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M4maths Previous Puzzles

05 Aug 2022 Number Series

Select the most appropriate option in which the number in the set share same relationship as the number in the given set
(30, 54, 28)

OPtion

1) (48, 42, 32)
2) (48, 72, 42)
3) (42, 36, 28)
4) (54, 60, 36)
5) (45, 27, 26)
6) (30, 12, 18)
7) (36, 45, 27)
8) (18, 33, 20)
9) (24, 30, 16)
10) None of these
Solution
Relationship between three numbers of a set is as follows:
(First Number+Second Number)/3 = Third Number
(30+54)/3=28
.'. Only correct set is (36, 45, 27), where (36+45)/3=27
Option 7)
Correct Option: 7 Best Solution (1)
G.S.Kantharao   7 Months AGO
The above series is sum of first two is thrice of third.
So(36,45,27)=36+45=3*27
So my option is 7 👈
Like? Yes | No   
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04 Aug 2022 Boat and Streams

A motorboat whose speed is 27 km/h in still water takes 20 minutes more to go 40 km upstream than to cover the same distance downstream. If the speed of the boat in still water is increased by 3 km/h, then how much time will it take to go 44 km downstream and 54 km upstream ?

OPtion

1) 3 hours 16 minutes
2) 4 hours 20 minutes
3) 6 hours 24 minutes
4) 4 hours 40 minutes
5) 6 hours 40 minutes
6) 1 hours 20 minutes
7) 2 hours 20 minutes
8) 3 hours 20 minutes
9) 2 hours 40 minutes
10) None of these
Solution
Let speed of the stream=x km/h, then Downstream speed=(27+x) km/h and Upstream speed=(27-x) km/h
Difference of time for 40 km upstream & downstream = 40/(27-x) - 40/(27+x) = 1/3 hrs.
⇒ x² + 240x - 729 = 0
(x+243) (x-3) = 0
x=3 km/h
Now, new speed of a boat in still water=27+3=30 km/h
.'. Downstream speed=(30+3)=33 km/h, Upstream speed=(30-3)=27 km/h
Hence, time required for 44 km downstream and 54 km upstream = (44/33) + (54/27) hrs = 10/3 hrs = 3 hrs 20 min.
Correct Option 8)
Correct Option: 8 Best Solution (1)
Dr.Dipin Singh   7 Months AGO
If x is speed of stream, then
40/ (27-x) - (40/(27+x) = 1/3
x= 3 kmph
Time reqd for given distances = 44/33+54/27= 3 1/3 hrs
Like? Yes (4) | No   

03 Aug 2022 Alligation and Mixture

Ratio of milk and water is 5:3. When 4.8 liters of mixture is taken out and added 800 ml milk and 600 ml water, the difference of milk and water in a mixture is 5 liters, then difference of quantities of water and milk in initial mixture was

OPtion

1) 8 liters
2) 6 liters
3) 9 liters
4) 12 liters
5) 15 liters
6) 24 liters
7) 18 liters
8) 10 liters
9) 20 liters
10) None of these
Solution
Let in initial mixture, Milk=5x, Water=3x
Qty. of milk after taking out 4.8 liters of mixture and adding 800 ml milk=5x - (4.8*5/8) + 0.8 L = (5x - 2.2) L
Qty. of water after taking out 4.8 liters of mixture and adding 600 ml water=3x - (4.8*3/8) + 0.6 L = (3x - 1.2) L
Difference of milk and water = (5x-2.2) - (3x-1.2) = 5
2x - 1 = 5
x = 3
Difference of milk and water in initial mixture = 5x - 3x = 2x = 2*3 = 6 liters
Correct Option 2)
Correct Option: 2 Best Solution (1)
G.S.Kantharao   7 Months AGO
Ratio of milk and water =5:3
Removed quantity=lt.4.8
Added milk and water =800ml,600ml
Difference=200ml
After adding difference =5lt
Before adding = lt.4.8.
Difference of ratio =5-3=2units
Total quantity after removing lt.4.8 is lt.19.2
Initial mixture=lt.19.2+lt.4.8=lt.24
Quantities of milk and water
are = lt.15,lt.9
Difference of water and milk
is =lt.6
My option is 2👈
Like? Yes (1) | No   

02 Aug 2022 Area

If cost of constructing a path of uniform width around a circular garden of diameter 50 meter at the rate of Rs. 350 per meter sq. is Rs. 144375, then width of a path is:

