M4maths Previous Puzzles

24 Sep 2014 Discount

A man purchases a cow for Rs.3000 and sold it on the same day allowing the buyer a credit of 2 years. If the buyer will pay Rs.3600 after 2 year at a rate of simple interest 50/7 % per annum, then the man has a gain of

OPtion

1) 5/2 %
2) 38/7 %
3) 5 %
4) 6 %
5) 9/2 %
6) 11/2 %
7) 7 %
8) 8/3 %
9) 13/2 %
10)None of these

Solution

P.W. of Rs. 3600 due 2 years hence at 50/7 % per annum
Rs (100*3600/ 100+(50*2/7)) = Rs. 3150
S.P. = Rs. 3150
Hence gain = 150*100/3000 = 5 %

Option 3)

Correct Option: 3 Best Solution (62)

v pavan   10 years AGO

r=50/7%,t=2years
let man sold it for p rupees
3600=p+(p*r*t/100)
solving it we get p=3150
gain (3150-3000)=150
gain%= 150*100/3000=5%

Like? Yes (12) | No (6)  

Perumal   10 years AGO

c.p=rs.3000
s.p=(3600*100)/(100+((50/7)*2)=rs.3150
gain = (3150-3000)/3000=0.05
% of gain = 5%

Like? Yes (2) | No   

V.Latha   10 years AGO

C.P = 3000
S.P = (3000*100)/(100+(50/7)*2) = 3150
gain = S.P- C.P = 3150-3000 = 150
% gain = (gain/cp)*100 = 5%

Like? Yes (1) | No   

vikash kumar   10 years AGO

5% is the ans

Like? Yes (1) | No   

Ankit Pandey   10 years AGO

C.P.= 3000 Rs.
Now, Actual S.P.= {(Given Money by Buyer*100)/(100+rate of interest*number of years)}
So S.P.= 3600*100/(100+2*50/7) = 3150 Rs
So Gain%= (S.P.- C.P./C.P.)*100 = 150*100/3000
Gain%= 5%

Like? Yes (1) | No   

Mahendra Jakka   10 years AGO

cp=3000
sp=pw of 3600 hence 2 years
=(100*3600)/(100+(50/7)*2)
=3150
profit=3150-3000=150
gain=(150/3000)*100=5%

Like? Yes (1) | No   

santosh kumar patel   10 years AGO

C.P. = Rs. 3000.
S.P. = Rs. [(3600 x 100)/(100+(50/7 x 2))]= Rs. 3150
gain=3150-3000=150
Gain% = (150*100)/3000=5%

Like? Yes (2) | No (1)  

NAMAN KAUSHIK   10 years AGO

cos d s.p for the cow will be rs 3150 for the man who sells it on d day same day. and the man being credited at given rate and time will pay back rs 3600 but will give after 2 years. so the profit percentage will be at the tym of selling the cow. hence gain/c.p*100== 150/3000*100=5%. anser.

Like? Yes (1) | No   

vinit   10 years AGO

3600*100/100(50/7*2)=3150(appox)
gain=3150-3000=150
now gain percentage=150*100/3000=5%

Like? Yes (2) | No (1)  

sai   10 years AGO

A=P(1+tr/100) we get principal as 3150
profit =150/3000*100
=5%

Like? Yes (1) | No   

mithilesh kumar   10 years AGO

c.p=3000
present value=future value/(1+r%)
so p.v=3600/(1+50/7*2) since for 2 yrs
on solving we get Rs.3150
so profit=150
%gain=(150/3000)*100=5%

Like? Yes (1) | No   

shikha panwar   10 years AGO

cost price=Rs. 3000
selling price=Rs.(3600*100)/(100+(57/7)*2)=Rs. 3150
gain=Rs.(3150-3000)=Rs. 150
% gain=(150/3000)*100=5%

Like? Yes (1) | No   

MOHIT GARG   10 years AGO

Let cost price is c and selling price is s .
C= (3000*50*2)/100*7=3248.55
S=3600
Gain= (s-c)*100/c=5%

Like? Yes (1) | No   

dhanaseelan   10 years AGO

Cost price=Rs 3000
Let selling price=x
after two years he will get 3600 Rs as total amount.
so Selling price + interest=Rs 3600
principle=x, interest rate= 50/7 %, time 2 years

3600= x + (x*(50/(7*100))*2)
By solving this x=3150
so selling price is Rs 3150
profit=3150-3000=Rs 150
gain percentage=(150/3000)*100= 5%

Like? Yes (1) | No   

A.Manohar   10 years AGO

finding p

Like? Yes (1) | No   

ADARSH GAURAV   10 years AGO

5% is the answer

Like? Yes (1) | No   

khushboo goenka   10 years AGO

coz, after 2 yr amt=3600 so originally he pay 3600*100/(100+50/7*2)=3150
so profit =150
ND 5% OF 3000=150

Like? Yes (1) | No   

ruthvik   10 years AGO

S.I for 2 years at 50/7 % S.I will be = (3000*2*50/7)/100 = 428.57
T.A= 3000+428.57=3428.57

therefore C.P of article after 2 years will be Rs 3428.57
but the buyer pays Rs 3600

therefore gain = 3600-3428.57 = Rs 171.43
gain %=(171.43/3428.57)*100= 5%

Like? Yes (1) | No   

amit yadav   10 years AGO

Let the actual selling price is X,
Now, we know that he takes 3600 after two years at the simple intrest of 50/7%,
So, X+2[50/7×X/100]=3600,
X=3150
Now gain of man is (3150-3000)/3000×100=5%

Like? Yes (1) | No   

DEDEEPYA J   10 years AGO

I=PTR/100
Here P=3000 , T= 2 years , R=50/7
so I= 428 rs
Act Amount + I = 3428
Gain= 3600-3428/3428 = 5.01 ~ 5 %

Like? Yes (1) | No   

Mounika inturi   10 years AGO

for Rs 3000 interest for two years will be Rs3428.57 but he was paid an amount of Rs3600 so the gain is 5%.

Like? Yes (1) | No   

Sundar Kumar   10 years AGO

cost price=Rs. 3000
selling price=Rs.(3600*100)/(100+(57/7)*2)=Rs. 3150
gain=Rs.(3150-3000)=Rs. 150
% gain=(150/3000)*100=5%
answer: Option 3) 5 %

Like? Yes (2) | No (1)  

deepak kumar   10 years AGO

3600-x=(x*2*50)/100*7
x=150
%gain=150*100/3000=5%

Like? Yes (1) | No   

Tania Chatterjee   10 years AGO

cost price=Rs. 3000
selling price=Rs.(3600*100)/(100+(57/7)*2)=Rs. 3150
gain=Rs.(3150-3000)=Rs. 150
% gain=(150/3000)*100=5%

Like? Yes (1) | No   

V SARATH KUMAR   10 years AGO

cost price=Rs. 3000
selling price=Rs.(3600*100)/(100+(57/7)*2)=Rs. 3150
gain=Rs.(3150-3000)=Rs. 150
% gain=(150/3000)*100=5%

Like? Yes (1) | No   

MP    10 years AGO

A man purchases a cow for Rs.3000 and sold it on the same day allowing the buyer a credit of 2 years. If the buyer will pay Rs.3600 after 2 year at a rate of simple interest 50/7 % per annum,then present value of that amount= Rs 3150/-.
profit = Rs 150.
% age profit= 100*150/3000= 5%

Like? Yes (1) | No   

Y V S Chandrakanth   10 years AGO

S.P+(S.P*2*50/7)/100=3600
then S.P=3150
Therefore,Gain %=((C.P-S.P)/C.P)*100
=5%

Like? Yes (1) | No   

Chirag Ranjan Lahiri   10 years AGO

Profit = 3150 - 3000 = 150
so gain% = (150*100)/3000 = 5%ans

Like? Yes (1) | No   

Chandra chur anand   10 years AGO

c.p=3000 rs
after 2 yr he will pay 3600rs so A=p+S.I.
and here amount A=3600
so S.I=P*50*2/700
S.I=P/7 hence we have to calculate P
A=P+S.I
3600=P+P/7
or 8P/7=3600 so P=3150
hence % gain= (3150-3000)*100/3000
= 5% gain ans
so option will be 3

Like? Yes (1) | No   

Anuj Tiwari   10 years AGO

sp=3600*100/(100+(50/7*2))
=3150

now gain =sp-cp
=3000-3150
=150

gain%=gain*100/cp
=15000/3000
=5
gain%= 5%

Like? Yes (1) | No   

gouthamdaneti   10 years AGO

cost=Rs. 3000
sp=Rs.(3600*100)/(100+(57/7)*2)=Rs. 3150
profit=Rs.(3150-3000)=Rs. 150
percent of profit=(150/3000)*100=5%

Like? Yes (1) | No   

Aastha   10 years AGO

given cp=3000
A=P+(P*r*t)/100
here,given A=3600,t=2years, r=50/7
3600=P +(P*50/7*2)/100
on solving,
P=3150=s.p
profit=s.p-c.p
profit=150
profit %=150/3000 *100
profit %=5%

Like? Yes (1) | No   

prabhat   10 years AGO

let assume principle is p
p+(p*50/7*2)/100=3600
p=3150
gain =3150-3000=150
gain%=(gain*100/cost price)
=(150*100)/3000
=5%

Like? Yes (1) | No   

lakshmi nalluri   10 years AGO

cp=3000
sp=3600*100/(100+50/7*2)
=3150
gain=sp-cp over cp
=(150/3000)*100
=5%

Like? Yes (1) | No   

Kushagra Tiwari   10 years AGO

cost price=Rs. 3000
selling price=Rs.(3600*100)/(100+(57/7)*2)=Rs. 3150
gain=Rs.(3150-3000)=Rs. 150
% gain=(150/3000)*100=5%

Like? Yes (1) | No   

Shreya Tiwari   10 years AGO

cost price=Rs. 3000
selling price=Rs.(3600*100)/(100+(57/7)*2)=Rs. 3150
gain=Rs.(3150-3000)=Rs. 150
% gain=(150/3000)*100=5%

Like? Yes (1) | No   

Abhishek Vishwakarma   10 years AGO

cost price=Rs. 3000
selling price=Rs.(3600*100)/(100+(57/7)*2)=Rs. 3150
gain=Rs.(3150-3000)=Rs. 150
% gain=(150/3000)*100=5%

Like? Yes (1) | No   

BHASKAR MANDAL   10 years AGO

amount = 3600
3600 = p (1+ (2*50)/(7*100) )
=> p = 3150

so the percentage profit
= (3150 - 3000)*100/3000
= 5%

Like? Yes (1) | No   

harika challagolla   10 years AGO

3600-p=(p*2*50)/(100*7)
p=3150
gain=(3150-3000)*100/3000=5%

Like? Yes (1) | No   

RANDHIR KUMAR   10 years AGO

(1200/7)/(24000/7)*100=5%

Like? Yes (1) | No   

Devesh Gupta   10 years AGO

Selling Price=(3600X100)/(100+((50/7)*2))=3150

Gain %= ((3150-3000)/3000)*100= 5%

Like? Yes (1) | No   

sujata chakraborty   10 years AGO

selling price of the man =present worth on Rs 3600due 2 year and interest of (50/7)% ,o selling price =(3600*100)/(100+(50/7)*2)=3150 Rs, so gain =s.p-c.p=3150-3000=Rs 150,so gain %gain =(gain/c.p)*100=(150/3000)*100=5%

Like? Yes (1) | No   

RAKESH   10 years AGO

3600*100 / (100+ 2*50/7) = 3150

gain = 150/3000 *100 = 5%

Like? Yes (1) | No (1)  

Tark Patel   10 years AGO

C.P. = 3000 /
S.P. = (3600 * 100) / ( 100 + ((50/7) *2) ) = 3150 /-

Gain = 5%

Like? Yes (3) | No (3)  

NAVEEN KUMAR   10 years AGO

cost price=Rs. 3000
selling price=Rs.(3600*100)/(100+(57/7)*2)=Rs. 3150
gain=Rs.(3150-3000)=Rs. 150
% gain=(150/3000)*100=5%

Like? Yes (2) | No (2)  

Shashank Kapoor   10 years AGO

S.p. will come out to be 3150
3600*100/100+((50/7)*2)=3150

there will be gain of 150

so (150/3000)*100=5%
so option 3 is correct

Like? Yes (1) | No (1)  

swarupa nuggu   10 years AGO

5

Like? Yes (1) | No (1)  

MD SOHAIL AKHTER   10 years AGO

let the principle be x
A/Q
x*2*(50/7)/100+x=3600
x=3150
gain =3150-3000=150

gain %= 150*100/3000=5%

Like? Yes (2) | No (2)  

Sourojit Dhua   10 years AGO

Using true discount formula-
we get SP=3150
So, net gain=150 i.e. 5%

Like? Yes (1) | No (1)  

pawan kumar   10 years AGO

after 2 yr=3000+ (3000*2*50)/(100*7) = Rs. 3428.57
so, gain= 3600-3428.57= 171.43

gain%= (171.43*100)/3428= 5%

Like? Yes (2) | No (2)  

sanjeev kumar   10 years AGO

5%

Like? Yes (1) | No (1)  

Mogilipuri.Harish   10 years AGO

3600x100/100+(100/7)=>3150

150X100/3000=5%
ans: 5%

Like? Yes (1) | No (1)  

mamta garkoti   10 years AGO

let the sp be p, then we have
3600-p=p*2*50/700
from here we get p=3150 and cp is 3000 so gain is 150 hence gain% is 150/3000*100= 5%

Like? Yes (1) | No (1)  

Manish Singhal   10 years AGO

si= p*{50/7*2}/100
si=p/7
A-p=p/7
A=p+p/7
3600=8p/7
450*7=p
p=3150
profit=3150-3000
profit=150
profit%=150*100/3000
profit%=5% Ans

Like? Yes (3) | No (3)  

Sagar Kumar Subudhi   10 years AGO

present worth of 3600 is 3150. so ((3150-3000)/3000)*100=5

Like? Yes (1) | No (1)  

Mahesh   10 years AGO

3600 after two years is equal to 3150 today

so the person gains 5%

Like? Yes (1) | No (1)  

ANKITA KUMARI   10 years AGO

gain =1200/7
original amount=24000/7
gain%=5%

Like? Yes (1) | No (1)  

arpan dhara   10 years AGO

amount = p+(p*r*t)/100
buyer gives 3600
original cost at rate 50/7 is 3428.58
so gain %=((3600-3428.58)/3428.58)*100

Like? Yes (1) | No (1)  

Rekha goyal   10 years AGO

selling price is 3150 according to simple interest formula. then gain is 5%

Like? Yes (1) | No (1)  

SANDEEPA   10 years AGO

calculate simple interest for p=300,R=50/7,T=2 yrs....
simple interest=3000*2*50/100*7=428...
so,amount=3428.
Gain %=(3600-3428/3428)*100
=5.01%

Like? Yes (1) | No (1)  

saisudha sarva   10 years AGO

S.I=3000*2*5/7*100=3000/7
amount=24000/7

thus get 5% profit.

