M4maths Previous Puzzles

10 Jan 2019 Stocks

The market value of a 8.5% stock, in which an income of Rs. 1900 is derived by investing Rs. 11000, brokerage being 1/4 %, is:

OPtion

1) 48.25
2) 48.75
3) 49.00
4) 49.21
5) 48.50
6) 48.96
7) 48.85
8) 48.45
9) 48.60
10) None of these

Solution

For an income of Rs. 1900, investment = Rs. 11000

For an income of Rs. 8.5, investment = Rs. (11000/1900) * 8.5 = 49.21
For a Rs. 100 stock, investment = Rs. 49.21

Market value of Rs. 100 stock = Rs. 49.21 - 0.25 = Rs. 48.96

Option 6)

Correct Option: 6 Best Solution (0)

09 Jan 2019 Percentage

If P is 60% of Q, Q is 50% of R; R is 40% of S, S is 45% of T. Find P: T ?

OPtion

1) 3/50
2) 3/25
3) 7/50
4) 8/25
5) 4/25
6) 27/1000
7) 27/250
8) 27/500
9) 27/2000
10) None of these

Solution

P = 0.6 Q
Q= 0.25 R
So P = 0.6*0.25 R
R = 0.4 S
So, P = 0.6*0.5 * 0.4 S
S = 0.45*T
Again, P = 0.6* 0.5 * 0.4 * 0.45*T = 54/1000T
So P/T = 27/500
Option 8)

Correct Option: 8 Best Solution (5)

Siddesh K C   1 Month AGO

Let assume T=100
Then S=45 % of 100 =45
R=40% of 45 =18
Q=50% of 18=9
P=60% of 9=5.4
Required ratio P:T =5.4 :100 = 27/500

Like? Yes (3) | No   

RISHIKA AGARWAL   1 Month AGO

P=0.6Q
Q=0.5R
R=0.4S
S=0.45T
P=0.6*0.5*0.4*0.45T
P=0.054T
P:T = 27:500

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Kariamal   1 Month AGO

p=0.6*0.5*0.4*0.45t
p/t=0.054/1
p/t=27/500

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RAMADURAI NATESAN   1 Month AGO

It is given that P = .6*.5*.4*.45*T = .054 T
Or 1000 P = 54 T . Or P/T = 54/1000 =27/500

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MANISHA JADHAV   1 Month AGO

p=60/100*50/100*40/100*45/100*T
T=T
P/T=27/500

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08 Jan 2019 Ratio

Isha’s grandfather was 5 times older to her 4 years ago. He would be three times of her age 8 years from now. 7 years ago, what was the ratio of Isha’s age to that of her grandfather’s age?

OPtion

1) 2:5
2) 1:6
3) 1:4
4) 3:19
5) 3:17
6) 5:23
7) 4:7
8) 4:19
9) 5:18
10) None of these

Solution

Suppose Isha's grandfathers age is x and Isha's age is y

4 years ago
x-4 = 5*(y-4)
=> x = 5y - 16 --(i)

8 years from now
x+8 = 3*(y+8)
=> x = 3y + 16 --(ii)

(i) = (ii)
5y - 16 = 3y + 16
=> 2y = 32
=> y = 16
So x = 64

7 years ago
Age of Grandfather = 64 - 7 = 57
Age of Isha = 16-7 = 9
Ratio of ages = 9:57 = 3 : 19


Option 4)

Correct Option: 4 Best Solution (8)

AASHRAY AJAY SHARMA   1 Month AGO

suppose that now their age is
x and y

4 years ago age was:x-4 , y-4
x-4=5(y-4)
after 8 years age would be
x+8=3(y+8)
on solving eq 1 and 2 we get x=64 y =16
so 7 years ago
(16-7)/(64-7)= 9/57
ratio is = 3:19--Option 4

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sonypriyavalluru   1 Month AGO

let Isha's present age be X and grandfather's be Y
four years ago Isha age is X-4
from given first condtion, 5(X-4)=Y-4
and 2nd condition, 3(X+8)=Y+8
solving those equations we get X=16; Y=64
now 7years ago their ages will be 16-7=9 and 64-7=57
now ratio is 9:57 = 3:19

