M4maths Previous Puzzles

08 Oct 2014 Percentage

Ramesh got 49/4 dozen T-shirts in 12 % discount to printed price and he sold two third of these T-shirts in 19 % profit to printed price, then he sold other T-shirts in printed price. If his overall profit is 3626 rupee then printed price of the T-shirt is

OPtion

1) 95
2) 108
3) 94
4) 125
5) 136
6) 101
7) 100
8) 98
9) 84
10)None of these

Solution

Let the printed price of the T-shirt is x, then according to given condition
1.19 x * 2/3 (147) + x * 1/3 (147) – 0.88 x *(147) = 3626
On solving this equation, we get x= 100

Option 7)

Correct Option: 7 Best Solution (62)

Anurag Dwivedi   10 years AGO

Suppose X is the printed Price
so, if he gets the tshirts in 12% discount,
then he spend = (49/4)* 12* (0.88*X)
now he sells it
so selling Price = (49/4)*12*(2/3)*(1.19*X) +(49/4)*12*(1/3)*(X).
so Net profit is = Selling Price- Buying Price
3626 = 36.26*X
X=Rs. 100

Like? Yes (19) | No (2)  

RAKESH   10 years AGO

49/4 *12 = 147
2/3 rd = 98, 1/3 rd = 49

(119x/100 *98 + 49*x ) - 88x/100 *147 = 3626

=> x = 100

Like? Yes (7) | No   

Ankit Sirohi   10 years AGO

let the printed price be x,
then CP= 147*(88x/100) = 12936x/100,
and the SP of 98 tshirts= 98*(119X/100)
and SP of remaining 49 tshirts = 49x ,
therefore total profit is given as below :

(98*119x/100)+(49x)-(147*88x/100)=3626
so x=100 ..option 7 is the answer...!

Like? Yes (4) | No   

Sanchit Kapoor   10 years AGO

Let the printed price of the T- shirt be m.
Then Ramesh got 49/4*12=147 T - shirts for 12936 m/100 at the discount of 12% on marked price.
Now he sold 2/3*147=98 T- shirts for 11662m/100 at the profit of 19% on the listed price.
The rest of them, i.e 49 T-shirts he sold for 49m/100 at the marked price only.
Hence overall SP of the T-shirts = 16562 m/100
According to the question Profit=3626
i.e (16562 - 12936)m/100 = 3626
On solving for m, we get m= 100
Thus option 7 is correct.

Like? Yes (5) | No (1)  

rajeev chaubey   10 years AGO

147 t shirt cost=.88*147x
98 t shirt cost of selling=1.19*98x
49 t shirt selling cost=49x
profit=165.62x-129.36x=3626
x=100

Like? Yes (3) | No (1)  

S.SHAFI   10 years AGO

Lets printed price = x;

Total number of shirts = (49/4)*12 = 147

Cost Price = (88/100)*x*147

2/3 rd of T-shirts = 98
Remaining T-shirts = 49

Selling Price = (119/100*x)*98 + 49*x

The equation would be
Selling Price - Cost Price = 3626;
The Printed Price is 100...

Like? Yes (2) | No   

Aastha   10 years AGO

let cost of 1 shirt be x
total shirt=49/4*12=147
c.p=147-12*147x/100
=129.36
s.p=2/3*147*x + 2/3*147*19/100 +1/3*147x
=165.62
profit=s.p-c.p
3626=36.26x
x=100

Like? Yes (2) | No   

shekhar suman   10 years AGO

let printed price per t-shirt=100
no of t-shirt bought=49/4*12=147
then, cp of 147 t-shirt=88*147=12936
selling price={147*2/3*199+147/3*100}=16562
profit=sp-cp=16562-12936=3626
so printed price=100

Like? Yes (1) | No   

BHASKAR MANDAL   10 years AGO

49/4 dozen = 49*12/4 = 147 items
profit = selling price (sp) - cost price (cp)
let the marked price be x
cp = (1-0.12)*x*147 = 0.88 * 147 x
= 129.36 x
sp = (1+0.19)*(2/3)*147*x + 1*(1/3)*147*x
= 165.62 x
profit = sp-cp
=> 3626 = 165.62x - 129.36x
=> 3626 = 36.26 x
=> x = 100
so the marked price is 100
option 7 is the correct answer

Like? Yes (1) | No   

Pooja P   10 years AGO

let printed price be p
total t-shrt bought=49/4*12=147 at discount of 12%
total money invested=147*(p-12%p)
no. of t-shrt sold at 19% profit=2/3*147=98
no. of t-shrt sold at printed price=147-98=49
total money earned=98*(p+19%p)+49p
then,total profit=[98(p+19/100*p)+49p]-[147*(p-12/100*p)]
=>[(19*98)/100 +(12*147)/100]*p=3626
by solving we get p=100
so ans=100

Like? Yes (1) | No   

PAWAN KUMAR   10 years AGO

Let the price of 1 T-shirt be Rs x.
Then, C.P. of 147 T-shirts = .88x*157
S.P. = 1.19x*98 + x*49
Profit = sp-cp = 36.26x = 3626 => x = 100 Ans.

Like? Yes (1) | No   

Vikram   10 years AGO

100 rupees

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vikram kasa   10 years AGO

ans is 100 rupees

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khushboo goenka   10 years AGO

coz let x is price thn he buy 147 shrt in .88x
now sell 98 shrt in 1.19x
and rest in 49x
now profit=165.62x-129.36x=36.26x

Like? Yes (1) | No   

Pankaj Modi   10 years AGO

(x+(19x/100)*98+49x-147(x-(12x/100))=3626

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santosh kumar patel   10 years AGO

ans: 100 according to option

Like? Yes (2) | No (1)  

MANISH KUMAR   10 years AGO

eqn is 98*19x+4900x-147*88x=362600

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ADARSH GAURAV   10 years AGO

100 is the answer.

Like? Yes (1) | No   

Anand Dwivedi   10 years AGO

i Think Answer Should Be 100

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Mahesh   10 years AGO

total number of shirsts sold is 147.
let price of each shirt be 100x
buying price of all the shirts is 88x
selling price of each of the first 98 shirts is 119x
profit on the first 98 shirts is 31x on each shirt
so a total of 3038x
for each of the next 49 shirts profit on each shirt is 12x
So total of 588x
total prfit is 3626x
now 3626x=3626
price of each shirt is 100

Like? Yes (1) | No   

Hemavathy Nangan   10 years AGO

Total T.shirt 147
s.p=98 (x-19x/100)+49x
c.p=(x-12x/100)
s.p-c.p=3626
ie., x=100

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dhanaseelan   10 years AGO

Answer is 100

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ganesh babu   10 years AGO

Ramesh got 49/4 dozen = 49x3 T.shirt
print price = A
S.P = 98 (A + 19 A/100) + 49 (A) = 16562 A/100
C.P = 49 x 3(A-12 A/100)= 12936 A/100
S.P - C.P = 16562 A/100 - 12936 A/100 =3626 A / 100
profit = 3626
3626 A / 100 = 3626
A = 100

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AKASH DEEP   10 years AGO

solve by the help of ans

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BITTU   10 years AGO

let printed price =100
then
total price of t-shirt after 12% discount = (49*12)/4 * 88 = 12936

sailing price of 147*2/3 t-shirt = 98*119=11662
sailing price of rest 49 t-shirt = 49*100=4900
total sailing price = (11662+4900)=16562

profit = 16562-12936= 3626

3626 is given as total profit so the printed price of t-shirt = rs 100

Like? Yes (1) | No   

siddhartha sadhu   10 years AGO

let the printed price be x
(49/4)*12=147 total t shirt
12% discount
so, c.p=147(x-(12/100)*x)
2/3*147=98 T shirt sold at 19% profit.
remaining 1/3*147=49 T shirt sold at x price.
so. s.p=98(x +(19/100)*x) + 49*x.
profit = 3626
profit=s.p-c.p
[98*(x +(19/100)*x)+49*x] - [ 147*(x-(12/100)*x)]= 3626
solving the above equation we find x= 100.

Like? Yes (1) | No   

SATHYA PRAKASH REDDY BOLLAMPALLY   10 years AGO

((147*88/100)-(98*119/100)-49)*x=3626
on solving,
therfore,printed price x=100

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CHANDAN KUMAR   10 years AGO

let cp of 1 t shirt=x
cp of 147 t shirt=147*88x/100=129.36x
sp=119*98x/100+49x=165.62x
gain=165.62x-129.36x=36.26x
36.26x=3626
x=100

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Gaurav Sharan   10 years AGO

cp= (49/4)*12*0.88C
sp=49(2.38c+c)
sp = cp+3626 will give c= 100

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Grishma Shah   10 years AGO

LET Y BE THE PRINTED PRICE

TOTAL PROFIT DONE = 3626
147(0.12Y) + 98(0.19Y) = 3626

HENCE, 36.26Y = 3626
PRINTED PRICE = 100.

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Ankur   10 years AGO

because he purchased at 22x/25( if x is printed price) and sold at 16562x/100, so as total profit is 3626 x is 100

Like? Yes (1) | No   

Aishwarya Chandra   10 years AGO

let c.p of 1 t-shrt be - x
total c.p of 49/4 dozen t-shrt i.e 147 shrt is- 147 x
s.p of two third of 98 t-shrt wid profit of 19% is- 98x X 1.19x
n s.p of remaininf 49 t-shrt is- 49x
then,
s.p - c.p = 3626
(98 X 1.19x + 49x) - (147x - 147x X 12%) = 3626
165.62x - 129.36x =3626
36.26x = 3626
x= 100

Like? Yes (1) | No   

anish singh   10 years AGO

the total no of t shirts are 147
let the t shirts price is x
then its cp is 88x/100
the sp of two third t shirt is 2x/3+2x/3*19/100=2.38x/3
rest t shirt sp is x/3
total sp is 2.38x/3+x/3=3.38x/3
profit is 3.38x/3-.88x=0.2467x
0.2467x=3626
x=3626/.2467
price of single t shirt is 3626/(0.2467*147)=99.98=aprox 100

Like? Yes (1) | No   

ashwini   10 years AGO

100 because c.p=147*88/100p
s.p1=98*119/100 p
s.p2=49p
3626=(sp1+sp2)-cp
solving we get 100

Like? Yes (1) | No   

Premangshu Howli   10 years AGO

let the price be x.then he got those in (147*88x)/100.now 2/3 means 96 sold in price (96*119x)/100.and rest in 49x.thus the equation become 96*119x/100+49x-147*88x/100=3626

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Devesh Gupta   10 years AGO

total T-shirts = (49/4)*12 = 147
let CP be Cost price, SP be selling price & PP be printed price
now
CP = (1-0.12)*147*PP = 129.3 PP

SP = (98*(1+0.19)*PP)+(49*PP) = 165.6 PP

Profit = SP-CP = 3626
thus
36.3*PP = 3626
PP = (3626/36.3) = 99.83 = 100

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vivek   10 years AGO

100

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rakhi kumari   10 years AGO

SIMPLE PROFIT AND LOSS CONCEPT IS USED

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Pulokesh Ghosh   10 years AGO

49/4 dozens = 147 T-shirts
let printed price of each shirt be x
total cost = (1 - 0.12)*x*147
=0.88*x*147
=129.36x
total selling price = (1+0.19)*x*147*(2/3) + x*147*(1/3)
=1.19*x*98 + 49x
=116.62x + 49x
=165.62x
total profit = 3626
=>165.62x - 129.36x = 3626
=>36.26x = 3626
=>x = 100

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MANU   10 years AGO

ans is 99.94 rs== 100 rs

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T.Aravinth kumar   10 years AGO

98X+0.19X(19X)+47X-(147X-0.12(147X))=3626
solve this equation
X=100.

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Pragati Kamal   10 years AGO

no of shirit=147
Marked price/shirit=x
total MP= 147x
C.p/shirit =88x100
total C.p=(147*88x)100
S.P1= (98*119x)100
S.P2=49x
total SP= S.P1+S.P2
therefore
TOTAL S.P- TOTAL C.P=3626
so x=100

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Jigyasa Kumar   10 years AGO

answer will be 7

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abhilasha   10 years AGO

acc to the options ans will be 100

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swasthika   10 years AGO

Let the print price be y,

49/4 dozen=147 shirts
profit1 : 12% of 147 shirts = (12/100)*147*y

2/3rd of 147 shirts =98 shirts
profit2: 19% of 98 shirts = (19/100)*98*y

total profit =3626
profit1+profit2=3626
y=100

Like? Yes (1) | No   

vikas singh   10 years AGO

(49*2*119 X)/100 + 49 X -(88 X*49*3)/100 =3626
BY SOLVING THIS EQU...
WE GET X=100
THIS IS PRINTED PRICE

Like? Yes (1) | No   

pratik   10 years AGO

Suppose printed price of tshrt is x.
Then price of 147 tshrt is 147x
He get in 12%discount is 147x -147*12x/100
Sold 98 tshrt in 19% profit is 98x +98*19x/100
Rest 49 tshrt in same printed price is 49x.
Total profit is
98x + 98*19x/100 - {147x-147*12x/100}=3626.

Like? Yes (1) | No   

Tania Chatterjee   10 years AGO

Ans is 100

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jyotishna bansal   10 years AGO

let x be the printed price of single t-shirt so difference between purchased t-shirt and sold t-shirt is equal to profit and we will get the value of x from that equation
[(x*98*119/100) + (49*x) ] - (x*(49/4)*12*88/100 ) = 3626

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Narasapu Hari prasad   10 years AGO

ans is option 7
let x is printed price
49/4 dozen t-shirts=147
2/3 of 147=98
so (147*88*x/100)+3626=(98*119*x/100)+(49*100*x/100)
12936x+362600=11662x+4900x
362600=3626x
x=362600/3626
x=100

Like? Yes (1) | No (1)  

Sourojit Dhua   10 years AGO

Solving the equation, We get: 36.26xMP=3626
Hence,
M.P=Rs.100

Like? Yes (1) | No (1)  

Manish Singhal   10 years AGO

let marked price be x
total no. of t-shirt=147
cost price of 147 t-shirt at 12% discount=129.36x
selling price of of 98 t-shirt at 19% profit= 116.62x
selling price of 49 t-shirt at mp = 49x
total selling price = 116.62x+49x=165.62
profit= sp-cp=165.62x-129.36x=36.26x
profit =3626 as given
then 3626=36.26x => x=100 Ans

Like? Yes (1) | No (1)  

pawan kumar   10 years AGO

49/4 dozen= 147
let, printed price of each t-shirt= Rs. X
then, total cost price= Rs. X*(88/100)*147
= Rs. 12936X/100

now, 2/3 of 147= 98
selling price of t-shirts= Rs. [X*(119/100)*98]+49X
= Rs. 16562X/100

hence, (16562X/100) - (12936X/100) = 3626
so, X= Rs. 100

Like? Yes (1) | No (1)  

Saikat Ghosh   10 years AGO

49/4 t.s m.p-x (let). so c.p 88x/100
2/3 t.s m.p - 2x/3
with 19^ profit s.p is - 2x*119/300
others sell at m.p so others s.p is x/3
so eqn is
2x*119/300 + x/3 = 3626 + 88x/100

solving it we get x=14700
cost of 1 dozon = 14700*4/49=1200
so 1 t.s m.p is 1200/12=100(ans)

Like? Yes (1) | No (1)  

Kunal Jaiswal   10 years AGO

Option 7. Rs 100 is the printed price of the t-shirt.

