3 = 255
7+49+343 - 3 = 396
8+64+512 -3 = 584
9+81+729 -3 = 816

it is clear from above that only 1,3,4 gives perfect square
so the sum will be 1+3+4 = 8
option 5 is the answer

Like? Yes (17) | No (6)  

Sourojit Dhua   10 years AGO

The numbers will be: 1,3 and 4
Sum=8

Like? Yes (6) | No (3)  

Dr.Dipin Singh   10 years AGO

such numbers are 1,3,4.
Their sum =8

Like? Yes (2) | No   

Thejas   10 years AGO

1+4+3

Like? Yes (1) | No   

saimeera   10 years AGO

the numbers are 1,3,4
so their sum is 8

Like? Yes (1) | No   

TINKU MITTAL   10 years AGO

answer is 8, here is my explanation
according to question we can write
1+1^2 + 1^3 -3 = 3-3 = 0, which is a perfect square
2+4+8 -3 = 11,
3+9+27 - 3 = 36
4+16+64- 3 =81
5+25+125 - 3 =152
6+36+216 -3 = 255
7+49+343 - 3 = 396
8+64+512 -3 = 584
9+81+729 -3 = 816

it is clear from above that only 1,3,4 gives perfect square
so the sum will be 1+3+4 = 8

Like? Yes (1) | No   

Mohan   10 years AGO

1+3+4=8

Like? Yes (1) | No   

CHANDAN KUMAR   10 years AGO

no. will be 1,3,4
sum will be=8

Like? Yes (1) | No   

jasmine kaur   10 years AGO

n2

Like? Yes (1) | No   

soni dabas   10 years AGO

ans. is 8

Like? Yes (1) | No   

AAKANCHA SRIVASTAV   10 years AGO

only 1,3 and 4are such single digits
so there sum is
1+3+4=8

Like? Yes (1) | No   

Anoop Tiwari   10 years AGO

lets check from 1 to 9
1+1^2 + 1^3 -3 = 3-3 = 0
similarily 2+2^2+2^3 -3 = 11,
3+3^2+3 ^3- 3 = 36
4+4^2+4^3- 3 =81
5+5^2+5^3 - 3 =152
6+6^2+6^3 -3 = 255
7+7^2+7^3 - 3 = 396
8+8^2+8^3 -3 = 584
9+9^2+9^3 -3 = 816
we can see that only 1,3,4 are giving perfect square,hence their sum=1+3+4=8

Like? Yes (1) | No   

Aishwarya Chandra   10 years AGO

Frm question
1+1^2 + 1^3 -3 = 3-3 = 0, which is a perfect square
Other chances are
3 + 9 + 27 - 3 = 36
and 4 + 16 + 64 - 3 = 81

(1+3+4) = 8(answer)

Like? Yes (1) | No   

Gitanjali K   10 years AGO

answer is 8

Like? Yes (1) | No   

RAKESH   10 years AGO

x + x^2 + x^3 = y^2 + 3

=> x = 1,3,4
sum =8

Like? Yes (1) | No   

ADARSH GAURAV   10 years AGO

8 is the answer.

Like? Yes (1) | No   

kishore muddada   10 years AGO

let x be the +ve single digit no
so x+x^2+x^3=3+perfect square
x+x^2(1+x)+1=4+perfect square
(1+x)(1+x^2)=4+perfect square
x=1 perfect square=0
x=2 perfect square= NA
x=3 perfect square=36
x=4 perfect square=81
x=5 perfect square=NA
x=6 perfect square=NA
x=7 perfect square=NA
x=8 perfect square=NA
x=9 perfect square=NA
so sum of all such single digit numbers will be 8

Like? Yes (1) | No   

RISHABH SHARMA   10 years AGO

only possbile numbers are 1 ,3 AND 4

Like? Yes (1) | No   

harini   10 years AGO

1+1^2+1^3-3=0
2+2^2+2^3-3=11
3+3^2+3^3-3=36
4+4^2+4^3-3=81
perfect squares for single digit numbers is possible for 1,3,4 only so
sum of 1,3,4 is 1+3+4=8
option 5

Like? Yes (1) | No   

vivek   10 years AGO

only 1+3+4=8 can be possible

Like? Yes (1) | No   

Sreetama Dam   10 years AGO

1+1+1=3 ;3-3=0,perfect square
3+9+27=39;39-3=36,perfect square
4+16+64=84;84-3=81,perfect square
rest 2,5,6,7,8,9 do not fulfill this condition
so result =1+3+4=8

Like? Yes (1) | No   

satyam sharma   10 years AGO

let the number be "x"
x+x^2+x^3=3+perfect square number
in this equation , only 1 and 3 satifies. so sum of these numbers are 4. that is correct answer will be option 8

Like? Yes (1) | No   

viresh pratap singh   10 years AGO

only 1, 3 and 4 satisfy the above relation

Like? Yes (1) | No   

Anusha   10 years AGO

only 1,3,4 are such number...when we add them it becomes 8...so option 5 is correct

Like? Yes (1) | No   

prem kumar   10 years AGO

according to question we can write
1+1^2 + 1^3 -3 = 3-3 = 0, which is a perfect square
2+4+8 -3 = 11,
3+9+27 - 3 = 36
4+16+64- 3 =81
5+25+125 - 3 =152
6+36+216 -3 = 255
7+49+343 - 3 = 396
8+64+512 -3 = 584
9+81+729 -3 = 816

it is clear from above that only 1,3,4 gives perfect square
so the sum will be 1+3+4 = 8

Like? Yes (1) | No   

Namrata Gupta   10 years AGO

y is a perfect square no.
x+x2+x3=3+y
the no 1,3,4 satisfy this eqn.
sum of 1+3+4=8

Like? Yes (1) | No   

rakhi kumari   10 years AGO

checking for each digit

Like? Yes (1) | No (1)  

SOURABH   10 years AGO

following are the no.
1,3,4
sum=1+3+4=8

Like? Yes (1) | No (1)  

NAVEEN KUMAR   10 years AGO

x x^2 x^3 (x+x^2+x^3)-3 perfect sqr
0 0 0 -3 no
1 1 1 0 yes
2 4 8 11 no
3 9 27 36 yes
4 16 64 81 yes
5 25 125 152 no
6 36 216 165 no
7 49 343 396 no
8 64 512 581 no
9 81 729 816 no
hence,
Sum of all such single digit numbers will be(all 'yes')=1+3+4=8
option(5)

Like? Yes (2) | No (2)  

abhinav singh   10 years AGO

(a+a^2+a^3-3)=perfect square
this condition satisfies 1, 3, 4
sum of these no.=1+3+4
=8
option is 5

Like? Yes (2) | No (2)  

santosh kumar patel   10 years AGO

sqrt(a+a^2+a^3-3)=a(perfect)........ natural number
hence 1,3,4 are the numbers
so Sum of the numbers=1+3+4=8

Like? Yes (2) | No (2)  

sanjeev kumar   10 years AGO

ans is 1+3+4=8

Like? Yes (1) | No (1)  

Chandra chur anand   10 years AGO

as per by Q
x+x^2+x^3=x^2+3
or sqrt(x+x2+x^3-3=x)
so for 1 it ll give 0
for 3 it ll give sqrt(36)
and for 4 it ll give sqrt(81)
so 1+3+4=8 ans..