Like? Yes (1) | No (1)  

Gitanjali K   10 years AGO

cost price= 3000 Rs
selling price=(3600*100)/(100+(50/7)*2)=3150 Rs
so,gain=(3150-3000)=150 Rs
therefore,
gain (%)=150*100/3000=5%

Like? Yes (1) | No (1)  

23 Sep 2014 Time and Distance

A man can row 30 km upstream and 44 km downstream in 10 hours. Also, he can row 40 km upstream and 55 km downstream in 13 hours. Find the rate of current and the speed of the man in still water.

OPtion

1) 3 km/hr and 8 km/hr
2) 5 km/hr and 12 km/hr
3) 4 km/hr and 11 km/hr
4) 3 km/hr and 12 km/hr
5) 4 km/hr and 10 km/hr
6) 5 km/hr and 11 km/hr
7) 7 km/hr and 14 km/hr
8) 6 km/hr and 15 km/hr
9) 3 km/hr and 4 km/hr
10)None of these

Solution

Let rate upstream = x kmph & rate downstream = y kmph
Then 30/x + 44/y = 10
and 40/x + 55/y = 13

On solving we get x = 5 and y = 11
So, rate upstream = 5 km/hr and rate downstream = 11 km/hr
Rate of current = 1/2(11-5) km/hr = 3 km/hr
Rate in still water = 1/2(11+5) km/hr = 8 km/hr

Option 1)

Correct Option: 1 Best Solution (93)

Sourojit Dhua   10 years AGO

Let rate upstream = x km/hr
and rate downstream = y km/hr.
Then,40/x +55/y = 13...(i)
and 30/x +44/y = 10
Multiplying (ii) by 4 and (i) by 3 and subtracting ,we get:11/y = 1 or y = 11.
Substituting y = 11 in (i),
we get: x = 5.
Rate in still water =1/2(11+5) kmph = 8 kmph.
Rate of current=1/2(11-5)kmph = 3 kmph

Like? Yes (55) | No (21)  

rajan kumar   10 years AGO

option 1) 3 km/hr and 8 km /hr
my solution is based on check by option...
for upstream :
speed of man = speed of man - rate of current
= 8 - 3 = 5 km/hr
for down stream :
speed of man= speed of man + rate of current
= 8+ 3= 11 km/hr
total time = up time + down time
= 30/5 + 44/11
6 + 4 = 10
so option satisfy the equation that's why Ans is (1)

Like? Yes (17) | No (4)  

Kushagra Tiwari   10 years AGO

Let rate upstream = x km/hr
and rate downstream = y km/hr.
Then,40/x +55/y = 13...(i)
and 30/x +44/y = 10
Multiplying (ii) by 4 and (i) by 3 and
subtracting ,we get:11/y = 1 or y = 11.
Substituting y = 11 in (i),
we get: x = 5.
Rate in still water =1/2(11+5) kmph =
8 kmph.
Rate of current=1/2(11-5)kmph = 3
kmph

Like? Yes (15) | No (5)  

suganya   10 years AGO

Let rate upstream = x km / hr and rate downstream = y km / hr.
Then, 40/x+ 55/y =13 ...(i)
and 30/x+44/y=10 ...(ii)
Multiplying (ii) by 4 and (i) by 3 and subtracting, we get :
11/y=1 or y=11.
Substituting y = 11 in (j), we get : x = 5.
threrefore Rate in still water =1/2(11+5)kmph=8kmph.
Rateofcurrent= 1/2(11−5)kmph=3kmph.

Like? Yes (12) | No (5)  

naina   10 years AGO

Let rate upstream = x km / hr and rate
downstream = y km / hr.
Then, 40x+ 55y =13 ...(i)
and 30x+44y=10 ...(ii)
Multiplying (ii) by 4 and (i) by 3 and
subtracting, we get :
11y=1ory=11.
Substituting y = 11 in (j), we get : x = 5.
\threrefore Rate in still water =
12(11+5)kmph=8kmph.
Rateofcurrent= 12(11−5)kmph=3kmph.

Like? Yes (14) | No (8)  

Vanika   10 years AGO

Let speed of man in still water= x km/h
rate of current = y km/h
so 30/(x-y) + 44/(x+y) = 10 .......eq(1)
40/ (x-y) + 55/ (x+y) = 13.......eq(2)
solving
x = 8 km/h
y = 3 km/h

Like? Yes (8) | No (2)  

Aastha   10 years AGO

let speed in upstream be u
speed in downstream be d
now,
a/c to question
30/u+44/d=10 .eq(1)
40/u+55/d=13...eq(2)
solving eq(1) & eq(2)
u=5km/hr
d=11km/hr
speed of current=c
speed of man=m
5=m-c
11=m+c
on solving
m=8,c=3

Like? Yes (10) | No (5)  

Inline Geek   10 years AGO

let speed of current and man in still water be y and x respectively

no solve these equetions

(30 / (x - y) ) + (44 / (x + y)) = 10

(40 / (x - y) ) + (55 / (x + y)) = 13

x = 8,
y = 3

Like? Yes (9) | No (5)  

Surya Srivastava   10 years AGO

equation is
30/x-y+44/x+y=10
now put the values given whenever it satisfies the equation
its the ans.

Like? Yes (5) | No (1)  

raushan kumar   10 years AGO

let the speed of man in still water be X
speed of current be Y
According to equation
30/X+Y + 44/X-Y =10
40/X+Y + 55/X-Y =13
by solving equation
X&Y=8&3 ans

Like? Yes (3) | No   

Premchander   10 years AGO

Let rate upstream = x km / hr and rate downstream = y km / hr.
Then, 40x+ 55y =13 ...(i)
and 30x+44y=10 ...(ii)
Multiplying (ii) by 4 and (i) by 3 and subtracting, we get :
11y=1ory=11.
Substituting y = 11 in (j), we get : x = 5.
\threrefore Rate in still water =
12(11+5)kmph=8kmph.
Rateofcurrent= 12(11−5)kmph=3kmph.

Like? Yes (4) | No (1)  

Anant Vardhan   10 years AGO

Downstream Speed = 11kmph = B + R
Upstream Speed = 5kmph = B - R
,where B= Speed of Man
R= Speed of River
Solve the above two equations.

Like? Yes (4) | No (1)  

Rashi Bansal   10 years AGO

let rate of upstream= x km/hr and rate of downstream= y km/hr
a.t.q.
30/x +44/y=10
40/x + 55/y=13
solving these equations x=5,y=11
rate of current=1/2(y-x)=3km/hr
rate in still water=1/2(y+x)=8km/hr

so option (1) is correct.

Like? Yes (5) | No (3)  

Shreya Tiwari   10 years AGO

Let rate upstream = x km/hr
and rate downstream = y km/hr.
Then,40/x +55/y = 13...(i)
and 30/x +44/y = 10
Multiplying (ii) by 4 and (i) by 3 and
subtracting ,we get:11/y = 1 or y = 11.
Substituting y = 11 in (i),
we get: x = 5.
Rate in still water =1/2(11+5) kmph =
8 kmph.
Rate of current=1/2(11-5)kmph = 3
kmph

Like? Yes (2) | No   

BHASKAR MANDAL   10 years AGO

let x be the speed of the man in still water, and y be the speed of stream.
we can write,
30/(x-y) + 44/(x+y) = 10
40/(x-y) + 55/(x+y) = 13

on solving, x=8 and y= 3
it can be directly found out by substituting the values in the equation.

Like? Yes (3) | No (1)  

Arnab Mukherjee   10 years AGO

let rate in upstream is xkm/hr and downstream is ykm/hr
40/x+55/y=13 and 30/x+44/y=10
multiplying this equation we get 11/y=1 y= 11

and substitute it any equation we get x=5
rate in still water=(11+5)/2=8 kmph
rate of the current=(11-5)/2=3 kmph

Like? Yes (2) | No   

Suganya   10 years AGO

LET X=rate of current
Y=speed of man in still water

30/x+44/y=10
40/x+55/y=13
Solving these two equations
x=5
y=11
rate of current =(x-y)/2=3km/hr
speed in still water=(x+y)/2=8km/hr

Like? Yes (5) | No (3)  

ADARSH GAURAV   10 years AGO

1 is the correct option

Like? Yes (2) | No   

Abhimanyu kumar   10 years AGO

30/(x-y) +44/(x+y) =10........(i)
40/(x-y) + 55/(x+y) =13 ......(ii)
solve &get x=8, y=3

Like? Yes (3) | No (1)  

pawan kumar   10 years AGO

Let. Upstream speed = U Downstream speed = D
so, 30D+44U = 10UD
40D+55U = 13UD
Hence, U=5 , D=11
so, speed of curr=3kmph ,
speed of man=8kmph

Like? Yes (2) | No   

Abhishek Tiwari   10 years AGO

let the speed upstream be: x km/hr and speed downstream be : y km/hr
now,
time=dist./speed
so, 30/x+44/y=10......................eqn(1)
and 40/x+55/y=13....................eqn(2)
on solving both, we get :
x=5 km/hr and y=11 km/hr
now, speed of man in still water will be:
1/2*(y+x)=8 km/hr
and rate of current will be : 1/2*(y-x) = 3 km/hr
so, option (1) is correct

Like? Yes (2) | No (1)  

neha kumari   10 years AGO

30/x+44/y=10
40/x+55/y=13

Like? Yes (1) | No   

somaiah tummala   10 years AGO

let upstream=x km/hr,downstream=y km/hr
then 40x+55y=13 ---(1)
and 30x+44y=10 ---(2)
multiply eqn(2) with 4 & eqn(1) with 3
we get x=5 and y=11
therefore rate in still water=12(11+5)=8kmphr
rate of current=12(11-5)=3kmphr

Like? Yes (2) | No (1)  

ANTRISH MISHRA   10 years AGO

if rate of US=x;
and rate of DS=y;
then,
(30/x) + (44/y) =10..........(1)
(40/x) + (55/y) =13...........(2)
solving 1 and 2 we get x=5,y=11
now rate in current water=1/2(11-5)=3 kmph
and rate in still water = 1/2(11+5)=8 kmph

Like? Yes (1) | No   

prabhat   10 years AGO

let rate of stream =x km/h and rate downstream =y km/h
30/x+44/y=10 and 40/x+55/y=13
then solve equation the value of x =5 and y=11
rate in steel water =1/2(11-5)=8
rate of current=1/2(11-5)=3

Like? Yes (2) | No (1)  

Ankit Pandey   10 years AGO

Let us suppose upstream rate= x km/hr
downstream rate = y km/hr
so,
(30/x)+(44/y)=10 .........(1)
(40/x)+(55/y)=13 .........(2)
on solving both, we get y=11 km/hr
and x= 5 km/hr
so current rate=1/2(11-5)=3 km/hr
and rate of man in still water= 1/2(11+5)= 8 km/hr

Like? Yes (1) | No   

shiv   10 years AGO

rate updtream=x
rate downstream=y
30/x + 44/y =10
40/x + 55/y=13
on solving , we get
x=5,y=11
rate of current=(11-5)/2 =3
spped of men in still water =(11+5)/2 =8

Like? Yes (1) | No   

Shashi nath jha   10 years AGO

Ans

Like? Yes (3) | No (2)  

Mahendra Jakka   10 years AGO

b, s speeds of boat and stream
from given data- (30/b-s)+(44/b+s)=10
(40/b-s)+(55/b+s)=13
37b-7s=5(b2-s2)
95b-15s=13(b2-s2)
solving we get b=8kmph & s=3 kmph

Like? Yes (1) | No   

Ritesh Kumar   10 years AGO

option matching

Like? Yes (2) | No (1)  

V.Latha   10 years AGO

rate of upstream = x km/hr,
rate of downstream = y km/hr
40x+55y = 13 ---->(i)
30x+44y = 10 ---->(ii)
x = 5 and y = 11
Rate in still water = (11+5)/2 =16/2 = 8km/hr
rate of current = (11-5)/2 = 6/2 = 3km/hr

Like? Yes (1) | No   

Bharat Ratna   10 years AGO

let sepeed upstream=x downstream=y
30/x+44/y=10 and 40/x+55/y=13
solving x=5 y=11 speed in still water =1/2(x+y) =8km/h speed stream=1/2(y-x)= 3km/h