Like? Yes (1) | No (1)  

ABHILESH PURI GOSWAMI   10 years AGO

4/3 dozen = 147 t-shirts
Let the printed price be x.
c.p. price of 147 t-shirts = 147*x*[(100-12)/100]
s.p. of 2/3 t-shirts=s.p. of 98 t-shirts=98*x[(100+19)/100]
s.p. of rest t-shirts=s.p. of 49 t-shirts = 49*x
profit = total s.p. -total c.p.
3626 = {98*x[(100+19)/100] + 49*x} - 147*x*[(100-12)/100]
on solving we get x = 100
hence printed price is 100 option 7

Like? Yes (1) | No (1)  

lakshmi nalluri   10 years AGO

let p be 100rs
then 147*88~[98*119+49*100]=3626

Like? Yes (1) | No (1)  

MRITUNJAY KUMAR   10 years AGO

100

Like? Yes (1) | No (1)  

harshit gupta   10 years AGO

total t shirt=49/4*12=147

let x be printed price
the equation will be
0.88x*147+3626=1.19x*98+49x
then x=100 rs

Like? Yes (1) | No (1)  

harshit gupta   10 years AGO

total t shirt=49/4*12=147

let x be printed price
the equation will be
0.88x*147+3626=1.19x*98+49x
then x=100 rs

Like? Yes (1) | No (1)  

Supriya_kamkar   10 years AGO

no. of shirts purchased--->147
if marked price is------>x
amount paid by him---->.88x(147)----> 1
he sold them for------>1.19x(98)+x(49)----> 2

profit= eqn.2 - eqn.1=3626
solving we get x=100.

Like? Yes (1) | No (1)  

Akshay   10 years AGO

98*1.19p+49p-0.88*147=3626
p=100

Like? Yes (1) | No (2)  

07 Oct 2014 Percentage

For a sphere of radius 10 cm, the numerical value of the surface area in how many percent of the numerical value of its volume:

OPtion

1) 26.5 %
2) 25 %
3) 24 %
4) 27 %
5) 30 %
6) 34.5 %
7) 45 %
8) 46.5 %
9) 48 %
10)None of these

Solution

Requirement percentage =
(Area*100/ Volume)% = (4*Pi*r^2*100/ (4/3 *Pi*r^2)) %
= (3*100/ r)% = (3*100/ 10)% = 30 %

Option 5)

Correct Option: 5 Best Solution (142)

prem kumar   10 years AGO

volume of a sphere=4/3(pi*r^3)=4186.66
volume of a surface area=4(pi*r^2)=1256
4186*x%=1256
x%=30

Like? Yes (11) | No (3)  

Grishma Shah   10 years AGO

=area /volume X 100%
=3/r X 100%
= 3/10 X 100%
=30%

Like? Yes (7) | No (1)  

Simranjit Singh   10 years AGO

Surface Area= 4*pi*r*r=400*pi
Volume= (4*pi*r*r*r)/3=4000*pi/3
Percentage= [(400*pi)/(4000*pi/3)]*100
= 30%

So option (5)

Like? Yes (6) | No (2)  

BHASKAR MANDAL   10 years AGO

radius, r = 10
surface area = 4*pi*r^2
volume = (4/3)*pi*r^3
so surface area/volume, in percentage = 3r = 30%

Like? Yes (2) | No   

Chandra chur anand   10 years AGO

=(4*pi*r^2*3/4*pi*r^3)*100%
=30%

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Raj   10 years AGO

sphere area=4πr^2,sphere volume=4/3 πr^3
so 30%

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khushboo goenka   10 years AGO

volume=4/3 *pi*r^3
and sur. area=4*pi*r^2
so pecnt=3/r
30

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Piyush   10 years AGO

Surface area=4pir^2
Volume=4/3*pi*r^3
%=sa/vol*100
Ans =30%

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mithilesh kumar   10 years AGO

s.area=4*pi*r*r
vol=(4/3)*pi*r*r*r
so area/vol=3/r=3/10=0.3
so 30%

Like? Yes (1) | No   

ravi prakash   10 years AGO

volume =(4*3.14*10*10*10)/3
surface area=4*3.14*10*10
on solving
(s/v)*100 =30%

Like? Yes (2) | No (1)  

harshit gupta   10 years AGO

surface area=4*pi*r*r=4*pi*10*10=400pi cm sq.
volume=4/3*pi*r*r*r=4/3*pi*10*10*10=4000/3*pi cm cube
perc.= (400pi)/(4000/3*pi)*100
perc.=30%

Like? Yes (2) | No (1)  

harshit gupta   10 years AGO

S.A=4*pi*r*r cm sq.
VOL= 4/3*pi*r*r*r cm cube
perc of S.A=(4*pi*r*r)/(4/3*pi*r*r*r)*100=3/r*100
if r=10
then percentage=3/10*100=30%

Like? Yes (2) | No (1)  

abhishek   10 years AGO

3/r *100

Like? Yes (2) | No (1)  

tirupathi reddy   10 years AGO

4*pi*r*r/(4/3*pi*r*r*r)
=3/r
0.3=30%

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MANU   10 years AGO

(4*pi*r*r)/(4/3*pi*r*r*r)*100=30%

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Vikram   10 years AGO

ans is 30%

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niraj   10 years AGO

area of square = 4*pi*r^2 = 1256
volume of square = 4/3*pi*r^3 = 4186.66
so, 1256/4186.66*100% = 30%

Like? Yes (1) | No   

Kushagra Tiwari   10 years AGO

Surface area = 4 *22/7 *r2
=
3/r(4/3 * 22/7 * r3)
=3/r * VOLUME
Where r = 10 cm
So we have S= 3/10 V
=3/10 *100 % of V
= 30 % of V
So surface area is 30 % of Volume.

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narapureddyyallareddy   10 years AGO

4pi*r^2/(4/3)pi*r^3

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lakshmi nalluri   10 years AGO

4*3.14*100=X/100(4/3*pi*1000)
300/10=x
30% be the ans

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Shreya Tiwari   10 years AGO

Surface Area= 4*pi*r*r=400*pi
Volume= (4*pi*r*r*r)/3=4000*pi/3
Percentage= [(400*pi)/
(4000*pi/3)]*100
= 30%
So option (5)

Like? Yes (1) | No   

santosh kumar patel   10 years AGO

Surface Area= 4*pi*r*r=400*pi
Volume= (4*pi*r*r*r)/3=4000*pi/3
Percentage= [(400*pi)/(4000*pi/3)]*100
= 30%
ans= 30%

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Ayesha Mathur   10 years AGO

4*pi*r*r= 4/3*pi*r*r*r gives 30% will be the answer.

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Abhishek Vishwakarma   10 years AGO

Surface Area= 4*pi*r*r=400*pi
Volume= (4*pi*r*r*r)/3=4000*pi/3
Percentage= [(400*pi)/
(4000*pi/3)]*100
= 30%
So option (5)

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Vansh Johri   10 years AGO

(4(pi)r^2)/(4/3 (pi)r^3)*100

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sandeep kumar   10 years AGO

percentage value=((4*3.14*10*10)/(1.33*3.14*10*10*10))*100=30%

Like? Yes (1) | No   

Udaybhan Viswkarma   10 years AGO

Surface Area of the Sphere/volume of the sphere=[(4*22/7*r^2)/(4/3*22/7*r^3)]
=3/r
=3/10(as radius=10cm)
%=(3/10)*100
%=30

Like? Yes (1) | No   

ANTRISH MISHRA   10 years AGO

area of sphere =1256.64
volume of sphere =4188.79

now
( (4188.79)* X )/ 100 =1256.64
X =30.00

answer is (5)

Like? Yes (1) | No   

pawan kumar   10 years AGO

%age = (s.area * 100)/vol
= [(8800/7) * 100] / (88000/21)
= 30%

Like? Yes (1) | No   

Ritika Shrivastava   10 years AGO

Surface area of sphere=4*3.14*r^2
R=10cm
S.a=4*10*10*3.14
Volume of sphere=4/3*3.14*r^3
=4/3*10*10*10*3.14
%=s.a/volume*100
Ans=30%

Like? Yes (1) | No   

shayali bhartiya   10 years AGO

numerical value=(is/of)*100
surface area =(4*22*10^2)/7(is)
volume=(4*22*10^3)/21(of)
answer will be 30%

Like? Yes (1) | No   

KIRANKUMAR AMBATI   10 years AGO

SA= x% of volume
SA=4*pi*r*r
volume=(4/3)*pi*r*r*r
=> 4*pi*r*r= x% * (4/3)*pi*r*r*r
On simplification:
Required answer = (3/r)*100
= (3/10)*100
=30 %

Like? Yes (1) | No   

anupriya sinha   10 years AGO

volume of sphere =4/3*22/7*r*r
surface area of sphere is =4*22/7*r*r
=> 4*3.14*10*104/3*3.14*10*10*10 =0.30016*100 =30 approx

Like? Yes (1) | No   

Kunal Jaiswal   10 years AGO

Surface area= 4Ï€r^2 = 1256.64
Volume= (4/3)Ï€r^3 = 4188.79
Therefore, (1256.64/4188.79)*100= 30%

Like? Yes (1) | No   

chirashree mitra   10 years AGO

{[(4*3.14*(10)^2)*3]/(4*3.14*(10)^3)} * 100 = 30%

Like? Yes (1) | No   

amit singh   10 years AGO

surface area=4*pi*r*r where pi=3.14
volume=(4*pi*r*r*r)/3...so percent of volume with surface area
is
(surface area/volume)*100......we get 30%

Like? Yes (1) | No   

gowthami medamalli   10 years AGO

surface area=4pi(10)^2
volume=4/3pi(10)^3
3/10*100%a=v
=30%

Like? Yes (1) | No   

Sahil Jain   10 years AGO

Surface area of sphere= 4Ï€r2
Volume of sphere= 4/3 πr3
% =surface area of sphere/volume of sphere
%= 4πr2/(4/3 πr3)
r=10
=(r2*3*100)/r3
=(100*3*100)/1000
=30%

Like? Yes (1) | No   

shashank   10 years AGO

volume of spere= 4.18r*3 = 4180
surface area = 12.57r*2 = 1257
numerical value of the surface area in percent of the numerical value of its volume = (1257/4180).100 = 30%

Like? Yes (1) | No   

siddharth prakash singh   10 years AGO

s.area/vol=4*pi*10*10/(4/3)*pi*10*10*10=3/10
%age= 3/10*100= 30%

Like? Yes (1) | No   

surya   10 years AGO

surface area=4*pi*r*r=4pi*100
valume=4*pi*r^3/3=4pi*1000/3
if you calculate percentage 30%

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J.DHANDAPANI   10 years AGO

V=SA x (10/3)
=> V x(3/10) = SA
=>30 % of V= SA

Like? Yes (1) | No   

Deepu Kumar   10 years AGO

Surface Area= 4*pi*r*r=400*pi
Volume= (4*pi*r*r*r)/3=4000*pi/3
Percentage= [(400*pi)/(4000*pi/3)]*100
= 30%

So option (5)

Like? Yes (1) | No   

Daivashala   10 years AGO

sphere area=4*3.14*r*r
volume=4/3*3.14*r*r*r
percent area=area/volume*100=(4*3.14*10*10)/(4/3*3.14*10*10*10)*100=30%

Like? Yes (1) | No   

siddhartha sadhu   10 years AGO

surface area of sphere=4*pi*r^2
volume of sphere=4/3*pi*r^3
(surface area of sphere/ volume of sphere)*100
30%

Like? Yes (1) | No   

Anand Dwivedi   10 years AGO

Total Surface= 4*pi*r*r
4000*pi/3
So Percentage= [(400*pi)/(4000*pi/3)]*100
= 30%

So Answer Will be 30%

Like? Yes (1) | No   

vanaja   10 years AGO

v=4/3pir^2;
a=4pir^2;

Like? Yes (1) | No   

Pranay Sharma   10 years AGO

Surface Area (SA) of Sphere : 4Ï€(R^2)

Volume Of Sphere, (V) : (4/3)Ï€(R^3)

Therefore, SA = 4Ï€(10^2) and V=(4/3)Ï€(10^3)

Required % = (SA/V)*100
= ( (4Ï€(10^2)) / ((4/3)Ï€(10^3)) )*100
= 30%

Like? Yes (1) | No   

manikanta   10 years AGO

surface area=4*pi*r*r
volume=4/3*pi*r*r*r
answer=30

Like? Yes (1) | No   

Sandeep Kumar   10 years AGO

surface area - 4*pi*r*r= 1256
volume - (4/3)*pi*r*r*r = 4186.6666
so, (1256/4186.66)*100 = 30

Like? Yes (1) | No   

Devesh Gupta   10 years AGO

SA=4*pi*r*r
VOL=(4/3)*pi*r*r*r

%age=SA/vol=30%

Like? Yes (1) | No   

Sanchit Kapoor   10 years AGO

Surface area of a sphere = 4 pi r square =S
volume of a sphere = 4/3 pi r cube = V
thus required percentage= S/V * 100 = 30%

Like? Yes (1) | No   

priya   10 years AGO

30%

Like? Yes (1) | No   

shubham tyagi   10 years AGO

area=4*pi*r^2
volume=(4*pi*r^3)/3
a/v=3/10
a/v%=3/10*100=30%

Like? Yes (1) | No   

Bhanu Pratap Singh   10 years AGO

4pir^2/((4/3)pir^3)= 3/r=.3
now .3*100=30

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Rahul shaw   10 years AGO

30%

Like? Yes (1) | No   

vivek prakash   10 years AGO

surface area=4*pi*r*r
volume=4/3*pi*r*r*r
so percentage=3/r*100=30%

Like? Yes (1) | No   

amit   10 years AGO

area / volume * 100

Like? Yes (1) | No   

saket suman   10 years AGO

surface area 4*pi*r^2
vol4/3*pi*r^3

so ratio 3/r 30%

Like? Yes (1) | No   

Hemadri   10 years AGO

r=10cm
surface area=4*22/7*100=1257.1428
volume=4/3*22/7*1000=4190.1761
% difference =29.33~30%

Like? Yes (1) | No   

Jagruti   10 years AGO

surface area = 4*22/7*10*10

volume = 4/3*22/7*10*10*10

ans = ( surface area / volume ) * 100
=(3/10) * 100
=30

So answer = 30%

Like? Yes (1) | No   

bhishma   10 years AGO

(4*pi*r^2)/(4/3*pi*r^3)*100=(3/r)*100=(0.3*100)=30%

Like? Yes (1) | No   

nishu kumar   10 years AGO

surfrace area=4*pi*r^2
volume=4/3 *pi*r^2=surface area*r/3
surface area=volume*3/r
= volume*3*100/10
=30%0f volume

Like? Yes (1) | No   

mohankumar   10 years AGO

Equalling these two we get 29.9999 so i choose 30 as answer

Like? Yes (1) | No   

ABHILESH PURI GOSWAMI   10 years AGO

Surface area of sphere = 4Ï€(r^2)
Volume of sphere = (4/3)Ï€r^3
% 0f surface area to volume = {[ 4Ï€(r^2) ] / [ (4/3)Ï€r^3 ]}*100
= (3/r)*100
=(3/10)*100
= 30 %
therefore and = option 5

Like? Yes (1) | No   

ADARSH GAURAV   10 years AGO

30% is the answer.

