Raghav beats Vinod by 60 meters or 12 seconds in a km race. Find Raghav’s time over the course.
OPtion
1) 3 min 10 sec
2) 3 min 15 sec
3) 3 min 20 sec
4) 4 min 10 sec
5) 4 min 3 sec
6) 3 min 8 sec
7) 3 min 6 sec
8) 4 min 20 sec
9) 4 min 25 sec
10) None of the above
Solution
As given, Vinod covers 60m in 12 seconds.
Vinod’s time over the course = (12/60 x 1000) = 200 sec.
Raghav’s time over the course = (200 – 12) = 188 seconds
= 188/60 = 3min. 8 seconds.
Hemant sold 10 sarees for a total profit of Rs. 460 and 12 sarees for total profit of Rs. 144. At what profit per saree should he sell the remaining 20 sarees so that he gets an average profit of Rs. 18 per saree?
In a school prayer line Amit is 11th from the top and Virendra is 5th from the bottom. If Amit is 5 student ahead of Virendra, Then how many students are there in the line?
first increased by 10% and then decreased by 10%
let company market share be 100
10% = 10/100 = 1/10
so 10% of 100 = 10
new share after increase= 100 + 10 = 110..
now 10% of 110 is 11
so new share after decrease is 110 -11 = 99
1 loss on 100 means 1%
Karan walks around a square park whose side is 150m. One day he walked around the park 4 times. How much distance did he walk in a day?
OPtion
1) 3.2 Km
2) 2.8 Km
3) 2.7 Km
4) 3.1 Km
5) 2.9 Km
6) 1.9 Km
7) 2.6 Km
8) 2.4 Km
9) 2.0 Km
10) None of the above
Solution
As given:
Side of square park = 150 m
Perimeter of square park = 150 x 4 = 600m
So by walking 4 time in a day total area cover = 600 x 4 = 2400m = 2.4 km
Vijay can do a certain work in 16 days. Subham is 60% more efficient than Viajy. How many days dose Subham alone take to do the same work?
OPtion
1) 12 days
2) 11 days
3) 14 days
4) 9.5 days
5) 13 days
6) 10 days
7) 15 days
8) 8 days
9) 16 days
10) None of the above
Solution
Ratio of time taken by Vijay and Subham = 160 : 100 = 8 : 5
Suppose Subham alone takes x days to the work = 8 : 5 : : 16 : x
= > 8x = 80
x = 80/8 = 10 days
Surface area of cylinder = 2πrh + 2πr2
(2 x 22/7 x 7 x h) + (2 x 22/7 x 7 x 7) = 1848
44h + 308 = 1848
44h = 1540
h = 1540/44 = 35 m
Volume => πr2h = 22/7 x 7 x 7 x 35
= 5390 m3