Like? Yes (2) | No (1)  

mithilesh kumar   10 years AGO

let upstraem=x doenstream=y
so 30/x+44/y=10 .....(1) sinse t=distance/speed
and
40/x+55/y=13.....(2)
solving these 2 eqn we get x=5 and y=11
now rate of current=(11-5)/2=3km/h
and speed of man=(11+5)/2=8km/h

Like? Yes (1) | No   

dhanaseelan   10 years AGO

lets take speed of the downstream is a and upstream is b
(30/a)+(44/b)=10
(40/a)+(55/b)=13
by solving these two equations you will get a=11, b=5
so rate of the current=(a-b)/2=3 kmph
speed of the man=(a+b)/2=8 kmph

Like? Yes (1) | No   

ANKUR ANAND   10 years AGO

by option checking we can get the result:
30/(8-5)+ 44/(8+3)=10
and 40/(8-5) +55/(8+5)=13

answer is 1)

Like? Yes (3) | No (2)  

Mello   10 years AGO

u=man speed, v=current
take upstream speed=u-v, downstream=u+v
so by time=distance/speed
and taking u-v=n and u+v=m we get
30n+44m=10
40n+55m=13
solve two eqn get values of m & n
then substitute it fr getting values of u & v

Like? Yes (2) | No (1)  

SOURABH   10 years AGO

let speed of man in still water be x and speed of current be y
speed in upstream=x-y
speed in downstream=x+y
30/(x-y)+44/(x+y)=10
40/(x-y)+55/(x+y)=13

Like? Yes (3) | No (2)  

veeranjaneyulu   10 years AGO

30/x+44/y=10,40/x+55/y=13
solve these two equations we get x=5,y=11
then in stillwter=1/2(x+y)=8
rate of current=1/2(x-y)=3 its not negative

Like? Yes (1) | No   

Anuj Tiwari   10 years AGO

let rate upstream=x & rate downstream=y

30/x + 44/y =10 ...(1)
40/x + 55/y =13 ...(2)
solving 1 & 2 we get,
x=5 y=11
now,
rate of current=(11-5)/2=3
speed of man in still water=(11+5)/2=8

Like? Yes (2) | No (1)  

Ravi Kumar   10 years AGO

let x=1/D and y=1/U
44x+30y=10
55x+40y=13
solving D=11 , U=5
rate of current = (D-U)/2=3
speed of man in still water =(D+U)/2=8

Like? Yes (2) | No (1)  

kadurla siva teja   10 years AGO

v-u=30/t1 v+u=4/t2 t1+t2=10
v-u=40/t1 v+u=55/t2 t1+t2=13
by solving we get v=8 u=3

Like? Yes (1) | No   

madhuri   10 years AGO

let downstream speed is d km/h
and upstream speed is u km/h
then
30/u + 44/d = 10
40/u + 55/d = 13
on solving,
u=5 km/h
d=11 km/h
So rate of current=1/2*(d-u)=1/2*(11-5)=3km/hr
and speed in still water=1/2*(u+d)=1/2*(5+11)=8km/hr

Like? Yes (1) | No   

Dark Knight   10 years AGO

let the upstream be x and downstream be y
then
40/x+55/y=13-------1
30/x+44/y=10-------2
solving we will get x as 5 and y as 11
rate of stream 1/2(11-5)=3km
rate at still h20=1/2(11+5)=16

Like? Yes (1) | No   

Chandra chur anand   10 years AGO

30/x+44/y=10 and 40/x+55/y=13
by equating both equation we get x=5 km/hhr and y=11 km/hr
now speed of man=(11+5)/2=8 km/hr
and rate of current=(11-5)/2=3km/hr
hence option 1 is correct

Like? Yes (1) | No   

amit vijayvargiya   10 years AGO

30u+44d=10
40u+55d=13
so u=5, d=11
rate of current=(d-u)/2;
speed of man in still water=(d+u)/2
rate of current=3
speed of man in still water=8

Like? Yes (1) | No   

Surit Datta   10 years AGO

Let rate of current is y and the speed of the man in still water is x
so according to the given data we say,
30/(x-y) + 44/(x+y) = 10
40/(x-y) + 55/(x+y) = 13
solving the above two we get,
x = 3
y = 8
So rate of current is 3km/hr
and
the speed of the man in still water is 8km/hr.
That's it..

Like? Yes (1) | No   

Biswajit Malakar   10 years AGO

let rate of upstream = x km/hr and downstream y km/hr
then
30/x + 44/y = 10 -(i) and 40/x + 55/y = 13 -(i)
multiplying 4 in (i)
and 3 with (ii)
we get y=11,x=5
rate in still water 1/2(11+5)=8 km/hr
rate of current 1/2(11-5)=3 km/hr

Like? Yes (1) | No   

srija   10 years AGO

30/x+44/y=10
40/x+55/y=13
after solving we get x=11,y=5
rate in stillwater=1/2(11+5)=8kmph
rate of current=1/2(11-5)=3kmph

Like? Yes (1) | No   

Y V S Chandrakanth   10 years AGO

30/(u-v)+44/(u+v)=10

40/(u-v)+55/(u+v)=13

By Verification of options we will get option (1).

Like? Yes (1) | No   

Avinash Aryan   10 years AGO

1

Like? Yes (1) | No   

ravi prakash   10 years AGO

30/a+44/b=10;
40/a+55/b=13;
here a=(x-y)down stream ,x=speed of current,y=of man
b=(x+y)upstream
on solving x=3
y=8

Like? Yes (1) | No   

suresh   10 years AGO

let upstream is x and downstream is y
30/x+44/y=10---------1
40/x+55/y=13---------2
now multiply 1 with 4 & multiply 2 with 3
then we get y=11 substituting in 1 we get x=5
then rate of current is=1/2(down stream-up stream)
=1/2(11-5)=3
speed of man=1/2(11+5)=8

Like? Yes (1) | No   

Basil Sufyan   10 years AGO

this will be solved by simultanious equation
30/(m-s)+44/(m+s)=10.... eqn 1
40/(m-s)+55(m+s)=13... eqn 2

where m=speed of man in still water and s =speed of stream
solve it and you will get the answer

Like? Yes (1) | No   

Souvik Datta   10 years AGO

Let rate upstream = x km/hr and rate downstream = y km/hr
then, 40/x+55/y=13 ... (i) and 30/x+44/y=10 ... (ii)
after solving this we get y=11, x=5
rate of current =1/2(11-5)= 3 kmph
man in still water= 1/2(11+5)= 8 kmph

Like? Yes (1) | No   

siddharth prakash singh   10 years AGO

let upstream=x, down stream=y
40/x+55/y=13
30/x+44/y=10
solving both. x=5 and y=11
so,rare in still water=(11+5)/2=8
rate of current=(11-5)/2=3

Like? Yes (1) | No   

khushboo goenka   10 years AGO

let upstream speed=x , downstrm=y.
thn in 10 hrs, time by upstrm=30/x
tym by dwn=44/y
30/x =+44/y=10
similarly, 40/x + 55/y =13
on solving these 2 eqtns we get x=5, y=11
now speed of man - speed of stil water=5
speed of man + speed of water = 11
on solving, man speed = 8 km/hr nd still water rate = 3 km/hr

Like? Yes (1) | No   

MANU   10 years AGO

let speed in upsterm =x km/h and down stream =y km/h;
40/x+55/y=13;
30/x+44/y=10
solving we get
x=5 and y=11;
so speed of man on still water=8 kn/h;
speed of current=3 km/h;

Like? Yes (1) | No   

Ayush Chawla   10 years AGO

let speed upstream be x kmhr and downstream be y kmhr
40/x + 55 /y = 13 -- (i)
30/x + 44/y = 10 -- (ii)
multiple (ii) by 4 and (i) by 3 and subtract we get y/11=1 or y=11
thus x =5
rate in still water of man = 1/2(11+5) = 8 km/hr
rate of current = 1/2(11-5)=3 km/hr

Like? Yes (1) | No   

Dr.Dipin Singh   10 years AGO

30/5+44/11=10
40/5+55/11=13

Like? Yes (1) | No   

Mahesh   10 years AGO

Let take his upstream speedd and down stream speed as x and y
30/x+44/y=10
40/x+55/y=13
lets take 1/x and 1/y as a and b respectively
By solvinf the two equations we will get a as 1/5 and b as 1/11
x and y are 5 and 11
So, speed of the stream and boat are 3 and 8 respectively
Correct answer is A

Like? Yes (2) | No (2)  

NAVEEN KUMAR   10 years AGO

let rate of up stream=x km/h and downstream= y km/h
then,30x+44y=10----(1)
40x+55y=13---(2)
after solving x=1/5
y=1/11
hence,upstram speed=5km/h
downstream=11km/h
rate of current=(11-5)/2=3km/h
speed of the man in still water=(11+5)/2=8km/h
option(1)

Like? Yes (5) | No (5)  

Ravi Bhalani   10 years AGO

Let rate upstream = x km / hr and rate downstream = y km / hr.
Then, 40/x+ 55/y =13 ...(i)
and 30/x+44/y=10 ...(ii)
Multiplying (ii) by 4 and (i) by 3 and subtracting, we get :
11/y=1 or y=11.
Substituting y = 11 in (j), we get : x = 5.
threrefore Rate in still water =
1/2(11+5)kmph=8kmph.
Rateofcurrent= 1/2(11−5)kmph=3kmph.

Like? Yes (2) | No (2)  

Sohidul Islam   10 years AGO

Let x and y be the speed of the boat in still water and speed of the stream respectively
So we get the following 2 equations
44/(x+y) +30/(x-y)=10 -------------[1]
55/(x+y)+40/(x-y)=13 --------------[2]
Solving this equations we get x=8,y=3........hence option 1

Like? Yes (2) | No (2)  

MOHIT GARG   10 years AGO

Let rate upstream = x km / hr and rate downstream = y km / hr.
Then,  40x+ 55y   =13   ...(i)
and   30x+44y=10       ...(ii)
Multiplying (ii) by 4 and (i) by 3 and subtracting, we get : 
11y=1ory=11.
Substituting y = 11 in (j), we get : x = 5.
\threrefore Rate in still water =
12(11+5)kmph=8kmph.
Rateofcurrent= 12(11−5)kmph=3kmph.

Like? Yes (4) | No (4)  

Abhishek Vishwakarma   10 years AGO

Let rate upstream = x km/hr
and rate downstream = y km/hr.
Then,40/x +55/y = 13...(i)
and 30/x +44/y = 10
Multiplying (ii) by 4 and (i) by 3 and
subtracting ,we get:11/y = 1 or y = 11.
Substituting y = 11 in (i),
we get: x = 5.
Rate in still water =1/2(11+5) kmph =
8 kmph.
Rate of current=1/2(11-5)kmph = 3
kmph

Like? Yes (2) | No (2)  

Narasapu Hari prasad   10 years AGO

option 1 is correct
let x be the speed of man in still water and y is current speed
from given data
30/(x-y)+44/(x+y)=10
74x-14y=10x^2-10y^2---------------(1)
40/(x-y)+55/(x+y)=13
95x-15y=13x^2-13y^2---------------(2)
solve (1) and(2) you will get
x/y=32/12=8/3
so x=8,y=3
speed of man is 8 and current water speed is 3

Like? Yes (1) | No (1)  

anandhakumar   10 years AGO

ans is option 1

Like? Yes (2) | No (2)  

Pradeep Saw   10 years AGO

Let rate upstream = x km / hr and rate downstream = y km / hr.
Then, 40x+ 55y =13 ...(i)
and 30x+44y=10 ...(ii)
Multiplying (ii) by 4 and (i) by 3 and
subtracting, we get y=11.
Substituting y = 11 in (j), we get : x =
5.
Rate in still water =12(11+5)kmph=8kmph.
Rate of current= 12(11−5) kmph=3kmph

Like? Yes (3) | No (3)  

vikash kumar   10 years AGO

3km/h and 8km/h is the ans

Like? Yes (1) | No (1)  

Mogilipuri.Harish   10 years AGO

up to stream is =x km/hr
rate of downto stream= y km/hr
then 40/x+55/y=13 and 30/x+44/y=10
then we get x=5 and y=11
rate in still water =1/2(11+5)= 8 km/hr
rate of current =1/2(11-5)= 3 km/hr

Like? Yes (3) | No (3)  

Gitanjali K   10 years AGO

let, rate upstream = x km/hr
rate downstream = y km/hr

given, 30/x+44/y=10.....(1)
40/x+55/y=13 ...(2)

solving eq(1)&(2)
we get x=5, y=11

so speed of man in still water=(11+5)/2=8km/hr
rate of current=(11-5)/2=3km/hr
hence is the answer..

Like? Yes (2) | No (3)  

S.SHAFI   10 years AGO

Let rate upstream = x km/hr
and rate downstream = y km/hr.
Then,40/x +55/y = 13...(i)
and 30/x +44/y = 10
Multiplying (ii) by 4 and (i) by 3 and subtracting ,we get:11/y = 1 or y = 11.
Substituting y = 11 in (i),
we get: x = 5.
Rate in still water =1/2(11+5) kmph = 8 kmph.
Rate of current=1/2(11-5)kmph = 3 kmph

Like? Yes (2) | No (3)  

PAWAN KUMAR   10 years AGO

let the spped of man in still water be x km/h and the speed of current be y km/h.
then, 30/(x-y) + 44/(m+s) = 10
and 40/(x-y) + 55/(x+y) = 13
on solving, we get x= 8km/h and y= 3 km/h. Ans.