Like? Yes (1) | No   

vinit   10 years AGO

Surface Area= 4*pi*r*r=400*pi
Volume= (4*pi*r*r*r)/3=4000*pi/3
Percentage= [(400*pi)/(4000*pi/3)]*100
= 30%

So option (5)

Like? Yes (1) | No   

Irfan   10 years AGO

Volume of sphere = (4/3)*pi*r^3
Surface area of sphere = 4*pi*r^2
((surface area)/(volume))*100

Like? Yes (1) | No   

anuj gupta   10 years AGO

30%

Like? Yes (1) | No   

laxmi   10 years AGO

suface area of sphere=4pier^2
volume of shere=4/3 pie r^3
hence ratio% will be=3/r%100=30%

Like? Yes (1) | No   

shareef   10 years AGO

required % = (Surface area / Volume) *100
==== 30%

Like? Yes (1) | No   

Rahul Kumar Singh   10 years AGO

Surface area= 4*pie*r^2
Volume=(4/3) pie*r^3
Percent=surface area/volume
=3/r*100
=30

Like? Yes (1) | No   

Arijit Acharyya   10 years AGO

let, the numerical value of the surface area is x% of the numerical value of its volume.
then, 4*pi*r^2=x%*(4/3*pi*r^3)
1=x%*(r/3)
x%=3/r
now, r=10 cm given
x%=3/10=0.3
x=30%
option 5)

Like? Yes (1) | No   

ARJUN M DANDAGI   10 years AGO

x=surfce area =4*pi*r*r
y=volume=4/3*pi*r*r*r
let x=zy
then z becomes 3/r which is o.3 in % it is 30%

Like? Yes (1) | No   

dhanaseelan   10 years AGO

Surface area=4*pi*r^2
Volume =(4*pi*r^3)/4
Ratio =300/r=30%

Like? Yes (1) | No   

pritika singh   10 years AGO

ac to formula

Like? Yes (1) | No   

vicky kumar   10 years AGO

(SA of sphere/ volume of sphure )*100 = 30%

putting radius=10cm in the formula

Like? Yes (1) | No   

Pulokesh Ghosh   10 years AGO

S area = 4 X (pi) X 10^2
vol = 4/3 X (pi) X 10^3
S area/vol = 3/10
%age = 3/10*100%
= 30%
Ans. 5(30%)

Like? Yes (1) | No   

urvish   10 years AGO

area-1256
vol-4188.80
so % is30%

Like? Yes (1) | No   

vinayak choubey   10 years AGO

by using formulae and calcualtion

Like? Yes (1) | No   

Sk Monjurul Haque   10 years AGO

Area=4*3.14*(r)2
Volume=4/3*3.14*(r)3.
so volume=(r*area)/3
now let area is x percent of numerical value of volume.
V*x/100=A
now, (r*A)/3 *x/100=A.
by solving this we get x=30.
so the answer is 30%.

Like? Yes (1) | No   

praveen   10 years AGO

v=4*3.14*r^3
s=4*3.14*r^2

Like? Yes (1) | No   

dee hack kr   10 years AGO

4000pi/3=volume, 400pi/=area
so,(400pi/(4000pi/3))*100=30%

Like? Yes (1) | No   

Gitanjali K   10 years AGO

percentage (%) = (area/volume)*100
= 30%

Like? Yes (1) | No   

adit choudhary   10 years AGO

((4*3.14*100)/((4/3)*3.14*1000))*100
=30%

Like? Yes (1) | No   

Anusha   10 years AGO

area=4*100*pie
volum=4/3*pie*1000

%=area/vol *100=30%

Like? Yes (1) | No   

Arkja tiwari   10 years AGO

area= 4pir^2/(4/3pir^3)
=0.3
30%

Like? Yes (1) | No   

Rashi Bansal   10 years AGO

the required percentage is (4 *3.14 *r^2 ) *100 / (4* 3.14 * r^3)
=3*100 / r
=30%

Like? Yes (1) | No   

RISHABH SHARMA   10 years AGO

3/r×100=30%

Like? Yes (1) | No   

Shankar Jha   10 years AGO

v=4/3*pie*r3=4000pie/3*100
s.a=4pie*r2=400*pie
s.a/v*100=30

Like? Yes (1) | No   

V.Mahesh   10 years AGO

surface area=Pi*d^2=22/7*20*20=1257.142
volume of sphere=pi/6*d^3=22/7*6*20*20*20=4190.476

S.A/Volume=29.9999 =30%

Like? Yes (1) | No   

Sayantan Bhattacharya   10 years AGO

Surface area/volume * 100 %
= 4*pi*r^2/(4/3*pi*r^3)
=3/10*100
=30

Like? Yes (1) | No   

A Rafi   10 years AGO

surface area of sphere 4*pi*r2
volume of sphere 4/3*pi*r3
%=surface area/volume *100 = 3/r*100=30%

Like? Yes (1) | No   

N SAI KRISHNA SRIKAR   10 years AGO

since SA=4*pi*r*r AND VOL=4*pi*r*r*r/3
SO RATIO OF SA/VOL=300/r=300/10=30%

Like? Yes (1) | No   

Abhishek Shah   10 years AGO

4Pir^2/4/3 pi R^3

Like? Yes (1) | No   

murari kumar   10 years AGO

ratio of surface area to volume of sphere is ( 3/r)
therefore - 3/10= 0.3
ans-30%

Like? Yes (1) | No   

Amara Rajalakshmi   10 years AGO

4*pi*rsquare = x% of (4/3)*pi*rcube

Like? Yes (1) | No   

ankit shukla    10 years AGO

Surface area=400*3.14
Volume=4*3.14*1000/3

Like? Yes (1) | No   

Mani kandan   10 years AGO

Surface area = 4 *22/7 *r2
=
3/r(4/3 * 22/7 * r3)
=3/r * VOLUME
Where r = 10 cm
So we have S= 3/10 V
=3/10 *100 % of V
= 30 % of V
So surface area is 30 % of Volume.

Like? Yes (2) | No (1)  

Shashank Agarwal   10 years AGO

Like? Yes (1) | No   

Jigyasa Kumar   10 years AGO

400pie = x/100 * 4000pie/3
x = 30%

Like? Yes (1) | No   

Subhosmit Choudhury   10 years AGO

V=4/3*Pi*r^3
SA=4*pi*r^2

therefore
SA/v=0.3
=>30%

Like? Yes (1) | No   

abhilasha   10 years AGO

400pi = x/100 * 4000pi/3
x = 30%

Like? Yes (1) | No   

Mithun Kumar Kesari   10 years AGO

30%

Like? Yes (1) | No   

ANUP KUMAR GUPTA   10 years AGO

since volume of a sphere =4/3pi r^3
and suraface area of sphere =4 pi r^2

by solving in percentage 30 %

Like? Yes (1) | No   

Soham Chakraborty   10 years AGO

volume/surface area

Like? Yes (1) | No   

vikas singh   10 years AGO

volume =4/3pi (10)qb
surface=4pi (10)sqr

%= (surface*100)/volume

Like? Yes (1) | No   

Rajat Jain   10 years AGO

Surface Area= 4*3.14*r^2
Volume = 4/3*3.14*r^3

Like? Yes (1) | No   

venkatesh   10 years AGO

Surface Area= 4*pi*r*r=400*pi
Volume= (4*pi*r*r*r)/3=4000*pi/3
Percentage= [(400*pi)/(4000*pi/3)]*100
= 30%

Like? Yes (1) | No   

CHANDAN KUMAR   10 years AGO

v=4*3.14*10^3/3
s=4*3.14*10^2
s*100/v=3*100/10=30%

Like? Yes (1) | No   

Onkar Nath Sharma   10 years AGO

% asked here = ((surface area)/(volume)) * 100
= (3/radius ) * 100
= (3/10) * 100
= 30%

Like? Yes (1) | No   

Mahesh   10 years AGO

The surface area is 4 pi r square and the volume is 4/3 pi r cube
The ratio of surface area to volume is 3 to r, so 3 to 10, which is eaqual to 30%

Like? Yes (2) | No (2)  

Ravi Kumar   10 years AGO

(4*pi*10*10)/(4/3*pi*10*10*10)*100=30%

Like? Yes (2) | No (2)  

Sundar Kumar   10 years AGO

SOLUTION:
Surface area = 4 *22/7 *r2
= 3/r(4/3 * 22/7 * r3)
=3/r * VOLUME
Where r = 10 cm
So we have S= 3/10 V
=3/10 *100 % of V
= 30 % of V
So surface area is 30 % of Volume.
Answer: Option 5) 30%

Like? Yes (2) | No (2)  

shekhar suman   10 years AGO

surface area of sphere=4*22/7*r*r
volume=4/3*22/7*r*r*r
so
surface area/volume={(4*22/7*r*r)/(4/3*22/7*r*r*r)}*100%=30%

Like? Yes (1) | No (1)  

Devendra Marghade   10 years AGO

=100*[4*Pi*r^2]/(4/3)*Pi*r^3]
=100*(4*3)/(4*10)
=30

Like? Yes (1) | No (1)  

Tania Chatterjee   10 years AGO

Surface area = 4 *22/7 *r2
=
3/r(4/3 * 22/7 * r3)
=3/r * VOLUME
Where r = 10 cm
So we have S= 3/10 V
=3/10 *100 % of V
= 30 % of V
So surface area is 30 % of Volume.

Like? Yes (1) | No (1)  

vartika    10 years AGO

VOLUME=4/3*PI*10^3
SURFACE AREA= 4*PI*R^2
=> s.a = 30% of volume

Like? Yes (1) | No (1)  

Md.Sultan Khichi   10 years AGO

Surface area=4r^2
Volume=4/3r^3
4r^2/(4/3r^3)*100=30%
Ans. 30%

Like? Yes (1) | No (1)  

AAKANCHA SRIVASTAV   10 years AGO

surface area=4*22/7*10*10
volume=4/3*22/7*10*10*10
percent= surface area/volume*100

Like? Yes (1) | No (1)  

Supriya_kamkar   10 years AGO

surface area of sphere=4 PI r^2
volume of sphere=(4/3)PI r^3


surface area/volume=(3/r)=(3/10)

=30%

Like? Yes (1) | No (1)  

Aastha   10 years AGO

surface area=4pi r^2
vol.=4/3 pi r^3
percantage=surface area/vol.*100
=3/r*100
=30%

Like? Yes (1) | No (1)  

Sukanya   10 years AGO

Surface area of sphere= 4*PI*r^2
Volume of sphere=4*PI*r^3

r=10
surface area=400 PI
volume=4000/3 PI
SA:Volume
400:4000/3
Mul by 3 on both sides
1200:4000
Which is 30%

Like? Yes (1) | No (1)  

Akshay   10 years AGO

4*3.14*10*10*100*3/4*3.14*10*10*10=30%

Like? Yes (1) | No (1)  

S.SHAFI   10 years AGO

Surface area = 4 *pi *r^2
= 3/r(4/3 * 22/7 * r3)
= 3/r * VOLUME
Where r = 10 cm
So we have S= 3/10* V
=3/10 *100 % of V
= 30 % of V
So surface area is 30 % of Volume.

Like? Yes (1) | No (1)  

VIMALRAJ V   10 years AGO

Surface area = 4 *22/7 *r2
=
3/r(4/3 * 22/7 * r3)
=3/r * VOLUME
Where r = 10 cm
So we have S= 3/10 V
=3/10 *100 % of V
= 30 % of V
So surface area is 30 % of Volume

Like? Yes (1) | No (1)  

Chirag Ranjan Lahiri   10 years AGO

Surface area = 4 *22/7 *r2
=
3/r(4/3 * 22/7 * r3)
=3/r * VOLUME
Where r = 10 cm
So we have S= 3/10 V
=3/10 *100 % of V
= 30 % of V
So surface area is 30 % of Volume.

Like? Yes (1) | No (1)  

Sandeep mishra   10 years AGO

percent =((400*3.14)/(4000*3.14/3))*100 = 30 %

Like? Yes (1) | No (1)  

Batthula Kondaiah   10 years AGO

surface area of sphere is 4*pi*r^2
volume=4/3 (pi*r^3)
percent means surface area/volume=3*100/10=30%

surface area/volume = 4*pi*r*r/(4/3*pi*r*r*r)=3/r

Like? Yes (1) | No (1)  

mamta garkoti   10 years AGO

4*22/7*10*10/ 4*3.14*10^3= 31.2 =30 approx

Like? Yes (1) | No (1)  

jyoti   10 years AGO

Surface area = 4 *22/7 *r2
=
3/r(4/3 * 22/7 * r3)
=3/r * VOLUME
Where r = 10 cm
So we have S= 3/10 V
=3/10 *100 % of V
= 30 % of V
So surface area is 30 % of Volume.