Like? Yes (1) | No (1)  

Deepu Kumar   10 years AGO

sqrt(a+a^2+a^3-3)=a natural number
1,3,4 are the numbers
so Sum of the numbers=1+3+4=8
SO OPTION 5 IS CORRECT.

Like? Yes (1) | No (1)  

Akshay   10 years AGO

1,3,4 are single digit numbers for which these no. itself ,its square and cube is 3 more than perfect square ;
hence their sum is 8.

Like? Yes (1) | No (1)  

niraj   10 years AGO

1+3+4=8

Like? Yes (1) | No (1)  

Gaurav Sharan   10 years AGO

1+1*1+1*1*1=0+3
3+9+27=39=36+3
4+16+64= 84= 81+3
so, 1+3+4=8

Like? Yes (1) | No (1)  

SAI KIRAN   10 years AGO

verified whether (x+x^2+x^3)-3 is perfect square, where x is a single digit positive number.

Like? Yes (1) | No (1)  

himanshu jaiswal   10 years AGO

only 1,3,4 satisfy the given condition
so the ans will be their sum = 8

Like? Yes (1) | No (1)  

stuti priyambda   10 years AGO

1+3+4=8

Like? Yes (1) | No (1)  

satyam shivam   10 years AGO

according to question we can write
1+1^2 + 1^3 -3 = 3-3 = 0, which is a perfect square
2+4+8 -3 = 11,
3+9+27 - 3 = 36
4+16+64- 3 =81
5+25+125 - 3 =152
6+36+216 -3 = 255
7+49+343 - 3 = 396
8+64+512 -3 = 584
9+81+729 -3 = 816

it is clear from above that only 1,3,4 gives perfect square
so the sum will be 1+3+4 = 8

Like? Yes (1) | No (1)  

Chirag Ranjan Lahiri   10 years AGO

From the question, we can write
1+1^2 + 1^3 -3 = 3-3 = 0, which is a perfect square
Similarly the other possibilities are
3 + 9 + 27 - 3 = 36
and 4 + 16 + 64 - 3 = 81

Hence the answer will be : (1+3+4) = 8(answer)

Like? Yes (1) | No (1)  

Sanchit Kapoor   10 years AGO

Such digits are 1,3 and 4 as
1+1+1=3=(0)^2+3
3+9+27=39=(6)^2+3
4+16+64=84=(9)^2+3
So their sum=1+3+4=8
Thus option 5 is correct

Like? Yes (2) | No (3)  

pawan kumar   10 years AGO

1+3+4=8

Like? Yes (1) | No (2)  

pritika singh   10 years AGO

only 3 nos. satisfy cndition
1+1^2+1^3=3= (0+3) 0 prfct sqr
3+3^2+3^3=39=(36+3) 36 prfct sqr
4+4^2+4^3=84=(81+3) 81 prfct sqr
hence, 1+3+4=8

Like? Yes (2) | No (3)  

NAGENDRA P   10 years AGO

1+4+3=8

Like? Yes (1) | No (2)  

ABHILESH PURI GOSWAMI   10 years AGO

solve taking all one digit no.

Like? Yes (1) | No (2)  

Jagruti   10 years AGO

answer = 8
there r only 3 such single digit numbers,viz.,1.,3.,4
1+1^2+1^3-3=0....a perfect square
3+3^2+3^3-3=36....a perfect square
4+4^2+4^4-3=81...a perfect square
1+3+4=8
so ans = 8

Like? Yes (1) | No (2)  

swarupa nuggu   10 years AGO

8

Like? Yes (1) | No (2)  

DEEPAK GOSWAMI   10 years AGO

1 3 4 only 3 num r there nd d sum of these r 8

Like? Yes (1) | No (2)  

S.SHAFI   10 years AGO

a + a^2 + a^3 = 3 + (perfect square number);
1 + 1+ 1 = 3 +(0) ;
3 + 9 + 27 = 3 + (36);
4 + 16 + 64 = 3 + (81);
it will work for only 1, 3, 4....
rest of them it won't satisfy the equation...
so sum of digits is 8...

Like? Yes (1) | No (2)  

Shreya Tiwari   10 years AGO

according to question we can write
1+1^2 + 1^3 -3 = 3-3 = 0, which is a
perfect square
2+4+8 -3 = 11,
3+9+27 - 3 = 36
4+16+64- 3 =81
5+25+125 - 3 =152
6+36+216 -3 = 255
7+49+343 - 3 = 396
8+64+512 -3 = 584
9+81+729 -3 = 816
it is clear from above that only 1,3,4
gives perfect square
so the sum will be 1+3+4 = 8

Like? Yes (1) | No (2)  

Supriya_kamkar   10 years AGO

1+1^2+1^3=0+3

3+3^2+3^3=36+3

4+4^2+4^3=81+3

there are no other such numbers.

1+3+4=8

Like? Yes (1) | No (2)  

Abhishek Vishwakarma   10 years AGO

according to question we can write
1+1^2 + 1^3 -3 = 3-3 = 0, which is a
perfect square
2+4+8 -3 = 11,
3+9+27 - 3 = 36
4+16+64- 3 =81
5+25+125 - 3 =152
6+36+216 -3 = 255
7+49+343 - 3 = 396
8+64+512 -3 = 584
9+81+729 -3 = 816
it is clear from above that only 1,3,4
gives perfect square
so the sum will be 1+3+4 = 8

Like? Yes (1) | No (2)  

lakshmi nalluri   10 years AGO

only 1,3,4 are applicable for above condition
sum=1+3+4=8
given ,
x+x^2+x^3=3+A^2
possibilities of x =[1,9]
only,1,3,4 are applicable

Like? Yes (1) | No (2)  

Kethineni Vinodh   10 years AGO

1,3,4
then sum is 8

Like? Yes (1) | No (2)  

Devendra Marghade   10 years AGO

1+1^2+1^3=3 =0+3
3+3^2+3^3=39=36+3
4+4^2+4^3=84=81+3
So sum of such single digit numbers=1+3+4=8

Like? Yes (1) | No (2)  

Nirmal Kumar Thakur   10 years AGO

1+1*1+1*1*1=1=0+3
3+3*3+3*3*3=39=6*6+3
4+4*4+4*4*4=84=9*9+3

Like? Yes (1) | No (2)  

14 Oct 2014 Percentage

In a class, the number of boys is more than the number of girls by 12% of the total strength. The ratio of boys to girls is:

OPtion

1) 11:14
2) 25:26
3) 26:25
4) 28:25
5) 12:13
6) 25:27
7) 27:25
8) 25:28
9) 14:11
10)None of these

Solution

Let the number of boys and girls be x and y respectively.
Then, (x-y) = 12% of (x+y)
(x-y) = 3*(x+y)/25
Therefore
25x - 25y = 3x+3y
or
22x = 28y
x/y = 28/22
14/11
14:11
Option 9)

Correct Option: 9 Best Solution (117)

Ishan Pushkarna   10 years AGO

Suppose the no. of students in the class is 100
So according to the question the no. of boys are 12 more than the no. of girls.
Therefore if x is the no. of girls then x+12 is the no. of boys.
Now, x+x+12=100 i.e. x=44 no. of girls
& no. of boys will be 44+12=56.
Therefore 56/44= 14:11.