OPtion

1) 350 cm
2) 225 cm
3) 300 cm
4) 275 cm
5) 260 cm
6) 325 cm
7) 250 cm
8) 370 cm
9) 200 cm
10) None of these
Solution
Radius of garden r = 50/2 = 25 m.
Let the width of a circular path=x m, then outer radius=(25+x) m.
Area of a path = Total Cost/Rate per m. sq. = 144375/350 = 412.5 m. sq.
Also, Area of a path = Area of a outer circle - Area of inner circle = π[(25+x)² - 25²]
⇒ π[(25+x)² - 25²] = 412.5
(22/7)*[625 + 50x + x² - 625] = 412.5
4x² + 200x - 525 = 0
4x² + 210x - 10x - 525 = 0
(2x-5) (2x+105) = 0
⇒ x=5/2, -52.5
Considering +ve value, x=5/2 or 2.5 m=250 cm
Correct Option 7)
Correct Option: 7 Best Solution (1)
G.S.Kantharao   7 Months AGO
Cost @ ₹350/m^2=₹144375
Path Area =144375/350
=412.5 m^2
Ï€(R^2-r^2)=412.5. d=50m=>r=25m
(R^2-r^2)=412.5*7/22=131.25
R^2=131.25+625=756.25
R=√756.25=27.5
Width=27.5-25=2.5m=250cm
My option is 7👈
Like? Yes (2) | No   

01 Aug 2022 Probability

A bag contains 5 green, 7 red and 4 white balls. If three balls are drawn one after the other with replacement, then the probability of getting balls of same colour is:

OPtion

1) 1/4
2) 1/35
3) 1/64
4) 1/32
5) 7/80
6) 2/35
7) 4/35
8) 133/512
9) 133/1024
10) None of these
Solution
Total number of balls in a bag = 5+7+4 = 16
As the balls are drawn with replacement, so probability of drawing same colour ball each time will be same.
P(Drawing 3 Green balls) = (5/16)*(5/16)*(5/16) = 125/4096
P(Drawing 3 Red balls) = (7/16)*(7/16)*(7/16) = 343/4096
P(Drawing 3 White balls) = (4/16)*(4/16)*(4/16) = 64/4096
.'. Probability of getting balls of same colour = P(3 Green) + P(3 Red) + P(3 White) = 125/4096 + 343/4096 + 64/4096 = 532/4096 = 133/1024
Correct Option 9)
Correct Option: 9 Best Solution (2)
Pargat Pal Singh   8 Months AGO
(5/16)^3 + (7/16)^3 +(4/16)^3 =133/1024
Like? Yes (3) | No   
RAMADURAI NATESAN   8 Months AGO
Ans = (5^3 +7^3 + 4^3 ) / 16^3 =133 / 1024
Like? Yes | No   

29 Jul 2022 Number System

A number consists of four different digits where last digit is two times the first digit, second digit is two times the last digit and third digit at tens place is 3 less than the second digit. The difference of this four digit number and number formed by reversing its digit is:

OPtion

1) 2268
2) 1728
3) 5454
4) 3726
5) 4266
6) 5868
7) 2637
8) 1269
9) 1459
10) None of these
Solution
Given, last digit is 2 times the first digit, so number can be: 1 __ __ 2 ; 2 __ __ 4 ; 3 __ __ 6 ; 4 __ __ 8
Also second digit is 2 times the last digit so we can have only two numbers from above four as other two will result into double digit at 2nd place .
.'. Remaining numbers are 1 4 __ 2 ; 2 8 __ 4
It is given that 3rd digit is 3 less than the 2nd digit, therefore, so we have numbers 1 4 1 2 and 2 8 5 4
As it is given that all four digits are different, so 1412 can not be the number and hence required number is 2854
Therefore difference of number and number formed by reversing digits = 4582 - 2854 = 1728
Correct Option 2)
Correct Option: 2 Best Solution (1)
Akanksha Shelke   8 Months AGO
The 4 digit number is 2854. So the difference between 4582 and 2854 is 1728
Like? Yes | No   

28 Jul 2022 Age Problem

Roshan's present age is five times his daughter's present age and five-eighth of his mother's present age. The average age of all of them is 32 years 8 months, then what is the difference between present ages of Roshan's daughter and mother (in years)?

OPtion

1) 56
2) 39
3) 42
4) 59
5) 45
6) 35
7) 40
8) 49
9) 47
10) None of these
Solution
Let Roshan's present age = x years
His daughter's age = x/5
His mother's age = (8/5)*x
Average of all three = [x + x/5 + (8/5)*x] / 3 = 98/3
14x / 5 = 98
x = 35
Present age of daughter=35/5=7 years
Present age of mother=(8/5)*35=56 years
Hence, required difference=56-7=49 years.
Correct Option 8)
Correct Option: 8 Best Solution (3)
G.S.Kantharao   8 Months AGO
Let their ages are 5x,x,8x
Average=14x/3=98/3yrs
=>x=7
Difference of their ages=7x
=7*7=49yrs.
My option is 8 👈
Like? Yes (1) | No   
Aarjav jain   8 Months AGO
Let's suppose rohan's age is x, so his daughter age is x/5, and his mother's age is 8x/5.
so average is (x+x/5+8x/5)/3=392 months
so value of x is 35 yrs.
then his daughter age is 7 years
and his mother age is 56 years
so difference between their ages is 49 years.
Like? Yes | No   
RAMADURAI NATESAN   8 Months AGO
R = 5D = 5M/8. M - D = 8R/5 - R/5 = 7R/5.
R + D + M = 98 (GIVEN) .I.E.,R + R/5 + 8R/5 = 98. R = 35
M - D = 7R/5 = 49
Like? Yes | No   