Like? Yes (1) | No (2)  

nishu kumar   10 years AGO

let rate in upstream =x km/h
rate downstrean=y km/h
then,
30/x+44/y=10......(1)
40/x+55/y=13.....(2)
solving both equations,we get
x=5km/h
y=11km/h
then
rate of current=1/2*(downstream speed-upstream speed)
=1/2*(11-5)
=3 km/h.
apeed of man in still water=1/2*(downstream speed+upstream speed)
=1/2*(11+5)
=8km/h

Like? Yes (1) | No (2)  

Urvashi Jain   10 years AGO

let rate upsream =xkm/hr and downstream y km/hr
30/x+44/y=10...1
40/x+55/y=13...2
x=5 y=11
rate of current=1/2(11-5)=3km/hr
rate in still water=1/2(11+5)=8km/hr

Like? Yes (1) | No (2)  

sudhakar   10 years AGO

option 1)3 km/hr and 8 km/hr

Like? Yes (3) | No (4)  

J.Praveen Kumar   10 years AGO

from problem we can have 2 equations:
sb=speed of boat(man)
sw=speed of water(current)
1) : (30/(sb-sw) ) + (44/(sb+sw)) = 10

2) : (40/(sb-sw))+(55/(sb+sw)) = 13

by solving these equations we have

12sb=32sw
substitute option 1 we have answer.

Like? Yes (1) | No (2)  

kumar   10 years AGO

eqn will be
30/(x-y) +44/(x+y) =10
and
40/(x-y)+55(x+y)=13

since you have options then check for eqn 1st if satisfy then check for eqn 2
so first opn
3,8
30/5+44/11=10 satisfy
for eqn 2
40/5+55/11=13
hence ans 1)

Like? Yes (1) | No (2)  

deepak kumar   10 years AGO

in up stream speed 8-3=5km/hr so time taken in up stream 30/5=6hr and during down stream speed=11km/hr and time = 44/11=4hr.total time=6+4=10 hr.

Like? Yes (1) | No (2)  

Neel Patel   10 years AGO

Check by option

Like? Yes (1) | No (2)  

Kumar Vishal   10 years AGO

1

Like? Yes (1) | No (2)  

Supriya Sinha   10 years AGO

Speed of man+ speed of stream==11

Like? Yes (1) | No (2)  

Tark Patel   10 years AGO

Let rate upstream = x km/h and rate downstream = y km/h

Given-> 40/x + 55/y = 13 and 30/x + 44/y = 10
Solving this two expressions we get x = 5 km/h and y = 11 km/h

rate in still water = 1/2 ( 11 + 5 ) = 8 km/h
rate of current = 1/2 ( 11 - 5 ) = 3 km/h

Like? Yes (1) | No (2)  

Amit Verma   10 years AGO

let the speed of man be x km/hr
and that of current be y km/hr
so
time taken to go upstream be t1 hrs and downstream (10-t1) hrs
similarly for second case t2 and 10-t2

(x-y)*t1+(x+y)(10-t1)=74
(x-y)*t2+(x+y)(10-t2)=95
now refer to options only first option satisfies it
crrent -= 3km/hr and man =8km/hr
because when we downstream 44 km of distance is travelled which is multiple of 4 and 11
so first option satisfies it

Like? Yes (1) | No (2)  

sandeepsingh   10 years AGO

find by solving

Like? Yes (1) | No (2)  

saimeera   10 years AGO

let man's speed be x;
and rate of current be y;

(30/(x-y))+(44/(x+y))=10
(40/(x-y))+(55/(x+y))=13

solving for x and y,
x=8 and y=3

Like? Yes (1) | No (2)  

Shashank Kapoor   10 years AGO

let upstream=x km/hr
let downstream=y km/hr

then 30/x+44/y=10 (i)
and 40/x +55/y=13 (ii)

solving (i) and (ii)
x= 5km/hr and y= 11km/hr

rate in still water= 1/2(11+5)=8 and rate of current= 1/2(11-5)=3.
so ans is option 1

Like? Yes (1) | No (3)  

Harshad    10 years AGO

Let rate upstream = x km / hr and rate downstream = y km / hr.
Then, 40/x+ 55/y =13 ...(i)
and 30/x+44/y=10 ...(ii)
Multiplying (ii) by 4 and (i) by 3 and subtracting, we get :
11/y=1 or y=11.
Substituting y = 11 in (j), we get : x = 5.
threrefore Rate in still water =
1/2(11+5)kmph=8kmph.
Rateofcurrent= 1/2(11−5)kmph=3kmph.

Like? Yes (1) | No (3)  

DIPAK TIWARI   10 years AGO

30/(u-v) + 44/(u+v) =10........(i)
40/(u-v) + 55/(u+v) =13........(ii)
u=8 & v=3
option 1

Like? Yes (2) | No (4)  

raghu   10 years AGO

check with options.....
x= speed in upstream, y=speed in down stream.....
30/x + 44/y =10 and 40/x + 55/y =13
check x and y with different values. you will get the answer
(or)
solve those equations above you get x=5 and y=11...

rate of current or speed of stream= 1/2(y-x)
=1/2(6)
=3 km/hr
speed of the man in still water=1/2(x+y)
=8 km/hr

Like? Yes (1) | No (3)  

RAKESH   10 years AGO

30/ x-y + 44/ x+y = 10

40/ x-y + 55/ x+y = 13

x=8,y=3

Like? Yes (2) | No (5)  

lakshmi nalluri   10 years AGO

upstream be x n downstream be y
then,30/x+44/y=10
and 40/x+55/y=13
on solving,x=5, y ll be 11
and rate in still water=(11+5)/2=8
rate of current=11-5)/2=3

Like? Yes (2) | No (6)  

santosh kumar patel   10 years AGO

let rate upstrem =x km/h and rate downstream=y km/h
then, 30/x+44/y=10...............1
and 40/x+55/y=13.................2
solve the equation 1 and 2
we get x=5 and y=11
so rate of current water=1/2(11-5)=3 km/h
and rate of still water=1/2(11+5)=8 km/h

hence ans: rate of current water = 3 km/h
rate of still water = 8 km/h

Like? Yes (1) | No (6)  

22 Sep 2014 Sequence

What is the next number of the following sequence
986, 7248, 14832, 432246, 1264824, .....

OPtion

1) 3983434
2) 21243281
3) 490758
4) 2243216852
5) 626828924
6) 71645342
7) 24162343
8) 2122432168
9) 297685421
10)None of these

Solution

First number is 986
Then 9*8/8*6 = 72/48 = 7248 (it is second number)
Then 7*2/2*4/4*8 = 14/8/32 = 14832 (it is third number)
Then 1*4/4*8/8*3/3*2 = 4/32/24/6 = 432246 (it is fourth number)
Then 4*3/3*2/2*2/2*4/4*6 = 12/6/4/8/24 =1264824 (it is fifth number)
Similarly 1*2/2*6/6*4/4*8/8*2/2*4 = 2/12/24/32/16/8 = 2122432168

Correct Option: 8

Correct Option: 8 Best Solution (144)

Kushagra Tiwari   10 years AGO

jst do the multiplication of
consecutive digits..

as 986= 9*8 8*6 ==7248

similarly for others ....

Like? Yes (32) | No (3)  

MD SOHAIL AKHTER   10 years AGO

986, 7248, 14832, 432246, 1264824
986=(9*8)(8*6)
similarly
1264824=(1*2)(2*6)(6*4)(4*8)(8*2)(2*4)=2122448168

Like? Yes (4) | No   

NAVEEN KUMAR   10 years AGO

multiplication of consecutive digits..
986=9*8&8*6=7248
.........
similarly,
1264824=1*2 2*6 6*4 4*8 8*2 & 2*4=2122432168
(option 8)

Like? Yes (6) | No (3)  

pawan kumar   10 years AGO

1*2=2
2*6=12
6*4=24
4*8=32
8*2=16
2*4=8

Like? Yes (2) | No   

Aastha   10 years AGO

here no is multiple of 1st two numbers as
7248=9*8 8*6
14832=7*2 2*4 4*8
similarly,
1*2=2
2*6=12
6*4=24
4*8=32
8*2=16
2*4=8
next number is=2122432168

Like? Yes (3) | No (1)  

santosh kumar patel   10 years AGO

for 986: 9*8=72
8*6=48 so next value=7248
7248:7*2=14
2*4=8
4*8=32 so next value=14832
14832:1*4=4
4*8=32
8*3=24
3*2=6 so next value =432246
432246:4*3=12
3*2=6
2*2=4
2*4=8
4*6=24 so next value=1264824
126824:1*2=2
2*6=12
6*4=24
4*8=32
8*2=16
2*4=8 so next vale=212243216
so ans: 212243216

Like? Yes (2) | No   

Md.Sultan Khichi   10 years AGO

1st no.=986=9*8,8*6=7248..
2nd no.=7248..=7*2,2*4,4*8=14832
3rd no. =14832
So on..
1264824=1*2,2*6,6*4,4*8,8*2,2*4=2122432168
So the next no. is 2122432168
Ans..ob 8..

Like? Yes (2) | No (1)  

Rashi Bansal   10 years AGO

In the above series , the digits of the next number are the product of consecutive two digits of the preceeding number .

I no= 986
II no = 9*8 8*6 == 7248
III no = 7*2 2*4 4*8==14832
IV no= 1*4 4*8 8*3 3*2
.
.
.
.
last no== 1*2 2*6 6*4 4*8 8*2 2*4== 2122432168

Like? Yes (2) | No (1)  

Gitanjali K   10 years AGO

just multiply consecutive digits like..
986=(9*8 8*6)=7248 is the next no.
7248=(7*2 2*4 4*8)=14832
14832=(1*4 4*8 8*3 3*2)=432246 and so on..
.
.
so answer is 2122432168

Like? Yes (2) | No (1)  

rajani   10 years AGO

986--->9(8) 8(6)=7248
7248--->7(2) 2(4) 4(8)=14832


In the same way,
1264824--->1(2) 2(6) 6(4) 4(8) 8(2) 2(4)=2122432168

Like? Yes (1) | No   

shubhi garg   10 years AGO

4*2 2*8 8*4 4*6 6*2 2*1

Like? Yes (1) | No   

BHASKAR MANDAL   10 years AGO

digit multiplication in sequence.
4*3=12
3*2=6, and so on
so the option is 8

Like? Yes (1) | No   

Tania Chatterjee   10 years AGO

jst do the multiplication of consecutive digits..

Like? Yes (1) | No   

Rupesh Rajesh Deshmukh   10 years AGO

8)2122432168

Like? Yes (1) | No   

Asha Praveena   10 years AGO

just do the multiplication of consecutive digits..

Like? Yes (1) | No   

Abhishek Tiwari   10 years AGO

consider the sequence :
986 i.e. 9*8=72 and 8*6=48 so, 7248
now the second one,
7248 i.e. 7*2=14 , 2*4=8 , and 4*8=32 so, 14832
just like that :
1264824 i.e. 1*2=2, 2*6=12, 6*4=24, 4*8=32, 8*2=16, and 4*2=8 so, 2122432168.
so, option 8 is correct

Like? Yes (1) | No   

Mogilipuri.Harish   10 years AGO

1*2 = 2
2*6= 12
6*4 =24
4*8=32
8*2=16
2*4=8

ans: 2122432168

Like? Yes (1) | No   

G.Mahesh   10 years AGO

1*2 = 2
2*6= 12
6*4 =24
4*8=32
8*2=16
2*4=8

ans: 2122432168

Like? Yes (1) | No   

Tark Patel   10 years AGO

986
7248 = (9*8)(8*6) [combine]
14832 = (7*2)(2*4)(4*8) [combine]
432246 = (1*4)(4*8)(8*3)(3*2) [combine]
1264824 = (4*3)(3*2)(2*2)(2*4)(4*6) [combine]

so next will be,
(1*2)(2*6)(6*4)(4*8)(8*2)(2*4) [combine] = 2122432168

Like? Yes (1) | No   

shikha panwar   10 years AGO

next number in the series is multiplication of consecutive 2 digits of the number.
first num 986, so next number is- 9*8= 72 and 8*6 = 48 i.e 7248
next number is 7*2=14 , 2*4=8, 4*8=32 so number is 14832.....and like wise....
so ans is 2122432168

Like? Yes (1) | No   

palasiva   10 years AGO

1*2 = 2
2*6= 12
6*4 =24
4*8=32
8*2=16
2*4=8

ans: 2122432168

Like? Yes (1) | No   

Sayantonee Maitra   10 years AGO

Because here the first no. of sequence is 986. so the second no. is (9*8)(8*6)=7248, like this the third no would be (7*2)(2*4)(4*8)=14832 like this the sixth no. would be (2*1)(2*6)(6*4)(4*8)(8*2)(2*4)=2122432168

Like? Yes (1) | No   

SIVA BALSUBRAMANIAN   10 years AGO

986= 9x8 , 8x6=72,48
like wise
1264824=1x2,2x6,6x4,4x8,8x2,2x4=2,12,24,32,16,8
ans is : 2122432168.