Like? Yes (40) | No (7)  

pritika singh   10 years AGO

no. of grls be x
boys=100-x
100-x=x+12
x=44
g=44 b=56
g/b=14/11

Like? Yes (54) | No (24)  

Kushagra Tiwari   10 years AGO

Let the number of boys and girls be x and y respectively.
Then (x-y) = 12% of (x+y)
or x-y = 3/25 (x+y)
25x-25y=3x+3y or
22x = 28y
or x/y=28/22=>14/11=>14:11
which is in option 9

Like? Yes (33) | No (11)  

Shreya Tiwari   10 years AGO

Let the number of boys and girls be x and y respectively.
Then (x-y) = 12% of (x+y)
or x-y = 3/25 (x+y)
25x-25y=3x+3y or
22x = 28y
or x/y=28/22=>14/11=>14:11
which is in option 9

Like? Yes (16) | No (6)  

Arijit Acharyya   10 years AGO

let, the number of boys and girls are b & g respectively
b=g+ 12 of (b+g)
b=g+(12/100)*(b+g)
b=g+(3/25)*(b+g)
by calculating....
b : g = 14 : 11

Like? Yes (9) | No (1)  

Divya Dawar   10 years AGO

let total students be 100, so boys more than girls is 12
let no of girls be x , so boys are x+12
ATQ, x+x+12=100
we get girls =44, boys =56
so boys:girls=14:11

Like? Yes (7) | No (1)  

Udhaya kumar   10 years AGO

let x as number of boys and y as number of girls
hence from given
x = y + 0.12(x+y)
by solving we get x / y = 1.12 / 0.88 = 14 / 11...

Like? Yes (6) | No   

shubhi vijayvergia   10 years AGO

total no. of students =100
x be no of girls then x+12 will be boys
x+x+12=100
x=44
56:44
14:11

Like? Yes (5) | No   

Udaybhan Viswkarma   10 years AGO

B-G=12%of(B+G)
B/G=112/88
B/G=14/11
So,9)14:11 is the correct answer.

Like? Yes (4) | No   

shubham   10 years AGO

suppose total is 100
the strenth of boys is 12% of total strength . so boys will be 12% more from 100 total student



now we substract 12 from 100 and get 88 now half of 88 will be 44 which same for boys and girls


now we add 12 in 44 boys and get 56 boys


so the ratio is boys and girls 56:44 = 14:11

Like? Yes (3) | No   

PRAVIN PRAJAPATI   10 years AGO

B-G=12%
B+G=100%
B=56%
G=44%
B:G=56:44=14:11

Like? Yes (3) | No   

sai naveen vanapalli   10 years AGO

b=g+12%(b+g)
b/g/= 14/11

Like? Yes (2) | No   

Chirag Ranjan Lahiri   10 years AGO

Let the number of boys and girls be x and y respectively.
Then (x-y) = 12% of (x+y)
So, x-y = (3/25)(x+y)
25x-25y = 3x+3y
22x = 28y
x/y = 28/22 = 14/11
So the required ratio will be - boys:girls = x:y = 14:11(answer)

Like? Yes (2) | No   

Ankit Sirohi   10 years AGO

x-y= (12/100) *(x+y)..i.e
25x-25y=3x+3y
=> x/y=14/11 ...14:11 option 9 ..is d answer

Like? Yes (2) | No   

H.Aparna Rao   10 years AGO

let x=boys and y=girls
then, x=y+12%(x+y)
x=y+0.12x+0.12y
0.88x=1.12y
x/y=112/88=14/11

Like? Yes (2) | No   

SOURABH   10 years AGO

let no. of boys be x and that of girls be y
total no. of students=x+y
x-y=12%(x+y)
on solving we get,
x:y=14:11

Like? Yes (3) | No (1)  

Aishwarya Chandra   10 years AGO

Let the no. Of boys = X
& no. Of girls = Y
Then,
X = Y + 12% (X + Y)
X = Y + .12 X + .12 Y
X/Y = 14/11

Answer = 14/11

Like? Yes (2) | No   

nikhil jaiswal   10 years AGO

let boys(x)+girls(y)=100
then given x-12=y
2x=112
x=56;y=44
x:y::56:44=14:11

Like? Yes (1) | No   

ravi prakash   10 years AGO

let total strength be 100 then
x+(x+12)=100
x=44(girls)
therefore boys =56
therefore ratio=14/11

Like? Yes (1) | No   

V.Latha   10 years AGO

b+g = 100
b = g+12% of 100
g+12+g = 100
2g = 88
g = 44
b = 100-44 = 56
b:g = 56:44 = 14:11

Like? Yes (1) | No   

TINKU MITTAL   10 years AGO

let boys=x
girls= y
so, x= y+ 12% of (x+y)
solving this, x:y= 14:11

Like? Yes (1) | No   

sudhakar   10 years AGO

let's Consider total Student are100
then
boys is 56
girls is 44 (then only the condition satisfies)
56:44=> 14:11

Like? Yes (2) | No (1)  

aman   10 years AGO

Let total strength be x
Let girls be y
Boys = y+0.12x
Total strength = boys + girls
x=y+0.12x+y
0.88x=2y
x:y=25/11
Total:girls=25/11
Boys:girls = (25-11)/11
Boys:girls = 14:11

Like? Yes (1) | No   

Sanchit Kapoor   10 years AGO

Let the total strength be x and
number of girls be y
Then number of boys=x-y
But x-y=12x/100+y
On solving x=200y/88
So ratio of boys to girls=x-y/y
(200y/88 -y)/y
=14:11
So option 9 is correct

Like? Yes (5) | No (4)  

Durgesh Tripathi   10 years AGO

Assume no of boys=b and no of girls=g
total strength=b+g
given condition
b=g+(12(b+g)/100)
b=g+0.12b+0.12g
(0.88)b=(1.12)g
=> b/g=14/11

Like? Yes (1) | No   

vinit   10 years AGO

let the total number be 1200;
now 12% of total strength 1200*12/100=144;
hence 1200-144=1056/2
528+144=672 (total number of boys)
528 (total number of girls)
672:528
14:11 ans

Like? Yes (2) | No (1)  

ramakrishnateja   10 years AGO

let the total strength is 100%. then strength of boys and girls is x&y. then boys %=100x/x+y
girls %=100y/x+y. given that the difference is12%. so 100(x-y)/x+y=12. then 88x=112y. so the ratio of boys and girls is 14:11.