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Kariamal   1 Month AGO

Isha's age=x, grandfather age=y
y-4=5(x-4)
y+8=3(x+8)
Solving above eqn.
x=16, y=64
7 years ago=9:57=3:19

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DIPIN   1 Month AGO

4 years ago, Ages were 12 years and 60 years.
8 years from now, ages will be 24 years and 72 years.
7 years ago, ages were 9 years and 57 years.
7 years ago, ratio of ages = 9/57=3/19

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A.P.Singh   1 Month AGO

Suppose 4 years ago, ages of grandfather and Isha were G and I respectively.
Then G=5I
G+12=3*(I+12)

solving , we get
I=12; G=60
7 years ago, Ages were 9 years and 57 years.
Hence ratio of ages 7 years ago = 9/57-3/19

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Mouli Paul   1 Month AGO

4 year ago
5(x-4)=y-4
after 8 year
3(x+8)=y+8
From two equ. we get 16 and 64
(16-7)/(64-7)=3:19

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RISHIKA AGARWAL   1 Month AGO

Let Isha's and Grandfather's present age be i and g resp.
4 yrs ago, Isha's age= i-4
her Grandfather's age=g-4
ATQ,
g-4=5(i-4)
Similarly, 8 yrs from now,
g+8 = 3 (i+8)
solving these 2 equations, we get, i=16 and g=64
Required Ans:
i-7:g-7=9:57
=3:19

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Siddesh K C   1 Month AGO

Let current ages of Isha be X yrs and her grandfather's be Y yrs
4 years ago, 5(X-4)=Y-4 ==> 5X-Y=16...Eq 1
8 Years Later, 3(X+8)=Y+8 ==> 3X-Y=-16....Eq 2
Solving eq 1 and eq 2,will get X=16 and Y=64
Then ages ratio 7 years ago is 9:57 =3:19....Option 4

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07 Jan 2019 Age

A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 55 years now, what would be the son's age 4.5 years later?

OPtion

1) 31
2) 30
3) 32
4) 29
5) 28
6) 23
7) 24
8) 25
9) 26
10) None of these

Solution

Let the sons current age be x
So fathers age x years back when son was born => 55-x = x
Solving we get x = 27.5
4.5 Years later son's age = 27.5 + 4.5 = 32 years

Option 3)

Correct Option: 3 Best Solution (11)

G.S.Kantharao   1 Month AGO

Father and son's age =55y,27.5y
After 4.5 y Son's age=32y
Right option is 3👈

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SAYAN CHATTERJEE   1 Month AGO

F= 2s= 55
s= 27.5
So, son's age after 4.5 years is (27.5+4.5)= 32.
Option 3.

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AASHRAY AJAY SHARMA   1 Month AGO

At the time of birth father's age =x
2x=55=>x=27.5
After 4.5 years son's age is=27.5+4.5=32
Hence my option is 3

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Siddesh K C   1 Month AGO

Let the age of son be X years
As per problem 55-X=X
then 2X=55
X=27.5 years
Then Son's age 4.5 years later 27.5+4.5=32 years...Option 3

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RAMADURAI NATESAN   1 Month AGO

Let son's present age be = n . Since father's present age is 55
father's age at the time of his son's birth is 55 - n =n as per given given information.Thus 2n = 55 or n = 27.5. after 4.5 years,son's age will be 32.

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Kariamal   1 Month AGO

x=55-x
2x=55
x=27.5
4.5 years later=27.5+4.5
=32

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Gargi   1 Month AGO

let now soms age is x
then,
55-x=x
2x=55
x=27.5
then after 4.5 yrs 27.5+4.5=32

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Navya   1 Month AGO

let,x-->age of son at present i.e.,,,age of father at time of his son birth
2x=55
x=27.5 yrs
4.5 yrs later 32 yrs

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MANISHA JADHAV   1 Month AGO

let age of son=x
at the birthof son fathers age=x
but now fathers age=55=x+x
x=55/2=27.5
son's age after 4.5 years=27.5+4.5=32

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udaychandu bachina   1 Month AGO

As the age of father was the same as the age of son at the time of his birth which mean age of son should be half the age of father. So half of 55 will be 27.5. Adding 4.5 to 27.5 will give 32 as the age son after 4.5 years. Hence age of son will be 32 years after 4.5 years

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Komal Mahangare   1 Month AGO

55-x = x .... son age
2x= 55
x = 27.5
4.5 years later
son's age = 27.5 + 4.5 = 32

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04 Jan 2019 Lift

Jack enters a lift on the 25th floor, which is going up @ 56 floors/min speed. At the same time Jill enters another lift on the 70th floor which is going down @ 64 floors/min speed. At what floor will

they be together?

