A Certain sum amounted to Rs. 900 at 5% in a time in which Rs. 750 amounted to Rs. 840 at 4%. If the rate of interest is simple, find the sum (approx.)
In the 45 litters mixture of Juice and water, the ratio of Juice and water is 5 : 4. Find the quantity of water required to be added so that resultant mixture will be in ratio 4 : 5.
The speed of a van increases by 5kmph after every one hour. If the distance travelled in the first one hour was 55 km, what was the total distance travelled in 8 hours?
Distance travelled in 1ST hour =55 km
Speed of the van increases by 5 kmph
after every one hour. Hence, distance travelled in 2nd hour =60 km
distance travelled in 3rd hour =65 km
and so on Total distance travelled =(55+60+……..+(8 terms))
=8/2(2*55+(8-1)5) =4(110+35) =580km
A tap can fill a cistern in 11hours, but due to a leakage it took 13hours to fill the cistern. If the cistern is full, in what time will the cistern become empty due to leakage?
The present ages of Vijay and Shubham differ by 35 years. 3 years later, Shubham would be 4.5 times as old as Vijay. What is the present age of Shubham?
OPtion
1) 37 years
2) 38 Years
3) 39 years
4) 45 years
5) 44 years
6) 41 years
7) 40 years
8) 42 years
9) 48 years
10) None of these
Solution
Let the present age of Shubham be x and Vijay be y
So x-y = 35 ----(i)
3 year later
(x+3) =4.5(y+3)
=> x = 4.5y + 10.5
Putting x value in (i)
4.5y + 10.5 - y = 35
=>3.5y = 24.5
=> y = 7 and x = 35+7 = 42
A father said to his son that he was thrice of his age 15 years before and will be twice of his age 10 years hence. Difference of the ages of father and son is
Let the age of father is f and that of son is s at present
According to the given conditions
f - 15 = 3 (s-15)
=> f - 3s = -30 (i)
f + 10 = 2 (s+10)
=> f - 2s = 10 (ii)
On solving (i) and (ii), we get f = 90; s = 40
A forms a wall in 10 days and B forms it in 15 days. A and B start the work of forming wall together
but after 2 days A leaves the work. How many days are required for making the remaining wall by B?
One day work of A = 1/10
One day work of B = 1/15
One day work of A and B = 1/10 + 1/15= 1/6
After 2 days of work remaining work = 1- (2*1/6) = 4/6
No. of days required by B for doing this work = (4/6) / (1/15 = 10