Like? Yes (1) | No   

Rounak Jain   10 years AGO

Let No. of boys = b
No. of girls = g
total strength = b+g
b = g + (12(b+g)/100)
100b = 100g + 12b + 12g
b/g = 112/88
b/g = 14/11
which is the required answer.

Like? Yes (2) | No (1)  

Bhupendra Rana   10 years AGO

x=boys
y=girls
x=y+12%(x+y)
x=(112/88)y
x/y=14/11

Like? Yes (1) | No   

vishnuvardhan   10 years AGO

lat x be no. of boys,y be no. of girls
x-y=12/100*(x+y)
88x=112y
x/y=14/11

Like? Yes (1) | No   

santosh kumar patel   10 years AGO

let total strength
ans=28:25=1200
so 12%=12*1200/100=144
so 1200-144=1056/2=528(girl)
boys=528+144=672
ratio=672:528
=14:11

Like? Yes (1) | No   

soni dabas   10 years AGO

let the total strength b 100...then boys r 56 n girls r 44...ratio comes to b...14:11...for boys:girls

Like? Yes (1) | No   

RAVI RANJAN   10 years AGO

14:11

Like? Yes (1) | No   

harini   10 years AGO

let no of boys & girls be X & Y
X-Y=12/100[X+Y]
X-Y=3/25[X+Y]
25X-25Y=3X+3Y
22X=28Y
X/Y=28/22=14/11
X:Y=14:11
option 9

Like? Yes (1) | No   

Ramesh Sriram   10 years AGO

let assume B+G=100
according to condition
B=G+(12*100/100)
B:G=56:44=14:11

Like? Yes (2) | No (1)  

Ravi Kumar Kodari   10 years AGO

let assume B+G=100
according to condition
B=G+(12*100/100)
B:G=56:44=14:11

Like? Yes (1) | No   

A Rafi   10 years AGO

let b = no.of boys, g = no.of girls, x = total strength = b + g
given that b = g + 0.12 x
x = b + g = g + 0.12 x + g => g = 0.44 x
b = x - 0.44x = 0.56x
b:g = 14 : 11

Like? Yes (1) | No   

SOURAV MUKHERJEE   10 years AGO

boys=x,girls=y;
x-y=12/100(x+y)
x:y=14:11

Like? Yes (1) | No   

ritu sameer   10 years AGO

b+g=x
g+(12100)x=b
after solving these equations if u find the ratio of b:g then the answer will be 14:11

Like? Yes (1) | No   

Ravinder Soni   10 years AGO

b=g+12/100(b+g)

b/g={ g+12/100(b+g) } / g

b/g= 1+12/100{b/g+1)

do some maths.....

(1-12/100)(b/g) = 1+12/100

b/g=112/88=14/11 ans.

Like? Yes (1) | No   

mahesh   10 years AGO

here let a=no.of boys and b=no.of girls then a=b+12%of (a+b)
a=b+0.12a+0.12b
then 0.88a=1.12b
a/b=1.12/88
a/b=14/11 which is required answer.option 9

Like? Yes (1) | No   

ANIMESH GORAI   10 years AGO

let x be the girl's percentage,
x+12 is boy's percentage
x+x+12=100
x=44
boy:girl=56:44
=14:11

Like? Yes (1) | No   

nishu kumar   10 years AGO

let total strength =x and number of girls=y then number of boys=x-y
now given,
boys=y+12/100*x
x-y=(100*y+12*x)/100
88x=200y
now x=200/88*y
subtracting y from both sides
x-y=(200-88)y/88
(x-y)/y=14/11
boys:girls=14:11

Like? Yes (1) | No   

jyoti   10 years AGO

let no of boys be x and girls be y
then x=y+12%(x+y)
x=y+0.12x+0.12y
0.88x=1.12y
x/y=14/11

Like? Yes (1) | No   

Himanshu Mittal   10 years AGO

boys percentage:56%
girls percentge:44%
boys:girls=56:44=14:11

Like? Yes (1) | No   

sujata chakraborty   10 years AGO

B=G+(12/100)X and B+G=X
DIVIDING BY G AND SUBSTITUTING X,

(88/100)*(B/G)=(112/100)

B/G=14/11

Like? Yes (2) | No (1)  

vivek   10 years AGO

Let no of boys be x and girls be y.
then total strength of class is x+y
so a/c to question,
x=y+(x+y)*12%
=> x=y+(x+y)*12/100
=> 25x=28y+3x
=> 22x=28y
so, x:y=14:11

Like? Yes (1) | No   

abhinav singh   10 years AGO

assume there is no of girls in the class =G and boys=B.
no. of boys is 12% more than girls in the class
then it will,
B=G+12/100(G+B)
B-12/100B=G+12/100G
11B=14G

ans is 25:28

Like? Yes (1) | No   

santu ghosh   10 years AGO

let
boys=x,girls=y
so,x-y=(x+y)*12/100
100x-100y=12x+12y
88x=112y
x/y=14/11
x:y=14:11

Like? Yes (1) | No   

sonu suman   10 years AGO

let the no. of boys be x
and no. of girls be y
again assume that total no. of student be 100
so we have x+y = 100
and from first case we have
x=y+(12% of (x+y))
or x=y+12
solving both we have
x= 56
y=44
so x/y = 14:11

Like? Yes (1) | No   

Gaurav Sharan   10 years AGO

b= g+0.12(b+g)
so, we get
b/g=112/88=14/11

Like? Yes (1) | No   

CHANDAN KUMAR   10 years AGO

b-g=12(b+g)/100
b/g(1-12/100)=112/100
b/g=112/88=14/11

Like? Yes (1) | No   

shree   10 years AGO

56/44=14/11

Like? Yes (1) | No   

Jagruti   10 years AGO

let total strength = 100
12% of total strength = 12
let x=no. of boys
let y=no. of girls
x+y=100
also x-y=12 (since no. of boys is 12 greater than girls)
hence x=56
y=44
ratio=14:11

Like? Yes (2) | No (1)  

Ankit   10 years AGO

No of boys =x
no of girls = y
total strength = x+y
So,
x-y=12/100(x+y)
100x-100y=12x+12y
100x-12x= 100y+12y
88x= 112y
x/y= 14/11
14:11

Like? Yes (1) | No   

yoganandan   10 years AGO

b=g+12/100(b+g)
b=g+12b/100 +12g/100
b-12b/100=g+12g/100
88b=112g
b/g=112/88
b/g=14/11

Like? Yes (1) | No   

Mahesh   10 years AGO

Let the number of girls be x%
The number of boys is (x+12)%
x+(x+12)=100
x=44
Girls percentage =44
Boys percentage = 56
Ratio of boys to girls = 56:44=14:11

Like? Yes (1) | No (1)  