OPtion

1) 41
2) 42
3) 43
4) 44
5) 45
6) 39
7) 47
8) 46
9) 48
10) None of these

Solution

Relative Speed = 56+64 = 120 floors/min
Relative Distance = 70 - 25 = 45 floors

Time to cover 45 floors = 45*60/120 = 22.5 seconds

Floors travelled by Jack in 22.5 seconds = (56/60)*22.5 = 21
Floors on which they will meet = 25 + 21 = 46th
Option 8)

Correct Option: 8 Best Solution (7)

G.S.Kantharao   1 Month AGO

Let x is the floor they meet
(70-x)/64=(x-25)/56
(70-x)56=(x-25)64
3920-56x=64x-1600
120x=5520=>x=5520/120=46
Right option is 8👈

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SAYAN CHATTERJEE   1 Month AGO

25+56x= 70-64x
x= 0.375
So, floor is 25+56*0.375= 46.
Option 8.

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Siddesh K C   1 Month AGO

let X be floor where both meet together.
then (X-25)/56 =(70-X)/64
Solving above equation will get X=46...Option 8

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RISHIKA AGARWAL   1 Month AGO

They will meet after t time so Time is constt here.
D/S=constt
Distance ratio = Speed Ratio= 56/64=7/8
Total floor between 25th and 70th = 70-25= 45 (This is 15 *3)
So Jack will travel 7*3=21 floors from 25th and Jill will travel 8*3=24 floors from 70th to meet Jack.
So they will meet at 25+21 or 70-24 =46th Floor.

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Devendra Marghade   1 Month AGO

Relative speed (in opposite direction)=56+64=120 floors/min.
Difference between them=70-25=45 floors.
So time taken to meet = 45/120 = 3/8 min.
Floors covered up by Jack in 3/8 min=56*3/8=21
Hence they meet at 25+21=46th floor.
Option 8)

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balaji   1 Month AGO

after 22.5 minute they will together

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Kariamal   1 Month AGO

Relative speed=56+64=120
Relative distance=70-25=45
So, 45/120*60=22.5
56/60*22.5=21
Floors on which they will meet=21+25=46

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03 Jan 2019 Number of Cans

Chintu works at a soft drink company and was arranging some particular number of cylindrical aluminium soft drink cans in a square box but the box became full and there were 8 cans remaining to be put in. Then, he started arranging all Cans in a rectangular box where he could arrange 6 cans more along the length than the breadth after putting all the cans in the rectangular box. He found out that there was still space left for another 11 cans. What is the number of cans Chintu had if it is known that the number of cans were more than 15 and no can was put on top of another can?

OPtion

1) 25
2) 33
3) 34
4) 36
5) 55
6) 44
7) 45
8) 54
9) 56
10) None of these

Solution

In a square box the number of cans arranged along the length and breadth would be same.
In case of rectangular box, lets assume that number of cans along breadth is x then number of boxes along the length would be x+6
Total number of cans the rectangular box can take = x*(x+6)
Total number of cans Chintu was able to put in the rectangular box (as some empty space was remaining ) = x*(x+6) - 6 ---- (i)


Given that the number of cans are more than 15, hence 2 & 3 cans along the length are ruled out

Lets try with 4 cans along length of square box, total cans in box would be 16
Total number of cans which Chintu has = 16+8 = 24 ---- (ii)
(i = (ii)
x*(x+6) - 11 = 24
=> x^2 + 6x = 35
Trying to solve we realize that there is no such whole number which x can take

Lets try with 5 cans along length of square box, total cans in box would be 25
Total number of cans which Chintu has = 25+8 = 33 ---- (ii)
(i = (ii)
x*(x+6) - 11 = 33
=> x^2 + 6x = 44
Trying to solve we realize that there is no such whole number which x can take