Like? Yes (1) | No   

prabhat   10 years AGO

986
9*8,8*6=7248
7*2,2*4,4*8=14832
1*4,4*8,8*3,3*2=432246
4*3,2*2,3*2,2*2,2*4,4*6=1264824
the next number will be
1*2,2*6,6*4,4*8,8*2,2*4=2122432168

Like? Yes (1) | No   

amol tarude   10 years AGO

986=9*8=72&8*6=48
986=7248
7248=7*2=14
4*2=8
4*8=32
7248=14832
.........
1264824=
1*2=2
2*6=12
6*4=24
4*8=32
8*2=16
2*4=8
1264824=2122432168

Like? Yes (1) | No   

Narasapu Hari prasad   10 years AGO

ans is option 8.
second number=(9*8)(8*6)=7248
thired number=(7*2)(2*4)(4*8)
final number is =(1*2)(2*6)(6*4)(4*8)(8*2)(2*4)=2122432168

Like? Yes (2) | No (1)  

ravish kumar   10 years AGO

986
9*8 & 8*6=7248
7*2 & 2*4 & 4*8 =14832
1*4 & 4*8 & 8*3 & 3*2=432246
4*3 & 3*2 & 2*2 & 2*4 & 4*6 =1264824
Ans- 1*2 & 2*6 & 6*4 & 4*8 & 8*2 & 2*4=2122432168

Like? Yes (1) | No   

v pavan   10 years AGO

consecutive digits are multiplied
1*2=2
2*6=12
6*4=24
4*8=32
8*2=16
2*4=8

Like? Yes (1) | No   

Urvashi Jain   10 years AGO

986=9*8 8*6=7248
7*2 2*4 4*8=14832
1*4 4*8 8*3 3*2=432246
4*3 3*2 2*2 2*4 4*6=1264824
1*2 2*6 6*4 4*8 8*2 2*4=2122432168
option 8)

Like? Yes (1) | No   

Shreya Tiwari   10 years AGO

jst do the multiplication of
consecutive digits..

as 986= 9*8 8*6 ==7248

similarly for others ....

Like? Yes (1) | No   

Piyush   10 years AGO

Multiply first two digit you will get the first no and multiply 2 digit with 3 you will get another no and repeat the process

Like? Yes (1) | No   

Abhishek Vishwakarma   10 years AGO

jst do the multiplication of
consecutive digits..

as 986= 9*8 8*6 ==7248

similarly for others ....

Like? Yes (1) | No   

KAUSTUBH MAHAKALKAR   10 years AGO

1. 986 = 9*8=72; 8*6=48; so next is 7248
2.7248 = 7*2=14; 2*4=8; 4*8=32;so next is 14832
similarly;
1264824 =1*2=2; 2*6= 12; 6*4= 24; 4*8= 32;8*2= 16; 2*4= 8
so the required number is 2122432168

Like? Yes (1) | No   

m.kusuma priyanka   10 years AGO

986= 9*8=72
8*6=48
7248 similarly ...... 1264824 =1*2=2
2*6=12
6*4-=24
4*8=32
8*2=16
2*4 =8
=2122432168

Like? Yes (1) | No   

ANTRISH MISHRA   10 years AGO

serially first number is multiplied to the next(from left to right)
and result becomes a new number
as- 9*8=72
8*6=48
and next number become 7248
similarly
1*2=2
2*6=12
6*4=24
4*8=32
8*2=16
2*4=8
and now the number is 2122432168

Like? Yes (1) | No   

swati dwivedi   10 years AGO

9*8=72
7*2=14
1*4=4
4*3=12
then1*2=2 means no. will starting from 2
8*6=48
4*8=32
3*2=6
4*6=24
then 2*4=8 means no. will end to 8

Like? Yes (1) | No   

Vanika   10 years AGO

first digit of next no. = first digit of previous no. * second digit of previous no.
so for 1264824
next no. is 1*2, 2*6, 6*4 , 4*8 ,8*2 , 2*4
= 2122432168

Like? Yes (1) | No   

mounika kadudhuri   10 years AGO

Next number is the product of two digits together

Like? Yes (1) | No   

Antony victor   10 years AGO

multiply the digits 9*8 8*6= 7248
similarly 7*2 2*4 4*8=14832
4*3 3*2 2*2 2*4 4*6= 1264824
so 1264824 = 21224168

Like? Yes (1) | No   

Simranjit Singh   10 years AGO

Each number is obtained from its previous number by multiplying each of the digits

7248= 9*8 & 8*6= 72 & 48

14832=7*2 & 2*4 & 4*8= 14 & 8 & 32

432246=1*4 & 4*8 & 8*3 & 3*2= 4 & 32 & 24 & 6

1264824=4*3 & 3*2 & 2*2 & 2*4 & 4*6= 12 & 6 & 4 & 8 & 24

So the answer an be obtained by:

=>1*2 & 2*6 & 6*4 & 4*8 & 8*2 2*4
=> 2 & 12 & 24 & 32 & 16 & 8
=> 2122432168

So the answer is option (8)

Like? Yes (1) | No   

Sukanya   10 years AGO

The next number starts with product of first two digits and ends with product of last two digits.


1*2=2 (start)
2*4=8(end)

Like? Yes (1) | No   

virendra dubey   10 years AGO

986: (9*8)+(8*6)==>7248
7248: (7*2)+(2*4)+(4*8)==>14832
14832: (1*4)+(4*8)+(8*3)+(3*2)==>432246
432246: (4*3)+(3*2)+(2*2)+(2*4)+(4*6)==>1264824
1264824: (1*2)+(2*6)+(6*4)+(4*8)+(8*2)+(2*4)==>2122432168
answer: option 9: 2122432168

Like? Yes (1) | No   

Mahendra Jakka   10 years AGO

1*2=2
2*6=12
6*4=24
4*8=32
8*2=16
2*4=8

Like? Yes (1) | No   

Kethineni Vinodh   10 years AGO

212332168

Like? Yes (1) | No   

SHUBHAM   10 years AGO

1*2=2
2*6=12
6*4=24
4*8=32

now we can match with the options

Like? Yes (1) | No   

ADARSH GAURAV   10 years AGO

2122432168 is the answer.

Like? Yes (1) | No   

vikash kumar   10 years AGO

2122432168 is the ans

Like? Yes (1) | No   

raushan kumar   10 years AGO

product of previous two terms= next term.
example.
124=1*2,2*4,1*4=284
22345=2*2,2*3,3*4,4*5=461220.

Like? Yes (1) | No   

anandhakumar   10 years AGO

option 8 is answer

Like? Yes (1) | No   

sudhakar   10 years AGO

answer is option8)2122432168

Like? Yes (1) | No   

Suganya   10 years AGO

986=multiplying consecutive two digits 7248
7248=14832
similarly 2122432168 is the answer

Like? Yes (1) | No   

Amit Verma   10 years AGO

986
consider digits of previos no.
7248=72(9*8) and 48 (8*6)
14832=32(8*4) 8(4*2) 14 (2*7)
similarly
do it same with last no. we will get the ans

Like? Yes (1) | No   

Amit Kumar   10 years AGO

Multiply 1st digit with 2nd digit then multiply all digit between 1st and last digit with the last digit

Like? Yes (1) | No   

Anshul   10 years AGO

986,7248 (which is 9*8=72, 8*6=48 ie 7248)
14832 (which is 7*2=14, 2*4=8, 4*8=32 ie 14832)
so last number of sequence is (1*2=2 , 2*6=12 , 6*4=24 , 4*8=32 , 8*2=16 , 2*4=8 ) ie 2122432168 . So option 8)

Like? Yes (1) | No   

Surit Datta   10 years AGO

here according to the problem.
9*8 8*6 = 72 48 = 7248
7*2 2*4 8*4 = 14 8 32 = 14832
1*4 4*8 8*3 3*2 = 4 32 24 6 = 432246
4*3 3*2 2*2 2*4 4*6 = 12 6 4 8 24=1264824
so the next number will be in the similar manner.
which is.
1*2 2*6 6*4 4*8 8*2 2*4 = 2 12 24 32 16 8=2122432168
that's it..

Like? Yes (1) | No   

Kumar Vishal   10 years AGO

8

Like? Yes (1) | No   

AJIT KUMAR SINGH   10 years AGO

1*2=2
2*6=12
.........

Like? Yes (1) | No   

Avinash Aryan   10 years AGO

option 8

Like? Yes (1) | No   

vijay mehta   10 years AGO

by multiplying the consequtive digits the product is to be written for next number digits

Like? Yes (1) | No   

Rajiv Agrawal   10 years AGO

next no. is 1*2 2*6 6*4 4*8 8*2 2*4

Like? Yes (1) | No   

Inline Geek   10 years AGO

(1*2)(2*6)(6*4)(4*8)(8*2)(2*4)= 2122432168

Like? Yes (1) | No   

subhadip sengupta   10 years AGO

2*4=8
8*2=16
4*8=32
....
...

Like? Yes (1) | No   

vinit   10 years AGO

2122432168
9*8=72
8*6=48
986=7248
similarly 1264824=2122432168

Like? Yes (1) | No   

srijani   10 years AGO

it is clearly seen frm the given series that, when first 2 digits of a number multiplied the obtained result is considered as the first digits of next following number and the same formula is applied to the last 2 digits of a number.

Like? Yes (1) | No   

sona   10 years AGO

next number= 1st digit*2nd digit,3rd digit*4th digit,

986
7248 = 9*8 8*6
14832= 7*2 4*2 2*4 4*8
432246= 1*4 4*8 8*3 3*2
1264824= 4*3 3*2 2*2 2*4 4*6
2122432168= 1*2 2*6 6*4 4*8 8*2 2*4

Like? Yes (1) | No   

Govind raj   10 years AGO

as 9*8=72 and 8*6=48 so 7248.
7*2=14,4*2=8,4*8=32 so 14832 ....1*2=2..2*6=12..6*4=24..4*8=32..8*2=16..2*4=8.. so 2122432168 ANS...

Like? Yes (1) | No   

ganesh babu   10 years AGO

986 ,
9X8 8X6 = 7248,
....,
1264824,
1x2 2x6 6x4 4x8 8x2 2x4 = 2122432168

Like? Yes (1) | No   

Sandeep Kumar   10 years AGO

multiply 1st number to the next, till end
1264824=2122432168

Like? Yes (1) | No   

SNEHA SUMAN   10 years AGO

product of two number gives the next number

Like? Yes (1) | No   

Ankit Pandey   10 years AGO

986=>9*8 =72 8*6= 48=7248
14832=>4*1=4 4*8=32 8*3=24 3*2=6 no. is 432246
in similar manner 1*2=2 2*6=12 6*4=24 4*8=32 8*2=16 2*4=8
thus the ans is=2122432168

Like? Yes (1) | No   

Rajat Jain   10 years AGO

1. 986
2. 7248=9*8,8*6
3. 14832=7*2,2*4,4*8
4. 432246= 1*4,4*8,8*3,3*2
.
.
.
.
2122432168=1*2,2*6,6*4,4*8,8*2,2*4

Like? Yes (1) | No   

sharad   10 years AGO

numbers are produced by multiplying 2 consecutive desists repetitively

Like? Yes (1) | No   

Dark Knight   10 years AGO

multiple with the previous number
1*2=2
2*6=12
6*4=24
4*8=32
8*2=16
2*4=8
2122432168

Like? Yes (1) | No   

Saurabh Jagdhane   10 years AGO

9*8=72, 8*6=48 hence, no. after 986 is 7248
7*2=14, 2*4=8, 4*8=32. Hence, 986, 7248, 14832
Finally,
1264824
1*2=2, 2*6=12, 6*4=24, 4*8=32, 8*2=16, 2*4=8
Hence, 2122432168

Like? Yes (1) | No   

kumar   10 years AGO

multiply first with secound ,
2nd with 3rd
3rd with 4th like that
for exam 986
9*8=72
8*6=48
hence result 7248
for 1264824 =
1*2 then 2*6 then 6*4 then 4*8 then 8*2 then 2*4
2 12 24 32 16 8
=2122432168
ans 8)

Like? Yes (1) | No   

Kavin Raja P   10 years AGO

The next number is multiplication of two digits of previous number

Like? Yes (1) | No   

Shaik Jahangeer Basha   10 years AGO

986,7248,14832,432246,1264824,
9*8 8*6=7248
7*2 2*4 4*8=14832
1*4 4*8 8*3 3*2=432246
4*3 3*2 2*2 2*4 4*6=1264824
1*2 2*6 6*4 4*8 8*2 2*4=2122432168

Like? Yes (1) | No   

madanpal vishwakarma    10 years AGO

just do the multiplication of consecutive digits..

Like? Yes (1) | No   

Santosh Kumar   10 years AGO

the next step after the no 432246 is written on this rule
6*4=24
4*2=8
2*2=4
2*3=6
3*4==12
and the final number is written as bottom to top so the next number is 1264824
simillary:
4*2=8
2*8=16
8*4=32
4*6=24
6*2=12
2*1=2
so the final answer is 2122432168

Like? Yes (1) | No   

akhilesh kumar   10 years AGO

9*8*6=7248
7*2*4*8=14832
1*4*8*3*2=432246
........
1*2*6*4*8*2*4=2122432168 Ans.