Sourojit Dhua   10 years AGO

Let total no. of students= 100
Then boys= 56
girls= 44
Therefore,
ratio= 14:11

Like? Yes (5) | No (5)  

sanjeeth   10 years AGO

(14 :11)
Total = 14 + 11 = 25
boys = 14
girs = 11
12/100 * 25 = 3
No. of boys = no. of girls + 12/100 * total strength
14 = no. of girls + 3
hence no. of girls is = 14 - 3 = 11

Like? Yes (2) | No (2)  

Rashi Bansal   10 years AGO

let number of boys = x
number of girls= y
so strength of class =(x+y)

a.t.c.

x= y + 12/100 *(x+y)
25x = 25y+3x+3y
22x=28y
so x/y=14/11
n hence the ratio is 14:11 which is option (9)

Like? Yes (1) | No (1)  

Gitanjali K   10 years AGO

14:11

Like? Yes (1) | No (1)  

ragini   10 years AGO

y+12/100(x+y)=x
25y+3x+3y=25x
x/y=14/11

Like? Yes (1) | No (1)  

Sundar Kumar   10 years AGO

Let the number of boys and girls be x and y respectively. Then (x-y) = 12% of (x+y)
or x-y = 3/25 (x+y)
25x-25y=3x+3y or 22x = 28y
or x/y=28/22=14/11=14:11
Answer: OPTION 9)14:11

Like? Yes (3) | No (3)  

BHASKAR MANDAL   10 years AGO

14/11 is the answer
let x be the no. of boys and y be no. of girls
then we can write
x=y+0.12(x+y)
divide throughout by y
x/y = 1+0.12((x/y)+1)
=> (x/y) (1-0.12) = 1+0.12
=>x/y = 1.12/0.88 = 112/88 = 14/7

so, x : y = 14 : 7
option 9 is the answer

Like? Yes (2) | No (2)  

SIDDHARTH KUMAR   10 years AGO

let total strength =100
let no. of girls=g
then no. of boys=g+12
then g+(g+12)=100
2g+12=100 =>g=44

now
boys/girls=(44+12)/44=14/11=14:11

Like? Yes (1) | No (1)  

pawan kumar   10 years AGO

Let, total student=100
so, B:G=56:11
=14:11

Like? Yes (1) | No (1)  

Abhishek Vishwakarma   10 years AGO

Let the number of boys and girls be x and y respectively.
Then (x-y) = 12% of (x+y)
or x-y = 3/25 (x+y)
25x-25y=3x+3y or
22x = 28y
or x/y=28/22=>14/11=>14:11
which is in option 9

Like? Yes (1) | No (1)  

Md.Sultan Khichi   10 years AGO

Let num of boys and girls are x and y.
So x=12/100*(x+y)+y
x/y=14/11
Ans 14:11

Like? Yes (1) | No (1)  

T.Aravinth kumar   10 years AGO

x+0.12*(x+y) > y
solve
x:y
14:11

Like? Yes (1) | No (1)  

Deepu Kumar   10 years AGO

Let The number of Boys be X and no.of Girls be Y.
then,
X=y+12%(X+Y)
X=Y+0.12X+0.12Y
0.88X=1.12Y
so X/Y=112/88=14/11
So The option 9 is correct.

Like? Yes (1) | No (1)  

anand agarwal   10 years AGO

b-g=(3/35)*(b+g)
if we solve it we get
b/g=14/11

Like? Yes (1) | No (1)  

Dr.Dipin Singh   10 years AGO

If there are total 100 students in class, then there are 56 boys and 44 girls because the number of boys is more than the number of girls by 12% of the total strength.
hence ratio = 56:44= 14:11

Like? Yes (1) | No (1)  

vartika    10 years AGO

LET TOTAL STRENGTH BE X.
AND number of boys be b and gals be g.
then according to question,
b+g=x
and b-g= 0.12x
solving above equations we get, b=0.56x
and g= 0.44x
=> reqd ratio= b/g= 14/11

Like? Yes (1) | No (1)  

PAWAN KUMAR   10 years AGO

let the no of boys be x and the no of girls be y respectively.
total strength = x+y
12% of total strength = 0.12*(x+y)
now,
x-y = 0.12*(x+y)
=> 0.88x = 1.12y
=> x:y = 1.12 : 0.88 = 14:11

Like? Yes (1) | No (1)  

shekhar suman   10 years AGO

let total strength=100
then,B=G+12----(1)
and B+G=100----(2)
from eq. 1 and 2
G=44
so B=56
now, B/G=56/44=14/11

Like? Yes (1) | No (1)  

Anmol Srivastava   10 years AGO

TAKING TOTAL STUDENTS AS 100, TAKING NUMBER OF BOYS AND GIRL IN SUCH A WAY THAT THE DIFFERENCE BETWEEN THEIR NUMBER BE 12% OF TOTAL STRENGTH i.e. 12 IN THIS CASE SO BOYS=56 AND GIRLS=44, THE RATIO COMES TO BE 14:11.

Like? Yes (1) | No (1)  

Mani kandan   10 years AGO

Let the number of boys and girls be x and y respectively. Then (x-y) = 12% of (x+y)
or x-y = 325 (x+y)
25x-25y=3x+3y or 22x = 28y
or xy=2822=1411=14:11

Like? Yes (1) | No (1)  

Surit Datta   10 years AGO

let the total strength is 100
number of boy = B
number of girl = G
according to the question
B = G +12
and
B + G = 100
solving this we get,
B = 56
G = 44
so there ratio is 14 : 11
That's it..

Like? Yes (1) | No (1)  

Nayan Agrawal   10 years AGO

Let the number of boys be B and number of girls be G
B = G + 12/100(B+G)
22B = 28G
B:G = 14:11

Like? Yes (1) | No (1)  

siddhartha sadhu   10 years AGO

let boys=x;
and girl=y;
x-y=(12/100)*(x+y)
x/y=14:11

Like? Yes (1) | No (1)  

ananth   10 years AGO

from the options 14:11
14+11=25
12% off 25 =3
14-11=3
therefore 14:11 is the answer

Like? Yes (1) | No (1)  

SHUBHAM KUMAR   10 years AGO

THROUGH AANSWERS

Like? Yes (1) | No (1)  

ravi prakash   10 years AGO

let no of boys=b
no of girls=g
and total strength=x
b+g=x
b-g=12%of x
=(12/100 )*x
on solving two equation
b=56/100
and g=44/100
b/g=56/44
=14:11

Like? Yes (1) | No (1)  

LIPIKA DAS   10 years AGO

let x and y be the no. of boys and girls respectively.
A/q
x-y=12% 0f (x+y)
x-y=12/100*(x+y)
x/y=14/11hence 14:11

Like? Yes (1) | No (1)  

Ritika Shrivastava   10 years AGO

Let total students be 100
So 12% of 100=12
No of boys b=12+g
No of girls g
b+g=100
g+12+g=100
G=44
B=56
14:11

Like? Yes (1) | No (1)  

shayali bhartiya   10 years AGO

no of boys =b
no of girls=g
b=g+12/100(b+g)
b/g=14/11

Like? Yes (1) | No (1)  