Like? Yes (1) | No (1)  

Narasapu Hari prasad   10 years AGO

surface of a sphere is 4*pi*r*r=4*3.14*1o*1o=1256.63
volume of sphere is 4/3*pi*r*r*r=4/3*3.14*10*10*10=4188.790
so percentage =1256.63*100/4188.790=30

Like? Yes (1) | No (1)  

DIPAK TIWARI   10 years AGO

Surface area=4Ï€r^2
Volume=(4Ï€r^3)/3
So percentage=[4Ï€r^2/(4Ï€r^3)/3]*100
=>3*100/r
=>30%

Like? Yes (1) | No (1)  

ANKUR ANAND   10 years AGO

Surface area of sphere=4*pi*r*r
volume of sphere=4*pi*r*r*r/3
Req. percent=3*100/10=30%

Like? Yes (1) | No (1)  

Neel Patel   10 years AGO

30%

Like? Yes (1) | No (1)  

Avinash roy   10 years AGO

Surface area = 4 *22/7 *r2
=
3/r(4/3 * 22/7 * r3)
=3/r * VOLUME
Where r = 10 cm
So we have S= 3/10 V
=3/10 *100 % of V
= 30 % of V
So surface area is 30 % of Volume

Like? Yes (1) | No (1)  

Sagar Kumar Subudhi   10 years AGO

volume=(4000/3)Ï€
area=400Ï€
100%=(4000/3)Ï€
1%=(40/3)Ï€
so, 400Ï€=400Ï€/(40Ï€/3)
ans is 30%

Like? Yes (1) | No (1)  

udit   10 years AGO

volume of sphere = 4 * π* 10^3 = 4000π/3
area of sphere =4 * π * 10^2 =400π
percentage =400Ï€*3*100/4000Ï€ =30%

Like? Yes (1) | No (1)  

Deb Das   10 years AGO

surface area/volume=(4*22/7*10^2)/(4/3*22/7*10^3)=3/10
So the ans is (3/10*100)% or 30%

Like? Yes (1) | No (1)  

MRITUNJAY KUMAR   10 years AGO

30

Like? Yes (1) | No (1)  

RAKESH   10 years AGO

(4*pi*r^2) /( 4/3 *pi*r^3) * 100

= 3/r * 100
put r=10
= 30 %

Like? Yes (1) | No (2)  

Surit Datta   10 years AGO

We know if r is the radius of the sphere
then it's surface area is 4*pi*r*r
and it's volume is (4*pi*r*r*r)/3
according to this formula
its surface area is 1256.64 cm sq.
and it's volume is 4188.79 cm cube
according to the numerical value we get that
the surface area is 30 % of the volume
that's it..

Like? Yes (1) | No (2)  

06 Oct 2014 Sequence

What is the next number of the following sequence
1, 3, 6, 10, 15, ......

OPtion

1) 35
2) 28
3) 19
4) 20
5) 18
6) 16
7) 30
8) 40
9) 51
10)None of these

Solution

Differences are 2,3,4,5,6 Correct

Option: 10

Correct Option: 10 Best Solution (139)

Kushagra Tiwari   10 years AGO

It's simply the triangular numbers:
1=1
1+2=3
1+2+3=6
1+2+3+4=10
and so on.
You could use the formula n(n+1)/2
to determine the nth triangular
number (ie the sum of the first n
numbers)

Like? Yes (25) | No (2)  

prem kumar   10 years AGO

3-1=2
6-3=3
10-6=4
15-10=5
so next number difference must be 6
so x-15=6
There fore x=21
None of the above

Like? Yes (8) | No (1)  

S.SHAFI   10 years AGO

1,3,6,10,15....

1 + 2 = 3
3 + 3 = 6
6 + 4 = 10
10 + 5 = 15
15 + 6 = 21....

Like? Yes (5) | No   

Sourojit Dhua   10 years AGO

1+2=3
3+3=6
6+4=10
10+5=15
15+6=21
Hence the next number should be 21 which is not in option. Besides;
This is the Triangular Number Sequence: 1, 3, 6, 10, 15, 21, 28, 36, 45, ... This sequence is generated from a pattern of dots which form a triangle.

Like? Yes (4) | No   

NAVEEN KUMAR   10 years AGO

1=1
1+2=3
1+2+3=6
1+2+3+4=10
1+2+3+4+5=15
1+2+3+4+5+6=21

Like? Yes (3) | No   

Aastha   10 years AGO

next no. will be 21
as difference between two no is in the increasing order
3-1=2
6-3=3
10-6=4
15-10=5
21-15=6

Like? Yes (5) | No (2)  

lakshmi nalluri   10 years AGO

21 will be next in the sequence

Like? Yes (2) | No   

santosh kumar patel   10 years AGO

1
1+2=3
3+3=6
6+4=10
10+5=15
15+6=21
hence ans:none of these

Like? Yes (2) | No   

Sandeep mishra   10 years AGO

1+2=3
3+3=6
6+4=10
10+5=15
15+6=21
so 21 is correct answer

Like? Yes (2) | No   

Rittik Mondal   10 years AGO

1
1+2 = 3
3+3 = 6
6+4 = 10
10+5= 15
15+6= 21;
so next number should be 21

Like? Yes (2) | No   

BHASKAR MANDAL   10 years AGO

it is of the form n(n+1)/2
1(2)/2 = 1
2*3/2 = 3
3*4/2 = 6
4*5/2 = 10
5*6/2 = 15
6*7/2 = 21

so the next number will be 21
option will be none of these

Like? Yes (1) | No   

Sanchit Kapoor   10 years AGO

Each succeeding number is obtained by adding consecutive natural number starting from 2 to the previous number
3=1+2
6=3+3
10=6+4
15=10+5 and so the next number should be 15+6=21
so option 10 none of these is correct.

Like? Yes (3) | No (2)  

vinit   10 years AGO

1,1+2=3,3+3=6,6+4=10,10+5=15,15+6=21;
so it should be 21 hence non of these

Like? Yes (1) | No   

Gitanjali K   10 years AGO

next no. should be 21

Like? Yes (2) | No (1)  

Ravi Bhalani   10 years AGO

next number should be 21

Like? Yes (1) | No   

vartika    10 years AGO

1+2=3
3+3=6
6+4=10
10+5=15
15+6=21

Like? Yes (1) | No   

dhanaseelan   10 years AGO

As per the sequence the answer must be 21

Like? Yes (1) | No   

Udhaya kumar   10 years AGO

addition of 2,3,4,5,6 respectively.........

Like? Yes (1) | No   

Udaybhan Viswkarma   10 years AGO

This is the Triangular Number Sequence:

1, 3, 6, 10, 15, 21, 28, ....

So, x(n) = n(n+1)/2
x(6)=6(6+1)/2
x(6)=21

Like? Yes (1) | No   

Pratik sharma   10 years AGO

i think difference is going like 2,3,4,5 ..so next term should be 21

Like? Yes (1) | No   

Kunal Jaiswal   10 years AGO

21 should be answer. So none of these.

Like? Yes (1) | No   

~Sandeep~   10 years AGO

This is the Triangular Number Sequence: 1, 3, 6, 10, 15, 21, 28, 36, 45,

Like? Yes (1) | No   

Chandra chur anand   10 years AGO

each no. is incremented by +1
like 1 then
1+2=3
3+3=6
6+4=10
10+5=15
15+6=21
so 21 ll be right ans

Like? Yes (1) | No   

DEEPAK GOSWAMI   10 years AGO

the difference is .. 2 , 3, 4, 5, 6 resp.

Like? Yes (1) | No   

kumar   10 years AGO

21

Like? Yes (1) | No   

prabhat   10 years AGO

1
1+2=3
3+3=6
6+4=10
then 15+6=21

Like? Yes (1) | No   

anupriya sinha   10 years AGO

1+2 =3
3+3=6
6+4 =10
10+5=15
15+6=21
21+7=28
28+9=37
and so on

Like? Yes (1) | No   

Abhishek Vishwakarma   10 years AGO

It's simply the triangular numbers:
1=1
1+2=3
1+2+3=6
1+2+3+4=10
and so on.
You could use the formula n(n+1)/2
to determine the nth triangular
number (ie the sum of the first n
numbers)

Like? Yes (1) | No   

Shashank Kapoor   10 years AGO

the number should be 21 as going by the series,as it is not there so answer is option 10 none of these..

Like? Yes (1) | No   

PAWAN KUMAR   10 years AGO

The next no will be 21.
1+2 = 3+3 = 6+4 =10+5 = 15+6 21 Ans.

Like? Yes (1) | No   

Sukanya   10 years AGO

1+2=3
3+3=6
6+4=10
10+5=15
15+6=21

Like? Yes (1) | No   

Jigyasa Kumar   10 years AGO

it is the triangular sequence 21, then 28, ....

Like? Yes (1) | No   

Chirag Ranjan Lahiri   10 years AGO

Simple, it must be 21 which is not in option, so ans - 10

Like? Yes (2) | No (1)  

abhilasha   10 years AGO

it is the triangular sequence 21, then 28, ....

Like? Yes (1) | No   

shreya sagar   10 years AGO

ans:(10)none of these
because next term is 21
1+2=3
3+3=6
6+4=10
10+5=15
15+6=21

Like? Yes (1) | No   

khushboo goenka   10 years AGO

21.
coz diff b/w each no is 2,3,4,5
so 3+3=6,6+4=10, 10+5=15,15+6=21

Like? Yes (1) | No   

Anitha   10 years AGO

Answer is 21, 1+2=3, 3+3=6, 6+4=10, 10+5=15, Answer - 15+6=21

Like? Yes (1) | No   

ragini   10 years AGO

answer 21 ... 1+2=3+3=6+4=10+5=15+6=21+7=28+.....

Like? Yes (1) | No   

pankaj   10 years AGO

since the difference between the consecutive numbers is sequencially increasing. thats why the next no. comes out to be 21 which is not from the above mentioned options......

Like? Yes (1) | No   

Supriya_kamkar   10 years AGO

1+2=3
3+3=6
6+4=10
10+5=15
15+6=21
ans:21

Like? Yes (1) | No   

Manish kumar   10 years AGO

diff b/w 1 & 3=2
3&6=3
6&10=4
10&15=5
then next is 6
ans = 15+6=21

Like? Yes (1) | No   

Nithin Kumar   10 years AGO

1
1+2=3
1+2+3=6
1+2+3+4=10
1+2+3+4+5=15
1+2+3+4+5+6=21

Like? Yes (1) | No   

Ankit Pandey   10 years AGO

1+2=3
3+3=6
6+4=10
10+5=15
So next term
15+6=21

Like? Yes (1) | No   

VIMALRAJ V   10 years AGO

The given series is a triangular series. Therefore the next number must be 21, it is not present in the option so answer is NONE OF THESE

Like? Yes (1) | No   

Mahesh   10 years AGO

10+5=15
15+6=21
so, 21 is the answer

Like? Yes (1) | No   

Neel Patel   10 years AGO

Option 10

Like? Yes (1) | No   

SAURISH KAR   10 years AGO

The difference bteween every consecutive number increases by 1

Like? Yes (1) | No   

mithilesh kumar   10 years AGO

since the diffrence b/w two consecutive no is in increasing order i.e 2,3,4,5,so next is =6
so no is=15+6=21

Like? Yes (1) | No   

ramakrishnateja   10 years AGO

the series is given as follows. 1,3,6,10,15.......... the next number after 15 is 21 the difference of the terms are
3-1=2
6-3=3
10-6=4
15-10=5
21-15=6.
so the number is 21.

Like? Yes (1) | No   

Perumal   10 years AGO

1, 1+2=3,1+2+3=6,1+2+3+4=10,1+2+3+4+5=15,1+2+3+4+5+6=21

Like? Yes (1) | No   

Albin Mathew   10 years AGO

the correct answer is 21.Because the differences between consecutive terms is in the progression:2,3,4,5,6.................

Like? Yes (1) | No   

SAI TEJA   10 years AGO

0+1=1
1+2=3
3+3=6
6+4=10
10+5=15

Like? Yes (1) | No   

jalaj   10 years AGO

In each of these numbers difference betwwen each digit is increasing So the next number in the sequence is 21(Hence option 10)
Ex 1 3 diff 2
3 6 diff 3
6 10 diff 4
10 to 15 diff 5
15 to 21 dii 6

Like? Yes (1) | No   

RADHA RANI   10 years AGO

no answer is matching

Like? Yes (1) | No   

Surit Datta   10 years AGO

It's simply the triangular numbers:
1=1
1+2=3
1+2+3=6
1+2+3+4=10
1+2+3+4+5=15
1+2+3+4+5+6=21
or the sequence n(n+1)/2 where n=1,2,3,.....
That's it..

Like? Yes (1) | No   

archanarao rane   10 years AGO

1+2=3
3+3=6
6+4=10
10+5=15
15+6=21

Like? Yes (1) | No   

mamta garkoti   10 years AGO

it should be 21

Like? Yes (1) | No   

Anusha   10 years AGO

ans is 21
1
1+2=3
1+2+3=6
1+2+3+4=10
1+2+3+4+5=15
1+2+3+4+5+6=21

Like? Yes (1) | No   

Anand Dwivedi   10 years AGO

1=1
1+2=3
1+2+3=6
1+2+3+4=10
1+2+3+4+5=15
1+2+3+4+5+6=21

So Answer Will be 21

Like? Yes (1) | No   

Rounak Jain   10 years AGO

Ans is 21. 0+1=1, 1+2=3, 3+3=6, 6+4=10, 10+5=15 so 15+6=21.

Like? Yes (1) | No   

niraj   10 years AGO

1,3,6,10,15,?
3-1=2
6-3=3
10-6=4
15-10=5
x-15=6
x=21(ans)

Like? Yes (1) | No   

saimeera   10 years AGO

1+ 2 =3
3+ 3 =6
6+ 4 =10
10+ 5 =15
15+ 6 =21

NONE OF THESE (21)

Like? Yes (1) | No   

sindhu   10 years AGO

1+2=3
3+3=6
6+4=10
10+5=15
15+6=21

Like? Yes (1) | No   

ankit   10 years AGO

differ 2 ,3,4,5 then 6
ans 21

Like? Yes (1) | No   

priyanka   10 years AGO

3-1=2
6-3=3
10-6=4
15-10=5
21-15=6
sequence number is answer,each number difference is sequence numbers

Like? Yes (1) | No   

Pravena   10 years AGO

answer is 21

Like? Yes (1) | No   

PALASH JAIN   10 years AGO

answer should be 21

Like? Yes (1) | No   

csemalli   10 years AGO

answer is 21

it is first n natural numbers sum

Like? Yes (1) | No   

surya   10 years AGO

1+2=3
3+3=6
6+4=10
10+5=15
15+6=21
this option not there in options

Like? Yes (1) | No   

Durgesh Tripathi   10 years AGO

Correct Answer =21
1+2=3
3+3=6
6+4=10
10+5=15
15+6=21

Like? Yes (1) | No   

Akash Dhananjay Pahurkar    10 years AGO

First we added 2 then 3 then 4,5.
Then 15+6=21

Like? Yes (1) | No   

upasana acharya   10 years AGO

no increasing by 1,2,3,4.... so on

Like? Yes (1) | No   

shubham tyagi   10 years AGO

1+2=3
3+3=6
6+4=10
10+5=15
15+6=21

Like? Yes (1) | No   

Pallab Das   10 years AGO

1+ 3+ 6+ 10 +15 +21
2 3 4 5 6

Like? Yes (1) | No   

Dr.Dipin Singh   10 years AGO

15+6=21

Like? Yes (1) | No   

v pavan   10 years AGO

15+6=21
1+2=3
3+3=6
6+4=10
10+5=15

Like? Yes (1) | No   

Bidulata   10 years AGO

difference is in a sequence of 2 3 4 5 6

Like? Yes (1) | No   

Ritika Shrivastava   10 years AGO

1,3,6,10,15
Next no is 21
1+2=3
3+3=6
6+4=10
10+5=15
So 15+6=21
Next no is 21
Option 10

Like? Yes (1) | No   

Sagar Kumar Subudhi   10 years AGO

3-1=2
6-3=3
10-6=4
15-10=5
similarly next difference should be 6, so 15+6=21
but no in the options so ans is option 10(none of these)

Like? Yes (1) | No   

shekhar suman   10 years AGO

1,3,6,10,15,.....
1+2=3
3+3=6
6+4=10
10+5=15
so
15+6=21 ans

Like? Yes (1) | No   

Amit   10 years AGO

diffrences are 2 3 4 5 6

Like? Yes (1) | No   

siddhartha sadhu   10 years AGO

(1) 2 (3) 4 5 (6) 7 8 9 (10) 11 12 13 14 (15) 16 17 18 19 20 (21).
the number with in the bracket is given . so the next number is 21.