Like? Yes (1) | No   

Atanu   10 years AGO

1*2 = 2
2* 6 = 12
6*4 = 24
4*8 = 32
8*2 = 16
2*4 = 8
Hence by combine them together we get 2122432168 i.e. No 8

Like? Yes (1) | No   

DILBAG SINGH   10 years AGO

1264824
1*2=2
2*6=12
6*4=24
4*8=32
8*2=16
2*4=8
total is =2122432168

Like? Yes (1) | No   

Sushmitha .V   10 years AGO

just multiple the consecutive nos

Like? Yes (1) | No   

veeranjaneyulu   10 years AGO

multiply with adjacent numbers

Like? Yes (1) | No   

shree   10 years AGO

2122432168

Like? Yes (1) | No   

satyam shivam   10 years AGO

986 = 9*8=72,8*6=48 = 7248
7248=7*2=14,2*4=8,4*8=32 =14832
14832=1*4=4,4*8=32,8*4=24,3*2=2
same 1264824=1*2=2,2*6=12,6*4=24,4*8 =32,8*2=16,2*4=8
ans is 2122432168

Like? Yes (1) | No   

Rajan Roy   10 years AGO

4*2=8,8*2=16,4*8=32,6*4=24,2*6=12,1*2=2...therefore next number will be 2122432168

Like? Yes (1) | No   

sanjeev kumar   10 years AGO

9*8=72,8*6=48 like.....
ans 8

Like? Yes (1) | No   

Grishma Shah   10 years AGO

Answer is the multiplication of adjecent no:
1264824 next no = 1*2 2*6 6*4 4*8 8*2 2*4
=2122432168

Like? Yes (1) | No   

divya arora   10 years AGO

986,7248=9*8=72
8*6=48=7248
1264824=1*2 2*6 6*4 4*8 8*2 2*4=2122432168

Like? Yes (1) | No   

monish patwa   10 years AGO

multiply adjacent number

Like? Yes (1) | No   

Anuj Tiwari   10 years AGO

9*8=72 , 8*6=48 ==7248
7*2=14 , 2*4=8 ,4*8=32 ==14832
.
.
.
similarly
1*2=2 ,2*6=12 ,6*4=24 ,4*8=32 ,8*2=16 ,2*4=8 ==2122432168

Like? Yes (1) | No   

swasthika   10 years AGO

By multiplying the adjacent digits the digits for the next number is obtained
986,
9*8=72
8*6=48
therefore 7248

likewise

1*2 2*6 6*4 4*8 8*2 2*4 =2122432168

Like? Yes (1) | No   

radhakrishna bajpai   10 years AGO

Multiply of first two digits are first digits of next no 1×2=2
Multyply of last two digit is the last digit is last digit of next no 2×4=8
And digits are increasing

Like? Yes (1) | No   

Vishal Potdar   10 years AGO

1*2= 2 2*6=12 6*4=24 4*8=32 8*2=16 2*4=8

==> 2122432168

Like? Yes (1) | No   

PINTU KUMAR   10 years AGO

9*8=72 & 8*6=48 ,,similarly for others 1*2=2,2*6=12,6*4=24,4*8=32,8*2=16,2*4=8..
so result will be 2122432168

Like? Yes (1) | No   

Pradeep Saw   10 years AGO

986 = 9*8=72,8*6=48 = 7248
7248=7*2=14,2*4=8,4*8=32 =14832
14832=1*4=4,4*8=32,8*4=24,3*2=2,
same
1264824=1*2=2,2*6=12,6*4=24,4*8=32,8*2=16,2*4=8
ans is 2122432168

Like? Yes (1) | No   

Hemadri   10 years AGO

986=9*8&8*6=7248
7248=7*2&2*4&4*8=14832
14832=1*4&4*8&8*3&3*2=432246
432246=4*3&3*2&2*2&2*4&4*6=1264824
1264824=1*2&2*6&6*4&4*8&8*2&2*4=2122432168.

Like? Yes (1) | No   

pravallika   10 years AGO

Each number is multiplied to its next number to get the result

Like? Yes (1) | No   

Manasa   10 years AGO

multiplication of two adjacent numbers
1*2=2, 2*6=12, 6*4=24, 4*8=32, 8*2=16, 2*4=8
writing all answers together = 2122432168

Like? Yes (1) | No   

Aravind prabu V   10 years AGO

9*8=72 ,8*6=48 ==>7248
7*2=14,2*4=8,4*8=32==>14832
.
.
.
1*2=2,2*6=12,6*4=24,4*8=32,8*2=16,2*4=8==> 2122432168

Like? Yes (1) | No   

NIVEDA SIVAPRAKASAM   10 years AGO

1*2,2*6,6*4,4*8,8*2,2*4

Like? Yes (1) | No   

shivam rathuar   10 years AGO

4*2=8
2*8=16
8*4=32
4*6=24
6*2=12
2*1=2

Like? Yes (1) | No   

Krishnajeet Saw   10 years AGO

multiply first and second

Like? Yes (1) | No   

kalaiselvi   10 years AGO

multiply the last two digits and so on..
consider this numbers 986, 7248
6*8=48
8*9=72
7248.....similarly so on
so answer=2122432168

Like? Yes (1) | No   

Utkarsh Srivastava   10 years AGO

2*4=8
2*8=16
8*4=32
4*6=24
6*2=12
2*1=2
so the next sequence is 2122432168

Like? Yes (1) | No   

harish rodd   10 years AGO

986=>9*8 =72 8*6= 48 =7248(next no) similarly, 1264824=>1*2 =2 2*6 = 12 6*4 = 24 4*8 = 32 8*2 = 16 2*4 = 8 the ans is=2122432168

Like? Yes (1) | No   

MOHIT GARG   10 years AGO

986 Then 9*8=72 & 8*6=48 so 7248....
Similarly 1264824
1*2=2 2*6=12 6*4=24 4*8=32 8*2=16 2*4=8
So answer is 21224 32168.
Logic behind that is answer is product of consecutive digits from left to right.

Like? Yes (1) | No   

gouthamdaneti   10 years AGO

multiply the side by side digits and place them accordingly

Like? Yes (1) | No   

vedavarshitha   10 years AGO

every number is multiplied with its previous one

Like? Yes (1) | No   

saimeera   10 years AGO

986=>9*8 =72 8*6= 48 so 7248
7*2=14,2*4=8,4*8=32, so 14832
similarly,1264824=>1*2 =22*6 = 126*4 = 244*8 = 328*2 = 162*4 = 8
ans is=2122432168

Like? Yes (1) | No   

Abhimanyu kumar   10 years AGO

986=9*8=72
8*6=48 7248 is 2nd term
7248=7*2=14
2*4=8
4*8=32 14832 is 3rd term
so 1264824=1*2=2
2*6=12
6*4=24
4*8=32
8*2=16
2*4=8
so next term will be 2122432168 (Answer)

Like? Yes (1) | No   

amit kumar   10 years AGO

986 = 9*8=72,8*6=48 = 7248
7248=7*2=14,2*4=8,4*8=32 =14832
14832=1*4=4,4*8=32,8*4=24,3*2=2,
same
1264824=1*2=2,2*6=12,6*4=24,4*8=32,8*2=16,2*4=8
ans is 2122432168

Like? Yes (1) | No   

Sneha   10 years AGO

986 = 9*8=72,8*6=48 = 7248
7248=7*2=14,2*4=8,4*8=32 =14832
14832=1*4=4,4*8=32,8*4=24,3*2=2
same 1264824=1*2=2,2*6=12,6*4=24,4*8 =32,8*2=16,2*4=8
ans is 2122432168

Like? Yes (1) | No   

Ankit Sirohi   10 years AGO

986=>9*8 =72 8*6= 48=7248
(next no)similarly,
1264824=>1*2 =22*6 = 126*4 = 244*8 = 328*2 = 162*4 = 8
the ans is=2122432168 option (8)...

Like? Yes (1) | No   

Chirag Ranjan Lahiri   10 years AGO

986=>9*8 =72 8*6= 48 =7248 (next no)
similarly, 1264824=>1*2 =2
2*6 = 12
6*4 = 24
4*8 = 32
8*2 = 16
2*4 = 8
so the ans is=2122432168

Like? Yes (1) | No   

RAVI RANJAN   10 years AGO

jst do the multiplication of consecutive digits..

Like? Yes (1) | No   

Prakash singh   10 years AGO

986
9*8,8*6=7248
7*2,2*4,4*8=14832
1*4,4*8,8*3,3*2=432246
.
.
1*2,2*6,6*4,4*8,8*2,2*4=2122432168

Like? Yes (1) | No   

Rahul Middha   10 years AGO

Just multiply the 1st digit with its next one that is 2nd one. write down the multiplication answer, then multiply 2nd digit with 3rd one & repeat the process upto last digit & note the result everytime. all the results from 1st to last from left to right is the answer.

Like? Yes (1) | No   

Ajay Kumar Gupta   10 years AGO

986 = 9*8=72,8*6=48 = 7248
7248=7*2=14,2*4=8,4*8=32 =14832
14832=1*4=4,4*8=32,8*4=24,3*2=2,
same
1264824=1*2=2,2*6=12,6*4=24,4*8=32,8*2=16,2*4=8

Like? Yes (1) | No   

Suraj Pawar   10 years AGO

986=>
9*8 =72
8*6= 48=7248(next no)
similarly,1264824=>
1*2 =2
2*6 = 12
6*4 = 24
4*8 = 32
8*2 = 16
2*4 = 8
the ans is=2122432168

Like? Yes (1) | No   

Devesh Gupta   10 years AGO

9*8=72 & 8*6=48...7248is next no.
similarly now
7*2=14, 2*4=8 & 4*8=32....14832 is next no.
thus
1*2=2, 2*6=12, 6*4=24, 4*8=32, 8*2=16 & 2*4=8....2122432168 is the required no.

Like? Yes (1) | No   

Rohini R Chandran   10 years AGO

just multiply subsequent numbers like: 1*2=2,2*6=12 and so on....

Like? Yes (1) | No   

Niharika   10 years AGO

1*2=2
2*6=12
6*4=24
4*8=32
8*2=16
2*4=8
by arranging them we get 2122432168

Like? Yes (1) | No   

DEEPAK GUPTA   10 years AGO

last digit= 1264824,
multiply consecutive digits= 1*2, 2*6, 6*4, 4*8, 8*2, 2*4
so the no. we get is 2122432168

Like? Yes (1) | No   

T.Aravinth kumar   10 years AGO

1264824=(1*2),(2*6),(6*4),(4*8),+),(8*2),(2*4)=2122432168

Like? Yes (1) | No   

Anup Majumdar   10 years AGO

986=9*8=72,8*6=48, so 7248
....................................................
......................................
1264824=1*2=2,
2*6=12,
6*4=24
4*8=32
8*2=16
2*4=8
so, 2122432168

Like? Yes (1) | No   

Nitish kumar   10 years AGO

9*8=72 and 8*6=48 so the next no. is 7248 similarly 1*2=2,2*6=12,6*4=24,4*8=32,8*2=16,2*4=8 so the next no is 2122432168

Like? Yes (1) | No   

MANU   10 years AGO

multiplication of consecutive numbers
ans is 2122432168

Like? Yes (1) | No   

Manish Singhal   10 years AGO

986= 9*8=72
8*6=48 7248
7248= 7*2=14
2*4=8
4*8=32 14832
14832=1*4=4
4*8=32
8*3=24
3*2=6 432246
------- next no. after this will be as
1264824=1*2=2
2*6=12
6*4=24
4*8=32
8*2=16
2*=8 .. 2122432168 Ans

Like? Yes (1) | No   

shiv pujan   10 years AGO

986=>9*8 =72 8*6= 48=7248(next no)
similarly,
1264824=>1*2 =2
2*6 = 12
6*4 = 24
4*8 = 32
8*2 = 16
2*4 = 8
the ans is=2122432168

Like? Yes (1) | No   

Ramu Giri   10 years AGO

by multipling the of the given no .
like---986=6*8=48
and 8*9=72
7248 so on

Like? Yes (1) | No   

rajan kumar   10 years AGO

986, 7248, 14832, 432246, 1264824,....
986 -> 9*8 8*6 ->7248
7248 -> 7*2 2*4 4*8 -> 14832
14832 -> 1*4 4*8 8*3 3*2 -> 432246
432246 -> 4*3 3*2 2*2 2*4 4*6 -> 1264824
1264824 -> 1*2 2*6 6*4 4*8 8*2 2*4 -> 2122432168
so, option is 8)

Like? Yes (1) | No   

LAXMI KANT RAKESH   10 years AGO

9*8=72 and 8*6=48 thats why next number is 7248
similarly for 1264824 the answer is 2122432168

Like? Yes (1) | No   

Anant Vardhan   10 years AGO

Next number can be determined by multiplying two consecutive digits of the previous number.

Like? Yes (1) | No   

Dr.Dipin Singh   10 years AGO

Multiply thr consecutive digits and put all products together to get next number.
Like
986........9x8 8x6.....7248

Like? Yes (1) | No   

himanshu   10 years AGO

9*8,8*6=72,48=7248
7*2,2*4,4*8=14,8,32=14832
like
1*2,2*6.6*4,4*8,8*2,2*4=2122432168

Like? Yes (1) | No   

RAKESH   10 years AGO

(1*2) (2*6) (6*4) (4*8) (8*2) (2*4)
= 2 12 24 32 16 8

Like? Yes (2) | No (2)  

Md Intshamuddin   10 years AGO

986=9*8 8*6= 7248=7*2 2*4 4*8= 14832, 432246, 1264824, .....and so on

Like? Yes (1) | No (1)  

Neel Patel   10 years AGO

986-->9*8=72,8*6=48-->7248

Same for all
1264824=1*2=2,2*6=12,6*4=24,
4*8=32,8*2=16,2*4=8
So ans is 2122432168

Like? Yes (1) | No (1)  

Ranjit Somisetty   10 years AGO

9*8 8*6=7248
7*2 2*4 4*8= 14832



1*2 2*6 6*4 4*8 8*2 2*4

Like? Yes (1) | No (1)  

Shashank Kapoor   10 years AGO

series is like multiplication of individual digits from the previous number
like 986 is first number
7248 is 9*8=72 and 8*6=48 so number is 7248
similarly 1264824=1*2 2*6 6*4 4*8 8*2 2*4=2122432168
ans is option 8

PEACE!

Like? Yes (1) | No (1)  

Saraswathy   10 years AGO

986, 7248, 14832, 432246, 1264824, x
986 => (9*8)|(8*6) = 7248
7248 => (7*2)|(2*4)|(4*8) = 14832
14832 => (1*4)|(4*8)|(8*3)|(3*2) = 432246
.
1264824 => (1*2)|(2*6)|(6*4)|(4*8)|(8*2)|(2*4) = 2122432168

Ans : 2122432168 (Option 8)

Like? Yes (1) | No (1)  

k srinivas   10 years AGO

product of two consecutive numbers placed in previous number

Like? Yes (1) | No (2)  

19 Sep 2014 Stock and Share

What is the annual income by investing Rs.3000 in 6% stock at 120.