27 Jul 2022 Time Distance & Speed

A bus takes 1 hour 20 minutes more to travel a distance of 210 km, if its speed is reduced by 10 km/hr than actual speed, then find the time taken to cover a distance of 300 km at double the usual speed.

OPtion

1) 6 hours 40 minutes
2) 4 hours 20 minutes
3) 3 hours 40 minutes
4) 4 hours 40 minutes
5) 6 hours 20 minutes
6) 3 hours 20 minutes
7) 2 hours 20 minutes
8) 1 hours 40 minutes
9) 2 hours 40 minutes
10) None of these
Solution
Let the usual speed of a bus=x km/h
Then, 210/(x-10) - 210/x = 4/3
x² - 10x - 1575 = 0
(x-45) (x+35) = 0
x=45
.'. Time taken to cover 300 km at 90 km/h = 300/90 hrs = 3â…“ hrs = 3 hrs 20 min.
Correct Option 6)
Correct Option: 6 Best Solution (1)
G.S.Kantharao   8 Months AGO
Let x be the initial speed.
Distance=210
210/x-10 -210/x=4/3
x^2-10x-1575=0
(x-45)(x+35)=0
x=45
Time taken to travel 300Km=300/90=3hr20min
My option is 6👈
Like? Yes (1) | No   

26 Jul 2022 Profit & Loss

Two varieties of tea having cost per kg Rs. 36 and Rs. 45 respectively are mixed in the ratio 13:8. How much quantity of this mixture should be sold at Rs. 45 per kg to get profit of Rs. 1950 ?

OPtion

1) 530 kg
2) 420 kg
3) 350 kg
4) 560 kg
5) 280 kg
6) 450 kg
7) 210 kg
8) 360 kg
9) 410 kg
10) None of these
Solution
For (13+8)=21 kg mixture, CP=36*13 + 45*8=Rs. 828
CP per kg=828/21=Rs. 276/7
Profit per kg = SP - CP = 45 - (276/7) = 39/7
⇒ For profit of Rs. 39/7, quantity to be sold = 1 kg
.'. For profit of Rs. 1950, quantity to be sold = 350 kg.
Correct Option 3)
Correct Option: 3 Best Solution (2)
G.S.Kantharao   8 Months AGO
C.P of 21 mga of mixture=13*36+8*45
=468+360=828
S.P of 21=45*21=945
Profit on 21=₹117
For a profit of ₹1950 quantity=1950*21/117=350
My option is 3👈
Like? Yes | No   
RAMADURAI NATESAN   8 Months AGO
Cost of 1kg of mixture = (36*13/21 + 8*45/21)=828/21
Let q kg of mixture be sold to make profit of 1950.
Profit = 45q - 828q/21 = 1950
Solving, q = 350
Like? Yes | No   

25 Jul 2022 Percentage

In an examination, 85% of the candidates passed in English and 65% of the candidates passed in Mathematics, but 5% failed in both of these subjects. If 154 candidates passed in both the subjects, the number of candidates who appeared in an examination was:

OPtion

1) 240
2) 210
3) 350
4) 140
5) 560
6) 420
7) 180
8) 280
9) 300
10) None of these
Solution
Given, 5% failed in both the subjects, so candidates passed in at least one subject=95%
Let total candidates=x, then 85% of x + 65% of x - 154 = 95% of x
0.85x + 0.65x - 154 = 0.95x
0.55x = 154
x = 280
Correct Option 8)
Correct Option: 8 Best Solution (1)
G.S.Kantharao   8 Months AGO
Method 1
No of failed in both=5%
Passed atleast one=95%
N(E)=85%,N(M)=65%
N(E^M)=N(E)+N(M)-N(EUM)
=85%+65%-95%=55%=154
Total Students=154*100/55=280
So my option is 8 👈
Method 2
English passed candidates =85%
English failed candidates =15%
Candidates passed in Maths= 65%
Candidates failed in Maths =35%
Overall Failed Candidates =5%
Total Failed Candidates= 15%+35%-5%=45%
Now Total Passed Candidates =100%-45%=55%
55% = 154
100%=280
So Total Candidates Appeared in Exam =280
My option is 8 👈
Like? Yes (1) | No   
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