Lets try with 6 cans along length of square box, total cans in box would be 36
Total number of cans which Chintu has = 36+8 = 44 ---- (ii)
(i = (ii)
x*(x+6) - 11 = 44
=> x^2 + 6x = 55
Solving we get x = 5

So total number of cans which Chintu had = x*(x+6) - 11 = 5(5+6) - 11 = 5*11 -11 = 44

Correct Option: 6 Best Solution (1)

G.S.Kantharao   1 Month AGO

Let the side of the Square=x
x^2>15=> x^2=16/25/36/...
Length and breadths are l and b where l=b+6
l*b=b(b+6)=16+8+11/25+8+11/36+8+11/...
b^2+6b=35/44/55/...
b^2+6b-55=0(55 gives real solution)
(b-5)(b+11)=0
Breadth =5
Length=11
Area =55
Chintu had at first =55-11=44
My option is 6👈

Like? Yes (7) | No (2)  

02 Jan 2019 Profit and Loss

A vendor bought 1300 toffees for 5850 rupees. How many toffees in 1053 rupees must he sell to gain 56%?

OPtion

1) 133.33
2) 134
3) 140
4) 150
5) 135
6) 155
7) 160
8) 250
9) 210
10)None of these

Solution

CP of 1 toffees = 5850/1300 = Rs. 4.5
SP of 1 toffees for 56% profit = 4.5*1.56 = Rs. 7.02
So in 1053 Rupees number of toffees to be sold = 1053/7.02 = 150

Option 4)

Correct Option: 4 Best Solution (10)

G.S.Kantharao   1 Month AGO

C.P.of 1300=₹5850
C.P.of each=₹4.5
%Profit =56.
S.P of each =4.5*(156/100)=₹7.02
No of Toffees=1053/7.02=150
Hence the right option is 4👈

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Devendra Marghade   1 Month AGO

CP of 1 toffee=5850/1300=Rs. 9/2
SP of 1 toffee with 56% gain=(9/2)*(156/100)=Rs. 351/50
So in Rs. 1053, quantities to be sold=1053/(351/50)= 150
Option 4)

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Kariamal   1 Month AGO

C.P of 1 toffee=5850/1300=4.5
Selling a toffee gain of 56%=4.5*1.56=7.02
So, number of toffees sold for rs.1053=1053/7.02=150

Like? Yes | No   

RAMADURAI NATESAN   1 Month AGO

P.P.of 1 toffee =5850/1300 = Rs 4.5.
At 56% profit,S.P.of 1 toffee =1.56*4.5 = 7.02.
Hence in Rs 1053, he mast sell 1053/7.02 = 150 toffees

Like? Yes | No   

Sowmya Reddy   1 Month AGO

cost price of 1 toffee is 4.5
sp=(100+56)%4.5
sp=7.02
sp of 1 toffee to obtain 56% gain is 7.02
for 1053 rs we can sell 150 toffees

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lakshman   1 Month AGO

CP=5850/1300
SP=1053/N

Therefore,
156/100*5850/1300=1053/N
N=150

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Alivia Pramanik   1 Month AGO

CP of 1 toffee = (5850/1300)
SP of 1 toffee = (5850/1300)*(156/100)
SP of 1053 toffee = 1053*(1300/5850)*(100/150)

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ushap   1 Month AGO

for 1 toff sp is 1.56×4.5=7,so for 1053 rupees 150 toff can be sold to get 56% profit

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Ramesh Muthukrishnan   1 Month AGO

1 tofee= 4.5Rs
S.P = 156/100 × 4.5
S.P of 1 toffee =Rs. 351/50
N toffees = 1053/351 ×50
N=150

Like? Yes | No   

minnu   1 Month AGO

56% of 5850/1300=2.52
5850/1300=4.5
1053/(4.5+2.52)=150

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01 Jan 2019 Decode

If VERY= 7369, HAPPY= 54889 and NEW = 231 then code for YEAR would be

OPtion

1) 9345
2) 9846
3) 9316
4) 9376
5) 9046
6) 9348
7) 9346
8) 9340
9) 9356
10) None of these

Solution

AS VERY is coded as "7369", HAPPY is coded as "54889" and NEW as 231
So Y is coded as 9, E as 3, A as 4, R as 6

So code for YEAR would be = 9346

Correct Option: 7 Best Solution (12)

G.S.Kantharao   1 Month AGO

VERY=7369
HAPPY=54889
NEW=231
YEAR=9346
Hence the right option is 7👈

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Ritul rana   1 Month AGO

select the digit for every letter from the given words..