Like? Yes (1) | No   

Sumeet Gupta   10 years AGO

Next will be 21

Like? Yes (1) | No   

AAKANCHA SRIVASTAV   10 years AGO

15+6=21

Like? Yes (1) | No   

MUKESH YADAV   10 years AGO

it would be 21

Like? Yes (1) | No   

satyam shivam   10 years AGO

It's simply the triangular numbers:
1=1
1+2=3
1+2+3=6
1+2+3+4=10

and so on.

Like? Yes (1) | No   

swapnil saxena   10 years AGO

diff is 2,3,4,5, then 6 =21

Like? Yes (1) | No   

vinay kumar m   10 years AGO

ans is 21(15+6)

Like? Yes (1) | No   

vishal shanker polowalia   10 years AGO

diference of 2,3,4,5 and 6 so on
so next nomber is 21

Like? Yes (1) | No   

ganesh babu   10 years AGO

1,1+2=3,3+3=6,6+4=10,10+5=15,15+6=21

Like? Yes (1) | No   

Abhirup Kundu   10 years AGO

difference is 2,3,4,5 and so on

Like? Yes (1) | No   

Shuja Malik   10 years AGO

21 will be the answer

Like? Yes (1) | No   

RISHABH RAJ   10 years AGO

3-1=2, 6-3=3, 10-6=4, 15-10=5 so next difference will be 6 ...i.e 15+6 =21..which is not available

Like? Yes (1) | No   

tirupathi reddy   10 years AGO

The diff is 2,3,4,5,6...
21 is answer

Like? Yes (1) | No   

Shaily Aggarwal   10 years AGO

should be 21

Like? Yes (1) | No   

sirisha   10 years AGO

the order is 1+2=3,3+3=6,------,15+6=21
there is no 21 present

Like? Yes (1) | No   

pawan kumar   10 years AGO

Next no. should be : 15+6=21

Like? Yes (1) | No   

CHANDAN KUMAR   10 years AGO

1+2=3
3+3=6
6+4=10
10+5=15
15+6=21

Like? Yes (1) | No   

Piyush   10 years AGO

The ans is 21
There is increasing difference between the no's
1, 3, 6, 10...
So between 1 and 3, 2 is the only no
So one no
Then between 3 and 6
Two no are present 4 and 5
And the process is repeated

Like? Yes (1) | No   

Komala.G   10 years AGO

1
1+2 =3
3+3 =6
6+4 =10
10+5 = 15
15+6 =21

Like? Yes (1) | No   

ravi   10 years AGO

1+2=3
3+3=6
6+4=10
10+5=15
15+6+21

Like? Yes (1) | No   

RenukaDevi   10 years AGO

answer is 21 bcz sequence is like
1+2=3
3+3=6
6+4=10
10+5=15
15+6=21

Like? Yes (1) | No   

Arpit Jain   10 years AGO

1+2=3
3+3=6
6+4=10
10+5=15
15+6=21
So answer is 10) None of these

Like? Yes (1) | No   

Yugandhara Shete   10 years AGO

1
1+2=3
3+3=6
6+4=10
10+5=15
15+6=21
non of these

Like? Yes (1) | No   

rajeev chaubey   10 years AGO

1,3,6,10,15,21

Like? Yes (1) | No   

Deepika Dubey   10 years AGO

the ans will be 21
1+2=3
3+3=6
6+4=10
10+5=15
15+6=21

Like? Yes (1) | No   

ankit tiwari   10 years AGO

3-1=2
3=(2+1)=6
6-3=3
6+(3+1)=10
a it is
ans shud be 21

Like? Yes (1) | No   

priyanka sharma   10 years AGO

1-3=2
6-3=3
10-6=4
15-x=5

Like? Yes (1) | No   

Sakshi Agarwal   10 years AGO

1+2=3
3+3=6
6+4=10
10+5=15
15+6=21 (option not given)

Like? Yes (1) | No   

Aritra Chatterjee   10 years AGO

+2 +3 +4 .....

Like? Yes (1) | No   

MANU   10 years AGO

1+2=3
3+3=6
6+4=10
10+5=15
15+6=21;
ans is 21

Like? Yes (1) | No   

ravi prakash   10 years AGO

1+2=3
3+3=6
6+4=10
10+5=15
15+6=21

Like? Yes (1) | No   

Puspendu Bhowmick   10 years AGO

1st increses by 2 then 3
so ans is 21

Like? Yes (1) | No   

Grishma Shah   10 years AGO

Answer is 21 which is not given in list.

1
3 = 1 +2
6 = 3 +3
10 = 6 +4
15 = 10 +5
21 = 15 +6

Like? Yes (1) | No   

nehasrivastava   10 years AGO

21 should be the answer

Like? Yes (1) | No   

KIRANKUMAR AMBATI   10 years AGO

since the answer is 211123123612345621

Like? Yes (1) | No   

narapureddyyallareddy   10 years AGO

15621so non of the options

Like? Yes (1) | No   

anuj gupta   10 years AGO

21

Like? Yes (1) | No   

Ankit   10 years AGO

21

Like? Yes (1) | No   

harshit gupta   10 years AGO

21

Like? Yes (1) | No   

ilamparithi   10 years AGO

12333664101051515621

Like? Yes (1) | No   

Priyam   10 years AGO

12333664101051515621

Like? Yes (1) | No   

Ravi Kumar   10 years AGO

01112333664101051515621ans none of these

Like? Yes (1) | No   

bikash tiwari   10 years AGO

21 is the right answer

Like? Yes (1) | No   

Souvik Basak   10 years AGO

3-12 6-3310-6415-10521-615

Like? Yes (1) | No   

rakesh   10 years AGO

21 should be the ans

Like? Yes (1) | No   

Akshay Kumar Jain   10 years AGO

The ans would be 21 As the in the series the difference is in the series like 3-12 6-3310-6415-105 therefore 21-156

Like? Yes (1) | No   

Bhanu Pratap Singh   10 years AGO

consecutive difference of terms is 2345 so next term will be 15621

Like? Yes (1) | No   

MRSwetha   10 years AGO

it should be 2112333664101051515621

Like? Yes (1) | No   

arpit agarwal   10 years AGO

112333664101051515621

Like? Yes (1) | No   

bhishma   10 years AGO

12333664101051515621

Like? Yes (1) | No   

anudeep   10 years AGO

difference between two numbers is increasing by one

Like? Yes (1) | No   

jhansi   10 years AGO

12333664101051515621

Like? Yes (1) | No   

Deepu Kumar   10 years AGO

AQ Option 10 is correct

Like? Yes (1) | No   

shivakrishna   10 years AGO

1231051515621

Like? Yes (1) | No   

Simranjit Singh   10 years AGO

12 333 664 1010515156 21So None of these

Like? Yes (1) | No   

Ritesh Kumar   10 years AGO

21

Like? Yes (1) | No   

vatan singh   10 years AGO

1361015the difference between no is 2345 ie an AP therefore next nois 6hence next no is 15621ans 21

Like? Yes (1) | No   

RAKESH   10 years AGO

next no. = 15+6 = 21
10) none

Like? Yes (1) | No (2)  

03 Oct 2014 Profit

A packet of toffee contains 57 toffees. The cost of packet is 44 rupee but every toffee is sold in 1 rupee separately. Find the percentage profit on selling the toffees one by one relative to sell the packet.

OPtion

1) 25
2) 35
3) 40
4) 30
5) 20
6) 45
7) 37
8) 28
9) 22
10)None of these

Solution

{(57/44)*100} - 100 = 29.55 (approx 30)

Correct Option: 4 Best Solution (56)

Kushagra Tiwari   10 years AGO

{(57/44)*100} � 100 = 29.55 (approx
30)

Like? Yes (47) | No (7)  

RAKESH   10 years AGO

(57-44)/44 * 100

= 13/44 * 100
= 29.54
~ 30%

Like? Yes (27) | No (16)  

Simranjit Singh   10 years AGO

Option (4)

CP of tofees= Rs 44
SP of tofees= Rs 1 *57 = Rs 57
Profit=Rs 57- Rs 44= Rs 13
Profit%=(13/44)*100=29.54% = 30%

Like? Yes (15) | No (10)  

shreya sagar   10 years AGO

profit on selling the packet= selling price-cost price
=44-44= 0
profit on selling the toffee one by one=57-44=13
relative profit = 13-0 =13
relative profit%=13/44 * 100 = 29.54 % = apprx 30%

Like? Yes (5) | No (1)  

vishal shanker polowalia   10 years AGO

Cp of 57 tofee =44
sp of 57 tofee =57
profit = 13
Profitt percentage = 13*100/44
=30

Like? Yes (3) | No   

Aastha   10 years AGO

cp=44
sp=57
profit=13
p %=13/44*100
29.54%=30%

Like? Yes (3) | No   

rajeev chaubey   10 years AGO

57 toffee cost 57 rupees if sold one by one
if sold packet cost =44
profit=57-44=13
p%=13/44=.2956=30%(approx)

Like? Yes (5) | No (2)  

Shashank Kapoor   10 years AGO

Since the CP of a packet of toffees is Rs 44 and selling the 57 toffees in it one by one earns Rs 57 , hence % profit is given by profit/CP *100 Where profit is Rs 57 - 44 = 13 . Putting the values and solving we get % profit = 29.55 ~ 30(approx)

Like? Yes (2) | No   

BHASKAR MANDAL   10 years AGO

selling price = 1*57 = 57
cost price of 57 toffee = 44
so profit % = ((selling price - cost price)/cost price) *100
= (57-44)/44 *100 = 29.54 = 30%

Like? Yes (2) | No   

Mahesh   10 years AGO

The profit is Rs.13 on Rs.44, so the percentage is 29.54% so the answer is 30%

Like? Yes (3) | No (1)  

R. Divya   10 years AGO

1 packet = 57toffees which costs 44 rupees. But each toffee sold individually at rs 1.

therefore, gain = 57 - 44 =13.
gain % = gain * 100 / c.p
= 13 *100 / 44
= 29.545

therefore gain % is 30

Like? Yes (3) | No (1)  

Sourojit Dhua   10 years AGO

44/57=0.2954
1-0.2954= 0.772=cp of 1 piece
so, profit= 1-cp= 0.2954
Hence profit %= (0.2954/1-0.2954)*100= 30%

Like? Yes (1) | No   

vartika    10 years AGO

profit%= 13/44*100 =29.5%

Like? Yes (2) | No (1)  

Ankit Pandey   10 years AGO

C.P. of 1 toffee=77 paise
S.P. of 1 toffee=100 paise
profit=(100-77)×100/77=29.8=30%

Like? Yes (1) | No   

Sagar Kumar Subudhi   10 years AGO

(13/44)*100=30%

Like? Yes (1) | No   

Gitanjali K   10 years AGO

29.5 so approx = 30

Like? Yes (1) | No   

Abhishek Vishwakarma   10 years AGO

{(57/44)*100} � 100 = 29.55 (approx
30)

Like? Yes (1) | No   

martha rachana   10 years AGO

(13/44)*100

Like? Yes (1) | No   

Arijit Acharyya   10 years AGO

profit=s.p-c.p=57-44=13
%profit=13/44*100=30%

Like? Yes (1) | No   

vinit   10 years AGO

profit=57-44=13

profit percentage=13*100/44=29.54 appox 30
so ans will be 30 option 4

Like? Yes (1) | No   

kumar   10 years AGO

13*100/44=30 approx

Like? Yes (1) | No   

Vishal Chugh   10 years AGO

(13/44)*100=30%

Like? Yes (3) | No (2)  

santosh kumar patel   10 years AGO

investment=44
profit=13
%profit=13*100/44=29.55
ans=30%

Like? Yes (2) | No (1)  

jitendra varshney   10 years AGO

profit=(57*1-44/44)*100
=29.545
=30 so option 4 is correct

Like? Yes (2) | No (1)  

Ajinkya Kulkarni   10 years AGO

Profit in Rs = 13
Cost Price = Rs 44
Percentage Profit = 13/44 *100
=30%

Like? Yes (1) | No   

RAKESH KUMAR RANJAN   10 years AGO

% profit=(57*1-44)*100/44=29.5454

Like? Yes (1) | No   

Shahrukh   10 years AGO

57-44/44*100

Like? Yes (1) | No   

Amit Verma   10 years AGO

cp=44
sp=57
profit=57-44=13
%profit=(13*100)/44

Like? Yes (1) | No   

AJAY KUMAR   10 years AGO

c.p of 57 toffies = s.p of 44 toffies.
so profit = rs 13 on 44.
so % profit = (13*100)/44
=29.55= 30(app.)