OPtion

1) Rs. 165
2) Rs. 160
3) Rs. 155
4) Rs. 150
5) Rs. 145
6) Rs. 140
7) Rs. 170
8) Rs. 175
9) Rs. 180
10)None of these

Solution

On investing Rs. 120, income = Rs. 6
On investing Rs. 3000,
income = Rs. (6/120 * 3000) = 150

Option 4)

Correct Option: 4 Best Solution (49)

NAVEEN KUMAR   10 years AGO

by investing Rs. 120, income obtained=Rs.6
by investing Rs.3000,income obtained=Rs.(6/120)*3000
=Rs. 150
option(4)

Like? Yes (21) | No (3)  

Surit Datta   10 years AGO

6% stock at 120
So let x be the annual income
so according to the question,
(120/6)*x=3000
so x is 150
so annual income is Rs 150
thats it...

Like? Yes (9) | No (2)  

nisha sharma   10 years AGO

annual income=invstement*rate/(market value+brokerage)
here br=0
hence annual inc is
(3000*6)/120=150
option 4

Like? Yes (5) | No (1)  

amit kumar   10 years AGO

Assume that face value = Rs.100.

Dividend per share = Rs.6 (as it is a 6% stock)

Investment needed to earn Rs.6 = 3000×6/120 = Rs.150

ie, stock is then quoted (then market value) = Rs.150

Like? Yes (4) | No   

jeevitha   10 years AGO

He is investing Rs120/- for 6%Stock
i.e;120------6
3000----?
Let X will be the ans then
120-------6
3000------X
By cross multiplying we get
X--3000*6/120
X is 150/-
So ans is Rs 150/-
Ans(4)

Like? Yes (4) | No   

pawan kumar   10 years AGO

Gain= (6*3000)/120=rs. 150

Like? Yes (3) | No   

Tark Patel   10 years AGO

annual income = ( 6 / 120 ) * 3000 = 150 Rs.

Like? Yes (4) | No (1)  

ANUJ KUMAR PAL   10 years AGO

for 6% stock at 120 means
1. face value of 1 share is Rs 100
2. market value of 1 share is Rs 120
3. profit on 1 share is Rs 6 per annum
4. income on Rs 120 is Rs 6 for one year

Like? Yes (3) | No   

MANDANGI JAGAPATHI   10 years AGO

investment=3000,total stock=120,percentage=6%
annual income=3000*6/120=150

Like? Yes (3) | No   

Bhagyalaxmi Yalla   10 years AGO

An investment of Rs. 120 gives an annual income of rs 6. So by investing Rs. 3000 we get 25*6=150

Like? Yes (3) | No   

Ajay Kumar   10 years AGO

3000*6/120

Like? Yes (3) | No   

Sarabeshwar   10 years AGO

By investing Rs.120, income obtained = Rs. 6 (Consider it for Rs.100 )


Now, we have to find for Rs.3000 = (6/120) * 3000
= 150 Rs

Like? Yes (3) | No (1)  

Pradeep Saw   10 years AGO

(6/120)*3000 = 150/-

Like? Yes (2) | No   

vartika    10 years AGO

by investing rs120, income= rs6
by investing rs.300, income= (6*3000/120)=150rs

Like? Yes (2) | No   

Dipika Singh   10 years AGO

Investing Rs 120,income obtained=rs.6
investing Rs 3000,income obtained=6*3000/120=Rs. 150

Like? Yes (2) | No   

RAKESH   10 years AGO

6/120 * 3000 = 150

Like? Yes (3) | No (1)  

Shashank Kapoor   10 years AGO

we have to solve this equation to solve this answer

120*(1/6)*x=3000

solving this we will get 150

Like? Yes (2) | No   

Rashmi bharti   10 years AGO

total income=(6/120)*3000
=150

Like? Yes (2) | No   

lakshmi nalluri   10 years AGO

by investing 120,income obtained is 6/-
by investing 3000 ,income ll be=6*3000/120
=150
option.4 ll be ans

Like? Yes (2) | No   

Urvashi Jain   10 years AGO

By investing rs 120 income obtained=6
By investing rs 3000 income obtained=6/120*3000=150

Like? Yes (2) | No   

Gitanjali K   10 years AGO

3000*6/120=150 Rs

Like? Yes (3) | No (1)  

Thalamanchi Kishan Kumar   10 years AGO

income=(case investment*rate)/market value
income=(3000*6)/120=150

Like? Yes (1) | No   

urvish   10 years AGO

25*6=150

Like? Yes (1) | No   

radheshyam chouhan   10 years AGO

(6/120*3000)=150

Like? Yes (1) | No   

V.Latha   10 years AGO

investment = 3000
stock at 120
r = 6%
A.I = 3000+(6/120) = 150

Like? Yes (1) | No   

ramakrishnateja   10 years AGO

here the answer is option 4.
By investing the Rs 120/- the income derived is 6.
By investing the amount 3000/- the income obtained is 3000*6/120=150/-.

Like? Yes (1) | No   

Saurabh   10 years AGO

For rs120 investment, annual income= rs6
For rs3000, annual income= rs((6 x 3000)/120)
= rs150

Like? Yes (1) | No   

sujatha   10 years AGO

by investing 3000 income obtained =(6/120)*3000=150Rs

Like? Yes (1) | No   

ADARSH GAURAV   10 years AGO

150 is the answer

Like? Yes (1) | No   

vikash kumar   10 years AGO

150 is the ans

Like? Yes (1) | No   

Vipul    10 years AGO

120 me 6₹ milte hai ...3000 pe 150 hi milenge

Like? Yes (1) | No   

Somanshu Kumar   10 years AGO

annual income = (6/120 * 3000)
= (1/20 * 3000)
= 150

Like? Yes (1) | No   

Chirag Ranjan Lahiri   10 years AGO

By investing Rs 120 the income is Rs 10.
So by investing Rs 3000 the income is = (6*3000)/120
= Rs 150.
Hence option 4 is correct.

Like? Yes (1) | No   

vivek   10 years AGO

by investing rs.120, income obtained= rs 6
so, by investing rs. 3000, income obtained= rs.(6/120)*3000
= rs 150

Like? Yes (1) | No   

Anshul Kashyap   10 years AGO

120/6*Annual Income = Investment

120/6*Annual Income = 3000

Annual Income = 3000/20 = 150

Like? Yes (1) | No   

Surya Srivastava   10 years AGO

N.V=100
M.V=120
INVESTMENT=3000
DIVIDENT%=6%
SO, DIVIDENT ON 1 SHARE = 6/100*100=6
N NO. OF SHARES=3000/120=25
ANNUAL DIVIDENT=25*6=150

Like? Yes (1) | No   

prakash kumar   10 years AGO

by investing 120, income obtained = 6
by investing 3000, income obtained = (6/120)*3000 = 150

Like? Yes (1) | No   

gouthamdaneti   10 years AGO

income = 3000*6/120

Like? Yes (1) | No   

Sanjit Kumar Sharma   10 years AGO

annual income= (6/120)*3000 =150

Like? Yes (1) | No   

Moti Kumari   10 years AGO

(3000*6)/120 = 150

Like? Yes (1) | No   

Mogilipuri.Harish   10 years AGO

3000x100/120=>2500

2500x6/100 => 150

Like? Yes (1) | No   

Mahesh   10 years AGO

We will get 25 stocks and 25 *6=150

Like? Yes (1) | No   

anuj gupta   10 years AGO

3000*6/120=150

Like? Yes (1) | No   

Ravi Kumar   10 years AGO

by investing 120, income obtained =rs 6
by investing 3000, income obtained = rs(6/120)*3000
= rs 150

Like? Yes (1) | No   

palasiva   10 years AGO

3000*100/120=2500
2500*6/100=150

Like? Yes (1) | No   

sujit   10 years AGO

r = 6*100/120 = 5%
income = 5% of 3000 = 3000*5/100 = 150

Like? Yes (1) | No   

BHASKAR MANDAL   10 years AGO

face value =3000
divedent = (6*3000)/120
= 150

Like? Yes (1) | No   

jitendra varshney   10 years AGO

income is 3000*6/120=150 so option 4 is correct

Like? Yes (1) | No   

himanshu   10 years AGO

3000x6/120=150

Like? Yes (1) | No   

18 Sep 2014 Discount

A has to pay Rs.220 to B after 1 year. B asks A to pay Rs.110 in cash and defer the payment of Rs.110 for 2 years. A agrees to it. Counting, the rate of interest at 10% per annum in this new mode of payment.

OPtion

1) A loses Rs 11
2) A gains Rs 9.45
3) A gains Rs 11
4) A loses Rs 9.45
5) A gains Rs 15
6) A gains Rs 7.34
7) A loses Rs 15
8) A loses Rs 7.34
9) There is no gain or loss to any one
10)None of these

Solution

A has to pay the P.W. (Present worth or Present value) of Rs. 220 due 1 year hence, which is
= Rs.(100*220 / 100+(10*1)) = Rs 200
Actually pays = Rs.[110 + P.W. of Rs. 110 due 2 years hence]
= Rs.[110 + (100*110 / (100+(8*2)) = 192.66
therefore A gains = Rs. 7.34

Option 6)

Correct Option: 6 Best Solution (22)

NAVEEN KUMAR   10 years AGO

'A' HAS TO PAY THE P.W OF RS.220 DUE 1 YEAR HENCE,

=RS.[(100*220)/100+(10*1)]=RS.200

'A' ACTUALLY PAY=RS[110+PW OF RS 110 DUE 2 YEAR]
=RS.[110+(110*100)/100+(8*2)]=RS.192.66

'A' GAINS=RS[200-192.66]=RS.7.34

Like? Yes (11) | No (8)  

padma   10 years AGO

A has to pay 220 ,
so, 100*220/100+(10*1) = 200
but A has already paid 110 so,
110+ (100*110/100+(8*2)) = 192.66
so, A gains 200-192.66 = 7.34

Like? Yes (3) | No (3)  

Kushagra Tiwari   10 years AGO

A has to pay PW of rs200 due 1 year hence which is
={(100*220)/(100+(10+1)}
on solving we get Rs 200

Now A actually pays= {rs 110 + pw of rs 110 due 2 years hence}
=Rs {(110)+ [(100*110)/(100+ (8*2))]}
i.r Rs 192.66

So A gains =RS[200-192.66] => 7.34

which is in option no 6

Like? Yes (15) | No (16)  

jitendra varshney   10 years AGO

a has to pay p.w of rs. 220 due 1 year hence,which is
[100*220/100+(10*1)]=rs.200,
a actually pay=rs[110+100*100/100(8*2)]=192.66
a gains=rs[200-192.66]=7.34 so option 6 is correct

Like? Yes (3) | No (4)  

lakshmi nalluri   10 years AGO

pw of 220 due to 1 year ll be=220*100/(100+(10*1))
=200
a is paying =110+110due for 2 years
=110+(110*100/(100+10*2))
=192.666
so,200-192.66 gives A a gain of 7.34

Like? Yes (3) | No (4)  

sharathbabu   10 years AGO

A has to pay =Present worth of Rs220 due 1yr hence
=Rs.(220*100)/(100+(10*1))
=Rs.200 A actually pays=Rs.110+Presentworth of Rs110 due 2 yrs hence
=[110+ (Amount*100) /(100+(R*T))]
=[110+((110*100)/(100+(10*2)))]
=Rs192.66
So A gains Rs(200-192.66)=Rs.7.34

Like? Yes (1) | No (2)  

Karthick Balaji G   10 years AGO

The present worth is Rs.220 . For 1 year he has to pay Rs. 200.
A pays Rs. 110 and Present worth of Rs.110 in due years. After 2 years it will be Rs.192.66 So option 6

Like? Yes (1) | No (2)  

Manikumar R   10 years AGO

A has to pay =Present worth of Rs220 due 1yr hence
=Rs.(220*100)/(100+(10*1))
=Rs.200 A actually pays=Rs.110+Presentworth of Rs110 due 2 yrs hence
=[110+ (Amount*100) /(100+(R*T))]
=[110+((110*100)/(100+(10*2)))]
=Rs192.66
So A gains Rs(200-192.66)=Rs.7.34

Like? Yes (4) | No (5)  

Priyanshi Agarwal   10 years AGO

gain=7.34

Like? Yes (1) | No (2)  

ragini   10 years AGO

A has to pay =Present worth of Rs220 due 1yr hence
=Rs.(220*100)/(100+(10*1))
=Rs.200 A actually pays=Rs.110+Presentworth of Rs110 due 2 yrs hence
=[110+ (Amount*100) /(100+(R*T))]
=[110+((110*100)/(100+(10*2)))]
=Rs192.66
So A gains Rs(200-192.66)=Rs.7.34

Like? Yes (1) | No (2)  

sanjeev kumar   10 years AGO

ans=6

Like? Yes (1) | No (2)  

Abhishek Vishwakarma   10 years AGO

A has to pay PW of rs200 due 1 year hence which is
={(100*220)/(100+(10+1)}
on solving we get Rs 200

Now A actually pays= {rs 110 + pw of rs 110 due 2 years hence}
=Rs {(110)+ [(100*110)/(100+ (8*2))]}
i.r Rs 192.66

So A gains =RS[200-192.66] => 7.34

Like? Yes (1) | No (3)  

Enukonda Ramakrishna   10 years AGO

jkljl;j

Like? Yes (1) | No (3)  

praveenkumar   10 years AGO

a has to pay the 220 rs de 1 year=(100*200/(100+10))=200
actual pays=110+110 due 2 years hence =110+110*100/(100+16)=192.66
A gain=200-192.66= 7.34 rs

Like? Yes (1) | No (3)  

anandhakumar   10 years AGO

ans is option 6

Like? Yes (1) | No (3)  

sudhakar   10 years AGO

Answer is option 6) A gains Rs 7.34

Like? Yes (1) | No (3)  

Urvashi Jain   10 years AGO

a has to pay =220*100/100+(1*10)=200
a actually pays=110+110*100/100+(2*10)=192.66
a gains=200-192.66=7.34
option(6)

Like? Yes (2) | No (4)  

S.SHAFI   10 years AGO

A has to pay the P.W. of Rs.220 due 1 year hence, which is
=> (100*220)/(100+(10*1)) ==> Rs.200

A actually pays = Rs.[110 + P.W.of Rs.110 due 2 years hence]
==> Rs.[110 + (100*110)/(100+(8*2))] ==> Rs.192.66

A gains = Rs.[200 - 192.66] = Rs.7.34

Like? Yes (2) | No (4)  

Anand Dwivedi   10 years AGO

Simply Answer is :- A gains Rs. 7.34

Like? Yes (1) | No (3)  

karpagavalli   10 years AGO

(100*220/100+(10*1))=200
110+(100*110/100+(8*2))=192.66
200-192.66=7.34-A gains

Like? Yes (1) | No (3)  

Gitanjali K   10 years AGO

A has to pay =100*(220/100+(10*1))=200 Rs

A paying=110+(100*(110/100+(8*2)))=192.66 Rs
so ( 200-192.66)=7.34 Rs. is the A's gain

so option (6) is the answer..