MRITUNJAY KUMAR   10 years AGO

56/44=14/11

Like? Yes (1) | No (1)  

sharathbabu   10 years AGO

Let the number of by be X and number of girl be Y
then X= Y+12%(X+Y)
0.88X = 1.12Y
X/Y = 112/0.88
= 14/11

Like? Yes (1) | No (1)  

Anoop Tiwari   10 years AGO

Let total number of student in the class=100
than number of boys=56
number of girls=44
hence ratio=56/44=14/11

Like? Yes (1) | No (1)  

Akshay   10 years AGO

let total number of student =100
let number of boys=x
number of girls=y
but number of boys x=y+12
then x+y=100
y=44
x=56
x=y=56/44=14/11

Like? Yes (1) | No (1)  

Partha Pratim Mahata   10 years AGO

Let's
Total=100
12% of total strength=12
let the no of boys =B
the the no of Girls=100-B
so,B=100-B+12
B=56
No of girl =44
so ratio is 56:44=14:11

Like? Yes (1) | No (1)  

Chandra chur anand   10 years AGO

x=(100-x)+12
so x=56 i.e. no. of boys
so 100-56=44 no. of girl
ratio=56/44=14/11 so 14:11 is ans

Like? Yes (1) | No (1)  

Hradesh patel   10 years AGO

let boy=x;girl=y;total strength=100;
x+y=100;
x=y+12;
solve ........get x=56,y=44;
ratio is 14:11

Like? Yes (1) | No (1)  

Rohan   10 years AGO

its simple,
x= y+(x+y)*12/100
after solving, x:y= 14:11

Like? Yes (1) | No (1)  

anandhakumar   10 years AGO

t's Consider total Student are100
then
boys is 56
girls is 44 (then only the condition satisfies)
56:44=> 14:11

Like? Yes (1) | No (1)  

selvakumar   10 years AGO

t's Consider total Student are100
then
boys is 56
girls is 44 (then only the condition satisfies)
56:44=> 14:11

Like? Yes (1) | No (1)  

sravs   10 years AGO

let the total students =x
number of boys =y, number of girls=x-y
y=(x-y)+(12*x/100)
we get y=56*x/100; x-y=44*x/100
y/x-y = 56/44 = 14/11

Like? Yes (1) | No (1)  

Anjali   10 years AGO

Let the number of boys and girls be x and y respectively. Then (x-y) = 12% of (x+y)
or x-y = 325 (x+y)
25x-25y=3x+3y or 22x = 28y
or xy=2822=1411=14:11

Like? Yes (1) | No (1)  

ashok   10 years AGO

14/11

Like? Yes (1) | No (1)  

Nikhil Awasthi   10 years AGO

let total marks be 11x +14x that is 25x.. and 12% of that is 3.
so no of boys are 3 more than girls if we see ratio. So 9th i.e. 14/11 i think is correct

Like? Yes (1) | No (1)  

Urvashi Verma   10 years AGO

B=12%T+G
B=0.12(B+G)+G
so, B/G=1.14/0.88
B/G=14/11

Like? Yes (1) | No (1)  

anuj gupta   10 years AGO

14:11

Like? Yes (1) | No (1)  

thasleema   10 years AGO

According to the question Difference between the two numbers is 12% of the total

=> x-y=(12/100)(x+y)
=>100x-100y=12x+12y
=>88x=112y
=>x/y=14/11

ans=14:11

Like? Yes (1) | No (1)  

priya saha   10 years AGO

ansr (9)14:11
soln:
let the total no. of students be 100
let no. of boys be x and girs be y
12% of 100=12
so x=y+12 ------1
and x+y=100 ------2
so putting value of x from equation 1 to equation 2 we get
y+12+y=100
2y+12=100 or 2(y+6)=100
or y+6=50
hence y=44 so x=56
so boys:girls =x:y=56:44=14:11

Like? Yes (2) | No (2)  

abhishek   10 years AGO

Answer=14:11

Like? Yes (1) | No (1)  

Soham Dalwadi   10 years AGO

Let the number of boys and girls be x and y respectively. Then (x-y) = 12% of (x+y)
or x-y = 3/25 (x+y)
25x-25y=3x+3y or 22x = 28y
or xy=28/22=14/11=14:11

Like? Yes (1) | No (1)  

niraj   10 years AGO

let total strngth is 100
14*4:11*4
56:44
100*12/100=12
44+12=56

Like? Yes (1) | No (1)  

Kethineni Vinodh   10 years AGO

by verification:
14/25*100=56
11/25*100=44

Like? Yes (1) | No (1)  

AMREEN   10 years AGO

let boys=B
Girls=G
Total no. of stuidents=x
B+G=x
B=G+(x*12/100)
G=x-B
after solvng these 2 equation we get
B/G=14/11

Like? Yes (1) | No (1)  

RAKESH   10 years AGO

b = g + (b+g)*12/100
=> b:g = 14:11

Like? Yes (1) | No (1)  

AJAI AGARWAL   10 years AGO

total=100;
boys in other class=12
b=100-12=88
44 pairs of two
hence b=44+12=56
g=44
ratio=56:44
hence: 14:11

Like? Yes (1) | No (1)  

Ramanand Yadav   10 years AGO

let total strength of claas is x.
Acc to question
x*12/100= 3x/25 boys more tahan girls.
Now x-3x/25= 22x/25 is number of both boys and giels. Now divide it by 2 i.e 22x/2*25=11x/25 number of girls.
Then boys= 11x/25+3x/25=14x/25
Now ratio (14x/25)/11x/25=14/11
i.e. 14:11

Like? Yes (1) | No (1)  

Priya Dharshini   10 years AGO

let x be the no of students in the class.
so x be no of boys + no of girls
moreover they given that boys is more than girls by 12% of total strength .




now take x=100;
then if girls is 44
boys=44+12*12/100=44+12=56;


answer is 56:44
14:11

Like? Yes (1) | No (1)  

mukesh agrawal   10 years AGO

112/88=14/11

Like? Yes (1) | No (1)  

swarupa nuggu   10 years AGO

14:11

Like? Yes (1) | No (2)  

maths hater   10 years AGO

say number of girls=x
112x/100*x=28/25

Like? Yes (1) | No (2)  

anjali   10 years AGO

let us assume total strength of class =100
boys+girls=100
let girls be x
then boys= x+12
(x+12)+x=100
x=44
girls=44
boys=56
therefore,
ratio=boys/girls=56/44=14/11

Like? Yes (1) | No (3)  

13 Oct 2014 Sequence

What is the next number of the following sequence
5, 8, 12, 18, 24, 30, 36, 42, ...?