Like? Yes (1) | No   

Perumal   10 years AGO

57 toffees pkt price is Rs 44. it sold at Rs.1 each toffee so 57*1=57 percentage profit =[(57-44)/44] 100=29.5

Like? Yes (2) | No (1)  

Ritika Shrivastava   10 years AGO

Cp of packet of 57toffees=rs44
S.p=57
P=s.p-c.p=57-44=13
P%=13/44*100=29.54=30
Ans is 30

Like? Yes (1) | No   

bhishma   10 years AGO

c.p=44
s.p=57*1
profit=57-44=13
profit%=(13/44)*100=29.54=30

Like? Yes (1) | No   

anupriya sinha   10 years AGO

if c.p of 1packet toffie is =44 Re
packet containing =57 toffie
s.p of one toffie is = 1 Re
than s.p of 57 toffie is = 57 Re
profit =s.p -- c.p=57-44=13 => profit% =profit/c.p =13/44 *100 => 29.54 =30 approx

Like? Yes (1) | No   

khushboo goenka   10 years AGO

coz profit=13
and profit %=13*100/44

Like? Yes (1) | No   

nikhil suthar   10 years AGO

answer is 29.51% whish is equal to 30 (round figure)

CP=44;
SP=53;
profie=SP-CP
53-44=13
%profit 13*100/44
29.51%

Like? Yes (1) | No   

KRISHAN MURARI   10 years AGO

13*100/44=30

Like? Yes (1) | No   

aditya kumar   10 years AGO

gain%= (gain*100)/C.P

Like? Yes (1) | No   

Arkja tiwari   10 years AGO

relative profit= (57-44)/44
percentafe =relative*100%

Like? Yes (1) | No   

Vikram   10 years AGO

44*0.3=57.2===57

Like? Yes (1) | No   

vivek prakash   10 years AGO

in realtive s.p paket s.p of 57 tofee is 57
c.p of 57 tofee is 44
so profit is (13/44)*100=30(approx)

Like? Yes (1) | No   

ganesh babu   10 years AGO

c.p=44
s.p=57x1=57
gain=13
gain%=(gain/c.p) x 100 =29.54

Like? Yes (1) | No   

urvish   10 years AGO

1tf cost =0.77
so profit on 1 tf =0.23
sorelative percentage for each profit is 13.11
so final profit =0.23*100/77
=29.878=30

Like? Yes (1) | No   

Deepu Kumar   10 years AGO

A/Q Option 4 is correct.

Like? Yes (1) | No   

shubham tyagi   10 years AGO

cp=44
sp=57
profit%=(57-44/44)*100
profit%=29.54~30%

Like? Yes (1) | No   

vivek mishra   10 years AGO

44/57 = cost of 1 tofee
1=sp of tofee
profit=[(1-.7719)/.7719]*100



90

Like? Yes (1) | No   

Theja Muppalla   10 years AGO

for each toffee 1 rupe relative to 44 rupes
1/44 *100

2. value
so 57-44 =13
2. some *13
29.545
app 30

Like? Yes (1) | No   

DILEEP KUMAR   10 years AGO

100-(57*100/44) = 29.54 (nearly 30)

Like? Yes (1) | No   

Sneha   10 years AGO

cp=44
sp=57
profit=57-44=13
profit percentage=13*100/44=29.54(approx 30)

Like? Yes (1) | No   

anuj gupta   10 years AGO

57-44=13/44*100=~30%

Like? Yes (1) | No   

TUSHAR    10 years AGO

30

Like? Yes (1) | No   

Pragati Kamal   10 years AGO

C.P=44
S.p=57
profit %= (57-44)100/44=29.546=30

Like? Yes (1) | No   

ekta abhishek   10 years AGO

profit= 57-44=13
profit %age=(profit/cp)*100
(13/44)*100=29.5=30

Like? Yes (1) | No   

avnesh saxena   10 years AGO

Total profit=57-44=13
Profit %=13/44=30

Like? Yes (1) | No   

Neel Patel   10 years AGO

(13/44)*100=29.5~~~>30

Like? Yes (1) | No (1)  

MRITUNJAY KUMAR   10 years AGO

30

Like? Yes (1) | No (2)  

NIVEDA SIVAPRAKASAM   10 years AGO

app 30%

Like? Yes (1) | No (2)  

02 Oct 2014 Probability

A seven digit number is formed by using the digits 3, 3, 4, 5, 5, 8 & 9. Probability that the number formed is great than 57,26,000 is?

OPtion

1) 3/8
2) 1/5
3) 1/3
4) 2/9
5) 12/35
6) 16/35
7) 8/35
8) 8/21
9) 2/5
10)None of these

Solution

Total no. of numbers formed by using the given digits 3,3,4,5,5,8,9 = (7*6*5*4*3*2*1)/(2*1)*(2*1) = 1260
(Denominator part is due to the repetition of 3 and 5)
Total no. of numbers formed by using the given digits 3,3,4,5,5,8,9 which are greater than 57,26,000 are of two types
Total no. of numbers started with 5 = (2*2*5*4*3*2*1)/ (2*1)*(2*1) = 120
Total no. of numbers started with 8&9 = (2*6*5*4*3*2*1)/ (2*1)*(2*1) = 360
Hence required probability = (120 + 360)/ 1260 = 480/1260 = 8/21

Correct Option: 8 Best Solution (29)

Narasapu Hari prasad   10 years AGO

total sample space is 7!/(2!*2!)=1260
total number of numbers formed by 3,3,4,5,5,8,9 which are greater than 5726000 are
when first digit is 5 second digit should be 8 or 9
so 58*****=5!/2!=60
and 59*****=5!/2!=60
or first digit should be 8 or 9
so 8******=6!/(2!*2!)=180
and 9******=6!/(2!*2!)=180
so required probability = (60+60+180+180)/1260=480/1260=8/21

Like? Yes (13) | No   

RAKESH   10 years AGO

total = 7!/2*2 = 1260

greater than 57,26,000 = 5(7/8)----- , 8------, 9-------
= 2*5!/2 + 6!/2*2 + 6!/2*2
= 120 + 180 + 180
= 480

p = 480/1260 = 8/21

Like? Yes (6) | No (1)  

Gitanjali K   10 years AGO

required probability = (120+360)/1260 =8/21

Like? Yes (3) | No   

harshit gupta   10 years AGO

OPTION 8 is correct. Here is a solution

total different no. = 7!/(2!*2!)
Now three cases are made for no. greater than 5726000

CASE 1 -- No. Starting with 8
total different no.= 6!/(2!*2!)

CASE 2 -- No. Starting with 9
total diff. no.= 6!/(2!*2!)

case 3 --No. Starting with 5
total no.= (2*5!)/2! ( since 8 &9 can come at second place)

Total no.= 6!/(2!*2!)+ 6!/(2!*2!)+ (2*5!)/2!=(2*5!+6!)/2!
Probability= ((2*5!+6!)*2!*2!)/(2!*7!)
prob= 8/21

Like? Yes (3) | No   

Chirag Ranjan Lahiri   10 years AGO

Total no. of numbers formed by using the given digits 3,3,4,5,5,8,9 = (7*6*5*4*3*2*1)/(2*1)*(2*1) = 1260

(Denominator part is due to the repetition of 3 and 5)

Total no. of numbers formed by using the given digits 3,3,4,5,5,8,9 which are greater than 57,26,000 are of two types

Total no. of numbers started with 5 = (2*2*5*4*3*2*1)/ (2*1)*(2*1) = 120
Total no. of numbers started with 8&9 = (2*6*5*4*3*2*1)/ (2*1)*(2*1) = 360
Hence required probability = (120 + 360)/ 1260 = 480/1260 = 8/21

Like? Yes (2) | No   

santosh kumar patel   10 years AGO

total no of formed=!7/!2*!2=1260
formed greater than 572600 are 2 ways
total no start from 5=120
8&9=360
hence required probability=120+360/1260=8/21
ans:8/21

Like? Yes (2) | No   

Mahesh   10 years AGO

The number of numbers that start with 58 is 5!/2!=60
The number of numbers that start with 59 is 5!/2!=60
The number of numbers that start with 8 is 6!/2!2!=180
The number of numbers that start with 9 is 6!/2!2!=180

The total possibilities= 7!/2!/2!=1260

The required probability = 480/1260=8/21

Like? Yes (1) | No   

kumar   10 years AGO

8/21

Like? Yes (1) | No   

Neel Patel   10 years AGO

In first place
By taking 8&9 there are
2*6!/(2!2!)=360
And taking 5 at first place
There 1*2*5!/2!=120

Total numbers =7!/2!/2!=1260
Prob=120+360)/1260=8/21

Like? Yes (1) | No   

MRITUNJAY KUMAR   10 years AGO

8/21

Like? Yes (1) | No   

vikash kumar   10 years AGO

tot=7!/(2!*2!)=A

ways=5!+(6!/2!*2!)+(6!/2!*2!)=B

ans:=B/A= 8/21

Like? Yes (1) | No   

vivek prakash   10 years AGO

if we start with 5 then 1st position is filled by 2 ways then 2nd placed is must filled with 8 or 9 so remaining position by !5 so if we start with 5 no ways of forming no is 2*2*!5
second case fist digit can start with 8 or 9 then no of ways of forming no is 2*!6
we no restriction then noof ways of forming no is !7
(4*!5+2*!6)/!7=8/21

Like? Yes (1) | No   

shekhar suman   10 years AGO

total no of possible outcome =7!/2!*2!
favorable outcome= 5!+2*6!/2!*2!
so p(a)=(5!+2*6!/2!*2!)*4/7!

Like? Yes (1) | No   

Karunendra Singh   10 years AGO

number will be greater than given 5726000 when first 2 position digit and 9 take place so for place one there will be two number
2*6*5*4*3*2*1
after this if we place first place digit 5 and at second place put 8 or 9 then it also will be greater than given number so for there are wo option because there are two five
2*2*5*4*3*2*1
total combination of number greater than given number =1440+480= 1920
and total number of combination of number = 7*6*5*4*3*2*1= 5040
and answer will be 5040/1920 = 8/211.........

Like? Yes (1) | No   

Vishesh Mishra   10 years AGO

for first position there will be two number that is 8 and 9 so 2*6*5*4*3*2*1= 1440 and if we place 5 at first then 2*2*5*4*3*2*1= 480 so total number of combination ie greater than given number = 1920 and total number that having 7 digit = 7*6*5*4*3*2*1= 5040 ,
answer = 5040/(1440+480)= 8/21..........

Like? Yes (1) | No   

rajeev chaubey   10 years AGO

5 8 - - - - - =5!/2!=60 numbers
5 9 - - - - - =5!/2!=60 numbers
8 - - - - - - =6!/2!2!=180 numbers
9 - - - - - - =6!/2!2!=180 numbers
60+60+180+180=480 numbers
total words formed by given numbers=7!/2!2!=1260
P=480/1260=8/21

Like? Yes (1) | No   

BalaGanesh S   10 years AGO

Total 7 digits numbers can be formed are 7!/(2!*2!)

Numbers greater than 5726000 means the numbers should start with 8 or 9 or start with 58 or 59,
i.e 8 _ _ _ _ _ _=6!/(2!*2!) +
9 _ _ _ _ _ _= 6!/(2!*2!) +
58 _ _ _ _ _ =5!/2! +
59 _ _ _ _ _ = 5!/2!

Probability = (2*6!/(2!*2!) + 2*5!/2!) / 7!/(2!*2!) = 8/21

Like? Yes (1) | No   

~Sandeep~   10 years AGO

Count of Numbers formed which are greater than 57,26,000 would be sum of=>
58* Series = 5!/2!
59* Series = 5! /2!
8* Series = 6! 2*2
9*Series = 6!/2*2
Sum= 4*5!

Total count of numbers formed using these 7 digits = 7!/(2!*2!)

Probability= (4*5!)/ (7!)/2*2 = 16/ 42 = 8/21

Like? Yes (1) | No   

urvish   10 years AGO

7C4+7C2/7C2
=8/21

Like? Yes (1) | No   

DE PRAKASH TIWARY   10 years AGO

total no of numbers formed by these digits is 7!/4. And the no of numbers greater than 5726000 is 8*5!/2

Like? Yes (1) | No   

Md.Sultan Khichi   10 years AGO

Num shud be greater than 5726000 for this num shud be start wid 58......=5!/2!=60
59.....=5!/2!=60
8......=6!/2!/2!=180
9......=6!/2!/2!=180
Total nums greater than 572600=60+60+180+180=480
And total nuns form by these digits are=7!/2!/2!=1260..
Probability=480/1260=8/21..
Ans.. 8/21

Like? Yes (1) | No   

CHANDAN KUMAR   10 years AGO

TOTAL NO. FORMED=7!/21*2!=1260
no. greater than 5726000=2*60+180*2=480
p=480/1260=8/21

Like? Yes (1) | No   

dhananjay kumar   10 years AGO

Total number greater than 572600=60+60+180+180=480
And total number=7!/2!/2!=1260..
Probability is 480/1260
Ans.. 8/21

Like? Yes (1) | No   

Rupesh Rajesh Deshmukh   10 years AGO

480/1260=8/21

Like? Yes (1) | No   

Vibha   10 years AGO

p(> 5726000) =
{ P(starting with 5) + P(starting with > 5) } /total
= 8/21

Like? Yes (1) | No   

Kushagra Tiwari   10 years AGO

Num shud be greater than 5726000
for this num shud be start wid
58......=5!/2!=60
59.....=5!/2!=60
8......=6!/2!/2!=180
9......=6!/2!/2!=180
Total nums greater than
572600=60+60+180+180=480
And total nuns form by these digits
are=7!/2!/2!=1260..
Probability=480/1260=8/21..
Ans.. 8/21

Like? Yes (1) | No   

Shreya Tiwari   10 years AGO

Num shud be greater than 5726000
for this num shud be start wid
58......=5!/2!=60
59.....=5!/2!=60
8......=6!/2!/2!=180
9......=6!/2!/2!=180
Total nums greater than
572600=60+60+180+180=480
And total nuns form by these digits
are=7!/2!/2!=1260..
Probability=480/1260=8/21..
Ans.. 8/21

Like? Yes (1) | No   

Abhishek Vishwakarma   10 years AGO

Num shud be greater than 5726000
for this num shud be start wid
58......=5!/2!=60
59.....=5!/2!=60
8......=6!/2!/2!=180
9......=6!/2!/2!=180
Total nums greater than
572600=60+60+180+180=480
And total nuns form by these digits
are=7!/2!/2!=1260..
Probability=480/1260=8/21..
Ans.. 8/21

Like? Yes (1) | No   

neha kumari   10 years AGO

no of no greater than 5726000=480
possible no=1260
p=8/21

Like? Yes (1) | No   

01 Oct 2014 Probability

There are two schemes in Vodafone mobiles.
First scheme :1 paise per second,
Second scheme :50 paise per minute,

Following conditions are given -
1) In second scheme, second minute will be started at 0:60 or 1:00,
2) 0 sec. call means to call and cut it abruptly when timer reads 0:00, this is equivalent to a call of 1 sec.
3) In first scheme 0:14 means 15 sec.

The probability that first scheme is more profitable over second in a call ranging from 0:00 (1 sec.) to 3:20 (201 sec.) is ?

OPtion

1) 139/201
2) 17/25
3) 139/200
4) 4/25
5) 17/50
6) 136/201
7) 100/201
8) 1/2
9) 1/4
10)None of these

Solution

The ranges in which first scheme is more profitable over second in a call ranging from 0:00 (1 sec.) to 3:20 (201 sec.) is ?
0-48, 60-98, 120-148, 180-198,
Hence total seconds in which first scheme is more profitable over second are 136.1
Therefore probability that first scheme is more profitable over second in a call ranging
from 0:00 (1 sec.) to 3:20 (201 sec.) is 136/201.