Like? Yes (1) | No (4)  

MOHIT GARG   10 years AGO

A has to pay =Present worth of Rs220 due 1yr hence
=Rs.(220*100)/(100+(10*1))
=Rs.200 A actually pays=Rs.110+Presentworth of Rs110 due 2 yrs hence
=[110+ (Amount*100) /(100+(R*T))]
=[110+((110*100)/(100+(10*2)))]
=Rs192.66
So A gains Rs(200-192.66)=Rs.7.34

Like? Yes (1) | No (4)  

17 Sep 2014 Four Digit Number

In a four digit number all the four digits are different and sum of all digits is 27. In the number 3 & 4 are not present. Ten's and unit's digits are least and greatest digits of the given number respectively; Sum of all possible results will be

OPtion

1) 11844
2) 14148
3) 18144
4) 14418
5) 15418
6) 14518
7) 15484
8) 14488
9) 18448
10)None of these

Solution

All the four digits are different and sum of all digits is 27 so 0, 1, 2 can not be taken as digits. 3 & 4 are not present as given so available digit are
5, 6, 7, 8, 9
Only 5+6+7+9 = 27
So 8 will be rejected
now according to given condition last two digits are least & greatest of the number so last two digits are 5 & 9 possible no are
6759 + 7659 = 14418

Option 4)

Correct Option: 4 Best Solution (64)

NAVEEN KUMAR   10 years AGO

possible digit are 9,5,6,7
number-6759 and 7659
hence sum=6759+7659=14418

Like? Yes (15) | No (2)  

vipin   10 years AGO

7659+6759=14418

Like? Yes (2) | No   

suganya   10 years AGO

possible numbers will be 6759 7659 so sum=14418

Like? Yes (2) | No   

pawan kumar   10 years AGO

By hit and trial method there are
only two numbers who satisfies all
the conditions... 7659 & 6759

so sum = 14418

Like? Yes (2) | No   

Ranjit Somisetty   10 years AGO

6759+7659=14418

Like? Yes (1) | No   

Inline Geek   10 years AGO

there is only one way to get digits with sum = 27 and given constraints these are 5, 6, 7 and 9
now as per question condition only two numbers can be formed out of these, which are : 6759 & 7659
and their addition is = 14418

Like? Yes (1) | No   

sumit   10 years AGO

6759+7659=14418(4)

Like? Yes (2) | No (1)  

BHASKAR MANDAL   10 years AGO

one digit max and ten digit lowest
so if one digit is 9 then one digit will be , as 3,4 is not possible so thousand and hundred place will be 7,6 both interchanging the place
6759 + 7659 = 14418

for 8 is and further is not possible
as, 27-8=19
possible summation are
2+9+8
3+9+7
4+8+7
4+9+6
5+8+6
which are not possible by the condition

same for 7,6, etc
so the solution is 14418

Like? Yes (1) | No   

Sohidul Islam   10 years AGO

Four digits that will sum up 27 are 5+6+7+9=27
Now the unit digit contains the max i.e 9 & the tenth digit is least...so the possible numbers are 6759 and 7659
If we add these 6759+7659=14418.....so the correct option is (4)

Like? Yes (1) | No   

sandip kumar gupta    10 years AGO

7659+6759=14418

Like? Yes (1) | No   

Mogilipuri.Harish   10 years AGO

4digit no: 7659+6759=>14418

ans: 14418

Like? Yes (1) | No   

shubhi garg   10 years AGO

7659+6759

as 9+5=14
and 7+6=13

Like? Yes (1) | No   

VANAMALA MAHESH BABU   10 years AGO

possible numbers are 7659 and 6759

then sum = 7659+6759
= 14418

Like? Yes (1) | No   

sagar garg   10 years AGO

only two nos satisfy the given condition which are
7659 and 6759
so add both
sum=14418(7659+6759)

Like? Yes (1) | No   

PRANEETH   10 years AGO

9+8+7+6 = 30
we need to get 27 as sum of digits so substract 3 from any digit so that no digit is repeated.
we can substract only from 8
so 9+5+7+6 =27
from the given conditions possible numbers are 7659 and 6759.
so sum of them is 14418

Like? Yes (1) | No   

MOHIT GARG   10 years AGO

Let the four digit number is 'abcd'
Such that a + b + c + d = 27
There are only one set possible I.e. (5,6,7,9)
7659 and 6759 are two possible cases.
There sum is 14418 (Answer)

Like? Yes (1) | No   

Vanika   10 years AGO

let the no. be xyzp
x + y +z +p = 27
then p is highest digit and z is smallest
let p=9
then by hit and trial for given condition
cases are 1. z=5
x=7
y=6
2. z=5
x=6
y=7
so sum of 7659 + 6759 = 14418

Like? Yes (1) | No   

Manish Singhal   10 years AGO

6 +7+5+9=27
7+6+5+9=27

6759+7659= 14418

Like? Yes (1) | No   

Chinmoy Barman   10 years AGO

None of 0,1,2 can be used because the sum of the 4 digits will be

Like? Yes (1) | No   

NISHANT VERMA   10 years AGO

numbers are 7659 and 6759
so sum = 14418

Like? Yes (1) | No   

Vinoth Varatharajan   10 years AGO

There are only two possible numbers with the given demands, They are 7659,6759.
The sum of these two numbers is 14418.

Like? Yes (1) | No   

S.SHAFI   10 years AGO

We have only two possibilities with greatest number in unit's place and least number in ten's place..

6759
7659

Sum is ---->>>>> 14418

Like? Yes (1) | No   

Urvashi Jain   10 years AGO

let a bcd
according to the question ten digit are least and unit digit should be largest digit
there are two possible cases:
7659+6759=14418

Like? Yes (1) | No   

Gitanjali K   10 years AGO

there are only 2 possible numbers.
and those are 6759 & 7659
so 6759+7659=14418
therefore option (4) is the answer

Like? Yes (1) | No   

virendra tiwari   10 years AGO

no 5+6+7+9=27
6759+7659=14418

Like? Yes (1) | No   

Mahendra Jakka   10 years AGO

6759+7659=14418

Like? Yes (1) | No   

Suganya   10 years AGO

given
a+b+c+d=27
c is least so let c=5
d is greatest so let d=9
so the nos satisfying these condition are 6759 and 7659
adding this 14418

Like? Yes (1) | No   

trinadh   10 years AGO

we can form sum equal to 27 using 5,6,7,9
but 3 digit should be least and fourth digit should be greatest
so 6759 is one number another number is 7659
sum is 14418

Like? Yes (1) | No   

Anesh Parvatha   10 years AGO

6759+7659

Like? Yes (1) | No   

AJAY KUMAR   10 years AGO

7+9+6+5=27
a/q
two possible nos are 7659 and 6759.
therefore, sum of possible results are (7659+6759)=14418

Like? Yes (1) | No   

sanjeev kumar   10 years AGO

Ans 4

Like? Yes (1) | No   

vikash kumar   10 years AGO

14418 is the answer

Like? Yes (1) | No   

ADARSH GAURAV   10 years AGO

14418 is the answer.
numbers are7659 and 6759

Like? Yes (1) | No   

ankit sharma   10 years AGO

only two possible cases
6759 and 7659
sum will be 14418
option 4

Like? Yes (1) | No   

MUTHAKANA UDAY BHASKAR   10 years AGO

Like? Yes (1) | No   

abhilasha   10 years AGO

Just I analyse the question

Like? Yes (1) | No   

ANKUR ANAND   10 years AGO

only one set of numbers is possible 9,5,6,7
arranging these digits we get two numbers these are 7659 and 6759
adding these two we 14418

Like? Yes (1) | No   

Syed Atamish Ali   10 years AGO

By considering all the above given constraints...
There are only two possible numbers following all conditions..
They are 67759 and 7659..
Their sum =14418
Hence answer 4 ).

Like? Yes (1) | No   

Amit Verma   10 years AGO

since sum of digits is 27 therefore last six options are not valid
tense and units digit are smallest and greatest digit of the no.
only possible answer is 14418
option 4 is correct

Like? Yes (1) | No   

g lokesh   10 years AGO

there are two possibilities.
two numbers are 6759,7659
sum=6759+7659
=14418
option 4

Like? Yes (1) | No   

posirajesh   10 years AGO

Two numbers are 6759 & 7659

Like? Yes (1) | No   

Pooja P   10 years AGO

there will be only two such numbers:-
6759 and 7659 and their sum=14418

Like? Yes (1) | No   

rajani   10 years AGO

based on the data the possible number would be formed using 5,6,7 and 9..
And the No .will be ,either 6759 or 7659
So the sum is 6759+7659=14418

Like? Yes (1) | No   

Aman   10 years AGO

possible numbers are 7659 and 6759.
sum = 14418.

Like? Yes (1) | No   

Pranav Bharti   10 years AGO

Those numbers will be in 0,1,2,5,6,7,8,9
only 7659 and 6759 numbers are possible that satisfy given conditions....
so sum is=14418

Like? Yes (1) | No   

Ajeet Singh   10 years AGO

we have the the numbers as 1,2,5,6,7,8,9
by condition Ten's and unit's digits are least and greatest digits of the given number respectively we have 5 and 9 as the last digit and for the sum to be 27 we should use 6 and 7
two number are 6759 and 7659 sum is 14418

Like? Yes (1) | No   

surya   10 years AGO

6759(sum is 27)
+ 7659(sum is 27)
...............
14418

Like? Yes (1) | No   

Ajinkya Kulkarni   10 years AGO

Possible combinations which satisfy all the condition are
6759 and 7659

So addition is 14418

Like? Yes (1) | No   

Narasapu Hari prasad   10 years AGO

there exists only two number with the given constraints those numbers are 6759 and 7659
addition of this two numbers is 14418

Like? Yes (1) | No   

Tania Chatterjee   10 years AGO

There are only two possible numbers with the given constraints those are
7659,6759
the sum of these two numbers is 14418.

Like? Yes (1) | No   

Soham Chakraborty   10 years AGO

x,10y+x,100y+x,1000y+x

Like? Yes (1) | No   

Anitha   10 years AGO

possible digits are 5,6,7,9
ten's digit will be 5
unit 's digit will be 9
there is only two possibilities 7659 and 6759
sum is 14418

Like? Yes (1) | No   

POTHEDAR PRAMODKUMAR   10 years AGO

7659
+ 6759
--------
14418
----------

Like? Yes (1) | No   

vishnuvardhan   10 years AGO

5,6,7,9 are possible digits whose sum is 27
5 is arranged in ten's place and 9 in unit's place
possible ways are
6759
7659
sum of all possible results 7659+6759=14418

Like? Yes (1) | No   

Shashank Kapoor   10 years AGO

there will be two numbers satisfying the condition ie 6759 and 7659
sum of these two numbers is 14418.

Like? Yes (1) | No   

gautam gaurav   10 years AGO

7659+6759=14418

Like? Yes (1) | No   

vivek   10 years AGO

only two such type of number are possible....6759 and 7659
so, sum= 6759+7659=14418

Like? Yes (1) | No   

joeroshan   10 years AGO

let's take unit digit as 9 as it is the largest. We can't take 2 and 1 in tens digit as they will not give sum of 27. So let's take 5. Now try remaining 6,7,8 and find which two numbers will end up in sum 27. Hence the numbers are 6759 and 7659. So the sum is 14418

Like? Yes (1) | No   

amit kumar   10 years AGO

Ans is 14418.
there are only two possible numbers with the given constraints those are
7659,6759
the sum of these two numbers is 14418.

Like? Yes (1) | No   

jitendra varshney   10 years AGO

reason is simple no is 7659 and 6759 ,so there sum is 7659+6759=14418

Like? Yes (1) | No   

yagnik pandya   10 years AGO

Answer is 4th option

Like? Yes (1) | No   

Phani Raaj   10 years AGO

possible numbers are 7659 and 6759
sum=14418

Like? Yes (1) | No (1)  

RAKESH   10 years AGO

6759 + 7659 = 14418

Like? Yes (1) | No (1)  

Mahesh   10 years AGO

The four digits to be used are 9,7,6,5
As 5 should be in the tens place and 9 in the units place, the only possibilties are
6759 and 7659
Sum lf them is 14418

Like? Yes (1) | No (1)