OPtion

1) 44
2) 48
3) 52
4) 50
5) 56
6) 62
7) 49
8) 64
9) 46
10)None of these

Solution

in the first step select the prime number
2 3 5 7 11 13 17 19 23 29
add two adjcent number at at time you will get the series
5 8 12 18 24 30 36 42 52

Option 3)

Correct Option: 3 Best Solution (63)

Kushagra Tiwari   10 years AGO

Each number is two prime numbers added to each other.
The two primes are consecutive and are ascending.
5=2+3, here 2 and 3 are prime and in ascending similarly others
8=3+5,
12=5+7,
18=7+11,
24=11+13,
30=13+17,
36=17+19,
42=19+23,

Now next term will be 23+ next prime no.
that is 23 + 29 => 52

which is in option no 3

Like? Yes (40) | No (5)  

Shreya Tiwari   10 years AGO

Each number is two prime numbers added to each other.The two primes are consecutive and are ascending.
5=2+3,
8=3+5,
12=5+7,
18=7+11,
24=11+13,
30=13+17,
36=17+19,
42=19+23,

Now next term will be 23+ next prime no.
that is 23 + 29 => 52

Like? Yes (12) | No (3)  

Sundar Kumar   10 years AGO

Each number is two prime numbers added to each other. The two primes are consecutive and are ascending.
5=2+3, 8=3+5, 12=5+7, 18=7+11, 24=11+13, 30=13+17, 36=17+19,42=19+23,52=23+29
Answer: Option 3) 52

Like? Yes (8) | No (1)  

Mahesh   10 years AGO

The first number is sum of the first two prime numbers that is 2 and 3
8 is sum of 3 and 5, the next pair of prime numbers
similarly,
12=5+7
18=7+11
24=11+13
30=13+17
36=17+19
42=19+23
The next number should be the sum of 23 and the next prime number which is 29
So, the next number is 23+29=52
52 is the next number

Like? Yes (7) | No (2)  

Aastha   10 years AGO

5=2+3
8=3+5
12=5+7
18=7+11
....
here each no is sum of two prime..ie. 1 prime no from the prev.
& other no. is the next no. prime to it
in the same way
42=19+23
52=23+29

Like? Yes (6) | No (3)  

Sanchit Kapoor   10 years AGO

Each term in the sequence is the sum of two consecutive prime numbers.
5=2+3
8=3+5
12=5+7
18=7+11
24=11+13
30=13+17
36=17+19
42=19+23
So next term should be 23+29=52
So option 3 is correct.

Like? Yes (3) | No   

BHASKAR MANDAL   10 years AGO

it is the sum of consequtiive prime numbers
3+5 = 8
5+7 = 12
7+11 = 18
11+13 = 24
13+17 = 30
17+19 = 36
19+23 = 42
23 + 29 = 52
option 3 is the answer

Like? Yes (4) | No (2)  

vinit   10 years AGO

05 = 02 + 03
08 = 03 + 05
12 = 05 + 07
18 = 07 + 11
24 = 11 + 13
30 = 13 + 17
36 = 17 + 19
42 = 19 + 23
52 = 23 + 29

Like? Yes (3) | No (1)  

Ankit Sirohi   10 years AGO

it is the sum of consequtiive prime numbers
3+5 = 8
5+7 = 12
7+11 = 18
11+13 = 24
13+17 = 30
17+19 = 36
19+23 = 42
23 + 29 = 52.. option 3 is d answer..!

Like? Yes (2) | No   

ashok   10 years AGO

Each number is two prime numbers added to each other. The two primes are consecutive and are ascending.
5=2+3, 8=3+5, 12=5+7, 18=7+11, 24=11+13, 30=13+17, etc.

Like? Yes (2) | No   

Anand   10 years AGO

5=2+3, 8=3+5, 12=5+7, 18=7+11, 24=11+13, 30=13+17,17+19=36, 19+23=42, 23+29=52

Like? Yes (2) | No (1)  

ravi prakash   10 years AGO

add two conscutive successive prime no .....
2+3=5
3+5=8
5+7=12
7+11=18
11+13=24
13+17=30
17+19=36
19+23=42
23+29=52

Like? Yes (2) | No (1)  

santosh kumar patel   10 years AGO

in the first step select the prime number
2 3 5 7 11 13 17 19 23 29
add two adjcent number at time you will get the series
5 8 12 18 24 30 36 42 52

Like? Yes (2) | No (1)  

sanjeev kumar   10 years AGO

ans is 52

Like? Yes (1) | No   

Anand Dwivedi   10 years AGO

5=2+3,
8=3+5,
12=5+7,
18=7+11,
24=11+13,
30=13+17

So Answer Will be 52

Like? Yes (1) | No   

Simranjit Singh   10 years AGO

next number is 52
it is the sum of consequtive prime numbers
3+5 = 8
5+7 = 12
7+11 = 18
11+13 = 24
13+17 = 30
17+19 = 36
19+23 = 42
23 + 29 = 52

Like? Yes (1) | No   

Chandra chur anand   10 years AGO

each no. is addition of consecutive two prime no.
5=2+3
8=3+5
12=5+7
18=7+11
24=11+13
30=13+17
36=17+19
42=19+23
so next term ll be 23+29=52 is ans...

Like? Yes (1) | No   

SIDDHARTH KUMAR   10 years AGO

Each number is two prime numbers added to each other. The two primes are consecutive and are ascending.
5=2+3,8=3+5,12=5+7,18=7+11,24=11+13,30=13+17,36=17+19,42=19+23,52=23+29
Ans=52

Like? Yes (1) | No   

NAVEEN KUMAR   10 years AGO

05=02+03
08=03+05
12=05+07
18=07+11
24=11+13
30=13+17
36=17+19
42=19+23
52=23+29 option ( 3 )

Like? Yes (1) | No   

puja kumari   10 years AGO

sum of successive pair of prime number.

2+3=5
3+5=8
5+7=12
7+11=18
11+13=24
13+17=30
17+19=36
19+23=42
23+29=52

Like? Yes (1) | No   

TINKU MITTAL   10 years AGO

Each number is two prime numbers added to each other. The two primes are consecutive and are ascending.
5=2+3, 8=3+5, 12=5+7, 18=7+11, 24=11+13, 30=13+17, etc.

Like? Yes (1) | No   

satyam shivam   10 years AGO

Each number is two prime numbers added to each other. The two primes are consecutive and are ascending.
5=2+3, 8=3+5, 12=5+7, 18=7+11, 24=11+13, 30=13+17, etc.