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Ayush Garg   1 Month AGO

E represents 3, Y represents 9, A represents 4, R represents 6

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Aritra Banerjee   1 Month AGO

9346

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Siddesh K C   1 Month AGO

Letters given in problem statement coded as
V E R Y H A P N W
7 3 6 9 5 4 8 2 1
Then YEAR can be coded as 9346

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Hema   1 Month AGO

y=9
E=3
A=4
R=6

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Sowmya Reddy   1 Month AGO

y is coded as 9 in happy and very where as E is coded as 3 in very and new

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Priyojeet Sarkar   1 Month AGO

In the word HAPPY and VERY Y=9 , in VERY and NEW E=3 , in HAPPY A=4 , in VERY R=6

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Abhijit   1 Month AGO

y=9
e=3
a=4
r=6
so year=9346

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Kariamal   1 Month AGO

YEAR=9346

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RAMADURAI NATESAN   1 Month AGO

From the code of VERY which is 7369 , we get
Y=9 , E=3 , and R = 6. From the code of HAPPY, which is
54889, we get A =4. Hence code for YEAR is 9346

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Kavya   1 Month AGO

By arranging the alphabets in order

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31 Dec 2018 Series

Find the next term of the series:
6, 11, 16, 21, 26, ?

OPtion

1) 27
2) 28
3) 29
4) 34
5) 35
6) 36
7) 31
8) 32
9) 30
10) None of these

Solution

Next term of series is derived
4*(n-1) + n+1 where n=1

So 4*1 + 2 = 6
4*2 + 3 = 11
4*3 + 4 = 16
4*4 + 5 = 21
4*5 + 6 = 26
4*6 + 7 = 31

Correct Option: 7 Best Solution (10)

G.S.Kantharao   1 Month AGO

6,11,16,21,26,... Common difference is 5
So Next term is 31.
My option is 7👈

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Varun   1 Month AGO

5 difference makes it 26+5 =31
= Option (7)

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vignesh   1 Month AGO

The difference between each term is 5 so next term will be 31

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sruthi pujari   1 Month AGO

next number in the series is calculated by adding +5 to previous number. so, 26+ 5 = 31
Hence, option>> 7

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Kariamal   1 Month AGO

6+5=11
11+5=16
16+5=21
21+5=26
26+5=31

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ARINJOY GHOSH   1 Month AGO

It's an Arithmetic Progression with first term and common difference 5. Next Term is =26+5=31
Ans. option(7)

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Ramana   1 Month AGO

6+5=11
11+5=16
16+5=21
21+5=26
26+5=31

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Sowmya Reddy   1 Month AGO

difference between 2 terms is 5

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Ritul rana   1 Month AGO

for each next term you have to add 5 to the present one i.e6+5=11,then 11+5=16 just like that 26+5=31.

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SAYAN CHATTERJEE   1 Month AGO

The swreis in AP with common difference 5,
So, next term is 26+5= 31.
Option 7.

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28 Dec 2018 ODD Number

How many factors of 3622184564625 are odd numbers?

OPtion

1) 600
2) 188
3) 144
4) 180
5) 288
6) 576
7) 128
8) 256
9) 96
10) None of these

Solution

3622184564625 = 37^2 * 19^1 * 11^3 * 5^3 * 3^2 * 31^1

Any factor of this number should be of the form 37^a * 19^b * 11^c * 5^d * 3^e * 31^f

All the factors of this number would be an odd number as there is no even factor

a can take values 0, 1, 2
b can take values 0, 1,
c can take values 0, 1, 2, 3
d can take values 0, 1, 2, 3
e can take values 0, 1, 2, 3
and f can take value 0, 1

Total number of odd factors = 3*2*4*4*4*2= 768

Option 10)

Correct Option: 10 Best Solution (0)