Option 6)

Correct Option: 6 Best Solution (7)

RAKESH   10 years AGO

1st is profitable 4
1-49 sec, 61-99 sec (b4 1:00)
121-149sec (for 48 sec as starts from 1:00)
181-199 sec (b4 2:00)
total = 49+39+29+19 = 136

p = 136/201

Like? Yes (13) | No   

Mahesh   10 years AGO

The first scheme is profitable from 0 to 48 seconds, because in all these cases the first scheme will be costing 50 paise. so 49 instances
Similarly, it is profitable from 60 to 98, which is 39 instances
It is profitable from 120 to 148 which is 29 instances
It is profitable from 180 to 198 which is 19 instances
total instances= 49+39+29+19=136
Required probability=136/201

Like? Yes (6) | No   

santosh kumar patel   10 years AGO

The ranges of the first scheme is more profitable over second in a call ranging from 0:00 (1 sec.) to 3:20 (201 sec.) is

0-48, 60-98, 120-148, 180-198,

Hence total seconds of the first scheme is more profitable over second are 136.
Therefore probability that first scheme is more profitable over second in a call ranging
from 0:00 (1 sec.) to 3:20 (201 sec.) is 136/201.

Like? Yes (3) | No   

sowmiya   10 years AGO

i hope that is answer

Like? Yes (2) | No   

Deepu Kumar   10 years AGO

A/Q option 6 is correct

Like? Yes (1) | No   

Neel Patel   10 years AGO

In seconds 0-49
60-99
120-149
180-199
Total 136 seconds
Scheme 1 is profitable out of 201 seconds
So ans is136/201

Like? Yes (1) | No   

Madhavan   10 years AGO

it is added last one second it is become the 136/201

Like? Yes (1) | No (1)  

30 Sep 2014 Percentage

In an examination, it is required to get 36% of maximum marks to pass. A student got 113 marks and was declared failed by 85 marks. The maximum marks are:

OPtion

1) 500
2) 490
3) 550
4) 510
5) 640
6) 750
7) 1008
8) 1150
9) 1200
10)None of these

Solution

Let maximum marks be x.
Then
36% of x = (113+85). So x = (198*100/ 36) = 550

Opton 3)

Correct Option: 3 Best Solution (179)

prem kumar   10 years AGO

pass marks=113+85=198
for 36%=198
for 100%=?
198*100/36=550 marks

Like? Yes (33) | No (5)  

Kushagra Tiwari   10 years AGO

since 36% of x = (113+85) = 198

therefore x = (100*198)/36
that is = 550

which is in 3rd option

Like? Yes (16) | No (4)  

Bhagyashree Bhatt   10 years AGO

Let us assume that the maximum marks for thr examination is x.

Then the equation we get as per simple linear equation:

36% of x = 113 + 85

36x/100 = 198

36x = 19800

x = 19800/36 = 550 marks.

Like? Yes (11) | No   

poojasaisri   10 years AGO

total pass marks=113+85=198
36% marks =198
110%-36%=64%
then 64% marks=(64*198)/36=352
therefore maximum marks=352+198=550

Like? Yes (6) | No   

Shashank Kapoor   10 years AGO

Since the student got 113 marks and was declared failed by 85 marks, therefore minimum passing marks are 113+85=198
this is 36% of total marks so 36/100 * X =198 on solving we get X=550 (X= TOTAL MARKS)

Like? Yes (4) | No (1)  

harini   10 years AGO

let max marks=x
then the min marks required=9x/25
but according to given information 9x/25=113+85=>x=550

Like? Yes (3) | No   

Gitanjali K   10 years AGO

100*198/36=550

Like? Yes (2) | No   

dhanaseelan   10 years AGO

Total marks to get pass is 113+85=198
This is 36 % of total marks
so total marks will be (100/36)*198=550

Like? Yes (2) | No   

NAVEEN KUMAR   10 years AGO

LET MAXIMUM MARKS=X
A/Q
36% 0F X=(113+85)
=>X=550

Like? Yes (3) | No (1)  

shreya sagar   10 years AGO

pass marks=113+85=198
let maxm marks be x.
Then given
36% of x=198
x=(198*100)/36=550

Like? Yes (3) | No (1)  

Abhimanyu kumar   10 years AGO

let max marks be x
pass marks is 36% of max marks =36x/100
student got 113 marks and failed by 85
so 113+85=36x/100
x=550

Like? Yes (2) | No   

Pooja Sandeep Shah   10 years AGO

36% of 550 is 198 which equals 113+85

Like? Yes (2) | No   

Soniya Jain   10 years AGO

113+85=198
36/100×MM=198
MM=198×100/36
MM=550

Like? Yes (2) | No   

Ankit Pandey   10 years AGO

Let us max marks = X
(36/100)X=113+85
X=550

Like? Yes (1) | No   

Kethineni Vinodh   10 years AGO

113+85=198
36%=198 then
100%=550

Like? Yes (1) | No   

ragini   10 years AGO

36% of x=113+85

x=(100*198)/36
x=550

Like? Yes (1) | No   

BHASKAR MANDAL   10 years AGO

he got 113
he is failed by 85
so, if he had got 113+85 = 198 then he would have passed.
given : 36% pass marks

so the total marks for getting 198 as pass marks
= (198/36)*100 = 550

Like? Yes (1) | No   

Aj   10 years AGO

Passing marks=113+85
(36/100)Max=Passing marks
Max=(113+85)*(100/36)
Therefore Max=550

Like? Yes (1) | No   

RAKESH   10 years AGO

(113+85)*100 / 36 = 550

Like? Yes (2) | No (1)  

Neel Patel   10 years AGO

113+85=198
36%-->198
100%-->?
198*100/36=550

Like? Yes (1) | No   

sanjeev kumar   10 years AGO

ans = option 3

Like? Yes (1) | No   

Shreya Tiwari   10 years AGO

since 36% of x = (113+85) = 198

therefore x = (100*198)/36
that is = 550

550 is the ans

Like? Yes (1) | No   

Abhishek Vishwakarma   10 years AGO

since 36% of x = (113+85) = 198

therefore x = (100*198)/36
that is = 550

ans is 550

Like? Yes (1) | No   

poojitha   10 years AGO

36% of x=113+85
x=(100*198)/36
x=550

Like? Yes (1) | No   

Aastha   10 years AGO

given to pass exam 36% required.
113 and fails by 85
so he required 113+85=198 to pass
let x be ma. marks
36*x/100=198
x=550

Like? Yes (5) | No (4)  

shekhar suman   10 years AGO

after getting 113 marks he failed by 85
so passing marks =113+85=198
now, 198=36%of x
thus x=(198*100)/36=550

Like? Yes (1) | No   

Simranjit Singh   10 years AGO

(3) is the correct answer

Let the total marks be x
Pass marks= 0.36*x

The student gets 113 and it is less by 85
So 0.36*x=113+85
=> x=198/0.36= 550

Like? Yes (1) | No   

Arijit Acharyya   10 years AGO

let the maximum marks=x
x*(36/100)=(113+85)
x=550

Like? Yes (1) | No   

Sahana   10 years AGO

36% of 550 is 198

Like? Yes (1) | No   

Deepu Kumar   10 years AGO

A/q
Its is being told that students got 113 marks but failed by 85 marks ..
so total marks that he obtained not to fail is 113+85=198 marks
and percent given to pass is 36%.
so for 1 percent it is 198/36=5.5 marks
so for 100 marks its multiplied by 100 that is 5.5*100=550 marks.

Like? Yes (1) | No   

Vibha   10 years AGO

max marks = (113+85)100/36
= 550

Like? Yes (1) | No   

PAWAN KUMAR   10 years AGO

The min marks to pass the exam = 113+85 = 198.
Let the max marks of the exam be x.
Then, 36% of x = 198
=> 36*x/100 = 198
=> x = 198*100/36 = 11*50 = 550 Ans.

Like? Yes (1) | No   

anupriya sinha   10 years AGO

36%ofx =113+85 =>x = 198*100*/36 => x = 550

Like? Yes (1) | No   

jitendra varshney   10 years AGO

answer is 113+85=198
so198/36*100=550
so option 3 is correct

Like? Yes (2) | No (1)  

Sundar Kumar   10 years AGO

113 + 85 = 198 = 36% of the aggregate marks
Therefore, the aggregate marks = 198 × 100/36 = 550. Ans.
Answer: Option 3)550

Like? Yes (1) | No   

pawan kumar   10 years AGO

36x/100= 198
so, x=550

Like? Yes (1) | No   

Mahendra Jakka   10 years AGO

let x be total marks
36% of x =113+85=198
x=[198*100]/36=550

Like? Yes (1) | No   

santosh kumar patel   10 years AGO

let thr max mark x
then 36% of x=113+85
36x/100=198
x=19800/36
x=550

Like? Yes (1) | No   

sohini maity   10 years AGO

the student requires 85 marks more to pass which is equal to 36% of max marks.so if max marks is x,then
113+85=36% of x
x=550.
so the correct option is 3.

Like? Yes (1) | No   

kumar   10 years AGO

after getting 113 mark fail by 85 mark
mean pass mark= 113+83 =198 marks

pass mark=36% of max mark
mean 36%=198
then 100%=198*100/36=550 mark

Like? Yes (1) | No   

AJAY KUMAR   10 years AGO

let total marks=x
pass marks=(36/100)x
marks obtained by student=113
therefore,
(36/100)x=(113+85)
x=550

Like? Yes (1) | No   

anuj gupta   10 years AGO

113+85=198*100/36==>550

Like? Yes (1) | No   

sahanashree H N   10 years AGO

X-Max marks
Passing marks=X*(36/100)
Passing marks=113+85=198
So substitute the value of passing marks
198=X*(36/100)
X=550

Option 3)

Like? Yes (1) | No   

swarupa nuggu   10 years AGO

550

Like? Yes (1) | No   

shubham tyagi   10 years AGO

let max marks be x
36% of x -85 =113
36% of x=198
x=198*100/36
x=550

Like? Yes (2) | No (1)  

Rahul Kumar Singh   10 years AGO

(113+85)*100/36

Like? Yes (1) | No   

Ashok   10 years AGO

198*100/36

Like? Yes (1) | No   

ADARSH GAURAV   10 years AGO

550 is the answer.

Like? Yes (1) | No   

shree   10 years AGO

(x*36)/100=113+85
x=19800/36
x=550

Like? Yes (1) | No   

Jigyasa Kumar   10 years AGO

36% *x = 113+ 85
x= 550

Like? Yes (1) | No   

abhilasha   10 years AGO

36% *x = 113+ 85
x= 550

Like? Yes (1) | No   

Aarush Singh   10 years AGO

36% *x = 113+ 85
x= 550

Like? Yes (1) | No   

kadambari   10 years AGO

36100*x=198
36x=19800
x=19800/36
x=550
therefore answer is 550.

Like? Yes (1) | No   

abhash kumar ranjan   10 years AGO

36*x/100=198
x=550

Like? Yes (1) | No   

Urvashi Verma   10 years AGO

Passing marks will be=113+85=198
let x be maximum marks
Thus 36% of x=198
x=550

Like? Yes (1) | No   

Ankan Biswas   10 years AGO

he has got 113 marks and is declared failed by 85 marks
therefore, pass marks = 85 + 113 = 218
pass marks is 36% of maximum marks.
Let the maximum marks in the exam be x.
Therefore, 36/100*x = 218
=>x = 218*100/36 => x = 550
Ans. 550 (option 3)

Like? Yes (1) | No   

mohit gupta   10 years AGO

113+85= 36%of x
x=550

Like? Yes (1) | No   

Sanjit Kumar Sharma   10 years AGO

36%=113+85=198
1%=198/36
100%=198/36*100=550

Like? Yes (1) | No   

Sabyasachi Pahari   10 years AGO

36% marks = (113+85) = 198
So, maximum marks = 198 x (100/36) = 550.

Like? Yes (1) | No   

Anvesh   10 years AGO

3

Like? Yes (1) | No   

Ritika Shrivastava   10 years AGO

No acquired by student =113
No required for passing=113+85=198
198=36%of total marks
198=36/100 of total marks
Total marks =550
Option 3 is the answer

Like? Yes (1) | No   

mahesh   10 years AGO

(36/100)*x=198
.: x=550

Like? Yes (1) | No   

T.Rami Reddy   10 years AGO

113+85=0.36*X where X is maximum marks
Solving for X
We get X=550

Like? Yes (1) | No   

Hemavathy Nangan   10 years AGO

(100/36)*8=550

Like? Yes (1) | No   

mamta garkoti   10 years AGO

marks obtained by him are 113 had he got 85 more, he woul have passed, so passing marks= 113+85= 198,
if max marks are x, then we have,
36/100 * x =198
on solving we have x= 550
hence max marks = 550

Like? Yes (1) | No   

DEEPAK GOSWAMI   10 years AGO

let x be the total marks then x*36/100=198
and x =550

Like? Yes (1) | No   

Ramesh Sriram   10 years AGO

36% MARKS IS=113+85=198
36----198
100-----?
198*100/36
=550

Like? Yes (1) | No   

Bheem Reddy Ravendra Reddy   10 years AGO

total marks are 550 because in this 36% of marks are 198

Like? Yes (1) | No   

Tania Chatterjee   10 years AGO

Let us assume that the maximum
marks for thr examination is x.
36% of x = 113 + 85
36x/100 = 198
36x = 19800
x = 19800/36 = 550 marks.
Ans: 550 marks.

Like? Yes (1) | No   

kanchan kumar   10 years AGO

{(113+85)*100}/36=550

Like? Yes (1) | No   

Anand Dwivedi   10 years AGO

Total markes Required For pass:-
113+85=198 are the passing marks.

198*100/36 = 550 marks

Like? Yes (1) | No   

sai kumari   10 years AGO

let max marks be x. given pass % is 36% therefore pass%=36%ofx. given he got 113 and still failed y 85 therefore total=113+85=198..therefore (36/100)x=198 hence x=550.

Like? Yes (1) | No   

pratima gupta   10 years AGO

113+85=198
198=x*36/100
x=550

Like? Yes (1) | No   

MOHIT GARG   10 years AGO

Let Max marks are M.
And 36*M/100 = 113+85
M=550

Like? Yes (1) | No   

sudeep   10 years AGO

let max marks be X
36% of X = Sum of 113 & 85
0.36*X = 198
Therefore X = 550.