Like? Yes (1) | No   

Aishwarya Chandra   10 years AGO

each no. is sum of prime no.-
5=2+3,
8=3+5,
12=5+7,
18=7+11,
24=11+13,
30=13+17,
36=17+19,
42=19+23,
52=23+29,

option- 3

Like? Yes (1) | No   

anuj gupta   10 years AGO

52

Like? Yes (2) | No (1)  

Swaraj Behera   10 years AGO

Adding of prime numbers serially

Like? Yes (1) | No   

Ankur   10 years AGO

add 3+5=8
then 5+7=12
then 7+11=18
then 11+13=24
then 13+17=30
then 17+19=36
then 19+23=42
then 23+29=52
so its sum of all prime numbers(consecutive)

Like? Yes (2) | No (1)  

Chirag Ranjan Lahiri   10 years AGO

3+5 = 8
5+7 = 12
7+11 = 18
11+13 = 24
13+17 = 30
17+19 = 36
19+23 = 42
23 + 29 = 52
So the next number is 52(answer)

Like? Yes (1) | No   

sudhakar   10 years AGO

answer 52

Like? Yes (1) | No   

anandhakumar   10 years AGO

answer 52

Like? Yes (1) | No   

sumit kumar   10 years AGO

Each number is two prime numbers added to each other....
(2,3,5,7,11,13,17,19,23,29)
5=2+3,
8=3+5,
......
52=23+29

Like? Yes (1) | No   

selvakumar   10 years AGO

answer 52

Like? Yes (1) | No   

MP    10 years AGO

Sum of consecutive prime number gives the number in this series.
like
2+3=5
3+5=8
5+7=12
7+11=18
..
..
19+23=42
23+29=52

Like? Yes (1) | No   

abhishek   10 years AGO

Every no is addition of 2 prime no ..
Eg:-36=17+19. ,42=19+23
So next no will be 52=25+29

Like? Yes (2) | No (1)  

arun   10 years AGO

sum of consecutive prime numbers
3+5 = 8
5+7 =12
7+11 = 18

so on

Like? Yes (1) | No   

ARUN KUMAR N   10 years AGO

2+3,3+5,5+7,7+11,11+13,13+17,17+19,19+23,23+29
sum of 2 adjacent prime numbers
so 52

Like? Yes (1) | No   

Rashi Bansal   10 years AGO

Each number is a sum of two prime nos.
2+3 = 5
3+5=8
5+7=12
7+11=18
.
.
.
23+29=52

Like? Yes (1) | No   

V.Mahesh   10 years AGO

this series is combination of prime no's
5=2+3
8=3+5
similarly
52=23+29

Like? Yes (1) | No   

Udaybhan Viswkarma   10 years AGO

Each number is two prime numbers added to each other. The two primes are consecutive and are ascending.
5=2+3, 8=3+5, 12=5+7, 18=7+11, 24=11+13, 30=13+17,17+19=36,19+23=42,23+29=52
so, 3)52 is the answer...

Like? Yes (1) | No   

Sneha   10 years AGO

next number is 52
it is the sum of consecutive prime numbers
3+5 = 8
5+7 = 12
7+11 = 18
11+13 = 24
13+17 = 30
17+19 = 36
19+23 = 42
23 + 29 = 52

Like? Yes (1) | No   

vikas singh   10 years AGO

5=2+3, 8=3+5, 12=5+7, 18=7+11, 24=11+13, 30=13+17

Like? Yes (1) | No   

S.SHAFI   10 years AGO

5,8,12,18,24,30,36,42...
observe the pattern...
3 + 5 = 8
5 + 7 = 12
7 + 11 = 18
11 + 13 = 24
13 + 17 = 30
17 + 19 = 36
19 + 23 = 42
23 + 29 = 52
It is the sum of prime numbers consecutively...
So, the next number is 52..

Like? Yes (1) | No   

Gitanjali K   10 years AGO

next no. will be 52

Like? Yes (1) | No   

g lokesh   10 years AGO

05=02+03
08=03+05
12=05+07
18=07+11
24=11+13
30=13+17
36=17+19
42=19+23
52=23+29

Like? Yes (1) | No   

Akshay   10 years AGO

sum of prime number from 5with 3 ,TO 23 -29

Like? Yes (1) | No   

Pawan Kumar Mishra   10 years AGO

addition of prime numbers

Like? Yes (1) | No   

abhilasha   10 years AGO

ans is 3rd option

Like? Yes (1) | No   

Aarush Singh   10 years AGO

52 will be the ans

Like? Yes (1) | No   

RAKESH   10 years AGO

23+29=52

Like? Yes (1) | No   

ADARSH GAURAV   10 years AGO

52 is the answer

Like? Yes (1) | No   

purushothama   10 years AGO

prime numbers are added to previous numbers such as2+3=5, 3+5=8 & so on

Like? Yes (1) | No   

Alok   10 years AGO

sum of 2 consecutive prime

Like? Yes (1) | No   

NAGENDRA P   10 years AGO

Each number is two prime numbers added to each other. The two primes are consecutive and are ascending.
5=2+3, 8=3+5, 12=5+7, 18=7+11, 24=11+13, 30=13+17,
17+19=36,19+23=42..23+29=52..So answer is 52
option is (3)

Like? Yes (1) | No   

Sourojit Dhua   10 years AGO

5=2+3, 8=3+5, 12=5+7, 18=7+11, 24=11+13, 30=13+17, etc......

Like? Yes (1) | No (1)  

Abhishek Vishwakarma   10 years AGO

Each number is two prime numbers added to each other.The two primes are consecutive and are ascending.
5=2+3,
8=3+5,
12=5+7,
18=7+11,
24=11+13,
30=13+17,
36=17+19,
42=19+23,

Now next term will be 23+ next prime no.
that is 23 + 29 => 52

Like? Yes (1) | No (1)  

Surit Datta   10 years AGO

Just add each pair of consecutive prime numbers to find the next number.
2+3 = 5

3+5 = 8

5+7 = 12

7+11 = 18

11+13 = 24

13+17 = 30

17+19 = 36

19+23 = 42

23+29 = 52
That's it..

Like? Yes (1) | No (1)  

sanjeeth   10 years AGO

sum of two consecutive noncomposite numbers a(1) = 1, for n>=2 we get 1,3,5,8,12,18, 24, 30, 36, 42,52,60... i.e 1,3,5,7,11,13,17,19,23,29... 23+29=52

Like? Yes (1) | No (1)  

Arijit Acharyya   10 years AGO

2+3=5
3+5=8
5+7=12
7+11=18
11+13=24
13+17=30
17+19=36
19+23=42
23+29=52
addition of primes

Like? Yes (1) | No (1)  

Deepu Kumar   10 years AGO

A/Q option 2 is correct.

Like? Yes (1) | No (1)  

Perumal   10 years AGO

5=2+3
8=3+5
12=5+7
.....

Like? Yes (1) | No (1)  

pawan kumar   10 years AGO

23+29=52

Like? Yes (1) | No (1)  

Partha Pratim Mahata   10 years AGO

Each number is two prime numbers added to each other. The two primes are consecutive and are ascending.
5=2+3, 8=3+5, 12=5+7, 18=7+11, 24=11+13, 30=13+17......
...
...
23+29=52
so ans is 52

Like? Yes (1) | No (1)  

harika challagolla   10 years AGO

adding 2 prime numbers.....
2+3,3+5,5+7,7+11,11+13,13+17,17+19,19+23i.e 52

Like? Yes (1) | No (1)  

vivek   10 years AGO

5=2+3 (sum of two consecutive prime number)
8=3+5
12=5+7
18=7+11
24=11+13
30=13+17
36=17+19
42=19+23
then, 23+29=52

Like? Yes (1) | No (1)