let age of x is a and y is b
now age of x is thrice age of y
a=3b;
now before three years (a-3)=4(b-3)
=>3b-3=4b-12
b=9
=>a=3*9=27
sum of ages is 27+9=36
The distance between two stations is 100 km. 2 cars start from A and B at the same time and return to the original station with speed 48 km/hr and 64 km/hr. The time gap between their meeting twice will be
Total distance covered between their meetings is 200 KM travelled together by 2 cars.
total combined speed = 64+48 = 112
Time take to cover 200KM with 112 KM/H speed is
200/112
=25/ 14 Hour
according to the given conditions
possible values of x, y and z are
x = 2, 3, 4
y = 5, 6, 7
z = 11, 12, 13
so possible combinations are
(2, 5, 12), (2, 6, 11), (3, 5, 11)
Ram invests βΉ46500 in 6% stock at 93 and sells the stock when its price rose to βΉ95. He invests the sale proceeds in 9% stock at 95. Find out the change in Ramβs income.
Income from first stock = (6/93 x 46500) = 3000
We have to find the amount realized on selling this stock.
Amount realized on selling 93 stock = 95
β΄ Amount realized on selling 46500 stock = 95/93 x 46500 = 475000
This amount is invested in 9% stock at 95.
β΄ Income from the second stock
= (9/95 x 47500) = 4500
Hence, increase in income
= (4500 - 3000) = 1500.