Like? Yes (1) | No   

Sandeep Kumar   10 years AGO

113+85=198
(198/36)*100=550

Like? Yes (1) | No   

Shital Saste   10 years AGO

suppose max marks is x,
so, (36/100)*x=190
=> x=550

Like? Yes (1) | No   

Souvik Datta   10 years AGO

Let us assume that the maximum
marks for the examination is x.
36% of x = 113 + 85
36x/100 = 198
36x = 19800
x = 19800/36 = 550
so maximum marks 550

Like? Yes (1) | No   

Sutanu Shit   10 years AGO

pass mark = 113+85 =198

maximum marks = (100*198)/36 = 550

Like? Yes (1) | No   

arun kumar   10 years AGO

let x be total marks.
he failed by 85 and got 113 .
hence pass marks =198
198=36*x/100
x=550

Like? Yes (1) | No   

bilbo   10 years AGO

36% passed percentage
student got 113 marks and failedby 85 marks so total marks for passing is 113+85=198 i.e 36% so 1% appr is5.5 so the max marks be 550

Like? Yes (1) | No   

nishu kumar   10 years AGO

let total marks be X.
then to pass 9X/25 is required,
student get 113 marks and failed by 85 marks ,so if he got (113+85=198)marks then he will be pass.
so
9x/25=198
x=550=(total marks)

Like? Yes (1) | No   

DILBAG SINGH   10 years AGO

113+85*100/36

Like? Yes (1) | No   

Aishwary Tiwari   10 years AGO

passing marks= 113+85=198
let max marks be x
36x/100 = 198
x=550

Like? Yes (1) | No   

RISHABH SHARMA   10 years AGO

let total marks x so 36 * x/100 =113+85

Like? Yes (1) | No   

CHANDAN KUMAR   10 years AGO

let maxm marks=x
passing marks=36x/100
passing marks=113+85=198
now 36x/100=198
x=198*100/36=550
so maximum marks=550(answer)

Like? Yes (1) | No   

Inline Geek   10 years AGO

(113+85)*100/36= 550

Like? Yes (1) | No   

Kritika Joshi   10 years AGO

36%x=(113+85)
x=550

Like? Yes (1) | No   

MRITUNJAY KUMAR   10 years AGO

ans-550

Like? Yes (1) | No   

siddhartha sadhu   10 years AGO

36/100=(113+85)/x;
x=550

Like? Yes (1) | No   

shweta   10 years AGO

as minimum passing marks is 198 and this is given that 36% of maximum marks then we have to calculate 198=36%x and then obtain the value of x i.e the answer

Like? Yes (1) | No   

chavali nikhita   10 years AGO

198*100/36

Like? Yes (1) | No   

Kamal Rajput   10 years AGO

36% of x=(113+85)=198
x=550

Like? Yes (1) | No   

prabhat   10 years AGO

X%of 36=passing mark
(x/100)*36=113+85
x=550
maximam mark is 550

Like? Yes (1) | No   

mukesh kumar   10 years AGO

assume full marks is x
then, x*0.36=113+85
so x=550

Like? Yes (1) | No   

Grishma Shah   10 years AGO

To passing marks should be 113+85 = 198
36% of x = 198
Hence, x = 198/0.36 = 550

Like? Yes (1) | No   

Bhanu Pratap Singh   10 years AGO

total passing marks let be ' X '
minimum passing marks 113+85=198
maximum marks = ( 198*100)/36 = 550

Like? Yes (1) | No   

Darpan Shah   10 years AGO

Let total marks x.
Required no to clear exam is 36%.
Student get 113 but he has to score 113+85=198
so who get 198 then it is 36% of x.
So,
X * 36% = 198
X * 36/100 = 198
X = 198*100/33
X = 550
So 3

Like? Yes (1) | No   

David Raj   10 years AGO

36% of x is equal to 113+85
so x is 550 which is total marks

Like? Yes (1) | No   

Sneha   10 years AGO

113 + 85 = 198 = 36% of the aggregate marks
Therefore, the aggregate marks = 198 × 100/36 = 550.

Like? Yes (1) | No   

IMRAN AKHTAR   10 years AGO

Let max. marks be x
total pass marks=113+85=198
36% of x=198
x=550 (option 3)

Like? Yes (1) | No   

Ajay   10 years AGO

(113+85)/x=36
x=550

Like? Yes (1) | No   

Dinesh thatti   10 years AGO

add 85 t o113 we get 198
if 36% = 198
then 100%=?
100*198/36=550

Like? Yes (1) | No   

sanjeev kumar   10 years AGO

LET us suppose total is x then
pass mark=113+85=198
x*36%=198
x=550

Like? Yes (1) | No   

niraj   10 years AGO

let maximum marks is x
a/c to qn.
113+85=36x/100
x=550(ans)

Like? Yes (1) | No   

Ashit Kumar   10 years AGO

Simple 35/100 *x= 113+85

solve for x

Like? Yes (1) | No   

urvish   10 years AGO

36 to 198
then 100- ??
19800/36=550

Like? Yes (1) | No   

senthilkumar47   10 years AGO

(198/36)*100=550

Like? Yes (1) | No   

harshit gupta   10 years AGO

if he got 85 more then he wud pass
113+85=198 , which is 36% of maximum marks
thus 0.36x=198
on solving we get
550=x

Like? Yes (1) | No   

RAJESH   10 years AGO

113+85=198
36%=198
100%= 198/36*100=550

Like? Yes (1) | No   

V.Mahesh   10 years AGO

for 36% = 113+85=198
by checking options 550*36/100=198
so option 3 is correct

Like? Yes (1) | No   

Y V S Chandrakanth   10 years AGO

36% of Maximum marks=113+85

Maximum marks=(198*100)/36=550

Like? Yes (1) | No   

Rashi Agarwal   10 years AGO

113+85=198 will be passing marks
198=36%of x where x is max marks
x=550 Ans.

Like? Yes (1) | No   

Mohan   10 years AGO

(113+85)*(100/36)=550

Like? Yes (1) | No   

Udit Kumar   10 years AGO

passing marks=113+85=198
36% of what is 198=198/36*100=550

Like? Yes (1) | No   

Kunal Jaiswal   10 years AGO

Let x be the maximum marks.
Then, 36% of x is the passing mark. Here a student got 113 marks but he failed by 85 marks, means
113+85 (=198) is the passing marks.
Which means (36/100)x=198
x=198/0.36
x=550.
So, option 3.

Like? Yes (1) | No   

Akshay   10 years AGO

x*.36=198
x=550

Like? Yes (1) | No   

subodh   10 years AGO

(198*100)/36

Like? Yes (1) | No   

T.Aravinth kumar   10 years AGO

((113+85)/0.36)*1=550

Like? Yes (1) | No   

Hemadri   10 years AGO

36%=113+85=198
1%=198/36=11/2
100%=11/2*100=550

Like? Yes (1) | No   

Priya Dharshini   10 years AGO

take min % to pass tat is 36%,

here this student needs 85 marks to reach this 36%,
now,consider total marks as x


36/100(x) -85=113

36/100(x)=113+85;

solving we get x=550;

Like? Yes (1) | No   

Ajinkya Kulkarni   10 years AGO

Let Max marks = m

That means marks required to be passed are 0.36m

So as per the condition equation become 0.36m-85=113
Solve it .
Ans is Max marks are 550

Like? Yes (1) | No   

BIKRAM KUMAR PANDA   10 years AGO

1oo(113+85)/36

Like? Yes (1) | No   

lakshmi nalluri   10 years AGO

.36(max.marks)=113+85
max marks=550

Like? Yes (1) | No   

Sandhya Goud   10 years AGO

113+85=198
198/550=36%

Like? Yes (1) | No   

gouthamdaneti   10 years AGO

x=(113+85)*100/36

Like? Yes (1) | No   

Anandh   10 years AGO

If 198 is 36% then 550 is 100%:

113+85=198
then x=(190x100)/36
=550

Like? Yes (1) | No   

SURAJIT KUNDU   10 years AGO

Total marks has to achieved (113+85)=198

so, 36% of 550=198

Hence, Ans=550

Like? Yes (1) | No   

rajeev chaubey   10 years AGO

x*36%=36x/100=.36x
.36x=113+85=198
x=550

Like? Yes (1) | No   

RAJU KUMAR MAHATO   10 years AGO

since the pass marks is 198 which can be seen by us in question which is 36% of max. marks i.e. 198

Like? Yes (1) | No   

RABI KR. SHAW   10 years AGO

36x/100=113+85
x=550

Like? Yes (1) | No   

akriti mishra   10 years AGO

let x be total marks
113+85=198
36%of x=198
then x=550

Like? Yes (1) | No   

nassarshahab   10 years AGO

113+85=198
36% of x=198
x=550

Like? Yes (1) | No   

neha kumari   10 years AGO

113+85=198
36x/100=198
x=550

Like? Yes (1) | No   

Devesh Gupta   10 years AGO

passing marks = 36% of maximum = 113+85

maximum marks=(198*100)/36=550

Like? Yes (1) | No   

Rahul Gupta   10 years AGO

Student got 113 mark and he was failed from 85 marks so Passing marks is = 113 + 85 = 198
Passing percent is 36% = 198
so for 100% = 198 * 100/ 36 = 550

Like? Yes (1) | No   

Ankit Sirohi   10 years AGO

36/100 *x= 113+85
=> x=198*100/36= 550 ..option 3.

Like? Yes (1) | No   

Anand   10 years AGO

let max marks= x
acc to ques 113= x*36% - 85
we get x= 550

Like? Yes (1) | No   

vinit   10 years AGO

since
113 marks he obtained and failled by 85 marks
and pass per=36%
113+85=198 which shuld be 36per of total marks
550*36/100=198

Like? Yes (1) | No   

shanmukha pradeep   10 years AGO

case 1:let x be the maximum marks and a minimum of 36% marks are the pass marks so 36% of x is the pass mark in the exam
case2:a student got 113 marks and failed by 85 marks it means he would have passed if he will get that 85 marks too so the sum of 113 and 85(total=198) will make him pass.
from case 1 and case 2 we can say that the pass % is 36% and the pass marks are 198.so 36% of x=198
36/100*x=198 by solving this we get x=550 marks

Like? Yes (1) | No   

nehal   10 years AGO

36/1oo *x=113+85

Like? Yes (1) | No   

swasthika   10 years AGO

pass mark =113+85
=198
let x be the maximum marks,
36% of x =198
x=550

Like? Yes (1) | No   

posirajesh   10 years AGO

19800÷36=550

Like? Yes (1) | No   

Mayank Joshi   10 years AGO

113+85=198
198=(36/100)*x
x=19800/36
x=550

Like? Yes (1) | No   

Raminder   10 years AGO

113+85=198 ie = 36%


then 100 %= ?

(198*100)/36=550

Like? Yes (1) | No   

Priya Verma   10 years AGO

(x*36)/100=113+85
x=550

Like? Yes (1) | No   

Shahrukh   10 years AGO

113+85=198
36=198/m.m*100
m.m=550

Like? Yes (1) | No   

SAMRIDHI GIRI   10 years AGO

36%100*x=113+85

Like? Yes (1) | No   

Sagar Kumar Subudhi   10 years AGO

36%=113+85
1%=198/36
100%=(198/36)*100
maximum mark is 550

Like? Yes (1) | No   

Harish   10 years AGO

196 is 36% so 100% is 550

Like? Yes (1) | No   

anitha   10 years AGO

36%x=198
x=198*100/36
x=550

Like? Yes (1) | No   

Abhinav Arpanam   10 years AGO

[x * (36/100)] - 85 = 113

Like? Yes (1) | No   

vishal shanker polowalia   10 years AGO

36%of x = 113+85

After solve
x = 550

Like? Yes (1) | No   

TUSHAR    10 years AGO

550

Like? Yes (1) | No   

Rabindranath Giri   10 years AGO

Marks need to pass 113+85 =198
So, maximum marks is (100*198)/36=550

Like? Yes (1) | No   

Arkja tiwari   10 years AGO

he got 113 marks
passing criteria 36%=(x*0.36)
failed by 85 marks
then 113+85=198
now 198=0.36*x
x=550

Like? Yes (1) | No   

Priyanshi Agarwal   10 years AGO

36% of max. marks 550= (550*36)/100=198
&
113+85=198
hence max. marks =550

Like? Yes (1) | No   

ruchika   10 years AGO

36*x=198*100

Like? Yes (1) | No   

jyoti   10 years AGO

The answer is 550marks because as the student failed by 85 marks (113+85)marks=36 percent.
=198marks=36percent.
Then as we are doing it by unitary method we take the value of 1 percent=198/36=5.5marks.
Then we multiply our answer by 100 to get 5.5*100=550

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phoenix    10 years AGO

36% = 113 + 85 = 198
so 100%= (198*100)/36
= 550

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Sohar Lal Singh   10 years AGO

let assume total marks require to pass=x marks
then he need to pass exam was=36% of total
=x*36/100
but he could score only =113 and fail by 85
so 36% of toal=113+85
x*36/100=198
then x=550; ans

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Namrata Gupta   10 years AGO

113+85=198
let us assume max marks=x
36% of x = x*(36/100)=198
x=(198*100)/36=550

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Vishal Chugh   10 years AGO

113+85=36%

36%=198;
100= 550

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Muthu Kumar M   10 years AGO

36%=113+85=198
100%=(198*100)/36=550 marks

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Masudur Rahaman   10 years AGO

assume, max marks = x
36x/100 = 113+85
=> x = 550

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RUPALI KUMARI   10 years AGO

113+85=198
let passing marks be 'x'
then , 36x/100=198
x=550

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SANTOSH SAHOO   10 years AGO

36%=198mark
100%=(198/36)*100

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k.madhu sudhan reddy   10 years AGO

verify the option failed by 85 marks & got 113 marks, so total marks need to pass the exam is 198 so in option we can verify that 550*36/100=198

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Annu Kumari   10 years AGO

36x/100=(113+85)
x=19800/36
x=550

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Pradip G Giri   10 years AGO

36*550/100

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Chandra chur anand   10 years AGO

let x be total no.
so 36x/100=113+85
or 36x/100=198
or x=550 so max mark ll be 550

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Subhash Singh Kushwaha   10 years AGO

let the max. marks be x then 36% of x=passing marks
where passing marks=113+85=198
(36*x)/100=(98)
which gives x=550

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Ranjeet singh   10 years AGO

36% of 550 is 198 i.e.(113+85)

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Mahesh   10 years AGO

198 marks is 36%
For finding the maximum markss, it should be 198*100/36=550

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prabhat kumar   10 years AGO

36%=198
hence 100%=550

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vartika    10 years AGO

let max marks be x
then 36% of x- 113=85
solving we get x=550

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Sourojit Dhua   10 years AGO

Let us assume that the maximum marks for thr examination is x.
Then the equation we get as per simple linear equation:
36% of x = 113 + 85
36x/100 = 198
36x = 19800
x = 19800/36 = 550 marks.
Ans: 550 marks

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pragati rathore   10 years AGO

113=85=198
198=(36/100)*x
x=550

Like? Yes (3) | No (3)  

Abhishek Kumar   10 years AGO

113+85=36% of total marks
if total marks=x
36x/100=198
x=550

Like? Yes (1) | No (1)